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fix(ontology): guard against empty query string in SPARQL generator

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Closes #870.  query.split()[0] in _generate_with_llm raised IndexError
when the LLM response 'query' field passed the keyword-startswith guard
but split to an empty list (e.g. if the guard is ever weakened during
refactoring).  Compute parts once, return None when empty, and reuse
parts[0] for the query_type read.

Signed-off-by: SAY-5 <saiasish.cnp@gmail.com>
This commit is contained in:
SAY-5 2026-05-07 02:47:15 -07:00
parent 1ffae12559
commit 0ed5ec00b3
2 changed files with 119 additions and 1 deletions
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5
trustgraph-flow/trustgraph/query/ontology/sparql_generator.py
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@ -203,10 +203,13 @@ ASK {{
if response and isinstance(response, dict):
query = response.get('query', '').strip()
if query.upper().startswith(('SELECT', 'ASK', 'CONSTRUCT', 'DESCRIBE')):
parts = query.split()
if not parts:
return None
return SPARQLQuery(
query=query,
variables=self._extract_variables(query),
query_type=query.split()[0].upper(),
query_type=parts[0].upper(),
explanation=response.get('explanation', 'Generated by LLM'),
complexity_score=self._calculate_complexity(query)
)