Initial commit: cuGenOpt GPU optimization solver

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L-yang-yang 2026-03-20 00:33:45 +08:00
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/**
* assignment.cuh - 指派问题
*
* 继承 ProblemBase使用 ObjDef 目标注册机制
*/
#pragma once
#include "types.cuh"
#include "cuda_utils.cuh"
#include "operators.cuh"
struct AssignmentProblem : ProblemBase<AssignmentProblem, 1, 16> {
const float* d_cost;
const float* h_cost; // host 端成本矩阵(用于 init_relation_matrix
int n;
// ---- 目标计算 ----
__device__ float calc_total_cost(const Sol& sol) const {
float total = 0.0f;
const int* assign = sol.data[0];
int size = sol.dim2_sizes[0];
for (int i = 0; i < size; i++)
total += d_cost[i * n + assign[i]];
return total;
}
// ---- 目标定义OBJ_DEFS 与 compute_obj 必须一一对应)----
static constexpr ObjDef OBJ_DEFS[] = {
{ObjDir::Minimize, 1.0f, 0.0f}, // case 0: calc_total_cost
};
__device__ float compute_obj(int idx, const Sol& sol) const {
switch (idx) {
case 0: return calc_total_cost(sol); // OBJ_DEFS[0]
default: return 0.0f;
}
}
__device__ float compute_penalty(const Sol& sol) const {
return 0.0f;
}
ProblemConfig config() const {
ProblemConfig cfg;
cfg.encoding = EncodingType::Permutation;
cfg.dim1 = 1; cfg.dim2_default = n;
fill_obj_config(cfg);
return cfg;
}
// ---- shared memory 接口 ----
static constexpr size_t SMEM_LIMIT = 48 * 1024;
size_t shared_mem_bytes() const {
size_t need = (size_t)n * n * sizeof(float);
return need <= SMEM_LIMIT ? need : 0;
}
size_t working_set_bytes() const {
return (size_t)n * n * sizeof(float);
}
__device__ void load_shared(char* smem, int tid, int bsz) {
float* sc = reinterpret_cast<float*>(smem);
int total = n * n;
for (int i = tid; i < total; i += bsz) sc[i] = d_cost[i];
d_cost = sc;
}
// 成本先验task j 和 task k 如果被相似 agent 偏好G 值高
// O 矩阵task j 在位置 i 成本低 → O[j][k] 略高j 倾向排在 k 前面的位置)
void init_relation_matrix(float* G, float* O, int N) const {
if (!h_cost || N != n) return;
// 对每个 task构建成本向量task 间余弦相似度 → G
// 简化:成本列向量的相关性
float max_c = 0.0f;
for (int i = 0; i < N * N; i++)
if (h_cost[i] > max_c) max_c = h_cost[i];
if (max_c <= 0.0f) return;
for (int j = 0; j < N; j++)
for (int k = 0; k < N; k++) {
if (j == k) continue;
// G: 两个 task 的成本向量越相似 → 越可能互换
float dot = 0.0f, nj = 0.0f, nk = 0.0f;
for (int i = 0; i < N; i++) {
float cj = h_cost[i * N + j] / max_c;
float ck = h_cost[i * N + k] / max_c;
dot += cj * ck;
nj += cj * cj;
nk += ck * ck;
}
float denom = sqrtf(nj) * sqrtf(nk);
float sim = (denom > 1e-6f) ? dot / denom : 0.0f;
G[j * N + k] = sim * 0.2f;
O[j * N + k] = sim * 0.05f;
}
}
static AssignmentProblem create(const float* hc, int n) {
AssignmentProblem prob;
prob.n = n;
prob.h_cost = hc;
float* dc;
CUDA_CHECK(cudaMalloc(&dc, sizeof(float)*n*n));
CUDA_CHECK(cudaMemcpy(dc, hc, sizeof(float)*n*n, cudaMemcpyHostToDevice));
prob.d_cost = dc;
return prob;
}
void destroy() {
if (d_cost) { cudaFree(const_cast<float*>(d_cost)); d_cost = nullptr; }
h_cost = nullptr;
}
};