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{"date": "2024-07-20 13:00", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascending order.\n\n For example:\n generate_integers(2, 8) => [2, 4, 6, 8]\n generate_integers(8, 2) => [2, 4, 6, 8]\n generate_integers(10, 14) => []\n \"\"\"\n # Determine the range of numbers to consider\n start = min(a, b)\n end = max(a, b)\n\n # Generate a list of even integers in the specified range\n even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n return even_integers", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[2, 10]], "plus_fail_tests": [[6, 12]]}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def compare_one(a, b):\n \"\"\"\n Create a function that takes integers, floats, or strings representing\n real numbers, and returns the larger variable in its given variable type.\n Return None if the values are equal.\n Note: If a real number is represented as a string, the floating point might be . or ,\n\n compare_one(1, 2.5) \u279e 2.5\n compare_one(1, \"2,3\") \u279e \"2,3\"\n compare_one(\"5,1\", \"6\") \u279e \"6\"\n compare_one(\"1\", 1) \u279e None\n \"\"\"\n \n def parse_value(value):\n \"\"\"Convert the input value to a float or return it as is if it's a string.\"\"\"\n if isinstance(value, str):\n # Replace comma with dot for float conversion\n value = value.replace(',', '.')\n try:\n return float(value)\n except ValueError:\n return value # Return the string if it cannot be converted\n return value\n\n # Parse both values\n parsed_a = parse_value(a)\n parsed_b = parse_value(b)\n\n # Check for equality\n if parsed_a == parsed_b:\n return None\n\n # Return the larger value in its original type\n if parsed_a > parsed_b:\n return a\n else:\n return b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n Example:\n even_odd_count(-12) ==> (1, 1)\n even_odd_count(123) ==> (1, 2)\n \"\"\"\n # Convert the number to a string and remove the negative sign if present\n num_str = str(abs(num))\n \n even_count = 0\n odd_count = 0\n \n # Iterate through each character in the string representation of the number\n for digit in num_str:\n if digit.isdigit(): # Check if the character is a digit\n if int(digit) % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n return (even_count, odd_count)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n \"\"\"Compares the actual game scores with the guessed scores and returns the absolute differences.\n \n Args:\n game (list of int): The actual scores of the matches.\n guess (list of int): The guessed scores of the matches.\n \n Returns:\n list of int: A list containing the absolute differences between the actual scores and the guessed scores.\n If the guess is correct, the value is 0.\n \"\"\"\n return [abs(g - a) for a, g in zip(game, guess)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n \"\"\"\n Write a function count_nums which takes an array of integers and returns\n the number of elements which has a sum of digits > 0.\n If a number is negative, then its first signed digit will be negative:\n e.g. -123 has signed digits -1, 2, and 3.\n \n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n def sum_of_digits(n):\n # Convert the number to string and calculate the sum of its digits\n # For negative numbers, we need to consider the first digit as negative\n str_n = str(n)\n if n < 0:\n return -int(str_n[1]) + sum(int(digit) for digit in str_n[2:])\n else:\n return sum(int(digit) for digit in str_n)\n\n count = 0\n for num in arr:\n if sum_of_digits(num) > 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list to avoid division by zero\n\n mean_value = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n return mad", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def factorial(i):\n \"\"\"Calculate the factorial of a given number i.\"\"\"\n if i == 0 or i == 1:\n return 1\n result = 1\n for j in range(2, i + 1):\n result *= j\n return result\ndef sum_of_numbers(i):\n \"\"\"Calculate the sum of numbers from 1 to i.\"\"\"\n return (i * (i + 1)) // 2\ndef f(n):\n \"\"\"Return a list of size n, where the value at index i is the factorial of i if i is even,\n or the sum of numbers from 1 to i if i is odd. Indexing starts from 1.\n \"\"\"\n result = []\n for i in range(1, n + 1):\n if i % 2 == 0: # i is even\n result.append(factorial(i))\n else: # i is odd\n result.append(sum_of_numbers(i))\n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n \"\"\"\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n \"\"\"\n # Split the string by commas and spaces, then filter out any empty strings\n words = [word.strip() for word in s.replace(',', ' ').split() if word]\n return words", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" \n You're given a list of deposit and withdrawal operations on a bank account that starts with\n zero balance. Your task is to detect if at any point the balance of account falls below zero, and\n at that point function should return True. Otherwise it should return False.\n \n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n \"\"\"\n balance = 0\n for operation in operations:\n balance += operation\n if balance < 0:\n return True\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string.\n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n >>> string_to_md5('') is None\n >>> string_to_md5('Python') == '5d41402abc4b2a76b9719d911017c592'\n \"\"\"\n if text == \"\":\n return None\n md5_hash = hashlib.md5(text.encode()).hexdigest()\n return md5_hash", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n \"\"\"Find the strongest extension based on the defined strength criteria.\"\"\"\n strongest_extension = None\n max_strength = float('-inf') # Start with the lowest possible strength\n\n for extension in extensions:\n # Calculate the strength of the current extension\n CAP = sum(1 for char in extension if char.isupper())\n SM = sum(1 for char in extension if char.islower())\n strength = CAP - SM\n\n # Check if this extension is stronger than the current strongest\n if strength > max_strength:\n max_strength = strength\n strongest_extension = extension\n\n # Return the result in the specified format\n return f\"{class_name}.{strongest_extension}\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n \"\"\"Check if the second word or any of its rotations is a substring in the first word.\n \n Args:\n a (str): The first word.\n b (str): The second word.\n \n Returns:\n bool: True if the second word or any of its rotations is a substring of the first word, False otherwise.\n \n Examples:\n >>> cycpattern_check(\"abcd\", \"abd\")\n False\n >>> cycpattern_check(\"hello\", \"ell\")\n True\n >>> cycpattern_check(\"whassup\", \"psus\")\n False\n >>> cycpattern_check(\"abab\", \"baa\")\n True\n >>> cycpattern_check(\"efef\", \"eeff\")\n False\n >>> cycpattern_check(\"himenss\", \"simen\")\n True\n \"\"\"\n # Create a string that contains all rotations of b\n rotations = [b[i:] + b[:i] for i in range(len(b))]\n \n # Check if any rotation is a substring of a\n for rotation in rotations:\n if rotation in a:\n return True\n \n return False", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["", ""]]}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n \"\"\"\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n >>> make_a_pile(4)\n [4, 6, 8, 10]\n >>> make_a_pile(1)\n [1]\n \"\"\"\n stones = []\n current_stones = n\n \n for i in range(n):\n stones.append(current_stones)\n if current_stones % 2 == 0: # current_stones is even\n current_stones += 2 # next even number\n else: # current_stones is odd\n current_stones += 2 # next odd number\n \n return stones", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into\n an integer part (largest integer smaller than given number) and decimals\n (leftover part always smaller than 1).\n\n Return the decimal part of the number.\n \n >>> truncate_number(3.5)\n 0.5\n >>> truncate_number(7.25)\n 0.25\n >>> truncate_number(10.0)\n 0.0\n >>> truncate_number(5.99)\n 0.99\n \"\"\"\n if number < 0:\n raise ValueError(\"The number must be positive.\")\n \n integer_part = int(number) # Get the integer part\n decimal_part = number - integer_part # Calculate the decimal part\n return decimal_part", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n \"\"\"Calculate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n if n < 0:\n return []\n\n # Initialize the list to store the Tribonacci numbers\n tribonacci_sequence = []\n\n # Define the base cases\n for i in range(n + 1):\n if i == 0:\n tribonacci_sequence.append(1) # tri(0) = 1\n elif i == 1:\n tribonacci_sequence.append(3) # tri(1) = 3\n elif i % 2 == 0: # Even case\n tribonacci_sequence.append(1 + i / 2)\n else: # Odd case\n tri_n_minus_1 = tribonacci_sequence[i - 1]\n tri_n_minus_2 = tribonacci_sequence[i - 2]\n tri_n_plus_1 = tribonacci_sequence[i + 1] if i + 1 <= n else 0\n tribonacci_sequence.append(tri_n_minus_1 + tri_n_minus_2 + tri_n_plus_1)\n\n return tribonacci_sequence", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[3]], "plus_fail_tests": [[10]]}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n \"\"\"\n Given a positive integer n, return a tuple that has the number of even and odd\n integer palindromes that fall within the range(1, n), inclusive.\n\n Example 1:\n Input: 3\n Output: (1, 2)\n Explanation:\n Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n Example 2:\n Input: 12\n Output: (4, 6)\n Explanation:\n Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n Note:\n 1. 1 <= n <= 10^3\n 2. returned tuple has the number of even and odd integer palindromes respectively.\n \"\"\"\n even_count = 0\n odd_count = 0\n\n for i in range(1, n + 1):\n if str(i) == str(i)[::-1]: # Check if the number is a palindrome\n if i % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n return (even_count, odd_count)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n \n Args:\n n (int): The number to evaluate.\n \n Returns:\n bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n \n Example:\n is_equal_to_sum_even(4) == False\n is_equal_to_sum_even(6) == False\n is_equal_to_sum_even(8) == True\n \"\"\"\n # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n if n < 8:\n return False\n \n # Check if n is even\n if n % 2 != 0:\n return False\n \n # If n is even and >= 8, it can be expressed as the sum of 4 positive even numbers\n return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n \"\"\" Insert a number 'delimiter' between every two consecutive elements of input list `numbers`\n \n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n for i in range(len(numbers) - 1):\n result.append(numbers[i])\n result.append(delimiter)\n result.append(numbers[-1]) # Append the last element\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n \"\"\"Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n For example:\n digits(1) == 1\n digits(4) == 0\n digits(235) == 15\n \"\"\"\n product = 1\n has_odd = False\n \n for digit in str(n):\n digit = int(digit)\n if digit % 2 != 0: # Check if the digit is odd\n product *= digit\n has_odd = True\n \n return product if has_odd else 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n '''\n Create a function that returns a tuple (a, b), where 'a' is\n the largest of negative integers, and 'b' is the smallest\n of positive integers in a list.\n If there is no negative or positive integers, return them as None.\n\n Examples:\n largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n largest_smallest_integers([]) == (None, None)\n largest_smallest_integers([0]) == (None, None)\n '''\n largest_negative = None\n smallest_positive = None\n\n for num in lst:\n if num < 0:\n if largest_negative is None or num > largest_negative:\n largest_negative = num\n elif num > 0:\n if smallest_positive is None or num < smallest_positive:\n smallest_positive = num\n\n return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return True else return False.\n If the given array is empty then return True.\n\n Note: The given list is guaranteed to have unique elements.\n\n For Example:\n \n move_one_ball([3, 4, 5, 1, 2])==>True\n Explanation: By performing 2 right shift operations, non-decreasing order can\n be achieved for the given array.\n move_one_ball([3, 5, 4, 1, 2])==>False\n Explanation: It is not possible to get non-decreasing order for the given\n array by performing any number of right shift operations.\n \"\"\"\n if not arr:\n return True\n\n n = len(arr)\n sorted_arr = sorted(arr)\n \n # Check for the number of \"breaks\" in the sorted array\n break_count = 0\n for i in range(n):\n if arr[i] > arr[(i + 1) % n]:\n break_count += 1\n\n # If there are more than one break, we cannot sort the array with shifts\n return break_count <= 1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to make it easier to find the closest pair\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest elements\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n \n >>> flip_case('Hello')\n 'hELLO'\n >>> flip_case('Python')\n 'pYTHON'\n >>> flip_case('123abcXYZ')\n '123ABCxyz'\n >>> flip_case('')\n ''\n \"\"\"\n return string.swapcase()", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n \n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n \"\"\"\n count = 0\n start = 0\n \n while True:\n start = string.find(substring, start)\n if start == -1:\n break\n count += 1\n start += 1 # Move to the next character to allow for overlapping matches\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n \"\"\" Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n \n >>> string_xor('010', '110')\n '100'\n >>> string_xor('111', '000')\n '111'\n >>> string_xor('101', '101')\n '000'\n >>> string_xor('000', '000')\n '000'\n >>> string_xor('1101', '1011')\n '0110'\n \"\"\"\n # Ensure both strings are of the same length\n max_len = max(len(a), len(b))\n a = a.zfill(max_len)\n b = b.zfill(max_len)\n \n # Perform XOR operation\n result = []\n for bit_a, bit_b in zip(a, b):\n result.append('1' if bit_a != bit_b else '0')\n \n return ''.join(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lower_string = string.lower()\n # Use a set to find distinct characters\n distinct_characters = set(lower_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n \n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n \"\"\"\n return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted = []\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Calculate the new character by shifting it down by 4 places\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a')) if char.islower() else \\\n chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n encrypted.append(new_char)\n else:\n encrypted.append(char) # Non-alphabetic characters remain unchanged\n return ''.join(encrypted)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n \n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n \"\"\"\n return [x + 1 for x in l]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n \"\"\"Given length of a side and height, return the area of a triangle.\n \n The area of a triangle can be calculated using the formula:\n area = (base * height) / 2\n \n Parameters:\n a (float): The length of the base of the triangle.\n h (float): The height of the triangle.\n \n Returns:\n float: The area of the triangle.\n \n >>> triangle_area(5, 3)\n 7.5\n >>> triangle_area(10, 2)\n 10.0\n >>> triangle_area(0, 5)\n 0.0\n >>> triangle_area(5, 0)\n 0.0\n \"\"\"\n return (a * h) / 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n \n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by row index (ascending) and then by column index (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n \"\"\"\n Given an array arr of integers, find the minimum number of elements that\n need to be changed to make the array palindromic. A palindromic array is an array that\n is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n For example:\n smallest_change([1,2,3,5,4,7,9,6]) == 4\n smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n smallest_change([1, 2, 3, 2, 1]) == 0\n \"\"\"\n n = len(arr)\n changes = 0\n \n # Compare elements from the start and end towards the center\n for i in range(n // 2):\n if arr[i] != arr[n - 1 - i]:\n changes += 1\n \n return changes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n else:\n return lst2", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": [[["happy", "birthday", "sarah"], ["happy", "birthday", "sally"]]]}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n \"\"\"You are given a string s.\n Your task is to check if the string is happy or not.\n A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n \n For example:\n is_happy('a') => False\n is_happy('aa') => False\n is_happy('abcd') => True\n is_happy('aabb') => False\n is_happy('adb') => True\n is_happy('xyy') => False\n \"\"\"\n # Check if the length of the string is at least 3\n if len(s) < 3:\n return False\n \n # Check every 3 consecutive characters\n for i in range(len(s) - 2):\n if len(set(s[i:i+3])) < 3: # If there are not 3 distinct characters\n return False\n \n return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" Input to this function is a string representing musical notes in a special ASCII format.\n Your task is to parse this string and return list of integers corresponding to how many beats does each\n note last.\n\n Here is a legend:\n 'o' - whole note, lasts four beats\n 'o|' - half note, lasts two beats\n '.|' - quarter note, lasts one beat\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n # Define a mapping of note representations to their corresponding beat values\n note_to_beats = {\n 'o': 4, # whole note\n 'o|': 2, # half note\n '.|': 1 # quarter note\n }\n \n # Split the input string into individual notes\n notes = music_string.split()\n \n # Parse the notes and convert them to their corresponding beat values\n beats = [note_to_beats[note] for note in notes if note in note_to_beats]\n \n return beats", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string.\n \n Args:\n strings (List[str]): A list of strings to concatenate.\n \n Returns:\n str: A single concatenated string.\n \n Examples:\n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n \"\"\"\n return ''.join(strings)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n \n >>> make_palindrome('')\n ''\n >>> make_palindrome('cat')\n 'catac'\n >>> make_palindrome('cata')\n 'catac'\n \"\"\"\n # Find the longest palindromic suffix\n for i in range(len(string)):\n if is_palindrome(string[i:]):\n # If the suffix is a palindrome, take the prefix before it\n prefix = string[:i]\n # Append the reverse of the prefix to the original string\n return string + prefix[::-1]\n return string # In case the string is empty or already a palindrome", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n \"\"\" \n Input is a space-delimited string of numerals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest.\n \n >>> sort_numbers('three one five')\n 'one three five'\n \"\"\"\n # Mapping of words to their corresponding numeric values\n num_map = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n \n # Split the input string into words\n words = numbers.split()\n \n # Sort the words based on their numeric values\n sorted_words = sorted(words, key=lambda word: num_map[word])\n \n # Join the sorted words back into a string\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n \n # Create a new list with elements that occur only once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1.\n \n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n min_val = min(numbers)\n max_val = max(numbers)\n \n # Avoid division by zero if all numbers are the same\n if min_val == max_val:\n return [0.0] * len(numbers)\n \n return [(num - min_val) / (max_val - min_val) for num in numbers]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef get_primes_up_to(limit):\n \"\"\"Return a list of all prime numbers up to a given limit.\"\"\"\n return [num for num in range(2, limit) if is_prime(num)]\ndef is_multiply_prime(a):\n \"\"\"Return true if the given number is the multiplication of 3 prime numbers, false otherwise.\"\"\"\n if a >= 100:\n return False\n \n primes = get_primes_up_to(a)\n prime_count = len(primes)\n \n # Check all combinations of three primes\n for i in range(prime_count):\n for j in range(i, prime_count):\n for k in range(j, prime_count):\n product = primes[i] * primes[j] * primes[k]\n if product == a:\n return True\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n letter_grades = []\n \n for gpa in grades:\n if gpa == 4.0:\n letter_grades.append('A+')\n elif gpa > 3.7:\n letter_grades.append('A')\n elif gpa > 3.3:\n letter_grades.append('A-')\n elif gpa > 3.0:\n letter_grades.append('B+')\n elif gpa > 2.7:\n letter_grades.append('B')\n elif gpa > 2.3:\n letter_grades.append('B-')\n elif gpa > 2.0:\n letter_grades.append('C+')\n elif gpa > 1.7:\n letter_grades.append('C')\n elif gpa > 1.3:\n letter_grades.append('C-')\n elif gpa > 1.0:\n letter_grades.append('D+')\n elif gpa > 0.7:\n letter_grades.append('D')\n elif gpa > 0.0:\n letter_grades.append('D-')\n else:\n letter_grades.append('E')\n \n return letter_grades", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n '''\n Write a function that returns True if the object q will fly, and False otherwise.\n The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n\n Example:\n will_it_fly([1, 2], 5) \u279e False \n # 1+2 is less than the maximum possible weight, but it's unbalanced.\n\n will_it_fly([3, 2, 3], 1) \u279e False\n # it's balanced, but 3+2+3 is more than the maximum possible weight.\n\n will_it_fly([3, 2, 3], 9) \u279e True\n # 3+2+3 is less than the maximum possible weight, and it's balanced.\n\n will_it_fly([3], 5) \u279e True\n # 3 is less than the maximum possible weight, and it's balanced.\n '''\n # Check if the list is a palindrome\n is_balanced = q == q[::-1]\n \n # Calculate the sum of the elements in the list\n total_weight = sum(q)\n \n # Check if the object will fly\n return is_balanced and total_weight <= w", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion.\n base numbers are less than 10.\n \n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n \"\"\"\n if base < 2 or base >= 10:\n raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n \n if x == 0:\n return '0'\n \n result = []\n while x > 0:\n result.append(str(x % base))\n x //= base\n \n return ''.join(reversed(result))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words while preserving spaces\n words = s.split(' ')\n \n # Sort each word and keep the spaces intact\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back with spaces\n result = ' '.join(sorted_words)\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n or sort it in descending order if the sum( first index value, last index value) is even.\n\n Note:\n * don't change the given array.\n\n Examples:\n * sort_array([]) => []\n * sort_array([5]) => [5]\n * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n \"\"\"\n if not array: # Check for empty array\n return []\n \n first_value = array[0]\n last_value = array[-1]\n sum_values = first_value + last_value\n\n # Create a copy of the array to sort\n sorted_array = array.copy()\n\n if sum_values % 2 == 0: # Even sum\n sorted_array.sort(reverse=True) # Sort in descending order\n else: # Odd sum\n sorted_array.sort() # Sort in ascending order\n\n return sorted_array", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n \n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n \"\"\"\n seen = set()\n for number in l:\n if -number in seen:\n return True\n seen.add(number)\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in lower \n case or all keys are strings in upper case, else return False.\n The function should return False if the given dictionary is empty.\n \n Examples:\n check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n \"\"\"\n if not input_dict:\n return False\n\n all_lower = all(isinstance(key, str) and key.islower() for key in input_dict.keys())\n all_upper = all(isinstance(key, str) and key.isupper() for key in input_dict.keys())\n\n return all_lower or all_upper", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"(\" and \")\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"(\")\n False\n >>> correct_bracketing(\"()\")\n True\n >>> correct_bracketing(\"(()())\")\n True\n >>> correct_bracketing(\")(()\")\n False\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n # If balance goes negative, there are unmatched closing brackets\n if balance < 0:\n return False\n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n \"\"\"Task\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n \"\"\"\n return sum(ord(char) for char in s if char.isupper())", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n '''\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n \n Examples\n any_int(5, 2, 7) \u279e True\n \n any_int(3, 2, 2) \u279e False\n\n any_int(3, -2, 1) \u279e True\n \n any_int(3.6, -2.2, 2) \u279e False\n '''\n # Check if all inputs are integers\n if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n # Check if one number is equal to the sum of the other two\n return x == y + z or y == x + z or z == x + y\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n # Keep dividing n by factor until it is no longer divisible\n while n > 1:\n if n % factor == 0:\n n //= factor # Divide n by the factor\n else:\n factor += 1 # Move to the next potential factor\n return factor # The last factor is the largest prime factor", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n \"\"\"Return True if list elements are monotonically increasing or decreasing.\n \n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n \"\"\"\n if not l: # An empty list is considered monotonic\n return True\n \n increasing = decreasing = True\n \n for i in range(1, len(l)):\n if l[i] > l[i - 1]:\n decreasing = False\n elif l[i] < l[i - 1]:\n increasing = False\n \n return increasing or decreasing", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n \"\"\"\n Takes as input string encoded with encode_shift function. Returns decoded string.\n \"\"\"\n return \"\".join([chr(((ord(ch) - ord(\"a\") - 5) % 26) + ord(\"a\")) for ch in s])", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n \"\"\"\n Given an array representing a branch of a tree that has non-negative integer nodes,\n your task is to pluck one of the nodes and return it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n The plucked node should be returned in a list, [ smallest_value, its index ],\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index. \n\n Example 3:\n Input: []\n Output: []\n \n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n Explanation: 0 is the smallest value, but there are two zeros,\n so we will choose the first zero, which has the smallest index.\n\n Constraints:\n * 1 <= nodes.length <= 10000\n * 0 <= node.value\n \"\"\"\n smallest_even = float('inf')\n smallest_index = -1\n\n for index, value in enumerate(arr):\n if value % 2 == 0: # Check if the value is even\n if value < smallest_even: # Check if it's the smallest even found\n smallest_even = value\n smallest_index = index\n\n if smallest_index == -1: # No even value found\n return []\n \n return [smallest_even, smallest_index]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float) -> float:\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list) -> list:\n \"\"\"\n Computes the derivative of the polynomial with coefficients xs.\n \"\"\"\n return [i * coeff for i, coeff in enumerate(xs) if i > 0]\ndef find_zero(xs: list, initial_guess: float = 0.0, tolerance: float = 1e-7, max_iterations: int = 1000) -> float:\n \"\"\" \n xs are coefficients of a polynomial.\n find_zero finds x such that poly(x) = 0.\n find_zero returns only one zero point, even if there are many.\n Moreover, find_zero only takes list xs having an even number of coefficients\n and the largest non-zero coefficient as it guarantees a solution.\n \n >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n -0.5\n >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n 1.0\n \"\"\"\n if len(xs) % 2 != 0:\n raise ValueError(\"The number of coefficients must be even.\")\n \n current_guess = initial_guess\n for _ in range(max_iterations):\n f_value = poly(xs, current_guess)\n f_derivative = poly(derivative(xs), current_guess)\n \n if f_derivative == 0:\n raise ValueError(\"Derivative is zero. No solution found.\")\n \n next_guess = current_guess - f_value / f_derivative\n \n if abs(next_guess - current_guess) < tolerance:\n return next_guess\n \n current_guess = next_guess\n \n raise ValueError(\"Maximum iterations reached. No solution found.\")", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[[5, 10, -3, 1]]]}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" brackets is a string of \"<\" and \">\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"<\")\n False\n >>> correct_bracketing(\"<>\")\n True\n >>> correct_bracketing(\"<<><>>\")\n True\n >>> correct_bracketing(\"><<>\")\n False\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '<':\n balance += 1\n elif char == '>':\n balance -= 1\n # If balance goes negative, there are more closing brackets\n if balance < 0:\n return False\n # At the end, balance should be zero for correct bracketing\n return balance == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n \"\"\"Return maximum element in the list.\n \n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty.\")\n \n max_value = l[0]\n for item in l:\n if item > max_value:\n max_value = item\n return max_value", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n \"\"\"\n Write a function that takes a message, and encodes in such a \n way that it swaps case of all letters, replaces all vowels in \n the message with the letter that appears 2 places ahead of that \n vowel in the english alphabet. \n Assume only letters. \n \n Examples:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n vowels = 'aeiouAEIOU'\n encoded_message = []\n\n for char in message:\n if char.isalpha(): # Check if the character is a letter\n # Swap case\n if char in vowels:\n # Replace vowel with the letter 2 places ahead\n if char.islower():\n new_char = chr((ord(char) - ord('a') + 2) % 26 + ord('a'))\n else:\n new_char = chr((ord(char) - ord('A') + 2) % 26 + ord('A'))\n else:\n new_char = char.swapcase() # Swap case for consonants\n encoded_message.append(new_char)\n else:\n encoded_message.append(char) # Keep non-letter characters unchanged\n\n return ''.join(encoded_message)", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["TEST"]], "plus_fail_tests": [["abcdefghijklmnopqrstuvwxyz"]]}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n '''\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequency greater than or equal to the value of the integer itself. \n The frequency of an integer is the number of times it appears in the list.\n If no such a value exist, return -1.\n \n Examples:\n search([4, 1, 2, 2, 3, 1]) == 2\n search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n search([5, 5, 4, 4, 4]) == -1\n '''\n from collections import Counter\n \n # Count the frequency of each number in the list\n frequency = Counter(lst)\n \n # Initialize the result variable\n result = -1\n \n # Iterate through the frequency dictionary\n for num, freq in frequency.items():\n # Check if the frequency is greater than or equal to the number itself\n if freq >= num:\n # Update the result if this number is greater than the current result\n result = max(result, num)\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n \n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n \"\"\"\n return n * (n + 1) // 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n \"\"\"\n In this task, you will be given a string that represents a number of apples and oranges \n that are distributed in a basket of fruit. This basket contains \n apples, oranges, and mango fruits. Given the string that represents the total number of \n the oranges and apples and an integer that represents the total number of the fruits \n in the basket, return the number of the mango fruits in the basket.\n \n Parameters:\n s (str): A string representing the number of apples and oranges.\n n (int): An integer representing the total number of fruits in the basket.\n \n Returns:\n int: The number of mango fruits in the basket.\n \n Examples:\n fruit_distribution(\"5 apples and 6 oranges\", 19) -> 8\n fruit_distribution(\"0 apples and 1 oranges\", 3) -> 2\n fruit_distribution(\"2 apples and 3 oranges\", 100) -> 95\n fruit_distribution(\"100 apples and 1 oranges\", 120) -> 19\n \"\"\"\n \n # Extract the number of apples and oranges from the string\n parts = s.split()\n apples = int(parts[0]) # First part is the number of apples\n oranges = int(parts[3]) # Fourth part is the number of oranges\n \n # Calculate the number of mangoes\n mangoes = n - apples - oranges\n \n return mangoes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(divisible_by_three)\n \n # Create a new list to hold the result\n result = l.copy()\n \n # Replace values at indices divisible by 3 with sorted values\n for index, value in zip((i for i in range(len(l)) if i % 3 == 0), sorted_values):\n result[index] = value\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n Example\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n \"\"\"\n # Initialize variables to track the minimum sum and the current sum\n min_sum = float('inf')\n current_sum = 0\n \n for num in nums:\n current_sum += num\n min_sum = min(min_sum, current_sum)\n \n # If current_sum is positive, reset it to 0\n if current_sum > 0:\n current_sum = 0\n \n return min_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n '''\n Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n \n Examples:\n split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"abcdef\") \u279e 3 \n '''\n # Check for whitespace in the text\n if ' ' in txt:\n return txt.split()\n \n # Check for commas in the text\n elif ',' in txt:\n return txt.split(',')\n \n # If no whitespace or commas, count lower-case letters with odd order\n else:\n odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n return odd_count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n \"\"\"\n Given a non-empty array of integers arr and an integer k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example:\n\n Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n Output: 24 # sum of 21 + 3\n\n Constraints:\n 1. 1 <= len(arr) <= 100\n 2. 1 <= k <= len(arr)\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate through the first k elements of the array\n for i in range(k):\n # Check if the current element has at most two digits\n if -100 < arr[i] < 100:\n total_sum += arr[i]\n \n return total_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length and alphabetically.\n \n Args:\n lst (list of str): A list of strings.\n \n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n \"\"\"\n Given a string text, replace all spaces in it with underscores, \n and if a string has more than 2 consecutive spaces, \n then replace all consecutive spaces with - \n \n fix_spaces(\"Example\") == \"Example\"\n fix_spaces(\"Example 1\") == \"Example_1\"\n fix_spaces(\" Example 2\") == \"_Example_2\"\n fix_spaces(\" Example 3\") == \"_Example-3\"\n \"\"\"\n import re\n\n # Replace more than 2 consecutive spaces with a single '-'\n text = re.sub(r' {3,}', '-', text)\n \n # Replace single spaces with underscores\n text = text.replace(' ', '_')\n \n return text", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n as follows: start with any positive integer n. Then each term is obtained from the \n previous term as follows: if the previous term is even, the next term is one half of \n the previous term. If the previous term is odd, the next term is 3 times the previous\n term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n Note: \n 1. Collatz(1) is [1].\n 2. returned list sorted in increasing order.\n\n For example:\n get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n collatz_sequence = []\n current = n\n \n while current != 1:\n collatz_sequence.append(current)\n if current % 2 == 0:\n current //= 2\n else:\n current = 3 * current + 1\n \n collatz_sequence.append(1) # Add the last term which is 1\n \n # Filter odd numbers and sort them\n odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n \n return odd_numbers", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n \n The date is valid if all of the following rules are satisfied:\n 1. The date string is not empty.\n 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n The number of days is not less than 1 or higher than 29 for the month 2.\n 3. The months should not be less than 1 or higher than 12.\n 4. The date should be in the format: mm-dd-yyyy\n \n Args:\n date (str): The date string to validate.\n \n Returns:\n bool: True if the date is valid, False otherwise.\n \"\"\"\n if not date:\n return False\n \n # Check the format\n parts = date.split('-')\n if len(parts) != 3:\n return False\n \n if not all(part.isdigit() for part in parts):\n return False\n \n month, day, year = map(int, parts)\n \n # Validate month\n if month < 1 or month > 12:\n return False\n \n # Validate day based on month\n if month in {1, 3, 5, 7, 8, 10, 12}:\n if day < 1 or day > 31:\n return False\n elif month in {4, 6, 9, 11}:\n if day < 1 or day > 30:\n return False\n elif month == 2:\n if day < 1 or day > 29:\n return False\n \n return True", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["06-04-202"]]}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n \"\"\"Task\n We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and True/False for the check.\n Example\n For s = \"abcde\", c = \"ae\", the result should be ('bcd',False)\n For s = \"abcdef\", c = \"b\", the result should be ('acdef',False)\n For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc',True)\n \"\"\"\n # Create a set of characters to delete for faster lookup\n delete_set = set(c)\n \n # Create the result string by filtering out characters in delete_set\n result = ''.join(char for char in s if char not in delete_set)\n \n # Check if the result string is a palindrome\n is_palindrome = result == result[::-1]\n \n return (result, is_palindrome)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n \"\"\"\n Calculate the number of times buckets need to be lowered to empty the wells.\n\n Parameters:\n grid (list of list of int): A rectangular grid representing wells.\n capacity (int): The capacity of each bucket.\n\n Returns:\n int: The total number of times buckets need to be lowered.\n \"\"\"\n total_water = 0\n \n # Count the total amount of water in the grid\n for row in grid:\n total_water += sum(row)\n \n # Calculate the number of times buckets need to be lowered\n # Each bucket can carry 'capacity' units of water\n if total_water == 0:\n return 0\n else:\n return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": [[[[1, 0, 0, 1], [0, 1, 1, 1], [0, 0, 0, 0], [1, 0, 1, 1]], 2]]}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n \"\"\"Create a function which takes a string representing a file's name, and returns\n 'Yes' if the the file's name is valid, and returns 'No' otherwise.\n A file's name is considered to be valid if and only if all the following conditions \n are met:\n - There should not be more than three digits ('0'-'9') in the file's name.\n - The file's name contains exactly one dot '.'\n - The substring before the dot should not be empty, and it starts with a letter from \n the latin alphapet ('a'-'z' and 'A'-'Z').\n - The substring after the dot should be one of these: ['txt', 'exe', 'dll']\n Examples:\n file_name_check(\"example.txt\") # => 'Yes'\n file_name_check(\"1example.dll\") # => 'No' (the name should start with a latin alphapet letter)\n \"\"\"\n \n # Split the file name into name and extension\n if file_name.count('.') != 1:\n return 'No'\n \n name, extension = file_name.split('.')\n \n # Check if the name is empty or starts with a non-letter\n if not name or not name[0].isalpha():\n return 'No'\n \n # Check the extension\n valid_extensions = ['txt', 'exe', 'dll']\n if extension not in valid_extensions:\n return 'No'\n \n # Count the digits in the file name\n digit_count = sum(c.isdigit() for c in file_name)\n if digit_count > 3:\n return 'No'\n \n return 'Yes'", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n \"\"\"Write a function that takes an array of numbers as input and returns \n the number of elements in the array that are greater than 10 and both \n first and last digits of a number are odd (1, 3, 5, 7, 9).\n \n For example:\n specialFilter([15, -73, 14, -15]) => 1 \n specialFilter([33, -2, -3, 45, 21, 109]) => 2\n \"\"\"\n \n def is_odd_digit(digit):\n return digit in {'1', '3', '5', '7', '9'}\n \n def first_and_last_odd(num):\n str_num = str(abs(num)) # Convert to string and take absolute value\n return is_odd_digit(str_num[0]) and is_odd_digit(str_num[-1])\n \n count = 0\n for num in nums:\n if num > 10 and first_and_last_odd(num):\n count += 1\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closest to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sorted by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct planet names. \n Examples\n bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n '''\n \n planets = [\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n ]\n \n if planet1 not in planets or planet2 not in planets:\n return ()\n \n index1 = planets.index(planet1)\n index2 = planets.index(planet2)\n \n # Ensure index1 is less than index2 for slicing\n start_index = min(index1, index2) + 1\n end_index = max(index1, index2)\n \n return tuple(planets[start_index:end_index])", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers.\n You need to return the sum of squared numbers in the given list,\n round each element in the list to the upper int (Ceiling) first.\n \n Examples:\n For lst = [1,2,3] the output should be 14\n For lst = [1,4,9] the output should be 98\n For lst = [1,3,5,7] the output should be 84\n For lst = [1.4,4.2,0] the output should be 29\n For lst = [-2.4,1,1] the output should be 6\n \"\"\"\n return sum(math.ceil(x) ** 2 for x in lst)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n '''\n Create a function that returns True if the last character\n of a given string is an alphabetical character and is not\n a part of a word, and False otherwise.\n Note: \"word\" is a group of characters separated by space.\n\n Examples:\n check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '''\n # Strip any trailing whitespace from the string\n txt = txt.rstrip()\n \n # Check if the string is empty after stripping\n if not txt:\n return False\n \n # Get the last character of the string\n last_char = txt[-1]\n \n # Check if the last character is a letter\n if last_char.isalpha():\n # Check if the last character is part of a word\n # A character is part of a word if it is preceded by a non-space character\n if len(txt) > 1 and txt[-2] != ' ':\n return False\n return True\n \n return False", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["eeeee e "]], "plus_fail_tests": [["k "]]}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef sum_of_digits(n):\n \"\"\"Return the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n largest_prime = -1\n \n for number in lst:\n if is_prime(number) and number > largest_prime:\n largest_prime = number\n \n if largest_prime == -1:\n return 0 # Return 0 if no prime number is found\n \n return sum_of_digits(largest_prime)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n \"\"\"\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,\n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example:\n Input: n = 5\n Output: 1\n Explanation:\n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n \"\"\"\n # Create the array a\n a = [i * i - i + 1 for i in range(1, n + 1)]\n \n # Count the number of valid triples\n count = 0\n \n # Check all combinations of triples (i, j, k) with i < j < k\n for i in range(n):\n for j in range(i + 1, n):\n for k in range(j + 1, n):\n if (a[i] + a[j] + a[k]) % 3 == 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n \"\"\"This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If \n there's no such number, then the function should return -1.\n\n For example:\n choose_num(12, 15) = 14\n choose_num(13, 12) = -1\n \"\"\"\n # Ensure x is less than or equal to y\n if x > y:\n return -1\n \n # Start from the largest number in the range and check for evenness\n for num in range(y, x - 1, -1):\n if num % 2 == 0:\n return num\n \n return -1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to make it easier to find close elements\n numbers.sort()\n \n # Check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n reverse the resulting array, and then replace each digit by its corresponding name from\n \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n For example:\n arr = [2, 1, 1, 4, 5, 8, 2, 3] \n -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n \n If the array is empty, return an empty array:\n arr = []\n return []\n \n If the array has any strange number ignore it:\n arr = [1, -1 , 55] \n -> sort arr -> [-1, 1, 55]\n -> reverse arr -> [55, 1, -1]\n return = ['One']\n \"\"\"\n \n # Mapping of digits to their corresponding names\n digit_to_name = {\n 1: \"One\", 2: \"Two\", 3: \"Three\", 4: \"Four\",\n 5: \"Five\", 6: \"Six\", 7: \"Seven\", 8: \"Eight\", 9: \"Nine\"\n }\n \n # Filter the array to include only numbers between 1 and 9\n filtered_arr = [num for num in arr if 1 <= num <= 9]\n \n # Sort the filtered array\n filtered_arr.sort()\n \n # Reverse the sorted array\n filtered_arr.reverse()\n \n # Convert the numbers to their corresponding names\n result = [digit_to_name[num] for num in filtered_arr]\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n \"\"\"\n return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n \"\"\"Calculate the factorial of n (n!).\"\"\"\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef special_factorial(n):\n \"\"\"The Brazilian factorial is defined as:\n brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!\n where n > 0\n\n For example:\n >>> special_factorial(4)\n 288\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n result = 1\n for i in range(1, n + 1):\n result *= factorial(i)\n \n return result", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[491]]}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n \n double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n double_the_difference([-1, -2, 0]) == 0\n double_the_difference([9, -2]) == 81\n double_the_difference([0]) == 0 \n \n If the input list is empty, return 0.\n '''\n if not lst: # Check if the list is empty\n return 0\n \n return sum(x**2 for x in lst if isinstance(x, int) and x >= 0 and x % 2 != 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n if not (1 <= number <= 1000):\n raise ValueError(\"Number must be between 1 and 1000\")\n\n roman_numerals = [\n (1000, 'm'),\n (900, 'cm'),\n (500, 'd'),\n (400, 'cd'),\n (100, 'c'),\n (90, 'xc'),\n (50, 'l'),\n (40, 'xl'),\n (10, 'x'),\n (9, 'ix'),\n (5, 'v'),\n (4, 'iv'),\n (1, 'i')\n ]\n\n result = []\n for value, numeral in roman_numerals:\n while number >= value:\n result.append(numeral)\n number -= value\n\n return ''.join(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic algebra operations, and \n the second list is a list of integers. Use the two given lists to build the algebraic \n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + ) \n Subtraction ( - ) \n Multiplication ( * ) \n Floor division ( // ) \n Exponentiation ( ** ) \n\n Example:\n operator = ['+', '*', '-']\n operand = [2, 3, 4, 5]\n result = 2 + 3 * 4 - 5\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.\n \"\"\"\n # Start with the first operand\n result = operand[0]\n \n # Iterate through the operators and operands\n for i in range(len(operator)):\n op = operator[i]\n next_operand = operand[i + 1]\n \n if op == '+':\n result += next_operand\n elif op == '-':\n result -= next_operand\n elif op == '*':\n result *= next_operand\n elif op == '//':\n result //= next_operand\n elif op == '**':\n result **= next_operand\n else:\n raise ValueError(f\"Unsupported operator: {op}\")\n \n return result", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": [[["+", "-", "*", "//"], [5, 2, 3, 4, 7]]]}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n \"\"\"Write a function that accepts a list of strings.\n The list contains different words. Return the word with maximum number\n of unique characters. If multiple strings have maximum number of unique\n characters, return the one which comes first in lexicographical order.\n\n find_max([\"name\", \"of\", \"string\"]) == \"string\"\n find_max([\"name\", \"enam\", \"game\"]) == \"enam\"\n find_max([\"aaaaaaa\", \"bb\" ,\"cc\"]) == \"aaaaaaa\"\n \"\"\"\n max_word = \"\"\n max_unique_count = 0\n\n for word in words:\n unique_chars = set(word)\n unique_count = len(unique_chars)\n\n if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n max_word = word\n max_unique_count = unique_count\n\n return max_word", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n def max_nesting_depth(s: str) -> int:\n max_depth = 0\n current_depth = 0\n for char in s:\n if char == '(':\n current_depth += 1\n max_depth = max(max_depth, current_depth)\n elif char == ')':\n current_depth -= 1\n return max_depth\n\n groups = paren_string.split()\n return [max_nesting_depth(group) for group in groups]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n \"\"\"Given a list of positive integers x, return a sorted list of all \n elements that haven't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n def has_even_digit(n):\n \"\"\"Check if the number has any even digit.\"\"\"\n return any(int(digit) % 2 == 0 for digit in str(n))\n\n # Filter the list to include only numbers without even digits\n result = [num for num in x if not has_even_digit(num)]\n \n # Return the sorted result\n return sorted(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" \n Input to this function is a string containing multiple groups of nested parentheses. \n Your goal is to separate those groups into separate strings and return the list of those.\n Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n Ignore any spaces in the input string.\n \n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n # Remove spaces from the input string\n paren_string = paren_string.replace(\" \", \"\")\n \n result = []\n balance = 0\n current_group = []\n \n for char in paren_string:\n if char == '(':\n if balance == 0 and current_group:\n result.append(''.join(current_group))\n current_group = []\n current_group.append(char)\n balance += 1\n elif char == ')':\n current_group.append(char)\n balance -= 1\n if balance == 0:\n result.append(''.join(current_group))\n current_group = []\n \n # In case there are any remaining groups (should not happen with valid input)\n if current_group:\n result.append(''.join(current_group))\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n \"\"\"Create a function which returns the largest index of an element which\n is not greater than or equal to the element immediately preceding it. If\n no such element exists then return -1. The given array will not contain\n duplicate values.\n\n Examples:\n can_arrange([1,2,4,3,5]) = 3\n can_arrange([1,2,3]) = -1\n \"\"\"\n # Initialize the index to -1, which will be returned if no such element is found\n largest_index = -1\n \n # Iterate through the array starting from the second element\n for i in range(1, len(arr)):\n # Check if the current element is less than the previous element\n if arr[i] < arr[i - 1]:\n largest_index = i # Update the largest index found\n \n return largest_index", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n '''\n Create a function that takes a string as input which contains only square brackets.\n The function should return True if and only if there is a valid subsequence of brackets \n where at least one bracket in the subsequence is nested.\n\n is_nested('[[]]') \u279e True\n is_nested('[]]]]]]][[[[[]') \u279e False\n is_nested('[][]') \u279e False\n is_nested('[]') \u279e False\n is_nested('[[][]]') \u279e True\n is_nested('[[]][[') \u279e True\n '''\n stack = []\n nested_found = False\n\n for char in string:\n if char == '[':\n stack.append(char)\n elif char == ']':\n if stack:\n stack.pop()\n if len(stack) > 0: # Check if there is a nested bracket\n nested_found = True\n else:\n return False # Unmatched closing bracket\n\n return nested_found and len(stack) == 0 # Must be balanced and have nested brackets", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["[[]][["]], "plus_fail_tests": [["[[]]]"]]}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n \n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n \"\"\"\n if not numbers:\n return (0, 1)\n \n total_sum = sum(numbers)\n total_product = 1\n for number in numbers:\n total_product *= number\n \n return (total_sum, total_product)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n \"\"\"\n You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n \n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n \n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots that exist in stock\n \n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n \"\"\"\n # Calculate how many more carrots are needed\n additional_needed = need - number\n \n # If no additional carrots are needed, return the current state\n if additional_needed <= 0:\n return [number, remaining]\n \n # Determine how many carrots can be eaten from the remaining stock\n eaten = min(additional_needed, remaining)\n \n # Calculate the total eaten and remaining carrots\n total_eaten = number + eaten\n remaining_after_meals = remaining - eaten\n \n return [total_eaten, remaining_after_meals]", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": [[2, 2, 2]]}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n \"\"\"You are given a string s.\n if s[i] is a letter, reverse its case from lower to upper or vise versa, \n otherwise keep it as it is.\n If the string contains no letters, reverse the string.\n The function should return the resulted string.\n \n Examples:\n solve(\"1234\") = \"4321\"\n solve(\"ab\") = \"AB\"\n solve(\"#a@C\") = \"#A@c\"\n \"\"\"\n # Check if there are any letters in the string\n has_letters = any(c.isalpha() for c in s)\n \n if has_letters:\n # Reverse case for letters and keep others the same\n return ''.join(c.swapcase() if c.isalpha() else c for c in s)\n else:\n # Reverse the string if there are no letters\n return s[::-1]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return True if the three\n sides form a right-angled triangle, False otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or \n 90 degree.\n \n Example:\n right_angle_triangle(3, 4, 5) == True\n right_angle_triangle(1, 2, 3) == False\n '''\n # Sort the sides to identify the longest side\n sides = sorted([a, b, c])\n \n # Check the Pythagorean theorem\n return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n \"\"\"Convert a decimal number to binary format with specific formatting.\n \n Args:\n decimal (int): A non-negative integer to convert to binary.\n \n Returns:\n str: A string representing the binary format of the decimal number,\n prefixed and suffixed with 'db'.\n \n Examples:\n >>> decimal_to_binary(15)\n 'db1111db'\n >>> decimal_to_binary(32)\n 'db100000db'\n \"\"\"\n if decimal < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n # Convert decimal to binary and remove the '0b' prefix\n binary_representation = bin(decimal)[2:]\n \n # Format the output with 'db' at the beginning and end\n formatted_output = f\"db{binary_representation}db\"\n \n return formatted_output", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef x_or_y(n, x, y):\n \"\"\"Return the value of x if n is a prime number, otherwise return y.\"\"\"\n if is_prime(n):\n return x\n else:\n return y", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fib4(0) -> 0\n fib4(1) -> 0\n fib4(2) -> 2\n fib4(3) -> 0\n fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.\n \n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 2\n elif n == 3:\n return 0\n\n # Initialize the first four values of the sequence\n fib_values = [0, 0, 2, 0]\n\n # Compute the values iteratively\n for i in range(4, n + 1):\n next_value = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n fib_values.append(next_value)\n\n return fib_values[n]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n \"\"\"\n Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move at the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.\n\n Parameters:\n n (int): The number of cars in each direction.\n\n Returns:\n int: The total number of collisions.\n \"\"\"\n # Each car moving left to right will collide with each car moving right to left\n # Therefore, the total number of collisions is n * n\n return n * n", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n \"\"\"\n Checks if given string is a palindrome.\n \n A palindrome is a string that reads the same forward and backward.\n \n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n \"\"\"\n # Normalize the string by removing spaces and converting to lowercase\n normalized_text = text.replace(\" \", \"\").lower()\n # Check if the string is equal to its reverse\n return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["never odd or even"]]}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this integer is a cube of some integer number.\n Note: you may assume the input is always valid.\n \n Examples:\n iscube(1) ==> True\n iscube(2) ==> False\n iscube(-1) ==> True\n iscube(64) ==> True\n iscube(0) ==> True\n iscube(180) ==> False\n '''\n # Calculate the cube root of the absolute value of a\n cube_root = round(abs(a) ** (1/3))\n \n # Check if the cube of the rounded cube root equals the absolute value of a\n return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n \"\"\"You are given two positive integers n and m, and your task is to compute the\n average of the integers from n through m (including n and m). \n Round the answer to the nearest integer and convert that to binary.\n If n is greater than m, return -1.\n \n Example:\n rounded_avg(1, 5) => \"0b11\"\n rounded_avg(7, 5) => -1\n rounded_avg(10, 20) => \"0b1111\"\n rounded_avg(20, 33) => \"0b11010\"\n \"\"\"\n if n > m:\n return -1\n \n # Calculate the sum of integers from n to m\n total_sum = sum(range(n, m + 1))\n count = m - n + 1 # Total numbers from n to m\n \n # Calculate the average and round it\n average = total_sum / count\n rounded_average = round(average)\n \n # Convert the rounded average to binary\n return bin(rounded_average)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n \"\"\"\n Given a positive integer n, return the count of the numbers of n-digit\n positive integers that start or end with 1.\n \"\"\"\n if n < 1:\n return 0\n\n # Total n-digit numbers\n total_n_digit_numbers = 9 * (10 ** (n - 1))\n\n # Count of n-digit numbers that start with 1\n start_with_1 = 10 ** (n - 1)\n\n # Count of n-digit numbers that end with 1\n end_with_1 = 9 * (10 ** (n - 2)) if n > 1 else 0\n\n # Total count of n-digit numbers that start or end with 1\n total_count = start_with_1 + end_with_1\n\n return total_count", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[2]], "plus_fail_tests": [[6]]}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits will be 1 the output should be \"1\".\n For N = 150, the sum of digits will be 6 the output should be \"110\".\n For N = 147, the sum of digits will be 12 the output should be \"1100\".\n \n Variables:\n @N integer\n Constraints: 0 \u2264 N \u2264 10000.\n Output:\n a string of binary number\n \"\"\"\n # Calculate the sum of the digits of N\n digit_sum = sum(int(digit) for digit in str(N))\n \n # Convert the sum to binary and remove the '0b' prefix\n binary_sum = bin(digit_sum)[2:]\n \n return binary_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n '''\n Given list of integers, return list in strange order.\n Strange sorting, is when you start with the minimum value,\n then maximum of the remaining integers, then minimum and so on.\n\n Examples:\n strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n strange_sort_list([]) == []\n '''\n if not lst:\n return []\n\n sorted_lst = sorted(lst)\n result = []\n left, right = 0, len(sorted_lst) - 1\n\n while left <= right:\n if left == right:\n result.append(sorted_lst[left])\n else:\n result.append(sorted_lst[left])\n result.append(sorted_lst[right])\n left += 1\n right -= 1\n\n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n \"\"\" Return length of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n \"\"\"\n return len(string)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(28)\n 14\n >>> largest_divisor(1)\n 0\n >>> largest_divisor(10)\n 5\n \"\"\"\n if n <= 1:\n return 0 # No divisors for 1 or less\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return the area of\n the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n Otherwise return -1.\n Three sides make a valid triangle when the sum of any two sides is greater \n than the third side.\n \n Example:\n triangle_area(3, 4, 5) == 6.00\n triangle_area(1, 2, 10) == -1\n '''\n # Check for valid triangle condition\n if a + b > c and a + c > b and b + c > a:\n # Calculate the semi-perimeter\n s = (a + b + c) / 2\n # Calculate the area using Heron's formula\n area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n return round(area, 2)\n else:\n return -1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n \n >>> longest([])\n >>> None\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n \"\"\"\n if not strings:\n return None\n \n longest_string = strings[0]\n \n for string in strings:\n if len(string) > len(longest_string):\n longest_string = string\n \n return longest_string", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n result = 1\n base = 2 % p # Start with 2 mod p\n while n > 0:\n if n % 2 == 1: # If n is odd, multiply the base with the result\n result = (result * base) % p\n base = (base * base) % p # Square the base\n n //= 2 # Divide n by 2\n return result", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[0, 1]]}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef prime_length(string):\n \"\"\"Return True if the string length is a prime number, False otherwise.\"\"\"\n length = len(string)\n return is_prime(length)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n \"\"\"Returns True if x is a simple power of n, otherwise False.\n \n A number x is a simple power of n if there exists an integer k such that n**k = x.\n \n Args:\n x (int): The number to check.\n n (int): The base number.\n \n Returns:\n bool: True if x is a simple power of n, False otherwise.\n \"\"\"\n if n <= 1:\n return x == 1 # 1 is a power of any number, and no other number can be a power of 1 or less.\n \n power = 1\n while True:\n result = n ** power\n if result == x:\n return True\n elif result > x:\n return False\n power += 1", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[1, 12]], "plus_fail_tests": [[1, 4]]}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n \n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n \"\"\"\n return ' '.join(str(i) for i in range(n + 1))", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[1000000]]}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n \"\"\"\n triples_sum_to_zero takes a list of integers as an input.\n it returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n \"\"\"\n n = len(l)\n # Sort the list to use the two-pointer technique\n l.sort()\n \n for i in range(n - 2):\n # Avoid duplicates for the first element\n if i > 0 and l[i] == l[i - 1]:\n continue\n \n left, right = i + 1, n - 1\n while left < right:\n current_sum = l[i] + l[left] + l[right]\n if current_sum == 0:\n return True\n elif current_sum < 0:\n left += 1\n else:\n right -= 1\n \n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n \"\"\"Counts the number of prime hexadecimal digits in the given hexadecimal string.\"\"\"\n # Define the set of prime hexadecimal digits\n prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n \n # Count the number of prime hexadecimal digits in the input string\n count = sum(1 for digit in num if digit in prime_hex_digits)\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n \"\"\"Return median of elements in the list l.\n \n The median is the middle value in a list of numbers. If the list has an even number of elements,\n the median is the average of the two middle numbers.\n \n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty\")\n \n sorted_list = sorted(l)\n n = len(sorted_list)\n mid = n // 2\n \n if n % 2 == 0: # Even number of elements\n return (sorted_list[mid - 1] + sorted_list[mid]) / 2\n else: # Odd number of elements\n return sorted_list[mid]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return a greatest common divisor of two integers a and b\n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n \"\"\"\n while b:\n a, b = b, a % b\n return abs(a)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers\n >>> filter_integers(['a', 3.14, 5])\n [5]\n >>> filter_integers([1, 2, 3, 'abc', {}, []])\n [1, 2, 3]\n \"\"\"\n return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[[true, false, null, 0, -10, "test", [], {}, 3.14]]]}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string\n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n \"\"\"\n return [string[:i] for i in range(1, len(string) + 1)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with the encode_cyclic function.\n Returns the decoded string.\n \"\"\"\n # Split string into groups of length 3\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # Reverse the cycling of elements in each group\n groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n Input number should be equal to the product of all factors\n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n \"\"\"\n factors = []\n # Check for number of 2s that divide n\n while n % 2 == 0:\n factors.append(2)\n n //= 2\n \n # n must be odd at this point so a skip of 2 (i.e., check only odd numbers) can be used\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, append i and divide n\n while n % i == 0:\n factors.append(i)\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n factors.append(n)\n \n return factors", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n \n For example:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n >>> is_bored(\"I am happy! Are you? I will go now.\")\n 2\n >>> is_bored(\"What a day. I can't believe it! I am so excited.\")\n 2\n \"\"\"\n # Split the input string into sentences using the delimiters\n sentences = []\n current_sentence = []\n for char in S:\n if char in '.!?':\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n current_sentence = []\n else:\n current_sentence.append(char)\n if current_sentence: # Add the last sentence if it exists\n sentences.append(''.join(current_sentence).strip())\n \n # Count the number of sentences that start with \"I\"\n boredom_count = sum(1 for sentence in sentences if sentence.startswith('I'))\n \n return boredom_count", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": [["In the morning, I like to have a cup of coffee to start my day off right. How about you?"]]}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n \n >>> circular_shift(12, 1)\n '21'\n >>> circular_shift(12, 2)\n '12'\n >>> circular_shift(12345, 1)\n '51234'\n >>> circular_shift(12345, 5)\n '54321'\n >>> circular_shift(12345, 6)\n '54321'\n \"\"\"\n # Convert the integer to a string to manipulate its digits\n str_x = str(x)\n num_digits = len(str_x)\n \n # If shift is greater than the number of digits, reverse the string\n if shift >= num_digits:\n return str_x[::-1]\n \n # Calculate the effective shift\n effective_shift = shift % num_digits\n \n # Perform the circular shift\n shifted_str = str_x[-effective_shift:] + str_x[:-effective_shift]\n \n return shifted_str", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[12, 2]], "plus_fail_tests": [[987654321, 9]]}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n \"\"\" \n xs represent coefficients of a polynomial.\n xs[0] + xs[1] * x + xs[2] * x^2 + ....\n Return derivative of this polynomial in the same form.\n \n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n \"\"\"\n # The derivative of a polynomial is calculated by multiplying each coefficient\n # by its corresponding power and reducing the power by one.\n return [i * coeff for i, coeff in enumerate(xs[1:], start=1)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two words have the same characters if they contain the same unique characters,\n regardless of the number of times each character appears.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n \"\"\"Add two numbers x and y.\n \n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n \"\"\"\n return x + y", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n count_upper('aBCdEf') returns 1\n count_upper('abcdefg') returns 0\n count_upper('dBBE') returns 0\n \"\"\"\n uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n count = 0\n \n for i in range(0, len(s), 2): # Iterate over even indices\n if s[i] in uppercase_vowels:\n count += 1\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_up_to(n):\n \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n primes = []\n for i in range(2, n):\n if is_prime(i):\n primes.append(i)\n return primes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n \"\"\"\n return [x for x in l if x > 0]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n even_indices = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indexed elements\n even_indices.sort()\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Place the sorted even indexed elements back into their positions\n for i, value in enumerate(even_indices):\n result[i * 2] = value\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n \"\"\"Return True if all numbers in the list l are below threshold t.\n \n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n \"\"\"\n return all(x < t for x in l)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n >>> closest_integer(\"14.5\")\n 15\n >>> closest_integer(\"-14.5\")\n -15\n >>> closest_integer(\"0.5\")\n 1\n >>> closest_integer(\"-0.5\")\n -1\n '''\n # Convert the string to a float\n num = float(value)\n \n # Get the floor and ceiling of the number\n lower = int(num // 1) # This is the largest integer less than or equal to num\n upper = lower + 1 # This is the smallest integer greater than num\n \n # Check if the number is equidistant from lower and upper\n if abs(num - lower) < abs(num - upper):\n return lower\n elif abs(num - lower) > abs(num - upper):\n return upper\n else:\n # If equidistant, round away from zero\n if num > 0:\n return upper\n else:\n return lower", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000"]]}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef fibonacci(n: int) -> int:\n \"\"\"Return the n-th Fibonacci number.\"\"\"\n a, b = 0, 1\n for _ in range(n):\n a, b = b, a + b\n return a\ndef prime_fib(n: int) -> int:\n \"\"\"\n prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n count = 0\n i = 0\n while True:\n fib_num = fibonacci(i)\n if is_prime(fib_num):\n count += 1\n if count == n:\n return fib_num\n i += 1", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[12]]}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n \"\"\"Return n-th Fibonacci number.\n \n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n elif n == 1:\n return 1\n elif n == 2:\n return 1\n else:\n a, b = 1, 1\n for _ in range(2, n):\n a, b = b, a + b\n return b", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[0]]}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.\n \"\"\"\n # Get the unit digit of the first number\n unit_digit_a = abs(a) % 10\n # Get the unit digit of the second number\n unit_digit_b = abs(b) % 10\n # Return the product of the unit digits\n return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n \n Args:\n n (int): The index of the FibFib number to compute.\n \n Returns:\n int: The n-th FibFib number.\n \n Examples:\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 1\n \n # Initialize the first three FibFib numbers\n fibfib_numbers = [0, 0, 1]\n \n # Compute the FibFib numbers iteratively\n for i in range(3, n + 1):\n next_fibfib = fibfib_numbers[i - 1] + fibfib_numbers[i - 2] + fibfib_numbers[i - 3]\n fibfib_numbers.append(next_fibfib)\n \n return fibfib_numbers[n]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Sort the unique elements\n sorted_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_elements[1]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = 0\n s = s.lower() # Convert to lowercase to handle case insensitivity\n\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1: # Check if 'y' is at the end\n count += 1\n\n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n \"\"\"Simplifies the expression x * n and checks if it evaluates to a whole number.\n \n Args:\n x (str): A string representation of a fraction in the format <numerator>/<denominator>.\n n (str): A string representation of a fraction in the format <numerator>/<denominator>.\n \n Returns:\n bool: True if x * n evaluates to a whole number, False otherwise.\n \"\"\"\n # Split the fractions into numerator and denominator\n x_numerator, x_denominator = map(int, x.split('/'))\n n_numerator, n_denominator = map(int, n.split('/'))\n \n # Calculate the product of the fractions\n # x * n = (x_numerator / x_denominator) * (n_numerator / n_denominator)\n # This simplifies to (x_numerator * n_numerator) / (x_denominator * n_denominator)\n numerator_product = x_numerator * n_numerator\n denominator_product = x_denominator * n_denominator\n \n # Check if the result is a whole number\n return numerator_product % denominator_product == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef words_in_sentence(sentence):\n \"\"\"\n You are given a string representing a sentence,\n the sentence contains some words separated by a space,\n and you have to return a string that contains the words from the original sentence,\n whose lengths are prime numbers,\n the order of the words in the new string should be the same as the original one.\n\n Example 1:\n Input: sentence = \"This is a test\"\n Output: \"is\"\n\n Example 2:\n Input: sentence = \"lets go for swimming\"\n Output: \"go for\"\n\n Constraints:\n * 1 <= len(sentence) <= 100\n * sentence contains only letters\n \"\"\"\n words = sentence.split()\n prime_length_words = [word for word in words if is_prime(len(word))]\n return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n \"\"\"In this problem, you will implement a function that takes two lists of numbers,\n and determines whether it is possible to perform an exchange of elements\n between them to make lst1 a list of only even numbers.\n There is no limit on the number of exchanged elements between lst1 and lst2.\n If it is possible to exchange elements between the lst1 and lst2 to make\n all the elements of lst1 to be even, return \"YES\".\n Otherwise, return \"NO\".\n For example:\n exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"YES\"\n exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n It is assumed that the input lists will be non-empty.\n \"\"\"\n # Count the number of odd numbers in lst1\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n \n # Check if there are enough even numbers in lst2 to replace the odd numbers in lst1\n even_count_lst2 = sum(1 for x in lst2 if x % 2 == 0)\n \n # If the number of odd numbers in lst1 is less than or equal to the number of even numbers in lst2\n if odd_count_lst1 <= even_count_lst2:\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n \"\"\"Given a string s and a natural number n, returns a list of all words from \n string s that contain exactly n consonants, in the order they appear in the \n string s. If the string s is empty, returns an empty list.\n \n Args:\n s (str): The input string containing words.\n n (int): The number of consonants to match.\n \n Returns:\n list: A list of words containing exactly n consonants.\n \"\"\"\n \n if not s:\n return []\n \n # Define a set of consonants\n consonants = set(\"bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ\")\n \n # Split the string into words\n words = s.split()\n \n # Function to count consonants in a word\n def count_consonants(word):\n return sum(1 for char in word if char in consonants)\n \n # Select words with exactly n consonants\n result = [word for word in words if count_consonants(word) == n]\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n if not arr:\n return None\n\n product_of_signs = 1\n sum_of_magnitudes = 0\n\n for num in arr:\n if num > 0:\n sum_of_magnitudes += num\n elif num < 0:\n sum_of_magnitudes += -num\n product_of_signs *= -1\n else: # num == 0\n return 0 # If there's a zero, the product of signs is zero\n\n return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n \n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0: # More closing than opening\n return False\n return balance == 0 # Must be balanced at the end\n\n # Check both concatenation orders\n return 'Yes' if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]) else 'No'", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n '''\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return False. Assume no negative numbers and only integers.\n\n Examples\n is_sorted([5]) \u279e True\n is_sorted([1, 2, 3, 4, 5]) \u279e True\n is_sorted([1, 3, 2, 4, 5]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n '''\n if len(lst) <= 1:\n return True\n \n seen = set()\n last_num = None\n \n for num in lst:\n if num in seen:\n return False\n seen.add(num)\n \n if last_num is not None and num < last_num:\n return False\n \n last_num = num\n \n return True", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": [[[1, 1, 2, 2, 3, 3, 4]]]}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n \"\"\"\n Write a function which sorts the given list of integers\n in ascending order according to the sum of their digits.\n Note: if there are several items with similar sum of their digits,\n order them based on their index in original list.\n\n For example:\n >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n >>> order_by_points([]) == []\n \"\"\"\n \n def digit_sum(n):\n \"\"\"Calculate the sum of the digits of n.\"\"\"\n return sum(int(digit) for digit in str(abs(n)))\n\n # Sort the list based on the sum of digits and original index\n return sorted(nums, key=lambda x: (digit_sum(x), nums.index(x)))", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": [[[-5, -12, 9, 15]]]}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n \"\"\"\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n \n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126\n \"\"\"\n total_sum = 0\n for index, value in enumerate(lst):\n if index % 3 == 0:\n total_sum += value ** 2\n elif index % 4 == 0:\n total_sum += value ** 3\n else:\n total_sum += value\n return total_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n two consonants from the right side of the word (case sensitive).\n \n Vowels in the beginning and ending don't count. Return empty string if you didn't\n find any vowel that meets the above condition. \n\n You may assume that the given string contains English letters only.\n\n Example:\n get_closest_vowel(\"yogurt\") ==> \"u\"\n get_closest_vowel(\"FULL\") ==> \"U\"\n get_closest_vowel(\"quick\") ==> \"\"\n get_closest_vowel(\"ab\") ==> \"\"\n \"\"\"\n vowels = \"aeiouAEIOU\"\n n = len(word)\n\n # Start from the end of the word\n for i in range(n - 2, 0, -1):\n if word[i] in vowels:\n # Check if the characters before and after the vowel are consonants\n if word[i - 1].isalpha() and word[i + 1].isalpha() and \\\n word[i - 1] not in vowels and word[i + 1] not in vowels:\n return word[i]\n \n return \"\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef intersection(interval1, interval2):\n \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n start1, end1 = interval1\n start2, end2 = interval2\n \n # Find the intersection\n start_intersection = max(start1, start2)\n end_intersection = min(end1, end2)\n \n # Check if there is an intersection\n if start_intersection > end_intersection:\n return \"NO\"\n \n # Calculate the length of the intersection\n length_of_intersection = end_intersection - start_intersection\n \n # Check if the length is a prime number\n if is_prime(length_of_intersection):\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Get the top k elements\n top_k = sorted_arr[:k]\n # Sort the result in ascending order before returning\n return sorted(top_k)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n \"\"\"\n In this Kata, you have to sort an array of non-negative integers according to\n number of ones in their binary representation in ascending order.\n For similar number of ones, sort based on decimal value.\n\n It must be implemented like this:\n >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n >>> sort_array([1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]\n \"\"\"\n # Sort the array using a custom key\n return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n \"\"\"\n if not test:\n return {}\n\n # Split the input string into a list of letters\n letters = test.split()\n \n # Create a dictionary to count occurrences of each letter\n count_dict = {}\n for letter in letters:\n count_dict[letter] = count_dict.get(letter, 0) + 1\n\n # Find the maximum count\n max_count = max(count_dict.values())\n \n # Create a result dictionary for letters with the maximum count\n result = {letter: count for letter, count in count_dict.items() if count == max_count}\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n from collections import deque\n\n N = len(grid)\n directions = [(0, 1), (1, 0), (0, -1), (-1, 0)] # right, down, left, up\n min_path = None\n\n def dfs(x, y, path):\n nonlocal min_path\n if len(path) == k:\n if min_path is None or path < min_path:\n min_path = path[:]\n return\n \n for dx, dy in directions:\n nx, ny = x + dx, y + dy\n if 0 <= nx < N and 0 <= ny < N:\n path.append(grid[nx][ny])\n dfs(nx, ny, path)\n path.pop()\n\n for i in range(N):\n for j in range(N):\n dfs(i, j, [grid[i][j]])\n\n return min_path", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": [[[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 15]]}]}} |