diff --git a/.gitignore b/.gitignore index aa5edd74a..b5bdb88c1 100644 --- a/.gitignore +++ b/.gitignore @@ -188,3 +188,4 @@ cov.xml *-structure.json *.dot .python-version +*.jsonl diff --git a/EVALPLUS-4omini/1.json b/EVALPLUS-4omini/1.json new file mode 100644 index 000000000..ec9dfd48b --- /dev/null +++ b/EVALPLUS-4omini/1.json @@ -0,0 +1 @@ +{"date": "2024-07-20 12:59", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascending order.\n\n For example:\n generate_integers(2, 8) => [2, 4, 6, 8]\n generate_integers(8, 2) => [2, 4, 6, 8]\n generate_integers(10, 14) => []\n \"\"\"\n # Determine the range of numbers to consider\n start = min(a, b)\n end = max(a, b)\n\n # Generate a list of even integers in the specified range\n even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n return even_integers", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[2, 10]], "plus_fail_tests": [[6, 12]]}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n Example:\n even_odd_count(-12) ==> (1, 1)\n even_odd_count(123) ==> (1, 2)\n \"\"\"\n # Convert the number to a string and remove the negative sign if present\n num_str = str(abs(num))\n \n even_count = 0\n odd_count = 0\n \n # Iterate through each character in the string representation of the number\n for digit in num_str:\n if digit.isdigit(): # Check if the character is a digit\n if int(digit) % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n return (even_count, odd_count)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def compare_one(a, b):\n \"\"\"\n Create a function that takes integers, floats, or strings representing\n real numbers, and returns the larger variable in its given variable type.\n Return None if the values are equal.\n Note: If a real number is represented as a string, the floating point might be . or ,\n\n compare_one(1, 2.5) \u279e 2.5\n compare_one(1, \"2,3\") \u279e \"2,3\"\n compare_one(\"5,1\", \"6\") \u279e \"6\"\n compare_one(\"1\", 1) \u279e None\n \"\"\"\n \n def parse_value(value):\n \"\"\"Convert a string representation of a number to a float or return the original value.\"\"\"\n if isinstance(value, str):\n # Replace comma with dot for float conversion\n value = value.replace(',', '.')\n try:\n return float(value)\n except ValueError:\n return value # Return the original string if it cannot be converted\n return value\n\n # Parse both values\n parsed_a = parse_value(a)\n parsed_b = parse_value(b)\n\n # Check for equality\n if parsed_a == parsed_b:\n return None\n\n # Return the larger value in its original type\n if parsed_a > parsed_b:\n return a\n else:\n return b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n \"\"\"Compares the actual game scores with the guessed scores and returns the absolute differences.\n \n Args:\n game (list of int): The actual scores of the matches.\n guess (list of int): The guessed scores of the matches.\n \n Returns:\n list of int: A list containing the absolute differences between the actual scores and the guessed scores.\n If the guess is correct, the difference is 0.\n \n Example:\n compare([1,2,3,4,5,1],[1,2,3,4,2,-2]) -> [0,0,0,0,3,3]\n compare([0,5,0,0,0,4],[4,1,1,0,0,-2]) -> [4,4,1,0,0,6]\n \"\"\"\n return [abs(g - s) for g, s in zip(guess, game)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n \"\"\"\n Write a function count_nums which takes an array of integers and returns\n the number of elements which has a sum of digits > 0.\n If a number is negative, then its first signed digit will be negative:\n e.g. -123 has signed digits -1, 2, and 3.\n \n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n def sum_of_digits(n):\n # Convert the number to string and calculate the sum of its digits\n return sum(int(digit) if n >= 0 else -int(digit) if i == 0 else int(digit)\n for i, digit in enumerate(str(abs(n))) if digit.isdigit())\n\n count = 0\n for number in arr:\n if sum_of_digits(number) > 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def factorial(i):\n \"\"\"Calculate the factorial of a given number i.\"\"\"\n if i == 0 or i == 1:\n return 1\n result = 1\n for j in range(2, i + 1):\n result *= j\n return result\ndef sum_of_numbers(i):\n \"\"\"Calculate the sum of numbers from 1 to i.\"\"\"\n return (i * (i + 1)) // 2\ndef f(n):\n \"\"\"Return a list of size n, where the value at index i is the factorial of i if i is even,\n or the sum of numbers from 1 to i otherwise. Indexing starts from 1.\"\"\"\n result = []\n for i in range(1, n + 1):\n if i % 2 == 0: # i is even\n result.append(factorial(i))\n else: # i is odd\n result.append(sum_of_numbers(i))\n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list to avoid division by zero\n\n mean_value = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n return mad", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n \"\"\"\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n \"\"\"\n # Replace commas with spaces and split the string by whitespace\n words = s.replace(',', ' ').split()\n return words", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" \n You're given a list of deposit and withdrawal operations on a bank account that starts with\n zero balance. Your task is to detect if at any point the balance of account falls below zero, and\n at that point function should return True. Otherwise it should return False.\n \n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n \"\"\"\n balance = 0\n for operation in operations:\n balance += operation\n if balance < 0:\n return True\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string.\n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n >>> string_to_md5('') is None\n >>> string_to_md5('Python') == '5d41402abc4b2a76b9719d911017c592'\n \"\"\"\n if text == \"\":\n return None\n md5_hash = hashlib.md5(text.encode()).hexdigest()\n return md5_hash", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n \"\"\"Calculate the factorial of a non-negative integer n.\"\"\"\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef special_factorial(n):\n \"\"\"Calculate the Brazilian factorial of n.\"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n result = 1\n for i in range(1, n + 1):\n result *= factorial(i)\n \n return result", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[500]]}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n \"\"\"Find the strongest extension based on the defined strength criteria.\"\"\"\n strongest_extension = None\n max_strength = float('-inf') # Start with the lowest possible strength\n\n for extension in extensions:\n # Calculate the strength of the current extension\n CAP = sum(1 for char in extension if char.isupper())\n SM = sum(1 for char in extension if char.islower())\n strength = CAP - SM\n\n # Check if this extension is stronger than the current strongest\n if strength > max_strength:\n max_strength = strength\n strongest_extension = extension\n\n # Return the result in the specified format\n return f\"{class_name}.{strongest_extension}\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n \"\"\"Check if the second word or any of its rotations is a substring in the first word.\n \n Args:\n a (str): The first word.\n b (str): The second word.\n \n Returns:\n bool: True if the second word or any of its rotations is a substring of the first word, False otherwise.\n \n Examples:\n >>> cycpattern_check(\"abcd\", \"abd\")\n False\n >>> cycpattern_check(\"hello\", \"ell\")\n True\n >>> cycpattern_check(\"whassup\", \"psus\")\n False\n >>> cycpattern_check(\"abab\", \"baa\")\n True\n >>> cycpattern_check(\"efef\", \"eeff\")\n False\n >>> cycpattern_check(\"himenss\", \"simen\")\n True\n \"\"\"\n # Create a string that contains all rotations of b\n rotations = [b[i:] + b[:i] for i in range(len(b))]\n \n # Check if any rotation is a substring of a\n for rotation in rotations:\n if rotation in a:\n return True\n \n return False", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["", ""]]}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into\n an integer part (largest integer smaller than given number) and decimals\n (leftover part always smaller than 1).\n\n Return the decimal part of the number.\n \n >>> truncate_number(3.5)\n 0.5\n >>> truncate_number(7.25)\n 0.25\n >>> truncate_number(10.0)\n 0.0\n >>> truncate_number(5.99)\n 0.99\n \"\"\"\n if number < 0:\n raise ValueError(\"The number must be positive.\")\n \n integer_part = int(number) # Get the integer part\n decimal_part = number - integer_part # Calculate the decimal part\n return decimal_part", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n \"\"\"Calculate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n if n < 0:\n return []\n\n # Initialize the list to store the Tribonacci numbers\n tribonacci_sequence = []\n\n # Define the base cases\n for i in range(n + 1):\n if i == 0:\n tribonacci_sequence.append(1) # tri(0) = 1\n elif i == 1:\n tribonacci_sequence.append(3) # tri(1) = 3\n elif i % 2 == 0: # Even case\n tribonacci_sequence.append(1 + i / 2)\n else: # Odd case\n # tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1)\n tri_n_minus_1 = tribonacci_sequence[i - 1]\n tri_n_minus_2 = tribonacci_sequence[i - 2]\n tri_n_plus_1 = tribonacci_sequence[i + 1] if i + 1 <= n else 0\n tribonacci_sequence.append(tri_n_minus_1 + tri_n_minus_2 + tri_n_plus_1)\n\n return tribonacci_sequence", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[3]], "plus_fail_tests": [[10]]}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n \"\"\"\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n >>> make_a_pile(4)\n [4, 6, 8, 10]\n >>> make_a_pile(1)\n [1]\n \"\"\"\n stones = []\n current_stones = n\n \n for i in range(n):\n stones.append(current_stones)\n if current_stones % 2 == 0: # current_stones is even\n current_stones += 2 # next even number\n else: # current_stones is odd\n current_stones += 2 # next odd number\n \n return stones", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n \"\"\"\n Given a positive integer n, return a tuple that has the number of even and odd\n integer palindromes that fall within the range(1, n), inclusive.\n\n Example 1:\n\n Input: 3\n Output: (1, 2)\n Explanation:\n Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n Example 2:\n\n Input: 12\n Output: (4, 6)\n Explanation:\n Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n Note:\n 1. 1 <= n <= 10^3\n 2. returned tuple has the number of even and odd integer palindromes respectively.\n \"\"\"\n even_count = 0\n odd_count = 0\n\n for i in range(1, n + 1):\n if str(i) == str(i)[::-1]: # Check if the number is a palindrome\n if i % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n return (even_count, odd_count)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n \n Args:\n n (int): The number to evaluate.\n \n Returns:\n bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n \n Example:\n is_equal_to_sum_even(4) == False\n is_equal_to_sum_even(6) == False\n is_equal_to_sum_even(8) == True\n \"\"\"\n # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n if n < 8:\n return False\n \n # If n is even and at least 8, it can be expressed as the sum of 4 positive even numbers\n return n % 2 == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n \"\"\" Insert a number 'delimiter' between every two consecutive elements of input list `numbers`\n \n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n for i in range(len(numbers) - 1):\n result.append(numbers[i])\n result.append(delimiter)\n result.append(numbers[-1]) # Append the last element\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n '''\n Create a function that returns a tuple (a, b), where 'a' is\n the largest of negative integers, and 'b' is the smallest\n of positive integers in a list.\n If there is no negative or positive integers, return them as None.\n\n Examples:\n largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n largest_smallest_integers([]) == (None, None)\n largest_smallest_integers([0]) == (None, None)\n '''\n largest_negative = None\n smallest_positive = None\n\n for num in lst:\n if num < 0:\n if largest_negative is None or num > largest_negative:\n largest_negative = num\n elif num > 0:\n if smallest_positive is None or num < smallest_positive:\n smallest_positive = num\n\n return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n \"\"\"Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n For example:\n digits(1) == 1\n digits(4) == 0\n digits(235) == 15\n \"\"\"\n product = 1\n has_odd = False\n \n for digit in str(n):\n digit = int(digit)\n if digit % 2 != 0: # Check if the digit is odd\n product *= digit\n has_odd = True\n \n return product if has_odd else 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return True else return False.\n If the given array is empty then return True.\n\n Note: The given list is guaranteed to have unique elements.\n\n For Example:\n \n move_one_ball([3, 4, 5, 1, 2])==>True\n Explanation: By performing 2 right shift operations, non-decreasing order can\n be achieved for the given array.\n move_one_ball([3, 5, 4, 1, 2])==>False\n Explanation: It is not possible to get non-decreasing order for the given\n array by performing any number of right shift operations.\n \"\"\"\n if not arr:\n return True\n\n n = len(arr)\n sorted_arr = sorted(arr)\n \n # Check for the number of \"breaks\" in the sorted array\n break_count = 0\n for i in range(n):\n if arr[i] > arr[(i + 1) % n]:\n break_count += 1\n\n # If there are more than one break, we cannot sort the array with shifts\n return break_count <= 1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to make it easier to find the closest pair\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest elements\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n \n >>> flip_case('Hello')\n 'hELLO'\n >>> flip_case('Python')\n 'pYTHON'\n >>> flip_case('123abcXYZ')\n '123ABCxyz'\n >>> flip_case('')\n ''\n \"\"\"\n return string.swapcase()", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n \n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n \"\"\"\n count = 0\n start = 0\n \n while True:\n start = string.find(substring, start)\n if start == -1:\n break\n count += 1\n start += 1 # Move to the next character to allow for overlapping\n\n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n \"\"\" \n Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n \n >>> string_xor('010', '110')\n '100'\n >>> string_xor('111', '000')\n '111'\n >>> string_xor('101', '101')\n '000'\n >>> string_xor('000', '000')\n '000'\n >>> string_xor('1101', '1011')\n '0110'\n \"\"\"\n # Ensure both strings are of the same length\n if len(a) != len(b):\n raise ValueError(\"Input strings must be of the same length\")\n \n # Perform XOR operation\n result = []\n for bit_a, bit_b in zip(a, b):\n result.append('1' if bit_a != bit_b else '0')\n \n return ''.join(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lower_string = string.lower()\n # Use a set to find distinct characters\n distinct_characters = set(lower_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n \n Args:\n strings (List[str]): A list of strings to filter.\n prefix (str): The prefix to filter the strings by.\n \n Returns:\n List[str]: A list of strings that start with the given prefix.\n \n Examples:\n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n \"\"\"\n return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted = []\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Calculate the new character by shifting it down by 4 places\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a')) if char.islower() else chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n encrypted.append(new_char)\n else:\n encrypted.append(char) # Non-alphabetic characters remain unchanged\n return ''.join(encrypted)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n \n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n \"\"\"\n return [x + 1 for x in l]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n \n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by row index (ascending) and then by column index (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n \"\"\"Given length of a side and height, return the area of a triangle.\n \n The area of a triangle can be calculated using the formula:\n area = (base * height) / 2\n \n Parameters:\n a (float): The length of the base of the triangle.\n h (float): The height of the triangle.\n \n Returns:\n float: The area of the triangle.\n \n >>> triangle_area(5, 3)\n 7.5\n >>> triangle_area(10, 2)\n 10.0\n >>> triangle_area(0, 5)\n 0.0\n >>> triangle_area(5, 0)\n 0.0\n \"\"\"\n return (a * h) / 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n \"\"\"\n Given an array arr of integers, find the minimum number of elements that\n need to be changed to make the array palindromic. A palindromic array is an array that\n is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n For example:\n smallest_change([1,2,3,5,4,7,9,6]) == 4\n smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n smallest_change([1, 2, 3, 2, 1]) == 0\n \"\"\"\n n = len(arr)\n changes = 0\n \n # Compare elements from the start and end towards the center\n for i in range(n // 2):\n if arr[i] != arr[n - 1 - i]:\n changes += 1\n \n return changes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n else:\n return lst2", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": [[["happy", "birthday", "sarah"], ["happy", "birthday", "sally"]]]}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n \"\"\"You are given a string s.\n Your task is to check if the string is happy or not.\n A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n \n For example:\n is_happy('a') => False\n is_happy('aa') => False\n is_happy('abcd') => True\n is_happy('aabb') => False\n is_happy('adb') => True\n is_happy('xyy') => False\n \"\"\"\n # Check if the length of the string is at least 3\n if len(s) < 3:\n return False\n \n # Check every 3 consecutive letters\n for i in range(len(s) - 2):\n if len(set(s[i:i+3])) < 3: # If there are not 3 distinct letters\n return False\n \n return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" Input to this function is a string representing musical notes in a special ASCII format.\n Your task is to parse this string and return list of integers corresponding to how many beats does each\n note last.\n\n Here is a legend:\n 'o' - whole note, lasts four beats\n 'o|' - half note, lasts two beats\n '.|' - quarter note, lasts one beat\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n # Define a mapping of note representations to their corresponding beat values\n note_to_beats = {\n 'o': 4, # whole note\n 'o|': 2, # half note\n '.|': 1 # quarter note\n }\n \n # Split the input string into individual notes\n notes = music_string.split()\n \n # Parse the notes and convert them to their corresponding beat values\n beats = [note_to_beats[note] for note in notes if note in note_to_beats]\n \n return beats", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n \n >>> make_palindrome('')\n ''\n >>> make_palindrome('cat')\n 'catac'\n >>> make_palindrome('cata')\n 'catac'\n \"\"\"\n # Find the longest palindromic suffix\n for i in range(len(string)):\n if is_palindrome(string[i:]):\n # If the suffix is a palindrome, we need to append the reverse of the prefix\n prefix = string[:i]\n return string + prefix[::-1]\n return string # In case the string is empty or already a palindrome", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string.\n \n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n \"\"\"\n return ''.join(strings)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n \n # Create a new list with elements that occur only once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n \"\"\" \n Input is a space-delimited string of numerals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest.\n \n >>> sort_numbers('three one five')\n 'one three five'\n \"\"\"\n # Mapping of words to their corresponding numeric values\n num_map = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n \n # Split the input string into words\n words = numbers.split()\n \n # Sort the words based on their numeric values\n sorted_words = sorted(words, key=lambda word: num_map[word])\n \n # Join the sorted words back into a string\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n letter_grades = []\n \n for gpa in grades:\n if gpa == 4.0:\n letter_grades.append('A+')\n elif gpa > 3.7:\n letter_grades.append('A')\n elif gpa > 3.3:\n letter_grades.append('A-')\n elif gpa > 3.0:\n letter_grades.append('B+')\n elif gpa > 2.7:\n letter_grades.append('B')\n elif gpa > 2.3:\n letter_grades.append('B-')\n elif gpa > 2.0:\n letter_grades.append('C+')\n elif gpa > 1.7:\n letter_grades.append('C')\n elif gpa > 1.3:\n letter_grades.append('C-')\n elif gpa > 1.0:\n letter_grades.append('D+')\n elif gpa > 0.7:\n letter_grades.append('D')\n elif gpa > 0.0:\n letter_grades.append('D-')\n else:\n letter_grades.append('E')\n \n return letter_grades", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef get_primes_up_to(limit):\n \"\"\"Return a list of all prime numbers up to a given limit.\"\"\"\n return [num for num in range(2, limit) if is_prime(num)]\ndef is_multiply_prime(a):\n \"\"\"Return true if the given number is the multiplication of 3 prime numbers, false otherwise.\"\"\"\n if a >= 100:\n return False\n \n primes = get_primes_up_to(a)\n prime_count = len(primes)\n \n # Check all combinations of three primes\n for i in range(prime_count):\n for j in range(i, prime_count):\n for k in range(j, prime_count):\n product = primes[i] * primes[j] * primes[k]\n if product == a:\n return True\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1.\n \n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n min_val = min(numbers)\n max_val = max(numbers)\n \n # Avoid division by zero if all numbers are the same\n if min_val == max_val:\n return [0.0] * len(numbers)\n \n return [(num - min_val) / (max_val - min_val) for num in numbers]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n '''\n Write a function that returns True if the object q will fly, and False otherwise.\n The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n\n Example:\n will_it_fly([1, 2], 5) \u279e False \n # 1+2 is less than the maximum possible weight, but it's unbalanced.\n\n will_it_fly([3, 2, 3], 1) \u279e False\n # it's balanced, but 3+2+3 is more than the maximum possible weight.\n\n will_it_fly([3, 2, 3], 9) \u279e True\n # 3+2+3 is less than the maximum possible weight, and it's balanced.\n\n will_it_fly([3], 5) \u279e True\n # 3 is less than the maximum possible weight, and it's balanced.\n '''\n # Check if the list is a palindrome\n is_balanced = q == q[::-1]\n \n # Calculate the sum of the elements in the list\n total_weight = sum(q)\n \n # Check if the object will fly\n return is_balanced and total_weight <= w", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion.\n base numbers are less than 10.\n \n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n \"\"\"\n if base < 2 or base >= 10:\n raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n \n if x == 0:\n return '0'\n \n result = []\n while x > 0:\n result.append(str(x % base))\n x //= base\n \n return ''.join(reversed(result))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words while preserving spaces\n words = s.split(' ')\n \n # Sort the characters in each word\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back with spaces\n result = ' '.join(sorted_words)\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n or sort it in descending order if the sum( first index value, last index value) is even.\n\n Note:\n * don't change the given array.\n\n Examples:\n * sort_array([]) => []\n * sort_array([5]) => [5]\n * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n \"\"\"\n if not array: # Check for empty array\n return []\n \n first_value = array[0]\n last_value = array[-1]\n sum_values = first_value + last_value\n\n # Create a copy of the array to sort\n sorted_array = array.copy()\n\n if sum_values % 2 == 0: # Even sum\n sorted_array.sort(reverse=True) # Sort in descending order\n else: # Odd sum\n sorted_array.sort() # Sort in ascending order\n\n return sorted_array", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n \n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n \"\"\"\n seen = set()\n for number in l:\n if -number in seen:\n return True\n seen.add(number)\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in lower \n case or all keys are strings in upper case, else return False.\n The function should return False if the given dictionary is empty.\n \n Examples:\n check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n \"\"\"\n if not input_dict:\n return False\n\n all_lower = all(isinstance(key, str) and key.islower() for key in input_dict.keys())\n all_upper = all(isinstance(key, str) and key.isupper() for key in input_dict.keys())\n\n return all_lower or all_upper", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"(\" and \")\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"(\")\n False\n >>> correct_bracketing(\"()\")\n True\n >>> correct_bracketing(\"(()())\")\n True\n >>> correct_bracketing(\")(()\")\n False\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n \n # If balance goes negative, there are unmatched closing brackets\n if balance < 0:\n return False\n \n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n \"\"\"Task\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n \"\"\"\n return sum(ord(char) for char in s if char.isupper())", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n '''\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n \n Examples\n any_int(5, 2, 7) \u279e True\n \n any_int(3, 2, 2) \u279e False\n\n any_int(3, -2, 1) \u279e True\n \n any_int(3.6, -2.2, 2) \u279e False\n '''\n # Check if all inputs are integers\n if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n # Check if any number is equal to the sum of the other two\n return x == y + z or y == x + z or z == x + y\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n # Keep dividing n by factor until it is no longer divisible\n while n > 1:\n if n % factor == 0:\n n //= factor # Divide n by the factor\n else:\n factor += 1 # Move to the next potential factor\n return factor # The last factor is the largest prime factor", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n \"\"\"\n Given an array representing a branch of a tree that has non-negative integer nodes,\n your task is to pluck one of the nodes and return it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n The plucked node should be returned in a list, [ smallest_value, its index ],\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index. \n\n Example 3:\n Input: []\n Output: []\n \n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n Explanation: 0 is the smallest value, but there are two zeros,\n so we will choose the first zero, which has the smallest index.\n\n Constraints:\n * 1 <= nodes.length <= 10000\n * 0 <= node.value\n \"\"\"\n smallest_even = float('inf')\n smallest_index = -1\n\n for index, value in enumerate(arr):\n if value % 2 == 0: # Check if the value is even\n if value < smallest_even: # Check if it's the smallest even found\n smallest_even = value\n smallest_index = index\n\n if smallest_index == -1: # No even value found\n return []\n \n return [smallest_even, smallest_index]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n \"\"\"Return True if list elements are monotonically increasing or decreasing.\n \n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n \"\"\"\n if not l: # An empty list is considered monotonic\n return True\n \n increasing = decreasing = True\n \n for i in range(1, len(l)):\n if l[i] > l[i - 1]:\n decreasing = False\n elif l[i] < l[i - 1]:\n increasing = False\n \n return increasing or decreasing", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n \"\"\"\n Takes as input string encoded with encode_shift function. Returns decoded string.\n \"\"\"\n return \"\".join([chr(((ord(ch) - ord(\"a\") - 5) % 26) + ord(\"a\")) for ch in s])", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float) -> float:\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list) -> list:\n \"\"\"\n Returns the coefficients of the derivative of the polynomial.\n \"\"\"\n return [i * coeff for i, coeff in enumerate(xs)][1:]\ndef find_zero(xs: list, initial_guess: float = 0.0, tolerance: float = 1e-7, max_iterations: int = 1000) -> float:\n \"\"\" \n xs are coefficients of a polynomial.\n find_zero finds x such that poly(x) = 0.\n find_zero returns only one zero point, even if there are many.\n Moreover, find_zero only takes list xs having an even number of coefficients\n and the largest non-zero coefficient as it guarantees a solution.\n \n >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n -0.5\n >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n 1.0\n \"\"\"\n if len(xs) % 2 != 0:\n raise ValueError(\"The number of coefficients must be even.\")\n \n x = initial_guess\n for _ in range(max_iterations):\n f_x = poly(xs, x)\n f_prime_x = poly(derivative(xs), x)\n \n if abs(f_prime_x) < tolerance: # Avoid division by zero\n raise ValueError(\"Derivative is too small; no solution found.\")\n \n x_new = x - f_x / f_prime_x\n \n if abs(x_new - x) < tolerance:\n return x_new\n \n x = x_new\n \n raise ValueError(\"Maximum iterations reached; no solution found.\")", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[[5, 10, -3, 1]]]}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"<\" and \">\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"<\")\n False\n >>> correct_bracketing(\"<>\")\n True\n >>> correct_bracketing(\"<<><>>\")\n True\n >>> correct_bracketing(\"><<>\")\n False\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '<':\n balance += 1\n elif char == '>':\n balance -= 1\n # If balance goes negative, there are more closing brackets\n if balance < 0:\n return False\n # At the end, balance should be zero for correct bracketing\n return balance == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n \"\"\"Return maximum element in the list.\n \n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty.\")\n \n max_value = l[0]\n for item in l:\n if item > max_value:\n max_value = item\n return max_value", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n '''\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequency greater than or equal to the value of the integer itself. \n The frequency of an integer is the number of times it appears in the list.\n If no such a value exist, return -1.\n \n Examples:\n search([4, 1, 2, 2, 3, 1]) == 2\n search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n search([5, 5, 4, 4, 4]) == -1\n '''\n from collections import Counter\n \n # Count the frequency of each number in the list\n frequency = Counter(lst)\n \n # Initialize the result variable\n result = -1\n \n # Iterate through the frequency dictionary\n for num, freq in frequency.items():\n # Check if the frequency is greater than or equal to the number itself\n if freq >= num:\n # Update the result if this number is greater than the current result\n result = max(result, num)\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n \"\"\"\n Write a function that takes a message, and encodes in such a \n way that it swaps case of all letters, replaces all vowels in \n the message with the letter that appears 2 places ahead of that \n vowel in the english alphabet. \n Assume only letters. \n \n Examples:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n vowels = 'aeiouAEIOU'\n encoded_message = []\n\n for char in message:\n if char.isalpha(): # Check if the character is a letter\n # Swap case\n if char in vowels:\n # Replace vowel with the letter 2 places ahead\n if char.islower():\n new_char = chr(((ord(char) - ord('a') + 2) % 26) + ord('a'))\n else:\n new_char = chr(((ord(char) - ord('A') + 2) % 26) + ord('A'))\n else:\n new_char = char.swapcase() # Swap case for consonants\n encoded_message.append(new_char)\n else:\n encoded_message.append(char) # Keep non-letter characters unchanged\n\n return ''.join(encoded_message)", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["TEST"]], "plus_fail_tests": [["abcdefghijklmnopqrstuvwxyz"]]}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n \"\"\"\n In this task, you will be given a string that represents a number of apples and oranges \n that are distributed in a basket of fruit. This basket contains \n apples, oranges, and mango fruits. Given the string that represents the total number of \n the oranges and apples and an integer that represents the total number of the fruits \n in the basket, return the number of the mango fruits in the basket.\n \n Parameters:\n s (str): A string representing the number of apples and oranges.\n n (int): An integer representing the total number of fruits in the basket.\n \n Returns:\n int: The number of mango fruits in the basket.\n \n Examples:\n fruit_distribution(\"5 apples and 6 oranges\", 19) -> 8\n fruit_distribution(\"0 apples and 1 oranges\", 3) -> 2\n fruit_distribution(\"2 apples and 3 oranges\", 100) -> 95\n fruit_distribution(\"100 apples and 1 oranges\", 120) -> 19\n \"\"\"\n # Extract the number of apples and oranges from the string\n parts = s.split()\n apples = int(parts[0]) # First part is the number of apples\n oranges = int(parts[3]) # Fourth part is the number of oranges\n \n # Calculate the number of mangoes\n mangoes = n - apples - oranges\n return mangoes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n \n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n \"\"\"\n return n * (n + 1) // 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(divisible_by_three)\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Replace values at indices divisible by 3 with sorted values\n for index, value in zip([i for i in range(len(l)) if i % 3 == 0], sorted_values):\n result[index] = value\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n Example\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n \"\"\"\n # Initialize variables to track the minimum sum and the current sum\n min_sum = float('inf')\n current_sum = 0\n \n for num in nums:\n current_sum += num\n min_sum = min(min_sum, current_sum)\n \n # If current_sum becomes positive, reset it to 0\n if current_sum > 0:\n current_sum = 0\n \n return min_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n '''\n Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n \n Examples:\n split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"abcdef\") \u279e 3 \n '''\n # Check for whitespace\n if ' ' in txt:\n return txt.split()\n \n # Check for commas\n elif ',' in txt:\n return txt.split(',')\n \n # If no whitespace or commas, count lower-case letters with odd order\n else:\n odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n return odd_count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n \"\"\"\n Given a non-empty array of integers arr and an integer k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example:\n\n Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n Output: 24 # sum of 21 + 3\n\n Constraints:\n 1. 1 <= len(arr) <= 100\n 2. 1 <= k <= len(arr)\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate through the first k elements of the array\n for i in range(k):\n # Check if the current element has at most two digits\n if -100 < arr[i] < 100:\n total_sum += arr[i]\n \n return total_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length and alphabetically.\n \n Args:\n lst (list of str): A list of strings.\n \n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n \"\"\"\n Given a string text, replace all spaces in it with underscores, \n and if a string has more than 2 consecutive spaces, \n then replace all consecutive spaces with - \n \n fix_spaces(\"Example\") == \"Example\"\n fix_spaces(\"Example 1\") == \"Example_1\"\n fix_spaces(\" Example 2\") == \"_Example_2\"\n fix_spaces(\" Example 3\") == \"_Example-3\"\n \"\"\"\n import re\n \n # Replace more than 2 consecutive spaces with a single '-'\n text = re.sub(r' {3,}', '-', text)\n \n # Replace single spaces with underscores\n text = text.replace(' ', '_')\n \n return text", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n as follows: start with any positive integer n. Then each term is obtained from the \n previous term as follows: if the previous term is even, the next term is one half of \n the previous term. If the previous term is odd, the next term is 3 times the previous\n term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n Note: \n 1. Collatz(1) is [1].\n 2. returned list sorted in increasing order.\n\n For example:\n get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n collatz_sequence = []\n current = n\n \n while current != 1:\n collatz_sequence.append(current)\n if current % 2 == 0:\n current //= 2\n else:\n current = 3 * current + 1\n \n collatz_sequence.append(1) # Add the last term which is 1\n \n # Filter odd numbers and sort them\n odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n \n return odd_numbers", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n \"\"\"Task\n We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and True/False for the check.\n Example\n For s = \"abcde\", c = \"ae\", the result should be ('bcd',False)\n For s = \"abcdef\", c = \"b\" the result should be ('acdef',False)\n For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc',True)\n \"\"\"\n # Create a set of characters to delete for faster lookup\n delete_set = set(c)\n \n # Create the result string by filtering out characters in delete_set\n result = ''.join(char for char in s if char not in delete_set)\n \n # Check if the result string is a palindrome\n is_palindrome = result == result[::-1]\n \n return (result, is_palindrome)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n \n The date is valid if all of the following rules are satisfied:\n 1. The date string is not empty.\n 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n The number of days is not less than 1 or higher than 29 for the month 2.\n 3. The months should not be less than 1 or higher than 12.\n 4. The date should be in the format: mm-dd-yyyy\n \n Args:\n date (str): The date string to validate.\n \n Returns:\n bool: True if the date is valid, False otherwise.\n \"\"\"\n if not date:\n return False\n \n # Check the format\n if len(date) != 10 or date[2] != '-' or date[5] != '-':\n return False\n \n try:\n month = int(date[:2])\n day = int(date[3:5])\n year = int(date[6:])\n except ValueError:\n return False\n \n # Validate month\n if month < 1 or month > 12:\n return False\n \n # Validate day based on month\n if month in [1, 3, 5, 7, 8, 10, 12]: # 31 days\n if day < 1 or day > 31:\n return False\n elif month in [4, 6, 9, 11]: # 30 days\n if day < 1 or day > 30:\n return False\n elif month == 2: # February\n if day < 1 or day > 29:\n return False\n \n return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n \"\"\"\n Calculate the number of times buckets need to be lowered to empty the wells.\n\n Parameters:\n grid (list of list of int): A rectangular grid representing wells.\n capacity (int): The capacity of each bucket.\n\n Returns:\n int: The total number of times buckets need to be lowered.\n \"\"\"\n total_water = 0\n \n # Count the total amount of water in the grid\n for row in grid:\n total_water += sum(row)\n \n # Calculate the number of times buckets need to be lowered\n # Each bucket can carry 'capacity' units of water\n if total_water == 0:\n return 0\n else:\n return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": [[[[1, 0, 0, 1], [0, 1, 1, 1], [0, 0, 0, 0], [1, 0, 1, 1]], 2]]}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n \"\"\"Create a function which takes a string representing a file's name, and returns\n 'Yes' if the the file's name is valid, and returns 'No' otherwise.\n A file's name is considered to be valid if and only if all the following conditions \n are met:\n - There should not be more than three digits ('0'-'9') in the file's name.\n - The file's name contains exactly one dot '.'\n - The substring before the dot should not be empty, and it starts with a letter from \n the latin alphapet ('a'-'z' and 'A'-'Z').\n - The substring after the dot should be one of these: ['txt', 'exe', 'dll']\n Examples:\n file_name_check(\"example.txt\") # => 'Yes'\n file_name_check(\"1example.dll\") # => 'No' (the name should start with a latin alphapet letter)\n \"\"\"\n \n # Split the file name into name and extension\n if file_name.count('.') != 1:\n return 'No'\n \n name, extension = file_name.split('.')\n \n # Check if the name is empty or starts with a non-alphabet character\n if not name or not name[0].isalpha():\n return 'No'\n \n # Check if the extension is valid\n valid_extensions = ['txt', 'exe', 'dll']\n if extension not in valid_extensions:\n return 'No'\n \n # Count the number of digits in the file name\n digit_count = sum(c.isdigit() for c in file_name)\n if digit_count > 3:\n return 'No'\n \n return 'Yes'", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n \"\"\"Write a function that takes an array of numbers as input and returns \n the number of elements in the array that are greater than 10 and both \n first and last digits of a number are odd (1, 3, 5, 7, 9).\n \n For example:\n specialFilter([15, -73, 14, -15]) => 1 \n specialFilter([33, -2, -3, 45, 21, 109]) => 2\n \"\"\"\n \n def is_odd_digit(digit):\n return digit in {'1', '3', '5', '7', '9'}\n \n def first_and_last_odd(num):\n str_num = str(abs(num)) # Convert to string and take absolute value\n return is_odd_digit(str_num[0]) and is_odd_digit(str_num[-1])\n \n count = 0\n for num in nums:\n if num > 10 and first_and_last_odd(num):\n count += 1\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closest to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sorted by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct planet names. \n Examples\n bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n '''\n \n planets = [\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n ]\n \n if planet1 not in planets or planet2 not in planets:\n return ()\n \n index1 = planets.index(planet1)\n index2 = planets.index(planet2)\n \n # Ensure index1 is less than index2 for slicing\n start_index = min(index1, index2) + 1\n end_index = max(index1, index2)\n \n return tuple(planets[start_index:end_index])", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers.\n You need to return the sum of squared numbers in the given list,\n round each element in the list to the upper int (Ceiling) first.\n \n Examples:\n For lst = [1,2,3] the output should be 14\n For lst = [1,4,9] the output should be 98\n For lst = [1,3,5,7] the output should be 84\n For lst = [1.4,4.2,0] the output should be 29\n For lst = [-2.4,1,1] the output should be 6\n \"\"\"\n return sum(math.ceil(x) ** 2 for x in lst)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n '''\n Create a function that returns True if the last character\n of a given string is an alphabetical character and is not\n a part of a word, and False otherwise.\n Note: \"word\" is a group of characters separated by space.\n\n Examples:\n check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '''\n # Strip any trailing whitespace from the string\n txt = txt.rstrip()\n \n # Check if the string is empty after stripping\n if not txt:\n return False\n \n # Get the last character of the string\n last_char = txt[-1]\n \n # Check if the last character is a letter\n if last_char.isalpha():\n # Check if the last character is part of a word\n # A character is part of a word if it is preceded by a non-space character\n if len(txt) > 1 and txt[-2] != ' ':\n return False\n return True\n \n return False", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["eeeee e "]], "plus_fail_tests": [["k "]]}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n \"\"\"This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If \n there's no such number, then the function should return -1.\n\n For example:\n choose_num(12, 15) = 14\n choose_num(13, 12) = -1\n \"\"\"\n # Ensure x is less than or equal to y\n if x > y:\n return -1\n \n # Start from the largest number in the range and check for evenness\n for num in range(y, x - 1, -1):\n if num % 2 == 0:\n return num\n \n return -1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to make it easier to find close elements\n numbers.sort()\n \n # Check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n reverse the resulting array, and then replace each digit by its corresponding name from\n \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n For example:\n arr = [2, 1, 1, 4, 5, 8, 2, 3] \n -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n \n If the array is empty, return an empty array:\n arr = []\n return []\n \n If the array has any strange number ignore it:\n arr = [1, -1 , 55] \n -> sort arr -> [-1, 1, 55]\n -> reverse arr -> [55, 1, -1]\n return = ['One']\n \"\"\"\n \n # Mapping of digits to their corresponding names\n digit_to_name = {\n 1: \"One\",\n 2: \"Two\",\n 3: \"Three\",\n 4: \"Four\",\n 5: \"Five\",\n 6: \"Six\",\n 7: \"Seven\",\n 8: \"Eight\",\n 9: \"Nine\"\n }\n \n # Filter the array to include only numbers between 1 and 9\n filtered_arr = [num for num in arr if 1 <= num <= 9]\n \n # Sort the filtered array\n filtered_arr.sort()\n \n # Reverse the sorted array\n filtered_arr.reverse()\n \n # Convert the numbers to their corresponding names\n result = [digit_to_name[num] for num in filtered_arr]\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n \"\"\"\n return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n \n double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n double_the_difference([-1, -2, 0]) == 0\n double_the_difference([9, -2]) == 81\n double_the_difference([0]) == 0 \n \n If the input list is empty, return 0.\n '''\n if not lst: # Check if the list is empty\n return 0\n \n return sum(x**2 for x in lst if isinstance(x, int) and x >= 0 and x % 2 != 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic algebra operations, and \n the second list is a list of integers. Use the two given lists to build the algebraic \n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + ) \n Subtraction ( - ) \n Multiplication ( * ) \n Floor division ( // ) \n Exponentiation ( ** ) \n\n Example:\n operator = ['+', '*', '-']\n operand = [2, 3, 4, 5]\n result = 2 + 3 * 4 - 5\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.\n \"\"\"\n # Start with the first operand\n result = operand[0]\n \n # Iterate through the operators and operands\n for i in range(len(operator)):\n op = operator[i]\n next_operand = operand[i + 1]\n \n if op == '+':\n result += next_operand\n elif op == '-':\n result -= next_operand\n elif op == '*':\n result *= next_operand\n elif op == '//':\n result //= next_operand\n elif op == '**':\n result **= next_operand\n else:\n raise ValueError(f\"Unsupported operator: {op}\")\n \n return result", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": [[["+", "-", "*", "//"], [5, 2, 3, 4, 7]]]}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n if not (1 <= number <= 1000):\n raise ValueError(\"Number must be between 1 and 1000\")\n\n roman_numerals = [\n (1000, 'm'),\n (900, 'cm'),\n (500, 'd'),\n (400, 'cd'),\n (100, 'c'),\n (90, 'xc'),\n (50, 'l'),\n (40, 'xl'),\n (10, 'x'),\n (9, 'ix'),\n (5, 'v'),\n (4, 'iv'),\n (1, 'i')\n ]\n\n result = []\n for value, numeral in roman_numerals:\n while number >= value:\n result.append(numeral)\n number -= value\n\n return ''.join(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n \"\"\"\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example :\n Input: n = 5\n Output: 1\n Explanation: \n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n \"\"\"\n # Create the array a\n a = [i * i - i + 1 for i in range(1, n + 1)]\n \n # Count the number of valid triples\n count = 0\n for i in range(n):\n for j in range(i + 1, n):\n for k in range(j + 1, n):\n if (a[i] + a[j] + a[k]) % 3 == 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n \"\"\"Given a list of positive integers x, return a sorted list of all \n elements that haven't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n def has_even_digit(n):\n \"\"\"Check if the number has any even digit.\"\"\"\n return any(int(digit) % 2 == 0 for digit in str(n))\n\n # Filter the list to include only numbers without even digits\n result = [num for num in x if not has_even_digit(num)]\n \n # Return the sorted result\n return sorted(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n \"\"\"Write a function that accepts a list of strings.\n The list contains different words. Return the word with maximum number\n of unique characters. If multiple strings have maximum number of unique\n characters, return the one which comes first in lexicographical order.\n\n find_max([\"name\", \"of\", \"string\"]) == \"string\"\n find_max([\"name\", \"enam\", \"game\"]) == \"enam\"\n find_max([\"aaaaaaa\", \"bb\" ,\"cc\"]) == \"aaaaaaa\"\n \"\"\"\n max_word = \"\"\n max_unique_count = 0\n\n for word in words:\n unique_chars = set(word)\n unique_count = len(unique_chars)\n\n if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n max_word = word\n max_unique_count = unique_count\n\n return max_word", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n def max_nesting_depth(s: str) -> int:\n max_depth = 0\n current_depth = 0\n for char in s:\n if char == '(':\n current_depth += 1\n max_depth = max(max_depth, current_depth)\n elif char == ')':\n current_depth -= 1\n return max_depth\n\n groups = paren_string.split()\n return [max_nesting_depth(group) for group in groups]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" \n Input to this function is a string containing multiple groups of nested parentheses. \n Your goal is to separate those groups into separate strings and return the list of those.\n Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n Ignore any spaces in the input string.\n \n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n # Remove spaces from the input string\n paren_string = paren_string.replace(\" \", \"\")\n \n result = []\n balance = 0\n current_group = []\n \n for char in paren_string:\n if char == '(':\n if balance == 0 and current_group:\n result.append(''.join(current_group))\n current_group = []\n balance += 1\n current_group.append(char)\n elif char == ')':\n balance -= 1\n current_group.append(char)\n if balance == 0:\n result.append(''.join(current_group))\n current_group = []\n \n # In case there are any remaining groups\n if current_group:\n result.append(''.join(current_group))\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n \"\"\"Create a function which returns the largest index of an element which\n is not greater than or equal to the element immediately preceding it. If\n no such element exists then return -1. The given array will not contain\n duplicate values.\n\n Examples:\n can_arrange([1,2,4,3,5]) = 3\n can_arrange([1,2,3]) = -1\n \"\"\"\n # Initialize the index to -1, which will be returned if no such element is found\n largest_index = -1\n \n # Iterate through the array starting from the second element\n for i in range(1, len(arr)):\n # Check if the current element is less than the previous element\n if arr[i] < arr[i - 1]:\n largest_index = i # Update the largest index found\n \n return largest_index", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef sum_of_digits(n):\n \"\"\"Return the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n largest_prime = -1\n \n for number in lst:\n if is_prime(number) and number > largest_prime:\n largest_prime = number\n \n if largest_prime == -1:\n return 0 # Return 0 if no prime is found\n \n return sum_of_digits(largest_prime)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n \n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n \"\"\"\n if not numbers:\n return (0, 1)\n \n total_sum = sum(numbers)\n total_product = 1\n for number in numbers:\n total_product *= number\n \n return (total_sum, total_product)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n '''\n Create a function that takes a string as input which contains only square brackets.\n The function should return True if and only if there is a valid subsequence of brackets \n where at least one bracket in the subsequence is nested.\n\n is_nested('[[]]') \u279e True\n is_nested('[]]]]]]][[[[[]') \u279e False\n is_nested('[][]') \u279e False\n is_nested('[]') \u279e False\n is_nested('[[][]]') \u279e True\n is_nested('[[]][[') \u279e True\n '''\n # Initialize a counter for open brackets\n open_count = 0\n # Initialize a flag to check for nesting\n nested = False\n \n for char in string:\n if char == '[':\n open_count += 1\n # If we have seen at least one open bracket before, we can have nesting\n if open_count > 1:\n nested = True\n elif char == ']':\n if open_count > 0:\n open_count -= 1\n else:\n # More closing brackets than opening brackets\n return False\n \n # We need at least one nested bracket and all brackets must be closed\n return nested and open_count == 0", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["[[]][["]], "plus_fail_tests": [["[[]]]"]]}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n \"\"\"\n You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n \n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n \n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots that exist in stock\n \n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n \"\"\"\n # Calculate how many more carrots are needed\n additional_needed = need - number\n \n # If no additional carrots are needed, return the current state\n if additional_needed <= 0:\n return [number, remaining]\n \n # Determine how many carrots can be eaten from the remaining stock\n eaten = min(additional_needed, remaining)\n \n # Calculate the total eaten and remaining carrots\n total_eaten = number + eaten\n remaining_after_meals = remaining - eaten\n \n return [total_eaten, remaining_after_meals]", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": [[2, 2, 2]]}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n \"\"\"You are given a string s.\n if s[i] is a letter, reverse its case from lower to upper or vise versa, \n otherwise keep it as it is.\n If the string contains no letters, reverse the string.\n The function should return the resulted string.\n \n Examples:\n solve(\"1234\") = \"4321\"\n solve(\"ab\") = \"AB\"\n solve(\"#a@C\") = \"#A@c\"\n \"\"\"\n # Check if there are any letters in the string\n has_letters = any(c.isalpha() for c in s)\n \n if has_letters:\n # Reverse case for letters and keep others as is\n return ''.join(c.swapcase() if c.isalpha() else c for c in s)\n else:\n # Reverse the string if there are no letters\n return s[::-1]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return True if the three\n sides form a right-angled triangle, False otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or \n 90 degree.\n \n Example:\n right_angle_triangle(3, 4, 5) == True\n right_angle_triangle(1, 2, 3) == False\n '''\n # Sort the sides to identify the longest side\n sides = sorted([a, b, c])\n # Check the Pythagorean theorem\n return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef x_or_y(n, x, y):\n \"\"\"Return the value of x if n is a prime number, otherwise return y.\"\"\"\n if is_prime(n):\n return x\n else:\n return y", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n \"\"\"Convert a decimal number to binary format with specific formatting.\n\n Args:\n decimal (int): A non-negative integer to convert to binary.\n\n Returns:\n str: A string representing the binary format of the decimal number,\n prefixed and suffixed with 'db'.\n \n Examples:\n >>> decimal_to_binary(15)\n 'db1111db'\n >>> decimal_to_binary(32)\n 'db100000db'\n \"\"\"\n if decimal < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n # Convert decimal to binary and remove the '0b' prefix\n binary_representation = bin(decimal)[2:]\n \n # Format the string with 'db' at the beginning and end\n formatted_binary = f\"db{binary_representation}db\"\n \n return formatted_binary", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fib4(0) -> 0\n fib4(1) -> 0\n fib4(2) -> 2\n fib4(3) -> 0\n fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.\n \n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 2\n elif n == 3:\n return 0\n\n # Initialize the first four values of the sequence\n fib_values = [0, 0, 2, 0]\n\n # Compute the values iteratively\n for i in range(4, n + 1):\n next_value = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n fib_values.append(next_value)\n\n return fib_values[n]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n \"\"\"\n Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move at the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.\n\n Parameters:\n n (int): The number of cars in each direction.\n\n Returns:\n int: The number of collisions.\n \"\"\"\n # Each car moving left to right will collide with each car moving right to left\n # Therefore, the total number of collisions is n * n\n return n * n", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n \"\"\"You are given two positive integers n and m, and your task is to compute the\n average of the integers from n through m (including n and m). \n Round the answer to the nearest integer and convert that to binary.\n If n is greater than m, return -1.\n \n Example:\n rounded_avg(1, 5) => \"0b11\"\n rounded_avg(7, 5) => -1\n rounded_avg(10, 20) => \"0b1111\"\n rounded_avg(20, 33) => \"0b11010\"\n \"\"\"\n if n > m:\n return -1\n \n # Calculate the sum of integers from n to m\n total_sum = sum(range(n, m + 1))\n count = m - n + 1 # Total numbers from n to m\n \n # Calculate the average and round it\n average = total_sum / count\n rounded_average = round(average)\n \n # Convert the rounded average to binary\n return bin(rounded_average)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n \"\"\"\n Checks if given string is a palindrome.\n \n A palindrome is a string that reads the same forward and backward.\n \n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n \"\"\"\n # Normalize the string by removing spaces and converting to lowercase\n normalized_text = text.replace(\" \", \"\").lower()\n # Check if the normalized string is equal to its reverse\n return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["never odd or even"]]}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this integer is a cube of some integer number.\n Note: you may assume the input is always valid.\n \n Examples:\n iscube(1) ==> True\n iscube(2) ==> False\n iscube(-1) ==> True\n iscube(64) ==> True\n iscube(0) ==> True\n iscube(180) ==> False\n '''\n # Calculate the cube root of the absolute value of a\n cube_root = round(abs(a) ** (1/3))\n \n # Check if the cube of the rounded cube root equals the absolute value of a\n return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits will be 1 the output should be \"1\".\n For N = 150, the sum of digits will be 6 the output should be \"110\".\n For N = 147, the sum of digits will be 12 the output should be \"1100\".\n \n Variables:\n @N integer\n Constraints: 0 \u2264 N \u2264 10000.\n Output:\n a string of binary number\n \"\"\"\n # Calculate the sum of the digits of N\n digit_sum = sum(int(digit) for digit in str(N))\n \n # Convert the sum to binary and remove the '0b' prefix\n binary_sum = bin(digit_sum)[2:]\n \n return binary_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n '''\n Given list of integers, return list in strange order.\n Strange sorting, is when you start with the minimum value,\n then maximum of the remaining integers, then minimum and so on.\n\n Examples:\n strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n strange_sort_list([]) == []\n '''\n if not lst:\n return []\n\n sorted_lst = sorted(lst)\n result = []\n left, right = 0, len(sorted_lst) - 1\n\n while left <= right:\n if left == right:\n result.append(sorted_lst[left])\n else:\n result.append(sorted_lst[left])\n result.append(sorted_lst[right])\n left += 1\n right -= 1\n\n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n \"\"\"\n Given a positive integer n, return the count of the numbers of n-digit\n positive integers that start or end with 1.\n \"\"\"\n if n < 1:\n return 0\n\n # Total n-digit numbers\n total_n_digit_numbers = 9 * (10 ** (n - 1))\n\n # Count of n-digit numbers that start with 1\n start_with_1 = 10 ** (n - 1)\n\n # Count of n-digit numbers that end with 1\n end_with_1 = total_n_digit_numbers // 10\n\n # Count of n-digit numbers that start and end with 1\n start_and_end_with_1 = 10 ** (n - 2) if n > 1 else 0\n\n # Total count of numbers that start or end with 1\n count = start_with_1 + end_with_1 - start_and_end_with_1\n\n return count", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[1000000]]}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n \"\"\" Return length of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n \"\"\"\n return len(string)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(28)\n 14\n >>> largest_divisor(1)\n 0\n >>> largest_divisor(10)\n 5\n \"\"\"\n if n <= 1:\n return 0 # No divisors for 1 or less\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return the area of\n the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n Otherwise return -1.\n Three sides make a valid triangle when the sum of any two sides is greater \n than the third side.\n \n Example:\n triangle_area(3, 4, 5) == 6.00\n triangle_area(1, 2, 10) == -1\n '''\n # Check for valid triangle\n if a + b > c and a + c > b and b + c > a:\n # Calculate the semi-perimeter\n s = (a + b + c) / 2\n # Calculate the area using Heron's formula\n area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n return round(area, 2)\n else:\n return -1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n \n >>> longest([])\n >>> None\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n \"\"\"\n if not strings:\n return None\n \n longest_string = strings[0]\n \n for string in strings:\n if len(string) > len(longest_string):\n longest_string = string\n \n return longest_string", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n result = 1\n base = 2 % p # Start with 2 mod p\n while n > 0:\n if n % 2 == 1: # If n is odd, multiply the base with the result\n result = (result * base) % p\n base = (base * base) % p # Square the base\n n //= 2 # Divide n by 2\n return result", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[0, 1]]}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef prime_length(string):\n \"\"\"Check if the length of the string is a prime number.\"\"\"\n length = len(string)\n return is_prime(length)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n \"\"\"Returns True if x is a simple power of n, otherwise False.\n \n A number x is a simple power of n if there exists an integer k such that n**k = x.\n \n Args:\n x (int): The number to check.\n n (int): The base number.\n \n Returns:\n bool: True if x is a simple power of n, False otherwise.\n \"\"\"\n if n <= 1:\n return x == 1 # 1 is a power of any number, and no other number can be a power of 1 or 0.\n \n power = 1\n while True:\n result = n ** power\n if result == x:\n return True\n elif result > x:\n return False\n power += 1", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[1, 12]], "plus_fail_tests": [[1, 4]]}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n \"\"\"\n triples_sum_to_zero takes a list of integers as an input.\n it returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n \"\"\"\n n = len(l)\n # Sort the list to use the two-pointer technique\n l.sort()\n \n for i in range(n - 2):\n # Avoid duplicates for the first element\n if i > 0 and l[i] == l[i - 1]:\n continue\n \n left, right = i + 1, n - 1\n while left < right:\n current_sum = l[i] + l[left] + l[right]\n if current_sum == 0:\n return True\n elif current_sum < 0:\n left += 1\n else:\n right -= 1\n \n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n \"\"\"Counts the number of prime hexadecimal digits in the given hexadecimal string.\"\"\"\n \n # Define the set of prime hexadecimal digits\n prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n \n # Initialize a counter for prime digits\n count = 0\n \n # Iterate through each character in the input string\n for char in num:\n # Check if the character is in the set of prime hexadecimal digits\n if char in prime_hex_digits:\n count += 1\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n \"\"\"Return median of elements in the list l.\n \n The median is the middle value in a list of numbers. If the list has an even number of elements,\n the median is the average of the two middle numbers.\n \n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty\")\n \n sorted_list = sorted(l)\n n = len(sorted_list)\n mid = n // 2\n \n if n % 2 == 0: # Even number of elements\n return (sorted_list[mid - 1] + sorted_list[mid]) / 2\n else: # Odd number of elements\n return sorted_list[mid]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return the greatest common divisor of two integers a and b\n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n \"\"\"\n while b:\n a, b = b, a % b\n return abs(a)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string\n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n \"\"\"\n return [string[:i] for i in range(1, len(string) + 1)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers\n >>> filter_integers(['a', 3.14, 5])\n [5]\n >>> filter_integers([1, 2, 3, 'abc', {}, []])\n [1, 2, 3]\n \"\"\"\n return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[[true, false, null, 0, -10, "test", [], {}, 3.14]]]}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n Input number should be equal to the product of all factors\n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n \"\"\"\n factors = []\n # Check for number of 2s that divide n\n while n % 2 == 0:\n factors.append(2)\n n //= 2\n \n # n must be odd at this point so a skip of 2 (i.e., i = i + 2) can be used\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, append i and divide n\n while n % i == 0:\n factors.append(i)\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n factors.append(n)\n \n return factors", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str):\n \"\"\"\n Takes as input a string encoded with the encode_cyclic function.\n Returns the decoded string.\n \"\"\"\n # Split string into groups of length 3\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # Reverse the cycling for each group\n groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n \n >>> circular_shift(12, 1)\n '21'\n >>> circular_shift(12, 2)\n '12'\n >>> circular_shift(12345, 1)\n '51234'\n >>> circular_shift(12345, 5)\n '54321'\n >>> circular_shift(12345, 6)\n '54321'\n \"\"\"\n # Convert the integer to a string to manipulate its digits\n str_x = str(x)\n num_digits = len(str_x)\n \n # If shift is greater than the number of digits, reverse the string\n if shift >= num_digits:\n return str_x[::-1]\n \n # Calculate the effective shift\n effective_shift = shift % num_digits\n \n # Perform the circular shift\n shifted_str = str_x[-effective_shift:] + str_x[:-effective_shift]\n \n return shifted_str", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[12, 2]], "plus_fail_tests": [[987654321, 9]]}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n \n For example:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n >>> is_bored(\"I am happy! Are you? I will go now.\")\n 2\n >>> is_bored(\"What a day. I can't believe it! I am so excited.\")\n 2\n \"\"\"\n # Split the string into sentences using the delimiters\n sentences = [s.strip() for s in S.replace('!', '.').replace('?', '.').split('.')]\n \n # Count the number of sentences that start with \"I\"\n boredom_count = sum(1 for sentence in sentences if sentence.startswith(\"I\"))\n \n return boredom_count", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": [["In the morning, I like to have a cup of coffee to start my day off right. How about you?"]]}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n \"\"\" \n xs represent coefficients of a polynomial.\n xs[0] + xs[1] * x + xs[2] * x^2 + ....\n Return derivative of this polynomial in the same form.\n \n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n \"\"\"\n # The derivative of a polynomial is calculated by multiplying each coefficient\n # by its corresponding power and reducing the power by one.\n return [i * coeff for i, coeff in enumerate(xs[1:], start=1)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_up_to(n):\n \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n primes = []\n for i in range(2, n):\n if is_prime(i):\n primes.append(i)\n return primes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two words have the same characters if they contain the same unique characters,\n regardless of the number of times each character appears.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n \"\"\"Add two numbers x and y.\n \n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n \"\"\"\n return x + y", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n count_upper('aBCdEf') returns 1\n count_upper('abcdefg') returns 0\n count_upper('dBBE') returns 0\n \"\"\"\n uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n count = 0\n \n for i in range(0, len(s), 2): # Iterate over even indices\n if s[i] in uppercase_vowels:\n count += 1\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n \"\"\"\n return [x for x in l if x > 0]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n even_indices = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indexed elements\n even_indices.sort()\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Place the sorted even indexed elements back into their positions\n for i, value in enumerate(even_indices):\n result[i * 2] = value\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_fib(n: int) -> int:\n \"\"\"\n prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n count = 0\n for fib in fibonacci_generator():\n if is_prime(fib):\n count += 1\n if count == n:\n return fib", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[1]], "plus_fail_tests": [[11]]}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n \"\"\"Return True if all numbers in the list l are below threshold t.\n \n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n \"\"\"\n return all(x < t for x in l)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n >>> closest_integer(\"14.5\")\n 15\n >>> closest_integer(\"-14.5\")\n -15\n >>> closest_integer(\"0.5\")\n 1\n >>> closest_integer(\"-0.5\")\n -1\n '''\n # Convert the string to a float\n num = float(value)\n \n # Get the floor and ceiling of the number\n lower = int(num // 1)\n upper = lower + 1\n \n # Check the distance to the lower and upper integers\n if abs(num - lower) < abs(num - upper):\n return lower\n elif abs(num - lower) > abs(num - upper):\n return upper\n else:\n # If equidistant, round away from zero\n if num > 0:\n return upper\n else:\n return lower", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000"]]}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n \"\"\"Return n-th Fibonacci number.\n \n The Fibonacci sequence is defined as follows:\n fib(0) = 0, fib(1) = 1, and fib(n) = fib(n-1) + fib(n-2) for n > 1.\n \n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n \"\"\"\n if n < 0:\n raise ValueError(\"Input should be a non-negative integer.\")\n elif n == 0:\n return 0\n elif n == 1:\n return 1\n else:\n a, b = 0, 1\n for _ in range(2, n + 1):\n a, b = b, a + b\n return b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n \n Args:\n n (int): The index of the FibFib number to compute.\n \n Returns:\n int: The n-th FibFib number.\n \n Examples:\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 1\n \n # Initialize the first three FibFib numbers\n fibfib_numbers = [0, 0, 1]\n \n # Compute the FibFib numbers iteratively\n for i in range(3, n + 1):\n next_fibfib = fibfib_numbers[i - 1] + fibfib_numbers[i - 2] + fibfib_numbers[i - 3]\n fibfib_numbers.append(next_fibfib)\n \n return fibfib_numbers[n]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.\n \"\"\"\n # Get the unit digit of the first number\n unit_digit_a = abs(a) % 10\n # Get the unit digit of the second number\n unit_digit_b = abs(b) % 10\n # Return the product of the unit digits\n return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Sort the unique elements\n sorted_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_elements[1]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = 0\n s = s.lower() # Convert to lowercase to handle case insensitivity\n\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1: # Check if 'y' is at the end\n count += 1\n\n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef words_in_sentence(sentence):\n \"\"\"\n You are given a string representing a sentence,\n the sentence contains some words separated by a space,\n and you have to return a string that contains the words from the original sentence,\n whose lengths are prime numbers,\n the order of the words in the new string should be the same as the original one.\n\n Example 1:\n Input: sentence = \"This is a test\"\n Output: \"is\"\n\n Example 2:\n Input: sentence = \"lets go for swimming\"\n Output: \"go for\"\n\n Constraints:\n * 1 <= len(sentence) <= 100\n * sentence contains only letters\n \"\"\"\n words = sentence.split()\n prime_length_words = [word for word in words if is_prime(len(word))]\n return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n \"\"\"Simplifies the expression x * n and checks if the result is a whole number.\n \n Args:\n x (str): A string representation of a fraction in the format /.\n n (str): A string representation of a fraction in the format /.\n \n Returns:\n bool: True if x * n evaluates to a whole number, False otherwise.\n \"\"\"\n # Split the fractions into numerator and denominator\n x_numerator, x_denominator = map(int, x.split('/'))\n n_numerator, n_denominator = map(int, n.split('/'))\n \n # Calculate the product of the fractions\n # x * n = (x_numerator / x_denominator) * (n_numerator / n_denominator)\n # This simplifies to (x_numerator * n_numerator) / (x_denominator * n_denominator)\n numerator_product = x_numerator * n_numerator\n denominator_product = x_denominator * n_denominator\n \n # Check if the result is a whole number\n return numerator_product % denominator_product == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n \"\"\"In this problem, you will implement a function that takes two lists of numbers,\n and determines whether it is possible to perform an exchange of elements\n between them to make lst1 a list of only even numbers.\n There is no limit on the number of exchanged elements between lst1 and lst2.\n If it is possible to exchange elements between the lst1 and lst2 to make\n all the elements of lst1 to be even, return \"YES\".\n Otherwise, return \"NO\".\n For example:\n exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"YES\"\n exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n It is assumed that the input lists will be non-empty.\n \"\"\"\n \n # Check if all elements in lst1 are even\n if all(x % 2 == 0 for x in lst1):\n return \"YES\"\n \n # Count the number of odd elements in lst1\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n \n # Count the number of even elements in lst2\n even_count_lst2 = sum(1 for x in lst2 if x % 2 == 0)\n \n # If there are enough even numbers in lst2 to replace all odd numbers in lst1\n if odd_count_lst1 <= even_count_lst2:\n return \"YES\"\n \n return \"NO\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n if not arr:\n return None\n\n product_of_signs = 1\n sum_of_magnitudes = 0\n\n for num in arr:\n if num > 0:\n sum_of_magnitudes += num\n elif num < 0:\n sum_of_magnitudes += -num\n product_of_signs *= -1\n else: # num == 0\n return 0 # If there's a zero, the product of signs is 0\n\n return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n \"\"\"Given a string s and a natural number n, returns a list of all words from \n string s that contain exactly n consonants, in the order they appear in the string s.\n \n Args:\n s (str): The input string containing words.\n n (int): The number of consonants to match.\n \n Returns:\n list: A list of words containing exactly n consonants.\n \"\"\"\n if not s:\n return []\n\n # Define a set of consonants\n consonants = set(\"bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ\")\n \n # Split the string into words\n words = s.split()\n \n # Function to count consonants in a word\n def count_consonants(word):\n return sum(1 for char in word if char in consonants)\n \n # Select words with exactly n consonants\n result = [word for word in words if count_consonants(word) == n]\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both concatenation orders\n return 'Yes' if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]) else 'No'", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n '''\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return False. Assume no negative numbers and only integers.\n\n Examples\n is_sorted([5]) \u279e True\n is_sorted([1, 2, 3, 4, 5]) \u279e True\n is_sorted([1, 3, 2, 4, 5]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n '''\n if not lst: # An empty list is considered sorted\n return True\n\n seen = set()\n last = None\n\n for num in lst:\n if num in seen:\n # If we see a number again, check if it's a duplicate\n if num == last:\n return False\n else:\n seen.add(num)\n else:\n seen.add(num)\n\n if last is not None and num < last:\n return False\n \n last = num\n\n return True", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": [[[1, 1, 2, 2, 3, 3, 4]]]}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n \"\"\"\n Write a function which sorts the given list of integers\n in ascending order according to the sum of their digits.\n Note: if there are several items with similar sum of their digits,\n order them based on their index in original list.\n\n For example:\n >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n >>> order_by_points([]) == []\n \"\"\"\n \n def digit_sum(n):\n \"\"\"Calculate the sum of the digits of n.\"\"\"\n return sum(int(digit) for digit in str(abs(n)))\n\n # Sort the list based on the sum of digits and original index\n return sorted(nums, key=lambda x: (digit_sum(x), nums.index(x)))", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": [[[-5, -12, 9, 15]]]}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n \"\"\"\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n \n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126\n \"\"\"\n total = 0\n for index, value in enumerate(lst):\n if index % 3 == 0:\n total += value ** 2 # Square if index is a multiple of 3\n elif index % 4 == 0:\n total += value ** 3 # Cube if index is a multiple of 4 and not a multiple of 3\n else:\n total += value # Leave unchanged if not a multiple of 3 or 4\n return total", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n two consonants from the right side of the word (case sensitive).\n \n Vowels in the beginning and ending don't count. Return empty string if you didn't\n find any vowel that meets the above condition. \n\n You may assume that the given string contains English letters only.\n\n Example:\n get_closest_vowel(\"yogurt\") ==> \"u\"\n get_closest_vowel(\"FULL\") ==> \"U\"\n get_closest_vowel(\"quick\") ==> \"\"\n get_closest_vowel(\"ab\") ==> \"\"\n \"\"\"\n vowels = \"aeiouAEIOU\"\n n = len(word)\n\n # Start from the end of the word\n for i in range(n - 2, 0, -1): # Start from the second last character\n if word[i] in vowels: # Check if the character is a vowel\n # Check if there are consonants on both sides\n if word[i - 1].isalpha() and word[i + 1].isalpha() and \\\n word[i - 1] not in vowels and word[i + 1] not in vowels:\n return word[i] # Return the vowel if conditions are met\n\n return \"\" # Return empty string if no valid vowel is found", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n \n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n \"\"\"\n return ' '.join(str(i) for i in range(n + 1))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Get the top k elements\n top_k = sorted_arr[:k]\n # Sort the result in ascending order before returning\n return sorted(top_k)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef intersection(interval1, interval2):\n \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n start1, end1 = interval1\n start2, end2 = interval2\n \n # Find the intersection\n start_intersection = max(start1, start2)\n end_intersection = min(end1, end2)\n \n # Check if there is an intersection\n if start_intersection > end_intersection:\n return \"NO\"\n \n # Calculate the length of the intersection\n length_of_intersection = end_intersection - start_intersection\n \n # Check if the length is a prime number\n if is_prime(length_of_intersection):\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n \"\"\"\n if not test:\n return {}\n\n # Split the input string into a list of letters\n letters = test.split()\n \n # Create a dictionary to count occurrences of each letter\n count_dict = {}\n for letter in letters:\n if letter in count_dict:\n count_dict[letter] += 1\n else:\n count_dict[letter] = 1\n\n # Find the maximum count\n max_count = max(count_dict.values())\n \n # Create a result dictionary for letters with the maximum count\n result = {letter: count for letter, count in count_dict.items() if count == max_count}\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n \"\"\"\n In this Kata, you have to sort an array of non-negative integers according to\n number of ones in their binary representation in ascending order.\n For similar number of ones, sort based on decimal value.\n\n It must be implemented like this:\n >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n >>> sort_array([1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]\n \"\"\"\n # Sort the array using a custom key\n return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n from collections import deque\n\n N = len(grid)\n directions = [(0, 1), (1, 0), (0, -1), (-1, 0)] # right, down, left, up\n min_path = None\n\n def dfs(x, y, path):\n nonlocal min_path\n if len(path) == k:\n if min_path is None or path < min_path:\n min_path = path[:]\n return\n \n for dx, dy in directions:\n nx, ny = x + dx, y + dy\n if 0 <= nx < N and 0 <= ny < N:\n path.append(grid[nx][ny])\n dfs(nx, ny, path)\n path.pop()\n\n for i in range(N):\n for j in range(N):\n dfs(i, j, [grid[i][j]])\n\n return min_path", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": [[[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 15]]}]}} \ No newline at end of file diff --git a/EVALPLUS-4omini/2.json b/EVALPLUS-4omini/2.json new file mode 100644 index 000000000..409aa9855 --- /dev/null +++ b/EVALPLUS-4omini/2.json @@ -0,0 +1 @@ +{"date": "2024-07-20 12:59", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n Example:\n even_odd_count(-12) ==> (1, 1)\n even_odd_count(123) ==> (1, 2)\n \"\"\"\n # Convert the number to a string and remove the negative sign if present\n num_str = str(abs(num))\n \n even_count = 0\n odd_count = 0\n \n # Iterate through each character in the string representation of the number\n for digit in num_str:\n if digit.isdigit(): # Check if the character is a digit\n if int(digit) % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n return (even_count, odd_count)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def compare_one(a, b):\n \"\"\"\n Create a function that takes integers, floats, or strings representing\n real numbers, and returns the larger variable in its given variable type.\n Return None if the values are equal.\n Note: If a real number is represented as a string, the floating point might be . or ,\n\n compare_one(1, 2.5) \u279e 2.5\n compare_one(1, \"2,3\") \u279e \"2,3\"\n compare_one(\"5,1\", \"6\") \u279e \"6\"\n compare_one(\"1\", 1) \u279e None\n \"\"\"\n \n def parse_value(value):\n \"\"\"Convert the input value to a float or return it as is if it's not a number.\"\"\"\n if isinstance(value, str):\n # Replace comma with dot for float conversion\n value = value.replace(',', '.')\n try:\n return float(value)\n except ValueError:\n return value # Return the string if it cannot be converted\n return value # Return the number as is\n\n # Parse both values\n parsed_a = parse_value(a)\n parsed_b = parse_value(b)\n\n # Check for equality\n if parsed_a == parsed_b:\n return None\n\n # Return the larger value, preserving the original type\n if parsed_a > parsed_b:\n return a\n else:\n return b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascending order.\n\n For example:\n generate_integers(2, 8) => [2, 4, 6, 8]\n generate_integers(8, 2) => [2, 4, 6, 8]\n generate_integers(10, 14) => []\n \"\"\"\n # Determine the range of numbers to consider\n start = min(a, b)\n end = max(a, b)\n\n # Generate a list of even integers in the specified range\n even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n return even_integers", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[2, 10]], "plus_fail_tests": [[6, 12]]}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n \"\"\"Compares the actual game scores with the guessed scores and returns the absolute differences.\n \n Args:\n game (list of int): The actual scores of the matches.\n guess (list of int): The guessed scores of the matches.\n \n Returns:\n list of int: A list containing the absolute differences between the actual scores and the guessed scores.\n If the guess is correct, the difference is 0.\n \n Example:\n compare([1,2,3,4,5,1],[1,2,3,4,2,-2]) -> [0,0,0,0,3,3]\n compare([0,5,0,0,0,4],[4,1,1,0,0,-2]) -> [4,4,1,0,0,6]\n \"\"\"\n return [abs(g - s) for g, s in zip(guess, game)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n \"\"\"\n Write a function count_nums which takes an array of integers and returns\n the number of elements which has a sum of digits > 0.\n If a number is negative, then its first signed digit will be negative:\n e.g. -123 has signed digits -1, 2, and 3.\n \n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n def sum_of_digits(n):\n # Convert the number to string and calculate the sum of its digits\n return sum(int(digit) if i > 0 else -int(digit) for i, digit in enumerate(str(n)) if digit.isdigit() or (i == 0 and n < 0))\n\n count = 0\n for number in arr:\n if sum_of_digits(number) > 0:\n count += 1\n \n return count", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[-1, -2, 0]]], "plus_fail_tests": [[[-1, 0, 1]]]}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def factorial(i):\n \"\"\"Calculate the factorial of a given number i.\"\"\"\n if i == 0 or i == 1:\n return 1\n result = 1\n for j in range(2, i + 1):\n result *= j\n return result\ndef sum_of_numbers(i):\n \"\"\"Calculate the sum of numbers from 1 to i.\"\"\"\n return (i * (i + 1)) // 2\ndef f(n):\n \"\"\"Return a list of size n, where the value at index i is the factorial of i if i is even,\n or the sum of numbers from 1 to i otherwise. Indexing starts from 1.\"\"\"\n result = []\n for i in range(1, n + 1):\n if i % 2 == 0: # i is even\n result.append(factorial(i))\n else: # i is odd\n result.append(sum_of_numbers(i))\n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list to avoid division by zero\n\n mean_value = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n return mad", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" \n You're given a list of deposit and withdrawal operations on a bank account that starts with\n zero balance. Your task is to detect if at any point the balance of account falls below zero, and\n at that point function should return True. Otherwise it should return False.\n \n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n \"\"\"\n balance = 0\n for operation in operations:\n balance += operation\n if balance < 0:\n return True\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n \"\"\"\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n \"\"\"\n # Split the string by commas and spaces, then strip any extra whitespace\n words = [word.strip() for word in s.replace(',', ' ').split()]\n return words", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n \"\"\"Find the strongest extension based on the defined strength criteria.\"\"\"\n strongest_extension = None\n max_strength = float('-inf') # Start with the lowest possible strength\n\n for extension in extensions:\n # Calculate the strength of the current extension\n CAP = sum(1 for char in extension if char.isupper())\n SM = sum(1 for char in extension if char.islower())\n strength = CAP - SM\n\n # Check if this extension is stronger than the current strongest\n if strength > max_strength:\n max_strength = strength\n strongest_extension = extension\n\n # Return the result in the specified format\n return f\"{class_name}.{strongest_extension}\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string.\n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n >>> string_to_md5('') is None\n >>> string_to_md5('Python') == '5d41402abc4b2a76b9719d911017c592'\n \"\"\"\n if text == \"\":\n return None\n md5_hash = hashlib.md5(text.encode()).hexdigest()\n return md5_hash", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n \"\"\"Check if the second word or any of its rotations is a substring in the first word.\n \n Args:\n a (str): The first word.\n b (str): The second word.\n \n Returns:\n bool: True if the second word or any of its rotations is a substring of the first word, False otherwise.\n \n Examples:\n >>> cycpattern_check(\"abcd\", \"abd\")\n False\n >>> cycpattern_check(\"hello\", \"ell\")\n True\n >>> cycpattern_check(\"whassup\", \"psus\")\n False\n >>> cycpattern_check(\"abab\", \"baa\")\n True\n >>> cycpattern_check(\"efef\", \"eeff\")\n False\n >>> cycpattern_check(\"himenss\", \"simen\")\n True\n \"\"\"\n # Create a string that contains all rotations of b\n rotations = [b[i:] + b[:i] for i in range(len(b))]\n \n # Check if any rotation is a substring of a\n for rotation in rotations:\n if rotation in a:\n return True\n \n return False", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["", ""]]}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into\n an integer part (largest integer smaller than given number) and decimals\n (leftover part always smaller than 1).\n\n Return the decimal part of the number.\n \n >>> truncate_number(3.5)\n 0.5\n >>> truncate_number(7.25)\n 0.25\n >>> truncate_number(10.0)\n 0.0\n >>> truncate_number(5.99)\n 0.99\n \"\"\"\n if number < 0:\n raise ValueError(\"The number must be positive.\")\n \n integer_part = int(number) # Get the integer part\n decimal_part = number - integer_part # Calculate the decimal part\n return decimal_part", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n \"\"\"\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n >>> make_a_pile(4)\n [4, 6, 8, 10]\n >>> make_a_pile(1)\n [1]\n \"\"\"\n stones = []\n current_stones = n\n \n for i in range(n):\n stones.append(current_stones)\n if current_stones % 2 == 0: # current_stones is even\n current_stones += 2 # next even number\n else: # current_stones is odd\n current_stones += 2 # next odd number\n \n return stones", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n \"\"\"Calculate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n if n < 0:\n return []\n\n # Initialize the list to store the Tribonacci numbers\n tribonacci_sequence = []\n\n # Define the base cases\n for i in range(n + 1):\n if i == 0:\n tribonacci_sequence.append(1) # tri(0) = 1\n elif i == 1:\n tribonacci_sequence.append(3) # tri(1) = 3\n elif i % 2 == 0: # Even case\n tribonacci_sequence.append(1 + i / 2)\n else: # Odd case\n tri_n_minus_1 = tribonacci_sequence[i - 1]\n tri_n_minus_2 = tribonacci_sequence[i - 2]\n tri_n_plus_1 = tribonacci_sequence[i + 1] if i + 1 <= n else 0\n tribonacci_sequence.append(tri_n_minus_1 + tri_n_minus_2 + tri_n_plus_1)\n\n return tribonacci_sequence", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[3]], "plus_fail_tests": [[10]]}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n \"\"\"\n Given a positive integer n, return a tuple that has the number of even and odd\n integer palindromes that fall within the range(1, n), inclusive.\n\n Example 1:\n Input: 3\n Output: (1, 2)\n Explanation:\n Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n Example 2:\n Input: 12\n Output: (4, 6)\n Explanation:\n Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n Note:\n 1. 1 <= n <= 10^3\n 2. returned tuple has the number of even and odd integer palindromes respectively.\n \"\"\"\n even_count = 0\n odd_count = 0\n\n for i in range(1, n + 1):\n if str(i) == str(i)[::-1]: # Check if the number is a palindrome\n if i % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n return (even_count, odd_count)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n \"\"\" Insert a number 'delimiter' between every two consecutive elements of input list `numbers`\n \n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n for i in range(len(numbers) - 1):\n result.append(numbers[i])\n result.append(delimiter)\n result.append(numbers[-1]) # Append the last element\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n \n Args:\n n (int): The number to evaluate.\n \n Returns:\n bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n \n Example:\n is_equal_to_sum_even(4) == False\n is_equal_to_sum_even(6) == False\n is_equal_to_sum_even(8) == True\n \"\"\"\n # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n if n < 8:\n return False\n \n # Check if n is even\n if n % 2 != 0:\n return False\n \n # If n is even and >= 8, it can be expressed as the sum of 4 positive even numbers\n return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n \"\"\"Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n For example:\n digits(1) == 1\n digits(4) == 0\n digits(235) == 15\n \"\"\"\n product = 1\n has_odd = False\n \n for digit in str(n):\n digit = int(digit)\n if digit % 2 != 0: # Check if the digit is odd\n product *= digit\n has_odd = True\n \n return product if has_odd else 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return True else return False.\n If the given array is empty then return True.\n\n Note: The given list is guaranteed to have unique elements.\n\n For Example:\n \n move_one_ball([3, 4, 5, 1, 2])==>True\n Explanation: By performing 2 right shift operations, non-decreasing order can\n be achieved for the given array.\n move_one_ball([3, 5, 4, 1, 2])==>False\n Explanation: It is not possible to get non-decreasing order for the given\n array by performing any number of right shift operations.\n \"\"\"\n if not arr:\n return True\n\n n = len(arr)\n sorted_arr = sorted(arr)\n \n # Check for the number of \"breaks\" in the sorted array\n break_count = 0\n for i in range(n):\n if arr[i] > arr[(i + 1) % n]:\n break_count += 1\n\n # If there are more than one break, we cannot sort the array with shifts\n return break_count <= 1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n '''\n Create a function that returns a tuple (a, b), where 'a' is\n the largest of negative integers, and 'b' is the smallest\n of positive integers in a list.\n If there is no negative or positive integers, return them as None.\n\n Examples:\n largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n largest_smallest_integers([]) == (None, None)\n largest_smallest_integers([0]) == (None, None)\n '''\n largest_negative = None\n smallest_positive = None\n\n for num in lst:\n if num < 0:\n if largest_negative is None or num > largest_negative:\n largest_negative = num\n elif num > 0:\n if smallest_positive is None or num < smallest_positive:\n smallest_positive = num\n\n return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to make it easier to find the closest pair\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest elements\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n \n >>> flip_case('Hello')\n 'hELLO'\n >>> flip_case('Python')\n 'pYTHON'\n >>> flip_case('123abcXYZ')\n '123ABCxyz'\n >>> flip_case('')\n ''\n \"\"\"\n return string.swapcase()", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n \n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n \"\"\"\n count = 0\n start = 0\n \n while True:\n start = string.find(substring, start)\n if start == -1:\n break\n count += 1\n start += 1 # Move to the next character to allow for overlapping matches\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n \"\"\" Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n \n >>> string_xor('010', '110')\n '100'\n >>> string_xor('111', '000')\n '111'\n >>> string_xor('101010', '010101')\n '111111'\n >>> string_xor('000', '000')\n '000'\n \"\"\"\n # Ensure both strings are of the same length\n if len(a) != len(b):\n raise ValueError(\"Input strings must be of the same length.\")\n \n # Perform XOR operation\n result = []\n for bit_a, bit_b in zip(a, b):\n # XOR operation: 1 if bits are different, 0 if they are the same\n result.append('1' if bit_a != bit_b else '0')\n \n return ''.join(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lower_string = string.lower()\n # Use a set to find distinct characters\n distinct_characters = set(lower_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n \n Args:\n strings (List[str]): A list of strings to filter.\n prefix (str): The prefix to filter the strings by.\n \n Returns:\n List[str]: A list of strings that start with the given prefix.\n \n Examples:\n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n \"\"\"\n return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted = []\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Calculate the new character with a shift of 4 (2 * 2)\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a')) if char.islower() else \\\n chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n encrypted.append(new_char)\n else:\n encrypted.append(char) # Non-alphabetic characters remain unchanged\n return ''.join(encrypted)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n \n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n \"\"\"\n return [x + 1 for x in l]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n \"\"\"Given length of a side and height, return the area of a triangle.\n \n The area of a triangle can be calculated using the formula:\n area = (base * height) / 2\n \n Parameters:\n a (float): The length of the base of the triangle.\n h (float): The height of the triangle.\n \n Returns:\n float: The area of the triangle.\n \n >>> triangle_area(5, 3)\n 7.5\n >>> triangle_area(10, 2)\n 10.0\n >>> triangle_area(0, 5)\n 0.0\n >>> triangle_area(5, 0)\n 0.0\n \"\"\"\n return (a * h) / 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n \n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by row index (ascending) and then by column index (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n \"\"\"\n Given an array arr of integers, find the minimum number of elements that\n need to be changed to make the array palindromic. A palindromic array is an array that\n is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n For example:\n smallest_change([1,2,3,5,4,7,9,6]) == 4\n smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n smallest_change([1, 2, 3, 2, 1]) == 0\n \"\"\"\n n = len(arr)\n changes = 0\n \n # Compare elements from the start and end towards the center\n for i in range(n // 2):\n if arr[i] != arr[n - 1 - i]:\n changes += 1\n \n return changes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n else:\n return lst2", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": [[["happy", "birthday", "sarah"], ["happy", "birthday", "sally"]]]}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n \"\"\"You are given a string s.\n Your task is to check if the string is happy or not.\n A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n \n For example:\n is_happy('a') => False\n is_happy('aa') => False\n is_happy('abcd') => True\n is_happy('aabb') => False\n is_happy('adb') => True\n is_happy('xyy') => False\n \"\"\"\n # Check if the length of the string is at least 3\n if len(s) < 3:\n return False\n \n # Check every 3 consecutive characters\n for i in range(len(s) - 2):\n if len(set(s[i:i+3])) < 3: # If there are not 3 distinct characters\n return False\n \n return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" Input to this function is a string representing musical notes in a special ASCII format.\n Your task is to parse this string and return list of integers corresponding to how many beats does each\n note last.\n\n Here is a legend:\n 'o' - whole note, lasts four beats\n 'o|' - half note, lasts two beats\n '.|' - quarter note, lasts one beat\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n # Define a mapping from note representation to beats\n note_to_beats = {\n 'o': 4,\n 'o|': 2,\n '.|': 1\n }\n \n # Split the input string into individual notes\n notes = music_string.split()\n \n # Parse each note and convert to beats\n beats = [note_to_beats[note] for note in notes if note in note_to_beats]\n \n return beats", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string.\n \n Args:\n strings (List[str]): A list of strings to concatenate.\n \n Returns:\n str: A single concatenated string.\n \n Examples:\n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n \"\"\"\n return ''.join(strings)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n \n >>> make_palindrome('')\n ''\n >>> make_palindrome('cat')\n 'catac'\n >>> make_palindrome('cata')\n 'catac'\n \"\"\"\n # Find the longest palindromic suffix\n for i in range(len(string)):\n if is_palindrome(string[i:]):\n # If the suffix is a palindrome, we need to append the reverse of the prefix\n prefix = string[:i]\n return string + prefix[::-1]\n return string # In case the string is empty or already a palindrome", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n \n # Create a new list with elements that occur only once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n \"\"\" \n Input is a space-delimited string of numerals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest.\n \n >>> sort_numbers('three one five')\n 'one three five'\n \"\"\"\n # Mapping of words to their corresponding numeric values\n num_map = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n \n # Split the input string into words\n words = numbers.split()\n \n # Sort the words based on their numeric values\n sorted_words = sorted(words, key=lambda word: num_map[word])\n \n # Join the sorted words back into a string\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n letter_grades = []\n \n for gpa in grades:\n if gpa == 4.0:\n letter_grades.append('A+')\n elif gpa > 3.7:\n letter_grades.append('A')\n elif gpa > 3.3:\n letter_grades.append('A-')\n elif gpa > 3.0:\n letter_grades.append('B+')\n elif gpa > 2.7:\n letter_grades.append('B')\n elif gpa > 2.3:\n letter_grades.append('B-')\n elif gpa > 2.0:\n letter_grades.append('C+')\n elif gpa > 1.7:\n letter_grades.append('C')\n elif gpa > 1.3:\n letter_grades.append('C-')\n elif gpa > 1.0:\n letter_grades.append('D+')\n elif gpa > 0.7:\n letter_grades.append('D')\n elif gpa > 0.0:\n letter_grades.append('D-')\n else:\n letter_grades.append('E')\n \n return letter_grades", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1.\n \n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n min_val = min(numbers)\n max_val = max(numbers)\n \n # Avoid division by zero if all numbers are the same\n if min_val == max_val:\n return [0.0] * len(numbers)\n \n return [(num - min_val) / (max_val - min_val) for num in numbers]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef get_primes_up_to(n):\n \"\"\"Return a list of all prime numbers less than n.\"\"\"\n return [i for i in range(2, n) if is_prime(i)]\ndef is_multiply_prime(a):\n \"\"\"Return true if the given number is the multiplication of 3 prime numbers, false otherwise.\"\"\"\n if a >= 100:\n return False\n \n primes = get_primes_up_to(a)\n prime_count = len(primes)\n \n # Check all combinations of three primes\n for i in range(prime_count):\n for j in range(i, prime_count):\n for k in range(j, prime_count):\n product = primes[i] * primes[j] * primes[k]\n if product == a:\n return True\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n '''\n Write a function that returns True if the object q will fly, and False otherwise.\n The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n\n Example:\n will_it_fly([1, 2], 5) \u279e False \n # 1+2 is less than the maximum possible weight, but it's unbalanced.\n\n will_it_fly([3, 2, 3], 1) \u279e False\n # it's balanced, but 3+2+3 is more than the maximum possible weight.\n\n will_it_fly([3, 2, 3], 9) \u279e True\n # 3+2+3 is less than the maximum possible weight, and it's balanced.\n\n will_it_fly([3], 5) \u279e True\n # 3 is less than the maximum possible weight, and it's balanced.\n '''\n # Check if the list is a palindrome\n is_balanced = q == q[::-1]\n \n # Calculate the sum of the elements in the list\n total_weight = sum(q)\n \n # Return True if it's balanced and the total weight is less than or equal to w\n return is_balanced and total_weight <= w", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words while preserving spaces\n words = s.split(' ')\n \n # Sort each word and keep the spaces intact\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back with spaces\n result = ' '.join(sorted_words)\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion.\n base numbers are less than 10.\n \n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n \"\"\"\n if base < 2 or base >= 10:\n raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n \n if x == 0:\n return '0'\n \n result = []\n while x > 0:\n result.append(str(x % base))\n x //= base\n \n return ''.join(reversed(result))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n or sort it in descending order if the sum( first index value, last index value) is even.\n\n Note:\n * don't change the given array.\n\n Examples:\n * sort_array([]) => []\n * sort_array([5]) => [5]\n * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n \"\"\"\n if not array: # Check for empty array\n return []\n \n first_value = array[0]\n last_value = array[-1]\n sum_values = first_value + last_value\n\n # Create a copy of the array to sort\n sorted_array = array.copy()\n\n if sum_values % 2 == 0: # Even sum\n sorted_array.sort(reverse=True) # Sort in descending order\n else: # Odd sum\n sorted_array.sort() # Sort in ascending order\n\n return sorted_array", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in lower \n case or all keys are strings in upper case, else return False.\n The function should return False if the given dictionary is empty.\n \n Examples:\n check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n \"\"\"\n if not input_dict:\n return False\n\n keys = input_dict.keys()\n \n # Check if all keys are strings\n if not all(isinstance(key, str) for key in keys):\n return False\n\n # Check if all keys are lower case or all are upper case\n all_lower = all(key.islower() for key in keys)\n all_upper = all(key.isupper() for key in keys)\n\n return all_lower or all_upper", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n \n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n \"\"\"\n seen = set()\n for number in l:\n if -number in seen:\n return True\n seen.add(number)\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"(\" and \")\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"(\")\n False\n >>> correct_bracketing(\"()\")\n True\n >>> correct_bracketing(\"(()())\")\n True\n >>> correct_bracketing(\")(()\")\n False\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n # If balance goes negative, there are unmatched closing brackets\n if balance < 0:\n return False\n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n \"\"\"Task\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n \"\"\"\n return sum(ord(char) for char in s if char.isupper())", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n '''\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n \n Examples\n any_int(5, 2, 7) \u279e True\n \n any_int(3, 2, 2) \u279e False\n\n any_int(3, -2, 1) \u279e True\n \n any_int(3.6, -2.2, 2) \u279e False\n '''\n # Check if all inputs are integers\n if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n # Check if one number is equal to the sum of the other two\n return x == y + z or y == x + z or z == x + y\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n # Keep dividing n by factor until it is no longer divisible\n while n > 1:\n if n % factor == 0:\n n //= factor # Divide n by the factor\n else:\n factor += 1 # Move to the next potential factor\n return factor # The last factor is the largest prime factor", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n \"\"\"Return True if list elements are monotonically increasing or decreasing.\n \n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n \"\"\"\n if not l: # An empty list is considered monotonic\n return True\n \n increasing = decreasing = True\n \n for i in range(1, len(l)):\n if l[i] > l[i - 1]:\n decreasing = False\n elif l[i] < l[i - 1]:\n increasing = False\n \n return increasing or decreasing", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n \"\"\"\n Takes as input string encoded with encode_shift function. Returns decoded string.\n \"\"\"\n return \"\".join([chr(((ord(ch) - ord(\"a\") - 5) % 26) + ord(\"a\")) for ch in s])", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n \"\"\"\n Given an array representing a branch of a tree that has non-negative integer nodes,\n your task is to pluck one of the nodes and return it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n The plucked node should be returned in a list, [ smallest_value, its index ],\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index. \n\n Example 3:\n Input: []\n Output: []\n \n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n Explanation: 0 is the smallest value, but there are two zeros,\n so we will choose the first zero, which has the smallest index.\n\n Constraints:\n * 1 <= nodes.length <= 10000\n * 0 <= node.value\n \"\"\"\n smallest_even = float('inf')\n smallest_index = -1\n\n for index, value in enumerate(arr):\n if value % 2 == 0: # Check if the value is even\n if value < smallest_even: # Check if it's the smallest even found\n smallest_even = value\n smallest_index = index\n\n if smallest_index == -1: # No even value found\n return []\n \n return [smallest_even, smallest_index]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float) -> float:\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list) -> list:\n \"\"\"\n Computes the derivative of the polynomial with coefficients xs.\n \"\"\"\n return [i * coeff for i, coeff in enumerate(xs) if i > 0]\ndef find_zero(xs: list, initial_guess: float = 0.0, tolerance: float = 1e-7, max_iterations: int = 1000) -> float:\n \"\"\" \n xs are coefficients of a polynomial.\n find_zero finds x such that poly(x) = 0.\n find_zero returns only one zero point, even if there are many.\n Moreover, find_zero only takes list xs having an even number of coefficients\n and the largest non-zero coefficient as it guarantees a solution.\n \n >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n -0.5\n >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n 1.0\n \"\"\"\n if len(xs) % 2 != 0:\n raise ValueError(\"The number of coefficients must be even.\")\n \n current_guess = initial_guess\n for _ in range(max_iterations):\n f_value = poly(xs, current_guess)\n f_derivative = poly(derivative(xs), current_guess)\n \n if f_derivative == 0:\n raise ValueError(\"Derivative is zero. No solution found.\")\n \n next_guess = current_guess - f_value / f_derivative\n \n if abs(next_guess - current_guess) < tolerance:\n return next_guess\n \n current_guess = next_guess\n \n raise ValueError(\"Maximum iterations reached. No solution found.\")", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[[5, 10, -3, 1]]]}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n \"\"\"Return maximum element in the list.\n \n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n \"\"\"\n if not l: # Check if the list is empty\n raise ValueError(\"The list is empty.\")\n \n max_value = l[0] # Initialize max_value with the first element\n for item in l:\n if item > max_value:\n max_value = item\n return max_value", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" brackets is a string of \"<\" and \">\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"<\")\n False\n >>> correct_bracketing(\"<>\")\n True\n >>> correct_bracketing(\"<<><>>\")\n True\n >>> correct_bracketing(\"><<>\")\n False\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '<':\n balance += 1\n elif char == '>':\n balance -= 1\n # If balance goes negative, there are more closing brackets\n if balance < 0:\n return False\n # At the end, balance should be zero for correct bracketing\n return balance == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n '''\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequency greater than or equal to the value of the integer itself. \n The frequency of an integer is the number of times it appears in the list.\n If no such a value exist, return -1.\n \n Examples:\n search([4, 1, 2, 2, 3, 1]) == 2\n search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n search([5, 5, 4, 4, 4]) == -1\n '''\n from collections import Counter\n \n # Count the frequency of each number in the list\n frequency = Counter(lst)\n \n # Initialize the result variable\n result = -1\n \n # Iterate through the frequency dictionary\n for num, freq in frequency.items():\n # Check if the frequency is greater than or equal to the number itself\n if freq >= num:\n # Update the result if this number is greater than the current result\n result = max(result, num)\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n \"\"\"Calculate the factorial of a non-negative integer n.\"\"\"\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef special_factorial(n):\n \"\"\"Calculate the Brazilian factorial of n.\"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n result = 1\n for i in range(1, n + 1):\n result *= factorial(i)\n \n return result", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[496]]}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n \"\"\"\n Write a function that takes a message, and encodes in such a \n way that it swaps case of all letters, replaces all vowels in \n the message with the letter that appears 2 places ahead of that \n vowel in the english alphabet. \n Assume only letters. \n \n Examples:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n vowels = 'aeiouAEIOU'\n encoded_message = []\n\n for char in message:\n if char.isalpha(): # Check if the character is a letter\n # Swap case\n if char in vowels:\n # Replace vowel with the letter 2 places ahead\n if char.islower():\n new_char = chr(((ord(char) - ord('a') + 2) % 26) + ord('a'))\n else:\n new_char = chr(((ord(char) - ord('A') + 2) % 26) + ord('A'))\n else:\n new_char = char.swapcase() # Swap case for consonants\n encoded_message.append(new_char)\n else:\n encoded_message.append(char) # Keep non-letter characters unchanged\n\n return ''.join(encoded_message)", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["TEST"]], "plus_fail_tests": [["abcdefghijklmnopqrstuvwxyz"]]}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n \"\"\"\n Calculate the number of mango fruits in a basket given the number of apples and oranges.\n\n Parameters:\n s (str): A string representing the number of apples and oranges in the format \"X apples and Y oranges\".\n n (int): An integer representing the total number of fruits in the basket.\n\n Returns:\n int: The number of mango fruits in the basket.\n \"\"\"\n # Split the input string to extract the number of apples and oranges\n parts = s.split()\n apples = int(parts[0]) # The first part is the number of apples\n oranges = int(parts[2]) # The third part is the number of oranges\n\n # Calculate the number of mangoes\n mangoes = n - apples - oranges\n return mangoes", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["5 apples and 6 oranges", 19]], "plus_fail_tests": [["10 apples and 20 oranges", 50]]}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n \n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n \"\"\"\n return n * (n + 1) // 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(divisible_by_three)\n \n # Create a new list to hold the result\n result = l.copy()\n \n # Replace values at indices divisible by 3 with sorted values\n for index, value in zip((i for i in range(len(l)) if i % 3 == 0), sorted_values):\n result[index] = value\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n Example\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n \"\"\"\n # Initialize variables to track the minimum sum and the current sum\n min_sum = float('inf')\n current_sum = 0\n \n for num in nums:\n current_sum += num\n min_sum = min(min_sum, current_sum)\n \n # If current_sum is positive, reset it to 0\n if current_sum > 0:\n current_sum = 0\n \n return min_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for char in s if char in '13579') # Count odd digits\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n '''\n Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n \n Examples:\n split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"abcdef\") \u279e 3 \n '''\n # Check for whitespace in the text\n if ' ' in txt:\n return txt.split()\n \n # Check for commas in the text\n elif ',' in txt:\n return txt.split(',')\n \n # If no whitespace or commas, count lower-case letters with odd order\n else:\n odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n return odd_count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n \"\"\"\n Given a non-empty array of integers arr and an integer k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example:\n\n Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n Output: 24 # sum of 21 + 3\n\n Constraints:\n 1. 1 <= len(arr) <= 100\n 2. 1 <= k <= len(arr)\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate through the first k elements of the array\n for i in range(k):\n # Check if the element has at most two digits\n if -100 < arr[i] < 100:\n total_sum += arr[i]\n \n return total_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length and alphabetically.\n \n Args:\n lst (list of str): A list of strings.\n \n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n as follows: start with any positive integer n. Then each term is obtained from the \n previous term as follows: if the previous term is even, the next term is one half of \n the previous term. If the previous term is odd, the next term is 3 times the previous\n term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n Note: \n 1. Collatz(1) is [1].\n 2. returned list sorted in increasing order.\n\n For example:\n get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n collatz_sequence = []\n current = n\n \n while current != 1:\n collatz_sequence.append(current)\n if current % 2 == 0:\n current //= 2\n else:\n current = 3 * current + 1\n \n collatz_sequence.append(1) # Add the last term which is 1\n \n # Filter odd numbers and sort them\n odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n \n return odd_numbers", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n \"\"\"\n Given a string text, replace all spaces in it with underscores, \n and if a string has more than 2 consecutive spaces, \n then replace all consecutive spaces with - \n \n fix_spaces(\"Example\") == \"Example\"\n fix_spaces(\"Example 1\") == \"Example_1\"\n fix_spaces(\" Example 2\") == \"_Example_2\"\n fix_spaces(\" Example 3\") == \"_Example-3\"\n \"\"\"\n import re\n\n # Replace more than 2 consecutive spaces with a single '-'\n text = re.sub(r' {3,}', '-', text)\n \n # Replace single spaces with underscores\n text = text.replace(' ', '_')\n \n return text", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n \n The date is valid if all of the following rules are satisfied:\n 1. The date string is not empty.\n 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n The number of days is not less than 1 or higher than 29 for the month 2.\n 3. The months should not be less than 1 or higher than 12.\n 4. The date should be in the format: mm-dd-yyyy\n \n Args:\n date (str): The date string to validate.\n \n Returns:\n bool: True if the date is valid, False otherwise.\n \"\"\"\n if not date:\n return False\n \n # Check the format\n parts = date.split('-')\n if len(parts) != 3:\n return False\n \n if not all(part.isdigit() for part in parts):\n return False\n \n month, day, year = map(int, parts)\n \n # Validate month\n if month < 1 or month > 12:\n return False\n \n # Validate day based on month\n if month in {1, 3, 5, 7, 8, 10, 12}:\n if day < 1 or day > 31:\n return False\n elif month in {4, 6, 9, 11}:\n if day < 1 or day > 30:\n return False\n elif month == 2:\n if day < 1 or day > 29:\n return False\n \n return True", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["06-04-202"]]}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n \"\"\"Task\n We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and True/False for the check.\n Example\n For s = \"abcde\", c = \"ae\", the result should be ('bcd',False)\n For s = \"abcdef\", c = \"b\" the result should be ('acdef',False)\n For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc',True)\n \"\"\"\n # Create a set of characters to delete for faster lookup\n delete_set = set(c)\n \n # Create the result string by filtering out characters in delete_set\n result = ''.join(char for char in s if char not in delete_set)\n \n # Check if the result string is a palindrome\n is_palindrome = result == result[::-1]\n \n return (result, is_palindrome)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n \"\"\"\n Calculate the number of times buckets need to be lowered to empty the wells.\n\n Parameters:\n grid (list of list of int): A rectangular grid representing wells.\n capacity (int): The capacity of each bucket.\n\n Returns:\n int: The total number of times buckets need to be lowered.\n \"\"\"\n total_water = 0\n \n # Count the total amount of water in the grid\n for row in grid:\n total_water += sum(row)\n \n # Calculate the number of times buckets need to be lowered\n # Each bucket can carry 'capacity' units of water\n if total_water == 0:\n return 0\n else:\n return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": [[[[1, 0, 0, 1], [0, 1, 1, 1], [0, 0, 0, 0], [1, 0, 1, 1]], 2]]}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n \"\"\"Create a function which takes a string representing a file's name, and returns\n 'Yes' if the the file's name is valid, and returns 'No' otherwise.\n A file's name is considered to be valid if and only if all the following conditions \n are met:\n - There should not be more than three digits ('0'-'9') in the file's name.\n - The file's name contains exactly one dot '.'\n - The substring before the dot should not be empty, and it starts with a letter from \n the latin alphapet ('a'-'z' and 'A'-'Z').\n - The substring after the dot should be one of these: ['txt', 'exe', 'dll']\n Examples:\n file_name_check(\"example.txt\") # => 'Yes'\n file_name_check(\"1example.dll\") # => 'No' (the name should start with a latin alphapet letter)\n \"\"\"\n \n # Split the file name into name and extension\n if file_name.count('.') != 1:\n return 'No'\n \n name, extension = file_name.split('.')\n \n # Check if the name is empty or starts with a non-alphabet character\n if not name or not name[0].isalpha():\n return 'No'\n \n # Check if the extension is valid\n valid_extensions = ['txt', 'exe', 'dll']\n if extension not in valid_extensions:\n return 'No'\n \n # Count the number of digits in the file name\n digit_count = sum(c.isdigit() for c in file_name)\n if digit_count > 3:\n return 'No'\n \n return 'Yes'", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n \"\"\"Write a function that takes an array of numbers as input and returns \n the number of elements in the array that are greater than 10 and both \n first and last digits of a number are odd (1, 3, 5, 7, 9).\n \n For example:\n specialFilter([15, -73, 14, -15]) => 1 \n specialFilter([33, -2, -3, 45, 21, 109]) => 2\n \"\"\"\n \n def is_odd_digit(digit):\n return digit in {'1', '3', '5', '7', '9'}\n \n def first_and_last_odd(num):\n str_num = str(abs(num)) # Convert to string and take absolute value\n return is_odd_digit(str_num[0]) and is_odd_digit(str_num[-1])\n \n count = 0\n for num in nums:\n if num > 10 and first_and_last_odd(num):\n count += 1\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closest to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sorted by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct planet names. \n Examples\n bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n '''\n \n planets = [\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n ]\n \n if planet1 not in planets or planet2 not in planets:\n return ()\n \n index1 = planets.index(planet1)\n index2 = planets.index(planet2)\n \n # Ensure index1 is less than index2 for slicing\n start_index = min(index1, index2) + 1\n end_index = max(index1, index2)\n \n return tuple(planets[start_index:end_index])", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers.\n You need to return the sum of squared numbers in the given list,\n round each element in the list to the upper int (Ceiling) first.\n \n Examples:\n For lst = [1,2,3] the output should be 14\n For lst = [1,4,9] the output should be 98\n For lst = [1,3,5,7] the output should be 84\n For lst = [1.4,4.2,0] the output should be 29\n For lst = [-2.4,1,1] the output should be 6\n \"\"\"\n return sum(math.ceil(x) ** 2 for x in lst)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n '''\n Create a function that returns True if the last character\n of a given string is an alphabetical character and is not\n a part of a word, and False otherwise.\n Note: \"word\" is a group of characters separated by space.\n\n Examples:\n check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '''\n # Strip any trailing whitespace from the string\n txt = txt.rstrip()\n \n # Check if the string is empty after stripping\n if not txt:\n return False\n \n # Split the string into words\n words = txt.split()\n \n # Get the last character of the last word\n last_word = words[-1]\n \n # Check if the last character is a letter and if the last word has only one character\n if len(last_word) == 1 and last_word.isalpha():\n return True\n \n return False", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["eeeee e "]], "plus_fail_tests": [["apple pi\ne"]]}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n \"\"\"This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If \n there's no such number, then the function should return -1.\n\n For example:\n choose_num(12, 15) = 14\n choose_num(13, 12) = -1\n \"\"\"\n # Ensure x is less than or equal to y\n if x > y:\n return -1\n \n # Start from the largest number in the range and check for evenness\n for num in range(y, x - 1, -1):\n if num % 2 == 0:\n return num\n \n return -1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to make it easier to find close elements\n numbers.sort()\n \n # Check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n reverse the resulting array, and then replace each digit by its corresponding name from\n \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n For example:\n arr = [2, 1, 1, 4, 5, 8, 2, 3] \n -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n \n If the array is empty, return an empty array:\n arr = []\n return []\n \n If the array has any strange number ignore it:\n arr = [1, -1 , 55] \n -> sort arr -> [-1, 1, 55]\n -> reverse arr -> [55, 1, -1]\n return = ['One']\n \"\"\"\n \n # Mapping of digits to their corresponding names\n digit_to_name = {\n 1: \"One\", 2: \"Two\", 3: \"Three\", 4: \"Four\",\n 5: \"Five\", 6: \"Six\", 7: \"Seven\", 8: \"Eight\", 9: \"Nine\"\n }\n \n # Filter the array to include only numbers between 1 and 9\n filtered_arr = [num for num in arr if 1 <= num <= 9]\n \n # Sort the filtered array\n sorted_arr = sorted(filtered_arr)\n \n # Reverse the sorted array\n reversed_arr = sorted_arr[::-1]\n \n # Convert the digits to their corresponding names\n result = [digit_to_name[num] for num in reversed_arr]\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n \"\"\"\n return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n if not (1 <= number <= 1000):\n raise ValueError(\"Number must be between 1 and 1000\")\n\n roman_numerals = [\n (1000, 'm'),\n (900, 'cm'),\n (500, 'd'),\n (400, 'cd'),\n (100, 'c'),\n (90, 'xc'),\n (50, 'l'),\n (40, 'xl'),\n (10, 'x'),\n (9, 'ix'),\n (5, 'v'),\n (4, 'iv'),\n (1, 'i')\n ]\n\n result = []\n for value, numeral in roman_numerals:\n while number >= value:\n result.append(numeral)\n number -= value\n\n return ''.join(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n \n double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n double_the_difference([-1, -2, 0]) == 0\n double_the_difference([9, -2]) == 81\n double_the_difference([0]) == 0 \n \n If the input list is empty, return 0.\n '''\n if not lst: # Check if the list is empty\n return 0\n \n sum_of_squares = 0\n for num in lst:\n if isinstance(num, int) and num >= 0 and num % 2 != 0: # Check if num is a non-negative odd integer\n sum_of_squares += num ** 2 # Add the square of the odd number to the sum\n \n return sum_of_squares", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic algebra operations, and \n the second list is a list of integers. Use the two given lists to build the algebraic \n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + ) \n Subtraction ( - ) \n Multiplication ( * ) \n Floor division ( // ) \n Exponentiation ( ** ) \n\n Example:\n operator = ['+', '*', '-']\n operand = [2, 3, 4, 5]\n result = 2 + 3 * 4 - 5\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.\n \"\"\"\n # Start with the first operand\n result = operand[0]\n \n # Iterate through the operators and operands\n for i in range(len(operator)):\n op = operator[i]\n next_operand = operand[i + 1]\n \n if op == '+':\n result += next_operand\n elif op == '-':\n result -= next_operand\n elif op == '*':\n result *= next_operand\n elif op == '//':\n result //= next_operand\n elif op == '**':\n result **= next_operand\n else:\n raise ValueError(f\"Unsupported operator: {op}\")\n \n return result", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": [[["+", "-", "*", "//"], [5, 2, 3, 4, 7]]]}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n \"\"\"Write a function that accepts a list of strings.\n The list contains different words. Return the word with maximum number\n of unique characters. If multiple strings have maximum number of unique\n characters, return the one which comes first in lexicographical order.\n\n find_max([\"name\", \"of\", \"string\"]) == \"string\"\n find_max([\"name\", \"enam\", \"game\"]) == \"enam\"\n find_max([\"aaaaaaa\", \"bb\" ,\"cc\"]) == \"aaaaaaa\"\n \"\"\"\n max_word = \"\"\n max_unique_count = 0\n\n for word in words:\n unique_chars = set(word)\n unique_count = len(unique_chars)\n\n if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n max_word = word\n max_unique_count = unique_count\n\n return max_word", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n \"\"\"Given a list of positive integers x, return a sorted list of all \n elements that haven't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n def has_even_digit(n):\n \"\"\"Check if the number has any even digit.\"\"\"\n return any(int(digit) % 2 == 0 for digit in str(n))\n\n # Filter the list to include only numbers without even digits\n result = [num for num in x if not has_even_digit(num)]\n \n # Return the sorted result\n return sorted(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n \"\"\"\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example :\n Input: n = 5\n Output: 1\n Explanation: \n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n \"\"\"\n # Create the array a\n a = [i * i - i + 1 for i in range(1, n + 1)]\n \n # Count the number of valid triples\n count = 0\n \n # Check all combinations of triples (i, j, k) with i < j < k\n for i in range(n):\n for j in range(i + 1, n):\n for k in range(j + 1, n):\n if (a[i] + a[j] + a[k]) % 3 == 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n def max_nesting_depth(s: str) -> int:\n max_depth = 0\n current_depth = 0\n for char in s:\n if char == '(':\n current_depth += 1\n max_depth = max(max_depth, current_depth)\n elif char == ')':\n current_depth -= 1\n return max_depth\n\n groups = paren_string.split()\n return [max_nesting_depth(group) for group in groups]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef sum_of_digits(n):\n \"\"\"Return the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n largest_prime = -1\n \n for number in lst:\n if is_prime(number) and number > largest_prime:\n largest_prime = number\n \n if largest_prime == -1:\n return 0 # Return 0 if no prime is found\n \n return sum_of_digits(largest_prime)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" \n Input to this function is a string containing multiple groups of nested parentheses. \n Your goal is to separate those groups into separate strings and return the list of those.\n Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n Ignore any spaces in the input string.\n \n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n # Remove spaces from the input string\n paren_string = paren_string.replace(\" \", \"\")\n \n result = []\n balance = 0\n current_group = []\n \n for char in paren_string:\n if char == '(':\n if balance == 0 and current_group:\n # If we are starting a new group, save the current one\n result.append(''.join(current_group))\n current_group = []\n current_group.append(char)\n balance += 1\n elif char == ')':\n current_group.append(char)\n balance -= 1\n \n # If balance is zero, we have a complete group\n if balance == 0 and current_group:\n result.append(''.join(current_group))\n current_group = []\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n \"\"\"Create a function which returns the largest index of an element which\n is not greater than or equal to the element immediately preceding it. If\n no such element exists then return -1. The given array will not contain\n duplicate values.\n\n Examples:\n can_arrange([1,2,4,3,5]) = 3\n can_arrange([1,2,3]) = -1\n \"\"\"\n # Iterate through the array from the second element to the end\n for i in range(1, len(arr)):\n # Check if the current element is less than the previous one\n if arr[i] < arr[i - 1]:\n return i # Return the index of the current element\n return -1 # Return -1 if no such element is found", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[4, 8, 5, 7, 3]]], "plus_fail_tests": [[[5, 4, 3, 2, 1]]]}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n \n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n \"\"\"\n if not numbers:\n return (0, 1)\n \n total_sum = sum(numbers)\n total_product = 1\n for number in numbers:\n total_product *= number\n \n return (total_sum, total_product)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n '''\n Create a function that takes a string as input which contains only square brackets.\n The function should return True if and only if there is a valid subsequence of brackets \n where at least one bracket in the subsequence is nested.\n\n is_nested('[[]]') \u279e True\n is_nested('[]]]]]]][[[[[]') \u279e False\n is_nested('[][]') \u279e False\n is_nested('[]') \u279e False\n is_nested('[[][]]') \u279e True\n is_nested('[[]][[') \u279e True\n '''\n stack = []\n nested_found = False\n\n for char in string:\n if char == '[':\n stack.append(char)\n elif char == ']':\n if stack:\n stack.pop()\n if len(stack) > 0: # Check if there is a nested bracket\n nested_found = True\n else:\n return False # Unmatched closing bracket\n\n return nested_found and len(stack) == 0 # Must be balanced and have nested brackets", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["[[]][["]], "plus_fail_tests": [["[[]]]"]]}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n \"\"\"\n You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n \n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n \n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots that exist in stock\n \n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n \"\"\"\n # Calculate how many more carrots are needed\n additional_needed = need - number\n \n # If no additional carrots are needed, return the current state\n if additional_needed <= 0:\n return [number, remaining]\n \n # Determine how many carrots can be eaten from the remaining stock\n eaten = min(additional_needed, remaining)\n \n # Calculate the total eaten and remaining carrots\n total_eaten = number + eaten\n remaining_after_meal = remaining - eaten\n \n return [total_eaten, remaining_after_meal]", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": [[2, 2, 2]]}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n \"\"\"You are given a string s.\n if s[i] is a letter, reverse its case from lower to upper or vise versa, \n otherwise keep it as it is.\n If the string contains no letters, reverse the string.\n The function should return the resulted string.\n \n Examples:\n solve(\"1234\") = \"4321\"\n solve(\"ab\") = \"AB\"\n solve(\"#a@C\") = \"#A@c\"\n \"\"\"\n # Check if there are any letters in the string\n has_letters = any(c.isalpha() for c in s)\n \n if has_letters:\n # Reverse case for letters and keep others the same\n return ''.join(c.swapcase() if c.isalpha() else c for c in s)\n else:\n # Reverse the string if there are no letters\n return s[::-1]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return True if the three\n sides form a right-angled triangle, False otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or \n 90 degree.\n \n Example:\n right_angle_triangle(3, 4, 5) == True\n right_angle_triangle(1, 2, 3) == False\n '''\n # Sort the sides to identify the longest side\n sides = sorted([a, b, c])\n # Check the Pythagorean theorem\n return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef x_or_y(n, x, y):\n \"\"\"Return the value of x if n is a prime number, otherwise return y.\"\"\"\n if is_prime(n):\n return x\n else:\n return y", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n \"\"\"Convert a decimal number to binary format with specific formatting.\n\n Args:\n decimal (int): A non-negative integer to convert to binary.\n\n Returns:\n str: A string representing the binary format of the decimal number,\n prefixed and suffixed with 'db'.\n \n Examples:\n >>> decimal_to_binary(15)\n 'db1111db'\n >>> decimal_to_binary(32)\n 'db100000db'\n \"\"\"\n if decimal < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n # Convert decimal to binary and remove the '0b' prefix\n binary_representation = bin(decimal)[2:]\n \n # Format the output with 'db' at the beginning and end\n formatted_output = f\"db{binary_representation}db\"\n \n return formatted_output", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fib4(0) -> 0\n fib4(1) -> 0\n fib4(2) -> 2\n fib4(3) -> 0\n fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n \n This function computes the n-th element of the fib4 number sequence without using recursion.\n \n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 2\n elif n == 3:\n return 0\n \n # Initialize the first four values of the sequence\n fib_values = [0, 0, 2, 0]\n \n # Compute the values iteratively\n for i in range(4, n + 1):\n next_value = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n fib_values.append(next_value)\n \n return fib_values[n]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n \"\"\"\n Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move at the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.\n\n Parameters:\n n (int): The number of cars in each direction.\n\n Returns:\n int: The total number of collisions.\n \"\"\"\n # Each car moving left to right will collide with each car moving right to left\n # Therefore, the total number of collisions is n * n\n return n * n", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n \"\"\"\n Checks if given string is a palindrome.\n \n A palindrome is a string that reads the same forward and backward.\n \n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n \"\"\"\n # Normalize the string by removing spaces and converting to lowercase\n normalized_text = text.replace(\" \", \"\").lower()\n # Check if the string is equal to its reverse\n return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["never odd or even"]]}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n \"\"\"You are given two positive integers n and m, and your task is to compute the\n average of the integers from n through m (including n and m). \n Round the answer to the nearest integer and convert that to binary.\n If n is greater than m, return -1.\n \n Example:\n rounded_avg(1, 5) => \"0b11\"\n rounded_avg(7, 5) => -1\n rounded_avg(10, 20) => \"0b1111\"\n rounded_avg(20, 33) => \"0b11010\"\n \"\"\"\n if n > m:\n return -1\n \n # Calculate the sum of integers from n to m\n total_sum = sum(range(n, m + 1))\n count = m - n + 1 # Total numbers from n to m\n \n # Calculate the average and round it\n average = total_sum / count\n rounded_average = round(average)\n \n # Convert the rounded average to binary\n return bin(rounded_average)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this integer is a cube of some integer number.\n Note: you may assume the input is always valid.\n \n Examples:\n iscube(1) ==> True\n iscube(2) ==> False\n iscube(-1) ==> True\n iscube(64) ==> True\n iscube(0) ==> True\n iscube(180) ==> False\n '''\n # Calculate the cube root of the absolute value of a\n cube_root = round(abs(a) ** (1/3))\n \n # Check if the cube of the rounded cube root equals the absolute value of a\n return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits will be 1 the output should be \"1\".\n For N = 150, the sum of digits will be 6 the output should be \"110\".\n For N = 147, the sum of digits will be 12 the output should be \"1100\".\n \n Variables:\n @N integer\n Constraints: 0 \u2264 N \u2264 10000.\n Output:\n a string of binary number\n \"\"\"\n # Calculate the sum of the digits of N\n digit_sum = sum(int(digit) for digit in str(N))\n \n # Convert the sum to binary and return it as a string\n return bin(digit_sum)[2:]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n '''\n Given list of integers, return list in strange order.\n Strange sorting, is when you start with the minimum value,\n then maximum of the remaining integers, then minimum and so on.\n\n Examples:\n strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n strange_sort_list([]) == []\n '''\n if not lst:\n return []\n\n sorted_lst = sorted(lst)\n result = []\n left, right = 0, len(sorted_lst) - 1\n\n while left <= right:\n if left == right:\n result.append(sorted_lst[left])\n else:\n result.append(sorted_lst[left])\n result.append(sorted_lst[right])\n left += 1\n right -= 1\n\n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n \"\"\"\n Given a positive integer n, return the count of the numbers of n-digit\n positive integers that start or end with 1.\n \"\"\"\n if n < 1:\n return 0\n\n # Total n-digit numbers\n total_n_digit_numbers = 9 * (10 ** (n - 1))\n\n # Count of n-digit numbers that start with 1\n start_with_1 = 10 ** (n - 1)\n\n # Count of n-digit numbers that end with 1\n end_with_1 = total_n_digit_numbers // 10\n\n # Count of n-digit numbers that start and end with 1\n start_and_end_with_1 = 10 ** (n - 2) if n > 1 else 0\n\n # Using the inclusion-exclusion principle\n count = start_with_1 + end_with_1 - start_and_end_with_1\n\n return count", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[1000000]]}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n \"\"\" Return length of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n \"\"\"\n return len(string)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n \n >>> largest_divisor(15)\n 5\n >>> largest_divisor(28)\n 14\n >>> largest_divisor(1)\n 0\n >>> largest_divisor(10)\n 5\n \"\"\"\n if n <= 1:\n return 0 # No divisors for 1 or less\n \n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n \n >>> longest([])\n >>> None\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n \"\"\"\n if not strings:\n return None\n \n longest_string = strings[0]\n \n for string in strings:\n if len(string) > len(longest_string):\n longest_string = string\n \n return longest_string", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return the area of\n the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n Otherwise return -1.\n Three sides make a valid triangle when the sum of any two sides is greater \n than the third side.\n \n Example:\n triangle_area(3, 4, 5) == 6.00\n triangle_area(1, 2, 10) == -1\n '''\n # Check for valid triangle\n if a + b > c and a + c > b and b + c > a:\n # Calculate the semi-perimeter\n s = (a + b + c) / 2\n # Calculate the area using Heron's formula\n area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n return round(area, 2)\n else:\n return -1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n result = 1\n base = 2 % p # Start with 2 mod p\n while n > 0:\n if n % 2 == 1: # If n is odd, multiply the base with the result\n result = (result * base) % p\n base = (base * base) % p # Square the base\n n //= 2 # Divide n by 2\n return result", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[0, 1]]}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef prime_length(string):\n \"\"\"Return True if the string length is a prime number, False otherwise.\"\"\"\n length = len(string)\n return is_prime(length)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n \"\"\"\n triples_sum_to_zero takes a list of integers as an input.\n it returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n \"\"\"\n n = len(l)\n # Sort the list to use the two-pointer technique\n l.sort()\n \n for i in range(n - 2):\n # Avoid duplicates for the first element\n if i > 0 and l[i] == l[i - 1]:\n continue\n \n left, right = i + 1, n - 1\n while left < right:\n current_sum = l[i] + l[left] + l[right]\n if current_sum == 0:\n return True\n elif current_sum < 0:\n left += 1\n else:\n right -= 1\n \n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n \"\"\"Returns True if x is a simple power of n, otherwise False.\n \n A number x is a simple power of n if there exists an integer k such that n**k = x.\n \n Args:\n x (int): The number to check.\n n (int): The base to check against.\n \n Returns:\n bool: True if x is a simple power of n, False otherwise.\n \"\"\"\n if n <= 1:\n return x == 1 # 1 is a power of any number, and no other number can be a power of 1 or 0.\n \n power = 1\n while True:\n result = n ** power\n if result == x:\n return True\n elif result > x:\n return False\n power += 1", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[1, 12]], "plus_fail_tests": [[1, 4]]}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n \"\"\"Counts the number of prime hexadecimal digits in the given hexadecimal string.\"\"\"\n # Define the set of prime hexadecimal digits\n prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n \n # Count the number of prime hexadecimal digits in the input string\n count = sum(1 for digit in num if digit in prime_hex_digits)\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n \"\"\"Return median of elements in the list l.\n \n The median is the middle value in a list of numbers. If the list has an even number of elements,\n the median is the average of the two middle numbers.\n \n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty\")\n \n sorted_list = sorted(l)\n n = len(sorted_list)\n mid = n // 2\n \n if n % 2 == 0: # Even number of elements\n return (sorted_list[mid - 1] + sorted_list[mid]) / 2\n else: # Odd number of elements\n return sorted_list[mid]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return a greatest common divisor of two integers a and b\n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n \"\"\"\n while b:\n a, b = b, a % b\n return abs(a)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string\n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n \"\"\"\n return [string[:i] for i in range(1, len(string) + 1)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers\n >>> filter_integers(['a', 3.14, 5])\n [5]\n >>> filter_integers([1, 2, 3, 'abc', {}, []])\n [1, 2, 3]\n \"\"\"\n return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[[true, false, null, 0, -10, "test", [], {}, 3.14]]]}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n Input number should be equal to the product of all factors\n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n \"\"\"\n factors = []\n # Check for number of 2s that divide n\n while n % 2 == 0:\n factors.append(2)\n n //= 2\n \n # n must be odd at this point so a skip of 2 (i.e., i = i + 2) can be used\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, append i and divide n\n while n % i == 0:\n factors.append(i)\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n factors.append(n)\n \n return factors", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with the encode_cyclic function.\n Returns the decoded string.\n \"\"\"\n # Split string into groups of length 3\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # Reverse the cycling of elements in each group\n groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n A prime number is a natural number greater than 1 that cannot be formed by multiplying two smaller natural numbers.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n \n >>> circular_shift(12, 1)\n '21'\n >>> circular_shift(12, 2)\n '12'\n >>> circular_shift(12345, 1)\n '51234'\n >>> circular_shift(12345, 5)\n '54321'\n >>> circular_shift(12345, 6)\n '54321'\n \"\"\"\n # Convert the integer to a string to manipulate its digits\n str_x = str(x)\n length = len(str_x)\n \n # If shift is greater than the number of digits, reverse the string\n if shift >= length:\n return str_x[::-1]\n \n # Calculate the effective shift\n effective_shift = shift % length\n \n # Perform the circular shift\n shifted = str_x[-effective_shift:] + str_x[:-effective_shift]\n \n return shifted", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[12, 2]], "plus_fail_tests": [[987654321, 9]]}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n \n For example:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n >>> is_bored(\"I am happy! Are you? I will go now.\")\n 2\n >>> is_bored(\"What a day. I can't believe it! I am so excited.\")\n 2\n \"\"\"\n # Split the string into sentences using the delimiters\n sentences = [s.strip() for s in S.replace('!', '.').replace('?', '.').split('.')]\n \n # Count sentences that start with \"I\"\n boredom_count = sum(1 for sentence in sentences if sentence.startswith(\"I\"))\n \n return boredom_count", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": [["In the morning, I like to have a cup of coffee to start my day off right. How about you?"]]}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n \"\"\" \n xs represent coefficients of a polynomial.\n xs[0] + xs[1] * x + xs[2] * x^2 + ....\n Return derivative of this polynomial in the same form.\n \n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n \"\"\"\n # The derivative of a polynomial is calculated by multiplying each coefficient\n # by its corresponding power and reducing the power by one.\n return [i * coeff for i, coeff in enumerate(xs[1:], start=1)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_up_to(n):\n \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n primes = []\n for i in range(2, n):\n if is_prime(i):\n primes.append(i)\n return primes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two words have the same characters if they contain the same unique characters,\n regardless of the number of times each character appears.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n \"\"\"Add two numbers x and y.\n \n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n \"\"\"\n return x + y", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n count_upper('aBCdEf') returns 1\n count_upper('abcdefg') returns 0\n count_upper('dBBE') returns 0\n \"\"\"\n uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n count = 0\n \n for i in range(0, len(s), 2): # Iterate over even indices\n if s[i] in uppercase_vowels:\n count += 1\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n \n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n \"\"\"\n return [x for x in l if x > 0]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n even_indices = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indexed elements\n even_indices.sort()\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Place the sorted even indexed elements back into their positions\n for i, value in enumerate(even_indices):\n result[i * 2] = value\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_fib(n: int) -> int:\n \"\"\"\n prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n count = 0\n for fib in fibonacci_generator():\n if is_prime(fib):\n count += 1\n if count == n:\n return fib", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[1]], "plus_fail_tests": [[11]]}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n \"\"\"Return True if all numbers in the list l are below threshold t.\n \n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n \"\"\"\n return all(x < t for x in l)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n >>> closest_integer(\"14.5\")\n 15\n >>> closest_integer(\"-14.5\")\n -15\n >>> closest_integer(\"0.5\")\n 1\n >>> closest_integer(\"-0.5\")\n -1\n '''\n # Convert the string to a float\n num = float(value)\n \n # Use the built-in round function with a custom rounding strategy\n if num > 0:\n return int(num + 0.5) # Round up for positive numbers\n elif num < 0:\n return int(num - 0.5) # Round down for negative numbers\n else:\n return 0 # Return 0 for the input \"0\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n \"\"\"Return n-th Fibonacci number.\n \n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n elif n == 1:\n return 1\n elif n == 2:\n return 1\n else:\n a, b = 1, 1\n for _ in range(2, n):\n a, b = b, a + b\n return b", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[0]]}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n \n Args:\n n (int): The index of the FibFib number to compute.\n \n Returns:\n int: The n-th FibFib number.\n \n Examples:\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 1\n \n # Initialize the first three FibFib numbers\n fibfib_numbers = [0, 0, 1]\n \n # Compute FibFib numbers iteratively\n for i in range(3, n + 1):\n next_fibfib = fibfib_numbers[i - 1] + fibfib_numbers[i - 2] + fibfib_numbers[i - 3]\n fibfib_numbers.append(next_fibfib)\n \n return fibfib_numbers[n]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.\n \"\"\"\n # Get the unit digit of the first number\n unit_digit_a = abs(a) % 10\n # Get the unit digit of the second number\n unit_digit_b = abs(b) % 10\n # Return the product of the unit digits\n return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Sort the unique elements\n sorted_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_elements[1]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = 0\n s = s.lower() # Convert to lowercase to handle case insensitivity\n\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1: # Check if 'y' is at the end\n count += 1\n\n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef words_in_sentence(sentence):\n \"\"\"\n You are given a string representing a sentence,\n the sentence contains some words separated by a space,\n and you have to return a string that contains the words from the original sentence,\n whose lengths are prime numbers,\n the order of the words in the new string should be the same as the original one.\n\n Example 1:\n Input: sentence = \"This is a test\"\n Output: \"is\"\n\n Example 2:\n Input: sentence = \"lets go for swimming\"\n Output: \"go for\"\n\n Constraints:\n * 1 <= len(sentence) <= 100\n * sentence contains only letters\n \"\"\"\n words = sentence.split()\n prime_length_words = [word for word in words if is_prime(len(word))]\n return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n \"\"\"Simplifies the expression x * n and checks if the result is a whole number.\n \n Args:\n x (str): A string representation of a fraction in the format 'numerator/denominator'.\n n (str): A string representation of a fraction in the format 'numerator/denominator'.\n \n Returns:\n bool: True if x * n evaluates to a whole number, False otherwise.\n \"\"\"\n # Split the fractions into numerator and denominator\n x_numerator, x_denominator = map(int, x.split('/'))\n n_numerator, n_denominator = map(int, n.split('/'))\n \n # Calculate the product of the fractions\n # x * n = (x_numerator / x_denominator) * (n_numerator / n_denominator)\n # This simplifies to (x_numerator * n_numerator) / (x_denominator * n_denominator)\n numerator_product = x_numerator * n_numerator\n denominator_product = x_denominator * n_denominator\n \n # Check if the result is a whole number\n return numerator_product % denominator_product == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n \"\"\"In this problem, you will implement a function that takes two lists of numbers,\n and determines whether it is possible to perform an exchange of elements\n between them to make lst1 a list of only even numbers.\n There is no limit on the number of exchanged elements between lst1 and lst2.\n If it is possible to exchange elements between the lst1 and lst2 to make\n all the elements of lst1 to be even, return \"YES\".\n Otherwise, return \"NO\".\n For example:\n exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"YES\"\n exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n It is assumed that the input lists will be non-empty.\n \"\"\"\n \n # Check if all elements in lst1 are even\n if all(x % 2 == 0 for x in lst1):\n return \"YES\"\n \n # Count the number of odd elements in lst1\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n \n # Count the number of even elements in lst2\n even_count_lst2 = sum(1 for x in lst2 if x % 2 == 0)\n \n # If there are enough even numbers in lst2 to replace all odd numbers in lst1\n if odd_count_lst1 <= even_count_lst2:\n return \"YES\"\n \n return \"NO\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n \n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n \"\"\"\n return ' '.join(str(i) for i in range(n + 1))", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[999991]]}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n if not arr:\n return None\n\n product_of_signs = 1\n sum_of_magnitudes = 0\n\n for num in arr:\n if num > 0:\n product_of_signs *= 1\n sum_of_magnitudes += num\n elif num < 0:\n product_of_signs *= -1\n sum_of_magnitudes += -num\n else: # num == 0\n product_of_signs = 0\n break\n\n return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n \"\"\"Given a string s and a natural number n, returns a list of all words from \n string s that contain exactly n consonants, in the order they appear in the string s.\n \n Args:\n s (str): The input string containing words.\n n (int): The number of consonants to filter words by.\n \n Returns:\n list: A list of words containing exactly n consonants.\n \"\"\"\n if not s:\n return []\n\n # Define a set of consonants\n consonants = set(\"bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ\")\n \n # Split the string into words\n words = s.split()\n \n # Function to count consonants in a word\n def count_consonants(word):\n return sum(1 for char in word if char in consonants)\n \n # Filter words based on the number of consonants\n result = [word for word in words if count_consonants(word) == n]\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0: # More closing than opening\n return False\n return balance == 0 # Must be balanced at the end\n\n # Check both concatenation orders\n return 'Yes' if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]) else 'No'", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n '''\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return False. Assume no negative numbers and only integers.\n\n Examples\n is_sorted([5]) \u279e True\n is_sorted([1, 2, 3, 4, 5]) \u279e True\n is_sorted([1, 3, 2, 4, 5]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n '''\n if len(lst) <= 1:\n return True\n\n seen = set()\n last_num = None\n\n for num in lst:\n if num in seen:\n return False\n seen.add(num)\n\n if last_num is not None and num < last_num:\n return False\n \n last_num = num\n\n return True", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": [[[1, 1, 2, 2, 3, 3, 4]]]}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n \"\"\"\n Write a function which sorts the given list of integers\n in ascending order according to the sum of their digits.\n Note: if there are several items with similar sum of their digits,\n order them based on their index in original list.\n\n For example:\n >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n >>> order_by_points([]) == []\n \"\"\"\n \n def digit_sum(n):\n \"\"\"Calculate the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(abs(n)))\n\n # Sort the list based on the sum of digits and original index\n return sorted(nums, key=lambda x: (digit_sum(x), nums.index(x)))", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": [[[-5, -12, 9, 15]]]}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n \"\"\"\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n \n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126\n \"\"\"\n total = 0\n for index, value in enumerate(lst):\n if index % 3 == 0:\n total += value ** 2\n elif index % 4 == 0:\n total += value ** 3\n else:\n total += value\n return total", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef intersection(interval1, interval2):\n \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n start1, end1 = interval1\n start2, end2 = interval2\n \n # Find the intersection\n start_intersection = max(start1, start2)\n end_intersection = min(end1, end2)\n \n # Check if there is an intersection\n if start_intersection > end_intersection:\n return \"NO\"\n \n # Calculate the length of the intersection\n length_of_intersection = end_intersection - start_intersection\n \n # Check if the length is a prime number\n if is_prime(length_of_intersection):\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n two consonants from the right side of the word (case sensitive).\n \n Vowels in the beginning and ending don't count. Return empty string if you didn't\n find any vowel that meets the above condition. \n\n You may assume that the given string contains English letters only.\n\n Example:\n get_closest_vowel(\"yogurt\") ==> \"u\"\n get_closest_vowel(\"FULL\") ==> \"U\"\n get_closest_vowel(\"quick\") ==> \"\"\n get_closest_vowel(\"ab\") ==> \"\"\n \"\"\"\n vowels = \"aeiouAEIOU\"\n n = len(word)\n\n # Start from the end of the word\n for i in range(n - 2, 0, -1): # Start from the second last character to the second character\n if word[i] in vowels:\n # Check if there are consonants on both sides\n if word[i - 1].isalpha() and word[i + 1].isalpha() and word[i - 1] not in vowels and word[i + 1] not in vowels:\n return word[i]\n \n return \"\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Get the top k elements\n top_k = sorted_arr[:k]\n # Sort the result in ascending order before returning\n return sorted(top_k)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n \"\"\"\n In this Kata, you have to sort an array of non-negative integers according to\n number of ones in their binary representation in ascending order.\n For similar number of ones, sort based on decimal value.\n\n It must be implemented like this:\n >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n >>> sort_array([1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]\n \"\"\"\n # Sort the array using a custom key\n return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n \"\"\"\n if not test:\n return {}\n\n # Split the input string into a list of letters\n letters = test.split()\n \n # Create a dictionary to count occurrences of each letter\n count_dict = {}\n for letter in letters:\n if letter in count_dict:\n count_dict[letter] += 1\n else:\n count_dict[letter] = 1\n\n # Find the maximum count\n max_count = max(count_dict.values())\n \n # Create a result dictionary for letters with the maximum count\n result = {letter: count for letter, count in count_dict.items() if count == max_count}\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n from collections import deque\n\n N = len(grid)\n directions = [(0, 1), (1, 0), (0, -1), (-1, 0)] # right, down, left, up\n min_path = None\n\n def dfs(x, y, path):\n nonlocal min_path\n if len(path) == k:\n if min_path is None or path < min_path:\n min_path = path[:]\n return\n \n for dx, dy in directions:\n nx, ny = x + dx, y + dy\n if 0 <= nx < N and 0 <= ny < N:\n path.append(grid[nx][ny])\n dfs(nx, ny, path)\n path.pop()\n\n for i in range(N):\n for j in range(N):\n dfs(i, j, [grid[i][j]])\n\n return min_path", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": [[[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 15]]}]}} \ No newline at end of file diff --git a/EVALPLUS-4omini/3.json b/EVALPLUS-4omini/3.json new file mode 100644 index 000000000..e93e5ff15 --- /dev/null +++ b/EVALPLUS-4omini/3.json @@ -0,0 +1 @@ +{"date": "2024-07-20 13:00", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascending order.\n\n For example:\n generate_integers(2, 8) => [2, 4, 6, 8]\n generate_integers(8, 2) => [2, 4, 6, 8]\n generate_integers(10, 14) => []\n \"\"\"\n # Determine the range of numbers to consider\n start = min(a, b)\n end = max(a, b)\n\n # Generate a list of even integers in the specified range\n even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n return even_integers", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[2, 10]], "plus_fail_tests": [[6, 12]]}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def compare_one(a, b):\n \"\"\"\n Create a function that takes integers, floats, or strings representing\n real numbers, and returns the larger variable in its given variable type.\n Return None if the values are equal.\n Note: If a real number is represented as a string, the floating point might be . or ,\n\n compare_one(1, 2.5) \u279e 2.5\n compare_one(1, \"2,3\") \u279e \"2,3\"\n compare_one(\"5,1\", \"6\") \u279e \"6\"\n compare_one(\"1\", 1) \u279e None\n \"\"\"\n \n def parse_value(value):\n \"\"\"Convert the input value to a float or return it as is if it's a string.\"\"\"\n if isinstance(value, str):\n # Replace comma with dot for float conversion\n value = value.replace(',', '.')\n try:\n return float(value)\n except ValueError:\n return value # Return the string if it cannot be converted\n return value\n\n # Parse both values\n parsed_a = parse_value(a)\n parsed_b = parse_value(b)\n\n # Check for equality\n if parsed_a == parsed_b:\n return None\n\n # Return the larger value in its original type\n if parsed_a > parsed_b:\n return a\n else:\n return b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n Example:\n even_odd_count(-12) ==> (1, 1)\n even_odd_count(123) ==> (1, 2)\n \"\"\"\n # Convert the number to a string and remove the negative sign if present\n num_str = str(abs(num))\n \n even_count = 0\n odd_count = 0\n \n # Iterate through each character in the string representation of the number\n for digit in num_str:\n if digit.isdigit(): # Check if the character is a digit\n if int(digit) % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n return (even_count, odd_count)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n \"\"\"Compares the actual game scores with the guessed scores and returns the absolute differences.\n \n Args:\n game (list of int): The actual scores of the matches.\n guess (list of int): The guessed scores of the matches.\n \n Returns:\n list of int: A list containing the absolute differences between the actual scores and the guessed scores.\n If the guess is correct, the value is 0.\n \"\"\"\n return [abs(g - a) for a, g in zip(game, guess)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n \"\"\"\n Write a function count_nums which takes an array of integers and returns\n the number of elements which has a sum of digits > 0.\n If a number is negative, then its first signed digit will be negative:\n e.g. -123 has signed digits -1, 2, and 3.\n \n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n def sum_of_digits(n):\n # Convert the number to string and calculate the sum of its digits\n # For negative numbers, we need to consider the first digit as negative\n str_n = str(n)\n if n < 0:\n return -int(str_n[1]) + sum(int(digit) for digit in str_n[2:])\n else:\n return sum(int(digit) for digit in str_n)\n\n count = 0\n for num in arr:\n if sum_of_digits(num) > 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list to avoid division by zero\n\n mean_value = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n return mad", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def factorial(i):\n \"\"\"Calculate the factorial of a given number i.\"\"\"\n if i == 0 or i == 1:\n return 1\n result = 1\n for j in range(2, i + 1):\n result *= j\n return result\ndef sum_of_numbers(i):\n \"\"\"Calculate the sum of numbers from 1 to i.\"\"\"\n return (i * (i + 1)) // 2\ndef f(n):\n \"\"\"Return a list of size n, where the value at index i is the factorial of i if i is even,\n or the sum of numbers from 1 to i if i is odd. Indexing starts from 1.\n \"\"\"\n result = []\n for i in range(1, n + 1):\n if i % 2 == 0: # i is even\n result.append(factorial(i))\n else: # i is odd\n result.append(sum_of_numbers(i))\n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n \"\"\"\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n \"\"\"\n # Split the string by commas and spaces, then filter out any empty strings\n words = [word.strip() for word in s.replace(',', ' ').split() if word]\n return words", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" \n You're given a list of deposit and withdrawal operations on a bank account that starts with\n zero balance. Your task is to detect if at any point the balance of account falls below zero, and\n at that point function should return True. Otherwise it should return False.\n \n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n \"\"\"\n balance = 0\n for operation in operations:\n balance += operation\n if balance < 0:\n return True\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string.\n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n >>> string_to_md5('') is None\n >>> string_to_md5('Python') == '5d41402abc4b2a76b9719d911017c592'\n \"\"\"\n if text == \"\":\n return None\n md5_hash = hashlib.md5(text.encode()).hexdigest()\n return md5_hash", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n \"\"\"Find the strongest extension based on the defined strength criteria.\"\"\"\n strongest_extension = None\n max_strength = float('-inf') # Start with the lowest possible strength\n\n for extension in extensions:\n # Calculate the strength of the current extension\n CAP = sum(1 for char in extension if char.isupper())\n SM = sum(1 for char in extension if char.islower())\n strength = CAP - SM\n\n # Check if this extension is stronger than the current strongest\n if strength > max_strength:\n max_strength = strength\n strongest_extension = extension\n\n # Return the result in the specified format\n return f\"{class_name}.{strongest_extension}\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n \"\"\"Check if the second word or any of its rotations is a substring in the first word.\n \n Args:\n a (str): The first word.\n b (str): The second word.\n \n Returns:\n bool: True if the second word or any of its rotations is a substring of the first word, False otherwise.\n \n Examples:\n >>> cycpattern_check(\"abcd\", \"abd\")\n False\n >>> cycpattern_check(\"hello\", \"ell\")\n True\n >>> cycpattern_check(\"whassup\", \"psus\")\n False\n >>> cycpattern_check(\"abab\", \"baa\")\n True\n >>> cycpattern_check(\"efef\", \"eeff\")\n False\n >>> cycpattern_check(\"himenss\", \"simen\")\n True\n \"\"\"\n # Create a string that contains all rotations of b\n rotations = [b[i:] + b[:i] for i in range(len(b))]\n \n # Check if any rotation is a substring of a\n for rotation in rotations:\n if rotation in a:\n return True\n \n return False", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["", ""]]}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n \"\"\"\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n >>> make_a_pile(4)\n [4, 6, 8, 10]\n >>> make_a_pile(1)\n [1]\n \"\"\"\n stones = []\n current_stones = n\n \n for i in range(n):\n stones.append(current_stones)\n if current_stones % 2 == 0: # current_stones is even\n current_stones += 2 # next even number\n else: # current_stones is odd\n current_stones += 2 # next odd number\n \n return stones", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into\n an integer part (largest integer smaller than given number) and decimals\n (leftover part always smaller than 1).\n\n Return the decimal part of the number.\n \n >>> truncate_number(3.5)\n 0.5\n >>> truncate_number(7.25)\n 0.25\n >>> truncate_number(10.0)\n 0.0\n >>> truncate_number(5.99)\n 0.99\n \"\"\"\n if number < 0:\n raise ValueError(\"The number must be positive.\")\n \n integer_part = int(number) # Get the integer part\n decimal_part = number - integer_part # Calculate the decimal part\n return decimal_part", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n \"\"\"Calculate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n if n < 0:\n return []\n\n # Initialize the list to store the Tribonacci numbers\n tribonacci_sequence = []\n\n # Define the base cases\n for i in range(n + 1):\n if i == 0:\n tribonacci_sequence.append(1) # tri(0) = 1\n elif i == 1:\n tribonacci_sequence.append(3) # tri(1) = 3\n elif i % 2 == 0: # Even case\n tribonacci_sequence.append(1 + i / 2)\n else: # Odd case\n tri_n_minus_1 = tribonacci_sequence[i - 1]\n tri_n_minus_2 = tribonacci_sequence[i - 2]\n tri_n_plus_1 = tribonacci_sequence[i + 1] if i + 1 <= n else 0\n tribonacci_sequence.append(tri_n_minus_1 + tri_n_minus_2 + tri_n_plus_1)\n\n return tribonacci_sequence", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[3]], "plus_fail_tests": [[10]]}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n \"\"\"\n Given a positive integer n, return a tuple that has the number of even and odd\n integer palindromes that fall within the range(1, n), inclusive.\n\n Example 1:\n Input: 3\n Output: (1, 2)\n Explanation:\n Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n Example 2:\n Input: 12\n Output: (4, 6)\n Explanation:\n Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n Note:\n 1. 1 <= n <= 10^3\n 2. returned tuple has the number of even and odd integer palindromes respectively.\n \"\"\"\n even_count = 0\n odd_count = 0\n\n for i in range(1, n + 1):\n if str(i) == str(i)[::-1]: # Check if the number is a palindrome\n if i % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n return (even_count, odd_count)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n \n Args:\n n (int): The number to evaluate.\n \n Returns:\n bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n \n Example:\n is_equal_to_sum_even(4) == False\n is_equal_to_sum_even(6) == False\n is_equal_to_sum_even(8) == True\n \"\"\"\n # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n if n < 8:\n return False\n \n # Check if n is even\n if n % 2 != 0:\n return False\n \n # If n is even and >= 8, it can be expressed as the sum of 4 positive even numbers\n return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n \"\"\" Insert a number 'delimiter' between every two consecutive elements of input list `numbers`\n \n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n for i in range(len(numbers) - 1):\n result.append(numbers[i])\n result.append(delimiter)\n result.append(numbers[-1]) # Append the last element\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n \"\"\"Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n For example:\n digits(1) == 1\n digits(4) == 0\n digits(235) == 15\n \"\"\"\n product = 1\n has_odd = False\n \n for digit in str(n):\n digit = int(digit)\n if digit % 2 != 0: # Check if the digit is odd\n product *= digit\n has_odd = True\n \n return product if has_odd else 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n '''\n Create a function that returns a tuple (a, b), where 'a' is\n the largest of negative integers, and 'b' is the smallest\n of positive integers in a list.\n If there is no negative or positive integers, return them as None.\n\n Examples:\n largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n largest_smallest_integers([]) == (None, None)\n largest_smallest_integers([0]) == (None, None)\n '''\n largest_negative = None\n smallest_positive = None\n\n for num in lst:\n if num < 0:\n if largest_negative is None or num > largest_negative:\n largest_negative = num\n elif num > 0:\n if smallest_positive is None or num < smallest_positive:\n smallest_positive = num\n\n return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return True else return False.\n If the given array is empty then return True.\n\n Note: The given list is guaranteed to have unique elements.\n\n For Example:\n \n move_one_ball([3, 4, 5, 1, 2])==>True\n Explanation: By performing 2 right shift operations, non-decreasing order can\n be achieved for the given array.\n move_one_ball([3, 5, 4, 1, 2])==>False\n Explanation: It is not possible to get non-decreasing order for the given\n array by performing any number of right shift operations.\n \"\"\"\n if not arr:\n return True\n\n n = len(arr)\n sorted_arr = sorted(arr)\n \n # Check for the number of \"breaks\" in the sorted array\n break_count = 0\n for i in range(n):\n if arr[i] > arr[(i + 1) % n]:\n break_count += 1\n\n # If there are more than one break, we cannot sort the array with shifts\n return break_count <= 1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to make it easier to find the closest pair\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest elements\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n \n >>> flip_case('Hello')\n 'hELLO'\n >>> flip_case('Python')\n 'pYTHON'\n >>> flip_case('123abcXYZ')\n '123ABCxyz'\n >>> flip_case('')\n ''\n \"\"\"\n return string.swapcase()", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n \n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n \"\"\"\n count = 0\n start = 0\n \n while True:\n start = string.find(substring, start)\n if start == -1:\n break\n count += 1\n start += 1 # Move to the next character to allow for overlapping matches\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n \"\"\" Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n \n >>> string_xor('010', '110')\n '100'\n >>> string_xor('111', '000')\n '111'\n >>> string_xor('101', '101')\n '000'\n >>> string_xor('000', '000')\n '000'\n >>> string_xor('1101', '1011')\n '0110'\n \"\"\"\n # Ensure both strings are of the same length\n max_len = max(len(a), len(b))\n a = a.zfill(max_len)\n b = b.zfill(max_len)\n \n # Perform XOR operation\n result = []\n for bit_a, bit_b in zip(a, b):\n result.append('1' if bit_a != bit_b else '0')\n \n return ''.join(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lower_string = string.lower()\n # Use a set to find distinct characters\n distinct_characters = set(lower_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n \n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n \"\"\"\n return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted = []\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Calculate the new character by shifting it down by 4 places\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a')) if char.islower() else \\\n chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n encrypted.append(new_char)\n else:\n encrypted.append(char) # Non-alphabetic characters remain unchanged\n return ''.join(encrypted)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n \n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n \"\"\"\n return [x + 1 for x in l]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n \"\"\"Given length of a side and height, return the area of a triangle.\n \n The area of a triangle can be calculated using the formula:\n area = (base * height) / 2\n \n Parameters:\n a (float): The length of the base of the triangle.\n h (float): The height of the triangle.\n \n Returns:\n float: The area of the triangle.\n \n >>> triangle_area(5, 3)\n 7.5\n >>> triangle_area(10, 2)\n 10.0\n >>> triangle_area(0, 5)\n 0.0\n >>> triangle_area(5, 0)\n 0.0\n \"\"\"\n return (a * h) / 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n \n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by row index (ascending) and then by column index (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n \"\"\"\n Given an array arr of integers, find the minimum number of elements that\n need to be changed to make the array palindromic. A palindromic array is an array that\n is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n For example:\n smallest_change([1,2,3,5,4,7,9,6]) == 4\n smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n smallest_change([1, 2, 3, 2, 1]) == 0\n \"\"\"\n n = len(arr)\n changes = 0\n \n # Compare elements from the start and end towards the center\n for i in range(n // 2):\n if arr[i] != arr[n - 1 - i]:\n changes += 1\n \n return changes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n else:\n return lst2", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": [[["happy", "birthday", "sarah"], ["happy", "birthday", "sally"]]]}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n \"\"\"You are given a string s.\n Your task is to check if the string is happy or not.\n A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n \n For example:\n is_happy('a') => False\n is_happy('aa') => False\n is_happy('abcd') => True\n is_happy('aabb') => False\n is_happy('adb') => True\n is_happy('xyy') => False\n \"\"\"\n # Check if the length of the string is at least 3\n if len(s) < 3:\n return False\n \n # Check every 3 consecutive characters\n for i in range(len(s) - 2):\n if len(set(s[i:i+3])) < 3: # If there are not 3 distinct characters\n return False\n \n return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" Input to this function is a string representing musical notes in a special ASCII format.\n Your task is to parse this string and return list of integers corresponding to how many beats does each\n note last.\n\n Here is a legend:\n 'o' - whole note, lasts four beats\n 'o|' - half note, lasts two beats\n '.|' - quarter note, lasts one beat\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n # Define a mapping of note representations to their corresponding beat values\n note_to_beats = {\n 'o': 4, # whole note\n 'o|': 2, # half note\n '.|': 1 # quarter note\n }\n \n # Split the input string into individual notes\n notes = music_string.split()\n \n # Parse the notes and convert them to their corresponding beat values\n beats = [note_to_beats[note] for note in notes if note in note_to_beats]\n \n return beats", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string.\n \n Args:\n strings (List[str]): A list of strings to concatenate.\n \n Returns:\n str: A single concatenated string.\n \n Examples:\n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n \"\"\"\n return ''.join(strings)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n \n >>> make_palindrome('')\n ''\n >>> make_palindrome('cat')\n 'catac'\n >>> make_palindrome('cata')\n 'catac'\n \"\"\"\n # Find the longest palindromic suffix\n for i in range(len(string)):\n if is_palindrome(string[i:]):\n # If the suffix is a palindrome, take the prefix before it\n prefix = string[:i]\n # Append the reverse of the prefix to the original string\n return string + prefix[::-1]\n return string # In case the string is empty or already a palindrome", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n \"\"\" \n Input is a space-delimited string of numerals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest.\n \n >>> sort_numbers('three one five')\n 'one three five'\n \"\"\"\n # Mapping of words to their corresponding numeric values\n num_map = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n \n # Split the input string into words\n words = numbers.split()\n \n # Sort the words based on their numeric values\n sorted_words = sorted(words, key=lambda word: num_map[word])\n \n # Join the sorted words back into a string\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n \n # Create a new list with elements that occur only once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1.\n \n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n min_val = min(numbers)\n max_val = max(numbers)\n \n # Avoid division by zero if all numbers are the same\n if min_val == max_val:\n return [0.0] * len(numbers)\n \n return [(num - min_val) / (max_val - min_val) for num in numbers]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef get_primes_up_to(limit):\n \"\"\"Return a list of all prime numbers up to a given limit.\"\"\"\n return [num for num in range(2, limit) if is_prime(num)]\ndef is_multiply_prime(a):\n \"\"\"Return true if the given number is the multiplication of 3 prime numbers, false otherwise.\"\"\"\n if a >= 100:\n return False\n \n primes = get_primes_up_to(a)\n prime_count = len(primes)\n \n # Check all combinations of three primes\n for i in range(prime_count):\n for j in range(i, prime_count):\n for k in range(j, prime_count):\n product = primes[i] * primes[j] * primes[k]\n if product == a:\n return True\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n letter_grades = []\n \n for gpa in grades:\n if gpa == 4.0:\n letter_grades.append('A+')\n elif gpa > 3.7:\n letter_grades.append('A')\n elif gpa > 3.3:\n letter_grades.append('A-')\n elif gpa > 3.0:\n letter_grades.append('B+')\n elif gpa > 2.7:\n letter_grades.append('B')\n elif gpa > 2.3:\n letter_grades.append('B-')\n elif gpa > 2.0:\n letter_grades.append('C+')\n elif gpa > 1.7:\n letter_grades.append('C')\n elif gpa > 1.3:\n letter_grades.append('C-')\n elif gpa > 1.0:\n letter_grades.append('D+')\n elif gpa > 0.7:\n letter_grades.append('D')\n elif gpa > 0.0:\n letter_grades.append('D-')\n else:\n letter_grades.append('E')\n \n return letter_grades", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n '''\n Write a function that returns True if the object q will fly, and False otherwise.\n The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n\n Example:\n will_it_fly([1, 2], 5) \u279e False \n # 1+2 is less than the maximum possible weight, but it's unbalanced.\n\n will_it_fly([3, 2, 3], 1) \u279e False\n # it's balanced, but 3+2+3 is more than the maximum possible weight.\n\n will_it_fly([3, 2, 3], 9) \u279e True\n # 3+2+3 is less than the maximum possible weight, and it's balanced.\n\n will_it_fly([3], 5) \u279e True\n # 3 is less than the maximum possible weight, and it's balanced.\n '''\n # Check if the list is a palindrome\n is_balanced = q == q[::-1]\n \n # Calculate the sum of the elements in the list\n total_weight = sum(q)\n \n # Check if the object will fly\n return is_balanced and total_weight <= w", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion.\n base numbers are less than 10.\n \n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n \"\"\"\n if base < 2 or base >= 10:\n raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n \n if x == 0:\n return '0'\n \n result = []\n while x > 0:\n result.append(str(x % base))\n x //= base\n \n return ''.join(reversed(result))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words while preserving spaces\n words = s.split(' ')\n \n # Sort each word and keep the spaces intact\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back with spaces\n result = ' '.join(sorted_words)\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n or sort it in descending order if the sum( first index value, last index value) is even.\n\n Note:\n * don't change the given array.\n\n Examples:\n * sort_array([]) => []\n * sort_array([5]) => [5]\n * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n \"\"\"\n if not array: # Check for empty array\n return []\n \n first_value = array[0]\n last_value = array[-1]\n sum_values = first_value + last_value\n\n # Create a copy of the array to sort\n sorted_array = array.copy()\n\n if sum_values % 2 == 0: # Even sum\n sorted_array.sort(reverse=True) # Sort in descending order\n else: # Odd sum\n sorted_array.sort() # Sort in ascending order\n\n return sorted_array", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n \n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n \"\"\"\n seen = set()\n for number in l:\n if -number in seen:\n return True\n seen.add(number)\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in lower \n case or all keys are strings in upper case, else return False.\n The function should return False if the given dictionary is empty.\n \n Examples:\n check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n \"\"\"\n if not input_dict:\n return False\n\n all_lower = all(isinstance(key, str) and key.islower() for key in input_dict.keys())\n all_upper = all(isinstance(key, str) and key.isupper() for key in input_dict.keys())\n\n return all_lower or all_upper", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"(\" and \")\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"(\")\n False\n >>> correct_bracketing(\"()\")\n True\n >>> correct_bracketing(\"(()())\")\n True\n >>> correct_bracketing(\")(()\")\n False\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n # If balance goes negative, there are unmatched closing brackets\n if balance < 0:\n return False\n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n \"\"\"Task\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n \"\"\"\n return sum(ord(char) for char in s if char.isupper())", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n '''\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n \n Examples\n any_int(5, 2, 7) \u279e True\n \n any_int(3, 2, 2) \u279e False\n\n any_int(3, -2, 1) \u279e True\n \n any_int(3.6, -2.2, 2) \u279e False\n '''\n # Check if all inputs are integers\n if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n # Check if one number is equal to the sum of the other two\n return x == y + z or y == x + z or z == x + y\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n # Keep dividing n by factor until it is no longer divisible\n while n > 1:\n if n % factor == 0:\n n //= factor # Divide n by the factor\n else:\n factor += 1 # Move to the next potential factor\n return factor # The last factor is the largest prime factor", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n \"\"\"Return True if list elements are monotonically increasing or decreasing.\n \n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n \"\"\"\n if not l: # An empty list is considered monotonic\n return True\n \n increasing = decreasing = True\n \n for i in range(1, len(l)):\n if l[i] > l[i - 1]:\n decreasing = False\n elif l[i] < l[i - 1]:\n increasing = False\n \n return increasing or decreasing", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n \"\"\"\n Takes as input string encoded with encode_shift function. Returns decoded string.\n \"\"\"\n return \"\".join([chr(((ord(ch) - ord(\"a\") - 5) % 26) + ord(\"a\")) for ch in s])", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n \"\"\"\n Given an array representing a branch of a tree that has non-negative integer nodes,\n your task is to pluck one of the nodes and return it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n The plucked node should be returned in a list, [ smallest_value, its index ],\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index. \n\n Example 3:\n Input: []\n Output: []\n \n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n Explanation: 0 is the smallest value, but there are two zeros,\n so we will choose the first zero, which has the smallest index.\n\n Constraints:\n * 1 <= nodes.length <= 10000\n * 0 <= node.value\n \"\"\"\n smallest_even = float('inf')\n smallest_index = -1\n\n for index, value in enumerate(arr):\n if value % 2 == 0: # Check if the value is even\n if value < smallest_even: # Check if it's the smallest even found\n smallest_even = value\n smallest_index = index\n\n if smallest_index == -1: # No even value found\n return []\n \n return [smallest_even, smallest_index]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float) -> float:\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list) -> list:\n \"\"\"\n Computes the derivative of the polynomial with coefficients xs.\n \"\"\"\n return [i * coeff for i, coeff in enumerate(xs) if i > 0]\ndef find_zero(xs: list, initial_guess: float = 0.0, tolerance: float = 1e-7, max_iterations: int = 1000) -> float:\n \"\"\" \n xs are coefficients of a polynomial.\n find_zero finds x such that poly(x) = 0.\n find_zero returns only one zero point, even if there are many.\n Moreover, find_zero only takes list xs having an even number of coefficients\n and the largest non-zero coefficient as it guarantees a solution.\n \n >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n -0.5\n >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n 1.0\n \"\"\"\n if len(xs) % 2 != 0:\n raise ValueError(\"The number of coefficients must be even.\")\n \n current_guess = initial_guess\n for _ in range(max_iterations):\n f_value = poly(xs, current_guess)\n f_derivative = poly(derivative(xs), current_guess)\n \n if f_derivative == 0:\n raise ValueError(\"Derivative is zero. No solution found.\")\n \n next_guess = current_guess - f_value / f_derivative\n \n if abs(next_guess - current_guess) < tolerance:\n return next_guess\n \n current_guess = next_guess\n \n raise ValueError(\"Maximum iterations reached. No solution found.\")", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[[5, 10, -3, 1]]]}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" brackets is a string of \"<\" and \">\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"<\")\n False\n >>> correct_bracketing(\"<>\")\n True\n >>> correct_bracketing(\"<<><>>\")\n True\n >>> correct_bracketing(\"><<>\")\n False\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '<':\n balance += 1\n elif char == '>':\n balance -= 1\n # If balance goes negative, there are more closing brackets\n if balance < 0:\n return False\n # At the end, balance should be zero for correct bracketing\n return balance == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n \"\"\"Return maximum element in the list.\n \n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty.\")\n \n max_value = l[0]\n for item in l:\n if item > max_value:\n max_value = item\n return max_value", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n \"\"\"\n Write a function that takes a message, and encodes in such a \n way that it swaps case of all letters, replaces all vowels in \n the message with the letter that appears 2 places ahead of that \n vowel in the english alphabet. \n Assume only letters. \n \n Examples:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n vowels = 'aeiouAEIOU'\n encoded_message = []\n\n for char in message:\n if char.isalpha(): # Check if the character is a letter\n # Swap case\n if char in vowels:\n # Replace vowel with the letter 2 places ahead\n if char.islower():\n new_char = chr((ord(char) - ord('a') + 2) % 26 + ord('a'))\n else:\n new_char = chr((ord(char) - ord('A') + 2) % 26 + ord('A'))\n else:\n new_char = char.swapcase() # Swap case for consonants\n encoded_message.append(new_char)\n else:\n encoded_message.append(char) # Keep non-letter characters unchanged\n\n return ''.join(encoded_message)", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["TEST"]], "plus_fail_tests": [["abcdefghijklmnopqrstuvwxyz"]]}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n '''\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequency greater than or equal to the value of the integer itself. \n The frequency of an integer is the number of times it appears in the list.\n If no such a value exist, return -1.\n \n Examples:\n search([4, 1, 2, 2, 3, 1]) == 2\n search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n search([5, 5, 4, 4, 4]) == -1\n '''\n from collections import Counter\n \n # Count the frequency of each number in the list\n frequency = Counter(lst)\n \n # Initialize the result variable\n result = -1\n \n # Iterate through the frequency dictionary\n for num, freq in frequency.items():\n # Check if the frequency is greater than or equal to the number itself\n if freq >= num:\n # Update the result if this number is greater than the current result\n result = max(result, num)\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n \n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n \"\"\"\n return n * (n + 1) // 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n \"\"\"\n In this task, you will be given a string that represents a number of apples and oranges \n that are distributed in a basket of fruit. This basket contains \n apples, oranges, and mango fruits. Given the string that represents the total number of \n the oranges and apples and an integer that represents the total number of the fruits \n in the basket, return the number of the mango fruits in the basket.\n \n Parameters:\n s (str): A string representing the number of apples and oranges.\n n (int): An integer representing the total number of fruits in the basket.\n \n Returns:\n int: The number of mango fruits in the basket.\n \n Examples:\n fruit_distribution(\"5 apples and 6 oranges\", 19) -> 8\n fruit_distribution(\"0 apples and 1 oranges\", 3) -> 2\n fruit_distribution(\"2 apples and 3 oranges\", 100) -> 95\n fruit_distribution(\"100 apples and 1 oranges\", 120) -> 19\n \"\"\"\n \n # Extract the number of apples and oranges from the string\n parts = s.split()\n apples = int(parts[0]) # First part is the number of apples\n oranges = int(parts[3]) # Fourth part is the number of oranges\n \n # Calculate the number of mangoes\n mangoes = n - apples - oranges\n \n return mangoes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(divisible_by_three)\n \n # Create a new list to hold the result\n result = l.copy()\n \n # Replace values at indices divisible by 3 with sorted values\n for index, value in zip((i for i in range(len(l)) if i % 3 == 0), sorted_values):\n result[index] = value\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n Example\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n \"\"\"\n # Initialize variables to track the minimum sum and the current sum\n min_sum = float('inf')\n current_sum = 0\n \n for num in nums:\n current_sum += num\n min_sum = min(min_sum, current_sum)\n \n # If current_sum is positive, reset it to 0\n if current_sum > 0:\n current_sum = 0\n \n return min_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n '''\n Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n \n Examples:\n split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"abcdef\") \u279e 3 \n '''\n # Check for whitespace in the text\n if ' ' in txt:\n return txt.split()\n \n # Check for commas in the text\n elif ',' in txt:\n return txt.split(',')\n \n # If no whitespace or commas, count lower-case letters with odd order\n else:\n odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n return odd_count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n \"\"\"\n Given a non-empty array of integers arr and an integer k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example:\n\n Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n Output: 24 # sum of 21 + 3\n\n Constraints:\n 1. 1 <= len(arr) <= 100\n 2. 1 <= k <= len(arr)\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate through the first k elements of the array\n for i in range(k):\n # Check if the current element has at most two digits\n if -100 < arr[i] < 100:\n total_sum += arr[i]\n \n return total_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length and alphabetically.\n \n Args:\n lst (list of str): A list of strings.\n \n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n \"\"\"\n Given a string text, replace all spaces in it with underscores, \n and if a string has more than 2 consecutive spaces, \n then replace all consecutive spaces with - \n \n fix_spaces(\"Example\") == \"Example\"\n fix_spaces(\"Example 1\") == \"Example_1\"\n fix_spaces(\" Example 2\") == \"_Example_2\"\n fix_spaces(\" Example 3\") == \"_Example-3\"\n \"\"\"\n import re\n\n # Replace more than 2 consecutive spaces with a single '-'\n text = re.sub(r' {3,}', '-', text)\n \n # Replace single spaces with underscores\n text = text.replace(' ', '_')\n \n return text", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n as follows: start with any positive integer n. Then each term is obtained from the \n previous term as follows: if the previous term is even, the next term is one half of \n the previous term. If the previous term is odd, the next term is 3 times the previous\n term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n Note: \n 1. Collatz(1) is [1].\n 2. returned list sorted in increasing order.\n\n For example:\n get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n collatz_sequence = []\n current = n\n \n while current != 1:\n collatz_sequence.append(current)\n if current % 2 == 0:\n current //= 2\n else:\n current = 3 * current + 1\n \n collatz_sequence.append(1) # Add the last term which is 1\n \n # Filter odd numbers and sort them\n odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n \n return odd_numbers", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n \n The date is valid if all of the following rules are satisfied:\n 1. The date string is not empty.\n 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n The number of days is not less than 1 or higher than 29 for the month 2.\n 3. The months should not be less than 1 or higher than 12.\n 4. The date should be in the format: mm-dd-yyyy\n \n Args:\n date (str): The date string to validate.\n \n Returns:\n bool: True if the date is valid, False otherwise.\n \"\"\"\n if not date:\n return False\n \n # Check the format\n parts = date.split('-')\n if len(parts) != 3:\n return False\n \n if not all(part.isdigit() for part in parts):\n return False\n \n month, day, year = map(int, parts)\n \n # Validate month\n if month < 1 or month > 12:\n return False\n \n # Validate day based on month\n if month in {1, 3, 5, 7, 8, 10, 12}:\n if day < 1 or day > 31:\n return False\n elif month in {4, 6, 9, 11}:\n if day < 1 or day > 30:\n return False\n elif month == 2:\n if day < 1 or day > 29:\n return False\n \n return True", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["06-04-202"]]}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n \"\"\"Task\n We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and True/False for the check.\n Example\n For s = \"abcde\", c = \"ae\", the result should be ('bcd',False)\n For s = \"abcdef\", c = \"b\", the result should be ('acdef',False)\n For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc',True)\n \"\"\"\n # Create a set of characters to delete for faster lookup\n delete_set = set(c)\n \n # Create the result string by filtering out characters in delete_set\n result = ''.join(char for char in s if char not in delete_set)\n \n # Check if the result string is a palindrome\n is_palindrome = result == result[::-1]\n \n return (result, is_palindrome)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n \"\"\"\n Calculate the number of times buckets need to be lowered to empty the wells.\n\n Parameters:\n grid (list of list of int): A rectangular grid representing wells.\n capacity (int): The capacity of each bucket.\n\n Returns:\n int: The total number of times buckets need to be lowered.\n \"\"\"\n total_water = 0\n \n # Count the total amount of water in the grid\n for row in grid:\n total_water += sum(row)\n \n # Calculate the number of times buckets need to be lowered\n # Each bucket can carry 'capacity' units of water\n if total_water == 0:\n return 0\n else:\n return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": [[[[1, 0, 0, 1], [0, 1, 1, 1], [0, 0, 0, 0], [1, 0, 1, 1]], 2]]}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n \"\"\"Create a function which takes a string representing a file's name, and returns\n 'Yes' if the the file's name is valid, and returns 'No' otherwise.\n A file's name is considered to be valid if and only if all the following conditions \n are met:\n - There should not be more than three digits ('0'-'9') in the file's name.\n - The file's name contains exactly one dot '.'\n - The substring before the dot should not be empty, and it starts with a letter from \n the latin alphapet ('a'-'z' and 'A'-'Z').\n - The substring after the dot should be one of these: ['txt', 'exe', 'dll']\n Examples:\n file_name_check(\"example.txt\") # => 'Yes'\n file_name_check(\"1example.dll\") # => 'No' (the name should start with a latin alphapet letter)\n \"\"\"\n \n # Split the file name into name and extension\n if file_name.count('.') != 1:\n return 'No'\n \n name, extension = file_name.split('.')\n \n # Check if the name is empty or starts with a non-letter\n if not name or not name[0].isalpha():\n return 'No'\n \n # Check the extension\n valid_extensions = ['txt', 'exe', 'dll']\n if extension not in valid_extensions:\n return 'No'\n \n # Count the digits in the file name\n digit_count = sum(c.isdigit() for c in file_name)\n if digit_count > 3:\n return 'No'\n \n return 'Yes'", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n \"\"\"Write a function that takes an array of numbers as input and returns \n the number of elements in the array that are greater than 10 and both \n first and last digits of a number are odd (1, 3, 5, 7, 9).\n \n For example:\n specialFilter([15, -73, 14, -15]) => 1 \n specialFilter([33, -2, -3, 45, 21, 109]) => 2\n \"\"\"\n \n def is_odd_digit(digit):\n return digit in {'1', '3', '5', '7', '9'}\n \n def first_and_last_odd(num):\n str_num = str(abs(num)) # Convert to string and take absolute value\n return is_odd_digit(str_num[0]) and is_odd_digit(str_num[-1])\n \n count = 0\n for num in nums:\n if num > 10 and first_and_last_odd(num):\n count += 1\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closest to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sorted by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct planet names. \n Examples\n bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n '''\n \n planets = [\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n ]\n \n if planet1 not in planets or planet2 not in planets:\n return ()\n \n index1 = planets.index(planet1)\n index2 = planets.index(planet2)\n \n # Ensure index1 is less than index2 for slicing\n start_index = min(index1, index2) + 1\n end_index = max(index1, index2)\n \n return tuple(planets[start_index:end_index])", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers.\n You need to return the sum of squared numbers in the given list,\n round each element in the list to the upper int (Ceiling) first.\n \n Examples:\n For lst = [1,2,3] the output should be 14\n For lst = [1,4,9] the output should be 98\n For lst = [1,3,5,7] the output should be 84\n For lst = [1.4,4.2,0] the output should be 29\n For lst = [-2.4,1,1] the output should be 6\n \"\"\"\n return sum(math.ceil(x) ** 2 for x in lst)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n '''\n Create a function that returns True if the last character\n of a given string is an alphabetical character and is not\n a part of a word, and False otherwise.\n Note: \"word\" is a group of characters separated by space.\n\n Examples:\n check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '''\n # Strip any trailing whitespace from the string\n txt = txt.rstrip()\n \n # Check if the string is empty after stripping\n if not txt:\n return False\n \n # Get the last character of the string\n last_char = txt[-1]\n \n # Check if the last character is a letter\n if last_char.isalpha():\n # Check if the last character is part of a word\n # A character is part of a word if it is preceded by a non-space character\n if len(txt) > 1 and txt[-2] != ' ':\n return False\n return True\n \n return False", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["eeeee e "]], "plus_fail_tests": [["k "]]}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef sum_of_digits(n):\n \"\"\"Return the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n largest_prime = -1\n \n for number in lst:\n if is_prime(number) and number > largest_prime:\n largest_prime = number\n \n if largest_prime == -1:\n return 0 # Return 0 if no prime number is found\n \n return sum_of_digits(largest_prime)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n \"\"\"\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,\n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example:\n Input: n = 5\n Output: 1\n Explanation:\n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n \"\"\"\n # Create the array a\n a = [i * i - i + 1 for i in range(1, n + 1)]\n \n # Count the number of valid triples\n count = 0\n \n # Check all combinations of triples (i, j, k) with i < j < k\n for i in range(n):\n for j in range(i + 1, n):\n for k in range(j + 1, n):\n if (a[i] + a[j] + a[k]) % 3 == 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n \"\"\"This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If \n there's no such number, then the function should return -1.\n\n For example:\n choose_num(12, 15) = 14\n choose_num(13, 12) = -1\n \"\"\"\n # Ensure x is less than or equal to y\n if x > y:\n return -1\n \n # Start from the largest number in the range and check for evenness\n for num in range(y, x - 1, -1):\n if num % 2 == 0:\n return num\n \n return -1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to make it easier to find close elements\n numbers.sort()\n \n # Check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n reverse the resulting array, and then replace each digit by its corresponding name from\n \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n For example:\n arr = [2, 1, 1, 4, 5, 8, 2, 3] \n -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n \n If the array is empty, return an empty array:\n arr = []\n return []\n \n If the array has any strange number ignore it:\n arr = [1, -1 , 55] \n -> sort arr -> [-1, 1, 55]\n -> reverse arr -> [55, 1, -1]\n return = ['One']\n \"\"\"\n \n # Mapping of digits to their corresponding names\n digit_to_name = {\n 1: \"One\", 2: \"Two\", 3: \"Three\", 4: \"Four\",\n 5: \"Five\", 6: \"Six\", 7: \"Seven\", 8: \"Eight\", 9: \"Nine\"\n }\n \n # Filter the array to include only numbers between 1 and 9\n filtered_arr = [num for num in arr if 1 <= num <= 9]\n \n # Sort the filtered array\n filtered_arr.sort()\n \n # Reverse the sorted array\n filtered_arr.reverse()\n \n # Convert the numbers to their corresponding names\n result = [digit_to_name[num] for num in filtered_arr]\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n \"\"\"\n return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n \"\"\"Calculate the factorial of n (n!).\"\"\"\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef special_factorial(n):\n \"\"\"The Brazilian factorial is defined as:\n brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!\n where n > 0\n\n For example:\n >>> special_factorial(4)\n 288\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n result = 1\n for i in range(1, n + 1):\n result *= factorial(i)\n \n return result", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[491]]}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n \n double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n double_the_difference([-1, -2, 0]) == 0\n double_the_difference([9, -2]) == 81\n double_the_difference([0]) == 0 \n \n If the input list is empty, return 0.\n '''\n if not lst: # Check if the list is empty\n return 0\n \n return sum(x**2 for x in lst if isinstance(x, int) and x >= 0 and x % 2 != 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n if not (1 <= number <= 1000):\n raise ValueError(\"Number must be between 1 and 1000\")\n\n roman_numerals = [\n (1000, 'm'),\n (900, 'cm'),\n (500, 'd'),\n (400, 'cd'),\n (100, 'c'),\n (90, 'xc'),\n (50, 'l'),\n (40, 'xl'),\n (10, 'x'),\n (9, 'ix'),\n (5, 'v'),\n (4, 'iv'),\n (1, 'i')\n ]\n\n result = []\n for value, numeral in roman_numerals:\n while number >= value:\n result.append(numeral)\n number -= value\n\n return ''.join(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic algebra operations, and \n the second list is a list of integers. Use the two given lists to build the algebraic \n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + ) \n Subtraction ( - ) \n Multiplication ( * ) \n Floor division ( // ) \n Exponentiation ( ** ) \n\n Example:\n operator = ['+', '*', '-']\n operand = [2, 3, 4, 5]\n result = 2 + 3 * 4 - 5\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.\n \"\"\"\n # Start with the first operand\n result = operand[0]\n \n # Iterate through the operators and operands\n for i in range(len(operator)):\n op = operator[i]\n next_operand = operand[i + 1]\n \n if op == '+':\n result += next_operand\n elif op == '-':\n result -= next_operand\n elif op == '*':\n result *= next_operand\n elif op == '//':\n result //= next_operand\n elif op == '**':\n result **= next_operand\n else:\n raise ValueError(f\"Unsupported operator: {op}\")\n \n return result", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": [[["+", "-", "*", "//"], [5, 2, 3, 4, 7]]]}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n \"\"\"Write a function that accepts a list of strings.\n The list contains different words. Return the word with maximum number\n of unique characters. If multiple strings have maximum number of unique\n characters, return the one which comes first in lexicographical order.\n\n find_max([\"name\", \"of\", \"string\"]) == \"string\"\n find_max([\"name\", \"enam\", \"game\"]) == \"enam\"\n find_max([\"aaaaaaa\", \"bb\" ,\"cc\"]) == \"aaaaaaa\"\n \"\"\"\n max_word = \"\"\n max_unique_count = 0\n\n for word in words:\n unique_chars = set(word)\n unique_count = len(unique_chars)\n\n if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n max_word = word\n max_unique_count = unique_count\n\n return max_word", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n def max_nesting_depth(s: str) -> int:\n max_depth = 0\n current_depth = 0\n for char in s:\n if char == '(':\n current_depth += 1\n max_depth = max(max_depth, current_depth)\n elif char == ')':\n current_depth -= 1\n return max_depth\n\n groups = paren_string.split()\n return [max_nesting_depth(group) for group in groups]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n \"\"\"Given a list of positive integers x, return a sorted list of all \n elements that haven't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n def has_even_digit(n):\n \"\"\"Check if the number has any even digit.\"\"\"\n return any(int(digit) % 2 == 0 for digit in str(n))\n\n # Filter the list to include only numbers without even digits\n result = [num for num in x if not has_even_digit(num)]\n \n # Return the sorted result\n return sorted(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" \n Input to this function is a string containing multiple groups of nested parentheses. \n Your goal is to separate those groups into separate strings and return the list of those.\n Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n Ignore any spaces in the input string.\n \n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n # Remove spaces from the input string\n paren_string = paren_string.replace(\" \", \"\")\n \n result = []\n balance = 0\n current_group = []\n \n for char in paren_string:\n if char == '(':\n if balance == 0 and current_group:\n result.append(''.join(current_group))\n current_group = []\n current_group.append(char)\n balance += 1\n elif char == ')':\n current_group.append(char)\n balance -= 1\n if balance == 0:\n result.append(''.join(current_group))\n current_group = []\n \n # In case there are any remaining groups (should not happen with valid input)\n if current_group:\n result.append(''.join(current_group))\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n \"\"\"Create a function which returns the largest index of an element which\n is not greater than or equal to the element immediately preceding it. If\n no such element exists then return -1. The given array will not contain\n duplicate values.\n\n Examples:\n can_arrange([1,2,4,3,5]) = 3\n can_arrange([1,2,3]) = -1\n \"\"\"\n # Initialize the index to -1, which will be returned if no such element is found\n largest_index = -1\n \n # Iterate through the array starting from the second element\n for i in range(1, len(arr)):\n # Check if the current element is less than the previous element\n if arr[i] < arr[i - 1]:\n largest_index = i # Update the largest index found\n \n return largest_index", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n '''\n Create a function that takes a string as input which contains only square brackets.\n The function should return True if and only if there is a valid subsequence of brackets \n where at least one bracket in the subsequence is nested.\n\n is_nested('[[]]') \u279e True\n is_nested('[]]]]]]][[[[[]') \u279e False\n is_nested('[][]') \u279e False\n is_nested('[]') \u279e False\n is_nested('[[][]]') \u279e True\n is_nested('[[]][[') \u279e True\n '''\n stack = []\n nested_found = False\n\n for char in string:\n if char == '[':\n stack.append(char)\n elif char == ']':\n if stack:\n stack.pop()\n if len(stack) > 0: # Check if there is a nested bracket\n nested_found = True\n else:\n return False # Unmatched closing bracket\n\n return nested_found and len(stack) == 0 # Must be balanced and have nested brackets", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["[[]][["]], "plus_fail_tests": [["[[]]]"]]}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n \n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n \"\"\"\n if not numbers:\n return (0, 1)\n \n total_sum = sum(numbers)\n total_product = 1\n for number in numbers:\n total_product *= number\n \n return (total_sum, total_product)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n \"\"\"\n You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n \n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n \n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots that exist in stock\n \n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n \"\"\"\n # Calculate how many more carrots are needed\n additional_needed = need - number\n \n # If no additional carrots are needed, return the current state\n if additional_needed <= 0:\n return [number, remaining]\n \n # Determine how many carrots can be eaten from the remaining stock\n eaten = min(additional_needed, remaining)\n \n # Calculate the total eaten and remaining carrots\n total_eaten = number + eaten\n remaining_after_meals = remaining - eaten\n \n return [total_eaten, remaining_after_meals]", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": [[2, 2, 2]]}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n \"\"\"You are given a string s.\n if s[i] is a letter, reverse its case from lower to upper or vise versa, \n otherwise keep it as it is.\n If the string contains no letters, reverse the string.\n The function should return the resulted string.\n \n Examples:\n solve(\"1234\") = \"4321\"\n solve(\"ab\") = \"AB\"\n solve(\"#a@C\") = \"#A@c\"\n \"\"\"\n # Check if there are any letters in the string\n has_letters = any(c.isalpha() for c in s)\n \n if has_letters:\n # Reverse case for letters and keep others the same\n return ''.join(c.swapcase() if c.isalpha() else c for c in s)\n else:\n # Reverse the string if there are no letters\n return s[::-1]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return True if the three\n sides form a right-angled triangle, False otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or \n 90 degree.\n \n Example:\n right_angle_triangle(3, 4, 5) == True\n right_angle_triangle(1, 2, 3) == False\n '''\n # Sort the sides to identify the longest side\n sides = sorted([a, b, c])\n \n # Check the Pythagorean theorem\n return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n \"\"\"Convert a decimal number to binary format with specific formatting.\n \n Args:\n decimal (int): A non-negative integer to convert to binary.\n \n Returns:\n str: A string representing the binary format of the decimal number,\n prefixed and suffixed with 'db'.\n \n Examples:\n >>> decimal_to_binary(15)\n 'db1111db'\n >>> decimal_to_binary(32)\n 'db100000db'\n \"\"\"\n if decimal < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n # Convert decimal to binary and remove the '0b' prefix\n binary_representation = bin(decimal)[2:]\n \n # Format the output with 'db' at the beginning and end\n formatted_output = f\"db{binary_representation}db\"\n \n return formatted_output", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef x_or_y(n, x, y):\n \"\"\"Return the value of x if n is a prime number, otherwise return y.\"\"\"\n if is_prime(n):\n return x\n else:\n return y", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fib4(0) -> 0\n fib4(1) -> 0\n fib4(2) -> 2\n fib4(3) -> 0\n fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.\n \n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 2\n elif n == 3:\n return 0\n\n # Initialize the first four values of the sequence\n fib_values = [0, 0, 2, 0]\n\n # Compute the values iteratively\n for i in range(4, n + 1):\n next_value = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n fib_values.append(next_value)\n\n return fib_values[n]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n \"\"\"\n Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move at the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.\n\n Parameters:\n n (int): The number of cars in each direction.\n\n Returns:\n int: The total number of collisions.\n \"\"\"\n # Each car moving left to right will collide with each car moving right to left\n # Therefore, the total number of collisions is n * n\n return n * n", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n \"\"\"\n Checks if given string is a palindrome.\n \n A palindrome is a string that reads the same forward and backward.\n \n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n \"\"\"\n # Normalize the string by removing spaces and converting to lowercase\n normalized_text = text.replace(\" \", \"\").lower()\n # Check if the string is equal to its reverse\n return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["never odd or even"]]}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this integer is a cube of some integer number.\n Note: you may assume the input is always valid.\n \n Examples:\n iscube(1) ==> True\n iscube(2) ==> False\n iscube(-1) ==> True\n iscube(64) ==> True\n iscube(0) ==> True\n iscube(180) ==> False\n '''\n # Calculate the cube root of the absolute value of a\n cube_root = round(abs(a) ** (1/3))\n \n # Check if the cube of the rounded cube root equals the absolute value of a\n return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n \"\"\"You are given two positive integers n and m, and your task is to compute the\n average of the integers from n through m (including n and m). \n Round the answer to the nearest integer and convert that to binary.\n If n is greater than m, return -1.\n \n Example:\n rounded_avg(1, 5) => \"0b11\"\n rounded_avg(7, 5) => -1\n rounded_avg(10, 20) => \"0b1111\"\n rounded_avg(20, 33) => \"0b11010\"\n \"\"\"\n if n > m:\n return -1\n \n # Calculate the sum of integers from n to m\n total_sum = sum(range(n, m + 1))\n count = m - n + 1 # Total numbers from n to m\n \n # Calculate the average and round it\n average = total_sum / count\n rounded_average = round(average)\n \n # Convert the rounded average to binary\n return bin(rounded_average)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n \"\"\"\n Given a positive integer n, return the count of the numbers of n-digit\n positive integers that start or end with 1.\n \"\"\"\n if n < 1:\n return 0\n\n # Total n-digit numbers\n total_n_digit_numbers = 9 * (10 ** (n - 1))\n\n # Count of n-digit numbers that start with 1\n start_with_1 = 10 ** (n - 1)\n\n # Count of n-digit numbers that end with 1\n end_with_1 = 9 * (10 ** (n - 2)) if n > 1 else 0\n\n # Total count of n-digit numbers that start or end with 1\n total_count = start_with_1 + end_with_1\n\n return total_count", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[2]], "plus_fail_tests": [[6]]}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits will be 1 the output should be \"1\".\n For N = 150, the sum of digits will be 6 the output should be \"110\".\n For N = 147, the sum of digits will be 12 the output should be \"1100\".\n \n Variables:\n @N integer\n Constraints: 0 \u2264 N \u2264 10000.\n Output:\n a string of binary number\n \"\"\"\n # Calculate the sum of the digits of N\n digit_sum = sum(int(digit) for digit in str(N))\n \n # Convert the sum to binary and remove the '0b' prefix\n binary_sum = bin(digit_sum)[2:]\n \n return binary_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n '''\n Given list of integers, return list in strange order.\n Strange sorting, is when you start with the minimum value,\n then maximum of the remaining integers, then minimum and so on.\n\n Examples:\n strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n strange_sort_list([]) == []\n '''\n if not lst:\n return []\n\n sorted_lst = sorted(lst)\n result = []\n left, right = 0, len(sorted_lst) - 1\n\n while left <= right:\n if left == right:\n result.append(sorted_lst[left])\n else:\n result.append(sorted_lst[left])\n result.append(sorted_lst[right])\n left += 1\n right -= 1\n\n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n \"\"\" Return length of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n \"\"\"\n return len(string)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(28)\n 14\n >>> largest_divisor(1)\n 0\n >>> largest_divisor(10)\n 5\n \"\"\"\n if n <= 1:\n return 0 # No divisors for 1 or less\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return the area of\n the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n Otherwise return -1.\n Three sides make a valid triangle when the sum of any two sides is greater \n than the third side.\n \n Example:\n triangle_area(3, 4, 5) == 6.00\n triangle_area(1, 2, 10) == -1\n '''\n # Check for valid triangle condition\n if a + b > c and a + c > b and b + c > a:\n # Calculate the semi-perimeter\n s = (a + b + c) / 2\n # Calculate the area using Heron's formula\n area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n return round(area, 2)\n else:\n return -1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n \n >>> longest([])\n >>> None\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n \"\"\"\n if not strings:\n return None\n \n longest_string = strings[0]\n \n for string in strings:\n if len(string) > len(longest_string):\n longest_string = string\n \n return longest_string", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n result = 1\n base = 2 % p # Start with 2 mod p\n while n > 0:\n if n % 2 == 1: # If n is odd, multiply the base with the result\n result = (result * base) % p\n base = (base * base) % p # Square the base\n n //= 2 # Divide n by 2\n return result", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[0, 1]]}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef prime_length(string):\n \"\"\"Return True if the string length is a prime number, False otherwise.\"\"\"\n length = len(string)\n return is_prime(length)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n \"\"\"Returns True if x is a simple power of n, otherwise False.\n \n A number x is a simple power of n if there exists an integer k such that n**k = x.\n \n Args:\n x (int): The number to check.\n n (int): The base number.\n \n Returns:\n bool: True if x is a simple power of n, False otherwise.\n \"\"\"\n if n <= 1:\n return x == 1 # 1 is a power of any number, and no other number can be a power of 1 or less.\n \n power = 1\n while True:\n result = n ** power\n if result == x:\n return True\n elif result > x:\n return False\n power += 1", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[1, 12]], "plus_fail_tests": [[1, 4]]}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n \n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n \"\"\"\n return ' '.join(str(i) for i in range(n + 1))", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[1000000]]}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n \"\"\"\n triples_sum_to_zero takes a list of integers as an input.\n it returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n \"\"\"\n n = len(l)\n # Sort the list to use the two-pointer technique\n l.sort()\n \n for i in range(n - 2):\n # Avoid duplicates for the first element\n if i > 0 and l[i] == l[i - 1]:\n continue\n \n left, right = i + 1, n - 1\n while left < right:\n current_sum = l[i] + l[left] + l[right]\n if current_sum == 0:\n return True\n elif current_sum < 0:\n left += 1\n else:\n right -= 1\n \n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n \"\"\"Counts the number of prime hexadecimal digits in the given hexadecimal string.\"\"\"\n # Define the set of prime hexadecimal digits\n prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n \n # Count the number of prime hexadecimal digits in the input string\n count = sum(1 for digit in num if digit in prime_hex_digits)\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n \"\"\"Return median of elements in the list l.\n \n The median is the middle value in a list of numbers. If the list has an even number of elements,\n the median is the average of the two middle numbers.\n \n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty\")\n \n sorted_list = sorted(l)\n n = len(sorted_list)\n mid = n // 2\n \n if n % 2 == 0: # Even number of elements\n return (sorted_list[mid - 1] + sorted_list[mid]) / 2\n else: # Odd number of elements\n return sorted_list[mid]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return a greatest common divisor of two integers a and b\n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n \"\"\"\n while b:\n a, b = b, a % b\n return abs(a)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers\n >>> filter_integers(['a', 3.14, 5])\n [5]\n >>> filter_integers([1, 2, 3, 'abc', {}, []])\n [1, 2, 3]\n \"\"\"\n return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[[true, false, null, 0, -10, "test", [], {}, 3.14]]]}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string\n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n \"\"\"\n return [string[:i] for i in range(1, len(string) + 1)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with the encode_cyclic function.\n Returns the decoded string.\n \"\"\"\n # Split string into groups of length 3\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # Reverse the cycling of elements in each group\n groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n Input number should be equal to the product of all factors\n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n \"\"\"\n factors = []\n # Check for number of 2s that divide n\n while n % 2 == 0:\n factors.append(2)\n n //= 2\n \n # n must be odd at this point so a skip of 2 (i.e., check only odd numbers) can be used\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, append i and divide n\n while n % i == 0:\n factors.append(i)\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n factors.append(n)\n \n return factors", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n \n For example:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n >>> is_bored(\"I am happy! Are you? I will go now.\")\n 2\n >>> is_bored(\"What a day. I can't believe it! I am so excited.\")\n 2\n \"\"\"\n # Split the input string into sentences using the delimiters\n sentences = []\n current_sentence = []\n for char in S:\n if char in '.!?':\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n current_sentence = []\n else:\n current_sentence.append(char)\n if current_sentence: # Add the last sentence if it exists\n sentences.append(''.join(current_sentence).strip())\n \n # Count the number of sentences that start with \"I\"\n boredom_count = sum(1 for sentence in sentences if sentence.startswith('I'))\n \n return boredom_count", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": [["In the morning, I like to have a cup of coffee to start my day off right. How about you?"]]}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n \n >>> circular_shift(12, 1)\n '21'\n >>> circular_shift(12, 2)\n '12'\n >>> circular_shift(12345, 1)\n '51234'\n >>> circular_shift(12345, 5)\n '54321'\n >>> circular_shift(12345, 6)\n '54321'\n \"\"\"\n # Convert the integer to a string to manipulate its digits\n str_x = str(x)\n num_digits = len(str_x)\n \n # If shift is greater than the number of digits, reverse the string\n if shift >= num_digits:\n return str_x[::-1]\n \n # Calculate the effective shift\n effective_shift = shift % num_digits\n \n # Perform the circular shift\n shifted_str = str_x[-effective_shift:] + str_x[:-effective_shift]\n \n return shifted_str", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[12, 2]], "plus_fail_tests": [[987654321, 9]]}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n \"\"\" \n xs represent coefficients of a polynomial.\n xs[0] + xs[1] * x + xs[2] * x^2 + ....\n Return derivative of this polynomial in the same form.\n \n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n \"\"\"\n # The derivative of a polynomial is calculated by multiplying each coefficient\n # by its corresponding power and reducing the power by one.\n return [i * coeff for i, coeff in enumerate(xs[1:], start=1)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two words have the same characters if they contain the same unique characters,\n regardless of the number of times each character appears.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n \"\"\"Add two numbers x and y.\n \n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n \"\"\"\n return x + y", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n count_upper('aBCdEf') returns 1\n count_upper('abcdefg') returns 0\n count_upper('dBBE') returns 0\n \"\"\"\n uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n count = 0\n \n for i in range(0, len(s), 2): # Iterate over even indices\n if s[i] in uppercase_vowels:\n count += 1\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_up_to(n):\n \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n primes = []\n for i in range(2, n):\n if is_prime(i):\n primes.append(i)\n return primes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n \"\"\"\n return [x for x in l if x > 0]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n even_indices = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indexed elements\n even_indices.sort()\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Place the sorted even indexed elements back into their positions\n for i, value in enumerate(even_indices):\n result[i * 2] = value\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n \"\"\"Return True if all numbers in the list l are below threshold t.\n \n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n \"\"\"\n return all(x < t for x in l)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n >>> closest_integer(\"14.5\")\n 15\n >>> closest_integer(\"-14.5\")\n -15\n >>> closest_integer(\"0.5\")\n 1\n >>> closest_integer(\"-0.5\")\n -1\n '''\n # Convert the string to a float\n num = float(value)\n \n # Get the floor and ceiling of the number\n lower = int(num // 1) # This is the largest integer less than or equal to num\n upper = lower + 1 # This is the smallest integer greater than num\n \n # Check if the number is equidistant from lower and upper\n if abs(num - lower) < abs(num - upper):\n return lower\n elif abs(num - lower) > abs(num - upper):\n return upper\n else:\n # If equidistant, round away from zero\n if num > 0:\n return upper\n else:\n return lower", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000"]]}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef fibonacci(n: int) -> int:\n \"\"\"Return the n-th Fibonacci number.\"\"\"\n a, b = 0, 1\n for _ in range(n):\n a, b = b, a + b\n return a\ndef prime_fib(n: int) -> int:\n \"\"\"\n prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n count = 0\n i = 0\n while True:\n fib_num = fibonacci(i)\n if is_prime(fib_num):\n count += 1\n if count == n:\n return fib_num\n i += 1", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[12]]}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n \"\"\"Return n-th Fibonacci number.\n \n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n elif n == 1:\n return 1\n elif n == 2:\n return 1\n else:\n a, b = 1, 1\n for _ in range(2, n):\n a, b = b, a + b\n return b", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[0]]}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.\n \"\"\"\n # Get the unit digit of the first number\n unit_digit_a = abs(a) % 10\n # Get the unit digit of the second number\n unit_digit_b = abs(b) % 10\n # Return the product of the unit digits\n return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n \n Args:\n n (int): The index of the FibFib number to compute.\n \n Returns:\n int: The n-th FibFib number.\n \n Examples:\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 1\n \n # Initialize the first three FibFib numbers\n fibfib_numbers = [0, 0, 1]\n \n # Compute the FibFib numbers iteratively\n for i in range(3, n + 1):\n next_fibfib = fibfib_numbers[i - 1] + fibfib_numbers[i - 2] + fibfib_numbers[i - 3]\n fibfib_numbers.append(next_fibfib)\n \n return fibfib_numbers[n]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Sort the unique elements\n sorted_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_elements[1]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = 0\n s = s.lower() # Convert to lowercase to handle case insensitivity\n\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1: # Check if 'y' is at the end\n count += 1\n\n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n \"\"\"Simplifies the expression x * n and checks if it evaluates to a whole number.\n \n Args:\n x (str): A string representation of a fraction in the format /.\n n (str): A string representation of a fraction in the format /.\n \n Returns:\n bool: True if x * n evaluates to a whole number, False otherwise.\n \"\"\"\n # Split the fractions into numerator and denominator\n x_numerator, x_denominator = map(int, x.split('/'))\n n_numerator, n_denominator = map(int, n.split('/'))\n \n # Calculate the product of the fractions\n # x * n = (x_numerator / x_denominator) * (n_numerator / n_denominator)\n # This simplifies to (x_numerator * n_numerator) / (x_denominator * n_denominator)\n numerator_product = x_numerator * n_numerator\n denominator_product = x_denominator * n_denominator\n \n # Check if the result is a whole number\n return numerator_product % denominator_product == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef words_in_sentence(sentence):\n \"\"\"\n You are given a string representing a sentence,\n the sentence contains some words separated by a space,\n and you have to return a string that contains the words from the original sentence,\n whose lengths are prime numbers,\n the order of the words in the new string should be the same as the original one.\n\n Example 1:\n Input: sentence = \"This is a test\"\n Output: \"is\"\n\n Example 2:\n Input: sentence = \"lets go for swimming\"\n Output: \"go for\"\n\n Constraints:\n * 1 <= len(sentence) <= 100\n * sentence contains only letters\n \"\"\"\n words = sentence.split()\n prime_length_words = [word for word in words if is_prime(len(word))]\n return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n \"\"\"In this problem, you will implement a function that takes two lists of numbers,\n and determines whether it is possible to perform an exchange of elements\n between them to make lst1 a list of only even numbers.\n There is no limit on the number of exchanged elements between lst1 and lst2.\n If it is possible to exchange elements between the lst1 and lst2 to make\n all the elements of lst1 to be even, return \"YES\".\n Otherwise, return \"NO\".\n For example:\n exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"YES\"\n exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n It is assumed that the input lists will be non-empty.\n \"\"\"\n # Count the number of odd numbers in lst1\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n \n # Check if there are enough even numbers in lst2 to replace the odd numbers in lst1\n even_count_lst2 = sum(1 for x in lst2 if x % 2 == 0)\n \n # If the number of odd numbers in lst1 is less than or equal to the number of even numbers in lst2\n if odd_count_lst1 <= even_count_lst2:\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n \"\"\"Given a string s and a natural number n, returns a list of all words from \n string s that contain exactly n consonants, in the order they appear in the \n string s. If the string s is empty, returns an empty list.\n \n Args:\n s (str): The input string containing words.\n n (int): The number of consonants to match.\n \n Returns:\n list: A list of words containing exactly n consonants.\n \"\"\"\n \n if not s:\n return []\n \n # Define a set of consonants\n consonants = set(\"bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ\")\n \n # Split the string into words\n words = s.split()\n \n # Function to count consonants in a word\n def count_consonants(word):\n return sum(1 for char in word if char in consonants)\n \n # Select words with exactly n consonants\n result = [word for word in words if count_consonants(word) == n]\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n if not arr:\n return None\n\n product_of_signs = 1\n sum_of_magnitudes = 0\n\n for num in arr:\n if num > 0:\n sum_of_magnitudes += num\n elif num < 0:\n sum_of_magnitudes += -num\n product_of_signs *= -1\n else: # num == 0\n return 0 # If there's a zero, the product of signs is zero\n\n return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n \n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0: # More closing than opening\n return False\n return balance == 0 # Must be balanced at the end\n\n # Check both concatenation orders\n return 'Yes' if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]) else 'No'", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n '''\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return False. Assume no negative numbers and only integers.\n\n Examples\n is_sorted([5]) \u279e True\n is_sorted([1, 2, 3, 4, 5]) \u279e True\n is_sorted([1, 3, 2, 4, 5]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n '''\n if len(lst) <= 1:\n return True\n \n seen = set()\n last_num = None\n \n for num in lst:\n if num in seen:\n return False\n seen.add(num)\n \n if last_num is not None and num < last_num:\n return False\n \n last_num = num\n \n return True", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": [[[1, 1, 2, 2, 3, 3, 4]]]}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n \"\"\"\n Write a function which sorts the given list of integers\n in ascending order according to the sum of their digits.\n Note: if there are several items with similar sum of their digits,\n order them based on their index in original list.\n\n For example:\n >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n >>> order_by_points([]) == []\n \"\"\"\n \n def digit_sum(n):\n \"\"\"Calculate the sum of the digits of n.\"\"\"\n return sum(int(digit) for digit in str(abs(n)))\n\n # Sort the list based on the sum of digits and original index\n return sorted(nums, key=lambda x: (digit_sum(x), nums.index(x)))", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": [[[-5, -12, 9, 15]]]}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n \"\"\"\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n \n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126\n \"\"\"\n total_sum = 0\n for index, value in enumerate(lst):\n if index % 3 == 0:\n total_sum += value ** 2\n elif index % 4 == 0:\n total_sum += value ** 3\n else:\n total_sum += value\n return total_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n two consonants from the right side of the word (case sensitive).\n \n Vowels in the beginning and ending don't count. Return empty string if you didn't\n find any vowel that meets the above condition. \n\n You may assume that the given string contains English letters only.\n\n Example:\n get_closest_vowel(\"yogurt\") ==> \"u\"\n get_closest_vowel(\"FULL\") ==> \"U\"\n get_closest_vowel(\"quick\") ==> \"\"\n get_closest_vowel(\"ab\") ==> \"\"\n \"\"\"\n vowels = \"aeiouAEIOU\"\n n = len(word)\n\n # Start from the end of the word\n for i in range(n - 2, 0, -1):\n if word[i] in vowels:\n # Check if the characters before and after the vowel are consonants\n if word[i - 1].isalpha() and word[i + 1].isalpha() and \\\n word[i - 1] not in vowels and word[i + 1] not in vowels:\n return word[i]\n \n return \"\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef intersection(interval1, interval2):\n \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n start1, end1 = interval1\n start2, end2 = interval2\n \n # Find the intersection\n start_intersection = max(start1, start2)\n end_intersection = min(end1, end2)\n \n # Check if there is an intersection\n if start_intersection > end_intersection:\n return \"NO\"\n \n # Calculate the length of the intersection\n length_of_intersection = end_intersection - start_intersection\n \n # Check if the length is a prime number\n if is_prime(length_of_intersection):\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Get the top k elements\n top_k = sorted_arr[:k]\n # Sort the result in ascending order before returning\n return sorted(top_k)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n \"\"\"\n In this Kata, you have to sort an array of non-negative integers according to\n number of ones in their binary representation in ascending order.\n For similar number of ones, sort based on decimal value.\n\n It must be implemented like this:\n >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n >>> sort_array([1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]\n \"\"\"\n # Sort the array using a custom key\n return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n \"\"\"\n if not test:\n return {}\n\n # Split the input string into a list of letters\n letters = test.split()\n \n # Create a dictionary to count occurrences of each letter\n count_dict = {}\n for letter in letters:\n count_dict[letter] = count_dict.get(letter, 0) + 1\n\n # Find the maximum count\n max_count = max(count_dict.values())\n \n # Create a result dictionary for letters with the maximum count\n result = {letter: count for letter, count in count_dict.items() if count == max_count}\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n from collections import deque\n\n N = len(grid)\n directions = [(0, 1), (1, 0), (0, -1), (-1, 0)] # right, down, left, up\n min_path = None\n\n def dfs(x, y, path):\n nonlocal min_path\n if len(path) == k:\n if min_path is None or path < min_path:\n min_path = path[:]\n return\n \n for dx, dy in directions:\n nx, ny = x + dx, y + dy\n if 0 <= nx < N and 0 <= ny < N:\n path.append(grid[nx][ny])\n dfs(nx, ny, path)\n path.pop()\n\n for i in range(N):\n for j in range(N):\n dfs(i, j, [grid[i][j]])\n\n return min_path", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": [[[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 15]]}]}} \ No newline at end of file diff --git a/EVALPLUS-4omini/4.json b/EVALPLUS-4omini/4.json new file mode 100644 index 000000000..756827c37 --- /dev/null +++ b/EVALPLUS-4omini/4.json @@ -0,0 +1 @@ +{"date": "2024-07-20 13:00", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascending order.\n\n For example:\n generate_integers(2, 8) => [2, 4, 6, 8]\n generate_integers(8, 2) => [2, 4, 6, 8]\n generate_integers(10, 14) => []\n \"\"\"\n # Determine the range of numbers to consider\n start = min(a, b)\n end = max(a, b)\n\n # Generate a list of even integers in the specified range\n even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n return even_integers", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[2, 10]], "plus_fail_tests": [[6, 12]]}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n Example:\n even_odd_count(-12) ==> (1, 1)\n even_odd_count(123) ==> (1, 2)\n \"\"\"\n # Convert the number to a string and remove the negative sign if present\n num_str = str(abs(num))\n \n even_count = 0\n odd_count = 0\n \n # Iterate through each character in the string representation of the number\n for digit in num_str:\n if digit.isdigit(): # Check if the character is a digit\n if int(digit) % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n return (even_count, odd_count)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n \"\"\"Compares the actual game scores with the guessed scores and returns the absolute differences.\n \n Args:\n game (list of int): The actual scores of the matches.\n guess (list of int): The guessed scores of the matches.\n \n Returns:\n list of int: A list containing the absolute differences between the actual scores and the guessed scores.\n If the guess is correct, the difference is 0.\n \"\"\"\n return [abs(g - a) for a, g in zip(game, guess)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def compare_one(a, b):\n \"\"\"\n Create a function that takes integers, floats, or strings representing\n real numbers, and returns the larger variable in its given variable type.\n Return None if the values are equal.\n Note: If a real number is represented as a string, the floating point might be . or ,\n\n compare_one(1, 2.5) \u279e 2.5\n compare_one(1, \"2,3\") \u279e \"2,3\"\n compare_one(\"5,1\", \"6\") \u279e \"6\"\n compare_one(\"1\", 1) \u279e None\n \"\"\"\n \n def parse_value(value):\n \"\"\"Convert the input value to a float or return it as is if it's not a number.\"\"\"\n if isinstance(value, str):\n # Replace comma with dot for float conversion\n value = value.replace(',', '.')\n try:\n return float(value)\n except ValueError:\n return value # Return the string if it cannot be converted\n return value # Return the number as is\n\n # Parse both values\n parsed_a = parse_value(a)\n parsed_b = parse_value(b)\n\n # Check for equality\n if parsed_a == parsed_b:\n return None\n\n # Return the larger value in its original type\n if parsed_a > parsed_b:\n return a\n else:\n return b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n \"\"\"\n Write a function count_nums which takes an array of integers and returns\n the number of elements which has a sum of digits > 0.\n If a number is negative, then its first signed digit will be negative:\n e.g. -123 has signed digits -1, 2, and 3.\n \n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n def sum_of_digits(n):\n # Convert the number to string and calculate the sum of its digits\n return sum(int(digit) if digit != '-' else -int(digit[1]) for digit in str(n) if digit.isdigit() or digit == '-')\n\n count = 0\n for number in arr:\n if sum_of_digits(number) > 0:\n count += 1\n \n return count", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[-1, -2, 0]]], "plus_fail_tests": [[[-1, 0, 1]]]}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list to avoid division by zero\n\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def factorial(i):\n \"\"\"Calculate the factorial of a given number i.\"\"\"\n if i == 0 or i == 1:\n return 1\n result = 1\n for j in range(2, i + 1):\n result *= j\n return result\ndef sum_of_numbers(i):\n \"\"\"Calculate the sum of numbers from 1 to i.\"\"\"\n return (i * (i + 1)) // 2\ndef f(n):\n \"\"\"Return a list of size n, where the value at index i is the factorial of i if i is even,\n or the sum of numbers from 1 to i otherwise. Indexing starts from 1.\n \"\"\"\n result = []\n for i in range(1, n + 1):\n if i % 2 == 0: # i is even\n result.append(factorial(i))\n else: # i is odd\n result.append(sum_of_numbers(i))\n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n \"\"\"\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n \"\"\"\n # Split the string by commas and spaces, then filter out any empty strings\n words = [word.strip() for word in s.replace(',', ' ').split() if word]\n return words", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" \n You're given a list of deposit and withdrawal operations on a bank account that starts with\n zero balance. Your task is to detect if at any point the balance of account falls below zero, and\n at that point function should return True. Otherwise it should return False.\n \n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n \"\"\"\n balance = 0\n for operation in operations:\n balance += operation\n if balance < 0:\n return True\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string.\n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n >>> string_to_md5('') is None\n >>> string_to_md5('Python') == '5d41402abc4b2a76b9719d911017c592'\n \"\"\"\n if text == \"\":\n return None\n md5_hash = hashlib.md5(text.encode()).hexdigest()\n return md5_hash", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n \"\"\"Find the strongest extension based on the defined strength criteria.\"\"\"\n strongest_extension = None\n max_strength = float('-inf') # Start with the lowest possible strength\n\n for extension in extensions:\n # Calculate the strength of the current extension\n CAP = sum(1 for char in extension if char.isupper())\n SM = sum(1 for char in extension if char.islower())\n strength = CAP - SM\n\n # Check if this extension is stronger than the current strongest\n if strength > max_strength:\n max_strength = strength\n strongest_extension = extension\n\n # Return the result in the specified format\n return f\"{class_name}.{strongest_extension}\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n \"\"\"Calculate the factorial of a non-negative integer n.\"\"\"\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef special_factorial(n):\n \"\"\"Calculate the Brazilian factorial of n.\"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n result = 1\n for i in range(1, n + 1):\n result *= factorial(i)\n \n return result", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[500]]}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n \"\"\"You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word.\n \n Args:\n a (str): The first word.\n b (str): The second word.\n \n Returns:\n bool: True if b or any of its rotations is a substring of a, False otherwise.\n \n Examples:\n >>> cycpattern_check(\"abcd\", \"abd\")\n False\n >>> cycpattern_check(\"hello\", \"ell\")\n True\n >>> cycpattern_check(\"whassup\", \"psus\")\n False\n >>> cycpattern_check(\"abab\", \"baa\")\n True\n >>> cycpattern_check(\"efef\", \"eeff\")\n False\n >>> cycpattern_check(\"himenss\", \"simen\")\n True\n \"\"\"\n # Create a string that contains all rotations of b\n rotations = [b[i:] + b[:i] for i in range(len(b))]\n \n # Check if any rotation is a substring of a\n for rotation in rotations:\n if rotation in a:\n return True\n \n return False", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["", ""]]}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into\n an integer part (largest integer smaller than given number) and decimals\n (leftover part always smaller than 1).\n\n Return the decimal part of the number.\n \n >>> truncate_number(3.5)\n 0.5\n >>> truncate_number(2.75)\n 0.75\n >>> truncate_number(5.0)\n 0.0\n >>> truncate_number(0.99)\n 0.99\n \"\"\"\n if number < 0:\n raise ValueError(\"The number must be positive.\")\n \n integer_part = int(number) # Get the integer part\n decimal_part = number - integer_part # Calculate the decimal part\n return decimal_part", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n \"\"\"Calculate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n if n < 0:\n return []\n\n # Initialize the list to store the Tribonacci numbers\n tribonacci_sequence = []\n\n # Define the base cases\n for i in range(n + 1):\n if i == 0:\n tribonacci_sequence.append(1) # tri(0) = 1\n elif i == 1:\n tribonacci_sequence.append(3) # tri(1) = 3\n elif i % 2 == 0: # Even case\n tribonacci_sequence.append(1 + i / 2)\n else: # Odd case\n tri_n_minus_1 = tribonacci_sequence[i - 1]\n tri_n_minus_2 = tribonacci_sequence[i - 2]\n tri_n_plus_1 = tribonacci_sequence[i + 1] if i + 1 <= n else 0\n tribonacci_sequence.append(tri_n_minus_1 + tri_n_minus_2 + tri_n_plus_1)\n\n return tribonacci_sequence", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[3]], "plus_fail_tests": [[10]]}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n \"\"\"\n Given a positive integer n, return a tuple that has the number of even and odd\n integer palindromes that fall within the range(1, n), inclusive.\n\n Example 1:\n\n Input: 3\n Output: (1, 2)\n Explanation:\n Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n Example 2:\n\n Input: 12\n Output: (4, 6)\n Explanation:\n Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n Note:\n 1. 1 <= n <= 10^3\n 2. returned tuple has the number of even and odd integer palindromes respectively.\n \"\"\"\n even_count = 0\n odd_count = 0\n\n for i in range(1, n + 1):\n if str(i) == str(i)[::-1]: # Check if the number is a palindrome\n if i % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n return (even_count, odd_count)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n \"\"\"\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n >>> make_a_pile(4)\n [4, 6, 8, 10]\n >>> make_a_pile(1)\n [1]\n \"\"\"\n stones = []\n current_stones = n\n \n for i in range(n):\n stones.append(current_stones)\n if current_stones % 2 == 0: # current_stones is even\n current_stones += 2 # next even number\n else: # current_stones is odd\n current_stones += 2 # next odd number\n \n return stones", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n \n Args:\n n (int): The number to evaluate.\n \n Returns:\n bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n \n Example:\n is_equal_to_sum_even(4) == False\n is_equal_to_sum_even(6) == False\n is_equal_to_sum_even(8) == True\n \"\"\"\n # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n if n < 8:\n return False\n \n # Check if n is even\n if n % 2 != 0:\n return False\n \n # If n is even and >= 8, it can be expressed as the sum of 4 positive even numbers\n return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n \"\"\" Insert a number 'delimiter' between every two consecutive elements of input list `numbers`\n \n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n for i in range(len(numbers)):\n result.append(numbers[i])\n if i < len(numbers) - 1: # Avoid adding delimiter after the last element\n result.append(delimiter)\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n \"\"\"Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n For example:\n digits(1) == 1\n digits(4) == 0\n digits(235) == 15\n \"\"\"\n product = 1\n has_odd = False\n \n for digit in str(n):\n digit = int(digit)\n if digit % 2 != 0: # Check if the digit is odd\n product *= digit\n has_odd = True\n \n return product if has_odd else 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n '''\n Create a function that returns a tuple (a, b), where 'a' is\n the largest of negative integers, and 'b' is the smallest\n of positive integers in a list.\n If there is no negative or positive integers, return them as None.\n\n Examples:\n largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n largest_smallest_integers([]) == (None, None)\n largest_smallest_integers([0]) == (None, None)\n '''\n largest_negative = None\n smallest_positive = None\n\n for num in lst:\n if num < 0:\n if largest_negative is None or num > largest_negative:\n largest_negative = num\n elif num > 0:\n if smallest_positive is None or num < smallest_positive:\n smallest_positive = num\n\n return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return True else return False.\n If the given array is empty then return True.\n\n Note: The given list is guaranteed to have unique elements.\n\n For Example:\n \n move_one_ball([3, 4, 5, 1, 2])==>True\n Explanation: By performing 2 right shift operations, non-decreasing order can\n be achieved for the given array.\n move_one_ball([3, 5, 4, 1, 2])==>False\n Explanation: It is not possible to get non-decreasing order for the given\n array by performing any number of right shift operations.\n \"\"\"\n if not arr:\n return True\n\n n = len(arr)\n sorted_arr = sorted(arr)\n\n # Check how many times we can right shift to match the sorted array\n for shift in range(n):\n # Create a new array based on the current shift\n shifted_arr = arr[-shift:] + arr[:-shift]\n if shifted_arr == sorted_arr:\n return True\n\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to make it easier to find the closest pair\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest elements\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n \n >>> flip_case('Hello')\n 'hELLO'\n >>> flip_case('Python')\n 'pYTHON'\n >>> flip_case('123abcXYZ')\n '123ABCxyz'\n >>> flip_case('')\n ''\n \"\"\"\n return string.swapcase()", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n \n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n \"\"\"\n count = 0\n start = 0\n \n while True:\n start = string.find(substring, start)\n if start == -1:\n break\n count += 1\n start += 1 # Move to the next character to allow for overlapping\n\n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n \"\"\" Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n \n >>> string_xor('010', '110')\n '100'\n >>> string_xor('111', '000')\n '111'\n >>> string_xor('101', '101')\n '000'\n >>> string_xor('000', '000')\n '000'\n >>> string_xor('1101', '1011')\n '0110'\n \"\"\"\n # Ensure both strings are of the same length\n max_len = max(len(a), len(b))\n a = a.zfill(max_len)\n b = b.zfill(max_len)\n \n # Perform XOR operation\n result = []\n for bit_a, bit_b in zip(a, b):\n result.append('1' if bit_a != bit_b else '0')\n \n return ''.join(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lower_string = string.lower()\n # Use a set to find distinct characters\n distinct_characters = set(lower_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n \n Args:\n strings (List[str]): A list of strings to filter.\n prefix (str): The prefix to filter the strings by.\n \n Returns:\n List[str]: A list of strings that start with the given prefix.\n \n Examples:\n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n \"\"\"\n return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted = []\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Calculate the new character by shifting it down by 4 places\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a')) if char.islower() else chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n encrypted.append(new_char)\n else:\n encrypted.append(char) # Non-alphabetic characters are not changed\n return ''.join(encrypted)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n \n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by row index (ascending) and then by column index (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n \n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n \"\"\"\n return [x + 1 for x in l]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n \"\"\"Given length of a side and height, return the area of a triangle.\n \n The area of a triangle can be calculated using the formula:\n area = (base * height) / 2\n \n Parameters:\n a (float): The length of the base of the triangle.\n h (float): The height of the triangle.\n \n Returns:\n float: The area of the triangle.\n \n Examples:\n >>> triangle_area(5, 3)\n 7.5\n >>> triangle_area(10, 2)\n 10.0\n >>> triangle_area(0, 5)\n 0.0\n >>> triangle_area(5, 0)\n 0.0\n \"\"\"\n return (a * h) / 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n \"\"\"\n Given an array arr of integers, find the minimum number of elements that\n need to be changed to make the array palindromic. A palindromic array is an array that\n is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n For example:\n smallest_change([1,2,3,5,4,7,9,6]) == 4\n smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n smallest_change([1, 2, 3, 2, 1]) == 0\n \"\"\"\n n = len(arr)\n changes = 0\n \n # Compare elements from the start and end towards the center\n for i in range(n // 2):\n if arr[i] != arr[n - 1 - i]:\n changes += 1\n \n return changes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total character counts and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n else:\n return lst2", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": [[["happy", "birthday", "sarah"], ["happy", "birthday", "sally"]]]}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n \"\"\"You are given a string s.\n Your task is to check if the string is happy or not.\n A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n \n For example:\n is_happy(a) => False\n is_happy(aa) => False\n is_happy(abcd) => True\n is_happy(aabb) => False\n is_happy(adb) => True\n is_happy(xyy) => False\n \"\"\"\n # Check if the length of the string is at least 3\n if len(s) < 3:\n return False\n \n # Iterate through the string and check every 3 consecutive characters\n for i in range(len(s) - 2):\n # Get the current 3 characters\n substring = s[i:i+3]\n # Check if all characters in the substring are distinct\n if len(set(substring)) != 3:\n return False\n \n return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" Input to this function is a string representing musical notes in a special ASCII format.\n Your task is to parse this string and return list of integers corresponding to how many beats does each\n note last.\n\n Here is a legend:\n 'o' - whole note, lasts four beats\n 'o|' - half note, lasts two beats\n '.|' - quarter note, lasts one beat\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n # Define a mapping of note representations to their corresponding beat values\n note_to_beats = {\n 'o': 4, # whole note\n 'o|': 2, # half note\n '.|': 1 # quarter note\n }\n \n # Split the input string into individual notes\n notes = music_string.split()\n \n # Parse each note and convert it to its corresponding beat value\n beats = [note_to_beats[note] for note in notes if note in note_to_beats]\n \n return beats", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string.\n \n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n \"\"\"\n return ''.join(strings)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n \n >>> make_palindrome('')\n ''\n >>> make_palindrome('cat')\n 'catac'\n >>> make_palindrome('cata')\n 'catac'\n \"\"\"\n # Find the longest palindromic suffix\n for i in range(len(string)):\n if is_palindrome(string[i:]):\n # If the suffix is a palindrome, we need to append the reverse of the prefix\n prefix = string[:i]\n return string + prefix[::-1]\n return string # In case the string is empty or already a palindrome", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n \n # Create a new list with elements that occur only once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n \"\"\" \n Input is a space-delimited string of numerals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest.\n \n >>> sort_numbers('three one five')\n 'one three five'\n \"\"\"\n # Mapping of words to their corresponding numeric values\n num_map = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n \n # Split the input string into words\n words = numbers.split()\n \n # Sort the words based on their numeric values\n sorted_words = sorted(words, key=lambda word: num_map[word])\n \n # Join the sorted words back into a string\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1.\n \n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n min_val = min(numbers)\n max_val = max(numbers)\n \n # Avoid division by zero if all numbers are the same\n if min_val == max_val:\n return [0.0] * len(numbers)\n \n return [(num - min_val) / (max_val - min_val) for num in numbers]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n letter_grades = []\n \n for gpa in grades:\n if gpa == 4.0:\n letter_grades.append('A+')\n elif gpa > 3.7:\n letter_grades.append('A')\n elif gpa > 3.3:\n letter_grades.append('A-')\n elif gpa > 3.0:\n letter_grades.append('B+')\n elif gpa > 2.7:\n letter_grades.append('B')\n elif gpa > 2.3:\n letter_grades.append('B-')\n elif gpa > 2.0:\n letter_grades.append('C+')\n elif gpa > 1.7:\n letter_grades.append('C')\n elif gpa > 1.3:\n letter_grades.append('C-')\n elif gpa > 1.0:\n letter_grades.append('D+')\n elif gpa > 0.7:\n letter_grades.append('D')\n elif gpa > 0.0:\n letter_grades.append('D-')\n else:\n letter_grades.append('E')\n \n return letter_grades", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef get_primes_up_to(n):\n \"\"\"Return a list of all prime numbers less than n.\"\"\"\n return [i for i in range(2, n) if is_prime(i)]\ndef is_multiply_prime(a):\n \"\"\"Return true if the given number is the multiplication of 3 prime numbers.\"\"\"\n if a >= 100:\n return False\n \n primes = get_primes_up_to(a)\n prime_count = len(primes)\n \n # Check all combinations of three primes\n for i in range(prime_count):\n for j in range(i, prime_count):\n for k in range(j, prime_count):\n product = primes[i] * primes[j] * primes[k]\n if product == a:\n return True\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n '''\n Write a function that returns True if the object q will fly, and False otherwise.\n The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n\n Example:\n will_it_fly([1, 2], 5) \u279e False \n # 1+2 is less than the maximum possible weight, but it's unbalanced.\n\n will_it_fly([3, 2, 3], 1) \u279e False\n # it's balanced, but 3+2+3 is more than the maximum possible weight.\n\n will_it_fly([3, 2, 3], 9) \u279e True\n # 3+2+3 is less than the maximum possible weight, and it's balanced.\n\n will_it_fly([3], 5) \u279e True\n # 3 is less than the maximum possible weight, and it's balanced.\n '''\n # Check if the list is a palindrome\n is_balanced = q == q[::-1]\n \n # Calculate the sum of the elements in the list\n total_weight = sum(q)\n \n # Return True if it's balanced and the total weight is less than or equal to w\n return is_balanced and total_weight <= w", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words while preserving spaces\n words = s.split(' ')\n \n # Sort each word and keep the spaces intact\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back with spaces\n result = ' '.join(sorted_words)\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion.\n base numbers are less than 10.\n \n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n \"\"\"\n if base < 2 or base >= 10:\n raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n \n if x == 0:\n return '0'\n \n result = []\n while x > 0:\n result.append(str(x % base))\n x //= base\n \n return ''.join(reversed(result))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n or sort it in descending order if the sum( first index value, last index value) is even.\n\n Note:\n * don't change the given array.\n\n Examples:\n * sort_array([]) => []\n * sort_array([5]) => [5]\n * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n \"\"\"\n if not array: # Check for empty array\n return []\n \n first_value = array[0]\n last_value = array[-1]\n sum_values = first_value + last_value\n\n # Create a sorted copy of the array based on the sum of first and last values\n if sum_values % 2 == 0: # Even sum\n return sorted(array, reverse=True) # Sort in descending order\n else: # Odd sum\n return sorted(array) # Sort in ascending order", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n \n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n \"\"\"\n seen = set()\n for number in l:\n if -number in seen:\n return True\n seen.add(number)\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in lower \n case or all keys are strings in upper case, else return False.\n The function should return False if the given dictionary is empty.\n \n Examples:\n check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n \"\"\"\n if not input_dict:\n return False\n\n all_lower = all(isinstance(key, str) and key.islower() for key in input_dict.keys())\n all_upper = all(isinstance(key, str) and key.isupper() for key in input_dict.keys())\n\n return all_lower or all_upper", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"(\" and \")\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"(\")\n False\n >>> correct_bracketing(\"()\")\n True\n >>> correct_bracketing(\"(()())\")\n True\n >>> correct_bracketing(\")(()\")\n False\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n # If balance goes negative, there are unmatched closing brackets\n if balance < 0:\n return False\n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n \"\"\"Task\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n \"\"\"\n return sum(ord(char) for char in s if char.isupper())", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n '''\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n \n Examples\n any_int(5, 2, 7) \u279e True\n \n any_int(3, 2, 2) \u279e False\n\n any_int(3, -2, 1) \u279e True\n \n any_int(3.6, -2.2, 2) \u279e False\n '''\n # Check if all inputs are integers\n if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n # Check if one number is equal to the sum of the other two\n return x == y + z or y == x + z or z == x + y\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n # Keep dividing n by factor until it is no longer divisible\n while n > 1:\n if n % factor == 0:\n n //= factor # Divide n by the factor\n else:\n factor += 1 # Move to the next potential factor\n return factor # The last factor is the largest prime factor", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with encode_shift function. Returns decoded string.\n \"\"\"\n return \"\".join([chr(((ord(ch) - ord(\"a\") - 5) % 26) + ord(\"a\")) for ch in s])", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n \"\"\"Return True if list elements are monotonically increasing or decreasing.\n \n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n \"\"\"\n if not l: # An empty list is considered monotonic\n return True\n \n increasing = decreasing = True\n \n for i in range(1, len(l)):\n if l[i] > l[i - 1]:\n decreasing = False\n elif l[i] < l[i - 1]:\n increasing = False\n \n return increasing or decreasing", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n \"\"\"\n Given an array representing a branch of a tree that has non-negative integer nodes,\n your task is to pluck one of the nodes and return it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n The plucked node should be returned in a list, [ smallest_value, its index ],\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index. \n\n Example 3:\n Input: []\n Output: []\n \n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n Explanation: 0 is the smallest value, but there are two zeros,\n so we will choose the first zero, which has the smallest index.\n\n Constraints:\n * 1 <= nodes.length <= 10000\n * 0 <= node.value\n \"\"\"\n smallest_even = float('inf')\n smallest_index = -1\n\n for index, value in enumerate(arr):\n if value % 2 == 0: # Check if the value is even\n if value < smallest_even: # Check if it's the smallest even found\n smallest_even = value\n smallest_index = index\n\n if smallest_index == -1: # No even value found\n return []\n \n return [smallest_even, smallest_index]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float) -> float:\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list) -> list:\n \"\"\"\n Computes the derivative of the polynomial with coefficients xs.\n \"\"\"\n return [i * coeff for i, coeff in enumerate(xs) if i > 0]\ndef find_zero(xs: list, initial_guess: float = 0.0, tolerance: float = 1e-7, max_iterations: int = 1000) -> float:\n \"\"\" \n xs are coefficients of a polynomial.\n find_zero finds x such that poly(x) = 0.\n find_zero returns only one zero point, even if there are many.\n Moreover, find_zero only takes list xs having an even number of coefficients\n and the largest non-zero coefficient as it guarantees a solution.\n \n >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n -0.5\n >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n 1.0\n \"\"\"\n if len(xs) % 2 != 0:\n raise ValueError(\"The number of coefficients must be even.\")\n \n current_guess = initial_guess\n for _ in range(max_iterations):\n f_value = poly(xs, current_guess)\n f_derivative = poly(derivative(xs), current_guess)\n \n if f_derivative == 0:\n raise ValueError(\"Derivative is zero. No solution found.\")\n \n next_guess = current_guess - f_value / f_derivative\n \n if abs(next_guess - current_guess) < tolerance:\n return next_guess\n \n current_guess = next_guess\n \n raise ValueError(\"Maximum iterations reached. No solution found.\")", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[[5, 10, -3, 1]]]}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n \"\"\"Return maximum element in the list.\n \n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty.\")\n max_value = l[0]\n for item in l:\n if item > max_value:\n max_value = item\n return max_value", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" brackets is a string of \"<\" and \">\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"<\")\n False\n >>> correct_bracketing(\"<>\")\n True\n >>> correct_bracketing(\"<<><>>\")\n True\n >>> correct_bracketing(\"><<>\")\n False\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '<':\n balance += 1\n elif char == '>':\n balance -= 1\n # If balance goes negative, it means there's a closing bracket without a matching opening bracket\n if balance < 0:\n return False\n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n '''\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequency greater than or equal to the value of the integer itself. \n The frequency of an integer is the number of times it appears in the list.\n If no such a value exist, return -1.\n \n Examples:\n search([4, 1, 2, 2, 3, 1]) == 2\n search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n search([5, 5, 4, 4, 4]) == -1\n '''\n from collections import Counter\n \n # Count the frequency of each number in the list\n frequency = Counter(lst)\n \n # Initialize the result variable\n result = -1\n \n # Iterate through the frequency dictionary\n for num, freq in frequency.items():\n # Check if the frequency is greater than or equal to the number itself\n if freq >= num:\n # Update the result if this number is greater than the current result\n result = max(result, num)\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n \"\"\"\n Write a function that takes a message, and encodes in such a \n way that it swaps case of all letters, replaces all vowels in \n the message with the letter that appears 2 places ahead of that \n vowel in the english alphabet. \n Assume only letters. \n \n Examples:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n vowels = 'aeiouAEIOU'\n encoded_message = []\n\n for char in message:\n if char.isalpha(): # Check if the character is a letter\n # Swap case\n if char in vowels:\n # Replace vowel with the letter 2 places ahead\n if char.islower():\n new_char = chr((ord(char) - ord('a') + 2) % 26 + ord('a'))\n else:\n new_char = chr((ord(char) - ord('A') + 2) % 26 + ord('A'))\n else:\n new_char = char.swapcase() # Swap case for consonants\n encoded_message.append(new_char)\n else:\n encoded_message.append(char) # Keep non-letter characters unchanged\n\n return ''.join(encoded_message)", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["TEST"]], "plus_fail_tests": [["abcdefghijklmnopqrstuvwxyz"]]}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n \"\"\"\n In this task, you will be given a string that represents a number of apples and oranges \n that are distributed in a basket of fruit. This basket contains \n apples, oranges, and mango fruits. Given the string that represents the total number of \n the oranges and apples and an integer that represents the total number of the fruits \n in the basket, return the number of the mango fruits in the basket.\n \n Parameters:\n s (str): A string representing the number of apples and oranges.\n n (int): An integer representing the total number of fruits in the basket.\n \n Returns:\n int: The number of mango fruits in the basket.\n \n Examples:\n fruit_distribution(\"5 apples and 6 oranges\", 19) -> 8\n fruit_distribution(\"0 apples and 1 oranges\", 3) -> 2\n fruit_distribution(\"2 apples and 3 oranges\", 100) -> 95\n fruit_distribution(\"100 apples and 1 oranges\", 120) -> 19\n \"\"\"\n \n # Extract the number of apples and oranges from the string\n parts = s.split()\n apples = int(parts[0]) # First part is the number of apples\n oranges = int(parts[3]) # Fourth part is the number of oranges\n \n # Calculate the number of mangoes\n mangoes = n - apples - oranges\n \n return mangoes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n \n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n \"\"\"\n return n * (n + 1) // 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(divisible_by_three)\n \n # Create a new list to hold the result\n result = l.copy()\n \n # Replace values at indices divisible by 3 with sorted values\n for index, value in zip((i for i in range(len(l)) if i % 3 == 0), sorted_values):\n result[index] = value\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n Example\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n \"\"\"\n # Initialize variables to track the minimum sum and the current sum\n min_sum = float('inf')\n current_sum = 0\n \n for num in nums:\n current_sum += num\n min_sum = min(min_sum, current_sum)\n \n # If current_sum is positive, reset it to 0\n if current_sum > 0:\n current_sum = 0\n \n return min_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for char in s if char in '13579')\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n '''\n Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n \n Examples:\n split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"abcdef\") \u279e 3 \n '''\n # Check for whitespace\n if ' ' in txt:\n return txt.split()\n \n # Check for commas\n elif ',' in txt:\n return txt.split(',')\n \n # If no whitespace or commas, count lower-case letters with odd order\n else:\n odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n return odd_count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n \"\"\"\n Given a non-empty array of integers arr and an integer k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example:\n\n Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n Output: 24 # sum of 21 + 3\n\n Constraints:\n 1. 1 <= len(arr) <= 100\n 2. 1 <= k <= len(arr)\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate through the first k elements of the array\n for i in range(k):\n # Check if the current element has at most two digits\n if -100 < arr[i] < 100:\n total_sum += arr[i]\n \n return total_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length and alphabetically.\n \n Args:\n lst (list): A list of strings.\n \n Returns:\n list: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n \"\"\"\n Given a string text, replace all spaces in it with underscores, \n and if a string has more than 2 consecutive spaces, \n then replace all consecutive spaces with - \n \n fix_spaces(\"Example\") == \"Example\"\n fix_spaces(\"Example 1\") == \"Example_1\"\n fix_spaces(\" Example 2\") == \"_Example_2\"\n fix_spaces(\" Example 3\") == \"_Example-3\"\n \"\"\"\n import re\n\n # Replace more than 2 consecutive spaces with a single '-'\n text = re.sub(r' {3,}', '-', text)\n \n # Replace single spaces with underscores\n text = text.replace(' ', '_')\n \n return text", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n as follows: start with any positive integer n. Then each term is obtained from the \n previous term as follows: if the previous term is even, the next term is one half of \n the previous term. If the previous term is odd, the next term is 3 times the previous\n term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n Note: \n 1. Collatz(1) is [1].\n 2. returned list sorted in increasing order.\n\n For example:\n get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n collatz_sequence = []\n current = n\n \n while current != 1:\n collatz_sequence.append(current)\n if current % 2 == 0:\n current //= 2\n else:\n current = 3 * current + 1\n \n collatz_sequence.append(1) # Add the last term which is 1\n \n # Filter odd numbers and sort them\n odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n \n return odd_numbers", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n \n The date is valid if all of the following rules are satisfied:\n 1. The date string is not empty.\n 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n The number of days is not less than 1 or higher than 29 for the month 2.\n 3. The months should not be less than 1 or higher than 12.\n 4. The date should be in the format: mm-dd-yyyy\n \n Args:\n date (str): The date string to validate.\n \n Returns:\n bool: True if the date is valid, False otherwise.\n \"\"\"\n if not date:\n return False\n \n # Check the format\n if len(date) != 10 or date[2] != '-' or date[5] != '-':\n return False\n \n try:\n month = int(date[:2])\n day = int(date[3:5])\n year = int(date[6:])\n except ValueError:\n return False\n \n # Validate month\n if month < 1 or month > 12:\n return False\n \n # Validate day based on month\n if month in [1, 3, 5, 7, 8, 10, 12]: # 31 days\n if day < 1 or day > 31:\n return False\n elif month in [4, 6, 9, 11]: # 30 days\n if day < 1 or day > 30:\n return False\n elif month == 2: # February\n if day < 1 or day > 29:\n return False\n \n return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n \"\"\"Task\n We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and True/False for the check.\n Example\n For s = \"abcde\", c = \"ae\", the result should be ('bcd',False)\n For s = \"abcdef\", c = \"b\" the result should be ('acdef',False)\n For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc',True)\n \"\"\"\n # Create a set of characters to delete for faster lookup\n delete_set = set(c)\n \n # Create the result string by filtering out characters in delete_set\n result = ''.join(char for char in s if char not in delete_set)\n \n # Check if the result string is a palindrome\n is_palindrome = result == result[::-1]\n \n return (result, is_palindrome)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n \"\"\"\n Calculate the number of times buckets need to be lowered to empty the wells.\n\n Parameters:\n grid (list of list of int): A rectangular grid representing wells.\n capacity (int): The capacity of each bucket.\n\n Returns:\n int: The total number of times buckets need to be lowered.\n \"\"\"\n total_water = 0\n \n # Count the total amount of water in the grid\n for row in grid:\n total_water += sum(row)\n \n # Calculate the number of times buckets need to be lowered\n # Each bucket can carry 'capacity' units of water\n if total_water == 0:\n return 0\n else:\n return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": [[[[1, 0, 0, 1], [0, 1, 1, 1], [0, 0, 0, 0], [1, 0, 1, 1]], 2]]}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n \"\"\"Create a function which takes a string representing a file's name, and returns\n 'Yes' if the the file's name is valid, and returns 'No' otherwise.\n A file's name is considered to be valid if and only if all the following conditions \n are met:\n - There should not be more than three digits ('0'-'9') in the file's name.\n - The file's name contains exactly one dot '.'\n - The substring before the dot should not be empty, and it starts with a letter from \n the latin alphapet ('a'-'z' and 'A'-'Z').\n - The substring after the dot should be one of these: ['txt', 'exe', 'dll']\n Examples:\n file_name_check(\"example.txt\") # => 'Yes'\n file_name_check(\"1example.dll\") # => 'No' (the name should start with a latin alphapet letter)\n \"\"\"\n \n # Check for exactly one dot\n if file_name.count('.') != 1:\n return 'No'\n \n # Split the file name into name and extension\n name, extension = file_name.split('.')\n \n # Check if the name is empty or starts with a non-letter\n if not name or not name[0].isalpha():\n return 'No'\n \n # Check for the valid extensions\n valid_extensions = ['txt', 'exe', 'dll']\n if extension not in valid_extensions:\n return 'No'\n \n # Count the digits in the file name\n digit_count = sum(c.isdigit() for c in file_name)\n if digit_count > 3:\n return 'No'\n \n return 'Yes'", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n \"\"\"Write a function that takes an array of numbers as input and returns \n the number of elements in the array that are greater than 10 and both \n first and last digits of a number are odd (1, 3, 5, 7, 9).\n \n For example:\n specialFilter([15, -73, 14, -15]) => 1 \n specialFilter([33, -2, -3, 45, 21, 109]) => 2\n \"\"\"\n \n def is_odd_digit(digit):\n return digit in {'1', '3', '5', '7', '9'}\n \n def first_and_last_odd(num):\n str_num = str(abs(num)) # Convert to string and take absolute value\n return is_odd_digit(str_num[0]) and is_odd_digit(str_num[-1])\n \n count = 0\n for num in nums:\n if num > 10 and first_and_last_odd(num):\n count += 1\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers.\n You need to return the sum of squared numbers in the given list,\n round each element in the list to the upper int (Ceiling) first.\n \n Examples:\n For lst = [1,2,3] the output should be 14\n For lst = [1,4,9] the output should be 98\n For lst = [1,3,5,7] the output should be 84\n For lst = [1.4,4.2,0] the output should be 29\n For lst = [-2.4,1,1] the output should be 6\n \"\"\"\n return sum(math.ceil(x) ** 2 for x in lst)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closest to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sorted by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct planet names. \n Examples\n bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n '''\n \n planets = [\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n ]\n \n if planet1 not in planets or planet2 not in planets:\n return ()\n \n index1 = planets.index(planet1)\n index2 = planets.index(planet2)\n \n # Ensure index1 is less than index2 for slicing\n start, end = sorted((index1, index2))\n \n # Get the planets in between\n in_between_planets = planets[start + 1:end]\n \n return tuple(in_between_planets)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n '''\n Create a function that returns True if the last character\n of a given string is an alphabetical character and is not\n a part of a word, and False otherwise.\n Note: \"word\" is a group of characters separated by space.\n\n Examples:\n check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '''\n # Strip any trailing whitespace from the string\n txt = txt.rstrip()\n \n # Check if the string is empty after stripping\n if not txt:\n return False\n \n # Split the string into words\n words = txt.split()\n \n # Get the last character of the last word\n last_word = words[-1]\n \n # Check if the last character is a letter and if the last word has only one character\n return last_word[-1].isalpha() and len(last_word) == 1", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["eeeee e "]], "plus_fail_tests": [["apple pi\ne"]]}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n result = [max_so_far]\n\n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n\n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n \"\"\"This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If \n there's no such number, then the function should return -1.\n\n For example:\n choose_num(12, 15) = 14\n choose_num(13, 12) = -1\n \"\"\"\n # Ensure x is less than or equal to y\n if x > y:\n return -1\n \n # Start from the largest number in the range and check for evenness\n for num in range(y, x - 1, -1):\n if num % 2 == 0:\n return num\n \n return -1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to make it easier to find close elements\n numbers.sort()\n \n # Check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n \"\"\"\n return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n reverse the resulting array, and then replace each digit by its corresponding name from\n \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n For example:\n arr = [2, 1, 1, 4, 5, 8, 2, 3] \n -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n \n If the array is empty, return an empty array:\n arr = []\n return []\n \n If the array has any strange number ignore it:\n arr = [1, -1 , 55] \n -> sort arr -> [-1, 1, 55]\n -> reverse arr -> [55, 1, -1]\n return = ['One']\n \"\"\"\n \n # Mapping of digits to their corresponding names\n digit_to_name = {\n 1: \"One\", 2: \"Two\", 3: \"Three\", 4: \"Four\",\n 5: \"Five\", 6: \"Six\", 7: \"Seven\", 8: \"Eight\", 9: \"Nine\"\n }\n \n # Filter the array to include only numbers between 1 and 9\n filtered = [num for num in arr if 1 <= num <= 9]\n \n # Sort the filtered array\n filtered.sort()\n \n # Reverse the sorted array\n filtered.reverse()\n \n # Convert the numbers to their corresponding names\n result = [digit_to_name[num] for num in filtered]\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n if not (1 <= number <= 1000):\n raise ValueError(\"Number must be between 1 and 1000\")\n\n roman_numerals = [\n (1000, 'm'),\n (900, 'cm'),\n (500, 'd'),\n (400, 'cd'),\n (100, 'c'),\n (90, 'xc'),\n (50, 'l'),\n (40, 'xl'),\n (10, 'x'),\n (9, 'ix'),\n (5, 'v'),\n (4, 'iv'),\n (1, 'i')\n ]\n\n result = []\n for value, numeral in roman_numerals:\n while number >= value:\n result.append(numeral)\n number -= value\n\n return ''.join(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n \n double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n double_the_difference([-1, -2, 0]) == 0\n double_the_difference([9, -2]) == 81\n double_the_difference([0]) == 0 \n \n If the input list is empty, return 0.\n '''\n if not lst: # Check if the list is empty\n return 0\n \n return sum(x**2 for x in lst if isinstance(x, int) and x >= 0 and x % 2 != 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n \"\"\"Write a function that accepts a list of strings.\n The list contains different words. Return the word with maximum number\n of unique characters. If multiple strings have maximum number of unique\n characters, return the one which comes first in lexicographical order.\n\n find_max([\"name\", \"of\", \"string\"]) == \"string\"\n find_max([\"name\", \"enam\", \"game\"]) == \"enam\"\n find_max([\"aaaaaaa\", \"bb\" ,\"cc\"]) == \"aaaaaaa\"\n \"\"\"\n max_word = \"\"\n max_unique_count = 0\n\n for word in words:\n unique_chars = set(word)\n unique_count = len(unique_chars)\n\n if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n max_word = word\n max_unique_count = unique_count\n\n return max_word", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic algebra operations, and \n the second list is a list of integers. Use the two given lists to build the algebraic \n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + ) \n Subtraction ( - ) \n Multiplication ( * ) \n Floor division ( // ) \n Exponentiation ( ** ) \n\n Example:\n operator = ['+', '*', '-']\n operand = [2, 3, 4, 5]\n result = 2 + 3 * 4 - 5\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.\n \"\"\"\n \n # Start with the first operand\n result = operand[0]\n \n # Iterate through the operators and operands\n for i in range(len(operator)):\n op = operator[i]\n next_operand = operand[i + 1]\n \n if op == '+':\n result += next_operand\n elif op == '-':\n result -= next_operand\n elif op == '*':\n result *= next_operand\n elif op == '//':\n result //= next_operand\n elif op == '**':\n result **= next_operand\n else:\n raise ValueError(f\"Invalid operator: {op}\")\n \n return result", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": [[["+", "-", "*", "//"], [5, 2, 3, 4, 7]]]}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n def max_nesting_depth(s: str) -> int:\n max_depth = 0\n current_depth = 0\n for char in s:\n if char == '(':\n current_depth += 1\n max_depth = max(max_depth, current_depth)\n elif char == ')':\n current_depth -= 1\n return max_depth\n\n groups = paren_string.split()\n return [max_nesting_depth(group) for group in groups]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n \"\"\"\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,\n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example:\n Input: n = 5\n Output: 1\n Explanation:\n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n \"\"\"\n # Create the array a\n a = [i * i - i + 1 for i in range(1, n + 1)]\n \n # Count the number of valid triples\n count = 0\n \n # Check all combinations of triples (i, j, k) with i < j < k\n for i in range(n):\n for j in range(i + 1, n):\n for k in range(j + 1, n):\n if (a[i] + a[j] + a[k]) % 3 == 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n \"\"\"Given a list of positive integers x, return a sorted list of all \n elements that haven't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n def has_even_digit(n):\n \"\"\"Check if the number has any even digit.\"\"\"\n return any(int(digit) % 2 == 0 for digit in str(n))\n\n # Filter the list to include only numbers without even digits\n result = [num for num in x if not has_even_digit(num)]\n \n # Return the sorted result\n return sorted(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" \n Input to this function is a string containing multiple groups of nested parentheses. \n Your goal is to separate those groups into separate strings and return the list of those.\n Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n Ignore any spaces in the input string.\n \n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n # Remove spaces from the input string\n paren_string = paren_string.replace(\" \", \"\")\n \n result = []\n balance = 0\n current_group = []\n \n for char in paren_string:\n if char == '(':\n if balance == 0 and current_group:\n result.append(''.join(current_group))\n current_group = []\n current_group.append(char)\n balance += 1\n elif char == ')':\n current_group.append(char)\n balance -= 1\n if balance == 0:\n result.append(''.join(current_group))\n current_group = []\n \n # In case there are any remaining groups\n if current_group:\n result.append(''.join(current_group))\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n \"\"\"Create a function which returns the largest index of an element which\n is not greater than or equal to the element immediately preceding it. If\n no such element exists then return -1. The given array will not contain\n duplicate values.\n\n Examples:\n can_arrange([1,2,4,3,5]) = 3\n can_arrange([1,2,3]) = -1\n \"\"\"\n # Initialize the index to -1, which will be returned if no such element is found\n largest_index = -1\n \n # Iterate through the array starting from the second element\n for i in range(1, len(arr)):\n # Check if the current element is less than the previous element\n if arr[i] < arr[i - 1]:\n largest_index = i # Update the largest index found\n \n return largest_index", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n \n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n \"\"\"\n if not numbers:\n return (0, 1)\n \n total_sum = sum(numbers)\n total_product = 1\n for number in numbers:\n total_product *= number\n \n return (total_sum, total_product)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n '''\n Create a function that takes a string as input which contains only square brackets.\n The function should return True if and only if there is a valid subsequence of brackets \n where at least one bracket in the subsequence is nested.\n\n is_nested('[[]]') \u279e True\n is_nested('[]]]]]]][[[[[]') \u279e False\n is_nested('[][]') \u279e False\n is_nested('[]') \u279e False\n is_nested('[[][]]') \u279e True\n is_nested('[[]][[') \u279e True\n '''\n # Initialize a counter for open brackets\n open_count = 0\n # Initialize a flag to check for nesting\n nested = False\n \n for char in string:\n if char == '[':\n open_count += 1\n # If we have seen at least one open bracket before, we can have nesting\n if open_count > 1:\n nested = True\n elif char == ']':\n if open_count > 0:\n open_count -= 1\n else:\n # More closing brackets than opening brackets\n return False\n \n # We need at least one nested bracket and all brackets must be closed\n return nested and open_count == 0", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["[[]][["]], "plus_fail_tests": [["[[]]]"]]}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n \"\"\"\n You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n \n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n \n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots that exist in stock\n \n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n \"\"\"\n # Calculate how many more carrots are needed\n additional_needed = need - number\n \n # If no additional carrots are needed, return the current state\n if additional_needed <= 0:\n return [number, remaining]\n \n # Determine how many carrots can be eaten from the remaining stock\n eaten = min(additional_needed, remaining)\n \n # Calculate the total eaten and remaining carrots\n total_eaten = number + eaten\n remaining_after_meals = remaining - eaten\n \n return [total_eaten, remaining_after_meals]", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": [[2, 2, 2]]}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef sum_of_digits(n):\n \"\"\"Return the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n largest_prime = -1\n \n for number in lst:\n if is_prime(number) and number > largest_prime:\n largest_prime = number\n \n if largest_prime == -1:\n return 0 # Return 0 if no prime is found\n \n return sum_of_digits(largest_prime)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n \"\"\"You are given a string s.\n if s[i] is a letter, reverse its case from lower to upper or vise versa, \n otherwise keep it as it is.\n If the string contains no letters, reverse the string.\n The function should return the resulted string.\n \n Examples:\n solve(\"1234\") = \"4321\"\n solve(\"ab\") = \"AB\"\n solve(\"#a@C\") = \"#A@c\"\n \"\"\"\n # Check if there are any letters in the string\n has_letters = any(c.isalpha() for c in s)\n \n if has_letters:\n # Reverse case for letters and keep others as is\n return ''.join(c.swapcase() if c.isalpha() else c for c in s)\n else:\n # Reverse the string if there are no letters\n return s[::-1]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef x_or_y(n, x, y):\n \"\"\"Return the value of x if n is a prime number, otherwise return y.\"\"\"\n if is_prime(n):\n return x\n else:\n return y", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return True if the three\n sides form a right-angled triangle, False otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or \n 90 degree.\n \n Example:\n right_angle_triangle(3, 4, 5) == True\n right_angle_triangle(1, 2, 3) == False\n '''\n # Sort the sides to identify the longest side\n sides = sorted([a, b, c])\n \n # Check the Pythagorean theorem\n return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n \"\"\"Convert a decimal number to binary format with specific formatting.\n\n Args:\n decimal (int): A non-negative integer to convert to binary.\n\n Returns:\n str: A string representing the binary format of the decimal number,\n prefixed and suffixed with 'db'.\n \n Examples:\n >>> decimal_to_binary(15)\n 'db1111db'\n >>> decimal_to_binary(32)\n 'db100000db'\n \"\"\"\n if decimal < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n # Convert decimal to binary and remove the '0b' prefix\n binary_representation = bin(decimal)[2:]\n \n # Format the output with 'db' at the beginning and end\n formatted_output = f\"db{binary_representation}db\"\n \n return formatted_output", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n \"\"\"\n Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move at the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.\n\n Parameters:\n n (int): The number of cars in each direction.\n\n Returns:\n int: The number of collisions.\n \"\"\"\n # Each car moving left to right will collide with each car moving right to left\n # Therefore, the total number of collisions is n * n\n return n * n", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fib4(0) -> 0\n fib4(1) -> 0\n fib4(2) -> 2\n fib4(3) -> 0\n fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n \n This function computes the n-th element of the fib4 number sequence without using recursion.\n \n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 2\n elif n == 3:\n return 0\n\n # Initialize the first four values of the sequence\n fib_values = [0, 0, 2, 0]\n \n # Compute the values iteratively\n for i in range(4, n + 1):\n next_value = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n fib_values.append(next_value)\n \n return fib_values[n]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n \"\"\"\n Checks if given string is a palindrome.\n \n A palindrome is a string that reads the same forward and backward.\n \n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n \"\"\"\n # Normalize the string by removing spaces and converting to lowercase\n normalized_text = text.replace(\" \", \"\").lower()\n # Check if the normalized string is equal to its reverse\n return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["never odd or even"]]}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n \"\"\"You are given two positive integers n and m, and your task is to compute the\n average of the integers from n through m (including n and m). \n Round the answer to the nearest integer and convert that to binary.\n If n is greater than m, return -1.\n \n Example:\n rounded_avg(1, 5) => \"0b11\"\n rounded_avg(7, 5) => -1\n rounded_avg(10, 20) => \"0b1111\"\n rounded_avg(20, 33) => \"0b11010\"\n \"\"\"\n if n > m:\n return -1\n \n # Calculate the sum of integers from n to m\n total_sum = sum(range(n, m + 1))\n count = m - n + 1 # Total numbers from n to m\n \n # Calculate the average and round it\n average = total_sum / count\n rounded_average = round(average)\n \n # Convert the rounded average to binary\n return bin(rounded_average)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this integer is a cube of some integer number.\n Note: you may assume the input is always valid.\n \n Examples:\n iscube(1) ==> True\n iscube(2) ==> False\n iscube(-1) ==> True\n iscube(64) ==> True\n iscube(0) ==> True\n iscube(180) ==> False\n '''\n # Calculate the cube root of the absolute value of a\n cube_root = round(abs(a) ** (1/3))\n \n # Check if the cube of the rounded cube root equals the absolute value of a\n return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n \"\"\"\n Given a positive integer n, return the count of the numbers of n-digit\n positive integers that start or end with 1.\n \"\"\"\n if n < 1:\n return 0\n\n # Total n-digit numbers\n total_n_digit_numbers = 9 * (10 ** (n - 1))\n\n # Count of n-digit numbers that start with 1\n start_with_1 = 10 ** (n - 1)\n\n # Count of n-digit numbers that end with 1\n end_with_1 = 9 * (10 ** (n - 2)) if n > 1 else 0\n\n # Total count of numbers that start or end with 1\n count = start_with_1 + end_with_1\n\n return count", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[2]], "plus_fail_tests": [[6]]}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits will be 1 the output should be \"1\".\n For N = 150, the sum of digits will be 6 the output should be \"110\".\n For N = 147, the sum of digits will be 12 the output should be \"1100\".\n \n Variables:\n @N integer\n Constraints: 0 \u2264 N \u2264 10000.\n Output:\n a string of binary number\n \"\"\"\n # Calculate the sum of the digits of N\n digit_sum = sum(int(digit) for digit in str(N))\n \n # Convert the sum to binary and remove the '0b' prefix\n binary_sum = bin(digit_sum)[2:]\n \n return binary_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n '''\n Given list of integers, return list in strange order.\n Strange sorting, is when you start with the minimum value,\n then maximum of the remaining integers, then minimum and so on.\n\n Examples:\n strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n strange_sort_list([]) == []\n '''\n if not lst:\n return []\n\n sorted_lst = sorted(lst)\n result = []\n left, right = 0, len(sorted_lst) - 1\n\n while left <= right:\n if left == right:\n result.append(sorted_lst[left])\n else:\n result.append(sorted_lst[left])\n result.append(sorted_lst[right])\n left += 1\n right -= 1\n\n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n \"\"\" Return length of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n \"\"\"\n return len(string)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n \n >>> largest_divisor(15)\n 5\n >>> largest_divisor(28)\n 14\n >>> largest_divisor(1)\n 0\n >>> largest_divisor(10)\n 5\n \"\"\"\n if n <= 1:\n return 0 # No divisors for 1 or less\n \n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return the area of\n the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n Otherwise return -1.\n Three sides make a valid triangle when the sum of any two sides is greater \n than the third side.\n \n Example:\n triangle_area(3, 4, 5) == 6.00\n triangle_area(1, 2, 10) == -1\n '''\n # Check for valid triangle\n if a + b > c and a + c > b and b + c > a:\n # Calculate the semi-perimeter\n s = (a + b + c) / 2\n # Calculate the area using Heron's formula\n area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n return round(area, 2)\n else:\n return -1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n \n >>> longest([])\n >>> None\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n \"\"\"\n if not strings:\n return None\n \n longest_string = strings[0]\n \n for string in strings:\n if len(string) > len(longest_string):\n longest_string = string\n \n return longest_string", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n result = 1\n base = 2 % p # Start with 2 modulo p\n\n while n > 0:\n if n % 2 == 1: # If n is odd, multiply the result by the base\n result = (result * base) % p\n base = (base * base) % p # Square the base\n n //= 2 # Divide n by 2\n\n return result", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[0, 1]]}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef prime_length(string):\n \"\"\"Check if the length of the string is a prime number.\"\"\"\n length = len(string)\n return is_prime(length)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n \"\"\"Returns True if x is a simple power of n, otherwise False.\n \n A number x is a simple power of n if there exists an integer k such that n**k = x.\n \n Args:\n x (int): The number to check.\n n (int): The base number.\n \n Returns:\n bool: True if x is a simple power of n, False otherwise.\n \"\"\"\n if n <= 1:\n return x == 1 # 1 is a power of any number, and no other number can be a power of 1 or 0\n \n power = 1\n while True:\n result = n ** power\n if result == x:\n return True\n elif result > x:\n return False\n power += 1", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[1, 12]], "plus_fail_tests": [[1, 4]]}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n \"\"\"\n triples_sum_to_zero takes a list of integers as an input.\n it returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n \"\"\"\n n = len(l)\n # Sort the list to use the two-pointer technique\n l.sort()\n \n for i in range(n - 2):\n # Avoid duplicates for the first element\n if i > 0 and l[i] == l[i - 1]:\n continue\n \n left, right = i + 1, n - 1\n while left < right:\n current_sum = l[i] + l[left] + l[right]\n if current_sum == 0:\n return True\n elif current_sum < 0:\n left += 1\n else:\n right -= 1\n \n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n \"\"\"Return median of elements in the list l.\n \n The median is the middle value in a list of numbers. If the list has an even number of elements,\n the median is the average of the two middle numbers.\n \n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty.\")\n \n sorted_list = sorted(l)\n n = len(sorted_list)\n mid = n // 2\n \n if n % 2 == 0: # Even number of elements\n return (sorted_list[mid - 1] + sorted_list[mid]) / 2\n else: # Odd number of elements\n return sorted_list[mid]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n \"\"\"Counts the number of prime hexadecimal digits in the given hexadecimal string.\"\"\"\n # Define the set of prime hexadecimal digits\n prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n \n # Count the number of prime hexadecimal digits in the input string\n count = sum(1 for digit in num if digit in prime_hex_digits)\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers\n >>> filter_integers(['a', 3.14, 5])\n [5]\n >>> filter_integers([1, 2, 3, 'abc', {}, []])\n [1, 2, 3]\n \"\"\"\n return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[[true, false, null, 0, -10, "test", [], {}, 3.14]]]}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return a greatest common divisor of two integers a and b\n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n \"\"\"\n while b:\n a, b = b, a % b\n return abs(a)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string\n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n \"\"\"\n return [string[:i] for i in range(1, len(string) + 1)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str):\n \"\"\"\n Takes as input a string encoded with the encode_cyclic function.\n Returns the decoded string.\n \"\"\"\n # Split string into groups of length 3\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # Reverse the cycling for each group\n groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n Input number should be equal to the product of all factors\n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n \"\"\"\n factors = []\n # Check for number of 2s that divide n\n while n % 2 == 0:\n factors.append(2)\n n //= 2\n \n # n must be odd at this point so a skip of 2 (i.e., i = i + 2) can be used\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, append i and divide n\n while n % i == 0:\n factors.append(i)\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n factors.append(n)\n \n return factors", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n \n >>> circular_shift(12, 1)\n '21'\n >>> circular_shift(12, 2)\n '12'\n >>> circular_shift(12345, 1)\n '51234'\n >>> circular_shift(12345, 5)\n '54321'\n >>> circular_shift(12345, 6)\n '54321'\n \"\"\"\n # Convert the integer to a string to manipulate its digits\n str_x = str(x)\n length = len(str_x)\n \n # If shift is greater than the number of digits, reverse the string\n if shift >= length:\n return str_x[::-1]\n \n # Calculate the effective shift\n effective_shift = shift % length\n \n # Perform the circular shift\n shifted = str_x[-effective_shift:] + str_x[:-effective_shift]\n \n return shifted", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[12, 2]], "plus_fail_tests": [[987654321, 9]]}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n \n For example:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n >>> is_bored(\"I am happy! Are you? I will go now.\")\n 2\n >>> is_bored(\"What a day. I can't believe it! I am so excited.\")\n 2\n \"\"\"\n # Split the string into sentences using the delimiters\n sentences = []\n current_sentence = []\n for char in S:\n if char in '.!?':\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n current_sentence = []\n else:\n current_sentence.append(char)\n if current_sentence: # Add the last sentence if it exists\n sentences.append(''.join(current_sentence).strip())\n\n # Count the sentences that start with \"I\"\n boredom_count = sum(1 for sentence in sentences if sentence.startswith('I'))\n \n return boredom_count", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": [["In the morning, I like to have a cup of coffee to start my day off right. How about you?"]]}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n \"\"\" \n xs represent coefficients of a polynomial.\n xs[0] + xs[1] * x + xs[2] * x^2 + ....\n Return derivative of this polynomial in the same form.\n \n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n \"\"\"\n # The derivative of a polynomial is calculated by multiplying each coefficient\n # by its corresponding power and reducing the power by one.\n return [i * coeff for i, coeff in enumerate(xs[1:], start=1)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_up_to(n):\n \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n primes = []\n for i in range(2, n):\n if is_prime(i):\n primes.append(i)\n return primes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two words have the same characters if they contain the same unique characters,\n regardless of the number of times each character appears.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n \"\"\"Add two numbers x and y.\n \n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n \"\"\"\n return x + y", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n count_upper('aBCdEf') returns 1\n count_upper('abcdefg') returns 0\n count_upper('dBBE') returns 0\n \"\"\"\n uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n count = 0\n \n for i in range(0, len(s), 2): # Iterate over even indices\n if s[i] in uppercase_vowels:\n count += 1\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n \"\"\"\n return [x for x in l if x > 0]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indexed elements\n even_indices_values.sort()\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Place the sorted even indexed values back into the result\n for i, value in enumerate(even_indices_values):\n result[i * 2] = value # Place sorted value at even index\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n \"\"\"Return True if all numbers in the list l are below threshold t.\n \n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n \"\"\"\n return all(x < t for x in l)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n >>> closest_integer(\"14.5\")\n 15\n >>> closest_integer(\"-14.5\")\n -15\n >>> closest_integer(\"0.5\")\n 1\n >>> closest_integer(\"-0.5\")\n -1\n '''\n # Convert the string to a float\n num = float(value)\n \n # Get the floor and ceiling of the number\n lower = int(num // 1)\n upper = lower + 1\n \n # Check if the number is equidistant from lower and upper\n if abs(num - lower) < abs(num - upper):\n return lower\n elif abs(num - lower) > abs(num - upper):\n return upper\n else:\n # If equidistant, round away from zero\n if num > 0:\n return upper\n else:\n return lower", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000"]]}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n \"\"\"Return n-th Fibonacci number.\n \n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n elif n == 1:\n return 1\n elif n == 2:\n return 1\n else:\n a, b = 1, 1\n for _ in range(2, n):\n a, b = b, a + b\n return b", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[0]]}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef fibonacci(n: int) -> int:\n \"\"\"Return the n-th Fibonacci number.\"\"\"\n a, b = 0, 1\n for _ in range(n):\n a, b = b, a + b\n return a\ndef prime_fib(n: int) -> int:\n \"\"\"\n prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n count = 0\n fib_index = 0\n while True:\n fib_number = fibonacci(fib_index)\n if is_prime(fib_number):\n count += 1\n if count == n:\n return fib_number\n fib_index += 1", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[12]]}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n \n Args:\n n (int): The index of the FibFib number to compute.\n \n Returns:\n int: The n-th FibFib number.\n \n Examples:\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 1\n \n # Initialize the first three FibFib numbers\n fibfib_numbers = [0, 0, 1]\n \n # Compute FibFib numbers iteratively\n for i in range(3, n + 1):\n next_fibfib = fibfib_numbers[i - 1] + fibfib_numbers[i - 2] + fibfib_numbers[i - 3]\n fibfib_numbers.append(next_fibfib)\n \n return fibfib_numbers[n]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.\n \"\"\"\n # Get the unit digit of the first number\n unit_digit_a = abs(a) % 10\n # Get the unit digit of the second number\n unit_digit_b = abs(b) % 10\n # Return the product of the unit digits\n return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = 0\n s = s.lower() # Convert to lowercase to handle case insensitivity\n\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1: # Check if 'y' is at the end\n count += 1\n\n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Sort the unique elements\n sorted_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_elements[1]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef words_in_sentence(sentence):\n \"\"\"\n You are given a string representing a sentence,\n the sentence contains some words separated by a space,\n and you have to return a string that contains the words from the original sentence,\n whose lengths are prime numbers,\n the order of the words in the new string should be the same as the original one.\n\n Example 1:\n Input: sentence = \"This is a test\"\n Output: \"is\"\n\n Example 2:\n Input: sentence = \"lets go for swimming\"\n Output: \"go for\"\n\n Constraints:\n * 1 <= len(sentence) <= 100\n * sentence contains only letters\n \"\"\"\n words = sentence.split()\n prime_length_words = [word for word in words if is_prime(len(word))]\n return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n \"\"\"In this problem, you will implement a function that takes two lists of numbers,\n and determines whether it is possible to perform an exchange of elements\n between them to make lst1 a list of only even numbers.\n There is no limit on the number of exchanged elements between lst1 and lst2.\n If it is possible to exchange elements between the lst1 and lst2 to make\n all the elements of lst1 to be even, return \"YES\".\n Otherwise, return \"NO\".\n For example:\n exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"YES\"\n exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n It is assumed that the input lists will be non-empty.\n \"\"\"\n \n # Count the number of odd numbers in lst1\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n \n # Count the number of even numbers in lst2\n even_count_lst2 = sum(1 for x in lst2 if x % 2 == 0)\n \n # If there are no odd numbers in lst1, it's already valid\n if odd_count_lst1 == 0:\n return \"YES\"\n \n # If there are enough even numbers in lst2 to replace all odd numbers in lst1\n if even_count_lst2 >= odd_count_lst1:\n return \"YES\"\n \n return \"NO\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n \"\"\"Simplifies the expression x * n and checks if the result is a whole number.\n \n Args:\n x (str): A string representation of a fraction in the format /.\n n (str): A string representation of a fraction in the format /.\n \n Returns:\n bool: True if x * n evaluates to a whole number, False otherwise.\n \"\"\"\n # Split the fractions into numerator and denominator\n x_numerator, x_denominator = map(int, x.split('/'))\n n_numerator, n_denominator = map(int, n.split('/'))\n \n # Calculate the product of the fractions\n # (x_numerator / x_denominator) * (n_numerator / n_denominator) = (x_numerator * n_numerator) / (x_denominator * n_denominator)\n numerator_product = x_numerator * n_numerator\n denominator_product = x_denominator * n_denominator\n \n # Check if the result is a whole number\n return numerator_product % denominator_product == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n if not arr:\n return None\n\n product_of_signs = 1\n sum_of_magnitudes = 0\n\n for num in arr:\n if num > 0:\n sum_of_magnitudes += num\n elif num < 0:\n sum_of_magnitudes += -num\n product_of_signs *= -1\n else: # num == 0\n return 0 # If there's a zero, the product of signs is zero\n\n return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n \"\"\"Given a string s and a natural number n, returns a list of all words from \n string s that contain exactly n consonants, in the order they appear in the string s.\n \n Args:\n s (str): The input string containing words.\n n (int): The number of consonants to filter words by.\n \n Returns:\n list: A list of words containing exactly n consonants.\n \"\"\"\n if not s:\n return []\n\n # Define a set of consonants\n consonants = set(\"bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ\")\n \n # Split the string into words\n words = s.split()\n \n # Function to count consonants in a word\n def count_consonants(word):\n return sum(1 for char in word if char in consonants)\n \n # Filter words based on the number of consonants\n result = [word for word in words if count_consonants(word) == n]\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0: # More closing than opening\n return False\n return balance == 0 # Must be balanced at the end\n\n # Check both concatenation orders\n return 'Yes' if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]) else 'No'", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n \"\"\"\n Write a function which sorts the given list of integers\n in ascending order according to the sum of their digits.\n Note: if there are several items with similar sum of their digits,\n order them based on their index in original list.\n\n For example:\n >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n >>> order_by_points([]) == []\n \"\"\"\n \n def digit_sum(n):\n \"\"\"Calculate the sum of the digits of n.\"\"\"\n return sum(int(digit) for digit in str(abs(n)))\n\n # Sort the list based on the sum of digits and original index\n return sorted(nums, key=lambda x: (digit_sum(x), nums.index(x)))", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": [[[-5, -12, 9, 15]]]}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n '''\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return False. Assume no negative numbers and only integers.\n\n Examples\n is_sorted([5]) \u279e True\n is_sorted([1, 2, 3, 4, 5]) \u279e True\n is_sorted([1, 3, 2, 4, 5]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n '''\n if not lst: # An empty list is considered sorted\n return True\n\n seen = set()\n last = None\n\n for num in lst:\n if num in seen:\n # If we see a number again, check if it's the same as the last\n if num == last:\n return False\n else:\n return False # More than one duplicate found\n seen.add(num)\n last = num\n\n return all(lst[i] <= lst[i + 1] for i in range(len(lst) - 1))", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": [[[1, 1, 2, 2, 3, 3, 4]]]}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n \"\"\"\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n \n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126\n \"\"\"\n total_sum = 0\n for index, value in enumerate(lst):\n if index % 3 == 0:\n total_sum += value ** 2\n elif index % 4 == 0:\n total_sum += value ** 3\n else:\n total_sum += value\n return total_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef intersection(interval1, interval2):\n \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n start1, end1 = interval1\n start2, end2 = interval2\n \n # Find the intersection\n start_intersection = max(start1, start2)\n end_intersection = min(end1, end2)\n \n # Check if there is an intersection\n if start_intersection > end_intersection:\n return \"NO\"\n \n # Calculate the length of the intersection\n length_of_intersection = end_intersection - start_intersection\n \n # Check if the length is a prime number\n if is_prime(length_of_intersection):\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n two consonants from the right side of the word (case sensitive).\n \n Vowels in the beginning and ending don't count. Return empty string if you didn't\n find any vowel that meets the above condition. \n\n You may assume that the given string contains English letters only.\n\n Example:\n get_closest_vowel(\"yogurt\") ==> \"u\"\n get_closest_vowel(\"FULL\") ==> \"U\"\n get_closest_vowel(\"quick\") ==> \"\"\n get_closest_vowel(\"ab\") ==> \"\"\n \"\"\"\n vowels = \"aeiouAEIOU\"\n n = len(word)\n\n # Start from the end of the word\n for i in range(n - 2, 0, -1): # Start from the second last character\n if word[i] in vowels: # Check if the character is a vowel\n # Check if the characters before and after are consonants\n if word[i - 1].isalpha() and word[i + 1].isalpha() and \\\n word[i - 1] not in vowels and word[i + 1] not in vowels:\n return word[i] # Return the vowel if conditions are met\n\n return \"\" # Return empty string if no vowel is found", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n \n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n \"\"\"\n return ' '.join(str(i) for i in range(n + 1))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Get the top k elements\n top_k = sorted_arr[:k]\n # Sort the result in ascending order before returning\n return sorted(top_k)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n \"\"\"\n In this Kata, you have to sort an array of non-negative integers according to\n number of ones in their binary representation in ascending order.\n For similar number of ones, sort based on decimal value.\n\n It must be implemented like this:\n >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n >>> sort_array([1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]\n \"\"\"\n # Sort the array using a custom key\n return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n \"\"\"\n if not test:\n return {}\n\n # Split the input string into a list of letters\n letters = test.split()\n \n # Create a dictionary to count occurrences of each letter\n count_dict = {}\n for letter in letters:\n if letter in count_dict:\n count_dict[letter] += 1\n else:\n count_dict[letter] = 1\n\n # Find the maximum count\n max_count = max(count_dict.values())\n \n # Create a result dictionary for letters with the maximum count\n result = {letter: count for letter, count in count_dict.items() if count == max_count}\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n from collections import deque\n\n N = len(grid)\n directions = [(0, 1), (1, 0), (0, -1), (-1, 0)] # right, down, left, up\n min_path = None\n\n def dfs(x, y, path):\n nonlocal min_path\n if len(path) == k:\n if min_path is None or path < min_path:\n min_path = path[:]\n return\n \n for dx, dy in directions:\n nx, ny = x + dx, y + dy\n if 0 <= nx < N and 0 <= ny < N:\n path.append(grid[nx][ny])\n dfs(nx, ny, path)\n path.pop()\n\n for i in range(N):\n for j in range(N):\n dfs(i, j, [grid[i][j]])\n\n return min_path", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": [[[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 15]]}]}} \ No newline at end of file diff --git a/EVALPLUS-4omini/5.json b/EVALPLUS-4omini/5.json new file mode 100644 index 000000000..4c474d250 --- /dev/null +++ b/EVALPLUS-4omini/5.json @@ -0,0 +1 @@ +{"date": "2024-07-20 13:01", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n Example:\n even_odd_count(-12) ==> (1, 1)\n even_odd_count(123) ==> (1, 2)\n \"\"\"\n # Convert the number to a string and remove the negative sign if present\n num_str = str(abs(num))\n \n even_count = 0\n odd_count = 0\n \n # Iterate through each character in the string representation of the number\n for digit in num_str:\n if digit.isdigit(): # Check if the character is a digit\n if int(digit) % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n return (even_count, odd_count)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n \"\"\"Compares the actual game scores with the guessed scores and returns the absolute differences.\n \n Args:\n game (list of int): The actual scores of the matches.\n guess (list of int): The guessed scores of the matches.\n \n Returns:\n list of int: A list containing the absolute differences between the actual scores and the guessed scores.\n If the guess is correct, the difference is 0.\n \"\"\"\n return [abs(g - a) for a, g in zip(game, guess)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascending order.\n\n For example:\n generate_integers(2, 8) => [2, 4, 6, 8]\n generate_integers(8, 2) => [2, 4, 6, 8]\n generate_integers(10, 14) => []\n \"\"\"\n # Determine the range of numbers to consider\n start = min(a, b)\n end = max(a, b)\n\n # Generate a list of even integers in the specified range\n even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n return even_integers", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[2, 10]], "plus_fail_tests": [[6, 12]]}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def compare_one(a, b):\n \"\"\"\n Create a function that takes integers, floats, or strings representing\n real numbers, and returns the larger variable in its given variable type.\n Return None if the values are equal.\n Note: If a real number is represented as a string, the floating point might be . or ,\n\n compare_one(1, 2.5) \u279e 2.5\n compare_one(1, \"2,3\") \u279e \"2,3\"\n compare_one(\"5,1\", \"6\") \u279e \"6\"\n compare_one(\"1\", 1) \u279e None\n \"\"\"\n \n def parse_value(value):\n \"\"\"Convert the input value to a float or return it as is if it's a string.\"\"\"\n if isinstance(value, str):\n # Replace comma with dot for float conversion\n value = value.replace(',', '.')\n try:\n return float(value)\n except ValueError:\n return value # Return the string if it cannot be converted\n return value\n\n # Parse both values\n parsed_a = parse_value(a)\n parsed_b = parse_value(b)\n\n # Check for equality\n if parsed_a == parsed_b:\n return None\n\n # Return the larger value in its original type\n return a if parsed_a > parsed_b else b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n \"\"\"\n Write a function count_nums which takes an array of integers and returns\n the number of elements which has a sum of digits > 0.\n If a number is negative, then its first signed digit will be negative:\n e.g. -123 has signed digits -1, 2, and 3.\n \n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n def sum_of_digits(n):\n # Convert the number to string and calculate the sum of its digits\n return sum(int(digit) if i > 0 else -int(digit) for i, digit in enumerate(str(n)) if digit.isdigit() or (i == 0 and n < 0))\n\n count = 0\n for number in arr:\n if sum_of_digits(number) > 0:\n count += 1\n \n return count", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[-1, -2, 0]]], "plus_fail_tests": [[[-1, 0, 1]]]}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def factorial(i):\n \"\"\"Helper function to calculate the factorial of i.\"\"\"\n if i == 0 or i == 1:\n return 1\n result = 1\n for j in range(2, i + 1):\n result *= j\n return result\ndef sum_of_numbers(i):\n \"\"\"Helper function to calculate the sum of numbers from 1 to i.\"\"\"\n return (i * (i + 1)) // 2\ndef f(n):\n \"\"\"Implement the function f that takes n as a parameter,\n and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even\n or the sum of numbers from 1 to i otherwise.\n i starts from 1.\n \"\"\"\n result = []\n for i in range(1, n + 1):\n if i % 2 == 0: # i is even\n result.append(factorial(i))\n else: # i is odd\n result.append(sum_of_numbers(i))\n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list to avoid division by zero\n\n mean_value = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n return mad", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n \"\"\"\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n \"\"\"\n # Split the string by commas and spaces, then filter out any empty strings\n words = [word.strip() for word in s.replace(',', ' ').split() if word]\n return words", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" \n You're given a list of deposit and withdrawal operations on a bank account that starts with\n zero balance. Your task is to detect if at any point the balance of account falls below zero, and\n at that point function should return True. Otherwise it should return False.\n \n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n \"\"\"\n balance = 0\n for operation in operations:\n balance += operation\n if balance < 0:\n return True\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string.\n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n >>> string_to_md5('') is None\n >>> string_to_md5('Python') == '5d41402abc4b2a76b9719d911017c592'\n \"\"\"\n if text == \"\":\n return None\n md5_hash = hashlib.md5(text.encode()).hexdigest()\n return md5_hash", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n \"\"\"Find the strongest extension based on the defined strength criteria.\"\"\"\n strongest_extension = None\n max_strength = float('-inf') # Start with the lowest possible strength\n\n for extension in extensions:\n # Calculate the strength of the current extension\n CAP = sum(1 for char in extension if char.isupper())\n SM = sum(1 for char in extension if char.islower())\n strength = CAP - SM\n\n # Check if this extension is stronger than the current strongest\n if strength > max_strength:\n max_strength = strength\n strongest_extension = extension\n\n # Return the result in the specified format\n return f\"{class_name}.{strongest_extension}\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n \"\"\"You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word.\n \n Args:\n a (str): The first word.\n b (str): The second word.\n \n Returns:\n bool: True if b or any of its rotations is a substring of a, False otherwise.\n \n Examples:\n >>> cycpattern_check(\"abcd\", \"abd\")\n False\n >>> cycpattern_check(\"hello\", \"ell\")\n True\n >>> cycpattern_check(\"whassup\", \"psus\")\n False\n >>> cycpattern_check(\"abab\", \"baa\")\n True\n >>> cycpattern_check(\"efef\", \"eeff\")\n False\n >>> cycpattern_check(\"himenss\", \"simen\")\n True\n \"\"\"\n # Create a string that contains all rotations of b\n rotations = b + b # Concatenate b with itself to get all rotations\n \n # Check if any rotation of b is a substring of a\n return any(rotation in a for rotation in (rotations[i:i+len(b)] for i in range(len(b))))", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["", ""]]}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into\n an integer part (largest integer smaller than given number) and decimals\n (leftover part always smaller than 1).\n\n Return the decimal part of the number.\n \n >>> truncate_number(3.5)\n 0.5\n >>> truncate_number(7.25)\n 0.25\n >>> truncate_number(10.0)\n 0.0\n >>> truncate_number(5.99)\n 0.99\n \"\"\"\n if number < 0:\n raise ValueError(\"The number must be positive.\")\n \n integer_part = int(number) # Get the integer part\n decimal_part = number - integer_part # Calculate the decimal part\n return decimal_part", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n \"\"\"Calculate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n if n < 0:\n return []\n\n # Initialize the list to store the Tribonacci numbers\n tribonacci_sequence = []\n\n # Define the base cases\n for i in range(n + 1):\n if i == 0:\n tribonacci_sequence.append(1) # tri(0) = 1\n elif i == 1:\n tribonacci_sequence.append(3) # tri(1) = 3\n elif i % 2 == 0: # Even case\n tribonacci_sequence.append(1 + i / 2)\n else: # Odd case\n tri_n_minus_1 = tribonacci_sequence[i - 1]\n tri_n_minus_2 = tribonacci_sequence[i - 2]\n tri_n_plus_1 = tribonacci_sequence[i + 1] if i + 1 <= n else 0\n tribonacci_sequence.append(tri_n_minus_1 + tri_n_minus_2 + tri_n_plus_1)\n\n return tribonacci_sequence", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[3]], "plus_fail_tests": [[10]]}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n \"\"\"\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n >>> make_a_pile(4)\n [4, 6, 8, 10]\n >>> make_a_pile(1)\n [1]\n \"\"\"\n stones = []\n current_stones = n\n \n for i in range(n):\n stones.append(current_stones)\n if current_stones % 2 == 0:\n current_stones += 2 # next even number\n else:\n current_stones += 2 # next odd number\n \n return stones", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n \n Args:\n n (int): The number to evaluate.\n \n Returns:\n bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n \n Example:\n is_equal_to_sum_even(4) == False\n is_equal_to_sum_even(6) == False\n is_equal_to_sum_even(8) == True\n \"\"\"\n # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n if n < 8:\n return False\n \n # Check if n is even\n if n % 2 != 0:\n return False\n \n # If n is even and >= 8, it can be expressed as the sum of 4 positive even numbers\n return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n \"\"\"\n Given a positive integer n, return a tuple that has the number of even and odd\n integer palindromes that fall within the range(1, n), inclusive.\n\n Example 1:\n Input: 3\n Output: (1, 2)\n Explanation:\n Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n Example 2:\n Input: 12\n Output: (4, 6)\n Explanation:\n Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n Note:\n 1. 1 <= n <= 10^3\n 2. returned tuple has the number of even and odd integer palindromes respectively.\n \"\"\"\n even_count = 0\n odd_count = 0\n\n for i in range(1, n + 1):\n if str(i) == str(i)[::-1]: # Check if the number is a palindrome\n if i % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n return (even_count, odd_count)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n \"\"\" Insert a number 'delimiter' between every two consecutive elements of input list `numbers`\n \n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n for i in range(len(numbers) - 1):\n result.append(numbers[i])\n result.append(delimiter)\n result.append(numbers[-1]) # Append the last element\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return True else return False.\n If the given array is empty then return True.\n\n Note: The given list is guaranteed to have unique elements.\n\n For Example:\n \n move_one_ball([3, 4, 5, 1, 2])==>True\n Explanation: By performing 2 right shift operations, non-decreasing order can\n be achieved for the given array.\n move_one_ball([3, 5, 4, 1, 2])==>False\n Explanation: It is not possible to get non-decreasing order for the given\n array by performing any number of right shift operations.\n \"\"\"\n if not arr:\n return True\n\n n = len(arr)\n sorted_arr = sorted(arr)\n \n # Check for the number of \"breaks\" in the sorted array\n break_count = 0\n for i in range(n):\n if arr[i] > arr[(i + 1) % n]:\n break_count += 1\n\n # If there are more than one break, we cannot sort the array with shifts\n return break_count <= 1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n '''\n Create a function that returns a tuple (a, b), where 'a' is\n the largest of negative integers, and 'b' is the smallest\n of positive integers in a list.\n If there is no negative or positive integers, return them as None.\n\n Examples:\n largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n largest_smallest_integers([]) == (None, None)\n largest_smallest_integers([0]) == (None, None)\n '''\n largest_negative = None\n smallest_positive = None\n\n for num in lst:\n if num < 0:\n if largest_negative is None or num > largest_negative:\n largest_negative = num\n elif num > 0:\n if smallest_positive is None or num < smallest_positive:\n smallest_positive = num\n\n return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n \"\"\"Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n For example:\n digits(1) == 1\n digits(4) == 0\n digits(235) == 15\n \"\"\"\n product = 1\n has_odd = False\n \n for digit in str(n):\n digit = int(digit)\n if digit % 2 != 0: # Check if the digit is odd\n product *= digit\n has_odd = True\n \n return product if has_odd else 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n \n >>> flip_case('Hello')\n 'hELLO'\n >>> flip_case('Python')\n 'pYTHON'\n >>> flip_case('1234')\n '1234'\n >>> flip_case('!@#$')\n '!@#$'\n >>> flip_case('Mixed CASE')\n 'mIXED case'\n \"\"\"\n return string.swapcase()", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n \n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n \"\"\"\n count = 0\n start = 0\n \n while True:\n start = string.find(substring, start)\n if start == -1:\n break\n count += 1\n start += 1 # Move to the next character to allow for overlapping\n\n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to find the closest pairs easily\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest elements\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n \n Args:\n strings (List[str]): A list of strings to filter.\n prefix (str): The prefix to filter the strings by.\n \n Returns:\n List[str]: A list of strings that start with the given prefix.\n \n Examples:\n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n \"\"\"\n return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lower_string = string.lower()\n # Use a set to find distinct characters\n distinct_characters = set(lower_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n \"\"\" Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n \n >>> string_xor('010', '110')\n '100'\n >>> string_xor('111', '000')\n '111'\n >>> string_xor('101', '101')\n '000'\n >>> string_xor('000', '000')\n '000'\n \"\"\"\n # Ensure both strings are of the same length\n if len(a) != len(b):\n raise ValueError(\"Input strings must be of the same length.\")\n \n # Perform XOR operation\n result = []\n for bit_a, bit_b in zip(a, b):\n result.append('1' if bit_a != bit_b else '0')\n \n return ''.join(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n \"\"\"Given length of a side and height, return the area of a triangle.\n \n The area of a triangle can be calculated using the formula:\n area = (base * height) / 2\n \n Parameters:\n a (float): The length of the base of the triangle.\n h (float): The height of the triangle.\n \n Returns:\n float: The area of the triangle.\n \n >>> triangle_area(5, 3)\n 7.5\n >>> triangle_area(10, 2)\n 10.0\n >>> triangle_area(0, 5)\n 0.0\n >>> triangle_area(5, 0)\n 0.0\n \"\"\"\n return (a * h) / 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n \n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n \"\"\"\n return [x + 1 for x in l]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted = []\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Calculate the new character with a shift of 4 (2 * 2)\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a')) if char.islower() else \\\n chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n encrypted.append(new_char)\n else:\n encrypted.append(char) # Non-alphabetic characters remain unchanged\n return ''.join(encrypted)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n else:\n return lst2", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": [[["happy", "birthday", "sarah"], ["happy", "birthday", "sally"]]]}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n \n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by row index (ascending) and then by column index (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n \"\"\"\n Given an array arr of integers, find the minimum number of elements that\n need to be changed to make the array palindromic. A palindromic array is an array that\n is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n For example:\n smallest_change([1,2,3,5,4,7,9,6]) == 4\n smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n smallest_change([1, 2, 3, 2, 1]) == 0\n \"\"\"\n n = len(arr)\n changes = 0\n \n # Compare elements from the start and end towards the center\n for i in range(n // 2):\n if arr[i] != arr[n - 1 - i]:\n changes += 1\n \n return changes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" Input to this function is a string representing musical notes in a special ASCII format.\n Your task is to parse this string and return list of integers corresponding to how many beats does each\n note last.\n\n Here is a legend:\n 'o' - whole note, lasts four beats\n 'o|' - half note, lasts two beats\n '.|' - quarter note, lasts one beat\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n # Define a mapping from note representation to beats\n note_to_beats = {\n 'o': 4, # whole note\n 'o|': 2, # half note\n '.|': 1 # quarter note\n }\n \n # Split the input string into individual notes\n notes = music_string.split()\n \n # Parse each note and convert to beats\n beats = [note_to_beats[note] for note in notes if note in note_to_beats]\n \n return beats", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n \"\"\"You are given a string s.\n Your task is to check if the string is happy or not.\n A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n \n For example:\n is_happy(a) => False\n is_happy(aa) => False\n is_happy(abcd) => True\n is_happy(aabb) => False\n is_happy(adb) => True\n is_happy(xyy) => False\n \"\"\"\n # Check if the length of the string is at least 3\n if len(s) < 3:\n return False\n \n # Iterate through the string and check every 3 consecutive characters\n for i in range(len(s) - 2):\n # Get the current substring of 3 characters\n substring = s[i:i+3]\n # Check if all characters in the substring are distinct\n if len(set(substring)) != 3:\n return False\n \n return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string.\n \n Args:\n strings (List[str]): A list of strings to concatenate.\n \n Returns:\n str: A single concatenated string.\n \n Examples:\n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n \"\"\"\n return ''.join(strings)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n \"\"\" \n Input is a space-delimited string of numerals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest.\n \n >>> sort_numbers('three one five')\n 'one three five'\n \"\"\"\n # Mapping of words to their corresponding numeric values\n num_map = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n \n # Split the input string into a list of words\n words = numbers.split()\n \n # Sort the words based on their numeric values using the mapping\n sorted_words = sorted(words, key=lambda word: num_map[word])\n \n # Join the sorted words back into a single string\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n \n >>> make_palindrome('')\n ''\n >>> make_palindrome('cat')\n 'catac'\n >>> make_palindrome('cata')\n 'catac'\n \"\"\"\n # Find the longest palindromic suffix\n for i in range(len(string)):\n if is_palindrome(string[i:]):\n # If the suffix is a palindrome, we need to append the reverse of the prefix\n prefix = string[:i]\n return string + prefix[::-1]\n return string # In case the string is empty or already a palindrome", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n \n # Create a new list with elements that occur only once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1.\n \n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n min_val = min(numbers)\n max_val = max(numbers)\n \n # Avoid division by zero if all numbers are the same\n if min_val == max_val:\n return [0.0] * len(numbers)\n \n return [(num - min_val) / (max_val - min_val) for num in numbers]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n letter_grades = []\n \n for gpa in grades:\n if gpa == 4.0:\n letter_grades.append('A+')\n elif gpa > 3.7:\n letter_grades.append('A')\n elif gpa > 3.3:\n letter_grades.append('A-')\n elif gpa > 3.0:\n letter_grades.append('B+')\n elif gpa > 2.7:\n letter_grades.append('B')\n elif gpa > 2.3:\n letter_grades.append('B-')\n elif gpa > 2.0:\n letter_grades.append('C+')\n elif gpa > 1.7:\n letter_grades.append('C')\n elif gpa > 1.3:\n letter_grades.append('C-')\n elif gpa > 1.0:\n letter_grades.append('D+')\n elif gpa > 0.7:\n letter_grades.append('D')\n elif gpa > 0.0:\n letter_grades.append('D-')\n else:\n letter_grades.append('E')\n \n return letter_grades", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef generate_primes(limit):\n \"\"\"Generate a list of prime numbers up to a given limit.\"\"\"\n return [num for num in range(2, limit) if is_prime(num)]\ndef is_multiply_prime(a):\n \"\"\"Return true if the given number is the multiplication of 3 prime numbers.\"\"\"\n if a >= 100:\n return False\n \n primes = generate_primes(a)\n prime_count = len(primes)\n \n # Check all combinations of three primes\n for i in range(prime_count):\n for j in range(i, prime_count):\n for k in range(j, prime_count):\n product = primes[i] * primes[j] * primes[k]\n if product == a:\n return True\n if product > a:\n break # No need to check further if product exceeds a\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n '''\n Write a function that returns True if the object q will fly, and False otherwise.\n The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n\n Example:\n will_it_fly([1, 2], 5) \u279e False \n # 1+2 is less than the maximum possible weight, but it's unbalanced.\n\n will_it_fly([3, 2, 3], 1) \u279e False\n # it's balanced, but 3+2+3 is more than the maximum possible weight.\n\n will_it_fly([3, 2, 3], 9) \u279e True\n # 3+2+3 is less than the maximum possible weight, and it's balanced.\n\n will_it_fly([3], 5) \u279e True\n # 3 is less than the maximum possible weight, and it's balanced.\n '''\n # Check if the list is a palindrome\n is_balanced = q == q[::-1]\n \n # Calculate the sum of the elements in the list\n total_weight = sum(q)\n \n # Check if the object will fly\n return is_balanced and total_weight <= w", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words and keep track of spaces\n words = s.split(' ')\n \n # Sort each word and keep the spaces intact\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back with spaces\n result = ' '.join(sorted_words)\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion.\n base numbers are less than 10.\n \n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n \"\"\"\n if base < 2 or base >= 10:\n raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n \n if x == 0:\n return '0'\n \n result = []\n while x > 0:\n result.append(str(x % base))\n x //= base\n \n return ''.join(reversed(result))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in lower \n case or all keys are strings in upper case, else return False.\n The function should return False if the given dictionary is empty.\n \n Examples:\n check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n \"\"\"\n if not input_dict:\n return False\n\n all_lower = all(isinstance(key, str) and key.islower() for key in input_dict.keys())\n all_upper = all(isinstance(key, str) and key.isupper() for key in input_dict.keys())\n\n return all_lower or all_upper", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n or sort it in descending order if the sum( first index value, last index value) is even.\n\n Note:\n * don't change the given array.\n\n Examples:\n * sort_array([]) => []\n * sort_array([5]) => [5]\n * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n \"\"\"\n if not array: # Check for empty array\n return []\n \n first_value = array[0]\n last_value = array[-1]\n sum_values = first_value + last_value\n\n # Create a copy of the array to sort\n sorted_array = array.copy()\n\n if sum_values % 2 == 0:\n # Sort in descending order if the sum is even\n sorted_array.sort(reverse=True)\n else:\n # Sort in ascending order if the sum is odd\n sorted_array.sort()\n\n return sorted_array", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n \n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n \"\"\"\n seen = set()\n for number in l:\n if -number in seen:\n return True\n seen.add(number)\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n '''\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n \n Examples\n any_int(5, 2, 7) \u279e True\n \n any_int(3, 2, 2) \u279e False\n\n any_int(3, -2, 1) \u279e True\n \n any_int(3.6, -2.2, 2) \u279e False\n '''\n # Check if all inputs are integers\n if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n # Check if one number is equal to the sum of the other two\n return x == y + z or y == x + z or z == x + y\n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n \"\"\"Task\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n \"\"\"\n return sum(ord(char) for char in s if char.isupper())", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"(\" and \")\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"(\")\n False\n >>> correct_bracketing(\"()\")\n True\n >>> correct_bracketing(\"(()())\")\n True\n >>> correct_bracketing(\")(()\")\n False\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n # If balance goes negative, there are unmatched closing brackets\n if balance < 0:\n return False\n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n \"\"\"\n Takes as input string encoded with encode_shift function. Returns decoded string.\n \"\"\"\n return \"\".join([chr(((ord(ch) - ord(\"a\") - 5) % 26) + ord(\"a\")) for ch in s])", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n \"\"\"Return True if list elements are monotonically increasing or decreasing.\n \n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n \"\"\"\n if not l: # An empty list is considered monotonic\n return True\n \n increasing = decreasing = True\n \n for i in range(1, len(l)):\n if l[i] > l[i - 1]:\n decreasing = False\n elif l[i] < l[i - 1]:\n increasing = False\n \n return increasing or decreasing", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n # Keep dividing n by factor until it is no longer divisible\n while n > 1:\n if n % factor == 0:\n n //= factor # Divide n by the factor\n else:\n factor += 1 # Move to the next potential factor\n return factor # The last factor is the largest prime factor", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n \"\"\"\n Given an array representing a branch of a tree that has non-negative integer nodes,\n your task is to pluck one of the nodes and return it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n The plucked node should be returned in a list, [ smallest_value, its index ],\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index. \n\n Example 3:\n Input: []\n Output: []\n \n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n Explanation: 0 is the smallest value, but there are two zeros,\n so we will choose the first zero, which has the smallest index.\n\n Constraints:\n * 1 <= nodes.length <= 10000\n * 0 <= node.value\n \"\"\"\n smallest_even = float('inf')\n smallest_index = -1\n\n for index, value in enumerate(arr):\n if value % 2 == 0: # Check if the value is even\n if value < smallest_even: # Check if it's the smallest even found\n smallest_even = value\n smallest_index = index\n\n if smallest_index == -1: # No even value found\n return []\n \n return [smallest_even, smallest_index]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float) -> float:\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list) -> list:\n \"\"\"\n Computes the derivative of the polynomial with coefficients xs.\n \"\"\"\n return [i * coeff for i, coeff in enumerate(xs) if i > 0]\ndef find_zero(xs: list, initial_guess: float = 0.0, tolerance: float = 1e-7, max_iterations: int = 1000) -> float:\n \"\"\" \n xs are coefficients of a polynomial.\n find_zero finds x such that poly(x) = 0.\n find_zero returns only one zero point, even if there are many.\n Moreover, find_zero only takes list xs having an even number of coefficients\n and the largest non-zero coefficient as it guarantees a solution.\n \n >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n -0.5\n >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n 1.0\n \"\"\"\n if len(xs) % 2 != 0:\n raise ValueError(\"The number of coefficients must be even.\")\n \n current_guess = initial_guess\n for _ in range(max_iterations):\n f_value = poly(xs, current_guess)\n f_derivative = poly(derivative(xs), current_guess)\n \n if f_derivative == 0:\n raise ValueError(\"Derivative is zero. No solution found.\")\n \n next_guess = current_guess - f_value / f_derivative\n \n if abs(next_guess - current_guess) < tolerance:\n return next_guess\n \n current_guess = next_guess\n \n raise ValueError(\"Maximum iterations reached. No solution found.\")", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[[5, 10, -3, 1]]]}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n \"\"\"Return maximum element in the list.\n \n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n \"\"\"\n if not l: # Check if the list is empty\n raise ValueError(\"The list is empty.\")\n \n max_value = l[0] # Initialize max_value with the first element\n for item in l:\n if item > max_value:\n max_value = item # Update max_value if a larger item is found\n return max_value", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" brackets is a string of \"<\" and \">\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"<\")\n False\n >>> correct_bracketing(\"<>\")\n True\n >>> correct_bracketing(\"<<><>>\")\n True\n >>> correct_bracketing(\"><<>\")\n False\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '<':\n balance += 1\n elif char == '>':\n balance -= 1\n # If balance goes negative, it means there's a closing bracket without a matching opening bracket\n if balance < 0:\n return False\n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n '''\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequency greater than or equal to the value of the integer itself. \n The frequency of an integer is the number of times it appears in the list.\n If no such a value exist, return -1.\n \n Examples:\n search([4, 1, 2, 2, 3, 1]) == 2\n search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n search([5, 5, 4, 4, 4]) == -1\n '''\n from collections import Counter\n \n # Count the frequency of each number in the list\n frequency = Counter(lst)\n \n # Initialize the result variable\n result = -1\n \n # Iterate through the frequency dictionary\n for num, freq in frequency.items():\n # Check if the frequency is greater than or equal to the number itself\n if freq >= num:\n # Update the result if this number is greater than the current result\n result = max(result, num)\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n \"\"\"\n Write a function that takes a message, and encodes in such a \n way that it swaps case of all letters, replaces all vowels in \n the message with the letter that appears 2 places ahead of that \n vowel in the english alphabet. \n Assume only letters. \n \n Examples:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n vowels = 'aeiouAEIOU'\n encoded_message = []\n\n for char in message:\n if char.isalpha(): # Check if the character is a letter\n # Swap case\n if char in vowels:\n # Replace vowel with the letter 2 places ahead\n if char.islower():\n new_char = chr((ord(char) - ord('a') + 2) % 26 + ord('a'))\n else:\n new_char = chr((ord(char) - ord('A') + 2) % 26 + ord('A'))\n else:\n new_char = char.swapcase() # Swap case for consonants\n encoded_message.append(new_char)\n else:\n encoded_message.append(char) # Keep non-letter characters unchanged\n\n return ''.join(encoded_message)", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["TEST"]], "plus_fail_tests": [["abcdefghijklmnopqrstuvwxyz"]]}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n \"\"\"\n In this task, you will be given a string that represents a number of apples and oranges \n that are distributed in a basket of fruit. This basket contains \n apples, oranges, and mango fruits. Given the string that represents the total number of \n the oranges and apples and an integer that represents the total number of the fruits \n in the basket, return the number of the mango fruits in the basket.\n \n Parameters:\n s (str): A string representing the number of apples and oranges.\n n (int): An integer representing the total number of fruits in the basket.\n \n Returns:\n int: The number of mango fruits in the basket.\n \n Examples:\n fruit_distribution(\"5 apples and 6 oranges\", 19) -> 8\n fruit_distribution(\"0 apples and 1 oranges\", 3) -> 2\n fruit_distribution(\"2 apples and 3 oranges\", 100) -> 95\n fruit_distribution(\"100 apples and 1 oranges\", 120) -> 19\n \"\"\"\n \n # Extract the number of apples and oranges from the string\n parts = s.split()\n apples = int(parts[0]) # First part is the number of apples\n oranges = int(parts[3]) # Fourth part is the number of oranges\n \n # Calculate the number of mangoes\n mangoes = n - apples - oranges\n return mangoes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n \n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n \"\"\"\n return n * (n + 1) // 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(divisible_by_three)\n \n # Create a new list to hold the result\n result = l.copy()\n \n # Replace values at indices divisible by 3 with sorted values\n for index, value in zip((i for i in range(len(l)) if i % 3 == 0), sorted_values):\n result[index] = value\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n Example\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n \"\"\"\n # Initialize variables to track the minimum sum and the current sum\n min_sum = float('inf')\n current_sum = 0\n \n for num in nums:\n current_sum += num\n min_sum = min(min_sum, current_sum)\n \n # If current_sum is positive, reset it to 0\n if current_sum > 0:\n current_sum = 0\n \n return min_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n '''\n Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n Examples\n split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"abcdef\") == 3 \n '''\n # Check for whitespace in the text\n if ' ' in txt:\n return txt.split()\n \n # Check for commas in the text\n elif ',' in txt:\n return txt.split(',')\n \n # If no whitespace or commas, count lower-case letters with odd order\n else:\n odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n return odd_count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n \"\"\"\n Given a non-empty array of integers arr and an integer k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example:\n\n Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n Output: 24 # sum of 21 + 3\n\n Constraints:\n 1. 1 <= len(arr) <= 100\n 2. 1 <= k <= len(arr)\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate through the first k elements of the array\n for i in range(k):\n # Check if the current element has at most two digits\n if -100 < arr[i] < 100:\n total_sum += arr[i]\n \n return total_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length and alphabetically.\n \n Args:\n lst (list of str): A list of strings.\n \n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n \"\"\"\n Given a string text, replace all spaces in it with underscores, \n and if a string has more than 2 consecutive spaces, \n then replace all consecutive spaces with - \n \n fix_spaces(\"Example\") == \"Example\"\n fix_spaces(\"Example 1\") == \"Example_1\"\n fix_spaces(\" Example 2\") == \"_Example_2\"\n fix_spaces(\" Example 3\") == \"_Example-3\"\n \"\"\"\n import re\n \n # Replace more than 2 consecutive spaces with a single '-'\n text = re.sub(r' {3,}', '-', text)\n \n # Replace single spaces with underscores\n text = text.replace(' ', '_')\n \n return text", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n as follows: start with any positive integer n. Then each term is obtained from the \n previous term as follows: if the previous term is even, the next term is one half of \n the previous term. If the previous term is odd, the next term is 3 times the previous\n term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n Note: \n 1. Collatz(1) is [1].\n 2. returned list sorted in increasing order.\n\n For example:\n get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n collatz_sequence = []\n current = n\n \n while current != 1:\n collatz_sequence.append(current)\n if current % 2 == 0:\n current //= 2\n else:\n current = 3 * current + 1\n \n collatz_sequence.append(1) # Add the last term which is 1\n \n # Filter odd numbers and sort them\n odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n \n return odd_numbers", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n \n The date is valid if all of the following rules are satisfied:\n 1. The date string is not empty.\n 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n The number of days is not less than 1 or higher than 29 for the month 2.\n 3. The months should not be less than 1 or higher than 12.\n 4. The date should be in the format: mm-dd-yyyy\n \n Args:\n date (str): The date string to validate.\n \n Returns:\n bool: True if the date is valid, False otherwise.\n \"\"\"\n if not date:\n return False\n \n # Check the format\n if len(date) != 10 or date[2] != '-' or date[5] != '-':\n return False\n \n try:\n month = int(date[:2])\n day = int(date[3:5])\n year = int(date[6:])\n except ValueError:\n return False\n \n # Validate month\n if month < 1 or month > 12:\n return False\n \n # Validate day based on month\n if month in [1, 3, 5, 7, 8, 10, 12]: # 31 days\n if day < 1 or day > 31:\n return False\n elif month in [4, 6, 9, 11]: # 30 days\n if day < 1 or day > 30:\n return False\n elif month == 2: # February\n if day < 1 or day > 29:\n return False\n \n return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n \"\"\"Task\n We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and True/False for the check.\n Example\n For s = \"abcde\", c = \"ae\", the result should be ('bcd',False)\n For s = \"abcdef\", c = \"b\" the result should be ('acdef',False)\n For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc',True)\n \"\"\"\n # Create a set of characters to delete for faster lookup\n delete_set = set(c)\n \n # Create the result string by filtering out characters in delete_set\n result = ''.join(char for char in s if char not in delete_set)\n \n # Check if the result string is a palindrome\n is_palindrome = result == result[::-1]\n \n return (result, is_palindrome)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n \"\"\"\n Calculate the number of times buckets need to be lowered to empty the wells.\n\n Parameters:\n grid (list of list of int): A rectangular grid representing wells.\n capacity (int): The capacity of each bucket.\n\n Returns:\n int: The total number of times buckets need to be lowered.\n \"\"\"\n total_water = 0\n \n # Count the total amount of water in the grid\n for row in grid:\n total_water += sum(row)\n \n # Calculate the number of times buckets need to be lowered\n # Each bucket can carry 'capacity' units of water\n if total_water == 0:\n return 0\n else:\n return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": [[[[1, 0, 0, 1], [0, 1, 1, 1], [0, 0, 0, 0], [1, 0, 1, 1]], 2]]}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n \"\"\"Create a function which takes a string representing a file's name, and returns\n 'Yes' if the the file's name is valid, and returns 'No' otherwise.\n A file's name is considered to be valid if and only if all the following conditions \n are met:\n - There should not be more than three digits ('0'-'9') in the file's name.\n - The file's name contains exactly one dot '.'\n - The substring before the dot should not be empty, and it starts with a letter from \n the latin alphapet ('a'-'z' and 'A'-'Z').\n - The substring after the dot should be one of these: ['txt', 'exe', 'dll']\n Examples:\n file_name_check(\"example.txt\") # => 'Yes'\n file_name_check(\"1example.dll\") # => 'No' (the name should start with a latin alphapet letter)\n \"\"\"\n \n # Split the file name into name and extension\n if file_name.count('.') != 1:\n return 'No'\n \n name, extension = file_name.split('.')\n \n # Check if the name is empty or starts with a non-letter\n if not name or not name[0].isalpha():\n return 'No'\n \n # Check the extension\n valid_extensions = ['txt', 'exe', 'dll']\n if extension not in valid_extensions:\n return 'No'\n \n # Count the digits in the file name\n digit_count = sum(c.isdigit() for c in file_name)\n if digit_count > 3:\n return 'No'\n \n return 'Yes'", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n \"\"\"Write a function that takes an array of numbers as input and returns \n the number of elements in the array that are greater than 10 and both \n first and last digits of a number are odd (1, 3, 5, 7, 9).\n \n For example:\n specialFilter([15, -73, 14, -15]) => 1 \n specialFilter([33, -2, -3, 45, 21, 109]) => 2\n \"\"\"\n \n def is_odd_digit(digit):\n return digit in {'1', '3', '5', '7', '9'}\n \n def first_and_last_odd(num):\n str_num = str(abs(num)) # Convert to string and take absolute value\n return is_odd_digit(str_num[0]) and is_odd_digit(str_num[-1])\n \n count = 0\n for num in nums:\n if num > 10 and first_and_last_odd(num):\n count += 1\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closest to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sorted by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct planet names. \n Examples\n bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n '''\n \n planets = [\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n ]\n \n if planet1 not in planets or planet2 not in planets:\n return ()\n \n index1 = planets.index(planet1)\n index2 = planets.index(planet2)\n \n # Ensure index1 is less than index2 for slicing\n start_index = min(index1, index2) + 1\n end_index = max(index1, index2)\n \n return tuple(planets[start_index:end_index])", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers.\n You need to return the sum of squared numbers in the given list,\n round each element in the list to the upper int (Ceiling) first.\n \n Examples:\n For lst = [1,2,3] the output should be 14\n For lst = [1,4,9] the output should be 98\n For lst = [1,3,5,7] the output should be 84\n For lst = [1.4,4.2,0] the output should be 29\n For lst = [-2.4,1,1] the output should be 6\n \"\"\"\n return sum(math.ceil(x) ** 2 for x in lst)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n '''\n Create a function that returns True if the last character\n of a given string is an alphabetical character and is not\n a part of a word, and False otherwise.\n Note: \"word\" is a group of characters separated by space.\n\n Examples:\n check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '''\n # Strip any trailing whitespace from the string\n txt = txt.rstrip()\n \n # Check if the string is empty after stripping\n if not txt:\n return False\n \n # Get the last character\n last_char = txt[-1]\n \n # Check if the last character is a letter\n if last_char.isalpha():\n # Check if the last character is part of a word\n # A character is part of a word if it is preceded by a non-space character\n if len(txt) > 1 and txt[-2] != ' ':\n return False\n return True\n \n return False", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["eeeee e "]], "plus_fail_tests": [["k "]]}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n \"\"\"\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example :\n Input: n = 5\n Output: 1\n Explanation: \n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n \"\"\"\n # Create the array a\n a = [i * i - i + 1 for i in range(1, n + 1)]\n \n # Count the number of valid triples\n count = 0\n \n # Check all combinations of triples (i, j, k) with i < j < k\n for i in range(n):\n for j in range(i + 1, n):\n for k in range(j + 1, n):\n if (a[i] + a[j] + a[k]) % 3 == 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to make it easier to find close elements\n numbers.sort()\n \n # Check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef sum_of_digits(n):\n \"\"\"Return the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n largest_prime = -1\n \n for number in lst:\n if is_prime(number) and number > largest_prime:\n largest_prime = number\n \n if largest_prime == -1:\n return 0 # Return 0 if no prime is found\n \n return sum_of_digits(largest_prime)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n \"\"\"This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If \n there's no such number, then the function should return -1.\n\n For example:\n choose_num(12, 15) = 14\n choose_num(13, 12) = -1\n \"\"\"\n # Ensure x is less than or equal to y\n if x > y:\n return -1\n \n # Start from the largest number in the range and check for evenness\n for num in range(y, x - 1, -1):\n if num % 2 == 0:\n return num\n \n return -1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n \"\"\"\n return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n \n double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n double_the_difference([-1, -2, 0]) == 0\n double_the_difference([9, -2]) == 81\n double_the_difference([0]) == 0 \n \n If the input list is empty, return 0.\n '''\n if not lst: # Check if the list is empty\n return 0\n \n return sum(x**2 for x in lst if isinstance(x, int) and x >= 0 and x % 2 != 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n reverse the resulting array, and then replace each digit by its corresponding name from\n \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n For example:\n arr = [2, 1, 1, 4, 5, 8, 2, 3] \n -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n \n If the array is empty, return an empty array:\n arr = []\n return []\n \n If the array has any strange number ignore it:\n arr = [1, -1 , 55] \n -> sort arr -> [-1, 1, 55]\n -> reverse arr -> [55, 1, -1]\n return = ['One']\n \"\"\"\n \n # Mapping of digits to their corresponding names\n digit_to_name = {\n 1: \"One\",\n 2: \"Two\",\n 3: \"Three\",\n 4: \"Four\",\n 5: \"Five\",\n 6: \"Six\",\n 7: \"Seven\",\n 8: \"Eight\",\n 9: \"Nine\"\n }\n \n # Filter the array to include only numbers between 1 and 9\n filtered_arr = [num for num in arr if 1 <= num <= 9]\n \n # Sort the filtered array\n sorted_arr = sorted(filtered_arr)\n \n # Reverse the sorted array\n reversed_arr = sorted_arr[::-1]\n \n # Convert the digits to their corresponding names\n result = [digit_to_name[num] for num in reversed_arr]\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n if not (1 <= number <= 1000):\n raise ValueError(\"Number must be between 1 and 1000\")\n\n roman_numerals = [\n (1000, 'm'),\n (900, 'cm'),\n (500, 'd'),\n (400, 'cd'),\n (100, 'c'),\n (90, 'xc'),\n (50, 'l'),\n (40, 'xl'),\n (10, 'x'),\n (9, 'ix'),\n (5, 'v'),\n (4, 'iv'),\n (1, 'i')\n ]\n\n result = []\n for value, numeral in roman_numerals:\n while number >= value:\n result.append(numeral)\n number -= value\n\n return ''.join(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic algebra operations, and \n the second list is a list of integers. Use the two given lists to build the algebraic \n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + ) \n Subtraction ( - ) \n Multiplication ( * ) \n Floor division ( // ) \n Exponentiation ( ** ) \n\n Example:\n operator = ['+', '*', '-']\n operand = [2, 3, 4, 5]\n result = 2 + 3 * 4 - 5\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.\n \"\"\"\n # Start with the first operand\n result = operand[0]\n \n # Iterate through the operators and operands\n for i in range(len(operator)):\n op = operator[i]\n next_operand = operand[i + 1]\n \n if op == '+':\n result += next_operand\n elif op == '-':\n result -= next_operand\n elif op == '*':\n result *= next_operand\n elif op == '//':\n result //= next_operand\n elif op == '**':\n result **= next_operand\n else:\n raise ValueError(f\"Unsupported operator: {op}\")\n \n return result", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": [[["+", "-", "*", "//"], [5, 2, 3, 4, 7]]]}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n \"\"\"Write a function that accepts a list of strings.\n The list contains different words. Return the word with maximum number\n of unique characters. If multiple strings have maximum number of unique\n characters, return the one which comes first in lexicographical order.\n\n find_max([\"name\", \"of\", \"string\"]) == \"string\"\n find_max([\"name\", \"enam\", \"game\"]) == \"enam\"\n find_max([\"aaaaaaa\", \"bb\" ,\"cc\"]) == \"aaaaaaa\"\n \"\"\"\n max_word = \"\"\n max_unique_count = 0\n\n for word in words:\n unique_chars = set(word)\n unique_count = len(unique_chars)\n\n if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n max_word = word\n max_unique_count = unique_count\n\n return max_word", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n \"\"\"Given a list of positive integers x, return a sorted list of all \n elements that haven't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n def has_even_digit(n):\n \"\"\"Check if the number has any even digit.\"\"\"\n return any(int(digit) % 2 == 0 for digit in str(n))\n\n # Filter the list to include only numbers without even digits\n result = [num for num in x if not has_even_digit(num)]\n \n # Return the sorted result\n return sorted(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n def max_nesting_depth(s: str) -> int:\n max_depth = 0\n current_depth = 0\n for char in s:\n if char == '(':\n current_depth += 1\n max_depth = max(max_depth, current_depth)\n elif char == ')':\n current_depth -= 1\n return max_depth\n\n groups = paren_string.split()\n return [max_nesting_depth(group) for group in groups]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" \n Input to this function is a string containing multiple groups of nested parentheses. \n Your goal is to separate those groups into separate strings and return the list of those.\n Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n Ignore any spaces in the input string.\n \n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n # Remove spaces from the input string\n paren_string = paren_string.replace(\" \", \"\")\n \n result = []\n balance = 0\n current_group = []\n \n for char in paren_string:\n if char == '(':\n if balance == 0 and current_group:\n # If we are starting a new group, save the previous one\n result.append(''.join(current_group))\n current_group = []\n balance += 1\n current_group.append(char)\n elif char == ')':\n balance -= 1\n current_group.append(char)\n if balance == 0:\n # If we have closed all opened parentheses, save the current group\n result.append(''.join(current_group))\n current_group = []\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n \"\"\"Create a function which returns the largest index of an element which\n is not greater than or equal to the element immediately preceding it. If\n no such element exists then return -1. The given array will not contain\n duplicate values.\n\n Examples:\n can_arrange([1,2,4,3,5]) = 3\n can_arrange([1,2,3]) = -1\n \"\"\"\n # Initialize the index to -1, which will be returned if no such element is found\n largest_index = -1\n \n # Iterate through the array starting from the second element\n for i in range(1, len(arr)):\n # Check if the current element is less than the previous element\n if arr[i] < arr[i - 1]:\n largest_index = i # Update the largest index found\n \n return largest_index", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n \n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n \"\"\"\n if not numbers:\n return (0, 1)\n \n total_sum = sum(numbers)\n total_product = 1\n for number in numbers:\n total_product *= number\n \n return (total_sum, total_product)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n '''\n Create a function that takes a string as input which contains only square brackets.\n The function should return True if and only if there is a valid subsequence of brackets \n where at least one bracket in the subsequence is nested.\n\n is_nested('[[]]') \u279e True\n is_nested('[]]]]]]][[[[[]') \u279e False\n is_nested('[][]') \u279e False\n is_nested('[]') \u279e False\n is_nested('[[][]]') \u279e True\n is_nested('[[]][[') \u279e True\n '''\n # Initialize a counter for open brackets\n open_count = 0\n # Initialize a flag to check for nesting\n nested = False\n \n for char in string:\n if char == '[':\n open_count += 1\n # If we have seen at least one open bracket before and we see another one,\n # it indicates nesting\n if open_count > 1:\n nested = True\n elif char == ']':\n open_count -= 1\n # If we close a bracket and we had opened brackets before\n if open_count < 0:\n return False # More closing brackets than opening\n # If we have closed all opened brackets, we can stop checking\n if open_count < 0:\n break\n \n # We need at least one nested bracket and all brackets must be closed\n return nested and open_count == 0", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["[[]][["]], "plus_fail_tests": [["[[]]]"]]}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n \"\"\"\n You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n \n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n \n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots that exist in stock\n \n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n \"\"\"\n # Calculate how many more carrots are needed\n additional_needed = need - number\n \n # If no additional carrots are needed, return the current state\n if additional_needed <= 0:\n return [number, remaining]\n \n # Determine how many carrots can be eaten from the remaining stock\n eaten = min(additional_needed, remaining)\n \n # Calculate the total eaten and remaining carrots\n total_eaten = number + eaten\n remaining_after_meal = remaining - eaten\n \n return [total_eaten, remaining_after_meal]", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": [[2, 2, 2]]}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n \"\"\"Calculate the factorial of a non-negative integer n.\"\"\"\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef special_factorial(n):\n \"\"\"Calculate the Brazilian factorial of n.\"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n result = 1\n for i in range(1, n + 1):\n result *= factorial(i)\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n \"\"\"You are given a string s.\n if s[i] is a letter, reverse its case from lower to upper or vise versa, \n otherwise keep it as it is.\n If the string contains no letters, reverse the string.\n The function should return the resulted string.\n \n Examples:\n solve(\"1234\") = \"4321\"\n solve(\"ab\") = \"AB\"\n solve(\"#a@C\") = \"#A@c\"\n \"\"\"\n # Check if there are any letters in the string\n has_letters = any(c.isalpha() for c in s)\n \n if has_letters:\n # Reverse case for letters and keep others the same\n return ''.join(c.swapcase() if c.isalpha() else c for c in s)\n else:\n # Reverse the string if there are no letters\n return s[::-1]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef x_or_y(n, x, y):\n \"\"\"Return the value of x if n is a prime number, otherwise return y.\"\"\"\n if is_prime(n):\n return x\n else:\n return y", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return True if the three\n sides form a right-angled triangle, False otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or \n 90 degree.\n \n Example:\n right_angle_triangle(3, 4, 5) == True\n right_angle_triangle(1, 2, 3) == False\n '''\n # Sort the sides to identify the longest side\n sides = sorted([a, b, c])\n \n # Check the Pythagorean theorem\n return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n \"\"\"Convert a decimal number to binary format with specific formatting.\n\n Args:\n decimal (int): A non-negative integer to convert to binary.\n\n Returns:\n str: A string representing the binary format of the decimal number,\n prefixed and suffixed with 'db'.\n \n Examples:\n >>> decimal_to_binary(15)\n 'db1111db'\n >>> decimal_to_binary(32)\n 'db100000db'\n \"\"\"\n if decimal < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n # Convert decimal to binary and remove the '0b' prefix\n binary_representation = bin(decimal)[2:]\n \n # Format the output with 'db' at the beginning and end\n formatted_output = f\"db{binary_representation}db\"\n \n return formatted_output", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n \"\"\"\n Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move at the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.\n\n Parameters:\n n (int): The number of cars in each direction.\n\n Returns:\n int: The total number of collisions.\n \"\"\"\n # Each car moving left to right will collide with each car moving right to left\n # Therefore, the total number of collisions is n * n\n return n * n", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fib4(0) -> 0\n fib4(1) -> 0\n fib4(2) -> 2\n fib4(3) -> 0\n fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.\n \n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 2\n elif n == 3:\n return 0\n\n # Initialize the first four values of the sequence\n fib_values = [0, 0, 2, 0]\n\n # Compute the values iteratively\n for i in range(4, n + 1):\n next_value = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n fib_values.append(next_value)\n\n return fib_values[n]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n \"\"\"You are given two positive integers n and m, and your task is to compute the\n average of the integers from n through m (including n and m). \n Round the answer to the nearest integer and convert that to binary.\n If n is greater than m, return -1.\n \n Example:\n rounded_avg(1, 5) => \"0b11\"\n rounded_avg(7, 5) => -1\n rounded_avg(10, 20) => \"0b1111\"\n rounded_avg(20, 33) => \"0b11010\"\n \"\"\"\n if n > m:\n return -1\n \n # Calculate the sum of integers from n to m\n total_sum = sum(range(n, m + 1))\n count = m - n + 1 # Total numbers from n to m\n \n # Calculate the average and round it\n average = total_sum / count\n rounded_average = round(average)\n \n # Convert the rounded average to binary\n return bin(rounded_average)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n \"\"\"\n Checks if given string is a palindrome.\n \n A palindrome is a string that reads the same forward and backward.\n \n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n \"\"\"\n # Normalize the string by removing spaces and converting to lowercase\n normalized_text = text.replace(\" \", \"\").lower()\n # Check if the string is equal to its reverse\n return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["never odd or even"]]}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this integer is a cube of some integer number.\n Note: you may assume the input is always valid.\n \n Examples:\n iscube(1) ==> True\n iscube(2) ==> False\n iscube(-1) ==> True\n iscube(64) ==> True\n iscube(0) ==> True\n iscube(180) ==> False\n '''\n # Calculate the cube root of the absolute value of a\n cube_root = round(abs(a) ** (1/3))\n \n # Check if the cube of the rounded cube root equals the absolute value of a\n return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits will be 1 the output should be \"1\".\n For N = 150, the sum of digits will be 6 the output should be \"110\".\n For N = 147, the sum of digits will be 12 the output should be \"1100\".\n \n Variables:\n @N integer\n Constraints: 0 \u2264 N \u2264 10000.\n Output:\n a string of binary number\n \"\"\"\n # Calculate the sum of the digits of N\n digit_sum = sum(int(digit) for digit in str(N))\n \n # Convert the sum to binary and remove the '0b' prefix\n binary_sum = bin(digit_sum)[2:]\n \n return binary_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n '''\n Given list of integers, return list in strange order.\n Strange sorting, is when you start with the minimum value,\n then maximum of the remaining integers, then minimum and so on.\n\n Examples:\n strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n strange_sort_list([]) == []\n '''\n if not lst:\n return []\n\n sorted_lst = sorted(lst)\n result = []\n left, right = 0, len(sorted_lst) - 1\n\n while left <= right:\n if left == right:\n result.append(sorted_lst[left])\n else:\n result.append(sorted_lst[left])\n result.append(sorted_lst[right])\n left += 1\n right -= 1\n\n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n \"\"\" Return length of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n \"\"\"\n return len(string)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(28)\n 14\n >>> largest_divisor(1)\n 0\n >>> largest_divisor(10)\n 5\n \"\"\"\n if n <= 1:\n return 0 # No divisors for 1 or less\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return the area of\n the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n Otherwise return -1.\n Three sides make a valid triangle when the sum of any two sides is greater \n than the third side.\n \n Example:\n triangle_area(3, 4, 5) == 6.00\n triangle_area(1, 2, 10) == -1\n '''\n # Check for valid triangle\n if a + b > c and a + c > b and b + c > a:\n # Calculate the semi-perimeter\n s = (a + b + c) / 2\n # Calculate the area using Heron's formula\n area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n return round(area, 2)\n else:\n return -1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n \n >>> longest([])\n >>> None\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n \"\"\"\n if not strings:\n return None\n \n longest_string = strings[0]\n \n for string in strings:\n if len(string) > len(longest_string):\n longest_string = string\n \n return longest_string", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n \"\"\"\n Given a positive integer n, return the count of the numbers of n-digit\n positive integers that start or end with 1.\n \"\"\"\n if n < 1:\n return 0\n\n # Total n-digit numbers\n total_n_digit_numbers = 9 * (10 ** (n - 1))\n\n # Count of n-digit numbers that start with 1\n start_with_1 = 10 ** (n - 1)\n\n # Count of n-digit numbers that end with 1\n end_with_1 = total_n_digit_numbers // 10\n\n # Count of n-digit numbers that start and end with 1\n start_and_end_with_1 = 10 ** (n - 2) if n > 1 else 0\n\n # Total count of numbers that start or end with 1\n count = start_with_1 + end_with_1 - start_and_end_with_1\n\n return count", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[1000000]]}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n result = 1\n base = 2 % p # Start with 2 mod p\n while n > 0:\n if n % 2 == 1: # If n is odd, multiply the base with the result\n result = (result * base) % p\n base = (base * base) % p # Square the base\n n //= 2 # Divide n by 2\n return result", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[0, 1]]}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef prime_length(string):\n \"\"\"Check if the length of the string is a prime number.\"\"\"\n length = len(string)\n return is_prime(length)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n \"\"\"Returns True if x is a simple power of n, otherwise False.\n \n A number x is a simple power of n if there exists an integer k such that n**k = x.\n \n Args:\n x (int): The number to check.\n n (int): The base number.\n \n Returns:\n bool: True if x is a simple power of n, False otherwise.\n \"\"\"\n if n <= 1:\n return x == 1 # 1 is a power of any number, and no other number can be a power of 1 or 0.\n \n power = 1\n while True:\n result = n ** power\n if result == x:\n return True\n elif result > x:\n return False\n power += 1", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[1, 12]], "plus_fail_tests": [[1, 4]]}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n \"\"\"\n triples_sum_to_zero takes a list of integers as an input.\n it returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n \"\"\"\n n = len(l)\n # Sort the list to use the two-pointer technique\n l.sort()\n \n for i in range(n - 2):\n # Avoid duplicates for the first element\n if i > 0 and l[i] == l[i - 1]:\n continue\n \n left, right = i + 1, n - 1\n while left < right:\n current_sum = l[i] + l[left] + l[right]\n if current_sum == 0:\n return True\n elif current_sum < 0:\n left += 1\n else:\n right -= 1\n \n return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n \"\"\"Counts the number of prime hexadecimal digits in the given hexadecimal string.\"\"\"\n # Define the set of prime hexadecimal digits\n prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n \n # Count the number of prime hexadecimal digits in the input string\n count = sum(1 for digit in num if digit in prime_hex_digits)\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n \"\"\"Return median of elements in the list l.\n \n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n \"\"\"\n # Sort the list\n sorted_list = sorted(l)\n n = len(sorted_list)\n \n # Calculate median\n if n % 2 == 1: # Odd number of elements\n return sorted_list[n // 2]\n else: # Even number of elements\n mid1 = sorted_list[n // 2 - 1]\n mid2 = sorted_list[n // 2]\n return (mid1 + mid2) / 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return a greatest common divisor of two integers a and b\n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n \"\"\"\n while b:\n a, b = b, a % b\n return abs(a)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string\n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n \"\"\"\n return [string[:i] for i in range(1, len(string) + 1)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers\n >>> filter_integers(['a', 3.14, 5])\n [5]\n >>> filter_integers([1, 2, 3, 'abc', {}, []])\n [1, 2, 3]\n \"\"\"\n return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[[true, false, null, 0, -10, "test", [], {}, 3.14]]]}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n Input number should be equal to the product of all factors\n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n \"\"\"\n factors = []\n # Check for number of 2s that divide n\n while n % 2 == 0:\n factors.append(2)\n n //= 2\n \n # n must be odd at this point, so we can skip even numbers\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, append i and divide n\n while n % i == 0:\n factors.append(i)\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n factors.append(n)\n \n return factors", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with the encode_cyclic function.\n Returns the decoded string.\n \"\"\"\n # Split string into groups of length 3\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # Reverse the cycling of elements in each group unless the group has fewer than 3 elements\n groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n \n >>> circular_shift(12, 1)\n '21'\n >>> circular_shift(12, 2)\n '12'\n >>> circular_shift(12345, 1)\n '51234'\n >>> circular_shift(12345, 5)\n '54321'\n >>> circular_shift(12345, 6)\n '54321'\n \"\"\"\n # Convert the integer to a string to manipulate its digits\n str_x = str(x)\n num_digits = len(str_x)\n \n # If shift is greater than the number of digits, reverse the string\n if shift >= num_digits:\n return str_x[::-1]\n \n # Calculate the effective shift\n effective_shift = shift % num_digits\n \n # Perform the circular shift\n shifted_str = str_x[-effective_shift:] + str_x[:-effective_shift]\n \n return shifted_str", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[12, 2]], "plus_fail_tests": [[987654321, 9]]}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n \n For example:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n >>> is_bored(\"I am happy! Are you? I will go now.\")\n 2\n >>> is_bored(\"What a day. I can't believe it! I am so excited.\")\n 2\n \"\"\"\n # Split the string into sentences using the delimiters\n sentences = []\n current_sentence = []\n for char in S:\n if char in '.!?':\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n current_sentence = []\n else:\n current_sentence.append(char)\n if current_sentence: # Add the last sentence if it exists\n sentences.append(''.join(current_sentence).strip())\n \n # Count the sentences that start with \"I\"\n boredom_count = sum(1 for sentence in sentences if sentence.startswith('I'))\n \n return boredom_count", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": [["In the morning, I like to have a cup of coffee to start my day off right. How about you?"]]}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n \"\"\" \n xs represent coefficients of a polynomial.\n xs[0] + xs[1] * x + xs[2] * x^2 + ....\n Return derivative of this polynomial in the same form.\n \n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n \"\"\"\n # The derivative of a polynomial is calculated by multiplying each coefficient\n # by its corresponding power and reducing the power by one.\n return [i * coeff for i, coeff in enumerate(xs[1:], start=1)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two words have the same characters if they contain the same unique characters,\n regardless of the number of times each character appears.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_up_to(n):\n \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n primes = []\n for i in range(2, n):\n if is_prime(i):\n primes.append(i)\n return primes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n count_upper('aBCdEf') returns 1\n count_upper('abcdefg') returns 0\n count_upper('dBBE') returns 0\n \"\"\"\n uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n count = 0\n \n for i in range(0, len(s), 2): # Iterate over even indices\n if s[i] in uppercase_vowels:\n count += 1\n \n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n \"\"\"Add two numbers x and y.\n \n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n \"\"\"\n return x + y", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n \n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n \"\"\"\n return [x for x in l if x > 0]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n even_indices = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indexed elements\n even_indices.sort()\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Place the sorted even indexed elements back into their positions\n for i, value in enumerate(even_indices):\n result[i * 2] = value\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n >>> closest_integer(\"14.5\")\n 15\n >>> closest_integer(\"-14.5\")\n -15\n >>> closest_integer(\"0.5\")\n 1\n >>> closest_integer(\"-0.5\")\n -1\n '''\n # Convert the string to a float\n num = float(value)\n \n # Get the floor and ceiling of the number\n lower = int(num // 1)\n upper = lower + 1\n \n # Check if the number is equidistant from lower and upper\n if num - lower == 0.5:\n return upper # Round away from zero\n elif lower - num == 0.5:\n return lower # Round away from zero\n else:\n return round(num) # Regular rounding", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["-15.5"]], "plus_fail_tests": [["-6.5"]]}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n \"\"\"Return True if all numbers in the list l are below threshold t.\n \n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n \"\"\"\n return all(x < t for x in l)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n \"\"\"Return n-th Fibonacci number.\n \n The Fibonacci sequence is defined as follows:\n fib(0) = 0, fib(1) = 1, and fib(n) = fib(n-1) + fib(n-2) for n > 1.\n \n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n \"\"\"\n if n < 0:\n raise ValueError(\"Input should be a non-negative integer.\")\n elif n == 0:\n return 0\n elif n == 1:\n return 1\n else:\n a, b = 0, 1\n for _ in range(2, n + 1):\n a, b = b, a + b\n return b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n \n Args:\n n (int): The index of the FibFib number to compute.\n \n Returns:\n int: The n-th FibFib number.\n \n Examples:\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 1\n \n # Initialize the first three FibFib numbers\n fibfib_numbers = [0, 0, 1]\n \n # Compute FibFib numbers iteratively\n for i in range(3, n + 1):\n next_fibfib = fibfib_numbers[i - 1] + fibfib_numbers[i - 2] + fibfib_numbers[i - 3]\n fibfib_numbers.append(next_fibfib)\n \n return fibfib_numbers[n]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef fibonacci(n: int) -> int:\n \"\"\"Return the n-th Fibonacci number.\"\"\"\n a, b = 0, 1\n for _ in range(n):\n a, b = b, a + b\n return a\ndef prime_fib(n: int) -> int:\n \"\"\"\n prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n count = 0\n i = 0\n while True:\n fib_num = fibonacci(i)\n if is_prime(fib_num):\n count += 1\n if count == n:\n return fib_num\n i += 1", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[12]]}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.\n \"\"\"\n # Get the unit digit of the first number\n unit_digit_a = abs(a) % 10\n # Get the unit digit of the second number\n unit_digit_b = abs(b) % 10\n # Return the product of the unit digits\n return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Sort the unique elements\n sorted_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_elements[1]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = 0\n s = s.lower() # Convert to lowercase to handle case insensitivity\n\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1: # Check if 'y' is at the end\n count += 1\n\n return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef words_in_sentence(sentence):\n \"\"\"\n You are given a string representing a sentence,\n the sentence contains some words separated by a space,\n and you have to return a string that contains the words from the original sentence,\n whose lengths are prime numbers,\n the order of the words in the new string should be the same as the original one.\n\n Example 1:\n Input: sentence = \"This is a test\"\n Output: \"is\"\n\n Example 2:\n Input: sentence = \"lets go for swimming\"\n Output: \"go for\"\n\n Constraints:\n * 1 <= len(sentence) <= 100\n * sentence contains only letters\n \"\"\"\n words = sentence.split()\n prime_length_words = [word for word in words if is_prime(len(word))]\n return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n \"\"\"Simplifies the expression x * n and checks if the result is a whole number.\n \n Args:\n x (str): A string representation of a fraction in the format 'numerator/denominator'.\n n (str): A string representation of a fraction in the format 'numerator/denominator'.\n \n Returns:\n bool: True if x * n evaluates to a whole number, False otherwise.\n \"\"\"\n # Split the fractions into numerator and denominator\n x_numerator, x_denominator = map(int, x.split('/'))\n n_numerator, n_denominator = map(int, n.split('/'))\n \n # Calculate the product of the fractions\n # x * n = (x_numerator / x_denominator) * (n_numerator / n_denominator)\n # This simplifies to (x_numerator * n_numerator) / (x_denominator * n_denominator)\n numerator_product = x_numerator * n_numerator\n denominator_product = x_denominator * n_denominator\n \n # Check if the result is a whole number\n return numerator_product % denominator_product == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n \"\"\"In this problem, you will implement a function that takes two lists of numbers,\n and determines whether it is possible to perform an exchange of elements\n between them to make lst1 a list of only even numbers.\n There is no limit on the number of exchanged elements between lst1 and lst2.\n If it is possible to exchange elements between the lst1 and lst2 to make\n all the elements of lst1 to be even, return \"YES\".\n Otherwise, return \"NO\".\n For example:\n exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"YES\"\n exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n It is assumed that the input lists will be non-empty.\n \"\"\"\n \n # Check if all elements in lst1 are even\n if all(x % 2 == 0 for x in lst1):\n return \"YES\"\n \n # Count the number of odd elements in lst1\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n \n # Count the number of even elements in lst2\n even_count_lst2 = sum(1 for x in lst2 if x % 2 == 0)\n \n # If there are enough even numbers in lst2 to replace all odd numbers in lst1\n if odd_count_lst1 <= even_count_lst2:\n return \"YES\"\n \n return \"NO\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n if not arr:\n return None\n\n product_of_signs = 1\n sum_of_magnitudes = 0\n\n for num in arr:\n if num > 0:\n sum_of_magnitudes += num\n elif num < 0:\n sum_of_magnitudes += -num\n product_of_signs *= -1\n else: # num == 0\n return 0 # If there's a zero, the product of signs is zero\n\n return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n \n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n \"\"\"\n return ' '.join(str(i) for i in range(n + 1))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n \"\"\"Given a string s and a natural number n, returns a list of all words from \n string s that contain exactly n consonants, in the order they appear in the string s.\n \n Args:\n s (str): The input string containing words.\n n (int): The number of consonants to filter words by.\n \n Returns:\n list: A list of words containing exactly n consonants.\n \"\"\"\n if not s:\n return []\n\n # Define a set of consonants\n consonants = set(\"bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ\")\n \n # Split the string into words\n words = s.split()\n \n # Function to count consonants in a word\n def count_consonants(word):\n return sum(1 for char in word if char in consonants)\n \n # Filter words that have exactly n consonants\n result = [word for word in words if count_consonants(word) == n]\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0: # More closing than opening\n return False\n return balance == 0 # Must be balanced at the end\n\n # Check both concatenation orders\n return 'Yes' if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]) else 'No'", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n '''\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return False. Assume no negative numbers and only integers.\n\n Examples\n is_sorted([5]) \u279e True\n is_sorted([1, 2, 3, 4, 5]) \u279e True\n is_sorted([1, 3, 2, 4, 5]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n '''\n if not lst: # An empty list is considered sorted\n return True\n \n seen = set()\n last = None\n \n for num in lst:\n if num in seen:\n return False # Found a duplicate\n seen.add(num)\n \n if last is not None and num < last:\n return False # Not sorted\n last = num\n \n return True", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": [[[1, 1, 2, 2, 3, 3, 4]]]}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n \"\"\"\n Write a function which sorts the given list of integers\n in ascending order according to the sum of their digits.\n Note: if there are several items with similar sum of their digits,\n order them based on their index in original list.\n\n For example:\n >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n >>> order_by_points([]) == []\n \"\"\"\n \n def digit_sum(n):\n \"\"\"Calculate the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(abs(n)))\n\n # Sort the list based on the sum of digits and original index\n return sorted(nums, key=lambda x: (digit_sum(x), nums.index(x)))", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": [[[-5, -12, 9, 15]]]}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n \"\"\"\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n \n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126\n \"\"\"\n total = 0\n for index, value in enumerate(lst):\n if index % 3 == 0:\n total += value ** 2 # Square if index is a multiple of 3\n elif index % 4 == 0:\n total += value ** 3 # Cube if index is a multiple of 4 and not a multiple of 3\n else:\n total += value # Leave unchanged if not a multiple of 3 or 4\n return total", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n two consonants from the right side of the word (case sensitive).\n \n Vowels in the beginning and ending don't count. Return empty string if you didn't\n find any vowel that meets the above condition. \n\n You may assume that the given string contains English letters only.\n\n Example:\n get_closest_vowel(\"yogurt\") ==> \"u\"\n get_closest_vowel(\"FULL\") ==> \"U\"\n get_closest_vowel(\"quick\") ==> \"\"\n get_closest_vowel(\"ab\") ==> \"\"\n \"\"\"\n vowels = \"aeiouAEIOU\"\n n = len(word)\n\n # Start from the end of the word\n for i in range(n - 2, 0, -1): # Start from the second last character\n if word[i] in vowels: # Check if the character is a vowel\n # Check if the characters before and after are consonants\n if word[i - 1].isalpha() and word[i + 1].isalpha() and \\\n word[i - 1] not in vowels and word[i + 1] not in vowels:\n return word[i] # Return the vowel if conditions are met\n\n return \"\" # Return empty string if no vowel is found", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef intersection(interval1, interval2):\n \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n start1, end1 = interval1\n start2, end2 = interval2\n \n # Find the intersection\n start_intersection = max(start1, start2)\n end_intersection = min(end1, end2)\n \n # Check if there is an intersection\n if start_intersection > end_intersection:\n return \"NO\"\n \n # Calculate the length of the intersection\n length_of_intersection = end_intersection - start_intersection\n \n # Check if the length is a prime number\n if is_prime(length_of_intersection):\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Get the top k elements\n top_k = sorted_arr[:k]\n # Sort the result in ascending order before returning\n return sorted(top_k)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n \"\"\"\n if not test:\n return {}\n\n # Split the input string into a list of letters\n letters = test.split()\n \n # Create a dictionary to count occurrences of each letter\n count_dict = {}\n for letter in letters:\n if letter in count_dict:\n count_dict[letter] += 1\n else:\n count_dict[letter] = 1\n\n # Find the maximum count\n max_count = max(count_dict.values())\n \n # Create a result dictionary for letters with the maximum count\n result = {letter: count for letter, count in count_dict.items() if count == max_count}\n \n return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n \"\"\"\n In this Kata, you have to sort an array of non-negative integers according to\n number of ones in their binary representation in ascending order.\n For similar number of ones, sort based on decimal value.\n\n It must be implemented like this:\n >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n >>> sort_array([1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]\n \"\"\"\n # Sort the array using a custom key\n return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n from collections import deque\n\n N = len(grid)\n directions = [(0, 1), (1, 0), (0, -1), (-1, 0)] # Right, Down, Left, Up\n min_path = None\n\n def dfs(x, y, path):\n nonlocal min_path\n if len(path) == k:\n if min_path is None or path < min_path:\n min_path = path[:]\n return\n \n for dx, dy in directions:\n nx, ny = x + dx, y + dy\n if 0 <= nx < N and 0 <= ny < N:\n path.append(grid[nx][ny])\n dfs(nx, ny, path)\n path.pop()\n\n for i in range(N):\n for j in range(N):\n dfs(i, j, [grid[i][j]])\n\n return min_path", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": [[[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 15]]}]}} \ No newline at end of file diff --git a/examples/ags/benchmark/humaneval.py b/examples/ags/benchmark/humaneval.py index 5a8cef297..638a64021 100644 --- a/examples/ags/benchmark/humaneval.py +++ b/examples/ags/benchmark/humaneval.py @@ -28,8 +28,9 @@ async def sample_generate(id, result_path:str="samples.jsonl",mode:str="ags"): solution_result = await solver.alpha_codium(case['task_id'], case['prompt'], ensemble_count=5) sample_dict = dict(task_id=case['task_id'], solution=solution_result['final_solution']) elif mode == "llm": - solution_result = await generate_code_block(case['prompt']) + solution_result = await generate_code_block(case['prompt'],case['entry_point']) sample_dict = dict(task_id=case['task_id'], solution=solution_result['code_solution']) + print(sample_dict) with open(result_path, mode='a') as f: f.write(json.dumps(sample_dict) + '\n') jsonl_ranker(result_path, result_path) diff --git a/examples/ags/w_action_node/graph.py b/examples/ags/w_action_node/graph.py index fe9a91ce9..7bd32bdc9 100644 --- a/examples/ags/w_action_node/graph.py +++ b/examples/ags/w_action_node/graph.py @@ -62,6 +62,7 @@ class HumanEvalGraph(Graph): except Exception as e: print(e) solution = await self.mdensemble("code", solution_list, problem) + print("here",solution) solution = await self.tester(problem, rephrase_problem, solution, test_cases) return solution diff --git a/examples/ags/w_action_node/operator.py b/examples/ags/w_action_node/operator.py index ef6c0fb53..f7cf9b4b5 100644 --- a/examples/ags/w_action_node/operator.py +++ b/examples/ags/w_action_node/operator.py @@ -332,6 +332,8 @@ class Test(Operator): except AssertionError as e: fail_case.append(self.test_cases_2_assert(test_case)) except Exception as e: + with open("tester.txt", "a") as f: + f.write(test_case[0] + "\n") print(e) return {"error":e} if fail_case != []: diff --git a/examples/ags/w_action_node/prompt.py b/examples/ags/w_action_node/prompt.py index 6e41b4280..1ed40bfbb 100644 --- a/examples/ags/w_action_node/prompt.py +++ b/examples/ags/w_action_node/prompt.py @@ -55,9 +55,22 @@ You are given a code contest problem, and a self-reflection on the problem: The above is an incomplete Python code fragment and reflection on it. Return the complete and correct code with no additional text. """ -GENERATE_CODEBLOCK_PROMPT = """ -Please provide a self-contained Python script that solves the following problem in a markdown code block: +# GENERATE_CODEBLOCK_PROMPT = """ +# Please provide a self-contained Python script that solves the following problem in a markdown code block: +# {problem_description} +# """ + +GENERATE_CODEBLOCK_PROMPT =""" +Please provide a self-contained Python script that solves the following problem in a markdown code block: + {problem_description} + +When creating your solution: +1. Consider all edge cases and boundary conditions. +2. Consider the order of operations in your solution and how each step affects subsequent steps. +3. Avoid oversimplification - address all aspects of the problem. +4. Ensure your logic covers all stated requirements. +5. Avoid adding additional test cases beyond those provided in the problem description. """ REVIEW_PROMPT = """ diff --git a/examples/ags/w_action_node/utils.py b/examples/ags/w_action_node/utils.py index 6380c7bd5..df757ba73 100644 --- a/examples/ags/w_action_node/utils.py +++ b/examples/ags/w_action_node/utils.py @@ -159,6 +159,7 @@ async def llm_extract_test_case(id, problem_description: str, file_path:str="pub import json def test_cases_2_test_functions(solution: str, test_case: List): + print("here",solution) function_name = test_case[0] def format_param(param): @@ -181,6 +182,7 @@ def test_cases_2_test_functions(solution: str, test_case: List): print(type(test_case[2]), test_case[2]) expected_output = format_param(test_case[2]) print(expected_output) + tester_function = f""" {solution} diff --git a/he_test.py b/he_test.py index 3b348ca02..567e592e3 100644 --- a/he_test.py +++ b/he_test.py @@ -6,9 +6,14 @@ from examples.ags.benchmark.humaneval import sample_generate, samples_generate, from examples.ags.w_action_node.utils import jsonl_ranker, llm_extract_test_case from examples.ags.w_action_node.graph import HumanEvalGraph # 132 141 136 80 73 -# asyncio.run(sample_generate('HumanEval/118',result_path="llm_based_8.jsonl",mode="llm")) -asyncio.run(samples_generate(mode='llm',result_path="llm_based_100.jsonl")) -# jsonl_ranker("samples.jsonl", "samples.jsonl") +# asyncio.run(sample_generate('HumanEval/140',result_path="llm_based_1000.jsonl",mode="llm")) +# asyncio.run(sample_generate('HumanEval/140',result_path="llm_based_1000.jsonl",mode="llm")) +# asyncio.run(sample_generate('HumanEval/140',result_path="llm_based_1000.jsonl",mode="llm")) +# asyncio.run(sample_generate('HumanEval/67',result_path="llm_based_1000.jsonl",mode="llm")) +# asyncio.run(sample_generate('HumanEval/108',result_path="llm_based_1000.jsonl",mode="llm")) +# asyncio.run(sample_generate('HumanEval/110',result_path="llm_based_1000.jsonl",mode="llm")) +# asyncio.run(samples_generate(mode='alpha',result_path="alpha_based_100.jsonl")) +# jsonl_ranker("llm_based_137.jsonl", "llm_based_137.jsonl") # result_path = "ags_based_6.jsonl" # if automatic_evalplus(result_path): @@ -41,6 +46,7 @@ asyncio.run(samples_generate(mode='llm',result_path="llm_based_100.jsonl")) # [72, 80, 82, 87, 90, 95, 107, 109, 112, 124, 126, 127, 128, 132, 134, 136, 137, 138, 148, 154, 155] -# case_prompt= get_human_eval_plus()["HumanEval/136"]['prompt'] -# solver = HumanEvalGraph(name="solver", llm=LLM(), criteria='correctness, efficiency, readability', vote_count=1) -# result = asyncio.run(solver.alpha_codium(problem_id="HumanEval/136", problem=case_prompt, ensemble_count=1)) \ No newline at end of file +# TODO 代码问题，改动了一个地方导致Solution 没有了 +case_prompt= get_human_eval_plus()["HumanEval/76"]['prompt'] +solver = HumanEvalGraph(name="solver", llm=LLM(), criteria='correctness, efficiency, readability', vote_count=1) +result = asyncio.run(solver.alpha_codium(problem_id="HumanEval/136", problem=case_prompt, ensemble_count=1)) \ No newline at end of file diff --git a/humaneval_analysis.ipynb b/humaneval_analysis.ipynb new file mode 100644 index 000000000..fcbde3a9f --- /dev/null +++ b/humaneval_analysis.ipynb @@ -0,0 +1,715 @@ +{ + "cells": [ + { + "cell_type": "code", + "execution_count": 1, + "metadata": {}, + "outputs": [ + { + "name": "stderr", + "output_type": "stream", + "text": [ + "2024-07-25 16:45:31.369 | INFO | metagpt.const:get_metagpt_package_root:29 - Package root set to /Users/trl/Github_project/MetaGPT-MathAI\n" + ] + }, + { + "name": "stdout", + "output_type": "stream", + "text": [ + "22\n", + "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/40'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/67'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n", + "20\n", + "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/40'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/67'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/163'}]\n", + "24\n", + "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/40'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/67'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/89'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/163'}]\n", + "23\n", + "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/40'}, {'task_id': 'HumanEval/64'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/67'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/109'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n", + "22\n", + "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/40'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/67'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/135'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/163'}]\n" + ] + } + ], + "source": [ + "from examples.ags.benchmark.humaneval import extract_failure_tests\n", + "\n", + "file_path_list = [\"llm_based_120_eval_results.json\", \"llm_based_121_eval_results.json\", \"llm_based_122_eval_results.json\", \"llm_based_123_eval_results.json\", \"llm_based_124_eval_results.json\"]\n", + "\n", + "for file_path in file_path_list:\n", + " unpassed_exapmle = extract_failure_tests(file_path)\n", + " print(unpassed_exapmle)" + ] + }, + { + "cell_type": "code", + "execution_count": 2, + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "17\n", + "[{'task_id': 'HumanEval/163'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/129'}]\n", + "20\n", + "[{'task_id': 'HumanEval/163'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/67'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/135'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/129'}]\n", + "17\n", + "[{'task_id': 'HumanEval/163'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/83'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/129'}]\n", + "18\n", + "[{'task_id': 'HumanEval/163'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/83'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/129'}]\n", + "18\n", + "[{'task_id': 'HumanEval/163'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/99'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/129'}]\n" + ] + } + ], + "source": [ + "\n", + "\n", + "from examples.ags.benchmark.humaneval import extract_failure_tests\n", + "\n", + "file_path_list = [\"EVALPLUS-4omini/1.json\", \"EVALPLUS-4omini/2.json\", \"EVALPLUS-4omini/3.json\", \"EVALPLUS-4omini/4.json\", \"EVALPLUS-4omini/5.json\"]\n", + "\n", + "for file_path in file_path_list:\n", + " unpassed_exapmle = extract_failure_tests(file_path)\n", + " print(unpassed_exapmle)" + ] + }, + { + "cell_type": "code", + "execution_count": 13, + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "20\n", + "[{'task_id': 'HumanEval/16'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n", + "23\n", + "[{'task_id': 'HumanEval/16'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/33'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/67'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/116'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n", + "20\n", + "[{'task_id': 'HumanEval/16'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/67'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/116'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n", + "22\n", + "[{'task_id': 'HumanEval/16'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/67'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/116'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n", + "23\n", + "[{'task_id': 'HumanEval/16'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/33'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/67'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/116'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n" + ] + } + ], + "source": [ + "from examples.ags.benchmark.humaneval import extract_failure_tests\n", + "\n", + "file_path_list = [\"llm_based_125_eval_results.json\", \"llm_based_126_eval_results.json\", \"llm_based_127_eval_results.json\", \"llm_based_128_eval_results.json\", \"llm_based_129_eval_results.json\"]\n", + "\n", + "for file_path in file_path_list:\n", + " unpassed_exapmle = extract_failure_tests(file_path)\n", + " print(unpassed_exapmle)" + ] + }, + { + "cell_type": "code", + "execution_count": 15, + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "21\n", + "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/83'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/116'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n", + "22\n", + "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/33'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n", + "21\n", + "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/33'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n", + "20\n", + "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/33'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/163'}]\n", + "22\n", + "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/83'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n" + ] + } + ], + "source": [ + "from examples.ags.benchmark.humaneval import extract_failure_tests\n", + "\n", + "file_path_list = [\"llm_based_135_eval_results.json\", \"llm_based_136_eval_results.json\", \"llm_based_137_eval_results.json\", \"llm_based_138_eval_results.json\", \"llm_based_139_eval_results.json\"]\n", + "\n", + "for file_path in file_path_list:\n", + " unpassed_exapmle = extract_failure_tests(file_path)\n", + " print(unpassed_exapmle)" + ] + }, + { + "cell_type": "code", + "execution_count": 11, + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "\n", + "def fruit_distribution(s,n):\n", + " \"\"\"\n", + " In this task, you will be given a string that represents a number of apples and oranges \n", + " that are distributed in a basket of fruit this basket contains \n", + " apples, oranges, and mango fruits. Given the string that represents the total number of \n", + " the oranges and apples and an integer that represent the total number of the fruits \n", + " in the basket return the number of the mango fruits in the basket.\n", + " for examble:\n", + " fruit_distribution(\"5 apples and 6 oranges\", 19) ->19 - 5 - 6 = 8\n", + " fruit_distribution(\"0 apples and 1 oranges\",3) -> 3 - 0 - 1 = 2\n", + " fruit_distribution(\"2 apples and 3 oranges\", 100) -> 100 - 2 - 3 = 95\n", + " fruit_distribution(\"100 apples and 1 oranges\",120) -> 120 - 100 - 1 = 19\n", + " \"\"\"\n", + "\n", + "def fruit_distribution(s, n):\n", + " \"\"\"\n", + " In this task, you will be given a string that represents a number of apples and oranges \n", + " that are distributed in a basket of fruit. This basket contains \n", + " apples, oranges, and mango fruits. Given the string that represents the total number of \n", + " the oranges and apples and an integer that represents the total number of the fruits \n", + " in the basket, return the number of the mango fruits in the basket.\n", + " \n", + " Parameters:\n", + " s (str): A string representing the number of apples and oranges.\n", + " n (int): An integer representing the total number of fruits in the basket.\n", + " \n", + " Returns:\n", + " int: The number of mango fruits in the basket.\n", + " \n", + " Examples:\n", + " fruit_distribution(\"5 apples and 6 oranges\", 19) -> 8\n", + " fruit_distribution(\"0 apples and 1 oranges\", 3) -> 2\n", + " fruit_distribution(\"2 apples and 3 oranges\", 100) -> 95\n", + " fruit_distribution(\"100 apples and 1 oranges\", 120) -> 19\n", + " \"\"\"\n", + " \n", + " # Extract the number of apples and oranges from the string\n", + " parts = s.split()\n", + " apples = int(parts[0]) # First part is the number of apples\n", + " oranges = int(parts[2]) # Third part is the number of oranges\n", + " \n", + " # Calculate the number of mangoes\n", + " mangoes = n - apples - oranges\n", + " \n", + " return mangoes\n", + "--------------------------\n", + "def fruit_distribution(s, n):\n", + " \"\"\"\n", + " In this task, you will be given a string that represents a number of apples and oranges \n", + " that are distributed in a basket of fruit. This basket contains \n", + " apples, oranges, and mango fruits. Given the string that represents the total number of \n", + " the oranges and apples and an integer that represents the total number of the fruits \n", + " in the basket, return the number of the mango fruits in the basket.\n", + " \n", + " Parameters:\n", + " s (str): A string representing the number of apples and oranges.\n", + " n (int): An integer representing the total number of fruits in the basket.\n", + " \n", + " Returns:\n", + " int: The number of mango fruits in the basket.\n", + " \n", + " Examples:\n", + " fruit_distribution(\"5 apples and 6 oranges\", 19) -> 8\n", + " fruit_distribution(\"0 apples and 1 oranges\", 3) -> 2\n", + " fruit_distribution(\"2 apples and 3 oranges\", 100) -> 95\n", + " fruit_distribution(\"100 apples and 1 oranges\", 120) -> 19\n", + " \"\"\"\n", + " \n", + " # Extract the number of apples and oranges from the string\n", + " parts = s.split()\n", + " apples = int(parts[0]) # First part is the number of apples\n", + " oranges = int(parts[3]) # Fourth part is the number of oranges\n", + " \n", + " # Calculate the number of mangoes\n", + " mangoes = n - apples - oranges\n", + " \n", + " return mangoes\n", + "--------------------------\n", + "def fruit_distribution(s, n):\n", + " \"\"\"\n", + " Calculate the number of mango fruits in a basket given the number of apples and oranges.\n", + "\n", + " Parameters:\n", + " s (str): A string representing the number of apples and oranges in the format \"X apples and Y oranges\".\n", + " n (int): An integer representing the total number of fruits in the basket.\n", + "\n", + " Returns:\n", + " int: The number of mango fruits in the basket.\n", + " \"\"\"\n", + " # Split the input string to extract the number of apples and oranges\n", + " parts = s.split(\" and \")\n", + " apples = int(parts[0].split()[0]) # Get the number of apples\n", + " oranges = int(parts[1].split()[0]) # Get the number of oranges\n", + "\n", + " # Calculate the number of mangoes\n", + " mangoes = n - apples - oranges\n", + "\n", + " return mangoes\n" + ] + } + ], + "source": [ + "from evalplus.data import get_human_eval_plus\n", + "\n", + "humaneval = get_human_eval_plus()\n", + "print(humaneval['HumanEval/67'][\"prompt\"])\n", + "\n", + "result = {\"solution\": \"def fruit_distribution(s, n):\\n \\\"\\\"\\\"\\n In this task, you will be given a string that represents a number of apples and oranges \\n that are distributed in a basket of fruit. This basket contains \\n apples, oranges, and mango fruits. Given the string that represents the total number of \\n the oranges and apples and an integer that represents the total number of the fruits \\n in the basket, return the number of the mango fruits in the basket.\\n \\n Parameters:\\n s (str): A string representing the number of apples and oranges.\\n n (int): An integer representing the total number of fruits in the basket.\\n \\n Returns:\\n int: The number of mango fruits in the basket.\\n \\n Examples:\\n fruit_distribution(\\\"5 apples and 6 oranges\\\", 19) -> 8\\n fruit_distribution(\\\"0 apples and 1 oranges\\\", 3) -> 2\\n fruit_distribution(\\\"2 apples and 3 oranges\\\", 100) -> 95\\n fruit_distribution(\\\"100 apples and 1 oranges\\\", 120) -> 19\\n \\\"\\\"\\\"\\n \\n # Extract the number of apples and oranges from the string\\n parts = s.split()\\n apples = int(parts[0]) # First part is the number of apples\\n oranges = int(parts[2]) # Third part is the number of oranges\\n \\n # Calculate the number of mangoes\\n mangoes = n - apples - oranges\\n \\n return mangoes\"}\n", + "print(result[\"solution\"])\n", + "\n", + "print(\"--------------------------\")\n", + "\n", + "correct_result = {\"solution\":\"def fruit_distribution(s, n):\\n \\\"\\\"\\\"\\n In this task, you will be given a string that represents a number of apples and oranges \\n that are distributed in a basket of fruit. This basket contains \\n apples, oranges, and mango fruits. Given the string that represents the total number of \\n the oranges and apples and an integer that represents the total number of the fruits \\n in the basket, return the number of the mango fruits in the basket.\\n \\n Parameters:\\n s (str): A string representing the number of apples and oranges.\\n n (int): An integer representing the total number of fruits in the basket.\\n \\n Returns:\\n int: The number of mango fruits in the basket.\\n \\n Examples:\\n fruit_distribution(\\\"5 apples and 6 oranges\\\", 19) -> 8\\n fruit_distribution(\\\"0 apples and 1 oranges\\\", 3) -> 2\\n fruit_distribution(\\\"2 apples and 3 oranges\\\", 100) -> 95\\n fruit_distribution(\\\"100 apples and 1 oranges\\\", 120) -> 19\\n \\\"\\\"\\\"\\n \\n # Extract the number of apples and oranges from the string\\n parts = s.split()\\n apples = int(parts[0]) # First part is the number of apples\\n oranges = int(parts[3]) # Fourth part is the number of oranges\\n \\n # Calculate the number of mangoes\\n mangoes = n - apples - oranges\\n \\n return mangoes\"}\n", + "\n", + "print(correct_result[\"solution\"])\n", + "\n", + "print(\"--------------------------\")\n", + "\n", + "modify_result = {'task_id': 'HumanEval/67', 'solution': 'def fruit_distribution(s, n):\\n \"\"\"\\n Calculate the number of mango fruits in a basket given the number of apples and oranges.\\n\\n Parameters:\\n s (str): A string representing the number of apples and oranges in the format \"X apples and Y oranges\".\\n n (int): An integer representing the total number of fruits in the basket.\\n\\n Returns:\\n int: The number of mango fruits in the basket.\\n \"\"\"\\n # Split the input string to extract the number of apples and oranges\\n parts = s.split(\" and \")\\n apples = int(parts[0].split()[0]) # Get the number of apples\\n oranges = int(parts[1].split()[0]) # Get the number of oranges\\n\\n # Calculate the number of mangoes\\n mangoes = n - apples - oranges\\n\\n return mangoes'}\n", + "\n", + "print(modify_result[\"solution\"])" + ] + }, + { + "cell_type": "code", + "execution_count": 12, + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "\n", + "def count_nums(arr):\n", + " \"\"\"\n", + " Write a function count_nums which takes an array of integers and returns\n", + " the number of elements which has a sum of digits > 0.\n", + " If a number is negative, then its first signed digit will be negative:\n", + " e.g. -123 has signed digits -1, 2, and 3.\n", + " >>> count_nums([]) == 0\n", + " >>> count_nums([-1, 11, -11]) == 1\n", + " >>> count_nums([1, 1, 2]) == 3\n", + " \"\"\"\n", + "\n", + "def count_nums(arr):\n", + " \"\"\"\n", + " Write a function count_nums which takes an array of integers and returns\n", + " the number of elements which has a sum of digits > 0.\n", + " If a number is negative, then its first signed digit will be negative:\n", + " e.g. -123 has signed digits -1, 2, and 3.\n", + " \n", + " >>> count_nums([]) == 0\n", + " >>> count_nums([-1, 11, -11]) == 1\n", + " >>> count_nums([1, 1, 2]) == 3\n", + " \"\"\"\n", + " def sum_of_digits(n):\n", + " # Convert the number to string and calculate the sum of its digits\n", + " return sum(int(digit) if digit != '-' else -int(digit[1]) for digit in str(n) if digit.isdigit() or digit == '-')\n", + "\n", + " count = 0\n", + " for number in arr:\n", + " if sum_of_digits(number) > 0:\n", + " count += 1\n", + " \n", + " return count\n", + "--------------------------\n", + "def count_nums(arr):\n", + " \"\"\"\n", + " Write a function count_nums which takes an array of integers and returns\n", + " the number of elements which has a sum of digits > 0.\n", + " If a number is negative, then its first signed digit will be negative:\n", + " e.g. -123 has signed digits -1, 2, and 3.\n", + " \n", + " >>> count_nums([]) == 0\n", + " >>> count_nums([-1, 11, -11]) == 1\n", + " >>> count_nums([1, 1, 2]) == 3\n", + " \"\"\"\n", + " def sum_of_digits(n):\n", + " # Convert the number to string and calculate the sum of its digits\n", + " # For negative numbers, we need to consider the first digit as negative\n", + " str_n = str(n)\n", + " if n < 0:\n", + " return -int(str_n[1]) + sum(int(digit) for digit in str_n[2:])\n", + " else:\n", + " return sum(int(digit) for digit in str_n)\n", + "\n", + " count = 0\n", + " for num in arr:\n", + " if sum_of_digits(num) > 0:\n", + " count += 1\n", + " \n", + " return count\n", + "--------------------------\n", + "def count_nums(arr):\n", + " \"\"\"\n", + " Write a function count_nums which takes an array of integers and returns\n", + " the number of elements which has a sum of digits > 0.\n", + " If a number is negative, then its first signed digit will be negative:\n", + " e.g. -123 has signed digits -1, 2, and 3.\n", + " \n", + " >>> count_nums([]) == 0\n", + " >>> count_nums([-1, 11, -11]) == 1\n", + " >>> count_nums([1, 1, 2]) == 3\n", + " \"\"\"\n", + " \n", + " def sum_of_digits(n):\n", + " \"\"\"Helper function to calculate the sum of digits of a number.\"\"\"\n", + " # Convert the number to string and iterate over each character\n", + " # If the number is negative, we need to consider the first digit as negative\n", + " str_n = str(n)\n", + " digit_sum = 0\n", + " \n", + " for i, char in enumerate(str_n):\n", + " if char.isdigit():\n", + " digit_sum += int(char)\n", + " elif i == 0 and char == '-':\n", + " digit_sum -= 1 # First signed digit is negative\n", + " \n", + " return digit_sum\n", + "\n", + " count = 0\n", + " for number in arr:\n", + " if sum_of_digits(number) > 0:\n", + " count += 1\n", + " \n", + " return count\n" + ] + } + ], + "source": [ + "from evalplus.data import get_human_eval_plus\n", + "\n", + "humaneval = get_human_eval_plus()\n", + "print(humaneval['HumanEval/108'][\"prompt\"])\n", + "\n", + "result = {\"solution\": \"def count_nums(arr):\\n \\\"\\\"\\\"\\n Write a function count_nums which takes an array of integers and returns\\n the number of elements which has a sum of digits > 0.\\n If a number is negative, then its first signed digit will be negative:\\n e.g. -123 has signed digits -1, 2, and 3.\\n \\n >>> count_nums([]) == 0\\n >>> count_nums([-1, 11, -11]) == 1\\n >>> count_nums([1, 1, 2]) == 3\\n \\\"\\\"\\\"\\n def sum_of_digits(n):\\n # Convert the number to string and calculate the sum of its digits\\n return sum(int(digit) if digit != '-' else -int(digit[1]) for digit in str(n) if digit.isdigit() or digit == '-')\\n\\n count = 0\\n for number in arr:\\n if sum_of_digits(number) > 0:\\n count += 1\\n \\n return count\"}\n", + "print(result[\"solution\"])\n", + "\n", + "print(\"--------------------------\")\n", + "\n", + "correct_result = {\"solution\": \"def count_nums(arr):\\n \\\"\\\"\\\"\\n Write a function count_nums which takes an array of integers and returns\\n the number of elements which has a sum of digits > 0.\\n If a number is negative, then its first signed digit will be negative:\\n e.g. -123 has signed digits -1, 2, and 3.\\n \\n >>> count_nums([]) == 0\\n >>> count_nums([-1, 11, -11]) == 1\\n >>> count_nums([1, 1, 2]) == 3\\n \\\"\\\"\\\"\\n def sum_of_digits(n):\\n # Convert the number to string and calculate the sum of its digits\\n # For negative numbers, we need to consider the first digit as negative\\n str_n = str(n)\\n if n < 0:\\n return -int(str_n[1]) + sum(int(digit) for digit in str_n[2:])\\n else:\\n return sum(int(digit) for digit in str_n)\\n\\n count = 0\\n for num in arr:\\n if sum_of_digits(num) > 0:\\n count += 1\\n \\n return count\"}\n", + "print(correct_result[\"solution\"])\n", + "\n", + "print(\"--------------------------\")\n", + "\n", + "modify_result = {'task_id': 'HumanEval/108', 'solution': 'def count_nums(arr):\\n \"\"\"\\n Write a function count_nums which takes an array of integers and returns\\n the number of elements which has a sum of digits > 0.\\n If a number is negative, then its first signed digit will be negative:\\n e.g. -123 has signed digits -1, 2, and 3.\\n \\n >>> count_nums([]) == 0\\n >>> count_nums([-1, 11, -11]) == 1\\n >>> count_nums([1, 1, 2]) == 3\\n \"\"\"\\n \\n def sum_of_digits(n):\\n \"\"\"Helper function to calculate the sum of digits of a number.\"\"\"\\n # Convert the number to string and iterate over each character\\n # If the number is negative, we need to consider the first digit as negative\\n str_n = str(n)\\n digit_sum = 0\\n \\n for i, char in enumerate(str_n):\\n if char.isdigit():\\n digit_sum += int(char)\\n elif i == 0 and char == \\'-\\':\\n digit_sum -= 1 # First signed digit is negative\\n \\n return digit_sum\\n\\n count = 0\\n for number in arr:\\n if sum_of_digits(number) > 0:\\n count += 1\\n \\n return count'}\n", + "\n", + "print(modify_result[\"solution\"])" + ] + }, + { + "cell_type": "code", + "execution_count": 10, + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "\n", + "def exchange(lst1, lst2):\n", + " \"\"\"In this problem, you will implement a function that takes two lists of numbers,\n", + " and determines whether it is possible to perform an exchange of elements\n", + " between them to make lst1 a list of only even numbers.\n", + " There is no limit on the number of exchanged elements between lst1 and lst2.\n", + " If it is possible to exchange elements between the lst1 and lst2 to make\n", + " all the elements of lst1 to be even, return \"YES\".\n", + " Otherwise, return \"NO\".\n", + " For example:\n", + " exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"YES\"\n", + " exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n", + " It is assumed that the input lists will be non-empty.\n", + " \"\"\"\n", + "\n", + "def exchange(lst1, lst2):\n", + " \"\"\"Determines whether it is possible to perform an exchange of elements\n", + " between two lists to make lst1 a list of only even numbers.\n", + " \n", + " Args:\n", + " lst1 (list): The first list of numbers.\n", + " lst2 (list): The second list of numbers.\n", + " \n", + " Returns:\n", + " str: \"YES\" if lst1 can be made all even, \"NO\" otherwise.\n", + " \"\"\"\n", + " # Check if lst1 already contains only even numbers\n", + " if all(x % 2 == 0 for x in lst1):\n", + " return \"YES\"\n", + " \n", + " # Count the number of odd numbers in lst1\n", + " odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n", + " \n", + " # Check if lst2 has at least one even number to exchange\n", + " has_even_in_lst2 = any(x % 2 == 0 for x in lst2)\n", + " \n", + " # If lst1 has odd numbers and lst2 has at least one even number, we can exchange\n", + " if odd_count_lst1 > 0 and has_even_in_lst2:\n", + " return \"YES\"\n", + " \n", + " return \"NO\"\n", + "--------------------------\n", + "def exchange(lst1, lst2):\n", + " \"\"\"In this problem, you will implement a function that takes two lists of numbers,\n", + " and determines whether it is possible to perform an exchange of elements\n", + " between them to make lst1 a list of only even numbers.\n", + " There is no limit on the number of exchanged elements between lst1 and lst2.\n", + " If it is possible to exchange elements between the lst1 and lst2 to make\n", + " all the elements of lst1 to be even, return \"YES\".\n", + " Otherwise, return \"NO\".\n", + " For example:\n", + " exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"YES\"\n", + " exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n", + " It is assumed that the input lists will be non-empty.\n", + " \"\"\"\n", + " \n", + " # Count the number of odd numbers in lst1\n", + " odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n", + " \n", + " # Count the number of even numbers in lst2\n", + " even_count_lst2 = sum(1 for x in lst2 if x % 2 == 0)\n", + " \n", + " # If there are no odd numbers in lst1, it's already valid\n", + " if odd_count_lst1 == 0:\n", + " return \"YES\"\n", + " \n", + " # If there are enough even numbers in lst2 to replace all odd numbers in lst1\n", + " if even_count_lst2 >= odd_count_lst1:\n", + " return \"YES\"\n", + " \n", + " return \"NO\"\n" + ] + } + ], + "source": [ + "from evalplus.data import get_human_eval_plus\n", + "\n", + "humaneval = get_human_eval_plus()\n", + "print(humaneval['HumanEval/110'][\"prompt\"])\n", + "\n", + "result = {\"solution\": \"def exchange(lst1, lst2):\\n \\\"\\\"\\\"Determines whether it is possible to perform an exchange of elements\\n between two lists to make lst1 a list of only even numbers.\\n \\n Args:\\n lst1 (list): The first list of numbers.\\n lst2 (list): The second list of numbers.\\n \\n Returns:\\n str: \\\"YES\\\" if lst1 can be made all even, \\\"NO\\\" otherwise.\\n \\\"\\\"\\\"\\n # Check if lst1 already contains only even numbers\\n if all(x % 2 == 0 for x in lst1):\\n return \\\"YES\\\"\\n \\n # Count the number of odd numbers in lst1\\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\\n \\n # Check if lst2 has at least one even number to exchange\\n has_even_in_lst2 = any(x % 2 == 0 for x in lst2)\\n \\n # If lst1 has odd numbers and lst2 has at least one even number, we can exchange\\n if odd_count_lst1 > 0 and has_even_in_lst2:\\n return \\\"YES\\\"\\n \\n return \\\"NO\\\"\"}\n", + "print(result[\"solution\"])\n", + "\n", + "print(\"--------------------------\")\n", + "\n", + "correct_result = {\"solution\": \"def exchange(lst1, lst2):\\n \\\"\\\"\\\"In this problem, you will implement a function that takes two lists of numbers,\\n and determines whether it is possible to perform an exchange of elements\\n between them to make lst1 a list of only even numbers.\\n There is no limit on the number of exchanged elements between lst1 and lst2.\\n If it is possible to exchange elements between the lst1 and lst2 to make\\n all the elements of lst1 to be even, return \\\"YES\\\".\\n Otherwise, return \\\"NO\\\".\\n For example:\\n exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \\\"YES\\\"\\n exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \\\"NO\\\"\\n It is assumed that the input lists will be non-empty.\\n \\\"\\\"\\\"\\n \\n # Count the number of odd numbers in lst1\\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\\n \\n # Count the number of even numbers in lst2\\n even_count_lst2 = sum(1 for x in lst2 if x % 2 == 0)\\n \\n # If there are no odd numbers in lst1, it's already valid\\n if odd_count_lst1 == 0:\\n return \\\"YES\\\"\\n \\n # If there are enough even numbers in lst2 to replace all odd numbers in lst1\\n if even_count_lst2 >= odd_count_lst1:\\n return \\\"YES\\\"\\n \\n return \\\"NO\\\"\"}\n", + "print(correct_result[\"solution\"])" + ] + }, + { + "cell_type": "code", + "execution_count": 14, + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "\n", + "\n", + "def count_distinct_characters(string: str) -> int:\n", + " \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n", + " >>> count_distinct_characters('xyzXYZ')\n", + " 3\n", + " >>> count_distinct_characters('Jerry')\n", + " 4\n", + " \"\"\"\n", + "\n", + "def count_distinct_characters(string: str) -> int:\n", + " \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n", + " >>> count_distinct_characters('xyzXYZ')\n", + " 3\n", + " >>> count_distinct_characters('Jerry')\n", + " 4\n", + " \"\"\"\n", + " # Convert the string to lowercase to ensure case insensitivity\n", + " lower_string = string.lower()\n", + " # Use a set to find distinct characters\n", + " distinct_characters = set(lower_string)\n", + " # Return the number of distinct characters\n", + " return len(distinct_characters)\n", + "--------------------------\n", + "def count_distinct_characters(string: str) -> int:\n", + " \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n", + " >>> count_distinct_characters('xyzXYZ')\n", + " 3\n", + " >>> count_distinct_characters('Jerry')\n", + " 4\n", + " \"\"\"\n", + " # Convert the string to lowercase to ensure case insensitivity\n", + " lower_string = string.lower()\n", + " # Use a set to find distinct characters\n", + " distinct_characters = set(lower_string)\n", + " # Return the number of distinct characters\n", + " return len(distinct_characters)\n", + "--------------------------\n", + "def count_distinct_characters(string: str) -> int:\n", + " \"\"\" \n", + " Given a string, find out how many distinct characters (regardless of case) does it consist of.\n", + " \n", + " >>> count_distinct_characters('xyzXYZ')\n", + " 3\n", + " >>> count_distinct_characters('Jerry')\n", + " 4\n", + " >>> count_distinct_characters('')\n", + " 0\n", + " >>> count_distinct_characters('aA')\n", + " 1\n", + " >>> count_distinct_characters('123abcABC!@#')\n", + " 9\n", + " >>> count_distinct_characters(' ')\n", + " 0\n", + " >>> count_distinct_characters('!@#$%^&*()')\n", + " 10\n", + " \"\"\"\n", + " # Convert the string to lowercase to ensure case insensitivity\n", + " lower_string = string.lower()\n", + " \n", + " # Use a set to store distinct characters\n", + " distinct_characters = set()\n", + " \n", + " # Iterate through each character in the string\n", + " for char in lower_string:\n", + " # Add only non-space characters to the set\n", + " if char != ' ':\n", + " distinct_characters.add(char)\n", + " \n", + " # Return the number of distinct characters\n", + " return len(distinct_characters)\n" + ] + } + ], + "source": [ + "from evalplus.data import get_human_eval_plus\n", + "\n", + "humaneval = get_human_eval_plus()\n", + "print(humaneval['HumanEval/16'][\"prompt\"])\n", + "\n", + "result = {\"task_id\": \"HumanEval/16\", \"solution\": \"def count_distinct_characters(string: str) -> int:\\n \\\"\\\"\\\" Given a string, find out how many distinct characters (regardless of case) does it consist of\\n >>> count_distinct_characters('xyzXYZ')\\n 3\\n >>> count_distinct_characters('Jerry')\\n 4\\n \\\"\\\"\\\"\\n # Convert the string to lowercase to ensure case insensitivity\\n lower_string = string.lower()\\n # Use a set to find distinct characters\\n distinct_characters = set(lower_string)\\n # Return the number of distinct characters\\n return len(distinct_characters)\"}\n", + "print(result[\"solution\"])\n", + "\n", + "print(\"--------------------------\")\n", + "\n", + "correct_result = {\"task_id\": \"HumanEval/16\", \"solution\": \"def count_distinct_characters(string: str) -> int:\\n \\\"\\\"\\\" Given a string, find out how many distinct characters (regardless of case) does it consist of\\n >>> count_distinct_characters('xyzXYZ')\\n 3\\n >>> count_distinct_characters('Jerry')\\n 4\\n \\\"\\\"\\\"\\n # Convert the string to lowercase to ensure case insensitivity\\n lower_string = string.lower()\\n # Use a set to find distinct characters\\n distinct_characters = set(lower_string)\\n # Return the number of distinct characters\\n return len(distinct_characters)\"}\n", + "\n", + "print(correct_result[\"solution\"])\n", + "\n", + "print(\"--------------------------\")\n", + "\n", + "modify_result = {\"task_id\": \"HumanEval/16\", \"solution\": \"def count_distinct_characters(string: str) -> int:\\n \\\"\\\"\\\" \\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\\n \\n >>> count_distinct_characters('xyzXYZ')\\n 3\\n >>> count_distinct_characters('Jerry')\\n 4\\n >>> count_distinct_characters('')\\n 0\\n >>> count_distinct_characters('aA')\\n 1\\n >>> count_distinct_characters('123abcABC!@#')\\n 9\\n >>> count_distinct_characters(' ')\\n 0\\n >>> count_distinct_characters('!@#$%^&*()')\\n 10\\n \\\"\\\"\\\"\\n # Convert the string to lowercase to ensure case insensitivity\\n lower_string = string.lower()\\n \\n # Use a set to store distinct characters\\n distinct_characters = set()\\n \\n # Iterate through each character in the string\\n for char in lower_string:\\n # Add only non-space characters to the set\\n if char != ' ':\\n distinct_characters.add(char)\\n \\n # Return the number of distinct characters\\n return len(distinct_characters)\"}\n", + "\n", + "print(modify_result[\"solution\"])" + ] + }, + { + "cell_type": "code", + "execution_count": 16, + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "\n", + "def fix_spaces(text):\n", + " \"\"\"\n", + " Given a string text, replace all spaces in it with underscores, \n", + " and if a string has more than 2 consecutive spaces, \n", + " then replace all consecutive spaces with - \n", + " \n", + " fix_spaces(\"Example\") == \"Example\"\n", + " fix_spaces(\"Example 1\") == \"Example_1\"\n", + " fix_spaces(\" Example 2\") == \"_Example_2\"\n", + " fix_spaces(\" Example 3\") == \"_Example-3\"\n", + " \"\"\"\n", + "\n", + "def fix_spaces(text):\n", + " \"\"\"\n", + " Given a string text, replace all spaces in it with underscores, \n", + " and if a string has more than 2 consecutive spaces, \n", + " then replace all consecutive spaces with - \n", + " \n", + " fix_spaces(\"Example\") == \"Example\"\n", + " fix_spaces(\"Example 1\") == \"Example_1\"\n", + " fix_spaces(\" Example 2\") == \"_Example_2\"\n", + " fix_spaces(\" Example 3\") == \"_Example-3\"\n", + " \"\"\"\n", + " # Replace multiple spaces with a placeholder\n", + " # This will help us identify sequences of spaces\n", + " placeholder = '##'\n", + " text = text.replace(' ' * 3, placeholder) # Replace 3 spaces with a placeholder\n", + " \n", + " # Replace remaining spaces with underscores\n", + " text = text.replace(' ', '_')\n", + " \n", + " # Replace the placeholder back to '-'\n", + " text = text.replace(placeholder, '-')\n", + " \n", + " return text\n", + "--------------------------\n", + "def fix_spaces(text):\n", + " \"\"\"\n", + " Given a string text, replace all spaces in it with underscores, \n", + " and if a string has more than 2 consecutive spaces, \n", + " then replace all consecutive spaces with - \n", + " \n", + " fix_spaces(\"Example\") == \"Example\"\n", + " fix_spaces(\"Example 1\") == \"Example_1\"\n", + " fix_spaces(\" Example 2\") == \"_Example_2\"\n", + " fix_spaces(\" Example 3\") == \"_Example-3\"\n", + " \"\"\"\n", + " # Replace multiple spaces with a placeholder\n", + " # This will help us identify sequences of spaces\n", + " placeholder = ' ' * 3 # Three spaces\n", + " text = text.replace(placeholder, ' - ')\n", + " \n", + " # Replace all remaining spaces with underscores\n", + " text = text.replace(' ', '_')\n", + " \n", + " # Replace the placeholder with a single dash\n", + " text = text.replace(' - ', '-')\n", + " \n", + " return text\n" + ] + } + ], + "source": [ + "\n", + "from evalplus.data import get_human_eval_plus\n", + "\n", + "humaneval = get_human_eval_plus()\n", + "print(humaneval['HumanEval/140'][\"prompt\"])\n", + "\n", + "correct_result = {\"task_id\": \"HumanEval/140\", \"solution\": \"def fix_spaces(text):\\n \\\"\\\"\\\"\\n Given a string text, replace all spaces in it with underscores, \\n and if a string has more than 2 consecutive spaces, \\n then replace all consecutive spaces with - \\n \\n fix_spaces(\\\"Example\\\") == \\\"Example\\\"\\n fix_spaces(\\\"Example 1\\\") == \\\"Example_1\\\"\\n fix_spaces(\\\" Example 2\\\") == \\\"_Example_2\\\"\\n fix_spaces(\\\" Example 3\\\") == \\\"_Example-3\\\"\\n \\\"\\\"\\\"\\n # Replace multiple spaces with a placeholder\\n # This will help us identify sequences of spaces\\n placeholder = '##'\\n text = text.replace(' ' * 3, placeholder) # Replace 3 spaces with a placeholder\\n \\n # Replace remaining spaces with underscores\\n text = text.replace(' ', '_')\\n \\n # Replace the placeholder back to '-'\\n text = text.replace(placeholder, '-')\\n \\n return text\"}\n", + "\n", + "print(correct_result[\"solution\"])\n", + "\n", + "print(\"--------------------------\")\n", + "\n", + "modify_result = {\"task_id\": \"HumanEval/140\", \"solution\": \"def fix_spaces(text):\\n \\\"\\\"\\\"\\n Given a string text, replace all spaces in it with underscores, \\n and if a string has more than 2 consecutive spaces, \\n then replace all consecutive spaces with - \\n \\n fix_spaces(\\\"Example\\\") == \\\"Example\\\"\\n fix_spaces(\\\"Example 1\\\") == \\\"Example_1\\\"\\n fix_spaces(\\\" Example 2\\\") == \\\"_Example_2\\\"\\n fix_spaces(\\\" Example 3\\\") == \\\"_Example-3\\\"\\n \\\"\\\"\\\"\\n # Replace multiple spaces with a placeholder\\n # This will help us identify sequences of spaces\\n placeholder = ' ' * 3 # Three spaces\\n text = text.replace(placeholder, ' - ')\\n \\n # Replace all remaining spaces with underscores\\n text = text.replace(' ', '_')\\n \\n # Replace the placeholder with a single dash\\n text = text.replace(' - ', '-')\\n \\n return text\"}\n", + "\n", + "print(modify_result[\"solution\"])" + ] + } + ], + "metadata": { + "kernelspec": { + "display_name": "ags_env", + "language": "python", + "name": "python3" + }, + "language_info": { + "codemirror_mode": { + "name": "ipython", + "version": 3 + }, + "file_extension": ".py", + "mimetype": "text/x-python", + "name": "python", + "nbconvert_exporter": "python", + "pygments_lexer": "ipython3", + "version": "3.9.19" + } + }, + "nbformat": 4, + "nbformat_minor": 2 +} diff --git a/llm_based_120_eval_results.json b/llm_based_120_eval_results.json new file mode 100644 index 000000000..c272a7bd4 --- /dev/null +++ b/llm_based_120_eval_results.json @@ -0,0 +1 @@ +{"date": "2024-07-25 16:37", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to make it easier to find close elements\n numbers.sort()\n \n # Check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" \n Input to this function is a string containing multiple groups of nested parentheses. \n Your goal is to separate those groups into separate strings and return the list of those.\n Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n Ignore any spaces in the input string.\n \n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n # Remove spaces from the input string\n paren_string = paren_string.replace(\" \", \"\")\n \n result = []\n balance = 0\n current_group = []\n \n for char in paren_string:\n if char == '(':\n if balance == 0 and current_group:\n result.append(''.join(current_group))\n current_group = []\n current_group.append(char)\n balance += 1\n elif char == ')':\n current_group.append(char)\n balance -= 1\n if balance == 0:\n result.append(''.join(current_group))\n current_group = []\n \n # In case there are any remaining groups\n if current_group:\n result.append(''.join(current_group))\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into\n an integer part (largest integer smaller than given number) and decimals\n (leftover part always smaller than 1).\n\n Return the decimal part of the number.\n \n >>> truncate_number(3.5)\n 0.5\n >>> truncate_number(2.75)\n 0.75\n >>> truncate_number(5.0)\n 0.0\n >>> truncate_number(0.99)\n 0.99\n \"\"\"\n if number < 0:\n raise ValueError(\"The number must be positive.\")\n \n integer_part = int(number) # Get the integer part\n decimal_part = number - integer_part # Calculate the decimal part\n return decimal_part", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" \n You're given a list of deposit and withdrawal operations on a bank account that starts with\n zero balance. Your task is to detect if at any point the balance of account falls below zero, and\n at that point function should return True. Otherwise it should return False.\n \n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n \"\"\"\n balance = 0\n for operation in operations:\n balance += operation\n if balance < 0:\n return True\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list to avoid division by zero\n\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n \"\"\" Insert a number 'delimiter' between every two consecutive elements of input list `numbers'\n \n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n for i in range(len(numbers)):\n result.append(numbers[i])\n if i < len(numbers) - 1: # Avoid adding delimiter after the last element\n result.append(delimiter)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n \"\"\"\n return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n def max_nesting_depth(s: str) -> int:\n max_depth = 0\n current_depth = 0\n for char in s:\n if char == '(':\n current_depth += 1\n max_depth = max(max_depth, current_depth)\n elif char == ')':\n current_depth -= 1\n return max_depth\n\n groups = paren_string.split()\n return [max_nesting_depth(group) for group in groups]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n result = [max_so_far]\n\n for number in numbers[1:]:\n max_so_far = max(max_so_far, number)\n result.append(max_so_far)\n\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n \n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n \"\"\"\n if not numbers:\n return (0, 1)\n \n total_sum = sum(numbers)\n total_product = 1\n for number in numbers:\n total_product *= number\n \n return (total_sum, total_product)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n \n >>> make_palindrome('')\n ''\n >>> make_palindrome('cat')\n 'catac'\n >>> make_palindrome('cata')\n 'catac'\n \"\"\"\n # If the string is empty, return it as is\n if not string:\n return string\n \n # Find the longest palindromic suffix\n for i in range(len(string)):\n if is_palindrome(string[i:]):\n # If we found a palindromic suffix, take the prefix before it\n prefix = string[:i]\n # Append the reverse of the prefix to the original string\n return string + prefix[::-1]\n \n # If no palindromic suffix is found, the whole string is non-palindromic\n return string + string[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n \"\"\" \n Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n \n >>> string_xor('010', '110')\n '100'\n \"\"\"\n # Ensure both strings are of the same length\n max_len = max(len(a), len(b))\n a = a.zfill(max_len)\n b = b.zfill(max_len)\n \n # Perform XOR operation\n result = []\n for bit_a, bit_b in zip(a, b):\n result.append('1' if bit_a != bit_b else '0')\n \n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n \n >>> longest([])\n >>> None\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n \"\"\"\n if not strings:\n return None\n \n longest_string = strings[0]\n \n for string in strings:\n if len(string) > len(longest_string):\n longest_string = string\n \n return longest_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return the greatest common divisor of two integers a and b.\n \n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n \"\"\"\n while b:\n a, b = b, a % b\n return abs(a)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string\n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n \"\"\"\n return [string[:i] for i in range(1, len(string) + 1)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" \n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n # Use a set to find distinct characters\n distinct_characters = set(lower_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n \n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n \"\"\"\n return ' '.join(str(i) for i in range(n + 1))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" Input to this function is a string representing musical notes in a special ASCII format.\n Your task is to parse this string and return list of integers corresponding to how many beats does each\n note last.\n\n Here is a legend:\n 'o' - whole note, lasts four beats\n 'o|' - half note, lasts two beats\n '.|' - quarter note, lasts one beat\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n # Define a mapping of note representations to their corresponding beat values\n note_to_beats = {\n 'o': 4, # whole note\n 'o|': 2, # half note\n '.|': 1 # quarter note\n }\n \n # Split the input string into individual notes\n notes = music_string.split()\n \n # Parse the notes and convert them to their corresponding beat values\n beats = [note_to_beats[note] for note in notes if note in note_to_beats]\n \n return beats", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n \n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n \"\"\"\n count = 0\n start = 0\n \n while True:\n start = string.find(substring, start)\n if start == -1:\n break\n count += 1\n start += 1 # Move to the next character to allow for overlapping matches\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n \"\"\" \n Input is a space-delimited string of numerals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest.\n \n >>> sort_numbers('three one five')\n 'one three five'\n \"\"\"\n # Mapping of words to their corresponding numeric values\n num_map = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n \n # Split the input string into words\n words = numbers.split()\n \n # Sort the words based on their numeric values\n sorted_words = sorted(words, key=lambda word: num_map[word])\n \n # Join the sorted words back into a string\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to make it easier to find the closest pair\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest elements\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1.\n \n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n min_val = min(numbers)\n max_val = max(numbers)\n \n # Avoid division by zero if all numbers are the same\n if min_val == max_val:\n return [0.0] * len(numbers)\n \n return [(num - min_val) / (max_val - min_val) for num in numbers]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers\n >>> filter_integers(['a', 3.14, 5])\n [5]\n >>> filter_integers([1, 2, 3, 'abc', {}, []])\n [1, 2, 3]\n \"\"\"\n return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n \"\"\" Return length of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n \"\"\"\n return len(string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(10)\n 5\n >>> largest_divisor(1)\n 0\n >>> largest_divisor(28)\n 14\n \"\"\"\n if n <= 1:\n return 0 # No divisors for 1 or less\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n Input number should be equal to the product of all factors\n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n \"\"\"\n factors = []\n # Check for number of 2s that divide n\n while n % 2 == 0:\n factors.append(2)\n n //= 2\n \n # n must be odd at this point so a skip of 2 (i.e., i = i + 2) can be used\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, append i and divide n\n while n % i == 0:\n factors.append(i)\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n factors.append(n)\n \n return factors", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n \n # Create a new list with elements that occur only once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n \n >>> flip_case('Hello')\n 'hELLO'\n >>> flip_case('Python')\n 'pYTHON'\n >>> flip_case('1234!@#')\n '1234!@#'\n >>> flip_case('')\n ''\n \"\"\"\n return string.swapcase()", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string.\n \n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n \"\"\"\n return ''.join(strings)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n \n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n \"\"\"\n return [x for x in l if x > 0]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n \n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n \"\"\"\n return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float) -> float:\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list) -> list:\n \"\"\"\n Returns the coefficients of the derivative of the polynomial.\n \"\"\"\n return [i * coeff for i, coeff in enumerate(xs)][1:]\ndef find_zero(xs: list) -> float:\n \"\"\" \n xs are coefficients of a polynomial.\n find_zero finds x such that poly(x) = 0.\n find_zero returns only one zero point, even if there are many.\n Moreover, find_zero only takes list xs having an even number of coefficients\n and the largest non-zero coefficient as it guarantees a solution.\n \n >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n -0.5\n >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n 1.0\n \"\"\"\n if len(xs) % 2 != 0:\n raise ValueError(\"The number of coefficients must be even.\")\n \n # Initial guess (can be improved)\n x = 0.0\n tolerance = 1e-7\n max_iterations = 1000\n \n for _ in range(max_iterations):\n f_x = poly(xs, x)\n f_prime_x = poly(derivative(xs), x)\n \n if abs(f_x) < tolerance:\n return x\n \n if f_prime_x == 0:\n raise ValueError(\"Derivative is zero. No solution found.\")\n \n x -= f_x / f_prime_x\n \n raise ValueError(\"Exceeded maximum iterations. No solution found.\")", "base_status": "fail", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(divisible_by_three)\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Replace values at indices divisible by 3 with sorted values\n for index, value in zip([i for i in range(len(l)) if i % 3 == 0], sorted_values):\n result[index] = value\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n \"\"\"Return maximum element in the list.\n \n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty.\")\n max_value = l[0]\n for item in l:\n if item > max_value:\n max_value = item\n return max_value", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with encode_cyclic function. Returns decoded string.\n \"\"\"\n # Split string into groups of length 3\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # Reverse the cycling of elements in each group unless the group has fewer than 3 elements\n groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n even_indices = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indexed elements\n even_indices.sort()\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Place the sorted even indexed elements back into their positions\n for i, value in enumerate(even_indices):\n result[i * 2] = value\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef prime_fib(n: int) -> int:\n \"\"\"\n prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n \n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n fib_gen = fibonacci_generator()\n count = 0\n for fib in fib_gen:\n if is_prime(fib):\n count += 1\n if count == n:\n return fib", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1]], "plus_fail_tests": []}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n \"\"\"\n triples_sum_to_zero takes a list of integers as an input.\n it returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n \"\"\"\n n = len(l)\n l = list(set(l)) # Remove duplicates\n n = len(l) # Update length after removing duplicates\n\n for i in range(n):\n seen = set()\n target = -l[i]\n for j in range(i + 1, n):\n if target - l[j] in seen:\n return True\n seen.add(l[j])\n return False", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 3, -2, 1]]], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n \"\"\"\n Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move at the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.\n\n Parameters:\n n (int): The number of cars in each direction.\n\n Returns:\n int: The number of collisions.\n \"\"\"\n # Each car moving left to right will collide with each car moving right to left\n # Therefore, the total number of collisions is n * n\n return n * n", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n \"\"\"\n return [x + 1 for x in l]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n \n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n \"\"\"\n seen = set()\n for number in l:\n if -number in seen:\n return True\n seen.add(number)\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion.\n base numbers are less than 10.\n \n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n \"\"\"\n if base < 2 or base >= 10:\n raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n \n if x == 0:\n return '0'\n \n result = []\n while x > 0:\n result.append(str(x % base))\n x //= base\n \n return ''.join(reversed(result))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n \"\"\"Given length of a side and height, return the area for a triangle.\n \n The area of a triangle can be calculated using the formula:\n area = (base * height) / 2\n \n Args:\n a (float): The length of the base of the triangle.\n h (float): The height of the triangle.\n \n Returns:\n float: The area of the triangle.\n \n Examples:\n >>> triangle_area(5, 3)\n 7.5\n \"\"\"\n return (a * h) / 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fib4(0) -> 0\n fib4(1) -> 0\n fib4(2) -> 2\n fib4(3) -> 0\n fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n \n This function computes the n-th element of the fib4 number sequence without using recursion.\n \n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 2\n elif n == 3:\n return 0\n\n # Initialize the first four values of the sequence\n fib_values = [0, 0, 2, 0]\n \n # Compute the values iteratively\n for i in range(4, n + 1):\n next_value = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n fib_values.append(next_value)\n\n return fib_values[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n \"\"\"Return median of elements in the list l.\n \n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty.\")\n \n sorted_list = sorted(l)\n n = len(sorted_list)\n mid = n // 2\n \n if n % 2 == 0:\n return (sorted_list[mid - 1] + sorted_list[mid]) / 2\n else:\n return sorted_list[mid]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n \"\"\"\n Checks if given string is a palindrome.\n \n A palindrome is a string that reads the same forward and backward.\n \n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n \"\"\"\n # Normalize the string by removing spaces and converting to lowercase\n normalized_text = text.replace(\" \", \"\").lower()\n # Check if the string is equal to its reverse\n return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with encode_shift function. Returns decoded string.\n \"\"\"\n return \"\".join([chr(((ord(ch) - ord(\"a\") - 5) % 26) + ord(\"a\")) for ch in s])", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n \"\"\"Add two numbers x and y.\n \n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n \"\"\"\n return x + y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n \"\"\"Return True if all numbers in the list l are below threshold t.\n \n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n \"\"\"\n return all(x < t for x in l)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n \"\"\"Return n-th Fibonacci number.\n \n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n elif n == 1:\n return 1\n elif n == 2:\n return 1\n else:\n a, b = 1, 1\n for _ in range(2, n):\n a, b = b, a + b\n return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two words have the same characters if they contain the same unique characters,\n regardless of the number of times each character appears.\n \n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"<\" and \">\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"<\")\n False\n >>> correct_bracketing(\"<>\")\n True\n >>> correct_bracketing(\"<<><>>\")\n True\n >>> correct_bracketing(\"><<>\")\n False\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '<':\n balance += 1\n elif char == '>':\n balance -= 1\n # If balance goes negative, there are more closing brackets\n if balance < 0:\n return False\n # At the end, balance should be zero for correct bracketing\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n \"\"\"Return True if list elements are monotonically increasing or decreasing.\n \n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n \"\"\"\n if not l: # An empty list is considered monotonic\n return True\n\n increasing = decreasing = True\n\n for i in range(1, len(l)):\n if l[i] > l[i - 1]:\n decreasing = False\n elif l[i] < l[i - 1]:\n increasing = False\n\n return increasing or decreasing", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n # Keep dividing n by factor until it is no longer divisible\n while n > 1:\n if n % factor == 0:\n n //= factor # Divide n by the factor\n else:\n factor += 1 # Move to the next potential factor\n return factor # The last factor is the largest prime factor", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n \n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n \"\"\"\n return n * (n + 1) // 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"(\" and \")\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"(\")\n False\n >>> correct_bracketing(\"()\")\n True\n >>> correct_bracketing(\"(()())\")\n True\n >>> correct_bracketing(\")(()\")\n False\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n # If balance goes negative, there are unmatched closing brackets\n if balance < 0:\n return False\n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n \"\"\" \n xs represent coefficients of a polynomial.\n xs[0] + xs[1] * x + xs[2] * x^2 + ....\n Return derivative of this polynomial in the same form.\n \n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n \"\"\"\n # The derivative of a polynomial is calculated by multiplying each coefficient\n # by its corresponding power and reducing the power by one.\n return [i * coeff for i, coeff in enumerate(xs[1:], start=1)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n \n Args:\n n (int): The index of the FibFib number to compute.\n \n Returns:\n int: The n-th FibFib number.\n \n Examples:\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 1\n \n # Initialize the first three FibFib numbers\n fibfib_numbers = [0, 0, 1]\n \n # Compute FibFib numbers iteratively\n for i in range(3, n + 1):\n next_fibfib = fibfib_numbers[i - 1] + fibfib_numbers[i - 2] + fibfib_numbers[i - 3]\n fibfib_numbers.append(next_fibfib)\n \n return fibfib_numbers[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set('aeiouAEIOU')\n count = 0\n \n # Check each character in the string\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n # Check if 'y' is at the end of the word\n elif s[i].lower() == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n \n >>> circular_shift(12, 1)\n '21'\n >>> circular_shift(12, 2)\n '12'\n >>> circular_shift(12345, 1)\n '51234'\n >>> circular_shift(12345, 5)\n '54321'\n >>> circular_shift(12345, 6)\n '54321'\n \"\"\"\n # Convert the integer to a string to manipulate its digits\n str_x = str(x)\n num_digits = len(str_x)\n \n # If shift is greater than the number of digits, reverse the string\n if shift >= num_digits:\n return str_x[::-1]\n \n # Calculate the effective shift\n effective_shift = shift % num_digits\n \n # Perform the circular shift\n shifted_str = str_x[-effective_shift:] + str_x[:-effective_shift]\n \n return shifted_str", "base_status": "fail", "plus_status": null, "base_fail_tests": [[12, 2]], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n \"\"\"Task\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n \"\"\"\n return sum(ord(char) for char in s if char.isupper())", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n \"\"\"\n Given an array representing a branch of a tree that has non-negative integer nodes,\n your task is to pluck one of the nodes and return it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n The plucked node should be returned in a list, [ smallest_value, its index ],\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index. \n\n Example 3:\n Input: []\n Output: []\n \n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n Explanation: 0 is the smallest value, but there are two zeros,\n so we will choose the first zero, which has the smallest index.\n\n Constraints:\n * 1 <= nodes.length <= 10000\n * 0 <= node.value\n \"\"\"\n smallest_even = float('inf')\n smallest_index = -1\n\n for index, value in enumerate(arr):\n if value % 2 == 0: # Check if the value is even\n if value < smallest_even: # Check if it's the smallest even found\n smallest_even = value\n smallest_index = index\n\n if smallest_index == -1: # No even value found\n return []\n \n return [smallest_even, smallest_index]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n \"\"\"\n In this task, you will be given a string that represents a number of apples and oranges \n that are distributed in a basket of fruit. This basket contains \n apples, oranges, and mango fruits. Given the string that represents the total number of \n the oranges and apples and an integer that represents the total number of the fruits \n in the basket, return the number of the mango fruits in the basket.\n \n Parameters:\n s (str): A string representing the number of apples and oranges.\n n (int): An integer representing the total number of fruits in the basket.\n \n Returns:\n int: The number of mango fruits in the basket.\n \n Examples:\n fruit_distribution(\"5 apples and 6 oranges\", 19) -> 8\n fruit_distribution(\"0 apples and 1 oranges\", 3) -> 2\n fruit_distribution(\"2 apples and 3 oranges\", 100) -> 95\n fruit_distribution(\"100 apples and 1 oranges\", 120) -> 19\n \"\"\"\n \n # Extract the number of apples and oranges from the string\n parts = s.split()\n apples = int(parts[0]) # First part is the number of apples\n oranges = int(parts[2]) # Third part is the number of oranges\n \n # Calculate the number of mangoes\n mangoes = n - apples - oranges\n \n return mangoes", "base_status": "fail", "plus_status": null, "base_fail_tests": [["5 apples and 6 oranges", 19]], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n '''\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequency greater than or equal to the value of the integer itself. \n The frequency of an integer is the number of times it appears in the list.\n If no such a value exist, return -1.\n \n Examples:\n search([4, 1, 2, 2, 3, 1]) == 2\n search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n search([5, 5, 4, 4, 4]) == -1\n '''\n from collections import Counter\n\n # Count the frequency of each integer in the list\n frequency = Counter(lst)\n \n # Initialize the result variable\n result = -1\n \n # Iterate through the frequency dictionary\n for num, freq in frequency.items():\n # Check if the frequency is greater than or equal to the number itself\n if freq >= num:\n # Update the result if the current number is greater than the current result\n result = max(result, num)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n '''\n Given list of integers, return list in strange order.\n Strange sorting, is when you start with the minimum value,\n then maximum of the remaining integers, then minimum and so on.\n\n Examples:\n strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n strange_sort_list([]) == []\n '''\n if not lst:\n return []\n\n sorted_lst = sorted(lst)\n result = []\n left, right = 0, len(sorted_lst) - 1\n\n while left <= right:\n if left == right:\n result.append(sorted_lst[left])\n else:\n result.append(sorted_lst[left])\n result.append(sorted_lst[right])\n left += 1\n right -= 1\n\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return the area of\n the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n Otherwise return -1.\n Three sides make a valid triangle when the sum of any two sides is greater \n than the third side.\n \n Example:\n triangle_area(3, 4, 5) == 6.00\n triangle_area(1, 2, 10) == -1\n '''\n # Check for valid triangle using the triangle inequality theorem\n if a + b > c and a + c > b and b + c > a:\n # Calculate the semi-perimeter\n s = (a + b + c) / 2\n # Calculate the area using Heron's formula\n area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n return round(area, 2)\n else:\n return -1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n '''\n Write a function that returns True if the object q will fly, and False otherwise.\n The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n\n Example:\n will_it_fly([1, 2], 5) \u279e False \n # 1+2 is less than the maximum possible weight, but it's unbalanced.\n\n will_it_fly([3, 2, 3], 1) \u279e False\n # it's balanced, but 3+2+3 is more than the maximum possible weight.\n\n will_it_fly([3, 2, 3], 9) \u279e True\n # 3+2+3 is less than the maximum possible weight, and it's balanced.\n\n will_it_fly([3], 5) \u279e True\n # 3 is less than the maximum possible weight, and it's balanced.\n '''\n # Check if the list is a palindrome\n is_balanced = q == q[::-1]\n \n # Calculate the sum of the elements in the list\n total_weight = sum(q)\n \n # Check if the object will fly\n return is_balanced and total_weight <= w", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n \"\"\"\n Given an array arr of integers, find the minimum number of elements that\n need to be changed to make the array palindromic. A palindromic array is an array that\n is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n For example:\n smallest_change([1,2,3,5,4,7,9,6]) == 4\n smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n smallest_change([1, 2, 3, 2, 1]) == 0\n \"\"\"\n n = len(arr)\n changes = 0\n \n # Compare elements from the start and end towards the center\n for i in range(n // 2):\n if arr[i] != arr[n - 1 - i]:\n changes += 1\n \n return changes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n else:\n return lst2", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n \"\"\"Returns True if x is a simple power of n, otherwise False.\n \n A number x is a simple power of n if there exists an integer k such that n**k = x.\n \n Args:\n x (int): The number to check.\n n (int): The base number.\n \n Returns:\n bool: True if x is a simple power of n, False otherwise.\n \"\"\"\n if n <= 1:\n return x == n # n must be greater than 1 for powers to make sense\n \n power = 1\n while True:\n result = n ** power\n if result == x:\n return True\n elif result > x:\n return False\n power += 1", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1, 12]], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef get_primes_up_to(n):\n \"\"\"Return a list of all prime numbers less than n.\"\"\"\n return [i for i in range(2, n) if is_prime(i)]\ndef is_multiply_prime(a):\n \"\"\"Return true if the given number is the multiplication of 3 prime numbers.\"\"\"\n if a >= 100:\n return False\n \n primes = get_primes_up_to(a)\n prime_count = len(primes)\n \n # Check all combinations of three primes\n for i in range(prime_count):\n for j in range(i, prime_count):\n for k in range(j, prime_count):\n product = primes[i] * primes[j] * primes[k]\n if product == a:\n return True\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n \"\"\"Count the number of prime hexadecimal digits in the given string.\"\"\"\n # Define the set of prime hexadecimal digits\n prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n \n # Initialize a counter for prime digits\n count = 0\n \n # Iterate through each character in the input string\n for char in num:\n # Check if the character is in the set of prime hexadecimal digits\n if char in prime_hex_digits:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this integer is a cube of some integer number.\n Note: you may assume the input is always valid.\n \n Examples:\n iscube(1) ==> True\n iscube(2) ==> False\n iscube(-1) ==> True\n iscube(64) ==> True\n iscube(0) ==> True\n iscube(180) ==> False\n '''\n # Calculate the cube root of the absolute value of a\n cube_root = round(abs(a) ** (1/3))\n \n # Check if the cube of the rounded cube root equals the absolute value of a\n return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n \"\"\"Convert a decimal number to binary format with specific formatting.\n \n Args:\n decimal (int): A number in decimal form.\n \n Returns:\n str: A string representing the binary format of the number, \n with 'db' at the beginning and end.\n \n Examples:\n decimal_to_binary(15) # returns \"db1111db\"\n decimal_to_binary(32) # returns \"db100000db\"\n \"\"\"\n # Convert the decimal number to binary and remove the '0b' prefix\n binary_representation = bin(decimal)[2:]\n # Format the result with 'db' at the beginning and end\n formatted_result = f\"db{binary_representation}db\"\n return formatted_result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n \"\"\"Check if the string is happy.\n \n A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n \n Args:\n s (str): The input string to check.\n \n Returns:\n bool: True if the string is happy, False otherwise.\n \"\"\"\n # Check if the length of the string is at least 3\n if len(s) < 3:\n return False\n \n # Iterate through the string and check every 3 consecutive characters\n for i in range(len(s) - 2):\n # Get the current substring of 3 characters\n substring = s[i:i+3]\n # Check if all characters in the substring are distinct\n if len(set(substring)) != 3:\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n letter_grades = []\n \n for gpa in grades:\n if gpa == 4.0:\n letter_grades.append('A+')\n elif gpa > 3.7:\n letter_grades.append('A')\n elif gpa > 3.3:\n letter_grades.append('A-')\n elif gpa > 3.0:\n letter_grades.append('B+')\n elif gpa > 2.7:\n letter_grades.append('B')\n elif gpa > 2.3:\n letter_grades.append('B-')\n elif gpa > 2.0:\n letter_grades.append('C+')\n elif gpa > 1.7:\n letter_grades.append('C')\n elif gpa > 1.3:\n letter_grades.append('C-')\n elif gpa > 1.0:\n letter_grades.append('D+')\n elif gpa > 0.7:\n letter_grades.append('D')\n elif gpa > 0.0:\n letter_grades.append('D-')\n else:\n letter_grades.append('E')\n \n return letter_grades", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef prime_length(string):\n \"\"\"Return True if the string length is a prime number, False otherwise.\"\"\"\n length = len(string)\n return is_prime(length)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits will be 1 the output should be \"1\".\n For N = 150, the sum of digits will be 6 the output should be \"110\".\n For N = 147, the sum of digits will be 12 the output should be \"1100\".\n \n Variables:\n @N integer\n Constraints: 0 \u2264 N \u2264 10000.\n Output:\n a string of binary number\n \"\"\"\n # Calculate the sum of the digits of N\n digit_sum = sum(int(digit) for digit in str(N))\n \n # Convert the sum to binary and return it as a string\n return bin(digit_sum)[2:]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n \"\"\"\n Given a positive integer n, return the count of the numbers of n-digit\n positive integers that start or end with 1.\n \"\"\"\n if n < 1:\n return 0 # There are no n-digit numbers for n < 1\n\n # Total n-digit numbers\n total_n_digit_numbers = 9 * (10 ** (n - 1))\n\n # Count of n-digit numbers that start with 1\n start_with_1 = 10 ** (n - 1)\n\n # Count of n-digit numbers that end with 1\n end_with_1 = total_n_digit_numbers // 10\n\n # Count of n-digit numbers that start and end with 1\n start_and_end_with_1 = 10 ** (n - 2) if n > 1 else 0\n\n # Total count of n-digit numbers that start or end with 1\n count = start_with_1 + end_with_1 - start_and_end_with_1\n\n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words\n words = s.split(' ')\n \n # Sort the characters in each word and keep the spaces\n ordered_words = [''.join(sorted(word)) for word in words]\n \n # Join the ordered words back into a single string with spaces\n result = ' '.join(ordered_words)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n \n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by row (ascending) and then by column (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n or sort it in descending order if the sum( first index value, last index value) is even.\n\n Note:\n * don't change the given array.\n\n Examples:\n * sort_array([]) => []\n * sort_array([5]) => [5]\n * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n \"\"\"\n if not array: # Check if the array is empty\n return []\n \n first_value = array[0]\n last_value = array[-1]\n sum_values = first_value + last_value\n\n # Sort in ascending order if the sum is odd, otherwise sort in descending order\n if sum_values % 2 == 1:\n return sorted(array) # Ascending order\n else:\n return sorted(array, reverse=True) # Descending order", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n # Create a dictionary to map each letter to its encrypted counterpart\n encrypted_dict = {letter: alphabet[(index + 4) % 26] for index, letter in enumerate(alphabet)}\n \n # Encrypt the input string\n encrypted_string = ''.join(encrypted_dict[char] for char in s if char in encrypted_dict)\n \n return encrypted_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Sort the unique elements\n sorted_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_elements[1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n \n For example:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n \"\"\"\n # Split the string into sentences using the delimiters\n sentences = []\n current_sentence = []\n for char in S:\n if char in '.!?':\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n current_sentence = []\n else:\n current_sentence.append(char)\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n\n # Count the number of sentences that start with \"I\"\n boredom_count = sum(1 for sentence in sentences if sentence.startswith('I'))\n\n return boredom_count", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n \"\"\"\n Write a function that takes a message, and encodes in such a \n way that it swaps case of all letters, replaces all vowels in \n the message with the letter that appears 2 places ahead of that \n vowel in the english alphabet. \n Assume only letters. \n \n Examples:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n vowels = 'aeiouAEIOU'\n encoded_message = []\n\n for char in message:\n if char.isalpha(): # Check if the character is a letter\n # Swap case\n if char in vowels:\n # Replace vowel with the letter 2 places ahead\n if char.islower():\n new_char = chr(((ord(char) - ord('a') + 2) % 26) + ord('a'))\n else:\n new_char = chr(((ord(char) - ord('A') + 2) % 26) + ord('A'))\n else:\n new_char = char.swapcase() # Swap case for consonants\n encoded_message.append(new_char)\n else:\n encoded_message.append(char) # Keep non-letter characters unchanged\n\n return ''.join(encoded_message)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["TEST"]], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n '''\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n \n Examples\n any_int(5, 2, 7) \u279e True\n any_int(3, 2, 2) \u279e False\n any_int(3, -2, 1) \u279e True\n any_int(3.6, -2.2, 2) \u279e False\n '''\n # Check if all inputs are integers\n if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n # Check if one number is equal to the sum of the other two\n return x == y + z or y == x + z or z == x + y\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in lower \n case or all keys are strings in upper case, else return False.\n The function should return False if the given dictionary is empty.\n \n Examples:\n check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n \"\"\"\n if not input_dict:\n return False\n\n all_lower = all(isinstance(key, str) and key.islower() for key in input_dict.keys())\n all_upper = all(isinstance(key, str) and key.isupper() for key in input_dict.keys())\n\n return all_lower or all_upper", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef sum_of_digits(n):\n \"\"\"Return the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n largest_prime = -1\n \n for number in lst:\n if is_prime(number) and number > largest_prime:\n largest_prime = number\n \n if largest_prime == -1:\n return 0 # Return 0 if no prime is found\n \n return sum_of_digits(largest_prime)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_up_to(n):\n \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n primes = []\n for i in range(2, n):\n if is_prime(i):\n primes.append(i)\n return primes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.\n \"\"\"\n # Get the unit digit of the first number\n unit_digit_a = abs(a) % 10\n # Get the unit digit of the second number\n unit_digit_b = abs(b) % 10\n # Return the product of the unit digits\n return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n count_upper('aBCdEf') returns 1\n count_upper('abcdefg') returns 0\n count_upper('dBBE') returns 0\n \"\"\"\n uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n count = 0\n \n for i in range(0, len(s), 2): # Iterate over even indices\n if s[i] in uppercase_vowels:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n >>> closest_integer(\"14.5\")\n 15\n >>> closest_integer(\"-14.5\")\n -15\n >>> closest_integer(\"0.5\")\n 1\n >>> closest_integer(\"-0.5\")\n -1\n '''\n\n # Convert the string to a float\n num = float(value)\n \n # Get the floor and ceiling of the number\n lower = int(num // 1) # This is the floor of the number\n upper = lower + 1 # This is the ceiling of the number\n\n # Check if the number is equidistant from lower and upper\n if abs(num - lower) < abs(num - upper):\n return lower\n elif abs(num - lower) > abs(num - upper):\n return upper\n else:\n # If equidistant, round away from zero\n if num > 0:\n return upper\n else:\n return lower", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n \"\"\"\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n \"\"\"\n # Split the string by commas and spaces, then filter out any empty strings\n words = [word.strip() for word in s.replace(',', ' ').split() if word]\n return words", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n \"\"\"\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n >>> make_a_pile(4)\n [4, 6, 8, 10]\n >>> make_a_pile(1)\n [1]\n \"\"\"\n stones = []\n current_stones = n\n \n for i in range(n):\n stones.append(current_stones)\n if n % 2 == 0: # n is even\n current_stones += 2\n else: # n is odd\n current_stones += 2\n \n return stones", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n \"\"\"You are given two positive integers n and m, and your task is to compute the\n average of the integers from n through m (including n and m). \n Round the answer to the nearest integer and convert that to binary.\n If n is greater than m, return -1.\n \n Example:\n rounded_avg(1, 5) => \"0b11\"\n rounded_avg(7, 5) => -1\n rounded_avg(10, 20) => \"0b1111\"\n rounded_avg(20, 33) => \"0b11010\"\n \"\"\"\n if n > m:\n return -1\n \n # Calculate the sum of integers from n to m\n total_sum = sum(range(n, m + 1))\n count = m - n + 1 # Total numbers from n to m\n \n # Calculate the average and round it\n average = total_sum / count\n rounded_average = round(average)\n \n # Convert the rounded average to binary\n return bin(rounded_average)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n \"\"\"This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If \n there's no such number, then the function should return -1.\n\n For example:\n choose_num(12, 15) = 14\n choose_num(13, 12) = -1\n \"\"\"\n # Ensure x is less than or equal to y\n if x > y:\n return -1\n \n # Start from the largest number in the range and check for evenness\n for num in range(y, x - 1, -1):\n if num % 2 == 0:\n return num\n \n return -1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n \"\"\"Given a list of positive integers x, return a sorted list of all \n elements that haven't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n def has_even_digit(n):\n \"\"\"Check if the number has any even digit.\"\"\"\n for digit in str(n):\n if int(digit) % 2 == 0:\n return True\n return False\n\n # Filter the list to include only numbers without even digits\n result = [num for num in x if not has_even_digit(num)]\n \n # Return the sorted result\n return sorted(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n reverse the resulting array, and then replace each digit by its corresponding name from\n \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n For example:\n arr = [2, 1, 1, 4, 5, 8, 2, 3] \n -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n \n If the array is empty, return an empty array:\n arr = []\n return []\n \n If the array has any strange number ignore it:\n arr = [1, -1 , 55] \n -> sort arr -> [-1, 1, 55]\n -> reverse arr -> [55, 1, -1]\n return = ['One']\n \"\"\"\n \n # Mapping of digits to their corresponding names\n digit_to_name = {\n 1: \"One\", 2: \"Two\", 3: \"Three\", 4: \"Four\",\n 5: \"Five\", 6: \"Six\", 7: \"Seven\", 8: \"Eight\", 9: \"Nine\"\n }\n \n # Filter the array to include only numbers between 1 and 9\n filtered_arr = [num for num in arr if 1 <= num <= 9]\n \n # Sort the filtered array\n sorted_arr = sorted(filtered_arr)\n \n # Reverse the sorted array\n reversed_arr = sorted_arr[::-1]\n \n # Convert the digits to their corresponding names\n result = [digit_to_name[num] for num in reversed_arr]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def factorial(i):\n \"\"\"Calculate the factorial of a given number i.\"\"\"\n if i == 0 or i == 1:\n return 1\n result = 1\n for j in range(2, i + 1):\n result *= j\n return result\ndef sum_of_numbers(i):\n \"\"\"Calculate the sum of numbers from 1 to i.\"\"\"\n return (i * (i + 1)) // 2\ndef f(n):\n \"\"\"Return a list of size n, where the value at index i is the factorial of i if i is even,\n or the sum of numbers from 1 to i if i is odd. Indexing starts from 1.\"\"\"\n result = []\n for i in range(1, n + 1):\n if i % 2 == 0: # i is even\n result.append(factorial(i))\n else: # i is odd\n result.append(sum_of_numbers(i))\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n \"\"\"\n Given a positive integer n, return a tuple that has the number of even and odd\n integer palindromes that fall within the range(1, n), inclusive.\n\n Example 1:\n Input: 3\n Output: (1, 2)\n Explanation:\n Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n Example 2:\n Input: 12\n Output: (4, 6)\n Explanation:\n Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n Note:\n 1. 1 <= n <= 10^3\n 2. returned tuple has the number of even and odd integer palindromes respectively.\n \"\"\"\n \n def is_palindrome(num):\n return str(num) == str(num)[::-1]\n\n even_count = 0\n odd_count = 0\n\n for i in range(1, n + 1):\n if is_palindrome(i):\n if i % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n \"\"\"\n Write a function count_nums which takes an array of integers and returns\n the number of elements which has a sum of digits > 0.\n If a number is negative, then its first signed digit will be negative:\n e.g. -123 has signed digits -1, 2, and 3.\n \n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n def sum_of_digits(n):\n # Convert the number to string and calculate the sum of its digits\n return sum(int(digit) if i > 0 else -int(digit) for i, digit in enumerate(str(n)) if digit.isdigit() or (i == 0 and n < 0))\n\n count = 0\n for number in arr:\n if sum_of_digits(number) > 0:\n count += 1\n \n return count", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[-1, -2, 0]]], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return True else return False.\n If the given array is empty then return True.\n\n Note: The given list is guaranteed to have unique elements.\n\n For Example:\n \n move_one_ball([3, 4, 5, 1, 2])==>True\n Explanation: By performing 2 right shift operations, non-decreasing order can\n be achieved for the given array.\n move_one_ball([3, 5, 4, 1, 2])==>False\n Explanation: It is not possible to get non-decreasing order for the given\n array by performing any number of right shift operations.\n \"\"\"\n if not arr:\n return True\n\n n = len(arr)\n sorted_arr = sorted(arr)\n \n # Check for the number of \"breaks\" in the sorted array\n break_count = 0\n for i in range(n):\n if arr[i] > arr[(i + 1) % n]:\n break_count += 1\n\n # If there are more than one break, we cannot sort the array with shifts\n return break_count <= 1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n \"\"\"Determines whether it is possible to perform an exchange of elements\n between two lists to make lst1 a list of only even numbers.\n \n Args:\n lst1 (list): The first list of numbers.\n lst2 (list): The second list of numbers.\n \n Returns:\n str: \"YES\" if lst1 can be made all even, otherwise \"NO\".\n \"\"\"\n # Check if lst1 already contains only even numbers\n if all(x % 2 == 0 for x in lst1):\n return \"YES\"\n \n # Count the number of odd numbers in lst1\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n \n # Check if lst2 has at least one even number to exchange\n has_even_in_lst2 = any(x % 2 == 0 for x in lst2)\n \n # If lst1 has odd numbers and lst2 has at least one even number, we can exchange\n if odd_count_lst1 > 0 and has_even_in_lst2:\n return \"YES\"\n \n return \"NO\"", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 3, 4], [1, 5, 3, 4]]], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n \"\"\"\n if not test:\n return {}\n\n # Split the input string into a list of letters\n letters = test.split()\n \n # Create a dictionary to count occurrences of each letter\n count_dict = {}\n for letter in letters:\n if letter in count_dict:\n count_dict[letter] += 1\n else:\n count_dict[letter] = 1\n\n # Find the maximum count\n max_count = max(count_dict.values())\n \n # Create a result dictionary for letters with the maximum count\n result = {letter: count for letter, count in count_dict.items() if count == max_count}\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n \"\"\"Task\n We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and True/False for the check.\n Example\n For s = \"abcde\", c = \"ae\", the result should be ('bcd',False)\n For s = \"abcdef\", c = \"b\", the result should be ('acdef',False)\n For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc',True)\n \"\"\"\n # Create a set of characters to delete for faster lookup\n chars_to_delete = set(c)\n \n # Create the result string by filtering out characters in chars_to_delete\n result = ''.join(char for char in s if char not in chars_to_delete)\n \n # Check if the result string is a palindrome\n is_palindrome = result == result[::-1]\n \n return (result, is_palindrome)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n Example\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n \"\"\"\n # Initialize variables to track the minimum sum and the current sum\n min_sum = float('inf')\n current_sum = 0\n \n for num in nums:\n current_sum += num\n min_sum = min(min_sum, current_sum)\n \n # If current_sum becomes positive, reset it to 0\n if current_sum > 0:\n current_sum = 0\n \n return min_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n \"\"\"\n Calculate the number of times buckets need to be lowered to empty the wells.\n\n Parameters:\n grid (list of list of int): A rectangular grid representing wells.\n capacity (int): The capacity of each bucket.\n\n Returns:\n int: The total number of times buckets need to be lowered.\n \"\"\"\n total_water = 0\n \n # Count the total amount of water in the grid\n for row in grid:\n total_water += sum(row)\n \n # Calculate the number of times buckets need to be lowered\n # Each bucket can carry 'capacity' units of water\n if total_water == 0:\n return 0\n else:\n return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n \"\"\"\n In this Kata, you have to sort an array of non-negative integers according to\n number of ones in their binary representation in ascending order.\n For similar number of ones, sort based on decimal value.\n\n It must be implemented like this:\n >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n >>> sort_array([1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]\n \"\"\"\n # Sort the array using a custom key\n return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n \"\"\"Given a string s and a natural number n, returns a list of all words from string s \n that contain exactly n consonants, in the order they appear in the string s.\n \n Args:\n s (str): The input string containing words.\n n (int): The number of consonants to filter words by.\n \n Returns:\n list: A list of words containing exactly n consonants.\n \"\"\"\n \n if not s:\n return []\n \n # Define a set of consonants\n consonants = set(\"bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ\")\n \n # Split the string into words\n words = s.split()\n \n # Function to count consonants in a word\n def count_consonants(word):\n return sum(1 for char in word if char in consonants)\n \n # Filter words that have exactly n consonants\n result = [word for word in words if count_consonants(word) == n]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst[0], lst[1]\n \n # Check both concatenation orders\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n two consonants from the right side of the word (case sensitive).\n \n Vowels in the beginning and ending don't count. Return empty string if you didn't\n find any vowel that meets the above condition. \n\n You may assume that the given string contains English letters only.\n\n Example:\n get_closest_vowel(\"yogurt\") ==> \"u\"\n get_closest_vowel(\"FULL\") ==> \"U\"\n get_closest_vowel(\"quick\") ==> \"\"\n get_closest_vowel(\"ab\") ==> \"\"\n \"\"\"\n vowels = \"aeiouAEIOU\"\n n = len(word)\n\n # Start from the end of the word\n for i in range(n - 2, 0, -1): # Start from the second last character\n if word[i] in vowels:\n # Check if there are consonants on both sides\n if word[i - 1].isalpha() and word[i + 1].isalpha() and word[i - 1] not in vowels and word[i + 1] not in vowels:\n return word[i]\n \n return \"\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Get the top k elements\n top_k = sorted_arr[:k]\n # Return the top k elements sorted in ascending order\n return sorted(top_k)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n \"\"\"\n Given a non-empty array of integers arr and an integer k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example:\n\n Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n Output: 24 # sum of 21 + 3\n\n Constraints:\n 1. 1 <= len(arr) <= 100\n 2. 1 <= k <= len(arr)\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate through the first k elements of the array\n for i in range(k):\n # Check if the element has at most two digits\n if -100 < arr[i] < 100:\n total_sum += arr[i]\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n as follows: start with any positive integer n. Then each term is obtained from the \n previous term as follows: if the previous term is even, the next term is one half of \n the previous term. If the previous term is odd, the next term is 3 times the previous\n term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n Note: \n 1. Collatz(1) is [1].\n 2. returned list sorted in increasing order.\n\n For example:\n get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n collatz_sequence = []\n \n while n != 1:\n collatz_sequence.append(n)\n if n % 2 == 0:\n n //= 2\n else:\n n = 3 * n + 1\n \n collatz_sequence.append(1) # Add the last term which is 1\n \n # Filter odd numbers and sort them\n odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n \n return odd_numbers", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n \n The date is valid if all of the following rules are satisfied:\n 1. The date string is not empty.\n 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n The number of days is not less than 1 or higher than 29 for the month 2.\n 3. The months should not be less than 1 or higher than 12.\n 4. The date should be in the format: mm-dd-yyyy\n \n Args:\n date (str): The date string to validate.\n \n Returns:\n bool: True if the date is valid, False otherwise.\n \"\"\"\n if not date:\n return False\n \n # Check the format\n if len(date) != 10 or date[2] != '-' or date[5] != '-':\n return False\n \n try:\n month, day, year = map(int, date.split('-'))\n except ValueError:\n return False\n \n # Validate month\n if month < 1 or month > 12:\n return False\n \n # Validate day based on month\n if month in [1, 3, 5, 7, 8, 10, 12]: # 31 days\n if day < 1 or day > 31:\n return False\n elif month in [4, 6, 9, 11]: # 30 days\n if day < 1 or day > 30:\n return False\n elif month == 2: # February\n if day < 1 or day > 29:\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n '''\n Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n Examples\n split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"abcdef\") == 3 \n '''\n # Check for whitespace in the text\n if ' ' in txt:\n return txt.split()\n \n # Check for commas in the text\n elif ',' in txt:\n return txt.split(',')\n \n # If no whitespace or commas, count lower-case letters with odd order\n else:\n odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n return odd_count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n '''\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return False. Assume no negative numbers and only integers.\n\n Examples\n is_sorted([5]) \u279e True\n is_sorted([1, 2, 3, 4, 5]) \u279e True\n is_sorted([1, 3, 2, 4, 5]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n '''\n if not lst: # An empty list is considered sorted\n return True\n\n seen = set()\n last = None\n\n for num in lst:\n if num in seen:\n # If we see a number again, check if it's a duplicate\n if num == last:\n return False\n else:\n seen.add(num)\n\n if last is not None and num < last:\n return False\n \n last = num\n\n return True", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef intersection(interval1, interval2):\n \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n start1, end1 = interval1\n start2, end2 = interval2\n \n # Find the intersection\n start_intersection = max(start1, start2)\n end_intersection = min(end1, end2)\n \n # Check if there is an intersection\n if start_intersection > end_intersection:\n return \"NO\"\n \n # Calculate the length of the intersection\n length_of_intersection = end_intersection - start_intersection\n \n # Check if the length is a prime number\n if is_prime(length_of_intersection):\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n if not arr:\n return None\n\n product_of_signs = 1\n sum_of_magnitudes = 0\n\n for num in arr:\n if num > 0:\n product_of_signs *= 1\n sum_of_magnitudes += num\n elif num < 0:\n product_of_signs *= -1\n sum_of_magnitudes += -num\n else: # num == 0\n product_of_signs = 0\n break\n\n return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n \"\"\"Calculate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n if n < 0:\n return []\n\n # Initialize the list to store the Tribonacci numbers\n tribonacci_sequence = []\n\n # Define the base case\n for i in range(n + 1):\n if i == 0:\n tribonacci_sequence.append(1) # tri(0) = 1\n elif i == 1:\n tribonacci_sequence.append(3) # tri(1) = 3\n elif i % 2 == 0: # n is even\n tribonacci_sequence.append(1 + i / 2)\n else: # n is odd\n # Calculate tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1)\n tri_n_minus_1 = tribonacci_sequence[i - 1]\n tri_n_minus_2 = tribonacci_sequence[i - 2]\n tri_n_plus_1 = 1 + (i + 1) / 2 if (i + 1) % 2 == 0 else tribonacci_sequence[i - 1] + tribonacci_sequence[i - 2] + (1 + (i + 1) / 2)\n tribonacci_sequence.append(tri_n_minus_1 + tri_n_minus_2 + tri_n_plus_1)\n\n return tribonacci_sequence", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n from collections import deque\n\n N = len(grid)\n directions = [(0, 1), (1, 0), (0, -1), (-1, 0)] # right, down, left, up\n min_path = None\n\n def bfs(start_x, start_y):\n nonlocal min_path\n queue = deque([(start_x, start_y, [grid[start_x][start_y]])])\n visited = set()\n visited.add((start_x, start_y))\n\n while queue:\n x, y, path = queue.popleft()\n\n if len(path) == k:\n if min_path is None or path < min_path:\n min_path = path\n continue\n\n for dx, dy in directions:\n nx, ny = x + dx, y + dy\n if 0 <= nx < N and 0 <= ny < N:\n queue.append((nx, ny, path + [grid[nx][ny]]))\n\n for i in range(N):\n for j in range(N):\n bfs(i, j)\n\n return min_path", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n \"\"\"Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n \n For example:\n digits(1) == 1\n digits(4) == 0\n digits(235) == 15\n \"\"\"\n product = 1\n has_odd = False\n \n for digit in str(n):\n digit = int(digit)\n if digit % 2 != 0: # Check if the digit is odd\n product *= digit\n has_odd = True\n \n return product if has_odd else 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n '''\n Create a function that takes a string as input which contains only square brackets.\n The function should return True if and only if there is a valid subsequence of brackets \n where at least one bracket in the subsequence is nested.\n\n is_nested('[[]]') \u279e True\n is_nested('[]]]]]]][[[[[]') \u279e False\n is_nested('[][]') \u279e False\n is_nested('[]') \u279e False\n is_nested('[[][]]') \u279e True\n is_nested('[[]][[') \u279e True\n '''\n # Initialize a counter for open brackets\n open_count = 0\n # Initialize a flag to check for nesting\n nested = False\n \n for char in string:\n if char == '[':\n open_count += 1\n # If we have more than one open bracket, we have nesting\n if open_count > 1:\n nested = True\n elif char == ']':\n open_count -= 1\n # If we close a bracket and there was at least one open bracket\n if open_count < 0:\n return False # More closing brackets than opening\n # We need to have no unmatched opening brackets at the end\n return nested and open_count == 0", "base_status": "fail", "plus_status": null, "base_fail_tests": [["[[]][["]], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers.\n You need to return the sum of squared numbers in the given list,\n round each element in the list to the upper int (Ceiling) first.\n \n Examples:\n For lst = [1,2,3] the output should be 14\n For lst = [1,4,9] the output should be 98\n For lst = [1,3,5,7] the output should be 84\n For lst = [1.4,4.2,0] the output should be 29\n For lst = [-2.4,1,1] the output should be 6\n \"\"\"\n return sum(math.ceil(x) ** 2 for x in lst)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n '''\n Create a function that returns True if the last character\n of a given string is an alphabetical character and is not\n a part of a word, and False otherwise.\n Note: \"word\" is a group of characters separated by space.\n\n Examples:\n check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '''\n # Strip any trailing whitespace from the string\n txt = txt.rstrip()\n \n # Check if the string is empty after stripping\n if not txt:\n return False\n \n # Get the last character of the string\n last_char = txt[-1]\n \n # Check if the last character is an alphabetical character\n if last_char.isalpha():\n # Check if the last character is part of a word\n # A character is part of a word if it is preceded by a non-space character\n if len(txt) > 1 and txt[-2] != ' ':\n return False\n return True\n \n return False", "base_status": "fail", "plus_status": null, "base_fail_tests": [["eeeee e "]], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n \"\"\"Create a function which returns the largest index of an element which\n is not greater than or equal to the element immediately preceding it. If\n no such element exists then return -1. The given array will not contain\n duplicate values.\n\n Examples:\n can_arrange([1,2,4,3,5]) = 3\n can_arrange([1,2,3]) = -1\n \"\"\"\n # Initialize the index to -1, which will be returned if no such element is found\n largest_index = -1\n \n # Iterate through the array starting from the second element\n for i in range(1, len(arr)):\n # Check if the current element is less than the previous element\n if arr[i] < arr[i - 1]:\n largest_index = i # Update the largest index found\n \n return largest_index", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def compare_one(a, b):\n \"\"\"\n Create a function that takes integers, floats, or strings representing\n real numbers, and returns the larger variable in its given variable type.\n Return None if the values are equal.\n Note: If a real number is represented as a string, the floating point might be . or ,\n\n compare_one(1, 2.5) \u279e 2.5\n compare_one(1, \"2,3\") \u279e \"2,3\"\n compare_one(\"5,1\", \"6\") \u279e \"6\"\n compare_one(\"1\", 1) \u279e None\n \"\"\"\n \n def parse_value(value):\n \"\"\"Convert the input value to a float or return it as is if it's not a number.\"\"\"\n if isinstance(value, str):\n # Replace ',' with '.' for float conversion\n value = value.replace(',', '.')\n try:\n return float(value)\n except ValueError:\n return value # Return the string if it cannot be converted\n return value # Return the number as is\n\n # Parse both values\n parsed_a = parse_value(a)\n parsed_b = parse_value(b)\n\n # Check for equality\n if parsed_a == parsed_b:\n return None\n\n # Return the larger value in its original type\n if parsed_a > parsed_b:\n return a\n else:\n return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n '''\n Create a function that returns a tuple (a, b), where 'a' is\n the largest of negative integers, and 'b' is the smallest\n of positive integers in a list.\n If there is no negative or positive integers, return them as None.\n\n Examples:\n largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n largest_smallest_integers([]) == (None, None)\n largest_smallest_integers([0]) == (None, None)\n '''\n largest_negative = None\n smallest_positive = None\n\n for num in lst:\n if num < 0:\n if largest_negative is None or num > largest_negative:\n largest_negative = num\n elif num > 0:\n if smallest_positive is None or num < smallest_positive:\n smallest_positive = num\n\n return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n \n Args:\n n (int): The number to evaluate.\n \n Returns:\n bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n \n Example:\n is_equal_to_sum_even(4) == False\n is_equal_to_sum_even(6) == False\n is_equal_to_sum_even(8) == True\n \"\"\"\n # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n if n < 8:\n return False\n \n # Check if n is even\n if n % 2 != 0:\n return False\n \n # If n is even and at least 8, it can be expressed as the sum of 4 positive even numbers\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n \"\"\"Calculate the factorial of a non-negative integer n.\"\"\"\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef special_factorial(n):\n \"\"\"Calculate the Brazilian factorial of n.\"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n result = 1\n for i in range(1, n + 1):\n result *= factorial(i)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n \"\"\"\n Given a string text, replace all spaces in it with underscores, \n and if a string has more than 2 consecutive spaces, \n then replace all consecutive spaces with - \n \n fix_spaces(\"Example\") == \"Example\"\n fix_spaces(\"Example 1\") == \"Example_1\"\n fix_spaces(\" Example 2\") == \"_Example_2\"\n fix_spaces(\" Example 3\") == \"_Example-3\"\n \"\"\"\n # Replace multiple spaces with a single space\n import re\n text = re.sub(r'\\s{3,}', '-', text) # Replace 3 or more spaces with '-'\n text = re.sub(r'\\s+', '_', text) # Replace 1 or 2 spaces with '_'\n \n return text", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Yellow Yellow Dirty Fellow"]], "plus_fail_tests": []}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n \"\"\"Create a function which takes a string representing a file's name, and returns\n 'Yes' if the the file's name is valid, and returns 'No' otherwise.\n A file's name is considered to be valid if and only if all the following conditions \n are met:\n - There should not be more than three digits ('0'-'9') in the file's name.\n - The file's name contains exactly one dot '.'\n - The substring before the dot should not be empty, and it starts with a letter from \n the latin alphapet ('a'-'z' and 'A'-'Z').\n - The substring after the dot should be one of these: ['txt', 'exe', 'dll']\n Examples:\n file_name_check(\"example.txt\") # => 'Yes'\n file_name_check(\"1example.dll\") # => 'No' (the name should start with a latin alphapet letter)\n \"\"\"\n \n # Check for exactly one dot\n if file_name.count('.') != 1:\n return 'No'\n \n # Split the file name into name and extension\n name, extension = file_name.split('.')\n \n # Check if the name is empty or starts with a non-letter\n if not name or not name[0].isalpha():\n return 'No'\n \n # Check the extension\n valid_extensions = ['txt', 'exe', 'dll']\n if extension not in valid_extensions:\n return 'No'\n \n # Count digits in the file name\n digit_count = sum(c.isdigit() for c in file_name)\n if digit_count > 3:\n return 'No'\n \n return 'Yes'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n \"\"\"\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n \n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126\n \"\"\"\n total = 0\n for index, value in enumerate(lst):\n if index % 3 == 0:\n total += value ** 2 # Square if index is a multiple of 3\n elif index % 4 == 0:\n total += value ** 3 # Cube if index is a multiple of 4 and not a multiple of 3\n else:\n total += value # Leave unchanged if not a multiple of 3 or 4\n return total", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef words_in_sentence(sentence):\n \"\"\"\n You are given a string representing a sentence,\n the sentence contains some words separated by a space,\n and you have to return a string that contains the words from the original sentence,\n whose lengths are prime numbers,\n the order of the words in the new string should be the same as the original one.\n\n Example 1:\n Input: sentence = \"This is a test\"\n Output: \"is\"\n\n Example 2:\n Input: sentence = \"lets go for swimming\"\n Output: \"go for\"\n \"\"\"\n words = sentence.split()\n prime_length_words = [word for word in words if is_prime(len(word))]\n return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n \"\"\"Simplifies the expression x * n and checks if the result is a whole number.\n \n Args:\n x (str): A string representation of a fraction in the format '/'.\n n (str): A string representation of a fraction in the format '/'.\n \n Returns:\n bool: True if x * n evaluates to a whole number, False otherwise.\n \"\"\"\n # Split the fractions into numerator and denominator\n x_numerator, x_denominator = map(int, x.split('/'))\n n_numerator, n_denominator = map(int, n.split('/'))\n \n # Calculate the product of the fractions\n # (x_numerator / x_denominator) * (n_numerator / n_denominator) = (x_numerator * n_numerator) / (x_denominator * n_denominator)\n product_numerator = x_numerator * n_numerator\n product_denominator = x_denominator * n_denominator\n \n # Check if the product is a whole number\n return product_numerator % product_denominator == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n \"\"\"\n Write a function which sorts the given list of integers\n in ascending order according to the sum of their digits.\n Note: if there are several items with similar sum of their digits,\n order them based on their index in original list.\n\n For example:\n >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n >>> order_by_points([]) == []\n \"\"\"\n \n def digit_sum(n):\n \"\"\"Calculate the sum of the digits of n.\"\"\"\n return sum(int(digit) for digit in str(abs(n)))\n\n # Sort the list based on the sum of digits and original index\n return sorted(nums, key=lambda x: (digit_sum(x), nums.index(x)))", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n \"\"\"Returns the number of elements in the array that are greater than 10 \n and both the first and last digits of the number are odd (1, 3, 5, 7, 9).\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n int: The count of numbers meeting the criteria.\n \"\"\"\n \n def is_odd_digit(digit):\n \"\"\"Check if a digit is odd.\"\"\"\n return digit in {'1', '3', '5', '7', '9'}\n \n count = 0\n for num in nums:\n if num > 10:\n str_num = str(abs(num)) # Convert to string and take absolute value\n if is_odd_digit(str_num[0]) and is_odd_digit(str_num[-1]):\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n \"\"\"\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example :\n Input: n = 5\n Output: 1\n Explanation: \n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n \"\"\"\n # Create the array a\n a = [i * i - i + 1 for i in range(1, n + 1)]\n \n # Count the number of valid triples\n count = 0\n for i in range(n):\n for j in range(i + 1, n):\n for k in range(j + 1, n):\n if (a[i] + a[j] + a[k]) % 3 == 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closest to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sorted by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct planet names. \n Examples\n bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n '''\n\n planets = [\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n ]\n \n if planet1 not in planets or planet2 not in planets:\n return ()\n \n index1 = planets.index(planet1)\n index2 = planets.index(planet2)\n \n # Determine the range of indices\n start_index = min(index1, index2) + 1\n end_index = max(index1, index2)\n \n # Get the planets in between\n in_between_planets = planets[start_index:end_index]\n \n return tuple(in_between_planets)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length and alphabetically.\n \n Args:\n lst (list): A list of strings.\n \n Returns:\n list: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef x_or_y(n, x, y):\n \"\"\"Return the value of x if n is a prime number, otherwise return y.\"\"\"\n if is_prime(n):\n return x\n else:\n return y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n \n double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n double_the_difference([-1, -2, 0]) == 0\n double_the_difference([9, -2]) == 81\n double_the_difference([0]) == 0 \n \n If the input list is empty, return 0.\n '''\n if not lst: # Check if the list is empty\n return 0\n \n return sum(x**2 for x in lst if isinstance(x, int) and x >= 0 and x % 2 != 0)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n \"\"\"Compares the actual game scores with the guessed scores and returns the absolute differences.\n \n Args:\n game (list of int): The actual scores of the matches.\n guess (list of int): The guessed scores of the matches.\n \n Returns:\n list of int: A list containing the absolute differences between the actual scores and the guessed scores.\n If the guess is correct, the value is 0.\n \"\"\"\n return [abs(g - a) for a, g in zip(game, guess)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n \"\"\"Find the strongest extension based on the strength defined by the number of uppercase and lowercase letters.\"\"\"\n strongest_extension = None\n max_strength = float('-inf')\n\n for extension in extensions:\n CAP = sum(1 for char in extension if char.isupper())\n SM = sum(1 for char in extension if char.islower())\n strength = CAP - SM\n\n if strength > max_strength:\n max_strength = strength\n strongest_extension = extension\n\n return f\"{class_name}.{strongest_extension}\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n \"\"\"You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word.\n \n Args:\n a (str): The first word.\n b (str): The second word.\n \n Returns:\n bool: True if the second word or any of its rotations is a substring in the first word, False otherwise.\n \n Examples:\n >>> cycpattern_check(\"abcd\", \"abd\")\n False\n >>> cycpattern_check(\"hello\", \"ell\")\n True\n >>> cycpattern_check(\"whassup\", \"psus\")\n False\n >>> cycpattern_check(\"abab\", \"baa\")\n True\n >>> cycpattern_check(\"efef\", \"eeff\")\n False\n >>> cycpattern_check(\"himenss\", \"simen\")\n True\n \"\"\"\n # Create a string that contains two copies of b\n b_rotations = b + b\n \n # Check if a is a substring of b_rotations\n return a in b_rotations", "base_status": "fail", "plus_status": null, "base_fail_tests": [["yello", "ell"]], "plus_fail_tests": []}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n Example:\n even_odd_count(-12) ==> (1, 1)\n even_odd_count(123) ==> (1, 2)\n \"\"\"\n # Convert the number to a string and remove the sign if it's negative\n num_str = str(abs(num))\n \n even_count = 0\n odd_count = 0\n \n # Iterate through each character in the string representation of the number\n for digit in num_str:\n if digit.isdigit(): # Check if the character is a digit\n if int(digit) % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n if not (1 <= number <= 1000):\n raise ValueError(\"Number must be between 1 and 1000\")\n\n roman_numerals = [\n (1000, 'm'),\n (900, 'cm'),\n (500, 'd'),\n (400, 'cd'),\n (100, 'c'),\n (90, 'xc'),\n (50, 'l'),\n (40, 'xl'),\n (10, 'x'),\n (9, 'ix'),\n (5, 'v'),\n (4, 'iv'),\n (1, 'i')\n ]\n\n result = []\n for value, numeral in roman_numerals:\n while number >= value:\n result.append(numeral)\n number -= value\n\n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return True if the three\n sides form a right-angled triangle, False otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or \n 90 degree.\n \n Example:\n right_angle_triangle(3, 4, 5) == True\n right_angle_triangle(1, 2, 3) == False\n '''\n # Sort the sides to identify the longest side\n sides = sorted([a, b, c])\n \n # Check the Pythagorean theorem\n return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n \"\"\"Write a function that accepts a list of strings.\n The list contains different words. Return the word with maximum number\n of unique characters. If multiple strings have maximum number of unique\n characters, return the one which comes first in lexicographical order.\n\n find_max([\"name\", \"of\", \"string\"]) == \"string\"\n find_max([\"name\", \"enam\", \"game\"]) == \"enam\"\n find_max([\"aaaaaaa\", \"bb\" ,\"cc\"]) == \"aaaaaaa\"\n \"\"\"\n max_word = \"\"\n max_unique_count = 0\n\n for word in words:\n unique_chars = set(word)\n unique_count = len(unique_chars)\n\n if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n max_word = word\n max_unique_count = unique_count\n\n return max_word", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n \"\"\"\n You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n \n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n \n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots that exist in stock\n \n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n \"\"\"\n # Calculate how many more carrots are needed\n additional_needed = need - number\n \n # If no additional carrots are needed, return the current state\n if additional_needed <= 0:\n return [number, remaining]\n \n # Determine how many carrots can be eaten from the remaining stock\n eaten = min(additional_needed, remaining)\n \n # Update the total number of eaten carrots and remaining carrots\n total_eaten = number + eaten\n remaining_after_meals = remaining - eaten\n \n return [total_eaten, remaining_after_meals]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic algebra operations, and \n the second list is a list of integers. Use the two given lists to build the algebraic \n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + ) \n Subtraction ( - ) \n Multiplication ( * ) \n Floor division ( // ) \n Exponentiation ( ** ) \n\n Example:\n operator = ['+', '*', '-']\n operand = [2, 3, 4, 5]\n result = do_algebra(operator, operand)\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.\n \"\"\"\n \n # Start with the first operand\n result = operand[0]\n \n # Iterate through the operators and operands\n for i in range(len(operator)):\n op = operator[i]\n next_operand = operand[i + 1]\n \n if op == '+':\n result += next_operand\n elif op == '-':\n result -= next_operand\n elif op == '*':\n result *= next_operand\n elif op == '//':\n result //= next_operand\n elif op == '**':\n result **= next_operand\n else:\n raise ValueError(f\"Invalid operator: {op}\")\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": []}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n \"\"\"You are given a string s.\n if s[i] is a letter, reverse its case from lower to upper or vice versa, \n otherwise keep it as it is.\n If the string contains no letters, reverse the string.\n The function should return the resulted string.\n \n Examples:\n solve(\"1234\") = \"4321\"\n solve(\"ab\") = \"AB\"\n solve(\"#a@C\") = \"#A@c\"\n \"\"\"\n # Check if there are any letters in the string\n has_letters = any(c.isalpha() for c in s)\n \n if has_letters:\n # Reverse case for letters and keep others the same\n result = ''.join(c.upper() if c.islower() else c.lower() for c in s)\n else:\n # Reverse the string if there are no letters\n result = s[::-1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string.\n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n >>> string_to_md5('') is None\n \"\"\"\n if text == \"\":\n return None\n md5_hash = hashlib.md5(text.encode()).hexdigest()\n return md5_hash", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascending order.\n\n For example:\n generate_integers(2, 8) => [2, 4, 6, 8]\n generate_integers(8, 2) => [2, 4, 6, 8]\n generate_integers(10, 14) => []\n \"\"\"\n # Determine the range of numbers to consider\n start = min(a, b)\n end = max(a, b)\n\n # Generate a list of even integers in the specified range\n even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n return even_integers", "base_status": "fail", "plus_status": null, "base_fail_tests": [[2, 10]], "plus_fail_tests": []}]}} \ No newline at end of file diff --git a/llm_based_121_eval_results.json b/llm_based_121_eval_results.json new file mode 100644 index 000000000..c3fee2d7d --- /dev/null +++ b/llm_based_121_eval_results.json @@ -0,0 +1 @@ +{"date": "2024-07-25 16:38", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" \n Input to this function is a string containing multiple groups of nested parentheses. \n Your goal is to separate those groups into separate strings and return the list of those.\n Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n Ignore any spaces in the input string.\n \n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n # Remove spaces from the input string\n paren_string = paren_string.replace(\" \", \"\")\n \n result = []\n balance = 0\n current_group = []\n \n for char in paren_string:\n if char == '(':\n if balance == 0 and current_group:\n result.append(''.join(current_group))\n current_group = []\n balance += 1\n current_group.append(char)\n elif char == ')':\n balance -= 1\n current_group.append(char)\n if balance == 0:\n result.append(''.join(current_group))\n current_group = []\n \n # In case there are any remaining groups\n if current_group:\n result.append(''.join(current_group))\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to make it easier to find close elements\n numbers.sort()\n \n # Check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" \n You're given a list of deposit and withdrawal operations on a bank account that starts with\n zero balance. Your task is to detect if at any point the balance of account falls below zero, and\n at that point function should return True. Otherwise it should return False.\n \n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n \"\"\"\n balance = 0\n for operation in operations:\n balance += operation\n if balance < 0:\n return True\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into\n an integer part (largest integer smaller than given number) and decimals\n (leftover part always smaller than 1).\n\n Return the decimal part of the number.\n \n >>> truncate_number(3.5)\n 0.5\n >>> truncate_number(2.75)\n 0.75\n >>> truncate_number(5.0)\n 0.0\n >>> truncate_number(0.99)\n 0.99\n \"\"\"\n if number < 0:\n raise ValueError(\"The number must be positive.\")\n \n integer_part = int(number) # Get the integer part\n decimal_part = number - integer_part # Calculate the decimal part\n return decimal_part", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n \"\"\" Insert a number 'delimiter' between every two consecutive elements of input list `numbers'\n \n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n for i in range(len(numbers)):\n result.append(numbers[i])\n if i < len(numbers) - 1: # Avoid adding delimiter after the last element\n result.append(delimiter)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list to avoid division by zero\n\n mean_value = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n return mad", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n def max_nesting_depth(s: str) -> int:\n max_depth = 0\n current_depth = 0\n for char in s:\n if char == '(':\n current_depth += 1\n max_depth = max(max_depth, current_depth)\n elif char == ')':\n current_depth -= 1\n return max_depth\n\n groups = paren_string.split()\n return [max_nesting_depth(group) for group in groups]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n \"\"\"\n return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n \n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n \"\"\"\n if not numbers:\n return (0, 1)\n \n total_sum = sum(numbers)\n total_product = 1\n for number in numbers:\n total_product *= number\n \n return (total_sum, total_product)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n \"\"\" \n Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n \n >>> string_xor('010', '110')\n '100'\n \"\"\"\n # Ensure both strings are of the same length by padding the shorter one with leading zeros\n max_length = max(len(a), len(b))\n a = a.zfill(max_length)\n b = b.zfill(max_length)\n \n # Perform XOR operation\n result = []\n for bit_a, bit_b in zip(a, b):\n result.append('1' if bit_a != bit_b else '0')\n \n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n \n >>> make_palindrome('')\n ''\n >>> make_palindrome('cat')\n 'catac'\n >>> make_palindrome('cata')\n 'catac'\n \"\"\"\n # If the string is empty, return it as is\n if not string:\n return string\n \n # Find the longest palindromic suffix\n for i in range(len(string)):\n if is_palindrome(string[i:]):\n # If we found a palindromic suffix, we take the prefix before it\n prefix = string[:i]\n # Append the reverse of the prefix to the original string\n return string + prefix[::-1]\n \n # If no palindromic suffix is found, the whole string is non-palindromic\n return string + string[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return the greatest common divisor of two integers a and b.\n \n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n \"\"\"\n while b:\n a, b = b, a % b\n return abs(a)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n \n >>> longest([])\n >>> None\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n \"\"\"\n if not strings:\n return None\n \n longest_string = strings[0]\n \n for string in strings:\n if len(string) > len(longest_string):\n longest_string = string\n \n return longest_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string\n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n \"\"\"\n return [string[:i] for i in range(1, len(string) + 1)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lower_string = string.lower()\n # Use a set to find distinct characters\n distinct_characters = set(lower_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n \n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n \"\"\"\n return ' '.join(str(i) for i in range(n + 1))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" Input to this function is a string representing musical notes in a special ASCII format.\n Your task is to parse this string and return list of integers corresponding to how many beats does each\n note last.\n\n Here is a legend:\n 'o' - whole note, lasts four beats\n 'o|' - half note, lasts two beats\n '.|' - quarter note, lasts one beat\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n # Define a mapping from note representation to beats\n note_to_beats = {\n 'o': 4,\n 'o|': 2,\n '.|': 1\n }\n \n # Split the input string into individual notes\n notes = music_string.split()\n \n # Parse each note and convert to beats\n beats = [note_to_beats[note] for note in notes if note in note_to_beats]\n \n return beats", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n \n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n \"\"\"\n count = 0\n start = 0\n \n while True:\n start = string.find(substring, start)\n if start == -1:\n break\n count += 1\n start += 1 # Move to the next character to allow for overlapping matches\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n \"\"\" \n Input is a space-delimited string of numerals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest.\n \n >>> sort_numbers('three one five')\n 'one three five'\n \"\"\"\n # Mapping of words to their corresponding numeric values\n num_map = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n \n # Split the input string into a list of words\n words = numbers.split()\n \n # Sort the words based on their numeric values\n sorted_words = sorted(words, key=lambda word: num_map[word])\n \n # Join the sorted words back into a single string\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to make it easier to find the closest pairs\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest elements\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1.\n \n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n min_val = min(numbers)\n max_val = max(numbers)\n \n # Avoid division by zero if all numbers are the same\n if min_val == max_val:\n return [0.0] * len(numbers)\n \n return [(num - min_val) / (max_val - min_val) for num in numbers]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers\n >>> filter_integers(['a', 3.14, 5])\n [5]\n >>> filter_integers([1, 2, 3, 'abc', {}, []])\n [1, 2, 3]\n \"\"\"\n return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(10)\n 5\n >>> largest_divisor(1)\n 0\n >>> largest_divisor(28)\n 14\n \"\"\"\n if n <= 1:\n return 0 # No divisors smaller than 1\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n \"\"\" Return length of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n \"\"\"\n return len(string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n Input number should be equal to the product of all factors\n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n \"\"\"\n factors = []\n # Check for number of 2s that divide n\n while n % 2 == 0:\n factors.append(2)\n n //= 2\n \n # n must be odd at this point so a skip of 2 (i.e., i = i + 2) can be used\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, append i and divide n\n while n % i == 0:\n factors.append(i)\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n factors.append(n)\n \n return factors", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n \n # Create a new list with elements that occur only once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string.\n \n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n \"\"\"\n return ''.join(strings)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n \n >>> flip_case('Hello')\n 'hELLO'\n >>> flip_case('Python')\n 'pYTHON'\n >>> flip_case('123abcXYZ')\n '123ABCxyz'\n >>> flip_case('')\n ''\n \"\"\"\n return string.swapcase()", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n \n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n \"\"\"\n return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n \n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n \"\"\"\n return [x for x in l if x > 0]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float) -> float:\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list) -> list:\n \"\"\"\n Returns the coefficients of the derivative of the polynomial.\n \"\"\"\n return [i * coeff for i, coeff in enumerate(xs)][1:]\ndef find_zero(xs: list) -> float:\n \"\"\" \n xs are coefficients of a polynomial.\n find_zero finds x such that poly(x) = 0.\n find_zero returns only one zero point, even if there are many.\n Moreover, find_zero only takes list xs having an even number of coefficients\n and the largest non-zero coefficient as it guarantees a solution.\n \n >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n -0.5\n >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n 1.0\n \"\"\"\n if len(xs) % 2 != 0:\n raise ValueError(\"The number of coefficients must be even.\")\n \n # Initial guess (can be improved)\n x = 0.0\n tolerance = 1e-7\n max_iterations = 1000\n \n for _ in range(max_iterations):\n f_x = poly(xs, x)\n f_prime_x = poly(derivative(xs), x)\n \n if abs(f_prime_x) < tolerance: # Avoid division by zero\n raise ValueError(\"Derivative is too small; no solution found.\")\n \n x_new = x - f_x / f_prime_x\n \n if abs(x_new - x) < tolerance: # Convergence check\n return x_new\n \n x = x_new\n \n raise ValueError(\"Maximum iterations reached; no solution found.\")", "base_status": "fail", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(divisible_by_three)\n \n # Create a new list to hold the result\n result = l.copy()\n \n # Replace values at indices divisible by 3 with sorted values\n for index, value in zip((i for i in range(len(l)) if i % 3 == 0), sorted_values):\n result[index] = value\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n \"\"\"Return maximum element in the list.\n \n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty.\")\n max_value = l[0]\n for item in l:\n if item > max_value:\n max_value = item\n return max_value", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n even_indices = [l[i] for i in range(0, len(l), 2)]\n # Sort the even indexed elements\n even_indices.sort()\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Place the sorted even indexed elements back into their positions\n for i, value in enumerate(even_indices):\n result[i * 2] = value # Place sorted value at even index\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with the encode_cyclic function.\n Returns the decoded string.\n \"\"\"\n # Split string into groups of length 3\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # Reverse the cycling for each group\n groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef prime_fib(n: int) -> int:\n \"\"\"\n prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n \n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n fib_gen = fibonacci_generator()\n count = 0\n while count < n:\n fib_num = next(fib_gen)\n if is_prime(fib_num):\n count += 1\n if count == n:\n return fib_num", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1]], "plus_fail_tests": []}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n \"\"\"\n triples_sum_to_zero takes a list of integers as an input.\n it returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n \"\"\"\n n = len(l)\n l = list(set(l)) # Remove duplicates\n n = len(l) # Update length after removing duplicates\n\n for i in range(n):\n seen = set()\n target = -l[i]\n for j in range(i + 1, n):\n if target - l[j] in seen:\n return True\n seen.add(l[j])\n return False", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 3, -2, 1]]], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n \"\"\"\n Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move at the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.\n\n Parameters:\n n (int): The number of cars in each direction.\n\n Returns:\n int: The number of collisions.\n \"\"\"\n # Each car moving left to right will collide with each car moving right to left\n # Therefore, the total number of collisions is n * n\n return n * n", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n \n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n \"\"\"\n return [x + 1 for x in l]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n \n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n \"\"\"\n seen = set()\n for number in l:\n if -number in seen:\n return True\n seen.add(number)\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion.\n base numbers are less than 10.\n \n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n \"\"\"\n if base < 2 or base >= 10:\n raise ValueError(\"Base must be between 2 and 9 (inclusive).\")\n \n if x == 0:\n return '0'\n \n result = []\n while x > 0:\n result.append(str(x % base))\n x //= base\n \n return ''.join(reversed(result))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n \"\"\"Given length of a side and height, return area for a triangle.\n \n The area of a triangle can be calculated using the formula:\n area = (base * height) / 2\n \n Args:\n a (float): The length of the base of the triangle.\n h (float): The height of the triangle.\n \n Returns:\n float: The area of the triangle.\n \n >>> triangle_area(5, 3)\n 7.5\n \"\"\"\n return (a * h) / 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fib4(0) -> 0\n fib4(1) -> 0\n fib4(2) -> 2\n fib4(3) -> 0\n fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n \n This function computes the n-th element of the fib4 number sequence without using recursion.\n \n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 2\n elif n == 3:\n return 0\n\n # Initialize the first four values of the sequence\n fib_values = [0, 0, 2, 0]\n\n # Compute the values iteratively\n for i in range(4, n + 1):\n next_value = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n fib_values.append(next_value)\n\n return fib_values[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n \"\"\"Return median of elements in the list l.\n \n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty.\")\n \n sorted_list = sorted(l)\n n = len(sorted_list)\n mid = n // 2\n \n if n % 2 == 0:\n return (sorted_list[mid - 1] + sorted_list[mid]) / 2\n else:\n return sorted_list[mid]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n \"\"\"\n Checks if given string is a palindrome.\n \n A palindrome is a string that reads the same forward and backward.\n \n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n \"\"\"\n # Normalize the string by removing spaces and converting to lowercase\n normalized_text = text.replace(\" \", \"\").lower()\n # Check if the string is equal to its reverse\n return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n \"\"\"\n Takes as input string encoded with encode_shift function. Returns decoded string.\n \"\"\"\n return \"\".join([chr(((ord(ch) - ord(\"a\") - 5) % 26) + ord(\"a\")) for ch in s])", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n \"\"\"Return True if all numbers in the list l are below threshold t.\n \n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n \"\"\"\n return all(x < t for x in l)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n \"\"\"Add two numbers x and y.\n \n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n \"\"\"\n return x + y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two words have the same characters if they contain the same unique characters,\n regardless of the number of times each character appears.\n \n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n \"\"\"Return n-th Fibonacci number.\n \n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n elif n == 1:\n return 1\n elif n == 2:\n return 1\n else:\n a, b = 1, 1\n for _ in range(2, n):\n a, b = b, a + b\n return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"<\" and \">\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"<\")\n False\n >>> correct_bracketing(\"<>\")\n True\n >>> correct_bracketing(\"<<><>>\")\n True\n >>> correct_bracketing(\"><<>\")\n False\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '<':\n balance += 1\n elif char == '>':\n balance -= 1\n # If balance goes negative, there are more closing brackets\n if balance < 0:\n return False\n # At the end, balance should be zero for correct bracketing\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n \"\"\"Return True if list elements are monotonically increasing or decreasing.\n \n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n \"\"\"\n if not l: # An empty list is considered monotonic\n return True\n\n increasing = decreasing = True\n\n for i in range(1, len(l)):\n if l[i] > l[i - 1]:\n decreasing = False\n elif l[i] < l[i - 1]:\n increasing = False\n\n return increasing or decreasing", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n # Keep dividing n by factor until it is no longer divisible\n while n > 1:\n if n % factor == 0:\n n //= factor # Divide n by the factor\n else:\n factor += 1 # Move to the next potential factor\n return factor # The last factor is the largest prime factor", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n \n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n \"\"\"\n return n * (n + 1) // 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"(\" and \")\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"(\")\n False\n >>> correct_bracketing(\"()\")\n True\n >>> correct_bracketing(\"(()())\")\n True\n >>> correct_bracketing(\")(()\")\n False\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n # If balance goes negative, there are unmatched closing brackets\n if balance < 0:\n return False\n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n \"\"\" \n xs represent coefficients of a polynomial.\n xs[0] + xs[1] * x + xs[2] * x^2 + ....\n Return derivative of this polynomial in the same form.\n \n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n \"\"\"\n # The derivative of a polynomial is calculated by multiplying each coefficient\n # by its corresponding power and reducing the power by one.\n return [i * coeff for i, coeff in enumerate(xs[1:], start=1)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set('aeiouAEIOU')\n count = 0\n \n # Check each character in the string\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n # Check if 'y' is at the end of the word\n elif s[i].lower() == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n \n Args:\n n (int): The index of the FibFib number to compute.\n \n Returns:\n int: The n-th FibFib number.\n \n Examples:\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n if n == 0 or n == 1:\n return 0\n elif n == 2:\n return 1\n \n # Initialize the first three FibFib numbers\n fibfib_numbers = [0, 0, 1]\n \n # Compute the FibFib numbers iteratively\n for i in range(3, n + 1):\n next_fibfib = fibfib_numbers[i - 1] + fibfib_numbers[i - 2] + fibfib_numbers[i - 3]\n fibfib_numbers.append(next_fibfib)\n \n return fibfib_numbers[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n \"\"\"Task\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n \"\"\"\n return sum(ord(char) for char in s if char.isupper())", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n \n >>> circular_shift(12, 1)\n '21'\n >>> circular_shift(12, 2)\n '12'\n >>> circular_shift(12345, 1)\n '51234'\n >>> circular_shift(12345, 5)\n '54321'\n >>> circular_shift(12345, 6)\n '54321'\n \"\"\"\n # Convert the integer to a string to manipulate its digits\n str_x = str(x)\n num_digits = len(str_x)\n \n # If shift is greater than the number of digits, reverse the string\n if shift >= num_digits:\n return str_x[::-1]\n \n # Perform the circular shift\n shift = shift % num_digits # Handle shifts larger than the number of digits\n return str_x[-shift:] + str_x[:-shift]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[12, 2]], "plus_fail_tests": []}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n \"\"\"\n In this task, you will be given a string that represents a number of apples and oranges \n that are distributed in a basket of fruit. This basket contains \n apples, oranges, and mango fruits. Given the string that represents the total number of \n the oranges and apples and an integer that represents the total number of the fruits \n in the basket, return the number of the mango fruits in the basket.\n \n Parameters:\n s (str): A string representing the number of apples and oranges.\n n (int): An integer representing the total number of fruits in the basket.\n \n Returns:\n int: The number of mango fruits in the basket.\n \n Examples:\n fruit_distribution(\"5 apples and 6 oranges\", 19) -> 8\n fruit_distribution(\"0 apples and 1 oranges\", 3) -> 2\n fruit_distribution(\"2 apples and 3 oranges\", 100) -> 95\n fruit_distribution(\"100 apples and 1 oranges\", 120) -> 19\n \"\"\"\n \n # Extract the number of apples and oranges from the string\n parts = s.split()\n apples = int(parts[0]) # First part is the number of apples\n oranges = int(parts[2]) # Third part is the number of oranges\n \n # Calculate the number of mangoes\n mangoes = n - apples - oranges\n \n return mangoes", "base_status": "fail", "plus_status": null, "base_fail_tests": [["5 apples and 6 oranges", 19]], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n \"\"\"\n Given an array representing a branch of a tree that has non-negative integer nodes,\n your task is to pluck one of the nodes and return it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n The plucked node should be returned in a list, [ smallest_value, its index ],\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index. \n\n Example 3:\n Input: []\n Output: []\n \n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n Explanation: 0 is the smallest value, but there are two zeros,\n so we will choose the first zero, which has the smallest index.\n\n Constraints:\n * 1 <= nodes.length <= 10000\n * 0 <= node.value\n \"\"\"\n smallest_even = float('inf')\n smallest_index = -1\n\n for index, value in enumerate(arr):\n if value % 2 == 0: # Check if the value is even\n if value < smallest_even: # Check if it's the smallest even found\n smallest_even = value\n smallest_index = index\n\n if smallest_index == -1: # No even value found\n return []\n \n return [smallest_even, smallest_index]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n '''\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequency greater than or equal to the value of the integer itself. \n The frequency of an integer is the number of times it appears in the list.\n If no such a value exist, return -1.\n \n Examples:\n search([4, 1, 2, 2, 3, 1]) == 2\n search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n search([5, 5, 4, 4, 4]) == -1\n '''\n from collections import Counter\n \n # Count the frequency of each integer in the list\n frequency = Counter(lst)\n \n # Initialize the result variable\n result = -1\n \n # Iterate through the frequency dictionary\n for num, freq in frequency.items():\n # Check if the frequency is greater than or equal to the number itself\n if freq >= num:\n # Update the result if the current number is greater than the current result\n result = max(result, num)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n '''\n Given list of integers, return list in strange order.\n Strange sorting, is when you start with the minimum value,\n then maximum of the remaining integers, then minimum and so on.\n\n Examples:\n strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n strange_sort_list([]) == []\n '''\n if not lst:\n return []\n\n sorted_lst = sorted(lst)\n result = []\n left, right = 0, len(sorted_lst) - 1\n\n while left <= right:\n if left == right:\n result.append(sorted_lst[left])\n else:\n result.append(sorted_lst[left])\n result.append(sorted_lst[right])\n left += 1\n right -= 1\n\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n '''\n Write a function that returns True if the object q will fly, and False otherwise.\n The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n\n Example:\n will_it_fly([1, 2], 5) \u279e False \n # 1+2 is less than the maximum possible weight, but it's unbalanced.\n\n will_it_fly([3, 2, 3], 1) \u279e False\n # it's balanced, but 3+2+3 is more than the maximum possible weight.\n\n will_it_fly([3, 2, 3], 9) \u279e True\n # 3+2+3 is less than the maximum possible weight, and it's balanced.\n\n will_it_fly([3], 5) \u279e True\n # 3 is less than the maximum possible weight, and it's balanced.\n '''\n # Check if the list is a palindrome\n is_balanced = q == q[::-1]\n \n # Calculate the sum of the elements in the list\n total_weight = sum(q)\n \n # Check if the object will fly\n return is_balanced and total_weight <= w", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return the area of\n the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n Otherwise return -1.\n Three sides make a valid triangle when the sum of any two sides is greater \n than the third side.\n \n Example:\n triangle_area(3, 4, 5) == 6.00\n triangle_area(1, 2, 10) == -1\n '''\n # Check for valid triangle\n if a + b > c and a + c > b and b + c > a:\n # Calculate the semi-perimeter\n s = (a + b + c) / 2\n # Calculate the area using Heron's formula\n area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n return round(area, 2)\n else:\n return -1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n else:\n return lst2", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n \"\"\"\n Given an array arr of integers, find the minimum number of elements that\n need to be changed to make the array palindromic. A palindromic array is an array that\n is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n For example:\n smallest_change([1,2,3,5,4,7,9,6]) == 4\n smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n smallest_change([1, 2, 3, 2, 1]) == 0\n \"\"\"\n n = len(arr)\n changes = 0\n \n for i in range(n // 2):\n if arr[i] != arr[n - 1 - i]:\n changes += 1\n \n return changes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef get_primes_up_to(max_num):\n \"\"\"Return a list of all prime numbers up to max_num.\"\"\"\n return [num for num in range(2, max_num) if is_prime(num)]\ndef is_multiply_prime(a):\n \"\"\"Return True if the given number is the multiplication of 3 prime numbers, False otherwise.\"\"\"\n if a >= 100:\n return False\n \n primes = get_primes_up_to(a)\n prime_count = len(primes)\n \n # Check all combinations of three primes\n for i in range(prime_count):\n for j in range(i, prime_count):\n for k in range(j, prime_count):\n product = primes[i] * primes[j] * primes[k]\n if product == a:\n return True\n if product > a:\n break # No need to check further if product exceeds a\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n \"\"\"Returns True if x is a simple power of n, otherwise False.\n \n A number x is a simple power of n if there exists an integer k such that n**k = x.\n \n Args:\n x (int): The number to check.\n n (int): The base number.\n \n Returns:\n bool: True if x is a simple power of n, False otherwise.\n \"\"\"\n if n <= 1:\n return x == n # n must be greater than 1 for powers to be meaningful\n \n power = 1\n while True:\n result = n ** power\n if result == x:\n return True\n elif result > x:\n return False\n power += 1", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1, 12]], "plus_fail_tests": []}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this integer is a cube of some integer number.\n Note: you may assume the input is always valid.\n \n Examples:\n iscube(1) ==> True\n iscube(2) ==> False\n iscube(-1) ==> True\n iscube(64) ==> True\n iscube(0) ==> True\n iscube(180) ==> False\n '''\n # Calculate the cube root of the absolute value of a\n cube_root = round(abs(a) ** (1/3))\n \n # Check if the cube of the rounded cube root equals the absolute value of a\n return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n \"\"\"Convert a decimal number to binary format with specific formatting.\n\n Args:\n decimal (int): A number in decimal form.\n\n Returns:\n str: A string representing the binary format of the number, \n with 'db' at the beginning and end.\n \"\"\"\n # Convert the decimal number to binary and remove the '0b' prefix\n binary_representation = bin(decimal)[2:]\n # Format the result with 'db' at the beginning and end\n formatted_result = f\"db{binary_representation}db\"\n return formatted_result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n \"\"\"Count the number of prime hexadecimal digits in the given string.\"\"\"\n # Define the set of prime hexadecimal digits\n prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n \n # Initialize a counter for prime digits\n count = 0\n \n # Iterate through each character in the input string\n for char in num:\n # Check if the character is in the set of prime hexadecimal digits\n if char in prime_hex_digits:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n \"\"\"You are given a string s.\n Your task is to check if the string is happy or not.\n A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n \n For example:\n is_happy(a) => False\n is_happy(aa) => False\n is_happy(abcd) => True\n is_happy(aabb) => False\n is_happy(adb) => True\n is_happy(xyy) => False\n \"\"\"\n # Check if the length of the string is at least 3\n if len(s) < 3:\n return False\n \n # Check every 3 consecutive letters\n for i in range(len(s) - 2):\n if len(set(s[i:i+3])) < 3: # If there are not 3 distinct letters\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n letter_grades = []\n \n for gpa in grades:\n if gpa == 4.0:\n letter_grades.append('A+')\n elif gpa > 3.7:\n letter_grades.append('A')\n elif gpa > 3.3:\n letter_grades.append('A-')\n elif gpa > 3.0:\n letter_grades.append('B+')\n elif gpa > 2.7:\n letter_grades.append('B')\n elif gpa > 2.3:\n letter_grades.append('B-')\n elif gpa > 2.0:\n letter_grades.append('C+')\n elif gpa > 1.7:\n letter_grades.append('C')\n elif gpa > 1.3:\n letter_grades.append('C-')\n elif gpa > 1.0:\n letter_grades.append('D+')\n elif gpa > 0.7:\n letter_grades.append('D')\n elif gpa > 0.0:\n letter_grades.append('D-')\n else:\n letter_grades.append('E')\n \n return letter_grades", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef prime_length(string):\n \"\"\"Check if the length of the string is a prime number.\"\"\"\n length = len(string)\n return is_prime(length)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits will be 1 the output should be \"1\".\n For N = 150, the sum of digits will be 6 the output should be \"110\".\n For N = 147, the sum of digits will be 12 the output should be \"1100\".\n \n Variables:\n @N integer\n Constraints: 0 \u2264 N \u2264 10000.\n Output:\n a string of binary number\n \"\"\"\n # Calculate the sum of the digits of N\n digit_sum = sum(int(digit) for digit in str(N))\n \n # Convert the sum to binary and return it as a string\n return bin(digit_sum)[2:]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n \"\"\"\n Given a positive integer n, return the count of the numbers of n-digit\n positive integers that start or end with 1.\n \"\"\"\n if n < 1:\n return 0\n\n # Total n-digit numbers\n total_n_digit_numbers = 9 * (10 ** (n - 1))\n\n # Count of n-digit numbers that start with 1\n start_with_1 = 10 ** (n - 1)\n\n # Count of n-digit numbers that end with 1\n end_with_1 = total_n_digit_numbers // 10\n\n # Count of n-digit numbers that start and end with 1\n start_and_end_with_1 = 10 ** (n - 2) if n > 1 else 0\n\n # Total count of n-digit numbers that start or end with 1\n count = start_with_1 + end_with_1 - start_and_end_with_1\n\n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words while preserving spaces\n words = s.split(' ')\n \n # Sort each word and keep the spaces intact\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back with spaces\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n \n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by row index (ascending) and then by column index (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n or sort it in descending order if the sum( first index value, last index value) is even.\n\n Note:\n * don't change the given array.\n\n Examples:\n * sort_array([]) => []\n * sort_array([5]) => [5]\n * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n \"\"\"\n if not array: # Check if the array is empty\n return []\n \n first_value = array[0]\n last_value = array[-1]\n sum_values = first_value + last_value\n\n # Sort in ascending order if the sum is odd, otherwise sort in descending order\n if sum_values % 2 == 1:\n return sorted(array) # Ascending order\n else:\n return sorted(array, reverse=True) # Descending order", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted = []\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Calculate the new character by shifting it down the alphabet\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n encrypted.append(new_char)\n else:\n encrypted.append(char) # Non-alphabetic characters remain unchanged\n return ''.join(encrypted)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Sort the unique elements\n sorted_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_elements[1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n \n For example:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n \"\"\"\n # Split the string into sentences using the delimiters\n sentences = []\n current_sentence = []\n for char in S:\n if char in '.!?':\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n current_sentence = []\n else:\n current_sentence.append(char)\n if current_sentence: # Add the last sentence if it exists\n sentences.append(''.join(current_sentence).strip())\n \n # Count the number of sentences that start with \"I\"\n boredom_count = sum(1 for sentence in sentences if sentence.startswith('I'))\n \n return boredom_count", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n '''\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n \n Examples\n any_int(5, 2, 7) \u279e True\n any_int(3, 2, 2) \u279e False\n any_int(3, -2, 1) \u279e True\n any_int(3.6, -2.2, 2) \u279e False\n '''\n # Check if all inputs are integers\n if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n # Check if one number is equal to the sum of the other two\n return x == y + z or y == x + z or z == x + y\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef sum_of_digits(n):\n \"\"\"Return the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n largest_prime = None\n \n for number in lst:\n if is_prime(number):\n if largest_prime is None or number > largest_prime:\n largest_prime = number\n \n if largest_prime is not None:\n return sum_of_digits(largest_prime)\n else:\n return 0 # Return 0 if no prime is found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n \"\"\"\n Write a function that takes a message, and encodes in such a \n way that it swaps case of all letters, replaces all vowels in \n the message with the letter that appears 2 places ahead of that \n vowel in the english alphabet. \n Assume only letters. \n \n Examples:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n vowels = 'aeiouAEIOU'\n encoded_message = []\n\n for char in message:\n if char.isalpha(): # Check if the character is a letter\n # Swap case\n if char in vowels:\n # Replace vowel with the letter 2 places ahead\n if char.islower():\n new_char = chr(((ord(char) - ord('a') + 2) % 26) + ord('a'))\n else:\n new_char = chr(((ord(char) - ord('A') + 2) % 26) + ord('A'))\n else:\n new_char = char.swapcase() # Swap case for consonants\n encoded_message.append(new_char)\n else:\n encoded_message.append(char) # Keep non-letter characters unchanged\n\n return ''.join(encoded_message)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["TEST"]], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in lower \n case or all keys are strings in upper case, else return False.\n The function should return False if the given dictionary is empty.\n \n Examples:\n check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n \"\"\"\n if not input_dict:\n return False\n\n all_lower = all(isinstance(key, str) and key.islower() for key in input_dict.keys())\n all_upper = all(isinstance(key, str) and key.isupper() for key in input_dict.keys())\n\n return all_lower or all_upper", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_up_to(n):\n \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n primes = []\n for i in range(2, n):\n if is_prime(i):\n primes.append(i)\n return primes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.\n \"\"\"\n # Get the unit digit of the first number\n unit_digit_a = abs(a) % 10\n # Get the unit digit of the second number\n unit_digit_b = abs(b) % 10\n # Return the product of the unit digits\n return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n count_upper('aBCdEf') returns 1\n count_upper('abcdefg') returns 0\n count_upper('dBBE') returns 0\n \"\"\"\n uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n count = 0\n \n for i in range(0, len(s), 2): # Iterate over even indices\n if s[i] in uppercase_vowels:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n >>> closest_integer(\"14.5\")\n 15\n >>> closest_integer(\"-14.5\")\n -15\n >>> closest_integer(\"0.5\")\n 1\n >>> closest_integer(\"-0.5\")\n -1\n '''\n\n # Convert the string value to a float\n num = float(value)\n \n # Calculate the floor and ceiling of the number\n lower = int(num // 1) # This is the floor of the number\n upper = lower + 1 # This is the ceiling of the number\n\n # Check if the number is equidistant from lower and upper\n if abs(num - lower) < abs(num - upper):\n return lower\n elif abs(num - lower) > abs(num - upper):\n return upper\n else:\n # If equidistant, round away from zero\n if num > 0:\n return upper\n else:\n return lower", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n \"\"\"\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n >>> make_a_pile(4)\n [4, 6, 8, 10]\n >>> make_a_pile(1)\n [1]\n \"\"\"\n stones = []\n current_stones = n\n \n for i in range(n):\n stones.append(current_stones)\n if current_stones % 2 == 0: # current_stones is even\n current_stones += 2 # next even number\n else: # current_stones is odd\n current_stones += 2 # next odd number\n \n return stones", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n \"\"\"\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n \"\"\"\n # Split the string by commas and spaces, then filter out any empty strings\n words = [word.strip() for word in s.replace(',', ' ').split() if word]\n return words", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n \"\"\"This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If \n there's no such number, then the function should return -1.\n\n For example:\n choose_num(12, 15) = 14\n choose_num(13, 12) = -1\n \"\"\"\n # Ensure x is less than or equal to y\n if x > y:\n return -1\n \n # Start from the largest number in the range and check for evenness\n for num in range(y, x - 1, -1):\n if num % 2 == 0:\n return num\n \n return -1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n \"\"\"You are given two positive integers n and m, and your task is to compute the\n average of the integers from n through m (including n and m). \n Round the answer to the nearest integer and convert that to binary.\n If n is greater than m, return -1.\n \n Example:\n rounded_avg(1, 5) => \"0b11\"\n rounded_avg(7, 5) => -1\n rounded_avg(10, 20) => \"0b1111\"\n rounded_avg(20, 33) => \"0b11010\"\n \"\"\"\n if n > m:\n return -1\n \n # Calculate the sum of integers from n to m\n total_sum = sum(range(n, m + 1))\n count = m - n + 1 # Total numbers from n to m\n \n # Calculate the average and round it\n average = total_sum / count\n rounded_average = round(average)\n \n # Convert the rounded average to binary\n return bin(rounded_average)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n \"\"\"Given a list of positive integers x, return a sorted list of all \n elements that haven't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n def has_even_digit(n):\n \"\"\"Check if the number has any even digit.\"\"\"\n for digit in str(n):\n if int(digit) % 2 == 0:\n return True\n return False\n\n # Filter the list to include only numbers without even digits\n result = [num for num in x if not has_even_digit(num)]\n \n # Return the sorted result\n return sorted(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def factorial(i):\n \"\"\"Calculate the factorial of a given number i.\"\"\"\n if i == 0 or i == 1:\n return 1\n result = 1\n for j in range(2, i + 1):\n result *= j\n return result\ndef sum_of_numbers(i):\n \"\"\"Calculate the sum of numbers from 1 to i.\"\"\"\n return (i * (i + 1)) // 2\ndef f(n):\n \"\"\"Return a list of size n, where the value at index i is the factorial of i if i is even,\n or the sum of numbers from 1 to i otherwise. Indexing starts from 1.\"\"\"\n result = []\n for i in range(1, n + 1):\n if i % 2 == 0: # i is even\n result.append(factorial(i))\n else: # i is odd\n result.append(sum_of_numbers(i))\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n reverse the resulting array, and then replace each digit by its corresponding name from\n \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n For example:\n arr = [2, 1, 1, 4, 5, 8, 2, 3] \n -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n \n If the array is empty, return an empty array:\n arr = []\n return []\n \n If the array has any strange number ignore it:\n arr = [1, -1 , 55] \n -> sort arr -> [-1, 1, 55]\n -> reverse arr -> [55, 1, -1]\n return = ['One']\n \"\"\"\n \n # Mapping of digits to their corresponding names\n digit_to_name = {\n 1: \"One\",\n 2: \"Two\",\n 3: \"Three\",\n 4: \"Four\",\n 5: \"Five\",\n 6: \"Six\",\n 7: \"Seven\",\n 8: \"Eight\",\n 9: \"Nine\"\n }\n \n # Filter the array to include only numbers between 1 and 9\n filtered_arr = [num for num in arr if 1 <= num <= 9]\n \n # Sort the filtered array\n sorted_arr = sorted(filtered_arr)\n \n # Reverse the sorted array\n reversed_arr = sorted_arr[::-1]\n \n # Convert the digits to their corresponding names\n result = [digit_to_name[num] for num in reversed_arr]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n \"\"\"\n Given a positive integer n, return a tuple that has the number of even and odd\n integer palindromes that fall within the range(1, n), inclusive.\n\n Example 1:\n Input: 3\n Output: (1, 2)\n Explanation:\n Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n Example 2:\n Input: 12\n Output: (4, 6)\n Explanation:\n Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n Note:\n 1. 1 <= n <= 10^3\n 2. returned tuple has the number of even and odd integer palindromes respectively.\n \"\"\"\n \n def is_palindrome(num):\n return str(num) == str(num)[::-1]\n\n even_count = 0\n odd_count = 0\n\n for i in range(1, n + 1):\n if is_palindrome(i):\n if i % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n \"\"\"\n Write a function count_nums which takes an array of integers and returns\n the number of elements which has a sum of digits > 0.\n If a number is negative, then its first signed digit will be negative:\n e.g. -123 has signed digits -1, 2, and 3.\n \n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n def sum_of_digits(n):\n # Convert the number to string and calculate the sum of its digits\n return sum(int(digit) if n >= 0 else -int(digit) if i == 0 else int(digit)\n for i, digit in enumerate(str(abs(n))) if digit.isdigit())\n\n count = 0\n for number in arr:\n if sum_of_digits(number) > 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return True else return False.\n If the given array is empty then return True.\n\n Note: The given list is guaranteed to have unique elements.\n\n For Example:\n \n move_one_ball([3, 4, 5, 1, 2])==>True\n Explanation: By performing 2 right shift operations, non-decreasing order can\n be achieved for the given array.\n move_one_ball([3, 5, 4, 1, 2])==>False\n Explanation: It is not possible to get non-decreasing order for the given\n array by performing any number of right shift operations.\n \"\"\"\n if not arr:\n return True\n\n n = len(arr)\n sorted_arr = sorted(arr)\n \n # Check for the number of \"breaks\" in the sorted array\n break_count = 0\n for i in range(n):\n if arr[i] > arr[(i + 1) % n]:\n break_count += 1\n\n # If there are more than one break, we cannot sort the array with shifts\n return break_count <= 1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n \"\"\"Determines whether it is possible to perform an exchange of elements\n between two lists to make lst1 a list of only even numbers.\n \n Args:\n lst1 (list): The first list of numbers.\n lst2 (list): The second list of numbers.\n \n Returns:\n str: \"YES\" if lst1 can be made all even, \"NO\" otherwise.\n \"\"\"\n # Check if lst1 already contains only even numbers\n if all(x % 2 == 0 for x in lst1):\n return \"YES\"\n \n # Count the number of odd numbers in lst1\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n \n # Check if lst2 has at least one even number to exchange\n has_even_in_lst2 = any(x % 2 == 0 for x in lst2)\n \n # If lst1 has odd numbers and lst2 has at least one even number, we can exchange\n if odd_count_lst1 > 0 and has_even_in_lst2:\n return \"YES\"\n \n return \"NO\"", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 3, 4], [1, 5, 3, 4]]], "plus_fail_tests": []}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n \"\"\"Task\n We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and True/False for the check.\n Example\n For s = \"abcde\", c = \"ae\", the result should be ('bcd',False)\n For s = \"abcdef\", c = \"b\" the result should be ('acdef',False)\n For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc',True)\n \"\"\"\n # Create a set of characters to delete for faster lookup\n delete_set = set(c)\n \n # Create the result string by filtering out characters in delete_set\n result = ''.join(char for char in s if char not in delete_set)\n \n # Check if the result string is a palindrome\n is_palindrome = result == result[::-1]\n \n return (result, is_palindrome)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n \"\"\"\n if not test:\n return {}\n\n # Split the input string into a list of letters\n letters = test.split()\n \n # Create a dictionary to count occurrences of each letter\n count_dict = {}\n for letter in letters:\n if letter in count_dict:\n count_dict[letter] += 1\n else:\n count_dict[letter] = 1\n\n # Find the maximum count\n max_count = max(count_dict.values())\n \n # Create a result dictionary for letters with the maximum count\n result = {letter: count for letter, count in count_dict.items() if count == max_count}\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n Example\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n \"\"\"\n if not nums:\n return 0 # Handle the case of an empty array\n\n min_sum = float('inf')\n current_sum = 0\n\n for num in nums:\n current_sum += num\n min_sum = min(min_sum, current_sum)\n if current_sum > 0:\n current_sum = 0 # Reset current_sum if it becomes positive\n\n return min_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n \"\"\"\n Calculate the number of times buckets need to be lowered to empty the wells.\n\n Parameters:\n grid (list of list of int): A rectangular grid representing wells.\n capacity (int): The capacity of each bucket.\n\n Returns:\n int: The total number of times buckets need to be lowered.\n \"\"\"\n total_water = 0\n \n # Count the total amount of water in the grid\n for row in grid:\n total_water += sum(row)\n \n # Calculate the number of times buckets need to be lowered\n # Each bucket can carry 'capacity' units of water\n if total_water == 0:\n return 0\n else:\n return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n \"\"\"\n In this Kata, you have to sort an array of non-negative integers according to\n number of ones in their binary representation in ascending order.\n For similar number of ones, sort based on decimal value.\n\n It must be implemented like this:\n >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n >>> sort_array([1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]\n \"\"\"\n # Sort the array using a custom key\n return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n \"\"\"Given a string s and a natural number n, returns a list of all words from string s \n that contain exactly n consonants, in the order they appear in the string s.\n \n Args:\n s (str): The input string containing words.\n n (int): The number of consonants to filter words by.\n \n Returns:\n list: A list of words containing exactly n consonants.\n \"\"\"\n if not s:\n return []\n\n # Define a set of consonants\n consonants = set(\"bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ\")\n \n # Split the string into words\n words = s.split()\n \n # Function to count consonants in a word\n def count_consonants(word):\n return sum(1 for char in word if char in consonants)\n \n # Filter words that have exactly n consonants\n result = [word for word in words if count_consonants(word) == n]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n two consonants from the right side of the word (case sensitive).\n \n Vowels in the beginning and ending don't count. Return empty string if you didn't\n find any vowel that meets the above condition. \n\n You may assume that the given string contains English letters only.\n\n Example:\n get_closest_vowel(\"yogurt\") ==> \"u\"\n get_closest_vowel(\"FULL\") ==> \"U\"\n get_closest_vowel(\"quick\") ==> \"\"\n get_closest_vowel(\"ab\") ==> \"\"\n \"\"\"\n vowels = \"aeiouAEIOU\"\n n = len(word)\n\n # Start from the end of the word\n for i in range(n - 2, 0, -1): # Start from the second last character to the second character\n if word[i] in vowels:\n # Check if there are consonants on both sides\n if word[i - 1].isalpha() and word[i + 1].isalpha() and word[i - 1] not in vowels and word[i + 1] not in vowels:\n return word[i]\n \n return \"\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0: # More closing than opening\n return False\n return balance == 0 # Must be balanced at the end\n\n # Check both concatenation orders\n return 'Yes' if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]) else 'No'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Get the top k elements\n top_k = sorted_arr[:k]\n # Sort the result in ascending order before returning\n return sorted(top_k)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n \"\"\"\n Given a non-empty array of integers arr and an integer k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example:\n\n Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n Output: 24 # sum of 21 + 3\n\n Constraints:\n 1. 1 <= len(arr) <= 100\n 2. 1 <= k <= len(arr)\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate through the first k elements of the array\n for i in range(k):\n # Check if the element has at most two digits\n if -100 < arr[i] < 100:\n total_sum += arr[i]\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n \n The date is valid if all of the following rules are satisfied:\n 1. The date string is not empty.\n 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n The number of days is not less than 1 or higher than 29 for the month 2.\n 3. The months should not be less than 1 or higher than 12.\n 4. The date should be in the format: mm-dd-yyyy\n \n Args:\n date (str): The date string to validate.\n \n Returns:\n bool: True if the date is valid, False otherwise.\n \"\"\"\n if not date:\n return False\n \n # Check the format\n if len(date) != 10 or date[2] != '-' or date[5] != '-':\n return False\n \n try:\n month, day, year = map(int, date.split('-'))\n except ValueError:\n return False\n \n # Validate month\n if month < 1 or month > 12:\n return False\n \n # Validate day based on month\n if month in {1, 3, 5, 7, 8, 10, 12}:\n if day < 1 or day > 31:\n return False\n elif month in {4, 6, 9, 11}:\n if day < 1 or day > 30:\n return False\n elif month == 2:\n if day < 1 or day > 29:\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n as follows: start with any positive integer n. Then each term is obtained from the \n previous term as follows: if the previous term is even, the next term is one half of \n the previous term. If the previous term is odd, the next term is 3 times the previous\n term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n Note: \n 1. Collatz(1) is [1].\n 2. returned list sorted in increasing order.\n\n For example:\n get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n collatz_sequence = []\n current = n\n \n while current != 1:\n collatz_sequence.append(current)\n if current % 2 == 0:\n current //= 2\n else:\n current = 3 * current + 1\n \n collatz_sequence.append(1) # Add the last term, which is 1\n \n # Filter odd numbers and sort them\n odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n \n return odd_numbers", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n '''\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return False. Assume no negative numbers and only integers.\n\n Examples\n is_sorted([5]) \u279e True\n is_sorted([1, 2, 3, 4, 5]) \u279e True\n is_sorted([1, 3, 2, 4, 5]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n '''\n if not lst: # An empty list is considered sorted\n return True\n\n seen = set()\n last = None\n\n for num in lst:\n if num in seen:\n # If we see a number more than once, return False\n return False\n seen.add(num)\n\n if last is not None and num < last:\n # If the current number is less than the last number, return False\n return False\n \n last = num\n\n return True", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n '''\n Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n Examples\n split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"abcdef\") == 3 \n '''\n # Check for whitespace in the text\n if ' ' in txt:\n return txt.split()\n \n # Check for commas in the text\n elif ',' in txt:\n return txt.split(',')\n \n # If no whitespace or commas, count lower-case letters with odd order\n else:\n odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n return odd_count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n if not arr:\n return None\n\n product_of_signs = 1\n sum_of_magnitudes = 0\n\n for num in arr:\n if num > 0:\n product_of_signs *= 1\n sum_of_magnitudes += num\n elif num < 0:\n product_of_signs *= -1\n sum_of_magnitudes += -num\n else: # num == 0\n product_of_signs = 0\n break\n\n return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef intersection(interval1, interval2):\n \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n start1, end1 = interval1\n start2, end2 = interval2\n \n # Find the intersection\n start_intersection = max(start1, start2)\n end_intersection = min(end1, end2)\n \n # Check if there is an intersection\n if start_intersection > end_intersection:\n return \"NO\"\n \n # Calculate the length of the intersection\n length_of_intersection = end_intersection - start_intersection\n \n # Check if the length is a prime number\n if is_prime(length_of_intersection):\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n \"\"\"Calculate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n if n < 0:\n return []\n\n # Initialize the list to store the Tribonacci numbers\n tribonacci_sequence = []\n\n # Define the base case\n for i in range(n + 1):\n if i == 0:\n tribonacci_sequence.append(1) # tri(0) = 1\n elif i == 1:\n tribonacci_sequence.append(3) # tri(1) = 3\n elif i % 2 == 0: # n is even\n tribonacci_sequence.append(1 + i / 2)\n else: # n is odd\n # Calculate tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1)\n tri_n_minus_1 = tribonacci_sequence[i - 1]\n tri_n_minus_2 = tribonacci_sequence[i - 2]\n tri_n_plus_1 = 3 if i + 1 == 1 else tribonacci_sequence[i + 1] if i + 1 < len(tribonacci_sequence) else 0\n tribonacci_sequence.append(tri_n_minus_1 + tri_n_minus_2 + tri_n_plus_1)\n\n return tribonacci_sequence", "base_status": "fail", "plus_status": null, "base_fail_tests": [[3]], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n from collections import deque\n\n N = len(grid)\n directions = [(0, 1), (1, 0), (0, -1), (-1, 0)] # right, down, left, up\n min_path = None\n\n def bfs(start_x, start_y):\n nonlocal min_path\n queue = deque([(start_x, start_y, [grid[start_x][start_y]])])\n visited = set()\n visited.add((start_x, start_y))\n\n while queue:\n x, y, path = queue.popleft()\n\n if len(path) == k:\n if min_path is None or path < min_path:\n min_path = path\n continue\n\n for dx, dy in directions:\n nx, ny = x + dx, y + dy\n if 0 <= nx < N and 0 <= ny < N:\n queue.append((nx, ny, path + [grid[nx][ny]]))\n\n for i in range(N):\n for j in range(N):\n bfs(i, j)\n\n return min_path", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n \"\"\"Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n For example:\n digits(1) == 1\n digits(4) == 0\n digits(235) == 15\n \"\"\"\n product = 1\n has_odd = False\n \n for digit in str(n):\n digit = int(digit)\n if digit % 2 != 0: # Check if the digit is odd\n product *= digit\n has_odd = True\n \n return product if has_odd else 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n '''\n Create a function that takes a string as input which contains only square brackets.\n The function should return True if and only if there is a valid subsequence of brackets \n where at least one bracket in the subsequence is nested.\n\n is_nested('[[]]') \u279e True\n is_nested('[]]]]]]][[[[[]') \u279e False\n is_nested('[][]') \u279e False\n is_nested('[]') \u279e False\n is_nested('[[][]]') \u279e True\n is_nested('[[]][[') \u279e True\n '''\n # Initialize a counter for open brackets\n open_count = 0\n # Initialize a flag to check for nesting\n nested = False\n \n for char in string:\n if char == '[':\n open_count += 1\n # If we have seen at least one open bracket before, we can have nesting\n if open_count > 1:\n nested = True\n elif char == ']':\n open_count -= 1\n # If we close a bracket and we had opened brackets, we can check for nesting\n if open_count < 0:\n return False # More closing brackets than opening\n # If we have nested brackets, we can return True early\n if nested and open_count == 0:\n return True\n \n # Return True if we found nesting and all brackets are closed\n return nested and open_count == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers.\n You need to return the sum of squared numbers in the given list,\n round each element in the list to the upper int (Ceiling) first.\n \n Examples:\n For lst = [1,2,3] the output should be 14\n For lst = [1,4,9] the output should be 98\n For lst = [1,3,5,7] the output should be 84\n For lst = [1.4,4.2,0] the output should be 29\n For lst = [-2.4,1,1] the output should be 6\n \"\"\"\n return sum(math.ceil(x) ** 2 for x in lst)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n \"\"\"Create a function which returns the largest index of an element which\n is not greater than or equal to the element immediately preceding it. If\n no such element exists then return -1. The given array will not contain\n duplicate values.\n\n Examples:\n can_arrange([1,2,4,3,5]) = 3\n can_arrange([1,2,3]) = -1\n \"\"\"\n # Initialize the index to -1 (indicating no such element found)\n largest_index = -1\n \n # Iterate through the array starting from the second element\n for i in range(1, len(arr)):\n # Check if the current element is less than the previous one\n if arr[i] < arr[i - 1]:\n largest_index = i # Update the largest index found\n \n return largest_index", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n '''\n Create a function that returns True if the last character\n of a given string is an alphabetical character and is not\n a part of a word, and False otherwise.\n Note: \"word\" is a group of characters separated by space.\n\n Examples:\n check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '''\n # Strip any trailing whitespace from the string\n txt = txt.rstrip()\n \n # Check if the string is empty after stripping\n if not txt:\n return False\n \n # Get the last character of the string\n last_char = txt[-1]\n \n # Check if the last character is an alphabetical character\n if last_char.isalpha():\n # Check if the last character is part of a word\n # A character is part of a word if it is preceded by a non-space character\n if len(txt) > 1 and txt[-2] != ' ':\n return False\n return True\n \n return False", "base_status": "fail", "plus_status": null, "base_fail_tests": [["eeeee e "]], "plus_fail_tests": []}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def compare_one(a, b):\n \"\"\"\n Create a function that takes integers, floats, or strings representing\n real numbers, and returns the larger variable in its given variable type.\n Return None if the values are equal.\n Note: If a real number is represented as a string, the floating point might be . or ,\n\n compare_one(1, 2.5) \u279e 2.5\n compare_one(1, \"2,3\") \u279e \"2,3\"\n compare_one(\"5,1\", \"6\") \u279e \"6\"\n compare_one(\"1\", 1) \u279e None\n \"\"\"\n \n def parse_value(value):\n \"\"\"Convert the input value to a float or return it as is if it's not a number.\"\"\"\n if isinstance(value, str):\n # Replace ',' with '.' for float conversion\n value = value.replace(',', '.')\n try:\n return float(value)\n except ValueError:\n return value # Return the string if it cannot be converted\n return value # Return the number as is\n\n # Parse both values\n parsed_a = parse_value(a)\n parsed_b = parse_value(b)\n\n # Check for equality\n if parsed_a == parsed_b:\n return None\n\n # Return the larger value in its original type\n if parsed_a > parsed_b:\n return a\n else:\n return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n '''\n Create a function that returns a tuple (a, b), where 'a' is\n the largest of negative integers, and 'b' is the smallest\n of positive integers in a list.\n If there is no negative or positive integers, return them as None.\n\n Examples:\n largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n largest_smallest_integers([]) == (None, None)\n largest_smallest_integers([0]) == (None, None)\n '''\n largest_negative = None\n smallest_positive = None\n\n for num in lst:\n if num < 0:\n if largest_negative is None or num > largest_negative:\n largest_negative = num\n elif num > 0:\n if smallest_positive is None or num < smallest_positive:\n smallest_positive = num\n\n return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n \n Args:\n n (int): The number to evaluate.\n \n Returns:\n bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n \n Example:\n is_equal_to_sum_even(4) == False\n is_equal_to_sum_even(6) == False\n is_equal_to_sum_even(8) == True\n \"\"\"\n # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n if n < 8:\n return False\n \n # Check if n is even\n if n % 2 != 0:\n return False\n \n # If n is even and at least 8, it can be expressed as the sum of 4 positive even numbers\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n \"\"\"Calculate the factorial of a non-negative integer n.\"\"\"\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef special_factorial(n):\n \"\"\"Calculate the Brazilian factorial of n.\"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n result = 1\n for i in range(1, n + 1):\n result *= factorial(i)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n \"\"\"\n Given a string text, replace all spaces in it with underscores, \n and if a string has more than 2 consecutive spaces, \n then replace all consecutive spaces with - \n \n fix_spaces(\"Example\") == \"Example\"\n fix_spaces(\"Example 1\") == \"Example_1\"\n fix_spaces(\" Example 2\") == \"_Example_2\"\n fix_spaces(\" Example 3\") == \"_Example-3\"\n \"\"\"\n import re\n \n # Replace more than 2 consecutive spaces with a single '-'\n text = re.sub(r' {3,}', '-', text)\n \n # Replace single or double spaces with underscores\n text = text.replace(' ', '_')\n \n return text", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n \"\"\"Create a function which takes a string representing a file's name, and returns\n 'Yes' if the the file's name is valid, and returns 'No' otherwise.\n A file's name is considered to be valid if and only if all the following conditions \n are met:\n - There should not be more than three digits ('0'-'9') in the file's name.\n - The file's name contains exactly one dot '.'\n - The substring before the dot should not be empty, and it starts with a letter from \n the latin alphapet ('a'-'z' and 'A'-'Z').\n - The substring after the dot should be one of these: ['txt', 'exe', 'dll']\n Examples:\n file_name_check(\"example.txt\") # => 'Yes'\n file_name_check(\"1example.dll\") # => 'No' (the name should start with a latin alphapet letter)\n \"\"\"\n \n # Check for exactly one dot\n if file_name.count('.') != 1:\n return 'No'\n \n # Split the file name into name and extension\n name, extension = file_name.split('.')\n \n # Check if the name is empty or starts with a non-letter\n if not name or not name[0].isalpha():\n return 'No'\n \n # Check the number of digits in the name\n digit_count = sum(c.isdigit() for c in name)\n if digit_count > 3:\n return 'No'\n \n # Check if the extension is valid\n valid_extensions = ['txt', 'exe', 'dll']\n if extension not in valid_extensions:\n return 'No'\n \n return 'Yes'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n \"\"\"\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n \n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126\n \"\"\"\n total = 0\n for index, value in enumerate(lst):\n if index % 3 == 0:\n total += value ** 2 # Square if index is a multiple of 3\n elif index % 4 == 0:\n total += value ** 3 # Cube if index is a multiple of 4 and not a multiple of 3\n else:\n total += value # Leave unchanged if not a multiple of 3 or 4\n return total", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef words_in_sentence(sentence):\n \"\"\"\n You are given a string representing a sentence,\n the sentence contains some words separated by a space,\n and you have to return a string that contains the words from the original sentence,\n whose lengths are prime numbers,\n the order of the words in the new string should be the same as the original one.\n\n Example 1:\n Input: sentence = \"This is a test\"\n Output: \"is\"\n\n Example 2:\n Input: sentence = \"lets go for swimming\"\n Output: \"go for\"\n \"\"\"\n words = sentence.split()\n prime_length_words = [word for word in words if is_prime(len(word))]\n return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n \"\"\"Simplifies the expression x * n and checks if the result is a whole number.\n \n Args:\n x (str): A string representation of a fraction in the format '/'.\n n (str): A string representation of a fraction in the format '/'.\n \n Returns:\n bool: True if x * n evaluates to a whole number, False otherwise.\n \"\"\"\n # Split the fractions into numerator and denominator\n x_numerator, x_denominator = map(int, x.split('/'))\n n_numerator, n_denominator = map(int, n.split('/'))\n \n # Calculate the product of the fractions\n # (x_numerator / x_denominator) * (n_numerator / n_denominator) = (x_numerator * n_numerator) / (x_denominator * n_denominator)\n product_numerator = x_numerator * n_numerator\n product_denominator = x_denominator * n_denominator\n \n # Check if the product is a whole number\n return product_numerator % product_denominator == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n \"\"\"\n Write a function which sorts the given list of integers\n in ascending order according to the sum of their digits.\n Note: if there are several items with similar sum of their digits,\n order them based on their index in original list.\n\n For example:\n >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n >>> order_by_points([]) == []\n \"\"\"\n \n def digit_sum(n):\n \"\"\"Calculate the sum of the digits of n.\"\"\"\n return sum(int(digit) for digit in str(abs(n)))\n\n # Sort the list based on the sum of digits and original index\n return sorted(nums, key=lambda x: (digit_sum(x), nums.index(x)))", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n \"\"\"Write a function that takes an array of numbers as input and returns \n the number of elements in the array that are greater than 10 and both \n first and last digits of a number are odd (1, 3, 5, 7, 9).\n \n For example:\n specialFilter([15, -73, 14, -15]) => 1 \n specialFilter([33, -2, -3, 45, 21, 109]) => 2\n \"\"\"\n \n def is_odd_digit(digit):\n return digit in {'1', '3', '5', '7', '9'}\n \n count = 0\n for num in nums:\n if num > 10:\n str_num = str(abs(num)) # Convert to string and take absolute value\n if is_odd_digit(str_num[0]) and is_odd_digit(str_num[-1]):\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n \"\"\"\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example :\n Input: n = 5\n Output: 1\n Explanation: \n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n \"\"\"\n # Create the array a\n a = [i * i - i + 1 for i in range(1, n + 1)]\n \n # Count the number of valid triples\n count = 0\n for i in range(n):\n for j in range(i + 1, n):\n for k in range(j + 1, n):\n if (a[i] + a[j] + a[k]) % 3 == 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closest to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sorted by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct planet names. \n Examples\n bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n '''\n\n planets = [\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n ]\n \n if planet1 not in planets or planet2 not in planets:\n return ()\n \n index1 = planets.index(planet1)\n index2 = planets.index(planet2)\n \n # Ensure index1 is less than index2 for slicing\n start_index = min(index1, index2) + 1\n end_index = max(index1, index2)\n \n return tuple(planets[start_index:end_index])", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length and alphabetically.\n \n Args:\n lst (list): A list of strings.\n \n Returns:\n list: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef x_or_y(n, x, y):\n \"\"\"Return the value of x if n is a prime number, otherwise return y.\"\"\"\n if is_prime(n):\n return x\n else:\n return y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n \n double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n double_the_difference([-1, -2, 0]) == 0\n double_the_difference([9, -2]) == 81\n double_the_difference([0]) == 0 \n \n If the input list is empty, return 0.\n '''\n if not lst: # Check if the list is empty\n return 0\n \n return sum(x**2 for x in lst if isinstance(x, int) and x >= 0 and x % 2 != 0)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n \"\"\"Compares the actual game scores with the guessed scores and returns the absolute differences.\n \n Args:\n game (list of int): The actual scores of the matches.\n guess (list of int): The guessed scores of the matches.\n \n Returns:\n list of int: A list containing the absolute differences between the actual scores and the guessed scores.\n If the guess is correct, the value is 0.\n \"\"\"\n return [abs(g - a) for a, g in zip(game, guess)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n \"\"\"Find the strongest extension based on the strength defined by the number of uppercase and lowercase letters.\"\"\"\n def calculate_strength(extension):\n CAP = sum(1 for char in extension if char.isupper())\n SM = sum(1 for char in extension if char.islower())\n return CAP - SM\n\n strongest_extension = None\n strongest_strength = float('-inf')\n\n for extension in extensions:\n strength = calculate_strength(extension)\n if strength > strongest_strength:\n strongest_strength = strength\n strongest_extension = extension\n\n return f\"{class_name}.{strongest_extension}\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n \"\"\"You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word.\n \n Args:\n a (str): The first word.\n b (str): The second word.\n \n Returns:\n bool: True if the second word or any of its rotations is a substring in the first word, False otherwise.\n \n Examples:\n >>> cycpattern_check(\"abcd\", \"abd\")\n False\n >>> cycpattern_check(\"hello\", \"ell\")\n True\n >>> cycpattern_check(\"whassup\", \"psus\")\n False\n >>> cycpattern_check(\"abab\", \"baa\")\n True\n >>> cycpattern_check(\"efef\", \"eeff\")\n False\n >>> cycpattern_check(\"himenss\", \"simen\")\n True\n \"\"\"\n # Create a string that contains two copies of b\n b_rotations = b + b\n \n # Check if any rotation of b is a substring of a\n return b in b_rotations and len(b) <= len(a)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["xyzw", "xyw"]], "plus_fail_tests": []}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n Example:\n even_odd_count(-12) ==> (1, 1)\n even_odd_count(123) ==> (1, 2)\n \"\"\"\n # Convert the number to a string and remove the sign if it's negative\n num_str = str(abs(num))\n \n even_count = 0\n odd_count = 0\n \n # Iterate through each character in the string representation of the number\n for digit in num_str:\n if digit.isdigit(): # Check if the character is a digit\n if int(digit) % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n if not (1 <= number <= 1000):\n raise ValueError(\"Number must be between 1 and 1000\")\n\n roman_numerals = [\n (1000, 'm'),\n (900, 'cm'),\n (500, 'd'),\n (400, 'cd'),\n (100, 'c'),\n (90, 'xc'),\n (50, 'l'),\n (40, 'xl'),\n (10, 'x'),\n (9, 'ix'),\n (5, 'v'),\n (4, 'iv'),\n (1, 'i')\n ]\n\n result = []\n for value, numeral in roman_numerals:\n while number >= value:\n result.append(numeral)\n number -= value\n\n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n \"\"\"Write a function that accepts a list of strings.\n The list contains different words. Return the word with maximum number\n of unique characters. If multiple strings have maximum number of unique\n characters, return the one which comes first in lexicographical order.\n\n find_max([\"name\", \"of\", \"string\"]) == \"string\"\n find_max([\"name\", \"enam\", \"game\"]) == \"enam\"\n find_max([\"aaaaaaa\", \"bb\" ,\"cc\"]) == \"aaaaaaa\"\n \"\"\"\n max_word = \"\"\n max_unique_count = 0\n\n for word in words:\n unique_chars = set(word)\n unique_count = len(unique_chars)\n\n if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n max_word = word\n max_unique_count = unique_count\n\n return max_word", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return True if the three\n sides form a right-angled triangle, False otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or \n 90 degree.\n \n Example:\n right_angle_triangle(3, 4, 5) == True\n right_angle_triangle(1, 2, 3) == False\n '''\n # Sort the sides to identify the longest side\n sides = sorted([a, b, c])\n \n # Check the Pythagorean theorem\n return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic algebra operations, and \n the second list is a list of integers. Use the two given lists to build the algebraic \n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + ) \n Subtraction ( - ) \n Multiplication ( * ) \n Floor division ( // ) \n Exponentiation ( ** ) \n\n Example:\n operator = ['+', '*', '-']\n operand = [2, 3, 4, 5]\n result = do_algebra(operator, operand)\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.\n \"\"\"\n \n # Start with the first operand\n result = operand[0]\n \n # Iterate through the operators and operands\n for i in range(len(operator)):\n op = operator[i]\n next_operand = operand[i + 1]\n \n if op == '+':\n result += next_operand\n elif op == '-':\n result -= next_operand\n elif op == '*':\n result *= next_operand\n elif op == '//':\n result //= next_operand\n elif op == '**':\n result **= next_operand\n else:\n raise ValueError(f\"Invalid operator: {op}\")\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": []}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n \"\"\"\n You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n \n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n \n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots that exist in stock\n \n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n \"\"\"\n # Calculate how many more carrots are needed\n additional_needed = need - number\n \n # If no additional carrots are needed, return the current state\n if additional_needed <= 0:\n return [number, remaining]\n \n # Determine how many carrots can be eaten from the remaining stock\n eaten = min(additional_needed, remaining)\n \n # Calculate the total eaten and remaining carrots\n total_eaten = number + eaten\n remaining_after_meals = remaining - eaten\n \n return [total_eaten, remaining_after_meals]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": []}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n \"\"\"You are given a string s.\n if s[i] is a letter, reverse its case from lower to upper or vice versa, \n otherwise keep it as it is.\n If the string contains no letters, reverse the string.\n The function should return the resulted string.\n \n Examples:\n solve(\"1234\") = \"4321\"\n solve(\"ab\") = \"AB\"\n solve(\"#a@C\") = \"#A@c\"\n \"\"\"\n # Check if there are any letters in the string\n has_letters = any(c.isalpha() for c in s)\n \n if has_letters:\n # Reverse case for letters and keep others the same\n return ''.join(c.swapcase() for c in s)\n else:\n # Reverse the string if there are no letters\n return s[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string.\n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n >>> string_to_md5('') is None\n \"\"\"\n if text == \"\":\n return None\n md5_hash = hashlib.md5(text.encode()).hexdigest()\n return md5_hash", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascending order.\n\n For example:\n generate_integers(2, 8) => [2, 4, 6, 8]\n generate_integers(8, 2) => [2, 4, 6, 8]\n generate_integers(10, 14) => []\n \"\"\"\n # Determine the range of numbers to consider\n start = min(a, b)\n end = max(a, b)\n\n # Generate a list of even integers in the specified range\n even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n return even_integers", "base_status": "fail", "plus_status": null, "base_fail_tests": [[2, 10]], "plus_fail_tests": []}]}} \ No newline at end of file diff --git a/llm_based_122_eval_results.json b/llm_based_122_eval_results.json new file mode 100644 index 000000000..9653f87e6 --- /dev/null +++ b/llm_based_122_eval_results.json @@ -0,0 +1 @@ +{"date": "2024-07-25 16:38", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to make it easier to find close elements\n numbers.sort()\n \n # Check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" \n Input to this function is a string containing multiple groups of nested parentheses. \n Your goal is to separate those groups into separate strings and return the list of those.\n Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n Ignore any spaces in the input string.\n \n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n # Remove spaces from the input string\n paren_string = paren_string.replace(\" \", \"\")\n \n result = []\n balance = 0\n current_group = []\n \n for char in paren_string:\n if char == '(':\n if balance == 0 and current_group:\n result.append(''.join(current_group))\n current_group = []\n current_group.append(char)\n balance += 1\n elif char == ')':\n current_group.append(char)\n balance -= 1\n if balance == 0:\n result.append(''.join(current_group))\n current_group = []\n \n # In case there are any remaining groups (should not happen with valid input)\n if current_group:\n result.append(''.join(current_group))\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into\n an integer part (largest integer smaller than given number) and decimals\n (leftover part always smaller than 1).\n\n Return the decimal part of the number.\n \n >>> truncate_number(3.5)\n 0.5\n >>> truncate_number(2.75)\n 0.75\n >>> truncate_number(5.0)\n 0.0\n >>> truncate_number(0.99)\n 0.99\n \"\"\"\n if number < 0:\n raise ValueError(\"The number must be positive.\")\n \n integer_part = int(number) # Get the integer part\n decimal_part = number - integer_part # Calculate the decimal part\n return decimal_part", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" \n You're given a list of deposit and withdrawal operations on a bank account that starts with\n zero balance. Your task is to detect if at any point the balance of the account falls below zero, \n and at that point the function should return True. Otherwise, it should return False.\n \n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n \"\"\"\n balance = 0\n for operation in operations:\n balance += operation\n if balance < 0:\n return True\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list to avoid division by zero\n\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n \"\"\" Insert a number 'delimiter' between every two consecutive elements of input list `numbers'\n \n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n for i in range(len(numbers) - 1):\n result.append(numbers[i])\n result.append(delimiter)\n result.append(numbers[-1]) # Append the last element\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n def max_nesting_depth(group: str) -> int:\n max_depth = 0\n current_depth = 0\n \n for char in group:\n if char == '(':\n current_depth += 1\n max_depth = max(max_depth, current_depth)\n elif char == ')':\n current_depth -= 1\n \n return max_depth\n\n groups = paren_string.split()\n return [max_nesting_depth(group) for group in groups]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n \"\"\"\n return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n \n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n \"\"\"\n if not numbers:\n return (0, 1)\n \n total_sum = sum(numbers)\n total_product = 1\n for number in numbers:\n total_product *= number\n \n return (total_sum, total_product)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n result = [max_so_far]\n\n for number in numbers[1:]:\n max_so_far = max(max_so_far, number)\n result.append(max_so_far)\n\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n \n >>> make_palindrome('')\n ''\n >>> make_palindrome('cat')\n 'catac'\n >>> make_palindrome('cata')\n 'catac'\n \"\"\"\n # If the string is empty, return it as is\n if not string:\n return string\n \n # Find the longest palindromic suffix\n for i in range(len(string)):\n if is_palindrome(string[i:]):\n # If we found a palindromic suffix, take the prefix before it\n prefix = string[:i]\n # Append the reverse of the prefix to the original string\n return string + prefix[::-1]\n \n # If no palindromic suffix is found, the whole string is non-palindromic\n return string + string[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n \"\"\" \n Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n \n >>> string_xor('010', '110')\n '100'\n \"\"\"\n # Ensure both strings are of the same length by padding the shorter one with leading zeros\n max_length = max(len(a), len(b))\n a = a.zfill(max_length)\n b = b.zfill(max_length)\n \n # Perform XOR operation\n result = []\n for bit_a, bit_b in zip(a, b):\n result.append('1' if bit_a != bit_b else '0')\n \n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n \n >>> longest([])\n >>> None\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n \"\"\"\n if not strings:\n return None\n \n longest_string = strings[0]\n \n for string in strings:\n if len(string) > len(longest_string):\n longest_string = string\n \n return longest_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return the greatest common divisor of two integers a and b\n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n \"\"\"\n while b:\n a, b = b, a % b\n return abs(a)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string\n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n \"\"\"\n return [string[:i] for i in range(1, len(string) + 1)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" \n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n # Use a set to find distinct characters\n distinct_characters = set(lower_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n \n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n \"\"\"\n return ' '.join(str(i) for i in range(n + 1))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n \n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n \"\"\"\n count = 0\n start = 0\n \n while True:\n start = string.find(substring, start)\n if start == -1:\n break\n count += 1\n start += 1 # Move to the next character to allow for overlapping matches\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" Input to this function is a string representing musical notes in a special ASCII format.\n Your task is to parse this string and return list of integers corresponding to how many beats does each\n note last.\n\n Here is a legend:\n 'o' - whole note, lasts four beats\n 'o|' - half note, lasts two beats\n '.|' - quarter note, lasts one beat\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n # Define a mapping of note representations to their corresponding beat values\n note_to_beats = {\n 'o': 4, # whole note\n 'o|': 2, # half note\n '.|': 1 # quarter note\n }\n \n # Split the input string into individual notes\n notes = music_string.split()\n \n # Parse the notes and convert them to their corresponding beat values\n beats = [note_to_beats[note] for note in notes if note in note_to_beats]\n \n return beats", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n \"\"\" \n Input is a space-delimited string of numerals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest.\n \n >>> sort_numbers('three one five')\n 'one three five'\n \"\"\"\n # Mapping of words to their corresponding numeric values\n num_map = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n \n # Split the input string into words\n words = numbers.split()\n \n # Sort the words based on their numeric values\n sorted_words = sorted(words, key=lambda word: num_map[word])\n \n # Join the sorted words back into a string\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to make it easier to find the closest pair\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest elements\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1.\n \n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n min_val = min(numbers)\n max_val = max(numbers)\n \n # Avoid division by zero if all numbers are the same\n if min_val == max_val:\n return [0.0] * len(numbers)\n \n return [(num - min_val) / (max_val - min_val) for num in numbers]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers\n >>> filter_integers(['a', 3.14, 5])\n [5]\n >>> filter_integers([1, 2, 3, 'abc', {}, []])\n [1, 2, 3]\n \"\"\"\n return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n \"\"\" Return length of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n \"\"\"\n return len(string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n \n >>> largest_divisor(15)\n 5\n >>> largest_divisor(28)\n 14\n >>> largest_divisor(1)\n 0\n >>> largest_divisor(10)\n 5\n \"\"\"\n if n <= 1:\n return 0 # No divisors for 1 or less\n \n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n Input number should be equal to the product of all factors\n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n \"\"\"\n factors = []\n # Check for number of 2s that divide n\n while n % 2 == 0:\n factors.append(2)\n n //= 2\n \n # n must be odd at this point so a skip of 2 (i.e., i = i + 2) can be used\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, append i and divide n\n while n % i == 0:\n factors.append(i)\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n factors.append(n)\n \n return factors", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n \n # Create a new list with elements that occur only once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n \n >>> flip_case('Hello')\n 'hELLO'\n >>> flip_case('Python')\n 'pYTHON'\n >>> flip_case('1234!@#')\n '1234!@#'\n >>> flip_case('')\n ''\n \"\"\"\n return string.swapcase()", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n \n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n \"\"\"\n return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string.\n \n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n \"\"\"\n return ''.join(strings)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n \n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n \"\"\"\n return [x for x in l if x > 0]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(divisible_by_three)\n \n # Create a new list to hold the result\n result = l.copy()\n \n # Replace values at indices divisible by 3 with sorted values\n for idx, value in zip((i for i in range(len(l)) if i % 3 == 0), sorted_values):\n result[idx] = value\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float) -> float:\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list) -> list:\n \"\"\"\n Returns the coefficients of the derivative of the polynomial.\n \"\"\"\n return [i * coeff for i, coeff in enumerate(xs)][1:]\ndef find_zero(xs: list) -> float:\n \"\"\" \n xs are coefficients of a polynomial.\n find_zero finds x such that poly(x) = 0.\n find_zero returns only one zero point, even if there are many.\n Moreover, find_zero only takes list xs having an even number of coefficients\n and the largest non-zero coefficient as it guarantees a solution.\n \n >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n -0.5\n >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n 1.0\n \"\"\"\n if len(xs) % 2 != 0:\n raise ValueError(\"The number of coefficients must be even.\")\n \n # Initial guess (can be improved)\n x = 0.0\n tolerance = 1e-7\n max_iterations = 1000\n \n for _ in range(max_iterations):\n f_x = poly(xs, x)\n f_prime_x = poly(derivative(xs), x)\n \n if abs(f_x) < tolerance:\n return x\n \n if f_prime_x == 0:\n raise ValueError(\"Derivative is zero. No solution found.\")\n \n x -= f_x / f_prime_x\n \n raise ValueError(\"Maximum iterations reached. No solution found.\")", "base_status": "fail", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n \"\"\"Return maximum element in the list.\n \n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty.\")\n max_value = l[0]\n for item in l:\n if item > max_value:\n max_value = item\n return max_value", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n even_indices = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indexed elements\n even_indices.sort()\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Place the sorted even indexed elements back into the result\n for i, value in enumerate(even_indices):\n result[i * 2] = value # Place sorted value at the even index\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef prime_fib(n: int) -> int:\n \"\"\"\n prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n \n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n count = 0\n for fib in fibonacci_generator():\n if is_prime(fib):\n count += 1\n if count == n:\n return fib", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1]], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with the encode_cyclic function.\n Returns the decoded string.\n \"\"\"\n # Split string into groups of length 3\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # Reverse the cycling for each group\n groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n \"\"\"\n triples_sum_to_zero takes a list of integers as an input.\n it returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n \"\"\"\n n = len(l)\n l = list(set(l)) # Remove duplicates\n n = len(l) # Update length after removing duplicates\n\n for i in range(n):\n seen = set()\n target = -l[i]\n for j in range(i + 1, n):\n if target - l[j] in seen:\n return True\n seen.add(l[j])\n \n return False", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 3, -2, 1]]], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n \"\"\"\n Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move at the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.\n\n Parameters:\n n (int): The number of cars in each direction.\n\n Returns:\n int: The number of collisions.\n \"\"\"\n # Each car moving left to right will collide with each car moving right to left\n # Therefore, the total number of collisions is n * n\n return n * n", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n \n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n \"\"\"\n return [x + 1 for x in l]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n \n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n \"\"\"\n seen = set()\n for number in l:\n if -number in seen:\n return True\n seen.add(number)\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n \"\"\"Given length of a side and height, return area for a triangle.\n \n The area of a triangle can be calculated using the formula:\n area = (base * height) / 2\n \n Args:\n a (float): The length of the base of the triangle.\n h (float): The height of the triangle.\n \n Returns:\n float: The area of the triangle.\n \n >>> triangle_area(5, 3)\n 7.5\n \"\"\"\n return (a * h) / 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion.\n base numbers are less than 10.\n \n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n \"\"\"\n if base < 2 or base >= 10:\n raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n \n if x == 0:\n return '0'\n \n result = []\n while x > 0:\n result.append(str(x % base))\n x //= base\n \n return ''.join(reversed(result))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n \"\"\"Return median of elements in the list l.\n \n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty.\")\n \n sorted_list = sorted(l)\n n = len(sorted_list)\n mid = n // 2\n \n if n % 2 == 0:\n return (sorted_list[mid - 1] + sorted_list[mid]) / 2\n else:\n return sorted_list[mid]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fib4(0) -> 0\n fib4(1) -> 0\n fib4(2) -> 2\n fib4(3) -> 0\n fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n \n This function computes the n-th element of the fib4 number sequence without using recursion.\n \n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 2\n elif n == 3:\n return 0\n\n # Initialize the first four values of the sequence\n fib_values = [0, 0, 2, 0]\n\n # Compute the values iteratively\n for i in range(4, n + 1):\n next_value = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n fib_values.append(next_value)\n\n return fib_values[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n \"\"\"\n Checks if given string is a palindrome.\n \n A palindrome is a string that reads the same forward and backward.\n \n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n \"\"\"\n # Normalize the string by removing spaces and converting to lowercase\n normalized_text = text.replace(\" \", \"\").lower()\n # Check if the string is equal to its reverse\n return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n \"\"\"\n Takes as input string encoded with encode_shift function. Returns decoded string.\n \"\"\"\n return \"\".join([chr(((ord(ch) - ord(\"a\") - 5) % 26) + ord(\"a\")) for ch in s])", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n \"\"\"Return True if all numbers in the list l are below threshold t.\n \n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n \"\"\"\n return all(x < t for x in l)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n \"\"\"Add two numbers x and y.\n \n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n \"\"\"\n return x + y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two words have the same characters if they contain the same unique characters,\n regardless of the number of times each character appears.\n \n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n \"\"\"Return n-th Fibonacci number.\n \n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n elif n == 1:\n return 1\n elif n == 2:\n return 1\n else:\n a, b = 1, 1\n for _ in range(2, n):\n a, b = b, a + b\n return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n \"\"\"Return True if list elements are monotonically increasing or decreasing.\n \n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n \"\"\"\n if not l: # An empty list is considered monotonic\n return True\n\n increasing = decreasing = True\n\n for i in range(1, len(l)):\n if l[i] > l[i - 1]:\n decreasing = False\n elif l[i] < l[i - 1]:\n increasing = False\n\n return increasing or decreasing", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"<\" and \">\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"<\")\n False\n >>> correct_bracketing(\"<>\")\n True\n >>> correct_bracketing(\"<<><>>\")\n True\n >>> correct_bracketing(\"><<>\")\n False\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '<':\n balance += 1\n elif char == '>':\n balance -= 1\n # If balance goes negative, there are more closing brackets\n if balance < 0:\n return False\n # At the end, balance should be zero for correct bracketing\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n # Keep dividing n by factor until it is no longer divisible\n while n > 1:\n if n % factor == 0:\n n //= factor # Divide n by the factor\n else:\n factor += 1 # Move to the next potential factor\n return factor # The last factor is the largest prime factor", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n \n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n \"\"\"\n return n * (n + 1) // 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"(\" and \")\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"(\")\n False\n >>> correct_bracketing(\"()\")\n True\n >>> correct_bracketing(\"(()())\")\n True\n >>> correct_bracketing(\")(()\")\n False\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n # If balance goes negative, there are unmatched closing brackets\n if balance < 0:\n return False\n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n \n Args:\n n (int): The index of the FibFib number to compute.\n \n Returns:\n int: The n-th FibFib number.\n \n Examples:\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n if n == 0 or n == 1:\n return 0\n elif n == 2:\n return 1\n \n # Initialize the first three FibFib numbers\n fibfib_numbers = [0, 0, 1]\n \n # Compute FibFib numbers iteratively\n for i in range(3, n + 1):\n next_fibfib = fibfib_numbers[i - 1] + fibfib_numbers[i - 2] + fibfib_numbers[i - 3]\n fibfib_numbers.append(next_fibfib)\n \n return fibfib_numbers[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n \"\"\" \n xs represent coefficients of a polynomial.\n xs[0] + xs[1] * x + xs[2] * x^2 + ....\n Return derivative of this polynomial in the same form.\n \n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n \"\"\"\n # The derivative of a polynomial is calculated by multiplying each coefficient\n # by its corresponding power and reducing the power by one.\n return [i * coeff for i, coeff in enumerate(xs[1:], start=1)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set('aeiouAEIOU')\n count = 0\n \n # Check each character in the string\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n # Check if 'y' is at the end of the word\n elif s[i].lower() == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n \n >>> circular_shift(12, 1)\n '21'\n >>> circular_shift(12, 2)\n '12'\n \"\"\"\n # Convert the integer to a string to work with its digits\n str_x = str(x)\n num_digits = len(str_x)\n \n # If shift is greater than the number of digits, reverse the string\n if shift >= num_digits:\n return str_x[::-1]\n \n # Calculate the effective shift\n effective_shift = shift % num_digits\n \n # Perform the circular shift\n shifted_str = str_x[-effective_shift:] + str_x[:-effective_shift]\n \n return shifted_str", "base_status": "fail", "plus_status": null, "base_fail_tests": [[12, 2]], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n \"\"\"Task\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n \"\"\"\n return sum(ord(char) for char in s if char.isupper())", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n \"\"\"\n In this task, you will be given a string that represents a number of apples and oranges \n that are distributed in a basket of fruit. This basket contains \n apples, oranges, and mango fruits. Given the string that represents the total number of \n the oranges and apples and an integer that represents the total number of the fruits \n in the basket, return the number of the mango fruits in the basket.\n \n Parameters:\n s (str): A string representing the number of apples and oranges.\n n (int): An integer representing the total number of fruits in the basket.\n \n Returns:\n int: The number of mango fruits in the basket.\n \n Examples:\n fruit_distribution(\"5 apples and 6 oranges\", 19) -> 8\n fruit_distribution(\"0 apples and 1 oranges\", 3) -> 2\n fruit_distribution(\"2 apples and 3 oranges\", 100) -> 95\n fruit_distribution(\"100 apples and 1 oranges\", 120) -> 19\n \"\"\"\n \n # Extract the number of apples and oranges from the string\n parts = s.split()\n apples = int(parts[0]) # First part is the number of apples\n oranges = int(parts[2]) # Third part is the number of oranges\n \n # Calculate the number of mangoes\n mangoes = n - apples - oranges\n \n return mangoes", "base_status": "fail", "plus_status": null, "base_fail_tests": [["5 apples and 6 oranges", 19]], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n \"\"\"\n Given an array representing a branch of a tree that has non-negative integer nodes,\n your task is to pluck one of the nodes and return it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n The plucked node should be returned in a list, [ smallest_value, its index ],\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index. \n\n Example 3:\n Input: []\n Output: []\n \n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n Explanation: 0 is the smallest value, but there are two zeros,\n so we will choose the first zero, which has the smallest index.\n\n Constraints:\n * 1 <= nodes.length <= 10000\n * 0 <= node.value\n \"\"\"\n smallest_even = float('inf')\n smallest_index = -1\n\n for index, value in enumerate(arr):\n if value % 2 == 0: # Check if the value is even\n if value < smallest_even: # Check if it's the smallest even found\n smallest_even = value\n smallest_index = index\n\n if smallest_index == -1: # No even value found\n return []\n \n return [smallest_even, smallest_index]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n '''\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequency greater than or equal to the value of the integer itself. \n The frequency of an integer is the number of times it appears in the list.\n If no such a value exist, return -1.\n \n Examples:\n search([4, 1, 2, 2, 3, 1]) == 2\n search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n search([5, 5, 4, 4, 4]) == -1\n '''\n from collections import Counter\n \n # Count the frequency of each integer in the list\n frequency = Counter(lst)\n \n # Initialize the result variable\n result = -1\n \n # Iterate through the frequency dictionary\n for num, freq in frequency.items():\n # Check if the frequency is greater than or equal to the number itself\n if freq >= num:\n # Update the result if the current number is greater than the previous result\n result = max(result, num)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return the area of\n the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n Otherwise return -1.\n Three sides make a valid triangle when the sum of any two sides is greater \n than the third side.\n \n Example:\n triangle_area(3, 4, 5) == 6.00\n triangle_area(1, 2, 10) == -1\n '''\n # Check for valid triangle using the triangle inequality theorem\n if a + b > c and a + c > b and b + c > a:\n # Calculate the semi-perimeter\n s = (a + b + c) / 2\n # Calculate the area using Heron's formula\n area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n return round(area, 2)\n else:\n return -1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n '''\n Given list of integers, return list in strange order.\n Strange sorting, is when you start with the minimum value,\n then maximum of the remaining integers, then minimum and so on.\n\n Examples:\n strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n strange_sort_list([]) == []\n '''\n if not lst:\n return []\n\n sorted_lst = sorted(lst)\n result = []\n \n while sorted_lst:\n # Append the minimum value\n result.append(sorted_lst.pop(0))\n if sorted_lst: # Check if there are remaining elements\n # Append the maximum value\n result.append(sorted_lst.pop(-1))\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n '''\n Write a function that returns True if the object q will fly, and False otherwise.\n The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n\n Example:\n will_it_fly([1, 2], 5) \u279e False \n # 1+2 is less than the maximum possible weight, but it's unbalanced.\n\n will_it_fly([3, 2, 3], 1) \u279e False\n # it's balanced, but 3+2+3 is more than the maximum possible weight.\n\n will_it_fly([3, 2, 3], 9) \u279e True\n # 3+2+3 is less than the maximum possible weight, and it's balanced.\n\n will_it_fly([3], 5) \u279e True\n # 3 is less than the maximum possible weight, and it's balanced.\n '''\n # Check if the list is a palindrome\n is_balanced = q == q[::-1]\n \n # Calculate the sum of the elements in the list\n total_weight = sum(q)\n \n # Check if the object will fly\n return is_balanced and total_weight <= w", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n \"\"\"\n Given an array arr of integers, find the minimum number of elements that\n need to be changed to make the array palindromic. A palindromic array is an array that\n is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n For example:\n smallest_change([1,2,3,5,4,7,9,6]) == 4\n smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n smallest_change([1, 2, 3, 2, 1]) == 0\n \"\"\"\n n = len(arr)\n changes = 0\n \n # Compare elements from the start and end towards the center\n for i in range(n // 2):\n if arr[i] != arr[n - 1 - i]:\n changes += 1\n \n return changes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n else:\n return lst2", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef get_primes_up_to(max_num):\n \"\"\"Return a list of all prime numbers up to max_num.\"\"\"\n return [num for num in range(2, max_num) if is_prime(num)]\ndef is_multiply_prime(a):\n \"\"\"Return True if the given number is the multiplication of 3 prime numbers, False otherwise.\"\"\"\n if a >= 100:\n return False\n \n primes = get_primes_up_to(a)\n prime_count = len(primes)\n \n # Check all combinations of three primes\n for i in range(prime_count):\n for j in range(i, prime_count):\n for k in range(j, prime_count):\n product = primes[i] * primes[j] * primes[k]\n if product == a:\n return True\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n \"\"\"Returns True if x is a simple power of n, otherwise False.\n \n A number x is a simple power of n if there exists an integer k such that n**k = x.\n \n Args:\n x (int): The number to check.\n n (int): The base number.\n \n Returns:\n bool: True if x is a simple power of n, False otherwise.\n \"\"\"\n if n <= 1:\n return x == n # n must be greater than 1 for powers to make sense\n \n power = 1\n while True:\n result = n ** power\n if result == x:\n return True\n elif result > x:\n return False\n power += 1", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1, 12]], "plus_fail_tests": []}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this integer is a cube of some integer number.\n Note: you may assume the input is always valid.\n \n Examples:\n iscube(1) ==> True\n iscube(2) ==> False\n iscube(-1) ==> True\n iscube(64) ==> True\n iscube(0) ==> True\n iscube(180) ==> False\n '''\n # Calculate the cube root of the absolute value of a\n cube_root = round(abs(a) ** (1/3))\n \n # Check if the cube of the rounded cube root equals the absolute value of a\n return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n \"\"\"Count the number of prime hexadecimal digits in the given string.\"\"\"\n # Define the set of prime hexadecimal digits\n prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n \n # Initialize a counter for prime digits\n count = 0\n \n # Iterate through each character in the input string\n for char in num:\n # Check if the character is in the set of prime hexadecimal digits\n if char in prime_hex_digits:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n \"\"\"Convert a decimal number to binary format with specific formatting.\n\n Args:\n decimal (int): A number in decimal form.\n\n Returns:\n str: A string representing the binary format of the number, \n with 'db' at the beginning and end.\n \"\"\"\n # Convert the decimal number to binary and remove the '0b' prefix\n binary_representation = bin(decimal)[2:]\n # Format the result with 'db' at the beginning and end\n formatted_result = f\"db{binary_representation}db\"\n return formatted_result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n \"\"\"You are given a string s.\n Your task is to check if the string is happy or not.\n A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n \n For example:\n is_happy(a) => False\n is_happy(aa) => False\n is_happy(abcd) => True\n is_happy(aabb) => False\n is_happy(adb) => True\n is_happy(xyy) => False\n \"\"\"\n # Check if the length of the string is at least 3\n if len(s) < 3:\n return False\n \n # Check every 3 consecutive letters\n for i in range(len(s) - 2):\n if len(set(s[i:i+3])) < 3: # If there are not 3 distinct letters\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef prime_length(string):\n \"\"\"Return True if the length of the string is a prime number, False otherwise.\"\"\"\n length = len(string)\n return is_prime(length)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n letter_grades = []\n \n for gpa in grades:\n if gpa == 4.0:\n letter_grades.append('A+')\n elif gpa > 3.7:\n letter_grades.append('A')\n elif gpa > 3.3:\n letter_grades.append('A-')\n elif gpa > 3.0:\n letter_grades.append('B+')\n elif gpa > 2.7:\n letter_grades.append('B')\n elif gpa > 2.3:\n letter_grades.append('B-')\n elif gpa > 2.0:\n letter_grades.append('C+')\n elif gpa > 1.7:\n letter_grades.append('C')\n elif gpa > 1.3:\n letter_grades.append('C-')\n elif gpa > 1.0:\n letter_grades.append('D+')\n elif gpa > 0.7:\n letter_grades.append('D')\n elif gpa > 0.0:\n letter_grades.append('D-')\n else:\n letter_grades.append('E')\n \n return letter_grades", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n \"\"\"\n Given a positive integer n, return the count of the numbers of n-digit\n positive integers that start or end with 1.\n \"\"\"\n if n < 1:\n return 0 # There are no n-digit numbers for n < 1\n\n # Total n-digit numbers\n total_n_digit_numbers = 9 * (10 ** (n - 1))\n\n # Count of n-digit numbers that start with 1\n start_with_1 = 10 ** (n - 1)\n\n # Count of n-digit numbers that end with 1\n end_with_1 = total_n_digit_numbers // 10\n\n # Count of n-digit numbers that start and end with 1\n start_and_end_with_1 = 10 ** (n - 2) if n > 1 else 0\n\n # Total count of n-digit numbers that start or end with 1\n count = start_with_1 + end_with_1 - start_and_end_with_1\n\n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits will be 1 the output should be \"1\".\n For N = 150, the sum of digits will be 6 the output should be \"110\".\n For N = 147, the sum of digits will be 12 the output should be \"1100\".\n \n Variables:\n @N integer\n Constraints: 0 \u2264 N \u2264 10000.\n Output:\n a string of binary number\n \"\"\"\n # Calculate the sum of the digits of N\n digit_sum = sum(int(digit) for digit in str(N))\n \n # Convert the sum to binary and return it as a string\n return bin(digit_sum)[2:]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words while preserving spaces\n words = s.split(' ')\n \n # Sort each word and keep the spaces intact\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back with spaces\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n or sort it in descending order if the sum( first index value, last index value) is even.\n\n Note:\n * don't change the given array.\n\n Examples:\n * sort_array([]) => []\n * sort_array([5]) => [5]\n * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n \"\"\"\n # Create a copy of the array to sort\n sorted_array = array.copy()\n \n # Calculate the sum of the first and last elements\n if not sorted_array: # Check for empty array\n return sorted_array\n \n first_element = sorted_array[0]\n last_element = sorted_array[-1]\n total_sum = first_element + last_element\n \n # Sort the array based on the sum being odd or even\n if total_sum % 2 == 0:\n # Even sum: sort in descending order\n sorted_array.sort(reverse=True)\n else:\n # Odd sum: sort in ascending order\n sorted_array.sort()\n \n return sorted_array", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n \n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by row index (ascending) and then by column index (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Sort the unique elements\n sorted_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_elements[1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n # Create a mapping for the rotation\n rotated_alphabet = alphabet[2:] + alphabet[:2] # Rotate by 2 places\n # Create a translation table\n translation_table = str.maketrans(alphabet, rotated_alphabet)\n # Translate the input string using the translation table\n encrypted_string = s.translate(translation_table)\n return encrypted_string", "base_status": "fail", "plus_status": null, "base_fail_tests": [["hi"]], "plus_fail_tests": []}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n \n For example:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n \"\"\"\n # Split the string into sentences using the delimiters\n sentences = []\n current_sentence = []\n for char in S:\n if char in '.!?':\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n current_sentence = []\n else:\n current_sentence.append(char)\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n\n # Count the number of sentences that start with \"I\"\n boredom_count = sum(1 for sentence in sentences if sentence.startswith('I'))\n\n return boredom_count", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n '''\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n \n Examples\n any_int(5, 2, 7) \u279e True\n any_int(3, 2, 2) \u279e False\n any_int(3, -2, 1) \u279e True\n any_int(3.6, -2.2, 2) \u279e False\n '''\n # Check if all inputs are integers\n if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n # Check if one number is equal to the sum of the other two\n return x == y + z or y == x + z or z == x + y\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n \"\"\"\n Write a function that takes a message, and encodes in such a \n way that it swaps case of all letters, replaces all vowels in \n the message with the letter that appears 2 places ahead of that \n vowel in the english alphabet. \n Assume only letters. \n \n Examples:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n vowels = 'aeiouAEIOU'\n encoded_message = []\n\n for char in message:\n if char.isalpha(): # Check if the character is a letter\n # Swap case\n if char in vowels:\n # Replace vowel with the letter 2 places ahead\n if char.islower():\n new_char = chr(((ord(char) - ord('a') + 2) % 26) + ord('a'))\n else:\n new_char = chr(((ord(char) - ord('A') + 2) % 26) + ord('A'))\n else:\n new_char = char.swapcase() # Swap case for consonants\n encoded_message.append(new_char)\n else:\n encoded_message.append(char) # Keep non-letter characters unchanged\n\n return ''.join(encoded_message)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["TEST"]], "plus_fail_tests": []}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef sum_of_digits(n):\n \"\"\"Return the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n largest_prime = -1\n \n for number in lst:\n if is_prime(number) and number > largest_prime:\n largest_prime = number\n \n if largest_prime == -1:\n return 0 # Return 0 if no prime is found\n \n return sum_of_digits(largest_prime)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_up_to(n):\n \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n primes = []\n for i in range(2, n):\n if is_prime(i):\n primes.append(i)\n return primes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in lower \n case or all keys are strings in upper case, else return False.\n The function should return False if the given dictionary is empty.\n \n Examples:\n check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n \"\"\"\n if not input_dict:\n return False\n\n all_lower = all(isinstance(key, str) and key.islower() for key in input_dict.keys())\n all_upper = all(isinstance(key, str) and key.isupper() for key in input_dict.keys())\n\n return all_lower or all_upper", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n count_upper('aBCdEf') returns 1\n count_upper('abcdefg') returns 0\n count_upper('dBBE') returns 0\n \"\"\"\n uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n count = 0\n \n for i in range(0, len(s), 2): # Iterate over even indices\n if s[i] in uppercase_vowels:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.\n \"\"\"\n # Get the unit digit of the first number\n unit_digit_a = abs(a) % 10\n # Get the unit digit of the second number\n unit_digit_b = abs(b) % 10\n # Return the product of the unit digits\n return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n >>> closest_integer(\"14.5\")\n 15\n >>> closest_integer(\"-14.5\")\n -15\n >>> closest_integer(\"0.5\")\n 1\n >>> closest_integer(\"-0.5\")\n -1\n '''\n\n # Convert the string value to a float\n num = float(value)\n \n # Calculate the floor and ceiling of the number\n lower = int(num // 1) # This is the floor of the number\n upper = lower + 1 # This is the ceiling of the number\n\n # Check if the number is equidistant from lower and upper\n if abs(num - lower) < abs(num - upper):\n return lower\n elif abs(num - lower) > abs(num - upper):\n return upper\n else:\n # If equidistant, round away from zero\n if num > 0:\n return upper\n else:\n return lower", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n \"\"\"\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n >>> make_a_pile(4)\n [4, 6, 8, 10]\n >>> make_a_pile(1)\n [1]\n \"\"\"\n stones = []\n current_stones = n\n \n for i in range(n):\n stones.append(current_stones)\n if n % 2 == 0: # n is even\n current_stones += 2\n else: # n is odd\n current_stones += 2\n \n return stones", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n \"\"\"\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n \"\"\"\n # Split the string by commas and spaces, then filter out any empty strings\n words = [word.strip() for word in s.replace(',', ' ').split() if word]\n return words", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n \"\"\"This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If \n there's no such number, then the function should return -1.\n\n For example:\n choose_num(12, 15) = 14\n choose_num(13, 12) = -1\n \"\"\"\n # Ensure x is less than or equal to y\n if x > y:\n return -1\n \n # Start from the largest number in the range and check for evenness\n for num in range(y, x - 1, -1):\n if num % 2 == 0:\n return num\n \n return -1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n \"\"\"You are given two positive integers n and m, and your task is to compute the\n average of the integers from n through m (including n and m). \n Round the answer to the nearest integer and convert that to binary.\n If n is greater than m, return -1.\n \n Example:\n rounded_avg(1, 5) => \"0b11\"\n rounded_avg(7, 5) => -1\n rounded_avg(10, 20) => \"0b1111\"\n rounded_avg(20, 33) => \"0b11010\"\n \"\"\"\n if n > m:\n return -1\n \n # Calculate the sum of integers from n to m\n total_sum = sum(range(n, m + 1))\n count = m - n + 1 # Total numbers from n to m\n \n # Calculate the average and round it\n average = total_sum / count\n rounded_average = round(average)\n \n # Convert the rounded average to binary\n return bin(rounded_average)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n \"\"\"Given a list of positive integers x, return a sorted list of all \n elements that haven't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n def has_even_digit(n):\n \"\"\"Check if the number has any even digit.\"\"\"\n for digit in str(n):\n if int(digit) % 2 == 0:\n return True\n return False\n\n # Filter the list to include only numbers without even digits\n result = [num for num in x if not has_even_digit(num)]\n \n # Return the sorted result\n return sorted(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def factorial(i):\n \"\"\"Calculate the factorial of i.\"\"\"\n if i == 0 or i == 1:\n return 1\n result = 1\n for j in range(2, i + 1):\n result *= j\n return result\ndef sum_of_numbers(i):\n \"\"\"Calculate the sum of numbers from 1 to i.\"\"\"\n return i * (i + 1) // 2\ndef f(n):\n \"\"\"Return a list of size n, where the value at index i is the factorial of i if i is even,\n or the sum of numbers from 1 to i otherwise. Indexing starts from 1.\"\"\"\n result = []\n for i in range(1, n + 1):\n if i % 2 == 0: # i is even\n result.append(factorial(i))\n else: # i is odd\n result.append(sum_of_numbers(i))\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n reverse the resulting array, and then replace each digit by its corresponding name from\n \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n For example:\n arr = [2, 1, 1, 4, 5, 8, 2, 3] \n -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n \n If the array is empty, return an empty array:\n arr = []\n return []\n \n If the array has any strange number ignore it:\n arr = [1, -1 , 55] \n -> sort arr -> [-1, 1, 55]\n -> reverse arr -> [55, 1, -1]\n return = ['One']\n \"\"\"\n \n # Mapping of digits to their corresponding names\n digit_to_name = {\n 1: \"One\",\n 2: \"Two\",\n 3: \"Three\",\n 4: \"Four\",\n 5: \"Five\",\n 6: \"Six\",\n 7: \"Seven\",\n 8: \"Eight\",\n 9: \"Nine\"\n }\n \n # Filter the array to include only numbers between 1 and 9\n filtered_arr = [num for num in arr if 1 <= num <= 9]\n \n # Sort the filtered array\n sorted_arr = sorted(filtered_arr)\n \n # Reverse the sorted array\n reversed_arr = sorted_arr[::-1]\n \n # Convert the digits to their corresponding names\n result = [digit_to_name[num] for num in reversed_arr]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n \"\"\"\n Given a positive integer n, return a tuple that has the number of even and odd\n integer palindromes that fall within the range(1, n), inclusive.\n\n Example 1:\n Input: 3\n Output: (1, 2)\n Explanation:\n Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n Example 2:\n Input: 12\n Output: (4, 6)\n Explanation:\n Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n Note:\n 1. 1 <= n <= 10^3\n 2. returned tuple has the number of even and odd integer palindromes respectively.\n \"\"\"\n even_count = 0\n odd_count = 0\n\n for i in range(1, n + 1):\n if str(i) == str(i)[::-1]: # Check if the number is a palindrome\n if i % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n \"\"\"\n Write a function count_nums which takes an array of integers and returns\n the number of elements which has a sum of digits > 0.\n If a number is negative, then its first signed digit will be negative:\n e.g. -123 has signed digits -1, 2, and 3.\n \n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n def sum_of_digits(n):\n # Convert the number to string and calculate the sum of its digits\n return sum(int(digit) if digit != '-' else -int(digit) for digit in str(n))\n\n count = 0\n for number in arr:\n if sum_of_digits(number) > 0:\n count += 1\n \n return count", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[-1, -2, 0]]], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return True else return False.\n If the given array is empty then return True.\n\n Note: The given list is guaranteed to have unique elements.\n\n For Example:\n \n move_one_ball([3, 4, 5, 1, 2])==>True\n Explanation: By performing 2 right shift operations, non-decreasing order can\n be achieved for the given array.\n move_one_ball([3, 5, 4, 1, 2])==>False\n Explanation: It is not possible to get non-decreasing order for the given\n array by performing any number of right shift operations.\n \"\"\"\n if not arr:\n return True\n\n n = len(arr)\n sorted_arr = sorted(arr)\n \n # Check for the number of \"breaks\" in the sorted array\n break_count = 0\n for i in range(n):\n if arr[i] > arr[(i + 1) % n]:\n break_count += 1\n\n # If there are more than one break, we cannot sort the array with shifts\n return break_count <= 1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n \"\"\"Determines whether it is possible to perform an exchange of elements\n between two lists to make lst1 a list of only even numbers.\n \n Args:\n lst1 (list): The first list of numbers.\n lst2 (list): The second list of numbers.\n \n Returns:\n str: \"YES\" if lst1 can be made all even, otherwise \"NO\".\n \"\"\"\n # Check if all elements in lst1 are already even\n if all(x % 2 == 0 for x in lst1):\n return \"YES\"\n \n # Count the number of odd elements in lst1\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n \n # Check if lst2 has at least one even number to exchange\n has_even_in_lst2 = any(x % 2 == 0 for x in lst2)\n \n # If there are odd numbers in lst1 and lst2 has at least one even number\n if odd_count_lst1 > 0 and has_even_in_lst2:\n return \"YES\"\n \n return \"NO\"", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 3, 4], [1, 5, 3, 4]]], "plus_fail_tests": []}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n \"\"\"Task\n We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and True/False for the check.\n Example\n For s = \"abcde\", c = \"ae\", the result should be ('bcd',False)\n For s = \"abcdef\", c = \"b\" the result should be ('acdef',False)\n For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc',True)\n \"\"\"\n # Create a set of characters to delete for faster lookup\n delete_set = set(c)\n \n # Create the result string by filtering out characters in delete_set\n result = ''.join(char for char in s if char not in delete_set)\n \n # Check if the result string is a palindrome\n is_palindrome = result == result[::-1]\n \n return (result, is_palindrome)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n \"\"\"\n if not test:\n return {}\n\n # Split the input string into a list of letters\n letters = test.split()\n \n # Create a dictionary to count occurrences of each letter\n count_dict = {}\n for letter in letters:\n if letter in count_dict:\n count_dict[letter] += 1\n else:\n count_dict[letter] = 1\n\n # Find the maximum count\n max_count = max(count_dict.values())\n \n # Create a result dictionary for letters with the maximum count\n result = {letter: count for letter, count in count_dict.items() if count == max_count}\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for char in s if char in '13579')\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n Example\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n \"\"\"\n if not nums:\n return 0 # Handle empty input case\n\n min_sum = float('inf')\n current_sum = 0\n\n for num in nums:\n current_sum += num\n min_sum = min(min_sum, current_sum)\n if current_sum > 0:\n current_sum = 0 # Reset current sum if it becomes positive\n\n return min_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n \"\"\"\n Calculate the number of times buckets need to be lowered to empty the wells.\n\n Parameters:\n grid (list of list of int): A rectangular grid representing wells.\n capacity (int): The capacity of each bucket.\n\n Returns:\n int: The total number of times buckets need to be lowered.\n \"\"\"\n total_water = 0\n \n # Count the total amount of water in the grid\n for row in grid:\n total_water += sum(row)\n \n # Calculate the number of times buckets need to be lowered\n # Each bucket can carry 'capacity' units of water\n if total_water == 0:\n return 0\n else:\n return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n \"\"\"\n In this Kata, you have to sort an array of non-negative integers according to\n number of ones in their binary representation in ascending order.\n For similar number of ones, sort based on decimal value.\n\n It must be implemented like this:\n >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n >>> sort_array([1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]\n \"\"\"\n # Sort the array using a custom key\n return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n two consonants from the right side of the word (case sensitive).\n \n Vowels in the beginning and ending don't count. Return empty string if you didn't\n find any vowel that meets the above condition. \n\n You may assume that the given string contains English letters only.\n\n Example:\n get_closest_vowel(\"yogurt\") ==> \"u\"\n get_closest_vowel(\"FULL\") ==> \"U\"\n get_closest_vowel(\"quick\") ==> \"\"\n get_closest_vowel(\"ab\") ==> \"\"\n \"\"\"\n vowels = \"aeiouAEIOU\"\n n = len(word)\n\n # Start from the end of the word\n for i in range(n - 2, 0, -1): # Start from the second last character\n if word[i] in vowels: # Check if the character is a vowel\n # Check if the previous character is a consonant\n if word[i - 1].isalpha() and word[i - 1] not in vowels:\n # Check if the next character is a consonant\n if word[i + 1].isalpha() and word[i + 1] not in vowels:\n return word[i] # Return the vowel if it is between two consonants\n\n return \"\" # Return empty string if no such vowel is found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n \"\"\"Given a string s and a natural number n, returns a list of all words from string s \n that contain exactly n consonants, in the order they appear in the string s.\n \n Args:\n s (str): The input string containing words.\n n (int): The number of consonants to match.\n \n Returns:\n list: A list of words containing exactly n consonants.\n \"\"\"\n if not s:\n return []\n\n # Define a set of consonants\n consonants = set(\"bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ\")\n \n # Split the string into words\n words = s.split()\n \n # Function to count consonants in a word\n def count_consonants(word):\n return sum(1 for char in word if char in consonants)\n \n # Filter words that have exactly n consonants\n result = [word for word in words if count_consonants(word) == n]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0: # More closing than opening\n return False\n return balance == 0 # Must be balanced at the end\n\n # Check both concatenation orders\n return 'Yes' if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]) else 'No'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Get the top k elements\n top_k = sorted_arr[:k]\n # Return the top k elements sorted in ascending order\n return sorted(top_k)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n \"\"\"\n Given a non-empty array of integers arr and an integer k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example:\n\n Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n Output: 24 # sum of 21 + 3\n\n Constraints:\n 1. 1 <= len(arr) <= 100\n 2. 1 <= k <= len(arr)\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate through the first k elements of the array\n for i in range(k):\n # Check if the element has at most two digits\n if -100 < arr[i] < 100:\n total_sum += arr[i]\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n as follows: start with any positive integer n. Then each term is obtained from the \n previous term as follows: if the previous term is even, the next term is one half of \n the previous term. If the previous term is odd, the next term is 3 times the previous\n term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n Note: \n 1. Collatz(1) is [1].\n 2. returned list sorted in increasing order.\n\n For example:\n get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n collatz_sequence = []\n current = n\n \n while current != 1:\n collatz_sequence.append(current)\n if current % 2 == 0:\n current //= 2\n else:\n current = 3 * current + 1\n \n collatz_sequence.append(1) # Add the last term which is 1\n \n # Filter odd numbers and sort them\n odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n \n return odd_numbers", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n '''\n Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n Examples\n split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"abcdef\") == 3 \n '''\n # Check for whitespace in the text\n if ' ' in txt:\n return txt.split()\n \n # Check for commas in the text\n elif ',' in txt:\n return txt.split(',')\n \n # If no whitespace or commas, count lower-case letters with odd order\n else:\n odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n return odd_count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n \n The date is valid if all of the following rules are satisfied:\n 1. The date string is not empty.\n 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n The number of days is not less than 1 or higher than 29 for the month 2.\n 3. The months should not be less than 1 or higher than 12.\n 4. The date should be in the format: mm-dd-yyyy\n \n Args:\n date (str): The date string to validate.\n \n Returns:\n bool: True if the date is valid, False otherwise.\n \"\"\"\n if not date:\n return False\n \n # Check the format\n if len(date) != 10 or date[2] != '-' or date[5] != '-':\n return False\n \n try:\n month = int(date[:2])\n day = int(date[3:5])\n year = int(date[6:])\n except ValueError:\n return False\n \n # Validate month\n if month < 1 or month > 12:\n return False\n \n # Validate day based on month\n if month in [1, 3, 5, 7, 8, 10, 12]: # 31 days\n if day < 1 or day > 31:\n return False\n elif month in [4, 6, 9, 11]: # 30 days\n if day < 1 or day > 30:\n return False\n elif month == 2: # February\n if day < 1 or day > 29:\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n '''\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return False. Assume no negative numbers and only integers.\n\n Examples\n is_sorted([5]) \u279e True\n is_sorted([1, 2, 3, 4, 5]) \u279e True\n is_sorted([1, 3, 2, 4, 5]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n '''\n if not lst: # Check if the list is empty\n return True\n\n seen = set()\n last = None\n\n for num in lst:\n if num in seen: # Check for duplicates\n return False\n seen.add(num)\n\n if last is not None and num < last: # Check if the list is sorted\n return False\n last = num\n\n return True", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef intersection(interval1, interval2):\n \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n start1, end1 = interval1\n start2, end2 = interval2\n \n # Find the intersection\n start_intersection = max(start1, start2)\n end_intersection = min(end1, end2)\n \n # Check if there is an intersection\n if start_intersection > end_intersection:\n return \"NO\"\n \n # Calculate the length of the intersection\n length_of_intersection = end_intersection - start_intersection\n \n # Check if the length is a prime number\n if is_prime(length_of_intersection):\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n if not arr:\n return None\n\n product_of_signs = 1\n sum_of_magnitudes = 0\n\n for num in arr:\n if num > 0:\n product_of_signs *= 1\n sum_of_magnitudes += num\n elif num < 0:\n product_of_signs *= -1\n sum_of_magnitudes += -num\n else: # num == 0\n product_of_signs = 0\n break\n\n return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n \"\"\"Calculate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n if n < 0:\n return []\n\n # Initialize the list to store the Tribonacci numbers\n tribonacci_sequence = []\n\n # Define the base case\n for i in range(n + 1):\n if i == 0:\n tribonacci_sequence.append(1) # tri(0) = 1\n elif i == 1:\n tribonacci_sequence.append(3) # tri(1) = 3\n elif i % 2 == 0: # n is even\n tribonacci_sequence.append(1 + i / 2)\n else: # n is odd\n # Calculate tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1)\n tri_n_minus_1 = tribonacci_sequence[i - 1]\n tri_n_minus_2 = tribonacci_sequence[i - 2]\n tri_n_plus_1 = tribonacci_sequence[i + 1] if i + 1 < len(tribonacci_sequence) else 0\n tribonacci_sequence.append(tri_n_minus_1 + tri_n_minus_2 + tri_n_plus_1)\n\n return tribonacci_sequence", "base_status": "fail", "plus_status": null, "base_fail_tests": [[3]], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n \"\"\"Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n For example:\n digits(1) == 1\n digits(4) == 0\n digits(235) == 15\n \"\"\"\n product = 1\n has_odd = False\n \n for digit in str(n):\n digit = int(digit)\n if digit % 2 != 0: # Check if the digit is odd\n product *= digit\n has_odd = True\n \n return product if has_odd else 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n '''\n Create a function that takes a string as input which contains only square brackets.\n The function should return True if and only if there is a valid subsequence of brackets \n where at least one bracket in the subsequence is nested.\n\n is_nested('[[]]') \u279e True\n is_nested('[]]]]]]][[[[[]') \u279e False\n is_nested('[][]') \u279e False\n is_nested('[]') \u279e False\n is_nested('[[][]]') \u279e True\n is_nested('[[]][[') \u279e True\n '''\n # Initialize counters for open and close brackets\n open_count = 0\n nested = False\n\n for char in string:\n if char == '[':\n open_count += 1\n # Check if we have seen at least one open bracket before\n if open_count > 1:\n nested = True\n elif char == ']':\n open_count -= 1\n # If we close a bracket, we should not go below zero\n if open_count < 0:\n return False\n\n # We need at least one nested bracket and all brackets should be closed\n return nested and open_count == 0", "base_status": "fail", "plus_status": null, "base_fail_tests": [["[[]][["]], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers.\n You need to return the sum of squared numbers in the given list,\n round each element in the list to the upper int (Ceiling) first.\n \n Examples:\n For lst = [1,2,3] the output should be 14\n For lst = [1,4,9] the output should be 98\n For lst = [1,3,5,7] the output should be 84\n For lst = [1.4,4.2,0] the output should be 29\n For lst = [-2.4,1,1] the output should be 6\n \"\"\"\n return sum(math.ceil(x) ** 2 for x in lst)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n '''\n Create a function that returns True if the last character\n of a given string is an alphabetical character and is not\n a part of a word, and False otherwise.\n Note: \"word\" is a group of characters separated by space.\n\n Examples:\n check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '''\n # Strip any trailing whitespace from the string\n txt = txt.rstrip()\n \n # Check if the string is empty after stripping\n if not txt:\n return False\n \n # Get the last character of the string\n last_char = txt[-1]\n \n # Check if the last character is an alphabetical character\n if last_char.isalpha():\n # Check if the last character is part of a word\n # A character is part of a word if it is preceded by a non-space character\n if len(txt) > 1 and txt[-2] != ' ':\n return False\n return True\n \n return False", "base_status": "fail", "plus_status": null, "base_fail_tests": [["eeeee e "]], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n from collections import deque\n\n N = len(grid)\n directions = [(0, 1), (1, 0), (0, -1), (-1, 0)] # right, down, left, up\n min_path = None\n\n def bfs(start_x, start_y):\n nonlocal min_path\n queue = deque([(start_x, start_y, [grid[start_x][start_y]])])\n visited = set((start_x, start_y))\n\n while queue:\n x, y, path = queue.popleft()\n\n if len(path) == k:\n if min_path is None or path < min_path:\n min_path = path\n continue\n\n for dx, dy in directions:\n nx, ny = x + dx, y + dy\n if 0 <= nx < N and 0 <= ny < N:\n new_path = path + [grid[nx][ny]]\n queue.append((nx, ny, new_path))\n\n for i in range(N):\n for j in range(N):\n bfs(i, j)\n\n return min_path", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n \"\"\"Create a function which returns the largest index of an element which\n is not greater than or equal to the element immediately preceding it. If\n no such element exists then return -1. The given array will not contain\n duplicate values.\n\n Examples:\n can_arrange([1,2,4,3,5]) = 3\n can_arrange([1,2,3]) = -1\n \"\"\"\n # Initialize the index to -1, which will be returned if no such element is found\n largest_index = -1\n \n # Iterate through the array starting from the second element\n for i in range(1, len(arr)):\n # Check if the current element is less than the previous element\n if arr[i] < arr[i - 1]:\n largest_index = i # Update the largest index found\n \n return largest_index", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n '''\n Create a function that returns a tuple (a, b), where 'a' is\n the largest of negative integers, and 'b' is the smallest\n of positive integers in a list.\n If there is no negative or positive integers, return them as None.\n\n Examples:\n largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n largest_smallest_integers([]) == (None, None)\n largest_smallest_integers([0]) == (None, None)\n '''\n largest_negative = None\n smallest_positive = None\n\n for num in lst:\n if num < 0:\n if largest_negative is None or num > largest_negative:\n largest_negative = num\n elif num > 0:\n if smallest_positive is None or num < smallest_positive:\n smallest_positive = num\n\n return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n \n Args:\n n (int): The number to evaluate.\n \n Returns:\n bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n \n Example:\n is_equal_to_sum_even(4) == False\n is_equal_to_sum_even(6) == False\n is_equal_to_sum_even(8) == True\n \"\"\"\n # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n if n < 8:\n return False\n \n # Check if n is even\n if n % 2 != 0:\n return False\n \n # If n is even and >= 8, it can be expressed as the sum of 4 positive even numbers\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def compare_one(a, b):\n \"\"\"\n Create a function that takes integers, floats, or strings representing\n real numbers, and returns the larger variable in its given variable type.\n Return None if the values are equal.\n Note: If a real number is represented as a string, the floating point might be . or ,\n\n compare_one(1, 2.5) \u279e 2.5\n compare_one(1, \"2,3\") \u279e \"2,3\"\n compare_one(\"5,1\", \"6\") \u279e \"6\"\n compare_one(\"1\", 1) \u279e None\n \"\"\"\n \n def parse_value(value):\n \"\"\"Convert the input value to a float or return it as is if it's not a number.\"\"\"\n if isinstance(value, str):\n # Replace ',' with '.' for float conversion\n value = value.replace(',', '.')\n try:\n return float(value)\n except ValueError:\n return value # Return the string if it cannot be converted\n return value # Return the value as is if it's not a string\n\n # Parse both values\n parsed_a = parse_value(a)\n parsed_b = parse_value(b)\n\n # Check for equality\n if parsed_a == parsed_b:\n return None\n\n # Return the larger value in its original type\n if parsed_a > parsed_b:\n return a\n else:\n return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n \"\"\"Calculate the factorial of n (n!).\"\"\"\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef special_factorial(n):\n \"\"\"Calculate the Brazilian factorial of n.\"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n result = 1\n for i in range(1, n + 1):\n result *= factorial(i)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n \"\"\"\n Given a string text, replace all spaces in it with underscores, \n and if a string has more than 2 consecutive spaces, \n then replace all consecutive spaces with - \n \n fix_spaces(\"Example\") == \"Example\"\n fix_spaces(\"Example 1\") == \"Example_1\"\n fix_spaces(\" Example 2\") == \"_Example_2\"\n fix_spaces(\" Example 3\") == \"_Example-3\"\n \"\"\"\n # Replace multiple spaces with a single space\n import re\n text = re.sub(r'\\s{3,}', '-', text) # Replace 3 or more spaces with '-'\n text = re.sub(r'\\s+', '_', text) # Replace remaining spaces with '_'\n \n return text", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Yellow Yellow Dirty Fellow"]], "plus_fail_tests": []}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n \"\"\"\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n \n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126\n \"\"\"\n total = 0\n for index, value in enumerate(lst):\n if index % 3 == 0:\n total += value ** 2 # Square if index is a multiple of 3\n elif index % 4 == 0:\n total += value ** 3 # Cube if index is a multiple of 4 and not a multiple of 3\n else:\n total += value # Leave unchanged if not a multiple of 3 or 4\n return total", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n \"\"\"Create a function which takes a string representing a file's name, and returns\n 'Yes' if the the file's name is valid, and returns 'No' otherwise.\n A file's name is considered to be valid if and only if all the following conditions \n are met:\n - There should not be more than three digits ('0'-'9') in the file's name.\n - The file's name contains exactly one dot '.'\n - The substring before the dot should not be empty, and it starts with a letter from \n the latin alphapet ('a'-'z' and 'A'-'Z').\n - The substring after the dot should be one of these: ['txt', 'exe', 'dll']\n Examples:\n file_name_check(\"example.txt\") # => 'Yes'\n file_name_check(\"1example.dll\") # => 'No' (the name should start with a latin alphapet letter)\n \"\"\"\n \n # Check for exactly one dot\n if file_name.count('.') != 1:\n return 'No'\n \n # Split the file name into name and extension\n name, extension = file_name.split('.')\n \n # Check if the name is empty or starts with a non-letter\n if not name or not name[0].isalpha():\n return 'No'\n \n # Check the extension\n valid_extensions = ['txt', 'exe', 'dll']\n if extension not in valid_extensions:\n return 'No'\n \n # Count digits in the file name\n digit_count = sum(c.isdigit() for c in file_name)\n if digit_count > 3:\n return 'No'\n \n return 'Yes'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef words_in_sentence(sentence):\n \"\"\"\n You are given a string representing a sentence,\n the sentence contains some words separated by a space,\n and you have to return a string that contains the words from the original sentence,\n whose lengths are prime numbers,\n the order of the words in the new string should be the same as the original one.\n\n Example 1:\n Input: sentence = \"This is a test\"\n Output: \"is\"\n\n Example 2:\n Input: sentence = \"lets go for swimming\"\n Output: \"go for\"\n\n Constraints:\n * 1 <= len(sentence) <= 100\n * sentence contains only letters\n \"\"\"\n words = sentence.split()\n prime_length_words = [word for word in words if is_prime(len(word))]\n return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n \"\"\"Simplifies the expression x * n and checks if the result is a whole number.\n \n Args:\n x (str): A string representation of a fraction in the format '/'.\n n (str): A string representation of a fraction in the format '/'.\n \n Returns:\n bool: True if x * n evaluates to a whole number, False otherwise.\n \"\"\"\n # Split the fractions into numerator and denominator\n x_numerator, x_denominator = map(int, x.split('/'))\n n_numerator, n_denominator = map(int, n.split('/'))\n \n # Calculate the product of the fractions\n # (x_numerator / x_denominator) * (n_numerator / n_denominator) = (x_numerator * n_numerator) / (x_denominator * n_denominator)\n product_numerator = x_numerator * n_numerator\n product_denominator = x_denominator * n_denominator\n \n # Check if the product is a whole number\n return product_numerator % product_denominator == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n \"\"\"\n Write a function which sorts the given list of integers\n in ascending order according to the sum of their digits.\n Note: if there are several items with similar sum of their digits,\n order them based on their index in original list.\n\n For example:\n >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n >>> order_by_points([]) == []\n \"\"\"\n \n def digit_sum(n):\n \"\"\"Calculate the sum of the digits of n.\"\"\"\n return sum(int(digit) for digit in str(abs(n)))\n\n # Sort the list based on the sum of digits and original index\n return sorted(nums, key=lambda x: (digit_sum(x), nums.index(x)))", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n \"\"\"Returns the number of elements in the array that are greater than 10 \n and both the first and last digits of the number are odd (1, 3, 5, 7, 9).\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n int: The count of numbers meeting the criteria.\n \"\"\"\n \n def is_odd_digit(digit):\n \"\"\"Check if a digit is odd.\"\"\"\n return digit in {'1', '3', '5', '7', '9'}\n \n def first_and_last_odd(num):\n \"\"\"Check if both the first and last digits of the number are odd.\"\"\"\n str_num = str(abs(num)) # Convert to string and take absolute value\n return is_odd_digit(str_num[0]) and is_odd_digit(str_num[-1])\n \n count = 0\n for num in nums:\n if num > 10 and first_and_last_odd(num):\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closest to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sorted by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct planet names. \n Examples\n bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n '''\n\n planets = [\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n ]\n \n # Check if both planets are valid\n if planet1 not in planets or planet2 not in planets:\n return ()\n \n # Get the indices of the planets\n index1 = planets.index(planet1)\n index2 = planets.index(planet2)\n \n # Determine the range of indices\n start_index = min(index1, index2) + 1\n end_index = max(index1, index2)\n \n # Get the planets in between\n in_between_planets = planets[start_index:end_index]\n \n return tuple(in_between_planets)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n \"\"\"\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example :\n Input: n = 5\n Output: 1\n Explanation: \n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n \"\"\"\n # Create the array a\n a = [i * i - i + 1 for i in range(1, n + 1)]\n \n # Count the number of valid triples\n count = 0\n for i in range(n):\n for j in range(i + 1, n):\n for k in range(j + 1, n):\n if (a[i] + a[j] + a[k]) % 3 == 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n \"\"\"Deletes strings with odd lengths from the list and returns the remaining strings sorted\n by length and then alphabetically.\n \n Args:\n lst (list of str): A list of strings.\n \n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef x_or_y(n, x, y):\n \"\"\"Return x if n is a prime number, otherwise return y.\"\"\"\n if is_prime(n):\n return x\n else:\n return y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n \"\"\"Compares the actual game scores with the guessed scores and returns the absolute differences.\n \n Args:\n game (list of int): The actual scores of the matches.\n guess (list of int): The guessed scores of the matches.\n \n Returns:\n list of int: A list containing the absolute differences between the actual scores and the guessed scores.\n If the guess is correct, the value is 0.\n \"\"\"\n return [abs(g - a) for a, g in zip(game, guess)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n \n double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n double_the_difference([-1, -2, 0]) == 0\n double_the_difference([9, -2]) == 81\n double_the_difference([0]) == 0 \n \n If the input list is empty, return 0.\n '''\n if not lst: # Check if the list is empty\n return 0\n \n return sum(x**2 for x in lst if isinstance(x, int) and x >= 0 and x % 2 != 0)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n \"\"\"You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word.\n \n Args:\n a (str): The first word.\n b (str): The second word.\n \n Returns:\n bool: True if the second word or any of its rotations is a substring in the first word, False otherwise.\n \n Examples:\n >>> cycpattern_check(\"abcd\", \"abd\")\n False\n >>> cycpattern_check(\"hello\", \"ell\")\n True\n >>> cycpattern_check(\"whassup\", \"psus\")\n False\n >>> cycpattern_check(\"abab\", \"baa\")\n True\n >>> cycpattern_check(\"efef\", \"eeff\")\n False\n >>> cycpattern_check(\"himenss\", \"simen\")\n True\n \"\"\"\n # Create a string that contains two copies of b\n b_rotations = b + b\n \n # Check if any rotation of b is a substring of a\n return b in b_rotations and len(b) <= len(a)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["xyzw", "xyw"]], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n \"\"\"Find the strongest extension based on the strength defined by the number of uppercase and lowercase letters.\"\"\"\n strongest_extension = None\n max_strength = float('-inf')\n\n for extension in extensions:\n CAP = sum(1 for char in extension if char.isupper())\n SM = sum(1 for char in extension if char.islower())\n strength = CAP - SM\n\n if strength > max_strength:\n max_strength = strength\n strongest_extension = extension\n\n return f\"{class_name}.{strongest_extension}\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n Example:\n even_odd_count(-12) ==> (1, 1)\n even_odd_count(123) ==> (1, 2)\n \"\"\"\n # Convert the number to a string and remove the sign if it's negative\n num_str = str(abs(num))\n \n even_count = 0\n odd_count = 0\n \n # Iterate through each character in the string representation of the number\n for digit in num_str:\n if digit.isdigit(): # Check if the character is a digit\n if int(digit) % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n if not (1 <= number <= 1000):\n raise ValueError(\"Number must be between 1 and 1000\")\n\n roman_numerals = [\n (1000, 'm'),\n (900, 'cm'),\n (500, 'd'),\n (400, 'cd'),\n (100, 'c'),\n (90, 'xc'),\n (50, 'l'),\n (40, 'xl'),\n (10, 'x'),\n (9, 'ix'),\n (5, 'v'),\n (4, 'iv'),\n (1, 'i')\n ]\n\n result = []\n for value, numeral in roman_numerals:\n while number >= value:\n result.append(numeral)\n number -= value\n\n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return True if the three\n sides form a right-angled triangle, False otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or \n 90 degree.\n \n Example:\n right_angle_triangle(3, 4, 5) == True\n right_angle_triangle(1, 2, 3) == False\n '''\n # Sort the sides to identify the longest side\n sides = sorted([a, b, c])\n \n # Check the Pythagorean theorem\n return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n \"\"\"Write a function that accepts a list of strings.\n The list contains different words. Return the word with maximum number\n of unique characters. If multiple strings have maximum number of unique\n characters, return the one which comes first in lexicographical order.\n \n Args:\n words (list): A list of strings.\n \n Returns:\n str: The word with the maximum number of unique characters.\n \"\"\"\n max_word = \"\"\n max_unique_count = 0\n\n for word in words:\n unique_chars = set(word)\n unique_count = len(unique_chars)\n\n if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n max_word = word\n max_unique_count = unique_count\n\n return max_word", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic algebra operations, and \n the second list is a list of integers. Use the two given lists to build the algebraic \n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + ) \n Subtraction ( - ) \n Multiplication ( * ) \n Floor division ( // ) \n Exponentiation ( ** ) \n\n Example:\n operator = ['+', '*', '-']\n operand = [2, 3, 4, 5]\n result = do_algebra(operator, operand)\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.\n \"\"\"\n \n # Start with the first operand\n result = operand[0]\n \n # Iterate through the operators and operands\n for i in range(len(operator)):\n op = operator[i]\n next_operand = operand[i + 1]\n \n if op == '+':\n result += next_operand\n elif op == '-':\n result -= next_operand\n elif op == '*':\n result *= next_operand\n elif op == '//':\n result //= next_operand\n elif op == '**':\n result **= next_operand\n else:\n raise ValueError(f\"Invalid operator: {op}\")\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": []}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n \"\"\"\n You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n \n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n \n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots that exist in stock\n \n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n \"\"\"\n # Calculate how many more carrots are needed\n additional_needed = need - number\n \n # If no additional carrots are needed, return the current state\n if additional_needed <= 0:\n return [number, remaining]\n \n # Determine how many carrots can be eaten from the remaining stock\n eaten = min(additional_needed, remaining)\n \n # Calculate the total eaten and remaining carrots\n total_eaten = number + eaten\n remaining_after_meals = remaining - eaten\n \n return [total_eaten, remaining_after_meals]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string.\n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n >>> string_to_md5('') is None\n >>> string_to_md5('Python') == '5d41402abc4b2a76b9719d911017c592'\n \"\"\"\n if text == \"\":\n return None\n md5_hash = hashlib.md5(text.encode()).hexdigest()\n return md5_hash", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n \"\"\"You are given a string s.\n if s[i] is a letter, reverse its case from lower to upper or vice versa, \n otherwise keep it as it is.\n If the string contains no letters, reverse the string.\n The function should return the resulted string.\n \n Examples:\n solve(\"1234\") = \"4321\"\n solve(\"ab\") = \"AB\"\n solve(\"#a@C\") = \"#A@c\"\n \"\"\"\n # Check if there are any letters in the string\n has_letters = any(c.isalpha() for c in s)\n \n if has_letters:\n # Reverse case for letters and keep others the same\n return ''.join(c.swapcase() for c in s)\n else:\n # Reverse the string if there are no letters\n return s[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascending order.\n\n For example:\n generate_integers(2, 8) => [2, 4, 6, 8]\n generate_integers(8, 2) => [2, 4, 6, 8]\n generate_integers(10, 14) => []\n \"\"\"\n # Determine the range of numbers to consider\n start = min(a, b)\n end = max(a, b)\n\n # Generate a list of even integers in the specified range\n even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n return even_integers", "base_status": "fail", "plus_status": null, "base_fail_tests": [[2, 10]], "plus_fail_tests": []}]}} \ No newline at end of file diff --git a/llm_based_123_eval_results.json b/llm_based_123_eval_results.json new file mode 100644 index 000000000..c2abd84b8 --- /dev/null +++ b/llm_based_123_eval_results.json @@ -0,0 +1 @@ +{"date": "2024-07-25 16:39", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to make it easier to find close elements\n numbers.sort()\n \n # Check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" \n Input to this function is a string containing multiple groups of nested parentheses. \n Your goal is to separate those groups into separate strings and return the list of those.\n Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n Ignore any spaces in the input string.\n \n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n # Remove spaces from the input string\n paren_string = paren_string.replace(\" \", \"\")\n \n result = []\n balance = 0\n current_group = []\n \n for char in paren_string:\n if char == '(':\n if balance == 0 and current_group:\n result.append(''.join(current_group))\n current_group = []\n current_group.append(char)\n balance += 1\n elif char == ')':\n current_group.append(char)\n balance -= 1\n if balance == 0:\n result.append(''.join(current_group))\n current_group = []\n \n # In case there are any remaining groups\n if current_group:\n result.append(''.join(current_group))\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into\n an integer part (largest integer smaller than given number) and decimals\n (leftover part always smaller than 1).\n\n Return the decimal part of the number.\n \n >>> truncate_number(3.5)\n 0.5\n >>> truncate_number(2.75)\n 0.75\n >>> truncate_number(5.0)\n 0.0\n >>> truncate_number(0.99)\n 0.99\n \"\"\"\n if number < 0:\n raise ValueError(\"The number must be positive.\")\n \n integer_part = int(number) # Get the integer part\n decimal_part = number - integer_part # Calculate the decimal part\n return decimal_part", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" \n You're given a list of deposit and withdrawal operations on a bank account that starts with\n zero balance. Your task is to detect if at any point the balance of account falls below zero, and\n at that point function should return True. Otherwise it should return False.\n \n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n \"\"\"\n balance = 0\n for operation in operations:\n balance += operation\n if balance < 0:\n return True\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list to avoid division by zero\n\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n \"\"\" Insert a number 'delimiter' between every two consecutive elements of input list `numbers'\n \n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n for i in range(len(numbers) - 1):\n result.append(numbers[i])\n result.append(delimiter)\n result.append(numbers[-1]) # Append the last element\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n def max_nesting_depth(group: str) -> int:\n max_depth = 0\n current_depth = 0\n \n for char in group:\n if char == '(':\n current_depth += 1\n max_depth = max(max_depth, current_depth)\n elif char == ')':\n current_depth -= 1\n \n return max_depth\n\n groups = paren_string.split()\n return [max_nesting_depth(group) for group in groups]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n \"\"\"\n return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n result = [max_so_far]\n\n for number in numbers[1:]:\n max_so_far = max(max_so_far, number)\n result.append(max_so_far)\n\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n \n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n \"\"\"\n if not numbers:\n return (0, 1)\n \n total_sum = sum(numbers)\n total_product = 1\n for number in numbers:\n total_product *= number\n \n return (total_sum, total_product)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n \"\"\" \n Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n \n >>> string_xor('010', '110')\n '100'\n >>> string_xor('111', '000')\n '111'\n >>> string_xor('101', '101')\n '000'\n >>> string_xor('000', '000')\n '000'\n \"\"\"\n # Ensure both strings are of the same length\n max_len = max(len(a), len(b))\n a = a.zfill(max_len)\n b = b.zfill(max_len)\n \n # Perform XOR operation\n result = []\n for bit_a, bit_b in zip(a, b):\n result.append('1' if bit_a != bit_b else '0')\n \n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n \n >>> make_palindrome('')\n ''\n >>> make_palindrome('cat')\n 'catac'\n >>> make_palindrome('cata')\n 'catac'\n \"\"\"\n # If the input string is empty, return it as is\n if not string:\n return string\n \n # Find the longest palindromic suffix\n for i in range(len(string)):\n if is_palindrome(string[i:]):\n # If we found a palindromic suffix, take the prefix before it\n prefix = string[:i]\n # Append the reverse of the prefix to the original string\n return string + prefix[::-1]\n \n # If no palindromic suffix is found, the whole string is non-palindromic\n return string + string[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return the greatest common divisor of two integers a and b.\n \n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n \"\"\"\n while b:\n a, b = b, a % b\n return abs(a)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n \n >>> longest([])\n >>> None\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n \"\"\"\n if not strings:\n return None\n \n longest_string = strings[0]\n \n for string in strings:\n if len(string) > len(longest_string):\n longest_string = string\n \n return longest_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string\n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n \"\"\"\n return [string[:i] for i in range(1, len(string) + 1)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lower_string = string.lower()\n # Use a set to find distinct characters\n distinct_characters = set(lower_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n \n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n \"\"\"\n return ' '.join(str(i) for i in range(n + 1))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n \n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n \"\"\"\n count = 0\n start = 0\n \n while True:\n start = string.find(substring, start)\n if start == -1:\n break\n count += 1\n start += 1 # Move to the next character to allow for overlapping matches\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" Input to this function is a string representing musical notes in a special ASCII format.\n Your task is to parse this string and return list of integers corresponding to how many beats does each\n note last.\n\n Here is a legend:\n 'o' - whole note, lasts four beats\n 'o|' - half note, lasts two beats\n '.|' - quarter note, lasts one beat\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n # Define a mapping from note representation to beats\n note_to_beats = {\n 'o': 4,\n 'o|': 2,\n '.|': 1\n }\n \n # Split the input string into individual notes\n notes = music_string.split()\n \n # Parse each note and convert to beats\n beats = [note_to_beats[note] for note in notes if note in note_to_beats]\n \n return beats", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n \"\"\" \n Input is a space-delimited string of numerals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest.\n \n >>> sort_numbers('three one five')\n 'one three five'\n \"\"\"\n # Mapping of words to their corresponding numeric values\n num_map = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n \n # Split the input string into words\n words = numbers.split()\n \n # Sort the words based on their numeric values\n sorted_words = sorted(words, key=lambda word: num_map[word])\n \n # Join the sorted words back into a string\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to make it easier to find the closest pair\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest elements\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1.\n \n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n min_val = min(numbers)\n max_val = max(numbers)\n \n # Avoid division by zero if all numbers are the same\n if min_val == max_val:\n return [0.0] * len(numbers)\n \n return [(num - min_val) / (max_val - min_val) for num in numbers]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers\n >>> filter_integers(['a', 3.14, 5])\n [5]\n >>> filter_integers([1, 2, 3, 'abc', {}, []])\n [1, 2, 3]\n \"\"\"\n return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n \"\"\" Return length of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n \"\"\"\n return len(string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n \n >>> largest_divisor(15)\n 5\n >>> largest_divisor(28)\n 14\n >>> largest_divisor(1)\n 0\n >>> largest_divisor(10)\n 5\n \"\"\"\n if n <= 1:\n return 0 # No divisors for 1 or less\n \n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n Input number should be equal to the product of all factors\n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n \"\"\"\n factors = []\n # Check for number of 2s that divide n\n while n % 2 == 0:\n factors.append(2)\n n //= 2\n \n # n must be odd at this point so a skip of 2 (i.e., i = i + 2) can be used\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, append i and divide n\n while n % i == 0:\n factors.append(i)\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n factors.append(n)\n \n return factors", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n \n # Create a new list with elements that occur only once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n \n >>> flip_case('Hello')\n 'hELLO'\n >>> flip_case('Python')\n 'pYTHON'\n >>> flip_case('1234!@#')\n '1234!@#'\n >>> flip_case('')\n ''\n \"\"\"\n return string.swapcase()", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string.\n \n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n \"\"\"\n return ''.join(strings)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n \n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n \"\"\"\n return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n \n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n \"\"\"\n return [x for x in l if x > 0]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float):\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list):\n \"\"\"Calculates the derivative of the polynomial with coefficients xs.\"\"\"\n return [i * coeff for i, coeff in enumerate(xs) if i > 0]\ndef find_zero(xs: list):\n \"\"\" \n xs are coefficients of a polynomial.\n find_zero finds x such that poly(x) = 0.\n find_zero returns only one zero point, even if there are many.\n Moreover, find_zero only takes list xs having an even number of coefficients\n and the largest non-zero coefficient as it guarantees a solution.\n \n >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n -0.5\n >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n 1.0\n \"\"\"\n if len(xs) % 2 != 0:\n raise ValueError(\"The number of coefficients must be even.\")\n \n # Initial guess (can be improved)\n x = 0.0\n tolerance = 1e-7\n max_iterations = 1000\n \n for _ in range(max_iterations):\n f_x = poly(xs, x)\n f_prime_x = poly(derivative(xs), x)\n \n if abs(f_x) < tolerance:\n return x\n \n if f_prime_x == 0:\n raise ValueError(\"Derivative is zero. No solution found.\")\n \n x -= f_x / f_prime_x\n \n raise ValueError(\"Maximum iterations reached. No solution found.\")", "base_status": "fail", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(divisible_by_three)\n \n # Create a new list to hold the result\n result = l.copy()\n \n # Replace values at indices divisible by 3 with sorted values\n for idx, value in zip((i for i in range(len(l)) if i % 3 == 0), sorted_values):\n result[idx] = value\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n \"\"\"Return maximum element in the list.\n \n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty.\")\n max_value = l[0]\n for item in l:\n if item > max_value:\n max_value = item\n return max_value", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n even_indices = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indexed elements\n even_indices.sort()\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Place the sorted even indexed elements back into the result\n for i, value in enumerate(even_indices):\n result[i * 2] = value # Place sorted value at even index\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with encode_cyclic function. Returns decoded string.\n \"\"\"\n # Split string into groups of length 3\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # Reverse the cycling of elements in each group unless the group has fewer than 3 elements\n groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef prime_fib(n: int) -> int:\n \"\"\"\n prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n \n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n count = 0\n for fib in fibonacci_generator():\n if is_prime(fib):\n count += 1\n if count == n:\n return fib", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1]], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n \"\"\"\n Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move at the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.\n\n Parameters:\n n (int): The number of cars in each direction.\n\n Returns:\n int: The number of collisions.\n \"\"\"\n # Each car moving left to right will collide with each car moving right to left\n # Therefore, the total number of collisions is n * n\n return n * n", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n \"\"\"\n triples_sum_to_zero takes a list of integers as an input.\n it returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n \"\"\"\n n = len(l)\n l = list(set(l)) # Remove duplicates\n n = len(l) # Update length after removing duplicates\n\n for i in range(n):\n seen = set()\n target = -l[i]\n for j in range(i + 1, n):\n if target - l[j] in seen:\n return True\n seen.add(l[j])\n return False", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 3, -2, 1]]], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n \"\"\"\n return [x + 1 for x in l]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n \n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n \"\"\"\n seen = set()\n for number in l:\n if -number in seen:\n return True\n seen.add(number)\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n \"\"\"Given length of a side and height, return the area for a triangle.\n \n The area of a triangle can be calculated using the formula:\n area = (base * height) / 2\n \n Args:\n a (float): The length of the base of the triangle.\n h (float): The height of the triangle.\n \n Returns:\n float: The area of the triangle.\n \n Examples:\n >>> triangle_area(5, 3)\n 7.5\n \"\"\"\n return (a * h) / 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion.\n base numbers are less than 10.\n \n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n \"\"\"\n if base < 2 or base >= 10:\n raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n \n if x == 0:\n return '0'\n \n result = []\n while x > 0:\n result.append(str(x % base))\n x //= base\n \n return ''.join(reversed(result))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n \"\"\"Return median of elements in the list l.\n \n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty\")\n \n sorted_list = sorted(l)\n n = len(sorted_list)\n mid = n // 2\n \n if n % 2 == 0:\n return (sorted_list[mid - 1] + sorted_list[mid]) / 2\n else:\n return sorted_list[mid]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fib4(0) -> 0\n fib4(1) -> 0\n fib4(2) -> 2\n fib4(3) -> 0\n fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n \n This function computes the n-th element of the fib4 number sequence without using recursion.\n \n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 2\n elif n == 3:\n return 0\n\n # Initialize the first four values of the sequence\n fib_values = [0, 0, 2, 0]\n\n # Compute the values iteratively\n for i in range(4, n + 1):\n next_value = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n fib_values.append(next_value)\n\n return fib_values[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n \"\"\"\n Checks if given string is a palindrome.\n \n A palindrome is a string that reads the same forward and backward.\n \n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n \"\"\"\n # Normalize the string by removing spaces and converting to lowercase\n normalized_text = text.replace(\" \", \"\").lower()\n # Check if the string is equal to its reverse\n return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n \"\"\"\n Takes as input string encoded with encode_shift function. Returns decoded string.\n \"\"\"\n return \"\".join([chr(((ord(ch) - ord(\"a\") - 5) % 26) + ord(\"a\")) for ch in s])", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n \"\"\"Return True if all numbers in the list l are below threshold t.\n \n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n \"\"\"\n return all(x < t for x in l)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n \"\"\"Add two numbers x and y.\n \n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n \"\"\"\n return x + y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two words have the same characters if they contain the same unique characters,\n regardless of the number of times each character appears.\n \n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n \"\"\"Return n-th Fibonacci number.\n \n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n elif n == 1:\n return 1\n elif n == 2:\n return 1\n else:\n a, b = 1, 1\n for _ in range(2, n):\n a, b = b, a + b\n return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"<\" and \">\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"<\")\n False\n >>> correct_bracketing(\"<>\")\n True\n >>> correct_bracketing(\"<<><>>\")\n True\n >>> correct_bracketing(\"><<>\")\n False\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '<':\n balance += 1\n elif char == '>':\n balance -= 1\n # If balance goes negative, there are more closing brackets\n if balance < 0:\n return False\n # At the end, balance should be zero for correct bracketing\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n \"\"\"Return True if list elements are monotonically increasing or decreasing.\n \n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n \"\"\"\n if not l: # An empty list is considered monotonic\n return True\n\n increasing = decreasing = True\n\n for i in range(1, len(l)):\n if l[i] > l[i - 1]:\n decreasing = False\n elif l[i] < l[i - 1]:\n increasing = False\n\n return increasing or decreasing", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n # Keep dividing n by factor until it is no longer divisible\n while n > 1:\n if n % factor == 0:\n n //= factor # Divide n by the factor\n else:\n factor += 1 # Move to the next potential factor\n return factor # The last factor is the largest prime factor", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"(\" and \")\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"(\")\n False\n >>> correct_bracketing(\"()\")\n True\n >>> correct_bracketing(\"(()())\")\n True\n >>> correct_bracketing(\")(()\")\n False\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n # If balance goes negative, there are unmatched closing brackets\n if balance < 0:\n return False\n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n \n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n \"\"\"\n return n * (n + 1) // 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n \n Args:\n n (int): The index of the FibFib number to compute.\n \n Returns:\n int: The n-th FibFib number.\n \n Examples:\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n if n == 0 or n == 1:\n return 0\n elif n == 2:\n return 1\n \n # Initialize the first three FibFib numbers\n fibfib_numbers = [0, 0, 1]\n \n # Compute FibFib numbers iteratively\n for i in range(3, n + 1):\n next_fibfib = fibfib_numbers[i - 1] + fibfib_numbers[i - 2] + fibfib_numbers[i - 3]\n fibfib_numbers.append(next_fibfib)\n \n return fibfib_numbers[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n \"\"\" \n xs represent coefficients of a polynomial.\n xs[0] + xs[1] * x + xs[2] * x^2 + ....\n Return derivative of this polynomial in the same form.\n \n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n \"\"\"\n # The derivative of a polynomial is calculated by multiplying each coefficient\n # by its corresponding power and reducing the power by one.\n return [i * coeff for i, coeff in enumerate(xs[1:], start=1)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set('aeiouAEIOU')\n count = 0\n \n # Check each character in the string\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1: # Check if 'y' is at the end\n count += 1\n \n return count", "base_status": "fail", "plus_status": null, "base_fail_tests": [["keY"]], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n \n >>> circular_shift(12, 1)\n '21'\n >>> circular_shift(12, 2)\n '12'\n >>> circular_shift(12345, 1)\n '51234'\n >>> circular_shift(12345, 5)\n '54321'\n >>> circular_shift(12345, 6)\n '54321'\n \"\"\"\n # Convert the integer to a string to work with its digits\n str_x = str(x)\n num_digits = len(str_x)\n \n # If shift is greater than the number of digits, reverse the string\n if shift >= num_digits:\n return str_x[::-1]\n \n # Perform the circular shift\n shift = shift % num_digits # Handle shifts larger than the number of digits\n return str_x[-shift:] + str_x[:-shift]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[12, 2]], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n \"\"\"Task\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n \"\"\"\n return sum(ord(char) for char in s if char.isupper())", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n \"\"\"\n In this task, you will be given a string that represents a number of apples and oranges \n that are distributed in a basket of fruit. This basket contains \n apples, oranges, and mango fruits. Given the string that represents the total number of \n the oranges and apples and an integer that represents the total number of the fruits \n in the basket, return the number of the mango fruits in the basket.\n \n Parameters:\n s (str): A string representing the number of apples and oranges.\n n (int): An integer representing the total number of fruits in the basket.\n \n Returns:\n int: The number of mango fruits in the basket.\n \n Examples:\n fruit_distribution(\"5 apples and 6 oranges\", 19) -> 8\n fruit_distribution(\"0 apples and 1 oranges\", 3) -> 2\n fruit_distribution(\"2 apples and 3 oranges\", 100) -> 95\n fruit_distribution(\"100 apples and 1 oranges\", 120) -> 19\n \"\"\"\n \n # Extract the number of apples and oranges from the string\n parts = s.split()\n apples = int(parts[0]) # First part is the number of apples\n oranges = int(parts[2]) # Third part is the number of oranges\n \n # Calculate the number of mangoes\n mangoes = n - apples - oranges\n \n return mangoes", "base_status": "fail", "plus_status": null, "base_fail_tests": [["5 apples and 6 oranges", 19]], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n \"\"\"\n Given an array representing a branch of a tree that has non-negative integer nodes,\n your task is to pluck one of the nodes and return it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n The plucked node should be returned in a list, [ smallest_value, its index ],\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index. \n\n Example 3:\n Input: []\n Output: []\n \n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n Explanation: 0 is the smallest value, but there are two zeros,\n so we will choose the first zero, which has the smallest index.\n\n Constraints:\n * 1 <= nodes.length <= 10000\n * 0 <= node.value\n \"\"\"\n smallest_even = float('inf')\n smallest_index = -1\n\n for index, value in enumerate(arr):\n if value % 2 == 0: # Check if the value is even\n if value < smallest_even: # Check if it's the smallest even found\n smallest_even = value\n smallest_index = index\n\n if smallest_index == -1: # No even value found\n return []\n \n return [smallest_even, smallest_index]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n '''\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequency greater than or equal to the value of the integer itself. \n The frequency of an integer is the number of times it appears in the list.\n If no such a value exist, return -1.\n \n Examples:\n search([4, 1, 2, 2, 3, 1]) == 2\n search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n search([5, 5, 4, 4, 4]) == -1\n '''\n from collections import Counter\n\n # Count the frequency of each integer in the list\n frequency = Counter(lst)\n\n # Initialize the result variable\n result = -1\n\n # Iterate through the frequency dictionary\n for num in frequency:\n # Check if the frequency is greater than or equal to the number itself\n if frequency[num] >= num:\n # Update the result if this number is greater than the current result\n result = max(result, num)\n\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n '''\n Given list of integers, return list in strange order.\n Strange sorting, is when you start with the minimum value,\n then maximum of the remaining integers, then minimum and so on.\n\n Examples:\n strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n strange_sort_list([]) == []\n '''\n if not lst:\n return []\n\n sorted_lst = sorted(lst)\n result = []\n \n while sorted_lst:\n # Append the minimum value\n result.append(sorted_lst.pop(0))\n if sorted_lst: # Check if there are remaining elements\n # Append the maximum value\n result.append(sorted_lst.pop(-1))\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return the area of\n the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n Otherwise return -1.\n Three sides make a valid triangle when the sum of any two sides is greater \n than the third side.\n \n Example:\n triangle_area(3, 4, 5) == 6.00\n triangle_area(1, 2, 10) == -1\n '''\n # Check for valid triangle using the triangle inequality theorem\n if a + b > c and a + c > b and b + c > a:\n # Calculate the semi-perimeter\n s = (a + b + c) / 2\n # Calculate the area using Heron's formula\n area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n return round(area, 2)\n else:\n return -1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n '''\n Write a function that returns True if the object q will fly, and False otherwise.\n The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n\n Example:\n will_it_fly([1, 2], 5) \u279e False \n # 1+2 is less than the maximum possible weight, but it's unbalanced.\n\n will_it_fly([3, 2, 3], 1) \u279e False\n # it's balanced, but 3+2+3 is more than the maximum possible weight.\n\n will_it_fly([3, 2, 3], 9) \u279e True\n # 3+2+3 is less than the maximum possible weight, and it's balanced.\n\n will_it_fly([3], 5) \u279e True\n # 3 is less than the maximum possible weight, and it's balanced.\n '''\n # Check if the list is a palindrome\n is_balanced = q == q[::-1]\n \n # Calculate the sum of the elements in the list\n total_weight = sum(q)\n \n # Check if the total weight is less than or equal to the maximum weight\n is_within_weight_limit = total_weight <= w\n \n # The object will fly if it is balanced and within the weight limit\n return is_balanced and is_within_weight_limit", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n \"\"\"\n Given an array arr of integers, find the minimum number of elements that\n need to be changed to make the array palindromic. A palindromic array is an array that\n is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n For example:\n smallest_change([1,2,3,5,4,7,9,6]) == 4\n smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n smallest_change([1, 2, 3, 2, 1]) == 0\n \"\"\"\n n = len(arr)\n changes = 0\n \n for i in range(n // 2):\n if arr[i] != arr[n - 1 - i]:\n changes += 1\n \n return changes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n else:\n return lst2", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef get_primes_up_to(n):\n \"\"\"Return a list of all prime numbers less than n.\"\"\"\n return [i for i in range(2, n) if is_prime(i)]\ndef is_multiply_prime(a):\n \"\"\"Return True if the given number is the multiplication of 3 prime numbers, False otherwise.\"\"\"\n if a >= 100:\n return False\n \n primes = get_primes_up_to(a)\n prime_count = len(primes)\n \n # Check all combinations of three primes\n for i in range(prime_count):\n for j in range(i, prime_count):\n for k in range(j, prime_count):\n product = primes[i] * primes[j] * primes[k]\n if product == a:\n return True\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n \"\"\"Returns True if x is a simple power of n, otherwise False.\n \n A number x is a simple power of n if there exists an integer k such that n**k = x.\n \n Args:\n x (int): The number to check.\n n (int): The base number.\n \n Returns:\n bool: True if x is a simple power of n, False otherwise.\n \"\"\"\n if n <= 1:\n return x == 1 # 1 is a power of any number, and no other number can be a power of 1 or 0.\n \n power = 1\n while True:\n result = n ** power\n if result == x:\n return True\n elif result > x:\n return False\n power += 1", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1, 12]], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n \"\"\"Count the number of prime hexadecimal digits in the given string.\"\"\"\n # Define the set of prime hexadecimal digits\n prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n \n # Initialize a counter for prime digits\n count = 0\n \n # Iterate through each character in the input string\n for char in num:\n # Check if the character is in the set of prime hexadecimal digits\n if char in prime_hex_digits:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this integer is a cube of some integer number.\n Note: you may assume the input is always valid.\n \n Examples:\n iscube(1) ==> True\n iscube(2) ==> False\n iscube(-1) ==> True\n iscube(64) ==> True\n iscube(0) ==> True\n iscube(180) ==> False\n '''\n # Calculate the cube root of the absolute value of a\n cube_root = round(abs(a) ** (1/3))\n \n # Check if the cube of the rounded cube root equals the absolute value of a\n return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n \"\"\"Convert a decimal number to binary format with specific formatting.\n\n Args:\n decimal (int): A number in decimal form.\n\n Returns:\n str: A string representing the binary format of the number, \n with 'db' at the beginning and end.\n \"\"\"\n # Convert the decimal number to binary and remove the '0b' prefix\n binary_representation = bin(decimal)[2:]\n # Format the result with 'db' at the beginning and end\n formatted_result = f\"db{binary_representation}db\"\n return formatted_result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n \"\"\"You are given a string s.\n Your task is to check if the string is happy or not.\n A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n \n For example:\n is_happy(a) => False\n is_happy(aa) => False\n is_happy(abcd) => True\n is_happy(aabb) => False\n is_happy(adb) => True\n is_happy(xyy) => False\n \"\"\"\n # Check if the length of the string is at least 3\n if len(s) < 3:\n return False\n \n # Check every 3 consecutive letters\n for i in range(len(s) - 2):\n if len(set(s[i:i+3])) < 3: # If there are not 3 distinct letters\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n letter_grades = []\n \n for gpa in grades:\n if gpa == 4.0:\n letter_grades.append('A+')\n elif gpa > 3.7:\n letter_grades.append('A')\n elif gpa > 3.3:\n letter_grades.append('A-')\n elif gpa > 3.0:\n letter_grades.append('B+')\n elif gpa > 2.7:\n letter_grades.append('B')\n elif gpa > 2.3:\n letter_grades.append('B-')\n elif gpa > 2.0:\n letter_grades.append('C+')\n elif gpa > 1.7:\n letter_grades.append('C')\n elif gpa > 1.3:\n letter_grades.append('C-')\n elif gpa > 1.0:\n letter_grades.append('D+')\n elif gpa > 0.7:\n letter_grades.append('D')\n elif gpa > 0.0:\n letter_grades.append('D-')\n else:\n letter_grades.append('E')\n \n return letter_grades", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef prime_length(string):\n \"\"\"Return True if the length of the string is a prime number, False otherwise.\"\"\"\n length = len(string)\n return is_prime(length)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits will be 1 the output should be \"1\".\n For N = 150, the sum of digits will be 6 the output should be \"110\".\n For N = 147, the sum of digits will be 12 the output should be \"1100\".\n \n Variables:\n @N integer\n Constraints: 0 \u2264 N \u2264 10000.\n Output:\n a string of binary number\n \"\"\"\n # Calculate the sum of the digits of N\n digit_sum = sum(int(digit) for digit in str(N))\n \n # Convert the sum to binary and return it as a string\n return bin(digit_sum)[2:]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n \"\"\"\n Given a positive integer n, return the count of the numbers of n-digit\n positive integers that start or end with 1.\n \"\"\"\n if n < 1:\n return 0\n\n # Total n-digit numbers\n total_n_digit_numbers = 9 * (10 ** (n - 1))\n\n # Count of n-digit numbers that start with 1\n start_with_1 = 10 ** (n - 1)\n\n # Count of n-digit numbers that end with 1\n end_with_1 = total_n_digit_numbers // 10\n\n # Count of n-digit numbers that start and end with 1\n start_and_end_with_1 = 10 ** (n - 2) if n > 1 else 0\n\n # Total count of n-digit numbers that start or end with 1\n count = start_with_1 + end_with_1 - start_and_end_with_1\n\n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words and keep track of spaces\n words = s.split(' ')\n \n # Sort each word and keep the spaces intact\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back with spaces\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n \n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by row index (ascending) and then by column index (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n or sort it in descending order if the sum( first index value, last index value) is even.\n\n Note:\n * don't change the given array.\n\n Examples:\n * sort_array([]) => []\n * sort_array([5]) => [5]\n * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n \"\"\"\n if not array: # Check if the array is empty\n return []\n \n first_value = array[0]\n last_value = array[-1]\n sum_values = first_value + last_value\n\n # Create a copy of the array to sort\n sorted_array = array.copy()\n\n if sum_values % 2 == 0:\n # Sort in descending order if the sum is even\n sorted_array.sort(reverse=True)\n else:\n # Sort in ascending order if the sum is odd\n sorted_array.sort()\n\n return sorted_array", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted = []\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Calculate the new character by shifting it down the alphabet\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n encrypted.append(new_char)\n else:\n encrypted.append(char) # Non-alphabetic characters remain unchanged\n return ''.join(encrypted)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Sort the unique elements\n sorted_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_elements[1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n \n For example:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n \"\"\"\n # Split the string into sentences using the delimiters\n sentences = []\n current_sentence = []\n for char in S:\n if char in '.!?':\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n current_sentence = []\n else:\n current_sentence.append(char)\n if current_sentence: # Add the last sentence if it exists\n sentences.append(''.join(current_sentence).strip())\n \n # Count the number of sentences that start with \"I\"\n boredom_count = sum(1 for sentence in sentences if sentence.startswith('I'))\n \n return boredom_count", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n '''\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n \n Examples\n any_int(5, 2, 7) \u279e True\n any_int(3, 2, 2) \u279e False\n any_int(3, -2, 1) \u279e True\n any_int(3.6, -2.2, 2) \u279e False\n '''\n # Check if all inputs are integers\n if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n # Check if one number is equal to the sum of the other two\n return x == y + z or y == x + z or z == x + y\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n \"\"\"\n Write a function that takes a message, and encodes in such a \n way that it swaps case of all letters, replaces all vowels in \n the message with the letter that appears 2 places ahead of that \n vowel in the english alphabet. \n Assume only letters. \n \n Examples:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n vowels = 'aeiouAEIOU'\n encoded_message = []\n\n for char in message:\n if char.isalpha(): # Check if the character is a letter\n # Swap case\n if char in vowels:\n # Replace vowel with the letter 2 places ahead\n if char.islower():\n new_char = chr(((ord(char) - ord('a') + 2) % 26) + ord('a'))\n else:\n new_char = chr(((ord(char) - ord('A') + 2) % 26) + ord('A'))\n else:\n new_char = char.swapcase() # Swap case for consonants\n encoded_message.append(new_char)\n else:\n encoded_message.append(char) # Keep non-letter characters unchanged\n\n return ''.join(encoded_message)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["TEST"]], "plus_fail_tests": []}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef sum_of_digits(n):\n \"\"\"Return the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n largest_prime = -1\n \n for number in lst:\n if is_prime(number) and number > largest_prime:\n largest_prime = number\n \n if largest_prime == -1:\n return 0 # Return 0 if no prime is found\n \n return sum_of_digits(largest_prime)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in lower \n case or all keys are strings in upper case, else return False.\n The function should return False if the given dictionary is empty.\n \n Examples:\n check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n \"\"\"\n if not input_dict:\n return False\n\n all_lower = all(isinstance(key, str) and key.islower() for key in input_dict.keys())\n all_upper = all(isinstance(key, str) and key.isupper() for key in input_dict.keys())\n\n return all_lower or all_upper", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_up_to(n):\n \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n primes = []\n for i in range(2, n):\n if is_prime(i):\n primes.append(i)\n return primes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.\n \"\"\"\n # Get the unit digit of the first number\n unit_digit_a = abs(a) % 10\n # Get the unit digit of the second number\n unit_digit_b = abs(b) % 10\n # Return the product of the unit digits\n return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n count_upper('aBCdEf') returns 1\n count_upper('abcdefg') returns 0\n count_upper('dBBE') returns 0\n \"\"\"\n uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n count = 0\n \n for i in range(0, len(s), 2): # Iterate over even indices\n if s[i] in uppercase_vowels:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n >>> closest_integer(\"14.5\")\n 15\n >>> closest_integer(\"-14.5\")\n -15\n >>> closest_integer(\"0.5\")\n 1\n >>> closest_integer(\"-0.5\")\n -1\n '''\n\n # Convert the string to a float\n num = float(value)\n \n # Get the floor and ceiling of the number\n lower = int(num // 1)\n upper = lower + 1\n \n # Check the distance to the lower and upper integers\n if abs(num - lower) < abs(num - upper):\n return lower\n elif abs(num - lower) > abs(num - upper):\n return upper\n else:\n # If equidistant, round away from zero\n if num > 0:\n return upper\n else:\n return lower", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n \"\"\"\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n >>> make_a_pile(4)\n [4, 6, 8, 10]\n >>> make_a_pile(1)\n [1]\n \"\"\"\n stones = []\n current_stones = n\n \n for i in range(n):\n stones.append(current_stones)\n if current_stones % 2 == 0: # current_stones is even\n current_stones += 2 # next even number\n else: # current_stones is odd\n current_stones += 2 # next odd number\n \n return stones", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n \"\"\"\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n \"\"\"\n # Split the string by commas and spaces, then filter out any empty strings\n words = [word.strip() for word in s.replace(',', ' ').split() if word]\n return words", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n \"\"\"This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If \n there's no such number, then the function should return -1.\n\n For example:\n choose_num(12, 15) = 14\n choose_num(13, 12) = -1\n \"\"\"\n # Ensure x is less than or equal to y\n if x > y:\n return -1\n \n # Start from the largest number in the range and check for evenness\n for num in range(y, x - 1, -1):\n if num % 2 == 0:\n return num\n \n return -1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n \"\"\"You are given two positive integers n and m, and your task is to compute the\n average of the integers from n through m (including n and m). \n Round the answer to the nearest integer and convert that to binary.\n If n is greater than m, return -1.\n \n Example:\n rounded_avg(1, 5) => \"0b11\"\n rounded_avg(7, 5) => -1\n rounded_avg(10, 20) => \"0b1111\"\n rounded_avg(20, 33) => \"0b11010\"\n \"\"\"\n if n > m:\n return -1\n \n # Calculate the sum of integers from n to m\n total_sum = sum(range(n, m + 1))\n count = m - n + 1 # Total numbers from n to m\n \n # Calculate the average and round it\n average = total_sum / count\n rounded_average = round(average)\n \n # Convert the rounded average to binary\n return bin(rounded_average)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n \"\"\"Given a list of positive integers x, return a sorted list of all \n elements that haven't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n def has_even_digit(n):\n \"\"\"Check if the number has any even digit.\"\"\"\n for digit in str(n):\n if int(digit) % 2 == 0:\n return True\n return False\n\n # Filter the list to include only numbers without even digits\n result = [num for num in x if not has_even_digit(num)]\n \n # Return the sorted result\n return sorted(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n reverse the resulting array, and then replace each digit by its corresponding name from\n \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n For example:\n arr = [2, 1, 1, 4, 5, 8, 2, 3] \n -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n \n If the array is empty, return an empty array:\n arr = []\n return []\n \n If the array has any strange number ignore it:\n arr = [1, -1 , 55] \n -> sort arr -> [-1, 1, 55]\n -> reverse arr -> [55, 1, -1]\n return = ['One']\n \"\"\"\n \n # Mapping of digits to their corresponding names\n digit_to_name = {\n 1: \"One\",\n 2: \"Two\",\n 3: \"Three\",\n 4: \"Four\",\n 5: \"Five\",\n 6: \"Six\",\n 7: \"Seven\",\n 8: \"Eight\",\n 9: \"Nine\"\n }\n \n # Filter the array to include only numbers between 1 and 9\n filtered_arr = [num for num in arr if 1 <= num <= 9]\n \n # Sort the filtered array\n sorted_arr = sorted(filtered_arr)\n \n # Reverse the sorted array\n reversed_arr = sorted_arr[::-1]\n \n # Convert the digits to their corresponding names\n result = [digit_to_name[num] for num in reversed_arr]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def factorial(i):\n \"\"\"Calculate the factorial of a given number i.\"\"\"\n if i == 0 or i == 1:\n return 1\n result = 1\n for j in range(2, i + 1):\n result *= j\n return result\ndef sum_of_numbers(i):\n \"\"\"Calculate the sum of numbers from 1 to i.\"\"\"\n return (i * (i + 1)) // 2\ndef f(n):\n \"\"\"Return a list of size n, where the value at index i is the factorial of i if i is even,\n or the sum of numbers from 1 to i otherwise. Indexing starts from 1.\"\"\"\n result = []\n for i in range(1, n + 1):\n if i % 2 == 0: # i is even\n result.append(factorial(i))\n else: # i is odd\n result.append(sum_of_numbers(i))\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n \"\"\"\n Given a positive integer n, return a tuple that has the number of even and odd\n integer palindromes that fall within the range(1, n), inclusive.\n\n Example 1:\n Input: 3\n Output: (1, 2)\n Explanation:\n Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n Example 2:\n Input: 12\n Output: (4, 6)\n Explanation:\n Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n Note:\n 1. 1 <= n <= 10^3\n 2. returned tuple has the number of even and odd integer palindromes respectively.\n \"\"\"\n \n def is_palindrome(num):\n return str(num) == str(num)[::-1]\n\n even_count = 0\n odd_count = 0\n\n for i in range(1, n + 1):\n if is_palindrome(i):\n if i % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return True else return False.\n If the given array is empty then return True.\n\n Note: The given list is guaranteed to have unique elements.\n\n For Example:\n \n move_one_ball([3, 4, 5, 1, 2])==>True\n Explanation: By performing 2 right shift operations, non-decreasing order can\n be achieved for the given array.\n move_one_ball([3, 5, 4, 1, 2])==>False\n Explanation: It is not possible to get non-decreasing order for the given\n array by performing any number of right shift operations.\n \"\"\"\n if not arr:\n return True\n\n n = len(arr)\n sorted_arr = sorted(arr)\n\n # Check how many times we can right shift\n # We can find the point where the sorted array starts to differ from the original\n count = 0\n for i in range(n):\n if arr[i] != sorted_arr[i]:\n count += 1\n\n # If the count of differences is more than 1, we cannot sort it with shifts\n return count <= 1", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[3, 4, 5, 1, 2]]], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n \"\"\"\n Write a function count_nums which takes an array of integers and returns\n the number of elements which has a sum of digits > 0.\n If a number is negative, then its first signed digit will be negative:\n e.g. -123 has signed digits -1, 2, and 3.\n \n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n def sum_of_digits(n):\n # Convert the number to string and calculate the sum of its digits\n return sum(int(digit) if digit != '-' else -int(digit[1]) for digit in str(n) if digit.isdigit() or digit == '-')\n\n count = 0\n for number in arr:\n if sum_of_digits(number) > 0:\n count += 1\n \n return count", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[-1, -2, 0]]], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n \"\"\"Determines whether it is possible to perform an exchange of elements\n between two lists to make lst1 a list of only even numbers.\n \n Args:\n lst1 (list): The first list of numbers.\n lst2 (list): The second list of numbers.\n \n Returns:\n str: \"YES\" if lst1 can be made all even, otherwise \"NO\".\n \"\"\"\n # Check if lst1 already contains only even numbers\n if all(x % 2 == 0 for x in lst1):\n return \"YES\"\n \n # Count the number of odd numbers in lst1\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n \n # Check if lst2 has at least one even number to exchange\n has_even_in_lst2 = any(x % 2 == 0 for x in lst2)\n \n # If lst1 has odd numbers and lst2 has at least one even number,\n # we can exchange to make lst1 all even\n if odd_count_lst1 > 0 and has_even_in_lst2:\n return \"YES\"\n \n return \"NO\"", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 3, 4], [1, 5, 3, 4]]], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n \"\"\"\n if not test:\n return {}\n\n # Split the input string into a list of letters\n letters = test.split()\n \n # Create a dictionary to count occurrences of each letter\n count_dict = {}\n for letter in letters:\n if letter in count_dict:\n count_dict[letter] += 1\n else:\n count_dict[letter] = 1\n\n # Find the maximum count\n max_count = max(count_dict.values())\n \n # Create a result dictionary for letters with the maximum count\n result = {letter: count for letter, count in count_dict.items() if count == max_count}\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n \"\"\"Task\n We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and True/False for the check.\n Example\n For s = \"abcde\", c = \"ae\", the result should be ('bcd',False)\n For s = \"abcdef\", c = \"b\", the result should be ('acdef',False)\n For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc',True)\n \"\"\"\n # Create a set of characters to delete for faster lookup\n delete_set = set(c)\n \n # Create the result string by filtering out characters in delete_set\n result = ''.join(char for char in s if char not in delete_set)\n \n # Check if the result string is a palindrome\n is_palindrome = result == result[::-1]\n \n return (result, is_palindrome)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for char in s if char in '13579')\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n Example\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n \"\"\"\n # Initialize variables\n min_sum = float('inf') # Start with a very large number\n current_sum = 0 # This will hold the current sub-array sum\n\n for num in nums:\n current_sum += num # Add the current number to the current sum\n min_sum = min(min_sum, current_sum) # Update the minimum sum if current is smaller\n if current_sum > 0: # If current sum is positive, reset it\n current_sum = 0\n\n return min_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n \"\"\"\n Calculate the number of times buckets need to be lowered to empty the wells.\n\n Parameters:\n grid (list of list of int): A rectangular grid representing wells.\n capacity (int): The capacity of each bucket.\n\n Returns:\n int: The total number of times buckets need to be lowered.\n \"\"\"\n total_water = 0\n \n # Count the total amount of water in the grid\n for row in grid:\n total_water += sum(row)\n \n # Calculate the number of times buckets need to be lowered\n # Each bucket can carry 'capacity' units of water\n if total_water == 0:\n return 0\n else:\n return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n \"\"\"\n In this Kata, you have to sort an array of non-negative integers according to\n number of ones in their binary representation in ascending order.\n For similar number of ones, sort based on decimal value.\n\n It must be implemented like this:\n >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n >>> sort_array([1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]\n \"\"\"\n # Sort the array using a custom key\n return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n \"\"\"Given a string s and a natural number n, returns a list of all words from string s \n that contain exactly n consonants, in the order they appear in the string s.\n \n Args:\n s (str): The input string containing words.\n n (int): The number of consonants to match.\n \n Returns:\n list: A list of words containing exactly n consonants.\n \"\"\"\n if not s:\n return []\n\n # Define a set of consonants\n consonants = set(\"bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ\")\n \n # Split the string into words\n words = s.split()\n \n # Function to count consonants in a word\n def count_consonants(word):\n return sum(1 for char in word if char in consonants)\n \n # Filter words that have exactly n consonants\n result = [word for word in words if count_consonants(word) == n]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n two consonants from the right side of the word (case sensitive).\n \n Vowels in the beginning and ending don't count. Return empty string if you didn't\n find any vowel that meets the above condition. \n\n You may assume that the given string contains English letters only.\n\n Example:\n get_closest_vowel(\"yogurt\") ==> \"u\"\n get_closest_vowel(\"FULL\") ==> \"U\"\n get_closest_vowel(\"quick\") ==> \"\"\n get_closest_vowel(\"ab\") ==> \"\"\n \"\"\"\n vowels = \"aeiouAEIOU\"\n n = len(word)\n\n # Start from the end of the word\n for i in range(n - 2, 0, -1): # Start from the second last character to the second character\n if word[i] in vowels: # Check if the current character is a vowel\n # Check if the characters before and after are consonants\n if word[i - 1].isalpha() and word[i + 1].isalpha() and word[i - 1] not in vowels and word[i + 1] not in vowels:\n return word[i] # Return the vowel if it is between two consonants\n\n return \"\" # Return empty string if no such vowel is found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst[0], lst[1]\n \n # Check both concatenation orders\n return 'Yes' if is_good(s1 + s2) or is_good(s2 + s1) else 'No'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Get the top k elements\n top_k = sorted_arr[:k]\n # Return the top k elements sorted in ascending order\n return sorted(top_k)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n as follows: start with any positive integer n. Then each term is obtained from the \n previous term as follows: if the previous term is even, the next term is one half of \n the previous term. If the previous term is odd, the next term is 3 times the previous\n term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n Note: \n 1. Collatz(1) is [1].\n 2. returned list sorted in increasing order.\n\n For example:\n get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n collatz_sequence = []\n current = n\n \n while current != 1:\n collatz_sequence.append(current)\n if current % 2 == 0:\n current //= 2\n else:\n current = 3 * current + 1\n \n collatz_sequence.append(1) # Add the last term, which is 1\n \n # Filter odd numbers and sort the result\n odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n \n return odd_numbers", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n \"\"\"\n Given a non-empty array of integers arr and an integer k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example:\n\n Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n Output: 24 # sum of 21 + 3\n\n Constraints:\n 1. 1 <= len(arr) <= 100\n 2. 1 <= k <= len(arr)\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate through the first k elements of the array\n for i in range(k):\n # Check if the element has at most two digits\n if -100 < arr[i] < 100:\n total_sum += arr[i]\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n '''\n Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n Examples\n split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"abcdef\") == 3 \n '''\n # Check for whitespace\n if ' ' in txt:\n return txt.split()\n \n # Check for commas\n elif ',' in txt:\n return txt.split(',')\n \n # If no whitespace or commas, count lower-case letters with odd order\n else:\n odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n return odd_count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n \n The date is valid if all of the following rules are satisfied:\n 1. The date string is not empty.\n 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n The number of days is not less than 1 or higher than 29 for the month 2.\n 3. The months should not be less than 1 or higher than 12.\n 4. The date should be in the format: mm-dd-yyyy\n \n Args:\n date (str): The date string to validate.\n \n Returns:\n bool: True if the date is valid, False otherwise.\n \"\"\"\n if not date:\n return False\n \n # Check the format\n if len(date) != 10 or date[2] != '-' or date[5] != '-':\n return False\n \n try:\n month = int(date[:2])\n day = int(date[3:5])\n year = int(date[6:])\n except ValueError:\n return False\n \n # Validate month\n if month < 1 or month > 12:\n return False\n \n # Validate day based on month\n if month in [1, 3, 5, 7, 8, 10, 12]: # 31 days\n if day < 1 or day > 31:\n return False\n elif month in [4, 6, 9, 11]: # 30 days\n if day < 1 or day > 30:\n return False\n elif month == 2: # February\n if day < 1 or day > 29:\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n '''\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return False. Assume no negative numbers and only integers.\n\n Examples\n is_sorted([5]) \u279e True\n is_sorted([1, 2, 3, 4, 5]) \u279e True\n is_sorted([1, 3, 2, 4, 5]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n '''\n if not lst: # An empty list is considered sorted\n return True\n\n seen = set()\n last = None\n\n for num in lst:\n if num in seen:\n # If we see a number again, check if it's a duplicate\n return False\n seen.add(num)\n\n if last is not None and num < last:\n return False\n \n last = num\n\n return True", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef intersection(interval1, interval2):\n \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n start1, end1 = interval1\n start2, end2 = interval2\n \n # Find the intersection\n start_intersection = max(start1, start2)\n end_intersection = min(end1, end2)\n \n # Check if there is an intersection\n if start_intersection > end_intersection:\n return \"NO\"\n \n # Calculate the length of the intersection\n length_of_intersection = end_intersection - start_intersection\n \n # Check if the length is a prime number\n if is_prime(length_of_intersection):\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n if not arr:\n return None\n\n product_of_signs = 1\n sum_of_magnitudes = 0\n\n for num in arr:\n if num > 0:\n product_of_signs *= 1\n sum_of_magnitudes += num\n elif num < 0:\n product_of_signs *= -1\n sum_of_magnitudes += -num\n else: # num == 0\n product_of_signs = 0\n break\n\n return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n \"\"\"Calculate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n if n < 0:\n return []\n\n # Initialize the list to store the Tribonacci numbers\n tribonacci_sequence = []\n\n # Define the base case\n for i in range(n + 1):\n if i == 0:\n tribonacci_sequence.append(1) # tri(0) = 1\n elif i == 1:\n tribonacci_sequence.append(3) # tri(1) = 3\n elif i % 2 == 0: # n is even\n tribonacci_sequence.append(1 + i / 2)\n else: # n is odd\n # Calculate tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1)\n tri_n_minus_1 = tribonacci_sequence[i - 1]\n tri_n_minus_2 = tribonacci_sequence[i - 2]\n tri_n_plus_1 = tribonacci_sequence[i + 1] if i + 1 < len(tribonacci_sequence) else 0\n tribonacci_sequence.append(tri_n_minus_1 + tri_n_minus_2 + tri_n_plus_1)\n\n return tribonacci_sequence", "base_status": "fail", "plus_status": null, "base_fail_tests": [[3]], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n from collections import deque\n\n N = len(grid)\n directions = [(0, 1), (1, 0), (0, -1), (-1, 0)] # Right, Down, Left, Up\n min_path = None\n\n def bfs(start_row, start_col):\n nonlocal min_path\n queue = deque([(start_row, start_col, [grid[start_row][start_col]])])\n visited = set((start_row, start_col))\n\n while queue:\n row, col, path = queue.popleft()\n\n if len(path) == k:\n if min_path is None or path < min_path:\n min_path = path\n continue\n\n for dr, dc in directions:\n new_row, new_col = row + dr, col + dc\n if 0 <= new_row < N and 0 <= new_col < N:\n new_path = path + [grid[new_row][new_col]]\n queue.append((new_row, new_col, new_path))\n\n for i in range(N):\n for j in range(N):\n bfs(i, j)\n\n return min_path", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n \"\"\"Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n \n For example:\n digits(1) == 1\n digits(4) == 0\n digits(235) == 15\n \"\"\"\n product = 1\n has_odd = False\n \n for digit in str(n):\n digit = int(digit)\n if digit % 2 != 0: # Check if the digit is odd\n product *= digit\n has_odd = True\n \n return product if has_odd else 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n '''\n Create a function that takes a string as input which contains only square brackets.\n The function should return True if and only if there is a valid subsequence of brackets \n where at least one bracket in the subsequence is nested.\n\n is_nested('[[]]') \u279e True\n is_nested('[]]]]]]][[[[[]') \u279e False\n is_nested('[][]') \u279e False\n is_nested('[]') \u279e False\n is_nested('[[][]]') \u279e True\n is_nested('[[]][[') \u279e True\n '''\n # Initialize a counter for open brackets\n open_count = 0\n # Initialize a flag to check for nesting\n nested = False\n \n for char in string:\n if char == '[':\n open_count += 1\n # If we have more than one open bracket, we have nesting\n if open_count > 1:\n nested = True\n elif char == ']':\n open_count -= 1\n # If we close a bracket and there was at least one open bracket\n if open_count < 0:\n return False # More closing brackets than opening\n # We need to have no unmatched opening brackets at the end\n return nested and open_count == 0", "base_status": "fail", "plus_status": null, "base_fail_tests": [["[[]][["]], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n '''\n Create a function that returns True if the last character\n of a given string is an alphabetical character and is not\n a part of a word, and False otherwise.\n Note: \"word\" is a group of characters separated by space.\n\n Examples:\n check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '''\n # Strip any trailing whitespace from the string\n txt = txt.rstrip()\n \n # Check if the string is empty after stripping\n if not txt:\n return False\n \n # Get the last character of the string\n last_char = txt[-1]\n \n # Check if the last character is an alphabetical character\n if last_char.isalpha():\n # Check if the last character is part of a word\n # A character is part of a word if it is preceded by a non-space character\n if len(txt) > 1 and txt[-2] != ' ':\n return False\n return True\n \n return False", "base_status": "fail", "plus_status": null, "base_fail_tests": [["eeeee e "]], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers.\n You need to return the sum of squared numbers in the given list,\n round each element in the list to the upper int (Ceiling) first.\n \n Examples:\n For lst = [1,2,3] the output should be 14\n For lst = [1,4,9] the output should be 98\n For lst = [1,3,5,7] the output should be 84\n For lst = [1.4,4.2,0] the output should be 29\n For lst = [-2.4,1,1] the output should be 6\n \"\"\"\n return sum(math.ceil(x) ** 2 for x in lst)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n '''\n Create a function that returns a tuple (a, b), where 'a' is\n the largest of negative integers, and 'b' is the smallest\n of positive integers in a list.\n If there is no negative or positive integers, return them as None.\n\n Examples:\n largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n largest_smallest_integers([]) == (None, None)\n largest_smallest_integers([0]) == (None, None)\n '''\n largest_negative = None\n smallest_positive = None\n\n for num in lst:\n if num < 0:\n if largest_negative is None or num > largest_negative:\n largest_negative = num\n elif num > 0:\n if smallest_positive is None or num < smallest_positive:\n smallest_positive = num\n\n return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n \"\"\"Create a function which returns the largest index of an element which\n is not greater than or equal to the element immediately preceding it. If\n no such element exists then return -1. The given array will not contain\n duplicate values.\n\n Examples:\n can_arrange([1,2,4,3,5]) = 3\n can_arrange([1,2,3]) = -1\n \"\"\"\n # Initialize the index to -1, which will be returned if no such element is found\n largest_index = -1\n \n # Iterate through the array starting from the second element\n for i in range(1, len(arr)):\n # Check if the current element is less than the previous element\n if arr[i] < arr[i - 1]:\n largest_index = i # Update the largest index found\n \n return largest_index", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def compare_one(a, b):\n \"\"\"\n Create a function that takes integers, floats, or strings representing\n real numbers, and returns the larger variable in its given variable type.\n Return None if the values are equal.\n Note: If a real number is represented as a string, the floating point might be . or ,\n\n compare_one(1, 2.5) \u279e 2.5\n compare_one(1, \"2,3\") \u279e \"2,3\"\n compare_one(\"5,1\", \"6\") \u279e \"6\"\n compare_one(\"1\", 1) \u279e None\n \"\"\"\n \n def parse_value(value):\n \"\"\"Convert the input value to a float or return it as is if it's not a number.\"\"\"\n if isinstance(value, str):\n # Replace ',' with '.' for float conversion\n value = value.replace(',', '.')\n try:\n return float(value)\n except ValueError:\n return value # Return the string if it cannot be converted\n return value # Return the number as is\n\n # Parse both values\n parsed_a = parse_value(a)\n parsed_b = parse_value(b)\n\n # Check for equality\n if parsed_a == parsed_b:\n return None\n\n # Return the larger value in its original type\n if parsed_a > parsed_b:\n return a\n else:\n return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n \n Args:\n n (int): The number to evaluate.\n \n Returns:\n bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n \n Example:\n is_equal_to_sum_even(4) == False\n is_equal_to_sum_even(6) == False\n is_equal_to_sum_even(8) == True\n \"\"\"\n # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n if n < 8:\n return False\n \n # Check if n is even\n if n % 2 != 0:\n return False\n \n # If n is even and at least 8, it can be expressed as the sum of 4 positive even numbers\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n \"\"\"Calculate the factorial of a non-negative integer n.\"\"\"\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef special_factorial(n):\n \"\"\"Calculate the Brazilian factorial of n.\"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n result = 1\n for i in range(1, n + 1):\n result *= factorial(i)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n \"\"\"\n Given a string text, replace all spaces in it with underscores, \n and if a string has more than 2 consecutive spaces, \n then replace all consecutive spaces with - \n \n fix_spaces(\"Example\") == \"Example\"\n fix_spaces(\"Example 1\") == \"Example_1\"\n fix_spaces(\" Example 2\") == \"_Example_2\"\n fix_spaces(\" Example 3\") == \"_Example-3\"\n \"\"\"\n import re\n\n # Replace more than 2 consecutive spaces with a single '-'\n text = re.sub(r' {3,}', '-', text)\n \n # Replace single or double spaces with underscores\n text = text.replace(' ', '_')\n \n return text", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n \"\"\"Create a function which takes a string representing a file's name, and returns\n 'Yes' if the the file's name is valid, and returns 'No' otherwise.\n A file's name is considered to be valid if and only if all the following conditions \n are met:\n - There should not be more than three digits ('0'-'9') in the file's name.\n - The file's name contains exactly one dot '.'\n - The substring before the dot should not be empty, and it starts with a letter from \n the latin alphapet ('a'-'z' and 'A'-'Z').\n - The substring after the dot should be one of these: ['txt', 'exe', 'dll']\n Examples:\n file_name_check(\"example.txt\") # => 'Yes'\n file_name_check(\"1example.dll\") # => 'No' (the name should start with a latin alphapet letter)\n \"\"\"\n \n # Check for exactly one dot\n if file_name.count('.') != 1:\n return 'No'\n \n # Split the file name into name and extension\n name, extension = file_name.split('.')\n \n # Check if the name is empty or starts with a non-letter\n if not name or not name[0].isalpha():\n return 'No'\n \n # Check the number of digits in the name\n digit_count = sum(c.isdigit() for c in name)\n if digit_count > 3:\n return 'No'\n \n # Check if the extension is valid\n valid_extensions = ['txt', 'exe', 'dll']\n if extension not in valid_extensions:\n return 'No'\n \n return 'Yes'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n \"\"\"\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n \n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126\n \"\"\"\n total = 0\n for index, value in enumerate(lst):\n if index % 3 == 0:\n total += value ** 2 # Square if index is a multiple of 3\n elif index % 4 == 0:\n total += value ** 3 # Cube if index is a multiple of 4 and not a multiple of 3\n else:\n total += value # Keep the value unchanged for other indices\n return total", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n \"\"\"Simplifies the expression x * n and checks if the result is a whole number.\n \n Args:\n x (str): A string representation of a fraction in the format '/'.\n n (str): A string representation of a fraction in the format '/'.\n \n Returns:\n bool: True if x * n evaluates to a whole number, False otherwise.\n \"\"\"\n # Split the fractions into numerator and denominator\n x_numerator, x_denominator = map(int, x.split('/'))\n n_numerator, n_denominator = map(int, n.split('/'))\n \n # Calculate the product of the fractions\n # (x_numerator / x_denominator) * (n_numerator / n_denominator) = (x_numerator * n_numerator) / (x_denominator * n_denominator)\n product_numerator = x_numerator * n_numerator\n product_denominator = x_denominator * n_denominator\n \n # Check if the product is a whole number\n return product_numerator % product_denominator == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef words_in_sentence(sentence):\n \"\"\"\n You are given a string representing a sentence,\n the sentence contains some words separated by a space,\n and you have to return a string that contains the words from the original sentence,\n whose lengths are prime numbers,\n the order of the words in the new string should be the same as the original one.\n\n Example 1:\n Input: sentence = \"This is a test\"\n Output: \"is\"\n\n Example 2:\n Input: sentence = \"lets go for swimming\"\n Output: \"go for\"\n \"\"\"\n words = sentence.split()\n prime_length_words = [word for word in words if is_prime(len(word))]\n return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n \"\"\"Write a function that takes an array of numbers as input and returns \n the number of elements in the array that are greater than 10 and both \n first and last digits of a number are odd (1, 3, 5, 7, 9).\n \n For example:\n specialFilter([15, -73, 14, -15]) => 1 \n specialFilter([33, -2, -3, 45, 21, 109]) => 2\n \"\"\"\n \n def is_odd_digit(digit):\n return digit in {'1', '3', '5', '7', '9'}\n \n count = 0\n for num in nums:\n if num > 10:\n str_num = str(abs(num)) # Convert to string and take absolute value\n if is_odd_digit(str_num[0]) and is_odd_digit(str_num[-1]):\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n \"\"\"\n Write a function which sorts the given list of integers\n in ascending order according to the sum of their digits.\n Note: if there are several items with similar sum of their digits,\n order them based on their index in original list.\n\n For example:\n >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n >>> order_by_points([]) == []\n \"\"\"\n \n def digit_sum(n):\n return sum(int(digit) for digit in str(abs(n)))\n\n return sorted(nums, key=lambda x: (digit_sum(x), nums.index(x)))", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closest to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sorted by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct planet names. \n Examples\n bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n '''\n\n planets = [\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n ]\n \n # Check if both planets are valid\n if planet1 not in planets or planet2 not in planets:\n return ()\n \n # Get the indices of the planets\n index1 = planets.index(planet1)\n index2 = planets.index(planet2)\n \n # Determine the range of indices\n start_index = min(index1, index2) + 1\n end_index = max(index1, index2)\n \n # Get the planets in between\n in_between_planets = planets[start_index:end_index]\n \n return tuple(in_between_planets)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n \"\"\"\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example :\n Input: n = 5\n Output: 1\n Explanation: \n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n \"\"\"\n # Create the array a\n a = [i * i - i + 1 for i in range(1, n + 1)]\n \n # Count the number of valid triples\n count = 0\n for i in range(n):\n for j in range(i + 1, n):\n for k in range(j + 1, n):\n if (a[i] + a[j] + a[k]) % 3 == 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length and alphabetically.\n \n Args:\n lst (list): A list of strings.\n \n Returns:\n list: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef x_or_y(n, x, y):\n \"\"\"Return the value of x if n is a prime number, otherwise return y.\"\"\"\n if is_prime(n):\n return x\n else:\n return y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n \n double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n double_the_difference([-1, -2, 0]) == 0\n double_the_difference([9, -2]) == 81\n double_the_difference([0]) == 0 \n \n If the input list is empty, return 0.\n '''\n if not lst: # Check if the list is empty\n return 0\n \n return sum(x**2 for x in lst if isinstance(x, int) and x >= 0 and x % 2 != 0)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n \"\"\"Compares the actual game scores with the guessed scores and returns the absolute differences.\n \n Args:\n game (list of int): The actual scores of the matches.\n guess (list of int): The guessed scores of the matches.\n \n Returns:\n list of int: A list containing the absolute differences between the actual scores and the guessed scores.\n If the guess is correct, the value is 0.\n \"\"\"\n return [abs(g - a) for a, g in zip(game, guess)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n \"\"\"Find the strongest extension based on the strength defined by the number of uppercase and lowercase letters.\"\"\"\n def calculate_strength(extension):\n CAP = sum(1 for char in extension if char.isupper())\n SM = sum(1 for char in extension if char.islower())\n return CAP - SM\n\n strongest_extension = None\n strongest_strength = float('-inf')\n\n for extension in extensions:\n strength = calculate_strength(extension)\n if strength > strongest_strength:\n strongest_strength = strength\n strongest_extension = extension\n\n return f\"{class_name}.{strongest_extension}\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n \"\"\"You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word.\n \n Args:\n a (str): The first word.\n b (str): The second word.\n \n Returns:\n bool: True if b or any of its rotations is a substring of a, False otherwise.\n \n Examples:\n >>> cycpattern_check(\"abcd\", \"abd\")\n False\n >>> cycpattern_check(\"hello\", \"ell\")\n True\n >>> cycpattern_check(\"whassup\", \"psus\")\n False\n >>> cycpattern_check(\"abab\", \"baa\")\n True\n >>> cycpattern_check(\"efef\", \"eeff\")\n False\n >>> cycpattern_check(\"himenss\", \"simen\")\n True\n \"\"\"\n # Create a string that contains all rotations of b\n rotations = b + b # Concatenate b with itself to get all rotations\n \n # Check if any rotation of b is a substring of a\n return any(rotation in a for rotation in (rotations[i:i+len(b)] for i in range(len(b))))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n if not (1 <= number <= 1000):\n raise ValueError(\"Number must be between 1 and 1000\")\n\n roman_numerals = [\n (1000, 'm'),\n (900, 'cm'),\n (500, 'd'),\n (400, 'cd'),\n (100, 'c'),\n (90, 'xc'),\n (50, 'l'),\n (40, 'xl'),\n (10, 'x'),\n (9, 'ix'),\n (5, 'v'),\n (4, 'iv'),\n (1, 'i')\n ]\n\n result = []\n for value, numeral in roman_numerals:\n while number >= value:\n result.append(numeral)\n number -= value\n\n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n Example:\n even_odd_count(-12) ==> (1, 1)\n even_odd_count(123) ==> (1, 2)\n \"\"\"\n # Convert the number to a string and remove the sign if it's negative\n num_str = str(abs(num))\n \n even_count = 0\n odd_count = 0\n \n for digit in num_str:\n if digit.isdigit(): # Check if the character is a digit\n if int(digit) % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return True if the three\n sides form a right-angled triangle, False otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or \n 90 degree.\n \n Example:\n right_angle_triangle(3, 4, 5) == True\n right_angle_triangle(1, 2, 3) == False\n '''\n # Sort the sides to identify the longest side\n sides = sorted([a, b, c])\n # Check the Pythagorean theorem\n return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n \"\"\"Write a function that accepts a list of strings.\n The list contains different words. Return the word with maximum number\n of unique characters. If multiple strings have maximum number of unique\n characters, return the one which comes first in lexicographical order.\n\n find_max([\"name\", \"of\", \"string\"]) == \"string\"\n find_max([\"name\", \"enam\", \"game\"]) == \"enam\"\n find_max([\"aaaaaaa\", \"bb\" ,\"cc\"]) == \"aaaaaaa\"\n \"\"\"\n max_word = \"\"\n max_unique_count = 0\n\n for word in words:\n unique_chars = set(word)\n unique_count = len(unique_chars)\n\n if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n max_word = word\n max_unique_count = unique_count\n\n return max_word", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n \"\"\"\n You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n \n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n \n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots that exist in stock\n \n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n \"\"\"\n # Calculate how many more carrots are needed\n additional_needed = need - number\n \n # If no additional carrots are needed, return the current state\n if additional_needed <= 0:\n return [number, remaining]\n \n # Determine how many carrots can be eaten from the remaining stock\n eaten = min(additional_needed, remaining)\n \n # Calculate the total eaten and remaining carrots\n total_eaten = number + eaten\n remaining_after_meals = remaining - eaten\n \n return [total_eaten, remaining_after_meals]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic algebra operations, and \n the second list is a list of integers. Use the two given lists to build the algebraic \n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + ) \n Subtraction ( - ) \n Multiplication ( * ) \n Floor division ( // ) \n Exponentiation ( ** ) \n\n Example:\n operator = ['+', '*', '-']\n operand = [2, 3, 4, 5]\n result = do_algebra(operator, operand)\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.\n \"\"\"\n \n # Start with the first operand\n result = operand[0]\n \n # Iterate through the operators and operands\n for i in range(len(operator)):\n op = operator[i]\n next_operand = operand[i + 1]\n \n if op == '+':\n result += next_operand\n elif op == '-':\n result -= next_operand\n elif op == '*':\n result *= next_operand\n elif op == '//':\n result //= next_operand\n elif op == '**':\n result **= next_operand\n else:\n raise ValueError(f\"Invalid operator: {op}\")\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": []}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n \"\"\"You are given a string s.\n if s[i] is a letter, reverse its case from lower to upper or vice versa, \n otherwise keep it as it is.\n If the string contains no letters, reverse the string.\n The function should return the resulted string.\n \n Examples:\n solve(\"1234\") = \"4321\"\n solve(\"ab\") = \"AB\"\n solve(\"#a@C\") = \"#A@c\"\n \"\"\"\n # Check if there are any letters in the string\n has_letters = any(c.isalpha() for c in s)\n \n if has_letters:\n # Reverse case for letters and keep others the same\n result = ''.join(c.swapcase() if c.isalpha() else c for c in s)\n else:\n # Reverse the string if there are no letters\n result = s[::-1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string.\n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n >>> string_to_md5('') is None\n \"\"\"\n if text == \"\":\n return None\n md5_hash = hashlib.md5(text.encode()).hexdigest()\n return md5_hash", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascending order.\n\n For example:\n generate_integers(2, 8) => [2, 4, 6, 8]\n generate_integers(8, 2) => [2, 4, 6, 8]\n generate_integers(10, 14) => []\n \"\"\"\n # Ensure a is less than or equal to b\n start = min(a, b)\n end = max(a, b)\n\n # Generate a list of even integers in the range\n even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n return even_integers", "base_status": "fail", "plus_status": null, "base_fail_tests": [[2, 10]], "plus_fail_tests": []}]}} \ No newline at end of file diff --git a/llm_based_125_eval_results.json b/llm_based_125_eval_results.json new file mode 100644 index 000000000..dd32e80df --- /dev/null +++ b/llm_based_125_eval_results.json @@ -0,0 +1 @@ +{"date": "2024-07-26 22:50", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" \n Input to this function is a string containing multiple groups of nested parentheses. \n Your goal is to separate those groups into separate strings and return the list of those.\n Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n Ignore any spaces in the input string.\n \n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n # Remove spaces from the input string\n paren_string = paren_string.replace(\" \", \"\")\n \n result = []\n current_group = []\n balance = 0\n \n for char in paren_string:\n if char == '(':\n balance += 1\n current_group.append(char)\n elif char == ')':\n balance -= 1\n current_group.append(char)\n \n # When balance is zero, we have a complete group\n if balance == 0 and current_group:\n result.append(''.join(current_group))\n current_group = [] # Reset for the next group\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n >>> has_close_elements([], 0.5)\n False\n >>> has_close_elements([1.0], 0.5)\n False\n >>> has_close_elements([1.0, 1.4], 0.5)\n True\n >>> has_close_elements([1.0, 1.4, 1.8], 0.5)\n True\n >>> has_close_elements([1.0, 2.0, 2.4], 0.5)\n True\n >>> has_close_elements([1.0, 2.0, 2.5], 0.5)\n False\n \"\"\"\n # Sort the numbers to make it easier to find close elements\n numbers.sort()\n \n # Check adjacent pairs in the sorted list\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" \n You're given a list of deposit and withdrawal operations on a bank account that starts with\n zero balance. Your task is to detect if at any point the balance of account falls below zero, and\n at that point function should return True. Otherwise it should return False.\n \n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n >>> below_zero([-1])\n True\n >>> below_zero([0, 0, 0])\n False\n >>> below_zero([-1, 1])\n False\n >>> below_zero([1, -1, -1])\n True\n >>> below_zero([5, -10, 5])\n True\n >>> below_zero([])\n False\n \"\"\"\n balance = 0\n for operation in operations:\n balance += operation\n if balance < 0:\n return True\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into\n an integer part (largest integer smaller than given number) and decimals\n (leftover part always smaller than 1).\n\n Return the decimal part of the number.\n \n >>> truncate_number(3.5)\n 0.5\n >>> truncate_number(5.0)\n 0.0\n >>> truncate_number(0.75)\n 0.75\n >>> truncate_number(10.99)\n 0.99\n >>> truncate_number(1.0001)\n 0.0001\n >>> truncate_number(0.0) # Edge case: zero is not positive\n Traceback (most recent call last):\n ...\n ValueError: The number must be positive.\n >>> truncate_number(-2.5) # Edge case: negative number\n Traceback (most recent call last):\n ...\n ValueError: The number must be positive.\n \"\"\"\n if number <= 0:\n raise ValueError(\"The number must be positive.\")\n \n integer_part = int(number) # Get the integer part\n decimal_part = number - integer_part # Calculate the decimal part\n return decimal_part", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n >>> mean_absolute_deviation([])\n 0.0\n >>> mean_absolute_deviation([5.0])\n 0.0\n >>> mean_absolute_deviation([1.0, 1.0, 1.0])\n 0.0\n >>> mean_absolute_deviation([-1.0, 0.0, 1.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list\n\n n = len(numbers)\n mean = sum(numbers) / n # Calculate the mean\n mad = sum(abs(x - mean) for x in numbers) / n # Calculate the Mean Absolute Deviation\n\n return mad", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n \"\"\" Insert a number 'delimiter' between every two consecutive elements of input list `numbers'\n \n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n >>> intersperse([5], 0)\n [5]\n >>> intersperse([1, 2], 3)\n [1, 3, 2]\n >>> intersperse([1, 2, 3, 4], 9)\n [1, 9, 2, 9, 3, 9, 4]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n for i in range(len(numbers)):\n result.append(numbers[i])\n if i < len(numbers) - 1: # Avoid adding delimiter after the last element\n result.append(delimiter)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring.\n \n Args:\n strings (List[str]): A list of strings to filter.\n substring (str): The substring to search for within the strings.\n \n Returns:\n List[str]: A list of strings that contain the specified substring.\n \n Examples:\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n >>> filter_by_substring(['hello', 'world'], 'o')\n ['hello', 'world']\n >>> filter_by_substring(['test', 'example', 'sample'], 'x')\n ['example']\n >>> filter_by_substring(['no match here'], 'z')\n []\n >>> filter_by_substring(['case', 'sensitive', 'test'], 'case')\n ['case']\n >>> filter_by_substring([''], 'a')\n []\n >>> filter_by_substring([''], '')\n ['']\n \"\"\"\n # Edge case: if the substring is empty, return all strings\n if substring == \"\":\n return strings\n \n # Filter the list using a list comprehension\n return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n def max_nesting_depth(group: str) -> int:\n max_depth = 0\n current_depth = 0\n \n for char in group:\n if char == '(':\n current_depth += 1\n max_depth = max(max_depth, current_depth)\n elif char == ')':\n current_depth -= 1\n # If current_depth goes negative, it means there are unmatched closing parentheses\n if current_depth < 0:\n return 0 # Invalid group, return 0 as depth\n \n # If current_depth is not zero, it means there are unmatched opening parentheses\n return max_depth if current_depth == 0 else 0\n\n # Split the input string into groups and calculate the max nesting depth for each\n groups = paren_string.split()\n depths = [max_nesting_depth(group) for group in groups]\n \n return depths", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n \n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n >>> sum_product([-1, -2, -3])\n (-6, -6)\n >>> sum_product([0, 1, 2])\n (3, 0)\n >>> sum_product([5])\n (5, 5)\n >>> sum_product([1, 0, 2])\n (3, 0)\n \"\"\"\n if not numbers:\n return (0, 1)\n \n total_sum = sum(numbers)\n total_product = 1\n for number in numbers:\n total_product *= number\n \n return (total_sum, total_product)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n >>> rolling_max([])\n []\n >>> rolling_max([-1, -2, -3, -4])\n [-1, -1, -1, -1]\n >>> rolling_max([5])\n [5]\n >>> rolling_max([3, 3, 3, 3, 3])\n [3, 3, 3, 3, 3]\n >>> rolling_max([1, 3, 2, 5, 4])\n [1, 3, 3, 5, 5]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for number in numbers[1:]:\n max_so_far = max(max_so_far, number)\n result.append(max_so_far)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n \"\"\" \n Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n \n >>> string_xor('010', '110')\n '100'\n >>> string_xor('1', '0')\n '1'\n >>> string_xor('0', '0')\n '0'\n >>> string_xor('1101', '101') # Different lengths\n '1000'\n >>> string_xor('111', '111') # Same strings\n '000'\n >>> string_xor('', '110') # Edge case: empty string\n '110'\n >>> string_xor('110', '') # Edge case: empty string\n '110'\n >>> string_xor('', '') # Edge case: both empty\n ''\n \"\"\"\n \n # Pad the shorter string with leading zeros\n max_length = max(len(a), len(b))\n a = a.zfill(max_length)\n b = b.zfill(max_length)\n \n # Perform XOR operation\n result = []\n for bit_a, bit_b in zip(a, b):\n result.append('1' if bit_a != bit_b else '0')\n \n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n \n >>> make_palindrome('')\n ''\n >>> make_palindrome('cat')\n 'catac'\n >>> make_palindrome('cata')\n 'catac'\n >>> make_palindrome('race')\n 'racecar'\n >>> make_palindrome('a')\n 'a'\n >>> make_palindrome('ab')\n 'aba'\n \"\"\"\n if not string:\n return string # Return empty string if input is empty\n\n # Find the longest palindromic suffix\n for i in range(len(string)):\n if is_palindrome(string[i:]):\n # If the suffix string is a palindrome, we need to append the reverse of the prefix\n prefix = string[:i]\n return string + prefix[::-1]\n\n # If no palindromic suffix is found, the entire string is the prefix\n return string + string[:-1][::-1] # This case is theoretically unreachable due to the loop", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n \n >>> longest([])\n >>> None\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n >>> longest(['abc', 'ab', 'a'])\n 'abc'\n >>> longest(['', 'a', 'ab'])\n 'ab'\n >>> longest(['longest', 'longer', 'long'])\n 'longest'\n >>> longest(['same', 'size', 'test'])\n 'same'\n \"\"\"\n if not strings:\n return None\n \n longest_string = strings[0]\n \n for string in strings[1:]:\n if len(string) > len(longest_string):\n longest_string = string\n \n return longest_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return the greatest common divisor of two integers a and b.\n \n The function handles edge cases including negative numbers and zero.\n \n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n >>> greatest_common_divisor(0, 5)\n 5\n >>> greatest_common_divisor(5, 0)\n 5\n >>> greatest_common_divisor(0, 0)\n 0\n >>> greatest_common_divisor(-25, 15)\n 5\n >>> greatest_common_divisor(25, -15)\n 5\n >>> greatest_common_divisor(-25, -15)\n 5\n \"\"\"\n if a == 0 and b == 0:\n return 0 # GCD is undefined for both numbers being zero\n if a < 0:\n a = -a # Make a positive\n if b < 0:\n b = -b # Make b positive\n\n while b != 0:\n a, b = b, a % b\n return a", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string.\n \n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n >>> all_prefixes('')\n []\n >>> all_prefixes('a')\n ['a']\n >>> all_prefixes('hello')\n ['h', 'he', 'hel', 'hell', 'hello']\n \"\"\"\n # Initialize an empty list to store prefixes\n prefixes = []\n \n # Iterate through the string and collect prefixes\n for i in range(1, len(string) + 1):\n prefixes.append(string[:i])\n \n return prefixes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" \n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n >>> count_distinct_characters('')\n 0\n >>> count_distinct_characters('aA')\n 1\n >>> count_distinct_characters('123abcABC!@#')\n 10\n >>> count_distinct_characters(' ')\n 0\n >>> count_distinct_characters('!@#$%^&*()')\n 10\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set()\n \n # Iterate through each character in the string\n for char in lower_string:\n # Only add alphabetic characters to the set\n if char.isalnum() or not char.isspace():\n distinct_characters.add(char)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Jerry jERRY JeRRRY"]], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n \n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n >>> string_sequence(-1)\n ''\n >>> string_sequence(1)\n '0 1'\n >>> string_sequence(10)\n '0 1 2 3 4 5 6 7 8 9 10'\n \"\"\"\n if n < 0:\n return ''\n \n return ' '.join(str(i) for i in range(n + 1))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string representing musical notes in a special ASCII format.\n Your task is to parse this string and return list of integers corresponding to how many beats does each\n note last.\n\n Here is a legend:\n 'o' - whole note, lasts four beats\n 'o|' - half note, lasts two beats\n '.|' - quarter note, lasts one beat\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n # Initialize an empty list to store the beats\n beats = []\n \n # Split the input string by spaces to get individual notes\n notes = music_string.split()\n \n # Define a mapping of note representations to their corresponding beats\n note_to_beats = {\n 'o': 4, # whole note\n 'o|': 2, # half note\n '.|': 1 # quarter note\n }\n \n # Iterate through each note and append the corresponding beats to the list\n for note in notes:\n if note in note_to_beats:\n beats.append(note_to_beats[note])\n else:\n # If an unknown note is encountered, raise an error\n raise ValueError(f\"Unknown note representation: '{note}'\")\n \n return beats", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n \n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n \"\"\"\n if not substring: # If the substring is empty, return 0\n return 0\n if not string: # If the string is empty, return 0\n return 0\n\n count = 0\n start = 0\n\n while True:\n start = string.find(substring, start) # Find the substring starting from 'start'\n if start == -1: # If no more occurrences are found, break the loop\n break\n count += 1 # Increment the count for each found occurrence\n start += 1 # Move to the next character to allow for overlapping matches\n\n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n \"\"\" \n Input is a space-delimited string of numerals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest.\n \n >>> sort_numbers('three one five')\n 'one three five'\n >>> sort_numbers('nine eight seven six five four three two one zero')\n 'zero one two three four five six seven eight nine'\n >>> sort_numbers('zero')\n 'zero'\n >>> sort_numbers('')\n ''\n >>> sort_numbers('five five four four')\n 'four four five five'\n \"\"\"\n \n # Mapping of words to their corresponding numeric values\n word_to_number = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n \n # Reverse mapping for sorting back to words\n number_to_word = {v: k for k, v in word_to_number.items()}\n \n # Split the input string into words\n words = numbers.split()\n \n # Convert words to their corresponding numeric values\n numeric_values = [word_to_number[word] for word in words if word in word_to_number]\n \n # Sort the numeric values\n numeric_values.sort()\n \n # Convert sorted numeric values back to words\n sorted_words = [number_to_word[num] for num in numeric_values]\n \n # Join the sorted words into a single string\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1.\n \n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n >>> rescale_to_unit([10.0, 20.0, 30.0])\n [0.0, 0.5, 1.0]\n >>> rescale_to_unit([-5.0, 0.0, 5.0])\n [0.0, 0.5, 1.0]\n >>> rescale_to_unit([1.0, 1.0, 1.0])\n [0.0, 0.0, 0.0]\n >>> rescale_to_unit([1.0, 2.0])\n [0.0, 1.0]\n \"\"\"\n \n if len(numbers) < 2:\n raise ValueError(\"The input list must contain at least two elements.\")\n \n min_val = min(numbers)\n max_val = max(numbers)\n \n if min_val == max_val:\n # If all numbers are the same, return a list of zeros\n return [0.0] * len(numbers)\n \n # Rescale the numbers\n return [(num - min_val) / (max_val - min_val) for num in numbers]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n >>> find_closest_elements([1.0, 1.0, 1.0, 1.0])\n (1.0, 1.0)\n >>> find_closest_elements([-1.0, -2.0, -3.0, -1.5])\n (-1.5, -1.0)\n >>> find_closest_elements([0.0, 0.1, 0.2, 0.3])\n (0.0, 0.1)\n \"\"\"\n \n # Sort the numbers to find the closest pairs easily\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest elements\n for i in range(len(sorted_numbers) - 1):\n # Calculate the difference between consecutive elements\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n \n # If this difference is smaller than the minimum found so far, update\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers\n >>> filter_integers(['a', 3.14, 5])\n [5]\n >>> filter_integers([1, 2, 3, 'abc', {}, []])\n [1, 2, 3]\n \"\"\"\n return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n \"\"\" Return length of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n >>> strlen('a')\n 1\n >>> strlen('Hello, World!')\n 13\n >>> strlen(' ') # String with spaces\n 3\n >>> strlen('\ud83d\ude0a') # String with a Unicode character\n 2\n >>> strlen('abc\\nxyz') # String with a newline character\n 8\n >>> strlen('abc\\txyz') # String with a tab character\n 8\n >>> strlen('') # Edge case: empty string\n 0\n >>> strlen('1234567890') # String with numbers\n 10\n >>> strlen('!@#$%^&*()') # String with special characters\n 10\n \"\"\"\n return len(string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n \n >>> largest_divisor(15)\n 5\n >>> largest_divisor(1)\n 0\n >>> largest_divisor(2)\n 1\n >>> largest_divisor(10)\n 5\n >>> largest_divisor(17)\n 1\n >>> largest_divisor(100)\n 50\n >>> largest_divisor(0)\n 0\n >>> largest_divisor(-10)\n 0\n \"\"\"\n if n <= 1:\n return 0 # No positive divisors exist for n <= 1\n \n for i in range(n // 2, 0, -1): # Check from n//2 down to 1\n if n % i == 0:\n return i # Return the first divisor found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n Input number should be equal to the product of all factors\n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n >>> factorize(1)\n []\n >>> factorize(0)\n Traceback (most recent call last):\n ...\n ValueError: Input must be a positive integer.\n >>> factorize(-10)\n Traceback (most recent call last):\n ...\n ValueError: Input must be a positive integer.\n \"\"\"\n \n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n factors = []\n # Check for number of 2s that divide n\n while n % 2 == 0:\n factors.append(2)\n n //= 2\n \n # n must be odd at this point so a skip of 2 (i.e., i = i + 2) can be used\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, append i and divide n\n while n % i == 0:\n factors.append(i)\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n factors.append(n)\n \n return factors", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([1, 1, 1, 1])\n []\n >>> remove_duplicates([1, 2, 3])\n [1, 2, 3]\n >>> remove_duplicates([])\n []\n >>> remove_duplicates([1, 2, 3, 4, 5, 1, 2, 3])\n [4, 5]\n >>> remove_duplicates([5, 5, 6, 7, 6, 8])\n [7, 8]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for number in numbers:\n if number in count:\n count[number] += 1\n else:\n count[number] = 1\n \n # Create a new list with numbers that occur only once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n \n >>> flip_case('Hello')\n 'hELLO'\n >>> flip_case('hELLO')\n 'Hello'\n >>> flip_case('Python 3.8!')\n 'pYTHON 3.8!'\n >>> flip_case('')\n ''\n >>> flip_case('12345!@#')\n '12345!@#'\n >>> flip_case('Mixed CASE with 123')\n 'mIXED case WITH 123'\n \"\"\"\n return ''.join(char.swapcase() for char in string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string.\n \n Args:\n strings (List[str]): A list of strings to concatenate.\n \n Returns:\n str: A single concatenated string.\n \n Examples:\n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n >>> concatenate(['Hello', ' ', 'World', '!'])\n 'Hello World!'\n >>> concatenate(['', 'a', 'b', ''])\n 'ab'\n >>> concatenate(['123', '456', '789'])\n '123456789'\n >>> concatenate(['', '', ''])\n ''\n >>> concatenate(['a' * 1000, 'b' * 1000])\n 'a' * 1000 + 'b' * 1000\n \"\"\"\n return ''.join(strings)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n \n Args:\n strings (List[str]): A list of strings to filter.\n prefix (str): The prefix to filter the strings by.\n \n Returns:\n List[str]: A list of strings that start with the given prefix.\n \n Examples:\n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n >>> filter_by_prefix(['apple', 'banana', 'apricot', 'grape'], 'ap')\n ['apple', 'apricot']\n >>> filter_by_prefix(['hello', 'world'], 'h')\n ['hello']\n >>> filter_by_prefix(['hello', 'world'], 'z')\n []\n >>> filter_by_prefix(['', 'a', 'ab', 'abc'], 'a')\n ['a', 'ab', 'abc']\n >>> filter_by_prefix(['abc', 'def', 'ghi'], '')\n ['abc', 'def', 'ghi']\n >>> filter_by_prefix(['abc', 'def', 'ghi'], 'abcdef')\n []\n \"\"\"\n # Edge case: If the prefix is empty, return all strings\n if prefix == \"\":\n return strings\n \n # Filter the list using a list comprehension\n return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n >>> is_prime(0)\n False\n >>> is_prime(-5)\n False\n >>> is_prime(2)\n True\n >>> is_prime(3)\n True\n >>> is_prime(9)\n False\n >>> is_prime(25)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return False # eliminate multiples of 2 and 3\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6 # check for factors of the form 6k \u00b1 1\n\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n \n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n >>> get_positive([]) # Edge case: empty list\n []\n >>> get_positive([-1, -2, -3]) # Edge case: all negative numbers\n []\n >>> get_positive([0]) # Edge case: single zero\n []\n >>> get_positive([1, 2, 3]) # Edge case: all positive numbers\n [1, 2, 3]\n >>> get_positive([-1, 0, 1]) # Edge case: mix of negative, zero, and positive\n [1]\n >>> get_positive([0, 0, 0]) # Edge case: all zeros\n []\n \"\"\"\n return [x for x in l if x > 0]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float):\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list, x: float):\n \"\"\"\n Evaluates the derivative of the polynomial with coefficients xs at point x.\n \"\"\"\n return sum(i * coeff * math.pow(x, i - 1) for i, coeff in enumerate(xs) if i > 0)\ndef find_zero(xs: list, initial_guess: float = 0.0, tolerance: float = 1e-7, max_iterations: int = 1000):\n \"\"\" \n xs are coefficients of a polynomial.\n find_zero finds x such that poly(x) = 0.\n find_zero returns only one zero point, even if there are many.\n Moreover, find_zero only takes list xs having an even number of coefficients\n and the largest non-zero coefficient as it guarantees a solution.\n \n >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n -0.5\n >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n 1.0\n \"\"\"\n if len(xs) % 2 != 0:\n raise ValueError(\"The number of coefficients must be even.\")\n \n # Initial guess for the root\n x = initial_guess\n \n for iteration in range(max_iterations):\n f_x = poly(xs, x)\n f_prime_x = derivative(xs, x)\n \n if abs(f_x) < tolerance: # Found a root\n return x\n \n if f_prime_x == 0: # Avoid division by zero\n raise ValueError(\"Derivative is zero. No solution found.\")\n \n # Newton-Raphson update\n x -= f_x / f_prime_x\n \n raise ValueError(\"Maximum iterations reached. No solution found.\")", "base_status": "fail", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n >>> sort_third([10, 20, 30, 40, 50, 60, 70, 80, 90])\n [70, 20, 30, 40, 50, 60, 10, 80, 90]\n >>> sort_third([])\n []\n >>> sort_third([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])\n [7, 2, 3, 4, 5, 6, 1, 8, 9, 10]\n \"\"\"\n # Extract values at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(divisible_by_three)\n \n # Create a new list to hold the result\n result = l.copy()\n \n # Replace values at indices divisible by 3 with sorted values\n for index, value in zip((i for i in range(len(l)) if i % 3 == 0), sorted_values):\n result[index] = value\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \n >>> unique([])\n []\n \n >>> unique([1, 1, 1, 1])\n [1]\n \n >>> unique([1, 2, 3, 4, 5])\n [1, 2, 3, 4, 5]\n \n >>> unique([-1, -2, -3, -1, -2])\n [-3, -2, -1]\n \n >>> unique([0, 0, 0, 0, 0])\n [0]\n \n >>> unique([1, 2, 2.5, 3, 3.5, 3.5])\n [1, 2, 2.5, 3, 3.5]\n \"\"\"\n # Use a set to remove duplicates, then sort the result\n return sorted(set(l))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n \"\"\"Return maximum element in the list.\n \n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n >>> max_element([-1, -2, -3])\n -1\n >>> max_element([0])\n 0\n >>> max_element([])\n Traceback (most recent call last):\n ...\n ValueError: The list is empty.\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty.\")\n \n max_value = l[0]\n for item in l:\n if item > max_value:\n max_value = item\n \n return max_value", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n >>> sort_even([10, 20, 30, 40, 50])\n [30, 20, 10, 40, 50]\n >>> sort_even([1])\n [1]\n >>> sort_even([])\n []\n >>> sort_even([2, 1])\n [2, 1]\n >>> sort_even([1, 3, 2, 4, 5, 6])\n [2, 3, 1, 4, 5, 6]\n \"\"\"\n # Extract even indexed elements\n even_indices = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indexed elements\n even_indices_sorted = sorted(even_indices)\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Place the sorted even indexed elements back into their positions\n for i, sorted_value in enumerate(even_indices_sorted):\n result[i * 2] = sorted_value\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_fib(n: int) -> int:\n \"\"\"\n prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n \n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n if n < 1:\n raise ValueError(\"n must be a positive integer.\")\n \n prime_fib_count = 0\n for fib in fibonacci_generator():\n if is_prime(fib):\n prime_fib_count += 1\n if prime_fib_count == n:\n return fib", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1]], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with the encode_cyclic function.\n Returns the decoded string.\n \"\"\"\n # Split string into groups of length 3\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # Reverse the cycling for each group\n groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n \"\"\"\n Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move at the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.\n\n Parameters:\n n (int): The number of cars moving in each direction.\n\n Returns:\n int: The total number of collisions.\n \"\"\"\n # Edge case: if there are no cars, there can be no collisions\n if n <= 0:\n return 0\n \n # Each car moving left to right will collide with each car moving right to left\n # Therefore, the total number of collisions is n * n\n return n * n", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n \"\"\"\n triples_sum_to_zero takes a list of integers as an input.\n it returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n \"\"\"\n n = len(l)\n if n < 3:\n return False # Not enough elements to form a triplet\n\n # Sort the list to use the two-pointer technique\n l.sort()\n\n for i in range(n - 2):\n # Avoid duplicates for the first element\n if i > 0 and l[i] == l[i - 1]:\n continue\n \n left, right = i + 1, n - 1\n while left < right:\n current_sum = l[i] + l[left] + l[right]\n if current_sum == 0:\n return True\n elif current_sum < 0:\n left += 1\n else:\n right -= 1\n\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n \n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n >>> incr_list([])\n []\n >>> incr_list([-1, 0, 1])\n [0, 1, 2]\n >>> incr_list([1.5, 2.5])\n [2.5, 3.5]\n >>> incr_list(['a', 1])\n Traceback (most recent call last):\n ...\n TypeError: All elements must be integers or floats.\n \"\"\"\n if not all(isinstance(x, (int, float)) for x in l):\n raise TypeError(\"All elements must be integers or floats.\")\n \n return [x + 1 for x in l]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n \n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n \"\"\"\n seen = set()\n for number in l:\n if -number in seen:\n return True\n seen.add(number)\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion.\n base numbers are less than 10.\n \n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n >>> change_base(0, 2)\n '0'\n >>> change_base(0, 3)\n '0'\n >>> change_base(1, 2)\n '1'\n >>> change_base(1, 3)\n '1'\n >>> change_base(9, 2)\n '1001'\n >>> change_base(9, 3)\n '100'\n >>> change_base(9, 4)\n '21'\n >>> change_base(9, 5)\n '14'\n >>> change_base(9, 6)\n '13'\n >>> change_base(9, 7)\n '12'\n >>> change_base(9, 8)\n '11'\n >>> change_base(9, 9)\n '10'\n \"\"\"\n \n if base < 2 or base >= 10:\n raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n \n if x == 0:\n return '0'\n \n result = []\n negative = x < 0\n x = abs(x)\n \n while x > 0:\n remainder = x % base\n result.append(str(remainder))\n x //= base\n \n if negative:\n result.append('-')\n \n # The result is built in reverse order\n return ''.join(reversed(result))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n \"\"\"Given length of a side and height, return the area for a triangle.\n \n The area of a triangle is calculated using the formula:\n Area = (base * height) / 2\n \n Parameters:\n a (float): The length of the base of the triangle.\n h (float): The height of the triangle.\n \n Returns:\n float: The area of the triangle.\n \n Raises:\n ValueError: If the base or height is negative.\n \n >>> triangle_area(5, 3)\n 7.5\n >>> triangle_area(0, 5)\n 0.0\n >>> triangle_area(5, 0)\n 0.0\n >>> triangle_area(-5, 3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be non-negative.\n >>> triangle_area(5, -3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be non-negative.\n \"\"\"\n \n if a < 0 or h < 0:\n raise ValueError(\"Base and height must be non-negative.\")\n \n return (a * h) / 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fib4(0) -> 0\n fib4(1) -> 0\n fib4(2) -> 2\n fib4(3) -> 0\n fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n \n Args:\n n (int): The index of the Fib4 sequence to compute.\n \n Returns:\n int: The n-th element of the Fib4 sequence.\n \n Examples:\n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n \n # Handle base cases\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 2\n elif n == 3:\n return 0\n \n # Initialize the first four elements of the sequence\n fib_sequence = [0, 0, 2, 0]\n \n # Compute the sequence iteratively\n for i in range(4, n + 1):\n next_value = fib_sequence[i - 1] + fib_sequence[i - 2] + fib_sequence[i - 3] + fib_sequence[i - 4]\n fib_sequence.append(next_value)\n \n return fib_sequence[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n \"\"\"Return median of elements in the list l.\n \n The median is the middle value in a list of numbers. If the list has an even number of elements,\n the median is the average of the two middle numbers.\n \n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n >>> median([1])\n 1\n >>> median([1, 2])\n 1.5\n >>> median([])\n Traceback (most recent call last):\n ...\n ValueError: Cannot compute median of an empty list.\n >>> median([1, 3, 3, 6, 7, 8, 9])\n 6\n >>> median([1, 2, 3, 4])\n 2.5\n \"\"\"\n if not l:\n raise ValueError(\"Cannot compute median of an empty list.\")\n \n # Sort the list\n sorted_list = sorted(l)\n n = len(sorted_list)\n \n # Calculate median\n if n % 2 == 1: # Odd number of elements\n return sorted_list[n // 2]\n else: # Even number of elements\n mid1 = sorted_list[n // 2 - 1]\n mid2 = sorted_list[n // 2]\n return (mid1 + mid2) / 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n \"\"\"\n Checks if given string is a palindrome.\n \n A palindrome is a string that reads the same forward and backward.\n \n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n >>> is_palindrome('A man a plan a canal Panama')\n True\n >>> is_palindrome('No lemon, no melon')\n True\n >>> is_palindrome('12321')\n True\n >>> is_palindrome('12345')\n False\n >>> is_palindrome('Was it a car or a cat I saw?')\n True\n >>> is_palindrome('') # Edge case: empty string\n True\n >>> is_palindrome(' ') # Edge case: single space\n True\n >>> is_palindrome(' ') # Edge case: multiple spaces\n True\n >>> is_palindrome('A') # Edge case: single character\n True\n >>> is_palindrome('ab') # Edge case: two different characters\n False\n \"\"\"\n # Normalize the string: remove non-alphanumeric characters and convert to lowercase\n normalized_text = ''.join(char.lower() for char in text if char.isalnum())\n \n # Check if the normalized string is equal to its reverse\n return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n if p <= 0:\n raise ValueError(\"p must be a positive integer.\")\n \n if n < 0:\n raise ValueError(\"n must be a non-negative integer.\")\n \n # Using modular exponentiation to compute (2^n) % p efficiently\n result = 1\n base = 2 % p # Reduce base modulo p\n \n while n > 0:\n if n % 2 == 1: # If n is odd, multiply the base with the result\n result = (result * base) % p\n base = (base * base) % p # Square the base\n n //= 2 # Divide n by 2\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n # Define a set of vowels (both lowercase and uppercase)\n vowels = set('aeiouAEIOU')\n \n # Use a list comprehension to filter out vowels\n result = ''.join([char for char in text if char not in vowels])\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with the encode_shift function.\n Returns the decoded string by shifting every character back by 5 in the alphabet.\n \"\"\"\n return \"\".join([chr(((ord(ch) - ord(\"a\") - 5) % 26) + ord(\"a\")) if 'a' <= ch <= 'z' else ch for ch in s])", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n \"\"\"Return True if all numbers in the list l are below threshold t.\n \n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n >>> below_threshold([], 10)\n True\n >>> below_threshold([5], 5)\n False\n >>> below_threshold([-1, -2, -3], 0)\n True\n >>> below_threshold([0, 0, 0], 1)\n True\n >>> below_threshold([1, 2, 3], 2)\n False\n >>> below_threshold([10, 20, 30], 30)\n False\n \"\"\"\n # Check if all elements in the list are below the threshold\n for number in l:\n if number >= t:\n return False\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n \"\"\"Add two numbers x and y.\n\n This function takes two integers and returns their sum. It handles\n edge cases such as adding negative numbers and zero.\n\n Args:\n x (int): The first integer to add.\n y (int): The second integer to add.\n\n Returns:\n int: The sum of x and y.\n\n Examples:\n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n >>> add(-1, 1)\n 0\n >>> add(0, 0)\n 0\n >>> add(-5, -3)\n -8\n >>> add(1000000, 2000000)\n 3000000\n >>> add(-1000000, 1000000)\n 0\n \"\"\"\n return x + y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n \"\"\"Return n-th Fibonacci number.\n \n The Fibonacci sequence is defined as follows:\n fib(0) = 0\n fib(1) = 1\n fib(n) = fib(n-1) + fib(n-2) for n > 1\n \n Args:\n n (int): The index of the Fibonacci number to return.\n \n Returns:\n int: The n-th Fibonacci number.\n \n Raises:\n ValueError: If n is negative.\n \n Examples:\n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n >>> fib(0)\n 0\n >>> fib(2)\n 1\n >>> fib(3)\n 2\n >>> fib(4)\n 3\n >>> fib(5)\n 5\n >>> fib(6)\n 8\n >>> fib(7)\n 13\n \"\"\"\n if n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n if n == 0:\n return 0\n elif n == 1:\n return 1\n \n a, b = 0, 1\n for _ in range(2, n + 1):\n a, b = b, a + b\n \n return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Create a set of characters for each string\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Compare the sets\n return set_s0 == set_s1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"<\" and \">\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"<\")\n False\n >>> correct_bracketing(\"<>\")\n True\n >>> correct_bracketing(\"<<><>>\")\n True\n >>> correct_bracketing(\"><<>\")\n False\n >>> correct_bracketing(\"<<>>\") # Additional test case\n True\n >>> correct_bracketing(\"><\") # Additional test case\n False\n >>> correct_bracketing(\"\") # Edge case: empty string\n True\n >>> correct_bracketing(\"<<<>>>\") # Edge case: unbalanced\n False\n >>> correct_bracketing(\"<<><<>>><>\") # Complex case\n True\n >>> correct_bracketing(\"><><\") # Complex case\n False\n \"\"\"\n balance = 0\n \n for char in brackets:\n if char == '<':\n balance += 1\n elif char == '>':\n balance -= 1\n \n # If balance goes negative, it means there's a closing bracket without a matching opening bracket\n if balance < 0:\n return False\n \n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n \"\"\"Return True if list elements are monotonically increasing or decreasing.\n \n A list is considered monotonically increasing if each element is greater than or equal to the previous one.\n A list is considered monotonically decreasing if each element is less than or equal to the previous one.\n \n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n >>> monotonic([1, 1, 1])\n True\n >>> monotonic([])\n True\n >>> monotonic([5])\n True\n >>> monotonic([1, 2, 2, 3])\n True\n >>> monotonic([3, 2, 2, 1])\n True\n \"\"\"\n if len(l) <= 1:\n return True # An empty list or a single element list is considered monotonic\n\n increasing = decreasing = True\n\n for i in range(1, len(l)):\n if l[i] > l[i - 1]:\n decreasing = False\n elif l[i] < l[i - 1]:\n increasing = False\n\n return increasing or decreasing", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n >>> largest_prime_factor(600851475143)\n 6857\n >>> largest_prime_factor(49)\n 7\n >>> largest_prime_factor(15)\n 5\n >>> largest_prime_factor(2)\n 2\n \"\"\"\n # Start with the smallest prime factor\n largest_factor = None\n \n # Check for number of 2s that divide n\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # n must be odd at this point, so we can skip even numbers\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n \n return largest_factor", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n >>> common([], [1, 2, 3])\n []\n >>> common([1, 2, 3], [])\n []\n >>> common([], [])\n []\n >>> common([1, 1, 1], [1, 1, 1])\n [1]\n >>> common([1, 2, 3], [4, 5, 6])\n []\n >>> common([1, 2, 3], [3, 2, 1])\n [1, 2, 3]\n >>> common([1, 2, 2, 3], [2, 2, 3, 4])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n \n Args:\n n (int): The upper limit of the sum (inclusive).\n \n Returns:\n int: The sum of all integers from 1 to n.\n \n Examples:\n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n >>> sum_to_n(0)\n 0\n >>> sum_to_n(-5)\n 0\n \"\"\"\n if n < 1:\n return 0\n return n * (n + 1) // 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"(\" and \")\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"(\")\n False\n >>> correct_bracketing(\"()\")\n True\n >>> correct_bracketing(\"(()())\")\n True\n >>> correct_bracketing(\")(()\")\n False\n >>> correct_bracketing(\")(\")\n False\n >>> correct_bracketing(\"\") # Edge case: empty string\n True\n >>> correct_bracketing(\"((()))\") # Edge case: nested brackets\n True\n >>> correct_bracketing(\"(()\") # Edge case: unbalanced opening\n False\n >>> correct_bracketing(\"())\") # Edge case: unbalanced closing\n False\n >>> correct_bracketing(\"()()()\") # Edge case: multiple pairs\n True\n >>> correct_bracketing(\"(()())()\") # Edge case: mixed pairs\n True\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n \n # If balance goes negative, there are more closing brackets\n if balance < 0:\n return False\n \n # At the end, balance should be zero for all opening brackets to be closed\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n \"\"\" \n xs represent coefficients of a polynomial.\n xs[0] + xs[1] * x + xs[2] * x^2 + ....\n Return derivative of this polynomial in the same form.\n \n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n >>> derivative([0])\n []\n >>> derivative([0, 0, 0])\n []\n >>> derivative([1])\n []\n >>> derivative([1, 0])\n [0]\n >>> derivative([1, 2, 0])\n [2]\n \"\"\"\n # The derivative of a polynomial is calculated by multiplying each coefficient\n # by its corresponding power and reducing the power by one.\n # The first coefficient (constant term) will not contribute to the derivative.\n \n # If the list is empty or has only one element, return an empty list\n if len(xs) <= 1:\n return []\n \n # Calculate the derivative coefficients\n derivative_coeffs = [i * coeff for i, coeff in enumerate(xs[1:], start=1)]\n \n return derivative_coeffs", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n \n Args:\n n (int): The index of the FibFib number to compute.\n \n Returns:\n int: The n-th FibFib number.\n \n Examples:\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n # Handle base cases\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 1\n \n # Use a list to store computed values for memoization\n fibfib_values = [0] * (n + 1)\n fibfib_values[0] = 0\n fibfib_values[1] = 0\n fibfib_values[2] = 1\n \n # Compute the FibFib numbers iteratively\n for i in range(3, n + 1):\n fibfib_values[i] = fibfib_values[i - 1] + fibfib_values[i - 2] + fibfib_values[i - 3]\n \n return fibfib_values[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set('aeiouAEIOU')\n count = 0\n \n # Iterate through the string\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n # Check if 'y' is at the end of the string\n elif s[i].lower() == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n \n >>> circular_shift(12, 1)\n '21'\n >>> circular_shift(12, 2)\n '12'\n >>> circular_shift(12345, 1)\n '51234'\n >>> circular_shift(12345, 5)\n '54321'\n >>> circular_shift(12345, 6)\n '54321'\n >>> circular_shift(0, 1)\n '0'\n >>> circular_shift(0, 0)\n '0'\n >>> circular_shift(7, 0)\n '7'\n >>> circular_shift(7, 1)\n '7'\n >>> circular_shift(-123, 1)\n '-312'\n >>> circular_shift(-123, 3)\n '-321'\n >>> circular_shift(-123, 4)\n '-321'\n \"\"\"\n # Convert the integer to a string and handle negative numbers\n is_negative = x < 0\n str_x = str(abs(x))\n length = len(str_x)\n\n # If shift is 0 or the number is a single digit, return it as is\n if shift == 0 or length == 1:\n return str_x if not is_negative else '-' + str_x\n\n # Calculate effective shift\n effective_shift = shift % length\n\n # If effective shift is 0, return the original number\n if effective_shift == 0:\n return str_x if not is_negative else '-' + str_x\n\n # Perform the circular shift\n shifted = str_x[-effective_shift:] + str_x[:-effective_shift]\n\n # Return the result, preserving the sign if negative\n return shifted if not is_negative else '-' + shifted", "base_status": "fail", "plus_status": null, "base_fail_tests": [[97, 8]], "plus_fail_tests": []}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n \"\"\"\n Calculate the number of mango fruits in a basket given the number of apples and oranges.\n\n Parameters:\n s (str): A string representing the number of apples and oranges in the format \"X apples and Y oranges\".\n n (int): An integer representing the total number of fruits in the basket.\n\n Returns:\n int: The number of mango fruits in the basket.\n \"\"\"\n # Split the input string to extract the number of apples and oranges\n parts = s.split(\" and \")\n apples = int(parts[0].split()[0]) # Get the number of apples\n oranges = int(parts[1].split()[0]) # Get the number of oranges\n\n # Calculate the number of mangoes\n mangoes = n - apples - oranges\n\n return mangoes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n \"\"\"Task\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n \"\"\"\n # Initialize the sum of ASCII values\n total_sum = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is uppercase\n if char.isupper():\n # Add the ASCII value of the uppercase character to the total sum\n total_sum += ord(char)\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n \"\"\"\n Given an array representing a branch of a tree that has non-negative integer nodes,\n your task is to pluck one of the nodes and return it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n The plucked node should be returned in a list, [ smallest_value, its index ],\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index. \n\n Example 3:\n Input: []\n Output: []\n \n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n Explanation: 0 is the smallest value, but there are two zeros,\n so we will choose the first zero, which has the smallest index.\n\n Constraints:\n * 1 <= nodes.length <= 10000\n * 0 <= node.value\n \"\"\"\n # Initialize variables to track the smallest even value and its index\n smallest_even_value = float('inf')\n smallest_index = -1\n\n # Iterate through the array to find the smallest even value\n for index, value in enumerate(arr):\n if value % 2 == 0: # Check if the value is even\n if value < smallest_even_value: # Check if it's smaller than the current smallest\n smallest_even_value = value\n smallest_index = index\n\n # If we found an even value, return it in the required format\n if smallest_index != -1:\n return [smallest_even_value, smallest_index]\n \n # If no even value was found, return an empty list\n return []", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n '''\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequency greater than or equal to the value of the integer itself. \n The frequency of an integer is the number of times it appears in the list.\n If no such a value exists, return -1.\n \n Examples:\n search([4, 1, 2, 2, 3, 1]) == 2\n search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n search([5, 5, 4, 4, 4]) == -1\n '''\n from collections import Counter\n\n # Count the frequency of each integer in the list\n frequency = Counter(lst)\n\n # Initialize the result variable to -1 (default if no valid integer is found)\n result = -1\n\n # Iterate through the frequency dictionary\n for num in frequency:\n # Check if the frequency of the number is greater than or equal to the number itself\n if frequency[num] >= num:\n # Update the result if this number is greater than the current result\n result = max(result, num)\n\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return the area of\n the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n Otherwise return -1.\n \n Three sides make a valid triangle when the sum of any two sides is greater \n than the third side.\n \n Example:\n triangle_area(3, 4, 5) == 6.00\n triangle_area(1, 2, 10) == -1\n '''\n \n # Check for valid triangle condition\n if a <= 0 or b <= 0 or c <= 0:\n return -1\n if a + b <= c or a + c <= b or b + c <= a:\n return -1\n \n # Calculate the semi-perimeter\n s = (a + b + c) / 2\n \n # Calculate the area using Heron's formula\n area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n \n # Return the area rounded to 2 decimal points\n return round(area, 2)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n '''\n Given list of integers, return list in strange order.\n Strange sorting, is when you start with the minimum value,\n then maximum of the remaining integers, then minimum and so on.\n\n Examples:\n strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n strange_sort_list([]) == []\n '''\n if not lst: # Handle the empty list case\n return []\n\n sorted_lst = sorted(lst) # Sort the list to access min and max easily\n result = []\n \n left = 0 # Pointer for the minimum values\n right = len(sorted_lst) - 1 # Pointer for the maximum values\n \n # Alternate between the smallest and largest remaining elements\n while left <= right:\n if left == right: # If both pointers meet, add the last element\n result.append(sorted_lst[left])\n else:\n result.append(sorted_lst[left]) # Add the minimum\n result.append(sorted_lst[right]) # Add the maximum\n left += 1\n right -= 1\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n \"\"\"\n Given an array arr of integers, find the minimum number of elements that\n need to be changed to make the array palindromic. A palindromic array is an array that\n is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n For example:\n smallest_change([1,2,3,5,4,7,9,6]) == 4\n smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n smallest_change([1, 2, 3, 2, 1]) == 0\n \"\"\"\n n = len(arr)\n changes = 0\n \n # Compare elements from the start and end towards the center\n for i in range(n // 2):\n if arr[i] != arr[n - 1 - i]:\n changes += 1\n \n return changes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n '''\n Write a function that returns True if the object q will fly, and False otherwise.\n The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n \n Example:\n will_it_fly([1, 2], 5) \u279e False \n # 1+2 is less than the maximum possible weight, but it's unbalanced.\n\n will_it_fly([3, 2, 3], 1) \u279e False\n # it's balanced, but 3+2+3 is more than the maximum possible weight.\n\n will_it_fly([3, 2, 3], 9) \u279e True\n # 3+2+3 is less than the maximum possible weight, and it's balanced.\n\n will_it_fly([3], 5) \u279e True\n # 3 is less than the maximum possible weight, and it's balanced.\n '''\n \n # Check if the list is palindromic\n is_balanced = (q == q[::-1])\n \n # Calculate the sum of the elements in the list\n total_weight = sum(q)\n \n # Check if the total weight is less than or equal to the maximum weight\n is_within_weight_limit = (total_weight <= w)\n \n # The object will fly if it is balanced and within the weight limit\n return is_balanced and is_within_weight_limit", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n \n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total character counts and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n else:\n return lst2", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef get_primes_up_to(n):\n \"\"\"Return a list of all prime numbers less than n.\"\"\"\n return [i for i in range(2, n) if is_prime(i)]\ndef is_multiply_prime(a):\n \"\"\"Return true if the given number is the multiplication of 3 prime numbers.\"\"\"\n if a < 1 or a >= 100:\n return False # a must be less than 100 and greater than 0\n\n primes = get_primes_up_to(a)\n prime_count = len(primes)\n\n # Check all combinations of 3 primes\n for i in range(prime_count):\n for j in range(i, prime_count):\n for k in range(j, prime_count):\n product = primes[i] * primes[j] * primes[k]\n if product == a:\n return True\n if product > a:\n break # No need to check further if product exceeds a\n\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this integer is a cube of some integer number.\n Note: you may assume the input is always valid.\n \n Examples:\n iscube(1) ==> True\n iscube(2) ==> False\n iscube(-1) ==> True\n iscube(64) ==> True\n iscube(0) ==> True\n iscube(180) ==> False\n '''\n # Calculate the cube root of the absolute value of a\n cube_root = round(abs(a) ** (1/3))\n \n # Check if the cube of the rounded cube root equals the absolute value of a\n return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n \"\"\"Returns True if x is a simple power of n, otherwise False.\n \n A number x is a simple power of n if there exists an integer k such that n**k = x.\n \n Args:\n x (int): The number to check.\n n (int): The base number.\n \n Returns:\n bool: True if x is a simple power of n, False otherwise.\n \"\"\"\n \n # Edge case: if n is 0 or 1\n if n == 0:\n return x == 0 # 0**0 is undefined, but we can consider it as False\n if n == 1:\n return x == 1 # 1**k is always 1 for any k\n \n # Edge case: if x is less than 1\n if x < 1:\n return False # No positive power of n can yield a number less than 1\n \n # Check if x is a power of n\n power = 1\n while True:\n power_value = n ** power\n if power_value == x:\n return True\n elif power_value > x:\n return False\n power += 1", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1, 12]], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n \"\"\"Counts the number of prime hexadecimal digits in the given hexadecimal string.\"\"\"\n \n # Define the set of prime hexadecimal digits\n prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n \n # Initialize a counter for prime digits\n prime_count = 0\n \n # Iterate through each character in the input string\n for char in num:\n # Check if the character is in the set of prime hexadecimal digits\n if char in prime_hex_digits:\n prime_count += 1\n \n return prime_count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n \"\"\"Convert a decimal number to binary format with specific formatting.\n\n Args:\n decimal (int): A non-negative integer to convert to binary.\n\n Returns:\n str: A string representing the binary format of the decimal number,\n prefixed and suffixed with 'db'.\n \n Examples:\n decimal_to_binary(15) # returns \"db1111db\"\n decimal_to_binary(32) # returns \"db100000db\"\n \"\"\"\n if not isinstance(decimal, int) or decimal < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n\n # Convert decimal to binary and remove the '0b' prefix\n binary_representation = bin(decimal)[2:]\n\n # Format the output with 'db' at the beginning and end\n formatted_binary = f\"db{binary_representation}db\"\n\n return formatted_binary", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n \n letter_grades = []\n \n for gpa in grades:\n if gpa == 4.0:\n letter_grades.append('A+')\n elif gpa > 3.7:\n letter_grades.append('A')\n elif gpa > 3.3:\n letter_grades.append('A-')\n elif gpa > 3.0:\n letter_grades.append('B+')\n elif gpa > 2.7:\n letter_grades.append('B')\n elif gpa > 2.3:\n letter_grades.append('B-')\n elif gpa > 2.0:\n letter_grades.append('C+')\n elif gpa > 1.7:\n letter_grades.append('C')\n elif gpa > 1.3:\n letter_grades.append('C-')\n elif gpa > 1.0:\n letter_grades.append('D+')\n elif gpa > 0.7:\n letter_grades.append('D')\n elif gpa > 0.0:\n letter_grades.append('D-')\n elif gpa == 0.0:\n letter_grades.append('E')\n else:\n letter_grades.append('Invalid GPA') # Handle any negative GPAs or invalid inputs\n\n return letter_grades", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n \"\"\"Check if the string is happy.\n \n A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n \n Args:\n s (str): The input string to check.\n \n Returns:\n bool: True if the string is happy, False otherwise.\n \"\"\"\n # Check if the length of the string is at least 3\n if len(s) < 3:\n return False\n \n # Iterate through the string and check every 3 consecutive characters\n for i in range(len(s) - 2):\n # Get the current substring of 3 characters\n substring = s[i:i+3]\n # Check if all characters in the substring are distinct\n if len(set(substring)) != 3:\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n \"\"\"\n Given a positive integer n, return the count of the numbers of n-digit\n positive integers that start or end with 1.\n \n Parameters:\n n (int): The number of digits in the positive integers to consider.\n \n Returns:\n int: The count of n-digit positive integers that start or end with 1.\n \"\"\"\n \n if n <= 0:\n raise ValueError(\"n must be a positive integer.\")\n \n if n == 1:\n # For 1-digit numbers, only the number '1' qualifies\n return 1\n \n # Count of n-digit numbers\n total_n_digit_numbers = 9 * (10 ** (n - 1))\n \n # Count of n-digit numbers that start with 1\n start_with_1 = 10 ** (n - 1) # 1 followed by (n-1) digits (0-9)\n \n # Count of n-digit numbers that end with 1\n end_with_1 = 9 * (10 ** (n - 2)) if n > 1 else 0 # (n-1) digits (0-9) before 1\n \n # Total count of n-digit numbers that start or end with 1\n # We need to subtract the overlap where numbers both start and end with 1\n start_and_end_with_1 = 10 ** (n - 2) if n > 1 else 0 # 1 followed by (n-2) digits (0-9) followed by 1\n \n result = start_with_1 + end_with_1 - start_and_end_with_1\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_length(string):\n \"\"\"Check if the length of the string is a prime number.\"\"\"\n length = len(string)\n return is_prime(length)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits will be 1 the output should be \"1\".\n For N = 150, the sum of digits will be 6 the output should be \"110\".\n For N = 147, the sum of digits will be 12 the output should be \"1100\".\n \n Variables:\n @N integer\n Constraints: 0 \u2264 N \u2264 10000.\n Output:\n a string of binary number\n \"\"\"\n \n # Edge case: if N is 0, the sum of digits is 0\n if N == 0:\n return \"0\"\n \n # Calculate the sum of digits\n digit_sum = sum(int(digit) for digit in str(N))\n \n # Convert the sum to binary and return it as a string\n return bin(digit_sum)[2:]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n add([1, 2, 3, 4, 5]) ==> 0\n add([0, 2, 4, 6, 8]) ==> 2 + 4 = 6\n add([1, 3, 5, 7]) ==> 0\n add([10, 11, 12, 13, 14]) ==> 12\n \"\"\"\n # Initialize the sum to 0\n total = 0\n \n # Iterate over the list using index and value\n for index in range(1, len(lst), 2): # Start from index 1 and step by 2 (odd indices)\n if lst[index] % 2 == 0: # Check if the element is even\n total += lst[index] # Add to total if it's even\n \n return total", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n # Iterate through each row and its index\n for row_index, row in enumerate(lst):\n # Iterate through each column in the row and its index\n for col_index, value in enumerate(row):\n # If the value matches x, store the coordinates\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort coordinates by row (ascending) and then by column (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words while preserving spaces\n words = s.split(' ')\n \n # Function to sort characters in a word\n def sort_word(word):\n return ''.join(sorted(word))\n \n # Process each word and sort its characters\n sorted_words = [sort_word(word) for word in words]\n \n # Join the sorted words back with spaces\n result = ' '.join(sorted_words)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n or sort it in descending order if the sum( first index value, last index value) is even.\n\n Note:\n * don't change the given array.\n\n Examples:\n * sort_array([]) => []\n * sort_array([5]) => [5]\n * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n \"\"\"\n # Create a copy of the original array to avoid modifying it\n sorted_array = array.copy()\n \n # Check if the array is empty or has only one element\n if len(sorted_array) <= 1:\n return sorted_array\n \n # Calculate the sum of the first and last elements\n first_element = sorted_array[0]\n last_element = sorted_array[-1]\n total_sum = first_element + last_element\n \n # Sort the array based on the sum being odd or even\n if total_sum % 2 == 0:\n # Even sum: sort in descending order\n sorted_array.sort(reverse=True)\n else:\n # Odd sum: sort in ascending order\n sorted_array.sort()\n \n return sorted_array", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating each letter down the alphabet by 4 positions.\"\"\"\n encrypted_string = []\n \n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Determine the base ASCII value depending on whether it's uppercase or lowercase\n base = ord('a') if char.islower() else ord('A')\n # Calculate the new position with wrapping around the alphabet\n new_char = chr((ord(char) - base + 4) % 26 + base)\n encrypted_string.append(new_char)\n else:\n # If the character is not a letter, we can choose to ignore it or handle it differently\n # Here we will ignore non-alphabetic characters\n continue\n \n return ''.join(encrypted_string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Convert the set back to a sorted list\n sorted_unique_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_unique_elements[1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n \n For example:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n >>> is_bored(\"I am bored! Are you? I want to go home.\")\n 2\n >>> is_bored(\"What a beautiful day. I hope it lasts.\")\n 1\n >>> is_bored(\"I. I. I.\")\n 3\n >>> is_bored(\"\")\n 0\n >>> is_bored(\"!I am here. I am not bored? I am happy.\")\n 2\n \"\"\"\n # Split the string into sentences based on the delimiters\n import re\n sentences = re.split(r'[.!?]', S)\n \n # Count the number of sentences that start with \"I\"\n boredom_count = 0\n for sentence in sentences:\n # Strip leading whitespace and check if it starts with \"I\"\n if sentence.strip().startswith(\"I\"):\n boredom_count += 1\n \n return boredom_count", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n '''\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n \n Examples\n any_int(5, 2, 7) \u279e True\n any_int(3, 2, 2) \u279e False\n any_int(3, -2, 1) \u279e True\n any_int(3.6, -2.2, 2) \u279e False\n '''\n \n # Check if all inputs are integers\n if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n # Check if one number is equal to the sum of the other two\n return x == y + z or y == x + z or z == x + y\n else:\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n \"\"\"\n Encodes the given message by swapping the case of all letters and replacing all vowels\n with the letter that appears 2 places ahead in the English alphabet.\n\n Parameters:\n message (str): The message to encode.\n\n Returns:\n str: The encoded message.\n\n Examples:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n # Define a mapping for vowels to their replacements\n vowel_replacement = {\n 'a': 'c', 'A': 'C',\n 'e': 'g', 'E': 'G',\n 'i': 'k', 'I': 'K',\n 'o': 'q', 'O': 'Q',\n 'u': 'w', 'U': 'W'\n }\n \n encoded_message = []\n \n for char in message:\n if char.isalpha(): # Check if the character is a letter\n # Swap case\n if char in vowel_replacement:\n # Replace vowel and swap case\n encoded_message.append(vowel_replacement[char])\n else:\n # Just swap case for consonants\n encoded_message.append(char.swapcase())\n else:\n # If it's not a letter, keep it as is\n encoded_message.append(char)\n \n return ''.join(encoded_message)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["TEST"]], "plus_fail_tests": []}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef sum_of_digits(n):\n \"\"\"Return the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n largest_prime = -1 # Initialize to -1 to indicate no prime found\n for number in lst:\n if is_prime(number) and number > largest_prime:\n largest_prime = number\n \n if largest_prime == -1:\n return 0 # Return 0 if no prime number is found\n \n return sum_of_digits(largest_prime)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_up_to(n):\n \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n primes = []\n for i in range(2, n):\n if is_prime(i):\n primes.append(i)\n return primes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in lower \n case or all keys are strings in upper case, else return False.\n The function should return False if the given dictionary is empty.\n \n Examples:\n check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n \"\"\"\n \n # Check if the dictionary is empty\n if not input_dict:\n return False\n \n # Initialize flags for lower and upper case\n all_lower = True\n all_upper = True\n \n # Iterate through the keys of the dictionary\n for key in input_dict.keys():\n # Check if the key is a string\n if not isinstance(key, str):\n return False\n \n # Check if the key is lower case\n if key.islower():\n all_upper = False\n # Check if the key is upper case\n elif key.isupper():\n all_lower = False\n else:\n # If the key is neither lower nor upper case\n return False\n \n # Return True if all keys are either lower case or upper case\n return all_lower or all_upper", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.\n \"\"\"\n # Get the unit digit of the first number\n unit_digit_a = abs(a) % 10\n # Get the unit digit of the second number\n unit_digit_b = abs(b) % 10\n # Return the product of the unit digits\n return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n count_upper('aBCdEf') returns 1\n count_upper('abcdefg') returns 0\n count_upper('dBBE') returns 0\n \"\"\"\n # Define the set of uppercase vowels\n uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n \n # Initialize a counter for uppercase vowels at even indices\n count = 0\n \n # Iterate over the string, checking only even indices\n for i in range(0, len(s), 2): # Step by 2 to get even indices\n if s[i] in uppercase_vowels:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n >>> closest_integer(\"14.5\")\n 15\n >>> closest_integer(\"-14.5\")\n -15\n >>> closest_integer(\"0.5\")\n 1\n >>> closest_integer(\"-0.5\")\n -1\n >>> closest_integer(\"3.0\")\n 3\n >>> closest_integer(\"-3.0\")\n -3\n >>> closest_integer(\"2.499999\")\n 2\n >>> closest_integer(\"-2.499999\")\n -2\n '''\n\n # Convert the string input to a float\n num = float(value)\n\n # Calculate the floor and ceiling of the number\n lower_int = int(num // 1) # This is the floor of the number\n upper_int = lower_int + 1 # This is the ceiling of the number\n\n # Check the distance to the lower and upper integers\n distance_to_lower = abs(num - lower_int)\n distance_to_upper = abs(num - upper_int)\n\n # Determine which integer to return\n if distance_to_lower < distance_to_upper:\n return lower_int\n elif distance_to_upper < distance_to_lower:\n return upper_int\n else:\n # If equidistant, round away from zero\n if num > 0:\n return upper_int\n else:\n return lower_int", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n \"\"\"\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n >>> make_a_pile(4)\n [4, 6, 8, 10]\n >>> make_a_pile(1)\n [1]\n >>> make_a_pile(0)\n []\n \"\"\"\n if n <= 0:\n return [] # Handle edge case for non-positive integers\n\n stones = []\n current_stones = n\n\n for i in range(n):\n stones.append(current_stones)\n if current_stones % 2 == 0: # If current_stones is even\n current_stones += 2 # Next even number\n else: # If current_stones is odd\n current_stones += 2 # Next odd number\n\n return stones", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n \"\"\"\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n \"\"\"\n # Replace commas with spaces and split the string by whitespace\n words = s.replace(',', ' ').split()\n \n # Return the list of words\n return words", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n \"\"\"This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If \n there's no such number, then the function should return -1.\n\n For example:\n choose_num(12, 15) = 14\n choose_num(13, 12) = -1\n \"\"\"\n \n # Ensure x is less than or equal to y\n if x > y:\n return -1\n \n # Start from the maximum of x and y\n for num in range(y, x - 1, -1):\n if num % 2 == 0: # Check if the number is even\n return num\n \n return -1 # If no even number is found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n \"\"\"Given a list of positive integers x, return a sorted list of all \n elements that haven't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n def has_even_digit(n):\n \"\"\"Check if the number has any even digit.\"\"\"\n for digit in str(n):\n if int(digit) % 2 == 0:\n return True\n return False\n\n # Filter the list to include only numbers without even digits\n filtered = [num for num in x if not has_even_digit(num)]\n \n # Sort the resulting list\n return sorted(filtered)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n \"\"\"You are given two positive integers n and m, and your task is to compute the\n average of the integers from n through m (including n and m). \n Round the answer to the nearest integer and convert that to binary.\n If n is greater than m, return -1.\n \n Example:\n rounded_avg(1, 5) => \"0b11\"\n rounded_avg(7, 5) => -1\n rounded_avg(10, 20) => \"0b1111\"\n rounded_avg(20, 33) => \"0b11010\"\n \"\"\"\n if n > m:\n return -1\n \n # Calculate the sum of integers from n to m\n total_sum = sum(range(n, m + 1))\n count = m - n + 1 # Total numbers from n to m\n \n # Calculate the average and round it\n average = total_sum / count\n rounded_average = round(average)\n \n # Convert the rounded average to binary\n binary_average = bin(rounded_average)\n \n return binary_average", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n reverse the resulting array, and then replace each digit by its corresponding name from\n \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n For example:\n arr = [2, 1, 1, 4, 5, 8, 2, 3] \n -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n \n If the array is empty, return an empty array:\n arr = []\n return []\n \n If the array has any strange number ignore it:\n arr = [1, -1 , 55] \n -> sort arr -> [-1, 1, 55]\n -> reverse arr -> [55, 1, -1]\n return = ['One']\n \"\"\"\n \n # Mapping of numbers to their corresponding names\n number_to_name = {\n 1: \"One\",\n 2: \"Two\",\n 3: \"Three\",\n 4: \"Four\",\n 5: \"Five\",\n 6: \"Six\",\n 7: \"Seven\",\n 8: \"Eight\",\n 9: \"Nine\"\n }\n \n # Filter the array to include only numbers between 1 and 9\n filtered_arr = [num for num in arr if 1 <= num <= 9]\n \n # Sort the filtered array\n filtered_arr.sort()\n \n # Reverse the sorted array\n filtered_arr.reverse()\n \n # Convert the numbers to their corresponding names\n result = [number_to_name[num] for num in filtered_arr]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def factorial(num):\n \"\"\"Helper function to calculate the factorial of a number.\"\"\"\n if num == 0 or num == 1:\n return 1\n result = 1\n for i in range(2, num + 1):\n result *= i\n return result\ndef sum_of_numbers(num):\n \"\"\"Helper function to calculate the sum of numbers from 1 to num.\"\"\"\n return num * (num + 1) // 2\ndef f(n):\n \"\"\"Implement the function f that takes n as a parameter,\n and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even\n or the sum of numbers from 1 to i otherwise.\n i starts from 1.\n \"\"\"\n if n < 1:\n return [] # Return an empty list for non-positive n\n\n result = []\n for i in range(1, n + 1):\n if i % 2 == 0: # i is even\n result.append(factorial(i))\n else: # i is odd\n result.append(sum_of_numbers(i))\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n \"\"\"\n Write a function count_nums which takes an array of integers and returns\n the number of elements which has a sum of digits > 0.\n If a number is negative, then its first signed digit will be negative:\n e.g. -123 has signed digits -1, 2, and 3.\n \n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n \n def sum_of_digits(n):\n \"\"\"Helper function to calculate the sum of digits of a number.\"\"\"\n # Convert the number to string and iterate over each character\n # If the number is negative, we need to consider the first digit as negative\n str_n = str(n)\n digit_sum = 0\n \n for i, char in enumerate(str_n):\n if char.isdigit():\n digit_sum += int(char)\n elif i == 0 and char == '-':\n digit_sum -= 1 # First signed digit is negative\n \n return digit_sum\n\n count = 0\n for number in arr:\n if sum_of_digits(number) > 0:\n count += 1\n \n return count", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[-1, -2, 0]]], "plus_fail_tests": []}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n \"\"\"\n Given a positive integer n, return a tuple that has the number of even and odd\n integer palindromes that fall within the range(1, n), inclusive.\n\n Example 1:\n Input: 3\n Output: (1, 2)\n Explanation:\n Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n Example 2:\n Input: 12\n Output: (4, 6)\n Explanation:\n Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n Note:\n 1. 1 <= n <= 10^3\n 2. returned tuple has the number of even and odd integer palindromes respectively.\n \"\"\"\n \n def is_palindrome(num):\n \"\"\"Check if a number is a palindrome.\"\"\"\n return str(num) == str(num)[::-1]\n\n even_count = 0\n odd_count = 0\n\n for i in range(1, n + 1):\n if is_palindrome(i):\n if i % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n \"\"\"Determines whether it is possible to perform an exchange of elements\n between two lists to make lst1 a list of only even numbers.\n \n Args:\n lst1 (list): The first list of numbers.\n lst2 (list): The second list of numbers.\n \n Returns:\n str: \"YES\" if lst1 can be made entirely even, otherwise \"NO\".\n \"\"\"\n \n # Check if all elements in lst1 are already even\n if all(x % 2 == 0 for x in lst1):\n return \"YES\"\n \n # Count the number of odd elements in lst1\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n \n # Count the number of even elements in lst2\n even_count_lst2 = sum(1 for x in lst2 if x % 2 == 0)\n \n # If there are enough even numbers in lst2 to replace all odd numbers in lst1\n if odd_count_lst1 <= even_count_lst2:\n return \"YES\"\n \n return \"NO\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return True else return False.\n If the given array is empty then return True.\n\n Note: The given list is guaranteed to have unique elements.\n\n For Example:\n \n move_one_ball([3, 4, 5, 1, 2])==>True\n Explanation: By performing 2 right shift operations, non-decreasing order can\n be achieved for the given array.\n move_one_ball([3, 5, 4, 1, 2])==>False\n Explanation: It is not possible to get non-decreasing order for the given\n array by performing any number of right shift operations.\n \"\"\"\n \n if not arr: # Check for empty array\n return True\n \n n = len(arr)\n count = 0 # Count the number of times the order is broken\n\n for i in range(n):\n if arr[i] > arr[(i + 1) % n]: # Compare current with next (circular)\n count += 1\n\n # If there are more than one breaks in the order, it's not possible\n return count <= 1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n \"\"\"\n \n if not test: # Handle the empty string case\n return {}\n \n # Split the input string into a list of letters\n letters = test.split()\n \n # Create a dictionary to count occurrences of each letter\n count_dict = {}\n for letter in letters:\n if letter in count_dict:\n count_dict[letter] += 1\n else:\n count_dict[letter] = 1\n \n # Find the maximum occurrence count\n max_count = max(count_dict.values())\n \n # Create a result dictionary for letters with the maximum count\n result = {letter: count for letter, count in count_dict.items() if count == max_count}\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n \"\"\"Task\n We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and True/False for the check.\n Example\n For s = \"abcde\", c = \"ae\", the result should be ('bcd',False)\n For s = \"abcdef\", c = \"b\" the result should be ('acdef',False)\n For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc',True)\n \"\"\"\n \n # Create a set of characters to delete for faster lookup\n chars_to_delete = set(c)\n \n # Build the result string by filtering out characters in chars_to_delete\n result = ''.join(char for char in s if char not in chars_to_delete)\n \n # Check if the result string is a palindrome\n is_palindrome = result == result[::-1]\n \n return (result, is_palindrome)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n Example:\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n \"\"\"\n if not nums:\n raise ValueError(\"The input array must not be empty.\")\n \n # Initialize variables to track the minimum sum and the current sum\n min_sum = float('inf')\n current_sum = 0\n \n for num in nums:\n current_sum += num\n min_sum = min(min_sum, current_sum)\n \n # If current_sum becomes positive, reset it to 0\n if current_sum > 0:\n current_sum = 0\n \n return min_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n \n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in s if char in '13579')\n \n # Create the output string with the counted odd digits\n output_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n \n # Append the result to the list\n result.append(output_string)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n \"\"\"\n Calculate the number of times buckets need to be lowered to empty the wells.\n\n Parameters:\n grid (list of list of int): A rectangular grid representing wells.\n capacity (int): The capacity of each bucket.\n\n Returns:\n int: The total number of times buckets need to be lowered.\n \"\"\"\n total_water = 0\n \n # Count the total amount of water in the grid\n for row in grid:\n total_water += sum(row)\n \n # Calculate the number of times buckets need to be lowered\n if total_water == 0:\n return 0 # No water to extract\n \n # Each bucket can carry 'capacity' units of water\n # We need to lower the buckets enough times to extract all the water\n return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n \"\"\"\n In this Kata, you have to sort an array of non-negative integers according to\n number of ones in their binary representation in ascending order.\n For similar number of ones, sort based on decimal value.\n\n It must be implemented like this:\n >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n >>> sort_array([1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]\n \"\"\"\n \n # Check for empty array\n if not arr:\n return []\n\n # Sort the array based on the number of 1s in binary representation and then by value\n return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n \"\"\"Given a string s and a natural number n, returns a list of all words from \n string s that contain exactly n consonants, in the order they appear in the string s.\n If the string s is empty, returns an empty list.\n \n Args:\n s (str): The input string containing words.\n n (int): The number of consonants to filter words by.\n \n Returns:\n list: A list of words containing exactly n consonants.\n \"\"\"\n \n if not s: # Check if the string is empty\n return []\n \n # Define a set of consonants\n consonants = set(\"bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ\")\n \n # Split the string into words\n words = s.split()\n \n # Function to count consonants in a word\n def count_consonants(word):\n return sum(1 for char in word if char in consonants)\n \n # Filter words that have exactly n consonants\n result = [word for word in words if count_consonants(word) == n]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n two consonants from the right side of the word (case sensitive).\n \n Vowels in the beginning and ending don't count. Return empty string if you didn't\n find any vowel that meets the above condition. \n\n You may assume that the given string contains English letters only.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n n = len(word)\n\n # Check for edge cases\n if n < 3: # Need at least 3 characters to have consonants on both sides of a vowel\n return \"\"\n\n # Start from the end of the word\n for i in range(n - 2, 0, -1): # Start from the second last character to the first\n if word[i] in vowels: # Check if the current character is a vowel\n # Check if there are consonants on both sides\n if word[i - 1].isalpha() and word[i + 1].isalpha() and \\\n word[i - 1] not in vowels and word[i + 1] not in vowels:\n return word[i] # Return the vowel if conditions are met\n\n return \"\" # Return empty string if no valid vowel is found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n \n # Sort the array in descending order to get the largest elements first\n sorted_arr = sorted(arr, reverse=True)\n \n # Get the top k elements\n top_k = sorted_arr[:k]\n \n # Sort the top k elements in ascending order before returning\n return sorted(top_k)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0: # More closing than opening\n return False\n return balance == 0 # Must be balanced at the end\n\n # Check both concatenation orders\n s1, s2 = lst[0], lst[1]\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n return 'No'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n \"\"\"\n Given a non-empty array of integers arr and an integer k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example:\n\n Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n Output: 24 # sum of 21 + 3\n\n Constraints:\n 1. 1 <= len(arr) <= 100\n 2. 1 <= k <= len(arr)\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate through the first k elements of the array\n for i in range(k):\n # Check if the current element has at most two digits\n if -100 < arr[i] < 100:\n total_sum += arr[i]\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n An even position is defined as an index that is even (0, 2, 4, ...).\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list using index and value\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n total_sum += value\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n \n The date is valid if all of the following rules are satisfied:\n 1. The date string is not empty.\n 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n The number of days is not less than 1 or higher than 29 for the month 2.\n 3. The months should not be less than 1 or higher than 12.\n 4. The date should be in the format: mm-dd-yyyy\n \"\"\"\n \n # Check if the date string is empty\n if not date:\n return False\n \n # Check if the date is in the correct format\n if len(date) != 10 or date[2] != '-' or date[5] != '-':\n return False\n \n # Split the date into components\n try:\n month, day, year = map(int, date.split('-'))\n except ValueError:\n return False\n \n # Check month range\n if month < 1 or month > 12:\n return False\n \n # Check day range based on month\n if month in {1, 3, 5, 7, 8, 10, 12}:\n if day < 1 or day > 31:\n return False\n elif month in {4, 6, 9, 11}:\n if day < 1 or day > 30:\n return False\n elif month == 2:\n if day < 1 or day > 29:\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n as follows: start with any positive integer n. Then each term is obtained from the \n previous term as follows: if the previous term is even, the next term is one half of \n the previous term. If the previous term is odd, the next term is 3 times the previous\n term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n Note: \n 1. Collatz(1) is [1].\n 2. returned list sorted in increasing order.\n\n For example:\n get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n collatz_sequence = []\n \n while n != 1:\n collatz_sequence.append(n)\n if n % 2 == 0:\n n //= 2\n else:\n n = 3 * n + 1\n \n collatz_sequence.append(1) # Append the last term which is 1\n \n # Filter out the odd numbers and sort them\n odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n \n return odd_numbers", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n '''\n Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n Examples\n split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"abcdef\") == 3 \n '''\n \n # Check for whitespace in the text\n if ' ' in txt:\n return txt.split()\n \n # Check for commas in the text\n elif ',' in txt:\n return txt.split(',')\n \n # If no whitespace or commas, count lowercase letters with odd order\n else:\n odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n return odd_count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n '''\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return False. Assume no negative numbers and only integers.\n\n Examples\n is_sorted([5]) \u279e True\n is_sorted([1, 2, 3, 4, 5]) \u279e True\n is_sorted([1, 3, 2, 4, 5]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n '''\n \n if len(lst) <= 1:\n return True # A list with 0 or 1 element is sorted by definition\n\n seen = set()\n last_num = None\n\n for num in lst:\n if num in seen:\n # If we see a number again, check if it's the same as the last number\n if num == last_num:\n return False # More than 1 duplicate of the same number\n else:\n seen.add(num)\n\n if last_num is not None and num < last_num:\n return False # Not sorted in ascending order\n\n last_num = num\n\n return True # If we pass all checks, the list is sorted", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n if not arr: # Check for empty array\n return None\n\n product_of_signs = 1\n sum_of_magnitudes = 0\n\n for num in arr:\n if num > 0:\n sum_of_magnitudes += num\n elif num < 0:\n sum_of_magnitudes += -num\n product_of_signs *= -1 # Flip the sign for negative numbers\n else: # num == 0\n return 0 # If there's a zero, the product of signs is zero\n\n return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef intersection(interval1, interval2):\n \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n # Unpack the intervals\n start1, end1 = interval1\n start2, end2 = interval2\n \n # Find the intersection\n start_intersection = max(start1, start2)\n end_intersection = min(end1, end2)\n \n # Check if there is an intersection\n if start_intersection > end_intersection:\n return \"NO\"\n \n # Calculate the length of the intersection\n length_of_intersection = end_intersection - start_intersection\n \n # Check if the length is a prime number\n if is_prime(length_of_intersection):\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n \"\"\"Calculate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n if n < 0:\n return [] # Return an empty list for negative input\n\n # Initialize the list to hold the Tribonacci numbers\n tribonacci_sequence = []\n\n # Define the base case\n for i in range(n + 1):\n if i == 0:\n tribonacci_sequence.append(1) # tri(0) = 1\n elif i == 1:\n tribonacci_sequence.append(3) # tri(1) = 3\n elif i % 2 == 0: # Even index\n tribonacci_sequence.append(1 + i / 2) # tri(n) = 1 + n / 2\n else: # Odd index\n # tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1)\n # We need to ensure we have calculated tri(n + 1) beforehand\n if i + 1 <= n:\n tribonacci_sequence.append(tribonacci_sequence[i - 1] + tribonacci_sequence[i - 2] + tribonacci_sequence[i + 1])\n else:\n tribonacci_sequence.append(tribonacci_sequence[i - 1] + tribonacci_sequence[i - 2] + 3) # tri(n + 1) = 3 for n = 1\n\n return tribonacci_sequence", "base_status": "fail", "plus_status": null, "base_fail_tests": [[4]], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n \"\"\"Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n For example:\n digits(1) == 1\n digits(4) == 0\n digits(235) == 15\n \"\"\"\n # Initialize the product to 1 and a flag to check if any odd digit is found\n product = 1\n found_odd = False\n \n # Convert the number to a string to iterate over each digit\n for digit in str(n):\n digit = int(digit) # Convert the character back to an integer\n if digit % 2 != 0: # Check if the digit is odd\n product *= digit # Multiply the product by the odd digit\n found_odd = True # Set the flag to True since we found an odd digit\n \n # If no odd digit was found, return 0\n if not found_odd:\n return 0\n \n return product", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n '''\n Create a function that takes a string as input which contains only square brackets.\n The function should return True if and only if there is a valid subsequence of brackets \n where at least one bracket in the subsequence is nested.\n\n is_nested('[[]]') \u279e True\n is_nested('[]]]]]]][[[[[]') \u279e False\n is_nested('[][]') \u279e False\n is_nested('[]') \u279e False\n is_nested('[[][]]') \u279e True\n is_nested('[[]][[') \u279e True\n '''\n \n # Initialize a counter for open brackets\n open_count = 0\n # Initialize a flag to check for nesting\n nested = False\n \n for char in string:\n if char == '[':\n open_count += 1\n # If we have more than one open bracket, we have a nested structure\n if open_count > 1:\n nested = True\n elif char == ']':\n open_count -= 1\n # If we close a bracket and there was at least one open bracket before\n if open_count < 0:\n return False # More closing brackets than opening\n # If we have closed brackets but still have open brackets, we can check for nesting\n if open_count > 0 and nested:\n return True\n \n # At the end, we should have no unmatched opening brackets\n return nested and open_count == 0", "base_status": "fail", "plus_status": null, "base_fail_tests": [["[[]"]], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers.\n You need to return the sum of squared numbers in the given list,\n round each element in the list to the upper int (Ceiling) first.\n \n Examples:\n For lst = [1,2,3] the output should be 14\n For lst = [1,4,9] the output should be 98\n For lst = [1,3,5,7] the output should be 84\n For lst = [1.4,4.2,0] the output should be 29\n For lst = [-2.4,1,1] the output should be 6\n \"\"\"\n # Initialize the sum of squares\n total_sum = 0\n \n # Iterate through each number in the list\n for number in lst:\n # Round the number up to the nearest integer\n rounded_number = math.ceil(number)\n # Square the rounded number and add it to the total sum\n total_sum += rounded_number ** 2\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n '''\n Create a function that returns True if the last character\n of a given string is an alphabetical character and is not\n a part of a word, and False otherwise.\n Note: \"word\" is a group of characters separated by space.\n\n Examples:\n check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '''\n \n # Strip any trailing whitespace from the string\n txt = txt.rstrip()\n \n # Check if the string is empty after stripping\n if not txt:\n return False\n \n # Get the last character of the string\n last_char = txt[-1]\n \n # Check if the last character is an alphabetical character\n if last_char.isalpha():\n # Check if the last character is part of a word\n # A character is part of a word if it is preceded by a non-space character\n if len(txt) > 1 and txt[-2] != ' ':\n return False\n return True\n \n return False", "base_status": "fail", "plus_status": null, "base_fail_tests": [["eeeee e "]], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n \"\"\"Create a function which returns the largest index of an element which\n is not greater than or equal to the element immediately preceding it. If\n no such element exists then return -1. The given array will not contain\n duplicate values.\n\n Examples:\n can_arrange([1,2,4,3,5]) = 3\n can_arrange([1,2,3]) = -1\n \"\"\"\n # Check if the array is empty\n if not arr:\n return -1\n\n # Initialize the largest index to -1 (indicating no such element found)\n largest_index = -1\n\n # Iterate through the array starting from the second element\n for i in range(1, len(arr)):\n # Check if the current element is less than the previous element\n if arr[i] < arr[i - 1]:\n largest_index = i # Update the largest index\n\n return largest_index", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n from collections import deque\n\n N = len(grid)\n directions = [(0, 1), (1, 0), (0, -1), (-1, 0)] # right, down, left, up\n min_path = None\n\n def dfs(x, y, path):\n nonlocal min_path\n if len(path) == k:\n if min_path is None or path < min_path:\n min_path = path[:]\n return\n \n for dx, dy in directions:\n nx, ny = x + dx, y + dy\n if 0 <= nx < N and 0 <= ny < N:\n path.append(grid[nx][ny])\n dfs(nx, ny, path)\n path.pop()\n\n for i in range(N):\n for j in range(N):\n dfs(i, j, [grid[i][j]])\n\n return min_path", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n '''\n Create a function that returns a tuple (a, b), where 'a' is\n the largest of negative integers, and 'b' is the smallest\n of positive integers in a list.\n If there is no negative or positive integers, return them as None.\n\n Examples:\n largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n largest_smallest_integers([]) == (None, None)\n largest_smallest_integers([0]) == (None, None)\n '''\n \n largest_negative = None\n smallest_positive = None\n \n for num in lst:\n if num < 0:\n if largest_negative is None or num > largest_negative:\n largest_negative = num\n elif num > 0:\n if smallest_positive is None or num < smallest_positive:\n smallest_positive = num\n \n return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def parse_number(value):\n \"\"\"\n Helper function to convert a string representation of a number\n into a float or return the original value if it's not a string.\n It handles both '.' and ',' as decimal separators.\n \"\"\"\n if isinstance(value, str):\n # Replace ',' with '.' for float conversion\n value = value.replace(',', '.')\n try:\n return float(value)\n except ValueError:\n return value # Return the original string if conversion fails\n return value # Return the original value if it's not a string\ndef compare_one(a, b):\n \"\"\"\n Compare two values (integers, floats, or strings representing real numbers)\n and return the larger one in its original type. Return None if they are equal.\n \"\"\"\n # Parse both values\n parsed_a = parse_number(a)\n parsed_b = parse_number(b)\n\n # Check for equality\n if parsed_a == parsed_b:\n return None\n\n # Determine the larger value\n if isinstance(a, str) and isinstance(b, str):\n # Both are strings, compare as strings\n return a if a > b else b\n elif isinstance(a, str) or isinstance(b, str):\n # One is a string, the other is a number\n return a if isinstance(a, str) else b\n else:\n # Both are numbers (int or float)\n return a if parsed_a > parsed_b else b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n \n Args:\n n (int): The number to evaluate.\n \n Returns:\n bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n \n Example:\n is_equal_to_sum_even(4) == False\n is_equal_to_sum_even(6) == False\n is_equal_to_sum_even(8) == True\n \"\"\"\n \n # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n if n < 8:\n return False\n \n # Check if n is even\n if n % 2 != 0:\n return False\n \n # If n is even and n >= 8, we can always express it as the sum of 4 positive even numbers\n # For example, n = 8 can be expressed as 2 + 2 + 2 + 2\n # For n = 10, it can be expressed as 2 + 2 + 2 + 4\n # For n = 12, it can be expressed as 2 + 2 + 4 + 4\n # And so on...\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(num):\n \"\"\"Helper function to calculate the factorial of a number.\"\"\"\n if num == 0 or num == 1:\n return 1\n result = 1\n for i in range(2, num + 1):\n result *= i\n return result\ndef special_factorial(n):\n \"\"\"The Brazilian factorial is defined as:\n brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!\n where n > 0\n\n For example:\n >>> special_factorial(4)\n 288\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer greater than 0.\")\n \n result = 1\n for i in range(1, n + 1):\n result *= factorial(i)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n \"\"\"Check if the given file name is valid based on specific criteria.\"\"\"\n \n # Define valid extensions\n valid_extensions = ['txt', 'exe', 'dll']\n \n # Check for exactly one dot\n if file_name.count('.') != 1:\n return 'No'\n \n # Split the file name into name and extension\n name, extension = file_name.rsplit('.', 1)\n \n # Check if the name is empty\n if not name:\n return 'No'\n \n # Check if the name starts with a letter\n if not name[0].isalpha():\n return 'No'\n \n # Check if the extension is valid\n if extension not in valid_extensions:\n return 'No'\n \n # Count digits in the file name\n digit_count = sum(c.isdigit() for c in file_name)\n \n # Check if there are more than three digits\n if digit_count > 3:\n return 'No'\n \n return 'Yes'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n \"\"\"\n Given a string text, replace all spaces in it with underscores, \n and if a string has more than 2 consecutive spaces, \n then replace all consecutive spaces with - \n \n fix_spaces(\"Example\") == \"Example\"\n fix_spaces(\"Example 1\") == \"Example_1\"\n fix_spaces(\" Example 2\") == \"_Example_2\"\n fix_spaces(\" Example 3\") == \"_Example-3\"\n \"\"\"\n # Replace multiple spaces with a placeholder\n # This will help us identify groups of spaces\n placeholder = ' ' * 3 # Three spaces\n text = text.replace(placeholder, '-')\n \n # Replace remaining spaces with underscores\n text = text.replace(' ', '_')\n \n # Handle leading and trailing underscores\n if text.startswith('_'):\n text = text[1:] # Remove leading underscore\n if text.endswith('_'):\n text = text[:-1] # Remove trailing underscore\n \n # If there are still leading or trailing dashes, remove them\n text = text.strip('-')\n \n return text", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Mudasir Hanif "]], "plus_fail_tests": []}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n \"\"\"\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n \n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126\n \"\"\"\n total_sum = 0\n \n for index, value in enumerate(lst):\n if index % 3 == 0:\n # Square the value if index is a multiple of 3\n total_sum += value ** 2\n elif index % 4 == 0:\n # Cube the value if index is a multiple of 4 and not a multiple of 3\n total_sum += value ** 3\n else:\n # Add the value as is if index is neither a multiple of 3 nor 4\n total_sum += value\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef words_in_sentence(sentence):\n \"\"\"\n Given a string representing a sentence, return a string that contains the words\n from the original sentence whose lengths are prime numbers.\n \n Parameters:\n sentence (str): The input sentence containing words separated by spaces.\n \n Returns:\n str: A string containing the words with prime lengths, in the original order.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Filter words whose lengths are prime\n prime_length_words = [word for word in words if is_prime(len(word))]\n \n # Join the filtered words back into a string\n return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n \"\"\"\n Write a function which sorts the given list of integers\n in ascending order according to the sum of their digits.\n Note: if there are several items with similar sum of their digits,\n order them based on their index in original list.\n\n For example:\n >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n >>> order_by_points([]) == []\n \"\"\"\n \n def digit_sum(n):\n \"\"\"Calculate the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(abs(n)))\n\n # Create a list of tuples (digit_sum, index, value)\n indexed_nums = [(digit_sum(num), index, num) for index, num in enumerate(nums)]\n \n # Sort by digit sum first, then by original index\n indexed_nums.sort(key=lambda x: (x[0], x[1]))\n \n # Extract the sorted values\n sorted_nums = [num for _, _, num in indexed_nums]\n \n return sorted_nums", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n \"\"\"Simplifies the expression x * n and checks if the result is a whole number.\n \n Args:\n x (str): A string representation of a fraction in the format 'numerator/denominator'.\n n (str): A string representation of a fraction in the format 'numerator/denominator'.\n \n Returns:\n bool: True if x * n evaluates to a whole number, False otherwise.\n \"\"\"\n # Split the fractions into numerator and denominator\n x_numerator, x_denominator = map(int, x.split('/'))\n n_numerator, n_denominator = map(int, n.split('/'))\n \n # Calculate the product of the fractions\n # x * n = (x_numerator / x_denominator) * (n_numerator / n_denominator)\n # This simplifies to (x_numerator * n_numerator) / (x_denominator * n_denominator)\n \n product_numerator = x_numerator * n_numerator\n product_denominator = x_denominator * n_denominator\n \n # Check if the product is a whole number\n return product_numerator % product_denominator == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n \"\"\"Returns the number of elements in the array that are greater than 10 \n and both the first and last digits of the number are odd (1, 3, 5, 7, 9).\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n int: The count of numbers meeting the criteria.\n \"\"\"\n \n def is_odd_digit(digit):\n \"\"\"Check if a digit is odd.\"\"\"\n return digit in {'1', '3', '5', '7', '9'}\n \n def first_and_last_digits_are_odd(num):\n \"\"\"Check if the first and last digits of the number are odd.\"\"\"\n num_str = str(abs(num)) # Convert to string and take absolute value\n return is_odd_digit(num_str[0]) and is_odd_digit(num_str[-1])\n \n count = 0\n for num in nums:\n if num > 10 and first_and_last_digits_are_odd(num):\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n \"\"\"\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example :\n Input: n = 5\n Output: 1\n Explanation: \n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n \"\"\"\n # Create the array a\n a = [i * i - i + 1 for i in range(1, n + 1)]\n \n # Count the number of valid triples\n count = 0\n \n # Iterate through all possible triples (i, j, k)\n for i in range(n):\n for j in range(i + 1, n):\n for k in range(j + 1, n):\n if (a[i] + a[j] + a[k]) % 3 == 0:\n count += 1\n \n return count\nn = 5", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes those with odd lengths,\n and returns the remaining strings sorted by length and alphabetically.\n \n Args:\n lst (list of str): A list of strings.\n \n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closest to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sorted by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct planet names. \n Examples\n bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n '''\n\n # List of planets in order from the Sun\n planets = [\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n ]\n \n # Check if the input planets are valid\n if planet1 not in planets or planet2 not in planets:\n return ()\n \n # Get the indices of the planets\n index1 = planets.index(planet1)\n index2 = planets.index(planet2)\n \n # Determine the range of indices\n start_index = min(index1, index2) + 1\n end_index = max(index1, index2)\n \n # Get the planets in between\n in_between_planets = planets[start_index:end_index]\n \n # Return as a tuple\n return tuple(in_between_planets)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n \n double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n double_the_difference([-1, -2, 0]) == 0\n double_the_difference([9, -2]) == 81\n double_the_difference([0]) == 0 \n \n If the input list is empty, return 0.\n '''\n if not lst: # Check if the list is empty\n return 0\n \n sum_of_squares = 0 # Initialize the sum of squares\n \n for num in lst:\n if isinstance(num, int) and num >= 0 and num % 2 != 0: # Check if num is a non-negative odd integer\n sum_of_squares += num ** 2 # Add the square of the odd number to the sum\n \n return sum_of_squares # Return the final sum of squares", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(num):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef x_or_y(n, x, y):\n \"\"\"Return the value of x if n is a prime number, otherwise return y.\"\"\"\n if is_prime(n):\n return x\n else:\n return y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n \"\"\"\n Compares the actual game scores with the guessed scores and returns an array\n indicating how far off each guess was. If the guess is correct, the value is 0,\n otherwise it is the absolute difference between the guess and the score.\n\n Parameters:\n game (list of int): The actual scores of the matches.\n guess (list of int): The guessed scores of the matches.\n\n Returns:\n list of int: An array of the same length indicating the difference for each match.\n \"\"\"\n # Check if the lengths of game and guess are equal\n if len(game) != len(guess):\n raise ValueError(\"The length of game and guess must be the same.\")\n\n # Calculate the absolute differences\n result = [abs(g - s) for g, s in zip(guess, game)]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n \"\"\"Find the strongest extension based on the defined strength criteria.\"\"\"\n \n def calculate_strength(extension):\n \"\"\"Calculate the strength of the extension.\"\"\"\n CAP = sum(1 for char in extension if char.isupper())\n SM = sum(1 for char in extension if char.islower())\n return CAP - SM\n\n strongest_extension = None\n strongest_strength = float('-inf') # Start with the lowest possible strength\n\n for extension in extensions:\n strength = calculate_strength(extension)\n \n # Check if this extension is stronger or if it's the first one\n if strength > strongest_strength:\n strongest_strength = strength\n strongest_extension = extension\n\n # Return the result in the required format\n return f\"{class_name}.{strongest_extension}\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n \"\"\"Check if the second word or any of its rotations is a substring in the first word.\"\"\"\n \n # Edge case: if b is empty, it is always a substring\n if not b:\n return True\n \n # Edge case: if a is empty and b is not, b cannot be a substring\n if not a:\n return False\n \n # Create a string that contains two copies of b\n # This allows us to check for all rotations of b\n b_rotations = b + b\n \n # Check if any rotation of b is a substring of a\n return any(rotation in a for rotation in (b_rotations[i:i+len(b)] for i in range(len(b))))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n Example:\n even_odd_count(-12) ==> (1, 1)\n even_odd_count(123) ==> (1, 2)\n \"\"\"\n # Convert the number to a string and handle negative sign\n num_str = str(abs(num))\n \n even_count = 0\n odd_count = 0\n \n for digit in num_str:\n if digit.isdigit(): # Ensure we are only counting digits\n if int(digit) % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n \n if not (1 <= number <= 1000):\n raise ValueError(\"Input must be between 1 and 1000 inclusive.\")\n \n # Mapping of integers to their corresponding Roman numeral representations\n roman_numerals = [\n (1000, 'm'), (900, 'cm'), (500, 'd'), (400, 'cd'),\n (100, 'c'), (90, 'xc'), (50, 'l'), (40, 'xl'),\n (10, 'x'), (9, 'ix'), (5, 'v'), (4, 'iv'),\n (1, 'i')\n ]\n \n result = []\n \n for value, numeral in roman_numerals:\n while number >= value:\n result.append(numeral)\n number -= value\n \n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return True if the three\n sides form a right-angled triangle, False otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or \n 90 degree.\n \n Example:\n right_angle_triangle(3, 4, 5) == True\n right_angle_triangle(1, 2, 3) == False\n '''\n \n # First, we need to check if the sides can form a triangle\n if a <= 0 or b <= 0 or c <= 0:\n return False # Sides must be positive\n \n # Sort the sides to easily identify the longest side\n sides = sorted([a, b, c])\n \n # Check the Pythagorean theorem: a^2 + b^2 = c^2\n return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n \"\"\"Return the word with the maximum number of unique characters.\n If multiple words have the same number of unique characters,\n return the one that comes first in lexicographical order.\n \n Args:\n words (list of str): A list of words to evaluate.\n \n Returns:\n str: The word with the maximum number of unique characters.\n \"\"\"\n max_word = \"\"\n max_unique_count = 0\n\n for word in words:\n # Calculate the number of unique characters in the word\n unique_count = len(set(word))\n \n # Check if this word has more unique characters or is lexicographically smaller\n if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n max_word = word\n max_unique_count = unique_count\n\n return max_word", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n \"\"\"\n You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n \n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n \n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots that exist in stock\n \n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n \"\"\"\n \n # Calculate how many more carrots are needed\n additional_needed = need - number\n \n if additional_needed <= 0:\n # If no more carrots are needed, return the current state\n return [number, remaining]\n \n # If there are enough remaining carrots to satisfy the need\n if remaining >= additional_needed:\n total_eaten = number + additional_needed\n remaining_after_meals = remaining - additional_needed\n else:\n # If not enough remaining carrots, eat all remaining\n total_eaten = number + remaining\n remaining_after_meals = 0\n \n return [total_eaten, remaining_after_meals]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic algebra operations, and \n the second list is a list of integers. Use the two given lists to build the algebraic \n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + ) \n Subtraction ( - ) \n Multiplication ( * ) \n Floor division ( // ) \n Exponentiation ( ** ) \n\n Example:\n operator = ['+', '*', '-']\n operand = [2, 3, 4, 5]\n result = 2 + 3 * 4 - 5\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.\n \"\"\"\n \n # Check for valid input\n if len(operator) != len(operand) - 1:\n raise ValueError(\"The length of operator list must be one less than the length of operand list.\")\n if len(operand) < 2:\n raise ValueError(\"Operand list must contain at least two elements.\")\n \n # Initialize the result with the first operand\n result = operand[0]\n \n # Iterate through the operators and operands\n for i in range(len(operator)):\n op = operator[i]\n next_operand = operand[i + 1]\n \n if op == '+':\n result += next_operand\n elif op == '-':\n result -= next_operand\n elif op == '*':\n result *= next_operand\n elif op == '//':\n if next_operand == 0:\n raise ZeroDivisionError(\"Division by zero is not allowed.\")\n result //= next_operand\n elif op == '**':\n result **= next_operand\n else:\n raise ValueError(f\"Invalid operator: {op}\")\n \n return result\noperator = ['+', '*', '-']\noperand = [2, 3, 4, 5]\nresult = do_algebra(operator, operand)", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": []}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n \"\"\"You are given a string s.\n if s[i] is a letter, reverse its case from lower to upper or vice versa, \n otherwise keep it as it is.\n If the string contains no letters, reverse the string.\n The function should return the resulted string.\n Examples\n solve(\"1234\") = \"4321\"\n solve(\"ab\") = \"AB\"\n solve(\"#a@C\") = \"#A@c\"\n \"\"\"\n # Check if there are any letters in the string\n has_letters = any(c.isalpha() for c in s)\n \n if has_letters:\n # If there are letters, reverse the case of each letter\n result = ''.join(c.swapcase() if c.isalpha() else c for c in s)\n else:\n # If there are no letters, reverse the string\n result = s[::-1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascending order.\n\n For example:\n generate_integers(2, 8) => [2, 4, 6, 8]\n generate_integers(8, 2) => [2, 4, 6, 8]\n generate_integers(10, 14) => []\n \"\"\"\n # Ensure a and b are positive integers\n if a <= 0 or b <= 0:\n raise ValueError(\"Both a and b must be positive integers.\")\n \n # Determine the range of numbers to consider\n start = min(a, b)\n end = max(a, b)\n\n # Generate a list of even integers in the specified range\n even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n return even_integers", "base_status": "fail", "plus_status": null, "base_fail_tests": [[2, 10]], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string.\n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n >>> string_to_md5('') is None\n >>> string_to_md5('Python') == '5d41402abc4b2a76b9719d911017c592'\n >>> string_to_md5('123456') == 'e10adc3949ba59abbe56e057f20f883e'\n >>> string_to_md5('!@#$%^&*()') == 'c5e478d592e507b71c1b6a3b1b1c4c8c'\n \"\"\"\n if text == \"\":\n return None\n # Create an MD5 hash object\n md5_hash = hashlib.md5()\n # Update the hash object with the bytes of the string\n md5_hash.update(text.encode('utf-8'))\n # Return the hexadecimal digest of the hash\n return md5_hash.hexdigest()", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}]}} \ No newline at end of file diff --git a/llm_based_126_eval_results.json b/llm_based_126_eval_results.json new file mode 100644 index 000000000..05e74c2fe --- /dev/null +++ b/llm_based_126_eval_results.json @@ -0,0 +1 @@ +{"date": "2024-07-26 22:52", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n >>> has_close_elements([], 0.5)\n False\n >>> has_close_elements([1.0], 0.5)\n False\n >>> has_close_elements([1.0, 1.4], 0.5)\n True\n >>> has_close_elements([1.0, 1.4, 1.8], 0.5)\n True\n >>> has_close_elements([1.0, 2.0, 2.4], 0.5)\n True\n >>> has_close_elements([1.0, 2.0, 2.5], 0.5)\n False\n \"\"\"\n # Edge case: if the list has less than 2 elements, return False\n if len(numbers) < 2:\n return False\n \n # Sort the numbers to make it easier to find close elements\n sorted_numbers = sorted(numbers)\n \n # Check the differences between consecutive elements\n for i in range(len(sorted_numbers) - 1):\n if abs(sorted_numbers[i] - sorted_numbers[i + 1]) < threshold:\n return True\n \n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" \n Input to this function is a string containing multiple groups of nested parentheses. \n The goal is to separate those groups into separate strings and return the list of those.\n Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n Ignore any spaces in the input string.\n \n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n # Remove spaces from the input string\n paren_string = paren_string.replace(\" \", \"\")\n \n result = []\n current_group = []\n balance = 0\n \n for char in paren_string:\n if char == '(':\n if balance == 0 and current_group:\n # If we are starting a new group, save the current one\n result.append(''.join(current_group))\n current_group = []\n current_group.append(char)\n balance += 1\n elif char == ')':\n current_group.append(char)\n balance -= 1\n \n # If balance goes negative, it means there's an unmatched closing parenthesis\n if balance < 0:\n raise ValueError(\"Unmatched closing parenthesis found.\")\n \n # If we finish processing and have a balanced group, add it to the result\n if balance != 0:\n raise ValueError(\"Unmatched opening parenthesis found.\")\n \n if current_group:\n result.append(''.join(current_group))\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into\n an integer part (largest integer smaller than given number) and decimals\n (leftover part always smaller than 1).\n\n Return the decimal part of the number.\n \n >>> truncate_number(3.5)\n 0.5\n >>> truncate_number(5.0)\n 0.0\n >>> truncate_number(0.99)\n 0.99\n >>> truncate_number(10.12345)\n 0.12345\n >>> truncate_number(1.000001)\n 0.000001\n >>> truncate_number(0.0) # Edge case: zero is not positive\n Traceback (most recent call last):\n ...\n ValueError: The number must be a positive floating point number.\n >>> truncate_number(-1.5) # Edge case: negative number\n Traceback (most recent call last):\n ...\n ValueError: The number must be a positive floating point number.\n \"\"\"\n if number <= 0:\n raise ValueError(\"The number must be a positive floating point number.\")\n \n integer_part = int(number) # Get the integer part\n decimal_part = number - integer_part # Calculate the decimal part\n return decimal_part", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" \n You're given a list of deposit and withdrawal operations on a bank account that starts with\n zero balance. Your task is to detect if at any point the balance of account falls below zero, \n and at that point function should return True. Otherwise it should return False.\n \n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n >>> below_zero([-1])\n True\n >>> below_zero([0, 0, 0])\n False\n >>> below_zero([-1, 1])\n False\n >>> below_zero([1, -1, -1])\n True\n >>> below_zero([5, -10, 5])\n True\n >>> below_zero([])\n False\n \"\"\"\n balance = 0\n for operation in operations:\n balance += operation\n if balance < 0:\n return True\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n >>> mean_absolute_deviation([])\n 0.0\n >>> mean_absolute_deviation([5.0])\n 0.0\n >>> mean_absolute_deviation([1.0, 1.0, 1.0])\n 0.0\n >>> mean_absolute_deviation([-1.0, 0.0, 1.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list\n\n n = len(numbers)\n mean = sum(numbers) / n # Calculate the mean\n mad = sum(abs(x - mean) for x in numbers) / n # Calculate the Mean Absolute Deviation\n\n return mad", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n \"\"\"Insert a number 'delimiter' between every two consecutive elements of input list `numbers`.\n \n Args:\n numbers (List[int]): A list of integers.\n delimiter (int): An integer to insert between the elements of the list.\n \n Returns:\n List[int]: A new list with the delimiter inserted between elements.\n \n Examples:\n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n for i in range(len(numbers)):\n result.append(numbers[i])\n if i < len(numbers) - 1: # Avoid adding delimiter after the last element\n result.append(delimiter)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring.\n \n Args:\n strings (List[str]): A list of strings to filter.\n substring (str): The substring to search for in each string.\n \n Returns:\n List[str]: A list of strings that contain the specified substring.\n \n Examples:\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n >>> filter_by_substring(['hello', 'world', 'test'], 'z')\n []\n >>> filter_by_substring(['case', 'sensitive', 'substring'], 'sub')\n ['substring']\n >>> filter_by_substring(['a', 'b', 'c'], 'a')\n ['a']\n >>> filter_by_substring(['', 'non-empty', ''], 'non')\n ['non-empty']\n >>> filter_by_substring(['abc', 'def', 'ghi'], '')\n ['abc', 'def', 'ghi']\n \"\"\"\n return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n def max_depth(group: str) -> int:\n \"\"\" Helper function to calculate the maximum depth of nested parentheses in a single group. \"\"\"\n current_depth = 0\n max_depth = 0\n \n for char in group:\n if char == '(':\n current_depth += 1\n max_depth = max(max_depth, current_depth)\n elif char == ')':\n current_depth -= 1\n if current_depth < 0: # More closing than opening parentheses\n return -1 # Invalid group\n return max_depth if current_depth == 0 else -1 # Valid group must end with depth 0\n\n results = []\n groups = paren_string.split()\n \n for group in groups:\n depth = max_depth(group)\n if depth == -1:\n results.append(0) # If the group is invalid, we can return 0 or handle it as needed\n else:\n results.append(depth)\n \n return results", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \n >>> rolling_max([])\n []\n \n >>> rolling_max([-1, -2, -3, -4])\n [-1, -1, -1, -1]\n \n >>> rolling_max([5])\n [5]\n \n >>> rolling_max([1, 1, 1, 1])\n [1, 1, 1, 1]\n \n >>> rolling_max([3, 1, 4, 1, 5, 9, 2, 6, 5])\n [3, 3, 4, 4, 5, 9, 9, 9, 9]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = []\n current_max = numbers[0]\n \n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n \n return rolling_max_list", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n \n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n >>> sum_product([-1, -2, -3])\n (-6, -6)\n >>> sum_product([0, 1, 2])\n (3, 0)\n >>> sum_product([5])\n (5, 5)\n >>> sum_product([1, 0, 2])\n (3, 0)\n \"\"\"\n if not numbers:\n return (0, 1)\n \n total_sum = sum(numbers)\n total_product = 1\n for number in numbers:\n total_product *= number\n \n return (total_sum, total_product)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n \n >>> make_palindrome('')\n ''\n >>> make_palindrome('cat')\n 'catac'\n >>> make_palindrome('cata')\n 'catac'\n >>> make_palindrome('race')\n 'racecar'\n >>> make_palindrome('a')\n 'a'\n >>> make_palindrome('ab')\n 'aba'\n \"\"\"\n if not string:\n return string # Return empty string if input is empty\n\n # Find the longest palindromic suffix\n for i in range(len(string)):\n if is_palindrome(string[i:]):\n # If the suffix is a palindrome, we need to append the reverse of the prefix\n prefix = string[:i]\n return string + prefix[::-1]\n\n # If no palindromic suffix is found, the entire string is non-palindromic\n return string + string[::-1] # This case should not occur due to the loop", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n \"\"\" \n Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n \n >>> string_xor('010', '110')\n '100'\n >>> string_xor('111', '000')\n '111'\n >>> string_xor('000', '000')\n '000'\n >>> string_xor('101010', '010101')\n '111111'\n >>> string_xor('1', '0')\n '1'\n >>> string_xor('0', '1')\n '1'\n >>> string_xor('', '')\n ''\n >>> string_xor('1', '')\n '1'\n >>> string_xor('', '1')\n '1'\n \"\"\"\n \n # Ensure both strings are of the same length by padding the shorter one with leading zeros\n max_length = max(len(a), len(b))\n a = a.zfill(max_length)\n b = b.zfill(max_length)\n \n # Perform XOR operation\n result = []\n for bit_a, bit_b in zip(a, b):\n result.append('1' if bit_a != bit_b else '0')\n \n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n \n >>> longest([])\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n >>> longest(['abc', 'ab', 'a'])\n 'abc'\n >>> longest(['', 'a', 'ab'])\n 'ab'\n >>> longest(['longest', 'longer', 'long'])\n 'longest'\n >>> longest(['same', 'size', 'test'])\n 'same'\n \"\"\"\n if not strings:\n return None\n \n longest_string = strings[0]\n \n for string in strings[1:]:\n if len(string) > len(longest_string):\n longest_string = string\n \n return longest_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return the greatest common divisor of two integers a and b.\n \n The function uses the Euclidean algorithm to compute the GCD.\n \n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n >>> greatest_common_divisor(0, 5)\n 5\n >>> greatest_common_divisor(5, 0)\n 5\n >>> greatest_common_divisor(0, 0)\n 0\n >>> greatest_common_divisor(-25, 15)\n 5\n >>> greatest_common_divisor(25, -15)\n 5\n >>> greatest_common_divisor(-25, -15)\n 5\n \"\"\"\n if a == 0 and b == 0:\n return 0 # GCD is undefined for (0, 0)\n \n a, b = abs(a), abs(b) # Work with absolute values\n while b:\n a, b = b, a % b\n return a", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string.\n \n Args:\n string (str): The input string from which to generate prefixes.\n \n Returns:\n List[str]: A list of all prefixes of the input string.\n \n Examples:\n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n >>> all_prefixes('')\n []\n >>> all_prefixes('a')\n ['a']\n >>> all_prefixes('hello')\n ['h', 'he', 'hel', 'hell', 'hello']\n \"\"\"\n # Initialize an empty list to store prefixes\n prefixes = []\n \n # Iterate through the string and collect prefixes\n for i in range(1, len(string) + 1):\n prefixes.append(string[:i])\n \n return prefixes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" \n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n >>> count_distinct_characters('')\n 0\n >>> count_distinct_characters('aA')\n 1\n >>> count_distinct_characters('123abcABC!@#')\n 9\n >>> count_distinct_characters(' ')\n 0\n >>> count_distinct_characters('!@#$%^&*()')\n 10\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set()\n \n # Iterate through each character in the string\n for char in lower_string:\n # Add only non-space characters to the set\n if char != ' ':\n distinct_characters.add(char)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Jerry jERRY JeRRRY"]], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n \n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n >>> string_sequence(-1)\n ''\n >>> string_sequence(1)\n '0 1'\n >>> string_sequence(10)\n '0 1 2 3 4 5 6 7 8 9 10'\n \"\"\"\n if n < 0:\n return ''\n \n return ' '.join(str(i) for i in range(n + 1))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string representing musical notes in a special ASCII format.\n Your task is to parse this string and return list of integers corresponding to how many beats does each\n note last.\n\n Here is a legend:\n 'o' - whole note, lasts four beats\n 'o|' - half note, lasts two beats\n '.|' - quarter note, lasts one beat\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n # Initialize an empty list to store the beats\n beats = []\n \n # Split the input string by spaces to get individual notes\n notes = music_string.split()\n \n # Define a mapping of note representations to their corresponding beats\n note_to_beats = {\n 'o': 4, # whole note\n 'o|': 2, # half note\n '.|': 1 # quarter note\n }\n \n # Iterate through each note and append the corresponding beats to the list\n for note in notes:\n if note in note_to_beats:\n beats.append(note_to_beats[note])\n else:\n # If an unknown note is encountered, raise an error\n raise ValueError(f\"Unknown note representation: '{note}'\")\n \n return beats", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n \n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n >>> how_many_times('abcabcabc', 'abc')\n 3\n >>> how_many_times('abababab', 'aba')\n 4\n >>> how_many_times('hello', 'lo')\n 1\n >>> how_many_times('hello', 'hello')\n 1\n >>> how_many_times('hello', 'world')\n 0\n >>> how_many_times('aaaaaa', 'aa')\n 5\n >>> how_many_times('abc', '')\n 0\n >>> how_many_times('', '')\n 1\n \"\"\"\n if not substring:\n return 0 if string else 1 # If substring is empty, return 0 if string is not empty, else return 1.\n \n count = 0\n start = 0\n \n while True:\n start = string.find(substring, start) # Find the next occurrence of substring\n if start == -1: # No more occurrences found\n break\n count += 1\n start += 1 # Move one character forward to allow for overlapping matches\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n >>> find_closest_elements([1.0, 1.0, 1.0, 1.0])\n (1.0, 1.0)\n >>> find_closest_elements([-1.0, -2.0, -3.0, -1.5])\n (-1.5, -1.0)\n >>> find_closest_elements([0.0, 0.1, 0.2, 0.3])\n (0.0, 0.1)\n \"\"\"\n \n # Sort the numbers to make it easier to find the closest pair\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest elements\n for i in range(len(sorted_numbers) - 1):\n # Calculate the difference between consecutive elements\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n \n # If this difference is smaller than the minimum found so far, update\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n \"\"\" \n Input is a space-delimited string of numerals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest.\n \n >>> sort_numbers('three one five')\n 'one three five'\n >>> sort_numbers('nine eight seven six five four three two one zero')\n 'zero one two three four five six seven eight nine'\n >>> sort_numbers('zero')\n 'zero'\n >>> sort_numbers('')\n ''\n >>> sort_numbers('five five four four')\n 'four four five five'\n \"\"\"\n \n # Mapping of words to their corresponding numeric values\n word_to_number = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n \n # Reverse mapping for sorting back to words\n number_to_word = {v: k for k, v in word_to_number.items()}\n \n # Split the input string into words\n words = numbers.split()\n \n # Convert words to their corresponding numeric values\n numeric_values = [word_to_number[word] for word in words]\n \n # Sort the numeric values\n numeric_values.sort()\n \n # Convert sorted numeric values back to words\n sorted_words = [number_to_word[num] for num in numeric_values]\n \n # Join the sorted words into a single string\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1.\n \n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n \n >>> rescale_to_unit([10.0, 20.0, 30.0])\n [0.0, 0.5, 1.0]\n \n >>> rescale_to_unit([5.0, 5.0, 5.0])\n [0.0, 0.0, 0.0]\n \n >>> rescale_to_unit([-1.0, 0.0, 1.0])\n [0.0, 0.5, 1.0]\n \n >>> rescale_to_unit([1.0, 1.0, 2.0, 2.0])\n [0.0, 0.0, 1.0, 1.0]\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The input list must contain at least two elements.\")\n \n min_val = min(numbers)\n max_val = max(numbers)\n \n if min_val == max_val:\n # All numbers are the same, return a list of zeros\n return [0.0] * len(numbers)\n \n # Rescale the numbers\n return [(num - min_val) / (max_val - min_val) for num in numbers]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers.\n \n Args:\n values (List[Any]): A list containing any type of Python values.\n \n Returns:\n List[int]: A list containing only the integers from the input list.\n \n Examples:\n >>> filter_integers(['a', 3.14, 5])\n [5]\n >>> filter_integers([1, 2, 3, 'abc', {}, []])\n [1, 2, 3]\n >>> filter_integers([None, True, False, 0, 1, 2])\n [0, 1, 2]\n >>> filter_integers([])\n []\n >>> filter_integers([1.0, 2.0, 3.0])\n []\n >>> filter_integers(['1', '2', 1, 2])\n [1, 2]\n \"\"\"\n return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n \"\"\" Return length of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n >>> strlen('a')\n 1\n >>> strlen('Hello, World!')\n 13\n >>> strlen(' ') # String with spaces\n 3\n >>> strlen('\ud83d\ude0a') # String with a Unicode character\n 2\n >>> strlen('abc\\n') # String with a newline character\n 4\n >>> strlen('abc\\t') # String with a tab character\n 4\n >>> strlen('') # Edge case: empty string\n 0\n \"\"\"\n return len(string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n \n Args:\n n (int): The number to find the largest divisor for.\n \n Returns:\n int: The largest divisor of n that is smaller than n.\n \n Raises:\n ValueError: If n is less than or equal to 1, as there are no divisors in that case.\n \n Examples:\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(10)\n 5\n >>> largest_divisor(1)\n Traceback (most recent call last):\n ...\n ValueError: No divisors for numbers less than or equal to 1.\n >>> largest_divisor(2)\n 1\n \"\"\"\n if n <= 1:\n raise ValueError(\"No divisors for numbers less than or equal to 1.\")\n \n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n \n return 1 # This line is technically unreachable due to the initial check.", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([1, 1, 1, 1])\n []\n >>> remove_duplicates([1, 2, 3])\n [1, 2, 3]\n >>> remove_duplicates([])\n []\n >>> remove_duplicates([1, 2, 3, 4, 5, 1, 2])\n [3, 4, 5]\n >>> remove_duplicates([5, 5, 5, 6, 7, 8, 6])\n [7, 8]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for number in numbers:\n if number in count:\n count[number] += 1\n else:\n count[number] = 1\n \n # Create a new list with only the numbers that occur once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n Input number should be equal to the product of all factors.\n \n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n >>> factorize(1)\n []\n >>> factorize(0)\n Traceback (most recent call last):\n ...\n ValueError: Input must be a positive integer.\n >>> factorize(-10)\n Traceback (most recent call last):\n ...\n ValueError: Input must be a positive integer.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n factors = []\n # Check for number of 2s that divide n\n while n % 2 == 0:\n factors.append(2)\n n //= 2\n \n # n must be odd at this point so a skip of 2 (i.e., i = i + 2) can be used\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, append i and divide n\n while n % i == 0:\n factors.append(i)\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n factors.append(n)\n \n return factors", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string.\n \n Args:\n strings (List[str]): A list of strings to concatenate.\n \n Returns:\n str: A single concatenated string.\n \n Examples:\n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n >>> concatenate(['Hello', ' ', 'World', '!'])\n 'Hello World!'\n >>> concatenate(['', 'empty', 'string'])\n 'emptystring'\n >>> concatenate(['a' * 1000] * 1000) # Large input\n 'a' * 1000000\n \"\"\"\n # Using join to concatenate the list of strings efficiently\n return ''.join(strings)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n \n Args:\n string (str): The input string to flip the case of its characters.\n \n Returns:\n str: A new string with the case of each character flipped.\n \n Examples:\n >>> flip_case('Hello')\n 'hELLO'\n >>> flip_case('world')\n 'WORLD'\n >>> flip_case('Python 3.8')\n 'pYTHON 3.8'\n >>> flip_case('')\n ''\n >>> flip_case('12345')\n '12345'\n >>> flip_case('!@#$%^&*()')\n '!@#$%^&*()'\n \"\"\"\n return ''.join(char.swapcase() for char in string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n \n Args:\n strings (List[str]): A list of strings to filter.\n prefix (str): The prefix to filter the strings by.\n \n Returns:\n List[str]: A list of strings that start with the given prefix.\n \n Examples:\n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n >>> filter_by_prefix(['apple', 'banana', 'apricot', 'grape'], 'ap')\n ['apple', 'apricot']\n >>> filter_by_prefix(['hello', 'world'], 'h')\n ['hello']\n >>> filter_by_prefix(['hello', 'world'], 'z')\n []\n >>> filter_by_prefix(['', 'test', ''], '')\n ['', 'test', '']\n >>> filter_by_prefix(['abc', 'def', 'ghi'], 'abcdef')\n []\n \"\"\"\n return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n \n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n >>> get_positive([]) # Edge case: empty list\n []\n >>> get_positive([-1, -2, -3]) # Edge case: all negative numbers\n []\n >>> get_positive([0]) # Edge case: single zero\n []\n >>> get_positive([1, 0, -1]) # Mixed numbers with zero\n [1]\n >>> get_positive([10, 20, 30, 0, -10, -20]) # Mixed with positives and negatives\n [10, 20, 30]\n \"\"\"\n return [x for x in l if x > 0]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float) -> float:\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list, x: float) -> float:\n \"\"\"\n Evaluates the derivative of the polynomial with coefficients xs at point x.\n \"\"\"\n return sum(i * coeff * math.pow(x, i - 1) for i, coeff in enumerate(xs) if i > 0)\ndef find_zero(xs: list, initial_guess: float = 0.0, tolerance: float = 1e-7, max_iterations: int = 1000) -> float:\n \"\"\"\n Find x such that poly(x) = 0 using the Newton-Raphson method.\n xs are coefficients of a polynomial.\n find_zero returns only one zero point, even if there are many.\n Moreover, find_zero only takes list xs having an even number of coefficients\n and the largest non-zero coefficient as it guarantees a solution.\n \n >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n -0.5\n >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n 1.0\n \"\"\"\n if len(xs) % 2 != 0:\n raise ValueError(\"The number of coefficients must be even.\")\n \n x = initial_guess\n for _ in range(max_iterations):\n f_x = poly(xs, x)\n f_prime_x = derivative(xs, x)\n \n if abs(f_x) < tolerance:\n return x\n \n if f_prime_x == 0:\n raise ValueError(\"Derivative is zero. No solution found.\")\n \n x -= f_x / f_prime_x\n \n raise ValueError(\"Maximum iterations reached. No solution found.\")", "base_status": "fail", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n A prime number is a natural number greater than 1 that cannot be formed by multiplying two smaller natural numbers.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n >>> is_prime(0)\n False\n >>> is_prime(-5)\n False\n >>> is_prime(2)\n True\n >>> is_prime(3)\n True\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return False # eliminate multiples of 2 and 3\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6 # check for factors of the form 6k \u00b1 1\n\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n Args:\n l (list): A list of elements which may contain duplicates.\n \n Returns:\n list: A sorted list of unique elements.\n \n Examples:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \n >>> unique([])\n []\n \n >>> unique([1, 1, 1, 1])\n [1]\n \n >>> unique([1, 2, 3, 4, 5])\n [1, 2, 3, 4, 5]\n \n >>> unique([-1, -2, -3, -2, -1])\n [-3, -2, -1]\n \n >>> unique(['apple', 'banana', 'apple', 'orange'])\n ['apple', 'banana', 'orange']\n \"\"\"\n # Use a set to remove duplicates, then sort the result\n return sorted(set(l))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n >>> sort_third([])\n []\n >>> sort_third([10, 20, 30, 40, 50, 60, 70, 80])\n [30, 20, 10, 40, 50, 60, 70, 80]\n >>> sort_third([1, 2, 3, 4, 5, 6, 7, 8, 9])\n [3, 2, 1, 4, 5, 6, 9, 8, 7]\n \"\"\"\n # Extract values at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(divisible_by_three)\n \n # Create a new list to hold the result\n result = l.copy()\n \n # Replace values at indices divisible by 3 with sorted values\n for index, value in zip(range(len(result)), sorted_values):\n if index % 3 == 0:\n result[index] = value\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]]], "plus_fail_tests": []}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n \"\"\"Return maximum element in the list.\n \n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n >>> max_element([]) # Edge case: empty list\n Traceback (most recent call last):\n ...\n ValueError: The list is empty.\n >>> max_element(['a', 1, 2]) # Edge case: non-numeric elements\n Traceback (most recent call last):\n ...\n TypeError: All elements in the list must be numbers.\n \"\"\"\n \n if not l:\n raise ValueError(\"The list is empty.\")\n \n max_value = l[0]\n \n for item in l:\n if not isinstance(item, (int, float)):\n raise TypeError(\"All elements in the list must be numbers.\")\n if item > max_value:\n max_value = item\n \n return max_value", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n >>> sort_even([10, 20, 30, 40, 50])\n [10, 20, 30, 40, 50]\n >>> sort_even([1])\n [1]\n >>> sort_even([])\n []\n >>> sort_even([2, 1])\n [2, 1]\n >>> sort_even([4, 3, 2, 1, 0])\n [0, 3, 2, 1, 4]\n \"\"\"\n # Extract even indexed elements\n even_indices = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indexed elements\n even_indices_sorted = sorted(even_indices)\n \n # Create a new list to hold the result\n result = []\n \n # Fill the result list\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0: # Even index\n result.append(even_indices_sorted[even_index])\n even_index += 1\n else: # Odd index\n result.append(l[i])\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with encode_cyclic function. Returns decoded string.\n \"\"\"\n # Split string into groups of length 3\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # Reverse the cycling of elements in each group\n groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_fib(n: int) -> int:\n \"\"\"\n prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n \n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n if n < 1:\n raise ValueError(\"n must be a positive integer.\")\n \n count = 0\n for fib in fibonacci_generator():\n if is_prime(fib):\n count += 1\n if count == n:\n return fib", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1]], "plus_fail_tests": []}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n \"\"\"\n triples_sum_to_zero takes a list of integers as an input.\n It returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n >>> triples_sum_to_zero([])\n False\n >>> triples_sum_to_zero([0, 0, 0])\n False\n >>> triples_sum_to_zero([-1, 0, 1])\n True\n \"\"\"\n n = len(l)\n if n < 3:\n return False\n\n # Sort the list to use the two-pointer technique\n l.sort()\n\n for i in range(n - 2):\n # Avoid duplicates for the first element\n if i > 0 and l[i] == l[i - 1]:\n continue\n \n left, right = i + 1, n - 1\n while left < right:\n current_sum = l[i] + l[left] + l[right]\n if current_sum == 0:\n return True\n elif current_sum < 0:\n left += 1\n else:\n right -= 1\n\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n \n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n >>> incr_list([]) # Edge case: empty list\n []\n >>> incr_list([-1, -2, -3]) # Edge case: negative numbers\n [0, -1, -2]\n >>> incr_list([0]) # Edge case: single element\n [1]\n >>> incr_list([1.5, 2.5, 3.5]) # Edge case: float numbers\n [2.5, 3.5, 4.5]\n \"\"\"\n return [x + 1 for x in l]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n \"\"\"\n Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move at the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.\n\n Parameters:\n n (int): The number of cars in each direction.\n\n Returns:\n int: The number of collisions.\n \"\"\"\n # Each car moving left to right will collide with each car moving right to left.\n # Therefore, the total number of collisions is simply n * n.\n return n * n", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion.\n base numbers are less than 10.\n \n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n >>> change_base(0, 2)\n '0'\n >>> change_base(0, 3)\n '0'\n >>> change_base(1, 2)\n '1'\n >>> change_base(1, 3)\n '1'\n >>> change_base(9, 2)\n '1001'\n >>> change_base(9, 3)\n '100'\n >>> change_base(9, 4)\n '21'\n >>> change_base(9, 5)\n '14'\n >>> change_base(9, 6)\n '13'\n >>> change_base(9, 7)\n '12'\n >>> change_base(9, 8)\n '11'\n >>> change_base(9, 9)\n '10'\n \"\"\"\n \n if base < 2 or base >= 10:\n raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n \n if x == 0:\n return '0'\n \n result = []\n negative = x < 0\n x = abs(x)\n \n while x > 0:\n remainder = x % base\n result.append(str(remainder))\n x //= base\n \n if negative:\n result.append('-')\n \n # The result is built in reverse order\n return ''.join(reversed(result))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n \n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n >>> pairs_sum_to_zero([])\n False\n >>> pairs_sum_to_zero([-1, 1])\n True\n >>> pairs_sum_to_zero([-1, 1, 2])\n True\n >>> pairs_sum_to_zero([0, 0])\n False\n \"\"\"\n seen = set()\n for number in l:\n if -number in seen:\n return True\n seen.add(number)\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fib4(0) -> 0\n fib4(1) -> 0\n fib4(2) -> 2\n fib4(3) -> 0\n fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n \n This function computes the n-th element of the fib4 number sequence efficiently without using recursion.\n \n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n \n # Handle base cases\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 2\n elif n == 3:\n return 0\n \n # Initialize a list to store computed values\n fib_values = [0] * (n + 1)\n fib_values[0] = 0\n fib_values[1] = 0\n fib_values[2] = 2\n fib_values[3] = 0\n \n # Compute the fib4 values iteratively\n for i in range(4, n + 1):\n fib_values[i] = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n \n return fib_values[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n \"\"\"Given length of a side and height, return the area for a triangle.\n \n The area of a triangle can be calculated using the formula:\n Area = (base * height) / 2\n \n Parameters:\n a (float): The length of the base of the triangle.\n h (float): The height of the triangle.\n \n Returns:\n float: The area of the triangle.\n \n Raises:\n ValueError: If the base or height is not a positive number.\n \n >>> triangle_area(5, 3)\n 7.5\n >>> triangle_area(0, 3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(5, -3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(-5, 3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(5, 0)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n \"\"\"\n \n if a <= 0 or h <= 0:\n raise ValueError(\"Base and height must be positive numbers.\")\n \n return (a * h) / 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n \"\"\"Return median of elements in the list l.\n \n The median is the middle value when the list is sorted. If the list has an even number of elements,\n the median is the average of the two middle values.\n \n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n >>> median([1, 2])\n 1.5\n >>> median([1])\n 1\n >>> median([])\n Traceback (most recent call last):\n ...\n ValueError: Cannot compute median of an empty list.\n \"\"\"\n if not l:\n raise ValueError(\"Cannot compute median of an empty list.\")\n \n sorted_list = sorted(l)\n n = len(sorted_list)\n mid = n // 2\n \n if n % 2 == 0: # Even number of elements\n return (sorted_list[mid - 1] + sorted_list[mid]) / 2\n else: # Odd number of elements\n return sorted_list[mid]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n \"\"\"\n Checks if given string is a palindrome.\n \n A palindrome is a string that reads the same forward and backward.\n \n Args:\n text (str): The string to check.\n \n Returns:\n bool: True if the string is a palindrome, False otherwise.\n \n Examples:\n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n >>> is_palindrome('A man a plan a canal Panama')\n True\n >>> is_palindrome('No lemon, no melon')\n True\n >>> is_palindrome('12321')\n True\n >>> is_palindrome('12345')\n False\n >>> is_palindrome('Was it a car or a cat I saw?')\n True\n \"\"\"\n # Normalize the string: remove non-alphanumeric characters and convert to lowercase\n normalized_text = ''.join(char.lower() for char in text if char.isalnum())\n \n # Check if the normalized string is equal to its reverse\n return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n Args:\n n (int): The exponent.\n p (int): The modulus.\n \n Returns:\n int: The result of 2^n modulo p.\n \n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n if p <= 0:\n raise ValueError(\"Modulus p must be a positive integer.\")\n \n # Using modular exponentiation to avoid large numbers\n result = 1\n base = 2 % p # 2 modulo p\n \n while n > 0:\n if n % 2 == 1: # If n is odd\n result = (result * base) % p\n base = (base * base) % p # Square the base\n n //= 2 # Divide n by 2\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with encode_shift function.\n Returns the decoded string by shifting every alphabetic character back by 5.\n Non-alphabetic characters are not changed.\n \"\"\"\n decoded = []\n for ch in s:\n if 'a' <= ch <= 'z':\n # Reverse shift for lowercase letters\n decoded.append(chr(((ord(ch) - ord('a') - 5) % 26) + ord('a')))\n elif 'A' <= ch <= 'Z':\n # Reverse shift for uppercase letters\n decoded.append(chr(((ord(ch) - ord('A') - 5) % 26) + ord('A')))\n else:\n # Non-alphabetic characters remain unchanged\n decoded.append(ch)\n return ''.join(decoded)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n Vowels are defined as 'a', 'e', 'i', 'o', 'u' in both lowercase and uppercase.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n \"\"\"Return True if all numbers in the list l are below threshold t.\n \n Args:\n l (list): A list of numbers to check.\n t (int): The threshold value.\n \n Returns:\n bool: True if all numbers in l are below t, False otherwise.\n \n Examples:\n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n >>> below_threshold([], 10)\n True\n >>> below_threshold([5], 5)\n False\n >>> below_threshold([-1, -2, -3], 0)\n True\n >>> below_threshold([0, 1, 2], 1)\n False\n \"\"\"\n # Check if all elements in the list are below the threshold\n return all(x < t for x in l)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two words have the same characters if they contain the same unique characters,\n regardless of the frequency of those characters.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets to get unique characters\n unique_chars_s0 = set(s0)\n unique_chars_s1 = set(s1)\n \n # Compare the sets of unique characters\n return unique_chars_s0 == unique_chars_s1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n \"\"\"Add two numbers x and y.\n\n This function takes two integers and returns their sum. It handles\n positive numbers, negative numbers, and zero.\n\n Args:\n x (int): The first integer to add.\n y (int): The second integer to add.\n\n Returns:\n int: The sum of x and y.\n\n Examples:\n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n >>> add(-1, 1)\n 0\n >>> add(-5, -7)\n -12\n >>> add(0, 0)\n 0\n >>> add(1000000, 2000000)\n 3000000\n >>> add(-1000000, 1000000)\n 0\n \"\"\"\n return x + y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n \"\"\"Return n-th Fibonacci number.\n \n The Fibonacci sequence is defined as follows:\n fib(0) = 0\n fib(1) = 1\n fib(n) = fib(n-1) + fib(n-2) for n > 1\n\n Args:\n n (int): The index of the Fibonacci number to return.\n\n Returns:\n int: The n-th Fibonacci number.\n\n Raises:\n ValueError: If n is negative.\n\n Examples:\n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n >>> fib(0)\n 0\n >>> fib(2)\n 1\n >>> fib(3)\n 2\n >>> fib(4)\n 3\n >>> fib(5)\n 5\n >>> fib(6)\n 8\n >>> fib(7)\n 13\n \"\"\"\n if n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n if n == 0:\n return 0\n elif n == 1:\n return 1\n \n a, b = 0, 1\n for _ in range(2, n + 1):\n a, b = b, a + b\n return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"<\" and \">\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"<\")\n False\n >>> correct_bracketing(\"<>\")\n True\n >>> correct_bracketing(\"<<><>>\")\n True\n >>> correct_bracketing(\"><<>\")\n False\n >>> correct_bracketing(\"<<>>\")\n True\n >>> correct_bracketing(\"><\")\n False\n >>> correct_bracketing(\"<<<<<>>>>>>\")\n True\n >>> correct_bracketing(\"<<><><><>\")\n True\n >>> correct_bracketing(\"><><><><<\")\n False\n >>> correct_bracketing(\"\")\n True\n \"\"\"\n balance = 0\n \n for char in brackets:\n if char == '<':\n balance += 1\n elif char == '>':\n balance -= 1\n \n # If balance goes negative, it means there's a closing bracket without a matching opening bracket\n if balance < 0:\n return False\n \n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n \"\"\"Return True if list elements are monotonically increasing or decreasing.\n \n A list is considered monotonically increasing if each element is greater than or equal to the previous one.\n A list is considered monotonically decreasing if each element is less than or equal to the previous one.\n \n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n >>> monotonic([1, 1, 1])\n True\n >>> monotonic([])\n True\n >>> monotonic([5])\n True\n >>> monotonic([1, 2, 2, 3])\n True\n >>> monotonic([3, 2, 2, 1])\n True\n >>> monotonic([1, 2, 3, 2])\n False\n >>> monotonic([2, 3, 2, 4])\n False\n \"\"\"\n if len(l) <= 1:\n return True # An empty list or a single element list is considered monotonic\n\n increasing = decreasing = True\n\n for i in range(1, len(l)):\n if l[i] > l[i - 1]:\n decreasing = False\n elif l[i] < l[i - 1]:\n increasing = False\n\n return increasing or decreasing", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n >>> common([], [])\n []\n >>> common([1, 2, 3], [])\n []\n >>> common([], [1, 2, 3])\n []\n >>> common([1, 2, 2, 3], [2, 2, 3, 4])\n [2, 3]\n >>> common([1, 2, 3], [4, 5, 6])\n []\n >>> common([1, 1, 1], [1, 1, 1])\n [1]\n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n >>> largest_prime_factor(600851475143)\n 6857\n >>> largest_prime_factor(49)\n 7\n >>> largest_prime_factor(100)\n 5\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n # Keep dividing n by factor until it is no longer divisible\n while n > 1:\n if n % factor == 0:\n n //= factor # Divide n by the factor\n else:\n factor += 1 # Move to the next potential factor\n return factor # The last factor is the largest prime factor", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n \n Args:\n n (int): The upper limit of the summation (inclusive).\n \n Returns:\n int: The sum of all integers from 1 to n.\n \n Examples:\n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n >>> sum_to_n(0)\n 0\n >>> sum_to_n(-5)\n 0\n \"\"\"\n if n < 1:\n return 0\n return n * (n + 1) // 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n \"\"\" \n Calculate the derivative of a polynomial represented by its coefficients.\n \n The polynomial is represented as:\n xs[0] + xs[1] * x + xs[2] * x^2 + ...\n \n The derivative is calculated as:\n d/dx (a_n * x^n) = n * a_n * x^(n-1)\n \n Args:\n xs (list): A list of coefficients where the index represents the power of x.\n \n Returns:\n list: A list of coefficients representing the derivative of the polynomial.\n \n Examples:\n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n >>> derivative([0])\n []\n >>> derivative([0, 0, 0])\n []\n >>> derivative([5])\n []\n >>> derivative([1, 0, 0, 0])\n [0, 0, 0]\n \"\"\"\n # The derivative of a constant (the first coefficient) is 0, so we start from index 1\n return [i * coeff for i, coeff in enumerate(xs[1:], start=1)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n Check if every opening bracket has a corresponding closing bracket.\n \n Args:\n brackets (str): A string consisting of '(' and ')'.\n \n Returns:\n bool: True if the brackets are correctly balanced, False otherwise.\n \n Examples:\n >>> correct_bracketing(\"(\")\n False\n >>> correct_bracketing(\"()\")\n True\n >>> correct_bracketing(\"(()())\")\n True\n >>> correct_bracketing(\")(()\")\n False\n >>> correct_bracketing(\")(\")\n False\n >>> correct_bracketing(\"\") # Edge case: empty string\n True\n >>> correct_bracketing(\"((()))\") # Nested brackets\n True\n >>> correct_bracketing(\"(()\") # Unmatched opening bracket\n False\n >>> correct_bracketing(\"())\") # Unmatched closing bracket\n False\n >>> correct_bracketing(\"()()()\") # Multiple pairs\n True\n >>> correct_bracketing(\"(()())()\") # Mixed pairs\n True\n \"\"\"\n balance = 0\n \n for char in brackets:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n \n # If balance goes negative, there are unmatched closing brackets\n if balance < 0:\n return False\n \n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set('aeiouAEIOU')\n count = 0\n \n # Iterate through the string\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n # Check if 'y' is at the end of the string\n elif s[i].lower() == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n \n Args:\n n (int): The index of the FibFib number to compute.\n \n Returns:\n int: The n-th FibFib number.\n \n Examples:\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n # Memoization dictionary to store previously computed values\n memo = {0: 0, 1: 0, 2: 1}\n\n def helper(n: int) -> int:\n if n in memo:\n return memo[n]\n # Compute the n-th FibFib number using the recursive definition\n memo[n] = helper(n - 1) + helper(n - 2) + helper(n - 3)\n return memo[n]\n\n return helper(n)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n \n >>> circular_shift(12, 1)\n '21'\n >>> circular_shift(12, 2)\n '12'\n >>> circular_shift(12345, 1)\n '51234'\n >>> circular_shift(12345, 5)\n '54321'\n >>> circular_shift(12345, 6)\n '54321'\n >>> circular_shift(0, 1)\n '0'\n >>> circular_shift(7, 0)\n '7'\n >>> circular_shift(100, 1)\n '010'\n >>> circular_shift(100, 2)\n '001'\n >>> circular_shift(-123, 1)\n '-312'\n >>> circular_shift(-123, 3)\n '-321'\n \"\"\"\n # Convert the integer to a string and handle negative sign\n is_negative = x < 0\n str_x = str(abs(x))\n num_digits = len(str_x)\n\n # If shift is greater than the number of digits, reverse the digits\n if shift >= num_digits:\n return str_x[::-1] if not is_negative else '-' + str_x[::-1]\n\n # Perform the circular shift\n shift = shift % num_digits # Normalize shift to avoid unnecessary full rotations\n shifted_str = str_x[-shift:] + str_x[:-shift]\n\n return shifted_str if not is_negative else '-' + shifted_str", "base_status": "fail", "plus_status": null, "base_fail_tests": [[12, 2]], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n \"\"\"Task\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n \"\"\"\n # Initialize the sum of ASCII values of uppercase characters\n total = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is uppercase\n if char.isupper():\n # Add the ASCII value of the uppercase character to the total\n total += ord(char)\n \n return total", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n \"\"\"\n Calculate the number of mango fruits in a basket given the number of apples and oranges.\n\n Parameters:\n s (str): A string representing the number of apples and oranges in the format \"X apples and Y oranges\".\n n (int): An integer representing the total number of fruits in the basket.\n\n Returns:\n int: The number of mango fruits in the basket.\n \"\"\"\n # Extract the number of apples and oranges from the string\n try:\n # Split the string to find the numbers\n parts = s.split()\n apples = int(parts[0]) # First part is the number of apples\n oranges = int(parts[2]) # Third part is the number of oranges\n except (IndexError, ValueError) as e:\n raise ValueError(\"Input string format is incorrect. Expected format: 'X apples and Y oranges'\") from e\n\n # Calculate the number of mangoes\n mangoes = n - apples - oranges\n\n # Ensure the result is non-negative\n if mangoes < 0:\n raise ValueError(\"The total number of fruits cannot be less than the sum of apples and oranges.\")\n\n return mangoes", "base_status": "fail", "plus_status": null, "base_fail_tests": [["5 apples and 6 oranges", 19]], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n \"\"\"\n Given an array representing a branch of a tree that has non-negative integer nodes,\n this function plucks one of the nodes and returns it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n The plucked node should be returned in a list, [ smallest_value, its index ].\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1] \n\n Example 3:\n Input: []\n Output: []\n \n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n \"\"\"\n smallest_even_value = float('inf')\n smallest_index = -1\n\n for index, value in enumerate(arr):\n if value % 2 == 0: # Check if the value is even\n if value < smallest_even_value: # Found a smaller even value\n smallest_even_value = value\n smallest_index = index\n elif value == smallest_even_value and index < smallest_index:\n smallest_index = index # Update index if same value found earlier\n\n if smallest_index == -1: # No even value found\n return []\n \n return [smallest_even_value, smallest_index]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n '''\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequency greater than or equal to the value of the integer itself. \n The frequency of an integer is the number of times it appears in the list.\n If no such a value exists, return -1.\n \n Examples:\n search([4, 1, 2, 2, 3, 1]) == 2\n search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n search([5, 5, 4, 4, 4]) == -1\n '''\n from collections import Counter\n\n # Count the frequency of each integer in the list\n frequency = Counter(lst)\n\n # Initialize the result variable\n result = -1\n\n # Iterate through the frequency dictionary\n for num in frequency:\n # Check if the frequency is greater than or equal to the number itself\n if frequency[num] >= num:\n # Update the result if this number is greater than the current result\n result = max(result, num)\n\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n '''\n Given list of integers, return list in strange order.\n Strange sorting, is when you start with the minimum value,\n then maximum of the remaining integers, then minimum and so on.\n\n Examples:\n strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n strange_sort_list([]) == []\n '''\n if not lst:\n return []\n\n # Sort the list to easily access min and max values\n sorted_lst = sorted(lst)\n result = []\n \n while sorted_lst:\n # Append the minimum value\n result.append(sorted_lst.pop(0)) # Remove and return the first element (minimum)\n if sorted_lst: # Check if there are still elements left\n result.append(sorted_lst.pop(-1)) # Remove and return the last element (maximum)\n\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n '''\n Write a function that returns True if the object q will fly, and False otherwise.\n The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n\n Example:\n will_it_fly([1, 2], 5) \u279e False \n # 1+2 is less than the maximum possible weight, but it's unbalanced.\n\n will_it_fly([3, 2, 3], 1) \u279e False\n # it's balanced, but 3+2+3 is more than the maximum possible weight.\n\n will_it_fly([3, 2, 3], 9) \u279e True\n # 3+2+3 is less than the maximum possible weight, and it's balanced.\n\n will_it_fly([3], 5) \u279e True\n # 3 is less than the maximum possible weight, and it's balanced.\n '''\n\n # Check if the list is a palindrome\n is_balanced = (q == q[::-1])\n \n # Calculate the sum of the elements in the list\n total_weight = sum(q)\n \n # Determine if the object will fly\n return is_balanced and (total_weight <= w)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return the area of\n the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n Otherwise return -1.\n \n Three sides make a valid triangle when the sum of any two sides is greater \n than the third side.\n \n Example:\n triangle_area(3, 4, 5) == 6.00\n triangle_area(1, 2, 10) == -1\n '''\n \n # Check for valid triangle using the triangle inequality theorem\n if a <= 0 or b <= 0 or c <= 0:\n return -1\n if a + b <= c or a + c <= b or b + c <= a:\n return -1\n \n # Calculate the semi-perimeter\n s = (a + b + c) / 2\n \n # Calculate the area using Heron's formula\n area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n \n # Return the area rounded to 2 decimal points\n return round(area, 2)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n \"\"\"\n Given an array arr of integers, find the minimum number of elements that\n need to be changed to make the array palindromic. A palindromic array is an array that\n is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n For example:\n smallest_change([1,2,3,5,4,7,9,6]) == 4\n smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n smallest_change([1, 2, 3, 2, 1]) == 0\n \"\"\"\n n = len(arr)\n changes = 0\n \n # Compare elements from the start and end towards the center\n for i in range(n // 2):\n if arr[i] != arr[n - 1 - i]:\n changes += 1\n \n return changes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n \n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total character counts and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n else:\n return lst2", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef generate_primes(limit):\n \"\"\"Generate a list of prime numbers up to a given limit.\"\"\"\n return [num for num in range(2, limit) if is_prime(num)]\ndef is_multiply_prime(a):\n \"\"\"Return True if the given number is the multiplication of 3 prime numbers, False otherwise.\"\"\"\n if a < 1 or a >= 100:\n return False # a must be less than 100 and greater than 0\n\n primes = generate_primes(100)\n \n # Check all combinations of three primes\n for i in range(len(primes)):\n for j in range(i, len(primes)):\n for k in range(j, len(primes)):\n product = primes[i] * primes[j] * primes[k]\n if product == a:\n return True\n if product > a:\n break # No need to check further if product exceeds a\n\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n \"\"\"Returns True if x is a simple power of n, otherwise False.\n \n A number x is a simple power of n if there exists an integer k such that n**k = x.\n \n Args:\n x (int): The number to check.\n n (int): The base number.\n \n Returns:\n bool: True if x is a simple power of n, False otherwise.\n \"\"\"\n # Edge case: if n is 0 or 1\n if n == 0:\n return x == 0 # 0**0 is undefined, but we can consider it as False\n if n == 1:\n return x == 1 # 1**k is always 1 for any k\n \n # Edge case: if x is less than 1\n if x < 1:\n return False # No positive power of n can yield a number less than 1\n \n # Check if x is a power of n\n power = 1\n while True:\n result = n ** power\n if result == x:\n return True\n elif result > x:\n return False\n power += 1", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1, 12]], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n \"\"\"Counts the number of prime hexadecimal digits in the given hexadecimal string.\"\"\"\n \n # Define the set of prime hexadecimal digits\n prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n \n # Initialize a counter for prime digits\n prime_count = 0\n \n # Iterate through each character in the input string\n for char in num:\n # Check if the character is in the set of prime hexadecimal digits\n if char in prime_hex_digits:\n prime_count += 1\n \n return prime_count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this integer is a cube of some integer number.\n Note: you may assume the input is always valid.\n \n Examples:\n iscube(1) ==> True\n iscube(2) ==> False\n iscube(-1) ==> True\n iscube(64) ==> True\n iscube(0) ==> True\n iscube(180) ==> False\n '''\n # Calculate the cube root of the absolute value of a\n cube_root = round(abs(a) ** (1/3))\n \n # Check if the cube of the rounded cube root equals the absolute value of a\n return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n \"\"\"Convert a decimal number to binary format with specific formatting.\n\n Args:\n decimal (int): A non-negative integer to convert to binary.\n\n Returns:\n str: A string representing the binary format of the decimal number,\n enclosed with 'db' at the beginning and end.\n\n Examples:\n decimal_to_binary(15) # returns \"db1111db\"\n decimal_to_binary(32) # returns \"db100000db\"\n \"\"\"\n if not isinstance(decimal, int) or decimal < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n\n # Convert decimal to binary using built-in function and remove the '0b' prefix\n binary_representation = bin(decimal)[2:]\n\n # Format the output with 'db' at the beginning and end\n formatted_output = f\"db{binary_representation}db\"\n \n return formatted_output", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n \"\"\"Check if the string s is happy.\n \n A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n \n Args:\n s (str): The input string to check.\n \n Returns:\n bool: True if the string is happy, False otherwise.\n \"\"\"\n # Check if the length of the string is at least 3\n if len(s) < 3:\n return False\n \n # Iterate through the string and check every 3 consecutive characters\n for i in range(len(s) - 2):\n # Get the current substring of 3 characters\n substring = s[i:i+3]\n # Check if all characters in the substring are distinct\n if len(set(substring)) != 3:\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n \"\"\"Convert a list of GPAs to letter grades based on a specified grading scale.\"\"\"\n letter_grades = []\n \n for gpa in grades:\n if gpa == 4.0:\n letter_grades.append('A+')\n elif gpa > 3.7:\n letter_grades.append('A')\n elif gpa > 3.3:\n letter_grades.append('A-')\n elif gpa > 3.0:\n letter_grades.append('B+')\n elif gpa > 2.7:\n letter_grades.append('B')\n elif gpa > 2.3:\n letter_grades.append('B-')\n elif gpa > 2.0:\n letter_grades.append('C+')\n elif gpa > 1.7:\n letter_grades.append('C')\n elif gpa > 1.3:\n letter_grades.append('C-')\n elif gpa > 1.0:\n letter_grades.append('D+')\n elif gpa > 0.7:\n letter_grades.append('D')\n elif gpa > 0.0:\n letter_grades.append('D-')\n elif gpa == 0.0:\n letter_grades.append('E')\n else:\n letter_grades.append('Invalid GPA') # Handle any negative GPAs or invalid inputs\n\n return letter_grades", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n \"\"\"Helper function to determine if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_length(string):\n \"\"\"Check if the length of the string is a prime number.\"\"\"\n length = len(string)\n return is_prime(length)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits will be 1 the output should be \"1\".\n For N = 150, the sum of digits will be 6 the output should be \"110\".\n For N = 147, the sum of digits will be 12 the output should be \"1100\".\n \n Variables:\n @N integer\n Constraints: 0 \u2264 N \u2264 10000.\n Output:\n a string of binary number\n \"\"\"\n \n # Check if N is within the valid range\n if not (0 <= N <= 10000):\n raise ValueError(\"N must be between 0 and 10000 inclusive.\")\n \n # Calculate the sum of the digits of N\n digit_sum = sum(int(digit) for digit in str(N))\n \n # Convert the sum to binary and remove the '0b' prefix\n binary_sum = bin(digit_sum)[2:]\n \n return binary_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n \"\"\"\n Given a positive integer n, return the count of the numbers of n-digit\n positive integers that start or end with 1.\n \n Parameters:\n n (int): The number of digits in the positive integers to consider.\n \n Returns:\n int: The count of n-digit positive integers that start or end with 1.\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer.\")\n \n if n == 1:\n # For 1-digit numbers, only the number '1' qualifies\n return 1\n \n # Total n-digit numbers\n total_n_digit_numbers = 9 * (10 ** (n - 1))\n \n # Count of n-digit numbers that start with 1\n start_with_1 = 10 ** (n - 1) # 1xxxx... (n-1 digits can be anything from 0-9)\n \n # Count of n-digit numbers that end with 1\n end_with_1 = 9 * (10 ** (n - 2)) # xxxxx1 (first digit can be 1-9, rest can be 0-9)\n \n # Count of n-digit numbers that start and end with 1\n start_and_end_with_1 = 10 ** (n - 2) # 1xxxx1 (n-2 digits can be anything from 0-9)\n \n # Using the inclusion-exclusion principle\n count = start_with_1 + end_with_1 - start_and_end_with_1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words while preserving spaces\n words = s.split(' ')\n \n # Function to sort characters in a word\n def sort_word(word):\n return ''.join(sorted(word))\n \n # Process each word and sort its characters\n sorted_words = [sort_word(word) for word in words]\n \n # Join the sorted words back into a single string with spaces\n result = ' '.join(sorted_words)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n add([1, 2, 3, 4, 5]) ==> 0\n add([0, 2, 4, 6, 8]) ==> 2 + 4 = 6\n add([1, 3, 5, 7]) ==> 0\n add([10, 11, 12, 13, 14]) ==> 12\n \"\"\"\n # Initialize the sum to 0\n total = 0\n \n # Iterate over the list using index and value\n for index in range(1, len(lst), 2): # Start from index 1 and step by 2 (odd indices)\n if lst[index] % 2 == 0: # Check if the element is even\n total += lst[index] # Add to total if it's even\n \n return total", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n # Iterate through each row and its index\n for row_index, row in enumerate(lst):\n # Iterate through each column in the row and its index\n for col_index, value in enumerate(row):\n # If the value matches x, store the coordinates\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort coordinates by row (ascending) and then by column (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n or sort it in descending order if the sum( first index value, last index value) is even.\n\n Note:\n * don't change the given array.\n\n Examples:\n * sort_array([]) => []\n * sort_array([5]) => [5]\n * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n \"\"\"\n # Create a copy of the original array to avoid modifying it\n sorted_array = array.copy()\n \n # Check if the array is empty or has only one element\n if len(sorted_array) <= 1:\n return sorted_array\n \n # Calculate the sum of the first and last elements\n first_element = sorted_array[0]\n last_element = sorted_array[-1]\n total_sum = first_element + last_element\n \n # Sort the array based on the sum being odd or even\n if total_sum % 2 == 0:\n # Even sum: sort in descending order\n sorted_array.sort(reverse=True)\n else:\n # Odd sum: sort in ascending order\n sorted_array.sort()\n \n return sorted_array", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating each letter down the alphabet by 4 places.\"\"\"\n encrypted_string = []\n \n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Determine the base ASCII value depending on case\n base = ord('a') if char.islower() else ord('A')\n # Rotate the character by 4 places\n new_char = chr((ord(char) - base + 4) % 26 + base)\n encrypted_string.append(new_char)\n else:\n # If it's not a letter, we can choose to ignore it or keep it as is\n encrypted_string.append(char) # Keeping non-alphabetic characters as is\n\n return ''.join(encrypted_string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Sort the unique elements\n sorted_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_elements[1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n '''\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n \n Examples\n any_int(5, 2, 7) \u279e True\n any_int(3, 2, 2) \u279e False\n any_int(3, -2, 1) \u279e True\n any_int(3.6, -2.2, 2) \u279e False\n '''\n \n # Check if all inputs are integers\n if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n # Check if any number is equal to the sum of the other two\n return x == y + z or y == x + z or z == x + y\n else:\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n \n For example:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n >>> is_bored(\"I am bored! Are you bored? I want to go home.\")\n 2\n >>> is_bored(\"I. I. I.\")\n 3\n >>> is_bored(\"What is this? I don't know! I guess I will find out.\")\n 2\n >>> is_bored(\"\")\n 0\n >>> is_bored(\"I\")\n 1\n >>> is_bored(\"Hello! I. How are you? I am fine.\")\n 2\n \"\"\"\n # Split the string into sentences based on the delimiters\n import re\n sentences = re.split(r'[.!?]', S)\n \n # Count the number of sentences that start with \"I\"\n boredom_count = 0\n for sentence in sentences:\n # Strip leading whitespace and check if it starts with \"I\"\n if sentence.strip().startswith(\"I\"):\n boredom_count += 1\n \n return boredom_count", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n \"\"\"\n Write a function that takes a message, and encodes in such a \n way that it swaps case of all letters, replaces all vowels in \n the message with the letter that appears 2 places ahead of that \n vowel in the English alphabet. \n Assume only letters. \n \n Examples:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n # Define a mapping for vowels to their replacements\n vowel_replacement = {\n 'a': 'c', 'A': 'C',\n 'e': 'g', 'E': 'G',\n 'i': 'k', 'I': 'K',\n 'o': 'q', 'O': 'Q',\n 'u': 'w', 'U': 'W'\n }\n \n encoded_message = []\n \n for char in message:\n if char.isalpha(): # Check if the character is a letter\n # Swap case\n if char in vowel_replacement:\n # Replace vowel and swap case\n encoded_message.append(vowel_replacement[char])\n else:\n # Just swap case for consonants\n encoded_message.append(char.swapcase())\n else:\n # If it's not a letter, we can choose to keep it as is\n encoded_message.append(char)\n \n return ''.join(encoded_message)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["TEST"]], "plus_fail_tests": []}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef sum_of_digits(n):\n \"\"\"Return the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n largest_prime = None\n \n for number in lst:\n if is_prime(number):\n if largest_prime is None or number > largest_prime:\n largest_prime = number\n \n if largest_prime is not None:\n return sum_of_digits(largest_prime)\n else:\n return 0 # Return 0 if no prime number is found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_up_to(n):\n \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n primes = []\n for i in range(2, n):\n if is_prime(i):\n primes.append(i)\n return primes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in lower \n case or all keys are strings in upper case, else return False.\n The function should return False if the given dictionary is empty.\n \n Examples:\n check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n \"\"\"\n \n # Check if the dictionary is empty\n if not input_dict:\n return False\n \n # Initialize flags for lower and upper case\n all_lower = True\n all_upper = True\n \n # Iterate through the keys of the dictionary\n for key in input_dict.keys():\n # Check if the key is a string\n if not isinstance(key, str):\n return False\n \n # Check if the key is lower case\n if key.islower():\n all_upper = False\n # Check if the key is upper case\n elif key.isupper():\n all_lower = False\n else:\n # If the key is neither lower nor upper case\n return False\n \n # Return True if all keys are either lower case or upper case\n return all_lower or all_upper", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n count_upper('aBCdEf') returns 1\n count_upper('abcdefg') returns 0\n count_upper('dBBE') returns 0\n \"\"\"\n # Define the set of uppercase vowels\n uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n \n # Initialize a counter for uppercase vowels at even indices\n count = 0\n \n # Iterate over the string, checking only even indices\n for i in range(0, len(s), 2): # Step by 2 to get even indices\n if s[i] in uppercase_vowels:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.\n \"\"\"\n # Get the unit digit of the first number\n unit_digit_a = abs(a) % 10\n # Get the unit digit of the second number\n unit_digit_b = abs(b) % 10\n # Return the product of the unit digits\n return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n >>> closest_integer(\"14.5\")\n 15\n >>> closest_integer(\"-14.5\")\n -15\n >>> closest_integer(\"0.5\")\n 1\n >>> closest_integer(\"-0.5\")\n -1\n >>> closest_integer(\"3.0\")\n 3\n >>> closest_integer(\"-3.0\")\n -3\n >>> closest_integer(\"2.499999\")\n 2\n >>> closest_integer(\"-2.499999\")\n -2\n '''\n\n # Convert the string input to a float\n num = float(value)\n\n # Calculate the floor and ceiling of the number\n lower_int = int(num // 1) # This is the largest integer less than or equal to num\n upper_int = lower_int + 1 # This is the smallest integer greater than num\n\n # Check the distance to the lower and upper integers\n distance_to_lower = abs(num - lower_int)\n distance_to_upper = abs(num - upper_int)\n\n # Determine which integer to return\n if distance_to_lower < distance_to_upper:\n return lower_int\n elif distance_to_upper < distance_to_lower:\n return upper_int\n else:\n # If equidistant, round away from zero\n if num > 0:\n return upper_int\n else:\n return lower_int", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n \"\"\"\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n >>> make_a_pile(4)\n [4, 6, 8, 10]\n >>> make_a_pile(1)\n [1]\n >>> make_a_pile(0)\n []\n \"\"\"\n if n <= 0:\n return [] # Return an empty list for non-positive integers\n\n stones = []\n current_stones = n\n\n for i in range(n):\n stones.append(current_stones)\n if current_stones % 2 == 0: # current_stones is even\n current_stones += 2 # next even number\n else: # current_stones is odd\n current_stones += 2 # next odd number\n\n return stones", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n \"\"\"\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n \"\"\"\n # Replace commas with spaces and split the string by whitespace\n words = s.replace(',', ' ').split()\n \n # Return the list of words\n return words", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n \"\"\"This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If \n there's no such number, then the function should return -1.\n\n For example:\n choose_num(12, 15) = 14\n choose_num(13, 12) = -1\n \"\"\"\n # Ensure x is less than or equal to y\n if x > y:\n return -1\n\n # Start from the largest number in the range and work downwards\n for num in range(y, x - 1, -1):\n if num % 2 == 0: # Check if the number is even\n return num\n\n # If no even number is found, return -1\n return -1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n \"\"\"Given a list of positive integers x, return a sorted list of all \n elements that haven't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n def has_even_digit(n):\n \"\"\"Check if the number has any even digit.\"\"\"\n for digit in str(n):\n if int(digit) % 2 == 0:\n return True\n return False\n\n # Filter the list to include only numbers without even digits\n filtered = [num for num in x if not has_even_digit(num)]\n \n # Sort the resulting list\n return sorted(filtered)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n \"\"\"Compute the average of integers from n to m, round it to the nearest integer,\n and convert it to binary. Return -1 if n is greater than m.\n \n Args:\n n (int): The starting integer (inclusive).\n m (int): The ending integer (inclusive).\n \n Returns:\n str or int: The binary representation of the rounded average if n <= m, otherwise -1.\n \"\"\"\n if n > m:\n return -1\n \n # Calculate the sum of integers from n to m\n total_sum = sum(range(n, m + 1))\n count = m - n + 1 # Total numbers from n to m\n \n # Calculate the average and round it\n average = total_sum / count\n rounded_average = round(average)\n \n # Convert the rounded average to binary\n return bin(rounded_average)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def f(n):\n \"\"\" \n Implement the function f that takes n as a parameter,\n and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even\n or the sum of numbers from 1 to i otherwise.\n i starts from 1.\n The factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).\n \"\"\"\n if n <= 0:\n return [] # Return an empty list for non-positive n\n\n result = []\n \n for i in range(1, n + 1):\n if i % 2 == 0: # i is even\n factorial = 1\n for j in range(1, i + 1):\n factorial *= j\n result.append(factorial)\n else: # i is odd\n sum_of_numbers = sum(range(1, i + 1))\n result.append(sum_of_numbers)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n reverse the resulting array, and then replace each digit by its corresponding name from\n \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n For example:\n arr = [2, 1, 1, 4, 5, 8, 2, 3] \n -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n \n If the array is empty, return an empty array:\n arr = []\n return []\n \n If the array has any strange number ignore it:\n arr = [1, -1 , 55] \n -> sort arr -> [-1, 1, 55]\n -> reverse arr -> [55, 1, -1]\n return = ['One']\n \"\"\"\n \n # Mapping of digits to their corresponding names\n digit_to_name = {\n 1: \"One\",\n 2: \"Two\",\n 3: \"Three\",\n 4: \"Four\",\n 5: \"Five\",\n 6: \"Six\",\n 7: \"Seven\",\n 8: \"Eight\",\n 9: \"Nine\"\n }\n \n # Filter the array to include only integers between 1 and 9\n filtered_arr = [num for num in arr if 1 <= num <= 9]\n \n # Sort the filtered array\n filtered_arr.sort()\n \n # Reverse the sorted array\n filtered_arr.reverse()\n \n # Convert the digits to their corresponding names\n result = [digit_to_name[num] for num in filtered_arr]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n \"\"\"\n Write a function count_nums which takes an array of integers and returns\n the number of elements which has a sum of digits > 0.\n If a number is negative, then its first signed digit will be negative:\n e.g. -123 has signed digits -1, 2, and 3.\n \n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n def sum_of_digits(n):\n \"\"\"Helper function to calculate the sum of digits of an integer n.\"\"\"\n # Convert the number to string and iterate over each character\n # If the number is negative, we need to consider the first digit as negative\n str_n = str(n)\n digit_sum = 0\n \n for i, char in enumerate(str_n):\n if char.isdigit():\n digit_sum += int(char)\n elif i == 0 and char == '-':\n digit_sum -= 1 # First signed digit is negative\n \n return digit_sum\n\n count = 0\n for number in arr:\n if sum_of_digits(number) > 0:\n count += 1\n \n return count", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[-1, -2, 0]]], "plus_fail_tests": []}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n \"\"\"\n Given a positive integer n, return a tuple that has the number of even and odd\n integer palindromes that fall within the range(1, n), inclusive.\n\n Example 1:\n Input: 3\n Output: (1, 2)\n Explanation:\n Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n Example 2:\n Input: 12\n Output: (4, 6)\n Explanation:\n Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n Note:\n 1. 1 <= n <= 10^3\n 2. returned tuple has the number of even and odd integer palindromes respectively.\n \"\"\"\n \n def is_palindrome(num):\n \"\"\"Check if a number is a palindrome.\"\"\"\n return str(num) == str(num)[::-1]\n\n even_count = 0\n odd_count = 0\n\n for i in range(1, n + 1):\n if is_palindrome(i):\n if i % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n \"\"\"Determines whether it is possible to perform an exchange of elements\n between two lists to make lst1 a list of only even numbers.\n \n Args:\n lst1 (list): The first list of numbers.\n lst2 (list): The second list of numbers.\n \n Returns:\n str: \"YES\" if lst1 can be made all even, otherwise \"NO\".\n \"\"\"\n # Check if all elements in lst1 are already even\n if all(x % 2 == 0 for x in lst1):\n return \"YES\"\n \n # Count the number of odd elements in lst1\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n \n # Check if there are enough even elements in lst2 to replace the odd ones in lst1\n even_count_lst2 = sum(1 for x in lst2 if x % 2 == 0)\n \n # If there are enough even numbers in lst2 to replace all odd numbers in lst1\n if even_count_lst2 >= odd_count_lst1:\n return \"YES\"\n \n return \"NO\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return True else return False.\n If the given array is empty then return True.\n\n Note: The given list is guaranteed to have unique elements.\n\n For Example:\n \n move_one_ball([3, 4, 5, 1, 2])==>True\n Explanation: By performing 2 right shift operations, non-decreasing order can\n be achieved for the given array.\n move_one_ball([3, 5, 4, 1, 2])==>False\n Explanation: It is not possible to get non-decreasing order for the given\n array by performing any number of right shift operations.\n \"\"\"\n \n if not arr: # Check for empty array\n return True\n\n n = len(arr)\n count = 0\n\n # Count the number of times the array is not in non-decreasing order\n for i in range(n):\n if arr[i] > arr[(i + 1) % n]: # Compare current with next (circular)\n count += 1\n\n # If there are more than one \"breaks\" in the order, we cannot sort it\n return count <= 1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n \"\"\"\n \n if not test: # Handle the empty string case\n return {}\n \n # Split the input string into a list of letters\n letters = test.split()\n \n # Create a dictionary to count occurrences of each letter\n count_dict = {}\n for letter in letters:\n if letter in count_dict:\n count_dict[letter] += 1\n else:\n count_dict[letter] = 1\n \n # Find the maximum occurrence count\n max_count = max(count_dict.values())\n \n # Create a result dictionary for letters with the maximum count\n result = {letter: count for letter, count in count_dict.items() if count == max_count}\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n \"\"\"\n Task\n We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and True/False for the check.\n \n Example\n For s = \"abcde\", c = \"ae\", the result should be ('bcd', False)\n For s = \"abcdef\", c = \"b\", the result should be ('acdef', False)\n For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc', True)\n \"\"\"\n \n # Create a set of characters to delete for faster lookup\n chars_to_delete = set(c)\n \n # Build the result string by filtering out characters in chars_to_delete\n result = ''.join(char for char in s if char not in chars_to_delete)\n \n # Check if the result string is a palindrome\n is_palindrome = result == result[::-1]\n \n return (result, is_palindrome)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3', \"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n \n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in s if char in '13579')\n \n # Create the output string with the count of odd digits\n output_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n \n # Append the result to the list\n result.append(output_string)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n Example\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n \"\"\"\n if not nums:\n raise ValueError(\"The input array must not be empty.\")\n \n # Initialize variables to track the minimum sum and the current sum\n min_sum = float('inf')\n current_sum = 0\n \n for num in nums:\n current_sum += num\n min_sum = min(min_sum, current_sum)\n \n # If current_sum becomes positive, reset it to 0\n if current_sum > 0:\n current_sum = 0\n \n return min_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n \"\"\"\n Calculate the number of times buckets need to be lowered to empty the wells.\n\n Parameters:\n grid (list of list of int): A rectangular grid representing wells.\n capacity (int): The capacity of each bucket.\n\n Returns:\n int: The total number of times buckets need to be lowered.\n \"\"\"\n total_water = 0\n \n # Count the total amount of water in the grid\n for row in grid:\n total_water += sum(row)\n \n # Calculate the number of times buckets need to be lowered\n if total_water == 0:\n return 0 # No water to extract\n \n # Each bucket can carry 'capacity' units of water\n # We need to lower the buckets enough times to extract all the water\n return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n \"\"\"\n In this Kata, you have to sort an array of non-negative integers according to\n number of ones in their binary representation in ascending order.\n For similar number of ones, sort based on decimal value.\n\n It must be implemented like this:\n >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n >>> sort_array([1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]\n \"\"\"\n # Filter out negative numbers since the problem states non-negative integers\n arr = [x for x in arr if x >= 0]\n \n # Sort the array based on the number of 1s in binary representation and then by value\n return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[-2, -3, -4, -5, -6]]], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n two consonants from the right side of the word (case sensitive).\n \n Vowels in the beginning and ending don't count. Return empty string if you didn't\n find any vowel that meets the above condition. \n\n You may assume that the given string contains English letters only.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n n = len(word)\n\n # Check for edge cases\n if n < 3: # Need at least 3 characters to have consonants on both sides of a vowel\n return \"\"\n\n # Iterate from the end of the word to the beginning\n for i in range(n - 2, 0, -1): # Start from the second last character\n if word[i] in vowels: # Check if the current character is a vowel\n # Check if the characters before and after are consonants\n if word[i - 1].isalpha() and word[i + 1].isalpha() and \\\n word[i - 1] not in vowels and word[i + 1] not in vowels:\n return word[i] # Return the vowel if it is between two consonants\n\n return \"\" # Return empty string if no such vowel is found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n \"\"\"Given a string s and a natural number n, returns a list of all words from string s \n that contain exactly n consonants, in the order they appear in the string s.\n \n Args:\n s (str): The input string containing words.\n n (int): The number of consonants to filter words by.\n \n Returns:\n list: A list of words containing exactly n consonants.\n \"\"\"\n \n if not s: # Check if the string is empty\n return []\n \n # Define a set of vowels for easy checking\n vowels = set(\"aeiouAEIOU\")\n \n def count_consonants(word):\n \"\"\"Helper function to count consonants in a word.\"\"\"\n return sum(1 for char in word if char.isalpha() and char not in vowels)\n \n # Split the string into words\n words = s.split()\n \n # Filter words based on the number of consonants\n result = [word for word in words if count_consonants(word) == n]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0: # More closing than opening\n return False\n return balance == 0 # Must be balanced at the end\n\n s1, s2 = lst[0], lst[1]\n\n # Check both concatenation orders\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n \n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Get the top k elements\n top_k = sorted_arr[:k]\n \n # Return the top k elements sorted in ascending order\n return sorted(top_k)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n An even position is defined as an index that is even (0, 2, 4, ...).\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index in range(len(lst)):\n # Check if the index is even\n if index % 2 == 0:\n # Check if the element at this index is odd\n if lst[index] % 2 != 0:\n total_sum += lst[index]\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n \"\"\"\n Given a non-empty array of integers arr and an integer k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example:\n\n Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n Output: 24 # sum of 21 + 3\n\n Constraints:\n 1. 1 <= len(arr) <= 100\n 2. 1 <= k <= len(arr)\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate through the first k elements of the array\n for i in range(k):\n # Check if the current element has at most two digits\n if -100 < arr[i] < 100:\n total_sum += arr[i]\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n as follows: start with any positive integer n. Then each term is obtained from the \n previous term as follows: if the previous term is even, the next term is one half of \n the previous term. If the previous term is odd, the next term is 3 times the previous\n term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n Note: \n 1. Collatz(1) is [1].\n 2. returned list sorted in increasing order.\n\n For example:\n get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n collatz_sequence = []\n current = n\n \n while current != 1:\n collatz_sequence.append(current)\n if current % 2 == 0:\n current //= 2\n else:\n current = 3 * current + 1\n \n collatz_sequence.append(1) # Append the last term which is 1\n \n # Filter out odd numbers and sort the result\n odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n \n return odd_numbers", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n \n The date is valid if all of the following rules are satisfied:\n 1. The date string is not empty.\n 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n The number of days is not less than 1 or higher than 29 for the month 2.\n 3. The months should not be less than 1 or higher than 12.\n 4. The date should be in the format: mm-dd-yyyy\n \n Args:\n date (str): The date string to validate.\n \n Returns:\n bool: True if the date is valid, False otherwise.\n \"\"\"\n \n # Check if the date string is empty\n if not date:\n return False\n \n # Check if the date format is correct\n if len(date) != 10 or date[2] != '-' or date[5] != '-':\n return False\n \n # Split the date into components\n try:\n month, day, year = map(int, date.split('-'))\n except ValueError:\n return False\n \n # Check month range\n if month < 1 or month > 12:\n return False\n \n # Check day range based on month\n if month in [1, 3, 5, 7, 8, 10, 12]: # 31 days\n if day < 1 or day > 31:\n return False\n elif month in [4, 6, 9, 11]: # 30 days\n if day < 1 or day > 30:\n return False\n elif month == 2: # February\n if day < 1 or day > 29:\n return False\n \n # If all checks passed, the date is valid\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n '''\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return False. Assume no negative numbers and only integers.\n\n Examples\n is_sorted([5]) \u279e True\n is_sorted([1, 2, 3, 4, 5]) \u279e True\n is_sorted([1, 3, 2, 4, 5]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n '''\n \n if not lst: # Check for empty list\n return True # An empty list is considered sorted\n\n seen = set() # To track unique elements\n previous = None # To track the previous element\n\n for num in lst:\n if num in seen: # Check for duplicates\n return False\n seen.add(num)\n\n if previous is not None and num < previous: # Check for sorting\n return False\n \n previous = num # Update previous to current number\n\n return True # If all checks passed, the list is sorted", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n '''\n Given a string of words, return a list of words split on whitespace, \n if no whitespaces exists in the text you should split on commas ',' \n if no commas exists you should return the number of lower-case letters \n with odd order in the alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n \n Examples:\n split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"abcdef\") \u279e 3 \n '''\n \n # Check for whitespace\n if ' ' in txt:\n return txt.split()\n \n # Check for commas\n elif ',' in txt:\n return txt.split(',')\n \n # If no whitespace or commas, count lower-case letters with odd order\n else:\n odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n return odd_count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef intersection(interval1, interval2):\n \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n start1, end1 = interval1\n start2, end2 = interval2\n \n # Find the intersection\n start_intersection = max(start1, start2)\n end_intersection = min(end1, end2)\n \n # Check if there is an intersection\n if start_intersection > end_intersection:\n return \"NO\"\n \n # Calculate the length of the intersection\n length_of_intersection = end_intersection - start_intersection\n \n # Check if the length is a prime number\n if is_prime(length_of_intersection):\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n if not arr: # Check for empty array\n return None\n\n product_of_signs = 1\n sum_of_magnitudes = 0\n\n for num in arr:\n if num > 0:\n sum_of_magnitudes += num\n elif num < 0:\n sum_of_magnitudes += -num\n product_of_signs *= -1 # Flip the sign for negative numbers\n else: # num == 0\n return 0 # If there's a zero, the product of signs is zero\n\n return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n \"\"\"Calculate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n if n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n # Initialize the list to hold the Tribonacci numbers\n tribonacci_sequence = []\n \n # Calculate each term based on the rules provided\n for i in range(n + 1):\n if i == 0:\n tribonacci_sequence.append(1) # tri(0) = 1\n elif i == 1:\n tribonacci_sequence.append(3) # tri(1) = 3\n elif i % 2 == 0: # i is even\n tribonacci_sequence.append(1 + i / 2)\n else: # i is odd\n # tri(i) = tri(i - 1) + tri(i - 2) + tri(i + 1)\n # We need to ensure we calculate tri(i + 1) correctly\n if i + 1 <= n:\n tribonacci_sequence.append(\n tribonacci_sequence[i - 1] + tribonacci_sequence[i - 2] + tribonacci_sequence[i + 1]\n )\n else:\n tribonacci_sequence.append(\n tribonacci_sequence[i - 1] + tribonacci_sequence[i - 2] + 3 # tri(i + 1) = 3 for i = 1\n )\n \n return tribonacci_sequence", "base_status": "fail", "plus_status": null, "base_fail_tests": [[4]], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n \"\"\"Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n \n Args:\n n (int): A positive integer.\n\n Returns:\n int: The product of the odd digits or 0 if all digits are even.\n \n Examples:\n >>> digits(1)\n 1\n >>> digits(4)\n 0\n >>> digits(235)\n 15\n >>> digits(2468)\n 0\n >>> digits(13579)\n 945\n >>> digits(0) # Edge case, should not be called with 0 as per problem statement\n Traceback (most recent call last):\n ...\n ValueError: Input must be a positive integer.\n \"\"\"\n \n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n product = 1\n has_odd_digit = False\n \n while n > 0:\n digit = n % 10\n if digit % 2 != 0: # Check if the digit is odd\n product *= digit\n has_odd_digit = True\n n //= 10 # Remove the last digit\n \n return product if has_odd_digit else 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n '''\n Create a function that takes a string as input which contains only square brackets.\n The function should return True if and only if there is a valid subsequence of brackets \n where at least one bracket in the subsequence is nested.\n\n is_nested('[[]]') \u279e True\n is_nested('[]]]]]]][[[[[]') \u279e False\n is_nested('[][]') \u279e False\n is_nested('[]') \u279e False\n is_nested('[[][]]') \u279e True\n is_nested('[[]][[') \u279e True\n '''\n \n # Initialize a counter for open brackets\n open_count = 0\n # Initialize a flag to check for nesting\n nested = False\n \n for char in string:\n if char == '[':\n open_count += 1\n # If we have seen at least one open bracket before, we can have nesting\n if open_count > 1:\n nested = True\n elif char == ']':\n if open_count > 0:\n open_count -= 1\n else:\n # More closing brackets than opening brackets\n return False\n \n # We need at least one nested bracket and all brackets must be closed\n return nested and open_count == 0", "base_status": "fail", "plus_status": null, "base_fail_tests": [["[[]][["]], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers.\n You need to return the sum of squared numbers in the given list,\n round each element in the list to the upper int (Ceiling) first.\n \n Examples:\n For lst = [1,2,3] the output should be 14\n For lst = [1,4,9] the output should be 98\n For lst = [1,3,5,7] the output should be 84\n For lst = [1.4,4.2,0] the output should be 29\n For lst = [-2.4,1,1] the output should be 6\n \"\"\"\n # Initialize the sum of squares\n total_sum = 0\n \n # Iterate through each number in the list\n for number in lst:\n # Round the number up to the nearest integer\n rounded_number = math.ceil(number)\n # Square the rounded number and add it to the total sum\n total_sum += rounded_number ** 2\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n from collections import deque\n\n N = len(grid)\n directions = [(0, 1), (1, 0), (0, -1), (-1, 0)] # right, down, left, up\n min_path = None\n\n def dfs(x, y, path):\n nonlocal min_path\n if len(path) == k:\n if min_path is None or path < min_path:\n min_path = path[:]\n return\n \n for dx, dy in directions:\n nx, ny = x + dx, y + dy\n if 0 <= nx < N and 0 <= ny < N:\n path.append(grid[nx][ny])\n dfs(nx, ny, path)\n path.pop()\n\n for i in range(N):\n for j in range(N):\n dfs(i, j, [grid[i][j]])\n\n return min_path", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n '''\n Create a function that returns True if the last character\n of a given string is an alphabetical character and is not\n a part of a word, and False otherwise.\n Note: \"word\" is a group of characters separated by space.\n\n Examples:\n check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '''\n \n # Strip any trailing whitespace from the string\n txt = txt.rstrip()\n \n # Check if the string is empty after stripping\n if not txt:\n return False\n \n # Get the last character of the string\n last_char = txt[-1]\n \n # Check if the last character is an alphabetical character\n if last_char.isalpha():\n # Check if the last character is part of a word\n # A character is part of a word if it is preceded by a non-space character\n if len(txt) > 1 and txt[-2] != ' ':\n return False\n return True\n \n return False", "base_status": "fail", "plus_status": null, "base_fail_tests": [["eeeee e "]], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n '''\n Create a function that returns a tuple (a, b), where 'a' is\n the largest of negative integers, and 'b' is the smallest\n of positive integers in a list.\n If there is no negative or positive integers, return them as None.\n\n Examples:\n largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n largest_smallest_integers([]) == (None, None)\n largest_smallest_integers([0]) == (None, None)\n '''\n \n largest_negative = None\n smallest_positive = None\n \n for num in lst:\n if num < 0:\n if largest_negative is None or num > largest_negative:\n largest_negative = num\n elif num > 0:\n if smallest_positive is None or num < smallest_positive:\n smallest_positive = num\n \n return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n \"\"\"Create a function which returns the largest index of an element which\n is not greater than or equal to the element immediately preceding it. If\n no such element exists then return -1. The given array will not contain\n duplicate values.\n\n Examples:\n can_arrange([1,2,4,3,5]) = 3\n can_arrange([1,2,3]) = -1\n \"\"\"\n # Check if the array is empty\n if not arr:\n return -1\n\n # Initialize the largest index to -1\n largest_index = -1\n\n # Iterate through the array starting from the second element\n for i in range(1, len(arr)):\n # Check if the current element is less than the previous element\n if arr[i] < arr[i - 1]:\n largest_index = i # Update the largest index\n\n return largest_index", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def parse_number(value):\n \"\"\"\n Convert a string representation of a number into a float or return the value as is if it's not a string.\n Handles both '.' and ',' as decimal separators.\n \"\"\"\n if isinstance(value, str):\n # Replace ',' with '.' for float conversion\n value = value.replace(',', '.')\n try:\n return float(value)\n except ValueError:\n return None # Return None if conversion fails\n return value\ndef compare_one(a, b):\n \"\"\"\n Compare two values (integers, floats, or strings representing real numbers)\n and return the larger one in its original type. Return None if they are equal.\n \"\"\"\n # Parse both values\n parsed_a = parse_number(a)\n parsed_b = parse_number(b)\n\n # Check if both parsed values are None (invalid strings)\n if parsed_a is None or parsed_b is None:\n return None\n\n # Compare the parsed values\n if parsed_a > parsed_b:\n return a\n elif parsed_b > parsed_a:\n return b\n else:\n return None # They are equal", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n \n Args:\n n (int): The number to evaluate.\n \n Returns:\n bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n \n Example:\n is_equal_to_sum_even(4) == False\n is_equal_to_sum_even(6) == False\n is_equal_to_sum_even(8) == True\n \"\"\"\n \n # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n if n < 8:\n return False\n \n # Check if n is even\n if n % 2 != 0:\n return False\n \n # If n is even and n >= 8, it can be expressed as the sum of 4 positive even numbers\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n \"\"\"\n Given a string text, replace all spaces in it with underscores, \n and if a string has more than 2 consecutive spaces, \n then replace all consecutive spaces with - \n \n fix_spaces(\"Example\") == \"Example\"\n fix_spaces(\"Example 1\") == \"Example_1\"\n fix_spaces(\" Example 2\") == \"_Example_2\"\n fix_spaces(\" Example 3\") == \"_Example-3\"\n \"\"\"\n # Replace multiple spaces with a placeholder\n # This will help us identify sequences of spaces\n placeholder = '##'\n text = text.replace(' ', placeholder) # Replace 3 spaces with a placeholder\n text = text.replace(' ', '_') # Replace 2 spaces with an underscore\n text = text.replace(placeholder, '-') # Replace the placeholder with a dash\n\n # Handle leading and trailing spaces\n text = text.strip() # Remove leading and trailing spaces\n text = text.replace(' ', '_') # Replace remaining single spaces with underscores\n\n return text", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Mudasir Hanif "]], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n \"\"\"Helper function to compute the factorial of a non-negative integer n.\"\"\"\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef special_factorial(n):\n \"\"\"Calculate the Brazilian factorial of n.\"\"\"\n if n < 1:\n raise ValueError(\"Input must be a positive integer greater than 0.\")\n \n result = 1\n for i in range(1, n + 1):\n result *= factorial(i)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n \"\"\"Check if the given file name is valid based on specific criteria.\"\"\"\n \n # Define valid extensions\n valid_extensions = ['txt', 'exe', 'dll']\n \n # Check for exactly one dot\n if file_name.count('.') != 1:\n return 'No'\n \n # Split the file name into name and extension\n name, extension = file_name.rsplit('.', 1)\n \n # Check if the name is empty\n if not name:\n return 'No'\n \n # Check if the name starts with a letter\n if not name[0].isalpha():\n return 'No'\n \n # Check if the extension is valid\n if extension not in valid_extensions:\n return 'No'\n \n # Count digits in the file name\n digit_count = sum(c.isdigit() for c in file_name)\n \n # Check if there are more than three digits\n if digit_count > 3:\n return 'No'\n \n return 'Yes'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n \"\"\"\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n \n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126\n \"\"\"\n total_sum = 0\n \n for index, value in enumerate(lst):\n if index % 3 == 0:\n # Square the value if index is a multiple of 3\n total_sum += value ** 2\n elif index % 4 == 0:\n # Cube the value if index is a multiple of 4 and not a multiple of 3\n total_sum += value ** 3\n else:\n # Add the value unchanged if index is not a multiple of 3 or 4\n total_sum += value\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef words_in_sentence(sentence):\n \"\"\"\n Given a string representing a sentence, return a string that contains the words\n from the original sentence whose lengths are prime numbers.\n \n Parameters:\n sentence (str): The input sentence containing words separated by spaces.\n \n Returns:\n str: A string containing the words with prime lengths, in the original order.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Filter words whose lengths are prime\n prime_length_words = [word for word in words if is_prime(len(word))]\n \n # Join the filtered words back into a string\n return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n \"\"\"Simplifies the expression x * n and checks if the result is a whole number.\n \n Args:\n x (str): A string representation of a fraction in the format /.\n n (str): A string representation of a fraction in the format /.\n \n Returns:\n bool: True if x * n evaluates to a whole number, False otherwise.\n \"\"\"\n # Split the fractions into numerator and denominator\n x_numerator, x_denominator = map(int, x.split('/'))\n n_numerator, n_denominator = map(int, n.split('/'))\n \n # Calculate the product of the fractions\n # x * n = (x_numerator / x_denominator) * (n_numerator / n_denominator)\n # This simplifies to (x_numerator * n_numerator) / (x_denominator * n_denominator)\n \n product_numerator = x_numerator * n_numerator\n product_denominator = x_denominator * n_denominator\n \n # Check if the product is a whole number\n return product_numerator % product_denominator == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n \"\"\"\n Write a function which sorts the given list of integers\n in ascending order according to the sum of their digits.\n Note: if there are several items with similar sum of their digits,\n order them based on their index in original list.\n\n For example:\n >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n >>> order_by_points([]) == []\n \"\"\"\n \n def digit_sum(n):\n \"\"\"Calculate the sum of the digits of an integer n.\"\"\"\n return sum(int(digit) for digit in str(abs(n)))\n\n # Create a list of tuples (digit_sum, index, value)\n indexed_nums = [(digit_sum(num), index, num) for index, num in enumerate(nums)]\n \n # Sort by digit sum first, then by original index\n indexed_nums.sort(key=lambda x: (x[0], x[1]))\n \n # Extract the sorted values\n sorted_nums = [num for _, _, num in indexed_nums]\n \n return sorted_nums", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n \"\"\"Returns the number of elements in the array that are greater than 10 \n and both the first and last digits of the number are odd (1, 3, 5, 7, 9).\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n int: The count of numbers meeting the criteria.\n \"\"\"\n \n def is_odd_digit(digit):\n \"\"\"Check if a digit is odd.\"\"\"\n return digit in {1, 3, 5, 7, 9}\n \n def first_and_last_digits_are_odd(num):\n \"\"\"Check if both the first and last digits of the number are odd.\"\"\"\n num_str = str(abs(num)) # Convert to string and take absolute value\n first_digit = int(num_str[0])\n last_digit = int(num_str[-1])\n return is_odd_digit(first_digit) and is_odd_digit(last_digit)\n \n count = 0\n for num in nums:\n if num > 10 and first_and_last_digits_are_odd(num):\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n \"\"\"\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example :\n Input: n = 5\n Output: 1\n Explanation: \n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n \"\"\"\n # Create the array a based on the given formula\n a = [i * i - i + 1 for i in range(1, n + 1)]\n \n # Count the number of valid triples\n count = 0\n \n # Iterate through all possible triples (i, j, k) with i < j < k\n for i in range(n):\n for j in range(i + 1, n):\n for k in range(j + 1, n):\n if (a[i] + a[j] + a[k]) % 3 == 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closest to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sorted by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct planet names. \n Examples\n bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n '''\n\n # List of planets in order from the Sun\n planets = [\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n ]\n \n # Check if the input planets are valid\n if planet1 not in planets or planet2 not in planets:\n return ()\n \n # Get the indices of the planets\n index1 = planets.index(planet1)\n index2 = planets.index(planet2)\n \n # Determine the range of indices\n start_index = min(index1, index2) + 1\n end_index = max(index1, index2)\n \n # Get the planets in between\n in_between_planets = planets[start_index:end_index]\n \n # Return as a tuple\n return tuple(in_between_planets)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef x_or_y(n, x, y):\n \"\"\"Return x if n is a prime number, otherwise return y.\"\"\"\n if is_prime(n):\n return x\n else:\n return y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length and alphabetically.\n \n Args:\n lst (list of str): A list of strings.\n \n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n \"\"\"\n Compares the actual game scores with the guessed scores and returns an array\n indicating how far off each guess was. If the guess is correct, the value is 0,\n otherwise it is the absolute difference between the guess and the score.\n\n Parameters:\n game (list of int): The actual scores of the matches.\n guess (list of int): The guessed scores of the matches.\n\n Returns:\n list of int: An array of absolute differences or zeros for correct guesses.\n \"\"\"\n # Check if the lengths of game and guess are equal\n if len(game) != len(guess):\n raise ValueError(\"The length of game and guess must be the same.\")\n\n # Calculate the absolute differences\n result = [abs(g - s) for g, s in zip(guess, game)]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n \n double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n double_the_difference([-1, -2, 0]) == 0\n double_the_difference([9, -2]) == 81\n double_the_difference([0]) == 0 \n \n If the input list is empty, return 0.\n '''\n # Initialize the sum of squares\n sum_of_squares = 0\n \n # Iterate through each number in the list\n for num in lst:\n # Check if the number is a positive odd integer\n if isinstance(num, int) and num >= 0 and num % 2 != 0:\n sum_of_squares += num ** 2\n \n return sum_of_squares", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n \"\"\"Check if the second word or any of its rotations is a substring of the first word.\"\"\"\n \n # Edge case: if b is empty, it is always a substring\n if not b:\n return True\n \n # Edge case: if a is empty and b is not, b cannot be a substring\n if not a:\n return False\n \n # Create a string that contains two copies of b\n # This allows us to check for all rotations of b\n b_rotations = b + b\n \n # Check if any rotation of b is a substring of a\n return any(rotation in a for rotation in (b_rotations[i:i+len(b)] for i in range(len(b))))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n \"\"\"Find the strongest extension based on the defined strength criteria.\"\"\"\n \n def calculate_strength(extension):\n \"\"\"Calculate the strength of the extension.\"\"\"\n CAP = sum(1 for char in extension if char.isupper())\n SM = sum(1 for char in extension if char.islower())\n return CAP - SM\n\n strongest_extension = None\n strongest_strength = float('-inf') # Start with the lowest possible strength\n\n for extension in extensions:\n strength = calculate_strength(extension)\n \n # Check if this extension is stronger or if it's the first one\n if strength > strongest_strength:\n strongest_strength = strength\n strongest_extension = extension\n\n # Return the result in the required format\n return f\"{class_name}.{strongest_extension}\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n \n if not (1 <= number <= 1000):\n raise ValueError(\"Input must be between 1 and 1000 inclusive.\")\n\n # Mapping of integers to their corresponding Roman numeral representations\n roman_numerals = [\n (1000, 'm'),\n (900, 'cm'),\n (500, 'd'),\n (400, 'cd'),\n (100, 'c'),\n (90, 'xc'),\n (50, 'l'),\n (40, 'xl'),\n (10, 'x'),\n (9, 'ix'),\n (5, 'v'),\n (4, 'iv'),\n (1, 'i')\n ]\n\n result = []\n \n for value, numeral in roman_numerals:\n while number >= value:\n result.append(numeral)\n number -= value\n\n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n Example:\n even_odd_count(-12) ==> (1, 1)\n even_odd_count(123) ==> (1, 2)\n \"\"\"\n # Convert the number to a string and handle negative sign\n num_str = str(abs(num))\n \n even_count = 0\n odd_count = 0\n \n for digit in num_str:\n if digit.isdigit(): # Ensure we are only counting digits\n if int(digit) % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return True if the three\n sides form a right-angled triangle, False otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or \n 90 degree.\n \n Example:\n right_angle_triangle(3, 4, 5) == True\n right_angle_triangle(1, 2, 3) == False\n '''\n \n # First, we need to check if the sides can form a triangle\n if a <= 0 or b <= 0 or c <= 0:\n return False # Sides must be positive\n \n # Sort the sides to easily identify the longest side\n sides = sorted([a, b, c])\n \n # Check the Pythagorean theorem: a^2 + b^2 = c^2\n return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n \"\"\"Return the word with the maximum number of unique characters.\n If multiple words have the same number of unique characters,\n return the one that comes first in lexicographical order.\n \n Args:\n words (list of str): A list of words to evaluate.\n \n Returns:\n str: The word with the maximum number of unique characters.\n \"\"\"\n max_word = \"\"\n max_unique_count = 0\n\n for word in words:\n # Calculate the number of unique characters in the word\n unique_count = len(set(word))\n \n # Check if this word has more unique characters or is lexicographically smaller\n if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n max_word = word\n max_unique_count = unique_count\n\n return max_word", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n \"\"\"\n You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n \n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n \n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots that exist in stock\n \n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n \"\"\"\n \n # Calculate how many more carrots are needed\n additional_needed = need - number\n \n # If no additional carrots are needed, return the current state\n if additional_needed <= 0:\n return [number, remaining]\n \n # If there are enough remaining carrots to satisfy the need\n if remaining >= additional_needed:\n total_eaten = number + additional_needed\n carrots_left = remaining - additional_needed\n return [total_eaten, carrots_left]\n \n # If there are not enough remaining carrots\n total_eaten = number + remaining\n carrots_left = 0 # All remaining carrots are eaten\n return [total_eaten, carrots_left]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic algebra operations, and \n the second list is a list of integers. Use the two given lists to build the algebraic \n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + ) \n Subtraction ( - ) \n Multiplication ( * ) \n Floor division ( // ) \n Exponentiation ( ** ) \n\n Example:\n operator = ['+', '*', '-']\n operand = [2, 3, 4, 5]\n result = 2 + 3 * 4 - 5\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.\n \"\"\"\n \n # Start with the first operand\n result = operand[0]\n \n # Iterate through the operators and operands\n for i in range(len(operator)):\n op = operator[i]\n next_operand = operand[i + 1]\n \n if op == '+':\n result += next_operand\n elif op == '-':\n result -= next_operand\n elif op == '*':\n result *= next_operand\n elif op == '//':\n # Handle division by zero\n if next_operand == 0:\n raise ValueError(\"Division by zero is not allowed.\")\n result //= next_operand\n elif op == '**':\n result **= next_operand\n else:\n raise ValueError(f\"Invalid operator: {op}\")\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string.\n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n >>> string_to_md5('') is None\n >>> string_to_md5('Python') == '3b3b3c4c4c4c4c4c4c4c4c4c4c4c4c4c'\n >>> string_to_md5('123456') == 'e10adc3949ba59abbe56e057f20f883e'\n >>> string_to_md5('!@#$%^&*()') == 'c5e478d5938c7b0b8c3e0c4c4c4c4c4c'\n \"\"\"\n if text == \"\":\n return None\n # Create an MD5 hash object\n md5_hash = hashlib.md5()\n # Update the hash object with the bytes of the string\n md5_hash.update(text.encode('utf-8'))\n # Return the hexadecimal digest of the hash\n return md5_hash.hexdigest()", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n \"\"\"You are given a string s.\n If s[i] is a letter, reverse its case from lower to upper or vice versa, \n otherwise keep it as it is.\n If the string contains no letters, reverse the string.\n The function should return the resulted string.\n \n Examples:\n solve(\"1234\") = \"4321\"\n solve(\"ab\") = \"AB\"\n solve(\"#a@C\") = \"#A@c\"\n \"\"\"\n # Check if there are any letters in the string\n has_letters = any(c.isalpha() for c in s)\n \n if has_letters:\n # If there are letters, reverse the case of each letter\n result = ''.join(c.swapcase() if c.isalpha() else c for c in s)\n else:\n # If there are no letters, reverse the string\n result = s[::-1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascending order.\n\n For example:\n generate_integers(2, 8) => [2, 4, 6, 8]\n generate_integers(8, 2) => [2, 4, 6, 8]\n generate_integers(10, 14) => []\n \"\"\"\n # Ensure a and b are positive integers\n if a <= 0 or b <= 0:\n raise ValueError(\"Both a and b must be positive integers.\")\n\n # Determine the range\n start = min(a, b)\n end = max(a, b)\n\n # Generate the list of even integers in the range\n even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n return even_integers", "base_status": "fail", "plus_status": null, "base_fail_tests": [[2, 10]], "plus_fail_tests": []}]}} \ No newline at end of file diff --git a/llm_based_127_eval_results.json b/llm_based_127_eval_results.json new file mode 100644 index 000000000..ff87410cb --- /dev/null +++ b/llm_based_127_eval_results.json @@ -0,0 +1 @@ +{"date": "2024-07-26 22:54", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" \n Input to this function is a string containing multiple groups of nested parentheses. \n The goal is to separate those groups into separate strings and return the list of those.\n Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n Ignore any spaces in the input string.\n \n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n # Remove spaces from the input string\n paren_string = paren_string.replace(\" \", \"\")\n \n result = []\n current_group = []\n balance = 0\n \n for char in paren_string:\n if char == '(':\n balance += 1\n current_group.append(char)\n elif char == ')':\n balance -= 1\n current_group.append(char)\n \n # When balance is zero, we have a complete group\n if balance == 0 and current_group:\n result.append(''.join(current_group))\n current_group = []\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n >>> has_close_elements([], 0.5)\n False\n >>> has_close_elements([1.0], 0.5)\n False\n >>> has_close_elements([1.0, 1.4], 0.5)\n True\n >>> has_close_elements([1.0, 1.4, 1.8], 0.5)\n True\n >>> has_close_elements([1.0, 2.0, 2.4], 0.5)\n True\n >>> has_close_elements([1.0, 2.0, 3.0], 0.0)\n True\n \"\"\"\n # Edge case: if the list has less than 2 elements, return False\n if len(numbers) < 2:\n return False\n \n # Sort the numbers to make it easier to find close elements\n numbers.sort()\n \n # Check for any two consecutive numbers in the sorted list\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into\n an integer part (largest integer smaller than given number) and decimals\n (leftover part always smaller than 1).\n\n Return the decimal part of the number.\n \n >>> truncate_number(3.5)\n 0.5\n >>> truncate_number(5.0)\n 0.0\n >>> truncate_number(0.75)\n 0.75\n >>> truncate_number(10.99)\n 0.99\n >>> truncate_number(1.0)\n 0.0\n >>> truncate_number(0.0)\n 0.0\n >>> truncate_number(2.999999)\n 0.999999\n \"\"\"\n if number < 0:\n raise ValueError(\"The number must be positive.\")\n \n integer_part = int(number) # Get the integer part\n decimal_part = number - integer_part # Calculate the decimal part\n return decimal_part", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" \n You're given a list of deposit and withdrawal operations on a bank account that starts with\n zero balance. Your task is to detect if at any point the balance of account falls below zero, \n and at that point function should return True. Otherwise it should return False.\n \n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n >>> below_zero([-1])\n True\n >>> below_zero([0, 0, 0])\n False\n >>> below_zero([-1, 1])\n False\n >>> below_zero([1, -1, -1])\n True\n >>> below_zero([5, -10, 5])\n True\n >>> below_zero([])\n False\n \"\"\"\n balance = 0\n for operation in operations:\n balance += operation\n if balance < 0:\n return True\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n >>> mean_absolute_deviation([])\n 0.0\n >>> mean_absolute_deviation([5.0])\n 0.0\n >>> mean_absolute_deviation([1.0, 1.0, 1.0])\n 0.0\n >>> mean_absolute_deviation([-1.0, 0.0, 1.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list\n\n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n \"\"\"Insert a number 'delimiter' between every two consecutive elements of input list `numbers`.\n \n Args:\n numbers (List[int]): A list of integers.\n delimiter (int): An integer to insert between the elements of the list.\n \n Returns:\n List[int]: A new list with the delimiter inserted between elements.\n \n Examples:\n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n for i in range(len(numbers)):\n result.append(numbers[i])\n if i < len(numbers) - 1: # Avoid adding delimiter after the last element\n result.append(delimiter)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring.\n \n Args:\n strings (List[str]): A list of strings to filter.\n substring (str): The substring to search for in each string.\n \n Returns:\n List[str]: A list of strings that contain the specified substring.\n \n Examples:\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n >>> filter_by_substring(['hello', 'world', 'test'], 'z')\n []\n >>> filter_by_substring(['case', 'sensitive', 'substring'], 'sub')\n ['substring']\n >>> filter_by_substring(['a', 'b', 'c'], 'a')\n ['a']\n >>> filter_by_substring(['', 'non-empty', ''], 'non')\n ['non-empty']\n >>> filter_by_substring(['abc', 'def', 'ghi'], '')\n ['abc', 'def', 'ghi']\n \"\"\"\n return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n def max_depth(group: str) -> int:\n \"\"\" Helper function to calculate the maximum depth of nested parentheses in a single group. \"\"\"\n current_depth = 0\n max_depth = 0\n \n for char in group:\n if char == '(':\n current_depth += 1\n max_depth = max(max_depth, current_depth)\n elif char == ')':\n current_depth -= 1\n if current_depth < 0: # More closing than opening parentheses\n return -1 # Invalid group\n return max_depth if current_depth == 0 else -1 # Valid group must end with depth 0\n\n results = []\n groups = paren_string.split()\n \n for group in groups:\n depth = max_depth(group)\n if depth == -1:\n results.append(0) # Treat invalid groups as having depth 0\n else:\n results.append(depth)\n \n return results", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n \n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n >>> sum_product([-1, -2, -3])\n (-6, -6)\n >>> sum_product([0, 1, 2])\n (3, 0)\n >>> sum_product([5])\n (5, 5)\n >>> sum_product([1, 0, 2])\n (3, 0)\n \"\"\"\n if not numbers:\n return (0, 1)\n \n total_sum = sum(numbers)\n total_product = 1\n for number in numbers:\n total_product *= number\n \n return (total_sum, total_product)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \n >>> rolling_max([])\n []\n \n >>> rolling_max([-1, -2, -3, -4])\n [-1, -1, -1, -1]\n \n >>> rolling_max([5])\n [5]\n \n >>> rolling_max([1, 1, 1, 1])\n [1, 1, 1, 1]\n \n >>> rolling_max([3, 1, 4, 1, 5, 9, 2, 6, 5])\n [3, 3, 4, 4, 5, 9, 9, 9, 9]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for number in numbers[1:]:\n max_so_far = max(max_so_far, number)\n result.append(max_so_far)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n \"\"\" \n Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n \n >>> string_xor('010', '110')\n '100'\n >>> string_xor('111', '000')\n '111'\n >>> string_xor('000', '000')\n '000'\n >>> string_xor('101010', '010101')\n '111111'\n >>> string_xor('1', '0')\n '1'\n >>> string_xor('0', '1')\n '1'\n >>> string_xor('', '')\n ''\n >>> string_xor('1', '')\n '1'\n >>> string_xor('', '1')\n '1'\n \"\"\"\n \n # Ensure both strings are of the same length by padding the shorter one with leading zeros\n max_length = max(len(a), len(b))\n a = a.zfill(max_length)\n b = b.zfill(max_length)\n \n # Perform XOR operation\n result = []\n for bit_a, bit_b in zip(a, b):\n result.append('1' if bit_a != bit_b else '0')\n \n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n \n >>> make_palindrome('')\n ''\n >>> make_palindrome('cat')\n 'catac'\n >>> make_palindrome('cata')\n 'catac'\n >>> make_palindrome('race')\n 'racecar'\n >>> make_palindrome('a')\n 'a'\n >>> make_palindrome('ab')\n 'aba'\n \"\"\"\n if not string:\n return string # Return empty string if input is empty\n\n # Find the longest palindromic suffix\n for i in range(len(string)):\n if is_palindrome(string[i:]):\n # If the suffix is a palindrome, we need to append the reverse of the prefix\n prefix = string[:i]\n return string + prefix[::-1]\n\n # If no palindromic suffix is found, the entire string is non-palindromic\n return string + string[::-1] # This case should not occur due to the loop logic", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n \n >>> longest([])\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n >>> longest(['abc', 'ab', 'a'])\n 'abc'\n >>> longest(['', 'a', 'ab'])\n 'ab'\n >>> longest(['longest', 'longer', 'long'])\n 'longest'\n >>> longest(['same', 'size', 'test'])\n 'same'\n \"\"\"\n if not strings:\n return None\n \n longest_string = strings[0]\n \n for string in strings[1:]:\n if len(string) > len(longest_string):\n longest_string = string\n \n return longest_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return the greatest common divisor of two integers a and b.\n \n The function uses the Euclidean algorithm to compute the GCD.\n \n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n >>> greatest_common_divisor(0, 5)\n 5\n >>> greatest_common_divisor(5, 0)\n 5\n >>> greatest_common_divisor(0, 0)\n 0\n >>> greatest_common_divisor(-25, 15)\n 5\n >>> greatest_common_divisor(25, -15)\n 5\n >>> greatest_common_divisor(-25, -15)\n 5\n \"\"\"\n if a == 0 and b == 0:\n return 0 # GCD is undefined for (0, 0)\n \n a, b = abs(a), abs(b) # Work with absolute values\n \n while b:\n a, b = b, a % b\n \n return a", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string.\n \n Args:\n string (str): The input string from which to generate prefixes.\n \n Returns:\n List[str]: A list of all prefixes of the input string.\n \n Examples:\n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n >>> all_prefixes('')\n []\n >>> all_prefixes('a')\n ['a']\n >>> all_prefixes('hello')\n ['h', 'he', 'hel', 'hell', 'hello']\n \"\"\"\n # Initialize an empty list to store prefixes\n prefixes = []\n \n # Iterate through the string and collect prefixes\n for i in range(1, len(string) + 1):\n prefixes.append(string[:i])\n \n return prefixes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" \n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n >>> count_distinct_characters('')\n 0\n >>> count_distinct_characters('aA')\n 1\n >>> count_distinct_characters('123abcABC!@#')\n 9\n >>> count_distinct_characters(' ')\n 0\n >>> count_distinct_characters('!@#$%^&*()')\n 10\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set()\n \n # Iterate through each character in the string\n for char in lower_string:\n # Add only non-space characters to the set\n if char != ' ':\n distinct_characters.add(char)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Jerry jERRY JeRRRY"]], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string representing musical notes in a special ASCII format.\n Your task is to parse this string and return list of integers corresponding to how many beats does each\n note last.\n\n Here is a legend:\n 'o' - whole note, lasts four beats\n 'o|' - half note, lasts two beats\n '.|' - quarter note, lasts one beat\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n # Initialize an empty list to store the beats\n beats = []\n \n # Split the input string by spaces to get individual notes\n notes = music_string.split()\n \n # Define a mapping of note representations to their corresponding beats\n note_to_beats = {\n 'o': 4, # whole note\n 'o|': 2, # half note\n '.|': 1 # quarter note\n }\n \n # Iterate through each note and append the corresponding beats to the list\n for note in notes:\n if note in note_to_beats:\n beats.append(note_to_beats[note])\n else:\n # If an unknown note is encountered, raise an error\n raise ValueError(f\"Unknown note representation: '{note}'\")\n \n return beats", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n \n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n >>> string_sequence(-1)\n ''\n >>> string_sequence(1)\n '0 1'\n >>> string_sequence(10)\n '0 1 2 3 4 5 6 7 8 9 10'\n \"\"\"\n if n < 0:\n return ''\n \n return ' '.join(str(i) for i in range(n + 1))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n \n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n >>> how_many_times('abcabcabc', 'abc')\n 3\n >>> how_many_times('abababab', 'aba')\n 4\n >>> how_many_times('hello', 'lo')\n 1\n >>> how_many_times('hello', 'hello')\n 1\n >>> how_many_times('hello', 'world')\n 0\n >>> how_many_times('aaaaaa', 'aa')\n 5\n >>> how_many_times('abc', '')\n 0\n >>> how_many_times('', '')\n 1\n \"\"\"\n if not substring:\n return 0\n if not string:\n return 0\n\n count = 0\n start = 0\n\n while True:\n start = string.find(substring, start)\n if start == -1:\n break\n count += 1\n start += 1 # Move one character forward to allow overlapping\n\n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n \"\"\" \n Input is a space-delimited string of numerals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest.\n \n >>> sort_numbers('three one five')\n 'one three five'\n >>> sort_numbers('nine eight seven six five four three two one zero')\n 'zero one two three four five six seven eight nine'\n >>> sort_numbers('zero')\n 'zero'\n >>> sort_numbers('')\n ''\n >>> sort_numbers('five five four four')\n 'four four five five'\n \"\"\"\n \n # Mapping of words to their corresponding numeric values\n word_to_number = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n \n # Reverse mapping for sorting back to words\n number_to_word = {v: k for k, v in word_to_number.items()}\n \n # Split the input string into words\n words = numbers.split()\n \n # Convert words to their corresponding numeric values\n numeric_values = [word_to_number[word] for word in words]\n \n # Sort the numeric values\n numeric_values.sort()\n \n # Convert sorted numeric values back to words\n sorted_words = [number_to_word[num] for num in numeric_values]\n \n # Join the sorted words into a single string\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n >>> find_closest_elements([1.0, 1.0, 1.0, 1.0])\n (1.0, 1.0)\n >>> find_closest_elements([-1.0, -2.0, -3.0, -1.5])\n (-1.5, -1.0)\n >>> find_closest_elements([0.0, 0.1, 0.2, 0.3])\n (0.0, 0.1)\n \"\"\"\n \n # Sort the numbers to make it easier to find the closest pairs\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest elements\n for i in range(len(sorted_numbers) - 1):\n # Calculate the difference between consecutive elements\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n \n # If this difference is smaller than the minimum found so far, update\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1.\n \n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n \n >>> rescale_to_unit([10.0, 20.0, 30.0])\n [0.0, 0.5, 1.0]\n \n >>> rescale_to_unit([5.0, 5.0, 5.0])\n [0.0, 0.0, 0.0]\n \n >>> rescale_to_unit([-1.0, 0.0, 1.0])\n [0.0, 0.5, 1.0]\n \n >>> rescale_to_unit([1.0, 1.0, 2.0, 2.0])\n [0.0, 0.0, 1.0, 1.0]\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The input list must contain at least two elements.\")\n \n min_value = min(numbers)\n max_value = max(numbers)\n \n if min_value == max_value:\n # If all numbers are the same, return a list of zeros\n return [0.0] * len(numbers)\n \n # Rescale the numbers\n return [(num - min_value) / (max_value - min_value) for num in numbers]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n \"\"\" Return length of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n >>> strlen('a')\n 1\n >>> strlen('Hello, World!')\n 13\n >>> strlen(' ') # String with spaces\n 3\n >>> strlen('\ud83d\ude0a') # String with a Unicode character\n 2\n >>> strlen('abc\\nxyz') # String with newline character\n 8\n >>> strlen('') # Edge case: empty string\n 0\n \"\"\"\n return len(string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers\n >>> filter_integers(['a', 3.14, 5])\n [5]\n >>> filter_integers([1, 2, 3, 'abc', {}, []])\n [1, 2, 3]\n \"\"\"\n return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n \n Args:\n n (int): The number to find the largest divisor for.\n \n Returns:\n int: The largest divisor of n that is smaller than n.\n \n Raises:\n ValueError: If n is less than or equal to 1, as there are no divisors in that case.\n \n Examples:\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(10)\n 5\n >>> largest_divisor(1)\n Traceback (most recent call last):\n ...\n ValueError: No divisors for numbers less than or equal to 1.\n >>> largest_divisor(2)\n 1\n \"\"\"\n if n <= 1:\n raise ValueError(\"No divisors for numbers less than or equal to 1.\")\n \n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n Input number should be equal to the product of all factors.\n \n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n >>> factorize(1)\n []\n >>> factorize(0)\n Traceback (most recent call last):\n ...\n ValueError: Input must be a positive integer.\n >>> factorize(-10)\n Traceback (most recent call last):\n ...\n ValueError: Input must be a positive integer.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n factors = []\n # Check for number of 2s that divide n\n while n % 2 == 0:\n factors.append(2)\n n //= 2\n \n # n must be odd at this point so a skip of 2 (i.e., i = i + 2) can be used\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, append i and divide n\n while n % i == 0:\n factors.append(i)\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n factors.append(n)\n \n return factors", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n \n Args:\n string (str): The input string to flip the case of its characters.\n \n Returns:\n str: A new string with the case of each character flipped.\n \n Examples:\n >>> flip_case('Hello')\n 'hELLO'\n >>> flip_case('world')\n 'WORLD'\n >>> flip_case('Python 3.8')\n 'pYTHON 3.8'\n >>> flip_case('')\n ''\n >>> flip_case('12345')\n '12345'\n >>> flip_case('!@#$%^&*()')\n '!@#$%^&*()'\n \"\"\"\n return ''.join(char.swapcase() for char in string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([1, 1, 1, 1])\n []\n >>> remove_duplicates([1, 2, 3])\n [1, 2, 3]\n >>> remove_duplicates([])\n []\n >>> remove_duplicates([1, 2, 3, 4, 5, 1, 2])\n [3, 4, 5]\n >>> remove_duplicates([5, 5, 5, 6, 7, 8, 6])\n [7, 8]\n >>> remove_duplicates([10, 20, 30, 10, 20, 30, 40])\n [40]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n \n # Create a new list with elements that occur only once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string.\n \n Args:\n strings (List[str]): A list of strings to concatenate.\n \n Returns:\n str: A single concatenated string.\n \n Examples:\n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n >>> concatenate(['Hello', ' ', 'World', '!'])\n 'Hello World!'\n >>> concatenate(['Python', 'is', 'fun'])\n 'Pythonisfun'\n >>> concatenate(['', 'empty', 'string'])\n 'emptystring'\n >>> concatenate(['a' * 1000, 'b' * 1000])\n 'a' * 1000 + 'b' * 1000\n \"\"\"\n # Using join to concatenate the list of strings efficiently\n return ''.join(strings)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n \n Args:\n strings (List[str]): A list of strings to filter.\n prefix (str): The prefix to filter the strings by.\n \n Returns:\n List[str]: A list of strings that start with the given prefix.\n \n Examples:\n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n >>> filter_by_prefix(['apple', 'banana', 'apricot', 'grape'], 'ap')\n ['apple', 'apricot']\n >>> filter_by_prefix(['hello', 'world'], 'h')\n ['hello']\n >>> filter_by_prefix(['hello', 'world'], 'x')\n []\n >>> filter_by_prefix(['', 'test', ''], '')\n ['', 'test', '']\n >>> filter_by_prefix(['abc', 'def', 'ghi'], 'abcdef')\n []\n \"\"\"\n return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n A prime number is a natural number greater than 1 that cannot be formed by multiplying two smaller natural numbers.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n >>> is_prime(0)\n False\n >>> is_prime(-5)\n False\n >>> is_prime(2)\n True\n >>> is_prime(3)\n True\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return False # eliminate multiples of 2 and 3\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6 # check for factors of the form 6k \u00b1 1\n\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n \n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n >>> get_positive([]) # Edge case: empty list\n []\n >>> get_positive([-1, -2, -3]) # Edge case: all negative numbers\n []\n >>> get_positive([0]) # Edge case: single zero\n []\n >>> get_positive([1, 0, -1]) # Mixed numbers with zero\n [1]\n >>> get_positive([10, 20, 30, 0, -10, -20]) # Mixed with positives and negatives\n [10, 20, 30]\n \"\"\"\n return [x for x in l if x > 0]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float) -> float:\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list) -> list:\n \"\"\"\n Computes the derivative of the polynomial with coefficients xs.\n The derivative is calculated as: \n d/dx (a0 + a1*x + a2*x^2 + ... + an*x^n) = a1 + 2*a2*x + ... + n*an*x^(n-1)\n \"\"\"\n return [i * coeff for i, coeff in enumerate(xs) if i > 0]\ndef find_zero(xs: list) -> float:\n \"\"\" \n xs are coefficients of a polynomial.\n find_zero finds x such that poly(x) = 0.\n find_zero returns only one zero point, even if there are many.\n Moreover, find_zero only takes list xs having an even number of coefficients\n and the largest non-zero coefficient as it guarantees a solution.\n \n >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n -0.5\n >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n 1.0\n \"\"\"\n if len(xs) % 2 != 0:\n raise ValueError(\"The number of coefficients must be even.\")\n \n # Initial guess for the root\n x0 = 0.0\n tolerance = 1e-7\n max_iterations = 1000\n \n for _ in range(max_iterations):\n f_x0 = poly(xs, x0)\n f_prime_x0 = poly(derivative(xs), x0)\n \n if f_prime_x0 == 0: # Avoid division by zero\n raise ValueError(\"Derivative is zero. No solution found.\")\n \n x1 = x0 - f_x0 / f_prime_x0\n \n if abs(x1 - x0) < tolerance:\n return x1\n \n x0 = x1\n \n raise ValueError(\"Maximum iterations reached. No solution found.\")", "base_status": "fail", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n >>> sort_third([10, 20, 30, 40, 50, 60, 70, 80, 90])\n [10, 20, 30, 40, 50, 60, 70, 80, 90]\n >>> sort_third([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])\n [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]\n >>> sort_third([])\n []\n >>> sort_third([1])\n [1]\n >>> sort_third([1, 2])\n [1, 2]\n >>> sort_third([3, 1, 2, 4, 5, 6, 7, 8, 9, 10])\n [1, 1, 2, 4, 5, 6, 7, 8, 9, 10]\n \"\"\"\n \n # Extract values at indices divisible by 3\n values_to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(values_to_sort)\n \n # Create a new list to hold the result\n result = l.copy()\n \n # Replace values at indices divisible by 3 with sorted values\n sorted_index = 0\n for i in range(len(result)):\n if i % 3 == 0:\n result[i] = sorted_values[sorted_index]\n sorted_index += 1\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n Args:\n l (list): A list of elements which may contain duplicates.\n \n Returns:\n list: A sorted list of unique elements.\n \n Examples:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use a set to remove duplicates, then convert back to a list\n unique_elements = set(l)\n \n # Sort the unique elements\n sorted_unique_elements = sorted(unique_elements)\n \n return sorted_unique_elements", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n \"\"\"Return maximum element in the list.\n \n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n >>> max_element([]) # Edge case: empty list\n Traceback (most recent call last):\n ...\n ValueError: The list is empty.\n >>> max_element(['a', 1, 2]) # Edge case: non-numeric elements\n Traceback (most recent call last):\n ...\n ValueError: All elements must be numeric.\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty.\")\n \n max_value = l[0]\n \n for item in l:\n if not isinstance(item, (int, float)):\n raise ValueError(\"All elements must be numeric.\")\n if item > max_value:\n max_value = item\n \n return max_value", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with encode_cyclic function. Returns decoded string.\n \"\"\"\n # Split string into groups of length 3\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # Reverse the cycling of elements in each group\n groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n >>> sort_even([10, 20, 30, 40, 50])\n [10, 20, 30, 40, 50]\n >>> sort_even([1])\n [1]\n >>> sort_even([])\n []\n >>> sort_even([2, 1])\n [2, 1]\n >>> sort_even([4, 3, 2, 1, 0])\n [0, 3, 2, 1, 4]\n \"\"\"\n # Extract even indexed elements\n even_indices = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indexed elements\n even_indices_sorted = sorted(even_indices)\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Place the sorted even indexed elements back into their positions\n for i, sorted_value in enumerate(even_indices_sorted):\n result[i * 2] = sorted_value\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_fib(n: int) -> int:\n \"\"\"\n prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n \n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n if n < 1:\n raise ValueError(\"n must be a positive integer.\")\n \n fib_gen = fibonacci_generator()\n count = 0\n for fib in fib_gen:\n if is_prime(fib):\n count += 1\n if count == n:\n return fib", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1]], "plus_fail_tests": []}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n \"\"\"\n triples_sum_to_zero takes a list of integers as an input.\n It returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n >>> triples_sum_to_zero([])\n False\n >>> triples_sum_to_zero([0, 0, 0])\n False\n >>> triples_sum_to_zero([-1, 0, 1])\n True\n \"\"\"\n n = len(l)\n if n < 3:\n return False\n\n # Sort the list to use the two-pointer technique\n l.sort()\n\n for i in range(n - 2):\n # Avoid duplicates for the first element\n if i > 0 and l[i] == l[i - 1]:\n continue\n \n left, right = i + 1, n - 1\n while left < right:\n current_sum = l[i] + l[left] + l[right]\n if current_sum == 0:\n return True\n elif current_sum < 0:\n left += 1\n else:\n right -= 1\n\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n \"\"\"\n Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move at the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.\n\n Parameters:\n n (int): The number of cars in each direction.\n\n Returns:\n int: The number of collisions.\n \"\"\"\n # Each car moving left to right will collide with each car moving right to left.\n # Therefore, the total number of collisions is simply n * n.\n return n * n", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n \n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n >>> incr_list([]) # Edge case: empty list\n []\n >>> incr_list([-1, -2, -3]) # Edge case: negative numbers\n [0, -1, -2]\n >>> incr_list([0]) # Edge case: single element\n [1]\n >>> incr_list([1.5, 2.5]) # Edge case: float numbers\n [2.5, 3.5]\n \"\"\"\n return [x + 1 for x in l]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input.\n It returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n \n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n >>> pairs_sum_to_zero([])\n False\n >>> pairs_sum_to_zero([-1, 1])\n True\n >>> pairs_sum_to_zero([-1, 2, 1, -2])\n True\n \"\"\"\n seen = set()\n for number in l:\n if -number in seen:\n return True\n seen.add(number)\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion.\n base numbers are less than 10.\n \n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n >>> change_base(0, 2)\n '0'\n >>> change_base(0, 3)\n '0'\n >>> change_base(1, 2)\n '1'\n >>> change_base(1, 3)\n '1'\n >>> change_base(9, 2)\n '1001'\n >>> change_base(9, 3)\n '100'\n >>> change_base(9, 4)\n '21'\n >>> change_base(9, 5)\n '14'\n >>> change_base(9, 6)\n '13'\n >>> change_base(9, 7)\n '12'\n >>> change_base(9, 8)\n '11'\n >>> change_base(9, 9)\n '10'\n \"\"\"\n \n if base < 2 or base >= 10:\n raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n \n if x == 0:\n return '0'\n \n result = []\n negative = x < 0\n x = abs(x)\n \n while x > 0:\n remainder = x % base\n result.append(str(remainder))\n x //= base\n \n if negative:\n result.append('-')\n \n # The result is built in reverse order\n return ''.join(reversed(result))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n \"\"\"Given length of a side and height, return the area for a triangle.\n \n The area of a triangle can be calculated using the formula:\n Area = (base * height) / 2\n \n Parameters:\n a (float): The length of the base of the triangle.\n h (float): The height of the triangle.\n \n Returns:\n float: The area of the triangle.\n \n Raises:\n ValueError: If the base or height is not a positive number.\n \n >>> triangle_area(5, 3)\n 7.5\n >>> triangle_area(0, 3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(5, -3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(-5, 3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(5, 0)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n \"\"\"\n \n if a <= 0 or h <= 0:\n raise ValueError(\"Base and height must be positive numbers.\")\n \n return (a * h) / 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fib4(0) -> 0\n fib4(1) -> 0\n fib4(2) -> 2\n fib4(3) -> 0\n fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n \n This function computes the n-th element of the fib4 number sequence efficiently without using recursion.\n \n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n \n # Handle base cases\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 2\n elif n == 3:\n return 0\n \n # Initialize the first four values of the sequence\n fib_values = [0, 0, 2, 0]\n \n # Compute the values iteratively from 4 to n\n for i in range(4, n + 1):\n next_value = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n fib_values.append(next_value)\n \n return fib_values[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n \"\"\"Return median of elements in the list l.\n \n The median is the middle value in a list of numbers. If the list has an even number of elements,\n the median is the average of the two middle numbers.\n \n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n >>> median([1])\n 1\n >>> median([1, 2])\n 1.5\n >>> median([])\n Traceback (most recent call last):\n ...\n ValueError: Cannot compute median of an empty list.\n \"\"\"\n if not l:\n raise ValueError(\"Cannot compute median of an empty list.\")\n \n # Sort the list\n sorted_list = sorted(l)\n n = len(sorted_list)\n \n # Calculate median\n if n % 2 == 1: # Odd number of elements\n return sorted_list[n // 2]\n else: # Even number of elements\n mid1 = sorted_list[n // 2 - 1]\n mid2 = sorted_list[n // 2]\n return (mid1 + mid2) / 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n \"\"\"\n Checks if given string is a palindrome.\n \n A palindrome is a string that reads the same forward and backward.\n \n Args:\n text (str): The string to check.\n \n Returns:\n bool: True if the string is a palindrome, False otherwise.\n \n Examples:\n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n >>> is_palindrome('A man a plan a canal Panama')\n True\n >>> is_palindrome('No lemon, no melon')\n True\n >>> is_palindrome('12321')\n True\n >>> is_palindrome('12345')\n False\n >>> is_palindrome('Was it a car or a cat I saw?')\n True\n \"\"\"\n # Normalize the string: remove non-alphanumeric characters and convert to lowercase\n normalized_text = ''.join(char.lower() for char in text if char.isalnum())\n \n # Check if the normalized string is equal to its reverse\n return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n Args:\n n (int): The exponent.\n p (int): The modulus.\n \n Returns:\n int: The result of 2^n modulo p.\n \n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n if p <= 0:\n raise ValueError(\"Modulus p must be a positive integer.\")\n \n # Using modular exponentiation to avoid large numbers\n result = 1\n base = 2 % p # Start with 2 mod p\n\n while n > 0:\n if n % 2 == 1: # If n is odd, multiply the base with the result\n result = (result * base) % p\n n //= 2 # Divide n by 2\n base = (base * base) % p # Square the base\n\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with encode_shift function.\n Returns the decoded string by shifting every alphabetic character back by 5.\n Non-alphabetic characters are not changed.\n \"\"\"\n decoded = []\n for ch in s:\n if 'a' <= ch <= 'z':\n # Reverse shift for lowercase letters\n decoded.append(chr(((ord(ch) - ord('a') - 5) % 26) + ord('a')))\n elif 'A' <= ch <= 'Z':\n # Reverse shift for uppercase letters\n decoded.append(chr(((ord(ch) - ord('A') - 5) % 26) + ord('A')))\n else:\n # Non-alphabetic characters remain unchanged\n decoded.append(ch)\n return ''.join(decoded)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n \"\"\"Return True if all numbers in the list l are below threshold t.\n \n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n >>> below_threshold([], 10)\n True\n >>> below_threshold([5], 5)\n False\n >>> below_threshold([-1, -2, -3], 0)\n True\n >>> below_threshold([0, 0, 0], 1)\n True\n >>> below_threshold([1, 2, 3], 2)\n False\n \"\"\"\n # Check if all elements in the list are below the threshold\n return all(x < t for x in l)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n \"\"\"Add two numbers x and y.\n\n This function takes two integers and returns their sum. It handles\n positive numbers, negative numbers, and zero.\n\n Args:\n x (int): The first number to add.\n y (int): The second number to add.\n\n Returns:\n int: The sum of x and y.\n\n Examples:\n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n >>> add(-1, 1)\n 0\n >>> add(-5, -7)\n -12\n >>> add(0, 0)\n 0\n >>> add(1000000, 2000000)\n 3000000\n >>> add(-1000000, 1000000)\n 0\n \"\"\"\n return x + y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two words have the same characters if they contain the same unique characters,\n regardless of the frequency of those characters.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets to get unique characters\n unique_chars_s0 = set(s0)\n unique_chars_s1 = set(s1)\n \n # Compare the sets of unique characters\n return unique_chars_s0 == unique_chars_s1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n \"\"\"Return n-th Fibonacci number.\n \n The Fibonacci sequence is defined as follows:\n fib(0) = 0\n fib(1) = 1\n fib(n) = fib(n-1) + fib(n-2) for n > 1\n\n Args:\n n (int): The index of the Fibonacci number to return.\n\n Returns:\n int: The n-th Fibonacci number.\n\n Raises:\n ValueError: If n is negative.\n\n Examples:\n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n >>> fib(0)\n 0\n >>> fib(2)\n 1\n >>> fib(3)\n 2\n >>> fib(4)\n 3\n >>> fib(5)\n 5\n >>> fib(6)\n 8\n >>> fib(7)\n 13\n \"\"\"\n if n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n if n == 0:\n return 0\n elif n == 1:\n return 1\n \n a, b = 0, 1\n for _ in range(2, n + 1):\n a, b = b, a + b\n return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n Check if every opening bracket has a corresponding closing bracket.\n \n Args:\n brackets (str): A string consisting of '<' and '>'.\n \n Returns:\n bool: True if the brackets are correctly balanced, False otherwise.\n \n Examples:\n >>> correct_bracketing(\"<\")\n False\n >>> correct_bracketing(\"<>\")\n True\n >>> correct_bracketing(\"<<><>>\")\n True\n >>> correct_bracketing(\"><<>\")\n False\n >>> correct_bracketing(\"<<>>\")\n True\n >>> correct_bracketing(\"><\")\n False\n >>> correct_bracketing(\"<<<>>>\")\n True\n >>> correct_bracketing(\"<<><><>\")\n True\n >>> correct_bracketing(\"><><><\")\n False\n >>> correct_bracketing(\"\")\n True\n \"\"\"\n balance = 0\n \n for char in brackets:\n if char == '<':\n balance += 1\n elif char == '>':\n balance -= 1\n \n # If balance goes negative, it means there's a closing bracket without a matching opening bracket\n if balance < 0:\n return False\n \n # At the end, balance should be zero for the brackets to be correctly balanced\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n >>> common([], [])\n []\n >>> common([1, 2, 3], [])\n []\n >>> common([], [4, 5, 6])\n []\n >>> common([1, 1, 1], [1, 1, 1])\n [1]\n >>> common([1, 2, 3], [4, 5, 6])\n []\n >>> common([1, 2, 3], [3, 2, 1])\n [1, 2, 3]\n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n \"\"\"Return True if list elements are monotonically increasing or decreasing.\n \n A list is considered monotonically increasing if each element is less than or equal to the next.\n A list is considered monotonically decreasing if each element is greater than or equal to the next.\n \n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n >>> monotonic([1, 1, 1])\n True\n >>> monotonic([])\n True\n >>> monotonic([5])\n True\n >>> monotonic([1, 2, 2, 3])\n True\n >>> monotonic([3, 2, 2, 1])\n True\n >>> monotonic([1, 2, 3, 2])\n False\n >>> monotonic([2, 3, 2, 4])\n False\n \"\"\"\n if len(l) <= 1:\n return True # A list with 0 or 1 element is trivially monotonic\n\n increasing = decreasing = True\n\n for i in range(1, len(l)):\n if l[i] > l[i - 1]:\n decreasing = False\n elif l[i] < l[i - 1]:\n increasing = False\n\n return increasing or decreasing", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n >>> largest_prime_factor(600851475143)\n 6857\n >>> largest_prime_factor(49)\n 7\n >>> largest_prime_factor(100)\n 5\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n # Keep dividing n by factor until it is no longer divisible\n while n > 1:\n if n % factor == 0:\n n //= factor # Divide n by the factor\n else:\n factor += 1 # Move to the next potential factor\n return factor", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n \n Args:\n n (int): The upper limit of the sum (inclusive).\n \n Returns:\n int: The sum of all integers from 1 to n.\n \n Examples:\n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n >>> sum_to_n(0)\n 0\n >>> sum_to_n(-5)\n 0\n \"\"\"\n if n < 1:\n return 0\n return n * (n + 1) // 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n Check if every opening bracket has a corresponding closing bracket.\n \n Args:\n brackets (str): A string consisting of '(' and ')'.\n \n Returns:\n bool: True if the brackets are correctly balanced, False otherwise.\n \n Examples:\n >>> correct_bracketing(\"(\")\n False\n >>> correct_bracketing(\"()\")\n True\n >>> correct_bracketing(\"(()())\")\n True\n >>> correct_bracketing(\")(()\")\n False\n >>> correct_bracketing(\")(\")\n False\n >>> correct_bracketing(\"\") # Edge case: empty string\n True\n >>> correct_bracketing(\"((()))\") # Nested brackets\n True\n >>> correct_bracketing(\"(()\") # Unmatched opening bracket\n False\n >>> correct_bracketing(\"())\") # Unmatched closing bracket\n False\n >>> correct_bracketing(\"()()()\") # Multiple pairs\n True\n >>> correct_bracketing(\"(()())()\") # Mixed pairs\n True\n \"\"\"\n balance = 0\n \n for char in brackets:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n \n # If balance goes negative, there are unmatched closing brackets\n if balance < 0:\n return False\n \n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n \"\"\" \n Calculate the derivative of a polynomial represented by its coefficients.\n \n The polynomial is represented as:\n xs[0] + xs[1] * x + xs[2] * x^2 + ...\n \n The derivative is calculated as:\n d/dx (a_n * x^n) = n * a_n * x^(n-1)\n \n Args:\n xs (list): A list of coefficients where the index represents the power of x.\n \n Returns:\n list: A list of coefficients representing the derivative of the polynomial.\n \n Examples:\n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n >>> derivative([0])\n []\n >>> derivative([0, 0, 0])\n []\n >>> derivative([5])\n []\n >>> derivative([1, 0, 0, 0])\n [0, 0, 0]\n \"\"\"\n # The derivative of a constant (degree 0) is 0, so we return an empty list\n if len(xs) <= 1:\n return []\n \n # Calculate the derivative coefficients\n derivative_coeffs = []\n for i in range(1, len(xs)):\n derivative_coeffs.append(i * xs[i])\n \n return derivative_coeffs", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n \n Args:\n n (int): The index of the FibFib number to compute.\n \n Returns:\n int: The n-th FibFib number.\n \n Examples:\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n # Memoization dictionary to store computed values\n memo = {0: 0, 1: 0, 2: 1}\n\n def helper(n: int) -> int:\n if n in memo:\n return memo[n]\n # Compute the n-th FibFib number recursively\n memo[n] = helper(n - 1) + helper(n - 2) + helper(n - 3)\n return memo[n]\n\n return helper(n)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set('aeiouAEIOU')\n count = 0\n \n # Iterate through the string\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n # Check if 'y' is at the end of the string\n elif s[i].lower() == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n \n >>> circular_shift(12, 1)\n '21'\n >>> circular_shift(12, 2)\n '12'\n >>> circular_shift(12345, 1)\n '51234'\n >>> circular_shift(12345, 5)\n '54321'\n >>> circular_shift(12345, 6)\n '54321'\n >>> circular_shift(0, 1)\n '0'\n >>> circular_shift(7, 0)\n '7'\n >>> circular_shift(100, 1)\n '010'\n >>> circular_shift(100, 2)\n '001'\n >>> circular_shift(100, 3)\n '001'\n \"\"\"\n # Convert the integer to a string to work with its digits\n str_x = str(x)\n length = len(str_x)\n \n # If the number is 0, return '0'\n if length == 1 and str_x == '0':\n return '0'\n \n # If shift is 0, return the original number as a string\n if shift == 0:\n return str_x\n \n # Calculate effective shift\n effective_shift = shift % length\n \n # If effective shift is 0, return the original number\n if effective_shift == 0:\n return str_x\n \n # If shift is greater than the number of digits, return reversed digits\n if shift > length:\n return str_x[::-1]\n \n # Perform the circular shift\n return str_x[-effective_shift:] + str_x[:-effective_shift]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[97, 8]], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n \"\"\"Task\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n \"\"\"\n # Initialize the sum of ASCII values of uppercase characters\n total = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is uppercase\n if char.isupper():\n # Add the ASCII value of the uppercase character to the total\n total += ord(char)\n \n return total", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n \"\"\"\n Calculate the number of mango fruits in a basket given the number of apples and oranges.\n\n Parameters:\n s (str): A string representing the number of apples and oranges in the format \"X apples and Y oranges\".\n n (int): An integer representing the total number of fruits in the basket.\n\n Returns:\n int: The number of mango fruits in the basket.\n \"\"\"\n # Extract the number of apples and oranges from the string\n try:\n # Split the string to find the numbers\n parts = s.split()\n apples = int(parts[0]) # First part is the number of apples\n oranges = int(parts[2]) # Third part is the number of oranges\n except (IndexError, ValueError) as e:\n raise ValueError(\"Input string format is incorrect. Expected format: 'X apples and Y oranges'\") from e\n\n # Calculate the number of mangoes\n mangoes = n - apples - oranges\n\n # Ensure the result is non-negative\n if mangoes < 0:\n raise ValueError(\"The total number of fruits cannot be less than the sum of apples and oranges.\")\n\n return mangoes", "base_status": "fail", "plus_status": null, "base_fail_tests": [["5 apples and 6 oranges", 19]], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n \"\"\"\n Given an array representing a branch of a tree that has non-negative integer nodes,\n your task is to pluck one of the nodes and return it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n The plucked node should be returned in a list, [ smallest_value, its index ],\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index. \n\n Example 3:\n Input: []\n Output: []\n \n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n Explanation: 0 is the smallest value, but there are two zeros,\n so we will choose the first zero, which has the smallest index.\n\n Constraints:\n * 1 <= nodes.length <= 10000\n * 0 <= node.value\n \"\"\"\n smallest_even_value = float('inf')\n smallest_index = -1\n\n for index, value in enumerate(arr):\n if value % 2 == 0: # Check if the value is even\n if value < smallest_even_value: # Check if it's the smallest even value\n smallest_even_value = value\n smallest_index = index\n\n if smallest_index == -1: # No even value found\n return []\n \n return [smallest_even_value, smallest_index]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n '''\n Given list of integers, return list in strange order.\n Strange sorting, is when you start with the minimum value,\n then maximum of the remaining integers, then minimum and so on.\n\n Examples:\n strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n strange_sort_list([]) == []\n '''\n if not lst:\n return []\n\n # Sort the list to easily access min and max values\n sorted_lst = sorted(lst)\n result = []\n \n # Use two pointers to select from both ends of the sorted list\n left = 0\n right = len(sorted_lst) - 1\n \n while left <= right:\n if left == right: # If both pointers meet, add the last element\n result.append(sorted_lst[left])\n else:\n result.append(sorted_lst[left]) # Add the minimum\n result.append(sorted_lst[right]) # Add the maximum\n left += 1\n right -= 1\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n '''\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequency greater than or equal to the value of the integer itself. \n The frequency of an integer is the number of times it appears in the list.\n If no such a value exists, return -1.\n \n Examples:\n search([4, 1, 2, 2, 3, 1]) == 2\n search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n search([5, 5, 4, 4, 4]) == -1\n '''\n from collections import Counter\n\n # Count the frequency of each integer in the list\n frequency = Counter(lst)\n\n # Initialize the result variable\n result = -1\n\n # Iterate through the frequency dictionary\n for num, freq in frequency.items():\n # Check if the frequency is greater than or equal to the number itself\n if freq >= num:\n # Update the result if this number is greater than the current result\n result = max(result, num)\n\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return the area of\n the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n Otherwise return -1.\n \n Three sides make a valid triangle when the sum of any two sides is greater \n than the third side.\n \n Example:\n triangle_area(3, 4, 5) == 6.00\n triangle_area(1, 2, 10) == -1\n '''\n \n # Check for valid triangle using the triangle inequality theorem\n if a <= 0 or b <= 0 or c <= 0:\n return -1\n if a + b <= c or a + c <= b or b + c <= a:\n return -1\n \n # Calculate the semi-perimeter\n s = (a + b + c) / 2\n \n # Calculate the area using Heron's formula\n area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n \n # Return the area rounded to 2 decimal points\n return round(area, 2)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n '''\n Write a function that returns True if the object q will fly, and False otherwise.\n The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n\n Example:\n will_it_fly([1, 2], 5) \u279e False \n # 1+2 is less than the maximum possible weight, but it's unbalanced.\n\n will_it_fly([3, 2, 3], 1) \u279e False\n # it's balanced, but 3+2+3 is more than the maximum possible weight.\n\n will_it_fly([3, 2, 3], 9) \u279e True\n # 3+2+3 is less than the maximum possible weight, and it's balanced.\n\n will_it_fly([3], 5) \u279e True\n # 3 is less than the maximum possible weight, and it's balanced.\n '''\n \n # Check if the list is a palindrome\n is_balanced = (q == q[::-1])\n \n # Calculate the sum of the elements in the list\n total_weight = sum(q)\n \n # Determine if the object will fly\n return is_balanced and (total_weight <= w)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n \"\"\"\n Given an array arr of integers, find the minimum number of elements that\n need to be changed to make the array palindromic. A palindromic array is an array that\n is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n For example:\n smallest_change([1,2,3,5,4,7,9,6]) == 4\n smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n smallest_change([1, 2, 3, 2, 1]) == 0\n \"\"\"\n n = len(arr)\n changes = 0\n \n # Compare elements from the start and end towards the center\n for i in range(n // 2):\n if arr[i] != arr[n - 1 - i]:\n changes += 1\n \n return changes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n \n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total character counts and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n else:\n return lst2", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef generate_primes(limit):\n \"\"\"Generate a list of prime numbers up to a given limit.\"\"\"\n return [num for num in range(2, limit) if is_prime(num)]\ndef is_multiply_prime(a):\n \"\"\"Return True if the given number is the multiplication of 3 prime numbers, False otherwise.\"\"\"\n if a < 1 or a >= 100:\n return False # a must be less than 100 and greater than 0\n\n primes = generate_primes(100)\n \n # Check all combinations of three primes\n for i in range(len(primes)):\n for j in range(i, len(primes)):\n for k in range(j, len(primes)):\n product = primes[i] * primes[j] * primes[k]\n if product == a:\n return True\n if product > a:\n break # No need to check further if product exceeds a\n\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n \"\"\"Returns True if x is a simple power of n, otherwise False.\n \n A number x is a simple power of n if there exists an integer k such that n**k = x.\n \n Args:\n x (int): The number to check.\n n (int): The base number.\n \n Returns:\n bool: True if x is a simple power of n, False otherwise.\n \"\"\"\n # Edge case: if n is 0, we cannot raise it to any power to get a positive x\n if n == 0:\n return x == 0\n \n # Edge case: if n is 1, n**k will always be 1 for any k >= 0\n if n == 1:\n return x == 1\n \n # Edge case: if x is 0, it can only be a power of n if n is also 0\n if x == 0:\n return n == 0\n \n # Edge case: if x is negative and n is even, it cannot be a power\n if x < 0 and n % 2 == 0:\n return False\n \n # Check if there exists an integer k such that n**k = x\n k = 0\n power = 1 # n**0 = 1\n while power < x:\n k += 1\n power = n ** k\n \n return power == x", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this integer is a cube of some integer number.\n Note: you may assume the input is always valid.\n \n Examples:\n iscube(1) ==> True\n iscube(2) ==> False\n iscube(-1) ==> True\n iscube(64) ==> True\n iscube(0) ==> True\n iscube(180) ==> False\n '''\n # Calculate the cube root of the absolute value of a\n cube_root = round(abs(a) ** (1/3))\n \n # Check if the cube of the rounded cube root equals the absolute value of a\n return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n \"\"\"Counts the number of prime hexadecimal digits in the given hexadecimal string.\"\"\"\n \n # Define the set of prime hexadecimal digits\n prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n \n # Initialize a counter for prime digits\n prime_count = 0\n \n # Iterate through each character in the input string\n for char in num:\n # Check if the character is in the set of prime hexadecimal digits\n if char in prime_hex_digits:\n prime_count += 1\n \n return prime_count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n \"\"\"Convert a decimal number to binary format with specific formatting.\n\n Args:\n decimal (int): A non-negative integer to convert to binary.\n\n Returns:\n str: A string representing the binary number, formatted with 'db' at the beginning and end.\n\n Examples:\n decimal_to_binary(15) # returns \"db1111db\"\n decimal_to_binary(32) # returns \"db100000db\"\n \"\"\"\n if not isinstance(decimal, int) or decimal < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n\n # Convert decimal to binary using built-in function\n binary_representation = bin(decimal)[2:] # bin() returns a string starting with '0b'\n\n # Format the output with 'db' at the beginning and end\n formatted_output = f\"db{binary_representation}db\"\n \n return formatted_output", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n letter_grades = []\n \n for gpa in grades:\n if gpa == 4.0:\n letter_grades.append('A+')\n elif gpa > 3.7:\n letter_grades.append('A')\n elif gpa > 3.3:\n letter_grades.append('A-')\n elif gpa > 3.0:\n letter_grades.append('B+')\n elif gpa > 2.7:\n letter_grades.append('B')\n elif gpa > 2.3:\n letter_grades.append('B-')\n elif gpa > 2.0:\n letter_grades.append('C+')\n elif gpa > 1.7:\n letter_grades.append('C')\n elif gpa > 1.3:\n letter_grades.append('C-')\n elif gpa > 1.0:\n letter_grades.append('D+')\n elif gpa > 0.7:\n letter_grades.append('D')\n elif gpa > 0.0:\n letter_grades.append('D-')\n elif gpa == 0.0:\n letter_grades.append('E')\n else:\n letter_grades.append('Invalid GPA') # Handle any negative GPAs or invalid inputs\n\n return letter_grades", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n \"\"\"Check if the string s is happy.\n \n A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n \n Args:\n s (str): The input string to check.\n \n Returns:\n bool: True if the string is happy, False otherwise.\n \"\"\"\n # Check if the length of the string is at least 3\n if len(s) < 3:\n return False\n \n # Iterate through the string and check every 3 consecutive characters\n for i in range(len(s) - 2):\n # Get the current substring of 3 characters\n substring = s[i:i+3]\n # Check if all characters in the substring are distinct\n if len(set(substring)) != 3:\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n \"\"\"\n Given a positive integer n, return the count of the numbers of n-digit\n positive integers that start or end with 1.\n \n Parameters:\n n (int): The number of digits in the positive integers to consider.\n \n Returns:\n int: The count of n-digit positive integers that start or end with 1.\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer.\")\n \n if n == 1:\n # For 1-digit numbers, only the number '1' qualifies\n return 1\n \n # Total n-digit numbers\n total_n_digit_numbers = 9 * (10 ** (n - 1))\n \n # Count of n-digit numbers that start with 1\n start_with_1 = 10 ** (n - 1) # 1 followed by (n-1) digits (0-9)\n \n # Count of n-digit numbers that end with 1\n end_with_1 = 9 * (10 ** (n - 2)) if n > 1 else 0 # (n-1) digits (0-9) before 1\n \n # Count of n-digit numbers that both start and end with 1\n start_and_end_with_1 = 10 ** (n - 2) if n > 1 else 0 # 1 followed by (n-2) digits (0-9) and ending with 1\n \n # Using the principle of inclusion-exclusion\n count = (start_with_1 + end_with_1 - start_and_end_with_1)\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n \"\"\"Helper function to determine if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_length(string):\n \"\"\"Check if the length of the string is a prime number.\"\"\"\n length = len(string)\n return is_prime(length)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n add([1, 2, 3, 4, 5]) ==> 0\n add([0, 2, 4, 6, 8]) ==> 2 + 4 = 6\n add([1, 3, 5, 7]) ==> 0\n add([10, 11, 12, 13, 14]) ==> 12\n \"\"\"\n # Initialize the sum to 0\n total = 0\n \n # Iterate over the list using index and value\n for index in range(1, len(lst), 2): # Start from index 1 and step by 2 (odd indices)\n if lst[index] % 2 == 0: # Check if the element is even\n total += lst[index] # Add to total if it's even\n \n return total", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits will be 1 the output should be \"1\".\n For N = 150, the sum of digits will be 6 the output should be \"110\".\n For N = 147, the sum of digits will be 12 the output should be \"1100\".\n \n Variables:\n @N integer\n Constraints: 0 \u2264 N \u2264 10000.\n Output:\n a string of binary number\n \"\"\"\n if N < 0 or N > 10000:\n raise ValueError(\"N must be between 0 and 10000 inclusive.\")\n \n # Calculate the sum of the digits of N\n digit_sum = sum(int(digit) for digit in str(N))\n \n # Convert the sum to binary and remove the '0b' prefix\n binary_sum = bin(digit_sum)[2:]\n \n return binary_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words while preserving spaces\n words = s.split(' ')\n \n # Function to sort characters in a word\n def sort_word(word):\n return ''.join(sorted(word))\n \n # Process each word and sort its characters\n sorted_words = [sort_word(word) for word in words]\n \n # Join the sorted words back with spaces\n result = ' '.join(sorted_words)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n or sort it in descending order if the sum( first index value, last index value) is even.\n\n Note:\n * don't change the given array.\n\n Examples:\n * sort_array([]) => []\n * sort_array([5]) => [5]\n * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n \"\"\"\n # Create a copy of the original array to avoid modifying it\n sorted_array = array.copy()\n \n # Check if the array is empty\n if not sorted_array:\n return sorted_array\n \n # Calculate the sum of the first and last elements\n first_element = sorted_array[0]\n last_element = sorted_array[-1]\n total_sum = first_element + last_element\n \n # Sort the array based on the sum being odd or even\n if total_sum % 2 == 0:\n # Even sum: sort in descending order\n sorted_array.sort(reverse=True)\n else:\n # Odd sum: sort in ascending order\n sorted_array.sort()\n \n return sorted_array", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n # Iterate through each row and its index\n for row_index, row in enumerate(lst):\n # Iterate through each column in the row and its index\n for col_index, value in enumerate(row):\n # If the value matches x, store the coordinates\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort coordinates by row (ascending) and then by column (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating each letter down the alphabet by 4 places.\"\"\"\n encrypted_string = []\n \n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Determine the base ASCII value depending on case\n base = ord('a') if char.islower() else ord('A')\n # Rotate the character by 4 places\n new_char = chr((ord(char) - base + 4) % 26 + base)\n encrypted_string.append(new_char)\n else:\n # If it's not a letter, we can choose to ignore it or keep it as is\n encrypted_string.append(char) # Keeping non-alphabetic characters as is\n\n return ''.join(encrypted_string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Sort the unique elements\n sorted_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_elements[1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n \n For example:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n >>> is_bored(\"I am bored! Are you bored? I want to go home.\")\n 2\n >>> is_bored(\"What a beautiful day. I hope it lasts. I really do!\")\n 2\n >>> is_bored(\"I. I. I.\")\n 3\n >>> is_bored(\"I\")\n 1\n >>> is_bored(\"\")\n 0\n \"\"\"\n # Split the string into sentences based on the delimiters\n sentences = []\n current_sentence = []\n \n for char in S:\n if char in '.!?':\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n current_sentence = []\n else:\n current_sentence.append(char)\n \n # Add the last sentence if it exists\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n \n # Count the number of sentences that start with \"I\"\n boredom_count = sum(1 for sentence in sentences if sentence.startswith('I'))\n \n return boredom_count", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n '''\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n \n Examples\n any_int(5, 2, 7) \u279e True\n any_int(3, 2, 2) \u279e False\n any_int(3, -2, 1) \u279e True\n any_int(3.6, -2.2, 2) \u279e False\n '''\n \n # Check if all inputs are integers\n if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n # Check if one number is equal to the sum of the other two\n return x == y + z or y == x + z or z == x + y\n else:\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n \"\"\"\n Write a function that takes a message, and encodes in such a \n way that it swaps case of all letters, replaces all vowels in \n the message with the letter that appears 2 places ahead of that \n vowel in the English alphabet. \n Assume only letters. \n \n Examples:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n # Define vowels and their replacements\n vowels = 'aeiouAEIOU'\n vowel_replacements = {\n 'a': 'c', 'A': 'C',\n 'e': 'g', 'E': 'G',\n 'i': 'k', 'I': 'K',\n 'o': 'q', 'O': 'Q',\n 'u': 'w', 'U': 'W'\n }\n \n encoded_message = []\n \n for char in message:\n if char.isalpha(): # Check if the character is a letter\n # Swap case\n if char in vowels:\n # Replace vowel with the corresponding letter\n encoded_message.append(vowel_replacements[char])\n else:\n # Just swap the case for consonants\n encoded_message.append(char.swapcase())\n else:\n # If it's not a letter, we can choose to keep it as is\n encoded_message.append(char)\n \n return ''.join(encoded_message)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["TEST"]], "plus_fail_tests": []}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef sum_of_digits(n):\n \"\"\"Return the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n largest_prime = None\n \n for number in lst:\n if is_prime(number):\n if largest_prime is None or number > largest_prime:\n largest_prime = number\n \n if largest_prime is not None:\n return sum_of_digits(largest_prime)\n else:\n return 0 # Return 0 if no prime number is found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in lower \n case or all keys are strings in upper case, else return False.\n The function should return False if the given dictionary is empty.\n \n Examples:\n check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n \"\"\"\n \n # Check if the dictionary is empty\n if not input_dict:\n return False\n \n # Initialize flags for lower and upper case\n all_lower = True\n all_upper = True\n \n # Iterate through the keys of the dictionary\n for key in input_dict.keys():\n # Check if the key is a string\n if not isinstance(key, str):\n return False\n \n # Check if the key is lower case\n if key.islower():\n all_upper = False\n # Check if the key is upper case\n elif key.isupper():\n all_lower = False\n else:\n # If the key is neither lower nor upper case\n return False\n \n # Return True if all keys are either lower case or upper case\n return all_lower or all_upper", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_up_to(n):\n \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n if n < 2:\n return []\n \n primes = []\n for num in range(2, n):\n if is_prime(num):\n primes.append(num)\n \n return primes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.\n \"\"\"\n # Get the unit digit of the first number\n unit_digit_a = abs(a) % 10\n # Get the unit digit of the second number\n unit_digit_b = abs(b) % 10\n # Return the product of the unit digits\n return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n count_upper('aBCdEf') returns 1\n count_upper('abcdefg') returns 0\n count_upper('dBBE') returns 0\n \"\"\"\n # Define the set of uppercase vowels\n uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n \n # Initialize a counter for uppercase vowels at even indices\n count = 0\n \n # Iterate over the string, checking only even indices\n for i in range(0, len(s), 2): # Step by 2 to get even indices\n if s[i] in uppercase_vowels:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n >>> closest_integer(\"14.5\")\n 15\n >>> closest_integer(\"-14.5\")\n -15\n >>> closest_integer(\"0.5\")\n 1\n >>> closest_integer(\"-0.5\")\n -1\n >>> closest_integer(\"3.0\")\n 3\n >>> closest_integer(\"-3.0\")\n -3\n >>> closest_integer(\"2.499999\")\n 2\n >>> closest_integer(\"-2.499999\")\n -2\n '''\n\n # Convert the string input to a float\n num = float(value)\n\n # Calculate the floor and ceiling of the number\n lower_int = int(num // 1) # This is the largest integer less than or equal to num\n upper_int = lower_int + 1 # This is the smallest integer greater than num\n\n # Check the distance to the lower and upper integers\n distance_to_lower = abs(num - lower_int)\n distance_to_upper = abs(num - upper_int)\n\n # Determine which integer to return based on the distances\n if distance_to_lower < distance_to_upper:\n return lower_int\n elif distance_to_upper < distance_to_lower:\n return upper_int\n else:\n # If equidistant, round away from zero\n if num > 0:\n return upper_int\n else:\n return lower_int", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n \"\"\"\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n >>> make_a_pile(4)\n [4, 6, 8, 10]\n >>> make_a_pile(1)\n [1]\n >>> make_a_pile(2)\n [2, 4]\n >>> make_a_pile(0)\n Traceback (most recent call last):\n ...\n ValueError: n must be a positive integer\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n \n stones = []\n current_stones = n\n \n for i in range(n):\n stones.append(current_stones)\n if current_stones % 2 == 0: # current_stones is even\n current_stones += 2 # next even number\n else: # current_stones is odd\n current_stones += 2 # next odd number\n \n return stones", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n \"\"\"This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If \n there's no such number, then the function should return -1.\n\n For example:\n choose_num(12, 15) = 14\n choose_num(13, 12) = -1\n \"\"\"\n # Ensure x is less than or equal to y\n if x > y:\n return -1\n\n # Start from the largest number in the range and work downwards\n for num in range(y, x - 1, -1):\n if num % 2 == 0: # Check if the number is even\n return num\n\n # If no even number is found, return -1\n return -1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n \"\"\"\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n \"\"\"\n # Replace commas with spaces and split the string by whitespace\n words = s.replace(',', ' ').split()\n \n # Return the list of words\n return words", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n \"\"\"Compute the average of integers from n to m, round it to the nearest integer,\n and convert that to binary. If n is greater than m, return -1.\n \n Args:\n n (int): The starting integer (inclusive).\n m (int): The ending integer (inclusive).\n \n Returns:\n str or int: The binary representation of the rounded average if n <= m, otherwise -1.\n \"\"\"\n if n > m:\n return -1\n \n # Calculate the sum of integers from n to m\n total_sum = sum(range(n, m + 1))\n count = m - n + 1 # Total numbers from n to m\n \n # Calculate the average and round it\n average = total_sum / count\n rounded_average = round(average)\n \n # Convert the rounded average to binary\n return bin(rounded_average)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n \"\"\"Given a list of positive integers x, return a sorted list of all \n elements that haven't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n def has_even_digit(n):\n \"\"\"Check if the number has any even digit.\"\"\"\n for digit in str(n):\n if int(digit) % 2 == 0:\n return True\n return False\n\n # Filter the list to include only numbers without even digits\n filtered_numbers = [num for num in x if not has_even_digit(num)]\n \n # Sort the resulting list\n return sorted(filtered_numbers)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n reverse the resulting array, and then replace each digit by its corresponding name from\n \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n For example:\n arr = [2, 1, 1, 4, 5, 8, 2, 3] \n -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n \n If the array is empty, return an empty array:\n arr = []\n return []\n \n If the array has any strange number ignore it:\n arr = [1, -1 , 55] \n -> sort arr -> [-1, 1, 55]\n -> reverse arr -> [55, 1, -1]\n return = ['One']\n \"\"\"\n \n # Mapping of digits to their corresponding names\n digit_to_name = {\n 1: \"One\",\n 2: \"Two\",\n 3: \"Three\",\n 4: \"Four\",\n 5: \"Five\",\n 6: \"Six\",\n 7: \"Seven\",\n 8: \"Eight\",\n 9: \"Nine\"\n }\n \n # Filter the array to include only integers between 1 and 9\n filtered_arr = [num for num in arr if 1 <= num <= 9]\n \n # Sort the filtered array\n filtered_arr.sort()\n \n # Reverse the sorted array\n filtered_arr.reverse()\n \n # Convert the digits to their corresponding names\n result = [digit_to_name[num] for num in filtered_arr]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def f(n):\n \"\"\" \n Implement the function f that takes n as a parameter,\n and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even\n or the sum of numbers from 1 to i otherwise.\n i starts from 1.\n The factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).\n \"\"\"\n if n < 1:\n return [] # Return an empty list for non-positive n\n\n result = []\n \n for i in range(1, n + 1):\n if i % 2 == 0: # i is even\n factorial = 1\n for j in range(1, i + 1):\n factorial *= j\n result.append(factorial)\n else: # i is odd\n sum_of_numbers = sum(range(1, i + 1))\n result.append(sum_of_numbers)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n \"\"\"\n Given a positive integer n, return a tuple that has the number of even and odd\n integer palindromes that fall within the range(1, n), inclusive.\n\n Example 1:\n Input: 3\n Output: (1, 2)\n Explanation:\n Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n Example 2:\n Input: 12\n Output: (4, 6)\n Explanation:\n Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n Note:\n 1. 1 <= n <= 10^3\n 2. returned tuple has the number of even and odd integer palindromes respectively.\n \"\"\"\n \n def is_palindrome(num):\n \"\"\"Check if a number is a palindrome.\"\"\"\n return str(num) == str(num)[::-1]\n\n even_count = 0\n odd_count = 0\n\n for i in range(1, n + 1):\n if is_palindrome(i):\n if i % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n \"\"\"\n Write a function count_nums which takes an array of integers and returns\n the number of elements which has a sum of digits > 0.\n If a number is negative, then its first signed digit will be negative:\n e.g. -123 has signed digits -1, 2, and 3.\n \n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n def sum_of_digits(n):\n \"\"\"Helper function to calculate the sum of digits of an integer n.\"\"\"\n # Convert the number to string and iterate over each character\n # If the number is negative, we need to consider the first digit as negative\n str_n = str(n)\n digit_sum = 0\n \n for i, char in enumerate(str_n):\n if char.isdigit():\n digit_sum += int(char)\n elif i == 0 and char == '-':\n digit_sum -= 1 # First signed digit is negative\n \n return digit_sum\n\n count = 0\n for number in arr:\n if sum_of_digits(number) > 0:\n count += 1\n \n return count", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[-1, -2, 0]]], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return True else return False.\n If the given array is empty then return True.\n\n Note: The given list is guaranteed to have unique elements.\n\n For Example:\n \n move_one_ball([3, 4, 5, 1, 2])==>True\n Explanation: By performing 2 right shift operations, non-decreasing order can\n be achieved for the given array.\n move_one_ball([3, 5, 4, 1, 2])==>False\n Explanation: It is not possible to get non-decreasing order for the given\n array by performing any number of right shift operations.\n \"\"\"\n \n if not arr: # Check for empty array\n return True\n \n n = len(arr)\n count = 0 # Count the number of times the order is broken\n\n for i in range(n):\n if arr[i] > arr[(i + 1) % n]: # Compare current with next (circular)\n count += 1\n\n # If there are more than one break in the order, it's not possible\n return count <= 1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n \"\"\"Determines whether it is possible to perform an exchange of elements\n between two lists to make lst1 a list of only even numbers.\n \n Args:\n lst1 (list): The first list of numbers.\n lst2 (list): The second list of numbers.\n \n Returns:\n str: \"YES\" if lst1 can be made all even, otherwise \"NO\".\n \"\"\"\n # Check if lst1 already contains only even numbers\n if all(x % 2 == 0 for x in lst1):\n return \"YES\"\n \n # Count the number of odd numbers in lst1\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n \n # Count the number of even numbers in lst2\n even_count_lst2 = sum(1 for x in lst2 if x % 2 == 0)\n \n # If there are enough even numbers in lst2 to replace all odd numbers in lst1\n if odd_count_lst1 <= even_count_lst2:\n return \"YES\"\n \n return \"NO\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n \"\"\"\n if not test: # Handle empty string case\n return {}\n\n # Split the input string into a list of letters\n letters = test.split()\n \n # Create a dictionary to count occurrences of each letter\n count_dict = {}\n for letter in letters:\n if letter in count_dict:\n count_dict[letter] += 1\n else:\n count_dict[letter] = 1\n\n # Find the maximum count\n max_count = max(count_dict.values())\n \n # Create a result dictionary for letters with the maximum count\n result = {letter: count for letter, count in count_dict.items() if count == max_count}\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n \"\"\"\n Task\n We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and True/False for the check.\n \n Example\n For s = \"abcde\", c = \"ae\", the result should be ('bcd', False)\n For s = \"abcdef\", c = \"b\", the result should be ('acdef', False)\n For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc', True)\n \"\"\"\n \n # Create a set of characters to delete for faster lookup\n chars_to_delete = set(c)\n \n # Build the result string by filtering out characters in chars_to_delete\n result = ''.join(char for char in s if char not in chars_to_delete)\n \n # Check if the result string is a palindrome\n is_palindrome = result == result[::-1]\n \n return result, is_palindrome", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3', \"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n \n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in s if char in '13579')\n \n # Create the output string with the count of odd digits\n output_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n \n # Append the result to the list\n result.append(output_string)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n Example\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n \"\"\"\n if not nums:\n raise ValueError(\"The input array must not be empty.\")\n \n # Initialize variables to track the minimum sum and the current sum\n min_sum = float('inf')\n current_sum = 0\n \n for num in nums:\n current_sum += num\n min_sum = min(min_sum, current_sum)\n \n # If current_sum is positive, reset it to 0\n if current_sum > 0:\n current_sum = 0\n \n return min_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n \"\"\"\n Calculate the number of times buckets need to be lowered to empty the wells.\n\n Parameters:\n grid (list of list of int): A rectangular grid representing wells.\n capacity (int): The capacity of each bucket.\n\n Returns:\n int: The total number of times buckets need to be lowered.\n \"\"\"\n total_water = 0\n \n # Count the total amount of water in the grid\n for row in grid:\n total_water += sum(row)\n \n # Calculate the number of times buckets need to be lowered\n if total_water == 0:\n return 0 # No water to extract\n \n # Each bucket can carry 'capacity' units of water\n # We need to lower the buckets enough times to extract all the water\n return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n \"\"\"\n In this Kata, you have to sort an array of non-negative integers according to\n number of ones in their binary representation in ascending order.\n For similar number of ones, sort based on decimal value.\n\n It must be implemented like this:\n >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n >>> sort_array([1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]\n \"\"\"\n # Filter out negative numbers as the problem states non-negative integers\n arr = [x for x in arr if x >= 0]\n \n # Sort the array based on the number of 1s in binary representation and then by value\n return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[-2, -3, -4, -5, -6]]], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n two consonants from the right side of the word (case sensitive).\n \n Vowels in the beginning and ending don't count. Return empty string if you didn't\n find any vowel that meets the above condition. \n\n You may assume that the given string contains English letters only.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n length = len(word)\n\n # Check for edge cases\n if length < 3: # Need at least two consonants and one vowel in between\n return \"\"\n\n # Start from the end of the word\n for i in range(length - 2, 0, -1): # Start from the second last character\n if word[i] in vowels: # Check if the current character is a vowel\n # Check if the characters before and after are consonants\n if word[i - 1].isalpha() and word[i + 1].isalpha() and \\\n word[i - 1] not in vowels and word[i + 1] not in vowels:\n return word[i] # Return the closest vowel found\n\n return \"\" # Return empty string if no valid vowel is found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n \"\"\"Given a string s and a natural number n, returns a list of all words from string s \n that contain exactly n consonants, in the order they appear in the string s.\n \n Args:\n s (str): The input string containing words.\n n (int): The number of consonants to match.\n \n Returns:\n list: A list of words containing exactly n consonants.\n \"\"\"\n \n if not s: # Check if the string is empty\n return []\n \n # Define a set of vowels for easy checking\n vowels = set(\"aeiouAEIOU\")\n \n def count_consonants(word):\n \"\"\"Helper function to count consonants in a word.\"\"\"\n return sum(1 for char in word if char.isalpha() and char not in vowels)\n \n # Split the string into words\n words = s.split()\n \n # Filter words based on the number of consonants\n result = [word for word in words if count_consonants(word) == n]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n \n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Get the top k elements\n top_k = sorted_arr[:k]\n \n # Return the top k elements sorted in ascending order\n return sorted(top_k)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0: # More closing than opening\n return False\n return balance == 0 # Must be balanced at the end\n\n a, b = lst[0], lst[1]\n\n # Check both concatenation orders\n if is_good(a + b) or is_good(b + a):\n return 'Yes'\n else:\n return 'No'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n An even position is defined as an index that is even (0, 2, 4, ...).\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list using index and value\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n total_sum += value\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n \"\"\"\n Given a non-empty array of integers arr and an integer k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example:\n\n Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n Output: 24 # sum of 21 + 3\n\n Constraints:\n 1. 1 <= len(arr) <= 100\n 2. 1 <= k <= len(arr)\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate through the first k elements of the array\n for i in range(k):\n # Check if the current element has at most two digits\n if -100 < arr[i] < 100:\n total_sum += arr[i]\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n as follows: start with any positive integer n. Then each term is obtained from the \n previous term as follows: if the previous term is even, the next term is one half of \n the previous term. If the previous term is odd, the next term is 3 times the previous\n term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n Note: \n 1. Collatz(1) is [1].\n 2. returned list sorted in increasing order.\n\n For example:\n get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n collatz_sequence = []\n \n while n != 1:\n collatz_sequence.append(n)\n if n % 2 == 0:\n n //= 2\n else:\n n = 3 * n + 1\n \n collatz_sequence.append(1) # Append the last term which is 1\n \n # Filter out odd numbers and sort the result\n odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n \n return odd_numbers", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n \n The date is valid if all of the following rules are satisfied:\n 1. The date string is not empty.\n 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n The number of days is not less than 1 or higher than 29 for the month 2.\n 3. The months should not be less than 1 or higher than 12.\n 4. The date should be in the format: mm-dd-yyyy\n \n Args:\n date (str): The date string to validate.\n \n Returns:\n bool: True if the date is valid, False otherwise.\n \"\"\"\n \n # Check if the date string is empty\n if not date:\n return False\n \n # Check if the date is in the correct format\n if len(date) != 10 or date[2] != '-' or date[5] != '-':\n return False\n \n # Split the date into components\n try:\n month, day, year = map(int, date.split('-'))\n except ValueError:\n return False\n \n # Check month range\n if month < 1 or month > 12:\n return False\n \n # Check day range based on month\n if month in {1, 3, 5, 7, 8, 10, 12}:\n if day < 1 or day > 31:\n return False\n elif month in {4, 6, 9, 11}:\n if day < 1 or day > 30:\n return False\n elif month == 2:\n if day < 1 or day > 29:\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n '''\n Given a string of words, return a list of words split on whitespace, \n if no whitespaces exists in the text you should split on commas ',' \n if no commas exists you should return the number of lower-case letters \n with odd order in the alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n \n Examples:\n split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"abcdef\") \u279e 3 \n '''\n \n # Check for whitespace\n if ' ' in txt:\n return txt.split()\n \n # Check for commas\n elif ',' in txt:\n return txt.split(',')\n \n # If no whitespace or commas, count lowercase letters with odd order\n else:\n odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n return odd_count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n '''\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return False. Assume no negative numbers and only integers.\n\n Examples\n is_sorted([5]) \u279e True\n is_sorted([1, 2, 3, 4, 5]) \u279e True\n is_sorted([1, 3, 2, 4, 5]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n '''\n \n if len(lst) <= 1:\n return True # A list with 0 or 1 element is sorted by definition\n\n seen = set()\n previous = None\n\n for num in lst:\n if num in seen:\n # If we see a number again, check if it's the same as the previous\n if num == previous:\n return False # More than 1 duplicate of the same number\n else:\n seen.add(num)\n\n if previous is not None and num < previous:\n return False # Not sorted in ascending order\n\n previous = num\n\n return True", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef intersection(interval1, interval2):\n \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n start1, end1 = interval1\n start2, end2 = interval2\n \n # Find the intersection\n start_intersection = max(start1, start2)\n end_intersection = min(end1, end2)\n \n # Check if there is an intersection\n if start_intersection > end_intersection:\n return \"NO\"\n \n # Calculate the length of the intersection\n length_of_intersection = end_intersection - start_intersection\n \n # Check if the length is a prime number\n if is_prime(length_of_intersection):\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n if not arr: # Check for empty array\n return None\n\n product_of_signs = 1 # Initialize product of signs\n sum_of_magnitudes = 0 # Initialize sum of magnitudes\n\n for num in arr:\n if num > 0:\n sum_of_magnitudes += num # Add magnitude for positive numbers\n elif num < 0:\n sum_of_magnitudes += -num # Add magnitude for negative numbers\n product_of_signs *= -1 # Flip sign for negative numbers\n else:\n product_of_signs = 0 # If any number is zero, product of signs is zero\n break # No need to continue if we hit zero\n\n return product_of_signs * sum_of_magnitudes # Return the final result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n \"\"\"Calculate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n if n < 0:\n return []\n\n # Initialize the list to hold the Tribonacci numbers\n tribonacci_sequence = []\n\n # Define the base case\n for i in range(n + 1):\n if i == 0:\n tribonacci_sequence.append(1) # tri(0) = 1\n elif i == 1:\n tribonacci_sequence.append(3) # tri(1) = 3\n elif i % 2 == 0: # Even case\n tribonacci_sequence.append(1 + i / 2)\n else: # Odd case\n # Calculate tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1)\n tri_n_minus_1 = tribonacci_sequence[i - 1]\n tri_n_minus_2 = tribonacci_sequence[i - 2]\n tri_n_plus_1 = 1 + (i + 1) / 2 if (i + 1) % 2 == 0 else tribonacci_sequence[i + 1]\n tribonacci_sequence.append(tri_n_minus_1 + tri_n_minus_2 + tri_n_plus_1)\n\n return tribonacci_sequence", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n \"\"\"Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n \n Args:\n n (int): A positive integer.\n\n Returns:\n int: The product of the odd digits or 0 if all digits are even.\n \n Examples:\n >>> digits(1)\n 1\n >>> digits(4)\n 0\n >>> digits(235)\n 15\n >>> digits(2468)\n 0\n >>> digits(13579)\n 945\n >>> digits(0) # Edge case: 0 is not a positive integer, should raise ValueError\n Traceback (most recent call last):\n ...\n ValueError: Input must be a positive integer.\n \"\"\"\n \n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n product = 1\n has_odd_digit = False\n \n while n > 0:\n digit = n % 10\n if digit % 2 != 0: # Check if the digit is odd\n product *= digit\n has_odd_digit = True\n n //= 10 # Remove the last digit\n \n return product if has_odd_digit else 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n from collections import deque\n\n N = len(grid)\n directions = [(0, 1), (1, 0), (0, -1), (-1, 0)] # Right, Down, Left, Up\n min_path = None\n\n def bfs(start_row, start_col):\n queue = deque([(start_row, start_col, [grid[start_row][start_col]])])\n while queue:\n row, col, path = queue.popleft()\n if len(path) == k:\n nonlocal min_path\n if min_path is None or path < min_path:\n min_path = path\n continue\n \n for dr, dc in directions:\n new_row, new_col = row + dr, col + dc\n if 0 <= new_row < N and 0 <= new_col < N:\n queue.append((new_row, new_col, path + [grid[new_row][new_col]]))\n\n for i in range(N):\n for j in range(N):\n bfs(i, j)\n\n return min_path", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n '''\n Create a function that takes a string as input which contains only square brackets.\n The function should return True if and only if there is a valid subsequence of brackets \n where at least one bracket in the subsequence is nested.\n\n is_nested('[[]]') \u279e True\n is_nested('[]]]]]]][[[[[]') \u279e False\n is_nested('[][]') \u279e False\n is_nested('[]') \u279e False\n is_nested('[[][]]') \u279e True\n is_nested('[[]][[') \u279e True\n '''\n \n # Initialize a counter for open brackets\n open_count = 0\n # Initialize a flag to check for nesting\n nested = False\n \n for char in string:\n if char == '[':\n open_count += 1\n # If we have more than one open bracket, we have a nested structure\n if open_count > 1:\n nested = True\n elif char == ']':\n open_count -= 1\n # If we close a bracket and there were open brackets, we check for nesting\n if open_count < 0:\n return False # More closing brackets than opening\n # If we have closed all opened brackets, we can reset the nested check\n if open_count == 0:\n nested = False\n \n # We need at least one nested structure and no unmatched brackets\n return nested and open_count == 0", "base_status": "fail", "plus_status": null, "base_fail_tests": [["[[]]"]], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers.\n You need to return the sum of squared numbers in the given list,\n round each element in the list to the upper int (Ceiling) first.\n \n Examples:\n For lst = [1,2,3] the output should be 14\n For lst = [1,4,9] the output should be 98\n For lst = [1,3,5,7] the output should be 84\n For lst = [1.4,4.2,0] the output should be 29\n For lst = [-2.4,1,1] the output should be 6\n \"\"\"\n # Initialize the sum of squares\n total_sum = 0\n \n # Iterate through each number in the list\n for number in lst:\n # Round the number up to the nearest integer\n rounded_number = math.ceil(number)\n # Add the square of the rounded number to the total sum\n total_sum += rounded_number ** 2\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n \"\"\"Create a function which returns the largest index of an element which\n is not greater than or equal to the element immediately preceding it. If\n no such element exists then return -1. The given array will not contain\n duplicate values.\n\n Examples:\n can_arrange([1,2,4,3,5]) = 3\n can_arrange([1,2,3]) = -1\n \"\"\"\n # Check if the array is empty\n if not arr:\n return -1\n\n # Initialize the largest index to -1\n largest_index = -1\n\n # Iterate through the array starting from the second element\n for i in range(1, len(arr)):\n # Check if the current element is less than the previous element\n if arr[i] < arr[i - 1]:\n largest_index = i # Update the largest index\n\n return largest_index", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n '''\n Create a function that returns True if the last character\n of a given string is an alphabetical character and is not\n a part of a word, and False otherwise.\n Note: \"word\" is a group of characters separated by space.\n\n Examples:\n check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '''\n \n # Strip any trailing whitespace from the string\n txt = txt.rstrip()\n \n # Check if the string is empty after stripping\n if not txt:\n return False\n \n # Get the last character of the string\n last_char = txt[-1]\n \n # Check if the last character is an alphabetical character\n if last_char.isalpha():\n # Check if the last character is part of a word\n # A character is part of a word if it is preceded by a non-space character\n if len(txt) > 1 and txt[-2] != ' ':\n return False\n return True\n \n return False", "base_status": "fail", "plus_status": null, "base_fail_tests": [["eeeee e "]], "plus_fail_tests": []}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def parse_number(value):\n \"\"\"\n Convert a string representation of a number to a float or return the value as is.\n Handles both '.' and ',' as decimal separators.\n \"\"\"\n if isinstance(value, str):\n # Replace ',' with '.' for float conversion\n value = value.replace(',', '.')\n try:\n return float(value)\n except ValueError:\n return value # Return the original value if it cannot be converted\ndef compare_one(a, b):\n \"\"\"\n Compare two values (integers, floats, or strings representing real numbers)\n and return the larger one in its original type. Return None if they are equal.\n \"\"\"\n # Parse both values to their numeric representations\n parsed_a = parse_number(a)\n parsed_b = parse_number(b)\n\n # Check for equality\n if parsed_a == parsed_b:\n return None\n\n # Return the larger value in its original type\n if parsed_a > parsed_b:\n return a\n else:\n return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n '''\n Create a function that returns a tuple (a, b), where 'a' is\n the largest of negative integers, and 'b' is the smallest\n of positive integers in a list.\n If there is no negative or positive integers, return them as None.\n\n Examples:\n largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n largest_smallest_integers([]) == (None, None)\n largest_smallest_integers([0]) == (None, None)\n '''\n \n largest_negative = None\n smallest_positive = None\n \n for num in lst:\n if num < 0:\n if largest_negative is None or num > largest_negative:\n largest_negative = num\n elif num > 0:\n if smallest_positive is None or num < smallest_positive:\n smallest_positive = num\n \n return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n \n Args:\n n (int): The number to evaluate.\n \n Returns:\n bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n \n Example:\n is_equal_to_sum_even(4) == False\n is_equal_to_sum_even(6) == False\n is_equal_to_sum_even(8) == True\n \"\"\"\n \n # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n if n < 8:\n return False\n \n # Check if n is even\n if n % 2 != 0:\n return False\n \n # If n is even and n >= 8, we can always express it as the sum of 4 positive even numbers\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n \"\"\"Helper function to compute the factorial of a non-negative integer n.\"\"\"\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef special_factorial(n):\n \"\"\"Calculate the Brazilian factorial of n.\"\"\"\n if n < 1:\n raise ValueError(\"Input must be a positive integer greater than 0.\")\n \n result = 1\n for i in range(1, n + 1):\n result *= factorial(i)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n \"\"\"\n Given a string text, replace all spaces in it with underscores, \n and if a string has more than 2 consecutive spaces, \n then replace all consecutive spaces with - \n \n fix_spaces(\"Example\") == \"Example\"\n fix_spaces(\"Example 1\") == \"Example_1\"\n fix_spaces(\" Example 2\") == \"_Example_2\"\n fix_spaces(\" Example 3\") == \"_Example-3\"\n \"\"\"\n # Replace multiple spaces with a placeholder\n text = text.replace(' ', '-').replace(' ', '_')\n \n # Replace any remaining spaces with underscores\n text = text.replace(' ', '_')\n \n # Handle the case where we might have replaced too many spaces\n # We need to ensure that we replace any remaining instances of\n # more than two spaces with a single '-'\n while ' ' in text:\n text = text.replace(' ', '-')\n \n return text", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Yellow Yellow Dirty Fellow"]], "plus_fail_tests": []}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n \"\"\"Check if the given file name is valid based on specific criteria.\"\"\"\n \n # Define valid extensions\n valid_extensions = ['txt', 'exe', 'dll']\n \n # Check for exactly one dot\n if file_name.count('.') != 1:\n return 'No'\n \n # Split the file name into name and extension\n name, extension = file_name.rsplit('.', 1)\n \n # Check if the name is empty\n if not name:\n return 'No'\n \n # Check if the name starts with a letter\n if not name[0].isalpha():\n return 'No'\n \n # Check if the extension is valid\n if extension not in valid_extensions:\n return 'No'\n \n # Count digits in the file name\n digit_count = sum(c.isdigit() for c in file_name)\n \n # Check if there are more than three digits\n if digit_count > 3:\n return 'No'\n \n return 'Yes'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n \"\"\"\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n \n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126\n \"\"\"\n total_sum = 0\n \n for index, value in enumerate(lst):\n if index % 3 == 0:\n # Square the value if index is a multiple of 3\n total_sum += value ** 2\n elif index % 4 == 0:\n # Cube the value if index is a multiple of 4 and not a multiple of 3\n total_sum += value ** 3\n else:\n # Add the value unchanged if index is not a multiple of 3 or 4\n total_sum += value\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef words_in_sentence(sentence):\n \"\"\"\n Given a string representing a sentence, return a string that contains the words\n from the original sentence whose lengths are prime numbers.\n \n Parameters:\n sentence (str): The input sentence containing words separated by spaces.\n \n Returns:\n str: A string containing the words with prime lengths, in the original order.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Filter words whose lengths are prime\n prime_length_words = [word for word in words if is_prime(len(word))]\n \n # Join the filtered words back into a string\n return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n \"\"\"\n Write a function which sorts the given list of integers\n in ascending order according to the sum of their digits.\n Note: if there are several items with similar sum of their digits,\n order them based on their index in original list.\n\n For example:\n >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n >>> order_by_points([]) == []\n \"\"\"\n \n def digit_sum(n):\n \"\"\"Calculate the sum of the digits of an integer n.\"\"\"\n return sum(int(digit) for digit in str(abs(n)))\n\n # Create a list of tuples (digit_sum, index, value)\n indexed_nums = [(digit_sum(num), index, num) for index, num in enumerate(nums)]\n \n # Sort by digit sum first, then by original index\n sorted_nums = sorted(indexed_nums, key=lambda x: (x[0], x[1]))\n \n # Extract the sorted values\n return [num for _, _, num in sorted_nums]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n \"\"\"Simplifies the expression x * n and checks if the result is a whole number.\n \n Args:\n x (str): A string representation of a fraction in the format /.\n n (str): A string representation of a fraction in the format /.\n \n Returns:\n bool: True if x * n evaluates to a whole number, False otherwise.\n \"\"\"\n # Split the fractions into numerator and denominator\n x_numerator, x_denominator = map(int, x.split('/'))\n n_numerator, n_denominator = map(int, n.split('/'))\n \n # Calculate the product of the fractions\n # x * n = (x_numerator / x_denominator) * (n_numerator / n_denominator)\n # This simplifies to (x_numerator * n_numerator) / (x_denominator * n_denominator)\n \n product_numerator = x_numerator * n_numerator\n product_denominator = x_denominator * n_denominator\n \n # Check if the product is a whole number\n return product_numerator % product_denominator == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n \"\"\"Returns the number of elements in the array that are greater than 10 \n and both the first and last digits of the number are odd (1, 3, 5, 7, 9).\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n int: The count of numbers meeting the criteria.\n \"\"\"\n \n def is_odd_digit(digit):\n \"\"\"Check if a digit is odd.\"\"\"\n return digit in {'1', '3', '5', '7', '9'}\n \n def first_and_last_digits_are_odd(num):\n \"\"\"Check if both the first and last digits of the number are odd.\"\"\"\n num_str = str(abs(num)) # Convert to string and take absolute value\n return is_odd_digit(num_str[0]) and is_odd_digit(num_str[-1])\n \n count = 0\n for num in nums:\n if num > 10 and first_and_last_digits_are_odd(num):\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n \"\"\"\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example :\n Input: n = 5\n Output: 1\n Explanation: \n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n \"\"\"\n # Create the array a based on the given formula\n a = [i * i - i + 1 for i in range(1, n + 1)]\n \n # Count the number of valid triples\n count = 0\n \n # Iterate through all possible triples (i, j, k)\n for i in range(n):\n for j in range(i + 1, n):\n for k in range(j + 1, n):\n if (a[i] + a[j] + a[k]) % 3 == 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length and alphabetically.\n \n Args:\n lst (list of str): A list of strings.\n \n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closest to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sorted by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct planet names. \n Examples\n bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n '''\n\n # List of planets in order from the Sun\n planets = [\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n ]\n \n # Check if the input planets are valid\n if planet1 not in planets or planet2 not in planets:\n return ()\n \n # Get the indices of the planets\n index1 = planets.index(planet1)\n index2 = planets.index(planet2)\n \n # Determine the range of indices\n start_index = min(index1, index2) + 1\n end_index = max(index1, index2)\n \n # Get the planets in between\n in_between_planets = planets[start_index:end_index]\n \n # Return the result as a tuple\n return tuple(in_between_planets)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n \n double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n double_the_difference([-1, -2, 0]) == 0\n double_the_difference([9, -2]) == 81\n double_the_difference([0]) == 0 \n \n If the input list is empty, return 0.\n '''\n # Initialize the sum of squares\n sum_of_squares = 0\n \n # Iterate through each number in the list\n for num in lst:\n # Check if the number is a positive odd integer\n if isinstance(num, int) and num >= 0 and num % 2 != 0:\n # Add the square of the odd number to the sum\n sum_of_squares += num ** 2\n \n return sum_of_squares", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef x_or_y(n, x, y):\n \"\"\"Return the value of x if n is a prime number, otherwise return y.\"\"\"\n if is_prime(n):\n return x\n else:\n return y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n \"\"\"\n Compares the actual game scores with the guessed scores and returns an array\n indicating how far off each guess was. If the guess is correct, the value is 0,\n otherwise it is the absolute difference between the guess and the actual score.\n\n Parameters:\n game (list of int): The actual scores of the matches.\n guess (list of int): The guessed scores of the matches.\n\n Returns:\n list of int: An array of absolute differences or zeros for correct guesses.\n \"\"\"\n # Check if the lengths of game and guess are equal\n if len(game) != len(guess):\n raise ValueError(\"The length of game and guess must be the same.\")\n\n # Calculate the absolute differences\n result = [abs(g - s) for g, s in zip(guess, game)]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n \"\"\"Find the strongest extension based on the defined strength criteria.\"\"\"\n \n def calculate_strength(extension):\n \"\"\"Calculate the strength of the extension.\"\"\"\n CAP = sum(1 for char in extension if char.isupper())\n SM = sum(1 for char in extension if char.islower())\n return CAP - SM\n\n strongest_extension = None\n strongest_strength = float('-inf') # Start with the lowest possible strength\n\n for extension in extensions:\n strength = calculate_strength(extension)\n \n # Check if this extension is stronger or if it's the first one\n if strength > strongest_strength:\n strongest_strength = strength\n strongest_extension = extension\n\n if strongest_extension is not None:\n return f\"{class_name}.{strongest_extension}\"\n else:\n return None # In case there are no extensions", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n \"\"\"Check if the second word or any of its rotations is a substring in the first word.\n \n Args:\n a (str): The first word.\n b (str): The second word.\n \n Returns:\n bool: True if the second word or any of its rotations is a substring of the first word, False otherwise.\n \n Examples:\n cycpattern_check(\"abcd\", \"abd\") => False\n cycpattern_check(\"hello\", \"ell\") => True\n cycpattern_check(\"whassup\", \"psus\") => False\n cycpattern_check(\"abab\", \"baa\") => True\n cycpattern_check(\"efef\", \"eeff\") => False\n cycpattern_check(\"himenss\", \"simen\") => True\n \"\"\"\n \n # Edge case: if b is empty, it is considered a substring of any string\n if not b:\n return True\n \n # Edge case: if b is longer than a, it cannot be a substring\n if len(b) > len(a):\n return False\n \n # Create a string that contains two copies of b concatenated\n # This allows us to check for all rotations of b\n double_b = b + b\n \n # Check if any rotation of b is a substring of a\n for i in range(len(b)):\n rotation = double_b[i:i + len(b)]\n if rotation in a:\n return True\n \n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n Example:\n even_odd_count(-12) ==> (1, 1)\n even_odd_count(123) ==> (1, 2)\n \"\"\"\n # Convert the number to a string and handle negative sign\n num_str = str(abs(num))\n \n even_count = 0\n odd_count = 0\n \n for digit in num_str:\n if digit.isdigit(): # Ensure we are only counting digits\n if int(digit) % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n \n if not (1 <= number <= 1000):\n raise ValueError(\"Input must be between 1 and 1000 inclusive.\")\n \n # Mapping of integers to their Roman numeral equivalents\n roman_numerals = [\n (1000, 'm'),\n (900, 'cm'),\n (500, 'd'),\n (400, 'cd'),\n (100, 'c'),\n (90, 'xc'),\n (50, 'l'),\n (40, 'xl'),\n (10, 'x'),\n (9, 'ix'),\n (5, 'v'),\n (4, 'iv'),\n (1, 'i')\n ]\n \n result = []\n \n for value, numeral in roman_numerals:\n while number >= value:\n result.append(numeral)\n number -= value\n \n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return True if the three\n sides form a right-angled triangle, False otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or \n 90 degree.\n \n Example:\n right_angle_triangle(3, 4, 5) == True\n right_angle_triangle(1, 2, 3) == False\n '''\n \n # First, we need to check if the sides can form a triangle\n if a <= 0 or b <= 0 or c <= 0:\n return False # Sides must be positive\n \n # Sort the sides to easily identify the longest side\n sides = sorted([a, b, c])\n \n # Check the Pythagorean theorem: a^2 + b^2 = c^2\n return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n \"\"\"Return the word with the maximum number of unique characters.\n If multiple words have the same maximum number of unique characters,\n return the one that comes first in lexicographical order.\n \n Args:\n words (list of str): A list of words to evaluate.\n \n Returns:\n str: The word with the maximum number of unique characters.\n \"\"\"\n max_word = \"\"\n max_unique_count = 0\n\n for word in words:\n # Calculate the number of unique characters in the word\n unique_count = len(set(word))\n \n # Check if this word has more unique characters or is lexicographically smaller\n if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n max_word = word\n max_unique_count = unique_count\n\n return max_word", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n \"\"\"\n You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n \n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n \n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots that exist in stock\n \n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n \"\"\"\n \n # Calculate how many more carrots are needed\n additional_needed = need - number\n \n if additional_needed <= 0:\n # Already eaten enough or more than needed\n return [number, remaining]\n \n # If there are enough remaining carrots to satisfy the need\n if remaining >= additional_needed:\n total_eaten = number + additional_needed\n carrots_left = remaining - additional_needed\n return [total_eaten, carrots_left]\n else:\n # Not enough remaining carrots, eat all remaining\n total_eaten = number + remaining\n return [total_eaten, 0]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic algebra operations, and \n the second list is a list of integers. Use the two given lists to build the algebraic \n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + ) \n Subtraction ( - ) \n Multiplication ( * ) \n Floor division ( // ) \n Exponentiation ( ** ) \n\n Example:\n operator = ['+', '*', '-']\n operand = [2, 3, 4, 5]\n result = 2 + 3 * 4 - 5\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.\n \"\"\"\n \n # Start with the first operand\n result = operand[0]\n \n # Iterate through the operators and operands\n for i in range(len(operator)):\n op = operator[i]\n next_operand = operand[i + 1]\n \n if op == '+':\n result += next_operand\n elif op == '-':\n result -= next_operand\n elif op == '*':\n result *= next_operand\n elif op == '//':\n # Handle division by zero\n if next_operand == 0:\n raise ValueError(\"Division by zero is not allowed.\")\n result //= next_operand\n elif op == '**':\n result **= next_operand\n else:\n raise ValueError(f\"Invalid operator: {op}\")\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": []}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n \"\"\"You are given a string s.\n If s[i] is a letter, reverse its case from lower to upper or vice versa,\n otherwise keep it as it is.\n If the string contains no letters, reverse the string.\n The function should return the resulted string.\n \n Examples:\n solve(\"1234\") = \"4321\"\n solve(\"ab\") = \"AB\"\n solve(\"#a@C\") = \"#A@c\"\n \"\"\"\n # Check if there are any letters in the string\n has_letters = any(c.isalpha() for c in s)\n \n if has_letters:\n # If there are letters, reverse their case\n result = ''.join(c.upper() if c.islower() else c.lower() for c in s)\n else:\n # If there are no letters, reverse the string\n result = s[::-1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascending order.\n\n For example:\n generate_integers(2, 8) => [2, 4, 6, 8]\n generate_integers(8, 2) => [2, 4, 6, 8]\n generate_integers(10, 14) => []\n \"\"\"\n # Ensure a and b are positive integers\n if a <= 0 or b <= 0:\n raise ValueError(\"Both a and b must be positive integers.\")\n\n # Determine the range of numbers to consider\n start = min(a, b)\n end = max(a, b)\n\n # Generate a list of even integers in the specified range\n even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n return even_integers", "base_status": "fail", "plus_status": null, "base_fail_tests": [[2, 10]], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string.\n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n >>> string_to_md5('') is None\n >>> string_to_md5('Python') == '5d41402abc4b2a76b9719d911017c592'\n >>> string_to_md5('OpenAI') == 'f3b2e1c1c1c1c1c1c1c1c1c1c1c1c1c1'\n >>> string_to_md5('123456') == 'e10adc3949ba59abbe56e057f20f883e'\n \"\"\"\n if text == \"\":\n return None\n # Create an MD5 hash object\n md5_hash = hashlib.md5()\n # Update the hash object with the bytes of the string\n md5_hash.update(text.encode('utf-8'))\n # Return the hexadecimal digest of the hash\n return md5_hash.hexdigest()", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}]}} \ No newline at end of file diff --git a/llm_based_128_eval_results.json b/llm_based_128_eval_results.json new file mode 100644 index 000000000..3ac1879e1 --- /dev/null +++ b/llm_based_128_eval_results.json @@ -0,0 +1 @@ +{"date": "2024-07-26 22:54", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" \n Input to this function is a string containing multiple groups of nested parentheses. \n The goal is to separate those groups into separate strings and return the list of those.\n Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n Ignore any spaces in the input string.\n \n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n # Remove spaces from the input string\n paren_string = paren_string.replace(\" \", \"\")\n \n result = []\n current_group = []\n balance = 0\n \n for char in paren_string:\n if char == '(':\n if balance == 0 and current_group:\n # If we are starting a new group, save the current one\n result.append(''.join(current_group))\n current_group = []\n current_group.append(char)\n balance += 1\n elif char == ')':\n current_group.append(char)\n balance -= 1\n \n # If balance goes negative, it means there's an unmatched closing parenthesis\n if balance < 0:\n raise ValueError(\"Unmatched closing parenthesis found.\")\n \n # If balance is zero, we have a complete group\n if balance == 0 and current_group:\n result.append(''.join(current_group))\n current_group = []\n \n # If there's any unmatched opening parenthesis left\n if balance > 0:\n raise ValueError(\"Unmatched opening parenthesis found.\")\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n >>> has_close_elements([], 0.5)\n False\n >>> has_close_elements([1.0], 0.5)\n False\n >>> has_close_elements([1.0, 1.4], 0.5)\n True\n >>> has_close_elements([1.0, 1.4, 1.8], 0.5)\n True\n >>> has_close_elements([1.0, 2.0, 2.4], 0.5)\n True\n >>> has_close_elements([1.0, 2.0, 2.5], 0.5)\n False\n \"\"\"\n # Edge case: if the list has less than 2 elements, return False\n if len(numbers) < 2:\n return False\n \n # Sort the numbers to make it easier to find close elements\n sorted_numbers = sorted(numbers)\n \n # Check the differences between consecutive elements\n for i in range(len(sorted_numbers) - 1):\n if abs(sorted_numbers[i] - sorted_numbers[i + 1]) < threshold:\n return True\n \n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into\n an integer part (largest integer smaller than given number) and decimals\n (leftover part always smaller than 1).\n\n Return the decimal part of the number.\n \n >>> truncate_number(3.5)\n 0.5\n >>> truncate_number(5.0)\n 0.0\n >>> truncate_number(0.99)\n 0.99\n >>> truncate_number(10.12345)\n 0.12345\n >>> truncate_number(1.0)\n 0.0\n >>> truncate_number(0.0)\n 0.0\n >>> truncate_number(2.71828)\n 0.71828\n \"\"\"\n if number < 0:\n raise ValueError(\"The number must be positive.\")\n \n integer_part = int(number) # Get the integer part\n decimal_part = number - integer_part # Calculate the decimal part\n return decimal_part", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" \n You're given a list of deposit and withdrawal operations on a bank account that starts with\n zero balance. Your task is to detect if at any point the balance of account falls below zero, and\n at that point function should return True. Otherwise it should return False.\n \n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n >>> below_zero([-1])\n True\n >>> below_zero([0, 0, 0])\n False\n >>> below_zero([-1, 1])\n False\n >>> below_zero([-1, -1, -1])\n True\n >>> below_zero([1, -1, -1])\n True\n >>> below_zero([])\n False\n \"\"\"\n balance = 0\n for operation in operations:\n balance += operation\n if balance < 0:\n return True\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n >>> mean_absolute_deviation([])\n 0.0\n >>> mean_absolute_deviation([5.0])\n 0.0\n >>> mean_absolute_deviation([1.0, 1.0, 1.0])\n 0.0\n >>> mean_absolute_deviation([-1.0, 0.0, 1.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list as there is no deviation\n\n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n \"\"\"Insert a number 'delimiter' between every two consecutive elements of input list `numbers`.\n \n Args:\n numbers (List[int]): A list of integers.\n delimiter (int): An integer to insert between the elements of the list.\n \n Returns:\n List[int]: A new list with the delimiter inserted between elements.\n \n Examples:\n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n for i in range(len(numbers)):\n result.append(numbers[i])\n if i < len(numbers) - 1: # Avoid adding delimiter after the last element\n result.append(delimiter)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" \n Filter an input list of strings only for ones that contain the given substring.\n \n Args:\n strings (List[str]): A list of strings to filter.\n substring (str): The substring to search for within the strings.\n \n Returns:\n List[str]: A list of strings that contain the given substring.\n \n Examples:\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n >>> filter_by_substring(['hello', 'world'], 'o')\n ['hello', 'world']\n >>> filter_by_substring(['test', 'example', 'sample'], 'x')\n ['example']\n >>> filter_by_substring(['case', 'test', 'string'], 'z')\n []\n >>> filter_by_substring(['a', 'b', 'c'], 'a')\n ['a']\n >>> filter_by_substring(['', 'non-empty', ''], '')\n ['', 'non-empty', '']\n \"\"\"\n return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n def max_depth(group: str) -> int:\n \"\"\" Helper function to calculate the maximum depth of nested parentheses in a single group. \"\"\"\n current_depth = 0\n max_depth = 0\n \n for char in group:\n if char == '(':\n current_depth += 1\n max_depth = max(max_depth, current_depth)\n elif char == ')':\n current_depth -= 1\n if current_depth < 0: # More closing than opening parentheses\n return -1 # Invalid group\n return max_depth if current_depth == 0 else -1 # Valid if all opened are closed\n\n # Split the input string into groups and calculate the max depth for each\n groups = paren_string.split()\n depths = []\n \n for group in groups:\n depth = max_depth(group)\n if depth == -1:\n depths.append(0) # If invalid, we can choose to append 0 or raise an error\n else:\n depths.append(depth)\n \n return depths", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \n >>> rolling_max([])\n []\n \n >>> rolling_max([-1, -2, -3, -4])\n [-1, -1, -1, -1]\n \n >>> rolling_max([5])\n [5]\n \n >>> rolling_max([1, 1, 1, 1])\n [1, 1, 1, 1]\n \n >>> rolling_max([3, 1, 4, 1, 5, 9, 2, 6, 5])\n [3, 3, 4, 4, 5, 9, 9, 9, 9]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = []\n current_max = numbers[0]\n \n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n \n return rolling_max_list", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n \n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n >>> sum_product([-1, -2, -3])\n (-6, -6)\n >>> sum_product([0, 1, 2])\n (3, 0)\n >>> sum_product([5])\n (5, 5)\n >>> sum_product([1, 0, 2])\n (3, 0)\n \"\"\"\n if not numbers:\n return (0, 1)\n \n total_sum = sum(numbers)\n total_product = 1\n for number in numbers:\n total_product *= number\n \n return (total_sum, total_product)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n \"\"\" \n Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n \n >>> string_xor('010', '110')\n '100'\n >>> string_xor('111', '000')\n '111'\n >>> string_xor('000', '000')\n '000'\n >>> string_xor('101010', '010101')\n '111111'\n >>> string_xor('1', '0')\n '1'\n >>> string_xor('0', '1')\n '1'\n >>> string_xor('', '')\n ''\n >>> string_xor('1', '')\n '1'\n >>> string_xor('', '1')\n '1'\n \"\"\"\n \n # Ensure both strings are of the same length by padding the shorter one with leading zeros\n max_length = max(len(a), len(b))\n a = a.zfill(max_length)\n b = b.zfill(max_length)\n \n # Perform XOR operation\n result = []\n for bit_a, bit_b in zip(a, b):\n result.append('1' if bit_a != bit_b else '0')\n \n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n \n >>> make_palindrome('')\n ''\n >>> make_palindrome('cat')\n 'catac'\n >>> make_palindrome('cata')\n 'catac'\n >>> make_palindrome('race')\n 'racecar'\n >>> make_palindrome('a')\n 'a'\n >>> make_palindrome('ab')\n 'aba'\n \"\"\"\n if not string:\n return string # Return empty string if input is empty\n\n # Find the longest palindromic suffix\n for i in range(len(string)):\n if is_palindrome(string[i:]):\n # If the suffix is a palindrome, we need to append the reverse of the prefix\n prefix = string[:i]\n return string + prefix[::-1]\n\n # If no palindromic suffix is found, the entire string is returned with its reverse\n return string + string[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n \n >>> longest([])\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n >>> longest(['abc', 'ab', 'a'])\n 'abc'\n >>> longest(['', 'a', 'ab'])\n 'ab'\n >>> longest(['longest', 'longer', 'long'])\n 'longest'\n >>> longest(['same', 'size', 'test'])\n 'same'\n \"\"\"\n if not strings:\n return None\n \n longest_string = strings[0]\n \n for string in strings[1:]:\n if len(string) > len(longest_string):\n longest_string = string\n \n return longest_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return the greatest common divisor of two integers a and b.\n \n The function uses the Euclidean algorithm to compute the GCD.\n \n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n >>> greatest_common_divisor(0, 5)\n 5\n >>> greatest_common_divisor(5, 0)\n 5\n >>> greatest_common_divisor(0, 0)\n 0\n >>> greatest_common_divisor(-25, 15)\n 5\n >>> greatest_common_divisor(25, -15)\n 5\n >>> greatest_common_divisor(-25, -15)\n 5\n \"\"\"\n if a == 0 and b == 0:\n return 0 # GCD is undefined for (0, 0)\n \n a, b = abs(a), abs(b) # Work with absolute values\n while b:\n a, b = b, a % b\n return a", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string.\n \n Args:\n string (str): The input string from which to generate prefixes.\n \n Returns:\n List[str]: A list of all prefixes of the input string.\n \n Examples:\n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n >>> all_prefixes('')\n []\n >>> all_prefixes('a')\n ['a']\n >>> all_prefixes('hello')\n ['h', 'he', 'hel', 'hell', 'hello']\n \"\"\"\n # Initialize an empty list to store prefixes\n prefixes = []\n \n # Iterate through the string and collect prefixes\n for i in range(1, len(string) + 1):\n prefixes.append(string[:i])\n \n return prefixes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" \n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n >>> count_distinct_characters('')\n 0\n >>> count_distinct_characters('aA')\n 1\n >>> count_distinct_characters('123abcABC!@#')\n 9\n >>> count_distinct_characters(' ')\n 0\n >>> count_distinct_characters('!@#$%^&*()')\n 10\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set()\n \n # Iterate through each character in the string\n for char in lower_string:\n # Add only non-space characters to the set\n if char != ' ':\n distinct_characters.add(char)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Jerry jERRY JeRRRY"]], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n \n Args:\n n (int): The upper limit of the sequence (inclusive).\n \n Returns:\n str: A space-delimited string of numbers from 0 to n.\n \n Examples:\n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n \"\"\"\n if n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n # Create a list of numbers from 0 to n\n numbers = [str(i) for i in range(n + 1)]\n \n # Join the list into a single string with spaces\n return ' '.join(numbers)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string representing musical notes in a special ASCII format.\n Your task is to parse this string and return list of integers corresponding to how many beats does each\n note last.\n\n Here is a legend:\n 'o' - whole note, lasts four beats\n 'o|' - half note, lasts two beats\n '.|' - quarter note, lasts one beat\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n # Initialize an empty list to store the beats\n beats = []\n \n # Split the input string by spaces to get individual notes\n notes = music_string.split()\n \n # Define a mapping of note representations to their corresponding beats\n note_to_beats = {\n 'o': 4, # whole note\n 'o|': 2, # half note\n '.|': 1 # quarter note\n }\n \n # Iterate through each note and append the corresponding beats to the list\n for note in notes:\n if note in note_to_beats:\n beats.append(note_to_beats[note])\n else:\n # If an unknown note is encountered, raise an error\n raise ValueError(f\"Unknown note representation: '{note}'\")\n \n return beats", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n \n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n >>> how_many_times('abcabcabc', 'abc')\n 3\n >>> how_many_times('abababab', 'aba')\n 4\n >>> how_many_times('hello', 'lo')\n 1\n >>> how_many_times('hello', 'hello')\n 1\n >>> how_many_times('hello', 'world')\n 0\n >>> how_many_times('aaaaaa', 'aa')\n 5\n >>> how_many_times('abc', '')\n 0\n >>> how_many_times('', '')\n 1\n \"\"\"\n if not substring:\n return 0\n if not string:\n return 0\n \n count = 0\n start = 0\n \n while True:\n start = string.find(substring, start)\n if start == -1:\n break\n count += 1\n start += 1 # Move one character forward to allow for overlapping matches\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n \"\"\" \n Input is a space-delimited string of numerals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest.\n \n >>> sort_numbers('three one five')\n 'one three five'\n >>> sort_numbers('nine eight seven six five four three two one zero')\n 'zero one two three four five six seven eight nine'\n >>> sort_numbers('zero')\n 'zero'\n >>> sort_numbers('')\n ''\n >>> sort_numbers('five five four four')\n 'four four five five'\n \"\"\"\n \n # Mapping of words to their corresponding numeric values\n word_to_number = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n \n # Reverse mapping for sorting back to words\n number_to_word = {v: k for k, v in word_to_number.items()}\n \n # Split the input string into words\n words = numbers.split()\n \n # Convert words to their corresponding numeric values\n numeric_values = [word_to_number[word] for word in words]\n \n # Sort the numeric values\n numeric_values.sort()\n \n # Convert sorted numeric values back to words\n sorted_words = [number_to_word[num] for num in numeric_values]\n \n # Join the sorted words into a single string\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n >>> find_closest_elements([1.0, 1.0, 1.0, 1.0])\n (1.0, 1.0)\n >>> find_closest_elements([-1.0, -2.0, -3.0, -1.5])\n (-1.5, -1.0)\n >>> find_closest_elements([0.0, 0.1, 0.2, 0.3])\n (0.0, 0.1)\n \"\"\"\n \n # Sort the numbers to make it easier to find the closest pairs\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest elements\n for i in range(len(sorted_numbers) - 1):\n # Calculate the difference between consecutive elements\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n \n # If this difference is smaller than the minimum found so far, update\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1.\n \n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n \n >>> rescale_to_unit([10.0, 20.0, 30.0])\n [0.0, 0.5, 1.0]\n \n >>> rescale_to_unit([5.0, 5.0, 5.0])\n [0.0, 0.0, 0.0]\n \n >>> rescale_to_unit([-1.0, 0.0, 1.0])\n [0.0, 0.5, 1.0]\n \n >>> rescale_to_unit([0.0, 0.0, 0.0])\n [0.0, 0.0, 0.0]\n \n >>> rescale_to_unit([1.0, 1.0, 2.0])\n [0.0, 0.0, 1.0]\n \"\"\"\n \n if len(numbers) < 2:\n raise ValueError(\"The input list must contain at least two elements.\")\n \n min_val = min(numbers)\n max_val = max(numbers)\n \n if min_val == max_val:\n # All numbers are the same\n return [0.0] * len(numbers)\n \n # Rescale the numbers\n return [(num - min_val) / (max_val - min_val) for num in numbers]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n \"\"\" Return length of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n >>> strlen('a')\n 1\n >>> strlen('Hello, World!')\n 13\n >>> strlen(' ') # String with spaces\n 3\n >>> strlen('\ud83d\ude0a') # String with a Unicode character\n 2\n >>> strlen('abc\\nxyz') # String with newline character\n 8\n >>> strlen('') # Edge case: empty string\n 0\n \"\"\"\n return len(string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers.\n \n Args:\n values (List[Any]): A list containing any type of Python values.\n \n Returns:\n List[int]: A list containing only the integers from the input list.\n \n Examples:\n >>> filter_integers(['a', 3.14, 5])\n [5]\n >>> filter_integers([1, 2, 3, 'abc', {}, []])\n [1, 2, 3]\n >>> filter_integers([None, True, False, 0, 1, 2])\n [0, 1, 2]\n >>> filter_integers([])\n []\n >>> filter_integers([1.0, 2.0, 3.0])\n []\n >>> filter_integers(['1', '2', 1, 2])\n [1, 2]\n \"\"\"\n return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n \n Args:\n n (int): The number to find the largest divisor for.\n \n Returns:\n int: The largest divisor of n that is smaller than n.\n \n Raises:\n ValueError: If n is less than or equal to 1, as there are no divisors in that case.\n \n Examples:\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(10)\n 5\n >>> largest_divisor(1)\n Traceback (most recent call last):\n ...\n ValueError: No divisors for numbers less than or equal to 1.\n >>> largest_divisor(2)\n 1\n >>> largest_divisor(100)\n 50\n \"\"\"\n if n <= 1:\n raise ValueError(\"No divisors for numbers less than or equal to 1.\")\n \n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n Input number should be equal to the product of all factors.\n \n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n >>> factorize(1)\n []\n >>> factorize(0)\n Traceback (most recent call last):\n ...\n ValueError: Input must be a positive integer.\n >>> factorize(-10)\n Traceback (most recent call last):\n ...\n ValueError: Input must be a positive integer.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n factors = []\n # Check for number of 2s that divide n\n while n % 2 == 0:\n factors.append(2)\n n //= 2\n \n # n must be odd at this point so a skip of 2 (i.e., i = i + 2) can be used\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, append i and divide n\n while n % i == 0:\n factors.append(i)\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n factors.append(n)\n \n return factors", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([1, 1, 1, 1])\n []\n >>> remove_duplicates([1, 2, 3])\n [1, 2, 3]\n >>> remove_duplicates([])\n []\n >>> remove_duplicates([1, 2, 3, 4, 5, 1, 2, 3])\n [4, 5]\n >>> remove_duplicates([5, 5, 6, 7, 6, 8])\n [7, 8]\n >>> remove_duplicates([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])\n [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n \n # Create a new list with only unique elements\n result = [number for number in numbers if count[number] == 1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n \n >>> flip_case('Hello')\n 'hELLO'\n >>> flip_case('WORLD')\n 'world'\n >>> flip_case('Python3')\n 'pYTHON3'\n >>> flip_case('12345')\n '12345'\n >>> flip_case('')\n ''\n >>> flip_case('!@#$%^&*()')\n '!@#$%^&*()'\n >>> flip_case('Mixed CASE 123 !@#')\n 'mIXED case 123 !@#'\n \"\"\"\n return ''.join(char.swapcase() for char in string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string.\n \n Args:\n strings (List[str]): A list of strings to concatenate.\n \n Returns:\n str: A single concatenated string.\n \n Examples:\n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n >>> concatenate(['Hello', ' ', 'World', '!'])\n 'Hello World!'\n >>> concatenate(['Python', 'is', 'fun'])\n 'Pythonisfun'\n >>> concatenate(['', 'empty', 'string'])\n 'emptysstring'\n >>> concatenate(['a' * 1000] * 1000) # Large input\n 'a' * 1000000\n \"\"\"\n # Using join to concatenate the list of strings efficiently\n return ''.join(strings)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" \n Filter an input list of strings only for ones that start with a given prefix.\n \n Args:\n strings (List[str]): A list of strings to filter.\n prefix (str): The prefix to filter the strings by.\n \n Returns:\n List[str]: A list of strings that start with the given prefix.\n \n Examples:\n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n >>> filter_by_prefix(['apple', 'banana', 'apricot', 'grape'], 'ap')\n ['apple', 'apricot']\n >>> filter_by_prefix(['hello', 'world'], 'h')\n ['hello']\n >>> filter_by_prefix(['hello', 'world'], 'z')\n []\n >>> filter_by_prefix(['', 'test', ''], '')\n ['', 'test', '']\n >>> filter_by_prefix(['abc', 'def', 'ghi'], 'abcdef')\n []\n \"\"\"\n return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n \n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n >>> get_positive([]) # Edge case: empty list\n []\n >>> get_positive([-1, -2, -3]) # Edge case: all negative numbers\n []\n >>> get_positive([0]) # Edge case: single zero\n []\n >>> get_positive([1, 0, -1]) # Mixed numbers with zero\n [1]\n >>> get_positive([10, 20, 30, 0]) # Edge case: positive numbers with zero\n [10, 20, 30]\n \"\"\"\n return [x for x in l if x > 0]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n A prime number is a natural number greater than 1 that cannot be formed by multiplying two smaller natural numbers.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n >>> is_prime(0)\n False\n >>> is_prime(-5)\n False\n >>> is_prime(2)\n True\n >>> is_prime(3)\n True\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return False # eliminate multiples of 2 and 3\n\n i = 5\n while i * i <= n: # check for factors from 5 to sqrt(n)\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6 # check for next potential factors (6k \u00b1 1)\n\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n >>> sort_third([])\n []\n >>> sort_third([10, 20, 30, 40, 50, 60, 70, 80, 90])\n [10, 20, 30, 40, 50, 60, 70, 80, 90]\n >>> sort_third([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])\n [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]\n >>> sort_third([3, 1, 4, 1, 5, 9, 2, 6, 5, 3])\n [2, 1, 4, 1, 5, 3, 3, 6, 5, 9]\n \"\"\"\n # Extract values at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(divisible_by_three)\n \n # Create a new list to hold the result\n result = l.copy()\n \n # Replace values at indices divisible by 3 with sorted values\n for i, value in enumerate(sorted_values):\n result[i * 3] = value\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float) -> float:\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list) -> list:\n \"\"\"\n Computes the derivative of the polynomial with coefficients xs.\n The derivative is calculated as: \n d/dx (a0 + a1*x + a2*x^2 + ... + an*x^n) = a1 + 2*a2*x + ... + n*an*x^(n-1)\n \"\"\"\n return [i * coeff for i, coeff in enumerate(xs) if i > 0]\ndef find_zero(xs: list, initial_guess: float = 0.0, tolerance: float = 1e-7, max_iterations: int = 1000) -> float:\n \"\"\" \n xs are coefficients of a polynomial.\n find_zero finds x such that poly(x) = 0.\n find_zero returns only one zero point, even if there are many.\n Moreover, find_zero only takes list xs having an even number of coefficients\n and the largest non-zero coefficient as it guarantees a solution.\n \n >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n -0.5\n >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n 1.0\n \"\"\"\n if len(xs) % 2 != 0:\n raise ValueError(\"The number of coefficients must be even.\")\n \n # Initial guess for the root\n x = initial_guess\n for _ in range(max_iterations):\n f_x = poly(xs, x)\n f_prime_x = poly(derivative(xs), x)\n \n if abs(f_prime_x) < tolerance: # Avoid division by zero\n raise ValueError(\"Derivative is too small; no convergence.\")\n \n x_new = x - f_x / f_prime_x\n \n if abs(x_new - x) < tolerance: # Convergence check\n return x_new\n \n x = x_new\n \n raise ValueError(\"Maximum iterations reached; no convergence.\")", "base_status": "fail", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n \"\"\"Return maximum element in the list.\n \n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n >>> max_element([]) # Edge case: empty list\n Traceback (most recent call last):\n ...\n ValueError: The list is empty.\n >>> max_element(['a', 1, 2]) # Edge case: non-numeric elements\n Traceback (most recent call last):\n ...\n TypeError: All elements in the list must be numbers.\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty.\")\n \n max_value = l[0]\n \n for item in l:\n if not isinstance(item, (int, float)):\n raise TypeError(\"All elements in the list must be numbers.\")\n if item > max_value:\n max_value = item\n \n return max_value", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \n >>> unique([]) # Edge case: empty list\n []\n \n >>> unique([1]) # Edge case: single element\n [1]\n \n >>> unique([1, 1, 1]) # Edge case: all elements the same\n [1]\n \n >>> unique([-1, 0, 1]) # Edge case: negative, zero, and positive\n [-1, 0, 1]\n \n >>> unique([3.5, 2.2, 3.5, 1.1]) # Edge case: float values\n [1.1, 2.2, 3.5]\n \n >>> unique(['apple', 'banana', 'apple']) # Edge case: string values\n ['apple', 'banana']\n \n >>> unique([None, None, 1, 2]) # Edge case: None values\n [None, 1, 2]\n \"\"\"\n return sorted(set(l))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n >>> sort_even([10, 20, 30, 40, 50])\n [30, 20, 10, 40, 50]\n >>> sort_even([1])\n [1]\n >>> sort_even([])\n []\n >>> sort_even([2, 1])\n [2, 1]\n >>> sort_even([1, 2, 3, 4, 5, 6])\n [3, 2, 1, 4, 5, 6]\n \"\"\"\n # Extract even indexed elements\n even_indices = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indexed elements\n even_indices_sorted = sorted(even_indices)\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Place the sorted even indexed elements back into their positions\n for i, sorted_value in enumerate(even_indices_sorted):\n result[i * 2] = sorted_value\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_fib(n: int) -> int:\n \"\"\"\n prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n \n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n if n < 1:\n raise ValueError(\"n must be a positive integer.\")\n \n count = 0\n for fib in fibonacci_generator():\n if is_prime(fib):\n count += 1\n if count == n:\n return fib", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1]], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with encode_cyclic function. Returns decoded string.\n \"\"\"\n # Split string into groups of length 3\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # Reverse the cycling of elements in each group\n groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n \"\"\"\n triples_sum_to_zero takes a list of integers as an input.\n It returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n >>> triples_sum_to_zero([])\n False\n >>> triples_sum_to_zero([-1, 0, 1])\n True\n >>> triples_sum_to_zero([-1, -1, 2])\n True\n >>> triples_sum_to_zero([-1, -1, -1])\n False\n \"\"\"\n n = len(l)\n if n < 3:\n return False\n\n # Sort the list to use the two-pointer technique\n l.sort()\n\n for i in range(n - 2):\n # Avoid duplicates for the first element\n if i > 0 and l[i] == l[i - 1]:\n continue\n \n left, right = i + 1, n - 1\n while left < right:\n current_sum = l[i] + l[left] + l[right]\n if current_sum == 0:\n return True\n elif current_sum < 0:\n left += 1\n else:\n right -= 1\n\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n \"\"\"\n Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move at the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.\n\n Parameters:\n n (int): The number of cars in each direction.\n\n Returns:\n int: The number of collisions.\n \"\"\"\n # Each car moving left to right will collide with each car moving right to left.\n # Therefore, the total number of collisions is simply n * n.\n return n * n", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n \n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n >>> incr_list([]) # Edge case: empty list\n []\n >>> incr_list([-1, -2, -3]) # Edge case: negative numbers\n [0, -1, -2]\n >>> incr_list([0]) # Edge case: single element\n [1]\n >>> incr_list([1.5, 2.5]) # Edge case: float numbers\n [2.5, 3.5]\n \"\"\"\n return [x + 1 for x in l]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n \n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n >>> pairs_sum_to_zero([])\n False\n >>> pairs_sum_to_zero([-1, 1])\n True\n >>> pairs_sum_to_zero([-1, 2, 1, -2])\n True\n \"\"\"\n seen = set()\n for number in l:\n if -number in seen:\n return True\n seen.add(number)\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion.\n base numbers are less than 10.\n \n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n >>> change_base(0, 2)\n '0'\n >>> change_base(0, 3)\n '0'\n >>> change_base(1, 2)\n '1'\n >>> change_base(1, 3)\n '1'\n >>> change_base(9, 2)\n '1001'\n >>> change_base(9, 3)\n '100'\n >>> change_base(9, 4)\n '21'\n >>> change_base(9, 5)\n '14'\n >>> change_base(9, 6)\n '13'\n >>> change_base(9, 7)\n '12'\n >>> change_base(9, 8)\n '11'\n >>> change_base(9, 9)\n '10'\n \"\"\"\n \n if base < 2 or base >= 10:\n raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n \n if x == 0:\n return '0'\n \n result = []\n negative = x < 0\n x = abs(x)\n \n while x > 0:\n remainder = x % base\n result.append(str(remainder))\n x //= base\n \n if negative:\n result.append('-')\n \n # The result is built in reverse order\n return ''.join(reversed(result))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n \"\"\"Given length of a side and height, return the area for a triangle.\n \n The area of a triangle can be calculated using the formula:\n Area = (base * height) / 2\n \n Parameters:\n a (float): The length of the base of the triangle.\n h (float): The height of the triangle.\n \n Returns:\n float: The area of the triangle.\n \n Raises:\n ValueError: If the base or height is not a positive number.\n \n >>> triangle_area(5, 3)\n 7.5\n >>> triangle_area(0, 3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(5, -3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(-5, 3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(5, 0)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n \"\"\"\n \n if a <= 0 or h <= 0:\n raise ValueError(\"Base and height must be positive numbers.\")\n \n return (a * h) / 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fib4(0) -> 0\n fib4(1) -> 0\n fib4(2) -> 2\n fib4(3) -> 0\n fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n \n This function computes the n-th element of the fib4 number sequence efficiently without using recursion.\n \n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n # Handle base cases\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 2\n elif n == 3:\n return 0\n \n # Initialize the first four values of the sequence\n fib_values = [0, 0, 2, 0]\n \n # Compute the values iteratively from 4 to n\n for i in range(4, n + 1):\n next_value = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n fib_values.append(next_value)\n \n return fib_values[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n \"\"\"Return median of elements in the list l.\n \n The median is the middle value in a list of numbers. If the list has an even number of elements,\n the median is the average of the two middle numbers.\n \n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n >>> median([1])\n 1\n >>> median([1, 2])\n 1.5\n >>> median([])\n Traceback (most recent call last):\n ...\n ValueError: Cannot compute median of an empty list.\n \"\"\"\n if not l:\n raise ValueError(\"Cannot compute median of an empty list.\")\n \n # Sort the list\n sorted_list = sorted(l)\n n = len(sorted_list)\n \n # Calculate median\n if n % 2 == 1: # Odd number of elements\n return sorted_list[n // 2]\n else: # Even number of elements\n mid1 = sorted_list[n // 2 - 1]\n mid2 = sorted_list[n // 2]\n return (mid1 + mid2) / 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n \"\"\"\n Checks if given string is a palindrome.\n \n A palindrome is a string that reads the same forward and backward.\n \n Args:\n text (str): The string to check.\n \n Returns:\n bool: True if the string is a palindrome, False otherwise.\n \n Examples:\n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n >>> is_palindrome('A man a plan a canal Panama')\n True\n >>> is_palindrome('No lemon, no melon')\n True\n >>> is_palindrome('12321')\n True\n >>> is_palindrome('12345')\n False\n >>> is_palindrome('Was it a car or a cat I saw?')\n True\n \"\"\"\n # Normalize the string: remove non-alphanumeric characters and convert to lowercase\n normalized_text = ''.join(char.lower() for char in text if char.isalnum())\n \n # Check if the normalized string is equal to its reverse\n return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with encode_shift function.\n Returns decoded string by shifting every character back by 5 in the alphabet.\n Non-alphabetic characters are not changed.\n \"\"\"\n decoded = []\n for ch in s:\n if 'a' <= ch <= 'z':\n # Shift back within lowercase letters\n decoded.append(chr(((ord(ch) - ord('a') - 5) % 26) + ord('a')))\n elif 'A' <= ch <= 'Z':\n # Shift back within uppercase letters\n decoded.append(chr(((ord(ch) - ord('A') - 5) % 26) + ord('A')))\n else:\n # Non-alphabetic characters remain unchanged\n decoded.append(ch)\n return ''.join(decoded)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n Args:\n n (int): The exponent.\n p (int): The modulus.\n \n Returns:\n int: The result of 2^n modulo p.\n \n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n if p <= 0:\n raise ValueError(\"Modulus p must be a positive integer.\")\n \n # Using modular exponentiation to avoid large numbers\n result = 1\n base = 2 % p # Start with 2 mod p\n\n while n > 0:\n if n % 2 == 1: # If n is odd, multiply the base with the result\n result = (result * base) % p\n n //= 2 # Divide n by 2\n base = (base * base) % p # Square the base\n\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n \"\"\"Return True if all numbers in the list l are below threshold t.\n \n Args:\n l (list): A list of numbers to check.\n t (int): The threshold value.\n \n Returns:\n bool: True if all numbers in l are below t, False otherwise.\n \n Examples:\n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n >>> below_threshold([], 10)\n True\n >>> below_threshold([5], 5)\n False\n >>> below_threshold([-1, -2, -3], 0)\n True\n >>> below_threshold([0, 1, 2], 1)\n False\n \"\"\"\n # Check if all elements in the list are below the threshold\n for number in l:\n if number >= t:\n return False\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two words have the same characters if they contain the same unique characters,\n regardless of the frequency of those characters.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets to get unique characters\n unique_chars_s0 = set(s0)\n unique_chars_s1 = set(s1)\n \n # Compare the sets of unique characters\n return unique_chars_s0 == unique_chars_s1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n \"\"\"Add two numbers x and y.\n\n This function takes two integers and returns their sum. It handles\n positive numbers, negative numbers, and zero.\n\n Args:\n x (int): The first integer to add.\n y (int): The second integer to add.\n\n Returns:\n int: The sum of x and y.\n\n Examples:\n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n >>> add(-1, 1)\n 0\n >>> add(-5, -7)\n -12\n >>> add(0, 0)\n 0\n >>> add(1000000, 2000000)\n 3000000\n >>> add(-1000000, 1000000)\n 0\n \"\"\"\n return x + y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n Check if every opening bracket has a corresponding closing bracket.\n \n Args:\n brackets (str): A string consisting of '<' and '>'.\n \n Returns:\n bool: True if the brackets are correctly balanced, False otherwise.\n \n Examples:\n >>> correct_bracketing(\"<\")\n False\n >>> correct_bracketing(\"<>\")\n True\n >>> correct_bracketing(\"<<><>>\")\n True\n >>> correct_bracketing(\"><<>\")\n False\n >>> correct_bracketing(\"<<>>\")\n True\n >>> correct_bracketing(\"><\")\n False\n >>> correct_bracketing(\"<<<>>>\")\n True\n >>> correct_bracketing(\"<<><><>\")\n True\n >>> correct_bracketing(\"><><><\")\n False\n >>> correct_bracketing(\"\")\n True\n \"\"\"\n balance = 0\n \n for char in brackets:\n if char == '<':\n balance += 1\n elif char == '>':\n balance -= 1\n \n # If balance goes negative, it means there's a closing bracket without a matching opening bracket\n if balance < 0:\n return False\n \n # At the end, balance should be zero for the brackets to be correctly balanced\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n \"\"\"Return n-th Fibonacci number.\n \n The Fibonacci sequence is defined as follows:\n fib(0) = 0\n fib(1) = 1\n fib(n) = fib(n-1) + fib(n-2) for n > 1\n \n Args:\n n (int): The index of the Fibonacci number to return.\n \n Returns:\n int: The n-th Fibonacci number.\n \n Raises:\n ValueError: If n is negative.\n \n Examples:\n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n >>> fib(0)\n 0\n >>> fib(2)\n 1\n >>> fib(3)\n 2\n >>> fib(4)\n 3\n >>> fib(5)\n 5\n >>> fib(6)\n 8\n >>> fib(7)\n 13\n >>> fib(9)\n 34\n \"\"\"\n if n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n if n == 0:\n return 0\n elif n == 1:\n return 1\n \n a, b = 0, 1\n for _ in range(2, n + 1):\n a, b = b, a + b\n return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n >>> common([], [])\n []\n >>> common([1, 2, 3], [])\n []\n >>> common([], [1, 2, 3])\n []\n >>> common([1, 2, 2, 3], [2, 2, 3, 4])\n [2, 3]\n >>> common([1, 2, 3], [4, 5, 6])\n []\n >>> common([1, 1, 1], [1, 1, 1])\n [1]\n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n \"\"\"Return True if list elements are monotonically increasing or decreasing.\n \n A list is considered monotonically increasing if each element is greater than or equal to the previous one.\n A list is considered monotonically decreasing if each element is less than or equal to the previous one.\n \n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n >>> monotonic([1, 1, 1])\n True\n >>> monotonic([])\n True\n >>> monotonic([5])\n True\n >>> monotonic([1, 2, 2, 3])\n True\n >>> monotonic([3, 2, 2, 1])\n True\n >>> monotonic([1, 2, 3, 2])\n False\n >>> monotonic([2, 3, 1])\n False\n \"\"\"\n if len(l) <= 1:\n return True # A list with 0 or 1 element is trivially monotonic\n\n increasing = decreasing = True\n\n for i in range(1, len(l)):\n if l[i] > l[i - 1]:\n decreasing = False\n elif l[i] < l[i - 1]:\n increasing = False\n\n return increasing or decreasing", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n >>> largest_prime_factor(600851475143)\n 6857\n >>> largest_prime_factor(49)\n 7\n >>> largest_prime_factor(15)\n 5\n \"\"\"\n # Start with the smallest prime factor\n largest_factor = None\n \n # Check for number of 2s that divide n\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # n must be odd at this point, so we can skip even numbers\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n \n return largest_factor", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n \n Args:\n n (int): The upper limit of the sum (inclusive).\n \n Returns:\n int: The sum of all integers from 1 to n.\n \n Examples:\n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n >>> sum_to_n(0)\n 0\n >>> sum_to_n(-5)\n 0\n \"\"\"\n if n < 1:\n return 0\n return n * (n + 1) // 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n Check if every opening bracket has a corresponding closing bracket.\n \n Args:\n brackets (str): A string consisting of '(' and ')'.\n \n Returns:\n bool: True if the brackets are correctly balanced, False otherwise.\n \n Examples:\n >>> correct_bracketing(\"(\")\n False\n >>> correct_bracketing(\"()\")\n True\n >>> correct_bracketing(\"(()())\")\n True\n >>> correct_bracketing(\")(()\")\n False\n >>> correct_bracketing(\")(\")\n False\n >>> correct_bracketing(\"\") # Edge case: empty string\n True\n >>> correct_bracketing(\"((()))\") # Nested brackets\n True\n >>> correct_bracketing(\"(()\") # Unmatched opening bracket\n False\n >>> correct_bracketing(\"())\") # Unmatched closing bracket\n False\n >>> correct_bracketing(\"()()()\") # Multiple pairs\n True\n >>> correct_bracketing(\"(()())()\") # Nested and sequential\n True\n \"\"\"\n balance = 0\n \n for char in brackets:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n \n # If balance goes negative, there are unmatched closing brackets\n if balance < 0:\n return False\n \n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n \"\"\" \n Calculate the derivative of a polynomial represented by its coefficients.\n \n The polynomial is represented as:\n xs[0] + xs[1] * x + xs[2] * x^2 + ...\n \n The derivative is computed as:\n d/dx (a_n * x^n) = n * a_n * x^(n-1)\n \n Args:\n xs (list): A list of coefficients where the index represents the power of x.\n \n Returns:\n list: A list of coefficients representing the derivative of the polynomial.\n \n Examples:\n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n >>> derivative([0])\n []\n >>> derivative([0, 0, 0])\n []\n >>> derivative([5])\n []\n >>> derivative([])\n []\n \"\"\"\n if not xs or len(xs) == 1:\n return [] # Derivative of a constant or empty polynomial is 0\n\n # Calculate the derivative coefficients\n derivative_coeffs = []\n for i in range(1, len(xs)):\n derivative_coeffs.append(i * xs[i])\n \n return derivative_coeffs", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n \n Args:\n n (int): The index of the FibFib number to compute.\n \n Returns:\n int: The n-th FibFib number.\n \n Examples:\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n # Memoization dictionary to store previously computed values\n memo = {0: 0, 1: 0, 2: 1}\n\n def helper(n: int) -> int:\n if n in memo:\n return memo[n]\n # Compute the n-th FibFib number using the recursive definition\n memo[n] = helper(n - 1) + helper(n - 2) + helper(n - 3)\n return memo[n]\n\n return helper(n)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set('aeiouAEIOU')\n count = 0\n \n # Iterate through the string\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n # Check if 'y' is at the end of the string\n elif s[i].lower() == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n \n >>> circular_shift(12, 1)\n '21'\n >>> circular_shift(12, 2)\n '12'\n >>> circular_shift(12345, 1)\n '51234'\n >>> circular_shift(12345, 5)\n '54321'\n >>> circular_shift(12345, 6)\n '54321'\n >>> circular_shift(0, 1)\n '0'\n >>> circular_shift(7, 3)\n '7'\n >>> circular_shift(-123, 1)\n '-312'\n >>> circular_shift(-123, 3)\n '-321'\n >>> circular_shift(-123, 4)\n '-123'\n \"\"\"\n # Convert the integer to a string and handle negative numbers\n is_negative = x < 0\n str_x = str(abs(x))\n num_digits = len(str_x)\n\n # If shift is greater than the number of digits, reverse the digits\n if shift >= num_digits:\n return str_x[::-1] if not is_negative else '-' + str_x[::-1]\n\n # Perform the circular shift\n shift = shift % num_digits # Normalize shift to avoid unnecessary full rotations\n shifted_str = str_x[-shift:] + str_x[:-shift]\n\n return shifted_str if not is_negative else '-' + shifted_str", "base_status": "fail", "plus_status": null, "base_fail_tests": [[12, 2]], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n \"\"\"Task\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n \"\"\"\n # Initialize the sum of ASCII values of uppercase characters\n total = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is uppercase\n if char.isupper():\n # Add the ASCII value of the uppercase character to the total\n total += ord(char)\n \n return total", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n \"\"\"\n Calculate the number of mango fruits in a basket given the number of apples and oranges.\n\n Parameters:\n s (str): A string representing the number of apples and oranges in the format \"X apples and Y oranges\".\n n (int): An integer representing the total number of fruits in the basket.\n\n Returns:\n int: The number of mango fruits in the basket.\n \"\"\"\n # Extract the number of apples and oranges from the string\n try:\n # Split the string to find the numbers\n parts = s.split()\n apples = int(parts[0]) # First part is the number of apples\n oranges = int(parts[2]) # Third part is the number of oranges\n except (IndexError, ValueError) as e:\n raise ValueError(\"Input string format is incorrect. Expected format: 'X apples and Y oranges'\") from e\n\n # Calculate the number of mangoes\n mangoes = n - apples - oranges\n\n # Ensure the result is non-negative\n if mangoes < 0:\n raise ValueError(\"The total number of fruits cannot be less than the sum of apples and oranges.\")\n\n return mangoes", "base_status": "fail", "plus_status": null, "base_fail_tests": [["5 apples and 6 oranges", 19]], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n \"\"\"\n Given an array representing a branch of a tree that has non-negative integer nodes,\n this function plucks one of the nodes and returns it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n The plucked node should be returned in a list, [ smallest_value, its index ].\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1] \n\n Example 3:\n Input: []\n Output: []\n \n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n \"\"\"\n smallest_even_value = float('inf')\n smallest_index = -1\n\n for index, value in enumerate(arr):\n if value % 2 == 0: # Check if the value is even\n if value < smallest_even_value: # Found a smaller even value\n smallest_even_value = value\n smallest_index = index\n elif value == smallest_even_value and index < smallest_index:\n smallest_index = index # Update index if same value found earlier\n\n if smallest_index == -1: # No even value found\n return []\n \n return [smallest_even_value, smallest_index]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n '''\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequency greater than or equal to the value of the integer itself. \n The frequency of an integer is the number of times it appears in the list.\n If no such a value exists, return -1.\n \n Examples:\n search([4, 1, 2, 2, 3, 1]) == 2\n search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n search([5, 5, 4, 4, 4]) == -1\n '''\n from collections import Counter\n\n # Count the frequency of each integer in the list\n frequency = Counter(lst)\n\n # Initialize the result variable\n result = -1\n\n # Iterate through the frequency dictionary\n for num, freq in frequency.items():\n # Check if the frequency is greater than or equal to the number itself\n if freq >= num:\n # Update the result if this number is greater than the current result\n result = max(result, num)\n\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n '''\n Given list of integers, return list in strange order.\n Strange sorting, is when you start with the minimum value,\n then maximum of the remaining integers, then minimum and so on.\n\n Examples:\n strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n strange_sort_list([]) == []\n '''\n if not lst:\n return []\n\n # Sort the list to easily access min and max values\n sorted_lst = sorted(lst)\n result = []\n \n # Use two pointers to select from both ends of the sorted list\n left = 0\n right = len(sorted_lst) - 1\n \n while left <= right:\n if left == right: # If both pointers meet, add the last element\n result.append(sorted_lst[left])\n else:\n result.append(sorted_lst[left]) # Add the minimum\n result.append(sorted_lst[right]) # Add the maximum\n left += 1\n right -= 1\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n '''\n Write a function that returns True if the object q will fly, and False otherwise.\n The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n\n Example:\n will_it_fly([1, 2], 5) \u279e False \n # 1+2 is less than the maximum possible weight, but it's unbalanced.\n\n will_it_fly([3, 2, 3], 1) \u279e False\n # it's balanced, but 3+2+3 is more than the maximum possible weight.\n\n will_it_fly([3, 2, 3], 9) \u279e True\n # 3+2+3 is less than the maximum possible weight, and it's balanced.\n\n will_it_fly([3], 5) \u279e True\n # 3 is less than the maximum possible weight, and it's balanced.\n '''\n\n # Check if the list is palindromic\n is_balanced = (q == q[::-1])\n \n # Calculate the sum of the elements in the list\n total_weight = sum(q)\n \n # Determine if the object will fly\n return is_balanced and (total_weight <= w)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return the area of\n the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n Otherwise return -1.\n \n Three sides make a valid triangle when the sum of any two sides is greater \n than the third side.\n \n Example:\n triangle_area(3, 4, 5) == 6.00\n triangle_area(1, 2, 10) == -1\n '''\n \n # Check for valid triangle using the triangle inequality theorem\n if a <= 0 or b <= 0 or c <= 0:\n return -1\n if a + b <= c or a + c <= b or b + c <= a:\n return -1\n \n # Calculate the semi-perimeter\n s = (a + b + c) / 2\n \n # Calculate the area using Heron's formula\n area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n \n # Return the area rounded to 2 decimal points\n return round(area, 2)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n \"\"\"\n Given an array arr of integers, find the minimum number of elements that\n need to be changed to make the array palindromic. A palindromic array is an array that\n is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n For example:\n smallest_change([1,2,3,5,4,7,9,6]) == 4\n smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n smallest_change([1, 2, 3, 2, 1]) == 0\n \"\"\"\n n = len(arr)\n changes = 0\n \n # Compare elements from the start and end towards the center\n for i in range(n // 2):\n if arr[i] != arr[n - 1 - i]:\n changes += 1\n \n return changes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n \n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total character counts and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n else:\n return lst2", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef generate_primes(limit):\n \"\"\"Generate a list of prime numbers up to a given limit.\"\"\"\n return [num for num in range(2, limit) if is_prime(num)]\ndef is_multiply_prime(a):\n \"\"\"Return True if the given number is the multiplication of 3 prime numbers, False otherwise.\"\"\"\n if a < 1 or a >= 100:\n return False # a must be less than 100 and greater than 0\n\n primes = generate_primes(100)\n \n # Check all combinations of three primes\n for i in range(len(primes)):\n for j in range(i, len(primes)):\n for k in range(j, len(primes)):\n product = primes[i] * primes[j] * primes[k]\n if product == a:\n return True\n if product > a:\n break # No need to check further if product exceeds a\n\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this integer is a cube of some integer number.\n Note: you may assume the input is always valid.\n \n Examples:\n iscube(1) ==> True\n iscube(2) ==> False\n iscube(-1) ==> True\n iscube(64) ==> True\n iscube(0) ==> True\n iscube(180) ==> False\n '''\n # Calculate the cube root of the absolute value of a\n cube_root = round(abs(a) ** (1/3))\n \n # Check if the cube of the rounded cube root equals the absolute value of a\n return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n \"\"\"Returns True if x is a simple power of n, otherwise False.\n \n A number x is a simple power of n if there exists an integer k such that n**k = x.\n \n Args:\n x (int): The number to check.\n n (int): The base number.\n \n Returns:\n bool: True if x is a simple power of n, False otherwise.\n \"\"\"\n # Edge case: if n is 0 or 1\n if n == 0:\n return x == 0 # 0**0 is undefined, but we can consider it as False\n if n == 1:\n return x == 1 # 1**k is always 1 for any k\n \n # Edge case: if x is less than 1\n if x < 1:\n return False # No positive power of n can yield a number less than 1\n \n # Check if x is a power of n\n power = 1\n while True:\n power_value = n ** power\n if power_value == x:\n return True\n elif power_value > x:\n return False\n power += 1", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1, 12]], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n \"\"\"Counts the number of prime hexadecimal digits in a given hexadecimal string.\"\"\"\n \n # Define the set of prime hexadecimal digits\n prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n \n # Initialize a counter for prime digits\n count = 0\n \n # Iterate through each character in the input string\n for char in num:\n # Check if the character is in the set of prime hexadecimal digits\n if char in prime_hex_digits:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n \"\"\"Convert a decimal number to binary format with specific formatting.\n\n Args:\n decimal (int): A non-negative integer to convert to binary.\n\n Returns:\n str: A string representing the binary number, formatted with 'db' at the beginning and end.\n\n Examples:\n decimal_to_binary(15) # returns \"db1111db\"\n decimal_to_binary(32) # returns \"db100000db\"\n \"\"\"\n if not isinstance(decimal, int) or decimal < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n\n # Convert decimal to binary using built-in function and remove the '0b' prefix\n binary_representation = bin(decimal)[2:]\n\n # Format the result with 'db' at the beginning and end\n formatted_result = f\"db{binary_representation}db\"\n \n return formatted_result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n \"\"\"Check if the string is happy.\n \n A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n \n Args:\n s (str): The input string to check.\n \n Returns:\n bool: True if the string is happy, False otherwise.\n \"\"\"\n # Check if the length of the string is at least 3\n if len(s) < 3:\n return False\n \n # Iterate through the string and check every 3 consecutive characters\n for i in range(len(s) - 2):\n # Get the current substring of 3 characters\n substring = s[i:i+3]\n # Check if all characters in the substring are distinct\n if len(set(substring)) != 3:\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n letter_grades = []\n \n for gpa in grades:\n if gpa == 4.0:\n letter_grades.append('A+')\n elif gpa > 3.7:\n letter_grades.append('A')\n elif gpa > 3.3:\n letter_grades.append('A-')\n elif gpa > 3.0:\n letter_grades.append('B+')\n elif gpa > 2.7:\n letter_grades.append('B')\n elif gpa > 2.3:\n letter_grades.append('B-')\n elif gpa > 2.0:\n letter_grades.append('C+')\n elif gpa > 1.7:\n letter_grades.append('C')\n elif gpa > 1.3:\n letter_grades.append('C-')\n elif gpa > 1.0:\n letter_grades.append('D+')\n elif gpa > 0.7:\n letter_grades.append('D')\n elif gpa > 0.0:\n letter_grades.append('D-')\n elif gpa == 0.0:\n letter_grades.append('E')\n else:\n letter_grades.append('Invalid GPA') # Handle negative GPAs or other invalid inputs\n\n return letter_grades", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n \"\"\"Helper function to determine if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_length(string):\n \"\"\"Check if the length of the string is a prime number.\"\"\"\n length = len(string)\n return is_prime(length)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n \"\"\"\n Given a positive integer n, return the count of the numbers of n-digit\n positive integers that start or end with 1.\n \n Parameters:\n n (int): The number of digits in the positive integers to consider.\n \n Returns:\n int: The count of n-digit positive integers that start or end with 1.\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer.\")\n \n if n == 1:\n # For 1-digit numbers, only the number '1' qualifies\n return 1\n \n # Total n-digit numbers\n total_n_digit_numbers = 9 * (10 ** (n - 1))\n \n # Count of n-digit numbers that start with 1\n start_with_1 = 10 ** (n - 1) # 1xxxx... (n-1 digits can be anything from 0-9)\n \n # Count of n-digit numbers that end with 1\n end_with_1 = 9 * (10 ** (n - 2)) # xxxxx1 (first digit can be 1-9, rest can be 0-9)\n \n # Count of n-digit numbers that start and end with 1\n start_and_end_with_1 = 10 ** (n - 2) # 1xxxx1 (n-2 digits can be anything from 0-9)\n \n # Using the principle of inclusion-exclusion\n count = start_with_1 + end_with_1 - start_and_end_with_1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits will be 1 the output should be \"1\".\n For N = 150, the sum of digits will be 6 the output should be \"110\".\n For N = 147, the sum of digits will be 12 the output should be \"1100\".\n \n Variables:\n @N integer\n Constraints: 0 \u2264 N \u2264 10000.\n Output:\n a string of binary number\n \"\"\"\n if N < 0 or N > 10000:\n raise ValueError(\"N must be between 0 and 10000 inclusive.\")\n \n # Calculate the sum of the digits of N\n digit_sum = sum(int(digit) for digit in str(N))\n \n # Convert the sum to binary and remove the '0b' prefix\n binary_sum = bin(digit_sum)[2:]\n \n return binary_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n add([1, 2, 3, 4, 5]) ==> 0\n add([0, 1, 2, 3, 4, 5]) ==> 6\n add([10, 11, 12, 13, 14]) ==> 12\n add([1]) ==> 0 # Single element, no odd index\n \"\"\"\n # Initialize the sum\n total = 0\n \n # Iterate over the list using index\n for index in range(1, len(lst), 2): # Start from index 1 and step by 2\n if lst[index] % 2 == 0: # Check if the element is even\n total += lst[index] # Add to total if it's even\n\n return total", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words while preserving spaces\n words = s.split(' ')\n \n # Function to sort characters in a word\n def sort_word(word):\n return ''.join(sorted(word))\n \n # Process each word and sort its characters\n sorted_words = [sort_word(word) for word in words]\n \n # Join the sorted words back into a single string with spaces\n result = ' '.join(sorted_words)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n # Iterate through each row and its index\n for row_index, row in enumerate(lst):\n # Iterate through each column in the row and its index\n for col_index, value in enumerate(row):\n # If the value matches x, store the coordinates\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort coordinates by row (ascending) and then by column (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating each letter down the alphabet by 4 positions.\"\"\"\n encrypted_string = []\n \n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Determine the base ASCII value based on case\n base = ord('a') if char.islower() else ord('A')\n # Rotate the character by 4 positions\n new_char = chr((ord(char) - base + 4) % 26 + base)\n encrypted_string.append(new_char)\n else:\n # If it's not a letter, we can choose to ignore it or keep it as is\n # Here we choose to ignore non-alphabetic characters\n continue\n \n return ''.join(encrypted_string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n or sort it in descending order if the sum( first index value, last index value) is even.\n\n Note:\n * don't change the given array.\n\n Examples:\n * sort_array([]) => []\n * sort_array([5]) => [5]\n * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n \"\"\"\n # Handle the edge case of an empty array\n if not array:\n return []\n\n # Calculate the sum of the first and last elements\n first_element = array[0]\n last_element = array[-1]\n total_sum = first_element + last_element\n\n # Create a copy of the array to sort\n sorted_array = array.copy()\n\n # Sort the array based on the sum's parity\n if total_sum % 2 == 0:\n # Even sum: sort in descending order\n sorted_array.sort(reverse=True)\n else:\n # Odd sum: sort in ascending order\n sorted_array.sort()\n\n return sorted_array", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n \n For example:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n >>> is_bored(\"I am bored! Are you bored? I want to go home.\")\n 2\n >>> is_bored(\"I. I. I.\")\n 3\n >>> is_bored(\"What is this? I don't know! I guess I will find out.\")\n 2\n >>> is_bored(\"\")\n 0\n >>> is_bored(\"I\")\n 1\n >>> is_bored(\"I am happy. I\")\n 2\n \"\"\"\n # Split the string into sentences based on the delimiters\n sentences = []\n current_sentence = []\n \n for char in S:\n if char in '.!?':\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n current_sentence = []\n else:\n current_sentence.append(char)\n \n # Add the last sentence if it exists\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n \n # Count the number of sentences that start with \"I\"\n boredom_count = sum(1 for sentence in sentences if sentence.startswith('I'))\n \n return boredom_count", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Sort the unique elements\n sorted_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_elements[1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n '''\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n \n Examples\n any_int(5, 2, 7) \u279e True\n any_int(3, 2, 2) \u279e False\n any_int(3, -2, 1) \u279e True\n any_int(3.6, -2.2, 2) \u279e False\n '''\n \n # Check if all inputs are integers\n if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n # Check if one number is equal to the sum of the other two\n return x == y + z or y == x + z or z == x + y\n else:\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n \"\"\"\n Write a function that takes a message, and encodes in such a \n way that it swaps case of all letters, replaces all vowels in \n the message with the letter that appears 2 places ahead of that \n vowel in the English alphabet. \n Assume only letters. \n \n Examples:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n # Define a mapping for vowels to their replacements\n vowel_replacement = {\n 'a': 'c', 'A': 'C',\n 'e': 'g', 'E': 'G',\n 'i': 'k', 'I': 'K',\n 'o': 'q', 'O': 'Q',\n 'u': 'w', 'U': 'W'\n }\n \n encoded_message = []\n \n for char in message:\n if char.isalpha(): # Check if the character is a letter\n # Swap case\n if char in vowel_replacement:\n # Replace vowel and swap case\n encoded_message.append(vowel_replacement[char])\n else:\n # Just swap case for consonants\n encoded_message.append(char.swapcase())\n else:\n # If it's not a letter, we can choose to keep it as is\n encoded_message.append(char)\n \n return ''.join(encoded_message)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["TEST"]], "plus_fail_tests": []}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef sum_of_digits(n):\n \"\"\"Return the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n largest_prime = None\n \n for number in lst:\n if is_prime(number):\n if largest_prime is None or number > largest_prime:\n largest_prime = number\n \n if largest_prime is not None:\n return sum_of_digits(largest_prime)\n else:\n return 0 # Return 0 if no prime number is found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in lower \n case or all keys are strings in upper case, else return False.\n The function should return False if the given dictionary is empty.\n \n Examples:\n check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n \"\"\"\n \n # Check if the dictionary is empty\n if not input_dict:\n return False\n \n # Initialize flags for lower and upper case\n all_lower = True\n all_upper = True\n \n # Iterate through the keys of the dictionary\n for key in input_dict.keys():\n # Check if the key is a string\n if not isinstance(key, str):\n return False\n \n # Check if the key is lower case\n if key.islower():\n all_upper = False\n # Check if the key is upper case\n elif key.isupper():\n all_lower = False\n else:\n # If the key is neither lower nor upper case\n return False\n \n # Return True if all keys are either lower case or upper case\n return all_lower or all_upper", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_up_to(n):\n \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n primes = []\n for i in range(2, n):\n if is_prime(i):\n primes.append(i)\n return primes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.\n \"\"\"\n # Get the unit digit of the first number\n unit_digit_a = abs(a) % 10\n # Get the unit digit of the second number\n unit_digit_b = abs(b) % 10\n # Return the product of the unit digits\n return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n count_upper('aBCdEf') returns 1\n count_upper('abcdefg') returns 0\n count_upper('dBBE') returns 0\n \"\"\"\n # Define the set of uppercase vowels\n uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n \n # Initialize a counter for uppercase vowels at even indices\n count = 0\n \n # Iterate over the string, checking only even indices\n for i in range(0, len(s), 2): # Step by 2 to get even indices\n if s[i] in uppercase_vowels:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n >>> closest_integer(\"14.5\")\n 15\n >>> closest_integer(\"-14.5\")\n -15\n >>> closest_integer(\"0.5\")\n 1\n >>> closest_integer(\"-0.5\")\n -1\n >>> closest_integer(\"3.0\")\n 3\n >>> closest_integer(\"-3.0\")\n -3\n >>> closest_integer(\"2.499\")\n 2\n >>> closest_integer(\"-2.499\")\n -2\n '''\n\n # Convert the input string to a float\n num = float(value)\n\n # Calculate the floor and ceiling of the number\n lower_int = int(num // 1) # This is the largest integer less than or equal to num\n upper_int = lower_int + 1 # This is the smallest integer greater than num\n\n # Check the distance to the lower and upper integers\n distance_to_lower = abs(num - lower_int)\n distance_to_upper = abs(num - upper_int)\n\n # Determine which integer to return\n if distance_to_lower < distance_to_upper:\n return lower_int\n elif distance_to_upper < distance_to_lower:\n return upper_int\n else:\n # If equidistant, round away from zero\n if num > 0:\n return upper_int\n else:\n return lower_int", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n \"\"\"\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n >>> make_a_pile(4)\n [4, 6, 8, 10]\n >>> make_a_pile(1)\n [1]\n >>> make_a_pile(2)\n [2, 4]\n >>> make_a_pile(0)\n Traceback (most recent call last):\n ...\n ValueError: n must be a positive integer\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n \n stones = []\n current_stones = n\n \n for i in range(n):\n stones.append(current_stones)\n if current_stones % 2 == 0:\n current_stones += 2 # next even number\n else:\n current_stones += 2 # next odd number\n \n return stones", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n \"\"\"\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n \"\"\"\n # Replace commas with spaces and split the string by whitespace\n words = s.replace(',', ' ').split()\n \n # Return the list of words\n return words", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n \"\"\"Compute the average of integers from n to m, round it to the nearest integer,\n and convert that to binary. If n is greater than m, return -1.\n \n Args:\n n (int): The starting integer.\n m (int): The ending integer.\n \n Returns:\n str or int: The binary representation of the rounded average or -1 if n > m.\n \"\"\"\n if n > m:\n return -1\n \n # Calculate the sum of integers from n to m\n total_sum = sum(range(n, m + 1))\n count = m - n + 1 # Total numbers from n to m\n \n # Calculate the average and round it\n average = total_sum / count\n rounded_average = round(average)\n \n # Convert the rounded average to binary\n return bin(rounded_average)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n \"\"\"This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If \n there's no such number, then the function should return -1.\n\n For example:\n choose_num(12, 15) = 14\n choose_num(13, 12) = -1\n \"\"\"\n # Ensure x is less than or equal to y\n if x > y:\n return -1\n\n # Start from the maximum of x and y\n max_even = -1\n\n # Check the range from y down to x\n for num in range(y, x - 1, -1):\n if num % 2 == 0: # Check if the number is even\n max_even = num\n break # We found the largest even number, exit the loop\n\n return max_even", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n reverse the resulting array, and then replace each digit by its corresponding name from\n \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n For example:\n arr = [2, 1, 1, 4, 5, 8, 2, 3] \n -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n \n If the array is empty, return an empty array:\n arr = []\n return []\n \n If the array has any strange number ignore it:\n arr = [1, -1 , 55] \n -> sort arr -> [-1, 1, 55]\n -> reverse arr -> [55, 1, -1]\n return = ['One']\n \"\"\"\n \n # Mapping of digits to their corresponding names\n digit_to_name = {\n 1: \"One\",\n 2: \"Two\",\n 3: \"Three\",\n 4: \"Four\",\n 5: \"Five\",\n 6: \"Six\",\n 7: \"Seven\",\n 8: \"Eight\",\n 9: \"Nine\"\n }\n \n # Filter the array to include only integers between 1 and 9\n filtered_arr = [num for num in arr if 1 <= num <= 9]\n \n # Sort the filtered array\n filtered_arr.sort()\n \n # Reverse the sorted array\n filtered_arr.reverse()\n \n # Convert the digits to their corresponding names\n result = [digit_to_name[num] for num in filtered_arr]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n \"\"\"Given a list of positive integers x, return a sorted list of all \n elements that haven't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n def has_even_digit(n):\n \"\"\"Check if the number has any even digit.\"\"\"\n for digit in str(n):\n if int(digit) % 2 == 0:\n return True\n return False\n\n # Filter the list to include only numbers without even digits\n filtered = [num for num in x if not has_even_digit(num)]\n \n # Sort the resulting list\n return sorted(filtered)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n \"\"\"\n Given a positive integer n, return a tuple that has the number of even and odd\n integer palindromes that fall within the range(1, n), inclusive.\n\n Example 1:\n Input: 3\n Output: (1, 2)\n Explanation:\n Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n Example 2:\n Input: 12\n Output: (4, 6)\n Explanation:\n Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n Note:\n 1. 1 <= n <= 10^3\n 2. returned tuple has the number of even and odd integer palindromes respectively.\n \"\"\"\n \n def is_palindrome(num):\n \"\"\"Check if a number is a palindrome.\"\"\"\n return str(num) == str(num)[::-1]\n\n even_count = 0\n odd_count = 0\n\n for i in range(1, n + 1):\n if is_palindrome(i):\n if i % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def f(n):\n \"\"\" \n Implement the function f that takes n as a parameter,\n and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even\n or the sum of numbers from 1 to i otherwise.\n i starts from 1.\n The factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).\n \"\"\"\n if n <= 0:\n return [] # Return an empty list for non-positive n\n\n result = []\n \n for i in range(1, n + 1):\n if i % 2 == 0: # i is even\n factorial = 1\n for j in range(1, i + 1):\n factorial *= j\n result.append(factorial)\n else: # i is odd\n sum_of_numbers = sum(range(1, i + 1))\n result.append(sum_of_numbers)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return True else return False.\n If the given array is empty then return True.\n\n Note: The given list is guaranteed to have unique elements.\n\n For Example:\n \n move_one_ball([3, 4, 5, 1, 2])==>True\n Explanation: By performing 2 right shift operations, non-decreasing order can\n be achieved for the given array.\n move_one_ball([3, 5, 4, 1, 2])==>False\n Explanation: It is not possible to get non-decreasing order for the given\n array by performing any number of right shift operations.\n \"\"\"\n \n if not arr: # Check for empty array\n return True\n\n n = len(arr)\n count_breaks = 0 # Count the number of times the order is broken\n\n for i in range(n):\n if arr[i] > arr[(i + 1) % n]: # Check if the current element is greater than the next\n count_breaks += 1\n\n # If there are more than one break in the order, we cannot sort it with shifts\n return count_breaks <= 1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n \"\"\"\n Write a function count_nums which takes an array of integers and returns\n the number of elements which has a sum of digits > 0.\n If a number is negative, then its first signed digit will be negative:\n e.g. -123 has signed digits -1, 2, and 3.\n \n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n def sum_of_digits(n):\n \"\"\"Helper function to calculate the sum of digits of an integer n.\"\"\"\n # Convert the number to string and iterate over each character\n # If the number is negative, we need to consider the first digit as negative\n str_n = str(n)\n digit_sum = 0\n \n for i, char in enumerate(str_n):\n if char.isdigit():\n digit_sum += int(char)\n elif i == 0 and char == '-':\n digit_sum -= 1 # First signed digit is negative\n \n return digit_sum\n\n count = 0\n for number in arr:\n if sum_of_digits(number) > 0:\n count += 1\n \n return count", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[-1, -2, 0]]], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n \"\"\"\n \n if not test: # Handle the empty string case\n return {}\n \n # Split the input string into a list of letters\n letters = test.split()\n \n # Create a dictionary to count occurrences of each letter\n count_dict = {}\n for letter in letters:\n if letter in count_dict:\n count_dict[letter] += 1\n else:\n count_dict[letter] = 1\n \n # Find the maximum count\n max_count = max(count_dict.values())\n \n # Create a result dictionary for letters with the maximum count\n result = {letter: count for letter, count in count_dict.items() if count == max_count}\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n \"\"\"Determines whether it is possible to perform an exchange of elements\n between two lists to make lst1 a list of only even numbers.\n \n Args:\n lst1 (list): The first list of numbers.\n lst2 (list): The second list of numbers.\n \n Returns:\n str: \"YES\" if lst1 can be made all even, otherwise \"NO\".\n \"\"\"\n # Check if all elements in lst1 are already even\n if all(x % 2 == 0 for x in lst1):\n return \"YES\"\n \n # Count the number of odd elements in lst1\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n \n # Check if lst2 has at least one even number to exchange\n has_even_in_lst2 = any(x % 2 == 0 for x in lst2)\n \n # If lst1 has odd numbers and lst2 has at least one even number,\n # we can perform exchanges to make lst1 all even\n if odd_count_lst1 > 0 and has_even_in_lst2:\n return \"YES\"\n \n # If lst1 has odd numbers and lst2 has no even numbers,\n # we cannot make lst1 all even\n return \"NO\"", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 3, 4], [1, 5, 3, 4]]], "plus_fail_tests": []}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n \"\"\"Task\n We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and True/False for the check.\n Example\n For s = \"abcde\", c = \"ae\", the result should be ('bcd',False)\n For s = \"abcdef\", c = \"b\" the result should be ('acdef',False)\n For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc',True)\n \"\"\"\n \n # Create a set of characters to delete for faster lookup\n chars_to_delete = set(c)\n \n # Build the result string by filtering out unwanted characters\n result = ''.join(char for char in s if char not in chars_to_delete)\n \n # Check if the result string is a palindrome\n is_palindrome = result == result[::-1]\n \n return (result, is_palindrome)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3', \"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n \n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in s if char in '13579')\n \n # Create the output string with the count of odd digits\n output_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n \n # Append the result to the list\n result.append(output_string)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n \"\"\"\n Calculate the number of times buckets need to be lowered to empty the wells.\n\n Parameters:\n grid (list of list of int): A rectangular grid representing wells.\n capacity (int): The capacity of each bucket.\n\n Returns:\n int: The total number of times buckets need to be lowered.\n \"\"\"\n total_water = 0\n \n # Count the total amount of water in the grid\n for row in grid:\n total_water += sum(row)\n \n # Calculate the number of times buckets need to be lowered\n if total_water == 0:\n return 0 # No water to extract\n \n # Each bucket can carry 'capacity' units of water\n # We need to lower the buckets enough times to extract all the water\n return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n Example\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n \"\"\"\n if not nums:\n raise ValueError(\"The input array must not be empty.\")\n \n # Initialize variables\n current_sum = float('inf')\n min_sum = float('inf')\n \n for num in nums:\n if current_sum > 0:\n current_sum = num # Start a new sub-array\n else:\n current_sum += num # Continue the current sub-array\n \n min_sum = min(min_sum, current_sum) # Update the minimum sum found\n \n return min_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n \"\"\"\n In this Kata, you have to sort an array of non-negative integers according to\n number of ones in their binary representation in ascending order.\n For similar number of ones, sort based on decimal value.\n\n It must be implemented like this:\n >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n >>> sort_array([1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]\n \"\"\"\n # Filter out negative numbers since the problem states non-negative integers\n arr = [x for x in arr if x >= 0]\n \n # Sort the array based on the number of 1s in binary representation and then by value\n return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[-2, -3, -4, -5, -6]]], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n \"\"\"Given a string s and a natural number n, returns a list of all words from string s \n that contain exactly n consonants, in the order they appear in the string s.\n \n Args:\n s (str): The input string containing words.\n n (int): The number of consonants to filter words by.\n \n Returns:\n list: A list of words containing exactly n consonants.\n \"\"\"\n \n if not s: # Check if the string is empty\n return []\n \n # Define a set of vowels for easy checking\n vowels = set(\"aeiouAEIOU\")\n \n def count_consonants(word):\n \"\"\"Helper function to count consonants in a word.\"\"\"\n return sum(1 for char in word if char.isalpha() and char not in vowels)\n \n # Split the string into words\n words = s.split()\n \n # Filter words based on the number of consonants\n result = [word for word in words if count_consonants(word) == n]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n two consonants from the right side of the word (case sensitive).\n \n Vowels in the beginning and ending don't count. Return empty string if you didn't\n find any vowel that meets the above condition. \n\n You may assume that the given string contains English letters only.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n n = len(word)\n\n # Check for edge cases\n if n < 3: # Need at least 3 characters to have consonants on both sides of a vowel\n return \"\"\n\n # Iterate from the end of the word to the beginning\n for i in range(n - 2, 0, -1): # Start from the second last character\n if word[i] in vowels: # Check if the current character is a vowel\n # Check if the characters before and after are consonants\n if word[i - 1].isalpha() and word[i - 1] not in vowels and word[i + 1].isalpha() and word[i + 1] not in vowels:\n return word[i] # Return the vowel if it is between two consonants\n\n return \"\" # Return empty string if no such vowel is found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0: # More closing than opening\n return False\n return balance == 0 # Must be balanced at the end\n\n s1, s2 = lst[0], lst[1]\n\n # Check both concatenation orders\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n \n # Sort the array in descending order to get the largest elements first\n sorted_arr = sorted(arr, reverse=True)\n \n # Get the first k elements\n max_k_elements = sorted_arr[:k]\n \n # Sort the result in ascending order before returning\n return sorted(max_k_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n An even position is defined as an index that is even (0, 2, 4, ...).\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index in range(len(lst)):\n # Check if the index is even\n if index % 2 == 0:\n # Check if the element at this index is odd\n if lst[index] % 2 != 0:\n total_sum += lst[index]\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n as follows: start with any positive integer n. Then each term is obtained from the \n previous term as follows: if the previous term is even, the next term is one half of \n the previous term. If the previous term is odd, the next term is 3 times the previous\n term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n Note: \n 1. Collatz(1) is [1].\n 2. returned list sorted in increasing order.\n\n For example:\n get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n collatz_sequence = []\n current = n\n \n while current != 1:\n collatz_sequence.append(current)\n if current % 2 == 0:\n current //= 2\n else:\n current = 3 * current + 1\n \n collatz_sequence.append(1) # Append the last term which is 1\n \n # Filter odd numbers and sort them\n odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n \n return odd_numbers", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n \"\"\"\n Given a non-empty array of integers arr and an integer k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example:\n\n Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n Output: 24 # sum of 21 + 3\n\n Constraints:\n 1. 1 <= len(arr) <= 100\n 2. 1 <= k <= len(arr)\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate through the first k elements of the array\n for i in range(k):\n # Check if the current element has at most two digits\n if -100 < arr[i] < 100:\n total_sum += arr[i]\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n '''\n Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n \n Examples:\n split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"abcdef\") \u279e 3 \n '''\n \n # Check for whitespace in the text\n if ' ' in txt:\n return txt.split()\n \n # Check for commas in the text\n elif ',' in txt:\n return txt.split(',')\n \n # If no whitespace or commas, count lowercase letters with odd order\n else:\n odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n return odd_count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n \n The date is valid if all of the following rules are satisfied:\n 1. The date string is not empty.\n 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n The number of days is not less than 1 or higher than 29 for the month 2.\n 3. The months should not be less than 1 or higher than 12.\n 4. The date should be in the format: mm-dd-yyyy\n \"\"\"\n \n # Check if the date string is empty\n if not date:\n return False\n \n # Check if the date format is correct\n if len(date) != 10 or date[2] != '-' or date[5] != '-':\n return False\n \n # Split the date into components\n try:\n month, day, year = map(int, date.split('-'))\n except ValueError:\n return False\n \n # Check month range\n if month < 1 or month > 12:\n return False\n \n # Check day range based on month\n if month in {1, 3, 5, 7, 8, 10, 12}:\n if day < 1 or day > 31:\n return False\n elif month in {4, 6, 9, 11}:\n if day < 1 or day > 30:\n return False\n elif month == 2:\n if day < 1 or day > 29:\n return False\n \n # If all checks are passed, the date is valid\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n '''\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return False. Assume no negative numbers and only integers.\n\n Examples\n is_sorted([5]) \u279e True\n is_sorted([1, 2, 3, 4, 5]) \u279e True\n is_sorted([1, 3, 2, 4, 5]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n '''\n \n if not lst: # Handle empty list case\n return True\n \n seen = set() # To track unique elements\n previous = None # To track the previous element\n \n for num in lst:\n # Check if the current number is less than the previous number\n if previous is not None and num < previous:\n return False\n \n # Check for duplicates\n if num in seen:\n return False\n \n # Add the current number to the seen set\n seen.add(num)\n previous = num # Update previous to current number\n \n return True # If all checks passed, the list is sorted", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef intersection(interval1, interval2):\n \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n start1, end1 = interval1\n start2, end2 = interval2\n \n # Find the intersection\n start_intersection = max(start1, start2)\n end_intersection = min(end1, end2)\n \n # Check if there is an intersection\n if start_intersection > end_intersection:\n return \"NO\"\n \n # Calculate the length of the intersection\n length_of_intersection = end_intersection - start_intersection\n \n # Check if the length is a prime number\n if is_prime(length_of_intersection):\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n if not arr: # Check for empty array\n return None\n\n product_of_signs = 1\n sum_of_magnitudes = 0\n\n for num in arr:\n if num > 0:\n sum_of_magnitudes += num\n elif num < 0:\n sum_of_magnitudes += -num\n product_of_signs *= -1 # Flip the sign for negative numbers\n else: # num == 0\n return 0 # If there's a zero, the product of signs is zero\n\n return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n \"\"\"Calculate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n if n < 0:\n return []\n\n # Initialize the list to hold the Tribonacci numbers\n tribonacci_sequence = []\n\n # Define the base case\n for i in range(n + 1):\n if i == 0:\n tribonacci_sequence.append(1) # tri(0) = 1\n elif i == 1:\n tribonacci_sequence.append(3) # tri(1) = 3\n elif i % 2 == 0: # Even case\n tribonacci_sequence.append(1 + i / 2)\n else: # Odd case\n # Calculate tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1)\n tri_n_minus_1 = tribonacci_sequence[i - 1]\n tri_n_minus_2 = tribonacci_sequence[i - 2]\n tri_n_plus_1 = tribonacci_sequence[i + 1] if i + 1 < n + 1 else 0\n tribonacci_sequence.append(tri_n_minus_1 + tri_n_minus_2 + tri_n_plus_1)\n\n return tribonacci_sequence", "base_status": "fail", "plus_status": null, "base_fail_tests": [[3]], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n from collections import deque\n \n N = len(grid)\n directions = [(0, 1), (1, 0), (0, -1), (-1, 0)] # Right, Down, Left, Up\n min_path = None\n\n def bfs(start_row, start_col):\n queue = deque([(start_row, start_col, [grid[start_row][start_col]])])\n while queue:\n row, col, path = queue.popleft()\n if len(path) == k:\n nonlocal min_path\n if min_path is None or path < min_path:\n min_path = path\n continue\n \n for dr, dc in directions:\n new_row, new_col = row + dr, col + dc\n if 0 <= new_row < N and 0 <= new_col < N:\n queue.append((new_row, new_col, path + [grid[new_row][new_col]]))\n\n for i in range(N):\n for j in range(N):\n bfs(i, j)\n\n return min_path", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n \"\"\"Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n \n Args:\n n (int): A positive integer.\n\n Returns:\n int: The product of the odd digits or 0 if all digits are even.\n \n Examples:\n >>> digits(1)\n 1\n >>> digits(4)\n 0\n >>> digits(235)\n 15\n >>> digits(2468)\n 0\n >>> digits(13579)\n 945\n >>> digits(0) # Edge case: should not be called with 0 as per problem statement\n Traceback (most recent call last):\n ...\n ValueError: n must be a positive integer\n \"\"\"\n \n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n \n product = 1\n has_odd_digit = False\n \n while n > 0:\n digit = n % 10\n if digit % 2 != 0: # Check if the digit is odd\n product *= digit\n has_odd_digit = True\n n //= 10 # Remove the last digit\n \n return product if has_odd_digit else 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n '''\n Create a function that takes a string as input which contains only square brackets.\n The function should return True if and only if there is a valid subsequence of brackets \n where at least one bracket in the subsequence is nested.\n\n is_nested('[[]]') \u279e True\n is_nested('[]]]]]]][[[[[]') \u279e False\n is_nested('[][]') \u279e False\n is_nested('[]') \u279e False\n is_nested('[[][]]') \u279e True\n is_nested('[[]][[') \u279e True\n '''\n \n # Initialize a counter for open brackets\n open_count = 0\n # Initialize a flag to check for nesting\n nested = False\n \n for char in string:\n if char == '[':\n open_count += 1\n # If we have seen at least one open bracket before and we see another one,\n # it indicates nesting\n if open_count > 1:\n nested = True\n elif char == ']':\n open_count -= 1\n # If we close a bracket and there were open brackets before, we can only close if we have open brackets\n if open_count < 0:\n return False # More closing brackets than opening brackets\n \n # We need to have at least one nested structure and all brackets must be closed\n return nested and open_count == 0", "base_status": "fail", "plus_status": null, "base_fail_tests": [["[[]][["]], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers.\n You need to return the sum of squared numbers in the given list,\n round each element in the list to the upper int (Ceiling) first.\n \n Examples:\n For lst = [1,2,3] the output should be 14\n For lst = [1,4,9] the output should be 98\n For lst = [1,3,5,7] the output should be 84\n For lst = [1.4,4.2,0] the output should be 29\n For lst = [-2.4,1,1] the output should be 6\n \"\"\"\n # Initialize the sum of squares\n total_sum = 0\n \n # Iterate through each number in the list\n for number in lst:\n # Round the number up to the nearest integer\n rounded_number = math.ceil(number)\n # Add the square of the rounded number to the total sum\n total_sum += rounded_number ** 2\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n '''\n Create a function that returns True if the last character\n of a given string is an alphabetical character and is not\n a part of a word, and False otherwise.\n Note: \"word\" is a group of characters separated by space.\n\n Examples:\n check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '''\n \n # Strip any trailing whitespace from the string\n txt = txt.rstrip()\n \n # Check if the string is empty after stripping\n if not txt:\n return False\n \n # Get the last character of the string\n last_char = txt[-1]\n \n # Check if the last character is an alphabetical character\n if last_char.isalpha():\n # Check if the last character is part of a word\n # A character is part of a word if it is preceded by a non-space character\n if len(txt) > 1 and txt[-2] != ' ':\n return False\n return True\n \n return False", "base_status": "fail", "plus_status": null, "base_fail_tests": [["eeeee e "]], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n \"\"\"Create a function which returns the largest index of an element which\n is not greater than or equal to the element immediately preceding it. If\n no such element exists then return -1. The given array will not contain\n duplicate values.\n\n Examples:\n can_arrange([1,2,4,3,5]) = 3\n can_arrange([1,2,3]) = -1\n \"\"\"\n # Check for empty array\n if not arr:\n return -1\n\n # Initialize the largest index to -1\n largest_index = -1\n\n # Iterate through the array starting from the second element\n for i in range(1, len(arr)):\n # Check if the current element is less than the previous one\n if arr[i] < arr[i - 1]:\n largest_index = i # Update the largest index\n\n return largest_index", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def parse_number(value):\n \"\"\"\n Convert a string representation of a number to a float or return the value as is.\n Handles both '.' and ',' as decimal separators.\n \"\"\"\n if isinstance(value, str):\n # Replace ',' with '.' for float conversion\n value = value.replace(',', '.')\n try:\n return float(value)\n except ValueError:\n return value # Return the original value if it cannot be converted\ndef compare_one(a, b):\n \"\"\"\n Compare two values (integers, floats, or strings representing real numbers)\n and return the larger one in its original type. Return None if they are equal.\n \"\"\"\n # Parse both values\n parsed_a = parse_number(a)\n parsed_b = parse_number(b)\n\n # Check for equality\n if parsed_a == parsed_b:\n return None\n\n # Return the larger value in its original type\n return a if parsed_a > parsed_b else b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n '''\n Create a function that returns a tuple (a, b), where 'a' is\n the largest of negative integers, and 'b' is the smallest\n of positive integers in a list.\n If there is no negative or positive integers, return them as None.\n\n Examples:\n largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n largest_smallest_integers([]) == (None, None)\n largest_smallest_integers([0]) == (None, None)\n '''\n \n largest_negative = None\n smallest_positive = None\n \n for num in lst:\n if num < 0:\n if largest_negative is None or num > largest_negative:\n largest_negative = num\n elif num > 0:\n if smallest_positive is None or num < smallest_positive:\n smallest_positive = num\n \n return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n \"\"\"Helper function to compute the factorial of a non-negative integer n.\"\"\"\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef special_factorial(n):\n \"\"\"Calculate the Brazilian factorial of n.\"\"\"\n if n < 1:\n raise ValueError(\"Input must be a positive integer greater than 0.\")\n \n result = 1\n for i in range(1, n + 1):\n result *= factorial(i)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n \n Args:\n n (int): The number to evaluate.\n \n Returns:\n bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n \n Example:\n is_equal_to_sum_even(4) == False\n is_equal_to_sum_even(6) == False\n is_equal_to_sum_even(8) == True\n is_equal_to_sum_even(16) == True\n is_equal_to_sum_even(18) == True\n is_equal_to_sum_even(20) == True\n is_equal_to_sum_even(22) == True\n is_equal_to_sum_even(24) == True\n is_equal_to_sum_even(2) == False\n is_equal_to_sum_even(0) == False\n is_equal_to_sum_even(-4) == False\n \"\"\"\n \n # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n if n < 8 or n % 2 != 0:\n return False\n \n # If n is 8 or greater and even, it can be expressed as the sum of 4 positive even numbers\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n \"\"\"\n Given a string text, replace all spaces in it with underscores, \n and if a string has more than 2 consecutive spaces, \n then replace all consecutive spaces with - \n \n fix_spaces(\"Example\") == \"Example\"\n fix_spaces(\"Example 1\") == \"Example_1\"\n fix_spaces(\" Example 2\") == \"_Example_2\"\n fix_spaces(\" Example 3\") == \"_Example-3\"\n \"\"\"\n # Replace multiple spaces with a placeholder\n import re\n \n # Replace sequences of 3 or more spaces with a single '-'\n text = re.sub(r' {3,}', '-', text)\n \n # Replace single or double spaces with underscores\n text = text.replace(' ', '_')\n \n return text", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n \"\"\"Check if the given file name is valid based on specific criteria.\"\"\"\n \n # Define valid extensions\n valid_extensions = ['txt', 'exe', 'dll']\n \n # Check for exactly one dot\n if file_name.count('.') != 1:\n return 'No'\n \n # Split the file name into name and extension\n name, extension = file_name.rsplit('.', 1)\n \n # Check if the name is empty\n if not name:\n return 'No'\n \n # Check if the name starts with a letter\n if not name[0].isalpha():\n return 'No'\n \n # Check if the extension is valid\n if extension not in valid_extensions:\n return 'No'\n \n # Count digits in the file name\n digit_count = sum(c.isdigit() for c in file_name)\n \n # Check if there are more than three digits\n if digit_count > 3:\n return 'No'\n \n return 'Yes'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n \"\"\"\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n \n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126\n \"\"\"\n total_sum = 0\n \n for index, value in enumerate(lst):\n if index % 3 == 0:\n # Square the value if index is a multiple of 3\n total_sum += value ** 2\n elif index % 4 == 0:\n # Cube the value if index is a multiple of 4 and not a multiple of 3\n total_sum += value ** 3\n else:\n # Add the value unchanged if index is not a multiple of 3 or 4\n total_sum += value\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef words_in_sentence(sentence):\n \"\"\"\n Given a string representing a sentence, return a string that contains the words\n from the original sentence whose lengths are prime numbers.\n \n Parameters:\n sentence (str): The input sentence containing words separated by spaces.\n \n Returns:\n str: A string containing the words with prime lengths, in the original order.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Filter words whose lengths are prime\n prime_length_words = [word for word in words if is_prime(len(word))]\n \n # Join the filtered words back into a string\n return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n \"\"\"Simplifies the expression x * n and checks if the result is a whole number.\n \n Args:\n x (str): A string representation of a fraction in the format /.\n n (str): A string representation of a fraction in the format /.\n \n Returns:\n bool: True if x * n evaluates to a whole number, False otherwise.\n \"\"\"\n # Split the fractions into numerator and denominator\n x_numerator, x_denominator = map(int, x.split('/'))\n n_numerator, n_denominator = map(int, n.split('/'))\n \n # Calculate the product of the fractions\n # x * n = (x_numerator / x_denominator) * (n_numerator / n_denominator)\n # This simplifies to (x_numerator * n_numerator) / (x_denominator * n_denominator)\n \n product_numerator = x_numerator * n_numerator\n product_denominator = x_denominator * n_denominator\n \n # Check if the product is a whole number\n return product_numerator % product_denominator == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n \"\"\"\n Write a function which sorts the given list of integers\n in ascending order according to the sum of their digits.\n Note: if there are several items with similar sum of their digits,\n order them based on their index in original list.\n\n For example:\n >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n >>> order_by_points([]) == []\n \"\"\"\n \n def digit_sum(n):\n \"\"\"Calculate the sum of the digits of an integer n.\"\"\"\n return sum(int(digit) for digit in str(abs(n)))\n\n # Create a list of tuples (digit_sum, index, value)\n indexed_nums = [(digit_sum(num), index, num) for index, num in enumerate(nums)]\n \n # Sort by digit sum first, then by original index\n sorted_nums = sorted(indexed_nums, key=lambda x: (x[0], x[1]))\n \n # Extract the sorted values\n return [num for _, _, num in sorted_nums]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n \"\"\"Returns the number of elements in the array that are greater than 10 \n and both the first and last digits of the number are odd (1, 3, 5, 7, 9).\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n int: The count of numbers meeting the criteria.\n \"\"\"\n \n def is_odd_digit(digit):\n \"\"\"Check if a digit is odd.\"\"\"\n return digit in {1, 3, 5, 7, 9}\n \n def first_and_last_digits_are_odd(num):\n \"\"\"Check if both the first and last digits of the number are odd.\"\"\"\n num_str = str(abs(num)) # Convert to string and take absolute value\n first_digit = int(num_str[0])\n last_digit = int(num_str[-1])\n return is_odd_digit(first_digit) and is_odd_digit(last_digit)\n \n count = 0\n for num in nums:\n if num > 10 and first_and_last_digits_are_odd(num):\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closest to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sorted by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct planet names. \n Examples\n bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n '''\n\n # List of planets in order from the Sun\n planets = [\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n ]\n \n # Check if the input planets are valid\n if planet1 not in planets or planet2 not in planets:\n return ()\n \n # Get the indices of the planets\n index1 = planets.index(planet1)\n index2 = planets.index(planet2)\n \n # Determine the range of indices\n start_index = min(index1, index2) + 1\n end_index = max(index1, index2)\n \n # Get the planets in between\n in_between_planets = planets[start_index:end_index]\n \n # Return as a tuple\n return tuple(in_between_planets)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n \"\"\"\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example :\n Input: n = 5\n Output: 1\n Explanation: \n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n \"\"\"\n # Create the array a based on the given formula\n a = [i * i - i + 1 for i in range(1, n + 1)]\n \n # Count the number of valid triples\n count = 0\n \n # Iterate through all possible triples (i, j, k)\n for i in range(n):\n for j in range(i + 1, n):\n for k in range(j + 1, n):\n if (a[i] + a[j] + a[k]) % 3 == 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length and alphabetically.\n \n Args:\n lst (list of str): A list of strings.\n \n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef x_or_y(n, x, y):\n \"\"\"Return the value of x if n is a prime number, otherwise return y.\"\"\"\n if is_prime(n):\n return x\n else:\n return y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n \"\"\"\n Compares the actual game scores with the guessed scores and returns an array\n indicating how far off each guess was. If the guess is correct, the value is 0,\n otherwise it is the absolute difference between the guess and the score.\n\n Parameters:\n game (list of int): The actual scores of the matches.\n guess (list of int): The guessed scores of the matches.\n\n Returns:\n list of int: An array of absolute differences or zeros for correct guesses.\n \"\"\"\n # Check if the lengths of game and guess are equal\n if len(game) != len(guess):\n raise ValueError(\"The length of game and guess lists must be equal.\")\n\n # Calculate the absolute differences\n result = [abs(g - s) for g, s in zip(guess, game)]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n \n double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n double_the_difference([-1, -2, 0]) == 0\n double_the_difference([9, -2]) == 81\n double_the_difference([0]) == 0 \n \n If the input list is empty, return 0.\n '''\n # Initialize the sum of squares\n sum_of_squares = 0\n \n # Iterate through each number in the list\n for num in lst:\n # Check if the number is a positive odd integer\n if isinstance(num, int) and num >= 0 and num % 2 != 0:\n # Add the square of the odd number to the sum\n sum_of_squares += num ** 2\n \n return sum_of_squares", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n \"\"\"Find the strongest extension based on the defined strength criteria.\"\"\"\n \n def calculate_strength(extension):\n \"\"\"Calculate the strength of the extension.\"\"\"\n CAP = sum(1 for char in extension if char.isupper())\n SM = sum(1 for char in extension if char.islower())\n return CAP - SM\n\n strongest_extension = None\n strongest_strength = float('-inf') # Start with the lowest possible strength\n\n for extension in extensions:\n strength = calculate_strength(extension)\n \n # Check if this extension is stronger or if it's the first one\n if strength > strongest_strength:\n strongest_strength = strength\n strongest_extension = extension\n\n if strongest_extension is not None:\n return f\"{class_name}.{strongest_extension}\"\n else:\n return None # In case there are no extensions", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n \"\"\"Check if the second word or any of its rotations is a substring in the first word.\n \n Args:\n a (str): The first word.\n b (str): The second word.\n \n Returns:\n bool: True if b or any of its rotations is a substring of a, False otherwise.\n \n Examples:\n cycpattern_check(\"abcd\", \"abd\") => False\n cycpattern_check(\"hello\", \"ell\") => True\n cycpattern_check(\"whassup\", \"psus\") => False\n cycpattern_check(\"abab\", \"baa\") => True\n cycpattern_check(\"efef\", \"eeff\") => False\n cycpattern_check(\"himenss\", \"simen\") => True\n \"\"\"\n \n # Edge case: if b is longer than a, it can't be a substring\n if len(b) > len(a):\n return False\n \n # Create a string that contains two copies of b\n # This allows us to check for all rotations of b\n double_b = b + b\n \n # Check if any rotation of b is a substring of a\n for i in range(len(b)):\n rotation = double_b[i:i + len(b)]\n if rotation in a:\n return True\n \n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n Example:\n even_odd_count(-12) ==> (1, 1)\n even_odd_count(123) ==> (1, 2)\n \"\"\"\n # Convert the number to its absolute value to handle negative numbers\n num = abs(num)\n \n # Initialize counters for even and odd digits\n even_count = 0\n odd_count = 0\n \n # Convert the number to a string to iterate over each digit\n for digit in str(num):\n # Check if the digit is even or odd\n if int(digit) % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n \n if not (1 <= number <= 1000):\n raise ValueError(\"Input must be between 1 and 1000 inclusive.\")\n \n # Mapping of integers to their corresponding Roman numeral representations\n roman_numerals = [\n (1000, 'm'),\n (900, 'cm'),\n (500, 'd'),\n (400, 'cd'),\n (100, 'c'),\n (90, 'xc'),\n (50, 'l'),\n (40, 'xl'),\n (10, 'x'),\n (9, 'ix'),\n (5, 'v'),\n (4, 'iv'),\n (1, 'i')\n ]\n \n result = []\n \n for value, numeral in roman_numerals:\n while number >= value:\n result.append(numeral)\n number -= value\n \n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n \"\"\"Return the word with the maximum number of unique characters.\n If multiple words have the same maximum number of unique characters,\n return the one that comes first in lexicographical order.\n \n Args:\n words (list of str): A list of words to evaluate.\n \n Returns:\n str: The word with the maximum number of unique characters.\n \"\"\"\n max_word = \"\"\n max_unique_count = 0\n\n for word in words:\n # Calculate the number of unique characters in the current word\n unique_count = len(set(word))\n \n # Check if this word has more unique characters or is lexicographically smaller\n if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n max_word = word\n max_unique_count = unique_count\n\n return max_word", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return True if the three\n sides form a right-angled triangle, False otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or \n 90 degree.\n \n Example:\n right_angle_triangle(3, 4, 5) == True\n right_angle_triangle(1, 2, 3) == False\n '''\n \n # First, we need to check if the sides can form a triangle\n if a <= 0 or b <= 0 or c <= 0:\n return False # Sides must be positive\n \n # Sort the sides to easily identify the longest side\n sides = sorted([a, b, c])\n \n # Check the Pythagorean theorem: a^2 + b^2 = c^2\n return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n \"\"\"\n You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n \n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n \n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots that exist in stock\n \n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n \"\"\"\n \n # Calculate how many more carrots are needed\n additional_needed = need - number\n \n # If no additional carrots are needed, return the current state\n if additional_needed <= 0:\n return [number, remaining]\n \n # If there are enough remaining carrots to satisfy the need\n if remaining >= additional_needed:\n total_eaten = number + additional_needed\n carrots_left = remaining - additional_needed\n return [total_eaten, carrots_left]\n \n # If there are not enough remaining carrots\n total_eaten = number + remaining\n carrots_left = 0 # All remaining carrots are eaten\n return [total_eaten, carrots_left]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic algebra operations, and \n the second list is a list of integers. Use the two given lists to build the algebraic \n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + ) \n Subtraction ( - ) \n Multiplication ( * ) \n Floor division ( // ) \n Exponentiation ( ** ) \n\n Example:\n operator = ['+', '*', '-']\n operand = [2, 3, 4, 5]\n result = 2 + 3 * 4 - 5\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.\n \"\"\"\n \n # Start with the first operand\n result = operand[0]\n \n # Iterate through the operators and operands\n for i in range(len(operator)):\n op = operator[i]\n next_operand = operand[i + 1]\n \n if op == '+':\n result += next_operand\n elif op == '-':\n result -= next_operand\n elif op == '*':\n result *= next_operand\n elif op == '//':\n # Handle division by zero\n if next_operand == 0:\n raise ValueError(\"Division by zero is not allowed.\")\n result //= next_operand\n elif op == '**':\n result **= next_operand\n else:\n raise ValueError(f\"Invalid operator: {op}\")\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": []}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n \"\"\"You are given a string s.\n If s[i] is a letter, reverse its case from lower to upper or vice versa, \n otherwise keep it as it is.\n If the string contains no letters, reverse the string.\n The function should return the resulted string.\n \n Examples:\n solve(\"1234\") = \"4321\"\n solve(\"ab\") = \"AB\"\n solve(\"#a@C\") = \"#A@c\"\n \"\"\"\n # Check if there are any letters in the string\n has_letters = any(c.isalpha() for c in s)\n \n if has_letters:\n # If there are letters, reverse the case of each letter\n result = ''.join(c.swapcase() for c in s)\n else:\n # If there are no letters, reverse the string\n result = s[::-1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string.\n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n >>> string_to_md5('') is None\n >>> string_to_md5('Python') == '3b3b3c4c4c4c4c4c4c4c4c4c4c4c4c4c'\n >>> string_to_md5('123456') == 'e10adc3949ba59abbe56e057f20f883e'\n >>> string_to_md5('!@#$%^&*()') == 'c5e478d5938ba0b11b3f6e0c3c3c3c3c'\n \"\"\"\n if text == \"\":\n return None\n # Create an MD5 hash object\n md5_hash = hashlib.md5()\n # Update the hash object with the bytes of the string\n md5_hash.update(text.encode('utf-8'))\n # Return the hexadecimal digest of the hash\n return md5_hash.hexdigest()", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascending order.\n\n For example:\n generate_integers(2, 8) => [2, 4, 6, 8]\n generate_integers(8, 2) => [2, 4, 6, 8]\n generate_integers(10, 14) => []\n \"\"\"\n # Ensure a and b are positive integers\n if a <= 0 or b <= 0:\n raise ValueError(\"Both a and b must be positive integers.\")\n\n # Determine the range of numbers to consider\n start = min(a, b)\n end = max(a, b)\n\n # Generate the list of even integers in the specified range\n even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n return even_integers", "base_status": "fail", "plus_status": null, "base_fail_tests": [[2, 10]], "plus_fail_tests": []}]}} \ No newline at end of file diff --git a/llm_based_129_eval_results.json b/llm_based_129_eval_results.json new file mode 100644 index 000000000..d02b4fc90 --- /dev/null +++ b/llm_based_129_eval_results.json @@ -0,0 +1 @@ +{"date": "2024-07-26 22:57", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n >>> has_close_elements([], 0.5)\n False\n >>> has_close_elements([1.0], 0.5)\n False\n >>> has_close_elements([1.0, 1.4], 0.5)\n True\n >>> has_close_elements([1.0, 1.4, 1.8], 0.5)\n True\n >>> has_close_elements([1.0, 2.0, 2.4], 0.5)\n True\n >>> has_close_elements([1.0, 2.0, 2.5], 0.5)\n False\n \"\"\"\n # Sort the numbers to make it easier to find close elements\n numbers.sort()\n \n # Check adjacent pairs in the sorted list\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" \n Input to this function is a string containing multiple groups of nested parentheses. \n The goal is to separate those groups into separate strings and return the list of those.\n Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n Ignore any spaces in the input string.\n \n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n # Remove spaces from the input string\n paren_string = paren_string.replace(\" \", \"\")\n \n result = []\n current_group = []\n balance = 0\n \n for char in paren_string:\n if char == '(':\n balance += 1\n current_group.append(char)\n elif char == ')':\n balance -= 1\n current_group.append(char)\n \n # When balance is zero, we have a complete group\n if balance == 0 and current_group:\n result.append(''.join(current_group))\n current_group = []\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" \n You're given a list of deposit and withdrawal operations on a bank account that starts with\n zero balance. Your task is to detect if at any point the balance of account falls below zero, \n and at that point function should return True. Otherwise it should return False.\n \n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n >>> below_zero([-1])\n True\n >>> below_zero([0, 0, 0])\n False\n >>> below_zero([-1, 1])\n False\n >>> below_zero([-1, -1, -1])\n True\n >>> below_zero([1, -1, -1])\n True\n >>> below_zero([])\n False\n \"\"\"\n balance = 0\n for operation in operations:\n balance += operation\n if balance < 0:\n return True\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into\n an integer part (largest integer smaller than given number) and decimals\n (leftover part always smaller than 1).\n\n Return the decimal part of the number.\n \n >>> truncate_number(3.5)\n 0.5\n >>> truncate_number(5.0)\n 0.0\n >>> truncate_number(0.75)\n 0.75\n >>> truncate_number(10.99)\n 0.99\n >>> truncate_number(1.0)\n 0.0\n >>> truncate_number(0.1)\n 0.1\n >>> truncate_number(0.999999)\n 0.999999\n >>> truncate_number(100.123456)\n 0.123456\n >>> truncate_number(0)\n Traceback (most recent call last):\n ...\n ValueError: The number must be a positive floating point number.\n \"\"\"\n if number <= 0:\n raise ValueError(\"The number must be a positive floating point number.\")\n \n integer_part = int(number) # Get the integer part\n decimal_part = number - integer_part # Calculate the decimal part\n return decimal_part", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n \"\"\"Insert a number 'delimiter' between every two consecutive elements of input list `numbers`.\n \n Args:\n numbers (List[int]): A list of integers.\n delimiter (int): An integer to insert between the elements of the list.\n \n Returns:\n List[int]: A new list with the delimiter inserted between elements.\n \n Examples:\n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n for i in range(len(numbers)):\n result.append(numbers[i])\n if i < len(numbers) - 1: # Avoid adding delimiter after the last element\n result.append(delimiter)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n >>> mean_absolute_deviation([])\n 0.0\n >>> mean_absolute_deviation([5.0])\n 0.0\n >>> mean_absolute_deviation([1.0, 1.0, 1.0])\n 0.0\n >>> mean_absolute_deviation([-1.0, 0.0, 1.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list\n\n mean_value = sum(numbers) / len(numbers) # Calculate the mean\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers) # Calculate MAD\n return mad", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n def max_depth(group: str) -> int:\n \"\"\" Helper function to calculate the maximum depth of nested parentheses in a single group. \"\"\"\n current_depth = 0\n max_depth = 0\n \n for char in group:\n if char == '(':\n current_depth += 1\n max_depth = max(max_depth, current_depth)\n elif char == ')':\n current_depth -= 1\n if current_depth < 0: # More closing than opening parentheses\n return -1 # Invalid group\n return max_depth if current_depth == 0 else -1 # Valid group must end with depth 0\n\n results = []\n for group in paren_string.split():\n depth = max_depth(group)\n if depth == -1:\n results.append(0) # Treat invalid groups as having depth 0\n else:\n results.append(depth)\n \n return results", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring.\n \n Args:\n strings (List[str]): A list of strings to filter.\n substring (str): The substring to search for within the strings.\n \n Returns:\n List[str]: A list of strings that contain the specified substring.\n \n Examples:\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n >>> filter_by_substring(['hello', 'world', 'test'], 'z')\n []\n >>> filter_by_substring(['case', 'sensitive', 'substring'], 'sub')\n ['substring']\n >>> filter_by_substring(['a', 'b', 'c', 'd'], 'a')\n ['a']\n >>> filter_by_substring(['', 'non-empty', ''], 'non')\n ['non-empty']\n >>> filter_by_substring(['abc', 'def', 'ghi'], '')\n ['abc', 'def', 'ghi']\n \"\"\"\n return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \n >>> rolling_max([])\n []\n \n >>> rolling_max([-1, -2, -3, -4])\n [-1, -1, -1, -1]\n \n >>> rolling_max([5])\n [5]\n \n >>> rolling_max([1, 1, 1, 1])\n [1, 1, 1, 1]\n \n >>> rolling_max([3, 1, 4, 1, 5, 9, 2, 6, 5])\n [3, 3, 4, 4, 5, 9, 9, 9, 9]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for number in numbers[1:]:\n max_so_far = max(max_so_far, number)\n result.append(max_so_far)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n \n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n >>> sum_product([-1, -2, -3])\n (-6, -6)\n >>> sum_product([0, 1, 2])\n (3, 0)\n >>> sum_product([5])\n (5, 5)\n >>> sum_product([0])\n (0, 1)\n \"\"\"\n if not numbers:\n return (0, 1)\n \n total_sum = sum(numbers)\n total_product = 1\n for number in numbers:\n total_product *= number\n \n return (total_sum, total_product)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n \"\"\" \n Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n \n >>> string_xor('010', '110')\n '100'\n >>> string_xor('111', '000')\n '111'\n >>> string_xor('000', '000')\n '000'\n >>> string_xor('101010', '010101')\n '111111'\n >>> string_xor('1', '0')\n '1'\n >>> string_xor('0', '1')\n '1'\n >>> string_xor('', '')\n ''\n >>> string_xor('1', '')\n '1'\n >>> string_xor('', '1')\n '1'\n \"\"\"\n \n # Check if both strings are empty\n if not a and not b:\n return ''\n \n # If one string is empty, return the other string\n if not a:\n return b\n if not b:\n return a\n \n # Ensure both strings are of the same length by padding the shorter one with leading zeros\n max_length = max(len(a), len(b))\n a = a.zfill(max_length)\n b = b.zfill(max_length)\n \n # Perform XOR operation\n result = []\n for bit_a, bit_b in zip(a, b):\n result.append('1' if bit_a != bit_b else '0')\n \n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n \n >>> make_palindrome('')\n ''\n >>> make_palindrome('cat')\n 'catac'\n >>> make_palindrome('cata')\n 'catac'\n >>> make_palindrome('race')\n 'racecar'\n >>> make_palindrome('a')\n 'a'\n >>> make_palindrome('ab')\n 'aba'\n \"\"\"\n if not string:\n return string # Return empty string if input is empty\n\n # Find the longest palindromic suffix\n for i in range(len(string)):\n if is_palindrome(string[i:]):\n # If the suffix is a palindrome, we need to append the reverse of the prefix\n prefix = string[:i]\n return string + prefix[::-1]\n\n # If no palindromic suffix is found, the entire string is returned with its reverse\n return string + string[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n \n >>> longest([])\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n >>> longest(['abc', 'ab', 'a'])\n 'abc'\n >>> longest(['', 'a', 'ab'])\n 'ab'\n >>> longest(['longest', 'longer', 'long'])\n 'longest'\n >>> longest(['same', 'size', 'test'])\n 'same'\n \"\"\"\n if not strings:\n return None\n \n longest_string = strings[0]\n \n for string in strings[1:]:\n if len(string) > len(longest_string):\n longest_string = string\n \n return longest_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return the greatest common divisor of two integers a and b.\n \n The function uses the Euclidean algorithm to compute the GCD.\n \n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n >>> greatest_common_divisor(0, 5)\n 5\n >>> greatest_common_divisor(5, 0)\n 5\n >>> greatest_common_divisor(0, 0)\n 0\n >>> greatest_common_divisor(-25, 15)\n 5\n >>> greatest_common_divisor(25, -15)\n 5\n >>> greatest_common_divisor(-25, -15)\n 5\n \"\"\"\n if a == 0 and b == 0:\n return 0 # GCD is undefined for (0, 0)\n \n a, b = abs(a), abs(b) # Work with absolute values\n while b:\n a, b = b, a % b\n return a", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string.\n \n Args:\n string (str): The input string from which to generate prefixes.\n \n Returns:\n List[str]: A list of all prefixes of the input string.\n \n Examples:\n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n >>> all_prefixes('')\n []\n >>> all_prefixes('a')\n ['a']\n >>> all_prefixes('hello')\n ['h', 'he', 'hel', 'hell', 'hello']\n \"\"\"\n # Initialize an empty list to store prefixes\n prefixes = []\n \n # Iterate through the string and collect prefixes\n for i in range(1, len(string) + 1):\n prefixes.append(string[:i])\n \n return prefixes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" \n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n >>> count_distinct_characters('')\n 0\n >>> count_distinct_characters('aA')\n 1\n >>> count_distinct_characters('123abcABC!@#')\n 9\n >>> count_distinct_characters(' ')\n 0\n >>> count_distinct_characters('!@#$%^&*()')\n 10\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set()\n \n # Iterate through each character in the string\n for char in lower_string:\n # Add only non-space characters to the set\n if char != ' ':\n distinct_characters.add(char)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Jerry jERRY JeRRRY"]], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n \n Args:\n n (int): The upper limit of the sequence (inclusive).\n \n Returns:\n str: A space-delimited string of numbers from 0 to n.\n \n Examples:\n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n \"\"\"\n # Check if n is negative\n if n < 0:\n return \"\"\n \n # Generate the sequence of numbers from 0 to n\n sequence = [str(i) for i in range(n + 1)]\n \n # Join the list into a single string with spaces\n return ' '.join(sequence)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n \n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n >>> how_many_times('abcabcabc', 'abc')\n 3\n >>> how_many_times('abababab', 'aba')\n 4\n >>> how_many_times('hello', 'lo')\n 1\n >>> how_many_times('hello', 'hello')\n 1\n >>> how_many_times('hello', 'world')\n 0\n >>> how_many_times('aaaaaa', 'aa')\n 5\n >>> how_many_times('abc', '')\n 0\n >>> how_many_times('', '')\n 1\n \"\"\"\n if not substring:\n return 0\n if not string:\n return 0\n\n count = 0\n start = 0\n\n while True:\n start = string.find(substring, start)\n if start == -1:\n break\n count += 1\n start += 1 # Move one character forward to allow for overlapping\n\n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string representing musical notes in a special ASCII format.\n Your task is to parse this string and return list of integers corresponding to how many beats does each\n note last.\n\n Here is a legend:\n 'o' - whole note, lasts four beats\n 'o|' - half note, lasts two beats\n '.|' - quarter note, lasts one beat\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n # Initialize an empty list to store the beats\n beats = []\n \n # Split the input string by spaces to get individual notes\n notes = music_string.split()\n \n # Define a mapping of note representations to their corresponding beats\n note_to_beats = {\n 'o': 4, # whole note\n 'o|': 2, # half note\n '.|': 1 # quarter note\n }\n \n # Iterate through each note and append the corresponding beats to the list\n for note in notes:\n if note in note_to_beats:\n beats.append(note_to_beats[note])\n else:\n # If an unknown note is encountered, raise an error\n raise ValueError(f\"Unknown note representation: '{note}'\")\n \n return beats", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n \"\"\" \n Input is a space-delimited string of numerals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest.\n \n >>> sort_numbers('three one five')\n 'one three five'\n >>> sort_numbers('nine eight seven six five four three two one zero')\n 'zero one two three four five six seven eight nine'\n >>> sort_numbers('zero')\n 'zero'\n >>> sort_numbers('')\n ''\n >>> sort_numbers('five five four four')\n 'four four five five'\n \"\"\"\n \n # Mapping of words to their corresponding numeric values\n word_to_number = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n \n # Reverse mapping for sorting back to words\n number_to_word = {v: k for k, v in word_to_number.items()}\n \n # Split the input string into words\n words = numbers.split()\n \n # Convert words to their corresponding numeric values\n numeric_values = [word_to_number[word] for word in words]\n \n # Sort the numeric values\n numeric_values.sort()\n \n # Convert sorted numeric values back to words\n sorted_words = [number_to_word[num] for num in numeric_values]\n \n # Join the sorted words into a single string\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n >>> find_closest_elements([1.0, 1.0, 1.0, 1.0])\n (1.0, 1.0)\n >>> find_closest_elements([-1.0, -2.0, -3.0, -1.5])\n (-1.5, -1.0)\n >>> find_closest_elements([0.0, 0.1, 0.2, 0.3])\n (0.0, 0.1)\n \"\"\"\n \n # Sort the numbers to find the closest pairs easily\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest elements\n for i in range(len(sorted_numbers) - 1):\n # Calculate the difference between consecutive elements\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n \n # If this difference is smaller than the minimum found so far, update\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1.\n \n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n \n >>> rescale_to_unit([10.0, 20.0, 30.0])\n [0.0, 0.5, 1.0]\n \n >>> rescale_to_unit([5.0, 5.0, 5.0])\n [0.0, 0.0, 0.0]\n \n >>> rescale_to_unit([-1.0, 0.0, 1.0])\n [0.0, 0.5, 1.0]\n \n >>> rescale_to_unit([1.0, 1.0, 2.0, 2.0])\n [0.0, 0.0, 1.0, 1.0]\n \n >>> rescale_to_unit([1.0, 2.0])\n [0.0, 1.0]\n \n >>> rescale_to_unit([2.0, 1.0])\n [1.0, 0.0]\n \"\"\"\n \n if len(numbers) < 2:\n raise ValueError(\"The input list must contain at least two elements.\")\n \n min_val = min(numbers)\n max_val = max(numbers)\n \n if min_val == max_val:\n # If all numbers are the same, return a list of zeros\n return [0.0] * len(numbers)\n \n # Rescale the numbers\n return [(num - min_val) / (max_val - min_val) for num in numbers]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers\n >>> filter_integers(['a', 3.14, 5])\n [5]\n >>> filter_integers([1, 2, 3, 'abc', {}, []])\n [1, 2, 3]\n \"\"\"\n return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n \n Args:\n n (int): The number to find the largest divisor for.\n \n Returns:\n int: The largest divisor of n that is smaller than n.\n \n Raises:\n ValueError: If n is less than or equal to 1, as there are no divisors in that case.\n \n Examples:\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(10)\n 5\n >>> largest_divisor(1)\n Traceback (most recent call last):\n ...\n ValueError: No divisors for numbers less than or equal to 1.\n >>> largest_divisor(2)\n 1\n \"\"\"\n if n <= 1:\n raise ValueError(\"No divisors for numbers less than or equal to 1.\")\n \n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n \"\"\" Return length of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n >>> strlen('a')\n 1\n >>> strlen('Hello, World!')\n 13\n >>> strlen(' ') # String with spaces\n 3\n >>> strlen('\ud83d\ude0a') # String with a Unicode character\n 2\n >>> strlen('1234567890') # String with numbers\n 10\n >>> strlen('') # Edge case: empty string\n 0\n \"\"\"\n return len(string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n Input number should be equal to the product of all factors.\n \n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n >>> factorize(1)\n []\n >>> factorize(0)\n Traceback (most recent call last):\n ...\n ValueError: Input must be a positive integer.\n >>> factorize(-10)\n Traceback (most recent call last):\n ...\n ValueError: Input must be a positive integer.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n factors = []\n # Check for number of 2s that divide n\n while n % 2 == 0:\n factors.append(2)\n n //= 2\n \n # n must be odd at this point so a skip of 2 (i.e., i = i + 2) can be used\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, append i and divide n\n while n % i == 0:\n factors.append(i)\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n factors.append(n)\n \n return factors", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([1, 1, 1, 1])\n []\n >>> remove_duplicates([1, 2, 3])\n [1, 2, 3]\n >>> remove_duplicates([])\n []\n >>> remove_duplicates([1, 2, 3, 4, 5, 1, 2, 3])\n [4, 5]\n >>> remove_duplicates([5, 5, 6, 7, 8, 6, 9])\n [7, 8, 9]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n \n # Create a new list with only the numbers that occur once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n \n Args:\n string (str): The input string to flip the case of its characters.\n \n Returns:\n str: A new string with the case of each character flipped.\n \n Examples:\n >>> flip_case('Hello')\n 'hELLO'\n >>> flip_case('WORLD')\n 'world'\n >>> flip_case('Python 3.8')\n 'pYTHON 3.8'\n >>> flip_case('')\n ''\n >>> flip_case('12345')\n '12345'\n >>> flip_case('!@#$%^&*()')\n '!@#$%^&*()'\n \"\"\"\n return ''.join(char.swapcase() for char in string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string.\n \n Args:\n strings (List[str]): A list of strings to concatenate.\n \n Returns:\n str: A single concatenated string.\n \n Examples:\n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n >>> concatenate(['Hello', ' ', 'World', '!'])\n 'Hello World!'\n >>> concatenate(['', 'a', 'b', ''])\n 'ab'\n >>> concatenate(['Python', '3.9', 'is', 'great!'])\n 'Python3.9isgreat!'\n \"\"\"\n # Initialize an empty string to hold the result\n result = ''\n \n # Iterate through each string in the list and concatenate\n for string in strings:\n result += string\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n \n Args:\n strings (List[str]): A list of strings to filter.\n prefix (str): The prefix to filter the strings by.\n \n Returns:\n List[str]: A list of strings that start with the given prefix.\n \n Examples:\n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n >>> filter_by_prefix(['apple', 'banana', 'apricot', 'grape'], 'ap')\n ['apple', 'apricot']\n >>> filter_by_prefix(['hello', 'world'], 'h')\n ['hello']\n >>> filter_by_prefix(['hello', 'world'], 'z')\n []\n >>> filter_by_prefix(['', 'test', ''], '')\n ['', 'test', '']\n >>> filter_by_prefix(['abc', 'def', 'ghi'], 'abcdef')\n []\n \"\"\"\n return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n \n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n >>> get_positive([]) # Edge case: empty list\n []\n >>> get_positive([-1, -2, -3]) # Edge case: all negative numbers\n []\n >>> get_positive([0]) # Edge case: single zero\n []\n >>> get_positive([1, 0, -1]) # Mixed numbers with zero\n [1]\n >>> get_positive([10, 20, 30, 0, -10, -20]) # Mixed with positives and negatives\n [10, 20, 30]\n \"\"\"\n return [x for x in l if x > 0]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n A prime number is a natural number greater than 1 that cannot be formed by multiplying two smaller natural numbers.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n >>> is_prime(0)\n False\n >>> is_prime(-5)\n False\n >>> is_prime(2)\n True\n >>> is_prime(3)\n True\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return False # eliminate multiples of 2 and 3\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6 # check for factors of the form 6k \u00b1 1\n\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float) -> float:\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list) -> list:\n \"\"\"\n Computes the derivative of the polynomial with coefficients xs.\n The derivative is calculated as: \n d/dx (a0 + a1*x + a2*x^2 + ... + an*x^n) = a1 + 2*a2*x + ... + n*an*x^(n-1)\n \"\"\"\n return [i * coeff for i, coeff in enumerate(xs) if i > 0]\ndef find_zero(xs: list, initial_guess: float = 0.0, tolerance: float = 1e-7, max_iterations: int = 1000) -> float:\n \"\"\" \n xs are coefficients of a polynomial.\n find_zero finds x such that poly(x) = 0.\n find_zero returns only one zero point, even if there are many.\n Moreover, find_zero only takes list xs having an even number of coefficients\n and the largest non-zero coefficient as it guarantees a solution.\n \n >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n -0.5\n >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n 1.0\n \"\"\"\n if len(xs) % 2 != 0:\n raise ValueError(\"The number of coefficients must be even.\")\n \n current_guess = initial_guess\n for _ in range(max_iterations):\n f_value = poly(xs, current_guess)\n f_derivative = poly(derivative(xs), current_guess)\n \n if abs(f_derivative) < tolerance: # Avoid division by zero\n raise ValueError(\"Derivative is too small; no solution found.\")\n \n next_guess = current_guess - f_value / f_derivative\n \n if abs(next_guess - current_guess) < tolerance:\n return next_guess\n \n current_guess = next_guess\n \n raise ValueError(\"Maximum iterations reached; no solution found.\")", "base_status": "fail", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n Args:\n l (list): A list of elements which may contain duplicates.\n \n Returns:\n list: A sorted list of unique elements.\n \n Examples:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use a set to remove duplicates, then sort the result\n return sorted(set(l))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n >>> sort_third([10, 20, 30, 40, 50, 60, 70, 80, 90])\n [10, 20, 30, 40, 50, 60, 70, 80, 90]\n >>> sort_third([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])\n [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]\n >>> sort_third([])\n []\n >>> sort_third([1])\n [1]\n >>> sort_third([1, 2])\n [1, 2]\n >>> sort_third([3, 1, 2, 5, 4, 6, 9, 8, 7])\n [1, 1, 2, 5, 4, 6, 3, 8, 7]\n \"\"\"\n # Extract values at indices divisible by 3\n values_to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(values_to_sort)\n \n # Create a new list to hold the result\n result = l.copy()\n \n # Replace values at indices divisible by 3 with sorted values\n for i, value in zip(range(len(result)), sorted_values):\n if i % 3 == 0:\n result[i] = value\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]]], "plus_fail_tests": []}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n \"\"\"Return maximum element in the list.\n \n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n >>> max_element([]) # Edge case: empty list\n Traceback (most recent call last):\n ...\n ValueError: The list is empty.\n >>> max_element(['a', 1, 2]) # Edge case: non-numeric elements\n Traceback (most recent call last):\n ...\n TypeError: All elements in the list must be numbers.\n \"\"\"\n \n if not l:\n raise ValueError(\"The list is empty.\")\n \n max_value = l[0]\n \n for item in l:\n if not isinstance(item, (int, float)):\n raise TypeError(\"All elements in the list must be numbers.\")\n if item > max_value:\n max_value = item\n \n return max_value", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n >>> sort_even([10, 20, 30, 40, 50])\n [10, 20, 30, 40, 50]\n >>> sort_even([1])\n [1]\n >>> sort_even([])\n []\n >>> sort_even([2, 1])\n [2, 1]\n >>> sort_even([4, 3, 2, 1, 0])\n [0, 3, 2, 1, 4]\n \"\"\"\n # Extract even indexed elements\n even_indices = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indexed elements\n even_indices_sorted = sorted(even_indices)\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Place the sorted even indexed elements back into their positions\n for i, sorted_value in enumerate(even_indices_sorted):\n result[i * 2] = sorted_value\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with encode_cyclic function. Returns decoded string.\n \"\"\"\n # Split string into groups of length 3\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # Reverse the cycling of elements in each group\n groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_fib(n: int) -> int:\n \"\"\"\n prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n \n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n if n < 1:\n raise ValueError(\"n must be a positive integer.\")\n \n count = 0\n for fib in fibonacci_generator():\n if is_prime(fib):\n count += 1\n if count == n:\n return fib", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1]], "plus_fail_tests": []}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n \"\"\"\n triples_sum_to_zero takes a list of integers as an input.\n It returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n >>> triples_sum_to_zero([])\n False\n >>> triples_sum_to_zero([-1, 0, 1])\n True\n >>> triples_sum_to_zero([-1, -1, 2])\n True\n >>> triples_sum_to_zero([-1, -1, -1])\n False\n \"\"\"\n n = len(l)\n if n < 3:\n return False\n\n # Sort the list to use the two-pointer technique\n l.sort()\n\n for i in range(n - 2):\n # Avoid duplicates for the first element\n if i > 0 and l[i] == l[i - 1]:\n continue\n \n left, right = i + 1, n - 1\n while left < right:\n current_sum = l[i] + l[left] + l[right]\n if current_sum == 0:\n return True\n elif current_sum < 0:\n left += 1\n else:\n right -= 1\n\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n \"\"\"\n Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move at the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.\n\n Parameters:\n n (int): The number of cars in each direction.\n\n Returns:\n int: The number of collisions.\n \"\"\"\n # Each car moving left to right will collide with each car moving right to left.\n # Therefore, the total number of collisions is simply n * n.\n return n * n", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n \n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n >>> incr_list([]) # Edge case: empty list\n []\n >>> incr_list([-1, -2, -3]) # Edge case: negative numbers\n [0, -1, -2]\n >>> incr_list([0]) # Edge case: single element\n [1]\n >>> incr_list([1.5, 2.5]) # Edge case: float numbers\n [2.5, 3.5]\n \"\"\"\n return [x + 1 for x in l]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion.\n base numbers are less than 10.\n \n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n >>> change_base(0, 2)\n '0'\n >>> change_base(0, 3)\n '0'\n >>> change_base(1, 2)\n '1'\n >>> change_base(1, 3)\n '1'\n >>> change_base(9, 2)\n '1001'\n >>> change_base(9, 3)\n '100'\n >>> change_base(9, 4)\n '21'\n >>> change_base(9, 5)\n '14'\n >>> change_base(9, 6)\n '13'\n >>> change_base(9, 7)\n '12'\n >>> change_base(9, 8)\n '11'\n >>> change_base(9, 9)\n '10'\n \"\"\"\n \n if base < 2 or base >= 10:\n raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n \n if x == 0:\n return '0'\n \n result = []\n negative = x < 0\n x = abs(x)\n \n while x > 0:\n remainder = x % base\n result.append(str(remainder))\n x //= base\n \n if negative:\n result.append('-')\n \n return ''.join(reversed(result))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n \n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n >>> pairs_sum_to_zero([])\n False\n >>> pairs_sum_to_zero([-1, 1])\n True\n >>> pairs_sum_to_zero([-1, 2, 1, -2])\n True\n \"\"\"\n seen = set()\n for number in l:\n if -number in seen:\n return True\n seen.add(number)\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fib4(0) -> 0\n fib4(1) -> 0\n fib4(2) -> 2\n fib4(3) -> 0\n fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n \n This function computes the n-th element of the fib4 number sequence efficiently without using recursion.\n \n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n # Handle base cases\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 2\n elif n == 3:\n return 0\n \n # Initialize a list to store computed values\n fib_values = [0] * (n + 1)\n fib_values[0] = 0\n fib_values[1] = 0\n fib_values[2] = 2\n fib_values[3] = 0\n \n # Compute the fib4 values iteratively\n for i in range(4, n + 1):\n fib_values[i] = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n \n return fib_values[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n \"\"\"Given length of a side and height, return the area for a triangle.\n \n The area of a triangle can be calculated using the formula:\n Area = (base * height) / 2\n \n Parameters:\n a (float): The length of the base of the triangle.\n h (float): The height of the triangle.\n \n Returns:\n float: The area of the triangle.\n \n Raises:\n ValueError: If the base or height is not a positive number.\n \n >>> triangle_area(5, 3)\n 7.5\n >>> triangle_area(0, 3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(5, -3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(-5, 3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(5, 0)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n \"\"\"\n \n if a <= 0 or h <= 0:\n raise ValueError(\"Base and height must be positive numbers.\")\n \n return (a * h) / 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n \"\"\"Return median of elements in the list l.\n \n The median is the middle value in a list of numbers. If the list has an even number of elements,\n the median is the average of the two middle numbers.\n \n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n >>> median([1])\n 1\n >>> median([1, 2])\n 1.5\n >>> median([])\n Traceback (most recent call last):\n ...\n ValueError: Cannot compute median of an empty list.\n \"\"\"\n if not l:\n raise ValueError(\"Cannot compute median of an empty list.\")\n \n # Sort the list\n sorted_list = sorted(l)\n n = len(sorted_list)\n \n # Calculate median\n if n % 2 == 1: # Odd number of elements\n return sorted_list[n // 2]\n else: # Even number of elements\n mid1 = sorted_list[n // 2 - 1]\n mid2 = sorted_list[n // 2]\n return (mid1 + mid2) / 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n \"\"\"\n Checks if given string is a palindrome.\n \n A palindrome is a string that reads the same forward and backward.\n \n Args:\n text (str): The string to check.\n \n Returns:\n bool: True if the string is a palindrome, False otherwise.\n \n Examples:\n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n >>> is_palindrome('A man a plan a canal Panama')\n True\n >>> is_palindrome('No lemon, no melon')\n True\n >>> is_palindrome('12321')\n True\n >>> is_palindrome('12345')\n False\n >>> is_palindrome('Was it a car or a cat I saw?')\n True\n \"\"\"\n # Normalize the string: remove non-alphanumeric characters and convert to lowercase\n normalized_text = ''.join(char.lower() for char in text if char.isalnum())\n \n # Check if the normalized string is equal to its reverse\n return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n Args:\n n (int): The exponent.\n p (int): The modulus.\n \n Returns:\n int: The result of 2^n modulo p.\n \n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n if p <= 0:\n raise ValueError(\"Modulus p must be a positive integer.\")\n \n # Using modular exponentiation to avoid large numbers\n result = 1\n base = 2 % p # Start with 2 mod p\n \n while n > 0:\n if n % 2 == 1: # If n is odd, multiply the base with the result\n result = (result * base) % p\n base = (base * base) % p # Square the base\n n //= 2 # Divide n by 2\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with encode_shift function.\n Returns the decoded string by shifting every alphabetic character back by 5.\n Non-alphabetic characters are not changed.\n \"\"\"\n decoded = []\n for ch in s:\n if 'a' <= ch <= 'z':\n # Reverse shift for lowercase letters\n decoded.append(chr(((ord(ch) - ord('a') - 5) % 26) + ord('a')))\n elif 'A' <= ch <= 'Z':\n # Reverse shift for uppercase letters\n decoded.append(chr(((ord(ch) - ord('A') - 5) % 26) + ord('A')))\n else:\n # Non-alphabetic characters remain unchanged\n decoded.append(ch)\n return ''.join(decoded)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n \"\"\"Return True if all numbers in the list l are below threshold t.\n \n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n >>> below_threshold([], 10)\n True\n >>> below_threshold([5], 5)\n False\n >>> below_threshold([-1, -2, -3], 0)\n True\n >>> below_threshold([0, 0, 0], 1)\n True\n >>> below_threshold([1, 2, 3], 3)\n False\n >>> below_threshold([10, 20, 30], 40)\n True\n >>> below_threshold([10, 20, 30], 30)\n False\n \"\"\"\n return all(x < t for x in l)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n \"\"\"Add two numbers x and y.\n\n This function takes two integers and returns their sum. It handles\n positive numbers, negative numbers, and zero.\n\n Args:\n x (int): The first integer to add.\n y (int): The second integer to add.\n\n Returns:\n int: The sum of x and y.\n\n Examples:\n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n >>> add(-1, 1)\n 0\n >>> add(-5, -7)\n -12\n >>> add(0, 0)\n 0\n >>> add(1000000, 2000000)\n 3000000\n >>> add(-1000000, 1000000)\n 0\n \"\"\"\n return x + y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two words have the same characters if they contain the same unique characters,\n regardless of the frequency of those characters.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets to get unique characters\n unique_chars_s0 = set(s0)\n unique_chars_s1 = set(s1)\n \n # Compare the sets of unique characters\n return unique_chars_s0 == unique_chars_s1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n \"\"\"Return n-th Fibonacci number.\n \n The Fibonacci sequence is defined as follows:\n - fib(0) = 0\n - fib(1) = 1\n - fib(n) = fib(n-1) + fib(n-2) for n > 1\n\n Args:\n n (int): The index of the Fibonacci number to return.\n\n Returns:\n int: The n-th Fibonacci number.\n\n Raises:\n ValueError: If n is negative.\n\n Examples:\n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n >>> fib(0)\n 0\n >>> fib(2)\n 1\n >>> fib(3)\n 2\n >>> fib(4)\n 3\n >>> fib(5)\n 5\n >>> fib(6)\n 8\n >>> fib(7)\n 13\n \"\"\"\n if n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n if n == 0:\n return 0\n elif n == 1:\n return 1\n \n a, b = 0, 1\n for _ in range(2, n + 1):\n a, b = b, a + b\n return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n Check if every opening bracket has a corresponding closing bracket.\n \n Args:\n brackets (str): A string consisting of '<' and '>'.\n \n Returns:\n bool: True if the brackets are correctly balanced, False otherwise.\n \n Examples:\n >>> correct_bracketing(\"<\")\n False\n >>> correct_bracketing(\"<>\")\n True\n >>> correct_bracketing(\"<<><>>\")\n True\n >>> correct_bracketing(\"><<>\")\n False\n >>> correct_bracketing(\"<<>>\")\n True\n >>> correct_bracketing(\"><\")\n False\n >>> correct_bracketing(\"<<<>>>\")\n True\n >>> correct_bracketing(\"<<><><>\")\n True\n >>> correct_bracketing(\"><><\")\n False\n >>> correct_bracketing(\"\")\n True\n \"\"\"\n balance = 0\n \n for char in brackets:\n if char == '<':\n balance += 1\n elif char == '>':\n balance -= 1\n \n # If balance goes negative, it means there's a closing bracket without a matching opening bracket\n if balance < 0:\n return False\n \n # At the end, balance should be zero for the brackets to be correctly balanced\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n \"\"\"Return True if list elements are monotonically increasing or decreasing.\n \n A list is considered monotonically increasing if each element is greater than or equal to the previous one.\n A list is considered monotonically decreasing if each element is less than or equal to the previous one.\n \n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n >>> monotonic([1, 1, 1])\n True\n >>> monotonic([])\n True\n >>> monotonic([5])\n True\n >>> monotonic([1, 2, 2, 3])\n True\n >>> monotonic([3, 2, 2, 1])\n True\n >>> monotonic([1, 2, 3, 2])\n False\n >>> monotonic([2, 3, 2, 4])\n False\n \"\"\"\n if len(l) <= 1:\n return True # A list with 0 or 1 element is trivially monotonic\n\n increasing = decreasing = True\n\n for i in range(1, len(l)):\n if l[i] > l[i - 1]:\n decreasing = False\n elif l[i] < l[i - 1]:\n increasing = False\n\n return increasing or decreasing", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n >>> common([], [])\n []\n >>> common([1, 2, 3], [])\n []\n >>> common([], [1, 2, 3])\n []\n >>> common([1, 2, 2, 3], [2, 2, 3, 4])\n [2, 3]\n >>> common([1, 2, 3], [4, 5, 6])\n []\n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n >>> largest_prime_factor(600851475143)\n 6857\n >>> largest_prime_factor(49)\n 7\n >>> largest_prime_factor(15)\n 5\n \"\"\"\n # Start with the smallest prime factor\n largest_factor = None\n \n # Check for number of 2s that divide n\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # n must be odd at this point, so we can skip even numbers\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n \n return largest_factor", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n \n Args:\n n (int): The upper limit of the sum (inclusive).\n \n Returns:\n int: The sum of all integers from 1 to n.\n \n Examples:\n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n >>> sum_to_n(0)\n 0\n >>> sum_to_n(-5)\n 0\n \"\"\"\n if n < 1:\n return 0\n return n * (n + 1) // 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n Check if every opening bracket has a corresponding closing bracket.\n \n Args:\n brackets (str): A string consisting of '(' and ')'.\n \n Returns:\n bool: True if the brackets are correctly balanced, False otherwise.\n \n Examples:\n >>> correct_bracketing(\"(\")\n False\n >>> correct_bracketing(\"()\")\n True\n >>> correct_bracketing(\"(()())\")\n True\n >>> correct_bracketing(\")(()\")\n False\n >>> correct_bracketing(\")(\")\n False\n >>> correct_bracketing(\"\") # Edge case: empty string\n True\n >>> correct_bracketing(\"((()))\") # Nested brackets\n True\n >>> correct_bracketing(\"(()\") # Unmatched opening bracket\n False\n >>> correct_bracketing(\"())\") # Unmatched closing bracket\n False\n >>> correct_bracketing(\"()()()\") # Multiple pairs\n True\n >>> correct_bracketing(\"(()(()))\") # Complex nested structure\n True\n \"\"\"\n balance = 0\n \n for char in brackets:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n \n # If balance goes negative, there are unmatched closing brackets\n if balance < 0:\n return False\n \n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n \"\"\" \n Calculate the derivative of a polynomial represented by its coefficients.\n \n The polynomial is represented as:\n xs[0] + xs[1] * x + xs[2] * x^2 + ... + xs[n] * x^n\n \n The derivative is calculated as:\n 0 + 1 * xs[1] + 2 * xs[2] * x + 3 * xs[3] * x^2 + ... + n * xs[n] * x^(n-1)\n \n Args:\n xs (list): A list of coefficients where the index represents the power of x.\n \n Returns:\n list: A list of coefficients representing the derivative of the polynomial.\n \n Examples:\n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n >>> derivative([0])\n []\n >>> derivative([0, 0, 0])\n []\n >>> derivative([5])\n []\n >>> derivative([0, 1])\n [1]\n \"\"\"\n # The derivative of a constant polynomial is 0, so we return an empty list\n if len(xs) <= 1:\n return []\n \n # Calculate the derivative coefficients\n derivative_coeffs = []\n for i in range(1, len(xs)):\n derivative_coeffs.append(i * xs[i])\n \n return derivative_coeffs", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n \n Args:\n n (int): The index of the FibFib number to compute.\n \n Returns:\n int: The n-th FibFib number.\n \n Examples:\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n # Memoization dictionary to store previously computed values\n memo = {0: 0, 1: 0, 2: 1}\n\n def helper(n):\n if n in memo:\n return memo[n]\n # Compute the value recursively and store it in the memo dictionary\n memo[n] = helper(n - 1) + helper(n - 2) + helper(n - 3)\n return memo[n]\n\n return helper(n)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set('aeiouAEIOU')\n count = 0\n \n # Iterate through the string\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n # Check if 'y' is at the end of the string\n elif s[i].lower() == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n \"\"\"Task\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n \"\"\"\n # Initialize the sum of ASCII values of uppercase characters\n total = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is uppercase\n if char.isupper():\n # Add the ASCII value of the uppercase character to the total\n total += ord(char)\n \n return total", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n \n >>> circular_shift(12, 1)\n '21'\n >>> circular_shift(12, 2)\n '12'\n >>> circular_shift(12345, 1)\n '51234'\n >>> circular_shift(12345, 5)\n '54321'\n >>> circular_shift(12345, 6)\n '54321'\n >>> circular_shift(0, 1)\n '0'\n >>> circular_shift(7, 3)\n '7'\n >>> circular_shift(100, 1)\n '010'\n >>> circular_shift(100, 2)\n '001'\n >>> circular_shift(-123, 1)\n '-312'\n >>> circular_shift(-123, 3)\n '-321'\n \"\"\"\n # Convert the integer to a string and handle negative numbers\n is_negative = x < 0\n x_str = str(abs(x))\n num_digits = len(x_str)\n\n # If shift is greater than the number of digits, reverse the digits\n if shift >= num_digits:\n result = x_str[::-1]\n else:\n # Perform the circular shift\n shift = shift % num_digits # Normalize shift to avoid unnecessary full rotations\n result = x_str[-shift:] + x_str[:-shift]\n\n # Add the negative sign back if the original number was negative\n if is_negative:\n result = '-' + result\n\n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [[12, 2]], "plus_fail_tests": []}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n \"\"\"\n Calculate the number of mango fruits in a basket given the number of apples and oranges.\n\n Parameters:\n s (str): A string representing the number of apples and oranges in the format \"X apples and Y oranges\".\n n (int): An integer representing the total number of fruits in the basket.\n\n Returns:\n int: The number of mango fruits in the basket.\n \"\"\"\n # Extract the number of apples and oranges from the string\n try:\n # Split the string to find the numbers\n parts = s.split()\n apples = int(parts[0]) # First part is the number of apples\n oranges = int(parts[2]) # Third part is the number of oranges\n except (IndexError, ValueError) as e:\n raise ValueError(\"Input string format is incorrect. Expected format: 'X apples and Y oranges'\") from e\n\n # Calculate the number of mangoes\n mangoes = n - apples - oranges\n\n # Ensure the result is non-negative\n if mangoes < 0:\n raise ValueError(\"The total number of fruits cannot be less than the sum of apples and oranges.\")\n\n return mangoes", "base_status": "fail", "plus_status": null, "base_fail_tests": [["5 apples and 6 oranges", 19]], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n \"\"\"\n Given an array representing a branch of a tree that has non-negative integer nodes,\n your task is to pluck one of the nodes and return it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n The plucked node should be returned in a list, [ smallest_value, its index ],\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index. \n\n Example 3:\n Input: []\n Output: []\n \n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n Explanation: 0 is the smallest value, but there are two zeros,\n so we will choose the first zero, which has the smallest index.\n\n Constraints:\n * 1 <= nodes.length <= 10000\n * 0 <= node.value\n \"\"\"\n # Initialize variables to track the smallest even value and its index\n smallest_even_value = float('inf')\n smallest_index = -1\n\n # Iterate through the array to find the smallest even value\n for index, value in enumerate(arr):\n if value % 2 == 0: # Check if the value is even\n if value < smallest_even_value: # Check if it's smaller than the current smallest\n smallest_even_value = value\n smallest_index = index\n\n # If we found an even value, return it in the required format\n if smallest_index != -1:\n return [smallest_even_value, smallest_index]\n \n # If no even value was found, return an empty list\n return []", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n '''\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequency greater than or equal to the value of the integer itself. \n The frequency of an integer is the number of times it appears in the list.\n If no such a value exists, return -1.\n \n Examples:\n search([4, 1, 2, 2, 3, 1]) == 2\n search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n search([5, 5, 4, 4, 4]) == -1\n '''\n from collections import Counter\n\n # Count the frequency of each integer in the list\n frequency = Counter(lst)\n\n # Initialize the result variable\n result = -1\n\n # Iterate through the frequency dictionary\n for num, freq in frequency.items():\n # Check if the frequency is greater than or equal to the number itself\n if freq >= num:\n # Update the result if this number is greater than the current result\n result = max(result, num)\n\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n '''\n Given list of integers, return list in strange order.\n Strange sorting, is when you start with the minimum value,\n then maximum of the remaining integers, then minimum and so on.\n\n Examples:\n strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n strange_sort_list([]) == []\n '''\n if not lst:\n return []\n\n # Sort the list to easily access min and max values\n sorted_lst = sorted(lst)\n result = []\n \n # Use two pointers to select from both ends of the sorted list\n left = 0\n right = len(sorted_lst) - 1\n \n while left <= right:\n if left == right: # If both pointers meet, add the last element\n result.append(sorted_lst[left])\n else:\n result.append(sorted_lst[left]) # Add the minimum\n result.append(sorted_lst[right]) # Add the maximum\n left += 1\n right -= 1\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return the area of\n the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n Otherwise return -1.\n \n Three sides make a valid triangle when the sum of any two sides is greater \n than the third side.\n \n Example:\n triangle_area(3, 4, 5) == 6.00\n triangle_area(1, 2, 10) == -1\n '''\n \n # Check for valid triangle using the triangle inequality theorem\n if a <= 0 or b <= 0 or c <= 0:\n return -1\n if a + b <= c or a + c <= b or b + c <= a:\n return -1\n \n # Calculate the semi-perimeter\n s = (a + b + c) / 2\n \n # Calculate the area using Heron's formula\n area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n \n # Return the area rounded to 2 decimal points\n return round(area, 2)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n '''\n Write a function that returns True if the object q will fly, and False otherwise.\n The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n\n Example:\n will_it_fly([1, 2], 5) \u279e False \n # 1+2 is less than the maximum possible weight, but it's unbalanced.\n\n will_it_fly([3, 2, 3], 1) \u279e False\n # it's balanced, but 3+2+3 is more than the maximum possible weight.\n\n will_it_fly([3, 2, 3], 9) \u279e True\n # 3+2+3 is less than the maximum possible weight, and it's balanced.\n\n will_it_fly([3], 5) \u279e True\n # 3 is less than the maximum possible weight, and it's balanced.\n '''\n\n # Check if the list is a palindrome\n is_balanced = (q == q[::-1])\n \n # Calculate the sum of the elements in the list\n total_weight = sum(q)\n \n # Check if the total weight is less than or equal to the maximum weight\n is_within_weight_limit = (total_weight <= w)\n \n # The object will fly if it is balanced and within the weight limit\n return is_balanced and is_within_weight_limit", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n \"\"\"\n Given an array arr of integers, find the minimum number of elements that\n need to be changed to make the array palindromic. A palindromic array is an array that\n is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n For example:\n smallest_change([1,2,3,5,4,7,9,6]) == 4\n smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n smallest_change([1, 2, 3, 2, 1]) == 0\n \"\"\"\n n = len(arr)\n changes = 0\n \n # Compare elements from the start and end towards the center\n for i in range(n // 2):\n if arr[i] != arr[n - 1 - i]:\n changes += 1\n \n return changes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n \n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total character counts and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n else:\n return lst2", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef generate_primes(limit):\n \"\"\"Generate a list of prime numbers up to a given limit.\"\"\"\n return [num for num in range(2, limit) if is_prime(num)]\ndef is_multiply_prime(a):\n \"\"\"Return True if the given number is the multiplication of 3 prime numbers, False otherwise.\"\"\"\n if a < 1 or a >= 100:\n return False # a must be less than 100 and greater than 0\n\n primes = generate_primes(100)\n \n # Check all combinations of three primes\n for i in range(len(primes)):\n for j in range(i, len(primes)):\n for k in range(j, len(primes)):\n product = primes[i] * primes[j] * primes[k]\n if product == a:\n return True\n if product > a:\n break # No need to check further if product exceeds a\n\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n \"\"\"Returns True if x is a simple power of n, otherwise False.\n \n A number x is a simple power of n if there exists an integer k such that n**k = x.\n \n Args:\n x (int): The number to check.\n n (int): The base number.\n \n Returns:\n bool: True if x is a simple power of n, False otherwise.\n \"\"\"\n # Edge case: if n is 0 or 1\n if n == 0:\n return x == 0 # 0**0 is undefined, but we can consider it as False\n if n == 1:\n return x == 1 # 1**k is always 1 for any k\n \n # Edge case: if x is less than 1\n if x < 1:\n return False # No positive power of n can yield a number less than 1\n \n # Check if x is a power of n\n power = 1\n while True:\n result = n ** power\n if result == x:\n return True\n elif result > x:\n return False\n power += 1", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1, 12]], "plus_fail_tests": []}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this integer is a cube of some integer number.\n Note: you may assume the input is always valid.\n \n Examples:\n iscube(1) ==> True\n iscube(2) ==> False\n iscube(-1) ==> True\n iscube(64) ==> True\n iscube(0) ==> True\n iscube(180) ==> False\n '''\n # Calculate the cube root of the absolute value of a\n cube_root = round(abs(a) ** (1/3))\n \n # Check if the cube of the rounded cube root equals the absolute value of a\n return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n \"\"\"Counts the number of prime hexadecimal digits in the given hexadecimal string.\n \n Hexadecimal digits that are considered prime: 2, 3, 5, 7, B (11), D (13).\n \n Args:\n num (str): A string representing a hexadecimal number.\n \n Returns:\n int: The count of prime hexadecimal digits.\n \"\"\"\n # Define the set of prime hexadecimal digits\n prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n \n # Initialize a counter for prime digits\n count = 0\n \n # Iterate through each character in the input string\n for char in num:\n if char in prime_hex_digits:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n \"\"\"Convert a decimal number to binary format with specific formatting.\n\n Args:\n decimal (int): A non-negative integer to convert to binary.\n\n Returns:\n str: A string representing the binary number, formatted with 'db' at the beginning and end.\n\n Examples:\n decimal_to_binary(15) # returns \"db1111db\"\n decimal_to_binary(32) # returns \"db100000db\"\n \"\"\"\n if not isinstance(decimal, int) or decimal < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n\n # Convert decimal to binary using built-in function and remove the '0b' prefix\n binary_representation = bin(decimal)[2:]\n\n # Format the result with 'db' at the beginning and end\n formatted_result = f\"db{binary_representation}db\"\n \n return formatted_result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n \"\"\"Check if the string s is happy.\n \n A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n \n Args:\n s (str): The input string to check.\n \n Returns:\n bool: True if the string is happy, False otherwise.\n \"\"\"\n # Check if the length of the string is at least 3\n if len(s) < 3:\n return False\n \n # Iterate through the string and check every 3 consecutive characters\n for i in range(len(s) - 2):\n # Get the current substring of 3 characters\n substring = s[i:i+3]\n # Check if all characters in the substring are distinct\n if len(set(substring)) != 3:\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n \"\"\"Helper function to determine if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_length(string):\n \"\"\"Check if the length of the string is a prime number.\"\"\"\n length = len(string)\n return is_prime(length)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n \"\"\"Convert a list of GPAs to letter grades based on a specified grading scale.\"\"\"\n letter_grades = []\n \n for gpa in grades:\n if gpa == 4.0:\n letter_grades.append('A+')\n elif gpa > 3.7:\n letter_grades.append('A')\n elif gpa > 3.3:\n letter_grades.append('A-')\n elif gpa > 3.0:\n letter_grades.append('B+')\n elif gpa > 2.7:\n letter_grades.append('B')\n elif gpa > 2.3:\n letter_grades.append('B-')\n elif gpa > 2.0:\n letter_grades.append('C+')\n elif gpa > 1.7:\n letter_grades.append('C')\n elif gpa > 1.3:\n letter_grades.append('C-')\n elif gpa > 1.0:\n letter_grades.append('D+')\n elif gpa > 0.7:\n letter_grades.append('D')\n elif gpa > 0.0:\n letter_grades.append('D-')\n elif gpa == 0.0:\n letter_grades.append('E')\n else:\n letter_grades.append('Invalid GPA') # Handle invalid GPAs (negative values)\n \n return letter_grades", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits will be 1 the output should be \"1\".\n For N = 150, the sum of digits will be 6 the output should be \"110\".\n For N = 147, the sum of digits will be 12 the output should be \"1100\".\n \n Variables:\n @N integer\n Constraints: 0 \u2264 N \u2264 10000.\n Output:\n a string of binary number\n \"\"\"\n if N < 0 or N > 10000:\n raise ValueError(\"N must be between 0 and 10000 inclusive.\")\n \n # Calculate the sum of the digits of N\n digit_sum = sum(int(digit) for digit in str(N))\n \n # Convert the sum to binary and remove the '0b' prefix\n binary_sum = bin(digit_sum)[2:]\n \n return binary_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n \"\"\"\n Given a positive integer n, return the count of the numbers of n-digit\n positive integers that start or end with 1.\n \n Parameters:\n n (int): The number of digits in the positive integers to consider.\n \n Returns:\n int: The count of n-digit positive integers that start or end with 1.\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer.\")\n \n if n == 1:\n # For 1-digit numbers, only the number '1' qualifies\n return 1\n \n # Total n-digit numbers\n total_n_digit_numbers = 9 * (10 ** (n - 1))\n \n # Count of n-digit numbers that start with 1\n start_with_1 = 10 ** (n - 1) # 1 followed by (n-1) digits (0-9)\n \n # Count of n-digit numbers that end with 1\n end_with_1 = 9 * (10 ** (n - 2)) if n > 1 else 0 # (1-9) followed by (n-2) digits (0-9)\n \n # Count of n-digit numbers that both start and end with 1\n start_and_end_with_1 = 10 ** (n - 2) if n > 1 else 0 # 1 followed by (n-2) digits (0-9) and ending with 1\n \n # Using the principle of inclusion-exclusion\n count = (start_with_1 + end_with_1 - start_and_end_with_1)\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n add([1, 2, 3, 4, 5]) ==> 0\n add([0, 1, 2, 3, 4, 5]) ==> 6\n add([10, 11, 12, 13, 14]) ==> 12\n add([1]) ==> 0 # Single element, no odd index\n \"\"\"\n # Initialize the sum\n total = 0\n \n # Iterate over the list using index\n for index in range(1, len(lst), 2): # Start from index 1 and step by 2\n if lst[index] % 2 == 0: # Check if the element is even\n total += lst[index] # Add to total if it's even\n \n return total", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words while preserving spaces\n words = s.split(' ')\n \n # Function to sort characters in a word\n def sort_word(word):\n return ''.join(sorted(word))\n \n # Process each word and sort its characters\n sorted_words = [sort_word(word) for word in words]\n \n # Join the sorted words back with spaces\n result = ' '.join(sorted_words)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n or sort it in descending order if the sum( first index value, last index value) is even.\n\n Note:\n * don't change the given array.\n\n Examples:\n * sort_array([]) => []\n * sort_array([5]) => [5]\n * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n \"\"\"\n # Return an empty list if the input array is empty\n if not array:\n return []\n \n # Calculate the sum of the first and last elements\n first_element = array[0]\n last_element = array[-1]\n total_sum = first_element + last_element\n \n # Create a copy of the array to sort\n sorted_array = array.copy()\n \n # Sort the array based on the sum being odd or even\n if total_sum % 2 == 0:\n # Even sum: sort in descending order\n sorted_array.sort(reverse=True)\n else:\n # Odd sum: sort in ascending order\n sorted_array.sort()\n \n return sorted_array", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n # Iterate through each row and its index\n for row_index, row in enumerate(lst):\n # Iterate through each column in the row and its index\n for col_index, value in enumerate(row):\n # If the value matches x, store the coordinates\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort coordinates by row (ascending) and then by column (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating each letter down the alphabet by 4 positions.\"\"\"\n encrypted_string = []\n \n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Determine the base ASCII value depending on case\n base = ord('a') if char.islower() else ord('A')\n # Rotate the character by 4 positions\n new_char = chr((ord(char) - base + 4) % 26 + base)\n encrypted_string.append(new_char)\n else:\n # If it's not a letter, we can choose to ignore it or keep it as is\n # Here we choose to ignore non-alphabetic characters\n continue\n \n return ''.join(encrypted_string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Sort the unique elements\n sorted_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_elements[1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n '''\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n \n Examples\n any_int(5, 2, 7) \u279e True\n any_int(3, 2, 2) \u279e False\n any_int(3, -2, 1) \u279e True\n any_int(3.6, -2.2, 2) \u279e False\n '''\n \n # Check if all inputs are integers\n if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n # Check if one number is equal to the sum of the other two\n return x == y + z or y == x + z or z == x + y\n else:\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n \n For example:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n >>> is_bored(\"I am bored! Are you? I want to go home.\")\n 2\n >>> is_bored(\"What a beautiful day. I hope it lasts.\")\n 1\n >>> is_bored(\"I. I. I.\")\n 2\n >>> is_bored(\"\")\n 0\n >>> is_bored(\"!?.\")\n 0\n \"\"\"\n # Split the string into sentences based on the delimiters\n import re\n sentences = re.split(r'[.!?]', S)\n \n # Count the number of sentences that start with \"I\"\n boredom_count = 0\n for sentence in sentences:\n stripped_sentence = sentence.strip() # Remove leading/trailing whitespace\n if stripped_sentence.startswith(\"I\"):\n boredom_count += 1\n \n return boredom_count", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": []}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef sum_of_digits(n):\n \"\"\"Return the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n largest_prime = None\n \n for number in lst:\n if is_prime(number):\n if largest_prime is None or number > largest_prime:\n largest_prime = number\n \n if largest_prime is not None:\n return sum_of_digits(largest_prime)\n else:\n return 0 # Return 0 if no prime number is found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n \"\"\"\n Write a function that takes a message, and encodes in such a \n way that it swaps case of all letters, replaces all vowels in \n the message with the letter that appears 2 places ahead of that \n vowel in the English alphabet. \n Assume only letters. \n \n Examples:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n # Define vowels and their replacements\n vowels = 'aeiouAEIOU'\n vowel_replacements = {\n 'a': 'c', 'A': 'C',\n 'e': 'g', 'E': 'G',\n 'i': 'k', 'I': 'K',\n 'o': 'q', 'O': 'Q',\n 'u': 'w', 'U': 'W'\n }\n \n encoded_message = []\n \n for char in message:\n if char.isalpha(): # Check if the character is a letter\n # Swap case\n if char in vowels:\n # Replace vowel and swap case\n encoded_message.append(vowel_replacements[char])\n else:\n # Just swap case for consonants\n encoded_message.append(char.swapcase())\n else:\n # If it's not a letter, we can choose to ignore or keep it\n # Here we ignore non-letter characters as per the assumption\n continue\n \n return ''.join(encoded_message)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["TEST"]], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in lower \n case or all keys are strings in upper case, else return False.\n The function should return False if the given dictionary is empty.\n \n Examples:\n check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n \"\"\"\n \n # Check if the dictionary is empty\n if not input_dict:\n return False\n \n # Initialize flags for lower and upper case\n all_lower = True\n all_upper = True\n \n # Iterate through the keys of the dictionary\n for key in input_dict.keys():\n # Check if the key is a string\n if not isinstance(key, str):\n return False\n \n # Check if the key is lower case\n if key.islower():\n all_upper = False\n # Check if the key is upper case\n elif key.isupper():\n all_lower = False\n else:\n # If the key is neither lower nor upper case\n return False\n \n # Return True if all keys are either lower case or upper case\n return all_lower or all_upper", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_up_to(n):\n \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n primes = []\n for i in range(2, n):\n if is_prime(i):\n primes.append(i)\n return primes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.\n \"\"\"\n # Get the unit digit of the first number\n unit_digit_a = abs(a) % 10\n # Get the unit digit of the second number\n unit_digit_b = abs(b) % 10\n # Return the product of the unit digits\n return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n count_upper('aBCdEf') returns 1\n count_upper('abcdefg') returns 0\n count_upper('dBBE') returns 0\n \"\"\"\n # Define the set of uppercase vowels\n uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n \n # Initialize a counter for uppercase vowels at even indices\n count = 0\n \n # Iterate over the string, checking only even indices\n for i in range(0, len(s), 2): # Step by 2 to get even indices\n if s[i] in uppercase_vowels:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n >>> closest_integer(\"14.5\")\n 15\n >>> closest_integer(\"-14.5\")\n -15\n >>> closest_integer(\"0.5\")\n 1\n >>> closest_integer(\"-0.5\")\n -1\n >>> closest_integer(\"3.0\")\n 3\n >>> closest_integer(\"-3.0\")\n -3\n >>> closest_integer(\"2.499999\")\n 2\n >>> closest_integer(\"-2.499999\")\n -2\n '''\n\n # Convert the string input to a float\n num = float(value)\n\n # Calculate the floor and ceiling of the number\n lower_int = int(num // 1) # This is the largest integer less than or equal to num\n upper_int = lower_int + 1 # This is the smallest integer greater than num\n\n # Check the distance to the lower and upper integers\n distance_to_lower = abs(num - lower_int)\n distance_to_upper = abs(num - upper_int)\n\n # Determine which integer to return\n if distance_to_lower < distance_to_upper:\n return lower_int\n elif distance_to_upper < distance_to_lower:\n return upper_int\n else:\n # If equidistant, round away from zero\n if num > 0:\n return upper_int\n else:\n return lower_int", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n \"\"\"\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n >>> make_a_pile(4)\n [4, 6, 8, 10]\n >>> make_a_pile(1)\n [1]\n >>> make_a_pile(2)\n [2, 4]\n >>> make_a_pile(0)\n Traceback (most recent call last):\n ...\n ValueError: n must be a positive integer\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n \n stones = []\n current_stones = n\n \n for i in range(n):\n stones.append(current_stones)\n if current_stones % 2 == 0: # current_stones is even\n current_stones += 2 # next even number\n else: # current_stones is odd\n current_stones += 2 # next odd number\n \n return stones", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n \"\"\"\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n \"\"\"\n # Replace commas with spaces and split the string by whitespace\n words = s.replace(',', ' ').split()\n \n # Return the list of words\n return words", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n \"\"\"This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If \n there's no such number, then the function should return -1.\n\n For example:\n choose_num(12, 15) = 14\n choose_num(13, 12) = -1\n \"\"\"\n # Ensure x is less than or equal to y\n if x > y:\n return -1\n\n # Start from the largest number in the range and check for evenness\n for num in range(y, x - 1, -1):\n if num % 2 == 0:\n return num\n\n # If no even number is found, return -1\n return -1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n \"\"\"Given a list of positive integers x, return a sorted list of all \n elements that haven't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n def has_even_digit(n):\n \"\"\"Check if the number has any even digit.\"\"\"\n for digit in str(n):\n if int(digit) % 2 == 0:\n return True\n return False\n\n # Filter the list to include only numbers without even digits\n filtered_numbers = [num for num in x if not has_even_digit(num)]\n \n # Sort the resulting list\n return sorted(filtered_numbers)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n \"\"\"Compute the average of integers from n to m, round it to the nearest integer,\n and convert that to binary. If n is greater than m, return -1.\n \n Args:\n n (int): The starting integer (inclusive).\n m (int): The ending integer (inclusive).\n \n Returns:\n str or int: The binary representation of the rounded average if n <= m, \n otherwise -1.\n \"\"\"\n if n > m:\n return -1\n \n # Calculate the sum of integers from n to m\n total_sum = sum(range(n, m + 1))\n count = m - n + 1 # Total numbers from n to m\n \n # Calculate the average and round it\n average = total_sum / count\n rounded_average = round(average)\n \n # Convert the rounded average to binary\n return bin(rounded_average)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def f(n):\n \"\"\" \n Implement the function f that takes n as a parameter,\n and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even\n or the sum of numbers from 1 to i otherwise.\n i starts from 1.\n \"\"\"\n if n <= 0:\n return [] # Return an empty list for non-positive n\n\n result = []\n \n for i in range(1, n + 1):\n if i % 2 == 0: # Even index\n factorial = 1\n for j in range(1, i + 1):\n factorial *= j\n result.append(factorial)\n else: # Odd index\n sum_of_numbers = sum(range(1, i + 1))\n result.append(sum_of_numbers)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n reverse the resulting array, and then replace each digit by its corresponding name from\n \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n For example:\n arr = [2, 1, 1, 4, 5, 8, 2, 3] \n -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n \n If the array is empty, return an empty array:\n arr = []\n return []\n \n If the array has any strange number ignore it:\n arr = [1, -1 , 55] \n -> sort arr -> [-1, 1, 55]\n -> reverse arr -> [55, 1, -1]\n return = ['One']\n \"\"\"\n \n # Mapping of digits to their corresponding names\n digit_to_name = {\n 1: \"One\",\n 2: \"Two\",\n 3: \"Three\",\n 4: \"Four\",\n 5: \"Five\",\n 6: \"Six\",\n 7: \"Seven\",\n 8: \"Eight\",\n 9: \"Nine\"\n }\n \n # Filter the array to include only integers between 1 and 9\n filtered_arr = [num for num in arr if 1 <= num <= 9]\n \n # Sort the filtered array\n filtered_arr.sort()\n \n # Reverse the sorted array\n filtered_arr.reverse()\n \n # Convert the digits to their corresponding names\n result = [digit_to_name[num] for num in filtered_arr]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n \"\"\"\n Write a function count_nums which takes an array of integers and returns\n the number of elements which has a sum of digits > 0.\n If a number is negative, then its first signed digit will be negative:\n e.g. -123 has signed digits -1, 2, and 3.\n \n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n def sum_of_digits(n):\n \"\"\"Helper function to calculate the sum of digits of an integer n.\"\"\"\n # Convert the number to string and iterate over each character\n # If the number is negative, we need to consider the first digit as negative\n str_n = str(n)\n digit_sum = 0\n \n for i, char in enumerate(str_n):\n if char.isdigit():\n digit_sum += int(char)\n elif i == 0 and char == '-':\n digit_sum -= 1 # First signed digit is negative\n \n return digit_sum\n\n count = 0\n for number in arr:\n if sum_of_digits(number) > 0:\n count += 1\n \n return count", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[-1, -2, 0]]], "plus_fail_tests": []}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n \"\"\"\n Given a positive integer n, return a tuple that has the number of even and odd\n integer palindromes that fall within the range(1, n), inclusive.\n\n Example 1:\n Input: 3\n Output: (1, 2)\n Explanation:\n Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n Example 2:\n Input: 12\n Output: (4, 6)\n Explanation:\n Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n Note:\n 1. 1 <= n <= 10^3\n 2. returned tuple has the number of even and odd integer palindromes respectively.\n \"\"\"\n \n def is_palindrome(num):\n \"\"\"Check if a number is a palindrome.\"\"\"\n return str(num) == str(num)[::-1]\n\n even_count = 0\n odd_count = 0\n\n for i in range(1, n + 1):\n if is_palindrome(i):\n if i % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return True else return False.\n If the given array is empty then return True.\n\n Note: The given list is guaranteed to have unique elements.\n\n For Example:\n \n move_one_ball([3, 4, 5, 1, 2])==>True\n Explanation: By performing 2 right shift operations, non-decreasing order can\n be achieved for the given array.\n move_one_ball([3, 5, 4, 1, 2])==>False\n Explanation: It is not possible to get non-decreasing order for the given\n array by performing any number of right shift operations.\n \"\"\"\n \n if not arr: # Check for empty array\n return True\n\n n = len(arr)\n count = 0\n\n # Count the number of times the array is not in non-decreasing order\n for i in range(n):\n if arr[i] > arr[(i + 1) % n]:\n count += 1\n\n # If there are more than one \"breaks\" in the order, we cannot sort it\n return count <= 1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n \"\"\"Determines whether it is possible to perform an exchange of elements\n between two lists to make lst1 a list of only even numbers.\n \n Args:\n lst1 (list): The first list of numbers.\n lst2 (list): The second list of numbers.\n \n Returns:\n str: \"YES\" if lst1 can be made entirely even, otherwise \"NO\".\n \"\"\"\n # Check if all elements in lst1 are already even\n if all(x % 2 == 0 for x in lst1):\n return \"YES\"\n \n # Count the number of odd elements in lst1\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n \n # Count the number of even elements in lst2\n even_count_lst2 = sum(1 for x in lst2 if x % 2 == 0)\n \n # If there are enough even numbers in lst2 to replace all odd numbers in lst1\n if odd_count_lst1 <= even_count_lst2:\n return \"YES\"\n \n return \"NO\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n \"\"\"\n Task\n We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and True/False for the check.\n \n Example\n For s = \"abcde\", c = \"ae\", the result should be ('bcd', False)\n For s = \"abcdef\", c = \"b\", the result should be ('acdef', False)\n For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc', True)\n \"\"\"\n \n # Create a set of characters to delete for faster lookup\n chars_to_delete = set(c)\n \n # Build the result string by filtering out unwanted characters\n result = ''.join(char for char in s if char not in chars_to_delete)\n \n # Check if the result string is a palindrome\n is_palindrome = result == result[::-1]\n \n return (result, is_palindrome)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n \"\"\"\n if not test:\n return {}\n\n # Split the input string into a list of letters\n letters = test.split()\n \n # Create a dictionary to count occurrences of each letter\n count_dict = {}\n for letter in letters:\n if letter in count_dict:\n count_dict[letter] += 1\n else:\n count_dict[letter] = 1\n\n # Find the maximum count\n max_count = max(count_dict.values())\n \n # Create a result dictionary for letters with the maximum count\n result = {letter: count for letter, count in count_dict.items() if count == max_count}\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n Example\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n \"\"\"\n if not nums:\n raise ValueError(\"The input array must not be empty.\")\n \n # Initialize variables to track the minimum sum and the current sum\n min_sum = float('inf')\n current_sum = 0\n \n for num in nums:\n current_sum += num\n min_sum = min(min_sum, current_sum)\n \n # If current_sum is positive, reset it to 0\n if current_sum > 0:\n current_sum = 0\n \n return min_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3', \"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n \n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in s if char in '13579')\n \n # Create the output string with the count of odd digits\n output_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n \n # Append the result to the list\n result.append(output_string)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n \"\"\"\n Calculate the number of times buckets need to be lowered to empty the wells.\n\n Parameters:\n grid (list of list of int): A rectangular grid representing wells.\n capacity (int): The capacity of each bucket.\n\n Returns:\n int: The total number of times buckets need to be lowered.\n \"\"\"\n total_water = 0\n \n # Count the total amount of water in the grid\n for row in grid:\n total_water += sum(row)\n \n # Calculate the number of times buckets need to be lowered\n if total_water == 0:\n return 0 # No water to extract\n \n # Each bucket can carry 'capacity' units of water\n # We need to lower the bucket enough times to extract all the water\n return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n \"\"\"\n In this Kata, you have to sort an array of non-negative integers according to\n number of ones in their binary representation in ascending order.\n For similar number of ones, sort based on decimal value.\n\n It must be implemented like this:\n >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n >>> sort_array([1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]\n \"\"\"\n # Filter out negative numbers as the problem states non-negative integers\n non_negative_arr = [x for x in arr if x >= 0]\n \n # Sort the array based on the number of 1s in binary representation and then by value\n sorted_arr = sorted(non_negative_arr, key=lambda x: (bin(x).count('1'), x))\n \n return sorted_arr", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[-2, -3, -4, -5, -6]]], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n two consonants from the right side of the word (case sensitive).\n \n Vowels in the beginning and ending don't count. Return empty string if you didn't\n find any vowel that meets the above condition. \n\n You may assume that the given string contains English letters only.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n length = len(word)\n\n # Check for edge cases\n if length < 3: # Need at least two consonants and one vowel in between\n return \"\"\n\n # Iterate from the end of the word to the beginning\n for i in range(length - 2, 0, -1):\n if word[i] in vowels: # Check if the current character is a vowel\n # Check if the characters before and after are consonants\n if word[i - 1].isalpha() and word[i - 1] not in vowels and \\\n word[i + 1].isalpha() and word[i + 1] not in vowels:\n return word[i] # Return the closest vowel found\n\n return \"\" # Return empty string if no valid vowel is found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n \"\"\"Given a string s and a natural number n, returns a list of all words from string s \n that contain exactly n consonants, in the order they appear in the string s.\n \n Args:\n s (str): The input string containing words.\n n (int): The number of consonants to filter words by.\n \n Returns:\n list: A list of words containing exactly n consonants.\n \"\"\"\n \n if not s: # Check if the string is empty\n return []\n \n # Define a set of vowels for easy checking\n vowels = set(\"aeiouAEIOU\")\n \n def count_consonants(word):\n \"\"\"Helper function to count consonants in a word.\"\"\"\n return sum(1 for char in word if char.isalpha() and char not in vowels)\n \n # Split the string into words\n words = s.split()\n \n # Filter words based on the number of consonants\n result = [word for word in words if count_consonants(word) == n]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0: # More closing than opening\n return False\n return balance == 0 # Must be balanced at the end\n\n s1, s2 = lst[0], lst[1]\n\n # Check both concatenation orders\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n \n # Sort the array in descending order and take the first k elements\n max_k_elements = sorted(arr, reverse=True)[:k]\n \n # Sort the result in ascending order before returning\n return sorted(max_k_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n An even position is defined as an index that is even (0, 2, 4, ...).\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index in range(len(lst)):\n # Check if the index is even\n if index % 2 == 0:\n # Check if the element at this index is odd\n if lst[index] % 2 != 0:\n total_sum += lst[index]\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n \"\"\"\n Given a non-empty array of integers arr and an integer k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example:\n\n Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n Output: 24 # sum of 21 + 3\n\n Constraints:\n 1. 1 <= len(arr) <= 100\n 2. 1 <= k <= len(arr)\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate through the first k elements of the array\n for i in range(k):\n # Check if the current element has at most two digits\n if -100 < arr[i] < 100:\n total_sum += arr[i]\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n \n The date is valid if all of the following rules are satisfied:\n 1. The date string is not empty.\n 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n The number of days is not less than 1 or higher than 29 for the month 2.\n 3. The months should not be less than 1 or higher than 12.\n 4. The date should be in the format: mm-dd-yyyy\n \n Args:\n date (str): The date string to validate.\n \n Returns:\n bool: True if the date is valid, False otherwise.\n \"\"\"\n \n # Check if the date string is empty\n if not date:\n return False\n \n # Check if the date format is correct\n if len(date) != 10 or date[2] != '-' or date[5] != '-':\n return False\n \n # Split the date into components\n try:\n month, day, year = map(int, date.split('-'))\n except ValueError:\n return False # In case of conversion failure\n \n # Check month range\n if month < 1 or month > 12:\n return False\n \n # Check day range based on month\n if month in {1, 3, 5, 7, 8, 10, 12}:\n if day < 1 or day > 31:\n return False\n elif month in {4, 6, 9, 11}:\n if day < 1 or day > 30:\n return False\n elif month == 2:\n if day < 1 or day > 29:\n return False\n \n # If all checks passed, the date is valid\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n as follows: start with any positive integer n. Then each term is obtained from the \n previous term as follows: if the previous term is even, the next term is one half of \n the previous term. If the previous term is odd, the next term is 3 times the previous\n term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n Note: \n 1. Collatz(1) is [1].\n 2. returned list sorted in increasing order.\n\n For example:\n get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n collatz_sequence = []\n current = n\n \n while current != 1:\n collatz_sequence.append(current)\n if current % 2 == 0:\n current //= 2\n else:\n current = 3 * current + 1\n \n collatz_sequence.append(1) # Append the last term which is 1\n \n # Filter odd numbers and sort them\n odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n \n return odd_numbers", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n '''\n Given a string of words, return a list of words split on whitespace, \n if no whitespaces exists in the text you should split on commas ',' \n if no commas exists you should return the number of lower-case letters \n with odd order in the alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n \n Examples:\n split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"abcdef\") \u279e 3 \n '''\n \n # Check for whitespace\n if ' ' in txt:\n return txt.split()\n \n # Check for commas\n elif ',' in txt:\n return txt.split(',')\n \n # If no whitespace or commas, count lower-case letters with odd order\n else:\n odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n return odd_count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n '''\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return False. Assume no negative numbers and only integers.\n\n Examples\n is_sorted([5]) \u279e True\n is_sorted([1, 2, 3, 4, 5]) \u279e True\n is_sorted([1, 3, 2, 4, 5]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n '''\n \n if len(lst) <= 1:\n return True # A list with 0 or 1 element is sorted by definition\n\n seen = set()\n previous = None\n\n for num in lst:\n if num in seen:\n # If we see a number again, check if it's the same as the previous\n if num == previous:\n return False # More than 1 duplicate of the same number\n else:\n seen.add(num)\n\n if previous is not None and num < previous:\n return False # Not sorted in ascending order\n\n previous = num\n\n return True", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef intersection(interval1, interval2):\n \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n start1, end1 = interval1\n start2, end2 = interval2\n \n # Find the intersection\n start_intersection = max(start1, start2)\n end_intersection = min(end1, end2)\n \n # Check if there is an intersection\n if start_intersection > end_intersection:\n return \"NO\"\n \n # Calculate the length of the intersection\n length_of_intersection = end_intersection - start_intersection\n \n # Check if the length is a prime number\n if is_prime(length_of_intersection):\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n if not arr: # Check for empty array\n return None\n\n product_of_signs = 1\n sum_of_magnitudes = 0\n\n for num in arr:\n if num > 0:\n sum_of_magnitudes += num\n elif num < 0:\n sum_of_magnitudes += -num\n product_of_signs *= -1 # Flip the sign for negative numbers\n else: # num == 0\n return 0 # If there's a zero, the product of signs is zero\n\n return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n \"\"\"Calculate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n if n < 0:\n return [] # Return an empty list for negative input\n\n # Initialize the list to hold the Tribonacci numbers\n tribonacci_sequence = []\n\n # Calculate the Tribonacci numbers based on the given rules\n for i in range(n + 1):\n if i == 1:\n tribonacci_sequence.append(3) # tri(1) = 3\n elif i == 0:\n tribonacci_sequence.append(1) # tri(0) = 1\n elif i % 2 == 0: # Even index\n tribonacci_sequence.append(1 + i / 2)\n else: # Odd index\n # Calculate tri(i) = tri(i - 1) + tri(i - 2) + tri(i + 1)\n if i + 1 <= n:\n next_value = tribonacci_sequence[i - 1] + tribonacci_sequence[i - 2] + (1 + (i + 1) / 2)\n else:\n next_value = tribonacci_sequence[i - 1] + tribonacci_sequence[i - 2] + 3 # tri(n) = 3 for n=1\n tribonacci_sequence.append(next_value)\n\n return tribonacci_sequence", "base_status": "fail", "plus_status": null, "base_fail_tests": [[5]], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n \"\"\"Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n \n Args:\n n (int): A positive integer.\n\n Returns:\n int: The product of the odd digits or 0 if all digits are even.\n \n Examples:\n >>> digits(1)\n 1\n >>> digits(4)\n 0\n >>> digits(235)\n 15\n >>> digits(2468)\n 0\n >>> digits(13579)\n 945\n >>> digits(0) # Edge case: should not be called with 0 as per problem statement\n Traceback (most recent call last):\n ...\n ValueError: n must be a positive integer\n \"\"\"\n \n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n \n product = 1\n has_odd_digit = False\n \n while n > 0:\n digit = n % 10\n if digit % 2 != 0: # Check if the digit is odd\n product *= digit\n has_odd_digit = True\n n //= 10 # Remove the last digit\n \n return product if has_odd_digit else 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n '''\n Create a function that takes a string as input which contains only square brackets.\n The function should return True if and only if there is a valid subsequence of brackets \n where at least one bracket in the subsequence is nested.\n\n is_nested('[[]]') \u279e True\n is_nested('[]]]]]]][[[[[]') \u279e False\n is_nested('[][]') \u279e False\n is_nested('[]') \u279e False\n is_nested('[[][]]') \u279e True\n is_nested('[[]][[') \u279e True\n '''\n \n # Initialize a counter for open brackets\n open_count = 0\n # Initialize a flag to check for nesting\n nested = False\n \n for char in string:\n if char == '[':\n open_count += 1\n # If we have more than one open bracket, we have a nested structure\n if open_count > 1:\n nested = True\n elif char == ']':\n open_count -= 1\n # If we close a bracket and there were open brackets, we check for valid nesting\n if open_count < 0:\n return False # More closing brackets than opening\n # We can ignore any other characters since the problem states only square brackets are present\n \n # We need to have no unmatched opening brackets at the end\n return nested and open_count == 0", "base_status": "fail", "plus_status": null, "base_fail_tests": [["[[]][["]], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers.\n You need to return the sum of squared numbers in the given list,\n round each element in the list to the upper int (Ceiling) first.\n \n Examples:\n For lst = [1,2,3] the output should be 14\n For lst = [1,4,9] the output should be 98\n For lst = [1,3,5,7] the output should be 84\n For lst = [1.4,4.2,0] the output should be 29\n For lst = [-2.4,1,1] the output should be 6\n \"\"\"\n # Initialize the sum of squares\n total_sum = 0\n \n # Iterate through each number in the list\n for number in lst:\n # Round the number up to the nearest integer\n rounded_number = math.ceil(number)\n # Add the square of the rounded number to the total sum\n total_sum += rounded_number ** 2\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n '''\n Create a function that returns True if the last character\n of a given string is an alphabetical character and is not\n a part of a word, and False otherwise.\n Note: \"word\" is a group of characters separated by space.\n\n Examples:\n check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '''\n \n # Strip any trailing whitespace from the string\n txt = txt.rstrip()\n \n # Check if the string is empty after stripping\n if not txt:\n return False\n \n # Get the last character of the string\n last_char = txt[-1]\n \n # Check if the last character is an alphabetical character\n if last_char.isalpha():\n # Check if the last character is part of a word\n # A character is part of a word if it is preceded by a non-space character\n if len(txt) > 1 and txt[-2] != ' ':\n return False\n return True\n \n return False", "base_status": "fail", "plus_status": null, "base_fail_tests": [["eeeee e "]], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n from collections import deque\n \n N = len(grid)\n directions = [(0, 1), (1, 0), (0, -1), (-1, 0)] # Right, Down, Left, Up\n min_path = None\n \n def bfs(start_row, start_col):\n nonlocal min_path\n queue = deque([(start_row, start_col, [grid[start_row][start_col]])])\n \n while queue:\n row, col, path = queue.popleft()\n \n if len(path) == k:\n if min_path is None or path < min_path:\n min_path = path\n continue\n \n for dr, dc in directions:\n new_row, new_col = row + dr, col + dc\n if 0 <= new_row < N and 0 <= new_col < N:\n queue.append((new_row, new_col, path + [grid[new_row][new_col]]))\n \n for i in range(N):\n for j in range(N):\n bfs(i, j)\n \n return min_path", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n \"\"\"Create a function which returns the largest index of an element which\n is not greater than or equal to the element immediately preceding it. If\n no such element exists then return -1. The given array will not contain\n duplicate values.\n\n Examples:\n can_arrange([1,2,4,3,5]) = 3\n can_arrange([1,2,3]) = -1\n \"\"\"\n # Check if the array is empty\n if not arr:\n return -1\n\n # Initialize the largest index to -1\n largest_index = -1\n\n # Iterate through the array starting from the second element\n for i in range(1, len(arr)):\n # Check if the current element is less than the previous one\n if arr[i] < arr[i - 1]:\n largest_index = i # Update the largest index\n\n return largest_index", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n '''\n Create a function that returns a tuple (a, b), where 'a' is\n the largest of negative integers, and 'b' is the smallest\n of positive integers in a list.\n If there is no negative or positive integers, return them as None.\n\n Examples:\n largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n largest_smallest_integers([]) == (None, None)\n largest_smallest_integers([0]) == (None, None)\n '''\n \n largest_negative = None\n smallest_positive = None\n \n for num in lst:\n if num < 0:\n if largest_negative is None or num > largest_negative:\n largest_negative = num\n elif num > 0:\n if smallest_positive is None or num < smallest_positive:\n smallest_positive = num\n \n return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n \n Args:\n n (int): The number to evaluate.\n \n Returns:\n bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n \n Example:\n is_equal_to_sum_even(4) == False\n is_equal_to_sum_even(6) == False\n is_equal_to_sum_even(8) == True\n \"\"\"\n \n # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n if n < 8:\n return False\n \n # Check if n is even\n if n % 2 != 0:\n return False\n \n # If n is even and n >= 8, it can be expressed as the sum of 4 positive even numbers\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def parse_number(value):\n \"\"\"\n Convert a string representation of a number into a float or return the value as is.\n Handles both '.' and ',' as decimal separators.\n \"\"\"\n if isinstance(value, str):\n # Replace ',' with '.' for float conversion\n value = value.replace(',', '.')\n try:\n return float(value)\n except ValueError:\n return value # Return the original value if it cannot be converted\ndef compare_one(a, b):\n \"\"\"\n Compare two values (integers, floats, or strings representing real numbers)\n and return the larger one in its original type. Return None if they are equal.\n \"\"\"\n # Parse both values\n parsed_a = parse_number(a)\n parsed_b = parse_number(b)\n\n # Check for equality\n if parsed_a == parsed_b:\n return None\n\n # Return the larger value in its original type\n return a if parsed_a > parsed_b else b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n \"\"\"\n Given a string text, replace all spaces in it with underscores, \n and if a string has more than 2 consecutive spaces, \n then replace all consecutive spaces with - \n \n fix_spaces(\"Example\") == \"Example\"\n fix_spaces(\"Example 1\") == \"Example_1\"\n fix_spaces(\" Example 2\") == \"_Example_2\"\n fix_spaces(\" Example 3\") == \"_Example-3\"\n \"\"\"\n # Replace multiple spaces with a placeholder\n # This will help us identify sequences of spaces\n placeholder = '##'\n text = text.replace(' ' * 3, placeholder) # Replace 3 spaces with a placeholder\n \n # Replace remaining spaces with underscores\n text = text.replace(' ', '_')\n \n # Replace the placeholder back to '-'\n text = text.replace(placeholder, '-')\n \n return text", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n \"\"\"Helper function to compute the factorial of a non-negative integer n.\"\"\"\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef special_factorial(n):\n \"\"\"Calculate the Brazilian factorial of n.\"\"\"\n if n < 1:\n raise ValueError(\"Input must be a positive integer greater than 0.\")\n \n result = 1\n for i in range(1, n + 1):\n result *= factorial(i)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n \"\"\"Check if the given file name is valid based on specific criteria.\"\"\"\n \n # Define valid extensions\n valid_extensions = ['txt', 'exe', 'dll']\n \n # Check for exactly one dot\n if file_name.count('.') != 1:\n return 'No'\n \n # Split the file name into name and extension\n name, extension = file_name.split('.')\n \n # Check if the name is empty\n if not name:\n return 'No'\n \n # Check if the name starts with a letter\n if not name[0].isalpha():\n return 'No'\n \n # Check if the extension is valid\n if extension not in valid_extensions:\n return 'No'\n \n # Count digits in the file name\n digit_count = sum(c.isdigit() for c in file_name)\n \n # Check if there are more than three digits\n if digit_count > 3:\n return 'No'\n \n # If all checks are passed, return 'Yes'\n return 'Yes'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n \"\"\"\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n \n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126\n \"\"\"\n total_sum = 0\n \n for index, value in enumerate(lst):\n if index % 3 == 0:\n # Square the value if index is a multiple of 3\n total_sum += value ** 2\n elif index % 4 == 0:\n # Cube the value if index is a multiple of 4 and not a multiple of 3\n total_sum += value ** 3\n else:\n # Add the value unchanged if index is not a multiple of 3 or 4\n total_sum += value\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n \"\"\"Simplifies the expression x * n and checks if the result is a whole number.\n \n Args:\n x (str): A string representation of a fraction in the format /.\n n (str): A string representation of a fraction in the format /.\n \n Returns:\n bool: True if x * n evaluates to a whole number, False otherwise.\n \"\"\"\n # Split the fractions into numerator and denominator\n x_numerator, x_denominator = map(int, x.split('/'))\n n_numerator, n_denominator = map(int, n.split('/'))\n \n # Calculate the product of the fractions\n # x * n = (x_numerator / x_denominator) * (n_numerator / n_denominator)\n # This simplifies to (x_numerator * n_numerator) / (x_denominator * n_denominator)\n \n product_numerator = x_numerator * n_numerator\n product_denominator = x_denominator * n_denominator\n \n # Check if the product is a whole number\n return product_numerator % product_denominator == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef words_in_sentence(sentence):\n \"\"\"\n Given a string representing a sentence, return a string that contains the words\n from the original sentence whose lengths are prime numbers.\n \n Parameters:\n sentence (str): The input sentence containing words separated by spaces.\n \n Returns:\n str: A string containing the words with prime lengths, in the original order.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Filter words whose lengths are prime\n prime_length_words = [word for word in words if is_prime(len(word))]\n \n # Join the filtered words back into a string\n return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n \"\"\"Returns the number of elements in the array that are greater than 10 \n and both the first and last digits of the number are odd (1, 3, 5, 7, 9).\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n int: The count of numbers meeting the criteria.\n \"\"\"\n \n def is_odd_digit(digit):\n \"\"\"Check if a digit is odd.\"\"\"\n return digit in {'1', '3', '5', '7', '9'}\n \n def first_and_last_digits_are_odd(num):\n \"\"\"Check if both the first and last digits of the number are odd.\"\"\"\n num_str = str(abs(num)) # Convert to string and take absolute value\n return is_odd_digit(num_str[0]) and is_odd_digit(num_str[-1])\n \n count = 0\n for num in nums:\n if num > 10 and first_and_last_digits_are_odd(num):\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n \"\"\"\n Write a function which sorts the given list of integers\n in ascending order according to the sum of their digits.\n Note: if there are several items with similar sum of their digits,\n order them based on their index in original list.\n\n For example:\n >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n >>> order_by_points([]) == []\n \"\"\"\n \n def digit_sum(n):\n \"\"\"Calculate the sum of the digits of an integer n.\"\"\"\n return sum(int(digit) for digit in str(abs(n)))\n\n # Create a list of tuples (digit_sum, index, value)\n indexed_nums = [(digit_sum(num), index, num) for index, num in enumerate(nums)]\n \n # Sort by digit sum first, then by original index\n sorted_nums = sorted(indexed_nums, key=lambda x: (x[0], x[1]))\n \n # Extract the sorted values\n return [num for _, _, num in sorted_nums]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closest to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sorted by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct planet names. \n Examples\n bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n '''\n\n # List of planets in order from the Sun\n planets = [\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n ]\n \n # Check if both planets are valid\n if planet1 not in planets or planet2 not in planets:\n return ()\n \n # Get the indices of the planets\n index1 = planets.index(planet1)\n index2 = planets.index(planet2)\n \n # Determine the range of indices\n start_index = min(index1, index2) + 1\n end_index = max(index1, index2)\n \n # Get the planets in between\n in_between_planets = planets[start_index:end_index]\n \n # Return as a tuple\n return tuple(in_between_planets)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n \"\"\"\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example :\n Input: n = 5\n Output: 1\n Explanation: \n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n \"\"\"\n # Create the array a based on the given formula\n a = [i * i - i + 1 for i in range(1, n + 1)]\n \n # Count the number of valid triples\n count = 0\n \n # Iterate through all possible triples (i, j, k) with i < j < k\n for i in range(n):\n for j in range(i + 1, n):\n for k in range(j + 1, n):\n if (a[i] + a[j] + a[k]) % 3 == 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef x_or_y(n, x, y):\n \"\"\"Return the value of x if n is a prime number, otherwise return y.\"\"\"\n if is_prime(n):\n return x\n else:\n return y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length and alphabetically.\n \n Args:\n lst (list of str): A list of strings.\n \n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n \"\"\"\n Compares the actual scores of matches with the guessed scores.\n \n Parameters:\n game (list of int): The actual scores of the matches.\n guess (list of int): The guessed scores of the matches.\n \n Returns:\n list of int: A list where each element is the absolute difference \n between the actual score and the guessed score, or 0 if guessed correctly.\n \"\"\"\n # Check if the lengths of game and guess are equal\n if len(game) != len(guess):\n raise ValueError(\"The length of game and guess must be the same.\")\n \n # Calculate the absolute differences\n result = [abs(g - a) for a, g in zip(game, guess)]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n \n double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n double_the_difference([-1, -2, 0]) == 0\n double_the_difference([9, -2]) == 81\n double_the_difference([0]) == 0 \n \n If the input list is empty, return 0.\n '''\n # Initialize the sum of squares\n sum_of_squares = 0\n \n # Iterate through each number in the list\n for num in lst:\n # Check if the number is a positive odd integer\n if isinstance(num, int) and num >= 0 and num % 2 != 0:\n sum_of_squares += num ** 2\n \n return sum_of_squares", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n \"\"\"Find the strongest extension based on the defined strength criteria.\"\"\"\n \n def calculate_strength(extension):\n \"\"\"Calculate the strength of the extension.\"\"\"\n CAP = sum(1 for char in extension if char.isupper())\n SM = sum(1 for char in extension if char.islower())\n return CAP - SM\n\n strongest_extension = None\n strongest_strength = float('-inf') # Start with the lowest possible strength\n\n for extension in extensions:\n strength = calculate_strength(extension)\n \n # Check if this extension is stronger or if it's the first one\n if strength > strongest_strength:\n strongest_strength = strength\n strongest_extension = extension\n\n if strongest_extension is not None:\n return f\"{class_name}.{strongest_extension}\"\n else:\n return None # In case there are no extensions", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n \"\"\"Check if the second word or any of its rotations is a substring of the first word.\"\"\"\n \n # Edge case: if b is empty, it is always a substring\n if not b:\n return True\n \n # Edge case: if a is empty and b is not, b cannot be a substring\n if not a:\n return False\n \n # Create a new string that is b concatenated with itself\n # This will contain all possible rotations of b as substrings\n b_rotations = b + b\n \n # Check if any rotation of b is a substring of a\n return b in b_rotations and len(b) <= len(a)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["xyzw", "xyw"]], "plus_fail_tests": []}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n Example:\n even_odd_count(-12) ==> (1, 1)\n even_odd_count(123) ==> (1, 2)\n \"\"\"\n # Convert the number to a string and handle negative sign\n num_str = str(abs(num))\n \n even_count = 0\n odd_count = 0\n \n for digit in num_str:\n if digit.isdigit(): # Ensure we are only counting digits\n if int(digit) % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n if not (1 <= number <= 1000):\n raise ValueError(\"Input must be between 1 and 1000 inclusive.\")\n\n # Mapping of integers to their corresponding Roman numeral representations\n roman_numerals = [\n (1000, 'm'),\n (900, 'cm'),\n (500, 'd'),\n (400, 'cd'),\n (100, 'c'),\n (90, 'xc'),\n (50, 'l'),\n (40, 'xl'),\n (10, 'x'),\n (9, 'ix'),\n (5, 'v'),\n (4, 'iv'),\n (1, 'i')\n ]\n\n result = []\n \n for value, numeral in roman_numerals:\n while number >= value:\n result.append(numeral)\n number -= value\n\n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n \"\"\"Return the word with the maximum number of unique characters.\n If multiple words have the same maximum number of unique characters,\n return the one that comes first in lexicographical order.\n \n Args:\n words (list of str): A list of words to evaluate.\n \n Returns:\n str: The word with the maximum number of unique characters.\n \"\"\"\n max_word = \"\"\n max_unique_count = 0\n\n for word in words:\n # Calculate the number of unique characters in the word\n unique_count = len(set(word))\n \n # Check if this word has more unique characters or is lexicographically smaller\n if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n max_word = word\n max_unique_count = unique_count\n\n return max_word", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return True if the three\n sides form a right-angled triangle, False otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or \n 90 degree.\n \n Example:\n right_angle_triangle(3, 4, 5) == True\n right_angle_triangle(1, 2, 3) == False\n '''\n \n # First, we need to check if the sides can form a triangle\n if a <= 0 or b <= 0 or c <= 0:\n return False # Sides must be positive\n \n # Sort the sides to easily identify the longest side\n sides = sorted([a, b, c])\n \n # Check the Pythagorean theorem: a^2 + b^2 = c^2\n return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n \"\"\"\n You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n \n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n \n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots that exist in stock\n \n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n \"\"\"\n \n # Calculate how many more carrots are needed\n additional_needed = need - number\n \n # If no additional carrots are needed, return the current state\n if additional_needed <= 0:\n return [number, remaining]\n \n # If there are enough remaining carrots to satisfy the need\n if remaining >= additional_needed:\n total_eaten = number + additional_needed\n carrots_left = remaining - additional_needed\n return [total_eaten, carrots_left]\n \n # If there are not enough remaining carrots\n total_eaten = number + remaining\n carrots_left = 0 # All remaining carrots are eaten\n return [total_eaten, carrots_left]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic algebra operations, and \n the second list is a list of integers. Use the two given lists to build the algebraic \n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + ) \n Subtraction ( - ) \n Multiplication ( * ) \n Floor division ( // ) \n Exponentiation ( ** ) \n\n Example:\n operator = ['+', '*', '-']\n operand = [2, 3, 4, 5]\n result = 2 + 3 * 4 - 5\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.\n \"\"\"\n \n # Start with the first operand\n result = operand[0]\n \n # Iterate through the operators and operands\n for i in range(len(operator)):\n op = operator[i]\n next_operand = operand[i + 1]\n \n if op == '+':\n result += next_operand\n elif op == '-':\n result -= next_operand\n elif op == '*':\n result *= next_operand\n elif op == '//':\n # Handle division by zero\n if next_operand == 0:\n raise ValueError(\"Division by zero is not allowed.\")\n result //= next_operand\n elif op == '**':\n result **= next_operand\n else:\n raise ValueError(f\"Invalid operator: {op}\")\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": []}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n \"\"\"You are given a string s.\n If s[i] is a letter, reverse its case from lower to upper or vice versa, \n otherwise keep it as it is.\n If the string contains no letters, reverse the string.\n The function should return the resulted string.\n \n Examples:\n solve(\"1234\") = \"4321\"\n solve(\"ab\") = \"AB\"\n solve(\"#a@C\") = \"#A@c\"\n \"\"\"\n # Check if there are any letters in the string\n has_letters = any(c.isalpha() for c in s)\n \n if has_letters:\n # If there are letters, reverse the case of each character\n result = ''.join(c.swapcase() for c in s)\n else:\n # If there are no letters, reverse the string\n result = s[::-1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string.\n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n >>> string_to_md5('') is None\n >>> string_to_md5('Python') == '5d41402abc4b2a76b9719d911017c592'\n >>> string_to_md5('123456') == 'e10adc3949ba59abbe56e057f20f883e'\n >>> string_to_md5('!@#$%^&*()') == 'c5e1c1c1c1c1c1c1c1c1c1c1c1c1c1c1'\n \"\"\"\n if text == \"\":\n return None\n # Create an MD5 hash object\n md5_hash = hashlib.md5()\n # Update the hash object with the bytes of the string\n md5_hash.update(text.encode('utf-8'))\n # Return the hexadecimal digest of the hash\n return md5_hash.hexdigest()", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascending order.\n\n For example:\n generate_integers(2, 8) => [2, 4, 6, 8]\n generate_integers(8, 2) => [2, 4, 6, 8]\n generate_integers(10, 14) => []\n \"\"\"\n # Ensure a and b are positive integers\n if a <= 0 or b <= 0:\n raise ValueError(\"Both a and b must be positive integers.\")\n\n # Determine the range of numbers to consider\n start = min(a, b)\n end = max(a, b)\n\n # Generate the list of even integers in the specified range\n even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n return even_integers", "base_status": "fail", "plus_status": null, "base_fail_tests": [[2, 10]], "plus_fail_tests": []}]}} \ No newline at end of file diff --git a/llm_based_130_eval_results.json b/llm_based_130_eval_results.json new file mode 100644 index 000000000..abacdaf20 --- /dev/null +++ b/llm_based_130_eval_results.json @@ -0,0 +1 @@ +{"date": "2024-07-26 23:17", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n >>> has_close_elements([], 0.5)\n False\n >>> has_close_elements([1.0], 0.5)\n False\n >>> has_close_elements([1.0, 1.4], 0.5)\n True\n >>> has_close_elements([1.0, 1.4, 1.8], 0.5)\n True\n >>> has_close_elements([1.0, 2.0, 2.4], 0.5)\n True\n >>> has_close_elements([1.0, 2.0, 2.5], 0.5)\n False\n \"\"\"\n if len(numbers) < 2:\n return False\n\n # Sort the numbers to make it easier to find close elements\n numbers.sort()\n\n # Check the differences between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" \n Input to this function is a string containing multiple groups of nested parentheses. \n The goal is to separate those groups into separate strings and return the list of those.\n Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n Ignore any spaces in the input string.\n \n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n # Remove spaces from the input string\n paren_string = paren_string.replace(\" \", \"\")\n \n result = []\n current_group = []\n balance = 0\n \n for char in paren_string:\n if char == '(':\n if balance == 0 and current_group:\n # If we are starting a new group, save the current one\n result.append(''.join(current_group))\n current_group = []\n current_group.append(char)\n balance += 1\n elif char == ')':\n current_group.append(char)\n balance -= 1\n \n # If balance is zero, we have a complete group\n if balance == 0 and current_group:\n result.append(''.join(current_group))\n current_group = []\n \n # In case there are any remaining characters in current_group\n if current_group:\n result.append(''.join(current_group))\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into\n an integer part (largest integer smaller than given number) and decimals\n (leftover part always smaller than 1).\n\n Return the decimal part of the number.\n \n >>> truncate_number(3.5)\n 0.5\n >>> truncate_number(5.0)\n 0.0\n >>> truncate_number(0.75)\n 0.75\n >>> truncate_number(10.99)\n 0.99\n >>> truncate_number(1.234567)\n 0.234567\n >>> truncate_number(0.1)\n 0.1\n >>> truncate_number(0.999)\n 0.999\n >>> truncate_number(100.001)\n 0.001\n >>> truncate_number(0)\n Traceback (most recent call last):\n ...\n ValueError: The number must be positive.\n \"\"\"\n if number < 0:\n raise ValueError(\"The number must be positive.\")\n \n integer_part = int(number) # Get the integer part\n decimal_part = number - integer_part # Calculate the decimal part\n return decimal_part", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" \n You're given a list of deposit and withdrawal operations on a bank account that starts with\n zero balance. Your task is to detect if at any point the balance of account falls below zero, and\n at that point function should return True. Otherwise it should return False.\n \n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n >>> below_zero([-1])\n True\n >>> below_zero([0, 0, 0])\n False\n >>> below_zero([-1, 1])\n False\n >>> below_zero([1, -1, -1])\n True\n >>> below_zero([5, -10, 5])\n True\n \"\"\"\n balance = 0\n for operation in operations:\n balance += operation\n if balance < 0:\n return True\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n >>> mean_absolute_deviation([1.0, 1.0, 1.0])\n 0.0\n >>> mean_absolute_deviation([])\n 0.0\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0, 5.0])\n 1.0\n >>> mean_absolute_deviation([-1.0, 0.0, 1.0])\n 0.6666666666666666\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list\n\n mean_value = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n \n return mad", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n \"\"\" Insert a number 'delimiter' between every two consecutive elements of input list `numbers'\n \n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n >>> intersperse([5], 0)\n [5]\n >>> intersperse([1, 2], 3)\n [1, 3, 2]\n >>> intersperse([1, 2, 3, 4], 9)\n [1, 9, 2, 9, 3, 9, 4]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n for i in range(len(numbers)):\n result.append(numbers[i])\n if i < len(numbers) - 1: # Avoid adding delimiter after the last element\n result.append(delimiter)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring.\n \n Args:\n strings (List[str]): A list of strings to filter.\n substring (str): The substring to search for within the strings.\n \n Returns:\n List[str]: A list of strings that contain the specified substring.\n \n Examples:\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n >>> filter_by_substring(['hello', 'world', 'test'], 'z')\n []\n >>> filter_by_substring(['case', 'sensitive', 'substring'], 'case')\n ['case']\n >>> filter_by_substring(['a', 'b', 'c'], 'a')\n ['a']\n >>> filter_by_substring(['', 'non-empty', ''], '')\n ['', 'non-empty', '']\n \"\"\"\n return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n def max_depth(group: str) -> int:\n current_depth = 0\n max_depth = 0\n \n for char in group:\n if char == '(':\n current_depth += 1\n max_depth = max(max_depth, current_depth)\n elif char == ')':\n current_depth -= 1\n if current_depth < 0: # More closing than opening\n return -1 # Invalid group\n return max_depth if current_depth == 0 else -1 # Valid if balanced\n\n groups = paren_string.split()\n depths = []\n \n for group in groups:\n depth = max_depth(group)\n if depth == -1:\n depths.append(0) # Treat invalid groups as depth 0\n else:\n depths.append(depth)\n \n return depths", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n \n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n >>> sum_product([-1, -2, -3])\n (-6, -6)\n >>> sum_product([0, 1, 2])\n (3, 0)\n >>> sum_product([5])\n (5, 5)\n >>> sum_product([1, 0, 2])\n (3, 0)\n \"\"\"\n if not numbers:\n return (0, 1)\n \n total_sum = sum(numbers)\n total_product = 1\n for number in numbers:\n total_product *= number\n \n return (total_sum, total_product)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \n >>> rolling_max([])\n []\n \n >>> rolling_max([-1, -2, -3, -4])\n [-1, -1, -1, -1]\n \n >>> rolling_max([5])\n [5]\n \n >>> rolling_max([1, 1, 1, 1])\n [1, 1, 1, 1]\n \n >>> rolling_max([3, 1, 4, 1, 5, 9, 2, 6, 5])\n [3, 3, 4, 4, 5, 9, 9, 9, 9]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for number in numbers[1:]:\n max_so_far = max(max_so_far, number)\n result.append(max_so_far)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n \n >>> make_palindrome('')\n ''\n >>> make_palindrome('cat')\n 'catac'\n >>> make_palindrome('cata')\n 'catac'\n >>> make_palindrome('race')\n 'racecar'\n >>> make_palindrome('a')\n 'a'\n >>> make_palindrome('ab')\n 'aba'\n >>> make_palindrome('abc')\n 'abcba'\n \"\"\"\n if not string:\n return string # Return empty string if input is empty\n\n # Find the longest palindromic suffix\n for i in range(len(string)):\n if is_palindrome(string[i:]):\n # If the suffix is a palindrome, take the prefix before it\n prefix = string[:i]\n # Append the reverse of the prefix to the original string\n return string + prefix[::-1]\n \n # If no palindromic suffix is found, the whole string is non-palindromic\n return string + string[:-1][::-1] # Append the reverse of the string minus the last character", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n \"\"\" \n Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n \n >>> string_xor('010', '110')\n '100'\n >>> string_xor('0', '0')\n '0'\n >>> string_xor('1', '1')\n '0'\n >>> string_xor('1', '0')\n '1'\n >>> string_xor('110', '1010')\n '1000'\n >>> string_xor('10101', '111')\n '10010'\n >>> string_xor('', '110')\n '110'\n >>> string_xor('110', '')\n '110'\n >>> string_xor('', '')\n ''\n \"\"\"\n \n # Pad the shorter string with leading zeros\n max_length = max(len(a), len(b))\n a = a.zfill(max_length)\n b = b.zfill(max_length)\n \n # Perform XOR operation\n result = []\n for bit_a, bit_b in zip(a, b):\n result.append('1' if bit_a != bit_b else '0')\n \n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n \n >>> longest([])\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n >>> longest(['abc', 'ab', 'a'])\n 'abc'\n >>> longest(['', 'a', 'ab'])\n 'ab'\n >>> longest(['longest', 'longer', 'long'])\n 'longest'\n >>> longest(['same', 'size', 'test'])\n 'same'\n \"\"\"\n if not strings:\n return None\n \n longest_string = strings[0]\n \n for string in strings[1:]:\n if len(string) > len(longest_string):\n longest_string = string\n \n return longest_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return the greatest common divisor of two integers a and b.\n \n The function uses the Euclidean algorithm to compute the GCD.\n \n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n >>> greatest_common_divisor(0, 5)\n 5\n >>> greatest_common_divisor(5, 0)\n 5\n >>> greatest_common_divisor(0, 0)\n 0\n >>> greatest_common_divisor(-25, 15)\n 5\n >>> greatest_common_divisor(25, -15)\n 5\n >>> greatest_common_divisor(-25, -15)\n 5\n \"\"\"\n if a == 0 and b == 0:\n return 0 # GCD is undefined for both numbers being zero\n if a < 0:\n a = -a # Make a positive\n if b < 0:\n b = -b # Make b positive\n\n while b != 0:\n a, b = b, a % b\n return a", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string.\n \n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n >>> all_prefixes('')\n []\n >>> all_prefixes('a')\n ['a']\n >>> all_prefixes('hello')\n ['h', 'he', 'hel', 'hell', 'hello']\n >>> all_prefixes('12345')\n ['1', '12', '123', '1234', '12345']\n \"\"\"\n return [string[:i] for i in range(1, len(string) + 1)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n >>> count_distinct_characters('')\n 0\n >>> count_distinct_characters('aA')\n 1\n >>> count_distinct_characters('123abcABC!@#')\n 9\n >>> count_distinct_characters(' ')\n 0\n >>> count_distinct_characters('!@#$%^&*()')\n 10\n \"\"\"\n # Convert the string to lowercase and use a set to find distinct characters\n return len(set(string.lower()))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n \n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n >>> string_sequence(-1)\n ''\n >>> string_sequence(1)\n '0 1'\n >>> string_sequence(10)\n '0 1 2 3 4 5 6 7 8 9 10'\n \"\"\"\n if n < 0:\n return ''\n return ' '.join(str(i) for i in range(n + 1))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string representing musical notes in a special ASCII format.\n Your task is to parse this string and return list of integers corresponding to how many beats does each\n note last.\n\n Here is a legend:\n 'o' - whole note, lasts four beats\n 'o|' - half note, lasts two beats\n '.|' - quarter note, lasts one beat\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n # Initialize an empty list to store the beats\n beats = []\n \n # Split the input string by spaces to get individual notes\n notes = music_string.split()\n \n # Define a mapping of note representations to their corresponding beats\n note_to_beats = {\n 'o': 4, # whole note\n 'o|': 2, # half note\n '.|': 1 # quarter note\n }\n \n # Iterate through each note and append the corresponding beats to the list\n for note in notes:\n if note in note_to_beats:\n beats.append(note_to_beats[note])\n else:\n # If an unknown note is encountered, we can choose to ignore it or raise an error\n # Here we will ignore it\n continue\n \n return beats", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n \n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n >>> how_many_times('abcabcabc', 'abc')\n 3\n >>> how_many_times('abababab', 'aba')\n 4\n >>> how_many_times('hello', 'lo')\n 1\n >>> how_many_times('hello', 'hello')\n 1\n >>> how_many_times('hello', 'world')\n 0\n >>> how_many_times('a', 'a')\n 1\n >>> how_many_times('a', 'b')\n 0\n >>> how_many_times('abc', '')\n 0\n >>> how_many_times('', '')\n 1\n \"\"\"\n if not substring:\n return 0\n count = 0\n start = 0\n \n while True:\n start = string.find(substring, start)\n if start == -1:\n break\n count += 1\n start += 1 # Move one character forward to allow overlapping matches\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n \"\"\" \n Input is a space-delimited string of numerals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest.\n \n >>> sort_numbers('three one five')\n 'one three five'\n >>> sort_numbers('nine eight seven')\n 'eight seven nine'\n >>> sort_numbers('zero one two three four five six seven eight nine')\n 'zero one two three four five six seven eight nine'\n >>> sort_numbers('five five five')\n 'five five five'\n >>> sort_numbers('')\n ''\n \"\"\"\n \n # Mapping of number words to their corresponding integer values\n number_map = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n \n # Split the input string into words\n number_words = numbers.split()\n \n # Convert words to their corresponding integer values\n number_values = [number_map[word] for word in number_words]\n \n # Sort the integer values\n number_values.sort()\n \n # Convert sorted integer values back to words\n sorted_number_words = [list(number_map.keys())[list(number_map.values()).index(value)] for value in number_values]\n \n # Join the sorted words into a single string\n return ' '.join(sorted_number_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n >>> find_closest_elements([1.0, 1.0, 1.0, 1.0])\n (1.0, 1.0)\n >>> find_closest_elements([-1.0, -2.0, -3.0, -1.5])\n (-1.5, -1.0)\n >>> find_closest_elements([0.0, 0.1, 0.2, 0.3])\n (0.0, 0.1)\n \"\"\"\n \n # Sort the numbers to find the closest pairs easily\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest elements\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1.\n \n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n \n >>> rescale_to_unit([10.0, 20.0, 30.0])\n [0.0, 0.5, 1.0]\n \n >>> rescale_to_unit([-5.0, 0.0, 5.0])\n [0.0, 0.5, 1.0]\n \n >>> rescale_to_unit([1.0, 1.0, 1.0])\n [0.0, 0.0, 0.0]\n \n >>> rescale_to_unit([1.0, 2.0])\n [0.0, 1.0]\n \n >>> rescale_to_unit([5.0, 5.0, 10.0, 10.0])\n [0.0, 0.0, 1.0, 1.0]\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The input list must contain at least two elements.\")\n \n min_val = min(numbers)\n max_val = max(numbers)\n \n if min_val == max_val:\n # All numbers are the same, return a list of zeros\n return [0.0] * len(numbers)\n \n # Rescale the numbers\n return [(num - min_val) / (max_val - min_val) for num in numbers]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers.\n \n Args:\n values (List[Any]): A list containing values of any type.\n \n Returns:\n List[int]: A list containing only the integers from the input list.\n \n Examples:\n >>> filter_integers(['a', 3.14, 5])\n [5]\n >>> filter_integers([1, 2, 3, 'abc', {}, []])\n [1, 2, 3]\n >>> filter_integers([]) # Edge case: empty list\n []\n >>> filter_integers([None, True, 0, -1, 2.5]) # Mixed types\n [0, -1]\n >>> filter_integers([1, 2, 3, 4, 5]) # All integers\n [1, 2, 3, 4, 5]\n >>> filter_integers(['1', '2', 3.0, 4]) # Strings and float\n [4]\n \"\"\"\n return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n \"\"\" Return length of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n >>> strlen('a')\n 1\n >>> strlen('Hello, World!')\n 13\n >>> strlen(' ') # String with spaces\n 3\n >>> strlen('\ud83d\ude0a') # String with a Unicode character\n 2\n >>> strlen('1234567890') # String of digits\n 10\n >>> strlen('') # Edge case: empty string\n 0\n \"\"\"\n return len(string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n \n >>> largest_divisor(15)\n 5\n >>> largest_divisor(10)\n 5\n >>> largest_divisor(1)\n 0\n >>> largest_divisor(2)\n 1\n >>> largest_divisor(100)\n 50\n >>> largest_divisor(37)\n 1\n \"\"\"\n if n <= 1:\n return 0 # No divisors less than 1\n \n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n Input number should be equal to the product of all factors.\n \n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n >>> factorize(1)\n []\n >>> factorize(0)\n Traceback (most recent call last):\n ...\n ValueError: Input must be a positive integer.\n >>> factorize(-10)\n Traceback (most recent call last):\n ...\n ValueError: Input must be a positive integer.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n factors = []\n # Check for number of 2s that divide n\n while n % 2 == 0:\n factors.append(2)\n n //= 2\n \n # n must be odd at this point, so we can skip even numbers\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n factors.append(i)\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n factors.append(n)\n \n return factors", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([1, 1, 1, 1])\n []\n >>> remove_duplicates([1, 2, 3])\n [1, 2, 3]\n >>> remove_duplicates([])\n []\n >>> remove_duplicates([1, 2, 3, 4, 5, 1, 2])\n [3, 4, 5]\n >>> remove_duplicates([5, 5, 5, 6, 7, 8, 6])\n [7, 8]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n \n # Create a new list with elements that occur only once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string.\n \n Args:\n strings (List[str]): A list of strings to concatenate.\n \n Returns:\n str: A single concatenated string.\n \n Examples:\n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n >>> concatenate(['Hello', ' ', 'World', '!'])\n 'Hello World!'\n >>> concatenate(['Python', '3.8', 'is', 'great'])\n 'Python3.8isgreat'\n >>> concatenate(['', 'empty', 'strings'])\n 'emptystrings'\n >>> concatenate(['a' * 1000] * 1000) # Large input\n 'a' * 1000000\n \"\"\"\n return ''.join(strings)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n \n >>> flip_case('Hello')\n 'hELLO'\n >>> flip_case('WORLD')\n 'world'\n >>> flip_case('Python3')\n 'pYTHON3'\n >>> flip_case('12345')\n '12345'\n >>> flip_case('')\n ''\n >>> flip_case('!@#$%^&*()')\n '!@#$%^&*()'\n \"\"\"\n return ''.join(char.swapcase() for char in string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n \n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n >>> get_positive([]) # Edge case: empty list\n []\n >>> get_positive([-1, -2, -3]) # Edge case: all negative numbers\n []\n >>> get_positive([0]) # Edge case: single zero\n []\n >>> get_positive([1, 2, 3]) # Edge case: all positive numbers\n [1, 2, 3]\n >>> get_positive([-1, 0, 1]) # Mixed case with zero\n [1]\n \"\"\"\n return [x for x in l if x > 0]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n \n Args:\n strings (List[str]): A list of strings to filter.\n prefix (str): The prefix to filter the strings by.\n \n Returns:\n List[str]: A list of strings that start with the given prefix.\n \n Examples:\n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n >>> filter_by_prefix(['apple', 'banana', 'apricot', 'grape'], 'ap')\n ['apple', 'apricot']\n >>> filter_by_prefix(['hello', 'world'], 'h')\n ['hello']\n >>> filter_by_prefix(['hello', 'world'], 'z')\n []\n >>> filter_by_prefix(['', 'test', ''], '')\n ['', 'test', '']\n >>> filter_by_prefix(['case', 'caseSensitive', 'caseInsensitive'], 'case')\n ['case', 'caseSensitive', 'caseInsensitive']\n \"\"\"\n return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n A prime number is a natural number greater than 1 that cannot be formed by multiplying two smaller natural numbers.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n >>> is_prime(0)\n False\n >>> is_prime(-5)\n False\n >>> is_prime(2)\n True\n >>> is_prime(3)\n True\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float) -> float:\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list) -> list:\n \"\"\"\n Computes the derivative of the polynomial with coefficients xs.\n The derivative is calculated as: \n d/dx (a0 + a1*x + a2*x^2 + ... + an*x^n) = a1 + 2*a2*x + ... + n*an*x^(n-1)\n \"\"\"\n return [i * coeff for i, coeff in enumerate(xs) if i > 0]\ndef find_zero(xs: list, initial_guess: float = 0.0, tolerance: float = 1e-7, max_iterations: int = 1000) -> float:\n \"\"\" \n xs are coefficients of a polynomial.\n find_zero finds x such that poly(x) = 0.\n find_zero returns only one zero point, even if there are many.\n Moreover, find_zero only takes list xs having an even number of coefficients\n and the largest non-zero coefficient as it guarantees a solution.\n \n >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n -0.5\n >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n 1.0\n \"\"\"\n if len(xs) % 2 != 0:\n raise ValueError(\"The number of coefficients must be even.\")\n \n x = initial_guess\n for _ in range(max_iterations):\n f_x = poly(xs, x)\n f_prime_x = poly(derivative(xs), x)\n \n if abs(f_prime_x) < tolerance: # Avoid division by zero\n raise ValueError(\"Derivative is too small; no solution found.\")\n \n x_new = x - f_x / f_prime_x\n \n if abs(x_new - x) < tolerance: # Convergence check\n return x_new\n \n x = x_new\n \n raise ValueError(\"Maximum iterations reached; no solution found.\")", "base_status": "fail", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \n >>> unique([]) # Edge case: empty list\n []\n \n >>> unique([1]) # Edge case: single element\n [1]\n \n >>> unique([1, 1, 1]) # Edge case: all elements the same\n [1]\n \n >>> unique([3, 2, 1]) # Edge case: already sorted in reverse\n [1, 2, 3]\n \n >>> unique([-1, 0, 1]) # Edge case: negative and positive numbers\n [-1, 0, 1]\n \n >>> unique([1.1, 2.2, 1.1, 3.3]) # Edge case: floats\n [1.1, 2.2, 3.3]\n \n >>> unique(['apple', 'banana', 'apple']) # Edge case: strings\n ['apple', 'banana']\n \"\"\"\n return sorted(set(l))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n >>> sort_third([])\n []\n >>> sort_third([10, 20, 30, 40, 50, 60])\n [30, 20, 10, 40, 50, 60]\n >>> sort_third([1, 2, 3, 4, 5, 6, 7, 8, 9])\n [3, 2, 1, 4, 5, 6, 9, 8, 7]\n \"\"\"\n # Extract values at indices divisible by 3\n values_to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n values_to_sort.sort()\n \n # Create a new list to hold the result\n result = l.copy()\n \n # Replace values at indices divisible by 3 with sorted values\n for idx, value in zip((i for i in range(len(l)) if i % 3 == 0), values_to_sort):\n result[idx] = value\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n \"\"\"Return maximum element in the list.\n \n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n >>> max_element([-1, -2, -3])\n -1\n >>> max_element([1])\n 1\n >>> max_element([])\n Traceback (most recent call last):\n ...\n ValueError: The list is empty.\n >>> max_element([1, 'a', 3])\n Traceback (most recent call last):\n ...\n TypeError: All elements in the list must be numeric.\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty.\")\n \n max_value = l[0]\n \n for item in l:\n if not isinstance(item, (int, float)):\n raise TypeError(\"All elements in the list must be numeric.\")\n if item > max_value:\n max_value = item\n \n return max_value", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n >>> sort_even([10, 20, 30, 40, 50])\n [10, 20, 30, 40, 50]\n >>> sort_even([1])\n [1]\n >>> sort_even([])\n []\n >>> sort_even([2, 1, 4, 3, 6, 5])\n [2, 1, 4, 3, 6, 5]\n >>> sort_even([8, 7, 6, 5, 4, 3, 2, 1])\n [2, 7, 4, 5, 6, 3, 8, 1]\n \"\"\"\n \n # Extract even indexed elements\n even_indices = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indexed elements\n even_indices.sort()\n \n # Create a new list to hold the result\n result = []\n \n # Fill the result list\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0: # Even index\n result.append(even_indices[even_index])\n even_index += 1\n else: # Odd index\n result.append(l[i])\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with encode_cyclic function. Returns decoded string.\n \"\"\"\n # Split string into groups of length 3\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # Reverse the cycling of elements in each group\n groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list) -> bool:\n \"\"\"\n triples_sum_to_zero takes a list of integers as an input.\n It returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n >>> triples_sum_to_zero([])\n False\n >>> triples_sum_to_zero([0, 0, 0])\n False\n >>> triples_sum_to_zero([-1, 0, 1])\n True\n \"\"\"\n n = len(l)\n if n < 3:\n return False\n\n # Sort the list to use the two-pointer technique\n l.sort()\n\n for i in range(n - 2):\n # Avoid duplicates for the first element\n if i > 0 and l[i] == l[i - 1]:\n continue\n \n left, right = i + 1, n - 1\n while left < right:\n current_sum = l[i] + l[left] + l[right]\n if current_sum == 0:\n return True\n elif current_sum < 0:\n left += 1\n else:\n right -= 1\n\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_fib(n: int) -> int:\n \"\"\"\n prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n \n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n if n < 1:\n raise ValueError(\"n must be a positive integer.\")\n \n count = 0\n for fib in fibonacci_generator():\n if is_prime(fib):\n count += 1\n if count == n:\n return fib", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1]], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n \"\"\"\n Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move at the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.\n\n Parameters:\n n (int): The number of cars in each direction.\n\n Returns:\n int: The number of collisions.\n \"\"\"\n # Each car moving left to right will collide with each car moving right to left.\n # Therefore, the total number of collisions is simply n * n.\n return n * n", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n \n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n >>> incr_list([]) # Edge case: empty list\n []\n >>> incr_list([-1, 0, 1]) # Edge case: negative and zero\n [0, 1, 2]\n >>> incr_list([1.5, 2.5]) # Edge case: floating point numbers\n [2.5, 3.5]\n >>> incr_list([None]) # Edge case: list with None\n Traceback (most recent call last):\n ...\n TypeError: unsupported operand type(s) for +: 'NoneType' and 'int'\n \"\"\"\n return [x + 1 for x in l]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n \n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n >>> pairs_sum_to_zero([])\n False\n >>> pairs_sum_to_zero([-1, 1])\n True\n >>> pairs_sum_to_zero([-1, 2, 1, -2])\n True\n \"\"\"\n seen = set()\n for number in l:\n if -number in seen:\n return True\n seen.add(number)\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion.\n base numbers are less than 10.\n \n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n >>> change_base(0, 2)\n '0'\n >>> change_base(0, 3)\n '0'\n >>> change_base(1, 2)\n '1'\n >>> change_base(1, 3)\n '1'\n >>> change_base(9, 2)\n '1001'\n >>> change_base(9, 3)\n '100'\n >>> change_base(9, 4)\n '21'\n >>> change_base(9, 5)\n '14'\n >>> change_base(9, 6)\n '13'\n >>> change_base(9, 7)\n '12'\n >>> change_base(9, 8)\n '11'\n >>> change_base(9, 9)\n '10'\n \"\"\"\n if base < 2 or base >= 10:\n raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n \n if x == 0:\n return '0'\n \n result = []\n negative = x < 0\n x = abs(x)\n \n while x > 0:\n result.append(str(x % base))\n x //= base\n \n if negative:\n result.append('-')\n \n return ''.join(reversed(result))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n \"\"\"Given length of a side and height, return the area for a triangle.\n \n The area of a triangle is calculated using the formula:\n Area = (base * height) / 2\n \n Parameters:\n a (float): The length of the base of the triangle.\n h (float): The height of the triangle.\n \n Returns:\n float: The area of the triangle.\n \n Raises:\n ValueError: If the base or height is not a positive number.\n \n >>> triangle_area(5, 3)\n 7.5\n >>> triangle_area(0, 3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(5, -3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(5, 0)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(1e6, 1e6)\n 5e11\n \"\"\"\n if a <= 0 or h <= 0:\n raise ValueError(\"Base and height must be positive numbers.\")\n \n return (a * h) / 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fib4(0) -> 0\n fib4(1) -> 0\n fib4(2) -> 2\n fib4(3) -> 0\n fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n \n This function computes the n-th element of the fib4 number sequence efficiently without using recursion.\n \n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n # Handle base cases\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 2\n elif n == 3:\n return 0\n \n # Initialize a list to store computed values\n fib_values = [0] * (n + 1)\n fib_values[0] = 0\n fib_values[1] = 0\n fib_values[2] = 2\n fib_values[3] = 0\n \n # Compute the fib4 values iteratively\n for i in range(4, n + 1):\n fib_values[i] = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n \n return fib_values[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n \"\"\"Return median of elements in the list l.\n \n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n >>> median([]) # Edge case: empty list\n Traceback (most recent call last):\n ...\n ValueError: Cannot compute median of an empty list.\n >>> median([1]) # Edge case: single element\n 1\n >>> median([1, 2]) # Edge case: two elements\n 1.5\n >>> median([1, 2, 3, 4]) # Even number of elements\n 2.5\n >>> median([5, 3, 1, 4, 2]) # Unsorted list\n 3\n \"\"\"\n if not l:\n raise ValueError(\"Cannot compute median of an empty list.\")\n \n sorted_list = sorted(l)\n n = len(sorted_list)\n mid = n // 2\n \n if n % 2 == 0: # Even number of elements\n return (sorted_list[mid - 1] + sorted_list[mid]) / 2\n else: # Odd number of elements\n return sorted_list[mid]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n \"\"\"\n Checks if given string is a palindrome.\n \n A palindrome is a string that reads the same forward and backward.\n \n Args:\n text (str): The string to check.\n \n Returns:\n bool: True if the string is a palindrome, False otherwise.\n \n Examples:\n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n >>> is_palindrome('A man a plan a canal Panama')\n True\n >>> is_palindrome('No lemon, no melon')\n True\n >>> is_palindrome('12321')\n True\n >>> is_palindrome('12345')\n False\n \"\"\"\n # Normalize the string: remove spaces, convert to lowercase, and filter out non-alphanumeric characters\n normalized_text = ''.join(char.lower() for char in text if char.isalnum())\n \n # Check if the normalized string is equal to its reverse\n return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n >>> modp(-1, 101)\n 0\n >>> modp(10, 1)\n 0\n >>> modp(1000, 2)\n 0\n >>> modp(1, 2)\n 0\n \"\"\"\n if p <= 1:\n return 0 # Any number mod 1 is 0, and mod with p <= 0 is not defined.\n \n # Using modular exponentiation to handle large n efficiently\n result = 1\n base = 2 % p\n \n while n > 0:\n if n % 2 == 1: # If n is odd\n result = (result * base) % p\n base = (base * base) % p # Square the base\n n //= 2 # Divide n by 2\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with encode_shift function.\n Returns the decoded string by shifting characters back by 5.\n Only lowercase alphabetic characters are shifted; others remain unchanged.\n \"\"\"\n decoded = []\n for ch in s:\n if 'a' <= ch <= 'z': # Check if the character is a lowercase letter\n decoded_char = chr(((ord(ch) - ord('a') - 5) % 26) + ord('a'))\n decoded.append(decoded_char)\n else:\n decoded.append(ch) # Non-alphabetic characters are unchanged\n return \"\".join(decoded)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n Vowels are defined as 'a', 'e', 'i', 'o', 'u' in both lowercase and uppercase.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n \"\"\"Return True if all numbers in the list l are below threshold t.\n \n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n >>> below_threshold([], 10)\n True\n >>> below_threshold([5], 5)\n False\n >>> below_threshold([-1, -2, -3], 0)\n True\n >>> below_threshold([0, 0, 0], 1)\n True\n >>> below_threshold([1, 2, 3], 3)\n False\n \"\"\"\n return all(x < t for x in l)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n \"\"\"Add two numbers x and y.\n\n This function takes two integers and returns their sum. It handles\n typical use cases as well as edge cases such as adding negative numbers\n and zero.\n\n Args:\n x (int): The first integer to add.\n y (int): The second integer to add.\n\n Returns:\n int: The sum of x and y.\n\n Examples:\n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n >>> add(-1, 1)\n 0\n >>> add(0, 0)\n 0\n >>> add(-5, -7)\n -12\n >>> add(2147483647, 1)\n 2147483648\n >>> add(-2147483648, -1)\n -2147483649\n \"\"\"\n return x + y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n This function checks if two strings contain the same unique characters,\n regardless of their frequency or order.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets to get unique characters\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Compare the two sets\n return set_s0 == set_s1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"<\" and \">\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"<\")\n False\n >>> correct_bracketing(\"<>\")\n True\n >>> correct_bracketing(\"<<><>>\")\n True\n >>> correct_bracketing(\"><<>\")\n False\n >>> correct_bracketing(\"<<>>\")\n True\n >>> correct_bracketing(\">>>\")\n False\n >>> correct_bracketing(\"<<<<<>>>>>>\")\n True\n >>> correct_bracketing(\"\")\n True\n >>> correct_bracketing(\"><\")\n False\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '<':\n balance += 1\n elif char == '>':\n balance -= 1\n \n # If balance goes negative, it means there's a closing bracket without a matching opening bracket\n if balance < 0:\n return False\n \n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n \"\"\"Return n-th Fibonacci number.\n \n The Fibonacci sequence is defined as follows:\n fib(0) = 0\n fib(1) = 1\n fib(n) = fib(n-1) + fib(n-2) for n > 1\n\n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n >>> fib(0)\n 0\n >>> fib(2)\n 1\n >>> fib(3)\n 2\n >>> fib(4)\n 3\n >>> fib(5)\n 5\n >>> fib(6)\n 8\n >>> fib(7)\n 13\n >>> fib(-1)\n Traceback (most recent call last):\n ...\n ValueError: Input must be a non-negative integer.\n \"\"\"\n if n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n elif n == 0:\n return 0\n elif n == 1:\n return 1\n \n a, b = 0, 1\n for _ in range(2, n + 1):\n a, b = b, a + b\n return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n \"\"\"Return True if list elements are monotonically increasing or decreasing.\n \n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n >>> monotonic([1, 1, 1])\n True\n >>> monotonic([])\n True\n >>> monotonic([5])\n True\n >>> monotonic([1, 2, 2, 3])\n True\n >>> monotonic([3, 2, 2, 1])\n True\n \"\"\"\n if len(l) <= 1:\n return True\n\n increasing = decreasing = True\n\n for i in range(1, len(l)):\n if l[i] > l[i - 1]:\n decreasing = False\n elif l[i] < l[i - 1]:\n increasing = False\n\n return increasing or decreasing", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n >>> common([], [1, 2, 3])\n []\n >>> common([1, 2, 3], [])\n []\n >>> common([], [])\n []\n >>> common([1, 1, 1], [1, 1, 1])\n [1]\n >>> common([1, 2, 3], [4, 5, 6])\n []\n >>> common([1, 2, 2, 3], [2, 2, 3, 3])\n [2, 3]\n >>> common([1, 2, 3], [3, 2, 1])\n [1, 2, 3]\n \"\"\"\n # Convert both lists to sets to get unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n >>> largest_prime_factor(600851475143)\n 6857\n >>> largest_prime_factor(49)\n 7\n >>> largest_prime_factor(15)\n 5\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n # Keep dividing n by factor until it is no longer divisible\n while n > 1:\n if n % factor == 0:\n n //= factor # Divide n by the factor\n else:\n factor += 1 # Move to the next potential factor\n return factor # The last factor is the largest prime factor", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n \n Args:\n n (int): The upper limit of the sum (inclusive).\n \n Returns:\n int: The sum of all integers from 1 to n.\n \n Examples:\n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n >>> sum_to_n(0)\n 0\n >>> sum_to_n(-5)\n 0\n \"\"\"\n if n < 1:\n return 0\n return n * (n + 1) // 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n \"\"\" \n Calculate the derivative of a polynomial represented by its coefficients.\n \n The polynomial is represented as:\n xs[0] + xs[1] * x + xs[2] * x^2 + ...\n \n The derivative is computed as:\n d/dx (a_n * x^n) = n * a_n * x^(n-1)\n \n Args:\n xs (list): Coefficients of the polynomial, where the index represents the power of x.\n \n Returns:\n list: Coefficients of the derivative polynomial.\n \n Examples:\n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n >>> derivative([5]) # Derivative of a constant\n []\n >>> derivative([]) # Derivative of an empty polynomial\n []\n >>> derivative([0]) # Derivative of zero polynomial\n []\n \"\"\"\n if not xs or len(xs) == 1:\n return [] # Derivative of a constant or empty polynomial is zero\n\n # Calculate the derivative coefficients\n return [i * coeff for i, coeff in enumerate(xs[1:], start=1)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"(\" and \")\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"(\")\n False\n >>> correct_bracketing(\"()\")\n True\n >>> correct_bracketing(\"(()())\")\n True\n >>> correct_bracketing(\")(()\")\n False\n >>> correct_bracketing(\")(\")\n False\n >>> correct_bracketing(\"\") # Edge case: empty string\n True\n >>> correct_bracketing(\"((((()))))\") # Edge case: nested brackets\n True\n >>> correct_bracketing(\"((())\") # Edge case: unbalanced opening\n False\n >>> correct_bracketing(\"(()))\") # Edge case: unbalanced closing\n False\n >>> correct_bracketing(\"()()()\") # Edge case: multiple pairs\n True\n >>> correct_bracketing(\"(()()())\") # Edge case: complex nested\n True\n \"\"\"\n balance = 0\n for char in brackets:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n # If balance goes negative, there are more closing brackets\n if balance < 0:\n return False\n # At the end, balance should be zero for correct bracketing\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n \n Args:\n n (int): The index of the FibFib number to compute.\n \n Returns:\n int: The n-th FibFib number.\n \n Examples:\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 1\n \n # Initialize the first three FibFib numbers\n fibfib_numbers = [0, 0, 1]\n \n # Compute FibFib numbers iteratively\n for i in range(3, n + 1):\n next_fibfib = fibfib_numbers[i - 1] + fibfib_numbers[i - 2] + fibfib_numbers[i - 3]\n fibfib_numbers.append(next_fibfib)\n \n return fibfib_numbers[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set('aeiouAEIOU')\n count = 0\n \n # Iterate through the string\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n # Check if 'y' is at the end of the string\n elif s[i].lower() == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n \"\"\"Task\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n \"\"\"\n # Initialize the sum of ASCII values\n total = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is uppercase\n if char.isupper():\n # Add the ASCII value of the uppercase character to the total\n total += ord(char)\n \n return total", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n \n >>> circular_shift(12, 1)\n '21'\n >>> circular_shift(12, 2)\n '12'\n >>> circular_shift(12345, 1)\n '51234'\n >>> circular_shift(12345, 5)\n '54321'\n >>> circular_shift(12345, 6)\n '54321'\n >>> circular_shift(0, 1)\n '0'\n >>> circular_shift(7, 0)\n '7'\n >>> circular_shift(7, 10)\n '7'\n >>> circular_shift(-123, 1)\n '-312'\n >>> circular_shift(-123, 3)\n '-321'\n \"\"\"\n # Convert the integer to a string and handle negative sign\n is_negative = x < 0\n str_x = str(abs(x))\n num_digits = len(str_x)\n\n # If shift is greater than the number of digits, reverse the digits\n if shift >= num_digits:\n return str_x[::-1] if not is_negative else '-' + str_x[::-1]\n\n # Perform the circular shift\n shift = shift % num_digits # Normalize shift\n shifted_str = str_x[-shift:] + str_x[:-shift]\n\n return shifted_str if not is_negative else '-' + shifted_str", "base_status": "fail", "plus_status": null, "base_fail_tests": [[12, 2]], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n \"\"\"\n Given an array representing a branch of a tree that has non-negative integer nodes,\n your task is to pluck one of the nodes and return it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n The plucked node should be returned in a list, [ smallest_value, its index ],\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index. \n\n Example 3:\n Input: []\n Output: []\n \n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n Explanation: 0 is the smallest value, but there are two zeros,\n so we will choose the first zero, which has the smallest index.\n\n Constraints:\n * 1 <= nodes.length <= 10000\n * 0 <= node.value\n \"\"\"\n smallest_even = float('inf')\n smallest_index = -1\n\n for index, value in enumerate(arr):\n if value % 2 == 0: # Check if the value is even\n if value < smallest_even: # Found a smaller even value\n smallest_even = value\n smallest_index = index\n\n if smallest_index == -1: # No even value found\n return []\n \n return [smallest_even, smallest_index]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n \"\"\"\n Calculate the number of mango fruits in a basket given the number of apples and oranges.\n\n Parameters:\n s (str): A string representing the number of apples and oranges in the format \"X apples and Y oranges\".\n n (int): The total number of fruits in the basket.\n\n Returns:\n int: The number of mango fruits in the basket.\n \"\"\"\n # Extract the number of apples and oranges from the string\n try:\n # Split the string to find the numbers\n parts = s.split()\n apples = int(parts[0]) # First part is the number of apples\n oranges = int(parts[2]) # Third part is the number of oranges\n except (IndexError, ValueError) as e:\n raise ValueError(\"Input string format is incorrect. Expected format: 'X apples and Y oranges'\") from e\n\n # Calculate the number of mangoes\n mangoes = n - apples - oranges\n\n # Ensure the result is non-negative\n if mangoes < 0:\n raise ValueError(\"The total number of fruits cannot be less than the sum of apples and oranges.\")\n\n return mangoes", "base_status": "fail", "plus_status": null, "base_fail_tests": [["5 apples and 6 oranges", 19]], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n '''\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequency greater than or equal to the value of the integer itself. \n The frequency of an integer is the number of times it appears in the list.\n If no such a value exists, return -1.\n \n Examples:\n search([4, 1, 2, 2, 3, 1]) == 2\n search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n search([5, 5, 4, 4, 4]) == -1\n '''\n from collections import Counter\n\n # Count the frequency of each integer in the list\n frequency = Counter(lst)\n\n # Initialize the result variable\n result = -1\n\n # Iterate through the frequency dictionary\n for num, freq in frequency.items():\n # Check if the frequency is greater than or equal to the number itself\n if freq >= num:\n # Update the result if this number is greater than the current result\n result = max(result, num)\n\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n '''\n Given list of integers, return list in strange order.\n Strange sorting, is when you start with the minimum value,\n then maximum of the remaining integers, then minimum and so on.\n\n Examples:\n strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n strange_sort_list([]) == []\n '''\n if not lst:\n return []\n\n # Sort the list to easily access min and max values\n sorted_lst = sorted(lst)\n result = []\n \n while sorted_lst:\n # Append the minimum value\n result.append(sorted_lst.pop(0)) # Remove and return the first element (minimum)\n if sorted_lst: # Check if there are still elements left\n result.append(sorted_lst.pop(-1)) # Remove and return the last element (maximum)\n\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return the area of\n the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n Otherwise return -1.\n \n Three sides make a valid triangle when the sum of any two sides is greater \n than the third side.\n \n Example:\n triangle_area(3, 4, 5) == 6.00\n triangle_area(1, 2, 10) == -1\n '''\n \n # Check for valid triangle using the triangle inequality theorem\n if a + b > c and a + c > b and b + c > a:\n # Calculate the semi-perimeter\n s = (a + b + c) / 2\n # Calculate the area using Heron's formula\n area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n return round(area, 2)\n else:\n return -1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n '''\n Write a function that returns True if the object q will fly, and False otherwise.\n The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n\n Example:\n will_it_fly([1, 2], 5) \u279e False \n # 1+2 is less than the maximum possible weight, but it's unbalanced.\n\n will_it_fly([3, 2, 3], 1) \u279e False\n # it's balanced, but 3+2+3 is more than the maximum possible weight.\n\n will_it_fly([3, 2, 3], 9) \u279e True\n # 3+2+3 is less than the maximum possible weight, and it's balanced.\n\n will_it_fly([3], 5) \u279e True\n # 3 is less than the maximum possible weight, and it's balanced.\n '''\n\n # Check if the list is a palindrome\n is_balanced = (q == q[::-1])\n \n # Calculate the sum of the elements in the list\n total_weight = sum(q)\n \n # Check if the total weight is less than or equal to the maximum weight\n is_within_weight_limit = (total_weight <= w)\n \n # The object will fly if it is balanced and within the weight limit\n return is_balanced and is_within_weight_limit", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n \n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total character counts and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n else:\n return lst2", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n \"\"\"\n Given an array arr of integers, find the minimum number of elements that\n need to be changed to make the array palindromic. A palindromic array is an array that\n is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n For example:\n smallest_change([1,2,3,5,4,7,9,6]) == 4\n smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n smallest_change([1, 2, 3, 2, 1]) == 0\n \"\"\"\n n = len(arr)\n changes = 0\n \n # Compare elements from the start and end towards the center\n for i in range(n // 2):\n if arr[i] != arr[n - 1 - i]:\n changes += 1\n \n return changes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n \"\"\"Returns True if x is a simple power of n, otherwise False.\n \n A number x is a simple power of n if there exists an integer k such that n**k = x.\n \n Args:\n x (int): The number to check.\n n (int): The base number.\n \n Returns:\n bool: True if x is a simple power of n, False otherwise.\n \"\"\"\n # Edge case: if n is 0 or 1\n if n == 0:\n return x == 0 # 0**0 is indeterminate, but we can consider it as True for this case\n if n == 1:\n return x == 1 # 1**k is always 1 for any k\n \n # Edge case: if x is less than 1\n if x < 1:\n return False # No positive power of n can yield a number less than 1\n \n # Check if x is a power of n\n power = 1\n while True:\n result = n ** power\n if result == x:\n return True\n elif result > x:\n return False\n power += 1", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1, 12]], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef generate_primes(limit):\n \"\"\"Generate a list of prime numbers less than the given limit.\"\"\"\n return [num for num in range(2, limit) if is_prime(num)]\ndef is_multiply_prime(a):\n \"\"\"Return True if the given number is the multiplication of 3 prime numbers, False otherwise.\"\"\"\n if a < 1 or a >= 100:\n return False\n \n primes = generate_primes(100)\n \n # Check all combinations of three primes\n for i in range(len(primes)):\n for j in range(i, len(primes)):\n for k in range(j, len(primes)):\n product = primes[i] * primes[j] * primes[k]\n if product == a:\n return True\n if product > a: # No need to check further if product exceeds 'a'\n break\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this integer is a cube of some integer number.\n Note: you may assume the input is always valid.\n \n Examples:\n iscube(1) ==> True\n iscube(2) ==> False\n iscube(-1) ==> True\n iscube(64) ==> True\n iscube(0) ==> True\n iscube(180) ==> False\n '''\n # Calculate the cube root of the absolute value of a\n cube_root = round(abs(a) ** (1/3))\n \n # Check if the cube of the rounded cube root equals the absolute value of a\n return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n \"\"\"Counts the number of prime hexadecimal digits in the given hexadecimal string.\"\"\"\n \n # Define the set of prime hexadecimal digits\n prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n \n # Initialize a counter for prime digits\n count = 0\n \n # Iterate through each character in the input string\n for char in num:\n # Check if the character is in the set of prime hexadecimal digits\n if char in prime_hex_digits:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n \"\"\"Check if the string is happy.\n \n A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n \n Args:\n s (str): The input string to check.\n \n Returns:\n bool: True if the string is happy, False otherwise.\n \"\"\"\n # Check if the length of the string is at least 3\n if len(s) < 3:\n return False\n \n # Iterate through the string and check every 3 consecutive characters\n for i in range(len(s) - 2):\n # Get the current substring of 3 characters\n substring = s[i:i+3]\n # Check if all characters in the substring are distinct\n if len(set(substring)) != 3:\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n \"\"\"Convert a decimal number to binary format with specific formatting.\n\n Args:\n decimal (int): A non-negative integer to convert to binary.\n\n Returns:\n str: A string representing the binary format of the decimal number,\n prefixed and suffixed with 'db'.\n \n Examples:\n decimal_to_binary(15) # returns \"db1111db\"\n decimal_to_binary(32) # returns \"db100000db\"\n \"\"\"\n if not isinstance(decimal, int) or decimal < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n\n # Convert decimal to binary and remove the '0b' prefix\n binary_representation = bin(decimal)[2:]\n\n # Format the output with 'db' prefix and suffix\n formatted_output = f\"db{binary_representation}db\"\n \n return formatted_output", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n letter_grades = []\n \n for gpa in grades:\n if gpa == 4.0:\n letter_grades.append('A+')\n elif gpa > 3.7:\n letter_grades.append('A')\n elif gpa > 3.3:\n letter_grades.append('A-')\n elif gpa > 3.0:\n letter_grades.append('B+')\n elif gpa > 2.7:\n letter_grades.append('B')\n elif gpa > 2.3:\n letter_grades.append('B-')\n elif gpa > 2.0:\n letter_grades.append('C+')\n elif gpa > 1.7:\n letter_grades.append('C')\n elif gpa > 1.3:\n letter_grades.append('C-')\n elif gpa > 1.0:\n letter_grades.append('D+')\n elif gpa > 0.7:\n letter_grades.append('D')\n elif gpa > 0.0:\n letter_grades.append('D-')\n else:\n letter_grades.append('E')\n \n return letter_grades", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_length(string):\n \"\"\"Check if the length of the string is a prime number.\"\"\"\n length = len(string)\n return is_prime(length)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n \"\"\"\n Given a positive integer n, return the count of the numbers of n-digit\n positive integers that start or end with 1.\n \n Parameters:\n n (int): The number of digits in the positive integers to consider.\n \n Returns:\n int: The count of n-digit positive integers that start or end with 1.\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer.\")\n \n if n == 1:\n # For 1-digit numbers, only the number 1 itself qualifies\n return 1\n \n # Total n-digit numbers\n total_n_digit_numbers = 9 * (10 ** (n - 1))\n \n # Count of n-digit numbers that start with 1\n start_with_1 = 10 ** (n - 1) # 1 followed by (n-1) digits (0-9)\n \n # Count of n-digit numbers that end with 1\n end_with_1 = 9 * (10 ** (n - 2)) if n > 1 else 0 # (n-1) digits (0-9) before 1\n \n # Count of n-digit numbers that both start and end with 1\n start_and_end_with_1 = 10 ** (n - 2) if n > 1 else 0 # 1 followed by (n-2) digits (0-9) and ending with 1\n \n # Using the principle of inclusion-exclusion\n count = start_with_1 + end_with_1 - start_and_end_with_1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits will be 1 the output should be \"1\".\n For N = 150, the sum of digits will be 6 the output should be \"110\".\n For N = 147, the sum of digits will be 12 the output should be \"1100\".\n \n Variables:\n @N integer\n Constraints: 0 \u2264 N \u2264 10000.\n Output:\n a string of binary number\n \"\"\"\n if N < 0 or N > 10000:\n raise ValueError(\"N must be between 0 and 10000 inclusive.\")\n \n # Calculate the sum of the digits of N\n digit_sum = sum(int(digit) for digit in str(N))\n \n # Convert the sum to binary and return it as a string\n return bin(digit_sum)[2:]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n add([1, 2, 3, 4, 5]) ==> 0\n add([0, 2, 4, 6, 8]) ==> 2 + 6 = 8\n add([1, 3, 5]) ==> 0\n add([2]) ==> 0\n \"\"\"\n # Initialize the sum\n total = 0\n \n # Iterate over the list using index\n for index in range(1, len(lst), 2): # Start from index 1 and step by 2\n if lst[index] % 2 == 0: # Check if the element is even\n total += lst[index] # Add to total if it's even\n\n return total", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words while preserving spaces\n words = s.split(' ')\n \n # Sort characters in each word and keep the spaces intact\n sorted_words = []\n for word in words:\n # Sort the characters of the word and join them back\n sorted_word = ''.join(sorted(word))\n sorted_words.append(sorted_word)\n \n # Join the sorted words back with spaces\n result = ' '.join(sorted_words)\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort by row index (ascending) and then by column index (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n or sort it in descending order if the sum( first index value, last index value) is even.\n\n Note:\n * don't change the given array.\n\n Examples:\n * sort_array([]) => []\n * sort_array([5]) => [5]\n * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n \"\"\"\n # Create a copy of the array to avoid modifying the original\n sorted_array = array.copy()\n \n # Check if the array is empty\n if not sorted_array:\n return sorted_array\n \n # Calculate the sum of the first and last elements\n first_element = sorted_array[0]\n last_element = sorted_array[-1]\n total_sum = first_element + last_element\n \n # Sort the array based on the sum being odd or even\n if total_sum % 2 == 0:\n # Even sum: sort in descending order\n sorted_array.sort(reverse=True)\n else:\n # Odd sum: sort in ascending order\n sorted_array.sort()\n \n return sorted_array", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Sort the unique elements\n sorted_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_elements[1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating each letter down the alphabet by 4 places.\"\"\"\n encrypted = []\n \n for char in s:\n if char.isalpha(): # Check if the character is an alphabet\n # Calculate the new position with rotation\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a')) if char.islower() else \\\n chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n encrypted.append(new_char)\n \n return ''.join(encrypted)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n \n For example:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n >>> is_bored(\"I am bored! Are you? I want to go home.\")\n 2\n >>> is_bored(\"What a beautiful day. I hope it lasts.\")\n 1\n >>> is_bored(\"I. I. I.\")\n 3\n >>> is_bored(\"\")\n 0\n >>> is_bored(\"!?.\")\n 0\n \"\"\"\n # Split the string into sentences based on the delimiters\n import re\n sentences = re.split(r'[.!?]', S)\n \n # Count sentences that start with \"I\" (case insensitive)\n boredom_count = sum(1 for sentence in sentences if sentence.strip().lower().startswith('i'))\n \n return boredom_count", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n '''\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n \n Examples\n any_int(5, 2, 7) \u279e True\n any_int(3, 2, 2) \u279e False\n any_int(3, -2, 1) \u279e True\n any_int(3.6, -2.2, 2) \u279e False\n '''\n \n # Check if all inputs are integers\n if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n # Check if any number is equal to the sum of the other two\n return x == y + z or y == x + z or z == x + y\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n \"\"\"\n Write a function that takes a message, and encodes in such a \n way that it swaps case of all letters, replaces all vowels in \n the message with the letter that appears 2 places ahead of that \n vowel in the English alphabet. \n Assume only letters. \n \n Examples:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n vowels = 'aeiouAEIOU'\n encoded_message = []\n\n for char in message:\n if char.isalpha(): # Check if the character is a letter\n # Swap case\n if char in vowels:\n # Replace vowel with the letter 2 places ahead\n if char.islower():\n new_char = chr(((ord(char) - ord('a') + 2) % 26) + ord('a'))\n else:\n new_char = chr(((ord(char) - ord('A') + 2) % 26) + ord('A'))\n encoded_message.append(new_char)\n else:\n # Just swap case for consonants\n encoded_message.append(char.swapcase())\n else:\n # If it's not a letter, we can choose to keep it as is\n encoded_message.append(char)\n\n return ''.join(encoded_message)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["TEST"]], "plus_fail_tests": []}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef sum_of_digits(n):\n \"\"\"Return the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n largest_prime = None\n \n for number in lst:\n if is_prime(number):\n if largest_prime is None or number > largest_prime:\n largest_prime = number\n \n if largest_prime is not None:\n return sum_of_digits(largest_prime)\n else:\n return 0 # Return 0 if no prime number is found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in lower \n case or all keys are strings in upper case, else return False.\n The function should return False if the given dictionary is empty.\n \n Examples:\n check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n \"\"\"\n \n # Check if the dictionary is empty\n if not input_dict:\n return False\n \n # Initialize flags for lower and upper case\n all_lower = True\n all_upper = True\n \n for key in input_dict.keys():\n # Check if the key is a string\n if not isinstance(key, str):\n return False\n \n # Check if the key is lower case\n if key.islower():\n all_upper = False\n # Check if the key is upper case\n elif key.isupper():\n all_lower = False\n else:\n # If the key is neither lower nor upper case\n return False\n \n # Return True if all keys are either lower case or upper case\n return all_lower or all_upper", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_up_to(n):\n \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n primes = []\n for i in range(2, n):\n if is_prime(i):\n primes.append(i)\n return primes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.\n \"\"\"\n # Get the unit digit of the first number\n unit_digit_a = abs(a) % 10\n # Get the unit digit of the second number\n unit_digit_b = abs(b) % 10\n # Return the product of the unit digits\n return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n count_upper('aBCdEf') returns 1\n count_upper('abcdefg') returns 0\n count_upper('dBBE') returns 0\n \"\"\"\n # Define the set of uppercase vowels\n uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n \n # Initialize the count of uppercase vowels at even indices\n count = 0\n \n # Iterate over the string, checking only even indices\n for i in range(0, len(s), 2): # Step by 2 to get even indices\n if s[i] in uppercase_vowels:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n \"\"\"\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n >>> make_a_pile(4)\n [4, 6, 8, 10]\n >>> make_a_pile(1)\n [1]\n >>> make_a_pile(0)\n []\n \"\"\"\n if n <= 0:\n return []\n\n stones = []\n current_stones = n\n\n for i in range(n):\n stones.append(current_stones)\n if current_stones % 2 == 0: # current_stones is even\n current_stones += 2 # next even number\n else: # current_stones is odd\n current_stones += 2 # next odd number\n\n return stones", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n >>> closest_integer(\"14.5\")\n 15\n >>> closest_integer(\"-14.5\")\n -15\n >>> closest_integer(\"0.5\")\n 1\n >>> closest_integer(\"-0.5\")\n -1\n >>> closest_integer(\"3.0\")\n 3\n >>> closest_integer(\"-3.0\")\n -3\n >>> closest_integer(\"2.499999\")\n 2\n >>> closest_integer(\"-2.499999\")\n -2\n '''\n\n # Convert the string input to a float\n num = float(value)\n\n # Use the built-in round function to round the number\n rounded = round(num)\n\n # Check if the number is equidistant from two integers\n if abs(num - rounded) == 0.5:\n # If equidistant, round away from zero\n if num > 0:\n return rounded + 1\n else:\n return rounded - 1\n else:\n return rounded", "base_status": "fail", "plus_status": null, "base_fail_tests": [["-15.5"]], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n \"\"\"This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If \n there's no such number, then the function should return -1.\n\n For example:\n choose_num(12, 15) = 14\n choose_num(13, 12) = -1\n \"\"\"\n # Ensure x is less than or equal to y\n if x > y:\n return -1\n\n # Start from the largest number in the range and work downwards\n for num in range(y, x - 1, -1):\n if num % 2 == 0: # Check if the number is even\n return num\n\n return -1 # No even number found in the range", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n \"\"\"\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n \"\"\"\n # Split the string by commas and spaces, then filter out any empty strings\n words = [word.strip() for word in s.replace(',', ' ').split() if word.strip()]\n return words", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n \"\"\"Compute the average of integers from n to m, round it, and convert to binary.\n \n Args:\n n (int): The starting integer (inclusive).\n m (int): The ending integer (inclusive).\n \n Returns:\n str or int: The binary representation of the rounded average if n <= m, \n otherwise -1.\n \"\"\"\n if n > m:\n return -1\n \n # Calculate the sum of integers from n to m\n total_sum = sum(range(n, m + 1))\n count = m - n + 1 # Total numbers from n to m\n \n # Calculate the average and round it\n average = total_sum / count\n rounded_average = round(average)\n \n # Convert the rounded average to binary\n return bin(rounded_average)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n \"\"\"Given a list of positive integers x, return a sorted list of all \n elements that haven't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n def has_even_digit(n):\n \"\"\"Check if the number has any even digit.\"\"\"\n for digit in str(n):\n if int(digit) % 2 == 0:\n return True\n return False\n\n # Filter the list to include only numbers without even digits\n result = [num for num in x if not has_even_digit(num)]\n \n # Sort the result in increasing order\n return sorted(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n reverse the resulting array, and then replace each digit by its corresponding name from\n \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n For example:\n arr = [2, 1, 1, 4, 5, 8, 2, 3] \n -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n \n If the array is empty, return an empty array:\n arr = []\n return []\n \n If the array has any strange number ignore it:\n arr = [1, -1 , 55] \n -> sort arr -> [-1, 1, 55]\n -> reverse arr -> [55, 1, -1]\n return = ['One']\n \"\"\"\n \n # Mapping of digits to their corresponding names\n digit_to_name = {\n 1: \"One\",\n 2: \"Two\",\n 3: \"Three\",\n 4: \"Four\",\n 5: \"Five\",\n 6: \"Six\",\n 7: \"Seven\",\n 8: \"Eight\",\n 9: \"Nine\"\n }\n \n # Filter the array to include only integers between 1 and 9\n filtered_arr = [num for num in arr if 1 <= num <= 9]\n \n # Sort the filtered array\n sorted_arr = sorted(filtered_arr)\n \n # Reverse the sorted array\n reversed_arr = sorted_arr[::-1]\n \n # Convert the digits to their corresponding names\n result = [digit_to_name[num] for num in reversed_arr]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def factorial(num):\n \"\"\"Helper function to calculate the factorial of a number.\"\"\"\n if num == 0 or num == 1:\n return 1\n result = 1\n for i in range(2, num + 1):\n result *= i\n return result\ndef sum_of_numbers(num):\n \"\"\"Helper function to calculate the sum of numbers from 1 to num.\"\"\"\n return num * (num + 1) // 2\ndef f(n):\n \"\"\"Implement the function f that takes n as a parameter,\n and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even\n or the sum of numbers from 1 to i otherwise.\n i starts from 1.\n \"\"\"\n if n < 1:\n return [] # Return an empty list for non-positive n\n\n result = []\n for i in range(1, n + 1):\n if i % 2 == 0: # i is even\n result.append(factorial(i))\n else: # i is odd\n result.append(sum_of_numbers(i))\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n \"\"\"\n Given a positive integer n, return a tuple that has the number of even and odd\n integer palindromes that fall within the range(1, n), inclusive.\n\n Example 1:\n Input: 3\n Output: (1, 2)\n Explanation:\n Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n Example 2:\n Input: 12\n Output: (4, 6)\n Explanation:\n Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n Note:\n 1. 1 <= n <= 10^3\n 2. returned tuple has the number of even and odd integer palindromes respectively.\n \"\"\"\n \n def is_palindrome(num):\n return str(num) == str(num)[::-1]\n\n even_count = 0\n odd_count = 0\n\n for i in range(1, n + 1):\n if is_palindrome(i):\n if i % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return True else return False.\n If the given array is empty then return True.\n\n Note: The given list is guaranteed to have unique elements.\n\n For Example:\n \n move_one_ball([3, 4, 5, 1, 2])==>True\n Explanation: By performing 2 right shift operations, non-decreasing order can\n be achieved for the given array.\n move_one_ball([3, 5, 4, 1, 2])==>False\n Explanation: It is not possible to get non-decreasing order for the given\n array by performing any number of right shift operations.\n \"\"\"\n \n if not arr: # Check for empty array\n return True\n \n n = len(arr)\n count = 0 # Count the number of times the order is broken\n\n for i in range(n):\n if arr[i] > arr[(i + 1) % n]: # Check if the current element is greater than the next\n count += 1\n\n # If there are more than one breaks in the order, it's not possible to sort by shifting\n return count <= 1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n \"\"\"\n Write a function count_nums which takes an array of integers and returns\n the number of elements which has a sum of digits > 0.\n If a number is negative, then its first signed digit will be negative:\n e.g. -123 has signed digits -1, 2, and 3.\n \n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n def sum_of_digits(n):\n \"\"\"Helper function to calculate the sum of digits of an integer.\"\"\"\n # Convert the number to string and iterate over each character\n # Convert back to int and sum them up\n return sum(int(digit) if digit != '-' else -int(digit) for digit in str(n))\n\n count = 0\n for number in arr:\n if sum_of_digits(number) > 0:\n count += 1\n \n return count", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[-1, -2, 0]]], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n \"\"\"Determines if it's possible to exchange elements between two lists\n to make all elements of lst1 even.\n \n Args:\n lst1 (list): The first list of numbers.\n lst2 (list): The second list of numbers.\n \n Returns:\n str: \"YES\" if lst1 can be made all even, \"NO\" otherwise.\n \"\"\"\n # Check if all elements in lst1 are already even\n if all(x % 2 == 0 for x in lst1):\n return \"YES\"\n \n # Count the number of odd elements in lst1\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n \n # Check if lst2 has at least one even number to exchange\n has_even_in_lst2 = any(x % 2 == 0 for x in lst2)\n \n # If lst1 has odd numbers and lst2 has at least one even number,\n # we can perform exchanges to make lst1 all even\n if odd_count_lst1 > 0 and has_even_in_lst2:\n return \"YES\"\n \n # If lst1 has odd numbers and lst2 has no even numbers, return \"NO\"\n return \"NO\"", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 3, 4], [1, 5, 3, 4]]], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n \"\"\"\n if not test:\n return {}\n\n # Split the input string into a list of letters\n letters = test.split()\n \n # Create a dictionary to count occurrences of each letter\n count_dict = {}\n for letter in letters:\n if letter in count_dict:\n count_dict[letter] += 1\n else:\n count_dict[letter] = 1\n\n # Find the maximum occurrence count\n max_count = max(count_dict.values())\n \n # Create a result dictionary for letters with the maximum count\n result = {letter: count for letter, count in count_dict.items() if count == max_count}\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n \"\"\"Task\n We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and True/False for the check.\n Example\n For s = \"abcde\", c = \"ae\", the result should be ('bcd',False)\n For s = \"abcdef\", c = \"b\" the result should be ('acdef',False)\n For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc',True)\n \"\"\"\n \n # Create a set of characters to delete for faster lookup\n delete_set = set(c)\n \n # Build the result string by filtering out characters in delete_set\n result = ''.join(char for char in s if char not in delete_set)\n \n # Check if the result string is a palindrome\n is_palindrome = result == result[::-1]\n \n return (result, is_palindrome)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3', \"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in s if char in '13579')\n # Create the output string with the count\n output_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output_string)\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n :param nums: List[int] - List of integers\n :return: int - Minimum sum of any non-empty sub-array\n \n Example:\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n \"\"\"\n if not nums:\n raise ValueError(\"Input array must not be empty.\")\n \n # Initialize variables\n min_sum = float('inf') # Start with a very large number\n current_sum = 0\n \n for num in nums:\n current_sum += num\n min_sum = min(min_sum, current_sum)\n \n # If current_sum is greater than 0, reset it to 0\n if current_sum > 0:\n current_sum = 0\n \n return min_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n \"\"\"\n Calculate the number of times buckets need to be lowered to empty the wells.\n\n Parameters:\n grid (list of list of int): A rectangular grid representing wells.\n capacity (int): The capacity of each bucket.\n\n Returns:\n int: The total number of times buckets need to be lowered.\n \"\"\"\n total_water = 0\n \n # Count the total amount of water in the grid\n for row in grid:\n total_water += sum(row)\n \n # Calculate the number of times buckets need to be lowered\n if total_water == 0:\n return 0 # No water to extract\n \n # Each bucket can carry 'capacity' units of water\n # We need to lower the buckets enough times to extract all the water\n return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n \"\"\"Given a string s and a natural number n, returns a list of all words from string s \n that contain exactly n consonants, in the order they appear in the string s.\n \n Args:\n s (str): The input string containing words.\n n (int): The number of consonants to filter words by.\n \n Returns:\n list: A list of words containing exactly n consonants.\n \"\"\"\n \n if not s: # Check if the string is empty\n return []\n \n # Define a set of vowels for easy checking\n vowels = set(\"aeiouAEIOU\")\n \n def count_consonants(word):\n \"\"\"Helper function to count consonants in a word.\"\"\"\n return sum(1 for char in word if char.isalpha() and char not in vowels)\n \n # Split the string into words\n words = s.split()\n \n # Filter words based on the number of consonants\n result = [word for word in words if count_consonants(word) == n]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n \"\"\"\n In this Kata, you have to sort an array of non-negative integers according to\n number of ones in their binary representation in ascending order.\n For similar number of ones, sort based on decimal value.\n\n It must be implemented like this:\n >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n >>> sort_array([1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]\n \"\"\"\n # Filter out negative numbers, as the problem states non-negative integers\n non_negative_arr = [x for x in arr if x >= 0]\n \n # Sort the array first by the number of 1s in binary representation, then by the value itself\n sorted_arr = sorted(non_negative_arr, key=lambda x: (bin(x).count('1'), x))\n \n return sorted_arr", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[-2, -3, -4, -5, -6]]], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n two consonants from the right side of the word (case sensitive).\n \n Vowels in the beginning and ending don't count. Return empty string if you didn't\n find any vowel that meets the above condition. \n\n You may assume that the given string contains English letters only.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n n = len(word)\n\n # Edge case: if the word is too short to have consonants\n if n < 3:\n return \"\"\n\n # Start from the end of the word\n for i in range(n - 2, 0, -1):\n if word[i] in vowels:\n # Check if there are consonants on both sides\n if word[i - 1].isalpha() and word[i + 1].isalpha():\n if word[i - 1] not in vowels and word[i + 1] not in vowels:\n return word[i]\n \n return \"\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0: # More closing than opening\n return False\n return balance == 0 # Must be balanced at the end\n\n a, b = lst[0], lst[1]\n\n # Check both concatenation orders\n if is_good(a + b) or is_good(b + a):\n return 'Yes'\n else:\n return 'No'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n \n # Sort the array in descending order and take the first k elements\n max_elements = sorted(arr, reverse=True)[:k]\n \n # Return the sorted list of the maximum k elements in ascending order\n return sorted(max_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n An even position is defined as an index that is even (0, 2, 4, ...).\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate over the list with index\n for index in range(len(lst)):\n # Check if the index is even\n if index % 2 == 0:\n # Check if the element is odd\n if lst[index] % 2 != 0:\n total_sum += lst[index]\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n as follows: start with any positive integer n. Then each term is obtained from the \n previous term as follows: if the previous term is even, the next term is one half of \n the previous term. If the previous term is odd, the next term is 3 times the previous\n term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n Note: \n 1. Collatz(1) is [1].\n 2. returned list sorted in increasing order.\n\n For example:\n get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n collatz_sequence = []\n \n while n != 1:\n collatz_sequence.append(n)\n if n % 2 == 0:\n n //= 2\n else:\n n = 3 * n + 1\n \n collatz_sequence.append(1) # Append the last term which is 1\n \n # Filter odd numbers and sort them\n odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n \n return odd_numbers", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n \"\"\"\n Given a non-empty array of integers arr and an integer k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example:\n\n Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n Output: 24 # sum of 21 + 3\n\n Constraints:\n 1. 1 <= len(arr) <= 100\n 2. 1 <= k <= len(arr)\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate through the first k elements of the array\n for i in range(k):\n # Check if the current element has at most two digits\n if -100 < arr[i] < 100:\n total_sum += arr[i]\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n \n The date is valid if all of the following rules are satisfied:\n 1. The date string is not empty.\n 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n The number of days is not less than 1 or higher than 29 for the month 2.\n 3. The months should not be less than 1 or higher than 12.\n 4. The date should be in the format: mm-dd-yyyy\n \"\"\"\n \n # Check if the date string is empty\n if not date:\n return False\n \n # Check if the date format is correct\n if len(date) != 10 or date[2] != '-' or date[5] != '-':\n return False\n \n # Split the date into components\n try:\n month, day, year = map(int, date.split('-'))\n except ValueError:\n return False\n \n # Validate month\n if month < 1 or month > 12:\n return False\n \n # Validate day based on month\n if month in {1, 3, 5, 7, 8, 10, 12}:\n if day < 1 or day > 31:\n return False\n elif month in {4, 6, 9, 11}:\n if day < 1 or day > 30:\n return False\n elif month == 2:\n if day < 1 or day > 29:\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n '''\n Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n \n Examples:\n split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"abcdef\") \u279e 3 \n '''\n \n # Check for whitespace in the text\n if ' ' in txt:\n return txt.split()\n \n # Check for commas in the text\n elif ',' in txt:\n return txt.split(',')\n \n # If no whitespace or commas, count lowercase letters with odd order\n else:\n odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n return odd_count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n '''\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return False. Assume no negative numbers and only integers.\n\n Examples\n is_sorted([5]) \u279e True\n is_sorted([1, 2, 3, 4, 5]) \u279e True\n is_sorted([1, 3, 2, 4, 5]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n '''\n \n if not lst: # Handle empty list case\n return True\n \n seen = set()\n previous = None\n \n for num in lst:\n if num in seen: # Check for duplicates\n return False\n seen.add(num)\n \n if previous is not None and num < previous: # Check for sorting\n return False\n \n previous = num\n \n return True", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef intersection(interval1, interval2):\n \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n start1, end1 = interval1\n start2, end2 = interval2\n \n # Find the intersection\n start_intersection = max(start1, start2)\n end_intersection = min(end1, end2)\n \n # Check if there is an intersection\n if start_intersection > end_intersection:\n return \"NO\"\n \n # Calculate the length of the intersection\n length_of_intersection = end_intersection - start_intersection\n \n # Check if the length is a prime number\n if is_prime(length_of_intersection):\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n if not arr: # Check for empty array\n return None\n\n product_of_signs = 1\n sum_of_magnitudes = 0\n\n for num in arr:\n if num > 0:\n sum_of_magnitudes += num\n elif num < 0:\n sum_of_magnitudes += -num\n product_of_signs *= -1 # Flip the sign for negative numbers\n else: # num == 0\n return 0 # If there's a zero, the product of signs is zero\n\n return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n \"\"\"Calculate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n if n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n # Initialize the list to store the Tribonacci numbers\n tribonacci_sequence = []\n \n # Calculate each Tribonacci number based on the rules provided\n for i in range(n + 1):\n if i == 1:\n tribonacci_sequence.append(3) # tri(1) = 3\n elif i == 0:\n tribonacci_sequence.append(1) # tri(0) = 1\n elif i % 2 == 0: # Even case\n tribonacci_sequence.append(1 + i / 2)\n else: # Odd case\n # tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1)\n tri_n_minus_1 = tribonacci_sequence[i - 1] if i - 1 >= 0 else 0\n tri_n_minus_2 = tribonacci_sequence[i - 2] if i - 2 >= 0 else 0\n tri_n_plus_1 = tribonacci_sequence[i + 1] if i + 1 <= n else 0\n \n # Calculate tri(n) for odd n\n tribonacci_sequence.append(tri_n_minus_1 + tri_n_minus_2 + tri_n_plus_1)\n \n return tribonacci_sequence", "base_status": "fail", "plus_status": null, "base_fail_tests": [[3]], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n \"\"\"Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n \n Args:\n n (int): A positive integer.\n \n Returns:\n int: The product of the odd digits or 0 if all are even.\n \n Examples:\n >>> digits(1)\n 1\n >>> digits(4)\n 0\n >>> digits(235)\n 15\n >>> digits(2468)\n 0\n >>> digits(13579)\n 945\n >>> digits(0) # Edge case: not a positive integer\n Traceback (most recent call last):\n ...\n ValueError: Input must be a positive integer.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n product = 1\n has_odd = False\n \n while n > 0:\n digit = n % 10\n if digit % 2 != 0: # Check if the digit is odd\n product *= digit\n has_odd = True\n n //= 10 # Remove the last digit\n \n return product if has_odd else 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n '''\n Create a function that takes a string as input which contains only square brackets.\n The function should return True if and only if there is a valid subsequence of brackets \n where at least one bracket in the subsequence is nested.\n\n is_nested('[[]]') \u279e True\n is_nested('[]]]]]]][[[[[]') \u279e False\n is_nested('[][]') \u279e False\n is_nested('[]') \u279e False\n is_nested('[[][]]') \u279e True\n is_nested('[[]][[') \u279e True\n '''\n \n # Initialize a counter for open brackets\n open_count = 0\n # Initialize a flag to check for nesting\n nested = False\n \n for char in string:\n if char == '[':\n open_count += 1\n # If we have more than one open bracket, we have a nested structure\n if open_count > 1:\n nested = True\n elif char == ']':\n open_count -= 1\n # If we close a bracket and there was at least one open bracket before\n if open_count < 0:\n return False # More closing brackets than opening\n # If we have a nested structure and we close a bracket\n if nested and open_count == 0:\n return True # We found a valid nested structure\n \n # If we finish and have open brackets left, it's not valid\n return nested and open_count == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers.\n You need to return the sum of squared numbers in the given list,\n round each element in the list to the upper int (Ceiling) first.\n \n Examples:\n For lst = [1,2,3] the output should be 14\n For lst = [1,4,9] the output should be 98\n For lst = [1,3,5,7] the output should be 84\n For lst = [1.4,4.2,0] the output should be 29\n For lst = [-2.4,1,1] the output should be 6\n \"\"\"\n return sum(math.ceil(x) ** 2 for x in lst)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n '''\n Create a function that returns True if the last character\n of a given string is an alphabetical character and is not\n a part of a word, and False otherwise.\n Note: \"word\" is a group of characters separated by space.\n\n Examples:\n check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '''\n \n # Strip any trailing whitespace from the string\n txt = txt.rstrip()\n \n # Check if the string is empty after stripping\n if not txt:\n return False\n \n # Get the last character of the string\n last_char = txt[-1]\n \n # Check if the last character is an alphabetical character\n if last_char.isalpha():\n # Check if the last character is part of a word\n # A character is part of a word if it is preceded by a non-space character\n if len(txt) > 1 and txt[-2] != ' ':\n return False\n return True\n \n return False", "base_status": "fail", "plus_status": null, "base_fail_tests": [["eeeee e "]], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "from collections import deque\ndef minPath(grid, k):\n N = len(grid)\n directions = [(0, 1), (1, 0), (0, -1), (-1, 0)] # Right, Down, Left, Up\n min_path = None\n\n def bfs(start_row, start_col):\n queue = deque([(start_row, start_col, [grid[start_row][start_col]])])\n while queue:\n row, col, path = queue.popleft()\n if len(path) == k:\n nonlocal min_path\n if min_path is None or path < min_path:\n min_path = path\n continue\n \n for dr, dc in directions:\n new_row, new_col = row + dr, col + dc\n if 0 <= new_row < N and 0 <= new_col < N:\n queue.append((new_row, new_col, path + [grid[new_row][new_col]]))\n\n for i in range(N):\n for j in range(N):\n bfs(i, j)\n\n return min_path", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n \"\"\"Create a function which returns the largest index of an element which\n is not greater than or equal to the element immediately preceding it. If\n no such element exists then return -1. The given array will not contain\n duplicate values.\n\n Examples:\n can_arrange([1,2,4,3,5]) = 3\n can_arrange([1,2,3]) = -1\n \"\"\"\n # Check for empty array\n if not arr:\n return -1\n\n # Initialize the largest index to -1\n largest_index = -1\n\n # Iterate through the array starting from the second element\n for i in range(1, len(arr)):\n # Check if the current element is less than the previous one\n if arr[i] < arr[i - 1]:\n largest_index = i\n\n return largest_index", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def parse_number(value):\n \"\"\"\n Convert a string representation of a number to a float or return the value as is.\n Handles both '.' and ',' as decimal separators.\n \"\"\"\n if isinstance(value, str):\n # Replace ',' with '.' for float conversion\n value = value.replace(',', '.')\n try:\n return float(value)\n except ValueError:\n return value # Return the original string if conversion fails\ndef compare_one(a, b):\n \"\"\"\n Compare two values (integers, floats, or strings representing real numbers)\n and return the larger one in its original type. Return None if they are equal.\n \"\"\"\n # Parse both values to comparable numbers\n parsed_a = parse_number(a)\n parsed_b = parse_number(b)\n\n # Check for equality\n if parsed_a == parsed_b:\n return None\n\n # Return the larger value in its original type\n return a if parsed_a > parsed_b else b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n '''\n Create a function that returns a tuple (a, b), where 'a' is\n the largest of negative integers, and 'b' is the smallest\n of positive integers in a list.\n If there is no negative or positive integers, return them as None.\n\n Examples:\n largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n largest_smallest_integers([]) == (None, None)\n largest_smallest_integers([0]) == (None, None)\n '''\n \n largest_negative = None\n smallest_positive = None\n \n for num in lst:\n if num < 0:\n if largest_negative is None or num > largest_negative:\n largest_negative = num\n elif num > 0:\n if smallest_positive is None or num < smallest_positive:\n smallest_positive = num\n \n return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n \"\"\"Calculate the factorial of a non-negative integer n.\"\"\"\n if n < 0:\n raise ValueError(\"Factorial is not defined for negative numbers.\")\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef special_factorial(n):\n \"\"\"Calculate the Brazilian factorial of n.\"\"\"\n if n < 1:\n raise ValueError(\"Input must be a positive integer greater than 0.\")\n \n result = 1\n for i in range(1, n + 1):\n result *= factorial(i)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n \n Args:\n n (int): The number to evaluate.\n \n Returns:\n bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n \n Example:\n is_equal_to_sum_even(4) == False\n is_equal_to_sum_even(6) == False\n is_equal_to_sum_even(8) == True\n \"\"\"\n # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n if n < 8:\n return False\n \n # Check if n is even\n if n % 2 != 0:\n return False\n \n # If n is even and >= 8, it can be expressed as the sum of 4 positive even numbers\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n \"\"\"Check if the given file name is valid based on specific criteria.\"\"\"\n \n # Define valid extensions\n valid_extensions = ['txt', 'exe', 'dll']\n \n # Check for exactly one dot\n if file_name.count('.') != 1:\n return 'No'\n \n # Split the file name into name and extension\n name, extension = file_name.rsplit('.', 1)\n \n # Check if the name is empty\n if not name:\n return 'No'\n \n # Check if the name starts with a letter\n if not name[0].isalpha():\n return 'No'\n \n # Check if the extension is valid\n if extension not in valid_extensions:\n return 'No'\n \n # Count digits in the file name\n digit_count = sum(c.isdigit() for c in file_name)\n \n # Check if there are more than three digits\n if digit_count > 3:\n return 'No'\n \n return 'Yes'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n \"\"\"\n Given a string text, replace all spaces in it with underscores, \n and if a string has more than 2 consecutive spaces, \n then replace all consecutive spaces with - \n \n fix_spaces(\"Example\") == \"Example\"\n fix_spaces(\"Example 1\") == \"Example_1\"\n fix_spaces(\" Example 2\") == \"_Example_2\"\n fix_spaces(\" Example 3\") == \"_Example-3\"\n \"\"\"\n # Replace multiple spaces with a placeholder\n text = text.replace(' ', '-').replace(' ', '-')\n \n # Replace remaining spaces with underscores\n text = text.replace(' ', '_')\n \n # Handle the case where we might have replaced more than 2 spaces\n # with a single '-' and then replaced spaces with underscores\n text = text.replace('_-_', '-')\n \n return text", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Yellow Yellow Dirty Fellow"]], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef words_in_sentence(sentence):\n \"\"\"\n Given a string representing a sentence, return a string that contains the words\n from the original sentence whose lengths are prime numbers.\n \n Parameters:\n sentence (str): The input sentence containing words separated by spaces.\n \n Returns:\n str: A string containing the words with prime lengths, in the original order.\n \"\"\"\n words = sentence.split()\n prime_length_words = [word for word in words if is_prime(len(word))]\n return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n \"\"\"\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n \n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126\n \"\"\"\n total_sum = 0\n \n for index, value in enumerate(lst):\n if index % 3 == 0:\n # Square the value if index is a multiple of 3\n total_sum += value ** 2\n elif index % 4 == 0:\n # Cube the value if index is a multiple of 4 and not a multiple of 3\n total_sum += value ** 3\n else:\n # Add the value unchanged if index is not a multiple of 3 or 4\n total_sum += value\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n \"\"\"\n Write a function which sorts the given list of integers\n in ascending order according to the sum of their digits.\n Note: if there are several items with similar sum of their digits,\n order them based on their index in original list.\n\n For example:\n >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n >>> order_by_points([]) == []\n \"\"\"\n \n def digit_sum(n):\n \"\"\"Calculate the sum of the digits of an integer n.\"\"\"\n return sum(int(digit) for digit in str(abs(n)))\n\n # Sort the list based on the sum of digits and original index\n return sorted(nums, key=lambda x: (digit_sum(x), nums.index(x)))", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n \"\"\"Simplifies the expression x * n and checks if the result is a whole number.\n \n Args:\n x (str): A string representation of a fraction in the format /.\n n (str): A string representation of a fraction in the format /.\n \n Returns:\n bool: True if x * n evaluates to a whole number, False otherwise.\n \"\"\"\n # Split the fractions into numerator and denominator\n x_numerator, x_denominator = map(int, x.split('/'))\n n_numerator, n_denominator = map(int, n.split('/'))\n \n # Calculate the product of the fractions\n # x * n = (x_numerator / x_denominator) * (n_numerator / n_denominator)\n # This simplifies to (x_numerator * n_numerator) / (x_denominator * n_denominator)\n \n numerator_product = x_numerator * n_numerator\n denominator_product = x_denominator * n_denominator\n \n # Check if the result is a whole number\n return numerator_product % denominator_product == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n \"\"\"Returns the number of elements in the array that are greater than 10 \n and both the first and last digits of the number are odd (1, 3, 5, 7, 9).\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n int: The count of numbers meeting the criteria.\n \"\"\"\n \n def is_odd_digit(digit):\n \"\"\"Check if a digit is odd.\"\"\"\n return digit in {1, 3, 5, 7, 9}\n \n def first_and_last_digits_are_odd(num):\n \"\"\"Check if both the first and last digits of the number are odd.\"\"\"\n num_str = str(abs(num)) # Convert to string and take absolute value\n first_digit = int(num_str[0])\n last_digit = int(num_str[-1])\n return is_odd_digit(first_digit) and is_odd_digit(last_digit)\n \n count = 0\n for num in nums:\n if num > 10 and first_and_last_digits_are_odd(num):\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n \"\"\"\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example:\n Input: n = 5\n Output: 1\n Explanation: \n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n \"\"\"\n # Create the array a\n a = [i * i - i + 1 for i in range(1, n + 1)]\n \n # Count the occurrences of each remainder when divided by 3\n count = [0, 0, 0]\n for value in a:\n count[value % 3] += 1\n \n # Calculate the number of valid triples\n total_triples = 0\n \n # Case 1: All three numbers have remainder 0\n total_triples += count[0] * (count[0] - 1) * (count[0] - 2) // 6\n \n # Case 2: All three numbers have remainder 1\n total_triples += count[1] * (count[1] - 1) * (count[1] - 2) // 6\n \n # Case 3: All three numbers have remainder 2\n total_triples += count[2] * (count[2] - 1) * (count[2] - 2) // 6\n \n # Case 4: One number from each remainder class\n total_triples += count[0] * count[1] * count[2]\n \n return total_triples", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closest to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sorted by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct planet names. \n Examples\n bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n '''\n\n # List of planets in order from the Sun\n planets = [\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n ]\n \n # Check if the input planets are valid\n if planet1 not in planets or planet2 not in planets:\n return ()\n \n # Get the indices of the planets\n index1 = planets.index(planet1)\n index2 = planets.index(planet2)\n \n # Determine the range of indices\n start_index = min(index1, index2) + 1\n end_index = max(index1, index2)\n \n # Get the planets in between\n in_between_planets = planets[start_index:end_index]\n \n return tuple(in_between_planets)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length and alphabetically.\n \n Args:\n lst (list of str): A list of strings.\n \n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the filtered list first by length, then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef x_or_y(n, x, y):\n \"\"\"Return x if n is a prime number, otherwise return y.\"\"\"\n if is_prime(n):\n return x\n else:\n return y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n \n double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n double_the_difference([-1, -2, 0]) == 0\n double_the_difference([9, -2]) == 81\n double_the_difference([0]) == 0 \n \n If the input list is empty, return 0.\n '''\n if not lst: # Check if the list is empty\n return 0\n \n sum_of_squares = 0\n for num in lst:\n if isinstance(num, int) and num >= 0 and num % 2 != 0: # Check for non-negative odd integers\n sum_of_squares += num ** 2 # Add the square of the odd number to the sum\n \n return sum_of_squares", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n \"\"\"\n Compares the actual game scores with the guessed scores and returns an array\n of the absolute differences. If the guess is correct, the difference is 0.\n\n Parameters:\n game (list of int): The actual scores of the matches.\n guess (list of int): The guessed scores of the matches.\n\n Returns:\n list of int: An array of absolute differences between the actual scores and the guesses.\n \"\"\"\n # Check if the lengths of game and guess are equal\n if len(game) != len(guess):\n raise ValueError(\"The length of game and guess must be the same.\")\n\n # Calculate the absolute differences\n result = [abs(g - a) for a, g in zip(game, guess)]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n \"\"\"Find the strongest extension based on the strength defined by the number of uppercase and lowercase letters.\"\"\"\n \n def calculate_strength(extension):\n \"\"\"Calculate the strength of the extension.\"\"\"\n CAP = sum(1 for char in extension if char.isupper())\n SM = sum(1 for char in extension if char.islower())\n return CAP - SM\n\n strongest_extension = None\n strongest_strength = float('-inf') # Start with the lowest possible strength\n\n for extension in extensions:\n strength = calculate_strength(extension)\n if strength > strongest_strength:\n strongest_strength = strength\n strongest_extension = extension\n\n if strongest_extension is not None:\n return f\"{class_name}.{strongest_extension}\"\n else:\n return None # In case there are no extensions", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n \"\"\"Check if the second word or any of its rotations is a substring in the first word.\"\"\"\n # Edge case: if b is empty, it is always a substring\n if not b:\n return True\n \n # Edge case: if a is empty and b is not, b cannot be a substring\n if not a:\n return False\n \n # Create a string that contains two copies of b\n # This allows us to check for all rotations of b\n b_rotations = b + b\n \n # Check if any rotation of b is a substring of a\n return any(rotation in a for rotation in (b_rotations[i:i+len(b)] for i in range(len(b))))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n Example:\n even_odd_count(-12) ==> (1, 1)\n even_odd_count(123) ==> (1, 2)\n \"\"\"\n # Convert the number to its absolute value and then to a string\n num_str = str(abs(num))\n \n even_count = 0\n odd_count = 0\n \n for digit in num_str:\n if digit.isdigit(): # Ensure we are only counting digits\n if int(digit) % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n if not (1 <= number <= 1000):\n raise ValueError(\"Number must be between 1 and 1000 inclusive.\")\n\n # Mapping of integers to their Roman numeral equivalents\n roman_numerals = [\n (1000, 'm'),\n (900, 'cm'),\n (500, 'd'),\n (400, 'cd'),\n (100, 'c'),\n (90, 'xc'),\n (50, 'l'),\n (40, 'xl'),\n (10, 'x'),\n (9, 'ix'),\n (5, 'v'),\n (4, 'iv'),\n (1, 'i')\n ]\n\n result = []\n \n for value, numeral in roman_numerals:\n while number >= value:\n result.append(numeral)\n number -= value\n\n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n \"\"\"Return the word with the maximum number of unique characters.\n If multiple words have the same maximum, return the one that comes first\n in lexicographical order.\n \n Args:\n words (list of str): A list of words to evaluate.\n \n Returns:\n str: The word with the maximum number of unique characters.\n \"\"\"\n max_word = \"\"\n max_unique_count = 0\n\n for word in words:\n unique_chars = set(word)\n unique_count = len(unique_chars)\n\n # Check if this word has more unique characters or is lexicographically smaller\n if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n max_word = word\n max_unique_count = unique_count\n\n return max_word", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return True if the three\n sides form a right-angled triangle, False otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or \n 90 degree.\n \n Example:\n right_angle_triangle(3, 4, 5) == True\n right_angle_triangle(1, 2, 3) == False\n '''\n # First, we need to check if the sides are positive\n if a <= 0 or b <= 0 or c <= 0:\n return False\n \n # Sort the sides to easily identify the longest side\n sides = sorted([a, b, c])\n \n # Check the Pythagorean theorem: a^2 + b^2 = c^2\n return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n \"\"\"\n You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n \n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n \n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots that exist in stock\n \n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n \"\"\"\n \n # Calculate how many more carrots are needed\n additional_needed = need - number\n \n # If no additional carrots are needed, return the current state\n if additional_needed <= 0:\n return [number, remaining]\n \n # Determine how many carrots can be eaten from the remaining stock\n carrots_eaten = min(additional_needed, remaining)\n \n # Calculate the total eaten and remaining carrots\n total_eaten = number + carrots_eaten\n remaining_after_meal = remaining - carrots_eaten\n \n return [total_eaten, remaining_after_meal]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic algebra operations, and \n the second list is a list of integers. Use the two given lists to build the algebraic \n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + ) \n Subtraction ( - ) \n Multiplication ( * ) \n Floor division ( // ) \n Exponentiation ( ** ) \n\n Example:\n operator = ['+', '*', '-']\n operand = [2, 3, 4, 5]\n result = 2 + 3 * 4 - 5\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.\n \"\"\"\n \n # Start with the first operand\n result = operand[0]\n \n # Iterate through the operators and operands\n for i in range(len(operator)):\n op = operator[i]\n next_operand = operand[i + 1]\n \n if op == '+':\n result += next_operand\n elif op == '-':\n result -= next_operand\n elif op == '*':\n result *= next_operand\n elif op == '//':\n if next_operand == 0:\n raise ValueError(\"Division by zero is not allowed.\")\n result //= next_operand\n elif op == '**':\n result **= next_operand\n else:\n raise ValueError(f\"Invalid operator: {op}\")\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": []}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n \"\"\"You are given a string s.\n If s[i] is a letter, reverse its case from lower to upper or vice versa,\n otherwise keep it as it is.\n If the string contains no letters, reverse the string.\n The function should return the resulted string.\n \n Examples:\n solve(\"1234\") = \"4321\"\n solve(\"ab\") = \"AB\"\n solve(\"#a@C\") = \"#A@c\"\n \"\"\"\n # Check if there are any letters in the string\n has_letters = any(c.isalpha() for c in s)\n \n if has_letters:\n # If there are letters, reverse the case of each letter\n result = ''.join(c.swapcase() if c.isalpha() else c for c in s)\n else:\n # If there are no letters, reverse the string\n result = s[::-1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string.\n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n >>> string_to_md5('') is None\n >>> string_to_md5('Python') == '3b3b3c4c4c4c4c4c4c4c4c4c4c4c4c4c'\n >>> string_to_md5('123456') == 'e10adc3949ba59abbe56e057f20f883e'\n >>> string_to_md5('!@#$%^&*()') == 'c5b8c3c3c3c3c3c3c3c3c3c3c3c3c3c3'\n \"\"\"\n if text == \"\":\n return None\n # Create an MD5 hash object\n md5_hash = hashlib.md5()\n # Update the hash object with the bytes of the string\n md5_hash.update(text.encode('utf-8'))\n # Return the hexadecimal digest of the hash\n return md5_hash.hexdigest()", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascending order.\n\n For example:\n generate_integers(2, 8) => [2, 4, 6, 8]\n generate_integers(8, 2) => [2, 4, 6, 8]\n generate_integers(10, 14) => []\n \"\"\"\n # Ensure a is less than or equal to b\n start = min(a, b)\n end = max(a, b)\n\n # Generate a list of even integers in the range\n even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n return even_integers", "base_status": "fail", "plus_status": null, "base_fail_tests": [[2, 10]], "plus_fail_tests": []}]}} \ No newline at end of file diff --git a/llm_based_135_eval_results.json b/llm_based_135_eval_results.json new file mode 100644 index 000000000..c4d3a92f4 --- /dev/null +++ b/llm_based_135_eval_results.json @@ -0,0 +1 @@ +{"date": "2024-07-27 00:37", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to make it easier to find close elements\n numbers.sort()\n \n # Check the differences between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" \n Input to this function is a string containing multiple groups of nested parentheses. \n The goal is to separate those groups into separate strings and return the list of those.\n Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n Ignore any spaces in the input string.\n \n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n # Remove spaces from the input string\n paren_string = paren_string.replace(\" \", \"\")\n \n result = []\n current_group = []\n balance = 0\n \n for char in paren_string:\n if char == '(':\n balance += 1\n current_group.append(char)\n elif char == ')':\n balance -= 1\n current_group.append(char)\n \n # When balance is zero, we have a complete group\n if balance == 0 and current_group:\n result.append(''.join(current_group))\n current_group = []\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into\n an integer part (largest integer smaller than given number) and decimals\n (leftover part always smaller than 1).\n\n Return the decimal part of the number.\n >>> truncate_number(3.5)\n 0.5\n \"\"\"\n if number < 0:\n raise ValueError(\"The number must be positive.\")\n \n # Get the integer part by using the floor function\n integer_part = int(number) # This truncates towards zero for positive numbers\n \n # Calculate the decimal part\n decimal_part = number - integer_part\n \n return decimal_part", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" \n Detect if the balance of a bank account falls below zero at any point \n given a list of deposit and withdrawal operations. The account starts \n with a zero balance.\n\n Args:\n operations (List[int]): A list of integers representing deposit (positive) \n and withdrawal (negative) operations.\n\n Returns:\n bool: True if the balance falls below zero at any point, otherwise False.\n\n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n \"\"\"\n balance = 0\n for operation in operations:\n balance += operation\n if balance < 0:\n return True\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimeter: int) -> List[int]:\n \"\"\" Insert a number 'delimeter' between every two consecutive elements of input list `numbers'\n \n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n \"\"\"\n if not numbers: # Check if the input list is empty\n return []\n \n result = [] # Initialize an empty list to store the result\n for i in range(len(numbers)):\n result.append(numbers[i]) # Add the current number to the result\n if i < len(numbers) - 1: # Check if it's not the last element\n result.append(delimeter) # Add the delimiter after the current number\n \n return result # Return the final result list", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list to avoid division by zero\n\n # Calculate the mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute deviations from the mean\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n \n # Calculate the mean of the absolute deviations\n mad = sum(absolute_deviations) / len(absolute_deviations)\n \n return mad", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string represented multiple groups for nested parentheses \n separated by spaces. For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n def max_nesting_depth(s: str) -> int:\n \"\"\" Helper function to calculate the maximum nesting depth of a single parenthesis string. \"\"\"\n max_depth = 0\n current_depth = 0\n \n for char in s:\n if char == '(':\n current_depth += 1\n max_depth = max(max_depth, current_depth)\n elif char == ')':\n current_depth -= 1\n if current_depth < 0: # More closing than opening parentheses\n return -1 # Invalid case\n return max_depth if current_depth == 0 else -1 # Valid if all opened are closed\n\n # Split the input string into groups and calculate the max nesting depth for each\n groups = paren_string.split()\n depths = []\n \n for group in groups:\n depth = max_nesting_depth(group)\n if depth == -1: # Handle invalid cases\n depths.append(0) # You can decide how to handle invalid cases\n else:\n depths.append(depth)\n \n return depths", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring.\n \n Args:\n strings (List[str]): A list of strings to filter.\n substring (str): The substring to search for within the strings.\n \n Returns:\n List[str]: A list of strings that contain the given substring.\n \n Examples:\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n \"\"\"\n # Use a list comprehension to filter the strings\n return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers: # Handle the case of an empty list\n return []\n \n max_so_far = numbers[0] # Initialize the maximum with the first element\n result = [max_so_far] # Start the result list with the first element\n\n for number in numbers[1:]: # Iterate through the rest of the numbers\n if number > max_so_far:\n max_so_far = number # Update the maximum if the current number is greater\n result.append(max_so_far) # Append the current maximum to the result list\n\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n \n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n \"\"\"\n if not numbers: # Check if the list is empty\n return (0, 1)\n \n total_sum = 0\n total_product = 1\n \n for number in numbers:\n total_sum += number\n total_product *= number\n \n return (total_sum, total_product)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n \"\"\" \n Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n \n >>> string_xor('010', '110')\n '100'\n \"\"\"\n # Ensure both strings are of the same length by padding the shorter one with leading zeros\n max_length = max(len(a), len(b))\n a = a.zfill(max_length)\n b = b.zfill(max_length)\n \n # Perform XOR operation\n result = []\n for bit_a, bit_b in zip(a, b):\n # XOR operation: '1' if bits are different, '0' if they are the same\n result.append('1' if bit_a != bit_b else '0')\n \n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n \"\"\"\n if not string:\n return ''\n \n # Find the longest palindromic suffix\n for i in range(len(string)):\n if is_palindrome(string[i:]):\n # If the suffix starting from index i is a palindrome,\n # we take the prefix before this suffix and reverse it\n prefix = string[:i]\n return string + prefix[::-1]\n \n # If no palindromic suffix is found, the whole string is non-palindromic\n return string + string[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return the greatest common divisor of two integers a and b.\n \n The function uses the Euclidean algorithm to compute the GCD.\n \n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n \"\"\"\n # Handle negative inputs by taking the absolute value\n a, b = abs(a), abs(b)\n \n # Base case: if one of the numbers is zero, return the other number\n if b == 0:\n return a\n # Recursive case: apply the Euclidean algorithm\n return greatest_common_divisor(b, a % b)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n \n >>> longest([])\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n \"\"\"\n if not strings:\n return None\n \n longest_string = strings[0]\n \n for string in strings:\n if len(string) > len(longest_string):\n longest_string = string\n \n return longest_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string.\n \n Args:\n string (str): The input string from which to generate prefixes.\n \n Returns:\n List[str]: A list of all prefixes of the input string.\n \n Examples:\n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n \"\"\"\n # Initialize an empty list to store the prefixes\n prefixes = []\n \n # Iterate over the range of the length of the string\n for i in range(1, len(string) + 1):\n # Append the substring from the start to the current index\n prefixes.append(string[:i])\n \n return prefixes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" \n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set()\n \n # Iterate through each character in the string\n for char in lower_string:\n # Add the character to the set\n distinct_characters.add(char)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n \n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n \"\"\"\n # Check if n is negative\n if n < 0:\n return \"\"\n \n # Create a list of numbers from 0 to n\n numbers = [str(i) for i in range(n + 1)]\n \n # Join the list into a single string with spaces\n return ' '.join(numbers)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string representing musical notes in a special ASCII format.\n Your task is to parse this string and return list of integers corresponding to how many beats does each\n note last.\n\n Here is a legend:\n 'o' - whole note, lasts four beats\n 'o|' - half note, lasts two beats\n '.|' - quarter note, lasts one beat\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n # Define a mapping of note representations to their corresponding beat values\n note_to_beats = {\n 'o': 4, # whole note\n 'o|': 2, # half note\n '.|': 1 # quarter note\n }\n \n # Split the input string into individual notes\n notes = music_string.split()\n \n # Initialize a list to hold the beats for each note\n beats = []\n \n # Iterate over each note and convert it to its corresponding beat value\n for note in notes:\n if note in note_to_beats:\n beats.append(note_to_beats[note])\n else:\n # If an unknown note is encountered, we can choose to ignore it or raise an error\n # Here we will ignore it for robustness\n continue\n \n return beats", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n \n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n \"\"\"\n if not substring: # If the substring is empty, return 0\n return 0\n \n count = 0\n start = 0\n \n while True:\n start = string.find(substring, start) # Find the next occurrence of the substring\n if start == -1: # If no more occurrences are found, break the loop\n break\n count += 1 # Increment the count for each found occurrence\n start += 1 # Move to the next character to allow for overlapping matches\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n \"\"\" \n Input is a space-delimited string of numerals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest.\n \n >>> sort_numbers('three one five')\n 'one three five'\n \"\"\"\n \n # Mapping of words to their corresponding numeric values\n word_to_number = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n \n # Split the input string into words\n words = numbers.split()\n \n # Convert words to their corresponding numeric values\n numeric_values = [word_to_number[word] for word in words]\n \n # Sort the numeric values\n sorted_values = sorted(numeric_values)\n \n # Convert sorted numeric values back to words\n number_to_word = {v: k for k, v in word_to_number.items()}\n sorted_words = [number_to_word[value] for value in sorted_values]\n \n # Join the sorted words into a single string and return\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to find the closest pairs easily\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest elements\n for i in range(len(sorted_numbers) - 1):\n # Calculate the difference between consecutive elements\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n \n # If this difference is smaller than the minimum found so far, update\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1.\n \n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The input list must contain at least two elements.\")\n \n min_value = min(numbers)\n max_value = max(numbers)\n \n if min_value == max_value:\n # If all numbers are the same, return a list of zeros\n return [0.0] * len(numbers)\n \n # Rescale the numbers\n rescaled = [(num - min_value) / (max_value - min_value) for num in numbers]\n \n return rescaled", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers \"\"\"\n return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n \n >>> largest_divisor(15)\n 5\n \"\"\"\n # Edge case: if n is less than or equal to 1, there are no divisors smaller than n\n if n <= 1:\n return None # or raise an exception, depending on how you want to handle this case\n\n # Start checking from n-1 down to 1\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n \"\"\" Return length of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n \"\"\"\n # Initialize a counter for the length\n length = 0\n \n # Iterate through each character in the string\n for char in string:\n length += 1 # Increment the length for each character\n \n return length", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n Input number should be equal to the product of all factors\n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n \"\"\"\n if n <= 1:\n return [] # No prime factors for numbers less than or equal to 1\n\n factors = []\n # Check for number of 2s that divide n\n while n % 2 == 0:\n factors.append(2)\n n //= 2\n\n # n must be odd at this point, so we can skip even numbers\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n factors.append(i)\n n //= i\n\n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n factors.append(n)\n\n return factors", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a dictionary to count occurrences of each number\n count = {}\n \n # Count each number's occurrences\n for number in numbers:\n if number in count:\n count[number] += 1\n else:\n count[number] = 1\n \n # Create a list to hold the result\n result = []\n \n # Add numbers that occur only once to the result list\n for number in numbers:\n if count[number] == 1:\n result.append(number)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n \n >>> flip_case('Hello')\n 'hELLO'\n \"\"\"\n # Initialize an empty list to store the flipped characters\n flipped_chars = []\n \n # Iterate through each character in the input string\n for char in string:\n # Check if the character is lowercase\n if char.islower():\n # Convert to uppercase\n flipped_chars.append(char.upper())\n # Check if the character is uppercase\n elif char.isupper():\n # Convert to lowercase\n flipped_chars.append(char.lower())\n else:\n # If it's neither, keep the character as is (e.g., punctuation, numbers, etc.)\n flipped_chars.append(char)\n \n # Join the list of flipped characters into a single string and return it\n return ''.join(flipped_chars)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string.\n \n Args:\n strings (List[str]): A list of strings to concatenate.\n \n Returns:\n str: A single concatenated string.\n \n Examples:\n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n \"\"\"\n # Initialize an empty string to hold the result\n result = ''\n \n # Iterate through each string in the list and concatenate\n for string in strings:\n result += string\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n \n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n \"\"\"\n return [x for x in l if x > 0]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n \n Args:\n strings (List[str]): A list of strings to filter.\n prefix (str): The prefix to filter the strings by.\n \n Returns:\n List[str]: A list of strings that start with the given prefix.\n \n Examples:\n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n \"\"\"\n # Use a list comprehension to filter the strings\n return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n A prime number is a natural number greater than 1 that cannot be formed by multiplying two smaller natural numbers.\n \n Args:\n n (int): The number to check for primality.\n \n Returns:\n bool: True if n is prime, False otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return False # eliminate multiples of 2 and 3\n\n i = 5\n while i * i <= n: # check for factors from 5 to sqrt(n)\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6 # check only 6k \u00b1 1\n\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float):\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list, x: float):\n \"\"\"\n Evaluates the derivative of the polynomial with coefficients xs at point x.\n \"\"\"\n return sum(i * coeff * math.pow(x, i - 1) for i, coeff in enumerate(xs) if i > 0)\ndef find_zero(xs: list):\n \"\"\" \n xs are coefficients of a polynomial.\n find_zero finds x such that poly(x) = 0.\n find_zero returns only one zero point, even if there are many.\n Moreover, find_zero only takes list xs having an even number of coefficients\n and the largest non-zero coefficient as it guarantees a solution.\n \"\"\"\n if len(xs) % 2 != 0:\n raise ValueError(\"The number of coefficients must be even.\")\n \n # Initial guess for the root\n x0 = 0.0\n \n # Newton-Raphson method parameters\n tolerance = 1e-7\n max_iterations = 1000\n \n for _ in range(max_iterations):\n f_x0 = poly(xs, x0)\n f_prime_x0 = derivative(xs, x0)\n \n if f_prime_x0 == 0:\n raise ValueError(\"Derivative is zero. No solution found.\")\n \n # Update x using Newton's method\n x1 = x0 - f_x0 / f_prime_x0\n \n # Check for convergence\n if abs(x1 - x0) < tolerance:\n return x1\n \n x0 = x1\n \n raise ValueError(\"Maximum iterations reached. No solution found.\")", "base_status": "fail", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n values_to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(values_to_sort)\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Replace values at indices divisible by 3 with sorted values\n sorted_index = 0\n for i in range(len(result)):\n if i % 3 == 0:\n result[i] = sorted_values[sorted_index]\n sorted_index += 1\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n This function takes a list as input, removes duplicate elements, \n and returns a new list containing only the unique elements sorted in ascending order.\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use a set to remove duplicates\n unique_elements = set(l)\n \n # Sort the unique elements and return as a list\n return sorted(unique_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n \"\"\"Return maximum element in the list.\n \n If the list is empty, raise a ValueError.\n \n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n \"\"\"\n if not l: # Check if the list is empty\n raise ValueError(\"The list is empty. Cannot determine the maximum element.\")\n \n max_value = l[0] # Initialize max_value with the first element of the list\n for element in l: # Iterate through each element in the list\n if element > max_value: # Compare each element with the current max_value\n max_value = element # Update max_value if a larger element is found\n \n return max_value # Return the maximum value found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indexed elements\n even_indices_values.sort()\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Place the sorted even indexed values back into their positions\n for i, value in enumerate(even_indices_values):\n result[i * 2] = value # Place sorted value at even index\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with the encode_cyclic function.\n Returns the decoded string.\n \"\"\"\n # Split string into groups of length 3\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # Reverse the cycling of elements in each group\n groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_fib(n: int) -> int:\n \"\"\"\n prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n \n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n count = 0\n for fib in fibonacci_generator():\n if is_prime(fib):\n count += 1\n if count == n:\n return fib", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1]], "plus_fail_tests": []}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n \"\"\"\n triples_sum_to_zero takes a list of integers as an input.\n it returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n \"\"\"\n n = len(l)\n if n < 3:\n return False\n\n # Sort the list to use the two-pointer technique\n l.sort()\n\n for i in range(n - 2):\n # Avoid duplicates for the first element\n if i > 0 and l[i] == l[i - 1]:\n continue\n \n left, right = i + 1, n - 1\n while left < right:\n current_sum = l[i] + l[left] + l[right]\n if current_sum == 0:\n return True\n elif current_sum < 0:\n left += 1\n else:\n right -= 1\n\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n \n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n \"\"\"\n # Check if the input is a list\n if not isinstance(l, list):\n raise ValueError(\"Input must be a list.\")\n \n # Increment each element in the list by 1\n return [x + 1 for x in l]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n \"\"\"\n Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move at the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.\n\n :param n: The number of cars in each direction.\n :return: The total number of collisions.\n \"\"\"\n # Each car moving left to right will collide with each car moving right to left.\n # Therefore, the total number of collisions is simply n * n.\n return n * n", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion.\n base numbers are less than 10.\n \n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n \"\"\"\n if base < 2 or base >= 10:\n raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n \n if x == 0:\n return '0'\n \n result = []\n negative = x < 0\n x = abs(x)\n\n while x > 0:\n remainder = x % base\n result.append(str(remainder))\n x //= base\n\n if negative:\n result.append('-')\n\n # The result is built in reverse order\n return ''.join(reversed(result))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n \n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n \"\"\"\n seen = set()\n for number in l:\n if -number in seen:\n return True\n seen.add(number)\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n \"\"\"Given length of a side and height, return area for a triangle.\n \n The area of a triangle can be calculated using the formula:\n Area = (base * height) / 2\n \n Parameters:\n a (float): The length of the base of the triangle.\n h (float): The height of the triangle.\n \n Returns:\n float: The area of the triangle.\n \n Raises:\n ValueError: If the base or height is not a positive number.\n \n >>> triangle_area(5, 3)\n 7.5\n >>> triangle_area(0, 3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(5, 0)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(-5, 3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(5, -3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n \"\"\"\n \n if a <= 0 or h <= 0:\n raise ValueError(\"Base and height must be positive numbers.\")\n \n return (a * h) / 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fib4(0) -> 0\n fib4(1) -> 0\n fib4(2) -> 2\n fib4(3) -> 0\n fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n \n This function computes the n-th element of the fib4 number sequence efficiently without using recursion.\n \n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n # Handle base cases\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 2\n elif n == 3:\n return 0\n \n # Initialize a list to store computed values\n fib_values = [0] * (n + 1)\n fib_values[0] = 0\n fib_values[1] = 0\n fib_values[2] = 2\n fib_values[3] = 0\n \n # Compute fib4 values iteratively\n for i in range(4, n + 1):\n fib_values[i] = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n \n return fib_values[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n \"\"\"Return median of elements in the list l.\n \n The median is the middle value in a list of numbers. If the list has an odd number of elements,\n the median is the middle element. If the list has an even number of elements, the median is the\n average of the two middle elements.\n \n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty. Cannot compute median.\")\n \n # Sort the list\n sorted_list = sorted(l)\n n = len(sorted_list)\n \n # Calculate median\n if n % 2 == 1: # Odd number of elements\n return sorted_list[n // 2]\n else: # Even number of elements\n mid1 = sorted_list[n // 2 - 1]\n mid2 = sorted_list[n // 2]\n return (mid1 + mid2) / 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n \"\"\"\n Checks if given string is a palindrome.\n \n A palindrome is a string that reads the same forward and backward.\n \n Args:\n text (str): The string to check.\n \n Returns:\n bool: True if the string is a palindrome, False otherwise.\n \n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n \"\"\"\n # Normalize the string by removing spaces and converting to lowercase\n normalized_text = text.replace(\" \", \"\").lower()\n \n # Check if the normalized string is equal to its reverse\n return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n \"\"\"\n Takes as input string encoded with encode_shift function. Returns decoded string.\n Non-alphabetic characters are not changed.\n \"\"\"\n return \"\".join([\n chr(((ord(ch) - ord('a') - 5) % 26) + ord('a')) if 'a' <= ch <= 'z' else ch\n for ch in s\n ])", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n if p <= 0:\n raise ValueError(\"p must be a positive integer.\")\n \n # Handle the case when n is negative\n if n < 0:\n return 0 # 2^n is not defined for negative n in this context\n \n result = 1\n base = 2\n \n # Use modular exponentiation\n while n > 0:\n if n % 2 == 1: # If n is odd\n result = (result * base) % p\n base = (base * base) % p # Square the base\n n //= 2 # Divide n by 2\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n \"\"\"Return True if all numbers in the list l are below threshold t.\n \n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n \"\"\"\n # Check if all elements in the list are below the threshold\n for number in l:\n if number >= t:\n return False\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n Vowels are defined as 'a', 'e', 'i', 'o', 'u' and their uppercase counterparts.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n \"\"\"Add two numbers x and y.\n\n This function takes two integers and returns their sum. It handles\n typical integer addition and ensures that the inputs are of the correct type.\n\n Args:\n x (int): The first integer to add.\n y (int): The second integer to add.\n\n Returns:\n int: The sum of x and y.\n\n Raises:\n TypeError: If either x or y is not an integer.\n\n Examples:\n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n \"\"\"\n if not isinstance(x, int) or not isinstance(y, int):\n raise TypeError(\"Both x and y must be integers.\")\n \n return x + y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two words have the same characters if they contain the same unique characters,\n regardless of the frequency of those characters.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Create a set of unique characters for each string\n unique_chars_s0 = set(s0)\n unique_chars_s1 = set(s1)\n \n # Compare the sets of unique characters\n return unique_chars_s0 == unique_chars_s1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n \"\"\"Return n-th Fibonacci number.\n \n The Fibonacci sequence is defined as follows:\n - fib(0) = 0\n - fib(1) = 1\n - fib(n) = fib(n-1) + fib(n-2) for n > 1\n\n Args:\n n (int): The index of the Fibonacci number to return.\n\n Returns:\n int: The n-th Fibonacci number.\n\n Raises:\n ValueError: If n is negative.\n\n Examples:\n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n \"\"\"\n if n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n if n == 0:\n return 0\n elif n == 1:\n return 1\n \n a, b = 0, 1\n for _ in range(2, n + 1):\n a, b = b, a + b\n \n return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"<\" and \">\".\n return True if every opening bracket has a corresponding closing bracket.\n \"\"\"\n balance = 0\n \n for char in brackets:\n if char == '<':\n balance += 1\n elif char == '>':\n balance -= 1\n \n # If balance goes negative, it means there's a closing bracket without a matching opening bracket\n if balance < 0:\n return False\n \n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n \"\"\"Return True if list elements are monotonically increasing or decreasing.\n \n A list is considered monotonically increasing if each element is greater than or equal to the previous one.\n A list is considered monotonically decreasing if each element is less than or equal to the previous one.\n \n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n \"\"\"\n if not l: # An empty list is considered monotonic\n return True\n \n increasing = decreasing = True\n \n for i in range(1, len(l)):\n if l[i] > l[i - 1]:\n decreasing = False\n elif l[i] < l[i - 1]:\n increasing = False\n \n # If both increasing and decreasing are False, we can return early\n if not increasing and not decreasing:\n return False\n \n return increasing or decreasing", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n \n Args:\n n (int): The upper limit of the sum (inclusive).\n \n Returns:\n int: The sum of all integers from 1 to n.\n \n Examples:\n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n \"\"\"\n if n < 1:\n return 0 # Return 0 for non-positive integers as the sum is not defined.\n \n return n * (n + 1) // 2 # Using the formula for the sum of the first n natural numbers.", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n largest_factor = None\n \n # Check for number of 2s that divide n\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # n must be odd at this point, so we can skip even numbers\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n \n return largest_factor", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n \"\"\" \n Calculate the derivative of a polynomial represented by its coefficients.\n \n The polynomial is represented as:\n xs[0] + xs[1] * x + xs[2] * x^2 + ...\n \n The derivative is calculated as:\n 0 + 1 * xs[1] + 2 * xs[2] * x + 3 * xs[3] * x^2 + ...\n \n Args:\n xs (list): A list of coefficients where the index represents the power of x.\n \n Returns:\n list: A list of coefficients representing the derivative of the polynomial.\n \n Examples:\n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n \"\"\"\n # Check if the input list is empty\n if not xs:\n return []\n \n # Calculate the derivative coefficients\n derivative_coeffs = []\n for i in range(1, len(xs)):\n derivative_coeffs.append(i * xs[i])\n \n return derivative_coeffs", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"(\" and \")\".\n return True if every opening bracket has a corresponding closing bracket.\n \"\"\"\n balance = 0\n \n for char in brackets:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n \n # If balance goes negative, it means there's a closing bracket without a matching opening bracket\n if balance < 0:\n return False\n \n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n \n Args:\n n (int): The index of the FibFib sequence to compute.\n \n Returns:\n int: The n-th element of the FibFib sequence.\n \n Examples:\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 1\n \n # Initialize the first three values of the sequence\n fibfib_values = [0, 0, 1]\n \n # Compute the values iteratively up to n\n for i in range(3, n + 1):\n next_value = fibfib_values[i - 1] + fibfib_values[i - 2] + fibfib_values[i - 3]\n fibfib_values.append(next_value)\n \n return fibfib_values[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set('aeiouAEIOU')\n count = 0\n \n # Check each character in the string\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n # Check if 'y' is at the end of the string\n elif s[i].lower() == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n \n >>> circular_shift(12, 1)\n \"21\"\n >>> circular_shift(12, 2)\n \"12\"\n \"\"\"\n # Convert the integer to a string to work with its digits\n str_x = str(x)\n num_digits = len(str_x)\n \n # If shift is greater than the number of digits, reverse the string\n if shift >= num_digits:\n return str_x[::-1]\n \n # Calculate the effective shift (in case shift is larger than num_digits)\n effective_shift = shift % num_digits\n \n # Perform the circular shift\n if effective_shift > 0:\n # Split the string into two parts and rearrange them\n return str_x[-effective_shift:] + str_x[:-effective_shift]\n \n # If effective_shift is 0, return the original string\n return str_x", "base_status": "fail", "plus_status": null, "base_fail_tests": [[12, 2]], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n \"\"\"Task\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n \"\"\"\n # Initialize the sum of ASCII values of uppercase characters\n total = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is uppercase\n if char.isupper():\n # Add the ASCII value of the uppercase character to the total\n total += ord(char)\n \n return total", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n \"\"\"\n Given an array representing a branch of a tree that has non-negative integer nodes,\n your task is to pluck one of the nodes and return it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n The plucked node should be returned in a list, [ smallest_value, its index ],\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1] \n\n Example 3:\n Input: []\n Output: []\n \n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n \"\"\"\n smallest_even_value = float('inf')\n smallest_index = -1\n\n for index, value in enumerate(arr):\n if value % 2 == 0: # Check if the value is even\n if value < smallest_even_value: # Found a smaller even value\n smallest_even_value = value\n smallest_index = index\n elif value == smallest_even_value and index < smallest_index:\n smallest_index = index # Update index if same value found earlier\n\n if smallest_index == -1: # No even value found\n return []\n \n return [smallest_even_value, smallest_index]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n \"\"\"\n Calculate the number of mango fruits in a basket given the number of apples and oranges.\n\n Parameters:\n s (str): A string representing the number of apples and oranges in the format \"X apples and Y oranges\".\n n (int): The total number of fruits in the basket.\n\n Returns:\n int: The number of mango fruits in the basket.\n \"\"\"\n # Split the input string to extract the number of apples and oranges\n parts = s.split(\" and \")\n apples = int(parts[0].split()[0]) # Get the number of apples\n oranges = int(parts[1].split()[0]) # Get the number of oranges\n\n # Calculate the number of mangoes\n mangoes = n - apples - oranges\n\n return mangoes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n '''\n Given list of integers, return list in strange order.\n Strange sorting, is when you start with the minimum value,\n then maximum of the remaining integers, then minimum and so on.\n\n Examples:\n strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n strange_sort_list([]) == []\n '''\n if not lst:\n return []\n\n # Sort the list to easily access min and max values\n sorted_lst = sorted(lst)\n result = []\n \n # Use two pointers to select min and max alternately\n left = 0\n right = len(sorted_lst) - 1\n \n while left <= right:\n if left == right: # If both pointers meet, add the last element\n result.append(sorted_lst[left])\n else:\n result.append(sorted_lst[left]) # Add the minimum\n result.append(sorted_lst[right]) # Add the maximum\n left += 1\n right -= 1\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n '''\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequency greater than or equal to the value of the integer itself. \n The frequency of an integer is the number of times it appears in the list.\n If no such a value exist, return -1.\n Examples:\n search([4, 1, 2, 2, 3, 1]) == 2\n search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n search([5, 5, 4, 4, 4]) == -1\n '''\n from collections import Counter\n\n # Count the frequency of each integer in the list\n frequency = Counter(lst)\n\n # Initialize the result variable to -1\n result = -1\n\n # Iterate through the frequency dictionary\n for num in frequency:\n # Check if the frequency is greater than or equal to the number itself\n if frequency[num] >= num:\n # Update the result if the current number is greater than the current result\n result = max(result, num)\n\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n '''\n Write a function that returns True if the object q will fly, and False otherwise.\n The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n '''\n # Check if the list is a palindrome\n is_balanced = (q == q[::-1])\n \n # Calculate the sum of the elements in the list\n total_weight = sum(q)\n \n # Determine if the object will fly\n return is_balanced and (total_weight <= w)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return the area of\n the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n Otherwise return -1.\n Three sides make a valid triangle when the sum of any two sides is greater \n than the third side.\n '''\n # Check for valid triangle using the triangle inequality theorem\n if a <= 0 or b <= 0 or c <= 0:\n return -1\n if a + b <= c or a + c <= b or b + c <= a:\n return -1\n \n # Calculate the semi-perimeter\n s = (a + b + c) / 2\n \n # Calculate the area using Heron's formula\n area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n \n # Return the area rounded to 2 decimal points\n return round(area, 2)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n \"\"\"\n Given an array arr of integers, find the minimum number of elements that\n need to be changed to make the array palindromic. A palindromic array is an array that\n is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n For example:\n smallest_change([1,2,3,5,4,7,9,6]) == 4\n smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n smallest_change([1, 2, 3, 2, 1]) == 0\n \"\"\"\n n = len(arr)\n changes = 0\n \n # Compare elements from the start and end towards the center\n for i in range(n // 2):\n if arr[i] != arr[n - 1 - i]:\n changes += 1\n \n return changes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n \n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total character counts and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n else:\n return lst2", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef generate_primes(limit):\n \"\"\"Generate a list of prime numbers up to a given limit.\"\"\"\n primes = []\n for num in range(2, limit):\n if is_prime(num):\n primes.append(num)\n return primes\ndef is_multiply_prime(a):\n \"\"\"Return true if the given number is the multiplication of 3 prime numbers, false otherwise.\"\"\"\n if a < 1 or a >= 100:\n return False\n \n primes = generate_primes(100)\n \n # Check all combinations of three primes\n for i in range(len(primes)):\n for j in range(i, len(primes)):\n for k in range(j, len(primes)):\n product = primes[i] * primes[j] * primes[k]\n if product == a:\n return True\n if product > a: # No need to check further if product exceeds 'a'\n break\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n \"\"\"Returns True if x is a simple power of n, otherwise False.\n \n A number x is a simple power of n if there exists an integer k such that n**k = x.\n \n Args:\n x (int): The number to check.\n n (int): The base number.\n \n Returns:\n bool: True if x is a simple power of n, False otherwise.\n \"\"\"\n # Edge case: if n is 0, we cannot raise it to any power to get a positive x\n if n == 0:\n return x == 0\n \n # Edge case: if n is 1, n**k is always 1 for any k, so x must be 1\n if n == 1:\n return x == 1\n \n # Edge case: if x is less than 1, we can only have x == 1 for n > 1\n if x < 1:\n return x == 1\n \n # Check if x is a power of n\n power = 1\n while True:\n power_value = n ** power\n if power_value == x:\n return True\n elif power_value > x:\n return False\n power += 1", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1, 12]], "plus_fail_tests": []}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this integer is a cube of some integer number.\n Note: you may assume the input is always valid.\n Examples:\n iscube(1) ==> True\n iscube(2) ==> False\n iscube(-1) ==> True\n iscube(64) ==> True\n iscube(0) ==> True\n iscube(180) ==> False\n '''\n # Calculate the cube root of the absolute value of a\n cube_root = round(abs(a) ** (1/3))\n \n # Check if the cube of the rounded cube root equals the absolute value of a\n return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n \"\"\"Counts the number of prime hexadecimal digits in the given hexadecimal string.\"\"\"\n \n # Define the set of prime hexadecimal digits\n prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n \n # Initialize a counter for prime digits\n count = 0\n \n # Iterate through each character in the input string\n for char in num:\n # Check if the character is in the set of prime hexadecimal digits\n if char in prime_hex_digits:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n \"\"\"Check if the string s is happy.\n \n A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n \n Args:\n s (str): The input string to check.\n \n Returns:\n bool: True if the string is happy, False otherwise.\n \"\"\"\n # Check if the length of the string is at least 3\n if len(s) < 3:\n return False\n \n # Iterate through the string and check every 3 consecutive characters\n for i in range(len(s) - 2):\n # Get the current substring of 3 characters\n substring = s[i:i+3]\n # Check if all characters in the substring are distinct\n if len(set(substring)) != 3:\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n \"\"\"Convert a decimal number to binary format with specific formatting.\n\n Args:\n decimal (int): A non-negative integer to convert to binary.\n\n Returns:\n str: A string representing the binary format of the decimal number,\n prefixed and suffixed with 'db'.\n \n Raises:\n ValueError: If the input is a negative integer.\n \"\"\"\n if decimal < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n # Convert decimal to binary and remove the '0b' prefix\n binary_representation = bin(decimal)[2:]\n \n # Format the result with 'db' at the beginning and end\n formatted_result = f\"db{binary_representation}db\"\n \n return formatted_result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n letter_grades = []\n \n for gpa in grades:\n if gpa == 4.0:\n letter_grades.append('A+')\n elif gpa > 3.7:\n letter_grades.append('A')\n elif gpa > 3.3:\n letter_grades.append('A-')\n elif gpa > 3.0:\n letter_grades.append('B+')\n elif gpa > 2.7:\n letter_grades.append('B')\n elif gpa > 2.3:\n letter_grades.append('B-')\n elif gpa > 2.0:\n letter_grades.append('C+')\n elif gpa > 1.7:\n letter_grades.append('C')\n elif gpa > 1.3:\n letter_grades.append('C-')\n elif gpa > 1.0:\n letter_grades.append('D+')\n elif gpa > 0.7:\n letter_grades.append('D')\n elif gpa > 0.0:\n letter_grades.append('D-')\n else:\n letter_grades.append('E')\n \n return letter_grades", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_length(string):\n \"\"\"Check if the length of the string is a prime number.\"\"\"\n length = len(string)\n return is_prime(length)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n \"\"\"\n Given a positive integer n, return the count of the numbers of n-digit\n positive integers that start or end with 1.\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n\n # Total n-digit numbers\n total_n_digit_numbers = 9 * (10 ** (n - 1))\n\n # Count of n-digit numbers that start with 1\n if n == 1:\n count_starting_with_1 = 1 # Only the number 1\n else:\n count_starting_with_1 = 10 ** (n - 1) # 1 followed by (n-1) digits (0-9)\n\n # Count of n-digit numbers that end with 1\n count_ending_with_1 = 9 * (10 ** (n - 2)) if n > 1 else 1 # (n-1) digits can be anything (0-9)\n\n # Total count of n-digit numbers that start or end with 1\n # We need to subtract the overlap where numbers both start and end with 1\n if n > 1:\n count_both_start_and_end_with_1 = 10 ** (n - 2) # 1 followed by (n-2) digits followed by 1\n else:\n count_both_start_and_end_with_1 = 0 # No overlap for single digit\n\n total_count = (count_starting_with_1 + count_ending_with_1 - count_both_start_and_end_with_1)\n\n return total_count", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1]], "plus_fail_tests": []}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits will be 1 the output should be \"1\".\n For N = 150, the sum of digits will be 6 the output should be \"110\".\n For N = 147, the sum of digits will be 12 the output should be \"1100\".\n \n Variables:\n @N integer\n Constraints: 0 \u2264 N \u2264 10000.\n Output:\n a string of binary number\n \"\"\"\n # Step 1: Calculate the sum of the digits of N\n digit_sum = sum(int(digit) for digit in str(N))\n \n # Step 2: Convert the sum to binary and remove the '0b' prefix\n binary_sum = bin(digit_sum)[2:]\n \n return binary_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum to 0\n total = 0\n \n # Iterate over the list using index and value\n for index in range(1, len(lst), 2): # Start from index 1 and step by 2 (odd indices)\n if lst[index] % 2 == 0: # Check if the element is even\n total += lst[index] # Add to total if it's even\n \n return total", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words and spaces\n words = s.split(' ')\n \n # Process each word to sort its characters\n sorted_words = []\n for word in words:\n # Sort the characters of the word and join them back\n sorted_word = ''.join(sorted(word))\n sorted_words.append(sorted_word)\n \n # Join the sorted words back with spaces\n result = ' '.join(sorted_words)\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n or sort it in descending order if the sum( first index value, last index value) is even.\n\n Note:\n * don't change the given array.\n\n Examples:\n * sort_array([]) => []\n * sort_array([5]) => [5]\n * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n \"\"\"\n # Create a copy of the original array to avoid modifying it\n sorted_array = array.copy()\n \n # Check if the array is empty\n if not sorted_array:\n return sorted_array\n \n # Calculate the sum of the first and last elements\n first_element = sorted_array[0]\n last_element = sorted_array[-1]\n total_sum = first_element + last_element\n \n # Sort the array based on the sum being odd or even\n if total_sum % 2 == 0:\n # Even sum: sort in descending order\n sorted_array.sort(reverse=True)\n else:\n # Odd sum: sort in ascending order\n sorted_array.sort()\n \n return sorted_array", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n # Iterate through each row in the list\n for row_index, row in enumerate(lst):\n # Check if the target value x is in the current row\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort coordinates by row (ascending) and then by column (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n # Create a dictionary to map each letter to its encrypted counterpart\n encrypted_dict = {}\n \n # Populate the dictionary with the shifted letters\n for i in range(len(alphabet)):\n # Calculate the new position with a shift of 4 (2 * 2)\n new_position = (i + 4) % 26\n encrypted_dict[alphabet[i]] = alphabet[new_position]\n \n # Encrypt the input string\n encrypted_string = ''\n for char in s:\n if char in encrypted_dict:\n encrypted_string += encrypted_dict[char]\n else:\n # If the character is not in the alphabet (e.g., spaces, punctuation), keep it unchanged\n encrypted_string += char\n \n return encrypted_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Convert the set back to a sorted list\n sorted_unique_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_unique_elements[1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n \n For example:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n \"\"\"\n # Split the input string into sentences based on the delimiters\n sentences = []\n current_sentence = []\n delimiters = {'.', '?', '!'}\n \n for char in S:\n if char in delimiters:\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n current_sentence = []\n else:\n current_sentence.append(char)\n \n # Add the last sentence if it exists\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n \n # Count the number of sentences that start with \"I\"\n boredom_count = sum(1 for sentence in sentences if sentence.startswith(\"I\"))\n \n return boredom_count", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n '''\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n \n Examples\n any_int(5, 2, 7) \u279e True\n any_int(3, 2, 2) \u279e False\n any_int(3, -2, 1) \u279e True\n any_int(3.6, -2.2, 2) \u279e False\n '''\n \n # Check if all inputs are integers\n if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n # Check if any number is equal to the sum of the other two\n return x == y + z or y == x + z or z == x + y\n else:\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef sum_of_digits(n):\n \"\"\"Return the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n largest_prime = -1\n \n for number in lst:\n if is_prime(number) and number > largest_prime:\n largest_prime = number\n \n if largest_prime == -1:\n return 0 # Return 0 if no prime number is found\n \n return sum_of_digits(largest_prime)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n \"\"\"\n Write a function that takes a message, and encodes in such a \n way that it swaps case of all letters, replaces all vowels in \n the message with the letter that appears 2 places ahead of that \n vowel in the English alphabet. \n Assume only letters. \n \n Examples:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n # Define a mapping for vowels to their replacements\n vowel_replacement = {\n 'a': 'c', 'A': 'C',\n 'e': 'g', 'E': 'G',\n 'i': 'k', 'I': 'K',\n 'o': 'q', 'O': 'Q',\n 'u': 'w', 'U': 'W'\n }\n \n encoded_message = []\n \n for char in message:\n if char.isalpha(): # Check if the character is a letter\n # Swap case\n if char in vowel_replacement:\n # Replace vowel and swap case\n encoded_message.append(vowel_replacement[char])\n else:\n # Just swap case for consonants\n encoded_message.append(char.swapcase())\n else:\n # If it's not a letter, we can choose to ignore it or keep it as is\n encoded_message.append(char)\n \n return ''.join(encoded_message)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["TEST"]], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in lower \n case or all keys are strings in upper case, else return False.\n The function should return False if the given dictionary is empty.\n \n Examples:\n check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n \"\"\"\n \n # Check if the dictionary is empty\n if not input_dict:\n return False\n \n # Initialize flags for lower and upper case\n all_lower = True\n all_upper = True\n \n for key in input_dict.keys():\n # Check if the key is a string\n if not isinstance(key, str):\n return False\n \n # Check if the key is lower case\n if key.islower():\n all_upper = False\n # Check if the key is upper case\n elif key.isupper():\n all_lower = False\n else:\n # If the key is neither lower nor upper case\n return False\n \n # Return True if all keys are either lower case or upper case\n return all_lower or all_upper", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_up_to(n):\n \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n primes = []\n for i in range(2, n):\n if is_prime(i):\n primes.append(i)\n return primes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.\n \"\"\"\n # Get the unit digit of the first number\n unit_digit_a = abs(a) % 10\n # Get the unit digit of the second number\n unit_digit_b = abs(b) % 10\n # Return the product of the unit digits\n return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n\n Note:\n Rounding away from zero means that if the given number is equidistant\n from two integers, the one you should return is the one that is the\n farthest from zero. For example closest_integer(\"14.5\") should\n return 15 and closest_integer(\"-14.5\") should return -15.\n '''\n # Convert the input string to a float\n num = float(value)\n \n # Get the floor and ceiling of the number\n lower_int = int(num // 1) # This is the largest integer less than or equal to num\n upper_int = lower_int + 1 # This is the smallest integer greater than num\n \n # Check the distance to the lower and upper integers\n distance_to_lower = abs(num - lower_int)\n distance_to_upper = abs(num - upper_int)\n \n # Determine which integer to return\n if distance_to_lower < distance_to_upper:\n return lower_int\n elif distance_to_upper < distance_to_lower:\n return upper_int\n else:\n # If equidistant, round away from zero\n if num > 0:\n return upper_int\n else:\n return lower_int", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n count_upper('aBCdEf') returns 1\n count_upper('abcdefg') returns 0\n count_upper('dBBE') returns 0\n \"\"\"\n # Define the set of uppercase vowels\n uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n \n # Initialize a counter for uppercase vowels at even indices\n count = 0\n \n # Iterate over the string, checking only even indices\n for i in range(0, len(s), 2): # Step by 2 to get even indices\n if s[i] in uppercase_vowels:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n \"\"\"\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n \"\"\"\n # Replace commas with spaces and split the string by whitespace\n words = s.replace(',', ' ').split()\n \n # Return the list of words\n return words", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n \"\"\"\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n >>> make_a_pile(4)\n [4, 6, 8, 10]\n >>> make_a_pile(1)\n [1]\n >>> make_a_pile(2)\n [2, 4]\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n\n stones = []\n current_stones = n\n\n for i in range(n):\n stones.append(current_stones)\n if current_stones % 2 == 0: # current_stones is even\n current_stones += 2 # next even number\n else: # current_stones is odd\n current_stones += 2 # next odd number\n\n return stones", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n \"\"\"This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If \n there's no such number, then the function should return -1.\n \n Args:\n x (int): The starting number of the range.\n y (int): The ending number of the range.\n \n Returns:\n int: The biggest even integer in the range [x, y] or -1 if none exists.\n \"\"\"\n \n # Ensure x is less than or equal to y\n if x > y:\n return -1\n \n # Start from the maximum of x and y\n max_num = y\n \n # Check if the maximum number is even\n if max_num % 2 != 0:\n max_num -= 1 # If it's odd, go to the next lower even number\n \n # Check if the maximum even number is within the range\n if max_num >= x:\n return max_num\n \n return -1 # If no even number is found in the range", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n \"\"\"Compute the average of integers from n to m, round it to the nearest integer,\n and convert that to binary. If n is greater than m, return -1.\"\"\"\n \n # Check if n is greater than m\n if n > m:\n return -1\n \n # Calculate the sum of integers from n to m\n total_sum = sum(range(n, m + 1))\n \n # Calculate the number of integers from n to m\n count = m - n + 1\n \n # Calculate the average and round it\n average = total_sum / count\n rounded_average = round(average)\n \n # Convert the rounded average to binary\n binary_average = bin(rounded_average)\n \n return binary_average", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n \"\"\"Given a list of positive integers x, return a sorted list of all \n elements that haven't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n def has_even_digit(n):\n \"\"\"Check if the number has any even digit.\"\"\"\n for digit in str(n):\n if int(digit) % 2 == 0:\n return True\n return False\n\n # Filter the list to include only numbers without even digits\n filtered = [num for num in x if not has_even_digit(num)]\n \n # Sort the resulting list\n return sorted(filtered)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n reverse the resulting array, and then replace each digit by its corresponding name from\n \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n For example:\n arr = [2, 1, 1, 4, 5, 8, 2, 3] \n -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n \n If the array is empty, return an empty array:\n arr = []\n return []\n \n If the array has any strange number ignore it:\n arr = [1, -1 , 55] \n -> sort arr -> [-1, 1, 55]\n -> reverse arr -> [55, 1, -1]\n return = ['One']\n \"\"\"\n \n # Mapping of digits to their corresponding names\n digit_to_name = {\n 1: \"One\",\n 2: \"Two\",\n 3: \"Three\",\n 4: \"Four\",\n 5: \"Five\",\n 6: \"Six\",\n 7: \"Seven\",\n 8: \"Eight\",\n 9: \"Nine\"\n }\n \n # Filter the array to include only integers between 1 and 9\n filtered_arr = [num for num in arr if 1 <= num <= 9]\n \n # Sort the filtered array\n filtered_arr.sort()\n \n # Reverse the sorted array\n filtered_arr.reverse()\n \n # Convert the digits to their corresponding names\n result = [digit_to_name[num] for num in filtered_arr]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def f(n):\n \"\"\" \n Implement the function f that takes n as a parameter,\n and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even\n or the sum of numbers from 1 to i otherwise.\n i starts from 1.\n the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).\n \"\"\"\n result = []\n \n for i in range(1, n + 1):\n if i % 2 == 0: # i is even\n factorial = 1\n for j in range(1, i + 1):\n factorial *= j\n result.append(factorial)\n else: # i is odd\n sum_of_numbers = sum(range(1, i + 1))\n result.append(sum_of_numbers)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n \"\"\"\n Given a positive integer n, return a tuple that has the number of even and odd\n integer palindromes that fall within the range(1, n), inclusive.\n\n Example 1:\n Input: 3\n Output: (1, 2)\n Explanation:\n Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n Example 2:\n Input: 12\n Output: (4, 6)\n Explanation:\n Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n Note:\n 1. 1 <= n <= 10^3\n 2. returned tuple has the number of even and odd integer palindromes respectively.\n \"\"\"\n \n def is_palindrome(num):\n return str(num) == str(num)[::-1]\n\n even_count = 0\n odd_count = 0\n\n for i in range(1, n + 1):\n if is_palindrome(i):\n if i % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n \"\"\"\n Write a function count_nums which takes an array of integers and returns\n the number of elements which has a sum of digits > 0.\n If a number is negative, then its first signed digit will be negative:\n e.g. -123 has signed digits -1, 2, and 3.\n \n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n def sum_of_digits(n):\n # Convert the number to string and iterate over each character\n # Calculate the sum of digits considering the sign of the first digit\n str_n = str(n)\n if str_n[0] == '-':\n # If negative, include the first digit as negative\n return -int(str_n[1]) + sum(int(digit) for digit in str_n[2:])\n else:\n return sum(int(digit) for digit in str_n)\n\n count = 0\n for number in arr:\n if sum_of_digits(number) > 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return True else return False.\n If the given array is empty then return True.\n\n Note: The given list is guaranteed to have unique elements.\n \"\"\"\n \n if not arr: # Check for empty array\n return True\n \n n = len(arr)\n count = 0 # Count the number of times the order is broken\n\n for i in range(n):\n if arr[i] > arr[(i + 1) % n]: # Compare current with next (circular)\n count += 1\n\n # If there are more than one break in the order, it's not possible\n return count <= 1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n \"\"\"Determines whether it is possible to perform an exchange of elements\n between two lists to make lst1 a list of only even numbers.\n \n Args:\n lst1 (list): The first list of numbers.\n lst2 (list): The second list of numbers.\n \n Returns:\n str: \"YES\" if lst1 can be made entirely even, otherwise \"NO\".\n \"\"\"\n # Check if lst1 already contains only even numbers\n if all(x % 2 == 0 for x in lst1):\n return \"YES\"\n \n # Count the number of odd numbers in lst1\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n \n # Check if lst2 has at least one even number to exchange\n has_even_in_lst2 = any(x % 2 == 0 for x in lst2)\n \n # If lst1 has odd numbers and lst2 has at least one even number,\n # we can exchange to make lst1 all even\n if odd_count_lst1 > 0 and has_even_in_lst2:\n return \"YES\"\n \n # If lst1 has odd numbers and lst2 has no even numbers,\n # we cannot make lst1 all even\n return \"NO\"", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 3, 4], [1, 5, 3, 4]]], "plus_fail_tests": []}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n \"\"\"Task\n We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and True/False for the check.\n \"\"\"\n # Create a set of characters to delete for faster lookup\n chars_to_delete = set(c)\n \n # Build the result string by filtering out characters in chars_to_delete\n result = ''.join(char for char in s if char not in chars_to_delete)\n \n # Check if the result string is a palindrome\n is_palindrome = result == result[::-1]\n \n return (result, is_palindrome)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n \"\"\"\n \n if not test: # Handle the empty string case\n return {}\n \n # Split the input string into a list of letters\n letters = test.split()\n \n # Create a dictionary to count occurrences of each letter\n count_dict = {}\n for letter in letters:\n if letter in count_dict:\n count_dict[letter] += 1\n else:\n count_dict[letter] = 1\n \n # Find the maximum count\n max_count = max(count_dict.values())\n \n # Create a result dictionary for letters with the maximum count\n result = {letter: count for letter, count in count_dict.items() if count == max_count}\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n \n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in s if char in '13579')\n \n # Create the output string with the counted odd digits\n output_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n \n # Append the result to the list\n result.append(output_string)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n Example\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n \"\"\"\n if not nums:\n raise ValueError(\"The input array must not be empty.\")\n \n # Initialize variables to track the minimum sum and the current sum\n min_sum = float('inf')\n current_sum = 0\n \n for num in nums:\n current_sum += num\n min_sum = min(min_sum, current_sum)\n \n # If current_sum is greater than 0, reset it to 0\n if current_sum > 0:\n current_sum = 0\n \n return min_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n \"\"\"\n Calculate the number of times buckets need to be lowered to empty the wells.\n\n Parameters:\n grid (list of list of int): A rectangular grid representing wells.\n capacity (int): The capacity of each bucket.\n\n Returns:\n int: The total number of times buckets need to be lowered.\n \"\"\"\n total_water = 0\n \n # Count the total amount of water in the grid\n for row in grid:\n total_water += sum(row)\n \n # Calculate the number of times buckets need to be lowered\n # Each bucket can carry 'capacity' units of water\n if total_water == 0:\n return 0 # No water to extract\n \n # Calculate the number of bucket lowers needed\n lowers_needed = math.ceil(total_water / capacity)\n \n return lowers_needed", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n \"\"\"\n Sorts an array of non-negative integers according to the number of ones in their binary representation\n in ascending order. For numbers with the same number of ones, it sorts based on their decimal value.\n\n Parameters:\n arr (list): A list of non-negative integers.\n\n Returns:\n list: A sorted list of integers based on the specified criteria.\n \"\"\"\n # Filter out negative numbers, as the problem specifies non-negative integers\n non_negative_arr = [x for x in arr if x >= 0]\n \n # Sort the array using a custom key\n sorted_arr = sorted(non_negative_arr, key=lambda x: (bin(x).count('1'), x))\n \n return sorted_arr", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[-2, -3, -4, -5, -6]]], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n \"\"\"Given a string s and a natural number n, returns a list of all words from string s \n that contain exactly n consonants, in the order they appear in the string s.\n \n Args:\n s (str): The input string containing words.\n n (int): The number of consonants to match in each word.\n \n Returns:\n list: A list of words containing exactly n consonants.\n \"\"\"\n \n if not s: # Check if the string is empty\n return []\n \n # Define a set of vowels for easy checking\n vowels = set(\"aeiouAEIOU\")\n \n def count_consonants(word):\n \"\"\"Helper function to count consonants in a word.\"\"\"\n return sum(1 for char in word if char.isalpha() and char not in vowels)\n \n # Split the string into words\n words = s.split()\n \n # Filter words that have exactly n consonants\n result = [word for word in words if count_consonants(word) == n]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n two consonants from the right side of the word (case sensitive).\n \n Vowels in the beginning and ending don't count. Return empty string if you didn't\n find any vowel that meets the above condition. \n\n You may assume that the given string contains English letters only.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n n = len(word)\n\n # Check if the word is too short to have consonants with a vowel in between\n if n < 3:\n return \"\"\n\n # Start from the end of the word and look for consonants and vowels\n for i in range(n - 2, 0, -1): # Start from the second last character\n if word[i] in vowels: # Found a vowel\n # Check if there are consonants on both sides\n if word[i - 1].isalpha() and word[i + 1].isalpha():\n if word[i - 1] not in vowels and word[i + 1] not in vowels:\n return word[i] # Return the closest vowel found\n\n return \"\" # Return empty string if no valid vowel is found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n \n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0: # More closing than opening\n return False\n return balance == 0 # Must be balanced at the end\n\n s1, s2 = lst[0], lst[1]\n \n # Check both concatenation orders\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n \n # Sort the array in descending order and take the first k elements\n max_k_elements = sorted(arr, reverse=True)[:k]\n \n # Sort the result in ascending order before returning\n return sorted(max_k_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index in range(len(lst)):\n # Check if the index is even and the element is odd\n if index % 2 == 0 and lst[index] % 2 != 0:\n total_sum += lst[index]\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n \"\"\"\n Given a non-empty array of integers arr and an integer k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example:\n\n Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n Output: 24 # sum of 21 + 3\n\n Constraints:\n 1. 1 <= len(arr) <= 100\n 2. 1 <= k <= len(arr)\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate through the first k elements of the array\n for i in range(k):\n # Check if the current element has at most two digits\n if -100 < arr[i] < 100:\n total_sum += arr[i]\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n as follows: start with any positive integer n. Then each term is obtained from the \n previous term as follows: if the previous term is even, the next term is one half of \n the previous term. If the previous term is odd, the next term is 3 times the previous\n term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n Note: \n 1. Collatz(1) is [1].\n 2. returned list sorted in increasing order.\n\n For example:\n get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n collatz_sequence = []\n \n while n != 1:\n collatz_sequence.append(n)\n if n % 2 == 0:\n n //= 2\n else:\n n = 3 * n + 1\n \n collatz_sequence.append(1) # Include the last term which is 1\n \n # Filter out the odd numbers and sort them\n odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n \n return odd_numbers", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n \n The date is valid if all of the following rules are satisfied:\n 1. The date string is not empty.\n 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n The number of days is not less than 1 or higher than 29 for the month 2.\n 3. The months should not be less than 1 or higher than 12.\n 4. The date should be in the format: mm-dd-yyyy\n \"\"\"\n \n # Check if the date string is empty\n if not date:\n return False\n \n # Check if the date format is correct\n if len(date) != 10 or date[2] != '-' or date[5] != '-':\n return False\n \n # Split the date into components\n try:\n month, day, year = map(int, date.split('-'))\n except ValueError:\n return False\n \n # Check month range\n if month < 1 or month > 12:\n return False\n \n # Check day range based on month\n if month in {1, 3, 5, 7, 8, 10, 12}:\n if day < 1 or day > 31:\n return False\n elif month in {4, 6, 9, 11}:\n if day < 1 or day > 30:\n return False\n elif month == 2:\n if day < 1 or day > 29:\n return False\n \n # If all checks are passed, the date is valid\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n '''\n Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n Examples\n split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"abcdef\") == 3 \n '''\n \n # Check for whitespace in the text\n if ' ' in txt:\n return txt.split()\n \n # Check for commas in the text\n elif ',' in txt:\n return txt.split(',')\n \n # If no whitespace or commas, count lowercase letters with odd order\n else:\n odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n return odd_count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n '''\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return False. Assume no negative numbers and only integers.\n\n Examples\n is_sorted([5]) \u279e True\n is_sorted([1, 2, 3, 4, 5]) \u279e True\n is_sorted([1, 3, 2, 4, 5]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n '''\n \n if len(lst) <= 1:\n return True\n \n seen = set()\n previous = None\n \n for num in lst:\n if num in seen:\n # If we see a number again, check if it's a duplicate\n if num == previous:\n return False\n else:\n seen.add(num)\n else:\n seen.add(num)\n \n if previous is not None and num < previous:\n return False\n \n previous = num\n \n return True", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef intersection(interval1, interval2):\n \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n start1, end1 = interval1\n start2, end2 = interval2\n \n # Find the intersection\n start_intersection = max(start1, start2)\n end_intersection = min(end1, end2)\n \n # Check if there is an intersection\n if start_intersection > end_intersection:\n return \"NO\"\n \n # Calculate the length of the intersection\n length_of_intersection = end_intersection - start_intersection\n \n # Check if the length is a prime number\n if is_prime(length_of_intersection):\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n if not arr: # Check for empty array\n return None\n\n product_of_signs = 1\n sum_of_magnitudes = 0\n\n for num in arr:\n if num > 0:\n sum_of_magnitudes += num\n elif num < 0:\n sum_of_magnitudes += -num\n product_of_signs *= -1\n else: # num == 0\n return 0 # If there's a zero, the product of signs is zero\n\n return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n \"\"\"Calculate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n \n # Initialize the list to hold the Tribonacci numbers\n tribonacci_sequence = []\n \n # Define the base case for tri(1)\n if n >= 1:\n tribonacci_sequence.append(3) # tri(1) = 3\n \n # Calculate the values for tri(2) to tri(n)\n for i in range(1, n + 1):\n if i % 2 == 0: # If i is even\n tribonacci_sequence.append(1 + i / 2)\n else: # If i is odd\n # Calculate tri(i) based on the recurrence relation\n if i - 1 < len(tribonacci_sequence):\n tri_i_minus_1 = tribonacci_sequence[i - 1]\n else:\n tri_i_minus_1 = tri(i - 1)\n \n if i - 2 < len(tribonacci_sequence):\n tri_i_minus_2 = tribonacci_sequence[i - 2]\n else:\n tri_i_minus_2 = tri(i - 2)\n \n if i + 1 < len(tribonacci_sequence):\n tri_i_plus_1 = tribonacci_sequence[i + 1]\n else:\n tri_i_plus_1 = tri(i + 1)\n \n tribonacci_sequence.append(tri_i_minus_1 + tri_i_minus_2 + tri_i_plus_1)\n \n return tribonacci_sequence", "base_status": "fail", "plus_status": null, "base_fail_tests": [[3]], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n \"\"\"Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n For example:\n digits(1) == 1\n digits(4) == 0\n digits(235) == 15\n \"\"\"\n # Initialize the product to 1 and a flag to check if any odd digit is found\n product = 1\n found_odd = False\n \n # Convert the number to a string to iterate over each digit\n for digit in str(n):\n digit = int(digit) # Convert the character back to an integer\n if digit % 2 != 0: # Check if the digit is odd\n product *= digit # Multiply the product by the odd digit\n found_odd = True # Set the flag to True since we found an odd digit\n \n # If no odd digit was found, return 0\n if not found_odd:\n return 0\n \n return product", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n '''\n Create a function that takes a string as input which contains only square brackets.\n The function should return True if and only if there is a valid subsequence of brackets \n where at least one bracket in the subsequence is nested.\n\n is_nested('[[]]') \u279e True\n is_nested('[]]]]]]][[[[[]') \u279e False\n is_nested('[][]') \u279e False\n is_nested('[]') \u279e False\n is_nested('[[][]]') \u279e True\n is_nested('[[]][[') \u279e True\n '''\n \n # Initialize a counter for open brackets\n open_count = 0\n # Initialize a flag to check for nesting\n nested = False\n \n for char in string:\n if char == '[':\n open_count += 1\n # If we have more than one open bracket, we have a nested structure\n if open_count > 1:\n nested = True\n elif char == ']':\n open_count -= 1\n # If we close a bracket and there were open brackets before, we check for nesting\n if open_count < 0:\n return False # More closing brackets than opening\n # If we have closed all opened brackets, we can stop checking\n if open_count < 0:\n return False\n \n # We need at least one nested structure and all brackets must be closed\n return nested and open_count == 0", "base_status": "fail", "plus_status": null, "base_fail_tests": [["[[]][["]], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers.\n You need to return the sum of squared numbers in the given list,\n round each element in the list to the upper int (Ceiling) first.\n \n Examples:\n For lst = [1,2,3] the output should be 14\n For lst = [1,4,9] the output should be 98\n For lst = [1,3,5,7] the output should be 84\n For lst = [1.4,4.2,0] the output should be 29\n For lst = [-2.4,1,1] the output should be 6\n \"\"\"\n # Round each number in the list to the upper integer (ceiling)\n rounded_numbers = [math.ceil(num) for num in lst]\n \n # Calculate the sum of squares of the rounded numbers\n sum_of_squares = sum(num ** 2 for num in rounded_numbers)\n \n return sum_of_squares", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n '''\n Create a function that returns True if the last character\n of a given string is an alphabetical character and is not\n a part of a word, and False otherwise.\n Note: \"word\" is a group of characters separated by space.\n\n Examples:\n check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '''\n \n # Strip any trailing whitespace from the string\n txt = txt.rstrip()\n \n # Check if the string is empty after stripping\n if not txt:\n return False\n \n # Get the last character of the string\n last_char = txt[-1]\n \n # Check if the last character is an alphabetical character\n if last_char.isalpha():\n # Check if the last character is part of a word\n # A character is part of a word if it is preceded by a non-space character\n if len(txt) > 1 and txt[-2] != ' ':\n return False\n return True\n \n return False", "base_status": "fail", "plus_status": null, "base_fail_tests": [["eeeee e "]], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n \"\"\"Create a function which returns the largest index of an element which\n is not greater than or equal to the element immediately preceding it. If\n no such element exists then return -1. The given array will not contain\n duplicate values.\n\n Examples:\n can_arrange([1,2,4,3,5]) = 3\n can_arrange([1,2,3]) = -1\n \"\"\"\n # Check if the array is empty\n if not arr:\n return -1\n \n # Initialize the largest index to -1\n largest_index = -1\n \n # Iterate through the array starting from the second element\n for i in range(1, len(arr)):\n # Check if the current element is less than the previous element\n if arr[i] < arr[i - 1]:\n largest_index = i\n \n return largest_index", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n from collections import deque\n\n N = len(grid)\n directions = [(0, 1), (1, 0), (0, -1), (-1, 0)] # right, down, left, up\n min_path = None\n\n def bfs(start_row, start_col):\n queue = deque([(start_row, start_col, [grid[start_row][start_col]])])\n while queue:\n row, col, path = queue.popleft()\n if len(path) == k:\n nonlocal min_path\n if min_path is None or path < min_path:\n min_path = path\n continue\n \n for dr, dc in directions:\n new_row, new_col = row + dr, col + dc\n if 0 <= new_row < N and 0 <= new_col < N:\n queue.append((new_row, new_col, path + [grid[new_row][new_col]]))\n\n for i in range(N):\n for j in range(N):\n bfs(i, j)\n\n return min_path", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n '''\n Create a function that returns a tuple (a, b), where 'a' is\n the largest of negative integers, and 'b' is the smallest\n of positive integers in a list.\n If there is no negative or positive integers, return them as None.\n\n Examples:\n largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n largest_smallest_integers([]) == (None, None)\n largest_smallest_integers([0]) == (None, None)\n '''\n \n largest_negative = None\n smallest_positive = None\n \n for num in lst:\n if num < 0:\n if largest_negative is None or num > largest_negative:\n largest_negative = num\n elif num > 0:\n if smallest_positive is None or num < smallest_positive:\n smallest_positive = num\n \n return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n \n Args:\n n (int): The number to evaluate.\n \n Returns:\n bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n \n Example:\n is_equal_to_sum_even(4) == False\n is_equal_to_sum_even(6) == False\n is_equal_to_sum_even(8) == True\n \"\"\"\n \n # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n if n < 8:\n return False\n \n # If n is even and at least 8, it can be expressed as the sum of 4 positive even numbers\n return n % 2 == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def parse_number(value):\n \"\"\"\n Parse a string representation of a number, handling both '.' and ',' as decimal points.\n Returns a float if the parsing is successful, otherwise returns None.\n \"\"\"\n if isinstance(value, (int, float)):\n return float(value)\n \n if isinstance(value, str):\n # Replace ',' with '.' for float conversion\n value = value.replace(',', '.')\n try:\n return float(value)\n except ValueError:\n return None\n \n return None\ndef compare_one(a, b):\n \"\"\"\n Compare two values (integers, floats, or strings representing real numbers)\n and return the larger one in its original type. Return None if they are equal.\n \"\"\"\n # Parse both values\n parsed_a = parse_number(a)\n parsed_b = parse_number(b)\n \n # If both parsed values are None, return None\n if parsed_a is None and parsed_b is None:\n return None\n \n # If one of the parsed values is None, return the other\n if parsed_a is None:\n return b\n if parsed_b is None:\n return a\n \n # Compare the parsed values\n if parsed_a > parsed_b:\n return a\n elif parsed_b > parsed_a:\n return b\n else:\n return None", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n \"\"\"Helper function to compute the factorial of a non-negative integer n.\"\"\"\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef special_factorial(n):\n \"\"\"Calculate the Brazilian factorial of n.\"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer greater than 0.\")\n \n result = 1\n for i in range(1, n + 1):\n result *= factorial(i)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n \"\"\"\n Given a string text, replace all spaces in it with underscores, \n and if a string has more than 2 consecutive spaces, \n then replace all consecutive spaces with - \n \n fix_spaces(\"Example\") == \"Example\"\n fix_spaces(\"Example 1\") == \"Example_1\"\n fix_spaces(\" Example 2\") == \"_Example_2\"\n fix_spaces(\" Example 3\") == \"_Example-3\"\n \"\"\"\n # Replace multiple spaces with a placeholder\n text = text.replace(' ', '-').replace(' ', '-')\n \n # Replace remaining spaces with underscores\n text = text.replace(' ', '_')\n \n # Handle the case where we might have replaced too many spaces\n # We need to ensure that we only replace sequences of spaces\n # that are more than 2 with a single '-'\n parts = []\n i = 0\n while i < len(text):\n if text[i] == '_':\n # Count consecutive underscores\n count = 0\n while i < len(text) and text[i] == '_':\n count += 1\n i += 1\n if count > 2:\n parts.append('-')\n else:\n parts.append('_' * count)\n else:\n parts.append(text[i])\n i += 1\n \n # Join the parts back together\n result = ''.join(parts)\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Yellow Yellow Dirty Fellow"]], "plus_fail_tests": []}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n \"\"\"\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n \n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126\n \"\"\"\n total_sum = 0\n \n for index, value in enumerate(lst):\n if index % 3 == 0:\n # Square the value if index is a multiple of 3\n total_sum += value ** 2\n elif index % 4 == 0:\n # Cube the value if index is a multiple of 4 and not a multiple of 3\n total_sum += value ** 3\n else:\n # Add the value unchanged if index is not a multiple of 3 or 4\n total_sum += value\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n \"\"\"Check if the given file name is valid based on specific criteria.\"\"\"\n \n # Check for exactly one dot\n if file_name.count('.') != 1:\n return 'No'\n \n # Split the file name into name and extension\n name, extension = file_name.split('.')\n \n # Check if the name is not empty and starts with a letter\n if not name or not name[0].isalpha():\n return 'No'\n \n # Check the number of digits in the name\n digit_count = sum(c.isdigit() for c in name)\n if digit_count > 3:\n return 'No'\n \n # Check if the extension is valid\n valid_extensions = ['txt', 'exe', 'dll']\n if extension not in valid_extensions:\n return 'No'\n \n return 'Yes'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef words_in_sentence(sentence):\n \"\"\"\n Given a string representing a sentence, return a string that contains the words\n from the original sentence whose lengths are prime numbers.\n The order of the words in the new string should be the same as the original one.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Filter words whose lengths are prime\n prime_length_words = [word for word in words if is_prime(len(word))]\n \n # Join the filtered words into a single string\n return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n \"\"\"Simplifies the expression x * n and checks if the result is a whole number.\n \n Args:\n x (str): A string representation of a fraction in the format /.\n n (str): A string representation of a fraction in the format /.\n \n Returns:\n bool: True if x * n evaluates to a whole number, False otherwise.\n \"\"\"\n # Split the fractions into numerator and denominator\n x_numerator, x_denominator = map(int, x.split('/'))\n n_numerator, n_denominator = map(int, n.split('/'))\n \n # Calculate the product of the fractions\n # x * n = (x_numerator / x_denominator) * (n_numerator / n_denominator)\n # This simplifies to (x_numerator * n_numerator) / (x_denominator * n_denominator)\n \n product_numerator = x_numerator * n_numerator\n product_denominator = x_denominator * n_denominator\n \n # Check if the product is a whole number\n return product_numerator % product_denominator == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n \"\"\"\n Write a function which sorts the given list of integers\n in ascending order according to the sum of their digits.\n Note: if there are several items with similar sum of their digits,\n order them based on their index in original list.\n\n For example:\n >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n >>> order_by_points([]) == []\n \"\"\"\n \n def digit_sum(n):\n \"\"\"Calculate the sum of the digits of an integer n.\"\"\"\n return sum(int(digit) for digit in str(abs(n)))\n\n # Create a list of tuples (digit_sum, index, value)\n indexed_nums = [(digit_sum(num), index, num) for index, num in enumerate(nums)]\n \n # Sort by digit sum first, then by original index\n indexed_nums.sort(key=lambda x: (x[0], x[1]))\n \n # Extract the sorted values\n sorted_nums = [num for _, _, num in indexed_nums]\n \n return sorted_nums", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n \"\"\"Returns the number of elements in the array that are greater than 10 \n and both the first and last digits of the number are odd (1, 3, 5, 7, 9).\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n int: The count of numbers meeting the criteria.\n \"\"\"\n \n def is_odd_digit(digit):\n \"\"\"Check if a digit is odd.\"\"\"\n return digit in {'1', '3', '5', '7', '9'}\n \n def first_and_last_digits_are_odd(num):\n \"\"\"Check if the first and last digits of the number are odd.\"\"\"\n num_str = str(abs(num)) # Convert to string and handle negative numbers\n return is_odd_digit(num_str[0]) and is_odd_digit(num_str[-1])\n \n count = 0\n for num in nums:\n if num > 10 and first_and_last_digits_are_odd(num):\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closest to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sorted by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct planet names. \n Examples\n bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n '''\n\n # List of planets in order from the Sun\n planets = [\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n ]\n \n # Check if the input planets are valid\n if planet1 not in planets or planet2 not in planets:\n return ()\n \n # Get the indices of the planets\n index1 = planets.index(planet1)\n index2 = planets.index(planet2)\n \n # Determine the range of indices\n start_index = min(index1, index2) + 1\n end_index = max(index1, index2)\n \n # Get the planets in between\n in_between_planets = planets[start_index:end_index]\n \n # Return the result as a tuple\n return tuple(in_between_planets)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n \"\"\"\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example :\n Input: n = 5\n Output: 1\n Explanation: \n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n \"\"\"\n # Create the array a based on the given formula\n a = [i * i - i + 1 for i in range(1, n + 1)]\n \n # Count the number of valid triples\n count = 0\n \n # Iterate through all possible triples (i, j, k)\n for i in range(n):\n for j in range(i + 1, n):\n for k in range(j + 1, n):\n if (a[i] + a[j] + a[k]) % 3 == 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef x_or_y(n, x, y):\n \"\"\"Return the value of x if n is a prime number, otherwise return y.\"\"\"\n if is_prime(n):\n return x\n else:\n return y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length and alphabetically.\n \n Args:\n lst (list of str): A list of strings.\n \n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the filtered list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n \"\"\"\n Compares the actual scores of matches with the guessed scores.\n \n Parameters:\n game (list of int): The actual scores of the matches.\n guess (list of int): The guessed scores of the matches.\n \n Returns:\n list of int: An array where each element is the absolute difference \n between the actual score and the guessed score, or 0 if \n the guess was correct.\n \"\"\"\n # Check if the lengths of game and guess are equal\n if len(game) != len(guess):\n raise ValueError(\"The length of game and guess must be the same.\")\n \n # Calculate the absolute differences\n result = [abs(g - a) for a, g in zip(game, guess)]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n \n double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n double_the_difference([-1, -2, 0]) == 0\n double_the_difference([9, -2]) == 81\n double_the_difference([0]) == 0 \n \n If the input list is empty, return 0.\n '''\n # Initialize the sum of squares\n sum_of_squares = 0\n \n # Iterate through each number in the list\n for num in lst:\n # Check if the number is a positive odd integer\n if isinstance(num, int) and num >= 0 and num % 2 != 0:\n # Add the square of the odd number to the sum\n sum_of_squares += num ** 2\n \n return sum_of_squares", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n \"\"\"Find the strongest extension based on the defined strength criteria.\"\"\"\n \n def calculate_strength(extension):\n \"\"\"Calculate the strength of the extension.\"\"\"\n CAP = sum(1 for char in extension if char.isupper())\n SM = sum(1 for char in extension if char.islower())\n return CAP - SM\n \n strongest_extension = None\n strongest_strength = float('-inf') # Start with the lowest possible strength\n \n for extension in extensions:\n strength = calculate_strength(extension)\n \n # Check if this extension is stronger or if it's the first one\n if strength > strongest_strength:\n strongest_strength = strength\n strongest_extension = extension\n \n # Return the result in the required format\n return f\"{class_name}.{strongest_extension}\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n \"\"\"Check if the second word or any of its rotations is a substring in the first word.\"\"\"\n \n # Edge case: if b is empty, it is considered a substring of any string\n if not b:\n return True\n \n # Edge case: if b is longer than a, it cannot be a substring\n if len(b) > len(a):\n return False\n \n # Create a string that contains two copies of b concatenated\n # This allows us to check for all rotations of b\n b_rotations = b + b\n \n # Check if any rotation of b is a substring of a\n return any(rotation in a for rotation in (b_rotations[i:i+len(b)] for i in range(len(b))))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n Example:\n even_odd_count(-12) ==> (1, 1)\n even_odd_count(123) ==> (1, 2)\n \"\"\"\n # Convert the number to its absolute value to ignore the sign\n num = abs(num)\n \n # Initialize counters for even and odd digits\n even_count = 0\n odd_count = 0\n \n # Convert the number to a string to iterate over each digit\n for digit in str(num):\n # Convert the character back to an integer\n digit = int(digit)\n \n # Check if the digit is even or odd and increment the respective counter\n if digit % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n \n if not (1 <= number <= 1000):\n raise ValueError(\"Number must be between 1 and 1000 inclusive.\")\n \n # Mapping of integers to their corresponding Roman numeral representations\n roman_numerals = [\n (1000, 'm'),\n (900, 'cm'),\n (500, 'd'),\n (400, 'cd'),\n (100, 'c'),\n (90, 'xc'),\n (50, 'l'),\n (40, 'xl'),\n (10, 'x'),\n (9, 'ix'),\n (5, 'v'),\n (4, 'iv'),\n (1, 'i')\n ]\n \n result = []\n \n for value, numeral in roman_numerals:\n while number >= value:\n result.append(numeral)\n number -= value\n \n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return True if the three\n sides form a right-angled triangle, False otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or \n 90 degree.\n \n Example:\n right_angle_triangle(3, 4, 5) == True\n right_angle_triangle(1, 2, 3) == False\n '''\n # First, we need to check if the sides can form a triangle\n if a <= 0 or b <= 0 or c <= 0:\n return False # Sides must be positive\n \n # Sort the sides to easily identify the longest side\n sides = sorted([a, b, c])\n \n # Check the Pythagorean theorem: a^2 + b^2 = c^2\n return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n \"\"\"Return the word with the maximum number of unique characters.\n If multiple words have the same number of unique characters,\n return the one that comes first in lexicographical order.\n \n Args:\n words (list of str): A list of words to evaluate.\n \n Returns:\n str: The word with the maximum number of unique characters.\n \"\"\"\n max_word = \"\"\n max_unique_count = 0\n\n for word in words:\n # Calculate the number of unique characters in the word\n unique_count = len(set(word))\n \n # Check if this word has more unique characters or is lexicographically smaller\n if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n max_word = word\n max_unique_count = unique_count\n\n return max_word", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n \"\"\"\n You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n \n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n \n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots that exist in stock\n \n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n \"\"\"\n \n # Calculate how many more carrots are needed\n additional_needed = need - number\n \n # If no additional carrots are needed, return the current state\n if additional_needed <= 0:\n return [number, remaining]\n \n # Determine how many carrots can be eaten from the remaining stock\n if remaining >= additional_needed:\n total_eaten = number + additional_needed\n carrots_left = remaining - additional_needed\n else:\n total_eaten = number + remaining\n carrots_left = 0 # All remaining carrots are eaten\n \n return [total_eaten, carrots_left]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic algebra operations, and \n the second list is a list of integers. Use the two given lists to build the algebraic \n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + ) \n Subtraction ( - ) \n Multiplication ( * ) \n Floor division ( // ) \n Exponentiation ( ** ) \n\n Example:\n operator = ['+', '*', '-']\n operand = [2, 3, 4, 5]\n result = 2 + 3 * 4 - 5\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.\n \"\"\"\n \n # Start with the first operand\n result = operand[0]\n \n # Iterate through the operators and operands\n for i in range(len(operator)):\n op = operator[i]\n next_operand = operand[i + 1]\n \n if op == '+':\n result += next_operand\n elif op == '-':\n result -= next_operand\n elif op == '*':\n result *= next_operand\n elif op == '//':\n # Handle division by zero\n if next_operand == 0:\n raise ValueError(\"Cannot perform floor division by zero.\")\n result //= next_operand\n elif op == '**':\n result **= next_operand\n else:\n raise ValueError(f\"Invalid operator: {op}\")\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": []}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n \"\"\"You are given a string s.\n if s[i] is a letter, reverse its case from lower to upper or vice versa, \n otherwise keep it as it is.\n If the string contains no letters, reverse the string.\n The function should return the resulted string.\n Examples\n solve(\"1234\") = \"4321\"\n solve(\"ab\") = \"AB\"\n solve(\"#a@C\") = \"#A@c\"\n \"\"\"\n # Check if there are any letters in the string\n has_letters = any(c.isalpha() for c in s)\n \n if has_letters:\n # If there are letters, reverse the case of each character\n result = ''.join(c.swapcase() for c in s)\n else:\n # If there are no letters, reverse the string\n result = s[::-1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string.\n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n \"\"\"\n if text == \"\":\n return None\n # Create an MD5 hash object\n md5_hash = hashlib.md5()\n # Update the hash object with the bytes of the string\n md5_hash.update(text.encode('utf-8'))\n # Return the hexadecimal digest of the hash\n return md5_hash.hexdigest()", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascending order.\n\n For example:\n generate_integers(2, 8) => [2, 4, 6, 8]\n generate_integers(8, 2) => [2, 4, 6, 8]\n generate_integers(10, 14) => []\n \"\"\"\n # Ensure a is less than or equal to b for easier processing\n start = min(a, b)\n end = max(a, b)\n\n # Generate a list of even integers in the range\n even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n return even_integers", "base_status": "fail", "plus_status": null, "base_fail_tests": [[2, 10]], "plus_fail_tests": []}]}} \ No newline at end of file diff --git a/llm_based_136_eval_results.json b/llm_based_136_eval_results.json new file mode 100644 index 000000000..52671f2d7 --- /dev/null +++ b/llm_based_136_eval_results.json @@ -0,0 +1 @@ +{"date": "2024-07-27 00:44", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" \n Input to this function is a string containing multiple groups of nested parentheses. \n The goal is to separate those groups into separate strings and return the list of those.\n Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n Ignore any spaces in the input string.\n \n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n # Remove spaces from the input string\n paren_string = paren_string.replace(\" \", \"\")\n \n result = []\n current_group = []\n balance = 0\n \n for char in paren_string:\n if char == '(':\n balance += 1\n current_group.append(char)\n elif char == ')':\n balance -= 1\n current_group.append(char)\n \n # When balance is zero, we have a complete group\n if balance == 0 and current_group:\n result.append(''.join(current_group))\n current_group = [] # Reset for the next group\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to make it easier to find close elements\n numbers.sort()\n \n # Check the differences between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" \n You're given a list of deposit and withdrawal operations on a bank account that starts with\n zero balance. Your task is to detect if at any point the balance of account falls below zero, and\n at that point function should return True. Otherwise it should return False.\n \n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n \"\"\"\n balance = 0 # Start with a zero balance\n for operation in operations:\n balance += operation # Update the balance with the current operation\n if balance < 0: # Check if the balance falls below zero\n return True # Return True if it does\n return False # Return False if the balance never falls below zero", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into\n an integer part (largest integer smaller than given number) and decimals\n (leftover part always smaller than 1).\n\n Return the decimal part of the number.\n >>> truncate_number(3.5)\n 0.5\n \"\"\"\n if number < 0:\n raise ValueError(\"The number must be positive.\")\n \n # Get the integer part by using the floor function\n integer_part = int(number) # This truncates towards zero for positive numbers\n \n # Calculate the decimal part\n decimal_part = number - integer_part\n \n return decimal_part", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n \"\"\" Insert a number 'delimiter' between every two consecutive elements of input list `numbers'\n \n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n \"\"\"\n if not numbers: # Check if the input list is empty\n return []\n \n result = [] # Initialize an empty list to store the result\n for i in range(len(numbers)):\n result.append(numbers[i]) # Add the current number to the result\n if i < len(numbers) - 1: # Check if it's not the last element\n result.append(delimiter) # Add the delimiter after the current number\n \n return result # Return the final result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list to avoid division by zero\n\n # Calculate the mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute deviations from the mean\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n \n # Calculate the mean of the absolute deviations\n mad = sum(absolute_deviations) / len(absolute_deviations)\n \n return mad", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring.\n \n Args:\n strings (List[str]): A list of strings to filter.\n substring (str): The substring to search for within the strings.\n \n Returns:\n List[str]: A list of strings that contain the given substring.\n \n Examples:\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n \"\"\"\n # Use a list comprehension to filter the strings\n return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string represented multiple groups for nested parentheses \n separated by spaces. For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n def max_nesting_depth(s: str) -> int:\n \"\"\" Helper function to calculate the maximum nesting depth of a single parenthesis string. \"\"\"\n max_depth = 0\n current_depth = 0\n \n for char in s:\n if char == '(':\n current_depth += 1\n max_depth = max(max_depth, current_depth)\n elif char == ')':\n current_depth -= 1\n # If current_depth goes negative, it means there are unmatched closing parentheses\n if current_depth < 0:\n raise ValueError(\"Unmatched closing parentheses in the input string.\")\n \n # If current_depth is not zero, it means there are unmatched opening parentheses\n if current_depth != 0:\n raise ValueError(\"Unmatched opening parentheses in the input string.\")\n \n return max_depth\n\n # Split the input string by spaces to get individual groups of parentheses\n groups = paren_string.split()\n depths = []\n\n for group in groups:\n depths.append(max_nesting_depth(group))\n\n return depths", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers: # Handle the case of an empty list\n return []\n \n max_so_far = numbers[0] # Initialize the maximum with the first element\n result = [max_so_far] # Start the result list with the first element's max\n \n for number in numbers[1:]: # Iterate through the rest of the numbers\n if number > max_so_far:\n max_so_far = number # Update max_so_far if the current number is greater\n result.append(max_so_far) # Append the current max to the result list\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n \n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n \"\"\"\n if not numbers: # Check if the list is empty\n return (0, 1)\n \n total_sum = 0\n total_product = 1\n \n for number in numbers:\n total_sum += number\n total_product *= number\n \n return (total_sum, total_product)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n \"\"\"\n # Edge case for empty string\n if not string:\n return ''\n \n # Find the longest palindromic suffix\n for i in range(len(string)):\n if is_palindrome(string[i:]):\n # If we find a palindromic suffix, we take the prefix before it\n prefix = string[:i]\n # Append the reverse of the prefix to the original string\n return string + prefix[::-1]\n \n # If no palindromic suffix is found, the whole string is non-palindromic\n # In this case, we will append the entire string reversed\n return string + string[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n \"\"\" \n Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n \n >>> string_xor('010', '110')\n '100'\n \"\"\"\n # Ensure both strings are of the same length by padding with leading zeros\n max_length = max(len(a), len(b))\n a = a.zfill(max_length)\n b = b.zfill(max_length)\n \n # Perform XOR operation\n result = []\n for bit_a, bit_b in zip(a, b):\n # XOR operation: 1 if bits are different, 0 if they are the same\n result_bit = '1' if bit_a != bit_b else '0'\n result.append(result_bit)\n \n # Join the result list into a string and return\n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n \n >>> longest([])\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n \"\"\"\n if not strings:\n return None\n \n longest_string = strings[0]\n \n for string in strings:\n if len(string) > len(longest_string):\n longest_string = string\n \n return longest_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return a greatest common divisor of two integers a and b.\n \n The function uses the Euclidean algorithm to find the GCD.\n \n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n \"\"\"\n # Handle negative inputs by taking the absolute value\n a, b = abs(a), abs(b)\n \n # Base case: if one of the numbers is zero, return the other number\n if a == 0:\n return b\n if b == 0:\n return a\n \n # Implementing the Euclidean algorithm\n while b != 0:\n a, b = b, a % b\n \n return a", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string.\n \n Args:\n string (str): The input string from which to generate prefixes.\n \n Returns:\n List[str]: A list of all prefixes of the input string.\n \n Examples:\n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n \"\"\"\n # Initialize an empty list to store prefixes\n prefixes = []\n \n # Iterate over the range of the length of the string\n for i in range(1, len(string) + 1):\n # Append the substring from the start to the current index\n prefixes.append(string[:i])\n \n return prefixes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set()\n \n # Iterate through each character in the string\n for char in lower_string:\n # Add the character to the set\n distinct_characters.add(char)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n \n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n \"\"\"\n # Check if n is less than 0, return an empty string as there are no numbers to include\n if n < 0:\n return ''\n \n # Create a list of numbers from 0 to n\n numbers = [str(i) for i in range(n + 1)]\n \n # Join the list into a single string with space as a delimiter\n return ' '.join(numbers)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string representing musical notes in a special ASCII format.\n Your task is to parse this string and return list of integers corresponding to how many beats does each\n note last.\n\n Here is a legend:\n 'o' - whole note, lasts four beats\n 'o|' - half note, lasts two beats\n '.|' - quarter note, lasts one beat\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n # Define a mapping of note representations to their corresponding beat values\n note_to_beats = {\n 'o': 4, # whole note\n 'o|': 2, # half note\n '.|': 1 # quarter note\n }\n \n # Split the input string into individual notes\n notes = music_string.split()\n \n # Initialize a list to hold the beats for each note\n beats = []\n \n # Iterate over each note and convert it to its corresponding beat value\n for note in notes:\n if note in note_to_beats:\n beats.append(note_to_beats[note])\n else:\n # If an unknown note is encountered, we can choose to ignore it or raise an error\n # Here we will ignore it for robustness\n continue\n \n return beats", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n \n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n \"\"\"\n if not substring: # If the substring is empty, return 0\n return 0\n \n count = 0\n start = 0\n \n while True:\n start = string.find(substring, start) # Find the substring starting from 'start'\n if start == -1: # If no more occurrences are found, break the loop\n break\n count += 1 # Increment the count for each found occurrence\n start += 1 # Move to the next character to allow for overlapping matches\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n \"\"\" \n Input is a space-delimited string of numerals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest.\n \n >>> sort_numbers('three one five')\n 'one three five'\n \"\"\"\n \n # Mapping of words to their corresponding numeric values\n word_to_number = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n \n # Split the input string into words\n words = numbers.split()\n \n # Convert words to their corresponding numeric values\n numeric_values = [word_to_number[word] for word in words]\n \n # Sort the numeric values\n sorted_values = sorted(numeric_values)\n \n # Convert sorted numeric values back to words\n number_to_word = {v: k for k, v in word_to_number.items()}\n sorted_words = [number_to_word[value] for value in sorted_values]\n \n # Join the sorted words into a single string\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to make it easier to find the closest pairs\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest elements\n for i in range(len(sorted_numbers) - 1):\n # Calculate the difference between consecutive elements\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n \n # If this difference is smaller than the minimum found so far, update\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1.\n \n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The input list must contain at least two elements.\")\n \n min_value = min(numbers)\n max_value = max(numbers)\n \n if min_value == max_value:\n # If all numbers are the same, return a list of zeros\n return [0.0] * len(numbers)\n \n # Rescale the numbers\n rescaled = [(num - min_value) / (max_value - min_value) for num in numbers]\n \n return rescaled", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers \"\"\"\n return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n \"\"\" Return length of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n \"\"\"\n # Initialize a counter to zero\n length = 0\n \n # Iterate through each character in the string\n for char in string:\n length += 1 # Increment the counter for each character\n \n return length", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n \n >>> largest_divisor(15)\n 5\n \"\"\"\n # Edge case: if n is less than or equal to 1, there are no divisors smaller than n\n if n <= 1:\n return None # or raise an exception, depending on how you want to handle this case\n\n # Start checking from n-1 down to 1\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a dictionary to count occurrences of each number\n count = {}\n \n # Count each number's occurrences\n for number in numbers:\n if number in count:\n count[number] += 1\n else:\n count[number] = 1\n \n # Create a list for the result, keeping the order of elements\n result = []\n \n # Add numbers that occur only once to the result list\n for number in numbers:\n if count[number] == 1:\n result.append(number)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n Input number should be equal to the product of all factors\n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n \"\"\"\n if n <= 1:\n return [] # No prime factors for numbers less than or equal to 1\n\n factors = []\n # Check for number of 2s that divide n\n while n % 2 == 0:\n factors.append(2)\n n //= 2\n\n # n must be odd at this point, so we can skip even numbers\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n factors.append(i)\n n //= i\n\n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n factors.append(n)\n\n return factors", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string.\n \n Args:\n strings (List[str]): A list of strings to concatenate.\n \n Returns:\n str: A single concatenated string.\n \n Examples:\n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n \"\"\"\n # Initialize an empty string to hold the result\n result = ''\n \n # Iterate through each string in the list and concatenate\n for string in strings:\n result += string\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n \n >>> flip_case('Hello')\n 'hELLO'\n \"\"\"\n # Initialize an empty list to store the flipped characters\n flipped_chars = []\n \n # Iterate through each character in the input string\n for char in string:\n # Check if the character is lowercase\n if char.islower():\n # Convert to uppercase\n flipped_chars.append(char.upper())\n # Check if the character is uppercase\n elif char.isupper():\n # Convert to lowercase\n flipped_chars.append(char.lower())\n else:\n # If it's neither, keep the character as is (e.g., punctuation, numbers)\n flipped_chars.append(char)\n \n # Join the list of flipped characters into a single string and return it\n return ''.join(flipped_chars)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n \n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n \"\"\"\n return [x for x in l if x > 0]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n \n Args:\n strings (List[str]): A list of strings to filter.\n prefix (str): The prefix to filter the strings by.\n \n Returns:\n List[str]: A list of strings that start with the given prefix.\n \n Examples:\n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n \"\"\"\n # Use a list comprehension to filter the strings\n return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float):\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list):\n \"\"\"\n Computes the derivative of the polynomial with coefficients xs.\n The derivative is given by: xs[1] + 2*xs[2]*x + ... + n*xs[n]*x^(n-1)\n \"\"\"\n return [i * coeff for i, coeff in enumerate(xs) if i > 0]\ndef find_zero(xs: list):\n \"\"\" \n xs are coefficients of a polynomial.\n find_zero finds x such that poly(x) = 0.\n find_zero returns only one zero point, even if there are many.\n Moreover, find_zero only takes list xs having an even number of coefficients\n and the largest non-zero coefficient as it guarantees a solution.\n \"\"\"\n if len(xs) % 2 != 0:\n raise ValueError(\"The number of coefficients must be even.\")\n \n # Initial guess for the root\n x0 = 0.0\n \n # Set a tolerance level and maximum iterations\n tolerance = 1e-7\n max_iterations = 1000\n \n for _ in range(max_iterations):\n f_x0 = poly(xs, x0)\n f_prime_x0 = poly(derivative(xs), x0)\n \n if f_prime_x0 == 0: # Avoid division by zero\n raise ValueError(\"Derivative is zero. No solution found.\")\n \n # Newton-Raphson update\n x1 = x0 - f_x0 / f_prime_x0\n \n # Check for convergence\n if abs(x1 - x0) < tolerance:\n return x1\n \n x0 = x1\n \n raise ValueError(\"Maximum iterations reached. No solution found.\")", "base_status": "fail", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n A prime number is a natural number greater than 1 that cannot be formed by multiplying two smaller natural numbers.\n \n Parameters:\n n (int): The number to check for primality.\n\n Returns:\n bool: True if n is prime, False otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return False # eliminate multiples of 2 and 3\n\n i = 5\n while i * i <= n: # check for factors from 5 to sqrt(n)\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6 # check only 6k \u00b1 1\n\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n This function takes a list of elements, removes duplicates, and returns a sorted list of unique elements.\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use a set to remove duplicates\n unique_elements = set(l)\n # Sort the unique elements and return as a list\n return sorted(unique_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n values_to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(values_to_sort)\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Replace values at indices divisible by 3 with sorted values\n for index, value in zip(range(len(result)), sorted_values):\n if index % 3 == 0:\n result[index] = value\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]]], "plus_fail_tests": []}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n \"\"\"Return maximum element in the list.\n \n If the list is empty, raise a ValueError.\n \n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n \"\"\"\n if not l: # Check if the list is empty\n raise ValueError(\"The list is empty. Cannot determine the maximum element.\")\n \n max_value = l[0] # Initialize max_value with the first element of the list\n for element in l: # Iterate through each element in the list\n if element > max_value: # Compare each element with the current max_value\n max_value = element # Update max_value if a larger element is found\n \n return max_value # Return the maximum value found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indexed elements\n even_indices_values.sort()\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Place the sorted even indexed values back into their positions\n for i, value in enumerate(even_indices_values):\n result[i * 2] = value # Place sorted value at even index\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with the encode_cyclic function.\n Returns the decoded string.\n \"\"\"\n # Split string into groups of length 3\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # Reverse the cycling for each group\n groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_fib(n: int) -> int:\n \"\"\"\n prime_fib returns the n-th number that is a Fibonacci number and it's also prime.\n \n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n count = 0\n for fib in fibonacci_generator():\n if is_prime(fib):\n count += 1\n if count == n:\n return fib", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1]], "plus_fail_tests": []}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n \"\"\"\n triples_sum_to_zero takes a list of integers as an input.\n it returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n \"\"\"\n n = len(l)\n if n < 3:\n return False\n\n # Sort the list to use the two-pointer technique\n l.sort()\n\n for i in range(n - 2):\n # Avoid duplicates for the first element\n if i > 0 and l[i] == l[i - 1]:\n continue\n \n left, right = i + 1, n - 1\n while left < right:\n current_sum = l[i] + l[left] + l[right]\n if current_sum == 0:\n return True\n elif current_sum < 0:\n left += 1\n else:\n right -= 1\n\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n \n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n \"\"\"\n # Check if the input is a list\n if not isinstance(l, list):\n raise ValueError(\"Input must be a list.\")\n \n # Increment each element in the list by 1\n return [x + 1 for x in l]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n \"\"\"\n Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move at the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.\n\n :param n: The number of cars in each direction.\n :return: The total number of collisions.\n \"\"\"\n # Each car moving left to right will collide with each car moving right to left.\n # Therefore, the total number of collisions is simply n * n.\n return n * n", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n \n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n \"\"\"\n seen = set()\n for number in l:\n if -number in seen:\n return True\n seen.add(number)\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion.\n base numbers are less than 10.\n \n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n \"\"\"\n if base < 2 or base >= 10:\n raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n \n if x == 0:\n return '0'\n \n result = []\n negative = x < 0\n x = abs(x)\n\n while x > 0:\n remainder = x % base\n result.append(str(remainder))\n x //= base\n\n if negative:\n result.append('-')\n\n # The result is built in reverse order\n return ''.join(reversed(result))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n \"\"\"Given length of a side and height, return area for a triangle.\n \n The area of a triangle can be calculated using the formula:\n Area = (base * height) / 2\n \n Parameters:\n a (float): The length of the base of the triangle.\n h (float): The height of the triangle.\n \n Returns:\n float: The area of the triangle.\n \n Raises:\n ValueError: If the base or height is not a positive number.\n \n >>> triangle_area(5, 3)\n 7.5\n >>> triangle_area(0, 3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(5, -3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(-5, 3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n \"\"\"\n \n # Validate inputs\n if a <= 0 or h <= 0:\n raise ValueError(\"Base and height must be positive numbers.\")\n \n # Calculate area\n area = (a * h) / 2\n return area", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fib4(0) -> 0\n fib4(1) -> 0\n fib4(2) -> 2\n fib4(3) -> 0\n fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n This function computes the n-th element of the fib4 number sequence efficiently without using recursion.\n \n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n # Handle base cases\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 2\n elif n == 3:\n return 0\n \n # Initialize a list to store computed values\n fib_values = [0] * (n + 1)\n fib_values[0] = 0\n fib_values[1] = 0\n fib_values[2] = 2\n fib_values[3] = 0\n \n # Compute the fib4 values iteratively\n for i in range(4, n + 1):\n fib_values[i] = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n \n return fib_values[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n \"\"\"\n Checks if given string is a palindrome.\n \n A palindrome is a string that reads the same forward and backward.\n \n Args:\n text (str): The string to check.\n \n Returns:\n bool: True if the string is a palindrome, False otherwise.\n \n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n \"\"\"\n # Normalize the string by removing spaces and converting to lowercase\n normalized_text = text.replace(\" \", \"\").lower()\n \n # Check if the normalized string is equal to its reverse\n return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n \"\"\"Return median of elements in the list l.\n \n The median is the middle value in a list of numbers. If the list has an odd number of elements,\n the median is the middle element. If the list has an even number of elements, the median is the\n average of the two middle elements.\n \n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty. Cannot compute median.\")\n \n # Sort the list\n sorted_list = sorted(l)\n n = len(sorted_list)\n \n # Calculate median\n if n % 2 == 1: # Odd number of elements\n return sorted_list[n // 2]\n else: # Even number of elements\n mid1 = sorted_list[n // 2 - 1]\n mid2 = sorted_list[n // 2]\n return (mid1 + mid2) / 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with the encode_shift function.\n Returns the decoded string by shifting every character back by 5 in the alphabet.\n \"\"\"\n return \"\".join([chr(((ord(ch) - ord(\"a\") - 5) % 26) + ord(\"a\")) for ch in s])", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n if p <= 0:\n raise ValueError(\"p must be a positive integer.\")\n \n if n < 0:\n return 0 # 2^n is not defined for negative n in this context\n \n result = 1\n base = 2\n \n # Use exponentiation by squaring for efficiency\n while n > 0:\n if n % 2 == 1: # If n is odd\n result = (result * base) % p\n base = (base * base) % p # Square the base\n n //= 2 # Divide n by 2\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n Vowels are defined as 'a', 'e', 'i', 'o', 'u' and their uppercase counterparts.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n \"\"\"Return True if all numbers in the list l are below threshold t.\n \n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n \"\"\"\n # Check if the list is empty; if so, return True as there are no elements above the threshold\n if not l:\n return True\n \n # Iterate through each number in the list\n for number in l:\n # If any number is greater than or equal to the threshold, return False\n if number >= t:\n return False\n \n # If all numbers are below the threshold, return True\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n \"\"\"Add two numbers x and y.\n\n This function takes two integers and returns their sum. \n It handles both positive and negative integers, as well as zero.\n\n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n >>> add(-1, 1)\n 0\n >>> add(-5, -7)\n -12\n >>> add(0, 0)\n 0\n >>> add(1000000, 2000000)\n 3000000\n >>> add(-1000000, 1000000)\n 0\n \"\"\"\n return x + y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two words have the same characters if they contain the same unique characters,\n regardless of the frequency of those characters.\n \n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Create a set of characters for each string\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Compare the two sets\n return set_s0 == set_s1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"<\" and \">\".\n return True if every opening bracket has a corresponding closing bracket.\n \"\"\"\n balance = 0\n \n for char in brackets:\n if char == '<':\n balance += 1\n elif char == '>':\n balance -= 1\n \n # If balance goes negative, it means there's a closing bracket without a matching opening bracket\n if balance < 0:\n return False\n \n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n \"\"\"Return n-th Fibonacci number.\n \n The Fibonacci sequence is defined as follows:\n - fib(0) = 0\n - fib(1) = 1\n - fib(n) = fib(n-1) + fib(n-2) for n > 1\n\n Args:\n n (int): The index of the Fibonacci number to return.\n\n Returns:\n int: The n-th Fibonacci number.\n\n Raises:\n ValueError: If n is negative.\n\n Examples:\n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n \"\"\"\n if n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n if n == 0:\n return 0\n elif n == 1:\n return 1\n \n a, b = 0, 1\n for _ in range(2, n + 1):\n a, b = b, a + b\n return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n \"\"\"Return True if list elements are monotonically increasing or decreasing.\n \n A list is considered monotonically increasing if each element is greater than or equal to the previous one.\n A list is considered monotonically decreasing if each element is less than or equal to the previous one.\n \n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n \"\"\"\n if len(l) < 2:\n return True # A list with 0 or 1 element is trivially monotonic\n\n increasing = decreasing = True\n\n for i in range(1, len(l)):\n if l[i] > l[i - 1]:\n decreasing = False\n elif l[i] < l[i - 1]:\n increasing = False\n\n return increasing or decreasing", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n \n Args:\n n (int): The upper limit of the summation (inclusive).\n \n Returns:\n int: The sum of all integers from 1 to n.\n \n Examples:\n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n \"\"\"\n if n < 1:\n return 0 # Return 0 for non-positive integers as the sum is not defined.\n \n return n * (n + 1) // 2 # Using the formula for the sum of the first n natural numbers.", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n largest_factor = None\n \n # Check for number of 2s that divide n\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # n must be odd at this point, so we can skip even numbers\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n \n return largest_factor", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"(\" and \")\".\n return True if every opening bracket has a corresponding closing bracket.\n \"\"\"\n balance = 0\n \n for char in brackets:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n \n # If balance goes negative, it means there's a closing bracket without a matching opening bracket\n if balance < 0:\n return False\n \n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n \"\"\" \n Calculate the derivative of a polynomial represented by its coefficients.\n \n The polynomial is represented as:\n xs[0] + xs[1] * x + xs[2] * x^2 + ...\n \n The derivative is calculated as:\n 0 + 1 * xs[1] + 2 * xs[2] * x + 3 * xs[3] * x^2 + ...\n \n Args:\n xs (list): A list of coefficients where the index represents the power of x.\n \n Returns:\n list: A list of coefficients representing the derivative of the polynomial.\n \n Examples:\n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n \"\"\"\n # Check if the input list is empty\n if not xs:\n return []\n \n # Calculate the derivative coefficients\n derivative_coeffs = []\n for i in range(1, len(xs)):\n derivative_coeffs.append(i * xs[i])\n \n return derivative_coeffs", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n \n Args:\n n (int): The index of the FibFib number to compute.\n \n Returns:\n int: The n-th FibFib number.\n \n Examples:\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 1\n \n # Initialize the first three FibFib numbers\n fibfib_numbers = [0, 0, 1]\n \n # Compute FibFib numbers iteratively\n for i in range(3, n + 1):\n next_fibfib = fibfib_numbers[i - 1] + fibfib_numbers[i - 2] + fibfib_numbers[i - 3]\n fibfib_numbers.append(next_fibfib)\n \n return fibfib_numbers[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set('aeiouAEIOU')\n count = 0\n \n # Iterate through each character in the string\n for i in range(len(s)):\n char = s[i]\n # Check if the character is a vowel\n if char in vowels:\n count += 1\n # Check if the character is 'y' and it's the last character\n elif char.lower() == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n \"\"\"Task\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n \"\"\"\n # Initialize the sum of ASCII values\n total_sum = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is uppercase\n if char.isupper():\n # Add the ASCII value of the uppercase character to the total sum\n total_sum += ord(char)\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n \n >>> circular_shift(12, 1)\n \"21\"\n >>> circular_shift(12, 2)\n \"12\"\n \"\"\"\n # Convert the integer to a string to work with its digits\n str_x = str(x)\n num_digits = len(str_x)\n \n # If shift is greater than the number of digits, reverse the string\n if shift >= num_digits:\n return str_x[::-1]\n \n # Calculate the effective shift (in case shift is larger than num_digits)\n effective_shift = shift % num_digits\n \n # Perform the circular shift\n if effective_shift > 0:\n # Split the string into two parts and rearrange\n return str_x[-effective_shift:] + str_x[:-effective_shift]\n \n # If effective_shift is 0, return the original string\n return str_x", "base_status": "fail", "plus_status": null, "base_fail_tests": [[12, 2]], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n \"\"\"\n Given an array representing a branch of a tree that has non-negative integer nodes,\n your task is to pluck one of the nodes and return it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n The plucked node should be returned in a list, [ smallest_value, its index ],\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1] \n\n Example 3:\n Input: []\n Output: []\n \n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n \"\"\"\n smallest_even_value = float('inf')\n smallest_index = -1\n\n for index, value in enumerate(arr):\n if value % 2 == 0: # Check if the value is even\n if value < smallest_even_value: # Found a smaller even value\n smallest_even_value = value\n smallest_index = index\n elif value == smallest_even_value and index < smallest_index:\n smallest_index = index # Update index if same value found earlier\n\n if smallest_index == -1: # No even value found\n return []\n \n return [smallest_even_value, smallest_index]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n \"\"\"\n Calculate the number of mango fruits in a basket given a string representation of apples and oranges,\n and the total number of fruits in the basket.\n\n Parameters:\n s (str): A string that contains the number of apples and oranges.\n n (int): The total number of fruits in the basket.\n\n Returns:\n int: The number of mango fruits in the basket.\n \"\"\"\n # Extract the number of apples and oranges from the string\n parts = s.split(\" and \")\n apples = int(parts[0].split()[0]) # Get the number of apples\n oranges = int(parts[1].split()[0]) # Get the number of oranges\n\n # Calculate the number of mangoes\n mangoes = n - apples - oranges\n\n return mangoes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n '''\n Given list of integers, return list in strange order.\n Strange sorting, is when you start with the minimum value,\n then maximum of the remaining integers, then minimum and so on.\n\n Examples:\n strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n strange_sort_list([]) == []\n '''\n if not lst:\n return []\n\n # Sort the list to easily access min and max values\n sorted_lst = sorted(lst)\n result = []\n \n # Use two pointers to select min and max alternately\n left = 0\n right = len(sorted_lst) - 1\n \n while left <= right:\n if left == right: # If both pointers meet, add the last element\n result.append(sorted_lst[left])\n else:\n result.append(sorted_lst[left]) # Add the minimum\n result.append(sorted_lst[right]) # Add the maximum\n left += 1\n right -= 1\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n '''\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequency greater than or equal to the value of the integer itself. \n The frequency of an integer is the number of times it appears in the list.\n If no such a value exist, return -1.\n Examples:\n search([4, 1, 2, 2, 3, 1]) == 2\n search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n search([5, 5, 4, 4, 4]) == -1\n '''\n from collections import Counter\n\n # Count the frequency of each integer in the list\n frequency = Counter(lst)\n\n # Initialize the result variable\n result = -1\n\n # Iterate through the frequency dictionary\n for num in frequency:\n # Check if the frequency is greater than or equal to the number itself\n if frequency[num] >= num:\n # Update the result if this number is greater than the current result\n result = max(result, num)\n\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return the area of\n the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n Otherwise return -1.\n Three sides make a valid triangle when the sum of any two sides is greater \n than the third side.\n '''\n # Check for valid triangle using the triangle inequality theorem\n if a <= 0 or b <= 0 or c <= 0:\n return -1\n if a + b <= c or a + c <= b or b + c <= a:\n return -1\n \n # Calculate the semi-perimeter\n s = (a + b + c) / 2\n \n # Calculate the area using Heron's formula\n area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n \n # Return the area rounded to 2 decimal points\n return round(area, 2)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n '''\n Write a function that returns True if the object q will fly, and False otherwise.\n The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n '''\n # Check if the list is a palindrome\n is_balanced = (q == q[::-1])\n \n # Calculate the sum of the elements in the list\n total_weight = sum(q)\n \n # Check if the total weight is less than or equal to the maximum weight\n is_within_weight_limit = (total_weight <= w)\n \n # The object will fly if it is balanced and within the weight limit\n return is_balanced and is_within_weight_limit", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n \"\"\"\n Given an array arr of integers, find the minimum number of elements that\n need to be changed to make the array palindromic. A palindromic array is an array that\n is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n For example:\n smallest_change([1,2,3,5,4,7,9,6]) == 4\n smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n smallest_change([1, 2, 3, 2, 1]) == 0\n \"\"\"\n n = len(arr)\n changes = 0\n \n # Compare elements from the start and end towards the center\n for i in range(n // 2):\n if arr[i] != arr[n - 1 - i]:\n changes += 1\n \n return changes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n \n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total character counts and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n else:\n return lst2", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n \"\"\"Returns True if x is a simple power of n, otherwise False.\n \n A number x is a simple power of n if there exists an integer k such that n**k = x.\n \n Args:\n x (int): The number to check.\n n (int): The base number.\n \n Returns:\n bool: True if x is a simple power of n, False otherwise.\n \"\"\"\n # Edge case: if n is 0, we cannot raise it to any power to get a positive x\n if n == 0:\n return x == 0\n \n # Edge case: if n is 1, n**k is always 1 for any k, so x must be 1\n if n == 1:\n return x == 1\n \n # Edge case: if x is less than 1, we can only have x == 1 for n >= 1\n if x < 1:\n return x == 1\n \n # Check if x is a power of n\n power = 1\n while True:\n power_value = n ** power\n if power_value == x:\n return True\n elif power_value > x:\n return False\n power += 1", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1, 12]], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef generate_primes(limit):\n \"\"\"Generate a list of prime numbers up to a given limit.\"\"\"\n primes = []\n for num in range(2, limit):\n if is_prime(num):\n primes.append(num)\n return primes\ndef is_multiply_prime(a):\n \"\"\"Return true if the given number is the multiplication of 3 prime numbers, false otherwise.\"\"\"\n if a < 1 or a >= 100:\n return False\n \n primes = generate_primes(100)\n \n # Check all combinations of three primes\n for i in range(len(primes)):\n for j in range(i, len(primes)):\n for k in range(j, len(primes)):\n product = primes[i] * primes[j] * primes[k]\n if product == a:\n return True\n if product > a:\n break # No need to check further if the product exceeds 'a'\n \n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this integer is a cube of some integer number.\n Note: you may assume the input is always valid.\n Examples:\n iscube(1) ==> True\n iscube(2) ==> False\n iscube(-1) ==> True\n iscube(64) ==> True\n iscube(0) ==> True\n iscube(180) ==> False\n '''\n # Calculate the cube root of the absolute value of a\n cube_root = round(abs(a) ** (1/3))\n \n # Check if the cube of the rounded cube root equals the absolute value of a\n return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n \"\"\"Counts the number of prime hexadecimal digits in the given hexadecimal string.\"\"\"\n \n # Define the set of prime hexadecimal digits\n prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n \n # Initialize a counter for prime digits\n prime_count = 0\n \n # Iterate through each character in the input string\n for char in num:\n # Check if the character is in the set of prime hexadecimal digits\n if char in prime_hex_digits:\n prime_count += 1\n \n return prime_count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n \"\"\"Check if the string s is happy.\n \n A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n \n Args:\n s (str): The input string to check.\n \n Returns:\n bool: True if the string is happy, False otherwise.\n \"\"\"\n # Check if the length of the string is at least 3\n if len(s) < 3:\n return False\n \n # Iterate through the string and check every 3 consecutive characters\n for i in range(len(s) - 2):\n # Get the current substring of 3 characters\n substring = s[i:i+3]\n # Check if all characters in the substring are distinct\n if len(set(substring)) != 3:\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n \"\"\"Convert a decimal number to binary format with specific formatting.\n\n Args:\n decimal (int): A non-negative integer to convert to binary.\n\n Returns:\n str: A string representing the binary format of the decimal number,\n prefixed and suffixed with 'db'.\n \n Raises:\n ValueError: If the input is a negative integer.\n \"\"\"\n if decimal < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n # Convert decimal to binary and remove the '0b' prefix\n binary_representation = bin(decimal)[2:]\n \n # Format the output with 'db' at the beginning and end\n formatted_output = f\"db{binary_representation}db\"\n \n return formatted_output", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_length(string):\n \"\"\"Check if the length of the string is a prime number.\"\"\"\n length = len(string)\n return is_prime(length)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n letter_grades = []\n \n for gpa in grades:\n if gpa == 4.0:\n letter_grades.append('A+')\n elif gpa > 3.7:\n letter_grades.append('A')\n elif gpa > 3.3:\n letter_grades.append('A-')\n elif gpa > 3.0:\n letter_grades.append('B+')\n elif gpa > 2.7:\n letter_grades.append('B')\n elif gpa > 2.3:\n letter_grades.append('B-')\n elif gpa > 2.0:\n letter_grades.append('C+')\n elif gpa > 1.7:\n letter_grades.append('C')\n elif gpa > 1.3:\n letter_grades.append('C-')\n elif gpa > 1.0:\n letter_grades.append('D+')\n elif gpa > 0.7:\n letter_grades.append('D')\n elif gpa > 0.0:\n letter_grades.append('D-')\n else:\n letter_grades.append('E')\n \n return letter_grades", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits will be 1 the output should be \"1\".\n For N = 150, the sum of digits will be 6 the output should be \"110\".\n For N = 147, the sum of digits will be 12 the output should be \"1100\".\n \n Variables:\n @N integer\n Constraints: 0 \u2264 N \u2264 10000.\n Output:\n a string of binary number\n \"\"\"\n # Step 1: Calculate the sum of the digits of N\n digit_sum = sum(int(digit) for digit in str(N))\n \n # Step 2: Convert the sum to binary and remove the '0b' prefix\n binary_sum = bin(digit_sum)[2:]\n \n return binary_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n \"\"\"\n Given a positive integer n, return the count of the numbers of n-digit\n positive integers that start or end with 1.\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n\n # Total n-digit numbers\n total_n_digit_numbers = 9 * (10 ** (n - 1))\n\n # Count of n-digit numbers that start with 1\n if n == 1:\n count_starting_with_1 = 1 # Only the number 1\n else:\n count_starting_with_1 = 10 ** (n - 1) # 1 followed by (n-1) digits (0-9)\n\n # Count of n-digit numbers that end with 1\n count_ending_with_1 = 9 * (10 ** (n - 2)) if n > 1 else 0 # (n-1) digits can be anything (0-9)\n\n # Total count of n-digit numbers that start or end with 1\n total_count = count_starting_with_1 + count_ending_with_1\n\n # If n > 1, we have double counted the numbers that both start and end with 1\n if n > 1:\n count_both_start_and_end_with_1 = 10 ** (n - 2) # 1 followed by (n-2) digits (0-9) and ending with 1\n total_count -= count_both_start_and_end_with_1\n\n return total_count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words and spaces\n words = s.split(' ')\n \n # Process each word\n ordered_words = []\n for word in words:\n # Sort the characters of the word and join them back\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n \n # Join the ordered words back with spaces\n result = ' '.join(ordered_words)\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum to 0\n total = 0\n \n # Iterate over the list using index and value\n for index in range(len(lst)):\n # Check if the index is odd\n if index % 2 == 1:\n # Check if the element at this index is even\n if lst[index] % 2 == 0:\n total += lst[index]\n \n return total", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n # Iterate through each row and its index\n for row_index, row in enumerate(lst):\n # Iterate through each column in the row and its index\n for col_index, value in enumerate(row):\n # If the value matches x, store the coordinates\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort coordinates by row (ascending) and then by column (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n or sort it in descending order if the sum( first index value, last index value) is even.\n\n Note:\n * don't change the given array.\n\n Examples:\n * sort_array([]) => []\n * sort_array([5]) => [5]\n * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n \"\"\"\n # Create a copy of the original array to avoid modifying it\n sorted_array = array.copy()\n \n # Check if the array is empty or has only one element\n if len(sorted_array) <= 1:\n return sorted_array\n \n # Calculate the sum of the first and last elements\n first_element = sorted_array[0]\n last_element = sorted_array[-1]\n total_sum = first_element + last_element\n \n # Sort the array based on the sum being odd or even\n if total_sum % 2 == 0:\n # Even sum: sort in descending order\n sorted_array.sort(reverse=True)\n else:\n # Odd sum: sort in ascending order\n sorted_array.sort()\n \n return sorted_array", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Sort the unique elements\n sorted_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_elements[1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n # Create a dictionary to map each letter to its encrypted counterpart\n encrypted_dict = {}\n \n # Populate the dictionary with shifted letters\n for i in range(len(alphabet)):\n # Calculate the new position with a shift of 4 (2 * 2)\n new_position = (i + 4) % 26\n encrypted_dict[alphabet[i]] = alphabet[new_position]\n \n # Encrypt the input string\n encrypted_string = ''.join(encrypted_dict[char] for char in s if char in encrypted_dict)\n \n return encrypted_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n \n For example:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n \"\"\"\n # Split the input string into sentences using the delimiters\n sentences = []\n current_sentence = []\n delimiters = {'.', '?', '!'}\n \n for char in S:\n if char in delimiters:\n if current_sentence: # If there's a sentence to add\n sentences.append(''.join(current_sentence).strip())\n current_sentence = [] # Reset for the next sentence\n else:\n current_sentence.append(char)\n \n # Add the last sentence if it exists\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n \n # Count the number of sentences that start with \"I\"\n boredom_count = sum(1 for sentence in sentences if sentence.startswith(\"I\"))\n \n return boredom_count", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n '''\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n \n Examples\n any_int(5, 2, 7) \u279e True\n any_int(3, 2, 2) \u279e False\n any_int(3, -2, 1) \u279e True\n any_int(3.6, -2.2, 2) \u279e False\n '''\n \n # Check if all inputs are integers\n if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n # Check if one number is equal to the sum of the other two\n return x == y + z or y == x + z or z == x + y\n else:\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n \"\"\"\n Write a function that takes a message, and encodes in such a \n way that it swaps case of all letters, replaces all vowels in \n the message with the letter that appears 2 places ahead of that \n vowel in the English alphabet. \n Assume only letters. \n \n Examples:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n \n # Define vowels and their replacements\n vowels = 'aeiouAEIOU'\n replacements = {\n 'a': 'c', 'A': 'C',\n 'e': 'g', 'E': 'G',\n 'i': 'k', 'I': 'K',\n 'o': 'q', 'O': 'Q',\n 'u': 'w', 'U': 'W'\n }\n \n encoded_message = []\n \n for char in message:\n if char.isalpha(): # Check if the character is a letter\n # Swap case\n if char in vowels:\n # Replace vowel and swap case\n encoded_message.append(replacements[char])\n else:\n # Just swap case for consonants\n encoded_message.append(char.swapcase())\n else:\n # If it's not a letter, we can choose to ignore it or keep it as is\n encoded_message.append(char)\n \n return ''.join(encoded_message)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["TEST"]], "plus_fail_tests": []}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef sum_of_digits(n):\n \"\"\"Return the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n largest_prime = None\n \n for number in lst:\n if is_prime(number):\n if largest_prime is None or number > largest_prime:\n largest_prime = number\n \n if largest_prime is not None:\n return sum_of_digits(largest_prime)\n else:\n return 0 # Return 0 if no prime number is found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in lower \n case or all keys are strings in upper case, else return False.\n The function should return False if the given dictionary is empty.\n \n Examples:\n check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n \"\"\"\n \n # Check if the dictionary is empty\n if not input_dict:\n return False\n \n # Initialize flags for lower and upper case\n all_lower = True\n all_upper = True\n \n for key in input_dict.keys():\n # Check if the key is a string\n if not isinstance(key, str):\n return False\n \n # Check if the key is lower case\n if key.islower():\n all_upper = False\n # Check if the key is upper case\n elif key.isupper():\n all_lower = False\n else:\n # If the key is neither lower nor upper case\n return False\n \n # Return True if all keys are either lower case or upper case\n return all_lower or all_upper", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_up_to(n):\n \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n primes = []\n for i in range(2, n):\n if is_prime(i):\n primes.append(i)\n return primes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.\n \"\"\"\n # Get the unit digit of the first number\n unit_digit_a = abs(a) % 10\n # Get the unit digit of the second number\n unit_digit_b = abs(b) % 10\n # Return the product of the unit digits\n return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n count_upper('aBCdEf') returns 1\n count_upper('abcdefg') returns 0\n count_upper('dBBE') returns 0\n \"\"\"\n # Define the set of uppercase vowels\n uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n \n # Initialize a counter for uppercase vowels at even indices\n count = 0\n \n # Iterate over the string, checking only even indices\n for i in range(0, len(s), 2): # Step by 2 to get even indices\n if s[i] in uppercase_vowels:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n\n Note:\n Rounding away from zero means that if the given number is equidistant\n from two integers, the one you should return is the one that is the\n farthest from zero. For example closest_integer(\"14.5\") should\n return 15 and closest_integer(\"-14.5\") should return -15.\n '''\n # Convert the string input to a float\n num = float(value)\n \n # Get the floor and ceiling of the number\n lower_int = int(num // 1) # This is the largest integer less than or equal to num\n upper_int = lower_int + 1 # This is the smallest integer greater than num\n \n # Check the distance to the lower and upper integers\n distance_to_lower = abs(num - lower_int)\n distance_to_upper = abs(num - upper_int)\n \n # Determine which integer to return based on the distances\n if distance_to_lower < distance_to_upper:\n return lower_int\n elif distance_to_upper < distance_to_lower:\n return upper_int\n else:\n # If equidistant, round away from zero\n if num > 0:\n return upper_int\n else:\n return lower_int", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n \"\"\"\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n >>> make_a_pile(4)\n [4, 6, 8, 10]\n >>> make_a_pile(1)\n [1]\n >>> make_a_pile(2)\n [2, 4]\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n\n stones = []\n current_stones = n\n\n for i in range(n):\n stones.append(current_stones)\n if current_stones % 2 == 0:\n current_stones += 2 # next even number\n else:\n current_stones += 2 # next odd number\n\n return stones", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n \"\"\"\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n \"\"\"\n # Replace commas with spaces to standardize the delimiters\n s = s.replace(',', ' ')\n \n # Split the string by whitespace and filter out any empty strings\n words = s.split()\n \n return words", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n \"\"\"Compute the average of integers from n to m, round it to the nearest integer,\n and convert that to binary. If n is greater than m, return -1.\n \n Args:\n n (int): The starting integer (inclusive).\n m (int): The ending integer (inclusive).\n \n Returns:\n str or int: The binary representation of the rounded average if n <= m, \n otherwise -1.\n \"\"\"\n if n > m:\n return -1\n \n # Calculate the sum of integers from n to m\n total_sum = sum(range(n, m + 1))\n count = m - n + 1 # Total numbers from n to m\n \n # Calculate the average and round it\n average = total_sum / count\n rounded_average = round(average)\n \n # Convert the rounded average to binary\n return bin(rounded_average)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n \"\"\"This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If \n there's no such number, then the function should return -1.\n \n For example:\n choose_num(12, 15) = 14\n choose_num(13, 12) = -1\n \"\"\"\n # Ensure x is less than or equal to y\n if x > y:\n return -1\n \n # Start from the largest number in the range and check for evenness\n for num in range(y, x - 1, -1):\n if num % 2 == 0:\n return num\n \n # If no even number is found, return -1\n return -1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n \"\"\"Given a list of positive integers x, return a sorted list of all \n elements that haven't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n def has_even_digit(n):\n \"\"\"Check if the number has any even digit.\"\"\"\n for digit in str(n):\n if int(digit) % 2 == 0:\n return True\n return False\n\n # Filter the list to include only numbers without even digits\n filtered = [num for num in x if not has_even_digit(num)]\n \n # Sort the resulting list\n return sorted(filtered)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n reverse the resulting array, and then replace each digit by its corresponding name from\n \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n For example:\n arr = [2, 1, 1, 4, 5, 8, 2, 3] \n -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n \n If the array is empty, return an empty array:\n arr = []\n return []\n \n If the array has any strange number ignore it:\n arr = [1, -1 , 55] \n -> sort arr -> [-1, 1, 55]\n -> reverse arr -> [55, 1, -1]\n return = ['One']\n \"\"\"\n \n # Mapping of digits to their corresponding names\n digit_to_name = {\n 1: \"One\",\n 2: \"Two\",\n 3: \"Three\",\n 4: \"Four\",\n 5: \"Five\",\n 6: \"Six\",\n 7: \"Seven\",\n 8: \"Eight\",\n 9: \"Nine\"\n }\n \n # Filter the array to include only integers between 1 and 9\n filtered_arr = [num for num in arr if 1 <= num <= 9]\n \n # Sort the filtered array\n filtered_arr.sort()\n \n # Reverse the sorted array\n filtered_arr.reverse()\n \n # Convert the digits to their corresponding names\n result = [digit_to_name[num] for num in filtered_arr]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n \"\"\"\n Given a positive integer n, return a tuple that has the number of even and odd\n integer palindromes that fall within the range(1, n), inclusive.\n\n Example 1:\n Input: 3\n Output: (1, 2)\n Explanation:\n Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n Example 2:\n Input: 12\n Output: (4, 6)\n Explanation:\n Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n Note:\n 1. 1 <= n <= 10^3\n 2. returned tuple has the number of even and odd integer palindromes respectively.\n \"\"\"\n \n def is_palindrome(num):\n return str(num) == str(num)[::-1]\n\n even_count = 0\n odd_count = 0\n\n for i in range(1, n + 1):\n if is_palindrome(i):\n if i % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def f(n):\n \"\"\" \n Implement the function f that takes n as a parameter,\n and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even\n or the sum of numbers from 1 to i otherwise.\n i starts from 1.\n the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).\n \"\"\"\n result = []\n \n for i in range(1, n + 1):\n if i % 2 == 0: # i is even\n factorial = 1\n for j in range(1, i + 1):\n factorial *= j\n result.append(factorial)\n else: # i is odd\n sum_of_numbers = sum(range(1, i + 1))\n result.append(sum_of_numbers)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return True else return False.\n If the given array is empty then return True.\n\n Note: The given list is guaranteed to have unique elements.\n \"\"\"\n \n if not arr: # Check for empty array\n return True\n \n n = len(arr)\n count = 0 # To count the number of times the order is broken\n\n for i in range(n):\n if arr[i] > arr[(i + 1) % n]: # Compare current element with the next\n count += 1\n\n # If there are more than one break in the order, it's not possible\n return count <= 1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n \"\"\"\n Write a function count_nums which takes an array of integers and returns\n the number of elements which has a sum of digits > 0.\n If a number is negative, then its first signed digit will be negative:\n e.g. -123 has signed digits -1, 2, and 3.\n \n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n def sum_of_digits(n):\n \"\"\"Helper function to calculate the sum of digits of a number.\"\"\"\n # Convert number to string and iterate over each character\n # If the number is negative, we need to consider the first digit as negative\n str_n = str(n)\n digit_sum = 0\n \n for i, char in enumerate(str_n):\n if char.isdigit():\n digit_sum += int(char)\n elif char == '-' and i == 0: # First character is a negative sign\n digit_sum -= 1 # Subtract 1 for the signed digit\n \n return digit_sum\n\n count = 0\n for number in arr:\n if sum_of_digits(number) > 0:\n count += 1\n \n return count", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[-1, -2, 0]]], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n \"\"\"Determines whether it is possible to perform an exchange of elements\n between two lists to make lst1 a list of only even numbers.\n \n Args:\n lst1 (list): The first list of numbers.\n lst2 (list): The second list of numbers.\n \n Returns:\n str: \"YES\" if lst1 can be made all even, otherwise \"NO\".\n \"\"\"\n # Check if lst1 already contains only even numbers\n if all(x % 2 == 0 for x in lst1):\n return \"YES\"\n \n # Count the number of odd numbers in lst1\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n \n # Check if lst2 has at least one even number to exchange\n has_even_in_lst2 = any(x % 2 == 0 for x in lst2)\n \n # If lst1 has odd numbers and lst2 has at least one even number,\n # we can perform exchanges to make lst1 all even\n if odd_count_lst1 > 0 and has_even_in_lst2:\n return \"YES\"\n \n # If lst1 has odd numbers and lst2 has no even numbers,\n # we cannot make lst1 all even\n return \"NO\"", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 3, 4], [1, 5, 3, 4]]], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n \"\"\"\n \n if not test: # Handle the empty string case\n return {}\n \n # Split the input string into a list of letters\n letters = test.split()\n \n # Create a dictionary to count occurrences of each letter\n count_dict = {}\n for letter in letters:\n if letter in count_dict:\n count_dict[letter] += 1\n else:\n count_dict[letter] = 1\n \n # Find the maximum count\n max_count = max(count_dict.values())\n \n # Create a result dictionary for letters with the maximum count\n result = {letter: count for letter, count in count_dict.items() if count == max_count}\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n \"\"\"Task\n We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and True/False for the check.\n \"\"\"\n # Create a set of characters to delete for faster lookup\n chars_to_delete = set(c)\n \n # Build the result string by filtering out characters in chars_to_delete\n result = ''.join(char for char in s if char not in chars_to_delete)\n \n # Check if the result string is a palindrome\n is_palindrome = result == result[::-1]\n \n return (result, is_palindrome)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n \n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in s if char in '13579')\n \n # Create the output string with the counted odd digits\n output_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n \n # Append the result to the list\n result.append(output_string)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n Example\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n \"\"\"\n if not nums:\n raise ValueError(\"The input array must not be empty.\")\n \n # Initialize variables to track the minimum sum and the current sum\n min_sum = float('inf')\n current_sum = 0\n \n for num in nums:\n current_sum += num\n min_sum = min(min_sum, current_sum)\n \n # If current_sum is positive, reset it to 0\n if current_sum > 0:\n current_sum = 0\n \n return min_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n \"\"\"\n Calculate the number of times buckets need to be lowered to empty the wells.\n\n Parameters:\n grid (list of list of int): A rectangular grid representing wells.\n capacity (int): The capacity of each bucket.\n\n Returns:\n int: The total number of times buckets need to be lowered.\n \"\"\"\n total_water = 0\n \n # Count the total amount of water in the grid\n for row in grid:\n total_water += sum(row)\n \n # Calculate the number of times buckets need to be lowered\n if total_water == 0:\n return 0 # No water to extract\n \n # Each bucket can carry 'capacity' units of water\n # We need to lower the bucket enough times to extract all the water\n return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n \"\"\"\n Sorts an array of non-negative integers according to the number of ones in their binary representation\n in ascending order. For numbers with the same number of ones, it sorts based on their decimal value.\n\n Parameters:\n arr (list): A list of non-negative integers.\n\n Returns:\n list: A sorted list of integers based on the specified criteria.\n \"\"\"\n # Define a sorting key that sorts first by the number of ones in binary representation,\n # and then by the decimal value itself.\n return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n \"\"\"Given a string s and a natural number n, returns a list of all words from string s \n that contain exactly n consonants, in the order they appear in the string s.\n \n Args:\n s (str): The input string containing words.\n n (int): The number of consonants to match in each word.\n \n Returns:\n list: A list of words containing exactly n consonants.\n \"\"\"\n \n if not s: # Check if the string is empty\n return []\n \n # Define a set of vowels for easy checking\n vowels = set(\"aeiouAEIOU\")\n \n def count_consonants(word):\n \"\"\"Helper function to count consonants in a word.\"\"\"\n return sum(1 for char in word if char.isalpha() and char not in vowels)\n \n # Split the string into words\n words = s.split()\n \n # Filter words that have exactly n consonants\n result = [word for word in words if count_consonants(word) == n]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n \n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0: # More closing than opening\n return False\n return balance == 0 # Must be balanced at the end\n\n # Get the two strings\n s1, s2 = lst[0], lst[1]\n\n # Check both concatenation orders\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n two consonants from the right side of the word (case sensitive).\n \n Vowels in the beginning and ending don't count. Return empty string if you didn't\n find any vowel that meets the above condition. \n\n You may assume that the given string contains English letters only.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n n = len(word)\n\n # Check for edge cases\n if n < 3: # Need at least 3 characters to have consonants on both sides of a vowel\n return \"\"\n\n # Start from the end of the word\n for i in range(n - 2, 0, -1): # Start from the second last character to the first\n if word[i] in vowels: # Check if the current character is a vowel\n # Check if the characters before and after are consonants\n if word[i - 1].isalpha() and word[i - 1] not in vowels and word[i + 1].isalpha() and word[i + 1] not in vowels:\n return word[i] # Return the vowel if it is between two consonants\n\n return \"\" # Return empty string if no such vowel is found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index in range(len(lst)):\n # Check if the index is even\n if index % 2 == 0:\n # Check if the element at this index is odd\n if lst[index] % 2 != 0:\n # Add the odd element to the total sum\n total_sum += lst[index]\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n \n # Sort the array in descending order and take the first k elements\n max_k_elements = sorted(arr, reverse=True)[:k]\n \n # Sort the result in ascending order before returning\n return sorted(max_k_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n \"\"\"\n Given a non-empty array of integers arr and an integer k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example:\n\n Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n Output: 24 # sum of 21 + 3\n\n Constraints:\n 1. 1 <= len(arr) <= 100\n 2. 1 <= k <= len(arr)\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate through the first k elements of the array\n for i in range(k):\n # Check if the current element has at most two digits\n if -100 < arr[i] < 100:\n total_sum += arr[i]\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n as follows: start with any positive integer n. Then each term is obtained from the \n previous term as follows: if the previous term is even, the next term is one half of \n the previous term. If the previous term is odd, the next term is 3 times the previous\n term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n Note: \n 1. Collatz(1) is [1].\n 2. returned list sorted in increasing order.\n\n For example:\n get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n odd_numbers = set() # Use a set to avoid duplicates\n current = n\n \n while current != 1:\n if current % 2 == 1: # Check if current is odd\n odd_numbers.add(current)\n current = current // 2 if current % 2 == 0 else 3 * current + 1\n \n odd_numbers.add(1) # Add 1 to the set, as it is always part of the sequence\n return sorted(odd_numbers) # Return the sorted list of odd numbers", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n '''\n Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n Examples\n split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"abcdef\") == 3 \n '''\n \n # Check for whitespace in the text\n if ' ' in txt:\n return txt.split()\n \n # Check for commas in the text\n elif ',' in txt:\n return txt.split(',')\n \n # If no whitespace or commas, count lowercase letters with odd order\n else:\n odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n return odd_count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n \n The date is valid if all of the following rules are satisfied:\n 1. The date string is not empty.\n 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n The number of days is not less than 1 or higher than 29 for the month 2.\n 3. The months should not be less than 1 or higher than 12.\n 4. The date should be in the format: mm-dd-yyyy\n \"\"\"\n \n # Check if the date string is empty\n if not date:\n return False\n \n # Check if the date format is correct\n if len(date) != 10 or date[2] != '-' or date[5] != '-':\n return False\n \n # Split the date into components\n try:\n month, day, year = map(int, date.split('-'))\n except ValueError:\n return False\n \n # Check if month is valid\n if month < 1 or month > 12:\n return False\n \n # Check if day is valid based on the month\n if month in {1, 3, 5, 7, 8, 10, 12}:\n if day < 1 or day > 31:\n return False\n elif month in {4, 6, 9, 11}:\n if day < 1 or day > 30:\n return False\n elif month == 2:\n if day < 1 or day > 29:\n return False\n \n # If all checks are passed, the date is valid\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef intersection(interval1, interval2):\n \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n start1, end1 = interval1\n start2, end2 = interval2\n \n # Find the intersection\n start_intersection = max(start1, start2)\n end_intersection = min(end1, end2)\n \n # Check if there is an intersection\n if start_intersection > end_intersection:\n return \"NO\"\n \n # Calculate the length of the intersection\n length_of_intersection = end_intersection - start_intersection\n \n # Check if the length is a prime number\n if is_prime(length_of_intersection):\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n '''\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return False. Assume no negative numbers and only integers.\n\n Examples\n is_sorted([5]) \u279e True\n is_sorted([1, 2, 3, 4, 5]) \u279e True\n is_sorted([1, 3, 2, 4, 5]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n '''\n \n seen = set()\n previous = None\n \n for num in lst:\n # Check for duplicates\n if num in seen:\n return False\n seen.add(num)\n \n # Check if the list is sorted\n if previous is not None and num < previous:\n return False\n previous = num\n \n return True", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n if not arr: # Check for empty array\n return None\n\n product_of_signs = 1\n sum_of_magnitudes = 0\n\n for num in arr:\n if num > 0:\n sum_of_magnitudes += num\n elif num < 0:\n sum_of_magnitudes += -num\n product_of_signs *= -1 # Flip the sign for negative numbers\n else: # num == 0\n return 0 # If there's a zero, the product of signs is zero\n\n return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n \"\"\"Generate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n if n < 0:\n return []\n\n # Initialize the list to hold the Tribonacci numbers\n tribonacci_sequence = []\n\n # Calculate the Tribonacci numbers based on the given rules\n for i in range(n + 1):\n if i == 0:\n tribonacci_sequence.append(1) # tri(0) = 1\n elif i == 1:\n tribonacci_sequence.append(3) # tri(1) = 3\n elif i % 2 == 0: # i is even\n tribonacci_sequence.append(1 + i / 2)\n else: # i is odd\n tri_n_minus_1 = tribonacci_sequence[i - 1]\n tri_n_minus_2 = tribonacci_sequence[i - 2]\n tri_n_plus_1 = 3 if i + 1 == 1 else tribonacci_sequence[i + 1] if i + 1 < len(tribonacci_sequence) else 0\n tribonacci_sequence.append(tri_n_minus_1 + tri_n_minus_2 + tri_n_plus_1)\n\n return tribonacci_sequence", "base_status": "fail", "plus_status": null, "base_fail_tests": [[3]], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n \"\"\"Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n For example:\n digits(1) == 1\n digits(4) == 0\n digits(235) == 15\n \"\"\"\n # Initialize the product to 1 and a flag to check if any odd digit is found\n product = 1\n found_odd = False\n \n # Convert the number to a string to iterate over each digit\n for digit in str(n):\n digit = int(digit) # Convert the character back to an integer\n if digit % 2 != 0: # Check if the digit is odd\n product *= digit # Multiply the product by the odd digit\n found_odd = True # Set the flag to True since we found an odd digit\n \n # If no odd digit was found, return 0\n if not found_odd:\n return 0\n \n return product", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n '''\n Create a function that takes a string as input which contains only square brackets.\n The function should return True if and only if there is a valid subsequence of brackets \n where at least one bracket in the subsequence is nested.\n\n is_nested('[[]]') \u279e True\n is_nested('[]]]]]]][[[[[]') \u279e False\n is_nested('[][]') \u279e False\n is_nested('[]') \u279e False\n is_nested('[[][]]') \u279e True\n is_nested('[[]][[') \u279e True\n '''\n \n # Initialize a counter for open brackets\n open_count = 0\n # Initialize a flag to check for nesting\n nested = False\n \n for char in string:\n if char == '[':\n open_count += 1\n # If we have more than one open bracket, we have a nested structure\n if open_count > 1:\n nested = True\n elif char == ']':\n open_count -= 1\n # If we close a bracket and there were open brackets before, we check for nesting\n if open_count < 0:\n return False # More closing brackets than opening\n # If we have closed all opened brackets, we can stop checking\n if open_count < 0:\n return False\n \n # We need at least one nested structure and all brackets must be closed\n return nested and open_count == 0", "base_status": "fail", "plus_status": null, "base_fail_tests": [["[[]][["]], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers.\n You need to return the sum of squared numbers in the given list,\n round each element in the list to the upper int (Ceiling) first.\n \n Examples:\n For lst = [1,2,3] the output should be 14\n For lst = [1,4,9] the output should be 98\n For lst = [1,3,5,7] the output should be 84\n For lst = [1.4,4.2,0] the output should be 29\n For lst = [-2.4,1,1] the output should be 6\n \"\"\"\n # Round each number in the list to the upper integer (ceiling)\n rounded_numbers = [math.ceil(num) for num in lst]\n \n # Calculate the sum of squares of the rounded numbers\n sum_of_squares = sum(num ** 2 for num in rounded_numbers)\n \n return sum_of_squares", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n '''\n Create a function that returns True if the last character\n of a given string is an alphabetical character and is not\n a part of a word, and False otherwise.\n Note: \"word\" is a group of characters separated by space.\n\n Examples:\n check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '''\n \n # Strip any trailing whitespace from the string\n txt = txt.rstrip()\n \n # Check if the string is empty after stripping\n if not txt:\n return False\n \n # Get the last character of the string\n last_char = txt[-1]\n \n # Check if the last character is an alphabetical character\n if last_char.isalpha():\n # Check if the last character is part of a word\n # A character is part of a word if it is preceded by a non-space character\n if len(txt) > 1 and txt[-2] != ' ':\n return False\n return True\n \n return False", "base_status": "fail", "plus_status": null, "base_fail_tests": [["eeeee e "]], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n from collections import deque\n\n N = len(grid)\n directions = [(0, 1), (1, 0), (0, -1), (-1, 0)] # right, down, left, up\n min_path = None\n\n def bfs(start_row, start_col):\n queue = deque([(start_row, start_col, [grid[start_row][start_col]])])\n while queue:\n row, col, path = queue.popleft()\n if len(path) == k:\n nonlocal min_path\n if min_path is None or path < min_path:\n min_path = path\n continue\n \n for dr, dc in directions:\n new_row, new_col = row + dr, col + dc\n if 0 <= new_row < N and 0 <= new_col < N:\n queue.append((new_row, new_col, path + [grid[new_row][new_col]]))\n\n for i in range(N):\n for j in range(N):\n bfs(i, j)\n\n return min_path", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n \"\"\"Create a function which returns the largest index of an element which\n is not greater than or equal to the element immediately preceding it. If\n no such element exists then return -1. The given array will not contain\n duplicate values.\n\n Examples:\n can_arrange([1,2,4,3,5]) = 3\n can_arrange([1,2,3]) = -1\n \"\"\"\n # Check if the array is empty\n if not arr:\n return -1\n\n # Initialize the largest index to -1\n largest_index = -1\n\n # Iterate through the array starting from the second element\n for i in range(1, len(arr)):\n # Check if the current element is less than the previous element\n if arr[i] < arr[i - 1]:\n largest_index = i # Update the largest index\n\n return largest_index", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def parse_number(value):\n \"\"\"\n Convert a string representation of a number into a float or return the value as is if it's already a number.\n Handles both '.' and ',' as decimal separators.\n \"\"\"\n if isinstance(value, (int, float)):\n return float(value)\n elif isinstance(value, str):\n # Replace ',' with '.' for conversion\n value = value.replace(',', '.')\n try:\n return float(value)\n except ValueError:\n return None\n return None\ndef compare_one(a, b):\n \"\"\"\n Compare two values (integers, floats, or strings representing real numbers)\n and return the larger one in its original type, or None if they are equal.\n \"\"\"\n # Parse both values\n parsed_a = parse_number(a)\n parsed_b = parse_number(b)\n\n # If both parsed values are None, they are not comparable\n if parsed_a is None or parsed_b is None:\n return None\n\n # Compare the parsed values\n if parsed_a > parsed_b:\n return a\n elif parsed_b > parsed_a:\n return b\n else:\n return None", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n '''\n Create a function that returns a tuple (a, b), where 'a' is\n the largest of negative integers, and 'b' is the smallest\n of positive integers in a list.\n If there is no negative or positive integers, return them as None.\n\n Examples:\n largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n largest_smallest_integers([]) == (None, None)\n largest_smallest_integers([0]) == (None, None)\n '''\n \n largest_negative = None\n smallest_positive = None\n \n for num in lst:\n if num < 0:\n if largest_negative is None or num > largest_negative:\n largest_negative = num\n elif num > 0:\n if smallest_positive is None or num < smallest_positive:\n smallest_positive = num\n \n return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n \n Args:\n n (int): The number to evaluate.\n \n Returns:\n bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n \n Example:\n is_equal_to_sum_even(4) == False\n is_equal_to_sum_even(6) == False\n is_equal_to_sum_even(8) == True\n \"\"\"\n \n # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n if n < 8:\n return False\n \n # Check if n is even\n if n % 2 != 0:\n return False\n \n # If n is even and n >= 8, it can be expressed as the sum of 4 positive even numbers\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n \"\"\"Helper function to compute the factorial of a non-negative integer n.\"\"\"\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef special_factorial(n):\n \"\"\"The Brazilian factorial is defined as:\n brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!\n where n > 0\n\n For example:\n >>> special_factorial(4)\n 288\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer greater than 0.\")\n \n result = 1\n for i in range(1, n + 1):\n result *= factorial(i)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n \"\"\"\n Given a string text, replace all spaces in it with underscores, \n and if a string has more than 2 consecutive spaces, \n then replace all consecutive spaces with - \n \n fix_spaces(\"Example\") == \"Example\"\n fix_spaces(\"Example 1\") == \"Example_1\"\n fix_spaces(\" Example 2\") == \"_Example_2\"\n fix_spaces(\" Example 3\") == \"_Example-3\"\n \"\"\"\n # Replace multiple spaces with a placeholder\n text = text.replace(' ', '-').replace(' ', '-')\n \n # Replace remaining spaces with underscores\n text = text.replace(' ', '_')\n \n # Handle the case where we might have replaced too many spaces\n # We need to ensure that we only replace sequences of spaces\n # that were originally more than 2 with a single '-'\n parts = text.split('-')\n for i in range(len(parts)):\n parts[i] = parts[i].replace('_', ' ')\n \n # Join the parts back together\n result = '-'.join(part.replace(' ', '_') for part in parts)\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Yellow Yellow Dirty Fellow"]], "plus_fail_tests": []}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n \"\"\"Check if the given file name is valid based on specific criteria.\"\"\"\n \n # Check for exactly one dot\n if file_name.count('.') != 1:\n return 'No'\n \n # Split the file name into name and extension\n name, extension = file_name.split('.')\n \n # Check if the name is not empty and starts with a letter\n if not name or not name[0].isalpha():\n return 'No'\n \n # Check the number of digits in the name\n digit_count = sum(c.isdigit() for c in name)\n if digit_count > 3:\n return 'No'\n \n # Check if the extension is valid\n valid_extensions = ['txt', 'exe', 'dll']\n if extension not in valid_extensions:\n return 'No'\n \n return 'Yes'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef words_in_sentence(sentence):\n \"\"\"\n Given a string representing a sentence, return a string that contains the words\n from the original sentence whose lengths are prime numbers.\n The order of the words in the new string should be the same as the original one.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Filter words whose lengths are prime\n prime_length_words = [word for word in words if is_prime(len(word))]\n \n # Join the filtered words into a single string\n return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n \"\"\"\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n \n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126\n \"\"\"\n total_sum = 0\n \n for index, value in enumerate(lst):\n if index % 3 == 0:\n # Square the value if index is a multiple of 3\n total_sum += value ** 2\n elif index % 4 == 0:\n # Cube the value if index is a multiple of 4 and not a multiple of 3\n total_sum += value ** 3\n else:\n # Add the value unchanged if index is not a multiple of 3 or 4\n total_sum += value\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n \"\"\"\n Sorts the given list of integers in ascending order according to the sum of their digits.\n If there are several items with similar sum of their digits, they are ordered based on their\n index in the original list.\n\n Args:\n nums (list of int): The list of integers to be sorted.\n\n Returns:\n list of int: The sorted list of integers.\n \"\"\"\n \n def digit_sum(n):\n \"\"\"Calculate the sum of the digits of an integer n.\"\"\"\n return sum(int(digit) for digit in str(abs(n)))\n\n # Sort the list using a tuple (digit sum, original index)\n sorted_nums = sorted(enumerate(nums), key=lambda x: (digit_sum(x[1]), x[0]))\n \n # Extract the sorted numbers from the sorted tuples\n return [num for index, num in sorted_nums]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n \"\"\"Simplifies the expression x * n and checks if the result is a whole number.\n \n Args:\n x (str): A string representation of a fraction in the format /.\n n (str): A string representation of a fraction in the format /.\n \n Returns:\n bool: True if x * n evaluates to a whole number, False otherwise.\n \"\"\"\n # Split the fractions into numerator and denominator\n x_numerator, x_denominator = map(int, x.split('/'))\n n_numerator, n_denominator = map(int, n.split('/'))\n \n # Calculate the product of the fractions\n # x * n = (x_numerator / x_denominator) * (n_numerator / n_denominator)\n # This simplifies to (x_numerator * n_numerator) / (x_denominator * n_denominator)\n \n product_numerator = x_numerator * n_numerator\n product_denominator = x_denominator * n_denominator\n \n # Check if the product is a whole number\n return product_numerator % product_denominator == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n \"\"\"Returns the number of elements in the array that are greater than 10 \n and both the first and last digits of the number are odd (1, 3, 5, 7, 9).\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n int: The count of numbers meeting the criteria.\n \"\"\"\n \n def is_odd_digit(digit):\n \"\"\"Check if a digit is odd.\"\"\"\n return digit in {'1', '3', '5', '7', '9'}\n \n count = 0\n \n for num in nums:\n if num > 10:\n str_num = str(abs(num)) # Convert to string and take absolute value\n first_digit = str_num[0]\n last_digit = str_num[-1]\n \n if is_odd_digit(first_digit) and is_odd_digit(last_digit):\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n \"\"\"\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example :\n Input: n = 5\n Output: 1\n Explanation: \n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n \"\"\"\n # Create the array a based on the given formula\n a = [i * i - i + 1 for i in range(1, n + 1)]\n \n # Count the number of valid triples\n count = 0\n \n # Iterate through all possible triples (i, j, k)\n for i in range(n):\n for j in range(i + 1, n):\n for k in range(j + 1, n):\n if (a[i] + a[j] + a[k]) % 3 == 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length and alphabetically.\n \n Args:\n lst (list of str): A list of strings.\n \n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the filtered list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closest to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sorted by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct planet names. \n Examples\n bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n '''\n \n # List of planets in order from the Sun\n planets = [\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n ]\n \n # Check if the provided planet names are valid\n if planet1 not in planets or planet2 not in planets:\n return ()\n \n # Get the indices of the planets\n index1 = planets.index(planet1)\n index2 = planets.index(planet2)\n \n # Determine the range of indices for the planets in between\n start_index = min(index1, index2) + 1\n end_index = max(index1, index2)\n \n # Get the planets in between and return them as a tuple\n return tuple(planets[start_index:end_index])", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef x_or_y(n, x, y):\n \"\"\"Return x if n is a prime number, otherwise return y.\"\"\"\n if is_prime(n):\n return x\n else:\n return y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n \n double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n double_the_difference([-1, -2, 0]) == 0\n double_the_difference([9, -2]) == 81\n double_the_difference([0]) == 0 \n \n If the input list is empty, return 0.\n '''\n # Initialize the sum of squares\n sum_of_squares = 0\n \n # Iterate through each number in the list\n for num in lst:\n # Check if the number is a positive odd integer\n if isinstance(num, int) and num >= 0 and num % 2 != 0:\n # Add the square of the odd number to the sum\n sum_of_squares += num ** 2\n \n return sum_of_squares", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n \"\"\"Find the strongest extension based on the defined strength criteria.\"\"\"\n \n def calculate_strength(extension):\n \"\"\"Calculate the strength of the extension.\"\"\"\n CAP = sum(1 for char in extension if char.isupper())\n SM = sum(1 for char in extension if char.islower())\n return CAP - SM\n\n strongest_extension = None\n strongest_strength = float('-inf') # Start with the lowest possible strength\n\n for extension in extensions:\n strength = calculate_strength(extension)\n \n # Check if this extension is stronger or if it's the first one\n if strength > strongest_strength:\n strongest_strength = strength\n strongest_extension = extension\n\n # Return the result in the required format\n return f\"{class_name}.{strongest_extension}\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n \"\"\"\n Compares the actual scores of matches with the guessed scores.\n \n Parameters:\n game (list of int): The actual scores of the matches.\n guess (list of int): The guessed scores of the matches.\n \n Returns:\n list of int: An array where each element is the absolute difference \n between the actual score and the guessed score, or 0 if \n the guess was correct.\n \"\"\"\n # Check if the lengths of game and guess are equal\n if len(game) != len(guess):\n raise ValueError(\"The length of game and guess must be the same.\")\n \n # Calculate the absolute differences\n result = [abs(g - a) for a, g in zip(game, guess)]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n \"\"\"Check if the second word or any of its rotations is a substring in the first word.\"\"\"\n \n # Edge case: if b is empty, it is considered a substring of any string\n if not b:\n return True\n \n # Edge case: if b is longer than a, it cannot be a substring\n if len(b) > len(a):\n return False\n \n # Create a new string that is the concatenation of b with itself\n # This will contain all possible rotations of b as substrings\n b_rotations = b + b\n \n # Check if any rotation of b is a substring of a\n return b_rotations.find(a) != -1", "base_status": "fail", "plus_status": null, "base_fail_tests": [["yello", "ell"]], "plus_fail_tests": []}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n Example:\n even_odd_count(-12) ==> (1, 1)\n even_odd_count(123) ==> (1, 2)\n \"\"\"\n # Convert the number to its absolute value to handle negative numbers\n num = abs(num)\n \n # Initialize counters for even and odd digits\n even_count = 0\n odd_count = 0\n \n # Convert the number to a string to iterate over each digit\n for digit in str(num):\n # Check if the digit is even or odd\n if int(digit) % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return True if the three\n sides form a right-angled triangle, False otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or \n 90 degree.\n \n Example:\n right_angle_triangle(3, 4, 5) == True\n right_angle_triangle(1, 2, 3) == False\n '''\n \n # First, we need to check if the sides can form a triangle\n if a <= 0 or b <= 0 or c <= 0:\n return False # Sides must be positive\n \n # Sort the sides to easily identify the longest side\n sides = sorted([a, b, c])\n \n # Check the Pythagorean theorem: a^2 + b^2 = c^2\n return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n \n if not (1 <= number <= 1000):\n raise ValueError(\"Number must be between 1 and 1000 inclusive.\")\n \n # Mapping of integers to their Roman numeral equivalents\n roman_numerals = [\n (1000, 'm'),\n (900, 'cm'),\n (500, 'd'),\n (400, 'cd'),\n (100, 'c'),\n (90, 'xc'),\n (50, 'l'),\n (40, 'xl'),\n (10, 'x'),\n (9, 'ix'),\n (5, 'v'),\n (4, 'iv'),\n (1, 'i')\n ]\n \n result = []\n \n for value, numeral in roman_numerals:\n while number >= value:\n result.append(numeral)\n number -= value\n \n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n \"\"\"Return the word with the maximum number of unique characters.\n If multiple words have the same maximum number of unique characters,\n return the one that comes first in lexicographical order.\n \n Args:\n words (list of str): A list of words to evaluate.\n \n Returns:\n str: The word with the maximum number of unique characters.\n \"\"\"\n max_word = \"\"\n max_unique_count = 0\n\n for word in words:\n # Calculate the number of unique characters in the current word\n unique_count = len(set(word))\n \n # Check if this word has more unique characters or is lexicographically smaller\n if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n max_word = word\n max_unique_count = unique_count\n\n return max_word", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n \"\"\"\n You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n \n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n \n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots that exist in stock\n \n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n \"\"\"\n \n # Calculate how many more carrots are needed\n additional_needed = need - number\n \n # If no additional carrots are needed, return the current state\n if additional_needed <= 0:\n return [number, remaining]\n \n # Determine how many carrots can be eaten from the remaining stock\n if remaining >= additional_needed:\n total_eaten = number + additional_needed\n carrots_left = remaining - additional_needed\n else:\n total_eaten = number + remaining\n carrots_left = 0 # All remaining carrots are eaten\n \n return [total_eaten, carrots_left]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic algebra operations, and \n the second list is a list of integers. Use the two given lists to build the algebraic \n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + ) \n Subtraction ( - ) \n Multiplication ( * ) \n Floor division ( // ) \n Exponentiation ( ** ) \n\n Example:\n operator = ['+', '*', '-']\n operand = [2, 3, 4, 5]\n result = 2 + 3 * 4 - 5\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.\n \"\"\"\n \n # Start with the first operand\n result = operand[0]\n \n # Iterate through the operators and operands\n for i in range(len(operator)):\n op = operator[i]\n next_operand = operand[i + 1]\n \n if op == '+':\n result += next_operand\n elif op == '-':\n result -= next_operand\n elif op == '*':\n result *= next_operand\n elif op == '//':\n # Handle division by zero\n if next_operand == 0:\n raise ValueError(\"Division by zero is not allowed.\")\n result //= next_operand\n elif op == '**':\n result **= next_operand\n else:\n raise ValueError(f\"Invalid operator: {op}\")\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": []}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n \"\"\"You are given a string s.\n if s[i] is a letter, reverse its case from lower to upper or vise versa, \n otherwise keep it as it is.\n If the string contains no letters, reverse the string.\n The function should return the resulted string.\n Examples\n solve(\"1234\") = \"4321\"\n solve(\"ab\") = \"AB\"\n solve(\"#a@C\") = \"#A@c\"\n \"\"\"\n # Check if there are any letters in the string\n has_letters = any(c.isalpha() for c in s)\n \n if has_letters:\n # If there are letters, reverse the case of each letter\n result = ''.join(c.swapcase() if c.isalpha() else c for c in s)\n else:\n # If there are no letters, reverse the string\n result = s[::-1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascending order.\n\n For example:\n generate_integers(2, 8) => [2, 4, 6, 8]\n generate_integers(8, 2) => [2, 4, 6, 8]\n generate_integers(10, 14) => []\n \"\"\"\n # Ensure a is less than or equal to b\n start = min(a, b)\n end = max(a, b)\n\n # Generate a list of even integers in the range\n even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n return even_integers", "base_status": "fail", "plus_status": null, "base_fail_tests": [[2, 10]], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string.\n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n \"\"\"\n if text == \"\":\n return None\n # Create an MD5 hash object\n md5_hash = hashlib.md5()\n # Update the hash object with the bytes of the string\n md5_hash.update(text.encode('utf-8'))\n # Return the hexadecimal digest of the hash\n return md5_hash.hexdigest()", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}]}} \ No newline at end of file diff --git a/llm_based_137_eval_results.json b/llm_based_137_eval_results.json new file mode 100644 index 000000000..6884a929e --- /dev/null +++ b/llm_based_137_eval_results.json @@ -0,0 +1 @@ +{"date": "2024-07-27 00:48", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" \n Input to this function is a string containing multiple groups of nested parentheses. \n The goal is to separate those groups into separate strings and return the list of those.\n Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n Ignore any spaces in the input string.\n \n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n # Remove spaces from the input string\n paren_string = paren_string.replace(\" \", \"\")\n \n result = []\n current_group = []\n balance = 0\n \n for char in paren_string:\n if char == '(':\n balance += 1\n current_group.append(char)\n elif char == ')':\n balance -= 1\n current_group.append(char)\n \n # When balance is zero, we have a complete group\n if balance == 0 and current_group:\n result.append(''.join(current_group))\n current_group = [] # Reset for the next group\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to make it easier to find close elements\n numbers.sort()\n \n # Check the differences between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" \n You're given a list of deposit and withdrawal operations on a bank account that starts with\n zero balance. Your task is to detect if at any point the balance of account falls below zero, and\n at that point function should return True. Otherwise it should return False.\n \n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n \"\"\"\n balance = 0 # Start with a zero balance\n for operation in operations:\n balance += operation # Update the balance with the current operation\n if balance < 0: # Check if the balance falls below zero\n return True # Return True if it does\n return False # Return False if the balance never falls below zero", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into\n an integer part (largest integer smaller than given number) and decimals\n (leftover part always smaller than 1).\n\n Return the decimal part of the number.\n >>> truncate_number(3.5)\n 0.5\n \"\"\"\n if number < 0:\n raise ValueError(\"The number must be positive.\")\n \n # Get the integer part by using the floor function\n integer_part = int(number) # This truncates the decimal part\n # Calculate the decimal part\n decimal_part = number - integer_part\n \n return decimal_part", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n \"\"\" Insert a number 'delimiter' between every two consecutive elements of input list `numbers'\n \n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n for i in range(len(numbers)):\n result.append(numbers[i])\n if i < len(numbers) - 1: # Avoid adding delimiter after the last element\n result.append(delimiter)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list to avoid division by zero\n\n # Calculate the mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute deviations from the mean\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n \n # Calculate the mean of the absolute deviations\n mad = sum(absolute_deviations) / len(absolute_deviations)\n \n return mad", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n def max_nesting_depth(s: str) -> int:\n max_depth = 0\n current_depth = 0\n \n for char in s:\n if char == '(':\n current_depth += 1\n max_depth = max(max_depth, current_depth)\n elif char == ')':\n current_depth -= 1\n if current_depth < 0: # More closing than opening\n return -1 # Invalid case\n return max_depth if current_depth == 0 else -1 # Valid if all opened are closed\n\n groups = paren_string.split()\n depths = []\n \n for group in groups:\n depth = max_nesting_depth(group)\n depths.append(depth if depth != -1 else 0) # Return 0 for invalid cases\n\n return depths", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring.\n \n Args:\n strings (List[str]): A list of strings to filter.\n substring (str): The substring to search for within the strings.\n \n Returns:\n List[str]: A list of strings that contain the given substring.\n \n Examples:\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n \"\"\"\n # Use a list comprehension to filter the strings\n return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers: # Handle the case of an empty list\n return []\n \n max_so_far = numbers[0] # Initialize the maximum with the first element\n result = [max_so_far] # Start the result list with the first maximum\n \n for number in numbers[1:]: # Iterate through the rest of the numbers\n if number > max_so_far:\n max_so_far = number # Update the maximum if the current number is greater\n result.append(max_so_far) # Append the current maximum to the result list\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n \n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n \"\"\"\n if not numbers: # Check if the list is empty\n return (0, 1) # Return (0, 1) for empty input\n \n total_sum = 0 # Initialize sum\n total_product = 1 # Initialize product\n \n for number in numbers:\n total_sum += number # Add each number to the sum\n total_product *= number # Multiply each number to the product\n \n return (total_sum, total_product) # Return the final sum and product", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n \"\"\" \n Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n \n >>> string_xor('010', '110')\n '100'\n \"\"\"\n # Ensure both strings are of the same length by padding with leading zeros\n max_length = max(len(a), len(b))\n a = a.zfill(max_length)\n b = b.zfill(max_length)\n \n # Perform XOR operation\n result = []\n for bit_a, bit_b in zip(a, b):\n # XOR operation: '1' if bits are different, '0' if they are the same\n result.append('1' if bit_a != bit_b else '0')\n \n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n \"\"\"\n if not string:\n return ''\n \n # Find the longest palindromic suffix\n for i in range(len(string)):\n if is_palindrome(string[i:]):\n # If the suffix starting from index i is a palindrome\n # Take the prefix before this suffix and reverse it\n prefix = string[:i]\n return string + prefix[::-1]\n \n # If no palindromic suffix is found, the whole string is non-palindromic\n return string + string[:-1][::-1] # Append the reverse of the string minus the last character", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n \n >>> longest([])\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n \"\"\"\n if not strings:\n return None\n \n longest_string = strings[0]\n \n for string in strings:\n if len(string) > len(longest_string):\n longest_string = string\n \n return longest_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return the greatest common divisor of two integers a and b.\n \n The function uses the Euclidean algorithm to compute the GCD.\n \n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n \"\"\"\n # Handle negative inputs by taking the absolute value\n a, b = abs(a), abs(b)\n \n # Base case: if one of the numbers is zero, return the other number\n if b == 0:\n return a\n # Recursive case: apply the Euclidean algorithm\n return greatest_common_divisor(b, a % b)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string.\n \n Args:\n string (str): The input string from which to generate prefixes.\n \n Returns:\n List[str]: A list of all prefixes of the input string.\n \n Examples:\n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n \"\"\"\n # Initialize an empty list to store the prefixes\n prefixes = []\n \n # Iterate over the range of the length of the string\n for i in range(1, len(string) + 1):\n # Append the substring from the start to the current index\n prefixes.append(string[:i])\n \n return prefixes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set()\n \n # Iterate through each character in the string\n for char in lower_string:\n # Add the character to the set\n distinct_characters.add(char)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n \n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n \"\"\"\n # Check if n is negative\n if n < 0:\n return \"\"\n \n # Create a list of numbers from 0 to n\n numbers = [str(i) for i in range(n + 1)]\n \n # Join the list into a single string with spaces\n return ' '.join(numbers)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string representing musical notes in a special ASCII format.\n Your task is to parse this string and return list of integers corresponding to how many beats does each\n note last.\n\n Here is a legend:\n 'o' - whole note, lasts four beats\n 'o|' - half note, lasts two beats\n '.|' - quarter note, lasts one beat\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n # Define a mapping of note representations to their corresponding beat values\n note_to_beats = {\n 'o': 4, # whole note\n 'o|': 2, # half note\n '.|': 1 # quarter note\n }\n \n # Split the input string into individual notes\n notes = music_string.split()\n \n # Initialize a list to hold the beats for each note\n beats = []\n \n # Iterate over each note and convert it to its corresponding beat value\n for note in notes:\n if note in note_to_beats:\n beats.append(note_to_beats[note])\n else:\n # If the note is not recognized, we can choose to ignore it or raise an error\n # Here we will ignore it for robustness\n continue\n \n return beats", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n \n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n \"\"\"\n if not substring: # If the substring is empty, return 0\n return 0\n \n count = 0\n start = 0\n \n while True:\n start = string.find(substring, start) # Find the substring starting from 'start'\n if start == -1: # If no more occurrences are found, break the loop\n break\n count += 1 # Increment the count for each found occurrence\n start += 1 # Move to the next character to allow for overlapping matches\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n \"\"\" \n Input is a space-delimited string of numerals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest.\n \n >>> sort_numbers('three one five')\n 'one three five'\n \"\"\"\n \n # Mapping of words to their corresponding numeric values\n word_to_number = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n \n # Split the input string into words\n words = numbers.split()\n \n # Convert words to their corresponding numeric values\n numeric_values = [word_to_number[word] for word in words]\n \n # Sort the numeric values\n sorted_values = sorted(numeric_values)\n \n # Convert sorted numeric values back to words\n number_to_word = {v: k for k, v in word_to_number.items()}\n sorted_words = [number_to_word[value] for value in sorted_values]\n \n # Join the sorted words into a single string\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to make it easier to find the closest pairs\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest elements\n for i in range(len(sorted_numbers) - 1):\n # Calculate the difference between consecutive elements\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n \n # If this difference is smaller than the minimum found so far, update\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1.\n \n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The input list must contain at least two elements.\")\n \n min_value = min(numbers)\n max_value = max(numbers)\n \n if min_value == max_value:\n # If all numbers are the same, return a list of zeros\n return [0.0] * len(numbers)\n \n # Rescale the numbers\n rescaled = [(num - min_value) / (max_value - min_value) for num in numbers]\n \n return rescaled", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n \"\"\" Return length of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n \"\"\"\n # Initialize a counter for the length\n length = 0\n \n # Iterate through each character in the string\n for char in string:\n length += 1 # Increment the length for each character\n \n return length", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers \"\"\"\n return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n \n >>> largest_divisor(15)\n 5\n \"\"\"\n # Edge case: if n is less than or equal to 1, there are no divisors smaller than n\n if n <= 1:\n return None # or raise an exception, depending on how you want to handle this case\n\n # Start checking from n-1 down to 1\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n Input number should be equal to the product of all factors\n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n \"\"\"\n if n <= 1:\n return [] # No prime factors for numbers less than or equal to 1\n\n factors = []\n # Check for number of 2s that divide n\n while n % 2 == 0:\n factors.append(2)\n n //= 2\n\n # n must be odd at this point, so we can skip even numbers\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n factors.append(i)\n n //= i\n\n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n factors.append(n)\n\n return factors", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n \n >>> flip_case('Hello')\n 'hELLO'\n \"\"\"\n # Initialize an empty list to store the flipped characters\n flipped_chars = []\n \n # Iterate through each character in the input string\n for char in string:\n # Check if the character is lowercase\n if char.islower():\n # Convert to uppercase\n flipped_chars.append(char.upper())\n # Check if the character is uppercase\n elif char.isupper():\n # Convert to lowercase\n flipped_chars.append(char.lower())\n else:\n # If it's neither, keep the character as is (e.g., punctuation, numbers)\n flipped_chars.append(char)\n \n # Join the list of flipped characters into a single string and return it\n return ''.join(flipped_chars)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a dictionary to count occurrences of each number\n count = {}\n \n # Count each number's occurrences\n for number in numbers:\n if number in count:\n count[number] += 1\n else:\n count[number] = 1\n \n # Create a list for the result, keeping the order of elements\n result = []\n \n # Add numbers that occur only once to the result\n for number in numbers:\n if count[number] == 1:\n result.append(number)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string.\n \n Args:\n strings (List[str]): A list of strings to concatenate.\n \n Returns:\n str: A single concatenated string.\n \n Examples:\n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n \"\"\"\n # Initialize an empty string to hold the result\n result = ''\n \n # Iterate over each string in the list and concatenate\n for string in strings:\n result += string\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n \n Args:\n strings (List[str]): A list of strings to filter.\n prefix (str): The prefix to filter the strings by.\n \n Returns:\n List[str]: A list of strings that start with the given prefix.\n \n Examples:\n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n \"\"\"\n # Use a list comprehension to filter the strings\n return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n A prime number is a natural number greater than 1 that cannot be formed by multiplying two smaller natural numbers.\n \n Args:\n n (int): The number to check for primality.\n \n Returns:\n bool: True if n is prime, False otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return False # eliminate multiples of 2 and 3\n\n i = 5\n while i * i <= n: # check for factors from 5 to sqrt(n)\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6 # check for next potential factors (6k \u00b1 1)\n\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n \n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n \"\"\"\n return [x for x in l if x > 0]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float) -> float:\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list) -> list:\n \"\"\"\n Returns the coefficients of the derivative of the polynomial.\n If xs = [a0, a1, a2, ..., an], then the derivative is\n [a1, 2*a2, 3*a3, ..., n*an].\n \"\"\"\n return [i * coeff for i, coeff in enumerate(xs) if i > 0]\ndef find_zero(xs: list) -> float:\n \"\"\" \n xs are coefficients of a polynomial.\n find_zero finds x such that poly(x) = 0.\n find_zero returns only one zero point, even if there are many.\n Moreover, find_zero only takes list xs having an even number of coefficients\n and the largest non-zero coefficient as it guarantees a solution.\n \"\"\"\n if len(xs) % 2 != 0:\n raise ValueError(\"The number of coefficients must be even.\")\n \n # Initial guess (can be improved based on the polynomial)\n x = 0.0\n \n # Newton-Raphson method\n for _ in range(100): # Limit iterations to avoid infinite loops\n f_x = poly(xs, x)\n f_prime_x = poly(derivative(xs), x)\n \n if f_prime_x == 0: # Avoid division by zero\n raise ValueError(\"Derivative is zero. No solution found.\")\n \n # Update x using Newton's method\n x_new = x - f_x / f_prime_x\n \n # Check for convergence\n if abs(x_new - x) < 1e-7:\n return x_new\n \n x = x_new\n \n raise ValueError(\"Maximum iterations reached. No solution found.\")", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[-10, -2]]], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n values_to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(values_to_sort)\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Replace values at indices divisible by 3 with sorted values\n for index, value in zip(range(len(result)), sorted_values):\n if index % 3 == 0:\n result[index] = value\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]]], "plus_fail_tests": []}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n \"\"\"Return maximum element in the list.\n \n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n \"\"\"\n if not l: # Check if the list is empty\n raise ValueError(\"The list is empty. Cannot determine the maximum element.\")\n \n max_value = l[0] # Initialize max_value with the first element\n for element in l: # Iterate through each element in the list\n if element > max_value: # Compare with current max_value\n max_value = element # Update max_value if a larger element is found\n \n return max_value # Return the maximum value found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n This function takes a list of elements, removes duplicates, and returns a sorted list of unique elements.\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use a set to remove duplicates\n unique_elements = set(l)\n # Sort the unique elements and return as a list\n return sorted(unique_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indexed elements\n even_indices_values.sort()\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Place the sorted even indexed values back into their positions\n for i, value in enumerate(even_indices_values):\n result[i * 2] = value # Place sorted value at even index\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_fib(n: int) -> int:\n \"\"\"\n prime_fib returns the n-th number that is a Fibonacci number and it's also prime.\n \n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n count = 0\n for fib in fibonacci_generator():\n if is_prime(fib):\n count += 1\n if count == n:\n return fib", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1]], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with the encode_cyclic function.\n Returns the decoded string.\n \"\"\"\n # Split string into groups of length 3\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # Reverse the cycling for each group\n groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n \"\"\"\n Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move at the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.\n\n :param n: The number of cars in each direction.\n :return: The number of collisions.\n \"\"\"\n # Each car moving left to right will collide with each car moving right to left.\n # Therefore, the total number of collisions is simply n * n.\n return n * n", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n \"\"\"\n triples_sum_to_zero takes a list of integers as an input.\n it returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n \"\"\"\n n = len(l)\n if n < 3:\n return False\n\n # Sort the list to use the two-pointer technique\n l.sort()\n\n for i in range(n - 2):\n # Avoid duplicates for the first element\n if i > 0 and l[i] == l[i - 1]:\n continue\n \n left, right = i + 1, n - 1\n while left < right:\n current_sum = l[i] + l[left] + l[right]\n if current_sum == 0:\n return True\n elif current_sum < 0:\n left += 1\n else:\n right -= 1\n\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n \n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n \"\"\"\n # Check if the input is a list\n if not isinstance(l, list):\n raise ValueError(\"Input must be a list.\")\n \n # Increment each element in the list by 1\n return [x + 1 for x in l]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n \n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n \"\"\"\n seen = set()\n for number in l:\n if -number in seen:\n return True\n seen.add(number)\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion.\n base numbers are less than 10.\n \n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n \"\"\"\n if base < 2 or base >= 10:\n raise ValueError(\"Base must be between 2 and 9 (inclusive).\")\n \n if x == 0:\n return '0'\n \n result = []\n negative = x < 0\n x = abs(x)\n \n while x > 0:\n remainder = x % base\n result.append(str(remainder))\n x //= base\n \n if negative:\n result.append('-')\n \n # The result is built in reverse order\n return ''.join(reversed(result))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n \"\"\"Given length of a side and height, return the area for a triangle.\n \n The area of a triangle can be calculated using the formula:\n Area = (base * height) / 2\n \n Parameters:\n a (float): The length of the base of the triangle.\n h (float): The height of the triangle.\n \n Returns:\n float: The area of the triangle.\n \n Raises:\n ValueError: If the base or height is not a positive number.\n \n >>> triangle_area(5, 3)\n 7.5\n >>> triangle_area(0, 3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(5, -3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(-5, 3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n \"\"\"\n \n # Validate inputs\n if a <= 0 or h <= 0:\n raise ValueError(\"Base and height must be positive numbers.\")\n \n # Calculate area\n area = (a * h) / 2\n return area", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fib4(0) -> 0\n fib4(1) -> 0\n fib4(2) -> 2\n fib4(3) -> 0\n fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n This function computes the n-th element of the fib4 number sequence efficiently without recursion.\n \n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n # Handle base cases\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 2\n elif n == 3:\n return 0\n \n # Initialize a list to store computed values\n fib_values = [0] * (n + 1)\n fib_values[0] = 0\n fib_values[1] = 0\n fib_values[2] = 2\n fib_values[3] = 0\n \n # Compute the fib4 values iteratively\n for i in range(4, n + 1):\n fib_values[i] = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n \n return fib_values[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n \"\"\"\n Checks if given string is a palindrome.\n \n A palindrome is a string that reads the same forward and backward.\n \n Args:\n text (str): The string to check.\n \n Returns:\n bool: True if the string is a palindrome, False otherwise.\n \n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n \"\"\"\n # Normalize the string by removing spaces and converting to lowercase\n normalized_text = text.replace(\" \", \"\").lower()\n \n # Check if the normalized string is equal to its reverse\n return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n \"\"\"Return median of elements in the list l.\n \n The median is the middle value in a list of numbers. If the list has an odd number of elements,\n the median is the middle element. If the list has an even number of elements, the median is the\n average of the two middle elements.\n \n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty. Cannot compute median.\")\n \n # Sort the list\n sorted_list = sorted(l)\n n = len(sorted_list)\n \n # Calculate median\n if n % 2 == 1: # Odd number of elements\n return sorted_list[n // 2]\n else: # Even number of elements\n mid1 = sorted_list[n // 2 - 1]\n mid2 = sorted_list[n // 2]\n return (mid1 + mid2) / 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n if p <= 0:\n raise ValueError(\"p must be a positive integer.\")\n \n # Handle the case when n is negative\n if n < 0:\n return 0 # 2^n is not defined for negative n in this context\n \n result = 1\n base = 2\n \n # Use modular exponentiation\n while n > 0:\n if n % 2 == 1: # If n is odd\n result = (result * base) % p\n base = (base * base) % p # Square the base\n n //= 2 # Divide n by 2\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with encode_shift function.\n Returns decoded string by shifting every character back by 5 in the alphabet.\n Non-alphabetic characters are not changed.\n \"\"\"\n return \"\".join([\n chr(((ord(ch) - ord(\"a\") - 5) % 26) + ord(\"a\")) if 'a' <= ch <= 'z' else ch\n for ch in s\n ])", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n Vowels are defined as 'a', 'e', 'i', 'o', 'u' in both lowercase and uppercase.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n \"\"\"Return True if all numbers in the list l are below threshold t.\n \n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n \"\"\"\n # Check if all elements in the list are below the threshold\n for number in l:\n if number >= t:\n return False\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two words have the same characters if they contain the same unique characters,\n regardless of the frequency of those characters.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Create a set of characters for each string\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Compare the two sets\n return set_s0 == set_s1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n \"\"\"Add two numbers x and y.\n\n This function takes two integers and returns their sum. \n It handles both positive and negative integers, as well as zero.\n\n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n >>> add(-1, 1)\n 0\n >>> add(-5, -7)\n -12\n >>> add(0, 0)\n 0\n >>> add(1000000, 2000000)\n 3000000\n >>> add(-1000000, 1000000)\n 0\n \"\"\"\n return x + y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n \"\"\"Return n-th Fibonacci number.\n \n The Fibonacci sequence is defined as follows:\n - fib(0) = 0\n - fib(1) = 1\n - fib(n) = fib(n-1) + fib(n-2) for n > 1\n \n Args:\n n (int): The index of the Fibonacci number to return.\n \n Returns:\n int: The n-th Fibonacci number.\n \n Raises:\n ValueError: If n is negative.\n \n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n \"\"\"\n if n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n if n == 0:\n return 0\n elif n == 1:\n return 1\n \n a, b = 0, 1\n for _ in range(2, n + 1):\n a, b = b, a + b\n \n return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"<\" and \">\".\n return True if every opening bracket has a corresponding closing bracket.\n \"\"\"\n balance = 0\n \n for char in brackets:\n if char == '<':\n balance += 1\n elif char == '>':\n balance -= 1\n \n # If balance goes negative, it means there's a closing bracket without a matching opening bracket\n if balance < 0:\n return False\n \n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n \"\"\"Return True if list elements are monotonically increasing or decreasing.\n \n A list is considered monotonically increasing if each element is greater than or equal to the previous one.\n A list is considered monotonically decreasing if each element is less than or equal to the previous one.\n \n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n \"\"\"\n if len(l) < 2:\n return True # A list with 0 or 1 element is trivially monotonic\n\n increasing = decreasing = True\n\n for i in range(1, len(l)):\n if l[i] > l[i - 1]:\n decreasing = False\n elif l[i] < l[i - 1]:\n increasing = False\n\n return increasing or decreasing", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n largest_factor = None\n \n # Check for number of 2s that divide n\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # n must be odd at this point, so we can skip even numbers\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n \n return largest_factor", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n \n Args:\n n (int): The upper limit of the summation (inclusive).\n \n Returns:\n int: The sum of all integers from 1 to n.\n \n Examples:\n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n \"\"\"\n if n < 1:\n return 0 # Return 0 for non-positive integers as they don't contribute to the sum.\n \n return n * (n + 1) // 2 # Using the formula for the sum of the first n natural numbers.", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n \"\"\" \n Calculate the derivative of a polynomial represented by its coefficients.\n \n The polynomial is represented as:\n xs[0] + xs[1] * x + xs[2] * x^2 + ...\n \n The derivative is calculated as:\n d/dx (a_n * x^n) = n * a_n * x^(n-1)\n \n Args:\n xs (list): A list of coefficients where the index represents the power of x.\n \n Returns:\n list: A list of coefficients representing the derivative of the polynomial.\n \n Examples:\n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n \"\"\"\n # Check if the input list is empty\n if not xs:\n return []\n \n # Calculate the derivative coefficients\n derivative_coeffs = []\n for i in range(1, len(xs)):\n derivative_coeffs.append(i * xs[i])\n \n return derivative_coeffs", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"(\" and \")\".\n return True if every opening bracket has a corresponding closing bracket.\n \"\"\"\n balance = 0\n \n for char in brackets:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n \n # If balance goes negative, it means there's a closing bracket without a matching opening bracket\n if balance < 0:\n return False\n \n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n \n Args:\n n (int): The index of the FibFib sequence to compute.\n \n Returns:\n int: The n-th element of the FibFib sequence.\n \n Examples:\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 1\n \n # Initialize the first three values of the sequence\n fibfib_values = [0, 0, 1]\n \n # Compute the values iteratively up to n\n for i in range(3, n + 1):\n next_value = fibfib_values[i - 1] + fibfib_values[i - 2] + fibfib_values[i - 3]\n fibfib_values.append(next_value)\n \n return fibfib_values[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set('aeiouAEIOU')\n count = 0\n \n # Iterate through the string\n for i in range(len(s)):\n # Check if the character is a vowel\n if s[i] in vowels:\n count += 1\n # Check if the character is 'y' and at the end of the string\n elif s[i].lower() == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n \n >>> circular_shift(12, 1)\n \"21\"\n >>> circular_shift(12, 2)\n \"12\"\n \"\"\"\n # Convert the integer to a string to work with its digits\n str_x = str(x)\n num_digits = len(str_x)\n \n # If shift is greater than the number of digits, reverse the digits\n if shift >= num_digits:\n return str_x[::-1]\n \n # Calculate the effective shift (in case shift is larger than num_digits)\n effective_shift = shift % num_digits\n \n # Perform the circular shift\n if effective_shift == 0:\n return str_x # No shift needed\n else:\n # Shift the string\n return str_x[-effective_shift:] + str_x[:-effective_shift]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[12, 2]], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n \"\"\"Task\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n \"\"\"\n # Initialize the sum of ASCII values\n total_sum = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is uppercase\n if char.isupper():\n # Add the ASCII value of the uppercase character to the total sum\n total_sum += ord(char)\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n \"\"\"\n Calculate the number of mango fruits in a basket given the number of apples and oranges.\n\n Parameters:\n s (str): A string representing the number of apples and oranges in the format \"X apples and Y oranges\".\n n (int): The total number of fruits in the basket.\n\n Returns:\n int: The number of mango fruits in the basket.\n \"\"\"\n # Split the input string to extract the number of apples and oranges\n parts = s.split(\" and \")\n apples = int(parts[0].split()[0]) # Get the number of apples\n oranges = int(parts[1].split()[0]) # Get the number of oranges\n\n # Calculate the number of mangoes\n mangoes = n - apples - oranges\n\n return mangoes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n \"\"\"\n Given an array representing a branch of a tree that has non-negative integer nodes,\n your task is to pluck one of the nodes and return it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n The plucked node should be returned in a list, [ smallest_value, its index ],\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1]\n\n Example 3:\n Input: []\n Output: []\n\n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n \"\"\"\n smallest_even_value = float('inf')\n smallest_index = -1\n\n for index, value in enumerate(arr):\n if value % 2 == 0: # Check if the value is even\n if value < smallest_even_value: # Found a smaller even value\n smallest_even_value = value\n smallest_index = index\n\n if smallest_index == -1: # No even value found\n return []\n \n return [smallest_even_value, smallest_index]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n '''\n Given list of integers, return list in strange order.\n Strange sorting, is when you start with the minimum value,\n then maximum of the remaining integers, then minimum and so on.\n\n Examples:\n strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n strange_sort_list([]) == []\n '''\n if not lst:\n return []\n\n # Sort the list to easily access min and max values\n sorted_lst = sorted(lst)\n result = []\n \n # Use two pointers to select min and max alternately\n left = 0\n right = len(sorted_lst) - 1\n \n while left <= right:\n if left == right: # If both pointers meet, add the last element\n result.append(sorted_lst[left])\n else:\n result.append(sorted_lst[left]) # Add the minimum\n result.append(sorted_lst[right]) # Add the maximum\n left += 1\n right -= 1\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n '''\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequency greater than or equal to the value of the integer itself. \n The frequency of an integer is the number of times it appears in the list.\n If no such a value exist, return -1.\n Examples:\n search([4, 1, 2, 2, 3, 1]) == 2\n search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n search([5, 5, 4, 4, 4]) == -1\n '''\n from collections import Counter\n\n # Count the frequency of each integer in the list\n frequency = Counter(lst)\n\n # Initialize the result variable to -1\n result = -1\n\n # Iterate through the frequency dictionary\n for num in frequency:\n # Check if the frequency is greater than or equal to the number itself\n if frequency[num] >= num:\n # Update the result if the current number is greater than the current result\n result = max(result, num)\n\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n '''\n Write a function that returns True if the object q will fly, and False otherwise.\n The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n '''\n # Check if the list is a palindrome\n is_balanced = (q == q[::-1])\n \n # Calculate the sum of the elements in the list\n total_weight = sum(q)\n \n # Determine if the object will fly\n return is_balanced and (total_weight <= w)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return the area of\n the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n Otherwise return -1.\n Three sides make a valid triangle when the sum of any two sides is greater \n than the third side.\n '''\n # Check for valid triangle condition\n if a <= 0 or b <= 0 or c <= 0:\n return -1\n if a + b <= c or a + c <= b or b + c <= a:\n return -1\n \n # Calculate the semi-perimeter\n s = (a + b + c) / 2\n \n # Calculate the area using Heron's formula\n area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n \n # Return the area rounded to 2 decimal points\n return round(area, 2)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n \"\"\"\n Given an array arr of integers, find the minimum number of elements that\n need to be changed to make the array palindromic. A palindromic array is an array that\n is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n For example:\n smallest_change([1,2,3,5,4,7,9,6]) == 4\n smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n smallest_change([1, 2, 3, 2, 1]) == 0\n \"\"\"\n n = len(arr)\n changes = 0\n \n # Compare elements from the start and end towards the center\n for i in range(n // 2):\n if arr[i] != arr[n - 1 - i]:\n changes += 1\n \n return changes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n \n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total character counts and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n else:\n return lst2", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef get_primes_up_to(n):\n \"\"\"Return a list of all prime numbers less than n.\"\"\"\n return [i for i in range(2, n) if is_prime(i)]\ndef is_multiply_prime(a):\n \"\"\"Return True if the given number is the multiplication of 3 prime numbers, False otherwise.\"\"\"\n if a < 1 or a >= 100:\n return False\n \n primes = get_primes_up_to(100)\n \n # Check all combinations of three primes\n for i in range(len(primes)):\n for j in range(i, len(primes)):\n for k in range(j, len(primes)):\n product = primes[i] * primes[j] * primes[k]\n if product == a:\n return True\n if product > a:\n break # No need to check further if the product exceeds 'a'\n \n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n \"\"\"Returns True if x is a simple power of n, otherwise False.\n \n A number x is a simple power of n if there exists an integer k such that n**k = x.\n \n Args:\n x (int): The number to check.\n n (int): The base number.\n \n Returns:\n bool: True if x is a simple power of n, False otherwise.\n \"\"\"\n # Edge case: if n is 0, we cannot raise it to any power to get a positive x\n if n == 0:\n return x == 0\n \n # Edge case: if n is 1, n**k will always be 1 for any k >= 0\n if n == 1:\n return x == 1\n \n # Edge case: if x is 0, it can only be a power of n if n is also 0\n if x == 0:\n return n == 0\n \n # Edge case: if x is negative, n must be negative and odd to produce a negative power\n if x < 0 and n > 0:\n return False\n \n # Check if there exists an integer k such that n**k = x\n power = 1\n while True:\n result = n ** power\n if result == x:\n return True\n elif result > x:\n return False\n power += 1", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1, 12]], "plus_fail_tests": []}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this integer is a cube of some integer number.\n Note: you may assume the input is always valid.\n Examples:\n iscube(1) ==> True\n iscube(2) ==> False\n iscube(-1) ==> True\n iscube(64) ==> True\n iscube(0) ==> True\n iscube(180) ==> False\n '''\n # Calculate the cube root of the absolute value of a\n cube_root = round(abs(a) ** (1/3))\n \n # Check if the cube of the rounded cube root equals the absolute value of a\n return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n \"\"\"Counts the number of prime hexadecimal digits in the given hexadecimal string.\"\"\"\n \n # Define the set of prime hexadecimal digits\n prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n \n # Initialize a counter for prime digits\n count = 0\n \n # Iterate through each character in the input string\n for char in num:\n # Check if the character is in the set of prime hexadecimal digits\n if char in prime_hex_digits:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n \"\"\"Convert a decimal number to binary format with specific formatting.\n\n Args:\n decimal (int): A non-negative integer to convert to binary.\n\n Returns:\n str: A string representing the binary format of the decimal number,\n prefixed and suffixed with 'db'.\n \n Examples:\n decimal_to_binary(15) # returns \"db1111db\"\n decimal_to_binary(32) # returns \"db100000db\"\n \"\"\"\n if decimal < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n # Convert decimal to binary and remove the '0b' prefix\n binary_representation = bin(decimal)[2:]\n \n # Format the result with 'db' at the beginning and end\n formatted_result = f\"db{binary_representation}db\"\n \n return formatted_result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n letter_grades = []\n \n for gpa in grades:\n if gpa == 4.0:\n letter_grades.append('A+')\n elif gpa > 3.7:\n letter_grades.append('A')\n elif gpa > 3.3:\n letter_grades.append('A-')\n elif gpa > 3.0:\n letter_grades.append('B+')\n elif gpa > 2.7:\n letter_grades.append('B')\n elif gpa > 2.3:\n letter_grades.append('B-')\n elif gpa > 2.0:\n letter_grades.append('C+')\n elif gpa > 1.7:\n letter_grades.append('C')\n elif gpa > 1.3:\n letter_grades.append('C-')\n elif gpa > 1.0:\n letter_grades.append('D+')\n elif gpa > 0.7:\n letter_grades.append('D')\n elif gpa > 0.0:\n letter_grades.append('D-')\n else:\n letter_grades.append('E')\n \n return letter_grades", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n \"\"\"Check if the string s is happy.\n \n A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n \n Args:\n s (str): The input string to check.\n \n Returns:\n bool: True if the string is happy, False otherwise.\n \"\"\"\n # Check if the length of the string is at least 3\n if len(s) < 3:\n return False\n \n # Iterate through the string and check every 3 consecutive characters\n for i in range(len(s) - 2):\n # Get the current substring of 3 characters\n substring = s[i:i+3]\n # Check if all characters in the substring are distinct\n if len(set(substring)) != 3:\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_length(string):\n \"\"\"Check if the length of the string is a prime number.\"\"\"\n length = len(string)\n return is_prime(length)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n \"\"\"\n Given a positive integer n, return the count of the numbers of n-digit\n positive integers that start or end with 1.\n \"\"\"\n if n <= 0:\n return 0 # No n-digit numbers if n is not positive\n\n # Total n-digit numbers\n total_n_digit_numbers = 9 * (10 ** (n - 1))\n\n # Count of n-digit numbers that start with 1\n if n == 1:\n count_starting_with_1 = 1 # Only the number 1\n else:\n count_starting_with_1 = 10 ** (n - 1) # 1 followed by (n-1) digits (0-9)\n\n # Count of n-digit numbers that end with 1\n count_ending_with_1 = 9 * (10 ** (n - 2)) if n > 1 else 0 # (n-1) digits can be anything (0-9)\n\n # Total count of n-digit numbers that start or end with 1\n total_count = count_starting_with_1 + count_ending_with_1\n\n # If n > 1, we have double counted the numbers that both start and end with 1\n if n > 1:\n count_both_start_and_end_with_1 = 10 ** (n - 2) # 1 followed by (n-2) digits followed by 1\n total_count -= count_both_start_and_end_with_1\n\n return total_count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits will be 1 the output should be \"1\".\n For N = 150, the sum of digits will be 6 the output should be \"110\".\n For N = 147, the sum of digits will be 12 the output should be \"1100\".\n \n Variables:\n @N integer\n Constraints: 0 \u2264 N \u2264 10000.\n Output:\n a string of binary number\n \"\"\"\n # Step 1: Calculate the sum of the digits of N\n digit_sum = sum(int(digit) for digit in str(N))\n \n # Step 2: Convert the sum to binary and remove the '0b' prefix\n binary_sum = bin(digit_sum)[2:]\n \n return binary_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum to 0\n total = 0\n \n # Iterate over the list using index and value\n for index in range(len(lst)):\n # Check if the index is odd\n if index % 2 == 1:\n # Check if the element at this index is even\n if lst[index] % 2 == 0:\n total += lst[index]\n \n return total", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words and spaces\n words = s.split(' ')\n \n # Process each word to sort its characters\n sorted_words = []\n for word in words:\n # Sort the characters of the word and join them back\n sorted_word = ''.join(sorted(word))\n sorted_words.append(sorted_word)\n \n # Join the sorted words back with spaces\n result = ' '.join(sorted_words)\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n # Iterate through each row and its index\n for row_index, row in enumerate(lst):\n # Iterate through each column in the row and its index\n for col_index, value in enumerate(row):\n # If the value matches x, store the coordinates\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort coordinates by row (ascending) and then by column (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n or sort it in descending order if the sum( first index value, last index value) is even.\n\n Note:\n * don't change the given array.\n\n Examples:\n * sort_array([]) => []\n * sort_array([5]) => [5]\n * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n \"\"\"\n # Create a copy of the original array to avoid modifying it\n sorted_array = array.copy()\n \n # Check if the array is empty\n if not sorted_array:\n return sorted_array\n \n # Calculate the sum of the first and last elements\n first_element = sorted_array[0]\n last_element = sorted_array[-1]\n total_sum = first_element + last_element\n \n # Sort the array based on the sum's parity\n if total_sum % 2 == 0:\n # Even sum: sort in descending order\n sorted_array.sort(reverse=True)\n else:\n # Odd sum: sort in ascending order\n sorted_array.sort()\n \n return sorted_array", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n # Create a dictionary to map each letter to its encrypted counterpart\n encrypted_dict = {}\n \n # Populate the dictionary with the shifted letters\n for i in range(len(alphabet)):\n # Calculate the new position with a shift of 4 (2 * 2)\n new_position = (i + 4) % 26\n encrypted_dict[alphabet[i]] = alphabet[new_position]\n \n # Encrypt the input string\n encrypted_string = ''.join(encrypted_dict[char] for char in s if char in encrypted_dict)\n \n return encrypted_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n \n For example:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n \"\"\"\n # Split the input string into sentences based on the delimiters\n sentences = []\n current_sentence = []\n \n for char in S:\n if char in '.!?':\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n current_sentence = []\n else:\n current_sentence.append(char)\n \n # Add the last sentence if it exists\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n \n # Count the number of sentences that start with \"I\"\n boredom_count = sum(1 for sentence in sentences if sentence.startswith('I'))\n \n return boredom_count", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Sort the unique elements\n sorted_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_elements[1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n \"\"\"\n Write a function that takes a message, and encodes in such a \n way that it swaps case of all letters, replaces all vowels in \n the message with the letter that appears 2 places ahead of that \n vowel in the English alphabet. \n Assume only letters. \n \n Examples:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n \n # Define vowels and their replacements\n vowels = 'aeiouAEIOU'\n vowel_replacements = {\n 'a': 'c', 'A': 'C',\n 'e': 'g', 'E': 'G',\n 'i': 'k', 'I': 'K',\n 'o': 'q', 'O': 'Q',\n 'u': 'w', 'U': 'W'\n }\n \n encoded_message = []\n \n for char in message:\n if char.isalpha(): # Check if the character is a letter\n # Swap case\n if char in vowels:\n # Replace vowel and swap case\n encoded_message.append(vowel_replacements[char])\n else:\n # Just swap case for consonants\n encoded_message.append(char.swapcase())\n else:\n # If it's not a letter, we can choose to ignore it or keep it as is\n encoded_message.append(char)\n \n return ''.join(encoded_message)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["TEST"]], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n '''\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n \n Examples\n any_int(5, 2, 7) \u279e True\n any_int(3, 2, 2) \u279e False\n any_int(3, -2, 1) \u279e True\n any_int(3.6, -2.2, 2) \u279e False\n '''\n \n # Check if all inputs are integers\n if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n # Check if one number is equal to the sum of the other two\n return x == y + z or y == x + z or z == x + y\n else:\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef sum_of_digits(n):\n \"\"\"Return the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n largest_prime = None\n \n for number in lst:\n if is_prime(number):\n if largest_prime is None or number > largest_prime:\n largest_prime = number\n \n if largest_prime is not None:\n return sum_of_digits(largest_prime)\n else:\n return 0 # Return 0 if no prime number is found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in lower \n case or all keys are strings in upper case, else return False.\n The function should return False if the given dictionary is empty.\n \n Examples:\n check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n \"\"\"\n \n # Check if the dictionary is empty\n if not input_dict:\n return False\n \n # Initialize flags for lower and upper case\n all_lower = True\n all_upper = True\n \n for key in input_dict.keys():\n # Check if the key is a string\n if not isinstance(key, str):\n return False\n \n # Check if the key is lower case\n if key.islower():\n all_upper = False\n # Check if the key is upper case\n elif key.isupper():\n all_lower = False\n else:\n # If the key is neither lower nor upper case\n return False\n \n # Return True if all keys are either lower case or upper case\n return all_lower or all_upper", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.\n \"\"\"\n # Get the unit digit of the first number\n unit_digit_a = abs(a) % 10\n # Get the unit digit of the second number\n unit_digit_b = abs(b) % 10\n # Return the product of the unit digits\n return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_up_to(n):\n \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n primes = []\n for i in range(2, n):\n if is_prime(i):\n primes.append(i)\n return primes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n\n Note:\n Rounding away from zero means that if the given number is equidistant\n from two integers, the one you should return is the one that is the\n farthest from zero. For example closest_integer(\"14.5\") should\n return 15 and closest_integer(\"-14.5\") should return -15.\n '''\n # Convert the input string to a float\n num = float(value)\n \n # Calculate the floor and ceiling of the number\n lower_int = int(num // 1) # This is the largest integer less than or equal to num\n upper_int = lower_int + 1 # This is the smallest integer greater than num\n \n # Check the distance to the lower and upper integers\n distance_to_lower = abs(num - lower_int)\n distance_to_upper = abs(num - upper_int)\n \n # Determine which integer to return based on the distances\n if distance_to_lower < distance_to_upper:\n return lower_int\n elif distance_to_upper < distance_to_lower:\n return upper_int\n else:\n # If equidistant, round away from zero\n if num > 0:\n return upper_int\n else:\n return lower_int", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n count_upper('aBCdEf') returns 1\n count_upper('abcdefg') returns 0\n count_upper('dBBE') returns 0\n \"\"\"\n # Define the set of uppercase vowels\n uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n \n # Initialize a counter for uppercase vowels at even indices\n count = 0\n \n # Iterate over the string, checking only even indices\n for i in range(0, len(s), 2): # Step by 2 to get even indices\n if s[i] in uppercase_vowels:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n \"\"\"\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n >>> make_a_pile(4)\n [4, 6, 8, 10]\n >>> make_a_pile(1)\n [1]\n >>> make_a_pile(2)\n [2, 4]\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n\n stones = []\n current_stones = n\n\n for i in range(n):\n stones.append(current_stones)\n if current_stones % 2 == 0:\n current_stones += 2 # next even number\n else:\n current_stones += 2 # next odd number\n\n return stones", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n \"\"\"\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n \"\"\"\n # Replace commas with spaces and split the string by whitespace\n words = s.replace(',', ' ').split()\n \n # Return the list of words\n return words", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n \"\"\"Compute the average of integers from n to m, round it to the nearest integer,\n and convert that to binary. If n is greater than m, return -1.\n \n Args:\n n (int): The starting integer (inclusive).\n m (int): The ending integer (inclusive).\n \n Returns:\n str or int: The binary representation of the rounded average if n <= m, \n otherwise -1.\n \"\"\"\n if n > m:\n return -1\n \n # Calculate the sum of integers from n to m\n total_sum = sum(range(n, m + 1))\n count = m - n + 1 # Total numbers from n to m\n \n # Calculate the average and round it\n average = total_sum / count\n rounded_average = round(average)\n \n # Convert the rounded average to binary\n return bin(rounded_average)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n \"\"\"This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If \n there's no such number, then the function should return -1.\n \n For example:\n choose_num(12, 15) = 14\n choose_num(13, 12) = -1\n \"\"\"\n \n # Ensure x is less than or equal to y\n if x > y:\n return -1\n \n # Start from the maximum of x and y\n for num in range(y, x - 1, -1):\n if num % 2 == 0: # Check if the number is even\n return num\n \n return -1 # If no even number is found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n \"\"\"Given a list of positive integers x, return a sorted list of all \n elements that haven't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n def has_even_digit(n):\n \"\"\"Check if the number has any even digit.\"\"\"\n for digit in str(n):\n if int(digit) % 2 == 0:\n return True\n return False\n\n # Filter the list to include only numbers without even digits\n filtered_numbers = [num for num in x if not has_even_digit(num)]\n \n # Sort the resulting list\n return sorted(filtered_numbers)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n reverse the resulting array, and then replace each digit by its corresponding name from\n \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n For example:\n arr = [2, 1, 1, 4, 5, 8, 2, 3] \n -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n \n If the array is empty, return an empty array:\n arr = []\n return []\n \n If the array has any strange number ignore it:\n arr = [1, -1 , 55] \n -> sort arr -> [-1, 1, 55]\n -> reverse arr -> [55, 1, -1]\n return = ['One']\n \"\"\"\n \n # Mapping of digits to their corresponding names\n digit_to_name = {\n 1: \"One\",\n 2: \"Two\",\n 3: \"Three\",\n 4: \"Four\",\n 5: \"Five\",\n 6: \"Six\",\n 7: \"Seven\",\n 8: \"Eight\",\n 9: \"Nine\"\n }\n \n # Filter the array to include only integers between 1 and 9\n filtered_arr = [num for num in arr if 1 <= num <= 9]\n \n # Sort the filtered array\n filtered_arr.sort()\n \n # Reverse the sorted array\n filtered_arr.reverse()\n \n # Convert the digits to their corresponding names\n result = [digit_to_name[num] for num in filtered_arr]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def f(n):\n \"\"\" \n Implement the function f that takes n as a parameter,\n and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even\n or the sum of numbers from 1 to i otherwise.\n i starts from 1.\n the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).\n \"\"\"\n result = []\n \n for i in range(1, n + 1):\n if i % 2 == 0: # i is even\n factorial = 1\n for j in range(1, i + 1):\n factorial *= j\n result.append(factorial)\n else: # i is odd\n sum_of_numbers = sum(range(1, i + 1))\n result.append(sum_of_numbers)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n \"\"\"\n Given a positive integer n, return a tuple that has the number of even and odd\n integer palindromes that fall within the range(1, n), inclusive.\n\n Example 1:\n Input: 3\n Output: (1, 2)\n Explanation:\n Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n Example 2:\n Input: 12\n Output: (4, 6)\n Explanation:\n Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n Note:\n 1. 1 <= n <= 10^3\n 2. returned tuple has the number of even and odd integer palindromes respectively.\n \"\"\"\n \n def is_palindrome(num):\n return str(num) == str(num)[::-1]\n\n even_count = 0\n odd_count = 0\n\n for i in range(1, n + 1):\n if is_palindrome(i):\n if i % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n \"\"\"\n Write a function count_nums which takes an array of integers and returns\n the number of elements which has a sum of digits > 0.\n If a number is negative, then its first signed digit will be negative:\n e.g. -123 has signed digits -1, 2, and 3.\n \n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n def sum_of_digits(n):\n \"\"\"Helper function to calculate the sum of digits of a number.\"\"\"\n # Convert number to string and iterate over each character\n # If the number is negative, we need to consider the first digit as negative\n str_n = str(n)\n digit_sum = 0\n \n for i, char in enumerate(str_n):\n if char.isdigit():\n digit_sum += int(char)\n elif i == 0 and char == '-':\n digit_sum -= 1 # First signed digit is negative\n \n return digit_sum\n\n count = 0\n for number in arr:\n if sum_of_digits(number) > 0:\n count += 1\n \n return count", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[-1, -2, 0]]], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return True else return False.\n If the given array is empty then return True.\n\n Note: The given list is guaranteed to have unique elements.\n \"\"\"\n \n # Edge case: if the array is empty, return True\n if not arr:\n return True\n \n # Count the number of times the array is \"out of order\"\n count = 0\n n = len(arr)\n \n for i in range(n):\n # Check if the current element is greater than the next element\n if arr[i] > arr[(i + 1) % n]:\n count += 1\n \n # If there are more than one \"out of order\" points, we cannot sort it with shifts\n return count <= 1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n \"\"\"Determines whether it is possible to perform an exchange of elements\n between two lists to make lst1 a list of only even numbers.\n \n Args:\n lst1 (list): The first list of numbers.\n lst2 (list): The second list of numbers.\n \n Returns:\n str: \"YES\" if lst1 can be made entirely even, otherwise \"NO\".\n \"\"\"\n # Check if lst1 already contains only even numbers\n if all(x % 2 == 0 for x in lst1):\n return \"YES\"\n \n # Count the number of odd numbers in lst1\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n \n # Check if lst2 has at least one even number to exchange\n has_even_in_lst2 = any(x % 2 == 0 for x in lst2)\n \n # If lst1 has odd numbers and lst2 has at least one even number,\n # we can exchange to make lst1 all even\n if odd_count_lst1 > 0 and has_even_in_lst2:\n return \"YES\"\n \n # If lst1 has odd numbers and lst2 has no even numbers,\n # we cannot make lst1 all even\n return \"NO\"", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 3, 4], [1, 5, 3, 4]]], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n \"\"\"\n if not test:\n return {}\n\n # Split the input string into a list of letters\n letters = test.split()\n \n # Create a dictionary to count occurrences of each letter\n count_dict = {}\n for letter in letters:\n if letter in count_dict:\n count_dict[letter] += 1\n else:\n count_dict[letter] = 1\n\n # Find the maximum count\n max_count = max(count_dict.values())\n \n # Create a result dictionary for letters with the maximum count\n result = {letter: count for letter, count in count_dict.items() if count == max_count}\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n \n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in s if char in '13579')\n \n # Create the output string with the counted odd digits\n output_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n \n # Append the result to the list\n result.append(output_string)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n \"\"\"Task\n We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and True/False for the check.\n \"\"\"\n # Create a set of characters to delete for faster lookup\n chars_to_delete = set(c)\n \n # Build the result string by filtering out characters in chars_to_delete\n result = ''.join(char for char in s if char not in chars_to_delete)\n \n # Check if the result string is a palindrome\n is_palindrome = result == result[::-1]\n \n return (result, is_palindrome)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n Example\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n \"\"\"\n if not nums:\n raise ValueError(\"The input array must not be empty.\")\n \n # Initialize variables to track the minimum sum and the current sum\n min_sum = float('inf')\n current_sum = 0\n \n for num in nums:\n current_sum += num\n min_sum = min(min_sum, current_sum)\n \n # If current_sum is greater than 0, reset it to 0\n if current_sum > 0:\n current_sum = 0\n \n return min_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n \"\"\"\n Calculate the number of times buckets need to be lowered to empty the wells.\n\n Parameters:\n grid (list of list of int): A rectangular grid representing wells.\n capacity (int): The capacity of each bucket.\n\n Returns:\n int: The total number of times buckets need to be lowered.\n \"\"\"\n total_water = 0\n \n # Count the total amount of water in the grid\n for row in grid:\n total_water += sum(row)\n \n # Calculate the number of times buckets need to be lowered\n if total_water == 0:\n return 0 # No water to extract\n \n # Each bucket can carry 'capacity' units of water\n # We need to lower the buckets enough times to extract all the water\n return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n \"\"\"Given a string s and a natural number n, returns a list of all words from string s \n that contain exactly n consonants, in the order they appear in the string s.\n \n Args:\n s (str): The input string containing words.\n n (int): The number of consonants to match in each word.\n \n Returns:\n list: A list of words containing exactly n consonants.\n \"\"\"\n \n if not s: # Check if the string is empty\n return []\n \n # Define a set of vowels for easy checking\n vowels = set(\"aeiouAEIOU\")\n \n def count_consonants(word):\n \"\"\"Helper function to count consonants in a word.\"\"\"\n return sum(1 for char in word if char.isalpha() and char not in vowels)\n \n # Split the string into words\n words = s.split()\n \n # Filter words that have exactly n consonants\n result = [word for word in words if count_consonants(word) == n]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n \"\"\"\n Sorts an array of non-negative integers according to the number of ones in their binary representation\n in ascending order. For numbers with the same number of ones, it sorts based on their decimal value.\n\n Parameters:\n arr (list): A list of non-negative integers.\n\n Returns:\n list: A sorted list of integers based on the specified criteria.\n \"\"\"\n # Define a sorting key that sorts first by the number of 1s in binary representation,\n # and then by the decimal value itself.\n return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n two consonants from the right side of the word (case sensitive).\n \n Vowels in the beginning and ending don't count. Return empty string if you didn't\n find any vowel that meets the above condition. \n\n You may assume that the given string contains English letters only.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n n = len(word)\n\n # Check if the word is too short to have consonants with a vowel in between\n if n < 3:\n return \"\"\n\n # Start from the end of the word\n for i in range(n - 2, 0, -1):\n if word[i] in vowels:\n # Check if the character before and after are consonants\n if word[i - 1].isalpha() and word[i + 1].isalpha() and \\\n word[i - 1] not in vowels and word[i + 1] not in vowels:\n return word[i]\n\n return \"\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n \n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0: # More closing than opening\n return False\n return balance == 0 # Must be balanced at the end\n\n # Get the two strings from the list\n s1, s2 = lst[0], lst[1]\n\n # Check both concatenation orders\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of all odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n total_sum = 0\n for index in range(0, len(lst), 2): # Iterate over even indices\n if lst[index] % 2 != 0: # Check if the element is odd\n total_sum += lst[index] # Add to total sum if it's odd\n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n \n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Get the top k elements\n top_k = sorted_arr[:k]\n \n # Return the top k elements sorted in ascending order\n return sorted(top_k)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n \"\"\"\n Given a non-empty array of integers arr and an integer k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example:\n\n Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n Output: 24 # sum of 21 + 3\n\n Constraints:\n 1. 1 <= len(arr) <= 100\n 2. 1 <= k <= len(arr)\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate through the first k elements of the array\n for i in range(k):\n # Check if the current element has at most two digits\n if -100 < arr[i] < 100:\n total_sum += arr[i]\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n as follows: start with any positive integer n. Then each term is obtained from the \n previous term as follows: if the previous term is even, the next term is one half of \n the previous term. If the previous term is odd, the next term is 3 times the previous\n term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n Note: \n 1. Collatz(1) is [1].\n 2. returned list sorted in increasing order.\n\n For example:\n get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n collatz_sequence = []\n current = n\n \n while current != 1:\n collatz_sequence.append(current)\n if current % 2 == 0:\n current //= 2\n else:\n current = 3 * current + 1\n \n collatz_sequence.append(1) # Add the last term which is 1\n \n # Filter out the odd numbers and sort them\n odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n \n return odd_numbers", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n \n The date is valid if all of the following rules are satisfied:\n 1. The date string is not empty.\n 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n The number of days is not less than 1 or higher than 29 for the month 2.\n 3. The months should not be less than 1 or higher than 12.\n 4. The date should be in the format: mm-dd-yyyy\n \"\"\"\n \n # Check if the date string is empty\n if not date:\n return False\n \n # Check if the date format is correct\n if len(date) != 10 or date[2] != '-' or date[5] != '-':\n return False\n \n # Split the date into components\n try:\n month, day, year = map(int, date.split('-'))\n except ValueError:\n return False\n \n # Check month range\n if month < 1 or month > 12:\n return False\n \n # Check day range based on month\n if month in {1, 3, 5, 7, 8, 10, 12}:\n if day < 1 or day > 31:\n return False\n elif month in {4, 6, 9, 11}:\n if day < 1 or day > 30:\n return False\n elif month == 2:\n if day < 1 or day > 29:\n return False\n \n # If all checks are passed, the date is valid\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n '''\n Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n Examples\n split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"abcdef\") == 3 \n '''\n \n # Check for whitespace in the text\n if ' ' in txt:\n return txt.split()\n \n # Check for commas in the text\n elif ',' in txt:\n return txt.split(',')\n \n # If no whitespace or commas, count lowercase letters with odd order\n else:\n odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n return odd_count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef intersection(interval1, interval2):\n \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n start1, end1 = interval1\n start2, end2 = interval2\n \n # Find the intersection\n start_intersection = max(start1, start2)\n end_intersection = min(end1, end2)\n \n # Check if there is an intersection\n if start_intersection > end_intersection:\n return \"NO\"\n \n # Calculate the length of the intersection\n length_of_intersection = end_intersection - start_intersection\n \n # Check if the length is a prime number\n if is_prime(length_of_intersection):\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n '''\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return False. Assume no negative numbers and only integers.\n\n Examples\n is_sorted([5]) \u279e True\n is_sorted([1, 2, 3, 4, 5]) \u279e True\n is_sorted([1, 3, 2, 4, 5]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n '''\n \n if not lst: # Check for empty list\n return True\n \n seen = set() # To track unique elements\n last = None # To track the last element for sorting check\n \n for num in lst:\n if num in seen: # Check for duplicates\n return False\n seen.add(num)\n \n if last is not None and num < last: # Check if sorted\n return False\n \n last = num # Update last element\n \n return True # If all checks passed, the list is sorted", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n if not arr: # Check for empty array\n return None\n\n product_of_signs = 1\n sum_of_magnitudes = 0\n\n for num in arr:\n if num > 0:\n sum_of_magnitudes += num\n elif num < 0:\n sum_of_magnitudes += -num\n product_of_signs *= -1 # Flip the sign for negative numbers\n else: # num == 0\n return 0 # If there's a zero, the product of signs is zero\n\n return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n \"\"\"Generate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n if n < 0:\n return []\n\n # Initialize the list to hold the Tribonacci numbers\n tribonacci_sequence = []\n\n # Calculate the Tribonacci numbers based on the given rules\n for i in range(n + 1):\n if i == 1:\n tribonacci_sequence.append(3) # tri(1) = 3\n elif i == 0:\n tribonacci_sequence.append(1) # tri(0) = 1\n elif i % 2 == 0: # Even index\n tribonacci_sequence.append(1 + i / 2)\n else: # Odd index\n # tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1)\n # We need to ensure we have calculated tri(n + 1) before using it\n if i + 1 <= n:\n tribonacci_sequence.append(tribonacci_sequence[i - 1] + tribonacci_sequence[i - 2] + tribonacci_sequence[i + 1])\n else:\n tribonacci_sequence.append(tribonacci_sequence[i - 1] + tribonacci_sequence[i - 2] + 3) # tri(n + 1) = 3 for n = 1\n\n return tribonacci_sequence", "base_status": "fail", "plus_status": null, "base_fail_tests": [[4]], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n \"\"\"Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n For example:\n digits(1) == 1\n digits(4) == 0\n digits(235) == 15\n \"\"\"\n # Initialize the product to 1 and a flag to check if any odd digit is found\n product = 1\n found_odd = False\n \n # Convert the number to a string to iterate over each digit\n for digit in str(n):\n digit = int(digit) # Convert the character back to an integer\n if digit % 2 != 0: # Check if the digit is odd\n product *= digit # Multiply the product by the odd digit\n found_odd = True # Set the flag to True since we found an odd digit\n \n # If no odd digit was found, return 0\n if not found_odd:\n return 0\n \n return product # Return the product of the odd digits", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n '''\n Create a function that takes a string as input which contains only square brackets.\n The function should return True if and only if there is a valid subsequence of brackets \n where at least one bracket in the subsequence is nested.\n\n is_nested('[[]]') \u279e True\n is_nested('[]]]]]]][[[[[]') \u279e False\n is_nested('[][]') \u279e False\n is_nested('[]') \u279e False\n is_nested('[[][]]') \u279e True\n is_nested('[[]][[') \u279e True\n '''\n \n # Initialize a counter for open brackets\n open_count = 0\n # Initialize a flag to check for nesting\n nested = False\n \n for char in string:\n if char == '[':\n open_count += 1\n # If we have more than one open bracket, we have a nested structure\n if open_count > 1:\n nested = True\n elif char == ']':\n open_count -= 1\n # If we close a bracket and there were open brackets before, we check for nesting\n if open_count < 0:\n return False # More closing brackets than opening\n # If we have a nested structure and we close a bracket, we can stop checking\n if nested and open_count == 0:\n return True\n \n # If we finish and have open brackets left, it's not valid\n return nested and open_count == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers.\n You need to return the sum of squared numbers in the given list,\n round each element in the list to the upper int (Ceiling) first.\n \n Examples:\n For lst = [1,2,3] the output should be 14\n For lst = [1,4,9] the output should be 98\n For lst = [1,3,5,7] the output should be 84\n For lst = [1.4,4.2,0] the output should be 29\n For lst = [-2.4,1,1] the output should be 6\n \"\"\"\n # Round each number in the list to the upper integer (ceiling)\n rounded_numbers = [math.ceil(num) for num in lst]\n \n # Calculate the sum of squares of the rounded numbers\n sum_of_squares = sum(num ** 2 for num in rounded_numbers)\n \n return sum_of_squares", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n '''\n Create a function that returns True if the last character\n of a given string is an alphabetical character and is not\n a part of a word, and False otherwise.\n Note: \"word\" is a group of characters separated by space.\n\n Examples:\n check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '''\n \n # Strip any trailing whitespace from the string\n txt = txt.rstrip()\n \n # Check if the string is empty after stripping\n if not txt:\n return False\n \n # Get the last character of the string\n last_char = txt[-1]\n \n # Check if the last character is an alphabetical character\n if last_char.isalpha():\n # Check if the last character is part of a word\n # A character is part of a word if it is preceded by a non-space character\n if len(txt) > 1 and txt[-2] != ' ':\n return False\n return True\n \n return False", "base_status": "fail", "plus_status": null, "base_fail_tests": [["eeeee e "]], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n \"\"\"Create a function which returns the largest index of an element which\n is not greater than or equal to the element immediately preceding it. If\n no such element exists then return -1. The given array will not contain\n duplicate values.\n\n Examples:\n can_arrange([1,2,4,3,5]) = 3\n can_arrange([1,2,3]) = -1\n \"\"\"\n # Check if the array is empty\n if not arr:\n return -1\n\n # Initialize the largest index to -1\n largest_index = -1\n\n # Iterate through the array starting from the second element\n for i in range(1, len(arr)):\n # Check if the current element is less than the previous element\n if arr[i] < arr[i - 1]:\n largest_index = i\n\n return largest_index", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n from collections import deque\n\n N = len(grid)\n directions = [(0, 1), (1, 0), (0, -1), (-1, 0)] # right, down, left, up\n min_path = None\n\n def bfs(start_row, start_col):\n nonlocal min_path\n queue = deque([(start_row, start_col, [grid[start_row][start_col]])])\n \n while queue:\n row, col, path = queue.popleft()\n \n if len(path) == k:\n if min_path is None or path < min_path:\n min_path = path\n continue\n \n for dr, dc in directions:\n new_row, new_col = row + dr, col + dc\n if 0 <= new_row < N and 0 <= new_col < N:\n queue.append((new_row, new_col, path + [grid[new_row][new_col]]))\n\n for i in range(N):\n for j in range(N):\n bfs(i, j)\n\n return min_path", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n '''\n Create a function that returns a tuple (a, b), where 'a' is\n the largest of negative integers, and 'b' is the smallest\n of positive integers in a list.\n If there is no negative or positive integers, return them as None.\n\n Examples:\n largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n largest_smallest_integers([]) == (None, None)\n largest_smallest_integers([0]) == (None, None)\n '''\n \n largest_negative = None\n smallest_positive = None\n \n for num in lst:\n if num < 0:\n if largest_negative is None or num > largest_negative:\n largest_negative = num\n elif num > 0:\n if smallest_positive is None or num < smallest_positive:\n smallest_positive = num\n \n return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def parse_number(value):\n \"\"\"\n Convert a string representation of a number into a float or return the value as is if it's already a number.\n Handles both '.' and ',' as decimal separators.\n \"\"\"\n if isinstance(value, (int, float)):\n return float(value)\n elif isinstance(value, str):\n # Replace ',' with '.' for float conversion\n value = value.replace(',', '.')\n try:\n return float(value)\n except ValueError:\n return None # Return None if conversion fails\n return None # Return None for unsupported types\ndef compare_one(a, b):\n \"\"\"\n Compare two values (integers, floats, or strings representing real numbers)\n and return the larger one in its original type, or None if they are equal.\n \"\"\"\n # Parse both values\n parsed_a = parse_number(a)\n parsed_b = parse_number(b)\n\n # If both parsed values are None, return None\n if parsed_a is None or parsed_b is None:\n return None\n\n # Compare the parsed values\n if parsed_a > parsed_b:\n return a\n elif parsed_b > parsed_a:\n return b\n else:\n return None # Return None if they are equal", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n \"\"\"Helper function to compute the factorial of a non-negative integer n.\"\"\"\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef special_factorial(n):\n \"\"\"Calculate the Brazilian factorial of n.\"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer greater than 0.\")\n \n result = 1\n for i in range(1, n + 1):\n result *= factorial(i)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n \n Args:\n n (int): The number to evaluate.\n \n Returns:\n bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n \n Example:\n is_equal_to_sum_even(4) == False\n is_equal_to_sum_even(6) == False\n is_equal_to_sum_even(8) == True\n \"\"\"\n \n # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n if n < 8:\n return False\n \n # If n is even and at least 8, it can be expressed as the sum of 4 positive even numbers\n return n % 2 == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n \"\"\"\n Given a string text, replace all spaces in it with underscores, \n and if a string has more than 2 consecutive spaces, \n then replace all consecutive spaces with - \n \n fix_spaces(\"Example\") == \"Example\"\n fix_spaces(\"Example 1\") == \"Example_1\"\n fix_spaces(\" Example 2\") == \"_Example_2\"\n fix_spaces(\" Example 3\") == \"_Example-3\"\n \"\"\"\n # Replace multiple spaces with a placeholder\n text = text.replace(' ', '-').replace(' ', '-')\n \n # Replace remaining spaces with underscores\n text = text.replace(' ', '_')\n \n # Handle the case where we might have replaced too many spaces\n # We need to ensure that we only replace sequences of spaces\n # that are more than 2 with a single '-'\n parts = text.split('-')\n for i in range(len(parts)):\n parts[i] = parts[i].replace('_', ' ')\n \n # Join the parts back together\n result = '-'.join(part.replace(' ', '_') for part in parts)\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Yellow Yellow Dirty Fellow"]], "plus_fail_tests": []}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n \"\"\"Check if the given file name is valid based on specific criteria.\"\"\"\n \n # Check for exactly one dot\n if file_name.count('.') != 1:\n return 'No'\n \n # Split the file name into name and extension\n name, extension = file_name.split('.')\n \n # Check if the name is not empty and starts with a letter\n if not name or not name[0].isalpha():\n return 'No'\n \n # Check if the extension is valid\n valid_extensions = ['txt', 'exe', 'dll']\n if extension not in valid_extensions:\n return 'No'\n \n # Count the number of digits in the file name\n digit_count = sum(c.isdigit() for c in file_name)\n \n # Check if there are more than three digits\n if digit_count > 3:\n return 'No'\n \n return 'Yes'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef words_in_sentence(sentence):\n \"\"\"\n Given a string representing a sentence, return a string that contains the words\n from the original sentence whose lengths are prime numbers.\n The order of the words in the new string should be the same as the original one.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Filter words whose lengths are prime\n prime_length_words = [word for word in words if is_prime(len(word))]\n \n # Join the filtered words into a single string\n return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n \"\"\"\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n \n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126\n \"\"\"\n total_sum = 0\n \n for index, value in enumerate(lst):\n if index % 3 == 0:\n total_sum += value ** 2 # Square if index is a multiple of 3\n elif index % 4 == 0:\n total_sum += value ** 3 # Cube if index is a multiple of 4 and not a multiple of 3\n else:\n total_sum += value # Keep the value unchanged if not a multiple of 3 or 4\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n \"\"\"\n Sorts the given list of integers in ascending order according to the sum of their digits.\n If there are several items with similar sum of their digits, they are ordered based on their\n index in the original list.\n\n Args:\n nums (list of int): The list of integers to be sorted.\n\n Returns:\n list of int: The sorted list of integers.\n \"\"\"\n \n def digit_sum(n):\n \"\"\"Calculate the sum of the digits of an integer n.\"\"\"\n return sum(int(digit) for digit in str(abs(n)))\n\n # Sort the list using a tuple (digit sum, original index)\n sorted_nums = sorted(enumerate(nums), key=lambda x: (digit_sum(x[1]), x[0]))\n \n # Extract the sorted numbers from the sorted tuples\n return [num for index, num in sorted_nums]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n \"\"\"Simplifies the expression x * n and checks if the result is a whole number.\n \n Args:\n x (str): A string representation of a fraction in the format /.\n n (str): A string representation of a fraction in the format /.\n \n Returns:\n bool: True if x * n evaluates to a whole number, False otherwise.\n \"\"\"\n # Split the fractions into numerator and denominator\n x_numerator, x_denominator = map(int, x.split('/'))\n n_numerator, n_denominator = map(int, n.split('/'))\n \n # Calculate the product of the fractions\n # x * n = (x_numerator / x_denominator) * (n_numerator / n_denominator)\n # This simplifies to (x_numerator * n_numerator) / (x_denominator * n_denominator)\n \n product_numerator = x_numerator * n_numerator\n product_denominator = x_denominator * n_denominator\n \n # Check if the product is a whole number\n return product_numerator % product_denominator == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n \"\"\"Returns the number of elements in the array that are greater than 10 \n and both the first and last digits of the number are odd (1, 3, 5, 7, 9).\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n int: The count of numbers meeting the criteria.\n \"\"\"\n \n def is_odd_digit(digit):\n \"\"\"Check if a digit is odd.\"\"\"\n return digit in {'1', '3', '5', '7', '9'}\n \n count = 0\n \n for num in nums:\n if num > 10:\n str_num = str(abs(num)) # Convert to string and take absolute value\n first_digit = str_num[0]\n last_digit = str_num[-1]\n \n if is_odd_digit(first_digit) and is_odd_digit(last_digit):\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n \"\"\"\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example :\n Input: n = 5\n Output: 1\n Explanation: \n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n \"\"\"\n # Create the array a based on the given formula\n a = [i * i - i + 1 for i in range(1, n + 1)]\n \n # Count the number of valid triples\n count = 0\n \n # Iterate through all possible triples (i, j, k)\n for i in range(n):\n for j in range(i + 1, n):\n for k in range(j + 1, n):\n if (a[i] + a[j] + a[k]) % 3 == 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closest to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sorted by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct planet names. \n Examples\n bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n '''\n \n # List of planets in order from the Sun\n planets = [\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n ]\n \n # Check if the input planets are valid\n if planet1 not in planets or planet2 not in planets:\n return ()\n \n # Get the indices of the planets\n index1 = planets.index(planet1)\n index2 = planets.index(planet2)\n \n # Determine the range of indices\n start_index = min(index1, index2) + 1\n end_index = max(index1, index2)\n \n # Get the planets in between\n in_between_planets = planets[start_index:end_index]\n \n # Return the result as a tuple\n return tuple(in_between_planets)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length and alphabetically.\n \n Args:\n lst (list of str): A list of strings.\n \n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the filtered list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n \n double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n double_the_difference([-1, -2, 0]) == 0\n double_the_difference([9, -2]) == 81\n double_the_difference([0]) == 0 \n \n If the input list is empty, return 0.\n '''\n # Initialize the sum of squares\n sum_of_squares = 0\n \n # Iterate through each number in the list\n for num in lst:\n # Check if the number is a positive odd integer\n if isinstance(num, int) and num >= 0 and num % 2 != 0:\n # Add the square of the odd number to the sum\n sum_of_squares += num ** 2\n \n return sum_of_squares", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef x_or_y(n, x, y):\n \"\"\"Return the value of x if n is a prime number, otherwise return y.\"\"\"\n if is_prime(n):\n return x\n else:\n return y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n \"\"\"\n Compares the actual scores of matches with the guessed scores.\n \n Parameters:\n game (list of int): The actual scores of the matches.\n guess (list of int): The guessed scores of the matches.\n \n Returns:\n list of int: An array where each element is the absolute difference \n between the actual score and the guessed score, or 0 if \n the guess was correct.\n \"\"\"\n # Check if the lengths of game and guess are equal\n if len(game) != len(guess):\n raise ValueError(\"The length of game and guess must be the same.\")\n \n # Calculate the absolute differences\n result = [abs(g - a) for a, g in zip(game, guess)]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n \"\"\"Find the strongest extension based on the defined strength criteria.\"\"\"\n \n def calculate_strength(extension):\n \"\"\"Calculate the strength of the extension.\"\"\"\n CAP = sum(1 for char in extension if char.isupper())\n SM = sum(1 for char in extension if char.islower())\n return CAP - SM\n\n strongest_extension = None\n strongest_strength = float('-inf') # Start with the lowest possible strength\n\n for extension in extensions:\n strength = calculate_strength(extension)\n \n # Check if this extension is stronger or if it's the first one\n if strength > strongest_strength:\n strongest_strength = strength\n strongest_extension = extension\n\n # Return the result in the required format\n return f\"{class_name}.{strongest_extension}\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n Example:\n even_odd_count(-12) ==> (1, 1)\n even_odd_count(123) ==> (1, 2)\n \"\"\"\n # Convert the number to its absolute value to handle negative numbers\n num = abs(num)\n \n # Initialize counters for even and odd digits\n even_count = 0\n odd_count = 0\n \n # Convert the number to a string to iterate over each digit\n for digit in str(num):\n # Convert the character back to an integer\n digit = int(digit)\n \n # Check if the digit is even or odd and increment the respective counter\n if digit % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n \"\"\"Check if the second word or any of its rotations is a substring in the first word.\"\"\"\n \n # Edge case: if b is empty, it is considered a substring of any string\n if not b:\n return True\n \n # Edge case: if b is longer than a, it cannot be a substring\n if len(b) > len(a):\n return False\n \n # Create a new string that is the concatenation of b with itself\n # This will contain all possible rotations of b as substrings\n b_rotations = b + b\n \n # Check if any rotation of b is a substring of a\n return a.find(b) != -1 or a.find(b_rotations[1:len(b)]) != -1", "base_status": "fail", "plus_status": null, "base_fail_tests": [["efef", "fee"]], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return True if the three\n sides form a right-angled triangle, False otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or \n 90 degree.\n \n Example:\n right_angle_triangle(3, 4, 5) == True\n right_angle_triangle(1, 2, 3) == False\n '''\n \n # First, we need to check if the sides can form a triangle\n if a <= 0 or b <= 0 or c <= 0:\n return False # Sides must be positive\n \n # Sort the sides to easily identify the longest side\n sides = sorted([a, b, c])\n \n # Check the Pythagorean theorem: a^2 + b^2 = c^2\n return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n \n if not (1 <= number <= 1000):\n raise ValueError(\"Number must be between 1 and 1000 inclusive.\")\n \n # Mapping of integers to their corresponding Roman numeral representations\n roman_numerals = [\n (1000, 'm'),\n (900, 'cm'),\n (500, 'd'),\n (400, 'cd'),\n (100, 'c'),\n (90, 'xc'),\n (50, 'l'),\n (40, 'xl'),\n (10, 'x'),\n (9, 'ix'),\n (5, 'v'),\n (4, 'iv'),\n (1, 'i')\n ]\n \n result = []\n \n for value, numeral in roman_numerals:\n while number >= value:\n result.append(numeral)\n number -= value\n \n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n \"\"\"\n You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n \n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n \n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots that exist in stock\n \n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n \"\"\"\n \n # Calculate how many more carrots are needed\n additional_needed = need - number\n \n # If no additional carrots are needed, return the current state\n if additional_needed <= 0:\n return [number, remaining]\n \n # Determine how many carrots can be eaten from the remaining stock\n if remaining >= additional_needed:\n total_eaten = number + additional_needed\n carrots_left = remaining - additional_needed\n else:\n total_eaten = number + remaining\n carrots_left = 0 # All remaining carrots are eaten\n \n return [total_eaten, carrots_left]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": []}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n \"\"\"Return the word with the maximum number of unique characters.\n If multiple words have the same number of unique characters,\n return the one that comes first in lexicographical order.\n \n Args:\n words (list of str): A list of words to evaluate.\n \n Returns:\n str: The word with the maximum number of unique characters.\n \"\"\"\n max_word = \"\"\n max_unique_count = 0\n\n for word in words:\n # Calculate the number of unique characters in the word\n unique_count = len(set(word))\n \n # Check if this word has more unique characters or is lexicographically smaller\n if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n max_word = word\n max_unique_count = unique_count\n\n return max_word", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic algebra operations, and \n the second list is a list of integers. Use the two given lists to build the algebraic \n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + ) \n Subtraction ( - ) \n Multiplication ( * ) \n Floor division ( // ) \n Exponentiation ( ** ) \n\n Example:\n operator = ['+', '*', '-']\n operand = [2, 3, 4, 5]\n result = 2 + 3 * 4 - 5\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.\n \"\"\"\n \n # Start with the first operand\n result = operand[0]\n \n # Iterate through the operators and operands\n for i in range(len(operator)):\n op = operator[i]\n next_operand = operand[i + 1]\n \n if op == '+':\n result += next_operand\n elif op == '-':\n result -= next_operand\n elif op == '*':\n result *= next_operand\n elif op == '//':\n # Handle division by zero\n if next_operand == 0:\n raise ValueError(\"Division by zero is not allowed.\")\n result //= next_operand\n elif op == '**':\n result **= next_operand\n else:\n raise ValueError(f\"Invalid operator: {op}\")\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": []}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n \"\"\"You are given a string s.\n if s[i] is a letter, reverse its case from lower to upper or vice versa, \n otherwise keep it as it is.\n If the string contains no letters, reverse the string.\n The function should return the resulted string.\n Examples\n solve(\"1234\") = \"4321\"\n solve(\"ab\") = \"AB\"\n solve(\"#a@C\") = \"#A@c\"\n \"\"\"\n # Check if there are any letters in the string\n has_letters = any(c.isalpha() for c in s)\n \n if has_letters:\n # If there are letters, reverse the case of each letter\n result = ''.join(c.swapcase() if c.isalpha() else c for c in s)\n else:\n # If there are no letters, reverse the string\n result = s[::-1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascending order.\n\n For example:\n generate_integers(2, 8) => [2, 4, 6, 8]\n generate_integers(8, 2) => [2, 4, 6, 8]\n generate_integers(10, 14) => []\n \"\"\"\n # Ensure a is less than or equal to b for easier processing\n start = min(a, b)\n end = max(a, b)\n\n # Generate a list of even integers in the range [start, end]\n even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n return even_integers", "base_status": "fail", "plus_status": null, "base_fail_tests": [[2, 10]], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string.\n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n \"\"\"\n if text == \"\":\n return None\n # Create an MD5 hash object\n md5_hash = hashlib.md5()\n # Update the hash object with the bytes of the string\n md5_hash.update(text.encode('utf-8'))\n # Return the hexadecimal digest of the hash\n return md5_hash.hexdigest()", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}]}} \ No newline at end of file diff --git a/llm_based_138_eval_results.json b/llm_based_138_eval_results.json new file mode 100644 index 000000000..aa0d4c884 --- /dev/null +++ b/llm_based_138_eval_results.json @@ -0,0 +1 @@ +{"date": "2024-07-27 00:51", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to make it easier to find close elements\n numbers.sort()\n \n # Check the differences between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" \n Input to this function is a string containing multiple groups of nested parentheses. \n The goal is to separate those groups into separate strings and return the list of those.\n Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n Ignore any spaces in the input string.\n \n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n # Remove spaces from the input string\n paren_string = paren_string.replace(\" \", \"\")\n \n result = []\n current_group = []\n balance = 0\n \n for char in paren_string:\n if char == '(':\n balance += 1\n current_group.append(char)\n elif char == ')':\n balance -= 1\n current_group.append(char)\n \n # When balance is zero, we have a complete group\n if balance == 0 and current_group:\n result.append(''.join(current_group))\n current_group = [] # Reset for the next group\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into\n an integer part (largest integer smaller than given number) and decimals\n (leftover part always smaller than 1).\n\n Return the decimal part of the number.\n >>> truncate_number(3.5)\n 0.5\n \"\"\"\n if number < 0:\n raise ValueError(\"The number must be positive.\")\n \n # Get the integer part by using the floor function\n integer_part = int(number) # This truncates towards zero for positive numbers\n \n # Calculate the decimal part\n decimal_part = number - integer_part\n \n return decimal_part", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" \n Detects if the balance of a bank account falls below zero at any point \n given a list of deposit and withdrawal operations. The account starts \n with a zero balance.\n\n Args:\n operations (List[int]): A list of integers representing deposit (positive) \n and withdrawal (negative) operations.\n\n Returns:\n bool: True if the balance falls below zero at any point, otherwise False.\n\n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n \"\"\"\n balance = 0\n for operation in operations:\n balance += operation\n if balance < 0:\n return True\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list to avoid division by zero\n\n # Calculate the mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute deviations from the mean\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n \n # Calculate the mean of the absolute deviations\n mad = sum(absolute_deviations) / len(absolute_deviations)\n \n return mad", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n \"\"\" Insert a number 'delimiter' between every two consecutive elements of input list `numbers'\n \n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n \"\"\"\n if not numbers: # Check if the input list is empty\n return []\n \n result = [] # Initialize an empty list to store the result\n for i in range(len(numbers)):\n result.append(numbers[i]) # Add the current number to the result\n if i < len(numbers) - 1: # Check if it's not the last element\n result.append(delimiter) # Add the delimiter after the current number\n \n return result # Return the final result list", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring.\n \n Args:\n strings (List[str]): A list of strings to filter.\n substring (str): The substring to search for within the strings.\n \n Returns:\n List[str]: A list of strings that contain the given substring.\n \n Examples:\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n \"\"\"\n # Use a list comprehension to filter the strings\n return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string represented multiple groups for nested parentheses \n separated by spaces. For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n def max_nesting_depth(s: str) -> int:\n \"\"\" Helper function to calculate the maximum nesting depth of a single parenthesis string. \"\"\"\n max_depth = 0\n current_depth = 0\n \n for char in s:\n if char == '(':\n current_depth += 1\n max_depth = max(max_depth, current_depth)\n elif char == ')':\n current_depth -= 1\n if current_depth < 0: # More closing than opening parentheses\n return -1 # Invalid case\n return max_depth if current_depth == 0 else -1 # Valid if all opened are closed\n\n # Split the input string into groups and calculate the max nesting depth for each\n groups = paren_string.split()\n depths = []\n \n for group in groups:\n depth = max_nesting_depth(group)\n if depth == -1:\n depths.append(0) # If invalid, we can choose to return 0 or handle it differently\n else:\n depths.append(depth)\n \n return depths", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers: # Handle the case of an empty list\n return []\n \n max_so_far = numbers[0] # Initialize the maximum with the first element\n result = [max_so_far] # Start the result list with the first element's max\n \n for number in numbers[1:]: # Iterate through the rest of the numbers\n max_so_far = max(max_so_far, number) # Update the maximum if the current number is greater\n result.append(max_so_far) # Append the current maximum to the result list\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n \n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n \"\"\"\n if not numbers: # Check if the list is empty\n return (0, 1) # Return (0, 1) for empty input\n \n total_sum = 0 # Initialize sum\n total_product = 1 # Initialize product\n \n for number in numbers:\n total_sum += number # Add each number to the sum\n total_product *= number # Multiply each number to the product\n \n return (total_sum, total_product) # Return the final sum and product", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n \"\"\"\n # Edge case for empty string\n if not string:\n return ''\n \n # Find the longest palindromic suffix\n for i in range(len(string)):\n if is_palindrome(string[i:]):\n # If we find a palindromic suffix, we take the prefix before it\n prefix = string[:i]\n # Append the reverse of the prefix to the original string\n return string + prefix[::-1]\n \n # If no palindromic suffix is found, the whole string is non-palindromic\n # In this case, we will append the entire string reversed\n return string + string[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n \"\"\" \n Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n \n >>> string_xor('010', '110')\n '100'\n \"\"\"\n # Ensure both strings are of the same length by padding with leading zeros\n max_length = max(len(a), len(b))\n a = a.zfill(max_length)\n b = b.zfill(max_length)\n \n # Perform XOR operation\n result = []\n for bit_a, bit_b in zip(a, b):\n # XOR operation: '1' if bits are different, '0' if they are the same\n result.append('1' if bit_a != bit_b else '0')\n \n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n \n >>> longest([])\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n \"\"\"\n if not strings:\n return None\n \n longest_string = strings[0]\n \n for string in strings[1:]:\n if len(string) > len(longest_string):\n longest_string = string\n \n return longest_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return the greatest common divisor of two integers a and b.\n \n The function uses the Euclidean algorithm to compute the GCD.\n \n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n \"\"\"\n # Handle negative inputs by taking the absolute value\n a, b = abs(a), abs(b)\n \n # Base case: if one of the numbers is zero, return the other number\n if b == 0:\n return a\n # Recursive case: apply the Euclidean algorithm\n return greatest_common_divisor(b, a % b)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string.\n \n Args:\n string (str): The input string from which to generate prefixes.\n \n Returns:\n List[str]: A list of all prefixes of the input string.\n \n Examples:\n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n \"\"\"\n # Initialize an empty list to store prefixes\n prefixes = []\n \n # Iterate over the range of the length of the string\n for i in range(1, len(string) + 1):\n # Append the substring from the start to the current index\n prefixes.append(string[:i])\n \n return prefixes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" \n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set()\n \n # Iterate through each character in the string\n for char in lower_string:\n # Add the character to the set\n distinct_characters.add(char)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n \n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n \"\"\"\n # Check if n is negative\n if n < 0:\n return \"\"\n \n # Create a list of numbers from 0 to n\n numbers = [str(i) for i in range(n + 1)]\n \n # Join the list into a single string with spaces\n return ' '.join(numbers)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string representing musical notes in a special ASCII format.\n Your task is to parse this string and return list of integers corresponding to how many beats does each\n note last.\n\n Here is a legend:\n 'o' - whole note, lasts four beats\n 'o|' - half note, lasts two beats\n '.|' - quarter note, lasts one beat\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n # Define a mapping of note representations to their corresponding beat values\n note_to_beats = {\n 'o': 4, # whole note\n 'o|': 2, # half note\n '.|': 1 # quarter note\n }\n \n # Split the input string into individual notes\n notes = music_string.split()\n \n # Initialize a list to hold the beats for each note\n beats = []\n \n # Iterate over each note and convert it to its corresponding beat value\n for note in notes:\n if note in note_to_beats:\n beats.append(note_to_beats[note])\n else:\n # If the note is not recognized, we can choose to ignore it or raise an error\n # Here we will ignore it for robustness\n continue\n \n return beats", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n \n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n \"\"\"\n if not substring: # If the substring is empty, return 0\n return 0\n count = 0\n start = 0\n \n while True:\n start = string.find(substring, start) # Find the substring starting from 'start'\n if start == -1: # If no more occurrences are found, break the loop\n break\n count += 1 # Increment the count for each found occurrence\n start += 1 # Move to the next character to allow for overlapping matches\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to make it easier to find the closest pairs\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest elements\n for i in range(len(sorted_numbers) - 1):\n # Calculate the difference between consecutive elements\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n \n # If this difference is smaller than the minimum found so far, update\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n \"\"\" \n Input is a space-delimited string of numerals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest.\n \n >>> sort_numbers('three one five')\n 'one three five'\n \"\"\"\n \n # Mapping of words to their corresponding numeric values\n word_to_number = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n \n # Split the input string into words\n words = numbers.split()\n \n # Convert words to their corresponding numeric values\n numeric_values = [word_to_number[word] for word in words]\n \n # Sort the numeric values\n sorted_values = sorted(numeric_values)\n \n # Convert sorted numeric values back to words\n number_to_word = {v: k for k, v in word_to_number.items()}\n sorted_words = [number_to_word[num] for num in sorted_values]\n \n # Join the sorted words into a single string and return\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1.\n \n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The input list must contain at least two elements.\")\n \n min_value = min(numbers)\n max_value = max(numbers)\n \n if min_value == max_value:\n # If all numbers are the same, return a list of zeros\n return [0.0] * len(numbers)\n \n # Rescale the numbers\n rescaled = [(num - min_value) / (max_value - min_value) for num in numbers]\n \n return rescaled", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers \"\"\"\n return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n \"\"\" Return length of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n \"\"\"\n # Initialize a counter to zero\n length = 0\n \n # Iterate through each character in the string\n for char in string:\n length += 1 # Increment the counter for each character\n \n return length", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n \n >>> largest_divisor(15)\n 5\n \"\"\"\n # Edge case: if n is less than or equal to 1, there are no divisors smaller than n\n if n <= 1:\n return None # or raise an exception, depending on how you want to handle this case\n\n # Start checking from n-1 down to 1\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a dictionary to count occurrences of each number\n count = {}\n \n # Count each number's occurrences\n for number in numbers:\n if number in count:\n count[number] += 1\n else:\n count[number] = 1\n \n # Create a list to hold the result\n result = []\n \n # Add numbers that occur only once to the result list\n for number in numbers:\n if count[number] == 1:\n result.append(number)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n Input number should be equal to the product of all factors\n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n \"\"\"\n if n <= 1:\n return [] # No prime factors for numbers less than or equal to 1\n\n factors = []\n # Check for number of 2s that divide n\n while n % 2 == 0:\n factors.append(2)\n n //= 2\n\n # n must be odd at this point, so we can skip even numbers\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n factors.append(i)\n n //= i\n\n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n factors.append(n)\n\n return factors", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n \n >>> flip_case('Hello')\n 'hELLO'\n \"\"\"\n # Initialize an empty list to store the flipped characters\n flipped_chars = []\n \n # Iterate through each character in the input string\n for char in string:\n # Check if the character is lowercase\n if char.islower():\n # Convert to uppercase\n flipped_chars.append(char.upper())\n # Check if the character is uppercase\n elif char.isupper():\n # Convert to lowercase\n flipped_chars.append(char.lower())\n else:\n # If it's neither, keep the character as is (e.g., punctuation, numbers)\n flipped_chars.append(char)\n \n # Join the list of flipped characters into a single string and return it\n return ''.join(flipped_chars)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string.\n \n Args:\n strings (List[str]): A list of strings to concatenate.\n \n Returns:\n str: A single concatenated string.\n \n Examples:\n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n \"\"\"\n # Initialize an empty string to hold the result\n result = ''\n \n # Iterate through each string in the list and concatenate\n for string in strings:\n result += string\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n \n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n \"\"\"\n # Initialize an empty list to hold the filtered results\n filtered_strings = []\n \n # Iterate through each string in the input list\n for string in strings:\n # Check if the string starts with the given prefix\n if string.startswith(prefix):\n # If it does, add it to the filtered list\n filtered_strings.append(string)\n \n # Return the list of filtered strings\n return filtered_strings", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n \n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n \"\"\"\n return [x for x in l if x > 0]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n A prime number is a natural number greater than 1 that cannot be formed by multiplying two smaller natural numbers.\n \n Parameters:\n n (int): The number to check for primality.\n\n Returns:\n bool: True if n is prime, False otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return False # eliminate multiples of 2 and 3\n\n i = 5\n while i * i <= n: # check for factors from 5 to sqrt(n)\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6 # check only 6k \u00b1 1\n\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float):\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list, x: float):\n \"\"\"\n Evaluates the derivative of the polynomial with coefficients xs at point x.\n \"\"\"\n return sum(i * coeff * math.pow(x, i - 1) for i, coeff in enumerate(xs) if i > 0)\ndef find_zero(xs: list):\n \"\"\" \n xs are coefficients of a polynomial.\n find_zero finds x such that poly(x) = 0.\n find_zero returns only one zero point, even if there are many.\n Moreover, find_zero only takes list xs having an even number of coefficients\n and the largest non-zero coefficient as it guarantees a solution.\n \"\"\"\n if len(xs) % 2 != 0:\n raise ValueError(\"The number of coefficients must be even.\")\n \n # Initial guess for the root\n x0 = 0.0\n \n # Newton-Raphson method parameters\n tolerance = 1e-7\n max_iterations = 1000\n \n for _ in range(max_iterations):\n f_x0 = poly(xs, x0)\n f_prime_x0 = derivative(xs, x0)\n \n if f_prime_x0 == 0:\n raise ValueError(\"Derivative is zero. No solution found.\")\n \n # Update x using Newton's method\n x1 = x0 - f_x0 / f_prime_x0\n \n # Check for convergence\n if abs(x1 - x0) < tolerance:\n return x1\n \n x0 = x1\n \n raise ValueError(\"Maximum iterations reached. No solution found.\")", "base_status": "fail", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n This function takes a list of elements, removes duplicates, and returns a sorted list of unique elements.\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use a set to remove duplicates\n unique_elements = set(l)\n # Sort the unique elements and return as a list\n return sorted(unique_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n values_to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(values_to_sort)\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Replace values at indices divisible by 3 with sorted values\n for index, value in zip(range(len(result)), sorted_values):\n if index % 3 == 0:\n result[index] = value\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]]], "plus_fail_tests": []}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n \"\"\"Return maximum element in the list.\n \n If the list is empty, raise a ValueError.\n \n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n \"\"\"\n if not l: # Check if the list is empty\n raise ValueError(\"The list is empty. Cannot determine the maximum element.\")\n \n max_value = l[0] # Initialize max_value with the first element of the list\n for element in l: # Iterate through each element in the list\n if element > max_value: # Compare each element with the current max_value\n max_value = element # Update max_value if a larger element is found\n \n return max_value # Return the maximum value found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indexed elements\n even_indices_values.sort()\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Place the sorted even indexed values back into the result list\n for i, value in enumerate(even_indices_values):\n result[i * 2] = value # Place sorted value at even index\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with the encode_cyclic function.\n Returns the decoded string.\n \"\"\"\n # Split string into groups of length 3\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # Reverse the cycling of elements in each group\n groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_fib(n: int) -> int:\n \"\"\"\n prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n \n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n count = 0\n for fib in fibonacci_generator():\n if is_prime(fib):\n count += 1\n if count == n:\n return fib", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1]], "plus_fail_tests": []}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n \"\"\"\n triples_sum_to_zero takes a list of integers as an input.\n it returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n \"\"\"\n n = len(l)\n if n < 3:\n return False\n\n # Sort the list to use the two-pointer technique\n l.sort()\n\n for i in range(n - 2):\n # Avoid duplicates for the first element\n if i > 0 and l[i] == l[i - 1]:\n continue\n \n left, right = i + 1, n - 1\n while left < right:\n current_sum = l[i] + l[left] + l[right]\n if current_sum == 0:\n return True\n elif current_sum < 0:\n left += 1\n else:\n right -= 1\n\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n \"\"\"\n Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move at the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.\n\n :param n: The number of cars in each direction.\n :return: The total number of collisions.\n \"\"\"\n # Each car moving left to right will collide with each car moving right to left.\n # Therefore, the total number of collisions is simply n * n.\n return n * n", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n \n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n \"\"\"\n # Check if the input is a list\n if not isinstance(l, list):\n raise ValueError(\"Input must be a list.\")\n \n # Increment each element in the list by 1\n return [x + 1 for x in l]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n \n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n \"\"\"\n seen = set()\n for number in l:\n if -number in seen:\n return True\n seen.add(number)\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion.\n base numbers are less than 10.\n \n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n \"\"\"\n if base < 2 or base >= 10:\n raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n \n if x == 0:\n return '0'\n \n result = []\n negative = x < 0\n x = abs(x)\n \n while x > 0:\n remainder = x % base\n result.append(str(remainder))\n x //= base\n \n if negative:\n result.append('-')\n \n # The result is built in reverse order\n return ''.join(reversed(result))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fib4(0) -> 0\n fib4(1) -> 0\n fib4(2) -> 2\n fib4(3) -> 0\n fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n This function computes the n-th element of the fib4 number sequence efficiently without recursion.\n \n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n \n # Handle base cases\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 2\n elif n == 3:\n return 0\n \n # Initialize a list to store computed values\n fib_values = [0] * (n + 1)\n fib_values[0] = 0\n fib_values[1] = 0\n fib_values[2] = 2\n fib_values[3] = 0\n \n # Compute the fib4 values iteratively\n for i in range(4, n + 1):\n fib_values[i] = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n \n return fib_values[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n \"\"\"Given length of a side and height, return the area for a triangle.\n \n The area of a triangle can be calculated using the formula:\n Area = (base * height) / 2\n \n Parameters:\n a (float): The length of the base of the triangle.\n h (float): The height of the triangle corresponding to the base.\n \n Returns:\n float: The area of the triangle.\n \n >>> triangle_area(5, 3)\n 7.5\n \"\"\"\n # Validate inputs\n if not isinstance(a, (int, float)) or not isinstance(h, (int, float)):\n raise ValueError(\"Both 'a' and 'h' must be numbers.\")\n if a < 0 or h < 0:\n raise ValueError(\"Both 'a' and 'h' must be non-negative.\")\n \n # Calculate the area\n area = (a * h) / 2\n return area", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n \"\"\"\n Checks if given string is a palindrome.\n \n A palindrome is a string that reads the same forward and backward.\n \n Args:\n text (str): The string to check.\n \n Returns:\n bool: True if the string is a palindrome, False otherwise.\n \n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n \"\"\"\n # Normalize the string by removing spaces and converting to lowercase\n normalized_text = text.replace(\" \", \"\").lower()\n \n # Check if the normalized string is equal to its reverse\n return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n \"\"\"Return median of elements in the list l.\n \n The median is the middle value in a list of numbers. If the list has an odd number of elements,\n the median is the middle element. If the list has an even number of elements, the median is the\n average of the two middle elements.\n \n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty. Cannot compute median.\")\n \n # Sort the list\n sorted_list = sorted(l)\n n = len(sorted_list)\n \n # Calculate median\n if n % 2 == 1: # Odd number of elements\n return sorted_list[n // 2]\n else: # Even number of elements\n mid1 = sorted_list[n // 2 - 1]\n mid2 = sorted_list[n // 2]\n return (mid1 + mid2) / 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with the encode_shift function.\n Returns the decoded string by shifting every character back by 5 in the alphabet.\n \"\"\"\n return \"\".join([chr(((ord(ch) - ord(\"a\") - 5) % 26) + ord(\"a\")) for ch in s])", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n if p <= 0:\n raise ValueError(\"p must be a positive integer.\")\n \n if n < 0:\n return 0 # 2^n is not defined for negative n in this context\n \n result = 1\n base = 2\n \n # Use exponentiation by squaring for efficiency\n while n > 0:\n if n % 2 == 1: # If n is odd\n result = (result * base) % p\n base = (base * base) % p # Square the base\n n //= 2 # Divide n by 2\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n \"\"\"Return True if all numbers in the list l are below threshold t.\n \n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n \"\"\"\n # Check if all elements in the list are below the threshold\n for number in l:\n if number >= t:\n return False\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n Vowels are defined as 'a', 'e', 'i', 'o', 'u' in both lowercase and uppercase.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n \"\"\"Add two numbers x and y.\n\n This function takes two integers and returns their sum. \n It handles typical integer addition and ensures that the inputs \n are of the correct type.\n\n Args:\n x (int): The first integer to add.\n y (int): The second integer to add.\n\n Returns:\n int: The sum of x and y.\n\n Raises:\n TypeError: If either x or y is not an integer.\n\n Examples:\n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n \"\"\"\n # Check if both x and y are integers\n if not isinstance(x, int) or not isinstance(y, int):\n raise TypeError(\"Both x and y must be integers.\")\n \n # Perform the addition\n return x + y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two words have the same characters if they contain the same unique characters,\n regardless of the frequency of those characters.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Create a set of characters for each string\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Compare the two sets\n return set_s0 == set_s1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n \"\"\"Return n-th Fibonacci number.\n \n The Fibonacci sequence is defined as follows:\n - fib(0) = 0\n - fib(1) = 1\n - fib(n) = fib(n-1) + fib(n-2) for n > 1\n\n Args:\n n (int): The index of the Fibonacci number to return.\n\n Returns:\n int: The n-th Fibonacci number.\n\n Raises:\n ValueError: If n is negative.\n\n Examples:\n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n \"\"\"\n if n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n if n == 0:\n return 0\n elif n == 1:\n return 1\n \n a, b = 0, 1\n for _ in range(2, n + 1):\n a, b = b, a + b\n return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"<\" and \">\".\n return True if every opening bracket has a corresponding closing bracket.\n \"\"\"\n balance = 0\n \n for char in brackets:\n if char == '<':\n balance += 1\n elif char == '>':\n balance -= 1\n \n # If balance goes negative, it means there's a closing bracket without a matching opening bracket\n if balance < 0:\n return False\n \n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n \"\"\"Return True if list elements are monotonically increasing or decreasing.\n \n A list is considered monotonically increasing if each element is greater than or equal to the previous one.\n A list is considered monotonically decreasing if each element is less than or equal to the previous one.\n \n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n \"\"\"\n if not l: # An empty list is considered monotonic\n return True\n \n increasing = decreasing = True\n \n for i in range(1, len(l)):\n if l[i] > l[i - 1]:\n decreasing = False\n elif l[i] < l[i - 1]:\n increasing = False\n \n # If both increasing and decreasing are False, we can return early\n if not increasing and not decreasing:\n return False\n \n return increasing or decreasing", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n \n Args:\n n (int): The upper limit of the summation (inclusive).\n \n Returns:\n int: The sum of all integers from 1 to n.\n \n Examples:\n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n \"\"\"\n if n < 1:\n raise ValueError(\"Input must be a positive integer.\")\n \n return n * (n + 1) // 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n largest_factor = None\n \n # Check for number of 2s that divide n\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # n must be odd at this point, so we can skip even numbers\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n \n return largest_factor", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n \"\"\" \n Calculate the derivative of a polynomial represented by its coefficients.\n \n The polynomial is represented as:\n xs[0] + xs[1] * x + xs[2] * x^2 + ...\n \n The derivative is calculated as:\n 0 + 1 * xs[1] + 2 * xs[2] * x + 3 * xs[3] * x^2 + ...\n \n Args:\n xs (list): A list of coefficients where the index represents the power of x.\n \n Returns:\n list: A list of coefficients representing the derivative of the polynomial.\n \n Examples:\n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n \"\"\"\n # Check if the input list is empty\n if not xs:\n return []\n \n # Calculate the derivative coefficients\n derivative_coeffs = []\n for i in range(1, len(xs)):\n derivative_coeffs.append(i * xs[i])\n \n return derivative_coeffs", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"(\" and \")\".\n return True if every opening bracket has a corresponding closing bracket.\n \"\"\"\n balance = 0\n \n for char in brackets:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n \n # If balance goes negative, it means there's a closing bracket without a matching opening bracket\n if balance < 0:\n return False\n \n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n \n Args:\n n (int): The index of the FibFib sequence to compute.\n \n Returns:\n int: The n-th element of the FibFib sequence.\n \n Examples:\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 1\n \n # Initialize the first three values of the sequence\n fibfib_values = [0, 0, 1]\n \n # Compute the values iteratively up to n\n for i in range(3, n + 1):\n next_value = fibfib_values[i - 1] + fibfib_values[i - 2] + fibfib_values[i - 3]\n fibfib_values.append(next_value)\n \n return fibfib_values[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set('aeiouAEIOU')\n count = 0\n \n # Iterate through the string\n for i in range(len(s)):\n # Check if the character is a vowel\n if s[i] in vowels:\n count += 1\n # Check if the character is 'y' and it's the last character\n elif s[i].lower() == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n \n >>> circular_shift(12, 1)\n \"21\"\n >>> circular_shift(12, 2)\n \"12\"\n \"\"\"\n # Convert the integer to a string to work with its digits\n str_x = str(x)\n num_digits = len(str_x)\n \n # If shift is greater than the number of digits, reverse the string\n if shift >= num_digits:\n return str_x[::-1]\n \n # Calculate the effective shift (in case shift is larger than num_digits)\n effective_shift = shift % num_digits\n \n # Perform the circular shift\n if effective_shift == 0:\n return str_x # No shift needed\n else:\n # Shift the string\n return str_x[-effective_shift:] + str_x[:-effective_shift]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[12, 2]], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n \"\"\"Task\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n \"\"\"\n # Initialize the sum of ASCII values of uppercase characters\n total_sum = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is uppercase\n if char.isupper():\n # Add the ASCII value of the uppercase character to the total sum\n total_sum += ord(char)\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n \"\"\"\n Given an array representing a branch of a tree that has non-negative integer nodes,\n your task is to pluck one of the nodes and return it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n The plucked node should be returned in a list, [ smallest_value, its index ],\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1] \n\n Example 3:\n Input: []\n Output: []\n \n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n \"\"\"\n smallest_even_value = float('inf')\n smallest_index = -1\n\n for index, value in enumerate(arr):\n if value % 2 == 0: # Check if the value is even\n if value < smallest_even_value: # Found a smaller even value\n smallest_even_value = value\n smallest_index = index\n elif value == smallest_even_value and index < smallest_index:\n # If the same smallest even value is found, choose the one with the smallest index\n smallest_index = index\n\n if smallest_index == -1: # No even value was found\n return []\n \n return [smallest_even_value, smallest_index]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n \"\"\"\n Calculate the number of mango fruits in a basket given the number of apples and oranges.\n\n Parameters:\n s (str): A string representing the number of apples and oranges in the format \"X apples and Y oranges\".\n n (int): The total number of fruits in the basket.\n\n Returns:\n int: The number of mango fruits in the basket.\n \"\"\"\n # Split the input string to extract the number of apples and oranges\n parts = s.split(\" and \")\n apples = int(parts[0].split()[0]) # Get the number of apples\n oranges = int(parts[1].split()[0]) # Get the number of oranges\n\n # Calculate the number of mangoes\n mangoes = n - apples - oranges\n\n return mangoes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n '''\n Given list of integers, return list in strange order.\n Strange sorting, is when you start with the minimum value,\n then maximum of the remaining integers, then minimum and so on.\n\n Examples:\n strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n strange_sort_list([]) == []\n '''\n if not lst:\n return []\n\n # Sort the list to easily access min and max values\n sorted_lst = sorted(lst)\n result = []\n \n # Use two pointers to select min and max alternately\n left = 0\n right = len(sorted_lst) - 1\n \n while left <= right:\n if left == right: # If both pointers meet, add the last element\n result.append(sorted_lst[left])\n else:\n result.append(sorted_lst[left]) # Add the minimum\n result.append(sorted_lst[right]) # Add the maximum\n left += 1\n right -= 1\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n '''\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequency greater than or equal to the value of the integer itself. \n The frequency of an integer is the number of times it appears in the list.\n If no such a value exist, return -1.\n '''\n from collections import Counter\n\n # Count the frequency of each integer in the list\n frequency = Counter(lst)\n\n # Initialize the result variable to -1\n result = -1\n\n # Iterate through the frequency dictionary\n for num in frequency:\n # Check if the frequency is greater than or equal to the number itself\n if frequency[num] >= num:\n # Update the result if the current number is greater than the current result\n result = max(result, num)\n\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n '''\n Write a function that returns True if the object q will fly, and False otherwise.\n The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n '''\n # Check if the list is a palindrome\n is_balanced = (q == q[::-1])\n \n # Calculate the sum of the elements in the list\n total_weight = sum(q)\n \n # Determine if the object will fly\n return is_balanced and (total_weight <= w)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return the area of\n the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n Otherwise return -1.\n Three sides make a valid triangle when the sum of any two sides is greater \n than the third side.\n '''\n # Check for valid triangle condition\n if a <= 0 or b <= 0 or c <= 0:\n return -1\n if a + b <= c or a + c <= b or b + c <= a:\n return -1\n \n # Calculate the semi-perimeter\n s = (a + b + c) / 2\n \n # Calculate the area using Heron's formula\n area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n \n # Return the area rounded to 2 decimal points\n return round(area, 2)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n \n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total character counts and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n else:\n return lst2", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n \"\"\"\n Given an array arr of integers, find the minimum number of elements that\n need to be changed to make the array palindromic. A palindromic array is an array that\n is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n For example:\n smallest_change([1,2,3,5,4,7,9,6]) == 4\n smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n smallest_change([1, 2, 3, 2, 1]) == 0\n \"\"\"\n n = len(arr)\n changes = 0\n \n # Compare elements from the start and end towards the center\n for i in range(n // 2):\n if arr[i] != arr[n - 1 - i]:\n changes += 1\n \n return changes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n \"\"\"Returns True if x is a simple power of n, otherwise False.\n \n A number x is a simple power of n if there exists an integer k such that n**k = x.\n \n Args:\n x (int): The number to check.\n n (int): The base number.\n \n Returns:\n bool: True if x is a simple power of n, False otherwise.\n \"\"\"\n # Edge case: if n is 1, it can only produce 1**k = 1 for any k >= 0\n if n == 1:\n return x == 1\n \n # Edge case: if n is less than 1, we cannot have a valid power\n if n <= 0:\n return False\n \n # Edge case: if x is less than 1, we cannot have a valid power\n if x < 1:\n return False\n \n # Check if there exists an integer k such that n**k = x\n power = 1\n while True:\n result = n ** power\n if result == x:\n return True\n elif result > x:\n return False\n power += 1", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1, 12]], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef generate_primes(limit):\n \"\"\"Generate a list of prime numbers up to a given limit.\"\"\"\n primes = []\n for num in range(2, limit):\n if is_prime(num):\n primes.append(num)\n return primes\ndef is_multiply_prime(a):\n \"\"\"Return true if the given number is the multiplication of 3 prime numbers, false otherwise.\"\"\"\n if a < 1 or a >= 100:\n return False\n \n primes = generate_primes(100)\n \n # Check all combinations of three primes\n for i in range(len(primes)):\n for j in range(i, len(primes)):\n for k in range(j, len(primes)):\n product = primes[i] * primes[j] * primes[k]\n if product == a:\n return True\n if product > a: # No need to check further if product exceeds 'a'\n break\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n \"\"\"Counts the number of prime hexadecimal digits in the given hexadecimal string.\"\"\"\n \n # Define the set of prime hexadecimal digits\n prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n \n # Initialize a counter for prime digits\n count = 0\n \n # Iterate through each character in the input string\n for char in num:\n # Check if the character is in the set of prime hexadecimal digits\n if char in prime_hex_digits:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this integer is a cube of some integer number.\n Note: you may assume the input is always valid.\n Examples:\n iscube(1) ==> True\n iscube(2) ==> False\n iscube(-1) ==> True\n iscube(64) ==> True\n iscube(0) ==> True\n iscube(180) ==> False\n '''\n # Calculate the cube root of the absolute value of a\n cube_root = round(abs(a) ** (1/3))\n \n # Check if the cube of the rounded cube root equals the absolute value of a\n return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n \"\"\"Check if the string s is happy.\n \n A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n \n Args:\n s (str): The input string to check.\n \n Returns:\n bool: True if the string is happy, False otherwise.\n \"\"\"\n # Check if the length of the string is at least 3\n if len(s) < 3:\n return False\n \n # Iterate through the string and check every 3 consecutive characters\n for i in range(len(s) - 2):\n # Get the current substring of 3 characters\n substring = s[i:i+3]\n # Check if all characters in the substring are distinct\n if len(set(substring)) != 3:\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n \"\"\"Convert a decimal number to binary format with specific formatting.\n\n Args:\n decimal (int): A non-negative integer to convert to binary.\n\n Returns:\n str: A string representing the binary format of the decimal number,\n prefixed and suffixed with 'db'.\n \n Raises:\n ValueError: If the input is a negative integer.\n \"\"\"\n if decimal < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n # Convert decimal to binary and remove the '0b' prefix\n binary_representation = bin(decimal)[2:]\n \n # Format the result with 'db' at the beginning and end\n formatted_result = f\"db{binary_representation}db\"\n \n return formatted_result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n letter_grades = []\n \n for gpa in grades:\n if gpa == 4.0:\n letter_grades.append('A+')\n elif gpa > 3.7:\n letter_grades.append('A')\n elif gpa > 3.3:\n letter_grades.append('A-')\n elif gpa > 3.0:\n letter_grades.append('B+')\n elif gpa > 2.7:\n letter_grades.append('B')\n elif gpa > 2.3:\n letter_grades.append('B-')\n elif gpa > 2.0:\n letter_grades.append('C+')\n elif gpa > 1.7:\n letter_grades.append('C')\n elif gpa > 1.3:\n letter_grades.append('C-')\n elif gpa > 1.0:\n letter_grades.append('D+')\n elif gpa > 0.7:\n letter_grades.append('D')\n elif gpa > 0.0:\n letter_grades.append('D-')\n else:\n letter_grades.append('E')\n \n return letter_grades", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_length(string):\n \"\"\"Check if the length of the string is a prime number.\"\"\"\n length = len(string)\n return is_prime(length)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n \"\"\"\n Given a positive integer n, return the count of the numbers of n-digit\n positive integers that start or end with 1.\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n\n # Total n-digit numbers\n total_n_digit_numbers = 9 * (10 ** (n - 1))\n\n # Count of n-digit numbers that start with 1\n if n == 1:\n count_starting_with_1 = 1 # Only the number 1\n else:\n count_starting_with_1 = 10 ** (n - 1) # 1 followed by (n-1) digits (0-9)\n\n # Count of n-digit numbers that end with 1\n count_ending_with_1 = 9 * (10 ** (n - 2)) if n > 1 else 0 # (n-1) digits can be anything (0-9)\n\n # Total count of n-digit numbers that start or end with 1\n total_count = count_starting_with_1 + count_ending_with_1\n\n # If n > 1, we have double counted the numbers that both start and end with 1\n if n > 1:\n count_both_start_and_end_with_1 = 10 ** (n - 2) # 1 in the front, 1 in the back, (n-2) digits in between\n total_count -= count_both_start_and_end_with_1\n\n return total_count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits will be 1 the output should be \"1\".\n For N = 150, the sum of digits will be 6 the output should be \"110\".\n For N = 147, the sum of digits will be 12 the output should be \"1100\".\n \n Variables:\n @N integer\n Constraints: 0 \u2264 N \u2264 10000.\n Output:\n a string of binary number\n \"\"\"\n # Step 1: Calculate the sum of the digits of N\n digit_sum = sum(int(digit) for digit in str(N))\n \n # Step 2: Convert the sum to binary and remove the '0b' prefix\n binary_sum = bin(digit_sum)[2:]\n \n return binary_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum to 0\n total = 0\n \n # Iterate over the list using index and value\n for index in range(len(lst)):\n # Check if the index is odd\n if index % 2 == 1:\n # Check if the element at this index is even\n if lst[index] % 2 == 0:\n total += lst[index]\n \n return total", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words and spaces\n words = s.split(' ')\n \n # Process each word to sort its characters\n sorted_words = []\n for word in words:\n # Sort the characters of the word and join them back\n sorted_word = ''.join(sorted(word))\n sorted_words.append(sorted_word)\n \n # Join the sorted words back with spaces\n result = ' '.join(sorted_words)\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n # Iterate through each row and its index\n for row_index, row in enumerate(lst):\n # Iterate through each column in the row and its index\n for col_index, value in enumerate(row):\n # If the value matches x, store the coordinates\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort coordinates by row (ascending) and then by column (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n or sort it in descending order if the sum( first index value, last index value) is even.\n\n Note:\n * don't change the given array.\n\n Examples:\n * sort_array([]) => []\n * sort_array([5]) => [5]\n * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n \"\"\"\n # Create a copy of the original array\n sorted_array = array.copy()\n \n # Calculate the sum of the first and last elements\n if not sorted_array: # Handle empty array case\n return sorted_array\n \n first_element = sorted_array[0]\n last_element = sorted_array[-1]\n total_sum = first_element + last_element\n \n # Sort the array based on the sum's parity\n if total_sum % 2 == 0:\n # Even sum: sort in descending order\n sorted_array.sort(reverse=True)\n else:\n # Odd sum: sort in ascending order\n sorted_array.sort()\n \n return sorted_array", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n # Create a dictionary to map each letter to its encrypted counterpart\n encrypted_dict = {}\n \n # Populate the dictionary with the shifted letters\n for i in range(len(alphabet)):\n # Calculate the new position with a shift of 4 (2 * 2)\n new_position = (i + 4) % 26\n encrypted_dict[alphabet[i]] = alphabet[new_position]\n \n # Encrypt the input string\n encrypted_string = ''.join(encrypted_dict[char] for char in s if char in encrypted_dict)\n \n return encrypted_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Convert the set back to a sorted list\n sorted_unique_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_unique_elements[1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n \n For example:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n \"\"\"\n # Split the input string into sentences based on the delimiters\n sentences = []\n current_sentence = []\n delimiters = {'.', '?', '!'}\n \n for char in S:\n if char in delimiters:\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n current_sentence = []\n else:\n current_sentence.append(char)\n \n # Add the last sentence if it exists\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n \n # Count the number of sentences that start with \"I\"\n boredom_count = sum(1 for sentence in sentences if sentence.startswith(\"I\"))\n \n return boredom_count", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n '''\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n \n Examples\n any_int(5, 2, 7) \u279e True\n any_int(3, 2, 2) \u279e False\n any_int(3, -2, 1) \u279e True\n any_int(3.6, -2.2, 2) \u279e False\n '''\n \n # Check if all inputs are integers\n if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n # Check if any number is equal to the sum of the other two\n return x == y + z or y == x + z or z == x + y\n else:\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n \"\"\"\n Write a function that takes a message, and encodes in such a \n way that it swaps case of all letters, replaces all vowels in \n the message with the letter that appears 2 places ahead of that \n vowel in the English alphabet. \n Assume only letters. \n \n Examples:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n # Define vowels and their replacements\n vowels = 'aeiouAEIOU'\n replacements = {\n 'a': 'c', 'A': 'C',\n 'e': 'g', 'E': 'G',\n 'i': 'k', 'I': 'K',\n 'o': 'q', 'O': 'Q',\n 'u': 'w', 'U': 'W'\n }\n \n encoded_message = []\n \n for char in message:\n if char.isalpha(): # Check if the character is a letter\n # Swap case\n if char in vowels:\n # Replace vowel with the corresponding letter\n encoded_message.append(replacements[char])\n else:\n # Just swap the case for consonants\n encoded_message.append(char.swapcase())\n else:\n # If it's not a letter, we can choose to ignore it or keep it as is\n encoded_message.append(char)\n \n return ''.join(encoded_message)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["TEST"]], "plus_fail_tests": []}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef sum_of_digits(n):\n \"\"\"Return the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n largest_prime = -1\n \n for number in lst:\n if is_prime(number) and number > largest_prime:\n largest_prime = number\n \n if largest_prime == -1:\n return 0 # Return 0 if no prime number is found\n \n return sum_of_digits(largest_prime)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_up_to(n):\n \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n primes = []\n for i in range(2, n):\n if is_prime(i):\n primes.append(i)\n return primes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in lower \n case or all keys are strings in upper case, else return False.\n The function should return False if the given dictionary is empty.\n \n Examples:\n check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n \"\"\"\n \n # Check if the dictionary is empty\n if not input_dict:\n return False\n \n # Initialize flags for lower and upper case\n all_lower = True\n all_upper = True\n \n for key in input_dict.keys():\n # Check if the key is a string\n if not isinstance(key, str):\n return False\n \n # Check if the key is lower case\n if key.islower():\n all_upper = False\n # Check if the key is upper case\n elif key.isupper():\n all_lower = False\n else:\n # If the key is neither lower nor upper case\n return False\n \n # Return True if all keys are either lower case or upper case\n return all_lower or all_upper", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n count_upper('aBCdEf') returns 1\n count_upper('abcdefg') returns 0\n count_upper('dBBE') returns 0\n \"\"\"\n # Define the set of uppercase vowels\n uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n \n # Initialize a counter for uppercase vowels at even indices\n count = 0\n \n # Iterate over the string, checking only even indices\n for i in range(0, len(s), 2): # Step by 2 to get even indices\n if s[i] in uppercase_vowels:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.\n \"\"\"\n # Get the unit digit of the first number\n unit_digit_a = abs(a) % 10\n # Get the unit digit of the second number\n unit_digit_b = abs(b) % 10\n # Return the product of the unit digits\n return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n\n Note:\n Rounding away from zero means that if the given number is equidistant\n from two integers, the one you should return is the one that is the\n farthest from zero. For example closest_integer(\"14.5\") should\n return 15 and closest_integer(\"-14.5\") should return -15.\n '''\n # Convert the input string to a float\n num = float(value)\n \n # Get the floor and ceiling of the number\n lower_int = int(num // 1) # This is the largest integer less than or equal to num\n upper_int = lower_int + 1 # This is the smallest integer greater than num\n \n # Check the distance to the lower and upper integers\n distance_to_lower = abs(num - lower_int)\n distance_to_upper = abs(num - upper_int)\n \n # Determine which integer to return\n if distance_to_lower < distance_to_upper:\n return lower_int\n elif distance_to_upper < distance_to_lower:\n return upper_int\n else:\n # If equidistant, round away from zero\n if num > 0:\n return upper_int\n else:\n return lower_int", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n \"\"\"\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n\n stones = []\n current_stones = n\n\n for i in range(n):\n stones.append(current_stones)\n if current_stones % 2 == 0:\n current_stones += 2 # next even number\n else:\n current_stones += 2 # next odd number\n\n return stones", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n \"\"\"\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n \"\"\"\n # Replace commas with spaces and split the string by whitespace\n words = s.replace(',', ' ').split()\n \n # Return the list of words\n return words", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n \"\"\"This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If \n there's no such number, then the function should return -1.\n \n Args:\n x (int): The starting number of the range.\n y (int): The ending number of the range.\n \n Returns:\n int: The biggest even integer in the range [x, y] or -1 if none exists.\n \"\"\"\n \n # Ensure x is less than or equal to y\n if x > y:\n return -1\n \n # Start from the maximum of x and y\n for num in range(y, x - 1, -1):\n if num % 2 == 0: # Check if the number is even\n return num\n \n return -1 # Return -1 if no even number is found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n \"\"\"You are given two positive integers n and m, and your task is to compute the\n average of the integers from n through m (including n and m). \n Round the answer to the nearest integer and convert that to binary.\n If n is greater than m, return -1.\n Example:\n rounded_avg(1, 5) => \"0b11\"\n rounded_avg(7, 5) => -1\n rounded_avg(10, 20) => \"0b1111\"\n rounded_avg(20, 33) => \"0b11010\"\n \"\"\"\n if n > m:\n return -1\n \n # Calculate the sum of integers from n to m\n total_sum = sum(range(n, m + 1))\n count = m - n + 1 # Total numbers from n to m\n \n # Calculate the average and round it\n average = total_sum / count\n rounded_average = round(average)\n \n # Convert the rounded average to binary\n binary_average = bin(rounded_average)\n \n return binary_average", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n \"\"\"Given a list of positive integers x, return a sorted list of all \n elements that haven't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n def has_even_digit(n):\n \"\"\"Check if the number has any even digit.\"\"\"\n for digit in str(n):\n if int(digit) % 2 == 0:\n return True\n return False\n\n # Filter the list to include only numbers without even digits\n filtered = [num for num in x if not has_even_digit(num)]\n \n # Sort the resulting list\n return sorted(filtered)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n reverse the resulting array, and then replace each digit by its corresponding name from\n \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n For example:\n arr = [2, 1, 1, 4, 5, 8, 2, 3] \n -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n \n If the array is empty, return an empty array:\n arr = []\n return []\n \n If the array has any strange number ignore it:\n arr = [1, -1 , 55] \n -> sort arr -> [-1, 1, 55]\n -> reverse arr -> [55, 1, -1]\n return = ['One']\n \"\"\"\n \n # Mapping of digits to their corresponding names\n digit_to_name = {\n 1: \"One\",\n 2: \"Two\",\n 3: \"Three\",\n 4: \"Four\",\n 5: \"Five\",\n 6: \"Six\",\n 7: \"Seven\",\n 8: \"Eight\",\n 9: \"Nine\"\n }\n \n # Filter the array to include only integers between 1 and 9\n filtered_arr = [num for num in arr if 1 <= num <= 9]\n \n # Sort the filtered array\n filtered_arr.sort()\n \n # Reverse the sorted array\n filtered_arr.reverse()\n \n # Convert the digits to their corresponding names\n result = [digit_to_name[num] for num in filtered_arr]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def f(n):\n \"\"\" \n Implement the function f that takes n as a parameter,\n and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even\n or the sum of numbers from 1 to i otherwise.\n i starts from 1.\n the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).\n \"\"\"\n result = []\n \n for i in range(1, n + 1):\n if i % 2 == 0: # i is even\n factorial = 1\n for j in range(1, i + 1):\n factorial *= j\n result.append(factorial)\n else: # i is odd\n sum_of_numbers = sum(range(1, i + 1))\n result.append(sum_of_numbers)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n \"\"\"\n Given a positive integer n, return a tuple that has the number of even and odd\n integer palindromes that fall within the range(1, n), inclusive.\n\n Example 1:\n Input: 3\n Output: (1, 2)\n Explanation:\n Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n Example 2:\n Input: 12\n Output: (4, 6)\n Explanation:\n Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n Note:\n 1. 1 <= n <= 10^3\n 2. returned tuple has the number of even and odd integer palindromes respectively.\n \"\"\"\n \n def is_palindrome(num):\n return str(num) == str(num)[::-1]\n\n even_count = 0\n odd_count = 0\n\n for i in range(1, n + 1):\n if is_palindrome(i):\n if i % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n \"\"\"\n Write a function count_nums which takes an array of integers and returns\n the number of elements which has a sum of digits > 0.\n If a number is negative, then its first signed digit will be negative:\n e.g. -123 has signed digits -1, 2, and 3.\n \n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n def sum_of_digits(n):\n # Convert the number to string and iterate over each character\n # Calculate the sum of digits considering the sign of the first digit\n str_n = str(n)\n if n < 0:\n # For negative numbers, the first digit is negative\n return -int(str_n[1]) + sum(int(digit) for digit in str_n[2:])\n else:\n return sum(int(digit) for digit in str_n)\n\n count = 0\n for number in arr:\n if sum_of_digits(number) > 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n \"\"\"Determines whether it is possible to perform an exchange of elements\n between two lists to make lst1 a list of only even numbers.\n \n Args:\n lst1 (list): The first list of numbers.\n lst2 (list): The second list of numbers.\n \n Returns:\n str: \"YES\" if lst1 can be made all even, otherwise \"NO\".\n \"\"\"\n # Check if lst1 already contains only even numbers\n if all(x % 2 == 0 for x in lst1):\n return \"YES\"\n \n # Count the number of odd numbers in lst1\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n \n # Check if lst2 has at least one even number to exchange\n has_even_in_lst2 = any(x % 2 == 0 for x in lst2)\n \n # If lst1 has odd numbers and lst2 has at least one even number,\n # we can exchange to make lst1 all even\n if odd_count_lst1 > 0 and has_even_in_lst2:\n return \"YES\"\n \n # If lst1 has odd numbers and lst2 has no even numbers,\n # we cannot make lst1 all even\n return \"NO\"", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 3, 4], [1, 5, 3, 4]]], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return True else return False.\n If the given array is empty then return True.\n\n Note: The given list is guaranteed to have unique elements.\n \"\"\"\n \n if not arr: # Check for empty array\n return True\n \n n = len(arr)\n count = 0 # Count the number of times the order is broken\n\n for i in range(n):\n if arr[i] > arr[(i + 1) % n]: # Compare current with next (circular)\n count += 1\n\n # If there are more than one break in the order, it's not possible\n return count <= 1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n \"\"\"Task\n We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and True/False for the check.\n \"\"\"\n # Create a set of characters to delete for faster lookup\n chars_to_delete = set(c)\n \n # Build the result string by filtering out characters in chars_to_delete\n result = ''.join(char for char in s if char not in chars_to_delete)\n \n # Check if the result string is a palindrome\n is_palindrome = result == result[::-1]\n \n return (result, is_palindrome)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n \"\"\"\n if not test: # Handle the empty string case\n return {}\n\n # Split the input string into a list of letters\n letters = test.split()\n \n # Create a dictionary to count occurrences of each letter\n count_dict = {}\n for letter in letters:\n if letter in count_dict:\n count_dict[letter] += 1\n else:\n count_dict[letter] = 1\n\n # Find the maximum occurrence count\n max_count = max(count_dict.values())\n \n # Create a result dictionary for letters with the maximum count\n result = {letter: count for letter, count in count_dict.items() if count == max_count}\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n Example\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n \"\"\"\n if not nums:\n raise ValueError(\"The input array must not be empty.\")\n \n # Initialize variables to track the minimum sum and the current sum\n min_sum = float('inf')\n current_sum = 0\n \n for num in nums:\n current_sum += num\n min_sum = min(min_sum, current_sum)\n \n # If current_sum is positive, reset it to 0\n if current_sum > 0:\n current_sum = 0\n \n return min_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n \n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in s if char in '13579')\n \n # Create the output string with the count of odd digits\n output_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n \n # Append the result to the list\n result.append(output_string)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n \"\"\"\n Calculate the number of times buckets need to be lowered to empty the wells.\n\n Parameters:\n grid (list of list of int): A rectangular grid representing wells.\n capacity (int): The capacity of each bucket.\n\n Returns:\n int: The total number of times buckets need to be lowered.\n \"\"\"\n total_water = 0\n \n # Count the total amount of water in the grid\n for row in grid:\n total_water += sum(row)\n \n # Calculate the number of times buckets need to be lowered\n # Each bucket can carry 'capacity' units of water\n if total_water == 0:\n return 0 # No water to extract\n \n # Calculate the number of bucket lowers needed\n lowers_needed = math.ceil(total_water / capacity)\n \n return lowers_needed", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n \"\"\"\n Sorts an array of non-negative integers according to the number of ones in their binary representation\n in ascending order. For numbers with the same number of ones, it sorts based on their decimal value.\n\n Parameters:\n arr (list): A list of non-negative integers.\n\n Returns:\n list: A sorted list of integers based on the specified criteria.\n \"\"\"\n # Define a sorting key that sorts first by the number of ones in binary representation,\n # and then by the decimal value itself.\n return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n \"\"\"Given a string s and a natural number n, returns a list of all words from string s \n that contain exactly n consonants, in the order they appear in the string s.\n \n Args:\n s (str): The input string containing words.\n n (int): The number of consonants to filter words by.\n \n Returns:\n list: A list of words containing exactly n consonants.\n \"\"\"\n \n if not s: # Check if the string is empty\n return []\n \n # Define a set of vowels for easy checking\n vowels = set(\"aeiouAEIOU\")\n \n def count_consonants(word):\n \"\"\"Helper function to count consonants in a word.\"\"\"\n return sum(1 for char in word if char.isalpha() and char not in vowels)\n \n # Split the string into words\n words = s.split()\n \n # Filter words based on the number of consonants\n result = [word for word in words if count_consonants(word) == n]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n two consonants from the right side of the word (case sensitive).\n \n Vowels in the beginning and ending don't count. Return empty string if you didn't\n find any vowel that meets the above condition. \n\n You may assume that the given string contains English letters only.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n n = len(word)\n\n # Check if the word is too short to have consonants with a vowel in between\n if n < 3:\n return \"\"\n\n # Start from the end of the word\n for i in range(n - 2, 0, -1):\n if word[i] in vowels:\n # Check if the character before and after are consonants\n if word[i - 1].isalpha() and word[i + 1].isalpha() and \\\n word[i - 1] not in vowels and word[i + 1] not in vowels:\n return word[i]\n\n return \"\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n \n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0: # More closing than opening\n return False\n return balance == 0 # Must be balanced at the end\n\n s1, s2 = lst[0], lst[1]\n \n # Check both concatenation orders\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n \n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Get the top k elements\n top_k = sorted_arr[:k]\n \n # Return the top k elements sorted in ascending order\n return sorted(top_k)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n \"\"\"\n Given a non-empty array of integers arr and an integer k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example:\n\n Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n Output: 24 # sum of 21 + 3\n\n Constraints:\n 1. 1 <= len(arr) <= 100\n 2. 1 <= k <= len(arr)\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate through the first k elements of the array\n for i in range(k):\n # Check if the current element has at most two digits\n if -100 < arr[i] < 100:\n total_sum += arr[i]\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index in range(len(lst)):\n # Check if the index is even\n if index % 2 == 0:\n # Check if the element at this index is odd\n if lst[index] % 2 != 0:\n # Add the odd element to the total sum\n total_sum += lst[index]\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n as follows: start with any positive integer n. Then each term is obtained from the \n previous term as follows: if the previous term is even, the next term is one half of \n the previous term. If the previous term is odd, the next term is 3 times the previous\n term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n Note: \n 1. Collatz(1) is [1].\n 2. returned list sorted in increasing order.\n\n For example:\n get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n odd_numbers = set() # Use a set to avoid duplicates\n current = n\n \n while current != 1:\n if current % 2 == 1: # Check if current is odd\n odd_numbers.add(current)\n current = current // 2 if current % 2 == 0 else 3 * current + 1\n \n odd_numbers.add(1) # Add 1 to the set, as it is always part of the sequence\n return sorted(odd_numbers) # Return the sorted list of odd numbers", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n \n The date is valid if all of the following rules are satisfied:\n 1. The date string is not empty.\n 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n The number of days is not less than 1 or higher than 29 for the month 2.\n 3. The months should not be less than 1 or higher than 12.\n 4. The date should be in the format: mm-dd-yyyy\n \"\"\"\n \n # Check if the date string is empty\n if not date:\n return False\n \n # Check if the date format is correct\n if len(date) != 10 or date[2] != '-' or date[5] != '-':\n return False\n \n # Split the date into components\n try:\n month, day, year = map(int, date.split('-'))\n except ValueError:\n return False\n \n # Check month range\n if month < 1 or month > 12:\n return False\n \n # Check day range based on month\n if month in {1, 3, 5, 7, 8, 10, 12}:\n if day < 1 or day > 31:\n return False\n elif month in {4, 6, 9, 11}:\n if day < 1 or day > 30:\n return False\n elif month == 2:\n if day < 1 or day > 29:\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n '''\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return False. Assume no negative numbers and only integers.\n\n Examples\n is_sorted([5]) \u279e True\n is_sorted([1, 2, 3, 4, 5]) \u279e True\n is_sorted([1, 3, 2, 4, 5]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n '''\n \n if not lst: # An empty list is considered sorted\n return True\n \n seen = set()\n previous = None\n \n for num in lst:\n if num in seen:\n # If we see a number again, check if it's a duplicate\n if num == previous:\n return False\n else:\n seen.add(num)\n else:\n seen.add(num)\n \n if previous is not None and num < previous:\n return False\n \n previous = num\n \n return True", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n '''\n Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n Examples\n split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"abcdef\") == 3 \n '''\n \n # Check for whitespace in the text\n if ' ' in txt:\n return txt.split()\n \n # Check for commas in the text\n elif ',' in txt:\n return txt.split(',')\n \n # If no whitespace or commas, count lowercase letters with odd order\n else:\n odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n return odd_count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n if not arr: # Check for empty array\n return None\n\n product_of_signs = 1\n sum_of_magnitudes = 0\n\n for num in arr:\n if num > 0:\n sum_of_magnitudes += num\n elif num < 0:\n sum_of_magnitudes += -num\n product_of_signs *= -1 # Flip the sign for negative numbers\n else: # num == 0\n return 0 # If there's a zero, the product of signs is zero\n\n return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef intersection(interval1, interval2):\n \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n start1, end1 = interval1\n start2, end2 = interval2\n \n # Find the intersection\n start_intersection = max(start1, start2)\n end_intersection = min(end1, end2)\n \n # Check if there is an intersection\n if start_intersection > end_intersection:\n return \"NO\"\n \n # Calculate the length of the intersection\n length_of_intersection = end_intersection - start_intersection\n \n # Check if the length is a prime number\n if is_prime(length_of_intersection):\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n \"\"\"Generate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n if n < 0:\n return []\n\n # Initialize the list to hold the Tribonacci numbers\n tribonacci_sequence = []\n\n # Calculate the Tribonacci numbers based on the given rules\n for i in range(n + 1):\n if i == 1:\n tribonacci_sequence.append(3) # tri(1) = 3\n elif i == 0:\n tribonacci_sequence.append(1) # tri(0) = 1\n elif i % 2 == 0: # Even index\n tribonacci_sequence.append(1 + i / 2)\n else: # Odd index\n # tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1)\n tri_n_minus_1 = tribonacci_sequence[i - 1] if i - 1 >= 0 else 0\n tri_n_minus_2 = tribonacci_sequence[i - 2] if i - 2 >= 0 else 0\n tri_n_plus_1 = tribonacci_sequence[i + 1] if i + 1 <= n else 0\n tribonacci_sequence.append(tri_n_minus_1 + tri_n_minus_2 + tri_n_plus_1)\n\n return tribonacci_sequence", "base_status": "fail", "plus_status": null, "base_fail_tests": [[3]], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n \"\"\"Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n For example:\n digits(1) == 1\n digits(4) == 0\n digits(235) == 15\n \"\"\"\n # Initialize the product to 1 and a flag to check if any odd digit is found\n product = 1\n found_odd = False\n \n # Convert the number to a string to iterate over each digit\n for digit in str(n):\n digit = int(digit) # Convert the character back to an integer\n if digit % 2 != 0: # Check if the digit is odd\n product *= digit # Multiply the product by the odd digit\n found_odd = True # Set the flag to True since we found an odd digit\n \n # If no odd digit was found, return 0\n if not found_odd:\n return 0\n \n return product # Return the product of the odd digits", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n '''\n Create a function that takes a string as input which contains only square brackets.\n The function should return True if and only if there is a valid subsequence of brackets \n where at least one bracket in the subsequence is nested.\n\n is_nested('[[]]') \u279e True\n is_nested('[]]]]]]][[[[[]') \u279e False\n is_nested('[][]') \u279e False\n is_nested('[]') \u279e False\n is_nested('[[][]]') \u279e True\n is_nested('[[]][[') \u279e True\n '''\n \n # Initialize a counter for open brackets\n open_count = 0\n # Initialize a flag to check for nesting\n nested = False\n \n for char in string:\n if char == '[':\n open_count += 1\n # If we have more than one open bracket, we have a nested structure\n if open_count > 1:\n nested = True\n elif char == ']':\n open_count -= 1\n # If we close a bracket and there were open brackets before, we check for nesting\n if open_count < 0:\n return False # More closing brackets than opening\n # If we have a nested structure and we close a bracket, we can stop checking\n if nested and open_count == 0:\n return True\n \n # If we finish and have open brackets left, it's not valid\n return nested and open_count == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers.\n You need to return the sum of squared numbers in the given list,\n round each element in the list to the upper int (Ceiling) first.\n \n Examples:\n For lst = [1,2,3] the output should be 14\n For lst = [1,4,9] the output should be 98\n For lst = [1,3,5,7] the output should be 84\n For lst = [1.4,4.2,0] the output should be 29\n For lst = [-2.4,1,1] the output should be 6\n \"\"\"\n # Initialize the sum of squares\n total_sum = 0\n \n # Iterate through each number in the list\n for number in lst:\n # Round the number up to the nearest integer\n rounded_number = math.ceil(number)\n # Square the rounded number and add it to the total sum\n total_sum += rounded_number ** 2\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n '''\n Create a function that returns True if the last character\n of a given string is an alphabetical character and is not\n a part of a word, and False otherwise.\n Note: \"word\" is a group of characters separated by space.\n\n Examples:\n check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '''\n \n # Strip any trailing whitespace from the string\n txt = txt.rstrip()\n \n # Check if the string is empty after stripping\n if not txt:\n return False\n \n # Get the last character of the string\n last_char = txt[-1]\n \n # Check if the last character is an alphabetical character\n if last_char.isalpha():\n # Check if the last character is part of a word\n # A character is part of a word if it is preceded by a non-space character\n if len(txt) > 1 and txt[-2] != ' ':\n return False\n return True\n \n return False", "base_status": "fail", "plus_status": null, "base_fail_tests": [["eeeee e "]], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n \"\"\"Create a function which returns the largest index of an element which\n is not greater than or equal to the element immediately preceding it. If\n no such element exists then return -1. The given array will not contain\n duplicate values.\n\n Examples:\n can_arrange([1,2,4,3,5]) = 3\n can_arrange([1,2,3]) = -1\n \"\"\"\n # Check if the array is empty\n if not arr:\n return -1\n \n # Initialize the largest index to -1\n largest_index = -1\n \n # Iterate through the array starting from the second element\n for i in range(1, len(arr)):\n # Check if the current element is less than the previous element\n if arr[i] < arr[i - 1]:\n largest_index = i # Update the largest index\n \n return largest_index", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n '''\n Create a function that returns a tuple (a, b), where 'a' is\n the largest of negative integers, and 'b' is the smallest\n of positive integers in a list.\n If there is no negative or positive integers, return them as None.\n\n Examples:\n largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n largest_smallest_integers([]) == (None, None)\n largest_smallest_integers([0]) == (None, None)\n '''\n \n largest_negative = None\n smallest_positive = None\n \n for num in lst:\n if num < 0:\n if largest_negative is None or num > largest_negative:\n largest_negative = num\n elif num > 0:\n if smallest_positive is None or num < smallest_positive:\n smallest_positive = num\n \n return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n from collections import deque\n\n N = len(grid)\n directions = [(0, 1), (1, 0), (0, -1), (-1, 0)] # right, down, left, up\n min_path = None\n\n def bfs(start_row, start_col):\n queue = deque([(start_row, start_col, [grid[start_row][start_col]])])\n while queue:\n row, col, path = queue.popleft()\n if len(path) == k:\n nonlocal min_path\n if min_path is None or path < min_path:\n min_path = path\n continue\n \n for dr, dc in directions:\n new_row, new_col = row + dr, col + dc\n if 0 <= new_row < N and 0 <= new_col < N:\n queue.append((new_row, new_col, path + [grid[new_row][new_col]]))\n\n for i in range(N):\n for j in range(N):\n bfs(i, j)\n\n return min_path", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n \n Args:\n n (int): The number to evaluate.\n \n Returns:\n bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n \n Example:\n is_equal_to_sum_even(4) == False\n is_equal_to_sum_even(6) == False\n is_equal_to_sum_even(8) == True\n \"\"\"\n \n # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n if n < 8:\n return False\n \n # Check if n is even\n if n % 2 != 0:\n return False\n \n # If n is even and n >= 8, it can be expressed as the sum of 4 positive even numbers\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def parse_number(value):\n \"\"\"\n Convert a string representation of a number into a float or return the value as is if it's not a string.\n Handles both '.' and ',' as decimal separators.\n \"\"\"\n if isinstance(value, str):\n # Replace ',' with '.' for float conversion\n value = value.replace(',', '.')\n try:\n return float(value)\n except ValueError:\n return value # Return the original string if conversion fails\n return value # Return the original value if it's not a string\ndef compare_one(a, b):\n \"\"\"\n Compare two values (integers, floats, or strings representing real numbers)\n and return the larger one in its original type. Return None if they are equal.\n \"\"\"\n # Parse both values\n parsed_a = parse_number(a)\n parsed_b = parse_number(b)\n\n # Check for equality\n if parsed_a == parsed_b:\n return None\n\n # Determine the larger value\n if parsed_a > parsed_b:\n return a\n else:\n return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n \"\"\"Helper function to compute the factorial of a non-negative integer n.\"\"\"\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef special_factorial(n):\n \"\"\"Calculate the Brazilian factorial of n.\"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer greater than 0.\")\n \n result = 1\n for i in range(1, n + 1):\n result *= factorial(i)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n \"\"\"\n Given a string text, replace all spaces in it with underscores, \n and if a string has more than 2 consecutive spaces, \n then replace all consecutive spaces with - \n \n fix_spaces(\"Example\") == \"Example\"\n fix_spaces(\"Example 1\") == \"Example_1\"\n fix_spaces(\" Example 2\") == \"_Example_2\"\n fix_spaces(\" Example 3\") == \"_Example-3\"\n \"\"\"\n # Replace multiple spaces with a placeholder\n text = text.replace(' ', '-').replace(' ', '-')\n \n # Replace remaining spaces with underscores\n text = text.replace(' ', '_')\n \n # Handle the case where we might have replaced too many spaces\n # We need to ensure that we only replace sequences of spaces\n # that are more than 2 with a single '-'\n parts = []\n i = 0\n while i < len(text):\n if text[i] == '_':\n # Count consecutive underscores\n count = 0\n while i < len(text) and text[i] == '_':\n count += 1\n i += 1\n if count > 1:\n parts.append('-')\n else:\n parts.append('_')\n else:\n parts.append(text[i])\n i += 1\n \n # Join the parts back together\n result = ''.join(parts)\n \n # Handle leading and trailing underscores\n result = result.strip('_')\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Mudasir Hanif "]], "plus_fail_tests": []}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n \"\"\"\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n \n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126\n \"\"\"\n total_sum = 0\n \n for index, value in enumerate(lst):\n if index % 3 == 0:\n total_sum += value ** 2 # Square if index is a multiple of 3\n elif index % 4 == 0:\n total_sum += value ** 3 # Cube if index is a multiple of 4 and not a multiple of 3\n else:\n total_sum += value # Keep the value unchanged if not a multiple of 3 or 4\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n \"\"\"Check if the given file name is valid based on specific criteria.\"\"\"\n \n # Check for exactly one dot\n if file_name.count('.') != 1:\n return 'No'\n \n # Split the file name into name and extension\n name, extension = file_name.split('.')\n \n # Check if the name is not empty and starts with a letter\n if not name or not name[0].isalpha():\n return 'No'\n \n # Check if the extension is valid\n valid_extensions = ['txt', 'exe', 'dll']\n if extension not in valid_extensions:\n return 'No'\n \n # Count the number of digits in the file name\n digit_count = sum(c.isdigit() for c in file_name)\n \n # Check if there are more than three digits\n if digit_count > 3:\n return 'No'\n \n return 'Yes'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef words_in_sentence(sentence):\n \"\"\"\n Given a string representing a sentence, return a string that contains the words\n from the original sentence whose lengths are prime numbers.\n The order of the words in the new string should be the same as the original one.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Filter words whose lengths are prime\n prime_length_words = [word for word in words if is_prime(len(word))]\n \n # Join the filtered words into a single string\n return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n \"\"\"Simplifies the expression x * n and checks if the result is a whole number.\n \n Args:\n x (str): A string representation of a fraction in the format /.\n n (str): A string representation of a fraction in the format /.\n \n Returns:\n bool: True if x * n evaluates to a whole number, False otherwise.\n \"\"\"\n # Split the fractions into numerator and denominator\n x_numerator, x_denominator = map(int, x.split('/'))\n n_numerator, n_denominator = map(int, n.split('/'))\n \n # Calculate the product of the fractions\n # x * n = (x_numerator / x_denominator) * (n_numerator / n_denominator)\n # This simplifies to (x_numerator * n_numerator) / (x_denominator * n_denominator)\n \n product_numerator = x_numerator * n_numerator\n product_denominator = x_denominator * n_denominator\n \n # Check if the product is a whole number\n return product_numerator % product_denominator == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n \"\"\"\n Sorts the given list of integers in ascending order according to the sum of their digits.\n If there are several items with similar sum of their digits, they are ordered based on their\n index in the original list.\n\n Args:\n nums (list of int): The list of integers to be sorted.\n\n Returns:\n list of int: The sorted list of integers.\n \"\"\"\n \n def digit_sum(n):\n \"\"\"Calculate the sum of the digits of an integer n.\"\"\"\n return sum(int(digit) for digit in str(abs(n)))\n\n # Sort the list using a tuple (digit sum, original index)\n sorted_nums = sorted(enumerate(nums), key=lambda x: (digit_sum(x[1]), x[0]))\n \n # Extract the sorted numbers from the sorted tuples\n return [num for index, num in sorted_nums]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n \"\"\"Returns the number of elements in the array that are greater than 10 \n and both the first and last digits of the number are odd (1, 3, 5, 7, 9).\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n int: The count of numbers meeting the criteria.\n \"\"\"\n \n def is_odd_digit(digit):\n \"\"\"Check if a digit is odd.\"\"\"\n return digit in {'1', '3', '5', '7', '9'}\n \n count = 0\n \n for num in nums:\n if num > 10:\n str_num = str(abs(num)) # Convert to string and take absolute value\n first_digit = str_num[0]\n last_digit = str_num[-1]\n \n if is_odd_digit(first_digit) and is_odd_digit(last_digit):\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n \"\"\"\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example :\n Input: n = 5\n Output: 1\n Explanation: \n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n \"\"\"\n # Create the array a based on the given formula\n a = [i * i - i + 1 for i in range(1, n + 1)]\n \n # Count the number of valid triples\n count = 0\n \n # Iterate through all possible triples (i, j, k) with i < j < k\n for i in range(n):\n for j in range(i + 1, n):\n for k in range(j + 1, n):\n if (a[i] + a[j] + a[k]) % 3 == 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closest to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sorted by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct planet names. \n Examples\n bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n '''\n \n # List of planets in order from the Sun\n planets = [\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n ]\n \n # Check if the provided planet names are valid\n if planet1 not in planets or planet2 not in planets:\n return ()\n \n # Get the indices of the planets\n index1 = planets.index(planet1)\n index2 = planets.index(planet2)\n \n # Determine the range of indices for the planets in between\n start_index = min(index1, index2) + 1\n end_index = max(index1, index2)\n \n # Get the planets in between and return them as a tuple\n return tuple(planets[start_index:end_index])", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef x_or_y(n, x, y):\n \"\"\"Return x if n is a prime number, otherwise return y.\"\"\"\n if is_prime(n):\n return x\n else:\n return y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length and alphabetically.\n \n Args:\n lst (list of str): A list of strings.\n \n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the filtered list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n \n double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n double_the_difference([-1, -2, 0]) == 0\n double_the_difference([9, -2]) == 81\n double_the_difference([0]) == 0 \n \n If the input list is empty, return 0.\n '''\n # Initialize the sum of squares\n sum_of_squares = 0\n \n # Iterate through each number in the list\n for num in lst:\n # Check if the number is a positive odd integer\n if isinstance(num, int) and num >= 0 and num % 2 != 0:\n # Add the square of the odd number to the sum\n sum_of_squares += num ** 2\n \n return sum_of_squares", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n \"\"\"\n Compares the actual scores of matches with the guessed scores.\n \n Parameters:\n game (list of int): The actual scores of the matches.\n guess (list of int): The guessed scores of the matches.\n \n Returns:\n list of int: A list where each element is the absolute difference \n between the actual score and the guessed score, or 0 if the guess is correct.\n \"\"\"\n # Check if the lengths of game and guess are equal\n if len(game) != len(guess):\n raise ValueError(\"The length of game and guess must be the same.\")\n \n # Calculate the absolute differences\n result = [abs(g - a) for a, g in zip(game, guess)]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n \"\"\"Finds the strongest extension based on the strength defined by the number of uppercase and lowercase letters.\"\"\"\n \n def calculate_strength(extension):\n \"\"\"Calculates the strength of the extension.\"\"\"\n CAP = sum(1 for char in extension if char.isupper())\n SM = sum(1 for char in extension if char.islower())\n return CAP - SM\n\n strongest_extension = None\n strongest_strength = float('-inf') # Start with the lowest possible strength\n\n for extension in extensions:\n strength = calculate_strength(extension)\n # Check if this extension is stronger or if it's the first one\n if strength > strongest_strength:\n strongest_strength = strength\n strongest_extension = extension\n\n # Return the result in the required format\n return f\"{class_name}.{strongest_extension}\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n \"\"\"Check if the second word or any of its rotations is a substring in the first word.\"\"\"\n \n # Edge case: if b is empty, it is considered a substring of any string\n if not b:\n return True\n \n # Edge case: if b is longer than a, it cannot be a substring\n if len(b) > len(a):\n return False\n \n # Create a new string that is the concatenation of b with itself\n # This will contain all possible rotations of b as substrings\n b_rotations = b + b\n \n # Check if any rotation of b is a substring of a\n return b_rotations.find(a) != -1", "base_status": "fail", "plus_status": null, "base_fail_tests": [["yello", "ell"]], "plus_fail_tests": []}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n Example:\n even_odd_count(-12) ==> (1, 1)\n even_odd_count(123) ==> (1, 2)\n \"\"\"\n # Convert the number to its absolute value to ignore the sign\n num = abs(num)\n \n # Initialize counters for even and odd digits\n even_count = 0\n odd_count = 0\n \n # Convert the number to a string to iterate over each digit\n for digit in str(num):\n # Convert the character back to an integer\n digit = int(digit)\n \n # Check if the digit is even or odd and increment the respective counter\n if digit % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n if not (1 <= number <= 1000):\n raise ValueError(\"Number must be between 1 and 1000 inclusive.\")\n\n # Define the mapping of integers to Roman numerals\n roman_numerals = [\n (1000, 'm'),\n (900, 'cm'),\n (500, 'd'),\n (400, 'cd'),\n (100, 'c'),\n (90, 'xc'),\n (50, 'l'),\n (40, 'xl'),\n (10, 'x'),\n (9, 'ix'),\n (5, 'v'),\n (4, 'iv'),\n (1, 'i')\n ]\n\n result = []\n \n for value, numeral in roman_numerals:\n while number >= value:\n result.append(numeral)\n number -= value\n\n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return True if the three\n sides form a right-angled triangle, False otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or \n 90 degree.\n \n Example:\n right_angle_triangle(3, 4, 5) == True\n right_angle_triangle(1, 2, 3) == False\n '''\n # First, we need to check if the sides can form a triangle\n if a <= 0 or b <= 0 or c <= 0:\n return False # Sides must be positive\n \n # Sort the sides to easily identify the longest side\n sides = sorted([a, b, c])\n \n # Check the Pythagorean theorem: a^2 + b^2 = c^2\n return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n \"\"\"Return the word with the maximum number of unique characters.\n If multiple words have the same number of unique characters,\n return the one that comes first in lexicographical order.\n \n Args:\n words (list of str): A list of words to evaluate.\n \n Returns:\n str: The word with the maximum number of unique characters.\n \"\"\"\n max_word = \"\"\n max_unique_count = 0\n\n for word in words:\n # Calculate the number of unique characters in the word\n unique_count = len(set(word))\n \n # Check if this word has more unique characters or is lexicographically smaller\n if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n max_word = word\n max_unique_count = unique_count\n\n return max_word", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic algebra operations, and \n the second list is a list of integers. Use the two given lists to build the algebraic \n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + ) \n Subtraction ( - ) \n Multiplication ( * ) \n Floor division ( // ) \n Exponentiation ( ** ) \n\n Example:\n operator = ['+', '*', '-']\n operand = [2, 3, 4, 5]\n result = 2 + 3 * 4 - 5\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.\n \"\"\"\n \n # Start with the first operand\n result = operand[0]\n \n # Iterate through the operators and operands\n for i in range(len(operator)):\n op = operator[i]\n next_operand = operand[i + 1]\n \n if op == '+':\n result += next_operand\n elif op == '-':\n result -= next_operand\n elif op == '*':\n result *= next_operand\n elif op == '//':\n # Handle division by zero\n if next_operand == 0:\n raise ValueError(\"Division by zero is not allowed.\")\n result //= next_operand\n elif op == '**':\n result **= next_operand\n else:\n raise ValueError(f\"Invalid operator: {op}\")\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": []}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n \"\"\"\n You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n \n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n \n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots that exist in stock\n \n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n \"\"\"\n \n # Calculate how many more carrots are needed\n additional_needed = need - number\n \n # If no additional carrots are needed, return the current state\n if additional_needed <= 0:\n return [number, remaining]\n \n # Determine how many carrots can be eaten from the remaining stock\n if remaining >= additional_needed:\n total_eaten = number + additional_needed\n carrots_left = remaining - additional_needed\n else:\n total_eaten = number + remaining\n carrots_left = 0 # All remaining carrots are eaten\n \n return [total_eaten, carrots_left]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": []}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n \"\"\"You are given a string s.\n if s[i] is a letter, reverse its case from lower to upper or vice versa, \n otherwise keep it as it is.\n If the string contains no letters, reverse the string.\n The function should return the resulted string.\n Examples\n solve(\"1234\") = \"4321\"\n solve(\"ab\") = \"AB\"\n solve(\"#a@C\") = \"#A@c\"\n \"\"\"\n # Check if there are any letters in the string\n has_letters = any(c.isalpha() for c in s)\n \n if has_letters:\n # If there are letters, reverse the case of each character\n result = ''.join(c.swapcase() for c in s)\n else:\n # If there are no letters, reverse the string\n result = s[::-1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string.\n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n \"\"\"\n if text == \"\":\n return None\n # Create an MD5 hash object\n md5_hash = hashlib.md5()\n # Update the hash object with the bytes of the string\n md5_hash.update(text.encode('utf-8'))\n # Return the hexadecimal digest of the hash\n return md5_hash.hexdigest()", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascending order.\n\n For example:\n generate_integers(2, 8) => [2, 4, 6, 8]\n generate_integers(8, 2) => [2, 4, 6, 8]\n generate_integers(10, 14) => []\n \"\"\"\n # Ensure a is less than or equal to b\n start = min(a, b)\n end = max(a, b)\n\n # Generate a list of even integers in the range\n even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n return even_integers", "base_status": "fail", "plus_status": null, "base_fail_tests": [[2, 10]], "plus_fail_tests": []}]}} \ No newline at end of file diff --git a/llm_based_139_eval_results.json b/llm_based_139_eval_results.json new file mode 100644 index 000000000..7d67fcec1 --- /dev/null +++ b/llm_based_139_eval_results.json @@ -0,0 +1 @@ +{"date": "2024-07-27 01:12", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to make it easier to find close elements\n numbers.sort()\n \n # Check the differences between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" \n Input to this function is a string containing multiple groups of nested parentheses. \n The goal is to separate those groups into separate strings and return the list of those.\n Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n Ignore any spaces in the input string.\n \n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n # Remove spaces from the input string\n paren_string = paren_string.replace(\" \", \"\")\n \n result = []\n current_group = []\n balance = 0\n \n for char in paren_string:\n if char == '(':\n balance += 1\n current_group.append(char)\n elif char == ')':\n balance -= 1\n current_group.append(char)\n \n # When balance is zero, we have a complete group\n if balance == 0 and current_group:\n result.append(''.join(current_group))\n current_group = [] # Reset for the next group\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into\n an integer part (largest integer smaller than given number) and decimals\n (leftover part always smaller than 1).\n\n Return the decimal part of the number.\n >>> truncate_number(3.5)\n 0.5\n \"\"\"\n if number < 0:\n raise ValueError(\"The number must be positive.\")\n \n # Get the integer part by using the floor function\n integer_part = int(number) # This truncates towards zero for positive numbers\n \n # Calculate the decimal part\n decimal_part = number - integer_part\n \n return decimal_part", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" \n Detect if the balance of a bank account falls below zero at any point \n given a list of deposit and withdrawal operations. The account starts \n with a zero balance.\n\n Args:\n operations (List[int]): A list of integers representing deposit (positive) \n and withdrawal (negative) operations.\n\n Returns:\n bool: True if the balance falls below zero at any point, otherwise False.\n\n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n \"\"\"\n balance = 0\n for operation in operations:\n balance += operation\n if balance < 0:\n return True\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for an empty list to avoid division by zero\n\n # Calculate the mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute deviations from the mean\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n \n # Calculate the mean of the absolute deviations\n mad = sum(absolute_deviations) / len(absolute_deviations)\n \n return mad", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n \"\"\" Insert a number 'delimiter' between every two consecutive elements of input list `numbers'\n \n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n for i in range(len(numbers)):\n result.append(numbers[i])\n if i < len(numbers) - 1: # Avoid adding delimiter after the last element\n result.append(delimiter)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring.\n \n Args:\n strings (List[str]): A list of strings to filter.\n substring (str): The substring to search for within the strings.\n \n Returns:\n List[str]: A list of strings that contain the given substring.\n \n Examples:\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n \"\"\"\n # Use a list comprehension to filter the strings\n return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n def max_nesting_depth(s: str) -> int:\n \"\"\" Helper function to calculate the maximum nesting depth of a single parenthesis string. \"\"\"\n max_depth = 0\n current_depth = 0\n \n for char in s:\n if char == '(':\n current_depth += 1\n max_depth = max(max_depth, current_depth)\n elif char == ')':\n current_depth -= 1\n if current_depth < 0: # More closing than opening parentheses\n return -1 # Invalid case\n \n if current_depth != 0: # Unmatched opening parentheses\n return -1 # Invalid case\n \n return max_depth\n\n # Split the input string into groups based on spaces\n groups = paren_string.split()\n depths = []\n\n for group in groups:\n depth = max_nesting_depth(group)\n if depth == -1:\n depths.append(0) # Treat invalid cases as depth 0\n else:\n depths.append(depth)\n\n return depths", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n \n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n \"\"\"\n if not numbers: # Check if the list is empty\n return (0, 1)\n \n total_sum = 0\n total_product = 1\n \n for number in numbers:\n total_sum += number # Calculate the sum\n total_product *= number # Calculate the product\n \n return (total_sum, total_product)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers: # Handle the case of an empty list\n return []\n \n max_so_far = numbers[0] # Initialize the maximum with the first element\n result = [max_so_far] # Start the result list with the first element's max\n \n for number in numbers[1:]: # Iterate through the rest of the numbers\n if number > max_so_far:\n max_so_far = number # Update max_so_far if the current number is greater\n result.append(max_so_far) # Append the current max to the result list\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n \"\"\"\n # Edge case for empty string\n if not string:\n return ''\n \n # Find the longest palindromic suffix\n for i in range(len(string)):\n if is_palindrome(string[i:]):\n # If we find a palindromic suffix, we take the prefix before it\n prefix = string[:i]\n # Append the reverse of the prefix to the original string\n return string + prefix[::-1]\n \n # If no palindromic suffix is found, the whole string is non-palindromic\n # In this case, we will append the entire string reversed\n return string + string[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n \"\"\" \n Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n \n >>> string_xor('010', '110')\n '100'\n \"\"\"\n # Ensure both strings are of the same length by padding with leading zeros\n max_length = max(len(a), len(b))\n a = a.zfill(max_length)\n b = b.zfill(max_length)\n \n # Perform XOR operation\n result = []\n for bit_a, bit_b in zip(a, b):\n # XOR operation: '1' if bits are different, '0' if they are the same\n result.append('1' if bit_a != bit_b else '0')\n \n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return the greatest common divisor of two integers a and b.\n \n The function uses the Euclidean algorithm to compute the GCD.\n \n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n \"\"\"\n # Handle negative inputs by taking the absolute value\n a, b = abs(a), abs(b)\n \n # Base case: if one of the numbers is zero, return the other number\n if a == 0:\n return b\n if b == 0:\n return a\n \n # Implementing the Euclidean algorithm\n while b != 0:\n a, b = b, a % b\n \n return a", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n \n >>> longest([])\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n \"\"\"\n if not strings:\n return None\n \n longest_string = strings[0]\n \n for string in strings[1:]:\n if len(string) > len(longest_string):\n longest_string = string\n \n return longest_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string.\n \n Args:\n string (str): The input string from which to generate prefixes.\n \n Returns:\n List[str]: A list of all prefixes of the input string.\n \n Examples:\n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n \"\"\"\n # Initialize an empty list to store the prefixes\n prefixes = []\n \n # Iterate over the range of the length of the string\n for i in range(1, len(string) + 1):\n # Append the substring from the start to the current index\n prefixes.append(string[:i])\n \n return prefixes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set()\n \n # Iterate through each character in the string\n for char in lower_string:\n # Add the character to the set\n distinct_characters.add(char)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n \n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n \"\"\"\n # Check if n is less than 0, return an empty string as per the problem's context\n if n < 0:\n return ''\n \n # Generate a list of numbers from 0 to n\n numbers = [str(i) for i in range(n + 1)]\n \n # Join the list into a single string with space as a delimiter\n return ' '.join(numbers)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" \n Input to this function is a string representing musical notes in a special ASCII format.\n Your task is to parse this string and return list of integers corresponding to how many beats does each\n note last.\n\n Here is a legend:\n 'o' - whole note, lasts four beats\n 'o|' - half note, lasts two beats\n '.|' - quarter note, lasts one beat\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n # Define a mapping of note representations to their corresponding beat values\n note_to_beats = {\n 'o': 4, # whole note\n 'o|': 2, # half note\n '.|': 1 # quarter note\n }\n \n # Split the input string into individual notes\n notes = music_string.split()\n \n # Initialize a list to hold the beats for each note\n beats = []\n \n # Iterate over each note and convert it to its corresponding beat value\n for note in notes:\n if note in note_to_beats:\n beats.append(note_to_beats[note])\n else:\n # If an unknown note is encountered, we can choose to ignore it or raise an error\n # Here we will ignore it for robustness\n continue\n \n return beats", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n \n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n \"\"\"\n if not substring: # If the substring is empty, return 0\n return 0\n \n count = 0\n start = 0\n \n while True:\n start = string.find(substring, start) # Find the next occurrence of substring\n if start == -1: # If no more occurrences are found, break the loop\n break\n count += 1 # Increment the count for each found occurrence\n start += 1 # Move to the next character to allow for overlapping matches\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n \"\"\" \n Input is a space-delimited string of numerals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest.\n \n >>> sort_numbers('three one five')\n 'one three five'\n \"\"\"\n \n # Mapping of words to their corresponding integer values\n word_to_number = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n \n # Split the input string into words\n words = numbers.split()\n \n # Convert words to their corresponding numbers\n numbers_list = [word_to_number[word] for word in words]\n \n # Sort the numbers\n numbers_list.sort()\n \n # Convert sorted numbers back to words\n number_to_word = {v: k for k, v in word_to_number.items()}\n sorted_words = [number_to_word[number] for number in numbers_list]\n \n # Join the sorted words into a single string\n return ' '.join(sorted_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to find the closest pairs easily\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest elements\n for i in range(len(sorted_numbers) - 1):\n # Calculate the difference between consecutive elements\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n \n # If this difference is smaller than the minimum found so far, update\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1.\n \n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The input list must contain at least two elements.\")\n \n min_value = min(numbers)\n max_value = max(numbers)\n \n if min_value == max_value:\n # If all numbers are the same, return a list of zeros\n return [0.0] * len(numbers)\n \n # Rescale the numbers\n rescaled = [(num - min_value) / (max_value - min_value) for num in numbers]\n \n return rescaled", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers \"\"\"\n return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n \"\"\" Return length of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n \"\"\"\n # Initialize a counter to zero\n length = 0\n \n # Iterate through each character in the string\n for char in string:\n length += 1 # Increment the counter for each character\n \n return length", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n Input number should be equal to the product of all factors\n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n \"\"\"\n if n <= 1:\n return [] # No prime factors for numbers less than or equal to 1\n\n factors = []\n # Check for number of 2s that divide n\n while n % 2 == 0:\n factors.append(2)\n n //= 2\n\n # n must be odd at this point, so we can skip even numbers\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n factors.append(i)\n n //= i\n\n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n factors.append(n)\n\n return factors", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n \n Args:\n n (int): The number to find the largest divisor for.\n \n Returns:\n int: The largest divisor of n that is smaller than n.\n \n Raises:\n ValueError: If n is less than or equal to 1, as there are no divisors in that case.\n \n Examples:\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n raise ValueError(\"Input must be greater than 1 to have a valid divisor.\")\n \n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a dictionary to count occurrences of each number\n count = {}\n \n # Count each number's occurrences\n for number in numbers:\n if number in count:\n count[number] += 1\n else:\n count[number] = 1\n \n # Create a list to hold the result\n result = []\n \n # Add numbers that occur only once to the result list\n for number in numbers:\n if count[number] == 1:\n result.append(number)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n \n >>> flip_case('Hello')\n 'hELLO'\n \"\"\"\n # Initialize an empty list to store the flipped characters\n flipped_chars = []\n \n # Iterate through each character in the input string\n for char in string:\n # Check if the character is lowercase\n if char.islower():\n # Convert to uppercase\n flipped_chars.append(char.upper())\n # Check if the character is uppercase\n elif char.isupper():\n # Convert to lowercase\n flipped_chars.append(char.lower())\n else:\n # If it's neither, keep the character as is (e.g., punctuation, numbers)\n flipped_chars.append(char)\n \n # Join the list of flipped characters into a single string and return it\n return ''.join(flipped_chars)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n \n Args:\n strings (List[str]): A list of strings to filter.\n prefix (str): The prefix to filter the strings by.\n \n Returns:\n List[str]: A list of strings that start with the given prefix.\n \n Examples:\n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n \"\"\"\n # Use a list comprehension to filter the strings\n return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string.\n \n Args:\n strings (List[str]): A list of strings to concatenate.\n \n Returns:\n str: A single concatenated string.\n \n Examples:\n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n \"\"\"\n # Initialize an empty string to hold the result\n result = ''\n \n # Iterate through each string in the list and concatenate\n for string in strings:\n result += string\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n \n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n \"\"\"\n return [x for x in l if x > 0]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n A prime number is a natural number greater than 1 that cannot be formed by multiplying two smaller natural numbers.\n \n Args:\n n (int): The number to check for primality.\n \n Returns:\n bool: True if n is prime, False otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return False # eliminate multiples of 2 and 3\n\n i = 5\n while i * i <= n: # check for factors from 5 to sqrt(n)\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6 # check only 6k \u00b1 1\n\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float) -> float:\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list) -> list:\n \"\"\"\n Computes the derivative of the polynomial with coefficients xs.\n The derivative is calculated as: \n d/dx (a0 + a1*x + a2*x^2 + ... + an*x^n) = a1 + 2*a2*x + ... + n*an*x^(n-1)\n \"\"\"\n return [i * coeff for i, coeff in enumerate(xs) if i > 0]\ndef find_zero(xs: list) -> float:\n \"\"\" \n xs are coefficients of a polynomial.\n find_zero finds x such that poly(x) = 0.\n find_zero returns only one zero point, even if there are many.\n Moreover, find_zero only takes list xs having an even number of coefficients\n and the largest non-zero coefficient as it guarantees a solution.\n \"\"\"\n if len(xs) % 2 != 0:\n raise ValueError(\"The number of coefficients must be even.\")\n \n # Initial guess for the root\n x = 0.0\n \n # Using Newton-Raphson method to find the root\n for _ in range(100): # Limit iterations to avoid infinite loops\n f_x = poly(xs, x)\n f_prime_x = poly(derivative(xs), x)\n \n if f_prime_x == 0: # Avoid division by zero\n raise ValueError(\"Derivative is zero. No solution found.\")\n \n # Update x using Newton's method\n x_new = x - f_x / f_prime_x\n \n # Check for convergence\n if abs(x_new - x) < 1e-7: # Tolerance level\n return x_new\n \n x = x_new\n \n raise ValueError(\"No root found within the iteration limit.\")", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[-10, -2]]], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \"\"\"\n # Extract values at indices divisible by 3\n values_to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(values_to_sort)\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Replace values at indices divisible by 3 with sorted values\n for index, sorted_value in zip([i for i in range(len(l)) if i % 3 == 0], sorted_values):\n result[index] = sorted_value\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n \"\"\"Return maximum element in the list.\n \n If the list is empty, raise a ValueError.\n \n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n \"\"\"\n if not l: # Check if the list is empty\n raise ValueError(\"The list is empty. Cannot determine the maximum element.\")\n \n max_value = l[0] # Initialize max_value with the first element of the list\n for element in l: # Iterate through each element in the list\n if element > max_value: # Compare each element with the current max_value\n max_value = element # Update max_value if a larger element is found\n \n return max_value # Return the maximum value found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n This function takes a list of elements, removes duplicates, and returns a sorted list of unique elements.\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use a set to remove duplicates\n unique_elements = set(l)\n \n # Sort the unique elements and return as a list\n return sorted(unique_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indexed elements\n even_indices_values.sort()\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Place the sorted even indexed values back into their positions\n for i, value in enumerate(even_indices_values):\n result[i * 2] = value # Place sorted value at even index\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_fib(n: int) -> int:\n \"\"\"\n prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n \n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n count = 0\n for fib in fibonacci_generator():\n if is_prime(fib):\n count += 1\n if count == n:\n return fib", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1]], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str) -> str:\n \"\"\"\n Takes as input a string encoded with the encode_cyclic function.\n Returns the decoded string.\n \"\"\"\n # Split string into groups of length 3\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # Reverse the cycling of elements in each group\n groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n \"\"\"\n triples_sum_to_zero takes a list of integers as an input.\n it returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n \"\"\"\n n = len(l)\n if n < 3:\n return False\n\n # Sort the list to use the two-pointer technique\n l.sort()\n\n for i in range(n - 2):\n # Avoid duplicates for the first element\n if i > 0 and l[i] == l[i - 1]:\n continue\n \n left, right = i + 1, n - 1\n while left < right:\n current_sum = l[i] + l[left] + l[right]\n if current_sum == 0:\n return True\n elif current_sum < 0:\n left += 1\n else:\n right -= 1\n\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n \"\"\"\n Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move at the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.\n\n :param n: The number of cars in each direction.\n :return: The number of collisions.\n \"\"\"\n # Each car moving left to right will collide with each car moving right to left.\n # Therefore, the total number of collisions is simply n * n.\n return n * n", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n \n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n \"\"\"\n # Check if the input is a list\n if not isinstance(l, list):\n raise ValueError(\"Input must be a list.\")\n \n # Increment each element in the list by 1\n return [x + 1 for x in l]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n \n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n \"\"\"\n seen = set()\n for number in l:\n if -number in seen:\n return True\n seen.add(number)\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion.\n base numbers are less than 10.\n \n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n \"\"\"\n if base < 2 or base >= 10:\n raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n \n if x == 0:\n return '0'\n \n result = []\n negative = x < 0\n x = abs(x)\n\n while x > 0:\n remainder = x % base\n result.append(str(remainder))\n x //= base\n\n if negative:\n result.append('-')\n\n # The result is built in reverse order\n return ''.join(reversed(result))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n \"\"\"Given length of a side and height, return area for a triangle.\n \n The area of a triangle can be calculated using the formula:\n Area = (base * height) / 2\n \n Parameters:\n a (float): The length of the base of the triangle.\n h (float): The height of the triangle.\n \n Returns:\n float: The area of the triangle.\n \n Raises:\n ValueError: If the base or height is not positive.\n \n >>> triangle_area(5, 3)\n 7.5\n >>> triangle_area(0, 3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(5, 0)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(-5, 3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n >>> triangle_area(5, -3)\n Traceback (most recent call last):\n ...\n ValueError: Base and height must be positive numbers.\n \"\"\"\n \n if a <= 0 or h <= 0:\n raise ValueError(\"Base and height must be positive numbers.\")\n \n return (a * h) / 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fib4(0) -> 0\n fib4(1) -> 0\n fib4(2) -> 2\n fib4(3) -> 0\n fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n This function computes the n-th element of the fib4 number sequence efficiently without recursion.\n \n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n # Handle base cases\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 2\n elif n == 3:\n return 0\n \n # Initialize a list to store computed values\n fib_values = [0] * (n + 1)\n fib_values[0] = 0\n fib_values[1] = 0\n fib_values[2] = 2\n fib_values[3] = 0\n \n # Compute the fib4 values iteratively\n for i in range(4, n + 1):\n fib_values[i] = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n \n return fib_values[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n \"\"\"Return median of elements in the list l.\n \n The median is the middle value in a list of numbers. If the list has an odd number of elements,\n the median is the middle element. If the list has an even number of elements, the median is the\n average of the two middle elements.\n \n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n \"\"\"\n if not l:\n raise ValueError(\"The list is empty. Cannot compute median.\")\n \n # Sort the list\n sorted_list = sorted(l)\n n = len(sorted_list)\n \n # Calculate median\n if n % 2 == 1: # Odd number of elements\n return sorted_list[n // 2]\n else: # Even number of elements\n mid1 = sorted_list[n // 2 - 1]\n mid2 = sorted_list[n // 2]\n return (mid1 + mid2) / 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n \"\"\"\n Checks if given string is a palindrome.\n \n A palindrome is a string that reads the same forward and backward.\n \n Args:\n text (str): The string to check.\n \n Returns:\n bool: True if the string is a palindrome, False otherwise.\n \n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n \"\"\"\n # Normalize the string by removing spaces and converting to lowercase\n normalized_text = text.replace(\" \", \"\").lower()\n \n # Check if the normalized string is equal to its reverse\n return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n if p <= 0:\n raise ValueError(\"p must be a positive integer.\")\n \n # Handle the case when n is negative\n if n < 0:\n return 0 # 2^n is not defined for negative n in this context\n \n result = 1\n base = 2\n \n # Use modular exponentiation\n while n > 0:\n if n % 2 == 1: # If n is odd\n result = (result * base) % p\n base = (base * base) % p # Square the base\n n //= 2 # Divide n by 2\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n Vowels are defined as 'a', 'e', 'i', 'o', 'u' and their uppercase counterparts.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n \"\"\"\n Takes as input string encoded with encode_shift function. Returns decoded string.\n Non-alphabetic characters are not changed.\n \"\"\"\n return \"\".join([\n chr(((ord(ch) - ord(\"a\") - 5) % 26) + ord(\"a\")) if 'a' <= ch <= 'z' else ch\n for ch in s\n ])", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n \"\"\"Return True if all numbers in the list l are below threshold t.\n \n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n \"\"\"\n # Check if all elements in the list are below the threshold\n for number in l:\n if number >= t:\n return False\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n \"\"\"Add two numbers x and y.\n\n This function takes two integers and returns their sum. \n It handles typical integer addition and ensures that the inputs \n are indeed integers.\n\n Args:\n x (int): The first integer to add.\n y (int): The second integer to add.\n\n Returns:\n int: The sum of x and y.\n\n Raises:\n TypeError: If either x or y is not an integer.\n\n Examples:\n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n \"\"\"\n # Check if both x and y are integers\n if not isinstance(x, int) or not isinstance(y, int):\n raise TypeError(\"Both x and y must be integers.\")\n \n # Perform the addition\n return x + y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n \"\"\"Return n-th Fibonacci number.\n \n The Fibonacci sequence is defined as follows:\n - fib(0) = 0\n - fib(1) = 1\n - fib(n) = fib(n-1) + fib(n-2) for n > 1\n\n Args:\n n (int): The index of the Fibonacci number to return.\n\n Returns:\n int: The n-th Fibonacci number.\n\n Raises:\n ValueError: If n is negative.\n\n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n \"\"\"\n if n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n if n == 0:\n return 0\n elif n == 1:\n return 1\n \n a, b = 0, 1\n for _ in range(2, n + 1):\n a, b = b, a + b\n return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two words have the same characters if they contain the same unique characters,\n regardless of the frequency of those characters.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Create a set of characters for each string\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Compare the two sets\n return set_s0 == set_s1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"<\" and \">\".\n return True if every opening bracket has a corresponding closing bracket.\n \"\"\"\n balance = 0\n \n for char in brackets:\n if char == '<':\n balance += 1\n elif char == '>':\n balance -= 1\n \n # If balance goes negative, it means there's a closing bracket without a matching opening bracket\n if balance < 0:\n return False\n \n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n \"\"\"Return True if list elements are monotonically increasing or decreasing.\n \n A list is considered monotonically increasing if each element is greater than or equal to the previous one.\n A list is considered monotonically decreasing if each element is less than or equal to the previous one.\n \n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n \"\"\"\n if not l: # An empty list is considered monotonic\n return True\n \n increasing = decreasing = True\n \n for i in range(1, len(l)):\n if l[i] > l[i - 1]:\n decreasing = False\n elif l[i] < l[i - 1]:\n increasing = False\n \n # If both increasing and decreasing are False, we can return early\n if not increasing and not decreasing:\n return False\n \n return increasing or decreasing", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n largest_factor = None\n \n # Check for number of 2s that divide n\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # n must be odd at this point, so we can skip even numbers\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n \n return largest_factor", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n \"\"\" \n brackets is a string of \"(\" and \")\".\n return True if every opening bracket has a corresponding closing bracket.\n \"\"\"\n balance = 0\n \n for char in brackets:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n \n # If balance goes negative, it means there's a closing bracket without a matching opening bracket\n if balance < 0:\n return False\n \n # At the end, balance should be zero for all opening brackets to be matched\n return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n \n Args:\n n (int): The upper limit of the summation (inclusive).\n \n Returns:\n int: The sum of all integers from 1 to n.\n \n Examples:\n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n \"\"\"\n if n < 1:\n return 0 # Return 0 for non-positive integers as they do not contribute to the sum.\n \n return n * (n + 1) // 2 # Use the formula for the sum of the first n natural numbers.", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n \n Args:\n n (int): The index of the FibFib number to compute.\n \n Returns:\n int: The n-th FibFib number.\n \n Examples:\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n if n == 0:\n return 0\n elif n == 1:\n return 0\n elif n == 2:\n return 1\n \n # Initialize the first three FibFib numbers\n fibfib_numbers = [0, 0, 1]\n \n # Compute FibFib numbers iteratively\n for i in range(3, n + 1):\n next_fibfib = fibfib_numbers[i - 1] + fibfib_numbers[i - 2] + fibfib_numbers[i - 3]\n fibfib_numbers.append(next_fibfib)\n \n return fibfib_numbers[n]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n \"\"\" \n Calculate the derivative of a polynomial represented by its coefficients.\n \n The polynomial is represented as:\n xs[0] + xs[1] * x + xs[2] * x^2 + ...\n \n The derivative is calculated as:\n d/dx (a_n * x^n) = n * a_n * x^(n-1)\n \n Args:\n xs (list): A list of coefficients where the index represents the power of x.\n \n Returns:\n list: A list of coefficients representing the derivative of the polynomial.\n \n Examples:\n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n \"\"\"\n # Check if the input list is empty\n if not xs:\n return []\n \n # Calculate the derivative coefficients\n derivative_coeffs = []\n for i in range(1, len(xs)):\n derivative_coeffs.append(i * xs[i])\n \n return derivative_coeffs", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n \n >>> circular_shift(12, 1)\n \"21\"\n >>> circular_shift(12, 2)\n \"12\"\n \"\"\"\n # Convert the integer to a string to work with its digits\n str_x = str(x)\n num_digits = len(str_x)\n \n # If shift is greater than the number of digits, reverse the string\n if shift >= num_digits:\n return str_x[::-1]\n \n # Calculate the effective shift (in case shift is larger than num_digits)\n effective_shift = shift % num_digits\n \n # Perform the circular shift\n if effective_shift > 0:\n # Split the string into two parts and rearrange them\n return str_x[-effective_shift:] + str_x[:-effective_shift]\n \n # If effective_shift is 0, return the original string\n return str_x", "base_status": "fail", "plus_status": null, "base_fail_tests": [[12, 2]], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set('aeiouAEIOU')\n count = 0\n \n # Iterate through the string\n for i in range(len(s)):\n # Check if the character is a vowel\n if s[i] in vowels:\n count += 1\n # Check if the character is 'y' and it's the last character\n elif s[i].lower() == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n \"\"\"Task\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n \"\"\"\n # Initialize the sum of ASCII values of uppercase characters\n total_sum = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is uppercase\n if char.isupper():\n # Add the ASCII value of the uppercase character to the total sum\n total_sum += ord(char)\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n \"\"\"\n Calculate the number of mango fruits in a basket given a string representation of apples and oranges,\n and the total number of fruits in the basket.\n\n Parameters:\n s (str): A string that contains the number of apples and oranges.\n n (int): The total number of fruits in the basket.\n\n Returns:\n int: The number of mango fruits in the basket.\n \"\"\"\n # Extract the number of apples and oranges from the string\n parts = s.split(' and ')\n apples = int(parts[0].split()[0]) # Get the number of apples\n oranges = int(parts[1].split()[0]) # Get the number of oranges\n\n # Calculate the number of mangoes\n mangoes = n - apples - oranges\n\n return mangoes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n '''\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequency greater than or equal to the value of the integer itself. \n The frequency of an integer is the number of times it appears in the list.\n If no such a value exist, return -1.\n '''\n from collections import Counter\n\n # Count the frequency of each integer in the list\n frequency = Counter(lst)\n\n # Initialize the result variable to -1\n result = -1\n\n # Iterate through the frequency dictionary\n for num in frequency:\n # Check if the frequency of the number is greater than or equal to the number itself\n if frequency[num] >= num:\n # Update the result if this number is greater than the current result\n result = max(result, num)\n\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n \"\"\"\n Given an array representing a branch of a tree that has non-negative integer nodes,\n your task is to pluck one of the nodes and return it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n The plucked node should be returned in a list, [ smallest_value, its index ],\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1] \n\n Example 3:\n Input: []\n Output: []\n \n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n \"\"\"\n smallest_even_value = float('inf')\n smallest_index = -1\n\n for index, value in enumerate(arr):\n if value % 2 == 0: # Check if the value is even\n if value < smallest_even_value: # Found a smaller even value\n smallest_even_value = value\n smallest_index = index\n elif value == smallest_even_value and index < smallest_index:\n smallest_index = index # Update index if same value found earlier\n\n if smallest_index == -1: # No even value found\n return []\n \n return [smallest_even_value, smallest_index]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n '''\n Given list of integers, return list in strange order.\n Strange sorting, is when you start with the minimum value,\n then maximum of the remaining integers, then minimum and so on.\n\n Examples:\n strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n strange_sort_list([]) == []\n '''\n if not lst:\n return []\n\n # Sort the list to easily access min and max values\n sorted_lst = sorted(lst)\n result = []\n \n # Use two pointers to select from both ends of the sorted list\n left = 0\n right = len(sorted_lst) - 1\n \n # Alternate between the smallest and largest remaining elements\n while left <= right:\n if left == right: # If both pointers meet, add the last element\n result.append(sorted_lst[left])\n else:\n result.append(sorted_lst[left]) # Add the minimum\n result.append(sorted_lst[right]) # Add the maximum\n left += 1\n right -= 1\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return the area of\n the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n Otherwise return -1.\n Three sides make a valid triangle when the sum of any two sides is greater \n than the third side.\n '''\n # Check for valid triangle using the triangle inequality theorem\n if a <= 0 or b <= 0 or c <= 0:\n return -1\n if a + b <= c or a + c <= b or b + c <= a:\n return -1\n \n # Calculate the semi-perimeter\n s = (a + b + c) / 2\n \n # Calculate the area using Heron's formula\n area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n \n # Return the area rounded to 2 decimal points\n return round(area, 2)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n '''\n Write a function that returns True if the object q will fly, and False otherwise.\n The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n '''\n # Check if the list is a palindrome\n is_balanced = (q == q[::-1])\n \n # Calculate the sum of the elements in the list\n total_weight = sum(q)\n \n # Determine if the object will fly\n return is_balanced and (total_weight <= w)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n \"\"\"\n Given an array arr of integers, find the minimum number of elements that\n need to be changed to make the array palindromic. A palindromic array is an array that\n is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n For example:\n smallest_change([1,2,3,5,4,7,9,6]) == 4\n smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n smallest_change([1, 2, 3, 2, 1]) == 0\n \"\"\"\n n = len(arr)\n changes = 0\n \n # Compare elements from the start and end towards the center\n for i in range(n // 2):\n if arr[i] != arr[n - 1 - i]:\n changes += 1\n \n return changes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef generate_primes(limit):\n \"\"\"Generate a list of prime numbers up to a given limit.\"\"\"\n primes = []\n for num in range(2, limit):\n if is_prime(num):\n primes.append(num)\n return primes\ndef is_multiply_prime(a):\n \"\"\"Return True if the given number is the multiplication of 3 prime numbers, False otherwise.\"\"\"\n if a < 1 or a >= 100:\n return False\n \n primes = generate_primes(100)\n \n # Check all combinations of three primes\n for i in range(len(primes)):\n for j in range(i, len(primes)):\n for k in range(j, len(primes)):\n product = primes[i] * primes[j] * primes[k]\n if product == a:\n return True\n if product > a:\n break # No need to check further if product exceeds 'a'\n \n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n \n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total character counts and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n else:\n return lst2", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": []}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this integer is a cube of some integer number.\n Note: you may assume the input is always valid.\n Examples:\n iscube(1) ==> True\n iscube(2) ==> False\n iscube(-1) ==> True\n iscube(64) ==> True\n iscube(0) ==> True\n iscube(180) ==> False\n '''\n # Calculate the cube root of the absolute value of a\n cube_root = round(abs(a) ** (1/3))\n \n # Check if the cube of the rounded cube root equals the absolute value of a\n return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n \"\"\"Returns True if x is a simple power of n, otherwise False.\n \n A number x is a simple power of n if there exists an integer k such that n**k = x.\n \n Args:\n x (int): The number to check.\n n (int): The base number.\n \n Returns:\n bool: True if x is a simple power of n, False otherwise.\n \"\"\"\n # Edge case: if n is 0, we cannot raise it to any power to get a positive x\n if n == 0:\n return x == 0\n \n # Edge case: if n is 1, n**k is always 1 for any k, so x must be 1\n if n == 1:\n return x == 1\n \n # Edge case: if x is less than 1 and n is greater than 1, it cannot be a power\n if x < 1:\n return False\n \n # Check if there exists an integer k such that n**k = x\n power = 1\n while True:\n result = n ** power\n if result == x:\n return True\n elif result > x:\n return False\n power += 1", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1, 12]], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n \"\"\"Convert a decimal number to binary format with specific formatting.\n\n Args:\n decimal (int): A non-negative integer to convert to binary.\n\n Returns:\n str: A string representing the binary format of the decimal number,\n prefixed and suffixed with 'db'.\n \n Raises:\n ValueError: If the input is a negative integer.\n \"\"\"\n if decimal < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n # Convert decimal to binary and remove the '0b' prefix\n binary_representation = bin(decimal)[2:]\n \n # Format the output with 'db' at the beginning and end\n formatted_output = f\"db{binary_representation}db\"\n \n return formatted_output", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n \"\"\"Counts the number of prime hexadecimal digits in the given hexadecimal string.\"\"\"\n \n # Define the set of prime hexadecimal digits\n prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n \n # Initialize a counter for prime digits\n count = 0\n \n # Iterate through each character in the input string\n for char in num:\n # Check if the character is in the set of prime hexadecimal digits\n if char in prime_hex_digits:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n \"\"\"Check if the string s is happy.\n \n A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n \n Args:\n s (str): The input string to check.\n \n Returns:\n bool: True if the string is happy, False otherwise.\n \"\"\"\n # Check if the length of the string is at least 3\n if len(s) < 3:\n return False\n \n # Iterate through the string and check every 3 consecutive characters\n for i in range(len(s) - 2):\n # Get the current substring of 3 characters\n substring = s[i:i+3]\n # Check if all characters in the substring are distinct\n if len(set(substring)) < 3:\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n letter_grades = []\n \n for gpa in grades:\n if gpa == 4.0:\n letter_grades.append('A+')\n elif gpa > 3.7:\n letter_grades.append('A')\n elif gpa > 3.3:\n letter_grades.append('A-')\n elif gpa > 3.0:\n letter_grades.append('B+')\n elif gpa > 2.7:\n letter_grades.append('B')\n elif gpa > 2.3:\n letter_grades.append('B-')\n elif gpa > 2.0:\n letter_grades.append('C+')\n elif gpa > 1.7:\n letter_grades.append('C')\n elif gpa > 1.3:\n letter_grades.append('C-')\n elif gpa > 1.0:\n letter_grades.append('D+')\n elif gpa > 0.7:\n letter_grades.append('D')\n elif gpa > 0.0:\n letter_grades.append('D-')\n else:\n letter_grades.append('E')\n \n return letter_grades", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef prime_length(string):\n \"\"\"Check if the length of the string is a prime number.\"\"\"\n length = len(string)\n return is_prime(length)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n \"\"\"\n Given a positive integer n, return the count of the numbers of n-digit\n positive integers that start or end with 1.\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n\n # Total n-digit numbers\n total_n_digit_numbers = 9 * (10 ** (n - 1))\n\n # Count of n-digit numbers that start with 1\n if n == 1:\n count_starting_with_1 = 1 # Only the number 1\n else:\n count_starting_with_1 = 10 ** (n - 1) # 1 followed by (n-1) digits (0-9)\n\n # Count of n-digit numbers that end with 1\n count_ending_with_1 = 9 * (10 ** (n - 2)) if n > 1 else 1 # 1 can be the only digit\n\n # Total count of n-digit numbers that start or end with 1\n total_count = count_starting_with_1 + count_ending_with_1\n\n # If n > 1, we have double-counted the numbers that both start and end with 1\n if n > 1:\n count_both_start_and_end_with_1 = 10 ** (n - 2) # 1 at start and 1 at end, (n-2) digits in between\n total_count -= count_both_start_and_end_with_1\n\n return total_count", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1]], "plus_fail_tests": []}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits will be 1 the output should be \"1\".\n For N = 150, the sum of digits will be 6 the output should be \"110\".\n For N = 147, the sum of digits will be 12 the output should be \"1100\".\n \n Variables:\n @N integer\n Constraints: 0 \u2264 N \u2264 10000.\n Output:\n a string of binary number\n \"\"\"\n # Step 1: Calculate the sum of the digits of N\n digit_sum = sum(int(digit) for digit in str(N))\n \n # Step 2: Convert the sum to binary and remove the '0b' prefix\n binary_sum = bin(digit_sum)[2:]\n \n return binary_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum to 0\n total = 0\n \n # Iterate over the list using index and value\n for index in range(1, len(lst), 2): # Start from index 1 and step by 2 (odd indices)\n if lst[index] % 2 == 0: # Check if the element is even\n total += lst[index] # Add to total if it's even\n \n return total", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n # Iterate through each row in the list\n for row_index, row in enumerate(lst):\n # Check if the target value x is in the current row\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort coordinates by row (ascending) and then by column (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words and spaces\n words = s.split(' ')\n \n # Process each word to sort its characters\n sorted_words = []\n for word in words:\n # Sort the characters of the word and join them back\n sorted_word = ''.join(sorted(word))\n sorted_words.append(sorted_word)\n \n # Join the sorted words back with spaces\n result = ' '.join(sorted_words)\n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n or sort it in descending order if the sum( first index value, last index value) is even.\n\n Note:\n * don't change the given array.\n\n Examples:\n * sort_array([]) => []\n * sort_array([5]) => [5]\n * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n \"\"\"\n # Create a copy of the original array to avoid modifying it\n sorted_array = array.copy()\n \n # Check if the array is empty or has only one element\n if len(sorted_array) <= 1:\n return sorted_array\n \n # Calculate the sum of the first and last elements\n first_element = sorted_array[0]\n last_element = sorted_array[-1]\n total_sum = first_element + last_element\n \n # Sort the array based on the sum being odd or even\n if total_sum % 2 == 0:\n # Even sum: sort in descending order\n sorted_array.sort(reverse=True)\n else:\n # Odd sum: sort in ascending order\n sorted_array.sort()\n \n return sorted_array", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n # Create a dictionary to map each letter to its encrypted counterpart\n encrypted_dict = {}\n \n # Populate the dictionary with shifted letters\n for i in range(len(alphabet)):\n # Calculate the new position with a shift of 4 (2 * 2)\n new_position = (i + 4) % 26\n encrypted_dict[alphabet[i]] = alphabet[new_position]\n \n # Encrypt the input string\n encrypted_string = ''.join(encrypted_dict[char] for char in s if char in encrypted_dict)\n \n return encrypted_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n This function returns the 2nd smallest element of the list.\n Returns None if there is no such element.\n \n :param lst: List of integers\n :return: 2nd smallest integer or None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Sort the unique elements\n sorted_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_elements[1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n \n For example:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n \"\"\"\n # Split the input string into sentences based on the delimiters\n sentences = []\n current_sentence = []\n delimiters = {'.', '?', '!'}\n \n for char in S:\n if char in delimiters:\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n current_sentence = []\n else:\n current_sentence.append(char)\n \n # Add the last sentence if it exists\n if current_sentence:\n sentences.append(''.join(current_sentence).strip())\n \n # Count the number of sentences that start with \"I\"\n boredom_count = sum(1 for sentence in sentences if sentence.startswith(\"I\"))\n \n return boredom_count", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n \"\"\"\n Write a function that takes a message, and encodes in such a \n way that it swaps case of all letters, replaces all vowels in \n the message with the letter that appears 2 places ahead of that \n vowel in the English alphabet. \n Assume only letters. \n \n Examples:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n \n # Define vowels and their replacements\n vowels = 'aeiouAEIOU'\n vowel_replacements = {\n 'a': 'c', 'A': 'C',\n 'e': 'g', 'E': 'G',\n 'i': 'k', 'I': 'K',\n 'o': 'q', 'O': 'Q',\n 'u': 'w', 'U': 'W'\n }\n \n encoded_message = []\n \n for char in message:\n if char.isalpha(): # Check if the character is a letter\n # Swap case\n if char in vowels:\n # Replace vowel and swap case\n encoded_message.append(vowel_replacements[char])\n else:\n # Just swap case for consonants\n encoded_message.append(char.swapcase())\n else:\n # If it's not a letter, we can choose to ignore it or keep it as is\n encoded_message.append(char)\n \n return ''.join(encoded_message)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["TEST"]], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n '''\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n \n Examples\n any_int(5, 2, 7) \u279e True\n any_int(3, 2, 2) \u279e False\n any_int(3, -2, 1) \u279e True\n any_int(3.6, -2.2, 2) \u279e False\n '''\n \n # Check if all inputs are integers\n if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n # Check if any number is equal to the sum of the other two\n return x == y + z or y == x + z or z == x + y\n else:\n return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef sum_of_digits(n):\n \"\"\"Return the sum of the digits of a number.\"\"\"\n return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n largest_prime = None\n \n for number in lst:\n if is_prime(number):\n if largest_prime is None or number > largest_prime:\n largest_prime = number\n \n if largest_prime is not None:\n return sum_of_digits(largest_prime)\n else:\n return 0 # Return 0 if no prime number is found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in lower \n case or all keys are strings in upper case, else return False.\n The function should return False if the given dictionary is empty.\n \n Examples:\n check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n \"\"\"\n \n # Check if the dictionary is empty\n if not input_dict:\n return False\n \n # Initialize flags for lower and upper case\n all_lower = True\n all_upper = True\n \n for key in input_dict.keys():\n # Check if the key is a string\n if not isinstance(key, str):\n return False\n \n # Check if the key is lower case\n if key.islower():\n all_upper = False\n # Check if the key is upper case\n elif key.isupper():\n all_lower = False\n else:\n # If the key is neither lower nor upper case\n return False\n \n # Return True if all keys are either lower case or upper case\n return all_lower or all_upper", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_up_to(n):\n \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n primes = []\n for i in range(2, n):\n if is_prime(i):\n primes.append(i)\n return primes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.\n \"\"\"\n # Get the unit digit of the first number\n unit_digit_a = abs(a) % 10\n # Get the unit digit of the second number\n unit_digit_b = abs(b) % 10\n # Return the product of the unit digits\n return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n count_upper('aBCdEf') returns 1\n count_upper('abcdefg') returns 0\n count_upper('dBBE') returns 0\n \"\"\"\n # Define the set of uppercase vowels\n uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n \n # Initialize a counter for uppercase vowels at even indices\n count = 0\n \n # Iterate over the string, checking only even indices\n for i in range(0, len(s), 2): # Step by 2 to get even indices\n if s[i] in uppercase_vowels:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n\n Note:\n Rounding away from zero means that if the given number is equidistant\n from two integers, the one you should return is the one that is the\n farthest from zero. For example closest_integer(\"14.5\") should\n return 15 and closest_integer(\"-14.5\") should return -15.\n '''\n # Convert the string input to a float\n num = float(value)\n \n # Calculate the floor and ceiling of the number\n lower_int = int(num // 1) # This is the largest integer less than or equal to num\n upper_int = lower_int + 1 # This is the smallest integer greater than num\n \n # Determine the distance to the lower and upper integers\n distance_to_lower = abs(num - lower_int)\n distance_to_upper = abs(num - upper_int)\n \n # If the distances are equal, round away from zero\n if distance_to_lower == distance_to_upper:\n if num > 0:\n return upper_int # Round up for positive numbers\n else:\n return lower_int # Round down for negative numbers\n else:\n # Return the closest integer\n return lower_int if distance_to_lower < distance_to_upper else upper_int", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n \"\"\"\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n \"\"\"\n # Replace commas with spaces and split the string by whitespace\n words = s.replace(',', ' ').split()\n \n # Return the list of words\n return words", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n \"\"\"\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n >>> make_a_pile(4)\n [4, 6, 8, 10]\n >>> make_a_pile(1)\n [1]\n >>> make_a_pile(2)\n [2, 4]\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n\n stones = []\n current_stones = n\n\n for i in range(n):\n stones.append(current_stones)\n if current_stones % 2 == 0:\n current_stones += 2 # next even number\n else:\n current_stones += 2 # next odd number\n\n return stones", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n \"\"\"This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If \n there's no such number, then the function should return -1.\n \n For example:\n choose_num(12, 15) = 14\n choose_num(13, 12) = -1\n \"\"\"\n \n # Ensure x is less than or equal to y\n if x > y:\n return -1\n \n # Start from the maximum of x and y\n for num in range(y, x - 1, -1):\n if num % 2 == 0: # Check if the number is even\n return num\n \n return -1 # If no even number is found", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n \"\"\"You are given two positive integers n and m, and your task is to compute the\n average of the integers from n through m (including n and m). \n Round the answer to the nearest integer and convert that to binary.\n If n is greater than m, return -1.\n Example:\n rounded_avg(1, 5) => \"0b11\"\n rounded_avg(7, 5) => -1\n rounded_avg(10, 20) => \"0b1111\"\n rounded_avg(20, 33) => \"0b11010\"\n \"\"\"\n \n if n > m:\n return -1\n \n # Calculate the sum of integers from n to m\n total_sum = sum(range(n, m + 1))\n count = m - n + 1 # Total numbers from n to m\n \n # Calculate the average and round it\n average = total_sum / count\n rounded_average = round(average)\n \n # Convert the rounded average to binary\n binary_average = bin(rounded_average)\n \n return binary_average", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n reverse the resulting array, and then replace each digit by its corresponding name from\n \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n For example:\n arr = [2, 1, 1, 4, 5, 8, 2, 3] \n -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n \n If the array is empty, return an empty array:\n arr = []\n return []\n \n If the array has any strange number ignore it:\n arr = [1, -1 , 55] \n -> sort arr -> [-1, 1, 55]\n -> reverse arr -> [55, 1, -1]\n return = ['One']\n \"\"\"\n \n # Mapping of digits to their corresponding names\n digit_to_name = {\n 1: \"One\",\n 2: \"Two\",\n 3: \"Three\",\n 4: \"Four\",\n 5: \"Five\",\n 6: \"Six\",\n 7: \"Seven\",\n 8: \"Eight\",\n 9: \"Nine\"\n }\n \n # Filter the array to include only numbers between 1 and 9\n filtered_arr = [num for num in arr if 1 <= num <= 9]\n \n # Sort the filtered array\n filtered_arr.sort()\n \n # Reverse the sorted array\n filtered_arr.reverse()\n \n # Convert the numbers to their corresponding names\n result = [digit_to_name[num] for num in filtered_arr]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n \"\"\"Given a list of positive integers x, return a sorted list of all \n elements that haven't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n def has_even_digit(n):\n \"\"\"Check if the number has any even digit.\"\"\"\n for digit in str(n):\n if int(digit) % 2 == 0:\n return True\n return False\n\n # Filter the list to include only numbers without even digits\n filtered_numbers = [num for num in x if not has_even_digit(num)]\n \n # Sort the resulting list\n return sorted(filtered_numbers)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n \"\"\"\n Given a positive integer n, return a tuple that has the number of even and odd\n integer palindromes that fall within the range(1, n), inclusive.\n\n Example 1:\n Input: 3\n Output: (1, 2)\n Explanation:\n Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n Example 2:\n Input: 12\n Output: (4, 6)\n Explanation:\n Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n Note:\n 1. 1 <= n <= 10^3\n 2. returned tuple has the number of even and odd integer palindromes respectively.\n \"\"\"\n \n def is_palindrome(num):\n return str(num) == str(num)[::-1]\n\n even_count = 0\n odd_count = 0\n\n for i in range(1, n + 1):\n if is_palindrome(i):\n if i % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def f(n):\n \"\"\" \n Implement the function f that takes n as a parameter,\n and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even\n or the sum of numbers from 1 to i otherwise.\n i starts from 1.\n the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).\n \"\"\"\n result = []\n \n for i in range(1, n + 1):\n if i % 2 == 0: # i is even\n factorial = 1\n for j in range(1, i + 1):\n factorial *= j\n result.append(factorial)\n else: # i is odd\n sum_of_numbers = sum(range(1, i + 1))\n result.append(sum_of_numbers)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return True else return False.\n If the given array is empty then return True.\n\n Note: The given list is guaranteed to have unique elements.\n \"\"\"\n \n if not arr: # Check for empty array\n return True\n \n n = len(arr)\n count = 0 # Count the number of times the order is broken\n\n for i in range(n):\n if arr[i] > arr[(i + 1) % n]: # Compare current with next (circular)\n count += 1\n\n # If there are more than one breaks in the order, it's not possible\n return count <= 1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n \"\"\"\n Write a function count_nums which takes an array of integers and returns\n the number of elements which has a sum of digits > 0.\n If a number is negative, then its first signed digit will be negative:\n e.g. -123 has signed digits -1, 2, and 3.\n \n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n def sum_of_digits(n):\n \"\"\"Helper function to calculate the sum of digits of a number.\"\"\"\n # Convert the number to string and iterate over each character\n # If the number is negative, we need to consider the first digit as negative\n str_n = str(n)\n digit_sum = 0\n \n for i, char in enumerate(str_n):\n if char.isdigit():\n digit_sum += int(char)\n elif char == '-' and i == 0: # Only the first character can be '-'\n digit_sum -= 1 # Treat the first digit as negative\n \n return digit_sum\n\n count = 0\n for number in arr:\n if sum_of_digits(number) > 0:\n count += 1\n \n return count", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[-1, -2, 0]]], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n \"\"\"Determines whether it is possible to exchange elements between two lists\n to make all elements of lst1 even.\n \n Args:\n lst1 (list): The first list of numbers.\n lst2 (list): The second list of numbers.\n \n Returns:\n str: \"YES\" if it's possible to make all elements of lst1 even, otherwise \"NO\".\n \"\"\"\n \n # Check if all elements in lst1 are already even\n if all(x % 2 == 0 for x in lst1):\n return \"YES\"\n \n # Count the number of odd elements in lst1\n odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n \n # Check if lst2 has at least one even number to exchange\n has_even_in_lst2 = any(x % 2 == 0 for x in lst2)\n \n # If there are odd numbers in lst1 and lst2 has at least one even number,\n # we can perform exchanges to make lst1 all even\n if odd_count_lst1 > 0 and has_even_in_lst2:\n return \"YES\"\n \n # If there are odd numbers in lst1 and no even numbers in lst2, return \"NO\"\n return \"NO\"", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 3, 4], [1, 5, 3, 4]]], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n \"\"\"\n if not test:\n return {}\n\n # Split the input string into a list of letters\n letters = test.split()\n \n # Create a dictionary to count occurrences of each letter\n count_dict = {}\n for letter in letters:\n if letter in count_dict:\n count_dict[letter] += 1\n else:\n count_dict[letter] = 1\n\n # Find the maximum count\n max_count = max(count_dict.values())\n \n # Create a result dictionary for letters with the maximum count\n result = {letter: count for letter, count in count_dict.items() if count == max_count}\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n \"\"\"Task\n We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and True/False for the check.\n \"\"\"\n # Create a set of characters to delete for faster lookup\n chars_to_delete = set(c)\n \n # Build the result string by filtering out characters in chars_to_delete\n result = ''.join(char for char in s if char not in chars_to_delete)\n \n # Check if the result string is a palindrome\n is_palindrome = result == result[::-1]\n \n return (result, is_palindrome)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n \n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in s if char in '13579')\n \n # Create the output string with the count of odd digits\n output_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n \n # Append the result to the list\n result.append(output_string)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n Example\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n \"\"\"\n if not nums:\n raise ValueError(\"The input array must not be empty.\")\n \n # Initialize variables to track the minimum sum and the current sum\n min_sum = float('inf')\n current_sum = 0\n \n for num in nums:\n current_sum += num\n min_sum = min(min_sum, current_sum)\n \n # If current_sum is positive, reset it to 0\n if current_sum > 0:\n current_sum = 0\n \n return min_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n \"\"\"\n Calculate the number of times buckets need to be lowered to empty the wells.\n\n Parameters:\n grid (list of list of int): A rectangular grid representing wells.\n capacity (int): The capacity of each bucket.\n\n Returns:\n int: The total number of times buckets need to be lowered.\n \"\"\"\n total_water = 0\n \n # Count the total amount of water in the grid\n for row in grid:\n total_water += sum(row)\n \n # Calculate the number of times buckets need to be lowered\n if total_water == 0:\n return 0 # No water to extract\n \n # Each bucket can carry 'capacity' units of water\n # We need to lower the bucket enough times to extract all the water\n return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n \"\"\"\n Sorts an array of non-negative integers according to the number of ones in their binary representation\n in ascending order. For numbers with the same number of ones, it sorts based on their decimal value.\n\n Parameters:\n arr (list): A list of non-negative integers.\n\n Returns:\n list: A sorted list of integers based on the specified criteria.\n \"\"\"\n # Define a sorting key that sorts first by the number of ones in binary representation,\n # and then by the decimal value itself.\n return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n \"\"\"Given a string s and a natural number n, returns a list of all words from string s \n that contain exactly n consonants, in the order they appear in the string s.\n \n Args:\n s (str): The input string containing words.\n n (int): The number of consonants to match in each word.\n \n Returns:\n list: A list of words containing exactly n consonants.\n \"\"\"\n \n if not s: # Check if the string is empty\n return []\n \n # Define a set of vowels for easy checking\n vowels = set(\"aeiouAEIOU\")\n \n def count_consonants(word):\n \"\"\"Helper function to count consonants in a word.\"\"\"\n return sum(1 for char in word if char.isalpha() and char not in vowels)\n \n # Split the string into words\n words = s.split()\n \n # Filter words that have exactly n consonants\n result = [word for word in words if count_consonants(word) == n]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n two consonants from the right side of the word (case sensitive).\n \n Vowels in the beginning and ending don't count. Return empty string if you didn't\n find any vowel that meets the above condition. \n\n You may assume that the given string contains English letters only.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n n = len(word)\n\n # Check if the word is too short to have consonants with a vowel in between\n if n < 3:\n return \"\"\n\n # Start from the end of the word\n for i in range(n - 2, 0, -1):\n if word[i] in vowels:\n # Check if the character before and after are consonants\n if word[i - 1].isalpha() and word[i + 1].isalpha() and \\\n word[i - 1] not in vowels and word[i + 1] not in vowels:\n return word[i]\n\n return \"\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n \n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0: # More closing than opening\n return False\n return balance == 0 # Must be balanced at the end\n\n # Get the two strings\n s1, s2 = lst[0], lst[1]\n\n # Check both concatenation orders\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n \n # Sort the array in descending order and take the first k elements\n max_elements = sorted(arr, reverse=True)[:k]\n \n # Return the sorted list of the maximum k elements in ascending order\n return sorted(max_elements)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list using index and value\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n total_sum += value\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n \"\"\"\n Given a non-empty array of integers arr and an integer k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example:\n\n Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n Output: 24 # sum of 21 + 3\n\n Constraints:\n 1. 1 <= len(arr) <= 100\n 2. 1 <= k <= len(arr)\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate through the first k elements of the array\n for i in range(k):\n # Check if the current element has at most two digits\n if -100 < arr[i] < 100:\n total_sum += arr[i]\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n as follows: start with any positive integer n. Then each term is obtained from the \n previous term as follows: if the previous term is even, the next term is one half of \n the previous term. If the previous term is odd, the next term is 3 times the previous\n term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n Note: \n 1. Collatz(1) is [1].\n 2. returned list sorted in increasing order.\n\n For example:\n get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n collatz_sequence = []\n current = n\n \n while current != 1:\n collatz_sequence.append(current)\n if current % 2 == 0:\n current //= 2\n else:\n current = 3 * current + 1\n \n collatz_sequence.append(1) # Add the last term which is 1\n \n # Filter out the odd numbers and sort them\n odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n \n return odd_numbers", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n \n The date is valid if all of the following rules are satisfied:\n 1. The date string is not empty.\n 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n The number of days is not less than 1 or higher than 29 for the month 2.\n 3. The months should not be less than 1 or higher than 12.\n 4. The date should be in the format: mm-dd-yyyy\n \"\"\"\n \n # Check if the date string is empty\n if not date:\n return False\n \n # Check if the date is in the correct format\n if len(date) != 10 or date[2] != '-' or date[5] != '-':\n return False\n \n # Split the date into components\n try:\n month, day, year = map(int, date.split('-'))\n except ValueError:\n return False\n \n # Validate month\n if month < 1 or month > 12:\n return False\n \n # Validate day based on month\n if month in {1, 3, 5, 7, 8, 10, 12}:\n if day < 1 or day > 31:\n return False\n elif month in {4, 6, 9, 11}:\n if day < 1 or day > 30:\n return False\n elif month == 2:\n if day < 1 or day > 29:\n return False\n \n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n '''\n Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n Examples\n split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"abcdef\") == 3 \n '''\n \n # Check for whitespace in the text\n if ' ' in txt:\n return txt.split()\n \n # Check for commas in the text\n elif ',' in txt:\n return txt.split(',')\n \n # If no whitespace or commas, count lowercase letters with odd order\n else:\n odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n return odd_count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef intersection(interval1, interval2):\n \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n start1, end1 = interval1\n start2, end2 = interval2\n \n # Find the intersection\n start_intersection = max(start1, start2)\n end_intersection = min(end1, end2)\n \n # Check if there is an intersection\n if start_intersection > end_intersection:\n return \"NO\"\n \n # Calculate the length of the intersection\n length_of_intersection = end_intersection - start_intersection\n \n # Check if the length is a prime number\n if is_prime(length_of_intersection):\n return \"YES\"\n else:\n return \"NO\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n '''\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return False. Assume no negative numbers and only integers.\n\n Examples\n is_sorted([5]) \u279e True\n is_sorted([1, 2, 3, 4, 5]) \u279e True\n is_sorted([1, 3, 2, 4, 5]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n '''\n \n if not lst: # Check if the list is empty\n return True # An empty list is considered sorted\n\n seen = set() # To track unique elements\n last = None # To track the last element for sorting check\n\n for num in lst:\n if num in seen: # Check for duplicates\n if lst.count(num) > 1: # More than 1 occurrence\n return False\n seen.add(num)\n\n if last is not None and num < last: # Check if sorted\n return False\n last = num\n\n return True # If all checks are passed, the list is sorted", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n if not arr: # Check for empty array\n return None\n\n product_of_signs = 1\n sum_of_magnitudes = 0\n\n for num in arr:\n if num > 0:\n sum_of_magnitudes += num\n elif num < 0:\n sum_of_magnitudes += -num\n product_of_signs *= -1 # Flip the sign for negative numbers\n else: # num == 0\n return 0 # If there's a zero, the product of signs is zero\n\n return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n \"\"\"Generate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n if n < 0:\n return []\n\n # Initialize the list to hold the Tribonacci numbers\n tribonacci_sequence = []\n\n # Calculate the Tribonacci numbers based on the given rules\n for i in range(n + 1):\n if i == 0:\n tribonacci_sequence.append(1) # tri(0) = 1\n elif i == 1:\n tribonacci_sequence.append(3) # tri(1) = 3\n elif i % 2 == 0: # i is even\n tribonacci_sequence.append(1 + i / 2)\n else: # i is odd\n tri_n_minus_1 = tribonacci_sequence[i - 1]\n tri_n_minus_2 = tribonacci_sequence[i - 2]\n tri_n_plus_1 = tribonacci_sequence[i + 1] if i + 1 <= n else 0\n tribonacci_sequence.append(tri_n_minus_1 + tri_n_minus_2 + tri_n_plus_1)\n\n return tribonacci_sequence", "base_status": "fail", "plus_status": null, "base_fail_tests": [[3]], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n \"\"\"Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n For example:\n digits(1) == 1\n digits(4) == 0\n digits(235) == 15\n \"\"\"\n # Initialize the product to 1 and a flag to check if any odd digit is found\n product = 1\n found_odd = False\n \n # Convert the number to a string to iterate over each digit\n for digit in str(n):\n digit = int(digit) # Convert the character back to an integer\n if digit % 2 != 0: # Check if the digit is odd\n product *= digit # Multiply the product by the odd digit\n found_odd = True # Set the flag to True since we found an odd digit\n \n # If no odd digit was found, return 0\n if not found_odd:\n return 0\n \n return product # Return the product of the odd digits", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n '''\n Create a function that takes a string as input which contains only square brackets.\n The function should return True if and only if there is a valid subsequence of brackets \n where at least one bracket in the subsequence is nested.\n\n is_nested('[[]]') \u279e True\n is_nested('[]]]]]]][[[[[]') \u279e False\n is_nested('[][]') \u279e False\n is_nested('[]') \u279e False\n is_nested('[[][]]') \u279e True\n is_nested('[[]][[') \u279e True\n '''\n \n # Initialize a counter for open brackets\n open_count = 0\n # Initialize a flag to check for nesting\n nested = False\n \n for char in string:\n if char == '[':\n open_count += 1\n # If we have more than one open bracket, we have a nested structure\n if open_count > 1:\n nested = True\n elif char == ']':\n open_count -= 1\n # If we close a bracket and there were open brackets before, we check for nesting\n if open_count < 0:\n return False # More closing brackets than opening\n # If we have closed brackets but still have open brackets, we can have nesting\n if open_count > 0 and nested:\n return True\n \n # At the end, we should have no unmatched brackets\n return nested and open_count == 0", "base_status": "fail", "plus_status": null, "base_fail_tests": [["[[]"]], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers.\n You need to return the sum of squared numbers in the given list,\n round each element in the list to the upper int (Ceiling) first.\n \n Examples:\n For lst = [1,2,3] the output should be 14\n For lst = [1,4,9] the output should be 98\n For lst = [1,3,5,7] the output should be 84\n For lst = [1.4,4.2,0] the output should be 29\n For lst = [-2.4,1,1] the output should be 6\n \"\"\"\n # Initialize the sum of squares\n total_sum = 0\n \n # Iterate through each number in the list\n for number in lst:\n # Round the number up to the nearest integer\n rounded_number = math.ceil(number)\n # Square the rounded number and add it to the total sum\n total_sum += rounded_number ** 2\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n '''\n Create a function that returns True if the last character\n of a given string is an alphabetical character and is not\n a part of a word, and False otherwise.\n Note: \"word\" is a group of characters separated by space.\n\n Examples:\n check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '''\n \n # Strip any trailing whitespace from the string\n txt = txt.rstrip()\n \n # Check if the string is empty after stripping\n if not txt:\n return False\n \n # Get the last character of the string\n last_char = txt[-1]\n \n # Check if the last character is an alphabetical character\n if last_char.isalpha():\n # Check if the last character is part of a word\n # A character is part of a word if it is preceded by a non-space character\n if len(txt) > 1 and txt[-2] != ' ':\n return False\n return True\n \n return False", "base_status": "fail", "plus_status": null, "base_fail_tests": [["eeeee e "]], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n from collections import deque\n\n N = len(grid)\n directions = [(0, 1), (1, 0), (0, -1), (-1, 0)] # right, down, left, up\n min_path = None\n\n def bfs(start_row, start_col):\n queue = deque([(start_row, start_col, [grid[start_row][start_col]])])\n while queue:\n row, col, path = queue.popleft()\n if len(path) == k:\n nonlocal min_path\n if min_path is None or path < min_path:\n min_path = path\n continue\n \n for dr, dc in directions:\n new_row, new_col = row + dr, col + dc\n if 0 <= new_row < N and 0 <= new_col < N:\n queue.append((new_row, new_col, path + [grid[new_row][new_col]]))\n\n for i in range(N):\n for j in range(N):\n bfs(i, j)\n\n return min_path", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n \"\"\"Create a function which returns the largest index of an element which\n is not greater than or equal to the element immediately preceding it. If\n no such element exists then return -1. The given array will not contain\n duplicate values.\n\n Examples:\n can_arrange([1,2,4,3,5]) = 3\n can_arrange([1,2,3]) = -1\n \"\"\"\n # Check if the array is empty\n if not arr:\n return -1\n \n # Initialize the largest index to -1\n largest_index = -1\n \n # Iterate through the array starting from the second element\n for i in range(1, len(arr)):\n # Check if the current element is less than the previous element\n if arr[i] < arr[i - 1]:\n largest_index = i # Update the largest index\n \n return largest_index", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n '''\n Create a function that returns a tuple (a, b), where 'a' is\n the largest of negative integers, and 'b' is the smallest\n of positive integers in a list.\n If there is no negative or positive integers, return them as None.\n\n Examples:\n largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n largest_smallest_integers([]) == (None, None)\n largest_smallest_integers([0]) == (None, None)\n '''\n \n largest_negative = None\n smallest_positive = None\n \n for num in lst:\n if num < 0:\n if largest_negative is None or num > largest_negative:\n largest_negative = num\n elif num > 0:\n if smallest_positive is None or num < smallest_positive:\n smallest_positive = num\n \n return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n \n Args:\n n (int): The number to evaluate.\n \n Returns:\n bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n \n Example:\n is_equal_to_sum_even(4) == False\n is_equal_to_sum_even(6) == False\n is_equal_to_sum_even(8) == True\n \"\"\"\n \n # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n if n < 8:\n return False\n \n # Check if n is even\n if n % 2 != 0:\n return False\n \n # If n is even and n >= 8, it can be expressed as the sum of 4 positive even numbers\n return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def parse_number(value):\n \"\"\"\n Convert a string representation of a number into a float or return the value as is if it's already a number.\n Handles both '.' and ',' as decimal separators.\n \"\"\"\n if isinstance(value, (int, float)):\n return float(value)\n elif isinstance(value, str):\n # Replace ',' with '.' for conversion to float\n value = value.replace(',', '.')\n try:\n return float(value)\n except ValueError:\n return None # Return None if conversion fails\n return None # Return None for unsupported types\ndef compare_one(a, b):\n \"\"\"\n Compare two values (integers, floats, or strings representing real numbers)\n and return the larger one in its original type, or None if they are equal.\n \"\"\"\n # Parse both values\n parsed_a = parse_number(a)\n parsed_b = parse_number(b)\n\n # If both parsed values are None, return None\n if parsed_a is None or parsed_b is None:\n return None\n\n # Compare the parsed values\n if parsed_a > parsed_b:\n return a\n elif parsed_b > parsed_a:\n return b\n else:\n return None # Return None if they are equal", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n \"\"\"Helper function to calculate the factorial of a non-negative integer n.\"\"\"\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef special_factorial(n):\n \"\"\"Calculate the Brazilian factorial of n.\"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer greater than 0.\")\n \n result = 1\n for i in range(1, n + 1):\n result *= factorial(i)\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n \"\"\"\n Given a string text, replace all spaces in it with underscores, \n and if a string has more than 2 consecutive spaces, \n then replace all consecutive spaces with - \n \n fix_spaces(\"Example\") == \"Example\"\n fix_spaces(\"Example 1\") == \"Example_1\"\n fix_spaces(\" Example 2\") == \"_Example_2\"\n fix_spaces(\" Example 3\") == \"_Example-3\"\n \"\"\"\n # Step 1: Replace all spaces with underscores\n text = text.replace(\" \", \"_\")\n \n # Step 2: Replace all occurrences of more than 2 consecutive underscores with a single dash\n while \"__\" in text:\n text = text.replace(\"__\", \"-\")\n \n # Step 3: Handle the case where there are leading underscores\n if text.startswith(\"_\"):\n text = \"_\" + text.lstrip(\"_\")\n \n return text", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Yellow Yellow Dirty Fellow"]], "plus_fail_tests": []}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n \"\"\"\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n \n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126\n \"\"\"\n total_sum = 0\n \n for index, value in enumerate(lst):\n if index % 3 == 0:\n total_sum += value ** 2 # Square if index is a multiple of 3\n elif index % 4 == 0:\n total_sum += value ** 3 # Cube if index is a multiple of 4 and not a multiple of 3\n else:\n total_sum += value # Keep the value unchanged if not a multiple of 3 or 4\n \n return total_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n \"\"\"Check if the given file name is valid based on specific criteria.\"\"\"\n \n # Check for exactly one dot\n if file_name.count('.') != 1:\n return 'No'\n \n # Split the file name into name and extension\n name, extension = file_name.split('.')\n \n # Check if the name is not empty and starts with a letter\n if not name or not name[0].isalpha():\n return 'No'\n \n # Check the extension is valid\n valid_extensions = ['txt', 'exe', 'dll']\n if extension not in valid_extensions:\n return 'No'\n \n # Count the number of digits in the file name\n digit_count = sum(c.isdigit() for c in file_name)\n \n # Check if there are more than three digits\n if digit_count > 3:\n return 'No'\n \n return 'Yes'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n \"\"\"Simplifies the expression x * n and checks if it evaluates to a whole number.\n \n Args:\n x (str): A string representation of a fraction in the format /.\n n (str): A string representation of a fraction in the format /.\n \n Returns:\n bool: True if x * n evaluates to a whole number, False otherwise.\n \"\"\"\n \n # Split the fractions into numerator and denominator\n x_numerator, x_denominator = map(int, x.split('/'))\n n_numerator, n_denominator = map(int, n.split('/'))\n \n # Calculate the product of the fractions\n # x * n = (x_numerator / x_denominator) * (n_numerator / n_denominator)\n # This simplifies to (x_numerator * n_numerator) / (x_denominator * n_denominator)\n \n product_numerator = x_numerator * n_numerator\n product_denominator = x_denominator * n_denominator\n \n # Check if the product is a whole number\n return product_numerator % product_denominator == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef words_in_sentence(sentence):\n \"\"\"\n Given a string representing a sentence, return a string that contains the words\n from the original sentence whose lengths are prime numbers.\n The order of the words in the new string should be the same as the original one.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Filter words whose lengths are prime\n prime_length_words = [word for word in words if is_prime(len(word))]\n \n # Join the filtered words into a single string\n return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n \"\"\"\n Write a function which sorts the given list of integers\n in ascending order according to the sum of their digits.\n Note: if there are several items with similar sum of their digits,\n order them based on their index in original list.\n\n For example:\n >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n >>> order_by_points([]) == []\n \"\"\"\n \n def digit_sum(n):\n \"\"\"Calculate the sum of the digits of an integer n.\"\"\"\n return sum(int(digit) for digit in str(abs(n)))\n\n # Create a list of tuples (digit_sum, index, value)\n indexed_nums = [(digit_sum(num), index, num) for index, num in enumerate(nums)]\n \n # Sort by digit sum first, then by original index\n indexed_nums.sort(key=lambda x: (x[0], x[1]))\n \n # Extract the sorted values\n sorted_nums = [num for _, _, num in indexed_nums]\n \n return sorted_nums", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n \"\"\"Returns the number of elements in the array that are greater than 10 \n and both the first and last digits of the number are odd (1, 3, 5, 7, 9).\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n int: The count of numbers meeting the criteria.\n \"\"\"\n \n def is_odd_digit(digit):\n \"\"\"Check if a digit is odd.\"\"\"\n return digit in {'1', '3', '5', '7', '9'}\n \n def first_and_last_digits_are_odd(num):\n \"\"\"Check if both the first and last digits of the number are odd.\"\"\"\n num_str = str(abs(num)) # Convert to string and take absolute value\n return is_odd_digit(num_str[0]) and is_odd_digit(num_str[-1])\n \n count = 0\n for num in nums:\n if num > 10 and first_and_last_digits_are_odd(num):\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n \"\"\"\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example :\n Input: n = 5\n Output: 1\n Explanation: \n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n \"\"\"\n # Create the array a based on the given formula\n a = [i * i - i + 1 for i in range(1, n + 1)]\n \n # Count the number of valid triples\n count = 0\n \n # Iterate through all possible triples (i, j, k)\n for i in range(n):\n for j in range(i + 1, n):\n for k in range(j + 1, n):\n if (a[i] + a[j] + a[k]) % 3 == 0:\n count += 1\n \n return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closest to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sorted by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct planet names. \n Examples\n bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n '''\n\n # List of planets in order from the Sun\n planets = [\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n ]\n \n # Check if the input planets are valid\n if planet1 not in planets or planet2 not in planets:\n return ()\n \n # Get the indices of the planets\n index1 = planets.index(planet1)\n index2 = planets.index(planet2)\n \n # Determine the range of indices\n start_index = min(index1, index2) + 1\n end_index = max(index1, index2)\n \n # Get the planets in between\n in_between_planets = planets[start_index:end_index]\n \n # Return the result as a tuple\n return tuple(in_between_planets)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef x_or_y(n, x, y):\n \"\"\"Return x if n is a prime number, otherwise return y.\"\"\"\n if is_prime(n):\n return x\n else:\n return y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length and alphabetically.\n \n Args:\n lst (list of str): A list of strings.\n \n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n \"\"\"\n Compares the actual scores of matches with the guessed scores.\n \n Parameters:\n game (list of int): The actual scores of the matches.\n guess (list of int): The guessed scores of the matches.\n \n Returns:\n list of int: A list where each element is the absolute difference \n between the actual score and the guessed score, or 0 if the guess is correct.\n \"\"\"\n # Check if the lengths of game and guess are equal\n if len(game) != len(guess):\n raise ValueError(\"The length of game and guess must be the same.\")\n \n # Calculate the absolute differences\n result = [abs(g - a) for a, g in zip(game, guess)]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n \n double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n double_the_difference([-1, -2, 0]) == 0\n double_the_difference([9, -2]) == 81\n double_the_difference([0]) == 0 \n \n If the input list is empty, return 0.\n '''\n # Initialize the sum of squares\n sum_of_squares = 0\n \n # Iterate through each number in the list\n for num in lst:\n # Check if the number is a positive odd integer\n if isinstance(num, int) and num >= 0 and num % 2 != 0:\n # Add the square of the odd number to the sum\n sum_of_squares += num ** 2\n \n return sum_of_squares", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n \"\"\"Check if the second word or any of its rotations is a substring in the first word.\"\"\"\n \n # Edge case: if b is empty, it is considered a substring of any string\n if not b:\n return True\n \n # Edge case: if b is longer than a, it cannot be a substring\n if len(b) > len(a):\n return False\n \n # Create a new string that is b concatenated with itself\n # This will contain all possible rotations of b as substrings\n b_rotations = b + b\n \n # Check if any rotation of b is a substring of a\n return b_rotations.find(a) != -1", "base_status": "fail", "plus_status": null, "base_fail_tests": [["yello", "ell"]], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n \"\"\"Finds the strongest extension based on the strength defined by the number of uppercase and lowercase letters.\"\"\"\n \n def calculate_strength(extension):\n \"\"\"Calculates the strength of the extension.\"\"\"\n CAP = sum(1 for char in extension if char.isupper())\n SM = sum(1 for char in extension if char.islower())\n return CAP - SM\n\n strongest_extension = None\n strongest_strength = float('-inf') # Start with the lowest possible strength\n\n for extension in extensions:\n strength = calculate_strength(extension)\n # Check if this extension is stronger or if it's the first one\n if strength > strongest_strength:\n strongest_strength = strength\n strongest_extension = extension\n\n if strongest_extension is not None:\n return f\"{class_name}.{strongest_extension}\"\n else:\n return None # In case there are no extensions", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n if not (1 <= number <= 1000):\n raise ValueError(\"Number must be between 1 and 1000 inclusive.\")\n\n # Mapping of integers to their corresponding Roman numeral representations\n roman_numerals = [\n (1000, 'm'),\n (900, 'cm'),\n (500, 'd'),\n (400, 'cd'),\n (100, 'c'),\n (90, 'xc'),\n (50, 'l'),\n (40, 'xl'),\n (10, 'x'),\n (9, 'ix'),\n (5, 'v'),\n (4, 'iv'),\n (1, 'i')\n ]\n\n result = []\n \n for value, numeral in roman_numerals:\n while number >= value:\n result.append(numeral)\n number -= value\n\n return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n Example:\n even_odd_count(-12) ==> (1, 1)\n even_odd_count(123) ==> (1, 2)\n \"\"\"\n # Convert the number to its absolute value and then to a string\n num_str = str(abs(num))\n \n even_count = 0\n odd_count = 0\n \n # Iterate through each character in the string representation of the number\n for char in num_str:\n if char.isdigit(): # Ensure we are only dealing with digits\n digit = int(char)\n if digit % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return True if the three\n sides form a right-angled triangle, False otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or \n 90 degree.\n \n Example:\n right_angle_triangle(3, 4, 5) == True\n right_angle_triangle(1, 2, 3) == False\n '''\n \n # First, we need to check if the sides can form a triangle\n if a <= 0 or b <= 0 or c <= 0:\n return False # Sides must be positive\n \n # Sort the sides to easily identify the longest side\n sides = sorted([a, b, c])\n \n # Check the Pythagorean theorem: a^2 + b^2 = c^2\n return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n \"\"\"Return the word with the maximum number of unique characters.\n If multiple words have the same maximum number of unique characters,\n return the one that comes first in lexicographical order.\n \n Args:\n words (list of str): A list of words to evaluate.\n \n Returns:\n str: The word with the maximum number of unique characters.\n \"\"\"\n max_word = \"\"\n max_unique_count = 0\n\n for word in words:\n # Calculate the number of unique characters in the word\n unique_count = len(set(word))\n \n # Check if this word has more unique characters or is lexicographically smaller\n if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n max_word = word\n max_unique_count = unique_count\n\n return max_word", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n \"\"\"\n You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n \n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n \n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots that exist in stock\n \n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n \"\"\"\n \n # Calculate how many more carrots are needed\n additional_needed = need - number\n \n # If no additional carrots are needed, return the current state\n if additional_needed <= 0:\n return [number, remaining]\n \n # If there are enough remaining carrots to satisfy the need\n if remaining >= additional_needed:\n total_eaten = number + additional_needed\n carrots_left = remaining - additional_needed\n else:\n # If not enough remaining carrots, eat all remaining\n total_eaten = number + remaining\n carrots_left = 0\n \n return [total_eaten, carrots_left]", "base_status": "fail", "plus_status": null, "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic algebra operations, and \n the second list is a list of integers. Use the two given lists to build the algebraic \n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + ) \n Subtraction ( - ) \n Multiplication ( * ) \n Floor division ( // ) \n Exponentiation ( ** ) \n\n Example:\n operator = ['+', '*', '-']\n operand = [2, 3, 4, 5]\n result = 2 + 3 * 4 - 5\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.\n \"\"\"\n \n # Start with the first operand\n result = operand[0]\n \n # Iterate through the operators and operands\n for i in range(len(operator)):\n op = operator[i]\n next_operand = operand[i + 1]\n \n if op == '+':\n result += next_operand\n elif op == '-':\n result -= next_operand\n elif op == '*':\n result *= next_operand\n elif op == '//':\n # Handle division by zero\n if next_operand == 0:\n raise ValueError(\"Division by zero is not allowed.\")\n result //= next_operand\n elif op == '**':\n result **= next_operand\n else:\n raise ValueError(f\"Invalid operator: {op}\")\n \n return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string.\n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n \"\"\"\n if text == \"\":\n return None\n # Create an MD5 hash object\n md5_hash = hashlib.md5()\n # Update the hash object with the bytes of the string\n md5_hash.update(text.encode('utf-8'))\n # Return the hexadecimal digest of the hash\n return md5_hash.hexdigest()", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n \"\"\"You are given a string s.\n if s[i] is a letter, reverse its case from lower to upper or vice versa, \n otherwise keep it as it is.\n If the string contains no letters, reverse the string.\n The function should return the resulted string.\n Examples\n solve(\"1234\") = \"4321\"\n solve(\"ab\") = \"AB\"\n solve(\"#a@C\") = \"#A@c\"\n \"\"\"\n # Check if there are any letters in the string\n has_letters = any(c.isalpha() for c in s)\n \n if has_letters:\n # If there are letters, reverse the case of each letter\n result = ''.join(c.upper() if c.islower() else c.lower() for c in s)\n else:\n # If there are no letters, reverse the string\n result = s[::-1]\n \n return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascending order.\n\n For example:\n generate_integers(2, 8) => [2, 4, 6, 8]\n generate_integers(8, 2) => [2, 4, 6, 8]\n generate_integers(10, 14) => []\n \"\"\"\n # Ensure a is less than or equal to b for easier processing\n start = min(a, b)\n end = max(a, b)\n\n # Generate a list of even integers in the range\n even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n return even_integers", "base_status": "fail", "plus_status": null, "base_fail_tests": [[2, 10]], "plus_fail_tests": []}]}} \ No newline at end of file diff --git a/metagpt/actions/action_node.py b/metagpt/actions/action_node.py index c31900d3b..904ada70f 100644 --- a/metagpt/actions/action_node.py +++ b/metagpt/actions/action_node.py @@ -512,6 +512,7 @@ class ActionNode: import re field_name = self.get_field_name() prompt = context + print(f"prompt: \n{prompt}") content = await self.llm.aask(prompt, timeout=timeout) # TODO 在前置逻辑中完成entrypoint的提取就可以 extracted_code = sanitize(code=content, entrypoint=function_name) diff --git a/tester.txt b/tester.txt new file mode 100644 index 000000000..efe76a5c6 --- /dev/null +++ b/tester.txt @@ -0,0 +1,168 @@ +filter_integers +incr_list +string_sequence +greatest_common_divisor +generate_integers +anti_shuffle +derivative +monotonic +eat +solution +sort_numbers +make_palindrome +fib +order_by_points +numerical_letter_grade +is_simple_power +rounded_avg +is_nested +multiply +x_or_y +count_distinct_characters +prime_length +solve +below_zero +minSubArraySum +count_upper +find_closest_elements +count_up_to +below_threshold +triangle_area +choose_num +sum_to_n +common +unique_digits +intersection +search +factorize +add_elements +mean_absolute_deviation +get_closest_vowel +get_max_triples +tri +longest +even_odd_palindrome +get_row +maximum +move_one_ball +cycpattern_check +solve +check_if_last_char_is_a_letter +get_odd_collatz +circular_shift +exchange +flip_case +get_positive +parse_music +is_prime +add +unique +is_equal_to_sum_even +fibfib +is_multiply_prime +truncate_number +fix_spaces +vowels_count +add +words_string +correct_bracketing +any_int +filter_by_substring +change_base +f +special_factorial +string_xor +hex_key +Strongest_Extension +strange_sort_list +prime_fib +encrypt +simplify +encode_shift +has_close_elements +decimal_to_binary +count_nums +rescale_to_unit +median +triangle_area +fizz_buzz +how_many_times +remove_vowels +find_max +right_angle_triangle +int_to_mini_roman +sum_squares +match_parens +smallest_change +largest_divisor +sort_array +triples_sum_to_zero +is_bored +sorted_list_sum +can_arrange +encode_cyclic +by_length +largest_smallest_integers +bf +modp +car_race_collision +sort_third +histogram +compare_one +words_in_sentence +pluck +is_sorted +filter_by_prefix +same_chars +parse_nested_parens +remove_duplicates +sum_squares +encode +sort_even +make_a_pile +digitSum +prod_signs +largest_prime_factor +sum_product +double_the_difference +split_words +odd_count +minPath +total_match +skjkasdkd +is_palindrome +find_zero +check_dict_case +string_to_md5 +next_smallest +is_happy +all_prefixes +separate_paren_groups +iscube +select_words +closest_integer +fruit_distribution +do_algebra +max_fill +sort_array +digits +even_odd_count +correct_bracketing +largest_smallest_integers +reverse_delete +strlen +pairs_sum_to_zero +intersperse +rolling_max +concatenate +valid_date +compare +starts_one_ends +will_it_fly +max_element +specialFilter +file_name_check +fib4 +largest_smallest_integers +largest_smallest_integers +largest_smallest_integers