diff --git a/.gitignore b/.gitignore
index 87f3f5de6..dea7d91f6 100644
--- a/.gitignore
+++ b/.gitignore
@@ -189,6 +189,6 @@ cov.xml
 *.dot
 .python-version
 *.csv
-/examples/ags/data/baselines/general
-/examples/ags/scripts/optimized/HumanEval/graphs
-/examples/ags/scripts/optimized/HumanEval/graphs_test
+/examples/aflow/data/baselines/general
+/examples/aflow/scripts/optimized/HumanEval/graphs
+/examples/aflow/scripts/optimized/HumanEval/graphs_test
diff --git a/10.txt b/10.txt
deleted file mode 100644
index 809a0da29..000000000
--- a/10.txt
+++ /dev/null
@@ -1,52 +0,0 @@
-2024-07-01 15:30:33.806 | DEBUG    | metagpt.provider.base_llm:aask:151 - [{'role': 'system', 'content': 'You are a helpful assistant.'}, {'role': 'user', 'content': '\n## context\n\nGenerate Code Solution for the following problem: \n\ndef is_palindrome(string: str) -> bool:\n    """ Test if given string is a palindrome """\n    return string == string[::-1]\n\n\ndef make_palindrome(string: str) -> str:\n    """ Find the shortest palindrome that begins with a supplied string.\n    Algorithm idea is simple:\n    - Find the longest postfix of supplied string that is a palindrome.\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n    >>> make_palindrome(\'\')\n    \'\'\n    >>> make_palindrome(\'cat\')\n    \'catac\'\n    >>> make_palindrome(\'cata\')\n    \'catac\'\n    """\n\n\n\n-----\n\n## format example\n[CONTENT]\n{\n    "solution": ""\n}\n[/CONTENT]\n\n## nodes: "<node>: <type>  # <instruction>"\n- solution: <class \'str\'>  # Your Code Solution for this problem\n\n\n## constraint\nLanguage: Please use the same language as Human INPUT.\nFormat: output wrapped inside [CONTENT][/CONTENT] like format example, nothing else.\n\n## action\nFollow instructions of nodes, generate output and make sure it follows the format example.\n'}]
-2024-07-01 15:30:42.412 | INFO     | metagpt.utils.cost_manager:update_cost:57 - Total running cost: $0.000 | Max budget: $10.000 | Current cost: $0.000, prompt_tokens: 318, completion_tokens: 175
-2024-07-01 15:30:42.413 | DEBUG    | metagpt.actions.action_node:_aask_v1:421 - llm raw output:
-[CONTENT]
-{
-    "solution": "def make_palindrome(string: str) -> str:\n    \"\"\" Find the shortest palindrome that begins with a supplied string.\n    Algorithm idea is simple:\n    - Find the longest postfix of supplied string that is a palindrome.\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n    \"\"\"\n    if not string:\n        return ''\n\n    for i in range(len(string)):\n        if string[i:] == string[i:][::-1]:\n            return string + string[:i][::-1]\n\n    return string + string[:-1][::-1]\n"
-}
-[/CONTENT]
-2024-07-01 15:30:42.418 | DEBUG    | metagpt.actions.action_node:_aask_v1:431 - parsed_data:
-{'solution': 'def make_palindrome(string: str) -> str:\n    """ Find the shortest palindrome that begins with a supplied string.\n    Algorithm idea is simple:\n    - Find the longest postfix of supplied string that is a palindrome.\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n    """\n    if not string:\n        return \'\'\n\n    for i in range(len(string)):\n        if string[i:] == string[i:][::-1]:\n            return string + string[:i][::-1]\n\n    return string + string[:-1][::-1]\n'}
-2024-07-01 15:30:42.419 | DEBUG    | metagpt.provider.base_llm:aask:151 - [{'role': 'system', 'content': 'You are a helpful assistant.'}, {'role': 'user', 'content': '\n## context\n\nFor the question described as \n\ndef is_palindrome(string: str) -> bool:\n    """ Test if given string is a palindrome """\n    return string == string[::-1]\n\n\ndef make_palindrome(string: str) -> str:\n    """ Find the shortest palindrome that begins with a supplied string.\n    Algorithm idea is simple:\n    - Find the longest postfix of supplied string that is a palindrome.\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n    >>> make_palindrome(\'\')\n    \'\'\n    >>> make_palindrome(\'cat\')\n    \'catac\'\n    >>> make_palindrome(\'cata\')\n    \'catac\'\n    """\n,\nplease review the following solution: {\'solution\': \'def make_palindrome(string: str) -> str:\\n    """ Find the shortest palindrome that begins with a supplied string.\\n    Algorithm idea is simple:\\n    - Find the longest postfix of supplied string that is a palindrome.\\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\\n    """\\n    if not string:\\n        return \\\'\\\'\\n\\n    for i in range(len(string)):\\n        if string[i:] == string[i:][::-1]:\\n            return string + string[:i][::-1]\\n\\n    return string + string[:-1][::-1]\\n\'}, and provide a review result in boolean format.\nIf you believe the solution is capable of resolving the issue, return True; otherwise, return False, and include your comments\n\n\n-----\n\n## format example\n[CONTENT]\n{\n    "review_result": false,\n    "feedback": ""\n}\n[/CONTENT]\n\n## nodes: "<node>: <type>  # <instruction>"\n- review_result: <class \'bool\'>  # The Review Result (Bool). If you think this solution looks good for you, return \'true\'; If not, return \'false\'\n- feedback: <class \'str\'>  # Your FeedBack for this problem based on the criteria. If the review result is true, you can put it \'nothing here\'.\n\n\n## constraint\nLanguage: Please use the same language as Human INPUT.\nFormat: output wrapped inside [CONTENT][/CONTENT] like format example, nothing else.\n\n## action\nFollow instructions of nodes, generate output and make sure it follows the format example.\n'}]
-2024-07-01 15:30:44.222 | INFO     | metagpt.utils.cost_manager:update_cost:57 - Total running cost: $0.000 | Max budget: $10.000 | Current cost: $0.000, prompt_tokens: 585, completion_tokens: 29
-2024-07-01 15:30:44.222 | DEBUG    | metagpt.actions.action_node:_aask_v1:421 - llm raw output:
-[CONTENT]
-{
-    "review_result": true,
-    "feedback": "nothing here"
-}
-[/CONTENT]
-2024-07-01 15:30:44.224 | DEBUG    | metagpt.actions.action_node:_aask_v1:431 - parsed_data:
-{'review_result': True, 'feedback': 'nothing here'}
-2024-07-01 15:30:44.224 | DEBUG    | metagpt.provider.base_llm:aask:151 - [{'role': 'system', 'content': 'You are a helpful assistant.'}, {'role': 'user', 'content': '\n## context\n\nGenerate Code Solution for the following problem: \n\ndef is_palindrome(string: str) -> bool:\n    """ Test if given string is a palindrome """\n    return string == string[::-1]\n\n\ndef make_palindrome(string: str) -> str:\n    """ Find the shortest palindrome that begins with a supplied string.\n    Algorithm idea is simple:\n    - Find the longest postfix of supplied string that is a palindrome.\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n    >>> make_palindrome(\'\')\n    \'\'\n    >>> make_palindrome(\'cat\')\n    \'catac\'\n    >>> make_palindrome(\'cata\')\n    \'catac\'\n    """\n\n\n\n-----\n\n## format example\n[CONTENT]\n{\n    "solution": ""\n}\n[/CONTENT]\n\n## nodes: "<node>: <type>  # <instruction>"\n- solution: <class \'str\'>  # Your Code Solution for this problem\n\n\n## constraint\nLanguage: Please use the same language as Human INPUT.\nFormat: output wrapped inside [CONTENT][/CONTENT] like format example, nothing else.\n\n## action\nFollow instructions of nodes, generate output and make sure it follows the format example.\n'}]
-2024-07-01 15:30:53.135 | INFO     | metagpt.utils.cost_manager:update_cost:57 - Total running cost: $0.000 | Max budget: $10.000 | Current cost: $0.000, prompt_tokens: 318, completion_tokens: 175
-2024-07-01 15:30:53.136 | DEBUG    | metagpt.actions.action_node:_aask_v1:421 - llm raw output:
-[CONTENT]
-{
-    "solution": "def make_palindrome(string: str) -> str:\n    \"\"\" Find the shortest palindrome that begins with a supplied string.\n    Algorithm idea is simple:\n    - Find the longest postfix of supplied string that is a palindrome.\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n    \"\"\"\n    if not string:\n        return ''\n\n    for i in range(len(string)):\n        if string[i:] == string[i:][::-1]:\n            return string + string[:i][::-1]\n\n    return string + string[:-1][::-1]\n"
-}
-[/CONTENT]
-2024-07-01 15:30:53.137 | DEBUG    | metagpt.actions.action_node:_aask_v1:431 - parsed_data:
-{'solution': 'def make_palindrome(string: str) -> str:\n    """ Find the shortest palindrome that begins with a supplied string.\n    Algorithm idea is simple:\n    - Find the longest postfix of supplied string that is a palindrome.\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n    """\n    if not string:\n        return \'\'\n\n    for i in range(len(string)):\n        if string[i:] == string[i:][::-1]:\n            return string + string[:i][::-1]\n\n    return string + string[:-1][::-1]\n'}
-2024-07-01 15:30:53.138 | DEBUG    | metagpt.provider.base_llm:aask:151 - [{'role': 'system', 'content': 'You are a helpful assistant.'}, {'role': 'user', 'content': '\n## context\n\nFor the question described as \n\ndef is_palindrome(string: str) -> bool:\n    """ Test if given string is a palindrome """\n    return string == string[::-1]\n\n\ndef make_palindrome(string: str) -> str:\n    """ Find the shortest palindrome that begins with a supplied string.\n    Algorithm idea is simple:\n    - Find the longest postfix of supplied string that is a palindrome.\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n    >>> make_palindrome(\'\')\n    \'\'\n    >>> make_palindrome(\'cat\')\n    \'catac\'\n    >>> make_palindrome(\'cata\')\n    \'catac\'\n    """\n,\nplease review the following solution: {\'solution\': \'def make_palindrome(string: str) -> str:\\n    """ Find the shortest palindrome that begins with a supplied string.\\n    Algorithm idea is simple:\\n    - Find the longest postfix of supplied string that is a palindrome.\\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\\n    """\\n    if not string:\\n        return \\\'\\\'\\n\\n    for i in range(len(string)):\\n        if string[i:] == string[i:][::-1]:\\n            return string + string[:i][::-1]\\n\\n    return string + string[:-1][::-1]\\n\'}, and provide a review result in boolean format.\nIf you believe the solution is capable of resolving the issue, return True; otherwise, return False, and include your comments\n\n\n-----\n\n## format example\n[CONTENT]\n{\n    "review_result": false,\n    "feedback": ""\n}\n[/CONTENT]\n\n## nodes: "<node>: <type>  # <instruction>"\n- review_result: <class \'bool\'>  # The Review Result (Bool). If you think this solution looks good for you, return \'true\'; If not, return \'false\'\n- feedback: <class \'str\'>  # Your FeedBack for this problem based on the criteria. If the review result is true, you can put it \'nothing here\'.\n\n\n## constraint\nLanguage: Please use the same language as Human INPUT.\nFormat: output wrapped inside [CONTENT][/CONTENT] like format example, nothing else.\n\n## action\nFollow instructions of nodes, generate output and make sure it follows the format example.\n'}]
-2024-07-01 15:30:55.232 | INFO     | metagpt.utils.cost_manager:update_cost:57 - Total running cost: $0.000 | Max budget: $10.000 | Current cost: $0.000, prompt_tokens: 585, completion_tokens: 29
-2024-07-01 15:30:55.233 | DEBUG    | metagpt.actions.action_node:_aask_v1:421 - llm raw output:
-[CONTENT]
-{
-    "review_result": true,
-    "feedback": "nothing here"
-}
-[/CONTENT]
-2024-07-01 15:30:55.234 | DEBUG    | metagpt.actions.action_node:_aask_v1:431 - parsed_data:
-{'review_result': True, 'feedback': 'nothing here'}
-2024-07-01 15:30:55.234 | DEBUG    | metagpt.provider.base_llm:aask:151 - [{'role': 'system', 'content': 'You are a helpful assistant.'}, {'role': 'user', 'content': '\n## context\n\nFor the question described as \n\ndef is_palindrome(string: str) -> bool:\n    """ Test if given string is a palindrome """\n    return string == string[::-1]\n\n\ndef make_palindrome(string: str) -> str:\n    """ Find the shortest palindrome that begins with a supplied string.\n    Algorithm idea is simple:\n    - Find the longest postfix of supplied string that is a palindrome.\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n    >>> make_palindrome(\'\')\n    \'\'\n    >>> make_palindrome(\'cat\')\n    \'catac\'\n    >>> make_palindrome(\'cata\')\n    \'catac\'\n    """\n, Solutions: def make_palindrome(string: str) -> str:\n    """ Find the shortest palindrome that begins with a supplied string.\n    Algorithm idea is simple:\n    - Find the longest postfix of supplied string that is a palindrome.\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n    """\n    if not string:\n        return \'\'\n\n    for i in range(len(string)):\n        if string[i:] == string[i:][::-1]:\n            return string + string[:i][::-1]\n\n    return string + string[:-1][::-1]\n\ndef make_palindrome(string: str) -> str:\n    """ Find the shortest palindrome that begins with a supplied string.\n    Algorithm idea is simple:\n    - Find the longest postfix of supplied string that is a palindrome.\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n    """\n    if not string:\n        return \'\'\n\n    for i in range(len(string)):\n        if string[i:] == string[i:][::-1]:\n            return string + string[:i][::-1]\n\n    return string + string[:-1][::-1]\n\n\nPlease select the solution that appears most frequently from these options and provide the best solution based on that.\n\n\n-----\n\n## format example\n[CONTENT]\n{\n    "solution": ""\n}\n[/CONTENT]\n\n## nodes: "<node>: <type>  # <instruction>"\n- solution: <class \'str\'>  # Final ensemble solution for this problem\n\n\n## constraint\nLanguage: Please use the same language as Human INPUT.\nFormat: output wrapped inside [CONTENT][/CONTENT] like format example, nothing else.\n\n## action\nFollow instructions of nodes, generate output and make sure it follows the format example.\n'}]
-2024-07-01 15:31:03.826 | INFO     | metagpt.utils.cost_manager:update_cost:57 - Total running cost: $0.001 | Max budget: $10.000 | Current cost: $0.000, prompt_tokens: 635, completion_tokens: 173
-2024-07-01 15:31:03.827 | DEBUG    | metagpt.actions.action_node:_aask_v1:421 - llm raw output:
-[CONTENT]
-{
-    "solution": "def make_palindrome(string: str) -> str:\n    \"\"\" Find the shortest palindrome that begins with a supplied string.\n    Algorithm idea is simple:\n    - Find the longest postfix of supplied string that is a palindrome.\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n    \"\"\"\n    if not string:\n        return ''\n\n    for i in range(len(string)):\n        if string[i:] == string[i:][::-1]:\n            return string + string[:i][::-1]\n\n    return string + string[:-1][::-1]"
-}
-[/CONTENT]
-2024-07-01 15:31:03.830 | DEBUG    | metagpt.actions.action_node:_aask_v1:431 - parsed_data:
-{'solution': 'def make_palindrome(string: str) -> str:\n    """ Find the shortest palindrome that begins with a supplied string.\n    Algorithm idea is simple:\n    - Find the longest postfix of supplied string that is a palindrome.\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n    """\n    if not string:\n        return \'\'\n\n    for i in range(len(string)):\n        if string[i:] == string[i:][::-1]:\n            return string + string[:i][::-1]\n\n    return string + string[:-1][::-1]'}
diff --git a/EVALPLUS-4omini/1.json b/EVALPLUS-4omini/1.json
deleted file mode 100644
index ec9dfd48b..000000000
--- a/EVALPLUS-4omini/1.json
+++ /dev/null
@@ -1 +0,0 @@
-{"date": "2024-07-20 12:59", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n    \"\"\"\n    Given two positive integers a and b, return the even digits between a\n    and b, in ascending order.\n\n    For example:\n    generate_integers(2, 8) => [2, 4, 6, 8]\n    generate_integers(8, 2) => [2, 4, 6, 8]\n    generate_integers(10, 14) => []\n    \"\"\"\n    # Determine the range of numbers to consider\n    start = min(a, b)\n    end = max(a, b)\n\n    # Generate a list of even integers in the specified range\n    even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n    return even_integers", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[2, 10]], "plus_fail_tests": [[6, 12]]}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n    \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n    Example:\n        even_odd_count(-12) ==> (1, 1)\n        even_odd_count(123) ==> (1, 2)\n    \"\"\"\n    # Convert the number to a string and remove the negative sign if present\n    num_str = str(abs(num))\n    \n    even_count = 0\n    odd_count = 0\n    \n    # Iterate through each character in the string representation of the number\n    for digit in num_str:\n        if digit.isdigit():  # Check if the character is a digit\n            if int(digit) % 2 == 0:\n                even_count += 1\n            else:\n                odd_count += 1\n    \n    return (even_count, odd_count)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def compare_one(a, b):\n    \"\"\"\n    Create a function that takes integers, floats, or strings representing\n    real numbers, and returns the larger variable in its given variable type.\n    Return None if the values are equal.\n    Note: If a real number is represented as a string, the floating point might be . or ,\n\n    compare_one(1, 2.5) \u279e 2.5\n    compare_one(1, \"2,3\") \u279e \"2,3\"\n    compare_one(\"5,1\", \"6\") \u279e \"6\"\n    compare_one(\"1\", 1) \u279e None\n    \"\"\"\n    \n    def parse_value(value):\n        \"\"\"Convert a string representation of a number to a float or return the original value.\"\"\"\n        if isinstance(value, str):\n            # Replace comma with dot for float conversion\n            value = value.replace(',', '.')\n            try:\n                return float(value)\n            except ValueError:\n                return value  # Return the original string if it cannot be converted\n        return value\n\n    # Parse both values\n    parsed_a = parse_value(a)\n    parsed_b = parse_value(b)\n\n    # Check for equality\n    if parsed_a == parsed_b:\n        return None\n\n    # Return the larger value in its original type\n    if parsed_a > parsed_b:\n        return a\n    else:\n        return b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n    \"\"\"Compares the actual game scores with the guessed scores and returns the absolute differences.\n    \n    Args:\n        game (list of int): The actual scores of the matches.\n        guess (list of int): The guessed scores of the matches.\n        \n    Returns:\n        list of int: A list containing the absolute differences between the actual scores and the guessed scores.\n                      If the guess is correct, the difference is 0.\n                      \n    Example:\n        compare([1,2,3,4,5,1],[1,2,3,4,2,-2]) -> [0,0,0,0,3,3]\n        compare([0,5,0,0,0,4],[4,1,1,0,0,-2]) -> [4,4,1,0,0,6]\n    \"\"\"\n    return [abs(g - s) for g, s in zip(guess, game)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n    \"\"\"\n    Write a function count_nums which takes an array of integers and returns\n    the number of elements which has a sum of digits > 0.\n    If a number is negative, then its first signed digit will be negative:\n    e.g. -123 has signed digits -1, 2, and 3.\n    \n    >>> count_nums([]) == 0\n    >>> count_nums([-1, 11, -11]) == 1\n    >>> count_nums([1, 1, 2]) == 3\n    \"\"\"\n    def sum_of_digits(n):\n        # Convert the number to string and calculate the sum of its digits\n        return sum(int(digit) if n >= 0 else -int(digit) if i == 0 else int(digit)\n                   for i, digit in enumerate(str(abs(n))) if digit.isdigit())\n\n    count = 0\n    for number in arr:\n        if sum_of_digits(number) > 0:\n            count += 1\n            \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def factorial(i):\n    \"\"\"Calculate the factorial of a given number i.\"\"\"\n    if i == 0 or i == 1:\n        return 1\n    result = 1\n    for j in range(2, i + 1):\n        result *= j\n    return result\ndef sum_of_numbers(i):\n    \"\"\"Calculate the sum of numbers from 1 to i.\"\"\"\n    return (i * (i + 1)) // 2\ndef f(n):\n    \"\"\"Return a list of size n, where the value at index i is the factorial of i if i is even,\n    or the sum of numbers from 1 to i otherwise. Indexing starts from 1.\"\"\"\n    result = []\n    for i in range(1, n + 1):\n        if i % 2 == 0:  # i is even\n            result.append(factorial(i))\n        else:  # i is odd\n            result.append(sum_of_numbers(i))\n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n    \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n    around the mean of this dataset.\n    Mean Absolute Deviation is the average absolute difference between each\n    element and a centerpoint (mean in this case):\n    MAD = average | x - x_mean |\n    \n    >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n    1.0\n    \"\"\"\n    if not numbers:\n        return 0.0  # Return 0 for empty list to avoid division by zero\n\n    mean_value = sum(numbers) / len(numbers)\n    mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n    return mad", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n    \"\"\"\n    You will be given a string of words separated by commas or spaces. Your task is\n    to split the string into words and return an array of the words.\n    \n    For example:\n    words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n    words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n    \"\"\"\n    # Replace commas with spaces and split the string by whitespace\n    words = s.replace(',', ' ').split()\n    return words", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n    \"\"\" \n    You're given a list of deposit and withdrawal operations on a bank account that starts with\n    zero balance. Your task is to detect if at any point the balance of account falls below zero, and\n    at that point function should return True. Otherwise it should return False.\n    \n    >>> below_zero([1, 2, 3])\n    False\n    >>> below_zero([1, 2, -4, 5])\n    True\n    \"\"\"\n    balance = 0\n    for operation in operations:\n        balance += operation\n        if balance < 0:\n            return True\n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n    \"\"\"\n    Given a string 'text', return its md5 hash equivalent string.\n    If 'text' is an empty string, return None.\n\n    >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n    >>> string_to_md5('') is None\n    >>> string_to_md5('Python') == '5d41402abc4b2a76b9719d911017c592'\n    \"\"\"\n    if text == \"\":\n        return None\n    md5_hash = hashlib.md5(text.encode()).hexdigest()\n    return md5_hash", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n    \"\"\"Calculate the factorial of a non-negative integer n.\"\"\"\n    if n == 0 or n == 1:\n        return 1\n    result = 1\n    for i in range(2, n + 1):\n        result *= i\n    return result\ndef special_factorial(n):\n    \"\"\"Calculate the Brazilian factorial of n.\"\"\"\n    if n <= 0:\n        raise ValueError(\"Input must be a positive integer.\")\n    \n    result = 1\n    for i in range(1, n + 1):\n        result *= factorial(i)\n    \n    return result", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[500]]}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n    \"\"\"Find the strongest extension based on the defined strength criteria.\"\"\"\n    strongest_extension = None\n    max_strength = float('-inf')  # Start with the lowest possible strength\n\n    for extension in extensions:\n        # Calculate the strength of the current extension\n        CAP = sum(1 for char in extension if char.isupper())\n        SM = sum(1 for char in extension if char.islower())\n        strength = CAP - SM\n\n        # Check if this extension is stronger than the current strongest\n        if strength > max_strength:\n            max_strength = strength\n            strongest_extension = extension\n\n    # Return the result in the specified format\n    return f\"{class_name}.{strongest_extension}\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n    \"\"\"Check if the second word or any of its rotations is a substring in the first word.\n    \n    Args:\n    a (str): The first word.\n    b (str): The second word.\n    \n    Returns:\n    bool: True if the second word or any of its rotations is a substring of the first word, False otherwise.\n    \n    Examples:\n    >>> cycpattern_check(\"abcd\", \"abd\")\n    False\n    >>> cycpattern_check(\"hello\", \"ell\")\n    True\n    >>> cycpattern_check(\"whassup\", \"psus\")\n    False\n    >>> cycpattern_check(\"abab\", \"baa\")\n    True\n    >>> cycpattern_check(\"efef\", \"eeff\")\n    False\n    >>> cycpattern_check(\"himenss\", \"simen\")\n    True\n    \"\"\"\n    # Create a string that contains all rotations of b\n    rotations = [b[i:] + b[:i] for i in range(len(b))]\n    \n    # Check if any rotation is a substring of a\n    for rotation in rotations:\n        if rotation in a:\n            return True\n            \n    return False", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["", ""]]}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n    \"\"\" Given a positive floating point number, it can be decomposed into\n    an integer part (largest integer smaller than given number) and decimals\n    (leftover part always smaller than 1).\n\n    Return the decimal part of the number.\n    \n    >>> truncate_number(3.5)\n    0.5\n    >>> truncate_number(7.25)\n    0.25\n    >>> truncate_number(10.0)\n    0.0\n    >>> truncate_number(5.99)\n    0.99\n    \"\"\"\n    if number < 0:\n        raise ValueError(\"The number must be positive.\")\n    \n    integer_part = int(number)  # Get the integer part\n    decimal_part = number - integer_part  # Calculate the decimal part\n    return decimal_part", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n    \"\"\"Calculate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n    if n < 0:\n        return []\n\n    # Initialize the list to store the Tribonacci numbers\n    tribonacci_sequence = []\n\n    # Define the base cases\n    for i in range(n + 1):\n        if i == 0:\n            tribonacci_sequence.append(1)  # tri(0) = 1\n        elif i == 1:\n            tribonacci_sequence.append(3)  # tri(1) = 3\n        elif i % 2 == 0:  # Even case\n            tribonacci_sequence.append(1 + i / 2)\n        else:  # Odd case\n            # tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1)\n            tri_n_minus_1 = tribonacci_sequence[i - 1]\n            tri_n_minus_2 = tribonacci_sequence[i - 2]\n            tri_n_plus_1 = tribonacci_sequence[i + 1] if i + 1 <= n else 0\n            tribonacci_sequence.append(tri_n_minus_1 + tri_n_minus_2 + tri_n_plus_1)\n\n    return tribonacci_sequence", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[3]], "plus_fail_tests": [[10]]}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n    \"\"\"\n    Given a positive integer n, you have to make a pile of n levels of stones.\n    The first level has n stones.\n    The number of stones in the next level is:\n        - the next odd number if n is odd.\n        - the next even number if n is even.\n    Return the number of stones in each level in a list, where element at index\n    i represents the number of stones in the level (i+1).\n\n    Examples:\n    >>> make_a_pile(3)\n    [3, 5, 7]\n    >>> make_a_pile(4)\n    [4, 6, 8, 10]\n    >>> make_a_pile(1)\n    [1]\n    \"\"\"\n    stones = []\n    current_stones = n\n    \n    for i in range(n):\n        stones.append(current_stones)\n        if current_stones % 2 == 0:  # current_stones is even\n            current_stones += 2  # next even number\n        else:  # current_stones is odd\n            current_stones += 2  # next odd number\n    \n    return stones", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n    \"\"\"\n    Given a positive integer n, return a tuple that has the number of even and odd\n    integer palindromes that fall within the range(1, n), inclusive.\n\n    Example 1:\n\n        Input: 3\n        Output: (1, 2)\n        Explanation:\n        Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n    Example 2:\n\n        Input: 12\n        Output: (4, 6)\n        Explanation:\n        Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n    Note:\n        1. 1 <= n <= 10^3\n        2. returned tuple has the number of even and odd integer palindromes respectively.\n    \"\"\"\n    even_count = 0\n    odd_count = 0\n\n    for i in range(1, n + 1):\n        if str(i) == str(i)[::-1]:  # Check if the number is a palindrome\n            if i % 2 == 0:\n                even_count += 1\n            else:\n                odd_count += 1\n\n    return (even_count, odd_count)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n    \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n    \n    Args:\n        n (int): The number to evaluate.\n        \n    Returns:\n        bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n    \n    Example:\n    is_equal_to_sum_even(4) == False\n    is_equal_to_sum_even(6) == False\n    is_equal_to_sum_even(8) == True\n    \"\"\"\n    # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n    if n < 8:\n        return False\n    \n    # If n is even and at least 8, it can be expressed as the sum of 4 positive even numbers\n    return n % 2 == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n    \"\"\" Insert a number 'delimiter' between every two consecutive elements of input list `numbers`\n    \n    >>> intersperse([], 4)\n    []\n    >>> intersperse([1, 2, 3], 4)\n    [1, 4, 2, 4, 3]\n    \"\"\"\n    if not numbers:\n        return []\n    \n    result = []\n    for i in range(len(numbers) - 1):\n        result.append(numbers[i])\n        result.append(delimiter)\n    result.append(numbers[-1])  # Append the last element\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n    '''\n    Create a function that returns a tuple (a, b), where 'a' is\n    the largest of negative integers, and 'b' is the smallest\n    of positive integers in a list.\n    If there is no negative or positive integers, return them as None.\n\n    Examples:\n    largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n    largest_smallest_integers([]) == (None, None)\n    largest_smallest_integers([0]) == (None, None)\n    '''\n    largest_negative = None\n    smallest_positive = None\n\n    for num in lst:\n        if num < 0:\n            if largest_negative is None or num > largest_negative:\n                largest_negative = num\n        elif num > 0:\n            if smallest_positive is None or num < smallest_positive:\n                smallest_positive = num\n\n    return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n    \"\"\"Given a positive integer n, return the product of the odd digits.\n    Return 0 if all digits are even.\n    For example:\n    digits(1)  == 1\n    digits(4)  == 0\n    digits(235) == 15\n    \"\"\"\n    product = 1\n    has_odd = False\n    \n    for digit in str(n):\n        digit = int(digit)\n        if digit % 2 != 0:  # Check if the digit is odd\n            product *= digit\n            has_odd = True\n            \n    return product if has_odd else 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n    \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n    numbers in the array will be randomly ordered. Your task is to determine if\n    it is possible to get an array sorted in non-decreasing order by performing \n    the following operation on the given array:\n        You are allowed to perform right shift operation any number of times.\n    \n    One right shift operation means shifting all elements of the array by one\n    position in the right direction. The last element of the array will be moved to\n    the starting position in the array i.e. 0th index. \n\n    If it is possible to obtain the sorted array by performing the above operation\n    then return True else return False.\n    If the given array is empty then return True.\n\n    Note: The given list is guaranteed to have unique elements.\n\n    For Example:\n    \n    move_one_ball([3, 4, 5, 1, 2])==>True\n    Explanation: By performing 2 right shift operations, non-decreasing order can\n                 be achieved for the given array.\n    move_one_ball([3, 5, 4, 1, 2])==>False\n    Explanation: It is not possible to get non-decreasing order for the given\n                array by performing any number of right shift operations.\n    \"\"\"\n    if not arr:\n        return True\n\n    n = len(arr)\n    sorted_arr = sorted(arr)\n    \n    # Check for the number of \"breaks\" in the sorted array\n    break_count = 0\n    for i in range(n):\n        if arr[i] > arr[(i + 1) % n]:\n            break_count += 1\n\n    # If there are more than one break, we cannot sort the array with shifts\n    return break_count <= 1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n    \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n    other and return them in order (smaller number, larger number).\n    \n    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n    (2.0, 2.2)\n    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n    (2.0, 2.0)\n    \"\"\"\n    # Sort the numbers to make it easier to find the closest pair\n    sorted_numbers = sorted(numbers)\n    \n    # Initialize the minimum difference and the closest pair\n    min_diff = float('inf')\n    closest_pair = (0.0, 0.0)\n    \n    # Iterate through the sorted list to find the closest elements\n    for i in range(len(sorted_numbers) - 1):\n        diff = sorted_numbers[i + 1] - sorted_numbers[i]\n        if diff < min_diff:\n            min_diff = diff\n            closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n    \n    return closest_pair", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n    \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n    \n    >>> flip_case('Hello')\n    'hELLO'\n    >>> flip_case('Python')\n    'pYTHON'\n    >>> flip_case('123abcXYZ')\n    '123ABCxyz'\n    >>> flip_case('')\n    ''\n    \"\"\"\n    return string.swapcase()", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n    \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n    \n    >>> how_many_times('', 'a')\n    0\n    >>> how_many_times('aaa', 'a')\n    3\n    >>> how_many_times('aaaa', 'aa')\n    3\n    \"\"\"\n    count = 0\n    start = 0\n    \n    while True:\n        start = string.find(substring, start)\n        if start == -1:\n            break\n        count += 1\n        start += 1  # Move to the next character to allow for overlapping\n\n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n    \"\"\" \n    Input are two strings a and b consisting only of 1s and 0s.\n    Perform binary XOR on these inputs and return result also as a string.\n    \n    >>> string_xor('010', '110')\n    '100'\n    >>> string_xor('111', '000')\n    '111'\n    >>> string_xor('101', '101')\n    '000'\n    >>> string_xor('000', '000')\n    '000'\n    >>> string_xor('1101', '1011')\n    '0110'\n    \"\"\"\n    # Ensure both strings are of the same length\n    if len(a) != len(b):\n        raise ValueError(\"Input strings must be of the same length\")\n    \n    # Perform XOR operation\n    result = []\n    for bit_a, bit_b in zip(a, b):\n        result.append('1' if bit_a != bit_b else '0')\n    \n    return ''.join(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n    \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n    >>> count_distinct_characters('xyzXYZ')\n    3\n    >>> count_distinct_characters('Jerry')\n    4\n    \"\"\"\n    # Convert the string to lowercase to ensure case insensitivity\n    lower_string = string.lower()\n    # Use a set to find distinct characters\n    distinct_characters = set(lower_string)\n    # Return the number of distinct characters\n    return len(distinct_characters)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n    \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n    \n    Args:\n        strings (List[str]): A list of strings to filter.\n        prefix (str): The prefix to filter the strings by.\n        \n    Returns:\n        List[str]: A list of strings that start with the given prefix.\n    \n    Examples:\n        >>> filter_by_prefix([], 'a')\n        []\n        >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n        ['abc', 'array']\n    \"\"\"\n    return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n    \"\"\"Create a function encrypt that takes a string as an argument and\n    returns a string encrypted with the alphabet being rotated. \n    The alphabet should be rotated in a manner such that the letters \n    shift down by two multiplied to two places.\n    For example:\n    encrypt('hi') returns 'lm'\n    encrypt('asdfghjkl') returns 'ewhjklnop'\n    encrypt('gf') returns 'kj'\n    encrypt('et') returns 'ix'\n    \"\"\"\n    encrypted = []\n    for char in s:\n        if char.isalpha():  # Check if the character is a letter\n            # Calculate the new character by shifting it down by 4 places\n            new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a')) if char.islower() else chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n            encrypted.append(new_char)\n        else:\n            encrypted.append(char)  # Non-alphabetic characters remain unchanged\n    return ''.join(encrypted)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n    \"\"\"Return list with elements incremented by 1.\n    \n    >>> incr_list([1, 2, 3])\n    [2, 3, 4]\n    >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n    [6, 4, 6, 3, 4, 4, 10, 1, 124]\n    \"\"\"\n    return [x + 1 for x in l]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n    \"\"\"\n    You are given a 2 dimensional data, as a nested lists,\n    which is similar to matrix, however, unlike matrices,\n    each row may contain a different number of columns.\n    Given lst, and integer x, find integers x in the list,\n    and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n    each tuple is a coordinate - (row, columns), starting with 0.\n    Sort coordinates initially by rows in ascending order.\n    Also, sort coordinates of the row by columns in descending order.\n    \n    Examples:\n    get_row([\n      [1,2,3,4,5,6],\n      [1,2,3,4,1,6],\n      [1,2,3,4,5,1]\n    ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n    get_row([], 1) == []\n    get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n    \"\"\"\n    coordinates = []\n    \n    for row_index, row in enumerate(lst):\n        for col_index, value in enumerate(row):\n            if value == x:\n                coordinates.append((row_index, col_index))\n    \n    # Sort by row index (ascending) and then by column index (descending)\n    coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n    \n    return coordinates", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n    \"\"\"Given length of a side and height, return the area of a triangle.\n    \n    The area of a triangle can be calculated using the formula:\n    area = (base * height) / 2\n    \n    Parameters:\n    a (float): The length of the base of the triangle.\n    h (float): The height of the triangle.\n    \n    Returns:\n    float: The area of the triangle.\n    \n    >>> triangle_area(5, 3)\n    7.5\n    >>> triangle_area(10, 2)\n    10.0\n    >>> triangle_area(0, 5)\n    0.0\n    >>> triangle_area(5, 0)\n    0.0\n    \"\"\"\n    return (a * h) / 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n    \"\"\"\n    Given an array arr of integers, find the minimum number of elements that\n    need to be changed to make the array palindromic. A palindromic array is an array that\n    is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n    For example:\n    smallest_change([1,2,3,5,4,7,9,6]) == 4\n    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n    smallest_change([1, 2, 3, 2, 1]) == 0\n    \"\"\"\n    n = len(arr)\n    changes = 0\n    \n    # Compare elements from the start and end towards the center\n    for i in range(n // 2):\n        if arr[i] != arr[n - 1 - i]:\n            changes += 1\n            \n    return changes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n    '''\n    Write a function that accepts two lists of strings and returns the list that has \n    total number of chars in the all strings of the list less than the other list.\n\n    if the two lists have the same number of chars, return the first list.\n\n    Examples\n    total_match([], []) \u279e []\n    total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n    total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n    total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n    total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n    '''\n    # Calculate the total number of characters in each list\n    total_chars_lst1 = sum(len(s) for s in lst1)\n    total_chars_lst2 = sum(len(s) for s in lst2)\n\n    # Compare the total characters and return the appropriate list\n    if total_chars_lst1 < total_chars_lst2:\n        return lst1\n    else:\n        return lst2", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": [[["happy", "birthday", "sarah"], ["happy", "birthday", "sally"]]]}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n    \"\"\"You are given a string s.\n    Your task is to check if the string is happy or not.\n    A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n    \n    For example:\n    is_happy('a') => False\n    is_happy('aa') => False\n    is_happy('abcd') => True\n    is_happy('aabb') => False\n    is_happy('adb') => True\n    is_happy('xyy') => False\n    \"\"\"\n    # Check if the length of the string is at least 3\n    if len(s) < 3:\n        return False\n    \n    # Check every 3 consecutive letters\n    for i in range(len(s) - 2):\n        if len(set(s[i:i+3])) < 3:  # If there are not 3 distinct letters\n            return False\n            \n    return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n    \"\"\" Input to this function is a string representing musical notes in a special ASCII format.\n    Your task is to parse this string and return list of integers corresponding to how many beats does each\n    note last.\n\n    Here is a legend:\n    'o' - whole note, lasts four beats\n    'o|' - half note, lasts two beats\n    '.|' - quarter note, lasts one beat\n\n    >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n    [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n    \"\"\"\n    # Define a mapping of note representations to their corresponding beat values\n    note_to_beats = {\n        'o': 4,   # whole note\n        'o|': 2,  # half note\n        '.|': 1   # quarter note\n    }\n    \n    # Split the input string into individual notes\n    notes = music_string.split()\n    \n    # Parse the notes and convert them to their corresponding beat values\n    beats = [note_to_beats[note] for note in notes if note in note_to_beats]\n    \n    return beats", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n    \"\"\" Test if given string is a palindrome \"\"\"\n    return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n    \"\"\" Find the shortest palindrome that begins with a supplied string.\n    Algorithm idea is simple:\n    - Find the longest postfix of supplied string that is a palindrome.\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n    \n    >>> make_palindrome('')\n    ''\n    >>> make_palindrome('cat')\n    'catac'\n    >>> make_palindrome('cata')\n    'catac'\n    \"\"\"\n    # Find the longest palindromic suffix\n    for i in range(len(string)):\n        if is_palindrome(string[i:]):\n            # If the suffix is a palindrome, we need to append the reverse of the prefix\n            prefix = string[:i]\n            return string + prefix[::-1]\n    return string  # In case the string is empty or already a palindrome", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n    \"\"\" Concatenate list of strings into a single string.\n    \n    >>> concatenate([])\n    ''\n    >>> concatenate(['a', 'b', 'c'])\n    'abc'\n    \"\"\"\n    return ''.join(strings)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n    \"\"\" From a list of integers, remove all elements that occur more than once.\n    Keep order of elements left the same as in the input.\n    \n    >>> remove_duplicates([1, 2, 3, 2, 4])\n    [1, 3, 4]\n    \"\"\"\n    # Count occurrences of each number\n    count = {}\n    for number in numbers:\n        count[number] = count.get(number, 0) + 1\n    \n    # Create a new list with elements that occur only once\n    result = [number for number in numbers if count[number] == 1]\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n    \"\"\" \n    Input is a space-delimited string of numerals from 'zero' to 'nine'.\n    Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n    Return the string with numbers sorted from smallest to largest.\n    \n    >>> sort_numbers('three one five')\n    'one three five'\n    \"\"\"\n    # Mapping of words to their corresponding numeric values\n    num_map = {\n        'zero': 0,\n        'one': 1,\n        'two': 2,\n        'three': 3,\n        'four': 4,\n        'five': 5,\n        'six': 6,\n        'seven': 7,\n        'eight': 8,\n        'nine': 9\n    }\n    \n    # Split the input string into words\n    words = numbers.split()\n    \n    # Sort the words based on their numeric values\n    sorted_words = sorted(words, key=lambda word: num_map[word])\n    \n    # Join the sorted words back into a string\n    return ' '.join(sorted_words)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n    \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n    letter_grades = []\n    \n    for gpa in grades:\n        if gpa == 4.0:\n            letter_grades.append('A+')\n        elif gpa > 3.7:\n            letter_grades.append('A')\n        elif gpa > 3.3:\n            letter_grades.append('A-')\n        elif gpa > 3.0:\n            letter_grades.append('B+')\n        elif gpa > 2.7:\n            letter_grades.append('B')\n        elif gpa > 2.3:\n            letter_grades.append('B-')\n        elif gpa > 2.0:\n            letter_grades.append('C+')\n        elif gpa > 1.7:\n            letter_grades.append('C')\n        elif gpa > 1.3:\n            letter_grades.append('C-')\n        elif gpa > 1.0:\n            letter_grades.append('D+')\n        elif gpa > 0.7:\n            letter_grades.append('D')\n        elif gpa > 0.0:\n            letter_grades.append('D-')\n        else:\n            letter_grades.append('E')\n    \n    return letter_grades", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef get_primes_up_to(limit):\n    \"\"\"Return a list of all prime numbers up to a given limit.\"\"\"\n    return [num for num in range(2, limit) if is_prime(num)]\ndef is_multiply_prime(a):\n    \"\"\"Return true if the given number is the multiplication of 3 prime numbers, false otherwise.\"\"\"\n    if a >= 100:\n        return False\n    \n    primes = get_primes_up_to(a)\n    prime_count = len(primes)\n    \n    # Check all combinations of three primes\n    for i in range(prime_count):\n        for j in range(i, prime_count):\n            for k in range(j, prime_count):\n                product = primes[i] * primes[j] * primes[k]\n                if product == a:\n                    return True\n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n    \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n    such that the smallest number will become 0 and the largest will become 1.\n    \n    >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n    [0.0, 0.25, 0.5, 0.75, 1.0]\n    \"\"\"\n    if len(numbers) < 2:\n        raise ValueError(\"The list must contain at least two elements.\")\n    \n    min_val = min(numbers)\n    max_val = max(numbers)\n    \n    # Avoid division by zero if all numbers are the same\n    if min_val == max_val:\n        return [0.0] * len(numbers)\n    \n    return [(num - min_val) / (max_val - min_val) for num in numbers]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n    '''\n    Write a function that returns True if the object q will fly, and False otherwise.\n    The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n\n    Example:\n    will_it_fly([1, 2], 5) \u279e False \n    # 1+2 is less than the maximum possible weight, but it's unbalanced.\n\n    will_it_fly([3, 2, 3], 1) \u279e False\n    # it's balanced, but 3+2+3 is more than the maximum possible weight.\n\n    will_it_fly([3, 2, 3], 9) \u279e True\n    # 3+2+3 is less than the maximum possible weight, and it's balanced.\n\n    will_it_fly([3], 5) \u279e True\n    # 3 is less than the maximum possible weight, and it's balanced.\n    '''\n    # Check if the list is a palindrome\n    is_balanced = q == q[::-1]\n    \n    # Calculate the sum of the elements in the list\n    total_weight = sum(q)\n    \n    # Check if the object will fly\n    return is_balanced and total_weight <= w", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n    \"\"\"Change numerical base of input number x to base.\n    return string representation after the conversion.\n    base numbers are less than 10.\n    \n    >>> change_base(8, 3)\n    '22'\n    >>> change_base(8, 2)\n    '1000'\n    >>> change_base(7, 2)\n    '111'\n    \"\"\"\n    if base < 2 or base >= 10:\n        raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n    \n    if x == 0:\n        return '0'\n    \n    result = []\n    while x > 0:\n        result.append(str(x % base))\n        x //= base\n    \n    return ''.join(reversed(result))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n    \"\"\"\n    Write a function that takes a string and returns an ordered version of it.\n    Ordered version of string, is a string where all words (separated by space)\n    are replaced by a new word where all the characters arranged in\n    ascending order based on ascii value.\n    Note: You should keep the order of words and blank spaces in the sentence.\n\n    For example:\n    anti_shuffle('Hi') returns 'Hi'\n    anti_shuffle('hello') returns 'ehllo'\n    anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n    \"\"\"\n    # Split the input string into words while preserving spaces\n    words = s.split(' ')\n    \n    # Sort the characters in each word\n    sorted_words = [''.join(sorted(word)) for word in words]\n    \n    # Join the sorted words back with spaces\n    result = ' '.join(sorted_words)\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n    \"\"\"\n    Given an array of non-negative integers, return a copy of the given array after sorting,\n    you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n    or sort it in descending order if the sum( first index value, last index value) is even.\n\n    Note:\n    * don't change the given array.\n\n    Examples:\n    * sort_array([]) => []\n    * sort_array([5]) => [5]\n    * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n    * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n    \"\"\"\n    if not array:  # Check for empty array\n        return []\n    \n    first_value = array[0]\n    last_value = array[-1]\n    sum_values = first_value + last_value\n\n    # Create a copy of the array to sort\n    sorted_array = array.copy()\n\n    if sum_values % 2 == 0:  # Even sum\n        sorted_array.sort(reverse=True)  # Sort in descending order\n    else:  # Odd sum\n        sorted_array.sort()  # Sort in ascending order\n\n    return sorted_array", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n    \"\"\"\n    pairs_sum_to_zero takes a list of integers as an input.\n    it returns True if there are two distinct elements in the list that\n    sum to zero, and False otherwise.\n    \n    >>> pairs_sum_to_zero([1, 3, 5, 0])\n    False\n    >>> pairs_sum_to_zero([1, 3, -2, 1])\n    False\n    >>> pairs_sum_to_zero([1, 2, 3, 7])\n    False\n    >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n    True\n    >>> pairs_sum_to_zero([1])\n    False\n    \"\"\"\n    seen = set()\n    for number in l:\n        if -number in seen:\n            return True\n        seen.add(number)\n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n    \"\"\"\n    Given a dictionary, return True if all keys are strings in lower \n    case or all keys are strings in upper case, else return False.\n    The function should return False if the given dictionary is empty.\n    \n    Examples:\n    check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n    check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n    check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n    check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n    check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n    \"\"\"\n    if not input_dict:\n        return False\n\n    all_lower = all(isinstance(key, str) and key.islower() for key in input_dict.keys())\n    all_upper = all(isinstance(key, str) and key.isupper() for key in input_dict.keys())\n\n    return all_lower or all_upper", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n    \"\"\" \n    brackets is a string of \"(\" and \")\".\n    return True if every opening bracket has a corresponding closing bracket.\n\n    >>> correct_bracketing(\"(\")\n    False\n    >>> correct_bracketing(\"()\")\n    True\n    >>> correct_bracketing(\"(()())\")\n    True\n    >>> correct_bracketing(\")(()\")\n    False\n    \"\"\"\n    balance = 0\n    for char in brackets:\n        if char == '(':\n            balance += 1\n        elif char == ')':\n            balance -= 1\n        \n        # If balance goes negative, there are unmatched closing brackets\n        if balance < 0:\n            return False\n    \n    # At the end, balance should be zero for all opening brackets to be matched\n    return balance == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n    \"\"\"Task\n    Write a function that takes a string as input and returns the sum of the upper characters only'\n    ASCII codes.\n\n    Examples:\n        digitSum(\"\") => 0\n        digitSum(\"abAB\") => 131\n        digitSum(\"abcCd\") => 67\n        digitSum(\"helloE\") => 69\n        digitSum(\"woArBld\") => 131\n        digitSum(\"aAaaaXa\") => 153\n    \"\"\"\n    return sum(ord(char) for char in s if char.isupper())", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n    '''\n    Create a function that takes 3 numbers.\n    Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n    Returns false in any other cases.\n    \n    Examples\n    any_int(5, 2, 7) \u279e True\n    \n    any_int(3, 2, 2) \u279e False\n\n    any_int(3, -2, 1) \u279e True\n    \n    any_int(3.6, -2.2, 2) \u279e False\n    '''\n    # Check if all inputs are integers\n    if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n        # Check if any number is equal to the sum of the other two\n        return x == y + z or y == x + z or z == x + y\n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int):\n    \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n    \n    >>> largest_prime_factor(13195)\n    29\n    >>> largest_prime_factor(2048)\n    2\n    \"\"\"\n    # Start with the smallest prime factor\n    factor = 2\n    # Keep dividing n by factor until it is no longer divisible\n    while n > 1:\n        if n % factor == 0:\n            n //= factor  # Divide n by the factor\n        else:\n            factor += 1  # Move to the next potential factor\n    return factor  # The last factor is the largest prime factor", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n    \"\"\"\n    Given an array representing a branch of a tree that has non-negative integer nodes,\n    your task is to pluck one of the nodes and return it.\n    The plucked node should be the node with the smallest even value.\n    If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n    The plucked node should be returned in a list, [ smallest_value, its index ],\n    If there are no even values or the given array is empty, return [].\n\n    Example 1:\n        Input: [4,2,3]\n        Output: [2, 1]\n        Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n    Example 2:\n        Input: [1,2,3]\n        Output: [2, 1]\n        Explanation: 2 has the smallest even value, and 2 has the smallest index. \n\n    Example 3:\n        Input: []\n        Output: []\n    \n    Example 4:\n        Input: [5, 0, 3, 0, 4, 2]\n        Output: [0, 1]\n        Explanation: 0 is the smallest value, but there are two zeros,\n                     so we will choose the first zero, which has the smallest index.\n\n    Constraints:\n        * 1 <= nodes.length <= 10000\n        * 0 <= node.value\n    \"\"\"\n    smallest_even = float('inf')\n    smallest_index = -1\n\n    for index, value in enumerate(arr):\n        if value % 2 == 0:  # Check if the value is even\n            if value < smallest_even:  # Check if it's the smallest even found\n                smallest_even = value\n                smallest_index = index\n\n    if smallest_index == -1:  # No even value found\n        return []\n    \n    return [smallest_even, smallest_index]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n    \"\"\"Return True if list elements are monotonically increasing or decreasing.\n    \n    >>> monotonic([1, 2, 4, 20])\n    True\n    >>> monotonic([1, 20, 4, 10])\n    False\n    >>> monotonic([4, 1, 0, -10])\n    True\n    \"\"\"\n    if not l:  # An empty list is considered monotonic\n        return True\n    \n    increasing = decreasing = True\n    \n    for i in range(1, len(l)):\n        if l[i] > l[i - 1]:\n            decreasing = False\n        elif l[i] < l[i - 1]:\n            increasing = False\n            \n    return increasing or decreasing", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n    \"\"\"\n    Takes as input string encoded with encode_shift function. Returns decoded string.\n    \"\"\"\n    return \"\".join([chr(((ord(ch) - ord(\"a\") - 5) % 26) + ord(\"a\")) for ch in s])", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float) -> float:\n    \"\"\"\n    Evaluates polynomial with coefficients xs at point x.\n    return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n    \"\"\"\n    return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list) -> list:\n    \"\"\"\n    Returns the coefficients of the derivative of the polynomial.\n    \"\"\"\n    return [i * coeff for i, coeff in enumerate(xs)][1:]\ndef find_zero(xs: list, initial_guess: float = 0.0, tolerance: float = 1e-7, max_iterations: int = 1000) -> float:\n    \"\"\" \n    xs are coefficients of a polynomial.\n    find_zero finds x such that poly(x) = 0.\n    find_zero returns only one zero point, even if there are many.\n    Moreover, find_zero only takes list xs having an even number of coefficients\n    and the largest non-zero coefficient as it guarantees a solution.\n    \n    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n    -0.5\n    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n    1.0\n    \"\"\"\n    if len(xs) % 2 != 0:\n        raise ValueError(\"The number of coefficients must be even.\")\n    \n    x = initial_guess\n    for _ in range(max_iterations):\n        f_x = poly(xs, x)\n        f_prime_x = poly(derivative(xs), x)\n        \n        if abs(f_prime_x) < tolerance:  # Avoid division by zero\n            raise ValueError(\"Derivative is too small; no solution found.\")\n        \n        x_new = x - f_x / f_prime_x\n        \n        if abs(x_new - x) < tolerance:\n            return x_new\n        \n        x = x_new\n    \n    raise ValueError(\"Maximum iterations reached; no solution found.\")", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[[5, 10, -3, 1]]]}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n    \"\"\" \n    brackets is a string of \"<\" and \">\".\n    return True if every opening bracket has a corresponding closing bracket.\n\n    >>> correct_bracketing(\"<\")\n    False\n    >>> correct_bracketing(\"<>\")\n    True\n    >>> correct_bracketing(\"<<><>>\")\n    True\n    >>> correct_bracketing(\"><<>\")\n    False\n    \"\"\"\n    balance = 0\n    for char in brackets:\n        if char == '<':\n            balance += 1\n        elif char == '>':\n            balance -= 1\n        # If balance goes negative, there are more closing brackets\n        if balance < 0:\n            return False\n    # At the end, balance should be zero for correct bracketing\n    return balance == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n    \"\"\"Return maximum element in the list.\n    \n    >>> max_element([1, 2, 3])\n    3\n    >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n    123\n    \"\"\"\n    if not l:\n        raise ValueError(\"The list is empty.\")\n    \n    max_value = l[0]\n    for item in l:\n        if item > max_value:\n            max_value = item\n    return max_value", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n    '''\n    You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n    zero, and has a frequency greater than or equal to the value of the integer itself. \n    The frequency of an integer is the number of times it appears in the list.\n    If no such a value exist, return -1.\n    \n    Examples:\n        search([4, 1, 2, 2, 3, 1]) == 2\n        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n        search([5, 5, 4, 4, 4]) == -1\n    '''\n    from collections import Counter\n    \n    # Count the frequency of each number in the list\n    frequency = Counter(lst)\n    \n    # Initialize the result variable\n    result = -1\n    \n    # Iterate through the frequency dictionary\n    for num, freq in frequency.items():\n        # Check if the frequency is greater than or equal to the number itself\n        if freq >= num:\n            # Update the result if this number is greater than the current result\n            result = max(result, num)\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n    \"\"\"\n    remove_vowels is a function that takes a string and returns a string without vowels.\n    \n    >>> remove_vowels('')\n    ''\n    >>> remove_vowels(\"abcdef\\nghijklm\")\n    'bcdf\\nghjklm'\n    >>> remove_vowels('abcdef')\n    'bcdf'\n    >>> remove_vowels('aaaaa')\n    ''\n    >>> remove_vowels('aaBAA')\n    'B'\n    >>> remove_vowels('zbcd')\n    'zbcd'\n    \"\"\"\n    vowels = 'aeiouAEIOU'\n    return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n    \"\"\"\n    Write a function that takes a message, and encodes in such a \n    way that it swaps case of all letters, replaces all vowels in \n    the message with the letter that appears 2 places ahead of that \n    vowel in the english alphabet. \n    Assume only letters. \n    \n    Examples:\n    >>> encode('test')\n    'TGST'\n    >>> encode('This is a message')\n    'tHKS KS C MGSSCGG'\n    \"\"\"\n    vowels = 'aeiouAEIOU'\n    encoded_message = []\n\n    for char in message:\n        if char.isalpha():  # Check if the character is a letter\n            # Swap case\n            if char in vowels:\n                # Replace vowel with the letter 2 places ahead\n                if char.islower():\n                    new_char = chr(((ord(char) - ord('a') + 2) % 26) + ord('a'))\n                else:\n                    new_char = chr(((ord(char) - ord('A') + 2) % 26) + ord('A'))\n            else:\n                new_char = char.swapcase()  # Swap case for consonants\n            encoded_message.append(new_char)\n        else:\n            encoded_message.append(char)  # Keep non-letter characters unchanged\n\n    return ''.join(encoded_message)", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["TEST"]], "plus_fail_tests": [["abcdefghijklmnopqrstuvwxyz"]]}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n    \"\"\"\n    In this task, you will be given a string that represents a number of apples and oranges \n    that are distributed in a basket of fruit. This basket contains \n    apples, oranges, and mango fruits. Given the string that represents the total number of \n    the oranges and apples and an integer that represents the total number of the fruits \n    in the basket, return the number of the mango fruits in the basket.\n    \n    Parameters:\n    s (str): A string representing the number of apples and oranges.\n    n (int): An integer representing the total number of fruits in the basket.\n    \n    Returns:\n    int: The number of mango fruits in the basket.\n    \n    Examples:\n    fruit_distribution(\"5 apples and 6 oranges\", 19) -> 8\n    fruit_distribution(\"0 apples and 1 oranges\", 3) -> 2\n    fruit_distribution(\"2 apples and 3 oranges\", 100) -> 95\n    fruit_distribution(\"100 apples and 1 oranges\", 120) -> 19\n    \"\"\"\n    # Extract the number of apples and oranges from the string\n    parts = s.split()\n    apples = int(parts[0])  # First part is the number of apples\n    oranges = int(parts[3])  # Fourth part is the number of oranges\n    \n    # Calculate the number of mangoes\n    mangoes = n - apples - oranges\n    return mangoes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n    \"\"\"Return sorted unique common elements for two lists.\n    \n    >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n    [1, 5, 653]\n    >>> common([5, 3, 2, 8], [3, 2])\n    [2, 3]\n    \n    \"\"\"\n    # Convert both lists to sets to find unique elements\n    set1 = set(l1)\n    set2 = set(l2)\n    \n    # Find the intersection of both sets\n    common_elements = set1.intersection(set2)\n    \n    # Return the sorted list of common elements\n    return sorted(common_elements)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n    \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n    \n    >>> sum_to_n(30)\n    465\n    >>> sum_to_n(100)\n    5050\n    >>> sum_to_n(5)\n    15\n    >>> sum_to_n(10)\n    55\n    >>> sum_to_n(1)\n    1\n    \"\"\"\n    return n * (n + 1) // 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n    \"\"\"Return sorted unique elements in a list\n    >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n    [0, 2, 3, 5, 9, 123]\n    \"\"\"\n    return sorted(set(l))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n    \"\"\"This function takes a list l and returns a list l' such that\n    l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n    to the values of the corresponding indices of l, but sorted.\n    \n    >>> sort_third([1, 2, 3])\n    [1, 2, 3]\n    >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n    [2, 6, 3, 4, 8, 9, 5]\n    \"\"\"\n    # Extract values at indices divisible by 3\n    divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n    \n    # Sort the extracted values\n    sorted_values = sorted(divisible_by_three)\n    \n    # Create a new list to hold the result\n    result = l[:]  # Start with a copy of the original list\n    \n    # Replace values at indices divisible by 3 with sorted values\n    for index, value in zip([i for i in range(len(l)) if i % 3 == 0], sorted_values):\n        result[index] = value\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n    \"\"\"\n    Given an array of integers nums, find the minimum sum of any non-empty sub-array\n    of nums.\n    \n    Example\n    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n    minSubArraySum([-1, -2, -3]) == -6\n    \"\"\"\n    # Initialize variables to track the minimum sum and the current sum\n    min_sum = float('inf')\n    current_sum = 0\n    \n    for num in nums:\n        current_sum += num\n        min_sum = min(min_sum, current_sum)\n        \n        # If current_sum becomes positive, reset it to 0\n        if current_sum > 0:\n            current_sum = 0\n            \n    return min_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n    \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n    Each element i of the output should be \"the number of odd elements in the\n    string i of the input.\" where all the i's should be replaced by the number\n    of odd digits in the i'th string of the input.\n\n    >>> odd_count(['1234567'])\n    [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n    >>> odd_count(['3',\"11111111\"])\n    [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n     \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n    \"\"\"\n    result = []\n    for s in lst:\n        odd_count = sum(1 for char in s if int(char) % 2 != 0)\n        result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n    '''\n    Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n    should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n    alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n    \n    Examples:\n    split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n    split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n    split_words(\"abcdef\") \u279e 3 \n    '''\n    # Check for whitespace\n    if ' ' in txt:\n        return txt.split()\n    \n    # Check for commas\n    elif ',' in txt:\n        return txt.split(',')\n    \n    # If no whitespace or commas, count lower-case letters with odd order\n    else:\n        odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n        return odd_count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n    \"\"\"\n    Given a non-empty array of integers arr and an integer k, return\n    the sum of the elements with at most two digits from the first k elements of arr.\n\n    Example:\n\n        Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n        Output: 24 # sum of 21 + 3\n\n    Constraints:\n        1. 1 <= len(arr) <= 100\n        2. 1 <= k <= len(arr)\n    \"\"\"\n    # Initialize the sum\n    total_sum = 0\n    \n    # Iterate through the first k elements of the array\n    for i in range(k):\n        # Check if the current element has at most two digits\n        if -100 < arr[i] < 100:\n            total_sum += arr[i]\n    \n    return total_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n    \"\"\"Accepts a list of strings, removes strings with odd lengths,\n    and returns the remaining strings sorted by length and alphabetically.\n    \n    Args:\n        lst (list of str): A list of strings.\n        \n    Returns:\n        list of str: A sorted list of strings with even lengths.\n    \"\"\"\n    # Filter out strings with odd lengths\n    filtered_lst = [s for s in lst if len(s) % 2 == 0]\n    \n    # Sort the list first by length, then alphabetically\n    sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n    \n    return sorted_lst", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n    \"\"\"\n    Given a string text, replace all spaces in it with underscores, \n    and if a string has more than 2 consecutive spaces, \n    then replace all consecutive spaces with - \n    \n    fix_spaces(\"Example\") == \"Example\"\n    fix_spaces(\"Example 1\") == \"Example_1\"\n    fix_spaces(\" Example 2\") == \"_Example_2\"\n    fix_spaces(\" Example   3\") == \"_Example-3\"\n    \"\"\"\n    import re\n    \n    # Replace more than 2 consecutive spaces with a single '-'\n    text = re.sub(r' {3,}', '-', text)\n    \n    # Replace single spaces with underscores\n    text = text.replace(' ', '_')\n    \n    return text", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n    \"\"\"\n    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n    as follows: start with any positive integer n. Then each term is obtained from the \n    previous term as follows: if the previous term is even, the next term is one half of \n    the previous term. If the previous term is odd, the next term is 3 times the previous\n    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n    Note: \n        1. Collatz(1) is [1].\n        2. returned list sorted in increasing order.\n\n    For example:\n    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n    \"\"\"\n    if n <= 0:\n        raise ValueError(\"Input must be a positive integer.\")\n    \n    collatz_sequence = []\n    current = n\n    \n    while current != 1:\n        collatz_sequence.append(current)\n        if current % 2 == 0:\n            current //= 2\n        else:\n            current = 3 * current + 1\n    \n    collatz_sequence.append(1)  # Add the last term which is 1\n    \n    # Filter odd numbers and sort them\n    odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n    \n    return odd_numbers", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n    \"\"\"Task\n    We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n    then check if the result string is palindrome.\n    A string is called palindrome if it reads the same backward as forward.\n    You should return a tuple containing the result string and True/False for the check.\n    Example\n    For s = \"abcde\", c = \"ae\", the result should be ('bcd',False)\n    For s = \"abcdef\", c = \"b\"  the result should be ('acdef',False)\n    For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc',True)\n    \"\"\"\n    # Create a set of characters to delete for faster lookup\n    delete_set = set(c)\n    \n    # Create the result string by filtering out characters in delete_set\n    result = ''.join(char for char in s if char not in delete_set)\n    \n    # Check if the result string is a palindrome\n    is_palindrome = result == result[::-1]\n    \n    return (result, is_palindrome)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n    \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n    \n    The date is valid if all of the following rules are satisfied:\n    1. The date string is not empty.\n    2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n       The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n       The number of days is not less than 1 or higher than 29 for the month 2.\n    3. The months should not be less than 1 or higher than 12.\n    4. The date should be in the format: mm-dd-yyyy\n    \n    Args:\n        date (str): The date string to validate.\n    \n    Returns:\n        bool: True if the date is valid, False otherwise.\n    \"\"\"\n    if not date:\n        return False\n    \n    # Check the format\n    if len(date) != 10 or date[2] != '-' or date[5] != '-':\n        return False\n    \n    try:\n        month = int(date[:2])\n        day = int(date[3:5])\n        year = int(date[6:])\n    except ValueError:\n        return False\n    \n    # Validate month\n    if month < 1 or month > 12:\n        return False\n    \n    # Validate day based on month\n    if month in [1, 3, 5, 7, 8, 10, 12]:  # 31 days\n        if day < 1 or day > 31:\n            return False\n    elif month in [4, 6, 9, 11]:  # 30 days\n        if day < 1 or day > 30:\n            return False\n    elif month == 2:  # February\n        if day < 1 or day > 29:\n            return False\n    \n    return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n    \"\"\"\n    Calculate the number of times buckets need to be lowered to empty the wells.\n\n    Parameters:\n    grid (list of list of int): A rectangular grid representing wells.\n    capacity (int): The capacity of each bucket.\n\n    Returns:\n    int: The total number of times buckets need to be lowered.\n    \"\"\"\n    total_water = 0\n    \n    # Count the total amount of water in the grid\n    for row in grid:\n        total_water += sum(row)\n    \n    # Calculate the number of times buckets need to be lowered\n    # Each bucket can carry 'capacity' units of water\n    if total_water == 0:\n        return 0\n    else:\n        return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": [[[[1, 0, 0, 1], [0, 1, 1, 1], [0, 0, 0, 0], [1, 0, 1, 1]], 2]]}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n    \"\"\"Create a function which takes a string representing a file's name, and returns\n    'Yes' if the the file's name is valid, and returns 'No' otherwise.\n    A file's name is considered to be valid if and only if all the following conditions \n    are met:\n    - There should not be more than three digits ('0'-'9') in the file's name.\n    - The file's name contains exactly one dot '.'\n    - The substring before the dot should not be empty, and it starts with a letter from \n    the latin alphapet ('a'-'z' and 'A'-'Z').\n    - The substring after the dot should be one of these: ['txt', 'exe', 'dll']\n    Examples:\n    file_name_check(\"example.txt\") # => 'Yes'\n    file_name_check(\"1example.dll\") # => 'No' (the name should start with a latin alphapet letter)\n    \"\"\"\n    \n    # Split the file name into name and extension\n    if file_name.count('.') != 1:\n        return 'No'\n    \n    name, extension = file_name.split('.')\n    \n    # Check if the name is empty or starts with a non-alphabet character\n    if not name or not name[0].isalpha():\n        return 'No'\n    \n    # Check if the extension is valid\n    valid_extensions = ['txt', 'exe', 'dll']\n    if extension not in valid_extensions:\n        return 'No'\n    \n    # Count the number of digits in the file name\n    digit_count = sum(c.isdigit() for c in file_name)\n    if digit_count > 3:\n        return 'No'\n    \n    return 'Yes'", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n    \"\"\"Write a function that takes an array of numbers as input and returns \n    the number of elements in the array that are greater than 10 and both \n    first and last digits of a number are odd (1, 3, 5, 7, 9).\n    \n    For example:\n    specialFilter([15, -73, 14, -15]) => 1 \n    specialFilter([33, -2, -3, 45, 21, 109]) => 2\n    \"\"\"\n    \n    def is_odd_digit(digit):\n        return digit in {'1', '3', '5', '7', '9'}\n    \n    def first_and_last_odd(num):\n        str_num = str(abs(num))  # Convert to string and take absolute value\n        return is_odd_digit(str_num[0]) and is_odd_digit(str_num[-1])\n    \n    count = 0\n    for num in nums:\n        if num > 10 and first_and_last_odd(num):\n            count += 1\n            \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n    '''\n    There are eight planets in our solar system: the closest to the Sun \n    is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n    Uranus, Neptune.\n    Write a function that takes two planet names as strings planet1 and planet2. \n    The function should return a tuple containing all planets whose orbits are \n    located between the orbit of planet1 and the orbit of planet2, sorted by \n    the proximity to the sun. \n    The function should return an empty tuple if planet1 or planet2\n    are not correct planet names. \n    Examples\n    bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n    bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n    bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n    '''\n    \n    planets = [\n        \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n        \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n    ]\n    \n    if planet1 not in planets or planet2 not in planets:\n        return ()\n    \n    index1 = planets.index(planet1)\n    index2 = planets.index(planet2)\n    \n    # Ensure index1 is less than index2 for slicing\n    start_index = min(index1, index2) + 1\n    end_index = max(index1, index2)\n    \n    return tuple(planets[start_index:end_index])", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n    \"\"\"You are given a list of numbers.\n    You need to return the sum of squared numbers in the given list,\n    round each element in the list to the upper int (Ceiling) first.\n    \n    Examples:\n    For lst = [1,2,3] the output should be 14\n    For lst = [1,4,9] the output should be 98\n    For lst = [1,3,5,7] the output should be 84\n    For lst = [1.4,4.2,0] the output should be 29\n    For lst = [-2.4,1,1] the output should be 6\n    \"\"\"\n    return sum(math.ceil(x) ** 2 for x in lst)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n    '''\n    Create a function that returns True if the last character\n    of a given string is an alphabetical character and is not\n    a part of a word, and False otherwise.\n    Note: \"word\" is a group of characters separated by space.\n\n    Examples:\n    check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n    check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n    check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n    check_if_last_char_is_a_letter(\"\") \u279e False \n    '''\n    # Strip any trailing whitespace from the string\n    txt = txt.rstrip()\n    \n    # Check if the string is empty after stripping\n    if not txt:\n        return False\n    \n    # Get the last character of the string\n    last_char = txt[-1]\n    \n    # Check if the last character is a letter\n    if last_char.isalpha():\n        # Check if the last character is part of a word\n        # A character is part of a word if it is preceded by a non-space character\n        if len(txt) > 1 and txt[-2] != ' ':\n            return False\n        return True\n    \n    return False", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["eeeee e "]], "plus_fail_tests": [["k "]]}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n    \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n    in the sequence.\n    \n    >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n    [1, 2, 3, 3, 3, 4, 4]\n    \"\"\"\n    if not numbers:\n        return []\n    \n    max_so_far = numbers[0]\n    result = [max_so_far]\n    \n    for num in numbers[1:]:\n        max_so_far = max(max_so_far, num)\n        result.append(max_so_far)\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n    \"\"\"This function takes two positive numbers x and y and returns the\n    biggest even integer number that is in the range [x, y] inclusive. If \n    there's no such number, then the function should return -1.\n\n    For example:\n    choose_num(12, 15) = 14\n    choose_num(13, 12) = -1\n    \"\"\"\n    # Ensure x is less than or equal to y\n    if x > y:\n        return -1\n    \n    # Start from the largest number in the range and check for evenness\n    for num in range(y, x - 1, -1):\n        if num % 2 == 0:\n            return num\n    \n    return -1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n    \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n    given threshold.\n    \n    >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n    False\n    >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n    True\n    \"\"\"\n    # Sort the numbers to make it easier to find close elements\n    numbers.sort()\n    \n    # Check the difference between consecutive elements\n    for i in range(len(numbers) - 1):\n        if abs(numbers[i] - numbers[i + 1]) < threshold:\n            return True\n            \n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n    \"\"\"\n    Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n    reverse the resulting array, and then replace each digit by its corresponding name from\n    \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n    For example:\n      arr = [2, 1, 1, 4, 5, 8, 2, 3]   \n            -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n            -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n      return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n    \n      If the array is empty, return an empty array:\n      arr = []\n      return []\n    \n      If the array has any strange number ignore it:\n      arr = [1, -1 , 55] \n            -> sort arr -> [-1, 1, 55]\n            -> reverse arr -> [55, 1, -1]\n      return = ['One']\n    \"\"\"\n    \n    # Mapping of digits to their corresponding names\n    digit_to_name = {\n        1: \"One\",\n        2: \"Two\",\n        3: \"Three\",\n        4: \"Four\",\n        5: \"Five\",\n        6: \"Six\",\n        7: \"Seven\",\n        8: \"Eight\",\n        9: \"Nine\"\n    }\n    \n    # Filter the array to include only numbers between 1 and 9\n    filtered_arr = [num for num in arr if 1 <= num <= 9]\n    \n    # Sort the filtered array\n    filtered_arr.sort()\n    \n    # Reverse the sorted array\n    filtered_arr.reverse()\n    \n    # Convert the numbers to their corresponding names\n    result = [digit_to_name[num] for num in filtered_arr]\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n    \"\"\" Filter an input list of strings only for ones that contain given substring\n    >>> filter_by_substring([], 'a')\n    []\n    >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n    ['abc', 'bacd', 'array']\n    \"\"\"\n    return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n    '''\n    Given a list of numbers, return the sum of squares of the numbers\n    in the list that are odd. Ignore numbers that are negative or not integers.\n    \n    double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n    double_the_difference([-1, -2, 0]) == 0\n    double_the_difference([9, -2]) == 81\n    double_the_difference([0]) == 0  \n   \n    If the input list is empty, return 0.\n    '''\n    if not lst:  # Check if the list is empty\n        return 0\n    \n    return sum(x**2 for x in lst if isinstance(x, int) and x >= 0 and x % 2 != 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n    \"\"\"\n    Given two lists operator, and operand. The first list has basic algebra operations, and \n    the second list is a list of integers. Use the two given lists to build the algebraic \n    expression and return the evaluation of this expression.\n\n    The basic algebra operations:\n    Addition ( + ) \n    Subtraction ( - ) \n    Multiplication ( * ) \n    Floor division ( // ) \n    Exponentiation ( ** ) \n\n    Example:\n    operator = ['+', '*', '-']\n    operand = [2, 3, 4, 5]\n    result = 2 + 3 * 4 - 5\n    => result = 9\n\n    Note:\n        The length of operator list is equal to the length of operand list minus one.\n        Operand is a list of non-negative integers.\n        Operator list has at least one operator, and operand list has at least two operands.\n    \"\"\"\n    # Start with the first operand\n    result = operand[0]\n    \n    # Iterate through the operators and operands\n    for i in range(len(operator)):\n        op = operator[i]\n        next_operand = operand[i + 1]\n        \n        if op == '+':\n            result += next_operand\n        elif op == '-':\n            result -= next_operand\n        elif op == '*':\n            result *= next_operand\n        elif op == '//':\n            result //= next_operand\n        elif op == '**':\n            result **= next_operand\n        else:\n            raise ValueError(f\"Unsupported operator: {op}\")\n    \n    return result", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": [[["+", "-", "*", "//"], [5, 2, 3, 4, 7]]]}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n    \"\"\"\n    Given a positive integer, obtain its roman numeral equivalent as a string,\n    and return it in lowercase.\n    Restrictions: 1 <= num <= 1000\n\n    Examples:\n    >>> int_to_mini_roman(19) == 'xix'\n    >>> int_to_mini_roman(152) == 'clii'\n    >>> int_to_mini_roman(426) == 'cdxxvi'\n    \"\"\"\n    if not (1 <= number <= 1000):\n        raise ValueError(\"Number must be between 1 and 1000\")\n\n    roman_numerals = [\n        (1000, 'm'),\n        (900, 'cm'),\n        (500, 'd'),\n        (400, 'cd'),\n        (100, 'c'),\n        (90, 'xc'),\n        (50, 'l'),\n        (40, 'xl'),\n        (10, 'x'),\n        (9, 'ix'),\n        (5, 'v'),\n        (4, 'iv'),\n        (1, 'i')\n    ]\n\n    result = []\n    for value, numeral in roman_numerals:\n        while number >= value:\n            result.append(numeral)\n            number -= value\n\n    return ''.join(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n    \"\"\"\n    You are given a positive integer n. You have to create an integer array a of length n.\n    For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n    Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n    and a[i] + a[j] + a[k] is a multiple of 3.\n\n    Example :\n        Input: n = 5\n        Output: 1\n        Explanation: \n        a = [1, 3, 7, 13, 21]\n        The only valid triple is (1, 7, 13).\n    \"\"\"\n    # Create the array a\n    a = [i * i - i + 1 for i in range(1, n + 1)]\n    \n    # Count the number of valid triples\n    count = 0\n    for i in range(n):\n        for j in range(i + 1, n):\n            for k in range(j + 1, n):\n                if (a[i] + a[j] + a[k]) % 3 == 0:\n                    count += 1\n                    \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n    \"\"\"Given a list of positive integers x, return a sorted list of all \n    elements that haven't any even digit.\n\n    Note: Returned list should be sorted in increasing order.\n    \n    For example:\n    >>> unique_digits([15, 33, 1422, 1])\n    [1, 15, 33]\n    >>> unique_digits([152, 323, 1422, 10])\n    []\n    \"\"\"\n    def has_even_digit(n):\n        \"\"\"Check if the number has any even digit.\"\"\"\n        return any(int(digit) % 2 == 0 for digit in str(n))\n\n    # Filter the list to include only numbers without even digits\n    result = [num for num in x if not has_even_digit(num)]\n    \n    # Return the sorted result\n    return sorted(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n    \"\"\"Write a function that accepts a list of strings.\n    The list contains different words. Return the word with maximum number\n    of unique characters. If multiple strings have maximum number of unique\n    characters, return the one which comes first in lexicographical order.\n\n    find_max([\"name\", \"of\", \"string\"]) == \"string\"\n    find_max([\"name\", \"enam\", \"game\"]) == \"enam\"\n    find_max([\"aaaaaaa\", \"bb\" ,\"cc\"]) == \"aaaaaaa\"\n    \"\"\"\n    max_word = \"\"\n    max_unique_count = 0\n\n    for word in words:\n        unique_chars = set(word)\n        unique_count = len(unique_chars)\n\n        if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n            max_word = word\n            max_unique_count = unique_count\n\n    return max_word", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n    \"\"\" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n    For each of the group, output the deepest level of nesting of parentheses.\n    E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n    >>> parse_nested_parens('(()()) ((())) () ((())()())')\n    [2, 3, 1, 3]\n    \"\"\"\n    def max_nesting_depth(s: str) -> int:\n        max_depth = 0\n        current_depth = 0\n        for char in s:\n            if char == '(':\n                current_depth += 1\n                max_depth = max(max_depth, current_depth)\n            elif char == ')':\n                current_depth -= 1\n        return max_depth\n\n    groups = paren_string.split()\n    return [max_nesting_depth(group) for group in groups]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n    \"\"\" \n    Input to this function is a string containing multiple groups of nested parentheses. \n    Your goal is to separate those groups into separate strings and return the list of those.\n    Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n    Ignore any spaces in the input string.\n    \n    >>> separate_paren_groups('( ) (( )) (( )( ))')\n    ['()', '(())', '(()())']\n    \"\"\"\n    # Remove spaces from the input string\n    paren_string = paren_string.replace(\" \", \"\")\n    \n    result = []\n    balance = 0\n    current_group = []\n    \n    for char in paren_string:\n        if char == '(':\n            if balance == 0 and current_group:\n                result.append(''.join(current_group))\n                current_group = []\n            balance += 1\n            current_group.append(char)\n        elif char == ')':\n            balance -= 1\n            current_group.append(char)\n            if balance == 0:\n                result.append(''.join(current_group))\n                current_group = []\n    \n    # In case there are any remaining groups\n    if current_group:\n        result.append(''.join(current_group))\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n    \"\"\"Create a function which returns the largest index of an element which\n    is not greater than or equal to the element immediately preceding it. If\n    no such element exists then return -1. The given array will not contain\n    duplicate values.\n\n    Examples:\n    can_arrange([1,2,4,3,5]) = 3\n    can_arrange([1,2,3]) = -1\n    \"\"\"\n    # Initialize the index to -1, which will be returned if no such element is found\n    largest_index = -1\n    \n    # Iterate through the array starting from the second element\n    for i in range(1, len(arr)):\n        # Check if the current element is less than the previous element\n        if arr[i] < arr[i - 1]:\n            largest_index = i  # Update the largest index found\n    \n    return largest_index", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef sum_of_digits(n):\n    \"\"\"Return the sum of the digits of a number.\"\"\"\n    return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n    \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n    largest_prime = -1\n    \n    for number in lst:\n        if is_prime(number) and number > largest_prime:\n            largest_prime = number\n            \n    if largest_prime == -1:\n        return 0  # Return 0 if no prime is found\n    \n    return sum_of_digits(largest_prime)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n    \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n    Empty sum should be equal to 0 and empty product should be equal to 1.\n    \n    >>> sum_product([])\n    (0, 1)\n    >>> sum_product([1, 2, 3, 4])\n    (10, 24)\n    \"\"\"\n    if not numbers:\n        return (0, 1)\n    \n    total_sum = sum(numbers)\n    total_product = 1\n    for number in numbers:\n        total_product *= number\n    \n    return (total_sum, total_product)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n    '''\n    Create a function that takes a string as input which contains only square brackets.\n    The function should return True if and only if there is a valid subsequence of brackets \n    where at least one bracket in the subsequence is nested.\n\n    is_nested('[[]]') \u279e True\n    is_nested('[]]]]]]][[[[[]') \u279e False\n    is_nested('[][]') \u279e False\n    is_nested('[]') \u279e False\n    is_nested('[[][]]') \u279e True\n    is_nested('[[]][[') \u279e True\n    '''\n    # Initialize a counter for open brackets\n    open_count = 0\n    # Initialize a flag to check for nesting\n    nested = False\n    \n    for char in string:\n        if char == '[':\n            open_count += 1\n            # If we have seen at least one open bracket before, we can have nesting\n            if open_count > 1:\n                nested = True\n        elif char == ']':\n            if open_count > 0:\n                open_count -= 1\n            else:\n                # More closing brackets than opening brackets\n                return False\n    \n    # We need at least one nested bracket and all brackets must be closed\n    return nested and open_count == 0", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["[[]][["]], "plus_fail_tests": [["[[]]]"]]}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n    \"\"\"\n    You're a hungry rabbit, and you already have eaten a certain number of carrots,\n    but now you need to eat more carrots to complete the day's meals.\n    you should return an array of [ total number of eaten carrots after your meals,\n                                    the number of carrots left after your meals ]\n    if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n    \n    Example:\n    * eat(5, 6, 10) -> [11, 4]\n    * eat(4, 8, 9) -> [12, 1]\n    * eat(1, 10, 10) -> [11, 0]\n    * eat(2, 11, 5) -> [7, 0]\n    \n    Variables:\n    @number : integer\n        the number of carrots that you have eaten.\n    @need : integer\n        the number of carrots that you need to eat.\n    @remaining : integer\n        the number of remaining carrots that exist in stock\n    \n    Constrain:\n    * 0 <= number <= 1000\n    * 0 <= need <= 1000\n    * 0 <= remaining <= 1000\n\n    Have fun :)\n    \"\"\"\n    # Calculate how many more carrots are needed\n    additional_needed = need - number\n    \n    # If no additional carrots are needed, return the current state\n    if additional_needed <= 0:\n        return [number, remaining]\n    \n    # Determine how many carrots can be eaten from the remaining stock\n    eaten = min(additional_needed, remaining)\n    \n    # Calculate the total eaten and remaining carrots\n    total_eaten = number + eaten\n    remaining_after_meals = remaining - eaten\n    \n    return [total_eaten, remaining_after_meals]", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": [[2, 2, 2]]}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n    \"\"\"You are given a string s.\n    if s[i] is a letter, reverse its case from lower to upper or vise versa, \n    otherwise keep it as it is.\n    If the string contains no letters, reverse the string.\n    The function should return the resulted string.\n    \n    Examples:\n    solve(\"1234\") = \"4321\"\n    solve(\"ab\") = \"AB\"\n    solve(\"#a@C\") = \"#A@c\"\n    \"\"\"\n    # Check if there are any letters in the string\n    has_letters = any(c.isalpha() for c in s)\n    \n    if has_letters:\n        # Reverse case for letters and keep others as is\n        return ''.join(c.swapcase() if c.isalpha() else c for c in s)\n    else:\n        # Reverse the string if there are no letters\n        return s[::-1]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n    '''\n    Given the lengths of the three sides of a triangle. Return True if the three\n    sides form a right-angled triangle, False otherwise.\n    A right-angled triangle is a triangle in which one angle is right angle or \n    90 degree.\n    \n    Example:\n    right_angle_triangle(3, 4, 5) == True\n    right_angle_triangle(1, 2, 3) == False\n    '''\n    # Sort the sides to identify the longest side\n    sides = sorted([a, b, c])\n    # Check the Pythagorean theorem\n    return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(num):\n    \"\"\"Check if a number is prime.\"\"\"\n    if num <= 1:\n        return False\n    for i in range(2, int(num**0.5) + 1):\n        if num % i == 0:\n            return False\n    return True\ndef x_or_y(n, x, y):\n    \"\"\"Return the value of x if n is a prime number, otherwise return y.\"\"\"\n    if is_prime(n):\n        return x\n    else:\n        return y", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n    \"\"\"Convert a decimal number to binary format with specific formatting.\n\n    Args:\n    decimal (int): A non-negative integer to convert to binary.\n\n    Returns:\n    str: A string representing the binary format of the decimal number,\n         prefixed and suffixed with 'db'.\n    \n    Examples:\n    >>> decimal_to_binary(15)\n    'db1111db'\n    >>> decimal_to_binary(32)\n    'db100000db'\n    \"\"\"\n    if decimal < 0:\n        raise ValueError(\"Input must be a non-negative integer.\")\n    \n    # Convert decimal to binary and remove the '0b' prefix\n    binary_representation = bin(decimal)[2:]\n    \n    # Format the string with 'db' at the beginning and end\n    formatted_binary = f\"db{binary_representation}db\"\n    \n    return formatted_binary", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n    \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n    fib4(0) -> 0\n    fib4(1) -> 0\n    fib4(2) -> 2\n    fib4(3) -> 0\n    fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n    Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.\n    \n    >>> fib4(5)\n    4\n    >>> fib4(6)\n    8\n    >>> fib4(7)\n    14\n    \"\"\"\n    if n == 0:\n        return 0\n    elif n == 1:\n        return 0\n    elif n == 2:\n        return 2\n    elif n == 3:\n        return 0\n\n    # Initialize the first four values of the sequence\n    fib_values = [0, 0, 2, 0]\n\n    # Compute the values iteratively\n    for i in range(4, n + 1):\n        next_value = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n        fib_values.append(next_value)\n\n    return fib_values[n]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n    \"\"\"\n    Imagine a road that's a perfectly straight infinitely long line.\n    n cars are driving left to right; simultaneously, a different set of n cars\n    are driving right to left. The two sets of cars start out being very far from\n    each other. All cars move at the same speed. Two cars are said to collide\n    when a car that's moving left to right hits a car that's moving right to left.\n    However, the cars are infinitely sturdy and strong; as a result, they continue moving\n    in their trajectory as if they did not collide.\n\n    This function outputs the number of such collisions.\n\n    Parameters:\n    n (int): The number of cars in each direction.\n\n    Returns:\n    int: The number of collisions.\n    \"\"\"\n    # Each car moving left to right will collide with each car moving right to left\n    # Therefore, the total number of collisions is n * n\n    return n * n", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n    \"\"\"You are given two positive integers n and m, and your task is to compute the\n    average of the integers from n through m (including n and m). \n    Round the answer to the nearest integer and convert that to binary.\n    If n is greater than m, return -1.\n    \n    Example:\n    rounded_avg(1, 5) => \"0b11\"\n    rounded_avg(7, 5) => -1\n    rounded_avg(10, 20) => \"0b1111\"\n    rounded_avg(20, 33) => \"0b11010\"\n    \"\"\"\n    if n > m:\n        return -1\n    \n    # Calculate the sum of integers from n to m\n    total_sum = sum(range(n, m + 1))\n    count = m - n + 1  # Total numbers from n to m\n    \n    # Calculate the average and round it\n    average = total_sum / count\n    rounded_average = round(average)\n    \n    # Convert the rounded average to binary\n    return bin(rounded_average)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n    \"\"\"\n    Checks if given string is a palindrome.\n    \n    A palindrome is a string that reads the same forward and backward.\n    \n    >>> is_palindrome('')\n    True\n    >>> is_palindrome('aba')\n    True\n    >>> is_palindrome('aaaaa')\n    True\n    >>> is_palindrome('zbcd')\n    False\n    \"\"\"\n    # Normalize the string by removing spaces and converting to lowercase\n    normalized_text = text.replace(\" \", \"\").lower()\n    # Check if the normalized string is equal to its reverse\n    return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["never odd or even"]]}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n    '''\n    Write a function that takes an integer a and returns True \n    if this integer is a cube of some integer number.\n    Note: you may assume the input is always valid.\n    \n    Examples:\n    iscube(1) ==> True\n    iscube(2) ==> False\n    iscube(-1) ==> True\n    iscube(64) ==> True\n    iscube(0) ==> True\n    iscube(180) ==> False\n    '''\n    # Calculate the cube root of the absolute value of a\n    cube_root = round(abs(a) ** (1/3))\n    \n    # Check if the cube of the rounded cube root equals the absolute value of a\n    return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n    \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n    \n    Example\n        For N = 1000, the sum of digits will be 1 the output should be \"1\".\n        For N = 150, the sum of digits will be 6 the output should be \"110\".\n        For N = 147, the sum of digits will be 12 the output should be \"1100\".\n    \n    Variables:\n        @N integer\n             Constraints: 0 \u2264 N \u2264 10000.\n    Output:\n         a string of binary number\n    \"\"\"\n    # Calculate the sum of the digits of N\n    digit_sum = sum(int(digit) for digit in str(N))\n    \n    # Convert the sum to binary and remove the '0b' prefix\n    binary_sum = bin(digit_sum)[2:]\n    \n    return binary_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n    '''\n    Given list of integers, return list in strange order.\n    Strange sorting, is when you start with the minimum value,\n    then maximum of the remaining integers, then minimum and so on.\n\n    Examples:\n    strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n    strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n    strange_sort_list([]) == []\n    '''\n    if not lst:\n        return []\n\n    sorted_lst = sorted(lst)\n    result = []\n    left, right = 0, len(sorted_lst) - 1\n\n    while left <= right:\n        if left == right:\n            result.append(sorted_lst[left])\n        else:\n            result.append(sorted_lst[left])\n            result.append(sorted_lst[right])\n        left += 1\n        right -= 1\n\n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n    \"\"\"\n    Given a positive integer n, return the count of the numbers of n-digit\n    positive integers that start or end with 1.\n    \"\"\"\n    if n < 1:\n        return 0\n\n    # Total n-digit numbers\n    total_n_digit_numbers = 9 * (10 ** (n - 1))\n\n    # Count of n-digit numbers that start with 1\n    start_with_1 = 10 ** (n - 1)\n\n    # Count of n-digit numbers that end with 1\n    end_with_1 = total_n_digit_numbers // 10\n\n    # Count of n-digit numbers that start and end with 1\n    start_and_end_with_1 = 10 ** (n - 2) if n > 1 else 0\n\n    # Total count of numbers that start or end with 1\n    count = start_with_1 + end_with_1 - start_and_end_with_1\n\n    return count", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[1000000]]}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n    \"\"\" Return length of given string\n    >>> strlen('')\n    0\n    >>> strlen('abc')\n    3\n    \"\"\"\n    return len(string)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n    \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n    >>> largest_divisor(15)\n    5\n    >>> largest_divisor(28)\n    14\n    >>> largest_divisor(1)\n    0\n    >>> largest_divisor(10)\n    5\n    \"\"\"\n    if n <= 1:\n        return 0  # No divisors for 1 or less\n    for i in range(n // 2, 0, -1):\n        if n % i == 0:\n            return i", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n    \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n    Args:\n        lst (list): A non-empty list of integers.\n\n    Returns:\n        int: The sum of even elements at odd indices.\n\n    Examples:\n        add([4, 2, 6, 7]) ==> 2 \n    \"\"\"\n    return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n    '''\n    Given the lengths of the three sides of a triangle. Return the area of\n    the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n    Otherwise return -1.\n    Three sides make a valid triangle when the sum of any two sides is greater \n    than the third side.\n    \n    Example:\n    triangle_area(3, 4, 5) == 6.00\n    triangle_area(1, 2, 10) == -1\n    '''\n    # Check for valid triangle\n    if a + b > c and a + c > b and b + c > a:\n        # Calculate the semi-perimeter\n        s = (a + b + c) / 2\n        # Calculate the area using Heron's formula\n        area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n        return round(area, 2)\n    else:\n        return -1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n    \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n    strings of the same length. Return None in case the input list is empty.\n    \n    >>> longest([])\n    >>> None\n    >>> longest(['a', 'b', 'c'])\n    'a'\n    >>> longest(['a', 'bb', 'ccc'])\n    'ccc'\n    \"\"\"\n    if not strings:\n        return None\n    \n    longest_string = strings[0]\n    \n    for string in strings:\n        if len(string) > len(longest_string):\n            longest_string = string\n            \n    return longest_string", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n    \"\"\"Return 2^n modulo p (be aware of numerics).\n    \n    >>> modp(3, 5)\n    3\n    >>> modp(1101, 101)\n    2\n    >>> modp(0, 101)\n    1\n    >>> modp(3, 11)\n    8\n    >>> modp(100, 101)\n    1\n    \"\"\"\n    result = 1\n    base = 2 % p  # Start with 2 mod p\n    while n > 0:\n        if n % 2 == 1:  # If n is odd, multiply the base with the result\n            result = (result * base) % p\n        base = (base * base) % p  # Square the base\n        n //= 2  # Divide n by 2\n    return result", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[0, 1]]}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n    \"\"\"Helper function to check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef prime_length(string):\n    \"\"\"Check if the length of the string is a prime number.\"\"\"\n    length = len(string)\n    return is_prime(length)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n    \"\"\"Returns True if x is a simple power of n, otherwise False.\n    \n    A number x is a simple power of n if there exists an integer k such that n**k = x.\n    \n    Args:\n        x (int): The number to check.\n        n (int): The base number.\n    \n    Returns:\n        bool: True if x is a simple power of n, False otherwise.\n    \"\"\"\n    if n <= 1:\n        return x == 1  # 1 is a power of any number, and no other number can be a power of 1 or 0.\n    \n    power = 1\n    while True:\n        result = n ** power\n        if result == x:\n            return True\n        elif result > x:\n            return False\n        power += 1", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[1, 12]], "plus_fail_tests": [[1, 4]]}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n    \"\"\"\n    triples_sum_to_zero takes a list of integers as an input.\n    it returns True if there are three distinct elements in the list that\n    sum to zero, and False otherwise.\n\n    >>> triples_sum_to_zero([1, 3, 5, 0])\n    False\n    >>> triples_sum_to_zero([1, 3, -2, 1])\n    True\n    >>> triples_sum_to_zero([1, 2, 3, 7])\n    False\n    >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n    True\n    >>> triples_sum_to_zero([1])\n    False\n    \"\"\"\n    n = len(l)\n    # Sort the list to use the two-pointer technique\n    l.sort()\n    \n    for i in range(n - 2):\n        # Avoid duplicates for the first element\n        if i > 0 and l[i] == l[i - 1]:\n            continue\n        \n        left, right = i + 1, n - 1\n        while left < right:\n            current_sum = l[i] + l[left] + l[right]\n            if current_sum == 0:\n                return True\n            elif current_sum < 0:\n                left += 1\n            else:\n                right -= 1\n    \n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n    \"\"\"Counts the number of prime hexadecimal digits in the given hexadecimal string.\"\"\"\n    \n    # Define the set of prime hexadecimal digits\n    prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n    \n    # Initialize a counter for prime digits\n    count = 0\n    \n    # Iterate through each character in the input string\n    for char in num:\n        # Check if the character is in the set of prime hexadecimal digits\n        if char in prime_hex_digits:\n            count += 1\n            \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n    \"\"\"Return median of elements in the list l.\n    \n    The median is the middle value in a list of numbers. If the list has an even number of elements,\n    the median is the average of the two middle numbers.\n    \n    >>> median([3, 1, 2, 4, 5])\n    3\n    >>> median([-10, 4, 6, 1000, 10, 20])\n    15.0\n    \"\"\"\n    if not l:\n        raise ValueError(\"The list is empty\")\n    \n    sorted_list = sorted(l)\n    n = len(sorted_list)\n    mid = n // 2\n    \n    if n % 2 == 0:  # Even number of elements\n        return (sorted_list[mid - 1] + sorted_list[mid]) / 2\n    else:  # Odd number of elements\n        return sorted_list[mid]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n    \"\"\" Return the greatest common divisor of two integers a and b\n    >>> greatest_common_divisor(3, 5)\n    1\n    >>> greatest_common_divisor(25, 15)\n    5\n    \"\"\"\n    while b:\n        a, b = b, a % b\n    return abs(a)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n    \"\"\" Return list of all prefixes from shortest to longest of the input string\n    >>> all_prefixes('abc')\n    ['a', 'ab', 'abc']\n    \"\"\"\n    return [string[:i] for i in range(1, len(string) + 1)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n    \"\"\" Filter given list of any python values only for integers\n    >>> filter_integers(['a', 3.14, 5])\n    [5]\n    >>> filter_integers([1, 2, 3, 'abc', {}, []])\n    [1, 2, 3]\n    \"\"\"\n    return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[[true, false, null, 0, -10, "test", [], {}, 3.14]]]}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n    \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n    Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n    Input number should be equal to the product of all factors\n    >>> factorize(8)\n    [2, 2, 2]\n    >>> factorize(25)\n    [5, 5]\n    >>> factorize(70)\n    [2, 5, 7]\n    \"\"\"\n    factors = []\n    # Check for number of 2s that divide n\n    while n % 2 == 0:\n        factors.append(2)\n        n //= 2\n    \n    # n must be odd at this point so a skip of 2 (i.e., i = i + 2) can be used\n    for i in range(3, int(n**0.5) + 1, 2):\n        # While i divides n, append i and divide n\n        while n % i == 0:\n            factors.append(i)\n            n //= i\n    \n    # This condition is to check if n is a prime number greater than 2\n    if n > 2:\n        factors.append(n)\n    \n    return factors", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str):\n    \"\"\"\n    Takes as input a string encoded with the encode_cyclic function.\n    Returns the decoded string.\n    \"\"\"\n    # Split string into groups of length 3\n    groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n    # Reverse the cycling for each group\n    groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n    return \"\".join(groups)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n    \"\"\"Return true if a given number is prime, and false otherwise.\n    \n    >>> is_prime(6)\n    False\n    >>> is_prime(101)\n    True\n    >>> is_prime(11)\n    True\n    >>> is_prime(13441)\n    True\n    >>> is_prime(61)\n    True\n    >>> is_prime(4)\n    False\n    >>> is_prime(1)\n    False\n    \"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n    \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n    and return the result as a string.\n    If shift > number of digits, return digits reversed.\n    \n    >>> circular_shift(12, 1)\n    '21'\n    >>> circular_shift(12, 2)\n    '12'\n    >>> circular_shift(12345, 1)\n    '51234'\n    >>> circular_shift(12345, 5)\n    '54321'\n    >>> circular_shift(12345, 6)\n    '54321'\n    \"\"\"\n    # Convert the integer to a string to manipulate its digits\n    str_x = str(x)\n    num_digits = len(str_x)\n    \n    # If shift is greater than the number of digits, reverse the string\n    if shift >= num_digits:\n        return str_x[::-1]\n    \n    # Calculate the effective shift\n    effective_shift = shift % num_digits\n    \n    # Perform the circular shift\n    shifted_str = str_x[-effective_shift:] + str_x[:-effective_shift]\n    \n    return shifted_str", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[12, 2]], "plus_fail_tests": [[987654321, 9]]}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n    \"\"\"\n    You'll be given a string of words, and your task is to count the number\n    of boredoms. A boredom is a sentence that starts with the word \"I\".\n    Sentences are delimited by '.', '?' or '!'.\n   \n    For example:\n    >>> is_bored(\"Hello world\")\n    0\n    >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n    1\n    >>> is_bored(\"I am happy! Are you? I will go now.\")\n    2\n    >>> is_bored(\"What a day. I can't believe it! I am so excited.\")\n    2\n    \"\"\"\n    # Split the string into sentences using the delimiters\n    sentences = [s.strip() for s in S.replace('!', '.').replace('?', '.').split('.')]\n    \n    # Count the number of sentences that start with \"I\"\n    boredom_count = sum(1 for sentence in sentences if sentence.startswith(\"I\"))\n    \n    return boredom_count", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": [["In the morning, I like to have a cup of coffee to start my day off right. How about you?"]]}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n    \"\"\" \n    xs represent coefficients of a polynomial.\n    xs[0] + xs[1] * x + xs[2] * x^2 + ....\n    Return derivative of this polynomial in the same form.\n    \n    >>> derivative([3, 1, 2, 4, 5])\n    [1, 4, 12, 20]\n    >>> derivative([1, 2, 3])\n    [2, 6]\n    \"\"\"\n    # The derivative of a polynomial is calculated by multiplying each coefficient\n    # by its corresponding power and reducing the power by one.\n    return [i * coeff for i, coeff in enumerate(xs[1:], start=1)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n    \"\"\"Check if a number is prime.\"\"\"\n    if num <= 1:\n        return False\n    for i in range(2, int(num**0.5) + 1):\n        if num % i == 0:\n            return False\n    return True\ndef count_up_to(n):\n    \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n    primes = []\n    for i in range(2, n):\n        if is_prime(i):\n            primes.append(i)\n    return primes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n    \"\"\"\n    Check if two words have the same characters.\n    \n    Two words have the same characters if they contain the same unique characters,\n    regardless of the number of times each character appears.\n\n    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n    True\n    >>> same_chars('abcd', 'dddddddabc')\n    True\n    >>> same_chars('dddddddabc', 'abcd')\n    True\n    >>> same_chars('eabcd', 'dddddddabc')\n    False\n    >>> same_chars('abcd', 'dddddddabce')\n    False\n    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n    False\n    \"\"\"\n    return set(s0) == set(s1)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n    \"\"\"Add two numbers x and y.\n    \n    >>> add(2, 3)\n    5\n    >>> add(5, 7)\n    12\n    \"\"\"\n    return x + y", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n    \"\"\"\n    Given a string s, count the number of uppercase vowels in even indices.\n    \n    For example:\n    count_upper('aBCdEf') returns 1\n    count_upper('abcdefg') returns 0\n    count_upper('dBBE') returns 0\n    \"\"\"\n    uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n    count = 0\n    \n    for i in range(0, len(s), 2):  # Iterate over even indices\n        if s[i] in uppercase_vowels:\n            count += 1\n            \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n    \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n    \n    >>> fizz_buzz(50)\n    0\n    >>> fizz_buzz(78)\n    2\n    >>> fizz_buzz(79)\n    3\n    \"\"\"\n    count_of_sevens = 0\n    \n    for i in range(n):\n        if i % 11 == 0 or i % 13 == 0:\n            count_of_sevens += str(i).count('7')\n    \n    return count_of_sevens", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n    \"\"\"Return only positive numbers in the list.\n    >>> get_positive([-1, 2, -4, 5, 6])\n    [2, 5, 6]\n    >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n    [5, 3, 2, 3, 9, 123, 1]\n    \"\"\"\n    return [x for x in l if x > 0]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n    \"\"\"This function takes a list l and returns a list l' such that\n    l' is identical to l in the odd indices, while its values at the even indices are equal\n    to the values of the even indices of l, but sorted.\n    \n    >>> sort_even([1, 2, 3])\n    [1, 2, 3]\n    >>> sort_even([5, 6, 3, 4])\n    [3, 6, 5, 4]\n    \"\"\"\n    # Extract even indexed elements\n    even_indices = [l[i] for i in range(0, len(l), 2)]\n    \n    # Sort the even indexed elements\n    even_indices.sort()\n    \n    # Create a new list to hold the result\n    result = l[:]  # Start with a copy of the original list\n    \n    # Place the sorted even indexed elements back into their positions\n    for i, value in enumerate(even_indices):\n        result[i * 2] = value\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n    \"\"\"Check if a number is prime.\"\"\"\n    if num <= 1:\n        return False\n    if num <= 3:\n        return True\n    if num % 2 == 0 or num % 3 == 0:\n        return False\n    i = 5\n    while i * i <= num:\n        if num % i == 0 or num % (i + 2) == 0:\n            return False\n        i += 6\n    return True\ndef prime_fib(n: int) -> int:\n    \"\"\"\n    prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n    >>> prime_fib(1)\n    2\n    >>> prime_fib(2)\n    3\n    >>> prime_fib(3)\n    5\n    >>> prime_fib(4)\n    13\n    >>> prime_fib(5)\n    89\n    \"\"\"\n    count = 0\n    for fib in fibonacci_generator():\n        if is_prime(fib):\n            count += 1\n            if count == n:\n                return fib", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[1]], "plus_fail_tests": [[11]]}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n    \"\"\"Return True if all numbers in the list l are below threshold t.\n    \n    >>> below_threshold([1, 2, 4, 10], 100)\n    True\n    >>> below_threshold([1, 20, 4, 10], 5)\n    False\n    \"\"\"\n    return all(x < t for x in l)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n    '''\n    Create a function that takes a value (string) representing a number\n    and returns the closest integer to it. If the number is equidistant\n    from two integers, round it away from zero.\n\n    Examples\n    >>> closest_integer(\"10\")\n    10\n    >>> closest_integer(\"15.3\")\n    15\n    >>> closest_integer(\"14.5\")\n    15\n    >>> closest_integer(\"-14.5\")\n    -15\n    >>> closest_integer(\"0.5\")\n    1\n    >>> closest_integer(\"-0.5\")\n    -1\n    '''\n    # Convert the string to a float\n    num = float(value)\n    \n    # Get the floor and ceiling of the number\n    lower = int(num // 1)\n    upper = lower + 1\n    \n    # Check the distance to the lower and upper integers\n    if abs(num - lower) < abs(num - upper):\n        return lower\n    elif abs(num - lower) > abs(num - upper):\n        return upper\n    else:\n        # If equidistant, round away from zero\n        if num > 0:\n            return upper\n        else:\n            return lower", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000"]]}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n    \"\"\"Return n-th Fibonacci number.\n    \n    The Fibonacci sequence is defined as follows:\n    fib(0) = 0, fib(1) = 1, and fib(n) = fib(n-1) + fib(n-2) for n > 1.\n    \n    >>> fib(10)\n    55\n    >>> fib(1)\n    1\n    >>> fib(8)\n    21\n    \"\"\"\n    if n < 0:\n        raise ValueError(\"Input should be a non-negative integer.\")\n    elif n == 0:\n        return 0\n    elif n == 1:\n        return 1\n    else:\n        a, b = 0, 1\n        for _ in range(2, n + 1):\n            a, b = b, a + b\n        return b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n    \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n    fibfib(0) == 0\n    fibfib(1) == 0\n    fibfib(2) == 1\n    fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n    \n    Args:\n        n (int): The index of the FibFib number to compute.\n        \n    Returns:\n        int: The n-th FibFib number.\n    \n    Examples:\n        >>> fibfib(1)\n        0\n        >>> fibfib(5)\n        4\n        >>> fibfib(8)\n        24\n    \"\"\"\n    if n == 0:\n        return 0\n    elif n == 1:\n        return 0\n    elif n == 2:\n        return 1\n    \n    # Initialize the first three FibFib numbers\n    fibfib_numbers = [0, 0, 1]\n    \n    # Compute the FibFib numbers iteratively\n    for i in range(3, n + 1):\n        next_fibfib = fibfib_numbers[i - 1] + fibfib_numbers[i - 2] + fibfib_numbers[i - 3]\n        fibfib_numbers.append(next_fibfib)\n    \n    return fibfib_numbers[n]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n    \"\"\"Complete the function that takes two integers and returns \n    the product of their unit digits.\n    Assume the input is always valid.\n    Examples:\n    multiply(148, 412) should return 16.\n    multiply(19, 28) should return 72.\n    multiply(2020, 1851) should return 0.\n    multiply(14,-15) should return 20.\n    \"\"\"\n    # Get the unit digit of the first number\n    unit_digit_a = abs(a) % 10\n    # Get the unit digit of the second number\n    unit_digit_b = abs(b) % 10\n    # Return the product of the unit digits\n    return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n    \"\"\"\n    You are given a list of integers.\n    Write a function next_smallest() that returns the 2nd smallest element of the list.\n    Return None if there is no such element.\n    \n    next_smallest([1, 2, 3, 4, 5]) == 2\n    next_smallest([5, 1, 4, 3, 2]) == 2\n    next_smallest([]) == None\n    next_smallest([1, 1]) == None\n    \"\"\"\n    # Remove duplicates by converting the list to a set\n    unique_elements = set(lst)\n    \n    # If there are less than 2 unique elements, return None\n    if len(unique_elements) < 2:\n        return None\n    \n    # Sort the unique elements\n    sorted_elements = sorted(unique_elements)\n    \n    # Return the second smallest element\n    return sorted_elements[1]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n    \"\"\"Write a function vowels_count which takes a string representing\n    a word as input and returns the number of vowels in the string.\n    Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n    vowel, but only when it is at the end of the given word.\n\n    Example:\n    >>> vowels_count(\"abcde\")\n    2\n    >>> vowels_count(\"ACEDY\")\n    3\n    \"\"\"\n    vowels = 'aeiou'\n    count = 0\n    s = s.lower()  # Convert to lowercase to handle case insensitivity\n\n    for i in range(len(s)):\n        if s[i] in vowels:\n            count += 1\n        elif s[i] == 'y' and i == len(s) - 1:  # Check if 'y' is at the end\n            count += 1\n\n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef words_in_sentence(sentence):\n    \"\"\"\n    You are given a string representing a sentence,\n    the sentence contains some words separated by a space,\n    and you have to return a string that contains the words from the original sentence,\n    whose lengths are prime numbers,\n    the order of the words in the new string should be the same as the original one.\n\n    Example 1:\n        Input: sentence = \"This is a test\"\n        Output: \"is\"\n\n    Example 2:\n        Input: sentence = \"lets go for swimming\"\n        Output: \"go for\"\n\n    Constraints:\n        * 1 <= len(sentence) <= 100\n        * sentence contains only letters\n    \"\"\"\n    words = sentence.split()\n    prime_length_words = [word for word in words if is_prime(len(word))]\n    return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n    \"\"\"Simplifies the expression x * n and checks if the result is a whole number.\n    \n    Args:\n        x (str): A string representation of a fraction in the format <numerator>/<denominator>.\n        n (str): A string representation of a fraction in the format <numerator>/<denominator>.\n    \n    Returns:\n        bool: True if x * n evaluates to a whole number, False otherwise.\n    \"\"\"\n    # Split the fractions into numerator and denominator\n    x_numerator, x_denominator = map(int, x.split('/'))\n    n_numerator, n_denominator = map(int, n.split('/'))\n    \n    # Calculate the product of the fractions\n    # x * n = (x_numerator / x_denominator) * (n_numerator / n_denominator)\n    # This simplifies to (x_numerator * n_numerator) / (x_denominator * n_denominator)\n    numerator_product = x_numerator * n_numerator\n    denominator_product = x_denominator * n_denominator\n    \n    # Check if the result is a whole number\n    return numerator_product % denominator_product == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n    \"\"\"In this problem, you will implement a function that takes two lists of numbers,\n    and determines whether it is possible to perform an exchange of elements\n    between them to make lst1 a list of only even numbers.\n    There is no limit on the number of exchanged elements between lst1 and lst2.\n    If it is possible to exchange elements between the lst1 and lst2 to make\n    all the elements of lst1 to be even, return \"YES\".\n    Otherwise, return \"NO\".\n    For example:\n    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"YES\"\n    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n    It is assumed that the input lists will be non-empty.\n    \"\"\"\n    \n    # Check if all elements in lst1 are even\n    if all(x % 2 == 0 for x in lst1):\n        return \"YES\"\n    \n    # Count the number of odd elements in lst1\n    odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n    \n    # Count the number of even elements in lst2\n    even_count_lst2 = sum(1 for x in lst2 if x % 2 == 0)\n    \n    # If there are enough even numbers in lst2 to replace all odd numbers in lst1\n    if odd_count_lst1 <= even_count_lst2:\n        return \"YES\"\n    \n    return \"NO\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n    \"\"\"\n    You are given an array arr of integers and you need to return\n    sum of magnitudes of integers multiplied by product of all signs\n    of each number in the array, represented by 1, -1 or 0.\n    Note: return None for empty arr.\n\n    Example:\n    >>> prod_signs([1, 2, 2, -4]) == -9\n    >>> prod_signs([0, 1]) == 0\n    >>> prod_signs([]) == None\n    \"\"\"\n    if not arr:\n        return None\n\n    product_of_signs = 1\n    sum_of_magnitudes = 0\n\n    for num in arr:\n        if num > 0:\n            sum_of_magnitudes += num\n        elif num < 0:\n            sum_of_magnitudes += -num\n            product_of_signs *= -1\n        else:  # num == 0\n            return 0  # If there's a zero, the product of signs is 0\n\n    return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n    \"\"\"Given a string s and a natural number n, returns a list of all words from \n    string s that contain exactly n consonants, in the order they appear in the string s.\n    \n    Args:\n    s (str): The input string containing words.\n    n (int): The number of consonants to match.\n    \n    Returns:\n    list: A list of words containing exactly n consonants.\n    \"\"\"\n    if not s:\n        return []\n\n    # Define a set of consonants\n    consonants = set(\"bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ\")\n    \n    # Split the string into words\n    words = s.split()\n    \n    # Function to count consonants in a word\n    def count_consonants(word):\n        return sum(1 for char in word if char in consonants)\n    \n    # Select words with exactly n consonants\n    result = [word for word in words if count_consonants(word) == n]\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n    \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n    \n    Examples\n    solution([5, 8, 7, 1]) ==> 12\n    solution([3, 3, 3, 3, 3]) ==> 9\n    solution([30, 13, 24, 321]) ==> 0\n    \"\"\"\n    return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n    '''\n    You are given a list of two strings, both strings consist of open\n    parentheses '(' or close parentheses ')' only.\n    Your job is to check if it is possible to concatenate the two strings in\n    some order, that the resulting string will be good.\n    A string S is considered to be good if and only if all parentheses in S\n    are balanced. For example: the string '(())()' is good, while the string\n    '())' is not.\n    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n    Examples:\n    match_parens(['()(', ')']) == 'Yes'\n    match_parens([')', ')']) == 'No'\n    '''\n\n    def is_good(s):\n        balance = 0\n        for char in s:\n            if char == '(':\n                balance += 1\n            else:\n                balance -= 1\n            if balance < 0:\n                return False\n        return balance == 0\n\n    # Check both concatenation orders\n    return 'Yes' if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]) else 'No'", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n    '''\n    Given a list of numbers, return whether or not they are sorted\n    in ascending order. If list has more than 1 duplicate of the same\n    number, return False. Assume no negative numbers and only integers.\n\n    Examples\n    is_sorted([5]) \u279e True\n    is_sorted([1, 2, 3, 4, 5]) \u279e True\n    is_sorted([1, 3, 2, 4, 5]) \u279e False\n    is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n    is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n    is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n    is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n    is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n    '''\n    if not lst:  # An empty list is considered sorted\n        return True\n\n    seen = set()\n    last = None\n\n    for num in lst:\n        if num in seen:\n            # If we see a number again, check if it's a duplicate\n            if num == last:\n                return False\n            else:\n                seen.add(num)\n        else:\n            seen.add(num)\n\n        if last is not None and num < last:\n            return False\n        \n        last = num\n\n    return True", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": [[[1, 1, 2, 2, 3, 3, 4]]]}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n    \"\"\"\n    Write a function which sorts the given list of integers\n    in ascending order according to the sum of their digits.\n    Note: if there are several items with similar sum of their digits,\n    order them based on their index in original list.\n\n    For example:\n    >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n    >>> order_by_points([]) == []\n    \"\"\"\n    \n    def digit_sum(n):\n        \"\"\"Calculate the sum of the digits of n.\"\"\"\n        return sum(int(digit) for digit in str(abs(n)))\n\n    # Sort the list based on the sum of digits and original index\n    return sorted(nums, key=lambda x: (digit_sum(x), nums.index(x)))", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": [[[-5, -12, 9, 15]]]}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n    \"\"\"\n    This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n    multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n    change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n    \n    Examples:\n    For lst = [1,2,3] the output should be 6\n    For lst = []  the output should be 0\n    For lst = [-1,-5,2,-1,-5]  the output should be -126\n    \"\"\"\n    total = 0\n    for index, value in enumerate(lst):\n        if index % 3 == 0:\n            total += value ** 2  # Square if index is a multiple of 3\n        elif index % 4 == 0:\n            total += value ** 3  # Cube if index is a multiple of 4 and not a multiple of 3\n        else:\n            total += value  # Leave unchanged if not a multiple of 3 or 4\n    return total", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n    \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n    two consonants from the right side of the word (case sensitive).\n    \n    Vowels in the beginning and ending don't count. Return empty string if you didn't\n    find any vowel that meets the above condition. \n\n    You may assume that the given string contains English letters only.\n\n    Example:\n    get_closest_vowel(\"yogurt\") ==> \"u\"\n    get_closest_vowel(\"FULL\") ==> \"U\"\n    get_closest_vowel(\"quick\") ==> \"\"\n    get_closest_vowel(\"ab\") ==> \"\"\n    \"\"\"\n    vowels = \"aeiouAEIOU\"\n    n = len(word)\n\n    # Start from the end of the word\n    for i in range(n - 2, 0, -1):  # Start from the second last character\n        if word[i] in vowels:  # Check if the character is a vowel\n            # Check if there are consonants on both sides\n            if word[i - 1].isalpha() and word[i + 1].isalpha() and \\\n               word[i - 1] not in vowels and word[i + 1] not in vowels:\n                return word[i]  # Return the vowel if conditions are met\n\n    return \"\"  # Return empty string if no valid vowel is found", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n    \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n    \n    >>> string_sequence(0)\n    '0'\n    >>> string_sequence(5)\n    '0 1 2 3 4 5'\n    \"\"\"\n    return ' '.join(str(i) for i in range(n + 1))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n    \"\"\"\n    Given an array arr of integers and a positive integer k, return a sorted list \n    of length k with the maximum k numbers in arr.\n\n    Example 1:\n        Input: arr = [-3, -4, 5], k = 3\n        Output: [-4, -3, 5]\n\n    Example 2:\n        Input: arr = [4, -4, 4], k = 2\n        Output: [4, 4]\n\n    Example 3:\n        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n        Output: [2]\n\n    Note:\n        1. The length of the array will be in the range of [1, 1000].\n        2. The elements in the array will be in the range of [-1000, 1000].\n        3. 0 <= k <= len(arr)\n    \"\"\"\n    # Sort the array in descending order\n    sorted_arr = sorted(arr, reverse=True)\n    # Get the top k elements\n    top_k = sorted_arr[:k]\n    # Sort the result in ascending order before returning\n    return sorted(top_k)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef intersection(interval1, interval2):\n    \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n    start1, end1 = interval1\n    start2, end2 = interval2\n    \n    # Find the intersection\n    start_intersection = max(start1, start2)\n    end_intersection = min(end1, end2)\n    \n    # Check if there is an intersection\n    if start_intersection > end_intersection:\n        return \"NO\"\n    \n    # Calculate the length of the intersection\n    length_of_intersection = end_intersection - start_intersection\n    \n    # Check if the length is a prime number\n    if is_prime(length_of_intersection):\n        return \"YES\"\n    else:\n        return \"NO\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n    \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n    of the letter with the most repetition and containing the corresponding count.\n    If several letters have the same occurrence, return all of them.\n    \n    Example:\n    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n    histogram('a b b a') == {'a': 2, 'b': 2}\n    histogram('a b c a b') == {'a': 2, 'b': 2}\n    histogram('b b b b a') == {'b': 4}\n    histogram('') == {}\n    \"\"\"\n    if not test:\n        return {}\n\n    # Split the input string into a list of letters\n    letters = test.split()\n    \n    # Create a dictionary to count occurrences of each letter\n    count_dict = {}\n    for letter in letters:\n        if letter in count_dict:\n            count_dict[letter] += 1\n        else:\n            count_dict[letter] = 1\n\n    # Find the maximum count\n    max_count = max(count_dict.values())\n    \n    # Create a result dictionary for letters with the maximum count\n    result = {letter: count for letter, count in count_dict.items() if count == max_count}\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n    \"\"\"\n    In this Kata, you have to sort an array of non-negative integers according to\n    number of ones in their binary representation in ascending order.\n    For similar number of ones, sort based on decimal value.\n\n    It must be implemented like this:\n    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n    >>> sort_array([1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]\n    \"\"\"\n    # Sort the array using a custom key\n    return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n    from collections import deque\n\n    N = len(grid)\n    directions = [(0, 1), (1, 0), (0, -1), (-1, 0)]  # right, down, left, up\n    min_path = None\n\n    def dfs(x, y, path):\n        nonlocal min_path\n        if len(path) == k:\n            if min_path is None or path < min_path:\n                min_path = path[:]\n            return\n        \n        for dx, dy in directions:\n            nx, ny = x + dx, y + dy\n            if 0 <= nx < N and 0 <= ny < N:\n                path.append(grid[nx][ny])\n                dfs(nx, ny, path)\n                path.pop()\n\n    for i in range(N):\n        for j in range(N):\n            dfs(i, j, [grid[i][j]])\n\n    return min_path", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": [[[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 15]]}]}}
\ No newline at end of file
diff --git a/EVALPLUS-4omini/2.json b/EVALPLUS-4omini/2.json
deleted file mode 100644
index 409aa9855..000000000
--- a/EVALPLUS-4omini/2.json
+++ /dev/null
@@ -1 +0,0 @@
-{"date": "2024-07-20 12:59", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n    \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n    Example:\n        even_odd_count(-12) ==> (1, 1)\n        even_odd_count(123) ==> (1, 2)\n    \"\"\"\n    # Convert the number to a string and remove the negative sign if present\n    num_str = str(abs(num))\n    \n    even_count = 0\n    odd_count = 0\n    \n    # Iterate through each character in the string representation of the number\n    for digit in num_str:\n        if digit.isdigit():  # Check if the character is a digit\n            if int(digit) % 2 == 0:\n                even_count += 1\n            else:\n                odd_count += 1\n    \n    return (even_count, odd_count)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def compare_one(a, b):\n    \"\"\"\n    Create a function that takes integers, floats, or strings representing\n    real numbers, and returns the larger variable in its given variable type.\n    Return None if the values are equal.\n    Note: If a real number is represented as a string, the floating point might be . or ,\n\n    compare_one(1, 2.5) \u279e 2.5\n    compare_one(1, \"2,3\") \u279e \"2,3\"\n    compare_one(\"5,1\", \"6\") \u279e \"6\"\n    compare_one(\"1\", 1) \u279e None\n    \"\"\"\n    \n    def parse_value(value):\n        \"\"\"Convert the input value to a float or return it as is if it's not a number.\"\"\"\n        if isinstance(value, str):\n            # Replace comma with dot for float conversion\n            value = value.replace(',', '.')\n            try:\n                return float(value)\n            except ValueError:\n                return value  # Return the string if it cannot be converted\n        return value  # Return the number as is\n\n    # Parse both values\n    parsed_a = parse_value(a)\n    parsed_b = parse_value(b)\n\n    # Check for equality\n    if parsed_a == parsed_b:\n        return None\n\n    # Return the larger value, preserving the original type\n    if parsed_a > parsed_b:\n        return a\n    else:\n        return b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n    \"\"\"\n    Given two positive integers a and b, return the even digits between a\n    and b, in ascending order.\n\n    For example:\n    generate_integers(2, 8) => [2, 4, 6, 8]\n    generate_integers(8, 2) => [2, 4, 6, 8]\n    generate_integers(10, 14) => []\n    \"\"\"\n    # Determine the range of numbers to consider\n    start = min(a, b)\n    end = max(a, b)\n\n    # Generate a list of even integers in the specified range\n    even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n    return even_integers", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[2, 10]], "plus_fail_tests": [[6, 12]]}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n    \"\"\"Compares the actual game scores with the guessed scores and returns the absolute differences.\n    \n    Args:\n        game (list of int): The actual scores of the matches.\n        guess (list of int): The guessed scores of the matches.\n        \n    Returns:\n        list of int: A list containing the absolute differences between the actual scores and the guessed scores.\n                      If the guess is correct, the difference is 0.\n                      \n    Example:\n        compare([1,2,3,4,5,1],[1,2,3,4,2,-2]) -> [0,0,0,0,3,3]\n        compare([0,5,0,0,0,4],[4,1,1,0,0,-2]) -> [4,4,1,0,0,6]\n    \"\"\"\n    return [abs(g - s) for g, s in zip(guess, game)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n    \"\"\"\n    Write a function count_nums which takes an array of integers and returns\n    the number of elements which has a sum of digits > 0.\n    If a number is negative, then its first signed digit will be negative:\n    e.g. -123 has signed digits -1, 2, and 3.\n    \n    >>> count_nums([]) == 0\n    >>> count_nums([-1, 11, -11]) == 1\n    >>> count_nums([1, 1, 2]) == 3\n    \"\"\"\n    def sum_of_digits(n):\n        # Convert the number to string and calculate the sum of its digits\n        return sum(int(digit) if i > 0 else -int(digit) for i, digit in enumerate(str(n)) if digit.isdigit() or (i == 0 and n < 0))\n\n    count = 0\n    for number in arr:\n        if sum_of_digits(number) > 0:\n            count += 1\n            \n    return count", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[-1, -2, 0]]], "plus_fail_tests": [[[-1, 0, 1]]]}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def factorial(i):\n    \"\"\"Calculate the factorial of a given number i.\"\"\"\n    if i == 0 or i == 1:\n        return 1\n    result = 1\n    for j in range(2, i + 1):\n        result *= j\n    return result\ndef sum_of_numbers(i):\n    \"\"\"Calculate the sum of numbers from 1 to i.\"\"\"\n    return (i * (i + 1)) // 2\ndef f(n):\n    \"\"\"Return a list of size n, where the value at index i is the factorial of i if i is even,\n    or the sum of numbers from 1 to i otherwise. Indexing starts from 1.\"\"\"\n    result = []\n    for i in range(1, n + 1):\n        if i % 2 == 0:  # i is even\n            result.append(factorial(i))\n        else:  # i is odd\n            result.append(sum_of_numbers(i))\n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n    \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n    around the mean of this dataset.\n    Mean Absolute Deviation is the average absolute difference between each\n    element and a centerpoint (mean in this case):\n    MAD = average | x - x_mean |\n    \n    >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n    1.0\n    \"\"\"\n    if not numbers:\n        return 0.0  # Return 0 for empty list to avoid division by zero\n\n    mean_value = sum(numbers) / len(numbers)\n    mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n    return mad", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n    \"\"\" \n    You're given a list of deposit and withdrawal operations on a bank account that starts with\n    zero balance. Your task is to detect if at any point the balance of account falls below zero, and\n    at that point function should return True. Otherwise it should return False.\n    \n    >>> below_zero([1, 2, 3])\n    False\n    >>> below_zero([1, 2, -4, 5])\n    True\n    \"\"\"\n    balance = 0\n    for operation in operations:\n        balance += operation\n        if balance < 0:\n            return True\n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n    \"\"\"\n    You will be given a string of words separated by commas or spaces. Your task is\n    to split the string into words and return an array of the words.\n    \n    For example:\n    words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n    words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n    \"\"\"\n    # Split the string by commas and spaces, then strip any extra whitespace\n    words = [word.strip() for word in s.replace(',', ' ').split()]\n    return words", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n    \"\"\"Find the strongest extension based on the defined strength criteria.\"\"\"\n    strongest_extension = None\n    max_strength = float('-inf')  # Start with the lowest possible strength\n\n    for extension in extensions:\n        # Calculate the strength of the current extension\n        CAP = sum(1 for char in extension if char.isupper())\n        SM = sum(1 for char in extension if char.islower())\n        strength = CAP - SM\n\n        # Check if this extension is stronger than the current strongest\n        if strength > max_strength:\n            max_strength = strength\n            strongest_extension = extension\n\n    # Return the result in the specified format\n    return f\"{class_name}.{strongest_extension}\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n    \"\"\"\n    Given a string 'text', return its md5 hash equivalent string.\n    If 'text' is an empty string, return None.\n\n    >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n    >>> string_to_md5('') is None\n    >>> string_to_md5('Python') == '5d41402abc4b2a76b9719d911017c592'\n    \"\"\"\n    if text == \"\":\n        return None\n    md5_hash = hashlib.md5(text.encode()).hexdigest()\n    return md5_hash", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n    \"\"\"Check if the second word or any of its rotations is a substring in the first word.\n    \n    Args:\n    a (str): The first word.\n    b (str): The second word.\n    \n    Returns:\n    bool: True if the second word or any of its rotations is a substring of the first word, False otherwise.\n    \n    Examples:\n    >>> cycpattern_check(\"abcd\", \"abd\")\n    False\n    >>> cycpattern_check(\"hello\", \"ell\")\n    True\n    >>> cycpattern_check(\"whassup\", \"psus\")\n    False\n    >>> cycpattern_check(\"abab\", \"baa\")\n    True\n    >>> cycpattern_check(\"efef\", \"eeff\")\n    False\n    >>> cycpattern_check(\"himenss\", \"simen\")\n    True\n    \"\"\"\n    # Create a string that contains all rotations of b\n    rotations = [b[i:] + b[:i] for i in range(len(b))]\n    \n    # Check if any rotation is a substring of a\n    for rotation in rotations:\n        if rotation in a:\n            return True\n            \n    return False", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["", ""]]}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n    \"\"\" Given a positive floating point number, it can be decomposed into\n    an integer part (largest integer smaller than given number) and decimals\n    (leftover part always smaller than 1).\n\n    Return the decimal part of the number.\n    \n    >>> truncate_number(3.5)\n    0.5\n    >>> truncate_number(7.25)\n    0.25\n    >>> truncate_number(10.0)\n    0.0\n    >>> truncate_number(5.99)\n    0.99\n    \"\"\"\n    if number < 0:\n        raise ValueError(\"The number must be positive.\")\n    \n    integer_part = int(number)  # Get the integer part\n    decimal_part = number - integer_part  # Calculate the decimal part\n    return decimal_part", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n    \"\"\"\n    Given a positive integer n, you have to make a pile of n levels of stones.\n    The first level has n stones.\n    The number of stones in the next level is:\n        - the next odd number if n is odd.\n        - the next even number if n is even.\n    Return the number of stones in each level in a list, where element at index\n    i represents the number of stones in the level (i+1).\n\n    Examples:\n    >>> make_a_pile(3)\n    [3, 5, 7]\n    >>> make_a_pile(4)\n    [4, 6, 8, 10]\n    >>> make_a_pile(1)\n    [1]\n    \"\"\"\n    stones = []\n    current_stones = n\n    \n    for i in range(n):\n        stones.append(current_stones)\n        if current_stones % 2 == 0:  # current_stones is even\n            current_stones += 2  # next even number\n        else:  # current_stones is odd\n            current_stones += 2  # next odd number\n    \n    return stones", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n    \"\"\"Calculate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n    if n < 0:\n        return []\n\n    # Initialize the list to store the Tribonacci numbers\n    tribonacci_sequence = []\n\n    # Define the base cases\n    for i in range(n + 1):\n        if i == 0:\n            tribonacci_sequence.append(1)  # tri(0) = 1\n        elif i == 1:\n            tribonacci_sequence.append(3)  # tri(1) = 3\n        elif i % 2 == 0:  # Even case\n            tribonacci_sequence.append(1 + i / 2)\n        else:  # Odd case\n            tri_n_minus_1 = tribonacci_sequence[i - 1]\n            tri_n_minus_2 = tribonacci_sequence[i - 2]\n            tri_n_plus_1 = tribonacci_sequence[i + 1] if i + 1 <= n else 0\n            tribonacci_sequence.append(tri_n_minus_1 + tri_n_minus_2 + tri_n_plus_1)\n\n    return tribonacci_sequence", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[3]], "plus_fail_tests": [[10]]}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n    \"\"\"\n    Given a positive integer n, return a tuple that has the number of even and odd\n    integer palindromes that fall within the range(1, n), inclusive.\n\n    Example 1:\n        Input: 3\n        Output: (1, 2)\n        Explanation:\n        Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n    Example 2:\n        Input: 12\n        Output: (4, 6)\n        Explanation:\n        Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n    Note:\n        1. 1 <= n <= 10^3\n        2. returned tuple has the number of even and odd integer palindromes respectively.\n    \"\"\"\n    even_count = 0\n    odd_count = 0\n\n    for i in range(1, n + 1):\n        if str(i) == str(i)[::-1]:  # Check if the number is a palindrome\n            if i % 2 == 0:\n                even_count += 1\n            else:\n                odd_count += 1\n\n    return (even_count, odd_count)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n    \"\"\" Insert a number 'delimiter' between every two consecutive elements of input list `numbers`\n    \n    >>> intersperse([], 4)\n    []\n    >>> intersperse([1, 2, 3], 4)\n    [1, 4, 2, 4, 3]\n    \"\"\"\n    if not numbers:\n        return []\n    \n    result = []\n    for i in range(len(numbers) - 1):\n        result.append(numbers[i])\n        result.append(delimiter)\n    result.append(numbers[-1])  # Append the last element\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n    \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n    \n    Args:\n        n (int): The number to evaluate.\n        \n    Returns:\n        bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n    \n    Example:\n    is_equal_to_sum_even(4) == False\n    is_equal_to_sum_even(6) == False\n    is_equal_to_sum_even(8) == True\n    \"\"\"\n    # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n    if n < 8:\n        return False\n    \n    # Check if n is even\n    if n % 2 != 0:\n        return False\n    \n    # If n is even and >= 8, it can be expressed as the sum of 4 positive even numbers\n    return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n    \"\"\"Given a positive integer n, return the product of the odd digits.\n    Return 0 if all digits are even.\n    For example:\n    digits(1)  == 1\n    digits(4)  == 0\n    digits(235) == 15\n    \"\"\"\n    product = 1\n    has_odd = False\n    \n    for digit in str(n):\n        digit = int(digit)\n        if digit % 2 != 0:  # Check if the digit is odd\n            product *= digit\n            has_odd = True\n            \n    return product if has_odd else 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n    \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n    numbers in the array will be randomly ordered. Your task is to determine if\n    it is possible to get an array sorted in non-decreasing order by performing \n    the following operation on the given array:\n        You are allowed to perform right shift operation any number of times.\n    \n    One right shift operation means shifting all elements of the array by one\n    position in the right direction. The last element of the array will be moved to\n    the starting position in the array i.e. 0th index. \n\n    If it is possible to obtain the sorted array by performing the above operation\n    then return True else return False.\n    If the given array is empty then return True.\n\n    Note: The given list is guaranteed to have unique elements.\n\n    For Example:\n    \n    move_one_ball([3, 4, 5, 1, 2])==>True\n    Explanation: By performing 2 right shift operations, non-decreasing order can\n                 be achieved for the given array.\n    move_one_ball([3, 5, 4, 1, 2])==>False\n    Explanation: It is not possible to get non-decreasing order for the given\n                array by performing any number of right shift operations.\n    \"\"\"\n    if not arr:\n        return True\n\n    n = len(arr)\n    sorted_arr = sorted(arr)\n    \n    # Check for the number of \"breaks\" in the sorted array\n    break_count = 0\n    for i in range(n):\n        if arr[i] > arr[(i + 1) % n]:\n            break_count += 1\n\n    # If there are more than one break, we cannot sort the array with shifts\n    return break_count <= 1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n    '''\n    Create a function that returns a tuple (a, b), where 'a' is\n    the largest of negative integers, and 'b' is the smallest\n    of positive integers in a list.\n    If there is no negative or positive integers, return them as None.\n\n    Examples:\n    largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n    largest_smallest_integers([]) == (None, None)\n    largest_smallest_integers([0]) == (None, None)\n    '''\n    largest_negative = None\n    smallest_positive = None\n\n    for num in lst:\n        if num < 0:\n            if largest_negative is None or num > largest_negative:\n                largest_negative = num\n        elif num > 0:\n            if smallest_positive is None or num < smallest_positive:\n                smallest_positive = num\n\n    return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n    \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n    other and return them in order (smaller number, larger number).\n    \n    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n    (2.0, 2.2)\n    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n    (2.0, 2.0)\n    \"\"\"\n    # Sort the numbers to make it easier to find the closest pair\n    sorted_numbers = sorted(numbers)\n    \n    # Initialize the minimum difference and the closest pair\n    min_diff = float('inf')\n    closest_pair = (0.0, 0.0)\n    \n    # Iterate through the sorted list to find the closest elements\n    for i in range(len(sorted_numbers) - 1):\n        diff = sorted_numbers[i + 1] - sorted_numbers[i]\n        if diff < min_diff:\n            min_diff = diff\n            closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n    \n    return closest_pair", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n    \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n    \n    >>> flip_case('Hello')\n    'hELLO'\n    >>> flip_case('Python')\n    'pYTHON'\n    >>> flip_case('123abcXYZ')\n    '123ABCxyz'\n    >>> flip_case('')\n    ''\n    \"\"\"\n    return string.swapcase()", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n    \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n    \n    >>> how_many_times('', 'a')\n    0\n    >>> how_many_times('aaa', 'a')\n    3\n    >>> how_many_times('aaaa', 'aa')\n    3\n    \"\"\"\n    count = 0\n    start = 0\n    \n    while True:\n        start = string.find(substring, start)\n        if start == -1:\n            break\n        count += 1\n        start += 1  # Move to the next character to allow for overlapping matches\n    \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n    \"\"\" Input are two strings a and b consisting only of 1s and 0s.\n    Perform binary XOR on these inputs and return result also as a string.\n    \n    >>> string_xor('010', '110')\n    '100'\n    >>> string_xor('111', '000')\n    '111'\n    >>> string_xor('101010', '010101')\n    '111111'\n    >>> string_xor('000', '000')\n    '000'\n    \"\"\"\n    # Ensure both strings are of the same length\n    if len(a) != len(b):\n        raise ValueError(\"Input strings must be of the same length.\")\n    \n    # Perform XOR operation\n    result = []\n    for bit_a, bit_b in zip(a, b):\n        # XOR operation: 1 if bits are different, 0 if they are the same\n        result.append('1' if bit_a != bit_b else '0')\n    \n    return ''.join(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n    \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n    >>> count_distinct_characters('xyzXYZ')\n    3\n    >>> count_distinct_characters('Jerry')\n    4\n    \"\"\"\n    # Convert the string to lowercase to ensure case insensitivity\n    lower_string = string.lower()\n    # Use a set to find distinct characters\n    distinct_characters = set(lower_string)\n    # Return the number of distinct characters\n    return len(distinct_characters)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n    \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n    \n    Args:\n        strings (List[str]): A list of strings to filter.\n        prefix (str): The prefix to filter the strings by.\n        \n    Returns:\n        List[str]: A list of strings that start with the given prefix.\n    \n    Examples:\n        >>> filter_by_prefix([], 'a')\n        []\n        >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n        ['abc', 'array']\n    \"\"\"\n    return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n    \"\"\"Create a function encrypt that takes a string as an argument and\n    returns a string encrypted with the alphabet being rotated. \n    The alphabet should be rotated in a manner such that the letters \n    shift down by two multiplied to two places.\n    For example:\n    encrypt('hi') returns 'lm'\n    encrypt('asdfghjkl') returns 'ewhjklnop'\n    encrypt('gf') returns 'kj'\n    encrypt('et') returns 'ix'\n    \"\"\"\n    encrypted = []\n    for char in s:\n        if char.isalpha():  # Check if the character is a letter\n            # Calculate the new character with a shift of 4 (2 * 2)\n            new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a')) if char.islower() else \\\n                        chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n            encrypted.append(new_char)\n        else:\n            encrypted.append(char)  # Non-alphabetic characters remain unchanged\n    return ''.join(encrypted)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n    \"\"\"Return list with elements incremented by 1.\n    \n    >>> incr_list([1, 2, 3])\n    [2, 3, 4]\n    >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n    [6, 4, 6, 3, 4, 4, 10, 1, 124]\n    \"\"\"\n    return [x + 1 for x in l]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n    \"\"\"Given length of a side and height, return the area of a triangle.\n    \n    The area of a triangle can be calculated using the formula:\n    area = (base * height) / 2\n    \n    Parameters:\n    a (float): The length of the base of the triangle.\n    h (float): The height of the triangle.\n    \n    Returns:\n    float: The area of the triangle.\n    \n    >>> triangle_area(5, 3)\n    7.5\n    >>> triangle_area(10, 2)\n    10.0\n    >>> triangle_area(0, 5)\n    0.0\n    >>> triangle_area(5, 0)\n    0.0\n    \"\"\"\n    return (a * h) / 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n    \"\"\"\n    You are given a 2 dimensional data, as a nested lists,\n    which is similar to matrix, however, unlike matrices,\n    each row may contain a different number of columns.\n    Given lst, and integer x, find integers x in the list,\n    and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n    each tuple is a coordinate - (row, columns), starting with 0.\n    Sort coordinates initially by rows in ascending order.\n    Also, sort coordinates of the row by columns in descending order.\n    \n    Examples:\n    get_row([\n      [1,2,3,4,5,6],\n      [1,2,3,4,1,6],\n      [1,2,3,4,5,1]\n    ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n    get_row([], 1) == []\n    get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n    \"\"\"\n    coordinates = []\n    \n    for row_index, row in enumerate(lst):\n        for col_index, value in enumerate(row):\n            if value == x:\n                coordinates.append((row_index, col_index))\n    \n    # Sort by row index (ascending) and then by column index (descending)\n    coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n    \n    return coordinates", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n    \"\"\"\n    Given an array arr of integers, find the minimum number of elements that\n    need to be changed to make the array palindromic. A palindromic array is an array that\n    is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n    For example:\n    smallest_change([1,2,3,5,4,7,9,6]) == 4\n    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n    smallest_change([1, 2, 3, 2, 1]) == 0\n    \"\"\"\n    n = len(arr)\n    changes = 0\n    \n    # Compare elements from the start and end towards the center\n    for i in range(n // 2):\n        if arr[i] != arr[n - 1 - i]:\n            changes += 1\n            \n    return changes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n    '''\n    Write a function that accepts two lists of strings and returns the list that has \n    total number of chars in the all strings of the list less than the other list.\n\n    if the two lists have the same number of chars, return the first list.\n\n    Examples\n    total_match([], []) \u279e []\n    total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n    total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n    total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n    total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n    '''\n    # Calculate the total number of characters in each list\n    total_chars_lst1 = sum(len(s) for s in lst1)\n    total_chars_lst2 = sum(len(s) for s in lst2)\n\n    # Compare the total characters and return the appropriate list\n    if total_chars_lst1 < total_chars_lst2:\n        return lst1\n    else:\n        return lst2", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": [[["happy", "birthday", "sarah"], ["happy", "birthday", "sally"]]]}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n    \"\"\"You are given a string s.\n    Your task is to check if the string is happy or not.\n    A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n    \n    For example:\n    is_happy('a') => False\n    is_happy('aa') => False\n    is_happy('abcd') => True\n    is_happy('aabb') => False\n    is_happy('adb') => True\n    is_happy('xyy') => False\n    \"\"\"\n    # Check if the length of the string is at least 3\n    if len(s) < 3:\n        return False\n    \n    # Check every 3 consecutive characters\n    for i in range(len(s) - 2):\n        if len(set(s[i:i+3])) < 3:  # If there are not 3 distinct characters\n            return False\n            \n    return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n    \"\"\" Input to this function is a string representing musical notes in a special ASCII format.\n    Your task is to parse this string and return list of integers corresponding to how many beats does each\n    note last.\n\n    Here is a legend:\n    'o' - whole note, lasts four beats\n    'o|' - half note, lasts two beats\n    '.|' - quarter note, lasts one beat\n\n    >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n    [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n    \"\"\"\n    # Define a mapping from note representation to beats\n    note_to_beats = {\n        'o': 4,\n        'o|': 2,\n        '.|': 1\n    }\n    \n    # Split the input string into individual notes\n    notes = music_string.split()\n    \n    # Parse each note and convert to beats\n    beats = [note_to_beats[note] for note in notes if note in note_to_beats]\n    \n    return beats", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n    \"\"\" Concatenate list of strings into a single string.\n    \n    Args:\n        strings (List[str]): A list of strings to concatenate.\n        \n    Returns:\n        str: A single concatenated string.\n    \n    Examples:\n        >>> concatenate([])\n        ''\n        >>> concatenate(['a', 'b', 'c'])\n        'abc'\n    \"\"\"\n    return ''.join(strings)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n    \"\"\" Test if given string is a palindrome \"\"\"\n    return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n    \"\"\" Find the shortest palindrome that begins with a supplied string.\n    Algorithm idea is simple:\n    - Find the longest postfix of supplied string that is a palindrome.\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n    \n    >>> make_palindrome('')\n    ''\n    >>> make_palindrome('cat')\n    'catac'\n    >>> make_palindrome('cata')\n    'catac'\n    \"\"\"\n    # Find the longest palindromic suffix\n    for i in range(len(string)):\n        if is_palindrome(string[i:]):\n            # If the suffix is a palindrome, we need to append the reverse of the prefix\n            prefix = string[:i]\n            return string + prefix[::-1]\n    return string  # In case the string is empty or already a palindrome", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n    \"\"\" From a list of integers, remove all elements that occur more than once.\n    Keep order of elements left the same as in the input.\n    \n    >>> remove_duplicates([1, 2, 3, 2, 4])\n    [1, 3, 4]\n    \"\"\"\n    # Count occurrences of each number\n    count = {}\n    for number in numbers:\n        count[number] = count.get(number, 0) + 1\n    \n    # Create a new list with elements that occur only once\n    result = [number for number in numbers if count[number] == 1]\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n    \"\"\" \n    Input is a space-delimited string of numerals from 'zero' to 'nine'.\n    Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n    Return the string with numbers sorted from smallest to largest.\n    \n    >>> sort_numbers('three one five')\n    'one three five'\n    \"\"\"\n    # Mapping of words to their corresponding numeric values\n    num_map = {\n        'zero': 0,\n        'one': 1,\n        'two': 2,\n        'three': 3,\n        'four': 4,\n        'five': 5,\n        'six': 6,\n        'seven': 7,\n        'eight': 8,\n        'nine': 9\n    }\n    \n    # Split the input string into words\n    words = numbers.split()\n    \n    # Sort the words based on their numeric values\n    sorted_words = sorted(words, key=lambda word: num_map[word])\n    \n    # Join the sorted words back into a string\n    return ' '.join(sorted_words)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n    \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n    letter_grades = []\n    \n    for gpa in grades:\n        if gpa == 4.0:\n            letter_grades.append('A+')\n        elif gpa > 3.7:\n            letter_grades.append('A')\n        elif gpa > 3.3:\n            letter_grades.append('A-')\n        elif gpa > 3.0:\n            letter_grades.append('B+')\n        elif gpa > 2.7:\n            letter_grades.append('B')\n        elif gpa > 2.3:\n            letter_grades.append('B-')\n        elif gpa > 2.0:\n            letter_grades.append('C+')\n        elif gpa > 1.7:\n            letter_grades.append('C')\n        elif gpa > 1.3:\n            letter_grades.append('C-')\n        elif gpa > 1.0:\n            letter_grades.append('D+')\n        elif gpa > 0.7:\n            letter_grades.append('D')\n        elif gpa > 0.0:\n            letter_grades.append('D-')\n        else:\n            letter_grades.append('E')\n    \n    return letter_grades", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n    \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n    such that the smallest number will become 0 and the largest will become 1.\n    \n    >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n    [0.0, 0.25, 0.5, 0.75, 1.0]\n    \"\"\"\n    if len(numbers) < 2:\n        raise ValueError(\"The list must contain at least two elements.\")\n    \n    min_val = min(numbers)\n    max_val = max(numbers)\n    \n    # Avoid division by zero if all numbers are the same\n    if min_val == max_val:\n        return [0.0] * len(numbers)\n    \n    return [(num - min_val) / (max_val - min_val) for num in numbers]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef get_primes_up_to(n):\n    \"\"\"Return a list of all prime numbers less than n.\"\"\"\n    return [i for i in range(2, n) if is_prime(i)]\ndef is_multiply_prime(a):\n    \"\"\"Return true if the given number is the multiplication of 3 prime numbers, false otherwise.\"\"\"\n    if a >= 100:\n        return False\n    \n    primes = get_primes_up_to(a)\n    prime_count = len(primes)\n    \n    # Check all combinations of three primes\n    for i in range(prime_count):\n        for j in range(i, prime_count):\n            for k in range(j, prime_count):\n                product = primes[i] * primes[j] * primes[k]\n                if product == a:\n                    return True\n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n    '''\n    Write a function that returns True if the object q will fly, and False otherwise.\n    The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n\n    Example:\n    will_it_fly([1, 2], 5) \u279e False \n    # 1+2 is less than the maximum possible weight, but it's unbalanced.\n\n    will_it_fly([3, 2, 3], 1) \u279e False\n    # it's balanced, but 3+2+3 is more than the maximum possible weight.\n\n    will_it_fly([3, 2, 3], 9) \u279e True\n    # 3+2+3 is less than the maximum possible weight, and it's balanced.\n\n    will_it_fly([3], 5) \u279e True\n    # 3 is less than the maximum possible weight, and it's balanced.\n    '''\n    # Check if the list is a palindrome\n    is_balanced = q == q[::-1]\n    \n    # Calculate the sum of the elements in the list\n    total_weight = sum(q)\n    \n    # Return True if it's balanced and the total weight is less than or equal to w\n    return is_balanced and total_weight <= w", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n    \"\"\"\n    Write a function that takes a string and returns an ordered version of it.\n    Ordered version of string, is a string where all words (separated by space)\n    are replaced by a new word where all the characters arranged in\n    ascending order based on ascii value.\n    Note: You should keep the order of words and blank spaces in the sentence.\n\n    For example:\n    anti_shuffle('Hi') returns 'Hi'\n    anti_shuffle('hello') returns 'ehllo'\n    anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n    \"\"\"\n    # Split the string into words while preserving spaces\n    words = s.split(' ')\n    \n    # Sort each word and keep the spaces intact\n    sorted_words = [''.join(sorted(word)) for word in words]\n    \n    # Join the sorted words back with spaces\n    result = ' '.join(sorted_words)\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n    \"\"\"Change numerical base of input number x to base.\n    return string representation after the conversion.\n    base numbers are less than 10.\n    \n    >>> change_base(8, 3)\n    '22'\n    >>> change_base(8, 2)\n    '1000'\n    >>> change_base(7, 2)\n    '111'\n    \"\"\"\n    if base < 2 or base >= 10:\n        raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n    \n    if x == 0:\n        return '0'\n    \n    result = []\n    while x > 0:\n        result.append(str(x % base))\n        x //= base\n    \n    return ''.join(reversed(result))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n    \"\"\"\n    Given an array of non-negative integers, return a copy of the given array after sorting,\n    you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n    or sort it in descending order if the sum( first index value, last index value) is even.\n\n    Note:\n    * don't change the given array.\n\n    Examples:\n    * sort_array([]) => []\n    * sort_array([5]) => [5]\n    * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n    * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n    \"\"\"\n    if not array:  # Check for empty array\n        return []\n    \n    first_value = array[0]\n    last_value = array[-1]\n    sum_values = first_value + last_value\n\n    # Create a copy of the array to sort\n    sorted_array = array.copy()\n\n    if sum_values % 2 == 0:  # Even sum\n        sorted_array.sort(reverse=True)  # Sort in descending order\n    else:  # Odd sum\n        sorted_array.sort()  # Sort in ascending order\n\n    return sorted_array", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n    \"\"\"\n    Given a dictionary, return True if all keys are strings in lower \n    case or all keys are strings in upper case, else return False.\n    The function should return False if the given dictionary is empty.\n    \n    Examples:\n    check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n    check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n    check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n    check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n    check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n    \"\"\"\n    if not input_dict:\n        return False\n\n    keys = input_dict.keys()\n    \n    # Check if all keys are strings\n    if not all(isinstance(key, str) for key in keys):\n        return False\n\n    # Check if all keys are lower case or all are upper case\n    all_lower = all(key.islower() for key in keys)\n    all_upper = all(key.isupper() for key in keys)\n\n    return all_lower or all_upper", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n    \"\"\"\n    pairs_sum_to_zero takes a list of integers as an input.\n    it returns True if there are two distinct elements in the list that\n    sum to zero, and False otherwise.\n    \n    >>> pairs_sum_to_zero([1, 3, 5, 0])\n    False\n    >>> pairs_sum_to_zero([1, 3, -2, 1])\n    False\n    >>> pairs_sum_to_zero([1, 2, 3, 7])\n    False\n    >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n    True\n    >>> pairs_sum_to_zero([1])\n    False\n    \"\"\"\n    seen = set()\n    for number in l:\n        if -number in seen:\n            return True\n        seen.add(number)\n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n    \"\"\" \n    brackets is a string of \"(\" and \")\".\n    return True if every opening bracket has a corresponding closing bracket.\n\n    >>> correct_bracketing(\"(\")\n    False\n    >>> correct_bracketing(\"()\")\n    True\n    >>> correct_bracketing(\"(()())\")\n    True\n    >>> correct_bracketing(\")(()\")\n    False\n    \"\"\"\n    balance = 0\n    for char in brackets:\n        if char == '(':\n            balance += 1\n        elif char == ')':\n            balance -= 1\n        # If balance goes negative, there are unmatched closing brackets\n        if balance < 0:\n            return False\n    # At the end, balance should be zero for all opening brackets to be matched\n    return balance == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n    \"\"\"Task\n    Write a function that takes a string as input and returns the sum of the upper characters only'\n    ASCII codes.\n\n    Examples:\n        digitSum(\"\") => 0\n        digitSum(\"abAB\") => 131\n        digitSum(\"abcCd\") => 67\n        digitSum(\"helloE\") => 69\n        digitSum(\"woArBld\") => 131\n        digitSum(\"aAaaaXa\") => 153\n    \"\"\"\n    return sum(ord(char) for char in s if char.isupper())", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n    '''\n    Create a function that takes 3 numbers.\n    Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n    Returns false in any other cases.\n    \n    Examples\n    any_int(5, 2, 7) \u279e True\n    \n    any_int(3, 2, 2) \u279e False\n\n    any_int(3, -2, 1) \u279e True\n    \n    any_int(3.6, -2.2, 2) \u279e False\n    '''\n    # Check if all inputs are integers\n    if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n        # Check if one number is equal to the sum of the other two\n        return x == y + z or y == x + z or z == x + y\n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int):\n    \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n    >>> largest_prime_factor(13195)\n    29\n    >>> largest_prime_factor(2048)\n    2\n    \"\"\"\n    # Start with the smallest prime factor\n    factor = 2\n    # Keep dividing n by factor until it is no longer divisible\n    while n > 1:\n        if n % factor == 0:\n            n //= factor  # Divide n by the factor\n        else:\n            factor += 1  # Move to the next potential factor\n    return factor  # The last factor is the largest prime factor", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n    \"\"\"Return True if list elements are monotonically increasing or decreasing.\n    \n    >>> monotonic([1, 2, 4, 20])\n    True\n    >>> monotonic([1, 20, 4, 10])\n    False\n    >>> monotonic([4, 1, 0, -10])\n    True\n    \"\"\"\n    if not l:  # An empty list is considered monotonic\n        return True\n    \n    increasing = decreasing = True\n    \n    for i in range(1, len(l)):\n        if l[i] > l[i - 1]:\n            decreasing = False\n        elif l[i] < l[i - 1]:\n            increasing = False\n            \n    return increasing or decreasing", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n    \"\"\"\n    Takes as input string encoded with encode_shift function. Returns decoded string.\n    \"\"\"\n    return \"\".join([chr(((ord(ch) - ord(\"a\") - 5) % 26) + ord(\"a\")) for ch in s])", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n    \"\"\"\n    Given an array representing a branch of a tree that has non-negative integer nodes,\n    your task is to pluck one of the nodes and return it.\n    The plucked node should be the node with the smallest even value.\n    If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n    The plucked node should be returned in a list, [ smallest_value, its index ],\n    If there are no even values or the given array is empty, return [].\n\n    Example 1:\n        Input: [4,2,3]\n        Output: [2, 1]\n        Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n    Example 2:\n        Input: [1,2,3]\n        Output: [2, 1]\n        Explanation: 2 has the smallest even value, and 2 has the smallest index. \n\n    Example 3:\n        Input: []\n        Output: []\n    \n    Example 4:\n        Input: [5, 0, 3, 0, 4, 2]\n        Output: [0, 1]\n        Explanation: 0 is the smallest value, but there are two zeros,\n                     so we will choose the first zero, which has the smallest index.\n\n    Constraints:\n        * 1 <= nodes.length <= 10000\n        * 0 <= node.value\n    \"\"\"\n    smallest_even = float('inf')\n    smallest_index = -1\n\n    for index, value in enumerate(arr):\n        if value % 2 == 0:  # Check if the value is even\n            if value < smallest_even:  # Check if it's the smallest even found\n                smallest_even = value\n                smallest_index = index\n\n    if smallest_index == -1:  # No even value found\n        return []\n    \n    return [smallest_even, smallest_index]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float) -> float:\n    \"\"\"\n    Evaluates polynomial with coefficients xs at point x.\n    return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n    \"\"\"\n    return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list) -> list:\n    \"\"\"\n    Computes the derivative of the polynomial with coefficients xs.\n    \"\"\"\n    return [i * coeff for i, coeff in enumerate(xs) if i > 0]\ndef find_zero(xs: list, initial_guess: float = 0.0, tolerance: float = 1e-7, max_iterations: int = 1000) -> float:\n    \"\"\" \n    xs are coefficients of a polynomial.\n    find_zero finds x such that poly(x) = 0.\n    find_zero returns only one zero point, even if there are many.\n    Moreover, find_zero only takes list xs having an even number of coefficients\n    and the largest non-zero coefficient as it guarantees a solution.\n    \n    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n    -0.5\n    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n    1.0\n    \"\"\"\n    if len(xs) % 2 != 0:\n        raise ValueError(\"The number of coefficients must be even.\")\n    \n    current_guess = initial_guess\n    for _ in range(max_iterations):\n        f_value = poly(xs, current_guess)\n        f_derivative = poly(derivative(xs), current_guess)\n        \n        if f_derivative == 0:\n            raise ValueError(\"Derivative is zero. No solution found.\")\n        \n        next_guess = current_guess - f_value / f_derivative\n        \n        if abs(next_guess - current_guess) < tolerance:\n            return next_guess\n        \n        current_guess = next_guess\n    \n    raise ValueError(\"Maximum iterations reached. No solution found.\")", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[[5, 10, -3, 1]]]}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n    \"\"\"Return maximum element in the list.\n    \n    >>> max_element([1, 2, 3])\n    3\n    >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n    123\n    \"\"\"\n    if not l:  # Check if the list is empty\n        raise ValueError(\"The list is empty.\")\n    \n    max_value = l[0]  # Initialize max_value with the first element\n    for item in l:\n        if item > max_value:\n            max_value = item\n    return max_value", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n    \"\"\" brackets is a string of \"<\" and \">\".\n    return True if every opening bracket has a corresponding closing bracket.\n\n    >>> correct_bracketing(\"<\")\n    False\n    >>> correct_bracketing(\"<>\")\n    True\n    >>> correct_bracketing(\"<<><>>\")\n    True\n    >>> correct_bracketing(\"><<>\")\n    False\n    \"\"\"\n    balance = 0\n    for char in brackets:\n        if char == '<':\n            balance += 1\n        elif char == '>':\n            balance -= 1\n        # If balance goes negative, there are more closing brackets\n        if balance < 0:\n            return False\n    # At the end, balance should be zero for correct bracketing\n    return balance == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n    '''\n    You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n    zero, and has a frequency greater than or equal to the value of the integer itself. \n    The frequency of an integer is the number of times it appears in the list.\n    If no such a value exist, return -1.\n    \n    Examples:\n        search([4, 1, 2, 2, 3, 1]) == 2\n        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n        search([5, 5, 4, 4, 4]) == -1\n    '''\n    from collections import Counter\n    \n    # Count the frequency of each number in the list\n    frequency = Counter(lst)\n    \n    # Initialize the result variable\n    result = -1\n    \n    # Iterate through the frequency dictionary\n    for num, freq in frequency.items():\n        # Check if the frequency is greater than or equal to the number itself\n        if freq >= num:\n            # Update the result if this number is greater than the current result\n            result = max(result, num)\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n    \"\"\"\n    remove_vowels is a function that takes a string and returns a string without vowels.\n    \n    >>> remove_vowels('')\n    ''\n    >>> remove_vowels(\"abcdef\\nghijklm\")\n    'bcdf\\nghjklm'\n    >>> remove_vowels('abcdef')\n    'bcdf'\n    >>> remove_vowels('aaaaa')\n    ''\n    >>> remove_vowels('aaBAA')\n    'B'\n    >>> remove_vowels('zbcd')\n    'zbcd'\n    \"\"\"\n    vowels = 'aeiouAEIOU'\n    return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n    \"\"\"Calculate the factorial of a non-negative integer n.\"\"\"\n    if n == 0 or n == 1:\n        return 1\n    result = 1\n    for i in range(2, n + 1):\n        result *= i\n    return result\ndef special_factorial(n):\n    \"\"\"Calculate the Brazilian factorial of n.\"\"\"\n    if n <= 0:\n        raise ValueError(\"Input must be a positive integer.\")\n    \n    result = 1\n    for i in range(1, n + 1):\n        result *= factorial(i)\n    \n    return result", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[496]]}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n    \"\"\"\n    Write a function that takes a message, and encodes in such a \n    way that it swaps case of all letters, replaces all vowels in \n    the message with the letter that appears 2 places ahead of that \n    vowel in the english alphabet. \n    Assume only letters. \n    \n    Examples:\n    >>> encode('test')\n    'TGST'\n    >>> encode('This is a message')\n    'tHKS KS C MGSSCGG'\n    \"\"\"\n    vowels = 'aeiouAEIOU'\n    encoded_message = []\n\n    for char in message:\n        if char.isalpha():  # Check if the character is a letter\n            # Swap case\n            if char in vowels:\n                # Replace vowel with the letter 2 places ahead\n                if char.islower():\n                    new_char = chr(((ord(char) - ord('a') + 2) % 26) + ord('a'))\n                else:\n                    new_char = chr(((ord(char) - ord('A') + 2) % 26) + ord('A'))\n            else:\n                new_char = char.swapcase()  # Swap case for consonants\n            encoded_message.append(new_char)\n        else:\n            encoded_message.append(char)  # Keep non-letter characters unchanged\n\n    return ''.join(encoded_message)", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["TEST"]], "plus_fail_tests": [["abcdefghijklmnopqrstuvwxyz"]]}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n    \"\"\"\n    Calculate the number of mango fruits in a basket given the number of apples and oranges.\n\n    Parameters:\n    s (str): A string representing the number of apples and oranges in the format \"X apples and Y oranges\".\n    n (int): An integer representing the total number of fruits in the basket.\n\n    Returns:\n    int: The number of mango fruits in the basket.\n    \"\"\"\n    # Split the input string to extract the number of apples and oranges\n    parts = s.split()\n    apples = int(parts[0])  # The first part is the number of apples\n    oranges = int(parts[2])  # The third part is the number of oranges\n\n    # Calculate the number of mangoes\n    mangoes = n - apples - oranges\n    return mangoes", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["5 apples and 6 oranges", 19]], "plus_fail_tests": [["10 apples and 20 oranges", 50]]}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n    \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n    \n    >>> sum_to_n(30)\n    465\n    >>> sum_to_n(100)\n    5050\n    >>> sum_to_n(5)\n    15\n    >>> sum_to_n(10)\n    55\n    >>> sum_to_n(1)\n    1\n    \"\"\"\n    return n * (n + 1) // 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n    \"\"\"Return sorted unique common elements for two lists.\n    \n    >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n    [1, 5, 653]\n    >>> common([5, 3, 2, 8], [3, 2])\n    [2, 3]\n    \n    \"\"\"\n    # Convert both lists to sets to find unique elements\n    set1 = set(l1)\n    set2 = set(l2)\n    \n    # Find the intersection of both sets\n    common_elements = set1.intersection(set2)\n    \n    # Return the sorted list of common elements\n    return sorted(common_elements)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n    \"\"\"Return sorted unique elements in a list\n    >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n    [0, 2, 3, 5, 9, 123]\n    \"\"\"\n    return sorted(set(l))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n    \"\"\"This function takes a list l and returns a list l' such that\n    l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n    to the values of the corresponding indices of l, but sorted.\n    \n    >>> sort_third([1, 2, 3])\n    [1, 2, 3]\n    >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n    [2, 6, 3, 4, 8, 9, 5]\n    \"\"\"\n    # Extract values at indices divisible by 3\n    divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n    \n    # Sort the extracted values\n    sorted_values = sorted(divisible_by_three)\n    \n    # Create a new list to hold the result\n    result = l.copy()\n    \n    # Replace values at indices divisible by 3 with sorted values\n    for index, value in zip((i for i in range(len(l)) if i % 3 == 0), sorted_values):\n        result[index] = value\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n    \"\"\"\n    Given an array of integers nums, find the minimum sum of any non-empty sub-array\n    of nums.\n    \n    Example\n    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n    minSubArraySum([-1, -2, -3]) == -6\n    \"\"\"\n    # Initialize variables to track the minimum sum and the current sum\n    min_sum = float('inf')\n    current_sum = 0\n    \n    for num in nums:\n        current_sum += num\n        min_sum = min(min_sum, current_sum)\n        \n        # If current_sum is positive, reset it to 0\n        if current_sum > 0:\n            current_sum = 0\n            \n    return min_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n    \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n    Each element i of the output should be \"the number of odd elements in the\n    string i of the input.\" where all the i's should be replaced by the number\n    of odd digits in the i'th string of the input.\n\n    >>> odd_count(['1234567'])\n    [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n    >>> odd_count(['3',\"11111111\"])\n    [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n     \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n    \"\"\"\n    result = []\n    for s in lst:\n        odd_count = sum(1 for char in s if char in '13579')  # Count odd digits\n        result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n    '''\n    Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n    should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n    alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n    \n    Examples:\n    split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n    split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n    split_words(\"abcdef\") \u279e 3 \n    '''\n    # Check for whitespace in the text\n    if ' ' in txt:\n        return txt.split()\n    \n    # Check for commas in the text\n    elif ',' in txt:\n        return txt.split(',')\n    \n    # If no whitespace or commas, count lower-case letters with odd order\n    else:\n        odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n        return odd_count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n    \"\"\"\n    Given a non-empty array of integers arr and an integer k, return\n    the sum of the elements with at most two digits from the first k elements of arr.\n\n    Example:\n\n        Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n        Output: 24 # sum of 21 + 3\n\n    Constraints:\n        1. 1 <= len(arr) <= 100\n        2. 1 <= k <= len(arr)\n    \"\"\"\n    # Initialize the sum\n    total_sum = 0\n    \n    # Iterate through the first k elements of the array\n    for i in range(k):\n        # Check if the element has at most two digits\n        if -100 < arr[i] < 100:\n            total_sum += arr[i]\n    \n    return total_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n    \"\"\"Accepts a list of strings, removes strings with odd lengths,\n    and returns the remaining strings sorted by length and alphabetically.\n    \n    Args:\n        lst (list of str): A list of strings.\n        \n    Returns:\n        list of str: A sorted list of strings with even lengths.\n    \"\"\"\n    # Filter out strings with odd lengths\n    filtered_lst = [s for s in lst if len(s) % 2 == 0]\n    \n    # Sort the list first by length, then alphabetically\n    sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n    \n    return sorted_lst", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n    \"\"\"\n    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n    as follows: start with any positive integer n. Then each term is obtained from the \n    previous term as follows: if the previous term is even, the next term is one half of \n    the previous term. If the previous term is odd, the next term is 3 times the previous\n    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n    Note: \n        1. Collatz(1) is [1].\n        2. returned list sorted in increasing order.\n\n    For example:\n    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n    \"\"\"\n    if n <= 0:\n        raise ValueError(\"Input must be a positive integer.\")\n    \n    collatz_sequence = []\n    current = n\n    \n    while current != 1:\n        collatz_sequence.append(current)\n        if current % 2 == 0:\n            current //= 2\n        else:\n            current = 3 * current + 1\n    \n    collatz_sequence.append(1)  # Add the last term which is 1\n    \n    # Filter odd numbers and sort them\n    odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n    \n    return odd_numbers", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n    \"\"\"\n    Given a string text, replace all spaces in it with underscores, \n    and if a string has more than 2 consecutive spaces, \n    then replace all consecutive spaces with - \n    \n    fix_spaces(\"Example\") == \"Example\"\n    fix_spaces(\"Example 1\") == \"Example_1\"\n    fix_spaces(\" Example 2\") == \"_Example_2\"\n    fix_spaces(\" Example   3\") == \"_Example-3\"\n    \"\"\"\n    import re\n\n    # Replace more than 2 consecutive spaces with a single '-'\n    text = re.sub(r' {3,}', '-', text)\n    \n    # Replace single spaces with underscores\n    text = text.replace(' ', '_')\n    \n    return text", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n    \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n    \n    The date is valid if all of the following rules are satisfied:\n    1. The date string is not empty.\n    2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n       The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n       The number of days is not less than 1 or higher than 29 for the month 2.\n    3. The months should not be less than 1 or higher than 12.\n    4. The date should be in the format: mm-dd-yyyy\n    \n    Args:\n        date (str): The date string to validate.\n    \n    Returns:\n        bool: True if the date is valid, False otherwise.\n    \"\"\"\n    if not date:\n        return False\n    \n    # Check the format\n    parts = date.split('-')\n    if len(parts) != 3:\n        return False\n    \n    if not all(part.isdigit() for part in parts):\n        return False\n    \n    month, day, year = map(int, parts)\n    \n    # Validate month\n    if month < 1 or month > 12:\n        return False\n    \n    # Validate day based on month\n    if month in {1, 3, 5, 7, 8, 10, 12}:\n        if day < 1 or day > 31:\n            return False\n    elif month in {4, 6, 9, 11}:\n        if day < 1 or day > 30:\n            return False\n    elif month == 2:\n        if day < 1 or day > 29:\n            return False\n    \n    return True", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["06-04-202"]]}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n    \"\"\"Task\n    We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n    then check if the result string is palindrome.\n    A string is called palindrome if it reads the same backward as forward.\n    You should return a tuple containing the result string and True/False for the check.\n    Example\n    For s = \"abcde\", c = \"ae\", the result should be ('bcd',False)\n    For s = \"abcdef\", c = \"b\"  the result should be ('acdef',False)\n    For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc',True)\n    \"\"\"\n    # Create a set of characters to delete for faster lookup\n    delete_set = set(c)\n    \n    # Create the result string by filtering out characters in delete_set\n    result = ''.join(char for char in s if char not in delete_set)\n    \n    # Check if the result string is a palindrome\n    is_palindrome = result == result[::-1]\n    \n    return (result, is_palindrome)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n    \"\"\"\n    Calculate the number of times buckets need to be lowered to empty the wells.\n\n    Parameters:\n    grid (list of list of int): A rectangular grid representing wells.\n    capacity (int): The capacity of each bucket.\n\n    Returns:\n    int: The total number of times buckets need to be lowered.\n    \"\"\"\n    total_water = 0\n    \n    # Count the total amount of water in the grid\n    for row in grid:\n        total_water += sum(row)\n    \n    # Calculate the number of times buckets need to be lowered\n    # Each bucket can carry 'capacity' units of water\n    if total_water == 0:\n        return 0\n    else:\n        return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": [[[[1, 0, 0, 1], [0, 1, 1, 1], [0, 0, 0, 0], [1, 0, 1, 1]], 2]]}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n    \"\"\"Create a function which takes a string representing a file's name, and returns\n    'Yes' if the the file's name is valid, and returns 'No' otherwise.\n    A file's name is considered to be valid if and only if all the following conditions \n    are met:\n    - There should not be more than three digits ('0'-'9') in the file's name.\n    - The file's name contains exactly one dot '.'\n    - The substring before the dot should not be empty, and it starts with a letter from \n    the latin alphapet ('a'-'z' and 'A'-'Z').\n    - The substring after the dot should be one of these: ['txt', 'exe', 'dll']\n    Examples:\n    file_name_check(\"example.txt\") # => 'Yes'\n    file_name_check(\"1example.dll\") # => 'No' (the name should start with a latin alphapet letter)\n    \"\"\"\n    \n    # Split the file name into name and extension\n    if file_name.count('.') != 1:\n        return 'No'\n    \n    name, extension = file_name.split('.')\n    \n    # Check if the name is empty or starts with a non-alphabet character\n    if not name or not name[0].isalpha():\n        return 'No'\n    \n    # Check if the extension is valid\n    valid_extensions = ['txt', 'exe', 'dll']\n    if extension not in valid_extensions:\n        return 'No'\n    \n    # Count the number of digits in the file name\n    digit_count = sum(c.isdigit() for c in file_name)\n    if digit_count > 3:\n        return 'No'\n    \n    return 'Yes'", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n    \"\"\"Write a function that takes an array of numbers as input and returns \n    the number of elements in the array that are greater than 10 and both \n    first and last digits of a number are odd (1, 3, 5, 7, 9).\n    \n    For example:\n    specialFilter([15, -73, 14, -15]) => 1 \n    specialFilter([33, -2, -3, 45, 21, 109]) => 2\n    \"\"\"\n    \n    def is_odd_digit(digit):\n        return digit in {'1', '3', '5', '7', '9'}\n    \n    def first_and_last_odd(num):\n        str_num = str(abs(num))  # Convert to string and take absolute value\n        return is_odd_digit(str_num[0]) and is_odd_digit(str_num[-1])\n    \n    count = 0\n    for num in nums:\n        if num > 10 and first_and_last_odd(num):\n            count += 1\n            \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n    '''\n    There are eight planets in our solar system: the closest to the Sun \n    is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n    Uranus, Neptune.\n    Write a function that takes two planet names as strings planet1 and planet2. \n    The function should return a tuple containing all planets whose orbits are \n    located between the orbit of planet1 and the orbit of planet2, sorted by \n    the proximity to the sun. \n    The function should return an empty tuple if planet1 or planet2\n    are not correct planet names. \n    Examples\n    bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n    bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n    bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n    '''\n    \n    planets = [\n        \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n        \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n    ]\n    \n    if planet1 not in planets or planet2 not in planets:\n        return ()\n    \n    index1 = planets.index(planet1)\n    index2 = planets.index(planet2)\n    \n    # Ensure index1 is less than index2 for slicing\n    start_index = min(index1, index2) + 1\n    end_index = max(index1, index2)\n    \n    return tuple(planets[start_index:end_index])", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n    \"\"\"You are given a list of numbers.\n    You need to return the sum of squared numbers in the given list,\n    round each element in the list to the upper int (Ceiling) first.\n    \n    Examples:\n    For lst = [1,2,3] the output should be 14\n    For lst = [1,4,9] the output should be 98\n    For lst = [1,3,5,7] the output should be 84\n    For lst = [1.4,4.2,0] the output should be 29\n    For lst = [-2.4,1,1] the output should be 6\n    \"\"\"\n    return sum(math.ceil(x) ** 2 for x in lst)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n    '''\n    Create a function that returns True if the last character\n    of a given string is an alphabetical character and is not\n    a part of a word, and False otherwise.\n    Note: \"word\" is a group of characters separated by space.\n\n    Examples:\n    check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n    check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n    check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n    check_if_last_char_is_a_letter(\"\") \u279e False \n    '''\n    # Strip any trailing whitespace from the string\n    txt = txt.rstrip()\n    \n    # Check if the string is empty after stripping\n    if not txt:\n        return False\n    \n    # Split the string into words\n    words = txt.split()\n    \n    # Get the last character of the last word\n    last_word = words[-1]\n    \n    # Check if the last character is a letter and if the last word has only one character\n    if len(last_word) == 1 and last_word.isalpha():\n        return True\n    \n    return False", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["eeeee e "]], "plus_fail_tests": [["apple pi\ne"]]}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n    \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n    in the sequence.\n    \n    >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n    [1, 2, 3, 3, 3, 4, 4]\n    \"\"\"\n    if not numbers:\n        return []\n    \n    max_so_far = numbers[0]\n    result = [max_so_far]\n    \n    for num in numbers[1:]:\n        max_so_far = max(max_so_far, num)\n        result.append(max_so_far)\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n    \"\"\"This function takes two positive numbers x and y and returns the\n    biggest even integer number that is in the range [x, y] inclusive. If \n    there's no such number, then the function should return -1.\n\n    For example:\n    choose_num(12, 15) = 14\n    choose_num(13, 12) = -1\n    \"\"\"\n    # Ensure x is less than or equal to y\n    if x > y:\n        return -1\n    \n    # Start from the largest number in the range and check for evenness\n    for num in range(y, x - 1, -1):\n        if num % 2 == 0:\n            return num\n    \n    return -1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n    \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n    given threshold.\n    \n    >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n    False\n    >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n    True\n    \"\"\"\n    # Sort the numbers to make it easier to find close elements\n    numbers.sort()\n    \n    # Check the difference between consecutive elements\n    for i in range(len(numbers) - 1):\n        if abs(numbers[i] - numbers[i + 1]) < threshold:\n            return True\n            \n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n    \"\"\"\n    Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n    reverse the resulting array, and then replace each digit by its corresponding name from\n    \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n    For example:\n      arr = [2, 1, 1, 4, 5, 8, 2, 3]   \n            -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n            -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n      return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n    \n      If the array is empty, return an empty array:\n      arr = []\n      return []\n    \n      If the array has any strange number ignore it:\n      arr = [1, -1 , 55] \n            -> sort arr -> [-1, 1, 55]\n            -> reverse arr -> [55, 1, -1]\n      return = ['One']\n    \"\"\"\n    \n    # Mapping of digits to their corresponding names\n    digit_to_name = {\n        1: \"One\", 2: \"Two\", 3: \"Three\", 4: \"Four\",\n        5: \"Five\", 6: \"Six\", 7: \"Seven\", 8: \"Eight\", 9: \"Nine\"\n    }\n    \n    # Filter the array to include only numbers between 1 and 9\n    filtered_arr = [num for num in arr if 1 <= num <= 9]\n    \n    # Sort the filtered array\n    sorted_arr = sorted(filtered_arr)\n    \n    # Reverse the sorted array\n    reversed_arr = sorted_arr[::-1]\n    \n    # Convert the digits to their corresponding names\n    result = [digit_to_name[num] for num in reversed_arr]\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n    \"\"\" Filter an input list of strings only for ones that contain given substring\n    >>> filter_by_substring([], 'a')\n    []\n    >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n    ['abc', 'bacd', 'array']\n    \"\"\"\n    return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n    \"\"\"\n    Given a positive integer, obtain its roman numeral equivalent as a string,\n    and return it in lowercase.\n    Restrictions: 1 <= num <= 1000\n\n    Examples:\n    >>> int_to_mini_roman(19) == 'xix'\n    >>> int_to_mini_roman(152) == 'clii'\n    >>> int_to_mini_roman(426) == 'cdxxvi'\n    \"\"\"\n    if not (1 <= number <= 1000):\n        raise ValueError(\"Number must be between 1 and 1000\")\n\n    roman_numerals = [\n        (1000, 'm'),\n        (900, 'cm'),\n        (500, 'd'),\n        (400, 'cd'),\n        (100, 'c'),\n        (90, 'xc'),\n        (50, 'l'),\n        (40, 'xl'),\n        (10, 'x'),\n        (9, 'ix'),\n        (5, 'v'),\n        (4, 'iv'),\n        (1, 'i')\n    ]\n\n    result = []\n    for value, numeral in roman_numerals:\n        while number >= value:\n            result.append(numeral)\n            number -= value\n\n    return ''.join(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n    '''\n    Given a list of numbers, return the sum of squares of the numbers\n    in the list that are odd. Ignore numbers that are negative or not integers.\n    \n    double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n    double_the_difference([-1, -2, 0]) == 0\n    double_the_difference([9, -2]) == 81\n    double_the_difference([0]) == 0  \n   \n    If the input list is empty, return 0.\n    '''\n    if not lst:  # Check if the list is empty\n        return 0\n    \n    sum_of_squares = 0\n    for num in lst:\n        if isinstance(num, int) and num >= 0 and num % 2 != 0:  # Check if num is a non-negative odd integer\n            sum_of_squares += num ** 2  # Add the square of the odd number to the sum\n    \n    return sum_of_squares", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n    \"\"\"\n    Given two lists operator, and operand. The first list has basic algebra operations, and \n    the second list is a list of integers. Use the two given lists to build the algebraic \n    expression and return the evaluation of this expression.\n\n    The basic algebra operations:\n    Addition ( + ) \n    Subtraction ( - ) \n    Multiplication ( * ) \n    Floor division ( // ) \n    Exponentiation ( ** ) \n\n    Example:\n    operator = ['+', '*', '-']\n    operand = [2, 3, 4, 5]\n    result = 2 + 3 * 4 - 5\n    => result = 9\n\n    Note:\n        The length of operator list is equal to the length of operand list minus one.\n        Operand is a list of non-negative integers.\n        Operator list has at least one operator, and operand list has at least two operands.\n    \"\"\"\n    # Start with the first operand\n    result = operand[0]\n    \n    # Iterate through the operators and operands\n    for i in range(len(operator)):\n        op = operator[i]\n        next_operand = operand[i + 1]\n        \n        if op == '+':\n            result += next_operand\n        elif op == '-':\n            result -= next_operand\n        elif op == '*':\n            result *= next_operand\n        elif op == '//':\n            result //= next_operand\n        elif op == '**':\n            result **= next_operand\n        else:\n            raise ValueError(f\"Unsupported operator: {op}\")\n    \n    return result", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": [[["+", "-", "*", "//"], [5, 2, 3, 4, 7]]]}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n    \"\"\"Write a function that accepts a list of strings.\n    The list contains different words. Return the word with maximum number\n    of unique characters. If multiple strings have maximum number of unique\n    characters, return the one which comes first in lexicographical order.\n\n    find_max([\"name\", \"of\", \"string\"]) == \"string\"\n    find_max([\"name\", \"enam\", \"game\"]) == \"enam\"\n    find_max([\"aaaaaaa\", \"bb\" ,\"cc\"]) == \"aaaaaaa\"\n    \"\"\"\n    max_word = \"\"\n    max_unique_count = 0\n\n    for word in words:\n        unique_chars = set(word)\n        unique_count = len(unique_chars)\n\n        if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n            max_word = word\n            max_unique_count = unique_count\n\n    return max_word", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n    \"\"\"Given a list of positive integers x, return a sorted list of all \n    elements that haven't any even digit.\n\n    Note: Returned list should be sorted in increasing order.\n    \n    For example:\n    >>> unique_digits([15, 33, 1422, 1])\n    [1, 15, 33]\n    >>> unique_digits([152, 323, 1422, 10])\n    []\n    \"\"\"\n    def has_even_digit(n):\n        \"\"\"Check if the number has any even digit.\"\"\"\n        return any(int(digit) % 2 == 0 for digit in str(n))\n\n    # Filter the list to include only numbers without even digits\n    result = [num for num in x if not has_even_digit(num)]\n    \n    # Return the sorted result\n    return sorted(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n    \"\"\"\n    You are given a positive integer n. You have to create an integer array a of length n.\n    For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n    Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n    and a[i] + a[j] + a[k] is a multiple of 3.\n\n    Example :\n        Input: n = 5\n        Output: 1\n        Explanation: \n        a = [1, 3, 7, 13, 21]\n        The only valid triple is (1, 7, 13).\n    \"\"\"\n    # Create the array a\n    a = [i * i - i + 1 for i in range(1, n + 1)]\n    \n    # Count the number of valid triples\n    count = 0\n    \n    # Check all combinations of triples (i, j, k) with i < j < k\n    for i in range(n):\n        for j in range(i + 1, n):\n            for k in range(j + 1, n):\n                if (a[i] + a[j] + a[k]) % 3 == 0:\n                    count += 1\n                    \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n    \"\"\" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n    For each of the group, output the deepest level of nesting of parentheses.\n    E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n    >>> parse_nested_parens('(()()) ((())) () ((())()())')\n    [2, 3, 1, 3]\n    \"\"\"\n    def max_nesting_depth(s: str) -> int:\n        max_depth = 0\n        current_depth = 0\n        for char in s:\n            if char == '(':\n                current_depth += 1\n                max_depth = max(max_depth, current_depth)\n            elif char == ')':\n                current_depth -= 1\n        return max_depth\n\n    groups = paren_string.split()\n    return [max_nesting_depth(group) for group in groups]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef sum_of_digits(n):\n    \"\"\"Return the sum of the digits of a number.\"\"\"\n    return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n    \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n    largest_prime = -1\n    \n    for number in lst:\n        if is_prime(number) and number > largest_prime:\n            largest_prime = number\n            \n    if largest_prime == -1:\n        return 0  # Return 0 if no prime is found\n    \n    return sum_of_digits(largest_prime)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n    \"\"\" \n    Input to this function is a string containing multiple groups of nested parentheses. \n    Your goal is to separate those groups into separate strings and return the list of those.\n    Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n    Ignore any spaces in the input string.\n    \n    >>> separate_paren_groups('( ) (( )) (( )( ))')\n    ['()', '(())', '(()())']\n    \"\"\"\n    # Remove spaces from the input string\n    paren_string = paren_string.replace(\" \", \"\")\n    \n    result = []\n    balance = 0\n    current_group = []\n    \n    for char in paren_string:\n        if char == '(':\n            if balance == 0 and current_group:\n                # If we are starting a new group, save the current one\n                result.append(''.join(current_group))\n                current_group = []\n            current_group.append(char)\n            balance += 1\n        elif char == ')':\n            current_group.append(char)\n            balance -= 1\n        \n        # If balance is zero, we have a complete group\n        if balance == 0 and current_group:\n            result.append(''.join(current_group))\n            current_group = []\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n    \"\"\"Create a function which returns the largest index of an element which\n    is not greater than or equal to the element immediately preceding it. If\n    no such element exists then return -1. The given array will not contain\n    duplicate values.\n\n    Examples:\n    can_arrange([1,2,4,3,5]) = 3\n    can_arrange([1,2,3]) = -1\n    \"\"\"\n    # Iterate through the array from the second element to the end\n    for i in range(1, len(arr)):\n        # Check if the current element is less than the previous one\n        if arr[i] < arr[i - 1]:\n            return i  # Return the index of the current element\n    return -1  # Return -1 if no such element is found", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[4, 8, 5, 7, 3]]], "plus_fail_tests": [[[5, 4, 3, 2, 1]]]}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n    \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n    Empty sum should be equal to 0 and empty product should be equal to 1.\n    \n    >>> sum_product([])\n    (0, 1)\n    >>> sum_product([1, 2, 3, 4])\n    (10, 24)\n    \"\"\"\n    if not numbers:\n        return (0, 1)\n    \n    total_sum = sum(numbers)\n    total_product = 1\n    for number in numbers:\n        total_product *= number\n    \n    return (total_sum, total_product)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n    '''\n    Create a function that takes a string as input which contains only square brackets.\n    The function should return True if and only if there is a valid subsequence of brackets \n    where at least one bracket in the subsequence is nested.\n\n    is_nested('[[]]') \u279e True\n    is_nested('[]]]]]]][[[[[]') \u279e False\n    is_nested('[][]') \u279e False\n    is_nested('[]') \u279e False\n    is_nested('[[][]]') \u279e True\n    is_nested('[[]][[') \u279e True\n    '''\n    stack = []\n    nested_found = False\n\n    for char in string:\n        if char == '[':\n            stack.append(char)\n        elif char == ']':\n            if stack:\n                stack.pop()\n                if len(stack) > 0:  # Check if there is a nested bracket\n                    nested_found = True\n            else:\n                return False  # Unmatched closing bracket\n\n    return nested_found and len(stack) == 0  # Must be balanced and have nested brackets", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["[[]][["]], "plus_fail_tests": [["[[]]]"]]}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n    \"\"\"\n    You're a hungry rabbit, and you already have eaten a certain number of carrots,\n    but now you need to eat more carrots to complete the day's meals.\n    you should return an array of [ total number of eaten carrots after your meals,\n                                    the number of carrots left after your meals ]\n    if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n    \n    Example:\n    * eat(5, 6, 10) -> [11, 4]\n    * eat(4, 8, 9) -> [12, 1]\n    * eat(1, 10, 10) -> [11, 0]\n    * eat(2, 11, 5) -> [7, 0]\n    \n    Variables:\n    @number : integer\n        the number of carrots that you have eaten.\n    @need : integer\n        the number of carrots that you need to eat.\n    @remaining : integer\n        the number of remaining carrots that exist in stock\n    \n    Constrain:\n    * 0 <= number <= 1000\n    * 0 <= need <= 1000\n    * 0 <= remaining <= 1000\n\n    Have fun :)\n    \"\"\"\n    # Calculate how many more carrots are needed\n    additional_needed = need - number\n    \n    # If no additional carrots are needed, return the current state\n    if additional_needed <= 0:\n        return [number, remaining]\n    \n    # Determine how many carrots can be eaten from the remaining stock\n    eaten = min(additional_needed, remaining)\n    \n    # Calculate the total eaten and remaining carrots\n    total_eaten = number + eaten\n    remaining_after_meal = remaining - eaten\n    \n    return [total_eaten, remaining_after_meal]", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": [[2, 2, 2]]}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n    \"\"\"You are given a string s.\n    if s[i] is a letter, reverse its case from lower to upper or vise versa, \n    otherwise keep it as it is.\n    If the string contains no letters, reverse the string.\n    The function should return the resulted string.\n    \n    Examples:\n    solve(\"1234\") = \"4321\"\n    solve(\"ab\") = \"AB\"\n    solve(\"#a@C\") = \"#A@c\"\n    \"\"\"\n    # Check if there are any letters in the string\n    has_letters = any(c.isalpha() for c in s)\n    \n    if has_letters:\n        # Reverse case for letters and keep others the same\n        return ''.join(c.swapcase() if c.isalpha() else c for c in s)\n    else:\n        # Reverse the string if there are no letters\n        return s[::-1]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n    '''\n    Given the lengths of the three sides of a triangle. Return True if the three\n    sides form a right-angled triangle, False otherwise.\n    A right-angled triangle is a triangle in which one angle is right angle or \n    90 degree.\n    \n    Example:\n    right_angle_triangle(3, 4, 5) == True\n    right_angle_triangle(1, 2, 3) == False\n    '''\n    # Sort the sides to identify the longest side\n    sides = sorted([a, b, c])\n    # Check the Pythagorean theorem\n    return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(num):\n    \"\"\"Check if a number is prime.\"\"\"\n    if num <= 1:\n        return False\n    for i in range(2, int(num**0.5) + 1):\n        if num % i == 0:\n            return False\n    return True\ndef x_or_y(n, x, y):\n    \"\"\"Return the value of x if n is a prime number, otherwise return y.\"\"\"\n    if is_prime(n):\n        return x\n    else:\n        return y", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n    \"\"\"Convert a decimal number to binary format with specific formatting.\n\n    Args:\n    decimal (int): A non-negative integer to convert to binary.\n\n    Returns:\n    str: A string representing the binary format of the decimal number,\n         prefixed and suffixed with 'db'.\n    \n    Examples:\n    >>> decimal_to_binary(15)\n    'db1111db'\n    >>> decimal_to_binary(32)\n    'db100000db'\n    \"\"\"\n    if decimal < 0:\n        raise ValueError(\"Input must be a non-negative integer.\")\n    \n    # Convert decimal to binary and remove the '0b' prefix\n    binary_representation = bin(decimal)[2:]\n    \n    # Format the output with 'db' at the beginning and end\n    formatted_output = f\"db{binary_representation}db\"\n    \n    return formatted_output", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n    \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n    fib4(0) -> 0\n    fib4(1) -> 0\n    fib4(2) -> 2\n    fib4(3) -> 0\n    fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n    \n    This function computes the n-th element of the fib4 number sequence without using recursion.\n    \n    >>> fib4(5)\n    4\n    >>> fib4(6)\n    8\n    >>> fib4(7)\n    14\n    \"\"\"\n    if n == 0:\n        return 0\n    elif n == 1:\n        return 0\n    elif n == 2:\n        return 2\n    elif n == 3:\n        return 0\n    \n    # Initialize the first four values of the sequence\n    fib_values = [0, 0, 2, 0]\n    \n    # Compute the values iteratively\n    for i in range(4, n + 1):\n        next_value = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n        fib_values.append(next_value)\n    \n    return fib_values[n]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n    \"\"\"\n    Imagine a road that's a perfectly straight infinitely long line.\n    n cars are driving left to right; simultaneously, a different set of n cars\n    are driving right to left. The two sets of cars start out being very far from\n    each other. All cars move at the same speed. Two cars are said to collide\n    when a car that's moving left to right hits a car that's moving right to left.\n    However, the cars are infinitely sturdy and strong; as a result, they continue moving\n    in their trajectory as if they did not collide.\n\n    This function outputs the number of such collisions.\n\n    Parameters:\n    n (int): The number of cars in each direction.\n\n    Returns:\n    int: The total number of collisions.\n    \"\"\"\n    # Each car moving left to right will collide with each car moving right to left\n    # Therefore, the total number of collisions is n * n\n    return n * n", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n    \"\"\"\n    Checks if given string is a palindrome.\n    \n    A palindrome is a string that reads the same forward and backward.\n    \n    >>> is_palindrome('')\n    True\n    >>> is_palindrome('aba')\n    True\n    >>> is_palindrome('aaaaa')\n    True\n    >>> is_palindrome('zbcd')\n    False\n    \"\"\"\n    # Normalize the string by removing spaces and converting to lowercase\n    normalized_text = text.replace(\" \", \"\").lower()\n    # Check if the string is equal to its reverse\n    return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["never odd or even"]]}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n    \"\"\"You are given two positive integers n and m, and your task is to compute the\n    average of the integers from n through m (including n and m). \n    Round the answer to the nearest integer and convert that to binary.\n    If n is greater than m, return -1.\n    \n    Example:\n    rounded_avg(1, 5) => \"0b11\"\n    rounded_avg(7, 5) => -1\n    rounded_avg(10, 20) => \"0b1111\"\n    rounded_avg(20, 33) => \"0b11010\"\n    \"\"\"\n    if n > m:\n        return -1\n    \n    # Calculate the sum of integers from n to m\n    total_sum = sum(range(n, m + 1))\n    count = m - n + 1  # Total numbers from n to m\n    \n    # Calculate the average and round it\n    average = total_sum / count\n    rounded_average = round(average)\n    \n    # Convert the rounded average to binary\n    return bin(rounded_average)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n    '''\n    Write a function that takes an integer a and returns True \n    if this integer is a cube of some integer number.\n    Note: you may assume the input is always valid.\n    \n    Examples:\n    iscube(1) ==> True\n    iscube(2) ==> False\n    iscube(-1) ==> True\n    iscube(64) ==> True\n    iscube(0) ==> True\n    iscube(180) ==> False\n    '''\n    # Calculate the cube root of the absolute value of a\n    cube_root = round(abs(a) ** (1/3))\n    \n    # Check if the cube of the rounded cube root equals the absolute value of a\n    return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n    \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n    \n    Example\n        For N = 1000, the sum of digits will be 1 the output should be \"1\".\n        For N = 150, the sum of digits will be 6 the output should be \"110\".\n        For N = 147, the sum of digits will be 12 the output should be \"1100\".\n    \n    Variables:\n        @N integer\n             Constraints: 0 \u2264 N \u2264 10000.\n    Output:\n         a string of binary number\n    \"\"\"\n    # Calculate the sum of the digits of N\n    digit_sum = sum(int(digit) for digit in str(N))\n    \n    # Convert the sum to binary and return it as a string\n    return bin(digit_sum)[2:]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n    '''\n    Given list of integers, return list in strange order.\n    Strange sorting, is when you start with the minimum value,\n    then maximum of the remaining integers, then minimum and so on.\n\n    Examples:\n    strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n    strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n    strange_sort_list([]) == []\n    '''\n    if not lst:\n        return []\n\n    sorted_lst = sorted(lst)\n    result = []\n    left, right = 0, len(sorted_lst) - 1\n\n    while left <= right:\n        if left == right:\n            result.append(sorted_lst[left])\n        else:\n            result.append(sorted_lst[left])\n            result.append(sorted_lst[right])\n        left += 1\n        right -= 1\n\n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n    \"\"\"\n    Given a positive integer n, return the count of the numbers of n-digit\n    positive integers that start or end with 1.\n    \"\"\"\n    if n < 1:\n        return 0\n\n    # Total n-digit numbers\n    total_n_digit_numbers = 9 * (10 ** (n - 1))\n\n    # Count of n-digit numbers that start with 1\n    start_with_1 = 10 ** (n - 1)\n\n    # Count of n-digit numbers that end with 1\n    end_with_1 = total_n_digit_numbers // 10\n\n    # Count of n-digit numbers that start and end with 1\n    start_and_end_with_1 = 10 ** (n - 2) if n > 1 else 0\n\n    # Using the inclusion-exclusion principle\n    count = start_with_1 + end_with_1 - start_and_end_with_1\n\n    return count", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[1000000]]}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n    \"\"\" Return length of given string\n    >>> strlen('')\n    0\n    >>> strlen('abc')\n    3\n    \"\"\"\n    return len(string)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n    \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n    \n    >>> largest_divisor(15)\n    5\n    >>> largest_divisor(28)\n    14\n    >>> largest_divisor(1)\n    0\n    >>> largest_divisor(10)\n    5\n    \"\"\"\n    if n <= 1:\n        return 0  # No divisors for 1 or less\n    \n    for i in range(n // 2, 0, -1):\n        if n % i == 0:\n            return i", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n    \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n    strings of the same length. Return None in case the input list is empty.\n    \n    >>> longest([])\n    >>> None\n    >>> longest(['a', 'b', 'c'])\n    'a'\n    >>> longest(['a', 'bb', 'ccc'])\n    'ccc'\n    \"\"\"\n    if not strings:\n        return None\n    \n    longest_string = strings[0]\n    \n    for string in strings:\n        if len(string) > len(longest_string):\n            longest_string = string\n            \n    return longest_string", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n    '''\n    Given the lengths of the three sides of a triangle. Return the area of\n    the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n    Otherwise return -1.\n    Three sides make a valid triangle when the sum of any two sides is greater \n    than the third side.\n    \n    Example:\n    triangle_area(3, 4, 5) == 6.00\n    triangle_area(1, 2, 10) == -1\n    '''\n    # Check for valid triangle\n    if a + b > c and a + c > b and b + c > a:\n        # Calculate the semi-perimeter\n        s = (a + b + c) / 2\n        # Calculate the area using Heron's formula\n        area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n        return round(area, 2)\n    else:\n        return -1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n    \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n    Args:\n        lst (list): A non-empty list of integers.\n\n    Returns:\n        int: The sum of even elements at odd indices.\n\n    Examples:\n        add([4, 2, 6, 7]) ==> 2 \n    \"\"\"\n    return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n    \"\"\"Return 2^n modulo p (be aware of numerics).\n    \n    >>> modp(3, 5)\n    3\n    >>> modp(1101, 101)\n    2\n    >>> modp(0, 101)\n    1\n    >>> modp(3, 11)\n    8\n    >>> modp(100, 101)\n    1\n    \"\"\"\n    result = 1\n    base = 2 % p  # Start with 2 mod p\n    while n > 0:\n        if n % 2 == 1:  # If n is odd, multiply the base with the result\n            result = (result * base) % p\n        base = (base * base) % p  # Square the base\n        n //= 2  # Divide n by 2\n    return result", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[0, 1]]}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef prime_length(string):\n    \"\"\"Return True if the string length is a prime number, False otherwise.\"\"\"\n    length = len(string)\n    return is_prime(length)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n    \"\"\"\n    triples_sum_to_zero takes a list of integers as an input.\n    it returns True if there are three distinct elements in the list that\n    sum to zero, and False otherwise.\n\n    >>> triples_sum_to_zero([1, 3, 5, 0])\n    False\n    >>> triples_sum_to_zero([1, 3, -2, 1])\n    True\n    >>> triples_sum_to_zero([1, 2, 3, 7])\n    False\n    >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n    True\n    >>> triples_sum_to_zero([1])\n    False\n    \"\"\"\n    n = len(l)\n    # Sort the list to use the two-pointer technique\n    l.sort()\n    \n    for i in range(n - 2):\n        # Avoid duplicates for the first element\n        if i > 0 and l[i] == l[i - 1]:\n            continue\n        \n        left, right = i + 1, n - 1\n        while left < right:\n            current_sum = l[i] + l[left] + l[right]\n            if current_sum == 0:\n                return True\n            elif current_sum < 0:\n                left += 1\n            else:\n                right -= 1\n    \n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n    \"\"\"Returns True if x is a simple power of n, otherwise False.\n    \n    A number x is a simple power of n if there exists an integer k such that n**k = x.\n    \n    Args:\n        x (int): The number to check.\n        n (int): The base to check against.\n    \n    Returns:\n        bool: True if x is a simple power of n, False otherwise.\n    \"\"\"\n    if n <= 1:\n        return x == 1  # 1 is a power of any number, and no other number can be a power of 1 or 0.\n    \n    power = 1\n    while True:\n        result = n ** power\n        if result == x:\n            return True\n        elif result > x:\n            return False\n        power += 1", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[1, 12]], "plus_fail_tests": [[1, 4]]}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n    \"\"\"Counts the number of prime hexadecimal digits in the given hexadecimal string.\"\"\"\n    # Define the set of prime hexadecimal digits\n    prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n    \n    # Count the number of prime hexadecimal digits in the input string\n    count = sum(1 for digit in num if digit in prime_hex_digits)\n    \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n    \"\"\"Return median of elements in the list l.\n    \n    The median is the middle value in a list of numbers. If the list has an even number of elements,\n    the median is the average of the two middle numbers.\n    \n    >>> median([3, 1, 2, 4, 5])\n    3\n    >>> median([-10, 4, 6, 1000, 10, 20])\n    15.0\n    \"\"\"\n    if not l:\n        raise ValueError(\"The list is empty\")\n    \n    sorted_list = sorted(l)\n    n = len(sorted_list)\n    mid = n // 2\n    \n    if n % 2 == 0:  # Even number of elements\n        return (sorted_list[mid - 1] + sorted_list[mid]) / 2\n    else:  # Odd number of elements\n        return sorted_list[mid]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n    \"\"\" Return a greatest common divisor of two integers a and b\n    >>> greatest_common_divisor(3, 5)\n    1\n    >>> greatest_common_divisor(25, 15)\n    5\n    \"\"\"\n    while b:\n        a, b = b, a % b\n    return abs(a)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n    \"\"\" Return list of all prefixes from shortest to longest of the input string\n    >>> all_prefixes('abc')\n    ['a', 'ab', 'abc']\n    \"\"\"\n    return [string[:i] for i in range(1, len(string) + 1)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n    \"\"\" Filter given list of any python values only for integers\n    >>> filter_integers(['a', 3.14, 5])\n    [5]\n    >>> filter_integers([1, 2, 3, 'abc', {}, []])\n    [1, 2, 3]\n    \"\"\"\n    return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[[true, false, null, 0, -10, "test", [], {}, 3.14]]]}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n    \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n    Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n    Input number should be equal to the product of all factors\n    >>> factorize(8)\n    [2, 2, 2]\n    >>> factorize(25)\n    [5, 5]\n    >>> factorize(70)\n    [2, 5, 7]\n    \"\"\"\n    factors = []\n    # Check for number of 2s that divide n\n    while n % 2 == 0:\n        factors.append(2)\n        n //= 2\n    \n    # n must be odd at this point so a skip of 2 (i.e., i = i + 2) can be used\n    for i in range(3, int(n**0.5) + 1, 2):\n        # While i divides n, append i and divide n\n        while n % i == 0:\n            factors.append(i)\n            n //= i\n    \n    # This condition is to check if n is a prime number greater than 2\n    if n > 2:\n        factors.append(n)\n    \n    return factors", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str) -> str:\n    \"\"\"\n    Takes as input a string encoded with the encode_cyclic function.\n    Returns the decoded string.\n    \"\"\"\n    # Split string into groups of length 3\n    groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n    # Reverse the cycling of elements in each group\n    groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n    return \"\".join(groups)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n    \"\"\"Return true if a given number is prime, and false otherwise.\n    \n    A prime number is a natural number greater than 1 that cannot be formed by multiplying two smaller natural numbers.\n    \n    >>> is_prime(6)\n    False\n    >>> is_prime(101)\n    True\n    >>> is_prime(11)\n    True\n    >>> is_prime(13441)\n    True\n    >>> is_prime(61)\n    True\n    >>> is_prime(4)\n    False\n    >>> is_prime(1)\n    False\n    \"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n    \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n    and return the result as a string.\n    If shift > number of digits, return digits reversed.\n    \n    >>> circular_shift(12, 1)\n    '21'\n    >>> circular_shift(12, 2)\n    '12'\n    >>> circular_shift(12345, 1)\n    '51234'\n    >>> circular_shift(12345, 5)\n    '54321'\n    >>> circular_shift(12345, 6)\n    '54321'\n    \"\"\"\n    # Convert the integer to a string to manipulate its digits\n    str_x = str(x)\n    length = len(str_x)\n    \n    # If shift is greater than the number of digits, reverse the string\n    if shift >= length:\n        return str_x[::-1]\n    \n    # Calculate the effective shift\n    effective_shift = shift % length\n    \n    # Perform the circular shift\n    shifted = str_x[-effective_shift:] + str_x[:-effective_shift]\n    \n    return shifted", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[12, 2]], "plus_fail_tests": [[987654321, 9]]}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n    \"\"\"\n    You'll be given a string of words, and your task is to count the number\n    of boredoms. A boredom is a sentence that starts with the word \"I\".\n    Sentences are delimited by '.', '?' or '!'.\n   \n    For example:\n    >>> is_bored(\"Hello world\")\n    0\n    >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n    1\n    >>> is_bored(\"I am happy! Are you? I will go now.\")\n    2\n    >>> is_bored(\"What a day. I can't believe it! I am so excited.\")\n    2\n    \"\"\"\n    # Split the string into sentences using the delimiters\n    sentences = [s.strip() for s in S.replace('!', '.').replace('?', '.').split('.')]\n    \n    # Count sentences that start with \"I\"\n    boredom_count = sum(1 for sentence in sentences if sentence.startswith(\"I\"))\n    \n    return boredom_count", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": [["In the morning, I like to have a cup of coffee to start my day off right. How about you?"]]}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n    \"\"\" \n    xs represent coefficients of a polynomial.\n    xs[0] + xs[1] * x + xs[2] * x^2 + ....\n    Return derivative of this polynomial in the same form.\n    \n    >>> derivative([3, 1, 2, 4, 5])\n    [1, 4, 12, 20]\n    >>> derivative([1, 2, 3])\n    [2, 6]\n    \"\"\"\n    # The derivative of a polynomial is calculated by multiplying each coefficient\n    # by its corresponding power and reducing the power by one.\n    return [i * coeff for i, coeff in enumerate(xs[1:], start=1)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n    \"\"\"Check if a number is prime.\"\"\"\n    if num <= 1:\n        return False\n    for i in range(2, int(num**0.5) + 1):\n        if num % i == 0:\n            return False\n    return True\ndef count_up_to(n):\n    \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n    primes = []\n    for i in range(2, n):\n        if is_prime(i):\n            primes.append(i)\n    return primes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n    \"\"\"\n    Check if two words have the same characters.\n    \n    Two words have the same characters if they contain the same unique characters,\n    regardless of the number of times each character appears.\n\n    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n    True\n    >>> same_chars('abcd', 'dddddddabc')\n    True\n    >>> same_chars('dddddddabc', 'abcd')\n    True\n    >>> same_chars('eabcd', 'dddddddabc')\n    False\n    >>> same_chars('abcd', 'dddddddabce')\n    False\n    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n    False\n    \"\"\"\n    return set(s0) == set(s1)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n    \"\"\"Add two numbers x and y.\n    \n    >>> add(2, 3)\n    5\n    >>> add(5, 7)\n    12\n    \"\"\"\n    return x + y", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n    \"\"\"\n    Given a string s, count the number of uppercase vowels in even indices.\n    \n    For example:\n    count_upper('aBCdEf') returns 1\n    count_upper('abcdefg') returns 0\n    count_upper('dBBE') returns 0\n    \"\"\"\n    uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n    count = 0\n    \n    for i in range(0, len(s), 2):  # Iterate over even indices\n        if s[i] in uppercase_vowels:\n            count += 1\n            \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n    \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n    \n    >>> fizz_buzz(50)\n    0\n    >>> fizz_buzz(78)\n    2\n    >>> fizz_buzz(79)\n    3\n    \"\"\"\n    count_of_sevens = 0\n    \n    for i in range(n):\n        if i % 11 == 0 or i % 13 == 0:\n            count_of_sevens += str(i).count('7')\n    \n    return count_of_sevens", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n    \"\"\"Return only positive numbers in the list.\n    \n    >>> get_positive([-1, 2, -4, 5, 6])\n    [2, 5, 6]\n    >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n    [5, 3, 2, 3, 9, 123, 1]\n    \"\"\"\n    return [x for x in l if x > 0]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n    \"\"\"This function takes a list l and returns a list l' such that\n    l' is identical to l in the odd indices, while its values at the even indices are equal\n    to the values of the even indices of l, but sorted.\n    \n    >>> sort_even([1, 2, 3])\n    [1, 2, 3]\n    >>> sort_even([5, 6, 3, 4])\n    [3, 6, 5, 4]\n    \"\"\"\n    # Extract even indexed elements\n    even_indices = [l[i] for i in range(0, len(l), 2)]\n    \n    # Sort the even indexed elements\n    even_indices.sort()\n    \n    # Create a new list to hold the result\n    result = l[:]  # Start with a copy of the original list\n    \n    # Place the sorted even indexed elements back into their positions\n    for i, value in enumerate(even_indices):\n        result[i * 2] = value\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n    \"\"\"Check if a number is prime.\"\"\"\n    if num <= 1:\n        return False\n    if num <= 3:\n        return True\n    if num % 2 == 0 or num % 3 == 0:\n        return False\n    i = 5\n    while i * i <= num:\n        if num % i == 0 or num % (i + 2) == 0:\n            return False\n        i += 6\n    return True\ndef prime_fib(n: int) -> int:\n    \"\"\"\n    prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n    >>> prime_fib(1)\n    2\n    >>> prime_fib(2)\n    3\n    >>> prime_fib(3)\n    5\n    >>> prime_fib(4)\n    13\n    >>> prime_fib(5)\n    89\n    \"\"\"\n    count = 0\n    for fib in fibonacci_generator():\n        if is_prime(fib):\n            count += 1\n            if count == n:\n                return fib", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[1]], "plus_fail_tests": [[11]]}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n    \"\"\"Return True if all numbers in the list l are below threshold t.\n    \n    >>> below_threshold([1, 2, 4, 10], 100)\n    True\n    >>> below_threshold([1, 20, 4, 10], 5)\n    False\n    \"\"\"\n    return all(x < t for x in l)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n    '''\n    Create a function that takes a value (string) representing a number\n    and returns the closest integer to it. If the number is equidistant\n    from two integers, round it away from zero.\n\n    Examples\n    >>> closest_integer(\"10\")\n    10\n    >>> closest_integer(\"15.3\")\n    15\n    >>> closest_integer(\"14.5\")\n    15\n    >>> closest_integer(\"-14.5\")\n    -15\n    >>> closest_integer(\"0.5\")\n    1\n    >>> closest_integer(\"-0.5\")\n    -1\n    '''\n    # Convert the string to a float\n    num = float(value)\n    \n    # Use the built-in round function with a custom rounding strategy\n    if num > 0:\n        return int(num + 0.5)  # Round up for positive numbers\n    elif num < 0:\n        return int(num - 0.5)  # Round down for negative numbers\n    else:\n        return 0  # Return 0 for the input \"0\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n    \"\"\"Return n-th Fibonacci number.\n    \n    >>> fib(10)\n    55\n    >>> fib(1)\n    1\n    >>> fib(8)\n    21\n    \"\"\"\n    if n <= 0:\n        raise ValueError(\"Input must be a positive integer.\")\n    elif n == 1:\n        return 1\n    elif n == 2:\n        return 1\n    else:\n        a, b = 1, 1\n        for _ in range(2, n):\n            a, b = b, a + b\n        return b", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[0]]}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n    \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n    fibfib(0) == 0\n    fibfib(1) == 0\n    fibfib(2) == 1\n    fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n    \n    Args:\n        n (int): The index of the FibFib number to compute.\n        \n    Returns:\n        int: The n-th FibFib number.\n    \n    Examples:\n        >>> fibfib(1)\n        0\n        >>> fibfib(5)\n        4\n        >>> fibfib(8)\n        24\n    \"\"\"\n    if n == 0:\n        return 0\n    elif n == 1:\n        return 0\n    elif n == 2:\n        return 1\n    \n    # Initialize the first three FibFib numbers\n    fibfib_numbers = [0, 0, 1]\n    \n    # Compute FibFib numbers iteratively\n    for i in range(3, n + 1):\n        next_fibfib = fibfib_numbers[i - 1] + fibfib_numbers[i - 2] + fibfib_numbers[i - 3]\n        fibfib_numbers.append(next_fibfib)\n    \n    return fibfib_numbers[n]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n    \"\"\"Complete the function that takes two integers and returns \n    the product of their unit digits.\n    Assume the input is always valid.\n    Examples:\n    multiply(148, 412) should return 16.\n    multiply(19, 28) should return 72.\n    multiply(2020, 1851) should return 0.\n    multiply(14,-15) should return 20.\n    \"\"\"\n    # Get the unit digit of the first number\n    unit_digit_a = abs(a) % 10\n    # Get the unit digit of the second number\n    unit_digit_b = abs(b) % 10\n    # Return the product of the unit digits\n    return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n    \"\"\"\n    You are given a list of integers.\n    Write a function next_smallest() that returns the 2nd smallest element of the list.\n    Return None if there is no such element.\n    \n    next_smallest([1, 2, 3, 4, 5]) == 2\n    next_smallest([5, 1, 4, 3, 2]) == 2\n    next_smallest([]) == None\n    next_smallest([1, 1]) == None\n    \"\"\"\n    # Remove duplicates by converting the list to a set\n    unique_elements = set(lst)\n    \n    # If there are less than 2 unique elements, return None\n    if len(unique_elements) < 2:\n        return None\n    \n    # Sort the unique elements\n    sorted_elements = sorted(unique_elements)\n    \n    # Return the second smallest element\n    return sorted_elements[1]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n    \"\"\"Write a function vowels_count which takes a string representing\n    a word as input and returns the number of vowels in the string.\n    Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n    vowel, but only when it is at the end of the given word.\n\n    Example:\n    >>> vowels_count(\"abcde\")\n    2\n    >>> vowels_count(\"ACEDY\")\n    3\n    \"\"\"\n    vowels = 'aeiou'\n    count = 0\n    s = s.lower()  # Convert to lowercase to handle case insensitivity\n\n    for i in range(len(s)):\n        if s[i] in vowels:\n            count += 1\n        elif s[i] == 'y' and i == len(s) - 1:  # Check if 'y' is at the end\n            count += 1\n\n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef words_in_sentence(sentence):\n    \"\"\"\n    You are given a string representing a sentence,\n    the sentence contains some words separated by a space,\n    and you have to return a string that contains the words from the original sentence,\n    whose lengths are prime numbers,\n    the order of the words in the new string should be the same as the original one.\n\n    Example 1:\n        Input: sentence = \"This is a test\"\n        Output: \"is\"\n\n    Example 2:\n        Input: sentence = \"lets go for swimming\"\n        Output: \"go for\"\n\n    Constraints:\n        * 1 <= len(sentence) <= 100\n        * sentence contains only letters\n    \"\"\"\n    words = sentence.split()\n    prime_length_words = [word for word in words if is_prime(len(word))]\n    return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n    \"\"\"Simplifies the expression x * n and checks if the result is a whole number.\n    \n    Args:\n        x (str): A string representation of a fraction in the format 'numerator/denominator'.\n        n (str): A string representation of a fraction in the format 'numerator/denominator'.\n    \n    Returns:\n        bool: True if x * n evaluates to a whole number, False otherwise.\n    \"\"\"\n    # Split the fractions into numerator and denominator\n    x_numerator, x_denominator = map(int, x.split('/'))\n    n_numerator, n_denominator = map(int, n.split('/'))\n    \n    # Calculate the product of the fractions\n    # x * n = (x_numerator / x_denominator) * (n_numerator / n_denominator)\n    # This simplifies to (x_numerator * n_numerator) / (x_denominator * n_denominator)\n    numerator_product = x_numerator * n_numerator\n    denominator_product = x_denominator * n_denominator\n    \n    # Check if the result is a whole number\n    return numerator_product % denominator_product == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n    \"\"\"In this problem, you will implement a function that takes two lists of numbers,\n    and determines whether it is possible to perform an exchange of elements\n    between them to make lst1 a list of only even numbers.\n    There is no limit on the number of exchanged elements between lst1 and lst2.\n    If it is possible to exchange elements between the lst1 and lst2 to make\n    all the elements of lst1 to be even, return \"YES\".\n    Otherwise, return \"NO\".\n    For example:\n    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"YES\"\n    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n    It is assumed that the input lists will be non-empty.\n    \"\"\"\n    \n    # Check if all elements in lst1 are even\n    if all(x % 2 == 0 for x in lst1):\n        return \"YES\"\n    \n    # Count the number of odd elements in lst1\n    odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n    \n    # Count the number of even elements in lst2\n    even_count_lst2 = sum(1 for x in lst2 if x % 2 == 0)\n    \n    # If there are enough even numbers in lst2 to replace all odd numbers in lst1\n    if odd_count_lst1 <= even_count_lst2:\n        return \"YES\"\n    \n    return \"NO\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n    \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n    \n    >>> string_sequence(0)\n    '0'\n    >>> string_sequence(5)\n    '0 1 2 3 4 5'\n    \"\"\"\n    return ' '.join(str(i) for i in range(n + 1))", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[999991]]}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n    \"\"\"\n    You are given an array arr of integers and you need to return\n    sum of magnitudes of integers multiplied by product of all signs\n    of each number in the array, represented by 1, -1 or 0.\n    Note: return None for empty arr.\n\n    Example:\n    >>> prod_signs([1, 2, 2, -4]) == -9\n    >>> prod_signs([0, 1]) == 0\n    >>> prod_signs([]) == None\n    \"\"\"\n    if not arr:\n        return None\n\n    product_of_signs = 1\n    sum_of_magnitudes = 0\n\n    for num in arr:\n        if num > 0:\n            product_of_signs *= 1\n            sum_of_magnitudes += num\n        elif num < 0:\n            product_of_signs *= -1\n            sum_of_magnitudes += -num\n        else:  # num == 0\n            product_of_signs = 0\n            break\n\n    return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n    \"\"\"Given a string s and a natural number n, returns a list of all words from \n    string s that contain exactly n consonants, in the order they appear in the string s.\n    \n    Args:\n    s (str): The input string containing words.\n    n (int): The number of consonants to filter words by.\n    \n    Returns:\n    list: A list of words containing exactly n consonants.\n    \"\"\"\n    if not s:\n        return []\n\n    # Define a set of consonants\n    consonants = set(\"bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ\")\n    \n    # Split the string into words\n    words = s.split()\n    \n    # Function to count consonants in a word\n    def count_consonants(word):\n        return sum(1 for char in word if char in consonants)\n    \n    # Filter words based on the number of consonants\n    result = [word for word in words if count_consonants(word) == n]\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n    \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n    \n    Examples\n    solution([5, 8, 7, 1]) ==> 12\n    solution([3, 3, 3, 3, 3]) ==> 9\n    solution([30, 13, 24, 321]) ==> 0\n    \"\"\"\n    return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n    '''\n    You are given a list of two strings, both strings consist of open\n    parentheses '(' or close parentheses ')' only.\n    Your job is to check if it is possible to concatenate the two strings in\n    some order, that the resulting string will be good.\n    A string S is considered to be good if and only if all parentheses in S\n    are balanced. For example: the string '(())()' is good, while the string\n    '())' is not.\n    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n    Examples:\n    match_parens(['()(', ')']) == 'Yes'\n    match_parens([')', ')']) == 'No'\n    '''\n\n    def is_good(s):\n        balance = 0\n        for char in s:\n            if char == '(':\n                balance += 1\n            else:  # char == ')'\n                balance -= 1\n            if balance < 0:  # More closing than opening\n                return False\n        return balance == 0  # Must be balanced at the end\n\n    # Check both concatenation orders\n    return 'Yes' if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]) else 'No'", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n    '''\n    Given a list of numbers, return whether or not they are sorted\n    in ascending order. If list has more than 1 duplicate of the same\n    number, return False. Assume no negative numbers and only integers.\n\n    Examples\n    is_sorted([5]) \u279e True\n    is_sorted([1, 2, 3, 4, 5]) \u279e True\n    is_sorted([1, 3, 2, 4, 5]) \u279e False\n    is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n    is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n    is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n    is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n    is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n    '''\n    if len(lst) <= 1:\n        return True\n\n    seen = set()\n    last_num = None\n\n    for num in lst:\n        if num in seen:\n            return False\n        seen.add(num)\n\n        if last_num is not None and num < last_num:\n            return False\n        \n        last_num = num\n\n    return True", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": [[[1, 1, 2, 2, 3, 3, 4]]]}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n    \"\"\"\n    Write a function which sorts the given list of integers\n    in ascending order according to the sum of their digits.\n    Note: if there are several items with similar sum of their digits,\n    order them based on their index in original list.\n\n    For example:\n    >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n    >>> order_by_points([]) == []\n    \"\"\"\n    \n    def digit_sum(n):\n        \"\"\"Calculate the sum of the digits of a number.\"\"\"\n        return sum(int(digit) for digit in str(abs(n)))\n\n    # Sort the list based on the sum of digits and original index\n    return sorted(nums, key=lambda x: (digit_sum(x), nums.index(x)))", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": [[[-5, -12, 9, 15]]]}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n    \"\"\"\n    This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n    multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n    change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n    \n    Examples:\n    For lst = [1,2,3] the output should be 6\n    For lst = []  the output should be 0\n    For lst = [-1,-5,2,-1,-5]  the output should be -126\n    \"\"\"\n    total = 0\n    for index, value in enumerate(lst):\n        if index % 3 == 0:\n            total += value ** 2\n        elif index % 4 == 0:\n            total += value ** 3\n        else:\n            total += value\n    return total", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef intersection(interval1, interval2):\n    \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n    start1, end1 = interval1\n    start2, end2 = interval2\n    \n    # Find the intersection\n    start_intersection = max(start1, start2)\n    end_intersection = min(end1, end2)\n    \n    # Check if there is an intersection\n    if start_intersection > end_intersection:\n        return \"NO\"\n    \n    # Calculate the length of the intersection\n    length_of_intersection = end_intersection - start_intersection\n    \n    # Check if the length is a prime number\n    if is_prime(length_of_intersection):\n        return \"YES\"\n    else:\n        return \"NO\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n    \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n    two consonants from the right side of the word (case sensitive).\n    \n    Vowels in the beginning and ending don't count. Return empty string if you didn't\n    find any vowel that meets the above condition. \n\n    You may assume that the given string contains English letters only.\n\n    Example:\n    get_closest_vowel(\"yogurt\") ==> \"u\"\n    get_closest_vowel(\"FULL\") ==> \"U\"\n    get_closest_vowel(\"quick\") ==> \"\"\n    get_closest_vowel(\"ab\") ==> \"\"\n    \"\"\"\n    vowels = \"aeiouAEIOU\"\n    n = len(word)\n\n    # Start from the end of the word\n    for i in range(n - 2, 0, -1):  # Start from the second last character to the second character\n        if word[i] in vowels:\n            # Check if there are consonants on both sides\n            if word[i - 1].isalpha() and word[i + 1].isalpha() and word[i - 1] not in vowels and word[i + 1] not in vowels:\n                return word[i]\n    \n    return \"\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n    \"\"\"\n    Given an array arr of integers and a positive integer k, return a sorted list \n    of length k with the maximum k numbers in arr.\n\n    Example 1:\n\n        Input: arr = [-3, -4, 5], k = 3\n        Output: [-4, -3, 5]\n\n    Example 2:\n\n        Input: arr = [4, -4, 4], k = 2\n        Output: [4, 4]\n\n    Example 3:\n\n        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n        Output: [2]\n\n    Note:\n        1. The length of the array will be in the range of [1, 1000].\n        2. The elements in the array will be in the range of [-1000, 1000].\n        3. 0 <= k <= len(arr)\n    \"\"\"\n    # Sort the array in descending order\n    sorted_arr = sorted(arr, reverse=True)\n    # Get the top k elements\n    top_k = sorted_arr[:k]\n    # Sort the result in ascending order before returning\n    return sorted(top_k)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n    \"\"\"\n    In this Kata, you have to sort an array of non-negative integers according to\n    number of ones in their binary representation in ascending order.\n    For similar number of ones, sort based on decimal value.\n\n    It must be implemented like this:\n    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n    >>> sort_array([1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]\n    \"\"\"\n    # Sort the array using a custom key\n    return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n    \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n    of the letter with the most repetition and containing the corresponding count.\n    If several letters have the same occurrence, return all of them.\n    \n    Example:\n    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n    histogram('a b b a') == {'a': 2, 'b': 2}\n    histogram('a b c a b') == {'a': 2, 'b': 2}\n    histogram('b b b b a') == {'b': 4}\n    histogram('') == {}\n    \"\"\"\n    if not test:\n        return {}\n\n    # Split the input string into a list of letters\n    letters = test.split()\n    \n    # Create a dictionary to count occurrences of each letter\n    count_dict = {}\n    for letter in letters:\n        if letter in count_dict:\n            count_dict[letter] += 1\n        else:\n            count_dict[letter] = 1\n\n    # Find the maximum count\n    max_count = max(count_dict.values())\n    \n    # Create a result dictionary for letters with the maximum count\n    result = {letter: count for letter, count in count_dict.items() if count == max_count}\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n    from collections import deque\n\n    N = len(grid)\n    directions = [(0, 1), (1, 0), (0, -1), (-1, 0)]  # right, down, left, up\n    min_path = None\n\n    def dfs(x, y, path):\n        nonlocal min_path\n        if len(path) == k:\n            if min_path is None or path < min_path:\n                min_path = path[:]\n            return\n        \n        for dx, dy in directions:\n            nx, ny = x + dx, y + dy\n            if 0 <= nx < N and 0 <= ny < N:\n                path.append(grid[nx][ny])\n                dfs(nx, ny, path)\n                path.pop()\n\n    for i in range(N):\n        for j in range(N):\n            dfs(i, j, [grid[i][j]])\n\n    return min_path", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": [[[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 15]]}]}}
\ No newline at end of file
diff --git a/EVALPLUS-4omini/3.json b/EVALPLUS-4omini/3.json
deleted file mode 100644
index e93e5ff15..000000000
--- a/EVALPLUS-4omini/3.json
+++ /dev/null
@@ -1 +0,0 @@
-{"date": "2024-07-20 13:00", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n    \"\"\"\n    Given two positive integers a and b, return the even digits between a\n    and b, in ascending order.\n\n    For example:\n    generate_integers(2, 8) => [2, 4, 6, 8]\n    generate_integers(8, 2) => [2, 4, 6, 8]\n    generate_integers(10, 14) => []\n    \"\"\"\n    # Determine the range of numbers to consider\n    start = min(a, b)\n    end = max(a, b)\n\n    # Generate a list of even integers in the specified range\n    even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n    return even_integers", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[2, 10]], "plus_fail_tests": [[6, 12]]}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def compare_one(a, b):\n    \"\"\"\n    Create a function that takes integers, floats, or strings representing\n    real numbers, and returns the larger variable in its given variable type.\n    Return None if the values are equal.\n    Note: If a real number is represented as a string, the floating point might be . or ,\n\n    compare_one(1, 2.5) \u279e 2.5\n    compare_one(1, \"2,3\") \u279e \"2,3\"\n    compare_one(\"5,1\", \"6\") \u279e \"6\"\n    compare_one(\"1\", 1) \u279e None\n    \"\"\"\n    \n    def parse_value(value):\n        \"\"\"Convert the input value to a float or return it as is if it's a string.\"\"\"\n        if isinstance(value, str):\n            # Replace comma with dot for float conversion\n            value = value.replace(',', '.')\n            try:\n                return float(value)\n            except ValueError:\n                return value  # Return the string if it cannot be converted\n        return value\n\n    # Parse both values\n    parsed_a = parse_value(a)\n    parsed_b = parse_value(b)\n\n    # Check for equality\n    if parsed_a == parsed_b:\n        return None\n\n    # Return the larger value in its original type\n    if parsed_a > parsed_b:\n        return a\n    else:\n        return b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n    \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n    Example:\n        even_odd_count(-12) ==> (1, 1)\n        even_odd_count(123) ==> (1, 2)\n    \"\"\"\n    # Convert the number to a string and remove the negative sign if present\n    num_str = str(abs(num))\n    \n    even_count = 0\n    odd_count = 0\n    \n    # Iterate through each character in the string representation of the number\n    for digit in num_str:\n        if digit.isdigit():  # Check if the character is a digit\n            if int(digit) % 2 == 0:\n                even_count += 1\n            else:\n                odd_count += 1\n    \n    return (even_count, odd_count)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n    \"\"\"Compares the actual game scores with the guessed scores and returns the absolute differences.\n    \n    Args:\n        game (list of int): The actual scores of the matches.\n        guess (list of int): The guessed scores of the matches.\n        \n    Returns:\n        list of int: A list containing the absolute differences between the actual scores and the guessed scores.\n                      If the guess is correct, the value is 0.\n    \"\"\"\n    return [abs(g - a) for a, g in zip(game, guess)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n    \"\"\"\n    Write a function count_nums which takes an array of integers and returns\n    the number of elements which has a sum of digits > 0.\n    If a number is negative, then its first signed digit will be negative:\n    e.g. -123 has signed digits -1, 2, and 3.\n    \n    >>> count_nums([]) == 0\n    >>> count_nums([-1, 11, -11]) == 1\n    >>> count_nums([1, 1, 2]) == 3\n    \"\"\"\n    def sum_of_digits(n):\n        # Convert the number to string and calculate the sum of its digits\n        # For negative numbers, we need to consider the first digit as negative\n        str_n = str(n)\n        if n < 0:\n            return -int(str_n[1]) + sum(int(digit) for digit in str_n[2:])\n        else:\n            return sum(int(digit) for digit in str_n)\n\n    count = 0\n    for num in arr:\n        if sum_of_digits(num) > 0:\n            count += 1\n            \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n    \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n    around the mean of this dataset.\n    Mean Absolute Deviation is the average absolute difference between each\n    element and a centerpoint (mean in this case):\n    MAD = average | x - x_mean |\n    \n    >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n    1.0\n    \"\"\"\n    if not numbers:\n        return 0.0  # Return 0 for empty list to avoid division by zero\n\n    mean_value = sum(numbers) / len(numbers)\n    mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n    return mad", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def factorial(i):\n    \"\"\"Calculate the factorial of a given number i.\"\"\"\n    if i == 0 or i == 1:\n        return 1\n    result = 1\n    for j in range(2, i + 1):\n        result *= j\n    return result\ndef sum_of_numbers(i):\n    \"\"\"Calculate the sum of numbers from 1 to i.\"\"\"\n    return (i * (i + 1)) // 2\ndef f(n):\n    \"\"\"Return a list of size n, where the value at index i is the factorial of i if i is even,\n    or the sum of numbers from 1 to i if i is odd. Indexing starts from 1.\n    \"\"\"\n    result = []\n    for i in range(1, n + 1):\n        if i % 2 == 0:  # i is even\n            result.append(factorial(i))\n        else:           # i is odd\n            result.append(sum_of_numbers(i))\n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n    \"\"\"\n    You will be given a string of words separated by commas or spaces. Your task is\n    to split the string into words and return an array of the words.\n    \n    For example:\n    words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n    words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n    \"\"\"\n    # Split the string by commas and spaces, then filter out any empty strings\n    words = [word.strip() for word in s.replace(',', ' ').split() if word]\n    return words", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n    \"\"\" \n    You're given a list of deposit and withdrawal operations on a bank account that starts with\n    zero balance. Your task is to detect if at any point the balance of account falls below zero, and\n    at that point function should return True. Otherwise it should return False.\n    \n    >>> below_zero([1, 2, 3])\n    False\n    >>> below_zero([1, 2, -4, 5])\n    True\n    \"\"\"\n    balance = 0\n    for operation in operations:\n        balance += operation\n        if balance < 0:\n            return True\n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n    \"\"\"\n    Given a string 'text', return its md5 hash equivalent string.\n    If 'text' is an empty string, return None.\n\n    >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n    >>> string_to_md5('') is None\n    >>> string_to_md5('Python') == '5d41402abc4b2a76b9719d911017c592'\n    \"\"\"\n    if text == \"\":\n        return None\n    md5_hash = hashlib.md5(text.encode()).hexdigest()\n    return md5_hash", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n    \"\"\"Find the strongest extension based on the defined strength criteria.\"\"\"\n    strongest_extension = None\n    max_strength = float('-inf')  # Start with the lowest possible strength\n\n    for extension in extensions:\n        # Calculate the strength of the current extension\n        CAP = sum(1 for char in extension if char.isupper())\n        SM = sum(1 for char in extension if char.islower())\n        strength = CAP - SM\n\n        # Check if this extension is stronger than the current strongest\n        if strength > max_strength:\n            max_strength = strength\n            strongest_extension = extension\n\n    # Return the result in the specified format\n    return f\"{class_name}.{strongest_extension}\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n    \"\"\"Check if the second word or any of its rotations is a substring in the first word.\n    \n    Args:\n    a (str): The first word.\n    b (str): The second word.\n    \n    Returns:\n    bool: True if the second word or any of its rotations is a substring of the first word, False otherwise.\n    \n    Examples:\n    >>> cycpattern_check(\"abcd\", \"abd\")\n    False\n    >>> cycpattern_check(\"hello\", \"ell\")\n    True\n    >>> cycpattern_check(\"whassup\", \"psus\")\n    False\n    >>> cycpattern_check(\"abab\", \"baa\")\n    True\n    >>> cycpattern_check(\"efef\", \"eeff\")\n    False\n    >>> cycpattern_check(\"himenss\", \"simen\")\n    True\n    \"\"\"\n    # Create a string that contains all rotations of b\n    rotations = [b[i:] + b[:i] for i in range(len(b))]\n    \n    # Check if any rotation is a substring of a\n    for rotation in rotations:\n        if rotation in a:\n            return True\n            \n    return False", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["", ""]]}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n    \"\"\"\n    Given a positive integer n, you have to make a pile of n levels of stones.\n    The first level has n stones.\n    The number of stones in the next level is:\n        - the next odd number if n is odd.\n        - the next even number if n is even.\n    Return the number of stones in each level in a list, where element at index\n    i represents the number of stones in the level (i+1).\n\n    Examples:\n    >>> make_a_pile(3)\n    [3, 5, 7]\n    >>> make_a_pile(4)\n    [4, 6, 8, 10]\n    >>> make_a_pile(1)\n    [1]\n    \"\"\"\n    stones = []\n    current_stones = n\n    \n    for i in range(n):\n        stones.append(current_stones)\n        if current_stones % 2 == 0:  # current_stones is even\n            current_stones += 2  # next even number\n        else:  # current_stones is odd\n            current_stones += 2  # next odd number\n    \n    return stones", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n    \"\"\" Given a positive floating point number, it can be decomposed into\n    an integer part (largest integer smaller than given number) and decimals\n    (leftover part always smaller than 1).\n\n    Return the decimal part of the number.\n    \n    >>> truncate_number(3.5)\n    0.5\n    >>> truncate_number(7.25)\n    0.25\n    >>> truncate_number(10.0)\n    0.0\n    >>> truncate_number(5.99)\n    0.99\n    \"\"\"\n    if number < 0:\n        raise ValueError(\"The number must be positive.\")\n    \n    integer_part = int(number)  # Get the integer part\n    decimal_part = number - integer_part  # Calculate the decimal part\n    return decimal_part", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n    \"\"\"Calculate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n    if n < 0:\n        return []\n\n    # Initialize the list to store the Tribonacci numbers\n    tribonacci_sequence = []\n\n    # Define the base cases\n    for i in range(n + 1):\n        if i == 0:\n            tribonacci_sequence.append(1)  # tri(0) = 1\n        elif i == 1:\n            tribonacci_sequence.append(3)  # tri(1) = 3\n        elif i % 2 == 0:  # Even case\n            tribonacci_sequence.append(1 + i / 2)\n        else:  # Odd case\n            tri_n_minus_1 = tribonacci_sequence[i - 1]\n            tri_n_minus_2 = tribonacci_sequence[i - 2]\n            tri_n_plus_1 = tribonacci_sequence[i + 1] if i + 1 <= n else 0\n            tribonacci_sequence.append(tri_n_minus_1 + tri_n_minus_2 + tri_n_plus_1)\n\n    return tribonacci_sequence", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[3]], "plus_fail_tests": [[10]]}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n    \"\"\"\n    Given a positive integer n, return a tuple that has the number of even and odd\n    integer palindromes that fall within the range(1, n), inclusive.\n\n    Example 1:\n        Input: 3\n        Output: (1, 2)\n        Explanation:\n        Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n    Example 2:\n        Input: 12\n        Output: (4, 6)\n        Explanation:\n        Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n    Note:\n        1. 1 <= n <= 10^3\n        2. returned tuple has the number of even and odd integer palindromes respectively.\n    \"\"\"\n    even_count = 0\n    odd_count = 0\n\n    for i in range(1, n + 1):\n        if str(i) == str(i)[::-1]:  # Check if the number is a palindrome\n            if i % 2 == 0:\n                even_count += 1\n            else:\n                odd_count += 1\n\n    return (even_count, odd_count)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n    \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n    \n    Args:\n        n (int): The number to evaluate.\n        \n    Returns:\n        bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n    \n    Example:\n    is_equal_to_sum_even(4) == False\n    is_equal_to_sum_even(6) == False\n    is_equal_to_sum_even(8) == True\n    \"\"\"\n    # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n    if n < 8:\n        return False\n    \n    # Check if n is even\n    if n % 2 != 0:\n        return False\n    \n    # If n is even and >= 8, it can be expressed as the sum of 4 positive even numbers\n    return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n    \"\"\" Insert a number 'delimiter' between every two consecutive elements of input list `numbers`\n    \n    >>> intersperse([], 4)\n    []\n    >>> intersperse([1, 2, 3], 4)\n    [1, 4, 2, 4, 3]\n    \"\"\"\n    if not numbers:\n        return []\n    \n    result = []\n    for i in range(len(numbers) - 1):\n        result.append(numbers[i])\n        result.append(delimiter)\n    result.append(numbers[-1])  # Append the last element\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n    \"\"\"Given a positive integer n, return the product of the odd digits.\n    Return 0 if all digits are even.\n    For example:\n    digits(1)  == 1\n    digits(4)  == 0\n    digits(235) == 15\n    \"\"\"\n    product = 1\n    has_odd = False\n    \n    for digit in str(n):\n        digit = int(digit)\n        if digit % 2 != 0:  # Check if the digit is odd\n            product *= digit\n            has_odd = True\n            \n    return product if has_odd else 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n    '''\n    Create a function that returns a tuple (a, b), where 'a' is\n    the largest of negative integers, and 'b' is the smallest\n    of positive integers in a list.\n    If there is no negative or positive integers, return them as None.\n\n    Examples:\n    largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n    largest_smallest_integers([]) == (None, None)\n    largest_smallest_integers([0]) == (None, None)\n    '''\n    largest_negative = None\n    smallest_positive = None\n\n    for num in lst:\n        if num < 0:\n            if largest_negative is None or num > largest_negative:\n                largest_negative = num\n        elif num > 0:\n            if smallest_positive is None or num < smallest_positive:\n                smallest_positive = num\n\n    return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n    \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n    numbers in the array will be randomly ordered. Your task is to determine if\n    it is possible to get an array sorted in non-decreasing order by performing \n    the following operation on the given array:\n        You are allowed to perform right shift operation any number of times.\n    \n    One right shift operation means shifting all elements of the array by one\n    position in the right direction. The last element of the array will be moved to\n    the starting position in the array i.e. 0th index. \n\n    If it is possible to obtain the sorted array by performing the above operation\n    then return True else return False.\n    If the given array is empty then return True.\n\n    Note: The given list is guaranteed to have unique elements.\n\n    For Example:\n    \n    move_one_ball([3, 4, 5, 1, 2])==>True\n    Explanation: By performing 2 right shift operations, non-decreasing order can\n                 be achieved for the given array.\n    move_one_ball([3, 5, 4, 1, 2])==>False\n    Explanation: It is not possible to get non-decreasing order for the given\n                array by performing any number of right shift operations.\n    \"\"\"\n    if not arr:\n        return True\n\n    n = len(arr)\n    sorted_arr = sorted(arr)\n    \n    # Check for the number of \"breaks\" in the sorted array\n    break_count = 0\n    for i in range(n):\n        if arr[i] > arr[(i + 1) % n]:\n            break_count += 1\n\n    # If there are more than one break, we cannot sort the array with shifts\n    return break_count <= 1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n    \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n    other and return them in order (smaller number, larger number).\n    \n    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n    (2.0, 2.2)\n    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n    (2.0, 2.0)\n    \"\"\"\n    # Sort the numbers to make it easier to find the closest pair\n    sorted_numbers = sorted(numbers)\n    \n    # Initialize the minimum difference and the closest pair\n    min_diff = float('inf')\n    closest_pair = (0.0, 0.0)\n    \n    # Iterate through the sorted list to find the closest elements\n    for i in range(len(sorted_numbers) - 1):\n        diff = sorted_numbers[i + 1] - sorted_numbers[i]\n        if diff < min_diff:\n            min_diff = diff\n            closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n    \n    return closest_pair", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n    \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n    \n    >>> flip_case('Hello')\n    'hELLO'\n    >>> flip_case('Python')\n    'pYTHON'\n    >>> flip_case('123abcXYZ')\n    '123ABCxyz'\n    >>> flip_case('')\n    ''\n    \"\"\"\n    return string.swapcase()", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n    \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n    \n    >>> how_many_times('', 'a')\n    0\n    >>> how_many_times('aaa', 'a')\n    3\n    >>> how_many_times('aaaa', 'aa')\n    3\n    \"\"\"\n    count = 0\n    start = 0\n    \n    while True:\n        start = string.find(substring, start)\n        if start == -1:\n            break\n        count += 1\n        start += 1  # Move to the next character to allow for overlapping matches\n    \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n    \"\"\" Input are two strings a and b consisting only of 1s and 0s.\n    Perform binary XOR on these inputs and return result also as a string.\n    \n    >>> string_xor('010', '110')\n    '100'\n    >>> string_xor('111', '000')\n    '111'\n    >>> string_xor('101', '101')\n    '000'\n    >>> string_xor('000', '000')\n    '000'\n    >>> string_xor('1101', '1011')\n    '0110'\n    \"\"\"\n    # Ensure both strings are of the same length\n    max_len = max(len(a), len(b))\n    a = a.zfill(max_len)\n    b = b.zfill(max_len)\n    \n    # Perform XOR operation\n    result = []\n    for bit_a, bit_b in zip(a, b):\n        result.append('1' if bit_a != bit_b else '0')\n    \n    return ''.join(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n    \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n    >>> count_distinct_characters('xyzXYZ')\n    3\n    >>> count_distinct_characters('Jerry')\n    4\n    \"\"\"\n    # Convert the string to lowercase to ensure case insensitivity\n    lower_string = string.lower()\n    # Use a set to find distinct characters\n    distinct_characters = set(lower_string)\n    # Return the number of distinct characters\n    return len(distinct_characters)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n    \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n    \n    >>> filter_by_prefix([], 'a')\n    []\n    >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n    ['abc', 'array']\n    \"\"\"\n    return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n    \"\"\"Create a function encrypt that takes a string as an argument and\n    returns a string encrypted with the alphabet being rotated. \n    The alphabet should be rotated in a manner such that the letters \n    shift down by two multiplied to two places.\n    For example:\n    encrypt('hi') returns 'lm'\n    encrypt('asdfghjkl') returns 'ewhjklnop'\n    encrypt('gf') returns 'kj'\n    encrypt('et') returns 'ix'\n    \"\"\"\n    encrypted = []\n    for char in s:\n        if char.isalpha():  # Check if the character is a letter\n            # Calculate the new character by shifting it down by 4 places\n            new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a')) if char.islower() else \\\n                        chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n            encrypted.append(new_char)\n        else:\n            encrypted.append(char)  # Non-alphabetic characters remain unchanged\n    return ''.join(encrypted)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n    \"\"\"Return list with elements incremented by 1.\n    \n    >>> incr_list([1, 2, 3])\n    [2, 3, 4]\n    >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n    [6, 4, 6, 3, 4, 4, 10, 1, 124]\n    \"\"\"\n    return [x + 1 for x in l]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n    \"\"\"Given length of a side and height, return the area of a triangle.\n    \n    The area of a triangle can be calculated using the formula:\n    area = (base * height) / 2\n    \n    Parameters:\n    a (float): The length of the base of the triangle.\n    h (float): The height of the triangle.\n    \n    Returns:\n    float: The area of the triangle.\n    \n    >>> triangle_area(5, 3)\n    7.5\n    >>> triangle_area(10, 2)\n    10.0\n    >>> triangle_area(0, 5)\n    0.0\n    >>> triangle_area(5, 0)\n    0.0\n    \"\"\"\n    return (a * h) / 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n    \"\"\"\n    You are given a 2 dimensional data, as a nested lists,\n    which is similar to matrix, however, unlike matrices,\n    each row may contain a different number of columns.\n    Given lst, and integer x, find integers x in the list,\n    and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n    each tuple is a coordinate - (row, columns), starting with 0.\n    Sort coordinates initially by rows in ascending order.\n    Also, sort coordinates of the row by columns in descending order.\n    \n    Examples:\n    get_row([\n      [1,2,3,4,5,6],\n      [1,2,3,4,1,6],\n      [1,2,3,4,5,1]\n    ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n    get_row([], 1) == []\n    get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n    \"\"\"\n    coordinates = []\n    \n    for row_index, row in enumerate(lst):\n        for col_index, value in enumerate(row):\n            if value == x:\n                coordinates.append((row_index, col_index))\n    \n    # Sort by row index (ascending) and then by column index (descending)\n    coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n    \n    return coordinates", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n    \"\"\"\n    Given an array arr of integers, find the minimum number of elements that\n    need to be changed to make the array palindromic. A palindromic array is an array that\n    is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n    For example:\n    smallest_change([1,2,3,5,4,7,9,6]) == 4\n    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n    smallest_change([1, 2, 3, 2, 1]) == 0\n    \"\"\"\n    n = len(arr)\n    changes = 0\n    \n    # Compare elements from the start and end towards the center\n    for i in range(n // 2):\n        if arr[i] != arr[n - 1 - i]:\n            changes += 1\n            \n    return changes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n    '''\n    Write a function that accepts two lists of strings and returns the list that has \n    total number of chars in the all strings of the list less than the other list.\n\n    if the two lists have the same number of chars, return the first list.\n\n    Examples\n    total_match([], []) \u279e []\n    total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n    total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n    total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n    total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n    '''\n    # Calculate the total number of characters in each list\n    total_chars_lst1 = sum(len(s) for s in lst1)\n    total_chars_lst2 = sum(len(s) for s in lst2)\n\n    # Compare the total characters and return the appropriate list\n    if total_chars_lst1 < total_chars_lst2:\n        return lst1\n    else:\n        return lst2", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": [[["happy", "birthday", "sarah"], ["happy", "birthday", "sally"]]]}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n    \"\"\"You are given a string s.\n    Your task is to check if the string is happy or not.\n    A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n    \n    For example:\n    is_happy('a') => False\n    is_happy('aa') => False\n    is_happy('abcd') => True\n    is_happy('aabb') => False\n    is_happy('adb') => True\n    is_happy('xyy') => False\n    \"\"\"\n    # Check if the length of the string is at least 3\n    if len(s) < 3:\n        return False\n    \n    # Check every 3 consecutive characters\n    for i in range(len(s) - 2):\n        if len(set(s[i:i+3])) < 3:  # If there are not 3 distinct characters\n            return False\n            \n    return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n    \"\"\" Input to this function is a string representing musical notes in a special ASCII format.\n    Your task is to parse this string and return list of integers corresponding to how many beats does each\n    note last.\n\n    Here is a legend:\n    'o' - whole note, lasts four beats\n    'o|' - half note, lasts two beats\n    '.|' - quarter note, lasts one beat\n\n    >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n    [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n    \"\"\"\n    # Define a mapping of note representations to their corresponding beat values\n    note_to_beats = {\n        'o': 4,   # whole note\n        'o|': 2,  # half note\n        '.|': 1   # quarter note\n    }\n    \n    # Split the input string into individual notes\n    notes = music_string.split()\n    \n    # Parse the notes and convert them to their corresponding beat values\n    beats = [note_to_beats[note] for note in notes if note in note_to_beats]\n    \n    return beats", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n    \"\"\" Concatenate list of strings into a single string.\n    \n    Args:\n        strings (List[str]): A list of strings to concatenate.\n        \n    Returns:\n        str: A single concatenated string.\n    \n    Examples:\n        >>> concatenate([])\n        ''\n        >>> concatenate(['a', 'b', 'c'])\n        'abc'\n    \"\"\"\n    return ''.join(strings)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n    \"\"\" Test if given string is a palindrome \"\"\"\n    return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n    \"\"\" Find the shortest palindrome that begins with a supplied string.\n    Algorithm idea is simple:\n    - Find the longest postfix of supplied string that is a palindrome.\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n    \n    >>> make_palindrome('')\n    ''\n    >>> make_palindrome('cat')\n    'catac'\n    >>> make_palindrome('cata')\n    'catac'\n    \"\"\"\n    # Find the longest palindromic suffix\n    for i in range(len(string)):\n        if is_palindrome(string[i:]):\n            # If the suffix is a palindrome, take the prefix before it\n            prefix = string[:i]\n            # Append the reverse of the prefix to the original string\n            return string + prefix[::-1]\n    return string  # In case the string is empty or already a palindrome", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n    \"\"\" \n    Input is a space-delimited string of numerals from 'zero' to 'nine'.\n    Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n    Return the string with numbers sorted from smallest to largest.\n    \n    >>> sort_numbers('three one five')\n    'one three five'\n    \"\"\"\n    # Mapping of words to their corresponding numeric values\n    num_map = {\n        'zero': 0,\n        'one': 1,\n        'two': 2,\n        'three': 3,\n        'four': 4,\n        'five': 5,\n        'six': 6,\n        'seven': 7,\n        'eight': 8,\n        'nine': 9\n    }\n    \n    # Split the input string into words\n    words = numbers.split()\n    \n    # Sort the words based on their numeric values\n    sorted_words = sorted(words, key=lambda word: num_map[word])\n    \n    # Join the sorted words back into a string\n    return ' '.join(sorted_words)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n    \"\"\" From a list of integers, remove all elements that occur more than once.\n    Keep order of elements left the same as in the input.\n    \n    >>> remove_duplicates([1, 2, 3, 2, 4])\n    [1, 3, 4]\n    \"\"\"\n    # Count occurrences of each number\n    count = {}\n    for number in numbers:\n        count[number] = count.get(number, 0) + 1\n    \n    # Create a new list with elements that occur only once\n    result = [number for number in numbers if count[number] == 1]\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n    \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n    such that the smallest number will become 0 and the largest will become 1.\n    \n    >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n    [0.0, 0.25, 0.5, 0.75, 1.0]\n    \"\"\"\n    if len(numbers) < 2:\n        raise ValueError(\"The list must contain at least two elements.\")\n    \n    min_val = min(numbers)\n    max_val = max(numbers)\n    \n    # Avoid division by zero if all numbers are the same\n    if min_val == max_val:\n        return [0.0] * len(numbers)\n    \n    return [(num - min_val) / (max_val - min_val) for num in numbers]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef get_primes_up_to(limit):\n    \"\"\"Return a list of all prime numbers up to a given limit.\"\"\"\n    return [num for num in range(2, limit) if is_prime(num)]\ndef is_multiply_prime(a):\n    \"\"\"Return true if the given number is the multiplication of 3 prime numbers, false otherwise.\"\"\"\n    if a >= 100:\n        return False\n    \n    primes = get_primes_up_to(a)\n    prime_count = len(primes)\n    \n    # Check all combinations of three primes\n    for i in range(prime_count):\n        for j in range(i, prime_count):\n            for k in range(j, prime_count):\n                product = primes[i] * primes[j] * primes[k]\n                if product == a:\n                    return True\n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n    \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n    letter_grades = []\n    \n    for gpa in grades:\n        if gpa == 4.0:\n            letter_grades.append('A+')\n        elif gpa > 3.7:\n            letter_grades.append('A')\n        elif gpa > 3.3:\n            letter_grades.append('A-')\n        elif gpa > 3.0:\n            letter_grades.append('B+')\n        elif gpa > 2.7:\n            letter_grades.append('B')\n        elif gpa > 2.3:\n            letter_grades.append('B-')\n        elif gpa > 2.0:\n            letter_grades.append('C+')\n        elif gpa > 1.7:\n            letter_grades.append('C')\n        elif gpa > 1.3:\n            letter_grades.append('C-')\n        elif gpa > 1.0:\n            letter_grades.append('D+')\n        elif gpa > 0.7:\n            letter_grades.append('D')\n        elif gpa > 0.0:\n            letter_grades.append('D-')\n        else:\n            letter_grades.append('E')\n    \n    return letter_grades", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n    '''\n    Write a function that returns True if the object q will fly, and False otherwise.\n    The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n\n    Example:\n    will_it_fly([1, 2], 5) \u279e False \n    # 1+2 is less than the maximum possible weight, but it's unbalanced.\n\n    will_it_fly([3, 2, 3], 1) \u279e False\n    # it's balanced, but 3+2+3 is more than the maximum possible weight.\n\n    will_it_fly([3, 2, 3], 9) \u279e True\n    # 3+2+3 is less than the maximum possible weight, and it's balanced.\n\n    will_it_fly([3], 5) \u279e True\n    # 3 is less than the maximum possible weight, and it's balanced.\n    '''\n    # Check if the list is a palindrome\n    is_balanced = q == q[::-1]\n    \n    # Calculate the sum of the elements in the list\n    total_weight = sum(q)\n    \n    # Check if the object will fly\n    return is_balanced and total_weight <= w", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n    \"\"\"Change numerical base of input number x to base.\n    return string representation after the conversion.\n    base numbers are less than 10.\n    \n    >>> change_base(8, 3)\n    '22'\n    >>> change_base(8, 2)\n    '1000'\n    >>> change_base(7, 2)\n    '111'\n    \"\"\"\n    if base < 2 or base >= 10:\n        raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n    \n    if x == 0:\n        return '0'\n    \n    result = []\n    while x > 0:\n        result.append(str(x % base))\n        x //= base\n    \n    return ''.join(reversed(result))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n    \"\"\"\n    Write a function that takes a string and returns an ordered version of it.\n    Ordered version of string, is a string where all words (separated by space)\n    are replaced by a new word where all the characters arranged in\n    ascending order based on ascii value.\n    Note: You should keep the order of words and blank spaces in the sentence.\n\n    For example:\n    anti_shuffle('Hi') returns 'Hi'\n    anti_shuffle('hello') returns 'ehllo'\n    anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n    \"\"\"\n    # Split the string into words while preserving spaces\n    words = s.split(' ')\n    \n    # Sort each word and keep the spaces intact\n    sorted_words = [''.join(sorted(word)) for word in words]\n    \n    # Join the sorted words back with spaces\n    result = ' '.join(sorted_words)\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n    \"\"\"\n    Given an array of non-negative integers, return a copy of the given array after sorting,\n    you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n    or sort it in descending order if the sum( first index value, last index value) is even.\n\n    Note:\n    * don't change the given array.\n\n    Examples:\n    * sort_array([]) => []\n    * sort_array([5]) => [5]\n    * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n    * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n    \"\"\"\n    if not array:  # Check for empty array\n        return []\n    \n    first_value = array[0]\n    last_value = array[-1]\n    sum_values = first_value + last_value\n\n    # Create a copy of the array to sort\n    sorted_array = array.copy()\n\n    if sum_values % 2 == 0:  # Even sum\n        sorted_array.sort(reverse=True)  # Sort in descending order\n    else:  # Odd sum\n        sorted_array.sort()  # Sort in ascending order\n\n    return sorted_array", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n    \"\"\"\n    pairs_sum_to_zero takes a list of integers as an input.\n    it returns True if there are two distinct elements in the list that\n    sum to zero, and False otherwise.\n    \n    >>> pairs_sum_to_zero([1, 3, 5, 0])\n    False\n    >>> pairs_sum_to_zero([1, 3, -2, 1])\n    False\n    >>> pairs_sum_to_zero([1, 2, 3, 7])\n    False\n    >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n    True\n    >>> pairs_sum_to_zero([1])\n    False\n    \"\"\"\n    seen = set()\n    for number in l:\n        if -number in seen:\n            return True\n        seen.add(number)\n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n    \"\"\"\n    Given a dictionary, return True if all keys are strings in lower \n    case or all keys are strings in upper case, else return False.\n    The function should return False if the given dictionary is empty.\n    \n    Examples:\n    check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n    check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n    check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n    check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n    check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n    \"\"\"\n    if not input_dict:\n        return False\n\n    all_lower = all(isinstance(key, str) and key.islower() for key in input_dict.keys())\n    all_upper = all(isinstance(key, str) and key.isupper() for key in input_dict.keys())\n\n    return all_lower or all_upper", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n    \"\"\" \n    brackets is a string of \"(\" and \")\".\n    return True if every opening bracket has a corresponding closing bracket.\n\n    >>> correct_bracketing(\"(\")\n    False\n    >>> correct_bracketing(\"()\")\n    True\n    >>> correct_bracketing(\"(()())\")\n    True\n    >>> correct_bracketing(\")(()\")\n    False\n    \"\"\"\n    balance = 0\n    for char in brackets:\n        if char == '(':\n            balance += 1\n        elif char == ')':\n            balance -= 1\n        # If balance goes negative, there are unmatched closing brackets\n        if balance < 0:\n            return False\n    # At the end, balance should be zero for all opening brackets to be matched\n    return balance == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n    \"\"\"Task\n    Write a function that takes a string as input and returns the sum of the upper characters only'\n    ASCII codes.\n\n    Examples:\n        digitSum(\"\") => 0\n        digitSum(\"abAB\") => 131\n        digitSum(\"abcCd\") => 67\n        digitSum(\"helloE\") => 69\n        digitSum(\"woArBld\") => 131\n        digitSum(\"aAaaaXa\") => 153\n    \"\"\"\n    return sum(ord(char) for char in s if char.isupper())", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n    '''\n    Create a function that takes 3 numbers.\n    Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n    Returns false in any other cases.\n    \n    Examples\n    any_int(5, 2, 7) \u279e True\n    \n    any_int(3, 2, 2) \u279e False\n\n    any_int(3, -2, 1) \u279e True\n    \n    any_int(3.6, -2.2, 2) \u279e False\n    '''\n    # Check if all inputs are integers\n    if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n        # Check if one number is equal to the sum of the other two\n        return x == y + z or y == x + z or z == x + y\n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int):\n    \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n    >>> largest_prime_factor(13195)\n    29\n    >>> largest_prime_factor(2048)\n    2\n    \"\"\"\n    # Start with the smallest prime factor\n    factor = 2\n    # Keep dividing n by factor until it is no longer divisible\n    while n > 1:\n        if n % factor == 0:\n            n //= factor  # Divide n by the factor\n        else:\n            factor += 1  # Move to the next potential factor\n    return factor  # The last factor is the largest prime factor", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n    \"\"\"Return True if list elements are monotonically increasing or decreasing.\n    \n    >>> monotonic([1, 2, 4, 20])\n    True\n    >>> monotonic([1, 20, 4, 10])\n    False\n    >>> monotonic([4, 1, 0, -10])\n    True\n    \"\"\"\n    if not l:  # An empty list is considered monotonic\n        return True\n    \n    increasing = decreasing = True\n    \n    for i in range(1, len(l)):\n        if l[i] > l[i - 1]:\n            decreasing = False\n        elif l[i] < l[i - 1]:\n            increasing = False\n            \n    return increasing or decreasing", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n    \"\"\"\n    Takes as input string encoded with encode_shift function. Returns decoded string.\n    \"\"\"\n    return \"\".join([chr(((ord(ch) - ord(\"a\") - 5) % 26) + ord(\"a\")) for ch in s])", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n    \"\"\"\n    Given an array representing a branch of a tree that has non-negative integer nodes,\n    your task is to pluck one of the nodes and return it.\n    The plucked node should be the node with the smallest even value.\n    If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n    The plucked node should be returned in a list, [ smallest_value, its index ],\n    If there are no even values or the given array is empty, return [].\n\n    Example 1:\n        Input: [4,2,3]\n        Output: [2, 1]\n        Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n    Example 2:\n        Input: [1,2,3]\n        Output: [2, 1]\n        Explanation: 2 has the smallest even value, and 2 has the smallest index. \n\n    Example 3:\n        Input: []\n        Output: []\n    \n    Example 4:\n        Input: [5, 0, 3, 0, 4, 2]\n        Output: [0, 1]\n        Explanation: 0 is the smallest value, but there are two zeros,\n                     so we will choose the first zero, which has the smallest index.\n\n    Constraints:\n        * 1 <= nodes.length <= 10000\n        * 0 <= node.value\n    \"\"\"\n    smallest_even = float('inf')\n    smallest_index = -1\n\n    for index, value in enumerate(arr):\n        if value % 2 == 0:  # Check if the value is even\n            if value < smallest_even:  # Check if it's the smallest even found\n                smallest_even = value\n                smallest_index = index\n\n    if smallest_index == -1:  # No even value found\n        return []\n    \n    return [smallest_even, smallest_index]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float) -> float:\n    \"\"\"\n    Evaluates polynomial with coefficients xs at point x.\n    return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n    \"\"\"\n    return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list) -> list:\n    \"\"\"\n    Computes the derivative of the polynomial with coefficients xs.\n    \"\"\"\n    return [i * coeff for i, coeff in enumerate(xs) if i > 0]\ndef find_zero(xs: list, initial_guess: float = 0.0, tolerance: float = 1e-7, max_iterations: int = 1000) -> float:\n    \"\"\" \n    xs are coefficients of a polynomial.\n    find_zero finds x such that poly(x) = 0.\n    find_zero returns only one zero point, even if there are many.\n    Moreover, find_zero only takes list xs having an even number of coefficients\n    and the largest non-zero coefficient as it guarantees a solution.\n    \n    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n    -0.5\n    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n    1.0\n    \"\"\"\n    if len(xs) % 2 != 0:\n        raise ValueError(\"The number of coefficients must be even.\")\n    \n    current_guess = initial_guess\n    for _ in range(max_iterations):\n        f_value = poly(xs, current_guess)\n        f_derivative = poly(derivative(xs), current_guess)\n        \n        if f_derivative == 0:\n            raise ValueError(\"Derivative is zero. No solution found.\")\n        \n        next_guess = current_guess - f_value / f_derivative\n        \n        if abs(next_guess - current_guess) < tolerance:\n            return next_guess\n        \n        current_guess = next_guess\n    \n    raise ValueError(\"Maximum iterations reached. No solution found.\")", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[[5, 10, -3, 1]]]}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n    \"\"\" brackets is a string of \"<\" and \">\".\n    return True if every opening bracket has a corresponding closing bracket.\n\n    >>> correct_bracketing(\"<\")\n    False\n    >>> correct_bracketing(\"<>\")\n    True\n    >>> correct_bracketing(\"<<><>>\")\n    True\n    >>> correct_bracketing(\"><<>\")\n    False\n    \"\"\"\n    balance = 0\n    for char in brackets:\n        if char == '<':\n            balance += 1\n        elif char == '>':\n            balance -= 1\n        # If balance goes negative, there are more closing brackets\n        if balance < 0:\n            return False\n    # At the end, balance should be zero for correct bracketing\n    return balance == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n    \"\"\"Return maximum element in the list.\n    \n    >>> max_element([1, 2, 3])\n    3\n    >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n    123\n    \"\"\"\n    if not l:\n        raise ValueError(\"The list is empty.\")\n    \n    max_value = l[0]\n    for item in l:\n        if item > max_value:\n            max_value = item\n    return max_value", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n    \"\"\"\n    Write a function that takes a message, and encodes in such a \n    way that it swaps case of all letters, replaces all vowels in \n    the message with the letter that appears 2 places ahead of that \n    vowel in the english alphabet. \n    Assume only letters. \n    \n    Examples:\n    >>> encode('test')\n    'TGST'\n    >>> encode('This is a message')\n    'tHKS KS C MGSSCGG'\n    \"\"\"\n    vowels = 'aeiouAEIOU'\n    encoded_message = []\n\n    for char in message:\n        if char.isalpha():  # Check if the character is a letter\n            # Swap case\n            if char in vowels:\n                # Replace vowel with the letter 2 places ahead\n                if char.islower():\n                    new_char = chr((ord(char) - ord('a') + 2) % 26 + ord('a'))\n                else:\n                    new_char = chr((ord(char) - ord('A') + 2) % 26 + ord('A'))\n            else:\n                new_char = char.swapcase()  # Swap case for consonants\n            encoded_message.append(new_char)\n        else:\n            encoded_message.append(char)  # Keep non-letter characters unchanged\n\n    return ''.join(encoded_message)", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["TEST"]], "plus_fail_tests": [["abcdefghijklmnopqrstuvwxyz"]]}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n    \"\"\"\n    remove_vowels is a function that takes a string and returns a string without vowels.\n    \n    >>> remove_vowels('')\n    ''\n    >>> remove_vowels(\"abcdef\\nghijklm\")\n    'bcdf\\nghjklm'\n    >>> remove_vowels('abcdef')\n    'bcdf'\n    >>> remove_vowels('aaaaa')\n    ''\n    >>> remove_vowels('aaBAA')\n    'B'\n    >>> remove_vowels('zbcd')\n    'zbcd'\n    \"\"\"\n    vowels = \"aeiouAEIOU\"\n    return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n    '''\n    You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n    zero, and has a frequency greater than or equal to the value of the integer itself. \n    The frequency of an integer is the number of times it appears in the list.\n    If no such a value exist, return -1.\n    \n    Examples:\n        search([4, 1, 2, 2, 3, 1]) == 2\n        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n        search([5, 5, 4, 4, 4]) == -1\n    '''\n    from collections import Counter\n    \n    # Count the frequency of each number in the list\n    frequency = Counter(lst)\n    \n    # Initialize the result variable\n    result = -1\n    \n    # Iterate through the frequency dictionary\n    for num, freq in frequency.items():\n        # Check if the frequency is greater than or equal to the number itself\n        if freq >= num:\n            # Update the result if this number is greater than the current result\n            result = max(result, num)\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n    \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n    \n    >>> sum_to_n(30)\n    465\n    >>> sum_to_n(100)\n    5050\n    >>> sum_to_n(5)\n    15\n    >>> sum_to_n(10)\n    55\n    >>> sum_to_n(1)\n    1\n    \"\"\"\n    return n * (n + 1) // 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n    \"\"\"Return sorted unique common elements for two lists.\n    \n    >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n    [1, 5, 653]\n    >>> common([5, 3, 2, 8], [3, 2])\n    [2, 3]\n    \n    \"\"\"\n    # Convert both lists to sets to find unique elements\n    set1 = set(l1)\n    set2 = set(l2)\n    \n    # Find the intersection of both sets\n    common_elements = set1.intersection(set2)\n    \n    # Return the sorted list of common elements\n    return sorted(common_elements)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n    \"\"\"\n    In this task, you will be given a string that represents a number of apples and oranges \n    that are distributed in a basket of fruit. This basket contains \n    apples, oranges, and mango fruits. Given the string that represents the total number of \n    the oranges and apples and an integer that represents the total number of the fruits \n    in the basket, return the number of the mango fruits in the basket.\n    \n    Parameters:\n    s (str): A string representing the number of apples and oranges.\n    n (int): An integer representing the total number of fruits in the basket.\n    \n    Returns:\n    int: The number of mango fruits in the basket.\n    \n    Examples:\n    fruit_distribution(\"5 apples and 6 oranges\", 19) -> 8\n    fruit_distribution(\"0 apples and 1 oranges\", 3) -> 2\n    fruit_distribution(\"2 apples and 3 oranges\", 100) -> 95\n    fruit_distribution(\"100 apples and 1 oranges\", 120) -> 19\n    \"\"\"\n    \n    # Extract the number of apples and oranges from the string\n    parts = s.split()\n    apples = int(parts[0])  # First part is the number of apples\n    oranges = int(parts[3])  # Fourth part is the number of oranges\n    \n    # Calculate the number of mangoes\n    mangoes = n - apples - oranges\n    \n    return mangoes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n    \"\"\"Return sorted unique elements in a list.\n    \n    >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n    [0, 2, 3, 5, 9, 123]\n    \"\"\"\n    return sorted(set(l))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n    \"\"\"This function takes a list l and returns a list l' such that\n    l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n    to the values of the corresponding indices of l, but sorted.\n    \n    >>> sort_third([1, 2, 3])\n    [1, 2, 3]\n    >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n    [2, 6, 3, 4, 8, 9, 5]\n    \"\"\"\n    # Extract values at indices divisible by 3\n    divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n    \n    # Sort the extracted values\n    sorted_values = sorted(divisible_by_three)\n    \n    # Create a new list to hold the result\n    result = l.copy()\n    \n    # Replace values at indices divisible by 3 with sorted values\n    for index, value in zip((i for i in range(len(l)) if i % 3 == 0), sorted_values):\n        result[index] = value\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n    \"\"\"\n    Given an array of integers nums, find the minimum sum of any non-empty sub-array\n    of nums.\n    \n    Example\n    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n    minSubArraySum([-1, -2, -3]) == -6\n    \"\"\"\n    # Initialize variables to track the minimum sum and the current sum\n    min_sum = float('inf')\n    current_sum = 0\n    \n    for num in nums:\n        current_sum += num\n        min_sum = min(min_sum, current_sum)\n        \n        # If current_sum is positive, reset it to 0\n        if current_sum > 0:\n            current_sum = 0\n            \n    return min_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n    \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n    Each element i of the output should be \"the number of odd elements in the\n    string i of the input.\" where all the i's should be replaced by the number\n    of odd digits in the i'th string of the input.\n\n    >>> odd_count(['1234567'])\n    [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n    >>> odd_count(['3',\"11111111\"])\n    [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n     \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n    \"\"\"\n    result = []\n    for s in lst:\n        odd_count = sum(1 for char in s if int(char) % 2 != 0)\n        result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n    '''\n    Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n    should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n    alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n    \n    Examples:\n    split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n    split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n    split_words(\"abcdef\") \u279e 3 \n    '''\n    # Check for whitespace in the text\n    if ' ' in txt:\n        return txt.split()\n    \n    # Check for commas in the text\n    elif ',' in txt:\n        return txt.split(',')\n    \n    # If no whitespace or commas, count lower-case letters with odd order\n    else:\n        odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n        return odd_count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n    \"\"\"\n    Given a non-empty array of integers arr and an integer k, return\n    the sum of the elements with at most two digits from the first k elements of arr.\n\n    Example:\n\n        Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n        Output: 24 # sum of 21 + 3\n\n    Constraints:\n        1. 1 <= len(arr) <= 100\n        2. 1 <= k <= len(arr)\n    \"\"\"\n    # Initialize the sum\n    total_sum = 0\n    \n    # Iterate through the first k elements of the array\n    for i in range(k):\n        # Check if the current element has at most two digits\n        if -100 < arr[i] < 100:\n            total_sum += arr[i]\n    \n    return total_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n    \"\"\"Accepts a list of strings, removes strings with odd lengths,\n    and returns the remaining strings sorted by length and alphabetically.\n    \n    Args:\n        lst (list of str): A list of strings.\n        \n    Returns:\n        list of str: A sorted list of strings with even lengths.\n    \"\"\"\n    # Filter out strings with odd lengths\n    filtered_lst = [s for s in lst if len(s) % 2 == 0]\n    \n    # Sort the list first by length, then alphabetically\n    sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n    \n    return sorted_lst", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n    \"\"\"\n    Given a string text, replace all spaces in it with underscores, \n    and if a string has more than 2 consecutive spaces, \n    then replace all consecutive spaces with - \n    \n    fix_spaces(\"Example\") == \"Example\"\n    fix_spaces(\"Example 1\") == \"Example_1\"\n    fix_spaces(\" Example 2\") == \"_Example_2\"\n    fix_spaces(\" Example   3\") == \"_Example-3\"\n    \"\"\"\n    import re\n\n    # Replace more than 2 consecutive spaces with a single '-'\n    text = re.sub(r' {3,}', '-', text)\n    \n    # Replace single spaces with underscores\n    text = text.replace(' ', '_')\n    \n    return text", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n    \"\"\"\n    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n    as follows: start with any positive integer n. Then each term is obtained from the \n    previous term as follows: if the previous term is even, the next term is one half of \n    the previous term. If the previous term is odd, the next term is 3 times the previous\n    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n    Note: \n        1. Collatz(1) is [1].\n        2. returned list sorted in increasing order.\n\n    For example:\n    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n    \"\"\"\n    if n <= 0:\n        raise ValueError(\"Input must be a positive integer.\")\n    \n    collatz_sequence = []\n    current = n\n    \n    while current != 1:\n        collatz_sequence.append(current)\n        if current % 2 == 0:\n            current //= 2\n        else:\n            current = 3 * current + 1\n    \n    collatz_sequence.append(1)  # Add the last term which is 1\n    \n    # Filter odd numbers and sort them\n    odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n    \n    return odd_numbers", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n    \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n    \n    The date is valid if all of the following rules are satisfied:\n    1. The date string is not empty.\n    2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n       The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n       The number of days is not less than 1 or higher than 29 for the month 2.\n    3. The months should not be less than 1 or higher than 12.\n    4. The date should be in the format: mm-dd-yyyy\n    \n    Args:\n        date (str): The date string to validate.\n    \n    Returns:\n        bool: True if the date is valid, False otherwise.\n    \"\"\"\n    if not date:\n        return False\n    \n    # Check the format\n    parts = date.split('-')\n    if len(parts) != 3:\n        return False\n    \n    if not all(part.isdigit() for part in parts):\n        return False\n    \n    month, day, year = map(int, parts)\n    \n    # Validate month\n    if month < 1 or month > 12:\n        return False\n    \n    # Validate day based on month\n    if month in {1, 3, 5, 7, 8, 10, 12}:\n        if day < 1 or day > 31:\n            return False\n    elif month in {4, 6, 9, 11}:\n        if day < 1 or day > 30:\n            return False\n    elif month == 2:\n        if day < 1 or day > 29:\n            return False\n    \n    return True", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["06-04-202"]]}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n    \"\"\"Task\n    We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n    then check if the result string is palindrome.\n    A string is called palindrome if it reads the same backward as forward.\n    You should return a tuple containing the result string and True/False for the check.\n    Example\n    For s = \"abcde\", c = \"ae\", the result should be ('bcd',False)\n    For s = \"abcdef\", c = \"b\",  the result should be ('acdef',False)\n    For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc',True)\n    \"\"\"\n    # Create a set of characters to delete for faster lookup\n    delete_set = set(c)\n    \n    # Create the result string by filtering out characters in delete_set\n    result = ''.join(char for char in s if char not in delete_set)\n    \n    # Check if the result string is a palindrome\n    is_palindrome = result == result[::-1]\n    \n    return (result, is_palindrome)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n    \"\"\"\n    Calculate the number of times buckets need to be lowered to empty the wells.\n\n    Parameters:\n    grid (list of list of int): A rectangular grid representing wells.\n    capacity (int): The capacity of each bucket.\n\n    Returns:\n    int: The total number of times buckets need to be lowered.\n    \"\"\"\n    total_water = 0\n    \n    # Count the total amount of water in the grid\n    for row in grid:\n        total_water += sum(row)\n    \n    # Calculate the number of times buckets need to be lowered\n    # Each bucket can carry 'capacity' units of water\n    if total_water == 0:\n        return 0\n    else:\n        return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": [[[[1, 0, 0, 1], [0, 1, 1, 1], [0, 0, 0, 0], [1, 0, 1, 1]], 2]]}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n    \"\"\"Create a function which takes a string representing a file's name, and returns\n    'Yes' if the the file's name is valid, and returns 'No' otherwise.\n    A file's name is considered to be valid if and only if all the following conditions \n    are met:\n    - There should not be more than three digits ('0'-'9') in the file's name.\n    - The file's name contains exactly one dot '.'\n    - The substring before the dot should not be empty, and it starts with a letter from \n    the latin alphapet ('a'-'z' and 'A'-'Z').\n    - The substring after the dot should be one of these: ['txt', 'exe', 'dll']\n    Examples:\n    file_name_check(\"example.txt\") # => 'Yes'\n    file_name_check(\"1example.dll\") # => 'No' (the name should start with a latin alphapet letter)\n    \"\"\"\n    \n    # Split the file name into name and extension\n    if file_name.count('.') != 1:\n        return 'No'\n    \n    name, extension = file_name.split('.')\n    \n    # Check if the name is empty or starts with a non-letter\n    if not name or not name[0].isalpha():\n        return 'No'\n    \n    # Check the extension\n    valid_extensions = ['txt', 'exe', 'dll']\n    if extension not in valid_extensions:\n        return 'No'\n    \n    # Count the digits in the file name\n    digit_count = sum(c.isdigit() for c in file_name)\n    if digit_count > 3:\n        return 'No'\n    \n    return 'Yes'", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n    \"\"\"Write a function that takes an array of numbers as input and returns \n    the number of elements in the array that are greater than 10 and both \n    first and last digits of a number are odd (1, 3, 5, 7, 9).\n    \n    For example:\n    specialFilter([15, -73, 14, -15]) => 1 \n    specialFilter([33, -2, -3, 45, 21, 109]) => 2\n    \"\"\"\n    \n    def is_odd_digit(digit):\n        return digit in {'1', '3', '5', '7', '9'}\n    \n    def first_and_last_odd(num):\n        str_num = str(abs(num))  # Convert to string and take absolute value\n        return is_odd_digit(str_num[0]) and is_odd_digit(str_num[-1])\n    \n    count = 0\n    for num in nums:\n        if num > 10 and first_and_last_odd(num):\n            count += 1\n            \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n    '''\n    There are eight planets in our solar system: the closest to the Sun \n    is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n    Uranus, Neptune.\n    Write a function that takes two planet names as strings planet1 and planet2. \n    The function should return a tuple containing all planets whose orbits are \n    located between the orbit of planet1 and the orbit of planet2, sorted by \n    the proximity to the sun. \n    The function should return an empty tuple if planet1 or planet2\n    are not correct planet names. \n    Examples\n    bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n    bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n    bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n    '''\n    \n    planets = [\n        \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n        \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n    ]\n    \n    if planet1 not in planets or planet2 not in planets:\n        return ()\n    \n    index1 = planets.index(planet1)\n    index2 = planets.index(planet2)\n    \n    # Ensure index1 is less than index2 for slicing\n    start_index = min(index1, index2) + 1\n    end_index = max(index1, index2)\n    \n    return tuple(planets[start_index:end_index])", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n    \"\"\"You are given a list of numbers.\n    You need to return the sum of squared numbers in the given list,\n    round each element in the list to the upper int (Ceiling) first.\n    \n    Examples:\n    For lst = [1,2,3] the output should be 14\n    For lst = [1,4,9] the output should be 98\n    For lst = [1,3,5,7] the output should be 84\n    For lst = [1.4,4.2,0] the output should be 29\n    For lst = [-2.4,1,1] the output should be 6\n    \"\"\"\n    return sum(math.ceil(x) ** 2 for x in lst)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n    '''\n    Create a function that returns True if the last character\n    of a given string is an alphabetical character and is not\n    a part of a word, and False otherwise.\n    Note: \"word\" is a group of characters separated by space.\n\n    Examples:\n    check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n    check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n    check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n    check_if_last_char_is_a_letter(\"\") \u279e False \n    '''\n    # Strip any trailing whitespace from the string\n    txt = txt.rstrip()\n    \n    # Check if the string is empty after stripping\n    if not txt:\n        return False\n    \n    # Get the last character of the string\n    last_char = txt[-1]\n    \n    # Check if the last character is a letter\n    if last_char.isalpha():\n        # Check if the last character is part of a word\n        # A character is part of a word if it is preceded by a non-space character\n        if len(txt) > 1 and txt[-2] != ' ':\n            return False\n        return True\n    \n    return False", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["eeeee e "]], "plus_fail_tests": [["k "]]}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef sum_of_digits(n):\n    \"\"\"Return the sum of the digits of a number.\"\"\"\n    return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n    \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n    largest_prime = -1\n    \n    for number in lst:\n        if is_prime(number) and number > largest_prime:\n            largest_prime = number\n            \n    if largest_prime == -1:\n        return 0  # Return 0 if no prime number is found\n    \n    return sum_of_digits(largest_prime)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n    \"\"\"\n    You are given a positive integer n. You have to create an integer array a of length n.\n    For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n    Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,\n    and a[i] + a[j] + a[k] is a multiple of 3.\n\n    Example:\n        Input: n = 5\n        Output: 1\n        Explanation:\n        a = [1, 3, 7, 13, 21]\n        The only valid triple is (1, 7, 13).\n    \"\"\"\n    # Create the array a\n    a = [i * i - i + 1 for i in range(1, n + 1)]\n    \n    # Count the number of valid triples\n    count = 0\n    \n    # Check all combinations of triples (i, j, k) with i < j < k\n    for i in range(n):\n        for j in range(i + 1, n):\n            for k in range(j + 1, n):\n                if (a[i] + a[j] + a[k]) % 3 == 0:\n                    count += 1\n                    \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n    \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n    in the sequence.\n    \n    >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n    [1, 2, 3, 3, 3, 4, 4]\n    \"\"\"\n    if not numbers:\n        return []\n    \n    max_so_far = numbers[0]\n    result = [max_so_far]\n    \n    for num in numbers[1:]:\n        max_so_far = max(max_so_far, num)\n        result.append(max_so_far)\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n    \"\"\"This function takes two positive numbers x and y and returns the\n    biggest even integer number that is in the range [x, y] inclusive. If \n    there's no such number, then the function should return -1.\n\n    For example:\n    choose_num(12, 15) = 14\n    choose_num(13, 12) = -1\n    \"\"\"\n    # Ensure x is less than or equal to y\n    if x > y:\n        return -1\n    \n    # Start from the largest number in the range and check for evenness\n    for num in range(y, x - 1, -1):\n        if num % 2 == 0:\n            return num\n    \n    return -1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n    \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n    given threshold.\n    \n    >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n    False\n    >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n    True\n    \"\"\"\n    # Sort the numbers to make it easier to find close elements\n    numbers.sort()\n    \n    # Check the difference between consecutive elements\n    for i in range(len(numbers) - 1):\n        if abs(numbers[i] - numbers[i + 1]) < threshold:\n            return True\n            \n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n    \"\"\"\n    Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n    reverse the resulting array, and then replace each digit by its corresponding name from\n    \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n    For example:\n      arr = [2, 1, 1, 4, 5, 8, 2, 3]   \n            -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n            -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n      return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n    \n      If the array is empty, return an empty array:\n      arr = []\n      return []\n    \n      If the array has any strange number ignore it:\n      arr = [1, -1 , 55] \n            -> sort arr -> [-1, 1, 55]\n            -> reverse arr -> [55, 1, -1]\n      return = ['One']\n    \"\"\"\n    \n    # Mapping of digits to their corresponding names\n    digit_to_name = {\n        1: \"One\", 2: \"Two\", 3: \"Three\", 4: \"Four\",\n        5: \"Five\", 6: \"Six\", 7: \"Seven\", 8: \"Eight\", 9: \"Nine\"\n    }\n    \n    # Filter the array to include only numbers between 1 and 9\n    filtered_arr = [num for num in arr if 1 <= num <= 9]\n    \n    # Sort the filtered array\n    filtered_arr.sort()\n    \n    # Reverse the sorted array\n    filtered_arr.reverse()\n    \n    # Convert the numbers to their corresponding names\n    result = [digit_to_name[num] for num in filtered_arr]\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n    \"\"\" Filter an input list of strings only for ones that contain given substring\n    >>> filter_by_substring([], 'a')\n    []\n    >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n    ['abc', 'bacd', 'array']\n    \"\"\"\n    return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n    \"\"\"Calculate the factorial of n (n!).\"\"\"\n    if n == 0 or n == 1:\n        return 1\n    result = 1\n    for i in range(2, n + 1):\n        result *= i\n    return result\ndef special_factorial(n):\n    \"\"\"The Brazilian factorial is defined as:\n    brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!\n    where n > 0\n\n    For example:\n    >>> special_factorial(4)\n    288\n    \"\"\"\n    if n <= 0:\n        raise ValueError(\"Input must be a positive integer.\")\n    \n    result = 1\n    for i in range(1, n + 1):\n        result *= factorial(i)\n    \n    return result", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[491]]}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n    '''\n    Given a list of numbers, return the sum of squares of the numbers\n    in the list that are odd. Ignore numbers that are negative or not integers.\n    \n    double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n    double_the_difference([-1, -2, 0]) == 0\n    double_the_difference([9, -2]) == 81\n    double_the_difference([0]) == 0  \n   \n    If the input list is empty, return 0.\n    '''\n    if not lst:  # Check if the list is empty\n        return 0\n    \n    return sum(x**2 for x in lst if isinstance(x, int) and x >= 0 and x % 2 != 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n    \"\"\"\n    Given a positive integer, obtain its roman numeral equivalent as a string,\n    and return it in lowercase.\n    Restrictions: 1 <= num <= 1000\n\n    Examples:\n    >>> int_to_mini_roman(19) == 'xix'\n    >>> int_to_mini_roman(152) == 'clii'\n    >>> int_to_mini_roman(426) == 'cdxxvi'\n    \"\"\"\n    if not (1 <= number <= 1000):\n        raise ValueError(\"Number must be between 1 and 1000\")\n\n    roman_numerals = [\n        (1000, 'm'),\n        (900, 'cm'),\n        (500, 'd'),\n        (400, 'cd'),\n        (100, 'c'),\n        (90, 'xc'),\n        (50, 'l'),\n        (40, 'xl'),\n        (10, 'x'),\n        (9, 'ix'),\n        (5, 'v'),\n        (4, 'iv'),\n        (1, 'i')\n    ]\n\n    result = []\n    for value, numeral in roman_numerals:\n        while number >= value:\n            result.append(numeral)\n            number -= value\n\n    return ''.join(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n    \"\"\"\n    Given two lists operator, and operand. The first list has basic algebra operations, and \n    the second list is a list of integers. Use the two given lists to build the algebraic \n    expression and return the evaluation of this expression.\n\n    The basic algebra operations:\n    Addition ( + ) \n    Subtraction ( - ) \n    Multiplication ( * ) \n    Floor division ( // ) \n    Exponentiation ( ** ) \n\n    Example:\n    operator = ['+', '*', '-']\n    operand = [2, 3, 4, 5]\n    result = 2 + 3 * 4 - 5\n    => result = 9\n\n    Note:\n        The length of operator list is equal to the length of operand list minus one.\n        Operand is a list of non-negative integers.\n        Operator list has at least one operator, and operand list has at least two operands.\n    \"\"\"\n    # Start with the first operand\n    result = operand[0]\n    \n    # Iterate through the operators and operands\n    for i in range(len(operator)):\n        op = operator[i]\n        next_operand = operand[i + 1]\n        \n        if op == '+':\n            result += next_operand\n        elif op == '-':\n            result -= next_operand\n        elif op == '*':\n            result *= next_operand\n        elif op == '//':\n            result //= next_operand\n        elif op == '**':\n            result **= next_operand\n        else:\n            raise ValueError(f\"Unsupported operator: {op}\")\n    \n    return result", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": [[["+", "-", "*", "//"], [5, 2, 3, 4, 7]]]}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n    \"\"\"Write a function that accepts a list of strings.\n    The list contains different words. Return the word with maximum number\n    of unique characters. If multiple strings have maximum number of unique\n    characters, return the one which comes first in lexicographical order.\n\n    find_max([\"name\", \"of\", \"string\"]) == \"string\"\n    find_max([\"name\", \"enam\", \"game\"]) == \"enam\"\n    find_max([\"aaaaaaa\", \"bb\" ,\"cc\"]) == \"aaaaaaa\"\n    \"\"\"\n    max_word = \"\"\n    max_unique_count = 0\n\n    for word in words:\n        unique_chars = set(word)\n        unique_count = len(unique_chars)\n\n        if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n            max_word = word\n            max_unique_count = unique_count\n\n    return max_word", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n    \"\"\" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n    For each of the group, output the deepest level of nesting of parentheses.\n    E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n    >>> parse_nested_parens('(()()) ((())) () ((())()())')\n    [2, 3, 1, 3]\n    \"\"\"\n    def max_nesting_depth(s: str) -> int:\n        max_depth = 0\n        current_depth = 0\n        for char in s:\n            if char == '(':\n                current_depth += 1\n                max_depth = max(max_depth, current_depth)\n            elif char == ')':\n                current_depth -= 1\n        return max_depth\n\n    groups = paren_string.split()\n    return [max_nesting_depth(group) for group in groups]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n    \"\"\"Given a list of positive integers x, return a sorted list of all \n    elements that haven't any even digit.\n\n    Note: Returned list should be sorted in increasing order.\n    \n    For example:\n    >>> unique_digits([15, 33, 1422, 1])\n    [1, 15, 33]\n    >>> unique_digits([152, 323, 1422, 10])\n    []\n    \"\"\"\n    def has_even_digit(n):\n        \"\"\"Check if the number has any even digit.\"\"\"\n        return any(int(digit) % 2 == 0 for digit in str(n))\n\n    # Filter the list to include only numbers without even digits\n    result = [num for num in x if not has_even_digit(num)]\n    \n    # Return the sorted result\n    return sorted(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n    \"\"\" \n    Input to this function is a string containing multiple groups of nested parentheses. \n    Your goal is to separate those groups into separate strings and return the list of those.\n    Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n    Ignore any spaces in the input string.\n    \n    >>> separate_paren_groups('( ) (( )) (( )( ))')\n    ['()', '(())', '(()())']\n    \"\"\"\n    # Remove spaces from the input string\n    paren_string = paren_string.replace(\" \", \"\")\n    \n    result = []\n    balance = 0\n    current_group = []\n    \n    for char in paren_string:\n        if char == '(':\n            if balance == 0 and current_group:\n                result.append(''.join(current_group))\n                current_group = []\n            current_group.append(char)\n            balance += 1\n        elif char == ')':\n            current_group.append(char)\n            balance -= 1\n            if balance == 0:\n                result.append(''.join(current_group))\n                current_group = []\n    \n    # In case there are any remaining groups (should not happen with valid input)\n    if current_group:\n        result.append(''.join(current_group))\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n    \"\"\"Create a function which returns the largest index of an element which\n    is not greater than or equal to the element immediately preceding it. If\n    no such element exists then return -1. The given array will not contain\n    duplicate values.\n\n    Examples:\n    can_arrange([1,2,4,3,5]) = 3\n    can_arrange([1,2,3]) = -1\n    \"\"\"\n    # Initialize the index to -1, which will be returned if no such element is found\n    largest_index = -1\n    \n    # Iterate through the array starting from the second element\n    for i in range(1, len(arr)):\n        # Check if the current element is less than the previous element\n        if arr[i] < arr[i - 1]:\n            largest_index = i  # Update the largest index found\n    \n    return largest_index", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n    '''\n    Create a function that takes a string as input which contains only square brackets.\n    The function should return True if and only if there is a valid subsequence of brackets \n    where at least one bracket in the subsequence is nested.\n\n    is_nested('[[]]') \u279e True\n    is_nested('[]]]]]]][[[[[]') \u279e False\n    is_nested('[][]') \u279e False\n    is_nested('[]') \u279e False\n    is_nested('[[][]]') \u279e True\n    is_nested('[[]][[') \u279e True\n    '''\n    stack = []\n    nested_found = False\n\n    for char in string:\n        if char == '[':\n            stack.append(char)\n        elif char == ']':\n            if stack:\n                stack.pop()\n                if len(stack) > 0:  # Check if there is a nested bracket\n                    nested_found = True\n            else:\n                return False  # Unmatched closing bracket\n\n    return nested_found and len(stack) == 0  # Must be balanced and have nested brackets", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["[[]][["]], "plus_fail_tests": [["[[]]]"]]}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n    \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n    Empty sum should be equal to 0 and empty product should be equal to 1.\n    \n    >>> sum_product([])\n    (0, 1)\n    >>> sum_product([1, 2, 3, 4])\n    (10, 24)\n    \"\"\"\n    if not numbers:\n        return (0, 1)\n    \n    total_sum = sum(numbers)\n    total_product = 1\n    for number in numbers:\n        total_product *= number\n    \n    return (total_sum, total_product)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n    \"\"\"\n    You're a hungry rabbit, and you already have eaten a certain number of carrots,\n    but now you need to eat more carrots to complete the day's meals.\n    you should return an array of [ total number of eaten carrots after your meals,\n                                    the number of carrots left after your meals ]\n    if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n    \n    Example:\n    * eat(5, 6, 10) -> [11, 4]\n    * eat(4, 8, 9) -> [12, 1]\n    * eat(1, 10, 10) -> [11, 0]\n    * eat(2, 11, 5) -> [7, 0]\n    \n    Variables:\n    @number : integer\n        the number of carrots that you have eaten.\n    @need : integer\n        the number of carrots that you need to eat.\n    @remaining : integer\n        the number of remaining carrots that exist in stock\n    \n    Constrain:\n    * 0 <= number <= 1000\n    * 0 <= need <= 1000\n    * 0 <= remaining <= 1000\n\n    Have fun :)\n    \"\"\"\n    # Calculate how many more carrots are needed\n    additional_needed = need - number\n    \n    # If no additional carrots are needed, return the current state\n    if additional_needed <= 0:\n        return [number, remaining]\n    \n    # Determine how many carrots can be eaten from the remaining stock\n    eaten = min(additional_needed, remaining)\n    \n    # Calculate the total eaten and remaining carrots\n    total_eaten = number + eaten\n    remaining_after_meals = remaining - eaten\n    \n    return [total_eaten, remaining_after_meals]", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": [[2, 2, 2]]}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n    \"\"\"You are given a string s.\n    if s[i] is a letter, reverse its case from lower to upper or vise versa, \n    otherwise keep it as it is.\n    If the string contains no letters, reverse the string.\n    The function should return the resulted string.\n    \n    Examples:\n    solve(\"1234\") = \"4321\"\n    solve(\"ab\") = \"AB\"\n    solve(\"#a@C\") = \"#A@c\"\n    \"\"\"\n    # Check if there are any letters in the string\n    has_letters = any(c.isalpha() for c in s)\n    \n    if has_letters:\n        # Reverse case for letters and keep others the same\n        return ''.join(c.swapcase() if c.isalpha() else c for c in s)\n    else:\n        # Reverse the string if there are no letters\n        return s[::-1]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n    '''\n    Given the lengths of the three sides of a triangle. Return True if the three\n    sides form a right-angled triangle, False otherwise.\n    A right-angled triangle is a triangle in which one angle is right angle or \n    90 degree.\n    \n    Example:\n    right_angle_triangle(3, 4, 5) == True\n    right_angle_triangle(1, 2, 3) == False\n    '''\n    # Sort the sides to identify the longest side\n    sides = sorted([a, b, c])\n    \n    # Check the Pythagorean theorem\n    return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n    \"\"\"Convert a decimal number to binary format with specific formatting.\n    \n    Args:\n    decimal (int): A non-negative integer to convert to binary.\n    \n    Returns:\n    str: A string representing the binary format of the decimal number,\n         prefixed and suffixed with 'db'.\n    \n    Examples:\n    >>> decimal_to_binary(15)\n    'db1111db'\n    >>> decimal_to_binary(32)\n    'db100000db'\n    \"\"\"\n    if decimal < 0:\n        raise ValueError(\"Input must be a non-negative integer.\")\n    \n    # Convert decimal to binary and remove the '0b' prefix\n    binary_representation = bin(decimal)[2:]\n    \n    # Format the output with 'db' at the beginning and end\n    formatted_output = f\"db{binary_representation}db\"\n    \n    return formatted_output", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(num):\n    \"\"\"Check if a number is prime.\"\"\"\n    if num <= 1:\n        return False\n    for i in range(2, int(num**0.5) + 1):\n        if num % i == 0:\n            return False\n    return True\ndef x_or_y(n, x, y):\n    \"\"\"Return the value of x if n is a prime number, otherwise return y.\"\"\"\n    if is_prime(n):\n        return x\n    else:\n        return y", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n    \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n    fib4(0) -> 0\n    fib4(1) -> 0\n    fib4(2) -> 2\n    fib4(3) -> 0\n    fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n    Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.\n    \n    >>> fib4(5)\n    4\n    >>> fib4(6)\n    8\n    >>> fib4(7)\n    14\n    \"\"\"\n    if n == 0:\n        return 0\n    elif n == 1:\n        return 0\n    elif n == 2:\n        return 2\n    elif n == 3:\n        return 0\n\n    # Initialize the first four values of the sequence\n    fib_values = [0, 0, 2, 0]\n\n    # Compute the values iteratively\n    for i in range(4, n + 1):\n        next_value = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n        fib_values.append(next_value)\n\n    return fib_values[n]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n    \"\"\"\n    Imagine a road that's a perfectly straight infinitely long line.\n    n cars are driving left to right; simultaneously, a different set of n cars\n    are driving right to left. The two sets of cars start out being very far from\n    each other. All cars move at the same speed. Two cars are said to collide\n    when a car that's moving left to right hits a car that's moving right to left.\n    However, the cars are infinitely sturdy and strong; as a result, they continue moving\n    in their trajectory as if they did not collide.\n\n    This function outputs the number of such collisions.\n\n    Parameters:\n    n (int): The number of cars in each direction.\n\n    Returns:\n    int: The total number of collisions.\n    \"\"\"\n    # Each car moving left to right will collide with each car moving right to left\n    # Therefore, the total number of collisions is n * n\n    return n * n", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n    \"\"\"\n    Checks if given string is a palindrome.\n    \n    A palindrome is a string that reads the same forward and backward.\n    \n    >>> is_palindrome('')\n    True\n    >>> is_palindrome('aba')\n    True\n    >>> is_palindrome('aaaaa')\n    True\n    >>> is_palindrome('zbcd')\n    False\n    \"\"\"\n    # Normalize the string by removing spaces and converting to lowercase\n    normalized_text = text.replace(\" \", \"\").lower()\n    # Check if the string is equal to its reverse\n    return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["never odd or even"]]}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n    '''\n    Write a function that takes an integer a and returns True \n    if this integer is a cube of some integer number.\n    Note: you may assume the input is always valid.\n    \n    Examples:\n    iscube(1) ==> True\n    iscube(2) ==> False\n    iscube(-1) ==> True\n    iscube(64) ==> True\n    iscube(0) ==> True\n    iscube(180) ==> False\n    '''\n    # Calculate the cube root of the absolute value of a\n    cube_root = round(abs(a) ** (1/3))\n    \n    # Check if the cube of the rounded cube root equals the absolute value of a\n    return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n    \"\"\"You are given two positive integers n and m, and your task is to compute the\n    average of the integers from n through m (including n and m). \n    Round the answer to the nearest integer and convert that to binary.\n    If n is greater than m, return -1.\n    \n    Example:\n    rounded_avg(1, 5) => \"0b11\"\n    rounded_avg(7, 5) => -1\n    rounded_avg(10, 20) => \"0b1111\"\n    rounded_avg(20, 33) => \"0b11010\"\n    \"\"\"\n    if n > m:\n        return -1\n    \n    # Calculate the sum of integers from n to m\n    total_sum = sum(range(n, m + 1))\n    count = m - n + 1  # Total numbers from n to m\n    \n    # Calculate the average and round it\n    average = total_sum / count\n    rounded_average = round(average)\n    \n    # Convert the rounded average to binary\n    return bin(rounded_average)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n    \"\"\"\n    Given a positive integer n, return the count of the numbers of n-digit\n    positive integers that start or end with 1.\n    \"\"\"\n    if n < 1:\n        return 0\n\n    # Total n-digit numbers\n    total_n_digit_numbers = 9 * (10 ** (n - 1))\n\n    # Count of n-digit numbers that start with 1\n    start_with_1 = 10 ** (n - 1)\n\n    # Count of n-digit numbers that end with 1\n    end_with_1 = 9 * (10 ** (n - 2)) if n > 1 else 0\n\n    # Total count of n-digit numbers that start or end with 1\n    total_count = start_with_1 + end_with_1\n\n    return total_count", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[2]], "plus_fail_tests": [[6]]}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n    \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n    \n    Example\n        For N = 1000, the sum of digits will be 1 the output should be \"1\".\n        For N = 150, the sum of digits will be 6 the output should be \"110\".\n        For N = 147, the sum of digits will be 12 the output should be \"1100\".\n    \n    Variables:\n        @N integer\n             Constraints: 0 \u2264 N \u2264 10000.\n    Output:\n         a string of binary number\n    \"\"\"\n    # Calculate the sum of the digits of N\n    digit_sum = sum(int(digit) for digit in str(N))\n    \n    # Convert the sum to binary and remove the '0b' prefix\n    binary_sum = bin(digit_sum)[2:]\n    \n    return binary_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n    '''\n    Given list of integers, return list in strange order.\n    Strange sorting, is when you start with the minimum value,\n    then maximum of the remaining integers, then minimum and so on.\n\n    Examples:\n    strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n    strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n    strange_sort_list([]) == []\n    '''\n    if not lst:\n        return []\n\n    sorted_lst = sorted(lst)\n    result = []\n    left, right = 0, len(sorted_lst) - 1\n\n    while left <= right:\n        if left == right:\n            result.append(sorted_lst[left])\n        else:\n            result.append(sorted_lst[left])\n            result.append(sorted_lst[right])\n        left += 1\n        right -= 1\n\n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n    \"\"\" Return length of given string\n    >>> strlen('')\n    0\n    >>> strlen('abc')\n    3\n    \"\"\"\n    return len(string)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n    \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n    >>> largest_divisor(15)\n    5\n    >>> largest_divisor(28)\n    14\n    >>> largest_divisor(1)\n    0\n    >>> largest_divisor(10)\n    5\n    \"\"\"\n    if n <= 1:\n        return 0  # No divisors for 1 or less\n    for i in range(n // 2, 0, -1):\n        if n % i == 0:\n            return i", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n    '''\n    Given the lengths of the three sides of a triangle. Return the area of\n    the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n    Otherwise return -1.\n    Three sides make a valid triangle when the sum of any two sides is greater \n    than the third side.\n    \n    Example:\n    triangle_area(3, 4, 5) == 6.00\n    triangle_area(1, 2, 10) == -1\n    '''\n    # Check for valid triangle condition\n    if a + b > c and a + c > b and b + c > a:\n        # Calculate the semi-perimeter\n        s = (a + b + c) / 2\n        # Calculate the area using Heron's formula\n        area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n        return round(area, 2)\n    else:\n        return -1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n    \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n    strings of the same length. Return None in case the input list is empty.\n    \n    >>> longest([])\n    >>> None\n    >>> longest(['a', 'b', 'c'])\n    'a'\n    >>> longest(['a', 'bb', 'ccc'])\n    'ccc'\n    \"\"\"\n    if not strings:\n        return None\n    \n    longest_string = strings[0]\n    \n    for string in strings:\n        if len(string) > len(longest_string):\n            longest_string = string\n            \n    return longest_string", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n    \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n    Args:\n        lst (list): A non-empty list of integers.\n\n    Returns:\n        int: The sum of even elements at odd indices.\n\n    Examples:\n        add([4, 2, 6, 7]) ==> 2 \n    \"\"\"\n    return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n    \"\"\"Return 2^n modulo p (be aware of numerics).\n    \n    >>> modp(3, 5)\n    3\n    >>> modp(1101, 101)\n    2\n    >>> modp(0, 101)\n    1\n    >>> modp(3, 11)\n    8\n    >>> modp(100, 101)\n    1\n    \"\"\"\n    result = 1\n    base = 2 % p  # Start with 2 mod p\n    while n > 0:\n        if n % 2 == 1:  # If n is odd, multiply the base with the result\n            result = (result * base) % p\n        base = (base * base) % p  # Square the base\n        n //= 2  # Divide n by 2\n    return result", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[0, 1]]}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef prime_length(string):\n    \"\"\"Return True if the string length is a prime number, False otherwise.\"\"\"\n    length = len(string)\n    return is_prime(length)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n    \"\"\"Returns True if x is a simple power of n, otherwise False.\n    \n    A number x is a simple power of n if there exists an integer k such that n**k = x.\n    \n    Args:\n        x (int): The number to check.\n        n (int): The base number.\n    \n    Returns:\n        bool: True if x is a simple power of n, False otherwise.\n    \"\"\"\n    if n <= 1:\n        return x == 1  # 1 is a power of any number, and no other number can be a power of 1 or less.\n    \n    power = 1\n    while True:\n        result = n ** power\n        if result == x:\n            return True\n        elif result > x:\n            return False\n        power += 1", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[1, 12]], "plus_fail_tests": [[1, 4]]}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n    \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n    \n    >>> string_sequence(0)\n    '0'\n    >>> string_sequence(5)\n    '0 1 2 3 4 5'\n    \"\"\"\n    return ' '.join(str(i) for i in range(n + 1))", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[1000000]]}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n    \"\"\"\n    triples_sum_to_zero takes a list of integers as an input.\n    it returns True if there are three distinct elements in the list that\n    sum to zero, and False otherwise.\n\n    >>> triples_sum_to_zero([1, 3, 5, 0])\n    False\n    >>> triples_sum_to_zero([1, 3, -2, 1])\n    True\n    >>> triples_sum_to_zero([1, 2, 3, 7])\n    False\n    >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n    True\n    >>> triples_sum_to_zero([1])\n    False\n    \"\"\"\n    n = len(l)\n    # Sort the list to use the two-pointer technique\n    l.sort()\n    \n    for i in range(n - 2):\n        # Avoid duplicates for the first element\n        if i > 0 and l[i] == l[i - 1]:\n            continue\n        \n        left, right = i + 1, n - 1\n        while left < right:\n            current_sum = l[i] + l[left] + l[right]\n            if current_sum == 0:\n                return True\n            elif current_sum < 0:\n                left += 1\n            else:\n                right -= 1\n    \n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n    \"\"\"Counts the number of prime hexadecimal digits in the given hexadecimal string.\"\"\"\n    # Define the set of prime hexadecimal digits\n    prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n    \n    # Count the number of prime hexadecimal digits in the input string\n    count = sum(1 for digit in num if digit in prime_hex_digits)\n    \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n    \"\"\"Return median of elements in the list l.\n    \n    The median is the middle value in a list of numbers. If the list has an even number of elements,\n    the median is the average of the two middle numbers.\n    \n    >>> median([3, 1, 2, 4, 5])\n    3\n    >>> median([-10, 4, 6, 1000, 10, 20])\n    15.0\n    \"\"\"\n    if not l:\n        raise ValueError(\"The list is empty\")\n    \n    sorted_list = sorted(l)\n    n = len(sorted_list)\n    mid = n // 2\n    \n    if n % 2 == 0:  # Even number of elements\n        return (sorted_list[mid - 1] + sorted_list[mid]) / 2\n    else:  # Odd number of elements\n        return sorted_list[mid]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n    \"\"\" Return a greatest common divisor of two integers a and b\n    >>> greatest_common_divisor(3, 5)\n    1\n    >>> greatest_common_divisor(25, 15)\n    5\n    \"\"\"\n    while b:\n        a, b = b, a % b\n    return abs(a)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n    \"\"\" Filter given list of any python values only for integers\n    >>> filter_integers(['a', 3.14, 5])\n    [5]\n    >>> filter_integers([1, 2, 3, 'abc', {}, []])\n    [1, 2, 3]\n    \"\"\"\n    return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[[true, false, null, 0, -10, "test", [], {}, 3.14]]]}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n    \"\"\" Return list of all prefixes from shortest to longest of the input string\n    >>> all_prefixes('abc')\n    ['a', 'ab', 'abc']\n    \"\"\"\n    return [string[:i] for i in range(1, len(string) + 1)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str) -> str:\n    \"\"\"\n    Takes as input a string encoded with the encode_cyclic function.\n    Returns the decoded string.\n    \"\"\"\n    # Split string into groups of length 3\n    groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n    # Reverse the cycling of elements in each group\n    groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n    return \"\".join(groups)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n    \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n    Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n    Input number should be equal to the product of all factors\n    >>> factorize(8)\n    [2, 2, 2]\n    >>> factorize(25)\n    [5, 5]\n    >>> factorize(70)\n    [2, 5, 7]\n    \"\"\"\n    factors = []\n    # Check for number of 2s that divide n\n    while n % 2 == 0:\n        factors.append(2)\n        n //= 2\n    \n    # n must be odd at this point so a skip of 2 (i.e., check only odd numbers) can be used\n    for i in range(3, int(n**0.5) + 1, 2):\n        # While i divides n, append i and divide n\n        while n % i == 0:\n            factors.append(i)\n            n //= i\n    \n    # This condition is to check if n is a prime number greater than 2\n    if n > 2:\n        factors.append(n)\n    \n    return factors", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n    \"\"\"Return true if a given number is prime, and false otherwise.\n    \n    >>> is_prime(6)\n    False\n    >>> is_prime(101)\n    True\n    >>> is_prime(11)\n    True\n    >>> is_prime(13441)\n    True\n    >>> is_prime(61)\n    True\n    >>> is_prime(4)\n    False\n    >>> is_prime(1)\n    False\n    \"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n    \"\"\"\n    You'll be given a string of words, and your task is to count the number\n    of boredoms. A boredom is a sentence that starts with the word \"I\".\n    Sentences are delimited by '.', '?' or '!'.\n   \n    For example:\n    >>> is_bored(\"Hello world\")\n    0\n    >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n    1\n    >>> is_bored(\"I am happy! Are you? I will go now.\")\n    2\n    >>> is_bored(\"What a day. I can't believe it! I am so excited.\")\n    2\n    \"\"\"\n    # Split the input string into sentences using the delimiters\n    sentences = []\n    current_sentence = []\n    for char in S:\n        if char in '.!?':\n            if current_sentence:\n                sentences.append(''.join(current_sentence).strip())\n                current_sentence = []\n        else:\n            current_sentence.append(char)\n    if current_sentence:  # Add the last sentence if it exists\n        sentences.append(''.join(current_sentence).strip())\n    \n    # Count the number of sentences that start with \"I\"\n    boredom_count = sum(1 for sentence in sentences if sentence.startswith('I'))\n    \n    return boredom_count", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": [["In the morning, I like to have a cup of coffee to start my day off right. How about you?"]]}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n    \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n    and return the result as a string.\n    If shift > number of digits, return digits reversed.\n    \n    >>> circular_shift(12, 1)\n    '21'\n    >>> circular_shift(12, 2)\n    '12'\n    >>> circular_shift(12345, 1)\n    '51234'\n    >>> circular_shift(12345, 5)\n    '54321'\n    >>> circular_shift(12345, 6)\n    '54321'\n    \"\"\"\n    # Convert the integer to a string to manipulate its digits\n    str_x = str(x)\n    num_digits = len(str_x)\n    \n    # If shift is greater than the number of digits, reverse the string\n    if shift >= num_digits:\n        return str_x[::-1]\n    \n    # Calculate the effective shift\n    effective_shift = shift % num_digits\n    \n    # Perform the circular shift\n    shifted_str = str_x[-effective_shift:] + str_x[:-effective_shift]\n    \n    return shifted_str", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[12, 2]], "plus_fail_tests": [[987654321, 9]]}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n    \"\"\" \n    xs represent coefficients of a polynomial.\n    xs[0] + xs[1] * x + xs[2] * x^2 + ....\n    Return derivative of this polynomial in the same form.\n    \n    >>> derivative([3, 1, 2, 4, 5])\n    [1, 4, 12, 20]\n    >>> derivative([1, 2, 3])\n    [2, 6]\n    \"\"\"\n    # The derivative of a polynomial is calculated by multiplying each coefficient\n    # by its corresponding power and reducing the power by one.\n    return [i * coeff for i, coeff in enumerate(xs[1:], start=1)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n    \"\"\"\n    Check if two words have the same characters.\n    \n    Two words have the same characters if they contain the same unique characters,\n    regardless of the number of times each character appears.\n\n    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n    True\n    >>> same_chars('abcd', 'dddddddabc')\n    True\n    >>> same_chars('dddddddabc', 'abcd')\n    True\n    >>> same_chars('eabcd', 'dddddddabc')\n    False\n    >>> same_chars('abcd', 'dddddddabce')\n    False\n    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n    False\n    \"\"\"\n    return set(s0) == set(s1)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n    \"\"\"Add two numbers x and y.\n    \n    >>> add(2, 3)\n    5\n    >>> add(5, 7)\n    12\n    \"\"\"\n    return x + y", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n    \"\"\"\n    Given a string s, count the number of uppercase vowels in even indices.\n    \n    For example:\n    count_upper('aBCdEf') returns 1\n    count_upper('abcdefg') returns 0\n    count_upper('dBBE') returns 0\n    \"\"\"\n    uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n    count = 0\n    \n    for i in range(0, len(s), 2):  # Iterate over even indices\n        if s[i] in uppercase_vowels:\n            count += 1\n            \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n    \"\"\"Check if a number is prime.\"\"\"\n    if num <= 1:\n        return False\n    for i in range(2, int(num**0.5) + 1):\n        if num % i == 0:\n            return False\n    return True\ndef count_up_to(n):\n    \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n    primes = []\n    for i in range(2, n):\n        if is_prime(i):\n            primes.append(i)\n    return primes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n    \"\"\"Return only positive numbers in the list.\n    >>> get_positive([-1, 2, -4, 5, 6])\n    [2, 5, 6]\n    >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n    [5, 3, 2, 3, 9, 123, 1]\n    \"\"\"\n    return [x for x in l if x > 0]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n    \"\"\"This function takes a list l and returns a list l' such that\n    l' is identical to l in the odd indices, while its values at the even indices are equal\n    to the values of the even indices of l, but sorted.\n    \n    >>> sort_even([1, 2, 3])\n    [1, 2, 3]\n    >>> sort_even([5, 6, 3, 4])\n    [3, 6, 5, 4]\n    \"\"\"\n    # Extract even indexed elements\n    even_indices = [l[i] for i in range(0, len(l), 2)]\n    \n    # Sort the even indexed elements\n    even_indices.sort()\n    \n    # Create a new list to hold the result\n    result = l[:]  # Start with a copy of the original list\n    \n    # Place the sorted even indexed elements back into their positions\n    for i, value in enumerate(even_indices):\n        result[i * 2] = value\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n    \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n    \n    >>> fizz_buzz(50)\n    0\n    >>> fizz_buzz(78)\n    2\n    >>> fizz_buzz(79)\n    3\n    \"\"\"\n    count_of_sevens = 0\n    \n    for i in range(n):\n        if i % 11 == 0 or i % 13 == 0:\n            count_of_sevens += str(i).count('7')\n    \n    return count_of_sevens", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n    \"\"\"Return True if all numbers in the list l are below threshold t.\n    \n    >>> below_threshold([1, 2, 4, 10], 100)\n    True\n    >>> below_threshold([1, 20, 4, 10], 5)\n    False\n    \"\"\"\n    return all(x < t for x in l)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n    '''\n    Create a function that takes a value (string) representing a number\n    and returns the closest integer to it. If the number is equidistant\n    from two integers, round it away from zero.\n\n    Examples\n    >>> closest_integer(\"10\")\n    10\n    >>> closest_integer(\"15.3\")\n    15\n    >>> closest_integer(\"14.5\")\n    15\n    >>> closest_integer(\"-14.5\")\n    -15\n    >>> closest_integer(\"0.5\")\n    1\n    >>> closest_integer(\"-0.5\")\n    -1\n    '''\n    # Convert the string to a float\n    num = float(value)\n    \n    # Get the floor and ceiling of the number\n    lower = int(num // 1)  # This is the largest integer less than or equal to num\n    upper = lower + 1      # This is the smallest integer greater than num\n    \n    # Check if the number is equidistant from lower and upper\n    if abs(num - lower) < abs(num - upper):\n        return lower\n    elif abs(num - lower) > abs(num - upper):\n        return upper\n    else:\n        # If equidistant, round away from zero\n        if num > 0:\n            return upper\n        else:\n            return lower", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000"]]}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n    \"\"\"Check if a number is prime.\"\"\"\n    if num <= 1:\n        return False\n    if num <= 3:\n        return True\n    if num % 2 == 0 or num % 3 == 0:\n        return False\n    i = 5\n    while i * i <= num:\n        if num % i == 0 or num % (i + 2) == 0:\n            return False\n        i += 6\n    return True\ndef fibonacci(n: int) -> int:\n    \"\"\"Return the n-th Fibonacci number.\"\"\"\n    a, b = 0, 1\n    for _ in range(n):\n        a, b = b, a + b\n    return a\ndef prime_fib(n: int) -> int:\n    \"\"\"\n    prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n    >>> prime_fib(1)\n    2\n    >>> prime_fib(2)\n    3\n    >>> prime_fib(3)\n    5\n    >>> prime_fib(4)\n    13\n    >>> prime_fib(5)\n    89\n    \"\"\"\n    count = 0\n    i = 0\n    while True:\n        fib_num = fibonacci(i)\n        if is_prime(fib_num):\n            count += 1\n            if count == n:\n                return fib_num\n        i += 1", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[12]]}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n    \"\"\"Return n-th Fibonacci number.\n    \n    >>> fib(10)\n    55\n    >>> fib(1)\n    1\n    >>> fib(8)\n    21\n    \"\"\"\n    if n <= 0:\n        raise ValueError(\"Input must be a positive integer.\")\n    elif n == 1:\n        return 1\n    elif n == 2:\n        return 1\n    else:\n        a, b = 1, 1\n        for _ in range(2, n):\n            a, b = b, a + b\n        return b", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[0]]}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n    \"\"\"Complete the function that takes two integers and returns \n    the product of their unit digits.\n    Assume the input is always valid.\n    Examples:\n    multiply(148, 412) should return 16.\n    multiply(19, 28) should return 72.\n    multiply(2020, 1851) should return 0.\n    multiply(14,-15) should return 20.\n    \"\"\"\n    # Get the unit digit of the first number\n    unit_digit_a = abs(a) % 10\n    # Get the unit digit of the second number\n    unit_digit_b = abs(b) % 10\n    # Return the product of the unit digits\n    return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n    \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n    fibfib(0) == 0\n    fibfib(1) == 0\n    fibfib(2) == 1\n    fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n    \n    Args:\n        n (int): The index of the FibFib number to compute.\n        \n    Returns:\n        int: The n-th FibFib number.\n    \n    Examples:\n        >>> fibfib(1)\n        0\n        >>> fibfib(5)\n        4\n        >>> fibfib(8)\n        24\n    \"\"\"\n    if n == 0:\n        return 0\n    elif n == 1:\n        return 0\n    elif n == 2:\n        return 1\n    \n    # Initialize the first three FibFib numbers\n    fibfib_numbers = [0, 0, 1]\n    \n    # Compute the FibFib numbers iteratively\n    for i in range(3, n + 1):\n        next_fibfib = fibfib_numbers[i - 1] + fibfib_numbers[i - 2] + fibfib_numbers[i - 3]\n        fibfib_numbers.append(next_fibfib)\n    \n    return fibfib_numbers[n]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n    \"\"\"\n    You are given a list of integers.\n    Write a function next_smallest() that returns the 2nd smallest element of the list.\n    Return None if there is no such element.\n    \n    next_smallest([1, 2, 3, 4, 5]) == 2\n    next_smallest([5, 1, 4, 3, 2]) == 2\n    next_smallest([]) == None\n    next_smallest([1, 1]) == None\n    \"\"\"\n    # Remove duplicates by converting the list to a set\n    unique_elements = set(lst)\n    \n    # If there are less than 2 unique elements, return None\n    if len(unique_elements) < 2:\n        return None\n    \n    # Sort the unique elements\n    sorted_elements = sorted(unique_elements)\n    \n    # Return the second smallest element\n    return sorted_elements[1]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n    \"\"\"Write a function vowels_count which takes a string representing\n    a word as input and returns the number of vowels in the string.\n    Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n    vowel, but only when it is at the end of the given word.\n\n    Example:\n    >>> vowels_count(\"abcde\")\n    2\n    >>> vowels_count(\"ACEDY\")\n    3\n    \"\"\"\n    vowels = 'aeiou'\n    count = 0\n    s = s.lower()  # Convert to lowercase to handle case insensitivity\n\n    for i in range(len(s)):\n        if s[i] in vowels:\n            count += 1\n        elif s[i] == 'y' and i == len(s) - 1:  # Check if 'y' is at the end\n            count += 1\n\n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n    \"\"\"Simplifies the expression x * n and checks if it evaluates to a whole number.\n    \n    Args:\n        x (str): A string representation of a fraction in the format <numerator>/<denominator>.\n        n (str): A string representation of a fraction in the format <numerator>/<denominator>.\n    \n    Returns:\n        bool: True if x * n evaluates to a whole number, False otherwise.\n    \"\"\"\n    # Split the fractions into numerator and denominator\n    x_numerator, x_denominator = map(int, x.split('/'))\n    n_numerator, n_denominator = map(int, n.split('/'))\n    \n    # Calculate the product of the fractions\n    # x * n = (x_numerator / x_denominator) * (n_numerator / n_denominator)\n    # This simplifies to (x_numerator * n_numerator) / (x_denominator * n_denominator)\n    numerator_product = x_numerator * n_numerator\n    denominator_product = x_denominator * n_denominator\n    \n    # Check if the result is a whole number\n    return numerator_product % denominator_product == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef words_in_sentence(sentence):\n    \"\"\"\n    You are given a string representing a sentence,\n    the sentence contains some words separated by a space,\n    and you have to return a string that contains the words from the original sentence,\n    whose lengths are prime numbers,\n    the order of the words in the new string should be the same as the original one.\n\n    Example 1:\n        Input: sentence = \"This is a test\"\n        Output: \"is\"\n\n    Example 2:\n        Input: sentence = \"lets go for swimming\"\n        Output: \"go for\"\n\n    Constraints:\n        * 1 <= len(sentence) <= 100\n        * sentence contains only letters\n    \"\"\"\n    words = sentence.split()\n    prime_length_words = [word for word in words if is_prime(len(word))]\n    return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n    \"\"\"In this problem, you will implement a function that takes two lists of numbers,\n    and determines whether it is possible to perform an exchange of elements\n    between them to make lst1 a list of only even numbers.\n    There is no limit on the number of exchanged elements between lst1 and lst2.\n    If it is possible to exchange elements between the lst1 and lst2 to make\n    all the elements of lst1 to be even, return \"YES\".\n    Otherwise, return \"NO\".\n    For example:\n    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"YES\"\n    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n    It is assumed that the input lists will be non-empty.\n    \"\"\"\n    # Count the number of odd numbers in lst1\n    odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n    \n    # Check if there are enough even numbers in lst2 to replace the odd numbers in lst1\n    even_count_lst2 = sum(1 for x in lst2 if x % 2 == 0)\n    \n    # If the number of odd numbers in lst1 is less than or equal to the number of even numbers in lst2\n    if odd_count_lst1 <= even_count_lst2:\n        return \"YES\"\n    else:\n        return \"NO\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n    \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n    \n    Examples\n    solution([5, 8, 7, 1]) ==> 12\n    solution([3, 3, 3, 3, 3]) ==> 9\n    solution([30, 13, 24, 321]) ==> 0\n    \"\"\"\n    return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n    \"\"\"Given a string s and a natural number n, returns a list of all words from \n    string s that contain exactly n consonants, in the order they appear in the \n    string s. If the string s is empty, returns an empty list.\n    \n    Args:\n    s (str): The input string containing words.\n    n (int): The number of consonants to match.\n    \n    Returns:\n    list: A list of words containing exactly n consonants.\n    \"\"\"\n    \n    if not s:\n        return []\n    \n    # Define a set of consonants\n    consonants = set(\"bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ\")\n    \n    # Split the string into words\n    words = s.split()\n    \n    # Function to count consonants in a word\n    def count_consonants(word):\n        return sum(1 for char in word if char in consonants)\n    \n    # Select words with exactly n consonants\n    result = [word for word in words if count_consonants(word) == n]\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n    \"\"\"\n    You are given an array arr of integers and you need to return\n    sum of magnitudes of integers multiplied by product of all signs\n    of each number in the array, represented by 1, -1 or 0.\n    Note: return None for empty arr.\n\n    Example:\n    >>> prod_signs([1, 2, 2, -4]) == -9\n    >>> prod_signs([0, 1]) == 0\n    >>> prod_signs([]) == None\n    \"\"\"\n    if not arr:\n        return None\n\n    product_of_signs = 1\n    sum_of_magnitudes = 0\n\n    for num in arr:\n        if num > 0:\n            sum_of_magnitudes += num\n        elif num < 0:\n            sum_of_magnitudes += -num\n            product_of_signs *= -1\n        else:  # num == 0\n            return 0  # If there's a zero, the product of signs is zero\n\n    return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n    '''\n    You are given a list of two strings, both strings consist of open\n    parentheses '(' or close parentheses ')' only.\n    Your job is to check if it is possible to concatenate the two strings in\n    some order, that the resulting string will be good.\n    A string S is considered to be good if and only if all parentheses in S\n    are balanced. For example: the string '(())()' is good, while the string\n    '())' is not.\n    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n    Examples:\n    match_parens(['()(', ')']) == 'Yes'\n    match_parens([')', ')']) == 'No'\n    '''\n    \n    def is_good(s):\n        balance = 0\n        for char in s:\n            if char == '(':\n                balance += 1\n            else:  # char == ')'\n                balance -= 1\n            if balance < 0:  # More closing than opening\n                return False\n        return balance == 0  # Must be balanced at the end\n\n    # Check both concatenation orders\n    return 'Yes' if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]) else 'No'", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n    '''\n    Given a list of numbers, return whether or not they are sorted\n    in ascending order. If list has more than 1 duplicate of the same\n    number, return False. Assume no negative numbers and only integers.\n\n    Examples\n    is_sorted([5]) \u279e True\n    is_sorted([1, 2, 3, 4, 5]) \u279e True\n    is_sorted([1, 3, 2, 4, 5]) \u279e False\n    is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n    is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n    is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n    is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n    is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n    '''\n    if len(lst) <= 1:\n        return True\n    \n    seen = set()\n    last_num = None\n    \n    for num in lst:\n        if num in seen:\n            return False\n        seen.add(num)\n        \n        if last_num is not None and num < last_num:\n            return False\n        \n        last_num = num\n    \n    return True", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": [[[1, 1, 2, 2, 3, 3, 4]]]}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n    \"\"\"\n    Write a function which sorts the given list of integers\n    in ascending order according to the sum of their digits.\n    Note: if there are several items with similar sum of their digits,\n    order them based on their index in original list.\n\n    For example:\n    >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n    >>> order_by_points([]) == []\n    \"\"\"\n    \n    def digit_sum(n):\n        \"\"\"Calculate the sum of the digits of n.\"\"\"\n        return sum(int(digit) for digit in str(abs(n)))\n\n    # Sort the list based on the sum of digits and original index\n    return sorted(nums, key=lambda x: (digit_sum(x), nums.index(x)))", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": [[[-5, -12, 9, 15]]]}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n    \"\"\"\n    This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n    multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n    change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n    \n    Examples:\n    For lst = [1,2,3] the output should be 6\n    For lst = []  the output should be 0\n    For lst = [-1,-5,2,-1,-5]  the output should be -126\n    \"\"\"\n    total_sum = 0\n    for index, value in enumerate(lst):\n        if index % 3 == 0:\n            total_sum += value ** 2\n        elif index % 4 == 0:\n            total_sum += value ** 3\n        else:\n            total_sum += value\n    return total_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n    \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n    two consonants from the right side of the word (case sensitive).\n    \n    Vowels in the beginning and ending don't count. Return empty string if you didn't\n    find any vowel that meets the above condition. \n\n    You may assume that the given string contains English letters only.\n\n    Example:\n    get_closest_vowel(\"yogurt\") ==> \"u\"\n    get_closest_vowel(\"FULL\") ==> \"U\"\n    get_closest_vowel(\"quick\") ==> \"\"\n    get_closest_vowel(\"ab\") ==> \"\"\n    \"\"\"\n    vowels = \"aeiouAEIOU\"\n    n = len(word)\n\n    # Start from the end of the word\n    for i in range(n - 2, 0, -1):\n        if word[i] in vowels:\n            # Check if the characters before and after the vowel are consonants\n            if word[i - 1].isalpha() and word[i + 1].isalpha() and \\\n               word[i - 1] not in vowels and word[i + 1] not in vowels:\n                return word[i]\n    \n    return \"\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef intersection(interval1, interval2):\n    \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n    start1, end1 = interval1\n    start2, end2 = interval2\n    \n    # Find the intersection\n    start_intersection = max(start1, start2)\n    end_intersection = min(end1, end2)\n    \n    # Check if there is an intersection\n    if start_intersection > end_intersection:\n        return \"NO\"\n    \n    # Calculate the length of the intersection\n    length_of_intersection = end_intersection - start_intersection\n    \n    # Check if the length is a prime number\n    if is_prime(length_of_intersection):\n        return \"YES\"\n    else:\n        return \"NO\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n    \"\"\"\n    Given an array arr of integers and a positive integer k, return a sorted list \n    of length k with the maximum k numbers in arr.\n\n    Example 1:\n        Input: arr = [-3, -4, 5], k = 3\n        Output: [-4, -3, 5]\n\n    Example 2:\n        Input: arr = [4, -4, 4], k = 2\n        Output: [4, 4]\n\n    Example 3:\n        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n        Output: [2]\n\n    Note:\n        1. The length of the array will be in the range of [1, 1000].\n        2. The elements in the array will be in the range of [-1000, 1000].\n        3. 0 <= k <= len(arr)\n    \"\"\"\n    # Sort the array in descending order\n    sorted_arr = sorted(arr, reverse=True)\n    # Get the top k elements\n    top_k = sorted_arr[:k]\n    # Sort the result in ascending order before returning\n    return sorted(top_k)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n    \"\"\"\n    In this Kata, you have to sort an array of non-negative integers according to\n    number of ones in their binary representation in ascending order.\n    For similar number of ones, sort based on decimal value.\n\n    It must be implemented like this:\n    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n    >>> sort_array([1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]\n    \"\"\"\n    # Sort the array using a custom key\n    return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n    \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n    of the letter with the most repetition and containing the corresponding count.\n    If several letters have the same occurrence, return all of them.\n    \n    Example:\n    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n    histogram('a b b a') == {'a': 2, 'b': 2}\n    histogram('a b c a b') == {'a': 2, 'b': 2}\n    histogram('b b b b a') == {'b': 4}\n    histogram('') == {}\n    \"\"\"\n    if not test:\n        return {}\n\n    # Split the input string into a list of letters\n    letters = test.split()\n    \n    # Create a dictionary to count occurrences of each letter\n    count_dict = {}\n    for letter in letters:\n        count_dict[letter] = count_dict.get(letter, 0) + 1\n\n    # Find the maximum count\n    max_count = max(count_dict.values())\n    \n    # Create a result dictionary for letters with the maximum count\n    result = {letter: count for letter, count in count_dict.items() if count == max_count}\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n    from collections import deque\n\n    N = len(grid)\n    directions = [(0, 1), (1, 0), (0, -1), (-1, 0)]  # right, down, left, up\n    min_path = None\n\n    def dfs(x, y, path):\n        nonlocal min_path\n        if len(path) == k:\n            if min_path is None or path < min_path:\n                min_path = path[:]\n            return\n        \n        for dx, dy in directions:\n            nx, ny = x + dx, y + dy\n            if 0 <= nx < N and 0 <= ny < N:\n                path.append(grid[nx][ny])\n                dfs(nx, ny, path)\n                path.pop()\n\n    for i in range(N):\n        for j in range(N):\n            dfs(i, j, [grid[i][j]])\n\n    return min_path", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": [[[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 15]]}]}}
\ No newline at end of file
diff --git a/EVALPLUS-4omini/4.json b/EVALPLUS-4omini/4.json
deleted file mode 100644
index 756827c37..000000000
--- a/EVALPLUS-4omini/4.json
+++ /dev/null
@@ -1 +0,0 @@
-{"date": "2024-07-20 13:00", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n    \"\"\"\n    Given two positive integers a and b, return the even digits between a\n    and b, in ascending order.\n\n    For example:\n    generate_integers(2, 8) => [2, 4, 6, 8]\n    generate_integers(8, 2) => [2, 4, 6, 8]\n    generate_integers(10, 14) => []\n    \"\"\"\n    # Determine the range of numbers to consider\n    start = min(a, b)\n    end = max(a, b)\n\n    # Generate a list of even integers in the specified range\n    even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n    return even_integers", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[2, 10]], "plus_fail_tests": [[6, 12]]}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n    \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n    Example:\n        even_odd_count(-12) ==> (1, 1)\n        even_odd_count(123) ==> (1, 2)\n    \"\"\"\n    # Convert the number to a string and remove the negative sign if present\n    num_str = str(abs(num))\n    \n    even_count = 0\n    odd_count = 0\n    \n    # Iterate through each character in the string representation of the number\n    for digit in num_str:\n        if digit.isdigit():  # Check if the character is a digit\n            if int(digit) % 2 == 0:\n                even_count += 1\n            else:\n                odd_count += 1\n    \n    return (even_count, odd_count)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n    \"\"\"Compares the actual game scores with the guessed scores and returns the absolute differences.\n    \n    Args:\n        game (list of int): The actual scores of the matches.\n        guess (list of int): The guessed scores of the matches.\n        \n    Returns:\n        list of int: A list containing the absolute differences between the actual scores and the guessed scores.\n                      If the guess is correct, the difference is 0.\n    \"\"\"\n    return [abs(g - a) for a, g in zip(game, guess)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def compare_one(a, b):\n    \"\"\"\n    Create a function that takes integers, floats, or strings representing\n    real numbers, and returns the larger variable in its given variable type.\n    Return None if the values are equal.\n    Note: If a real number is represented as a string, the floating point might be . or ,\n\n    compare_one(1, 2.5) \u279e 2.5\n    compare_one(1, \"2,3\") \u279e \"2,3\"\n    compare_one(\"5,1\", \"6\") \u279e \"6\"\n    compare_one(\"1\", 1) \u279e None\n    \"\"\"\n    \n    def parse_value(value):\n        \"\"\"Convert the input value to a float or return it as is if it's not a number.\"\"\"\n        if isinstance(value, str):\n            # Replace comma with dot for float conversion\n            value = value.replace(',', '.')\n            try:\n                return float(value)\n            except ValueError:\n                return value  # Return the string if it cannot be converted\n        return value  # Return the number as is\n\n    # Parse both values\n    parsed_a = parse_value(a)\n    parsed_b = parse_value(b)\n\n    # Check for equality\n    if parsed_a == parsed_b:\n        return None\n\n    # Return the larger value in its original type\n    if parsed_a > parsed_b:\n        return a\n    else:\n        return b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n    \"\"\"\n    Write a function count_nums which takes an array of integers and returns\n    the number of elements which has a sum of digits > 0.\n    If a number is negative, then its first signed digit will be negative:\n    e.g. -123 has signed digits -1, 2, and 3.\n    \n    >>> count_nums([]) == 0\n    >>> count_nums([-1, 11, -11]) == 1\n    >>> count_nums([1, 1, 2]) == 3\n    \"\"\"\n    def sum_of_digits(n):\n        # Convert the number to string and calculate the sum of its digits\n        return sum(int(digit) if digit != '-' else -int(digit[1]) for digit in str(n) if digit.isdigit() or digit == '-')\n\n    count = 0\n    for number in arr:\n        if sum_of_digits(number) > 0:\n            count += 1\n            \n    return count", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[-1, -2, 0]]], "plus_fail_tests": [[[-1, 0, 1]]]}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n    \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n    around the mean of this dataset.\n    Mean Absolute Deviation is the average absolute difference between each\n    element and a centerpoint (mean in this case):\n    MAD = average | x - x_mean |\n    \n    >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n    1.0\n    \"\"\"\n    if not numbers:\n        return 0.0  # Return 0 for empty list to avoid division by zero\n\n    mean = sum(numbers) / len(numbers)\n    mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n    return mad", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def factorial(i):\n    \"\"\"Calculate the factorial of a given number i.\"\"\"\n    if i == 0 or i == 1:\n        return 1\n    result = 1\n    for j in range(2, i + 1):\n        result *= j\n    return result\ndef sum_of_numbers(i):\n    \"\"\"Calculate the sum of numbers from 1 to i.\"\"\"\n    return (i * (i + 1)) // 2\ndef f(n):\n    \"\"\"Return a list of size n, where the value at index i is the factorial of i if i is even,\n    or the sum of numbers from 1 to i otherwise. Indexing starts from 1.\n    \"\"\"\n    result = []\n    for i in range(1, n + 1):\n        if i % 2 == 0:  # i is even\n            result.append(factorial(i))\n        else:  # i is odd\n            result.append(sum_of_numbers(i))\n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n    \"\"\"\n    You will be given a string of words separated by commas or spaces. Your task is\n    to split the string into words and return an array of the words.\n    \n    For example:\n    words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n    words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n    \"\"\"\n    # Split the string by commas and spaces, then filter out any empty strings\n    words = [word.strip() for word in s.replace(',', ' ').split() if word]\n    return words", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n    \"\"\" \n    You're given a list of deposit and withdrawal operations on a bank account that starts with\n    zero balance. Your task is to detect if at any point the balance of account falls below zero, and\n    at that point function should return True. Otherwise it should return False.\n    \n    >>> below_zero([1, 2, 3])\n    False\n    >>> below_zero([1, 2, -4, 5])\n    True\n    \"\"\"\n    balance = 0\n    for operation in operations:\n        balance += operation\n        if balance < 0:\n            return True\n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n    \"\"\"\n    Given a string 'text', return its md5 hash equivalent string.\n    If 'text' is an empty string, return None.\n\n    >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n    >>> string_to_md5('') is None\n    >>> string_to_md5('Python') == '5d41402abc4b2a76b9719d911017c592'\n    \"\"\"\n    if text == \"\":\n        return None\n    md5_hash = hashlib.md5(text.encode()).hexdigest()\n    return md5_hash", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n    \"\"\"Find the strongest extension based on the defined strength criteria.\"\"\"\n    strongest_extension = None\n    max_strength = float('-inf')  # Start with the lowest possible strength\n\n    for extension in extensions:\n        # Calculate the strength of the current extension\n        CAP = sum(1 for char in extension if char.isupper())\n        SM = sum(1 for char in extension if char.islower())\n        strength = CAP - SM\n\n        # Check if this extension is stronger than the current strongest\n        if strength > max_strength:\n            max_strength = strength\n            strongest_extension = extension\n\n    # Return the result in the specified format\n    return f\"{class_name}.{strongest_extension}\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n    \"\"\"Calculate the factorial of a non-negative integer n.\"\"\"\n    if n == 0 or n == 1:\n        return 1\n    result = 1\n    for i in range(2, n + 1):\n        result *= i\n    return result\ndef special_factorial(n):\n    \"\"\"Calculate the Brazilian factorial of n.\"\"\"\n    if n <= 0:\n        raise ValueError(\"Input must be a positive integer.\")\n    \n    result = 1\n    for i in range(1, n + 1):\n        result *= factorial(i)\n    \n    return result", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[500]]}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n    \"\"\"You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word.\n    \n    Args:\n    a (str): The first word.\n    b (str): The second word.\n    \n    Returns:\n    bool: True if b or any of its rotations is a substring of a, False otherwise.\n    \n    Examples:\n    >>> cycpattern_check(\"abcd\", \"abd\")\n    False\n    >>> cycpattern_check(\"hello\", \"ell\")\n    True\n    >>> cycpattern_check(\"whassup\", \"psus\")\n    False\n    >>> cycpattern_check(\"abab\", \"baa\")\n    True\n    >>> cycpattern_check(\"efef\", \"eeff\")\n    False\n    >>> cycpattern_check(\"himenss\", \"simen\")\n    True\n    \"\"\"\n    # Create a string that contains all rotations of b\n    rotations = [b[i:] + b[:i] for i in range(len(b))]\n    \n    # Check if any rotation is a substring of a\n    for rotation in rotations:\n        if rotation in a:\n            return True\n            \n    return False", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["", ""]]}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n    \"\"\" Given a positive floating point number, it can be decomposed into\n    an integer part (largest integer smaller than given number) and decimals\n    (leftover part always smaller than 1).\n\n    Return the decimal part of the number.\n    \n    >>> truncate_number(3.5)\n    0.5\n    >>> truncate_number(2.75)\n    0.75\n    >>> truncate_number(5.0)\n    0.0\n    >>> truncate_number(0.99)\n    0.99\n    \"\"\"\n    if number < 0:\n        raise ValueError(\"The number must be positive.\")\n    \n    integer_part = int(number)  # Get the integer part\n    decimal_part = number - integer_part  # Calculate the decimal part\n    return decimal_part", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n    \"\"\"Calculate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n    if n < 0:\n        return []\n\n    # Initialize the list to store the Tribonacci numbers\n    tribonacci_sequence = []\n\n    # Define the base cases\n    for i in range(n + 1):\n        if i == 0:\n            tribonacci_sequence.append(1)  # tri(0) = 1\n        elif i == 1:\n            tribonacci_sequence.append(3)  # tri(1) = 3\n        elif i % 2 == 0:  # Even case\n            tribonacci_sequence.append(1 + i / 2)\n        else:  # Odd case\n            tri_n_minus_1 = tribonacci_sequence[i - 1]\n            tri_n_minus_2 = tribonacci_sequence[i - 2]\n            tri_n_plus_1 = tribonacci_sequence[i + 1] if i + 1 <= n else 0\n            tribonacci_sequence.append(tri_n_minus_1 + tri_n_minus_2 + tri_n_plus_1)\n\n    return tribonacci_sequence", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[3]], "plus_fail_tests": [[10]]}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n    \"\"\"\n    Given a positive integer n, return a tuple that has the number of even and odd\n    integer palindromes that fall within the range(1, n), inclusive.\n\n    Example 1:\n\n        Input: 3\n        Output: (1, 2)\n        Explanation:\n        Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n    Example 2:\n\n        Input: 12\n        Output: (4, 6)\n        Explanation:\n        Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n    Note:\n        1. 1 <= n <= 10^3\n        2. returned tuple has the number of even and odd integer palindromes respectively.\n    \"\"\"\n    even_count = 0\n    odd_count = 0\n\n    for i in range(1, n + 1):\n        if str(i) == str(i)[::-1]:  # Check if the number is a palindrome\n            if i % 2 == 0:\n                even_count += 1\n            else:\n                odd_count += 1\n\n    return (even_count, odd_count)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n    \"\"\"\n    Given a positive integer n, you have to make a pile of n levels of stones.\n    The first level has n stones.\n    The number of stones in the next level is:\n        - the next odd number if n is odd.\n        - the next even number if n is even.\n    Return the number of stones in each level in a list, where element at index\n    i represents the number of stones in the level (i+1).\n\n    Examples:\n    >>> make_a_pile(3)\n    [3, 5, 7]\n    >>> make_a_pile(4)\n    [4, 6, 8, 10]\n    >>> make_a_pile(1)\n    [1]\n    \"\"\"\n    stones = []\n    current_stones = n\n    \n    for i in range(n):\n        stones.append(current_stones)\n        if current_stones % 2 == 0:  # current_stones is even\n            current_stones += 2  # next even number\n        else:  # current_stones is odd\n            current_stones += 2  # next odd number\n    \n    return stones", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n    \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n    \n    Args:\n        n (int): The number to evaluate.\n        \n    Returns:\n        bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n    \n    Example:\n    is_equal_to_sum_even(4) == False\n    is_equal_to_sum_even(6) == False\n    is_equal_to_sum_even(8) == True\n    \"\"\"\n    # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n    if n < 8:\n        return False\n    \n    # Check if n is even\n    if n % 2 != 0:\n        return False\n    \n    # If n is even and >= 8, it can be expressed as the sum of 4 positive even numbers\n    return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n    \"\"\" Insert a number 'delimiter' between every two consecutive elements of input list `numbers`\n    \n    >>> intersperse([], 4)\n    []\n    >>> intersperse([1, 2, 3], 4)\n    [1, 4, 2, 4, 3]\n    \"\"\"\n    if not numbers:\n        return []\n    \n    result = []\n    for i in range(len(numbers)):\n        result.append(numbers[i])\n        if i < len(numbers) - 1:  # Avoid adding delimiter after the last element\n            result.append(delimiter)\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n    \"\"\"Given a positive integer n, return the product of the odd digits.\n    Return 0 if all digits are even.\n    For example:\n    digits(1)  == 1\n    digits(4)  == 0\n    digits(235) == 15\n    \"\"\"\n    product = 1\n    has_odd = False\n    \n    for digit in str(n):\n        digit = int(digit)\n        if digit % 2 != 0:  # Check if the digit is odd\n            product *= digit\n            has_odd = True\n            \n    return product if has_odd else 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n    '''\n    Create a function that returns a tuple (a, b), where 'a' is\n    the largest of negative integers, and 'b' is the smallest\n    of positive integers in a list.\n    If there is no negative or positive integers, return them as None.\n\n    Examples:\n    largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n    largest_smallest_integers([]) == (None, None)\n    largest_smallest_integers([0]) == (None, None)\n    '''\n    largest_negative = None\n    smallest_positive = None\n\n    for num in lst:\n        if num < 0:\n            if largest_negative is None or num > largest_negative:\n                largest_negative = num\n        elif num > 0:\n            if smallest_positive is None or num < smallest_positive:\n                smallest_positive = num\n\n    return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n    \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n    numbers in the array will be randomly ordered. Your task is to determine if\n    it is possible to get an array sorted in non-decreasing order by performing \n    the following operation on the given array:\n        You are allowed to perform right shift operation any number of times.\n    \n    One right shift operation means shifting all elements of the array by one\n    position in the right direction. The last element of the array will be moved to\n    the starting position in the array i.e. 0th index. \n\n    If it is possible to obtain the sorted array by performing the above operation\n    then return True else return False.\n    If the given array is empty then return True.\n\n    Note: The given list is guaranteed to have unique elements.\n\n    For Example:\n    \n    move_one_ball([3, 4, 5, 1, 2])==>True\n    Explanation: By performing 2 right shift operations, non-decreasing order can\n                 be achieved for the given array.\n    move_one_ball([3, 5, 4, 1, 2])==>False\n    Explanation: It is not possible to get non-decreasing order for the given\n                array by performing any number of right shift operations.\n    \"\"\"\n    if not arr:\n        return True\n\n    n = len(arr)\n    sorted_arr = sorted(arr)\n\n    # Check how many times we can right shift to match the sorted array\n    for shift in range(n):\n        # Create a new array based on the current shift\n        shifted_arr = arr[-shift:] + arr[:-shift]\n        if shifted_arr == sorted_arr:\n            return True\n\n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n    \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n    other and return them in order (smaller number, larger number).\n    \n    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n    (2.0, 2.2)\n    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n    (2.0, 2.0)\n    \"\"\"\n    # Sort the numbers to make it easier to find the closest pair\n    sorted_numbers = sorted(numbers)\n    \n    # Initialize the minimum difference and the closest pair\n    min_diff = float('inf')\n    closest_pair = (0.0, 0.0)\n    \n    # Iterate through the sorted list to find the closest elements\n    for i in range(len(sorted_numbers) - 1):\n        diff = sorted_numbers[i + 1] - sorted_numbers[i]\n        if diff < min_diff:\n            min_diff = diff\n            closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n    \n    return closest_pair", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n    \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n    \n    >>> flip_case('Hello')\n    'hELLO'\n    >>> flip_case('Python')\n    'pYTHON'\n    >>> flip_case('123abcXYZ')\n    '123ABCxyz'\n    >>> flip_case('')\n    ''\n    \"\"\"\n    return string.swapcase()", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n    \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n    \n    >>> how_many_times('', 'a')\n    0\n    >>> how_many_times('aaa', 'a')\n    3\n    >>> how_many_times('aaaa', 'aa')\n    3\n    \"\"\"\n    count = 0\n    start = 0\n    \n    while True:\n        start = string.find(substring, start)\n        if start == -1:\n            break\n        count += 1\n        start += 1  # Move to the next character to allow for overlapping\n\n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n    \"\"\" Input are two strings a and b consisting only of 1s and 0s.\n    Perform binary XOR on these inputs and return result also as a string.\n    \n    >>> string_xor('010', '110')\n    '100'\n    >>> string_xor('111', '000')\n    '111'\n    >>> string_xor('101', '101')\n    '000'\n    >>> string_xor('000', '000')\n    '000'\n    >>> string_xor('1101', '1011')\n    '0110'\n    \"\"\"\n    # Ensure both strings are of the same length\n    max_len = max(len(a), len(b))\n    a = a.zfill(max_len)\n    b = b.zfill(max_len)\n    \n    # Perform XOR operation\n    result = []\n    for bit_a, bit_b in zip(a, b):\n        result.append('1' if bit_a != bit_b else '0')\n    \n    return ''.join(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n    \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n    >>> count_distinct_characters('xyzXYZ')\n    3\n    >>> count_distinct_characters('Jerry')\n    4\n    \"\"\"\n    # Convert the string to lowercase to ensure case insensitivity\n    lower_string = string.lower()\n    # Use a set to find distinct characters\n    distinct_characters = set(lower_string)\n    # Return the number of distinct characters\n    return len(distinct_characters)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n    \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n    \n    Args:\n        strings (List[str]): A list of strings to filter.\n        prefix (str): The prefix to filter the strings by.\n    \n    Returns:\n        List[str]: A list of strings that start with the given prefix.\n    \n    Examples:\n        >>> filter_by_prefix([], 'a')\n        []\n        >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n        ['abc', 'array']\n    \"\"\"\n    return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n    \"\"\"Create a function encrypt that takes a string as an argument and\n    returns a string encrypted with the alphabet being rotated. \n    The alphabet should be rotated in a manner such that the letters \n    shift down by two multiplied to two places.\n    For example:\n    encrypt('hi') returns 'lm'\n    encrypt('asdfghjkl') returns 'ewhjklnop'\n    encrypt('gf') returns 'kj'\n    encrypt('et') returns 'ix'\n    \"\"\"\n    encrypted = []\n    for char in s:\n        if char.isalpha():  # Check if the character is a letter\n            # Calculate the new character by shifting it down by 4 places\n            new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a')) if char.islower() else chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n            encrypted.append(new_char)\n        else:\n            encrypted.append(char)  # Non-alphabetic characters are not changed\n    return ''.join(encrypted)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n    \"\"\"\n    You are given a 2 dimensional data, as a nested lists,\n    which is similar to matrix, however, unlike matrices,\n    each row may contain a different number of columns.\n    Given lst, and integer x, find integers x in the list,\n    and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n    each tuple is a coordinate - (row, columns), starting with 0.\n    Sort coordinates initially by rows in ascending order.\n    Also, sort coordinates of the row by columns in descending order.\n    \n    Examples:\n    get_row([\n      [1,2,3,4,5,6],\n      [1,2,3,4,1,6],\n      [1,2,3,4,5,1]\n    ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n    get_row([], 1) == []\n    get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n    \"\"\"\n    coordinates = []\n    \n    for row_index, row in enumerate(lst):\n        for col_index, value in enumerate(row):\n            if value == x:\n                coordinates.append((row_index, col_index))\n    \n    # Sort by row index (ascending) and then by column index (descending)\n    coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n    \n    return coordinates", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n    \"\"\"Return list with elements incremented by 1.\n    \n    >>> incr_list([1, 2, 3])\n    [2, 3, 4]\n    >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n    [6, 4, 6, 3, 4, 4, 10, 1, 124]\n    \"\"\"\n    return [x + 1 for x in l]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n    \"\"\"Given length of a side and height, return the area of a triangle.\n    \n    The area of a triangle can be calculated using the formula:\n    area = (base * height) / 2\n    \n    Parameters:\n    a (float): The length of the base of the triangle.\n    h (float): The height of the triangle.\n    \n    Returns:\n    float: The area of the triangle.\n    \n    Examples:\n    >>> triangle_area(5, 3)\n    7.5\n    >>> triangle_area(10, 2)\n    10.0\n    >>> triangle_area(0, 5)\n    0.0\n    >>> triangle_area(5, 0)\n    0.0\n    \"\"\"\n    return (a * h) / 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n    \"\"\"\n    Given an array arr of integers, find the minimum number of elements that\n    need to be changed to make the array palindromic. A palindromic array is an array that\n    is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n    For example:\n    smallest_change([1,2,3,5,4,7,9,6]) == 4\n    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n    smallest_change([1, 2, 3, 2, 1]) == 0\n    \"\"\"\n    n = len(arr)\n    changes = 0\n    \n    # Compare elements from the start and end towards the center\n    for i in range(n // 2):\n        if arr[i] != arr[n - 1 - i]:\n            changes += 1\n            \n    return changes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n    '''\n    Write a function that accepts two lists of strings and returns the list that has \n    total number of chars in the all strings of the list less than the other list.\n\n    if the two lists have the same number of chars, return the first list.\n\n    Examples\n    total_match([], []) \u279e []\n    total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n    total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n    total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n    total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n    '''\n    # Calculate the total number of characters in each list\n    total_chars_lst1 = sum(len(s) for s in lst1)\n    total_chars_lst2 = sum(len(s) for s in lst2)\n\n    # Compare the total character counts and return the appropriate list\n    if total_chars_lst1 < total_chars_lst2:\n        return lst1\n    else:\n        return lst2", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": [[["happy", "birthday", "sarah"], ["happy", "birthday", "sally"]]]}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n    \"\"\"You are given a string s.\n    Your task is to check if the string is happy or not.\n    A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n    \n    For example:\n    is_happy(a) => False\n    is_happy(aa) => False\n    is_happy(abcd) => True\n    is_happy(aabb) => False\n    is_happy(adb) => True\n    is_happy(xyy) => False\n    \"\"\"\n    # Check if the length of the string is at least 3\n    if len(s) < 3:\n        return False\n    \n    # Iterate through the string and check every 3 consecutive characters\n    for i in range(len(s) - 2):\n        # Get the current 3 characters\n        substring = s[i:i+3]\n        # Check if all characters in the substring are distinct\n        if len(set(substring)) != 3:\n            return False\n    \n    return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n    \"\"\" Input to this function is a string representing musical notes in a special ASCII format.\n    Your task is to parse this string and return list of integers corresponding to how many beats does each\n    note last.\n\n    Here is a legend:\n    'o' - whole note, lasts four beats\n    'o|' - half note, lasts two beats\n    '.|' - quarter note, lasts one beat\n\n    >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n    [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n    \"\"\"\n    # Define a mapping of note representations to their corresponding beat values\n    note_to_beats = {\n        'o': 4,   # whole note\n        'o|': 2,  # half note\n        '.|': 1   # quarter note\n    }\n    \n    # Split the input string into individual notes\n    notes = music_string.split()\n    \n    # Parse each note and convert it to its corresponding beat value\n    beats = [note_to_beats[note] for note in notes if note in note_to_beats]\n    \n    return beats", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n    \"\"\" Concatenate list of strings into a single string.\n    \n    >>> concatenate([])\n    ''\n    >>> concatenate(['a', 'b', 'c'])\n    'abc'\n    \"\"\"\n    return ''.join(strings)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n    \"\"\" Test if given string is a palindrome \"\"\"\n    return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n    \"\"\" Find the shortest palindrome that begins with a supplied string.\n    Algorithm idea is simple:\n    - Find the longest postfix of supplied string that is a palindrome.\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n    \n    >>> make_palindrome('')\n    ''\n    >>> make_palindrome('cat')\n    'catac'\n    >>> make_palindrome('cata')\n    'catac'\n    \"\"\"\n    # Find the longest palindromic suffix\n    for i in range(len(string)):\n        if is_palindrome(string[i:]):\n            # If the suffix is a palindrome, we need to append the reverse of the prefix\n            prefix = string[:i]\n            return string + prefix[::-1]\n    return string  # In case the string is empty or already a palindrome", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n    \"\"\" From a list of integers, remove all elements that occur more than once.\n    Keep order of elements left the same as in the input.\n    \n    >>> remove_duplicates([1, 2, 3, 2, 4])\n    [1, 3, 4]\n    \"\"\"\n    # Count occurrences of each number\n    count = {}\n    for number in numbers:\n        count[number] = count.get(number, 0) + 1\n    \n    # Create a new list with elements that occur only once\n    result = [number for number in numbers if count[number] == 1]\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n    \"\"\" \n    Input is a space-delimited string of numerals from 'zero' to 'nine'.\n    Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n    Return the string with numbers sorted from smallest to largest.\n    \n    >>> sort_numbers('three one five')\n    'one three five'\n    \"\"\"\n    # Mapping of words to their corresponding numeric values\n    num_map = {\n        'zero': 0,\n        'one': 1,\n        'two': 2,\n        'three': 3,\n        'four': 4,\n        'five': 5,\n        'six': 6,\n        'seven': 7,\n        'eight': 8,\n        'nine': 9\n    }\n    \n    # Split the input string into words\n    words = numbers.split()\n    \n    # Sort the words based on their numeric values\n    sorted_words = sorted(words, key=lambda word: num_map[word])\n    \n    # Join the sorted words back into a string\n    return ' '.join(sorted_words)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n    \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n    such that the smallest number will become 0 and the largest will become 1.\n    \n    >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n    [0.0, 0.25, 0.5, 0.75, 1.0]\n    \"\"\"\n    if len(numbers) < 2:\n        raise ValueError(\"The list must contain at least two elements.\")\n    \n    min_val = min(numbers)\n    max_val = max(numbers)\n    \n    # Avoid division by zero if all numbers are the same\n    if min_val == max_val:\n        return [0.0] * len(numbers)\n    \n    return [(num - min_val) / (max_val - min_val) for num in numbers]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n    \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n    letter_grades = []\n    \n    for gpa in grades:\n        if gpa == 4.0:\n            letter_grades.append('A+')\n        elif gpa > 3.7:\n            letter_grades.append('A')\n        elif gpa > 3.3:\n            letter_grades.append('A-')\n        elif gpa > 3.0:\n            letter_grades.append('B+')\n        elif gpa > 2.7:\n            letter_grades.append('B')\n        elif gpa > 2.3:\n            letter_grades.append('B-')\n        elif gpa > 2.0:\n            letter_grades.append('C+')\n        elif gpa > 1.7:\n            letter_grades.append('C')\n        elif gpa > 1.3:\n            letter_grades.append('C-')\n        elif gpa > 1.0:\n            letter_grades.append('D+')\n        elif gpa > 0.7:\n            letter_grades.append('D')\n        elif gpa > 0.0:\n            letter_grades.append('D-')\n        else:\n            letter_grades.append('E')\n    \n    return letter_grades", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef get_primes_up_to(n):\n    \"\"\"Return a list of all prime numbers less than n.\"\"\"\n    return [i for i in range(2, n) if is_prime(i)]\ndef is_multiply_prime(a):\n    \"\"\"Return true if the given number is the multiplication of 3 prime numbers.\"\"\"\n    if a >= 100:\n        return False\n    \n    primes = get_primes_up_to(a)\n    prime_count = len(primes)\n    \n    # Check all combinations of three primes\n    for i in range(prime_count):\n        for j in range(i, prime_count):\n            for k in range(j, prime_count):\n                product = primes[i] * primes[j] * primes[k]\n                if product == a:\n                    return True\n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n    '''\n    Write a function that returns True if the object q will fly, and False otherwise.\n    The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n\n    Example:\n    will_it_fly([1, 2], 5) \u279e False \n    # 1+2 is less than the maximum possible weight, but it's unbalanced.\n\n    will_it_fly([3, 2, 3], 1) \u279e False\n    # it's balanced, but 3+2+3 is more than the maximum possible weight.\n\n    will_it_fly([3, 2, 3], 9) \u279e True\n    # 3+2+3 is less than the maximum possible weight, and it's balanced.\n\n    will_it_fly([3], 5) \u279e True\n    # 3 is less than the maximum possible weight, and it's balanced.\n    '''\n    # Check if the list is a palindrome\n    is_balanced = q == q[::-1]\n    \n    # Calculate the sum of the elements in the list\n    total_weight = sum(q)\n    \n    # Return True if it's balanced and the total weight is less than or equal to w\n    return is_balanced and total_weight <= w", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n    \"\"\"\n    Write a function that takes a string and returns an ordered version of it.\n    Ordered version of string, is a string where all words (separated by space)\n    are replaced by a new word where all the characters arranged in\n    ascending order based on ascii value.\n    Note: You should keep the order of words and blank spaces in the sentence.\n\n    For example:\n    anti_shuffle('Hi') returns 'Hi'\n    anti_shuffle('hello') returns 'ehllo'\n    anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n    \"\"\"\n    # Split the input string into words while preserving spaces\n    words = s.split(' ')\n    \n    # Sort each word and keep the spaces intact\n    sorted_words = [''.join(sorted(word)) for word in words]\n    \n    # Join the sorted words back with spaces\n    result = ' '.join(sorted_words)\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n    \"\"\"Change numerical base of input number x to base.\n    return string representation after the conversion.\n    base numbers are less than 10.\n    \n    >>> change_base(8, 3)\n    '22'\n    >>> change_base(8, 2)\n    '1000'\n    >>> change_base(7, 2)\n    '111'\n    \"\"\"\n    if base < 2 or base >= 10:\n        raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n    \n    if x == 0:\n        return '0'\n    \n    result = []\n    while x > 0:\n        result.append(str(x % base))\n        x //= base\n    \n    return ''.join(reversed(result))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n    \"\"\"\n    Given an array of non-negative integers, return a copy of the given array after sorting,\n    you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n    or sort it in descending order if the sum( first index value, last index value) is even.\n\n    Note:\n    * don't change the given array.\n\n    Examples:\n    * sort_array([]) => []\n    * sort_array([5]) => [5]\n    * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n    * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n    \"\"\"\n    if not array:  # Check for empty array\n        return []\n    \n    first_value = array[0]\n    last_value = array[-1]\n    sum_values = first_value + last_value\n\n    # Create a sorted copy of the array based on the sum of first and last values\n    if sum_values % 2 == 0:  # Even sum\n        return sorted(array, reverse=True)  # Sort in descending order\n    else:  # Odd sum\n        return sorted(array)  # Sort in ascending order", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n    \"\"\"\n    pairs_sum_to_zero takes a list of integers as an input.\n    it returns True if there are two distinct elements in the list that\n    sum to zero, and False otherwise.\n    \n    >>> pairs_sum_to_zero([1, 3, 5, 0])\n    False\n    >>> pairs_sum_to_zero([1, 3, -2, 1])\n    False\n    >>> pairs_sum_to_zero([1, 2, 3, 7])\n    False\n    >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n    True\n    >>> pairs_sum_to_zero([1])\n    False\n    \"\"\"\n    seen = set()\n    for number in l:\n        if -number in seen:\n            return True\n        seen.add(number)\n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n    \"\"\"\n    Given a dictionary, return True if all keys are strings in lower \n    case or all keys are strings in upper case, else return False.\n    The function should return False if the given dictionary is empty.\n    \n    Examples:\n    check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n    check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n    check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n    check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n    check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n    \"\"\"\n    if not input_dict:\n        return False\n\n    all_lower = all(isinstance(key, str) and key.islower() for key in input_dict.keys())\n    all_upper = all(isinstance(key, str) and key.isupper() for key in input_dict.keys())\n\n    return all_lower or all_upper", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n    \"\"\" \n    brackets is a string of \"(\" and \")\".\n    return True if every opening bracket has a corresponding closing bracket.\n\n    >>> correct_bracketing(\"(\")\n    False\n    >>> correct_bracketing(\"()\")\n    True\n    >>> correct_bracketing(\"(()())\")\n    True\n    >>> correct_bracketing(\")(()\")\n    False\n    \"\"\"\n    balance = 0\n    for char in brackets:\n        if char == '(':\n            balance += 1\n        elif char == ')':\n            balance -= 1\n        # If balance goes negative, there are unmatched closing brackets\n        if balance < 0:\n            return False\n    # At the end, balance should be zero for all opening brackets to be matched\n    return balance == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n    \"\"\"Task\n    Write a function that takes a string as input and returns the sum of the upper characters only'\n    ASCII codes.\n\n    Examples:\n        digitSum(\"\") => 0\n        digitSum(\"abAB\") => 131\n        digitSum(\"abcCd\") => 67\n        digitSum(\"helloE\") => 69\n        digitSum(\"woArBld\") => 131\n        digitSum(\"aAaaaXa\") => 153\n    \"\"\"\n    return sum(ord(char) for char in s if char.isupper())", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n    '''\n    Create a function that takes 3 numbers.\n    Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n    Returns false in any other cases.\n    \n    Examples\n    any_int(5, 2, 7) \u279e True\n    \n    any_int(3, 2, 2) \u279e False\n\n    any_int(3, -2, 1) \u279e True\n    \n    any_int(3.6, -2.2, 2) \u279e False\n    '''\n    # Check if all inputs are integers\n    if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n        # Check if one number is equal to the sum of the other two\n        return x == y + z or y == x + z or z == x + y\n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int):\n    \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n    \n    >>> largest_prime_factor(13195)\n    29\n    >>> largest_prime_factor(2048)\n    2\n    \"\"\"\n    # Start with the smallest prime factor\n    factor = 2\n    # Keep dividing n by factor until it is no longer divisible\n    while n > 1:\n        if n % factor == 0:\n            n //= factor  # Divide n by the factor\n        else:\n            factor += 1  # Move to the next potential factor\n    return factor  # The last factor is the largest prime factor", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n    \"\"\"\n    Takes as input a string encoded with encode_shift function. Returns decoded string.\n    \"\"\"\n    return \"\".join([chr(((ord(ch) - ord(\"a\") - 5) % 26) + ord(\"a\")) for ch in s])", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n    \"\"\"Return True if list elements are monotonically increasing or decreasing.\n    \n    >>> monotonic([1, 2, 4, 20])\n    True\n    >>> monotonic([1, 20, 4, 10])\n    False\n    >>> monotonic([4, 1, 0, -10])\n    True\n    \"\"\"\n    if not l:  # An empty list is considered monotonic\n        return True\n    \n    increasing = decreasing = True\n    \n    for i in range(1, len(l)):\n        if l[i] > l[i - 1]:\n            decreasing = False\n        elif l[i] < l[i - 1]:\n            increasing = False\n            \n    return increasing or decreasing", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n    \"\"\"\n    Given an array representing a branch of a tree that has non-negative integer nodes,\n    your task is to pluck one of the nodes and return it.\n    The plucked node should be the node with the smallest even value.\n    If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n    The plucked node should be returned in a list, [ smallest_value, its index ],\n    If there are no even values or the given array is empty, return [].\n\n    Example 1:\n        Input: [4,2,3]\n        Output: [2, 1]\n        Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n    Example 2:\n        Input: [1,2,3]\n        Output: [2, 1]\n        Explanation: 2 has the smallest even value, and 2 has the smallest index. \n\n    Example 3:\n        Input: []\n        Output: []\n    \n    Example 4:\n        Input: [5, 0, 3, 0, 4, 2]\n        Output: [0, 1]\n        Explanation: 0 is the smallest value, but there are two zeros,\n                     so we will choose the first zero, which has the smallest index.\n\n    Constraints:\n        * 1 <= nodes.length <= 10000\n        * 0 <= node.value\n    \"\"\"\n    smallest_even = float('inf')\n    smallest_index = -1\n\n    for index, value in enumerate(arr):\n        if value % 2 == 0:  # Check if the value is even\n            if value < smallest_even:  # Check if it's the smallest even found\n                smallest_even = value\n                smallest_index = index\n\n    if smallest_index == -1:  # No even value found\n        return []\n    \n    return [smallest_even, smallest_index]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float) -> float:\n    \"\"\"\n    Evaluates polynomial with coefficients xs at point x.\n    return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n    \"\"\"\n    return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list) -> list:\n    \"\"\"\n    Computes the derivative of the polynomial with coefficients xs.\n    \"\"\"\n    return [i * coeff for i, coeff in enumerate(xs) if i > 0]\ndef find_zero(xs: list, initial_guess: float = 0.0, tolerance: float = 1e-7, max_iterations: int = 1000) -> float:\n    \"\"\" \n    xs are coefficients of a polynomial.\n    find_zero finds x such that poly(x) = 0.\n    find_zero returns only one zero point, even if there are many.\n    Moreover, find_zero only takes list xs having an even number of coefficients\n    and the largest non-zero coefficient as it guarantees a solution.\n    \n    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n    -0.5\n    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n    1.0\n    \"\"\"\n    if len(xs) % 2 != 0:\n        raise ValueError(\"The number of coefficients must be even.\")\n    \n    current_guess = initial_guess\n    for _ in range(max_iterations):\n        f_value = poly(xs, current_guess)\n        f_derivative = poly(derivative(xs), current_guess)\n        \n        if f_derivative == 0:\n            raise ValueError(\"Derivative is zero. No solution found.\")\n        \n        next_guess = current_guess - f_value / f_derivative\n        \n        if abs(next_guess - current_guess) < tolerance:\n            return next_guess\n        \n        current_guess = next_guess\n    \n    raise ValueError(\"Maximum iterations reached. No solution found.\")", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[[5, 10, -3, 1]]]}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n    \"\"\"Return maximum element in the list.\n    \n    >>> max_element([1, 2, 3])\n    3\n    >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n    123\n    \"\"\"\n    if not l:\n        raise ValueError(\"The list is empty.\")\n    max_value = l[0]\n    for item in l:\n        if item > max_value:\n            max_value = item\n    return max_value", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n    \"\"\" brackets is a string of \"<\" and \">\".\n    return True if every opening bracket has a corresponding closing bracket.\n\n    >>> correct_bracketing(\"<\")\n    False\n    >>> correct_bracketing(\"<>\")\n    True\n    >>> correct_bracketing(\"<<><>>\")\n    True\n    >>> correct_bracketing(\"><<>\")\n    False\n    \"\"\"\n    balance = 0\n    for char in brackets:\n        if char == '<':\n            balance += 1\n        elif char == '>':\n            balance -= 1\n        # If balance goes negative, it means there's a closing bracket without a matching opening bracket\n        if balance < 0:\n            return False\n    # At the end, balance should be zero for all opening brackets to be matched\n    return balance == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n    \"\"\"\n    remove_vowels is a function that takes a string and returns a string without vowels.\n    \n    >>> remove_vowels('')\n    ''\n    >>> remove_vowels(\"abcdef\\nghijklm\")\n    'bcdf\\nghjklm'\n    >>> remove_vowels('abcdef')\n    'bcdf'\n    >>> remove_vowels('aaaaa')\n    ''\n    >>> remove_vowels('aaBAA')\n    'B'\n    >>> remove_vowels('zbcd')\n    'zbcd'\n    \"\"\"\n    vowels = 'aeiouAEIOU'\n    return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n    '''\n    You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n    zero, and has a frequency greater than or equal to the value of the integer itself. \n    The frequency of an integer is the number of times it appears in the list.\n    If no such a value exist, return -1.\n    \n    Examples:\n        search([4, 1, 2, 2, 3, 1]) == 2\n        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n        search([5, 5, 4, 4, 4]) == -1\n    '''\n    from collections import Counter\n    \n    # Count the frequency of each number in the list\n    frequency = Counter(lst)\n    \n    # Initialize the result variable\n    result = -1\n    \n    # Iterate through the frequency dictionary\n    for num, freq in frequency.items():\n        # Check if the frequency is greater than or equal to the number itself\n        if freq >= num:\n            # Update the result if this number is greater than the current result\n            result = max(result, num)\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n    \"\"\"\n    Write a function that takes a message, and encodes in such a \n    way that it swaps case of all letters, replaces all vowels in \n    the message with the letter that appears 2 places ahead of that \n    vowel in the english alphabet. \n    Assume only letters. \n    \n    Examples:\n    >>> encode('test')\n    'TGST'\n    >>> encode('This is a message')\n    'tHKS KS C MGSSCGG'\n    \"\"\"\n    vowels = 'aeiouAEIOU'\n    encoded_message = []\n\n    for char in message:\n        if char.isalpha():  # Check if the character is a letter\n            # Swap case\n            if char in vowels:\n                # Replace vowel with the letter 2 places ahead\n                if char.islower():\n                    new_char = chr((ord(char) - ord('a') + 2) % 26 + ord('a'))\n                else:\n                    new_char = chr((ord(char) - ord('A') + 2) % 26 + ord('A'))\n            else:\n                new_char = char.swapcase()  # Swap case for consonants\n            encoded_message.append(new_char)\n        else:\n            encoded_message.append(char)  # Keep non-letter characters unchanged\n\n    return ''.join(encoded_message)", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["TEST"]], "plus_fail_tests": [["abcdefghijklmnopqrstuvwxyz"]]}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n    \"\"\"\n    In this task, you will be given a string that represents a number of apples and oranges \n    that are distributed in a basket of fruit. This basket contains \n    apples, oranges, and mango fruits. Given the string that represents the total number of \n    the oranges and apples and an integer that represents the total number of the fruits \n    in the basket, return the number of the mango fruits in the basket.\n    \n    Parameters:\n    s (str): A string representing the number of apples and oranges.\n    n (int): An integer representing the total number of fruits in the basket.\n    \n    Returns:\n    int: The number of mango fruits in the basket.\n    \n    Examples:\n    fruit_distribution(\"5 apples and 6 oranges\", 19) -> 8\n    fruit_distribution(\"0 apples and 1 oranges\", 3) -> 2\n    fruit_distribution(\"2 apples and 3 oranges\", 100) -> 95\n    fruit_distribution(\"100 apples and 1 oranges\", 120) -> 19\n    \"\"\"\n    \n    # Extract the number of apples and oranges from the string\n    parts = s.split()\n    apples = int(parts[0])  # First part is the number of apples\n    oranges = int(parts[3])  # Fourth part is the number of oranges\n    \n    # Calculate the number of mangoes\n    mangoes = n - apples - oranges\n    \n    return mangoes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n    \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n    \n    >>> sum_to_n(30)\n    465\n    >>> sum_to_n(100)\n    5050\n    >>> sum_to_n(5)\n    15\n    >>> sum_to_n(10)\n    55\n    >>> sum_to_n(1)\n    1\n    \"\"\"\n    return n * (n + 1) // 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n    \"\"\"Return sorted unique common elements for two lists.\n    \n    >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n    [1, 5, 653]\n    >>> common([5, 3, 2, 8], [3, 2])\n    [2, 3]\n    \n    \"\"\"\n    # Convert both lists to sets to find unique elements\n    set1 = set(l1)\n    set2 = set(l2)\n    \n    # Find the intersection of both sets\n    common_elements = set1.intersection(set2)\n    \n    # Return the sorted list of common elements\n    return sorted(common_elements)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n    \"\"\"Return sorted unique elements in a list\n    >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n    [0, 2, 3, 5, 9, 123]\n    \"\"\"\n    return sorted(set(l))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n    \"\"\"This function takes a list l and returns a list l' such that\n    l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n    to the values of the corresponding indices of l, but sorted.\n    \n    >>> sort_third([1, 2, 3])\n    [1, 2, 3]\n    >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n    [2, 6, 3, 4, 8, 9, 5]\n    \"\"\"\n    # Extract values at indices divisible by 3\n    divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n    \n    # Sort the extracted values\n    sorted_values = sorted(divisible_by_three)\n    \n    # Create a new list to hold the result\n    result = l.copy()\n    \n    # Replace values at indices divisible by 3 with sorted values\n    for index, value in zip((i for i in range(len(l)) if i % 3 == 0), sorted_values):\n        result[index] = value\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n    \"\"\"\n    Given an array of integers nums, find the minimum sum of any non-empty sub-array\n    of nums.\n    \n    Example\n    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n    minSubArraySum([-1, -2, -3]) == -6\n    \"\"\"\n    # Initialize variables to track the minimum sum and the current sum\n    min_sum = float('inf')\n    current_sum = 0\n    \n    for num in nums:\n        current_sum += num\n        min_sum = min(min_sum, current_sum)\n        \n        # If current_sum is positive, reset it to 0\n        if current_sum > 0:\n            current_sum = 0\n            \n    return min_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n    \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n    Each element i of the output should be \"the number of odd elements in the\n    string i of the input.\" where all the i's should be replaced by the number\n    of odd digits in the i'th string of the input.\n\n    >>> odd_count(['1234567'])\n    [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n    >>> odd_count(['3',\"11111111\"])\n    [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n     \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n    \"\"\"\n    result = []\n    for s in lst:\n        odd_count = sum(1 for char in s if char in '13579')\n        result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n    '''\n    Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n    should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n    alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n    \n    Examples:\n    split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n    split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n    split_words(\"abcdef\") \u279e 3 \n    '''\n    # Check for whitespace\n    if ' ' in txt:\n        return txt.split()\n    \n    # Check for commas\n    elif ',' in txt:\n        return txt.split(',')\n    \n    # If no whitespace or commas, count lower-case letters with odd order\n    else:\n        odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n        return odd_count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n    \"\"\"\n    Given a non-empty array of integers arr and an integer k, return\n    the sum of the elements with at most two digits from the first k elements of arr.\n\n    Example:\n\n        Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n        Output: 24 # sum of 21 + 3\n\n    Constraints:\n        1. 1 <= len(arr) <= 100\n        2. 1 <= k <= len(arr)\n    \"\"\"\n    # Initialize the sum\n    total_sum = 0\n    \n    # Iterate through the first k elements of the array\n    for i in range(k):\n        # Check if the current element has at most two digits\n        if -100 < arr[i] < 100:\n            total_sum += arr[i]\n    \n    return total_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n    \"\"\"Accepts a list of strings, removes strings with odd lengths,\n    and returns the remaining strings sorted by length and alphabetically.\n    \n    Args:\n        lst (list): A list of strings.\n    \n    Returns:\n        list: A sorted list of strings with even lengths.\n    \"\"\"\n    # Filter out strings with odd lengths\n    filtered_lst = [s for s in lst if len(s) % 2 == 0]\n    \n    # Sort the list first by length, then alphabetically\n    sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n    \n    return sorted_lst", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n    \"\"\"\n    Given a string text, replace all spaces in it with underscores, \n    and if a string has more than 2 consecutive spaces, \n    then replace all consecutive spaces with - \n    \n    fix_spaces(\"Example\") == \"Example\"\n    fix_spaces(\"Example 1\") == \"Example_1\"\n    fix_spaces(\" Example 2\") == \"_Example_2\"\n    fix_spaces(\" Example   3\") == \"_Example-3\"\n    \"\"\"\n    import re\n\n    # Replace more than 2 consecutive spaces with a single '-'\n    text = re.sub(r' {3,}', '-', text)\n    \n    # Replace single spaces with underscores\n    text = text.replace(' ', '_')\n    \n    return text", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n    \"\"\"\n    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n    as follows: start with any positive integer n. Then each term is obtained from the \n    previous term as follows: if the previous term is even, the next term is one half of \n    the previous term. If the previous term is odd, the next term is 3 times the previous\n    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n    Note: \n        1. Collatz(1) is [1].\n        2. returned list sorted in increasing order.\n\n    For example:\n    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n    \"\"\"\n    if n <= 0:\n        raise ValueError(\"Input must be a positive integer.\")\n    \n    collatz_sequence = []\n    current = n\n    \n    while current != 1:\n        collatz_sequence.append(current)\n        if current % 2 == 0:\n            current //= 2\n        else:\n            current = 3 * current + 1\n    \n    collatz_sequence.append(1)  # Add the last term which is 1\n    \n    # Filter odd numbers and sort them\n    odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n    \n    return odd_numbers", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n    \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n    \n    The date is valid if all of the following rules are satisfied:\n    1. The date string is not empty.\n    2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n       The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n       The number of days is not less than 1 or higher than 29 for the month 2.\n    3. The months should not be less than 1 or higher than 12.\n    4. The date should be in the format: mm-dd-yyyy\n    \n    Args:\n        date (str): The date string to validate.\n    \n    Returns:\n        bool: True if the date is valid, False otherwise.\n    \"\"\"\n    if not date:\n        return False\n    \n    # Check the format\n    if len(date) != 10 or date[2] != '-' or date[5] != '-':\n        return False\n    \n    try:\n        month = int(date[:2])\n        day = int(date[3:5])\n        year = int(date[6:])\n    except ValueError:\n        return False\n    \n    # Validate month\n    if month < 1 or month > 12:\n        return False\n    \n    # Validate day based on month\n    if month in [1, 3, 5, 7, 8, 10, 12]:  # 31 days\n        if day < 1 or day > 31:\n            return False\n    elif month in [4, 6, 9, 11]:  # 30 days\n        if day < 1 or day > 30:\n            return False\n    elif month == 2:  # February\n        if day < 1 or day > 29:\n            return False\n    \n    return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n    \"\"\"Task\n    We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n    then check if the result string is palindrome.\n    A string is called palindrome if it reads the same backward as forward.\n    You should return a tuple containing the result string and True/False for the check.\n    Example\n    For s = \"abcde\", c = \"ae\", the result should be ('bcd',False)\n    For s = \"abcdef\", c = \"b\"  the result should be ('acdef',False)\n    For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc',True)\n    \"\"\"\n    # Create a set of characters to delete for faster lookup\n    delete_set = set(c)\n    \n    # Create the result string by filtering out characters in delete_set\n    result = ''.join(char for char in s if char not in delete_set)\n    \n    # Check if the result string is a palindrome\n    is_palindrome = result == result[::-1]\n    \n    return (result, is_palindrome)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n    \"\"\"\n    Calculate the number of times buckets need to be lowered to empty the wells.\n\n    Parameters:\n    grid (list of list of int): A rectangular grid representing wells.\n    capacity (int): The capacity of each bucket.\n\n    Returns:\n    int: The total number of times buckets need to be lowered.\n    \"\"\"\n    total_water = 0\n    \n    # Count the total amount of water in the grid\n    for row in grid:\n        total_water += sum(row)\n    \n    # Calculate the number of times buckets need to be lowered\n    # Each bucket can carry 'capacity' units of water\n    if total_water == 0:\n        return 0\n    else:\n        return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": [[[[1, 0, 0, 1], [0, 1, 1, 1], [0, 0, 0, 0], [1, 0, 1, 1]], 2]]}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n    \"\"\"Create a function which takes a string representing a file's name, and returns\n    'Yes' if the the file's name is valid, and returns 'No' otherwise.\n    A file's name is considered to be valid if and only if all the following conditions \n    are met:\n    - There should not be more than three digits ('0'-'9') in the file's name.\n    - The file's name contains exactly one dot '.'\n    - The substring before the dot should not be empty, and it starts with a letter from \n    the latin alphapet ('a'-'z' and 'A'-'Z').\n    - The substring after the dot should be one of these: ['txt', 'exe', 'dll']\n    Examples:\n    file_name_check(\"example.txt\") # => 'Yes'\n    file_name_check(\"1example.dll\") # => 'No' (the name should start with a latin alphapet letter)\n    \"\"\"\n    \n    # Check for exactly one dot\n    if file_name.count('.') != 1:\n        return 'No'\n    \n    # Split the file name into name and extension\n    name, extension = file_name.split('.')\n    \n    # Check if the name is empty or starts with a non-letter\n    if not name or not name[0].isalpha():\n        return 'No'\n    \n    # Check for the valid extensions\n    valid_extensions = ['txt', 'exe', 'dll']\n    if extension not in valid_extensions:\n        return 'No'\n    \n    # Count the digits in the file name\n    digit_count = sum(c.isdigit() for c in file_name)\n    if digit_count > 3:\n        return 'No'\n    \n    return 'Yes'", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n    \"\"\"Write a function that takes an array of numbers as input and returns \n    the number of elements in the array that are greater than 10 and both \n    first and last digits of a number are odd (1, 3, 5, 7, 9).\n    \n    For example:\n    specialFilter([15, -73, 14, -15]) => 1 \n    specialFilter([33, -2, -3, 45, 21, 109]) => 2\n    \"\"\"\n    \n    def is_odd_digit(digit):\n        return digit in {'1', '3', '5', '7', '9'}\n    \n    def first_and_last_odd(num):\n        str_num = str(abs(num))  # Convert to string and take absolute value\n        return is_odd_digit(str_num[0]) and is_odd_digit(str_num[-1])\n    \n    count = 0\n    for num in nums:\n        if num > 10 and first_and_last_odd(num):\n            count += 1\n            \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n    \"\"\"You are given a list of numbers.\n    You need to return the sum of squared numbers in the given list,\n    round each element in the list to the upper int (Ceiling) first.\n    \n    Examples:\n    For lst = [1,2,3] the output should be 14\n    For lst = [1,4,9] the output should be 98\n    For lst = [1,3,5,7] the output should be 84\n    For lst = [1.4,4.2,0] the output should be 29\n    For lst = [-2.4,1,1] the output should be 6\n    \"\"\"\n    return sum(math.ceil(x) ** 2 for x in lst)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n    '''\n    There are eight planets in our solar system: the closest to the Sun \n    is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n    Uranus, Neptune.\n    Write a function that takes two planet names as strings planet1 and planet2. \n    The function should return a tuple containing all planets whose orbits are \n    located between the orbit of planet1 and the orbit of planet2, sorted by \n    the proximity to the sun. \n    The function should return an empty tuple if planet1 or planet2\n    are not correct planet names. \n    Examples\n    bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n    bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n    bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n    '''\n    \n    planets = [\n        \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n        \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n    ]\n    \n    if planet1 not in planets or planet2 not in planets:\n        return ()\n    \n    index1 = planets.index(planet1)\n    index2 = planets.index(planet2)\n    \n    # Ensure index1 is less than index2 for slicing\n    start, end = sorted((index1, index2))\n    \n    # Get the planets in between\n    in_between_planets = planets[start + 1:end]\n    \n    return tuple(in_between_planets)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n    '''\n    Create a function that returns True if the last character\n    of a given string is an alphabetical character and is not\n    a part of a word, and False otherwise.\n    Note: \"word\" is a group of characters separated by space.\n\n    Examples:\n    check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n    check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n    check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n    check_if_last_char_is_a_letter(\"\") \u279e False \n    '''\n    # Strip any trailing whitespace from the string\n    txt = txt.rstrip()\n    \n    # Check if the string is empty after stripping\n    if not txt:\n        return False\n    \n    # Split the string into words\n    words = txt.split()\n    \n    # Get the last character of the last word\n    last_word = words[-1]\n    \n    # Check if the last character is a letter and if the last word has only one character\n    return last_word[-1].isalpha() and len(last_word) == 1", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["eeeee e "]], "plus_fail_tests": [["apple pi\ne"]]}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n    \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n    in the sequence.\n    \n    >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n    [1, 2, 3, 3, 3, 4, 4]\n    \"\"\"\n    if not numbers:\n        return []\n\n    max_so_far = numbers[0]\n    result = [max_so_far]\n\n    for num in numbers[1:]:\n        max_so_far = max(max_so_far, num)\n        result.append(max_so_far)\n\n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n    \"\"\"This function takes two positive numbers x and y and returns the\n    biggest even integer number that is in the range [x, y] inclusive. If \n    there's no such number, then the function should return -1.\n\n    For example:\n    choose_num(12, 15) = 14\n    choose_num(13, 12) = -1\n    \"\"\"\n    # Ensure x is less than or equal to y\n    if x > y:\n        return -1\n    \n    # Start from the largest number in the range and check for evenness\n    for num in range(y, x - 1, -1):\n        if num % 2 == 0:\n            return num\n    \n    return -1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n    \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n    given threshold.\n    \n    >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n    False\n    >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n    True\n    \"\"\"\n    # Sort the numbers to make it easier to find close elements\n    numbers.sort()\n    \n    # Check the difference between consecutive elements\n    for i in range(len(numbers) - 1):\n        if abs(numbers[i] - numbers[i + 1]) < threshold:\n            return True\n            \n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n    \"\"\" Filter an input list of strings only for ones that contain given substring\n    >>> filter_by_substring([], 'a')\n    []\n    >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n    ['abc', 'bacd', 'array']\n    \"\"\"\n    return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n    \"\"\"\n    Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n    reverse the resulting array, and then replace each digit by its corresponding name from\n    \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n    For example:\n      arr = [2, 1, 1, 4, 5, 8, 2, 3]   \n            -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n            -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n      return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n    \n      If the array is empty, return an empty array:\n      arr = []\n      return []\n    \n      If the array has any strange number ignore it:\n      arr = [1, -1 , 55] \n            -> sort arr -> [-1, 1, 55]\n            -> reverse arr -> [55, 1, -1]\n      return = ['One']\n    \"\"\"\n    \n    # Mapping of digits to their corresponding names\n    digit_to_name = {\n        1: \"One\", 2: \"Two\", 3: \"Three\", 4: \"Four\",\n        5: \"Five\", 6: \"Six\", 7: \"Seven\", 8: \"Eight\", 9: \"Nine\"\n    }\n    \n    # Filter the array to include only numbers between 1 and 9\n    filtered = [num for num in arr if 1 <= num <= 9]\n    \n    # Sort the filtered array\n    filtered.sort()\n    \n    # Reverse the sorted array\n    filtered.reverse()\n    \n    # Convert the numbers to their corresponding names\n    result = [digit_to_name[num] for num in filtered]\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n    \"\"\"\n    Given a positive integer, obtain its roman numeral equivalent as a string,\n    and return it in lowercase.\n    Restrictions: 1 <= num <= 1000\n\n    Examples:\n    >>> int_to_mini_roman(19) == 'xix'\n    >>> int_to_mini_roman(152) == 'clii'\n    >>> int_to_mini_roman(426) == 'cdxxvi'\n    \"\"\"\n    if not (1 <= number <= 1000):\n        raise ValueError(\"Number must be between 1 and 1000\")\n\n    roman_numerals = [\n        (1000, 'm'),\n        (900, 'cm'),\n        (500, 'd'),\n        (400, 'cd'),\n        (100, 'c'),\n        (90, 'xc'),\n        (50, 'l'),\n        (40, 'xl'),\n        (10, 'x'),\n        (9, 'ix'),\n        (5, 'v'),\n        (4, 'iv'),\n        (1, 'i')\n    ]\n\n    result = []\n    for value, numeral in roman_numerals:\n        while number >= value:\n            result.append(numeral)\n            number -= value\n\n    return ''.join(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n    '''\n    Given a list of numbers, return the sum of squares of the numbers\n    in the list that are odd. Ignore numbers that are negative or not integers.\n    \n    double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n    double_the_difference([-1, -2, 0]) == 0\n    double_the_difference([9, -2]) == 81\n    double_the_difference([0]) == 0  \n   \n    If the input list is empty, return 0.\n    '''\n    if not lst:  # Check if the list is empty\n        return 0\n    \n    return sum(x**2 for x in lst if isinstance(x, int) and x >= 0 and x % 2 != 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n    \"\"\"Write a function that accepts a list of strings.\n    The list contains different words. Return the word with maximum number\n    of unique characters. If multiple strings have maximum number of unique\n    characters, return the one which comes first in lexicographical order.\n\n    find_max([\"name\", \"of\", \"string\"]) == \"string\"\n    find_max([\"name\", \"enam\", \"game\"]) == \"enam\"\n    find_max([\"aaaaaaa\", \"bb\" ,\"cc\"]) == \"aaaaaaa\"\n    \"\"\"\n    max_word = \"\"\n    max_unique_count = 0\n\n    for word in words:\n        unique_chars = set(word)\n        unique_count = len(unique_chars)\n\n        if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n            max_word = word\n            max_unique_count = unique_count\n\n    return max_word", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n    \"\"\"\n    Given two lists operator, and operand. The first list has basic algebra operations, and \n    the second list is a list of integers. Use the two given lists to build the algebraic \n    expression and return the evaluation of this expression.\n\n    The basic algebra operations:\n    Addition ( + ) \n    Subtraction ( - ) \n    Multiplication ( * ) \n    Floor division ( // ) \n    Exponentiation ( ** ) \n\n    Example:\n    operator = ['+', '*', '-']\n    operand = [2, 3, 4, 5]\n    result = 2 + 3 * 4 - 5\n    => result = 9\n\n    Note:\n        The length of operator list is equal to the length of operand list minus one.\n        Operand is a list of non-negative integers.\n        Operator list has at least one operator, and operand list has at least two operands.\n    \"\"\"\n    \n    # Start with the first operand\n    result = operand[0]\n    \n    # Iterate through the operators and operands\n    for i in range(len(operator)):\n        op = operator[i]\n        next_operand = operand[i + 1]\n        \n        if op == '+':\n            result += next_operand\n        elif op == '-':\n            result -= next_operand\n        elif op == '*':\n            result *= next_operand\n        elif op == '//':\n            result //= next_operand\n        elif op == '**':\n            result **= next_operand\n        else:\n            raise ValueError(f\"Invalid operator: {op}\")\n    \n    return result", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": [[["+", "-", "*", "//"], [5, 2, 3, 4, 7]]]}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n    \"\"\" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n    For each of the group, output the deepest level of nesting of parentheses.\n    E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n    >>> parse_nested_parens('(()()) ((())) () ((())()())')\n    [2, 3, 1, 3]\n    \"\"\"\n    def max_nesting_depth(s: str) -> int:\n        max_depth = 0\n        current_depth = 0\n        for char in s:\n            if char == '(':\n                current_depth += 1\n                max_depth = max(max_depth, current_depth)\n            elif char == ')':\n                current_depth -= 1\n        return max_depth\n\n    groups = paren_string.split()\n    return [max_nesting_depth(group) for group in groups]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n    \"\"\"\n    You are given a positive integer n. You have to create an integer array a of length n.\n    For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n    Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,\n    and a[i] + a[j] + a[k] is a multiple of 3.\n\n    Example:\n        Input: n = 5\n        Output: 1\n        Explanation:\n        a = [1, 3, 7, 13, 21]\n        The only valid triple is (1, 7, 13).\n    \"\"\"\n    # Create the array a\n    a = [i * i - i + 1 for i in range(1, n + 1)]\n    \n    # Count the number of valid triples\n    count = 0\n    \n    # Check all combinations of triples (i, j, k) with i < j < k\n    for i in range(n):\n        for j in range(i + 1, n):\n            for k in range(j + 1, n):\n                if (a[i] + a[j] + a[k]) % 3 == 0:\n                    count += 1\n                    \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n    \"\"\"Given a list of positive integers x, return a sorted list of all \n    elements that haven't any even digit.\n\n    Note: Returned list should be sorted in increasing order.\n    \n    For example:\n    >>> unique_digits([15, 33, 1422, 1])\n    [1, 15, 33]\n    >>> unique_digits([152, 323, 1422, 10])\n    []\n    \"\"\"\n    def has_even_digit(n):\n        \"\"\"Check if the number has any even digit.\"\"\"\n        return any(int(digit) % 2 == 0 for digit in str(n))\n\n    # Filter the list to include only numbers without even digits\n    result = [num for num in x if not has_even_digit(num)]\n    \n    # Return the sorted result\n    return sorted(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n    \"\"\" \n    Input to this function is a string containing multiple groups of nested parentheses. \n    Your goal is to separate those groups into separate strings and return the list of those.\n    Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n    Ignore any spaces in the input string.\n    \n    >>> separate_paren_groups('( ) (( )) (( )( ))')\n    ['()', '(())', '(()())']\n    \"\"\"\n    # Remove spaces from the input string\n    paren_string = paren_string.replace(\" \", \"\")\n    \n    result = []\n    balance = 0\n    current_group = []\n    \n    for char in paren_string:\n        if char == '(':\n            if balance == 0 and current_group:\n                result.append(''.join(current_group))\n                current_group = []\n            current_group.append(char)\n            balance += 1\n        elif char == ')':\n            current_group.append(char)\n            balance -= 1\n            if balance == 0:\n                result.append(''.join(current_group))\n                current_group = []\n    \n    # In case there are any remaining groups\n    if current_group:\n        result.append(''.join(current_group))\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n    \"\"\"Create a function which returns the largest index of an element which\n    is not greater than or equal to the element immediately preceding it. If\n    no such element exists then return -1. The given array will not contain\n    duplicate values.\n\n    Examples:\n    can_arrange([1,2,4,3,5]) = 3\n    can_arrange([1,2,3]) = -1\n    \"\"\"\n    # Initialize the index to -1, which will be returned if no such element is found\n    largest_index = -1\n    \n    # Iterate through the array starting from the second element\n    for i in range(1, len(arr)):\n        # Check if the current element is less than the previous element\n        if arr[i] < arr[i - 1]:\n            largest_index = i  # Update the largest index found\n    \n    return largest_index", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n    \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n    Empty sum should be equal to 0 and empty product should be equal to 1.\n    \n    >>> sum_product([])\n    (0, 1)\n    >>> sum_product([1, 2, 3, 4])\n    (10, 24)\n    \"\"\"\n    if not numbers:\n        return (0, 1)\n    \n    total_sum = sum(numbers)\n    total_product = 1\n    for number in numbers:\n        total_product *= number\n    \n    return (total_sum, total_product)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n    '''\n    Create a function that takes a string as input which contains only square brackets.\n    The function should return True if and only if there is a valid subsequence of brackets \n    where at least one bracket in the subsequence is nested.\n\n    is_nested('[[]]') \u279e True\n    is_nested('[]]]]]]][[[[[]') \u279e False\n    is_nested('[][]') \u279e False\n    is_nested('[]') \u279e False\n    is_nested('[[][]]') \u279e True\n    is_nested('[[]][[') \u279e True\n    '''\n    # Initialize a counter for open brackets\n    open_count = 0\n    # Initialize a flag to check for nesting\n    nested = False\n    \n    for char in string:\n        if char == '[':\n            open_count += 1\n            # If we have seen at least one open bracket before, we can have nesting\n            if open_count > 1:\n                nested = True\n        elif char == ']':\n            if open_count > 0:\n                open_count -= 1\n            else:\n                # More closing brackets than opening brackets\n                return False\n    \n    # We need at least one nested bracket and all brackets must be closed\n    return nested and open_count == 0", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["[[]][["]], "plus_fail_tests": [["[[]]]"]]}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n    \"\"\"\n    You're a hungry rabbit, and you already have eaten a certain number of carrots,\n    but now you need to eat more carrots to complete the day's meals.\n    you should return an array of [ total number of eaten carrots after your meals,\n                                    the number of carrots left after your meals ]\n    if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n    \n    Example:\n    * eat(5, 6, 10) -> [11, 4]\n    * eat(4, 8, 9) -> [12, 1]\n    * eat(1, 10, 10) -> [11, 0]\n    * eat(2, 11, 5) -> [7, 0]\n    \n    Variables:\n    @number : integer\n        the number of carrots that you have eaten.\n    @need : integer\n        the number of carrots that you need to eat.\n    @remaining : integer\n        the number of remaining carrots that exist in stock\n    \n    Constrain:\n    * 0 <= number <= 1000\n    * 0 <= need <= 1000\n    * 0 <= remaining <= 1000\n\n    Have fun :)\n    \"\"\"\n    # Calculate how many more carrots are needed\n    additional_needed = need - number\n    \n    # If no additional carrots are needed, return the current state\n    if additional_needed <= 0:\n        return [number, remaining]\n    \n    # Determine how many carrots can be eaten from the remaining stock\n    eaten = min(additional_needed, remaining)\n    \n    # Calculate the total eaten and remaining carrots\n    total_eaten = number + eaten\n    remaining_after_meals = remaining - eaten\n    \n    return [total_eaten, remaining_after_meals]", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": [[2, 2, 2]]}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef sum_of_digits(n):\n    \"\"\"Return the sum of the digits of a number.\"\"\"\n    return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n    \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n    largest_prime = -1\n    \n    for number in lst:\n        if is_prime(number) and number > largest_prime:\n            largest_prime = number\n            \n    if largest_prime == -1:\n        return 0  # Return 0 if no prime is found\n    \n    return sum_of_digits(largest_prime)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n    \"\"\"You are given a string s.\n    if s[i] is a letter, reverse its case from lower to upper or vise versa, \n    otherwise keep it as it is.\n    If the string contains no letters, reverse the string.\n    The function should return the resulted string.\n    \n    Examples:\n    solve(\"1234\") = \"4321\"\n    solve(\"ab\") = \"AB\"\n    solve(\"#a@C\") = \"#A@c\"\n    \"\"\"\n    # Check if there are any letters in the string\n    has_letters = any(c.isalpha() for c in s)\n    \n    if has_letters:\n        # Reverse case for letters and keep others as is\n        return ''.join(c.swapcase() if c.isalpha() else c for c in s)\n    else:\n        # Reverse the string if there are no letters\n        return s[::-1]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(num):\n    \"\"\"Check if a number is prime.\"\"\"\n    if num <= 1:\n        return False\n    for i in range(2, int(num**0.5) + 1):\n        if num % i == 0:\n            return False\n    return True\ndef x_or_y(n, x, y):\n    \"\"\"Return the value of x if n is a prime number, otherwise return y.\"\"\"\n    if is_prime(n):\n        return x\n    else:\n        return y", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n    '''\n    Given the lengths of the three sides of a triangle. Return True if the three\n    sides form a right-angled triangle, False otherwise.\n    A right-angled triangle is a triangle in which one angle is right angle or \n    90 degree.\n    \n    Example:\n    right_angle_triangle(3, 4, 5) == True\n    right_angle_triangle(1, 2, 3) == False\n    '''\n    # Sort the sides to identify the longest side\n    sides = sorted([a, b, c])\n    \n    # Check the Pythagorean theorem\n    return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n    \"\"\"Convert a decimal number to binary format with specific formatting.\n\n    Args:\n    decimal (int): A non-negative integer to convert to binary.\n\n    Returns:\n    str: A string representing the binary format of the decimal number,\n         prefixed and suffixed with 'db'.\n    \n    Examples:\n    >>> decimal_to_binary(15)\n    'db1111db'\n    >>> decimal_to_binary(32)\n    'db100000db'\n    \"\"\"\n    if decimal < 0:\n        raise ValueError(\"Input must be a non-negative integer.\")\n    \n    # Convert decimal to binary and remove the '0b' prefix\n    binary_representation = bin(decimal)[2:]\n    \n    # Format the output with 'db' at the beginning and end\n    formatted_output = f\"db{binary_representation}db\"\n    \n    return formatted_output", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n    \"\"\"\n    Imagine a road that's a perfectly straight infinitely long line.\n    n cars are driving left to right; simultaneously, a different set of n cars\n    are driving right to left. The two sets of cars start out being very far from\n    each other. All cars move at the same speed. Two cars are said to collide\n    when a car that's moving left to right hits a car that's moving right to left.\n    However, the cars are infinitely sturdy and strong; as a result, they continue moving\n    in their trajectory as if they did not collide.\n\n    This function outputs the number of such collisions.\n\n    Parameters:\n    n (int): The number of cars in each direction.\n\n    Returns:\n    int: The number of collisions.\n    \"\"\"\n    # Each car moving left to right will collide with each car moving right to left\n    # Therefore, the total number of collisions is n * n\n    return n * n", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n    \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n    fib4(0) -> 0\n    fib4(1) -> 0\n    fib4(2) -> 2\n    fib4(3) -> 0\n    fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n    \n    This function computes the n-th element of the fib4 number sequence without using recursion.\n    \n    >>> fib4(5)\n    4\n    >>> fib4(6)\n    8\n    >>> fib4(7)\n    14\n    \"\"\"\n    if n == 0:\n        return 0\n    elif n == 1:\n        return 0\n    elif n == 2:\n        return 2\n    elif n == 3:\n        return 0\n\n    # Initialize the first four values of the sequence\n    fib_values = [0, 0, 2, 0]\n    \n    # Compute the values iteratively\n    for i in range(4, n + 1):\n        next_value = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n        fib_values.append(next_value)\n    \n    return fib_values[n]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n    \"\"\"\n    Checks if given string is a palindrome.\n    \n    A palindrome is a string that reads the same forward and backward.\n    \n    >>> is_palindrome('')\n    True\n    >>> is_palindrome('aba')\n    True\n    >>> is_palindrome('aaaaa')\n    True\n    >>> is_palindrome('zbcd')\n    False\n    \"\"\"\n    # Normalize the string by removing spaces and converting to lowercase\n    normalized_text = text.replace(\" \", \"\").lower()\n    # Check if the normalized string is equal to its reverse\n    return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["never odd or even"]]}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n    \"\"\"You are given two positive integers n and m, and your task is to compute the\n    average of the integers from n through m (including n and m). \n    Round the answer to the nearest integer and convert that to binary.\n    If n is greater than m, return -1.\n    \n    Example:\n    rounded_avg(1, 5) => \"0b11\"\n    rounded_avg(7, 5) => -1\n    rounded_avg(10, 20) => \"0b1111\"\n    rounded_avg(20, 33) => \"0b11010\"\n    \"\"\"\n    if n > m:\n        return -1\n    \n    # Calculate the sum of integers from n to m\n    total_sum = sum(range(n, m + 1))\n    count = m - n + 1  # Total numbers from n to m\n    \n    # Calculate the average and round it\n    average = total_sum / count\n    rounded_average = round(average)\n    \n    # Convert the rounded average to binary\n    return bin(rounded_average)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n    '''\n    Write a function that takes an integer a and returns True \n    if this integer is a cube of some integer number.\n    Note: you may assume the input is always valid.\n    \n    Examples:\n    iscube(1) ==> True\n    iscube(2) ==> False\n    iscube(-1) ==> True\n    iscube(64) ==> True\n    iscube(0) ==> True\n    iscube(180) ==> False\n    '''\n    # Calculate the cube root of the absolute value of a\n    cube_root = round(abs(a) ** (1/3))\n    \n    # Check if the cube of the rounded cube root equals the absolute value of a\n    return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n    \"\"\"\n    Given a positive integer n, return the count of the numbers of n-digit\n    positive integers that start or end with 1.\n    \"\"\"\n    if n < 1:\n        return 0\n\n    # Total n-digit numbers\n    total_n_digit_numbers = 9 * (10 ** (n - 1))\n\n    # Count of n-digit numbers that start with 1\n    start_with_1 = 10 ** (n - 1)\n\n    # Count of n-digit numbers that end with 1\n    end_with_1 = 9 * (10 ** (n - 2)) if n > 1 else 0\n\n    # Total count of numbers that start or end with 1\n    count = start_with_1 + end_with_1\n\n    return count", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[2]], "plus_fail_tests": [[6]]}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n    \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n    \n    Example\n        For N = 1000, the sum of digits will be 1 the output should be \"1\".\n        For N = 150, the sum of digits will be 6 the output should be \"110\".\n        For N = 147, the sum of digits will be 12 the output should be \"1100\".\n    \n    Variables:\n        @N integer\n             Constraints: 0 \u2264 N \u2264 10000.\n    Output:\n         a string of binary number\n    \"\"\"\n    # Calculate the sum of the digits of N\n    digit_sum = sum(int(digit) for digit in str(N))\n    \n    # Convert the sum to binary and remove the '0b' prefix\n    binary_sum = bin(digit_sum)[2:]\n    \n    return binary_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n    '''\n    Given list of integers, return list in strange order.\n    Strange sorting, is when you start with the minimum value,\n    then maximum of the remaining integers, then minimum and so on.\n\n    Examples:\n    strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n    strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n    strange_sort_list([]) == []\n    '''\n    if not lst:\n        return []\n\n    sorted_lst = sorted(lst)\n    result = []\n    left, right = 0, len(sorted_lst) - 1\n\n    while left <= right:\n        if left == right:\n            result.append(sorted_lst[left])\n        else:\n            result.append(sorted_lst[left])\n            result.append(sorted_lst[right])\n        left += 1\n        right -= 1\n\n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n    \"\"\" Return length of given string\n    >>> strlen('')\n    0\n    >>> strlen('abc')\n    3\n    \"\"\"\n    return len(string)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n    \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n    \n    >>> largest_divisor(15)\n    5\n    >>> largest_divisor(28)\n    14\n    >>> largest_divisor(1)\n    0\n    >>> largest_divisor(10)\n    5\n    \"\"\"\n    if n <= 1:\n        return 0  # No divisors for 1 or less\n    \n    for i in range(n // 2, 0, -1):\n        if n % i == 0:\n            return i", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n    '''\n    Given the lengths of the three sides of a triangle. Return the area of\n    the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n    Otherwise return -1.\n    Three sides make a valid triangle when the sum of any two sides is greater \n    than the third side.\n    \n    Example:\n    triangle_area(3, 4, 5) == 6.00\n    triangle_area(1, 2, 10) == -1\n    '''\n    # Check for valid triangle\n    if a + b > c and a + c > b and b + c > a:\n        # Calculate the semi-perimeter\n        s = (a + b + c) / 2\n        # Calculate the area using Heron's formula\n        area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n        return round(area, 2)\n    else:\n        return -1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n    \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n    strings of the same length. Return None in case the input list is empty.\n    \n    >>> longest([])\n    >>> None\n    >>> longest(['a', 'b', 'c'])\n    'a'\n    >>> longest(['a', 'bb', 'ccc'])\n    'ccc'\n    \"\"\"\n    if not strings:\n        return None\n    \n    longest_string = strings[0]\n    \n    for string in strings:\n        if len(string) > len(longest_string):\n            longest_string = string\n            \n    return longest_string", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n    \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n    Args:\n        lst (list): A non-empty list of integers.\n\n    Returns:\n        int: The sum of even elements at odd indices.\n\n    Examples:\n        add([4, 2, 6, 7]) ==> 2 \n    \"\"\"\n    return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n    \"\"\"Return 2^n modulo p (be aware of numerics).\n    \n    >>> modp(3, 5)\n    3\n    >>> modp(1101, 101)\n    2\n    >>> modp(0, 101)\n    1\n    >>> modp(3, 11)\n    8\n    >>> modp(100, 101)\n    1\n    \"\"\"\n    result = 1\n    base = 2 % p  # Start with 2 modulo p\n\n    while n > 0:\n        if n % 2 == 1:  # If n is odd, multiply the result by the base\n            result = (result * base) % p\n        base = (base * base) % p  # Square the base\n        n //= 2  # Divide n by 2\n\n    return result", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[0, 1]]}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n    \"\"\"Helper function to check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef prime_length(string):\n    \"\"\"Check if the length of the string is a prime number.\"\"\"\n    length = len(string)\n    return is_prime(length)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n    \"\"\"Returns True if x is a simple power of n, otherwise False.\n    \n    A number x is a simple power of n if there exists an integer k such that n**k = x.\n    \n    Args:\n        x (int): The number to check.\n        n (int): The base number.\n    \n    Returns:\n        bool: True if x is a simple power of n, False otherwise.\n    \"\"\"\n    if n <= 1:\n        return x == 1  # 1 is a power of any number, and no other number can be a power of 1 or 0\n    \n    power = 1\n    while True:\n        result = n ** power\n        if result == x:\n            return True\n        elif result > x:\n            return False\n        power += 1", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[1, 12]], "plus_fail_tests": [[1, 4]]}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n    \"\"\"\n    triples_sum_to_zero takes a list of integers as an input.\n    it returns True if there are three distinct elements in the list that\n    sum to zero, and False otherwise.\n\n    >>> triples_sum_to_zero([1, 3, 5, 0])\n    False\n    >>> triples_sum_to_zero([1, 3, -2, 1])\n    True\n    >>> triples_sum_to_zero([1, 2, 3, 7])\n    False\n    >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n    True\n    >>> triples_sum_to_zero([1])\n    False\n    \"\"\"\n    n = len(l)\n    # Sort the list to use the two-pointer technique\n    l.sort()\n    \n    for i in range(n - 2):\n        # Avoid duplicates for the first element\n        if i > 0 and l[i] == l[i - 1]:\n            continue\n        \n        left, right = i + 1, n - 1\n        while left < right:\n            current_sum = l[i] + l[left] + l[right]\n            if current_sum == 0:\n                return True\n            elif current_sum < 0:\n                left += 1\n            else:\n                right -= 1\n    \n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n    \"\"\"Return median of elements in the list l.\n    \n    The median is the middle value in a list of numbers. If the list has an even number of elements,\n    the median is the average of the two middle numbers.\n    \n    >>> median([3, 1, 2, 4, 5])\n    3\n    >>> median([-10, 4, 6, 1000, 10, 20])\n    15.0\n    \"\"\"\n    if not l:\n        raise ValueError(\"The list is empty.\")\n    \n    sorted_list = sorted(l)\n    n = len(sorted_list)\n    mid = n // 2\n    \n    if n % 2 == 0:  # Even number of elements\n        return (sorted_list[mid - 1] + sorted_list[mid]) / 2\n    else:  # Odd number of elements\n        return sorted_list[mid]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n    \"\"\"Counts the number of prime hexadecimal digits in the given hexadecimal string.\"\"\"\n    # Define the set of prime hexadecimal digits\n    prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n    \n    # Count the number of prime hexadecimal digits in the input string\n    count = sum(1 for digit in num if digit in prime_hex_digits)\n    \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n    \"\"\" Filter given list of any python values only for integers\n    >>> filter_integers(['a', 3.14, 5])\n    [5]\n    >>> filter_integers([1, 2, 3, 'abc', {}, []])\n    [1, 2, 3]\n    \"\"\"\n    return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[[true, false, null, 0, -10, "test", [], {}, 3.14]]]}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n    \"\"\" Return a greatest common divisor of two integers a and b\n    >>> greatest_common_divisor(3, 5)\n    1\n    >>> greatest_common_divisor(25, 15)\n    5\n    \"\"\"\n    while b:\n        a, b = b, a % b\n    return abs(a)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n    \"\"\" Return list of all prefixes from shortest to longest of the input string\n    >>> all_prefixes('abc')\n    ['a', 'ab', 'abc']\n    \"\"\"\n    return [string[:i] for i in range(1, len(string) + 1)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str):\n    \"\"\"\n    Takes as input a string encoded with the encode_cyclic function.\n    Returns the decoded string.\n    \"\"\"\n    # Split string into groups of length 3\n    groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n    # Reverse the cycling for each group\n    groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n    return \"\".join(groups)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n    \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n    Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n    Input number should be equal to the product of all factors\n    >>> factorize(8)\n    [2, 2, 2]\n    >>> factorize(25)\n    [5, 5]\n    >>> factorize(70)\n    [2, 5, 7]\n    \"\"\"\n    factors = []\n    # Check for number of 2s that divide n\n    while n % 2 == 0:\n        factors.append(2)\n        n //= 2\n    \n    # n must be odd at this point so a skip of 2 (i.e., i = i + 2) can be used\n    for i in range(3, int(n**0.5) + 1, 2):\n        # While i divides n, append i and divide n\n        while n % i == 0:\n            factors.append(i)\n            n //= i\n    \n    # This condition is to check if n is a prime number greater than 2\n    if n > 2:\n        factors.append(n)\n    \n    return factors", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n    \"\"\"Return true if a given number is prime, and false otherwise.\n    \n    >>> is_prime(6)\n    False\n    >>> is_prime(101)\n    True\n    >>> is_prime(11)\n    True\n    >>> is_prime(13441)\n    True\n    >>> is_prime(61)\n    True\n    >>> is_prime(4)\n    False\n    >>> is_prime(1)\n    False\n    \"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n    \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n    and return the result as a string.\n    If shift > number of digits, return digits reversed.\n    \n    >>> circular_shift(12, 1)\n    '21'\n    >>> circular_shift(12, 2)\n    '12'\n    >>> circular_shift(12345, 1)\n    '51234'\n    >>> circular_shift(12345, 5)\n    '54321'\n    >>> circular_shift(12345, 6)\n    '54321'\n    \"\"\"\n    # Convert the integer to a string to manipulate its digits\n    str_x = str(x)\n    length = len(str_x)\n    \n    # If shift is greater than the number of digits, reverse the string\n    if shift >= length:\n        return str_x[::-1]\n    \n    # Calculate the effective shift\n    effective_shift = shift % length\n    \n    # Perform the circular shift\n    shifted = str_x[-effective_shift:] + str_x[:-effective_shift]\n    \n    return shifted", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[12, 2]], "plus_fail_tests": [[987654321, 9]]}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n    \"\"\"\n    You'll be given a string of words, and your task is to count the number\n    of boredoms. A boredom is a sentence that starts with the word \"I\".\n    Sentences are delimited by '.', '?' or '!'.\n   \n    For example:\n    >>> is_bored(\"Hello world\")\n    0\n    >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n    1\n    >>> is_bored(\"I am happy! Are you? I will go now.\")\n    2\n    >>> is_bored(\"What a day. I can't believe it! I am so excited.\")\n    2\n    \"\"\"\n    # Split the string into sentences using the delimiters\n    sentences = []\n    current_sentence = []\n    for char in S:\n        if char in '.!?':\n            if current_sentence:\n                sentences.append(''.join(current_sentence).strip())\n                current_sentence = []\n        else:\n            current_sentence.append(char)\n    if current_sentence:  # Add the last sentence if it exists\n        sentences.append(''.join(current_sentence).strip())\n\n    # Count the sentences that start with \"I\"\n    boredom_count = sum(1 for sentence in sentences if sentence.startswith('I'))\n    \n    return boredom_count", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": [["In the morning, I like to have a cup of coffee to start my day off right. How about you?"]]}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n    \"\"\" \n    xs represent coefficients of a polynomial.\n    xs[0] + xs[1] * x + xs[2] * x^2 + ....\n    Return derivative of this polynomial in the same form.\n    \n    >>> derivative([3, 1, 2, 4, 5])\n    [1, 4, 12, 20]\n    >>> derivative([1, 2, 3])\n    [2, 6]\n    \"\"\"\n    # The derivative of a polynomial is calculated by multiplying each coefficient\n    # by its corresponding power and reducing the power by one.\n    return [i * coeff for i, coeff in enumerate(xs[1:], start=1)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n    \"\"\"Check if a number is prime.\"\"\"\n    if num <= 1:\n        return False\n    for i in range(2, int(num**0.5) + 1):\n        if num % i == 0:\n            return False\n    return True\ndef count_up_to(n):\n    \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n    primes = []\n    for i in range(2, n):\n        if is_prime(i):\n            primes.append(i)\n    return primes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n    \"\"\"\n    Check if two words have the same characters.\n    \n    Two words have the same characters if they contain the same unique characters,\n    regardless of the number of times each character appears.\n\n    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n    True\n    >>> same_chars('abcd', 'dddddddabc')\n    True\n    >>> same_chars('dddddddabc', 'abcd')\n    True\n    >>> same_chars('eabcd', 'dddddddabc')\n    False\n    >>> same_chars('abcd', 'dddddddabce')\n    False\n    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n    False\n    \"\"\"\n    return set(s0) == set(s1)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n    \"\"\"Add two numbers x and y.\n    \n    >>> add(2, 3)\n    5\n    >>> add(5, 7)\n    12\n    \"\"\"\n    return x + y", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n    \"\"\"\n    Given a string s, count the number of uppercase vowels in even indices.\n    \n    For example:\n    count_upper('aBCdEf') returns 1\n    count_upper('abcdefg') returns 0\n    count_upper('dBBE') returns 0\n    \"\"\"\n    uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n    count = 0\n    \n    for i in range(0, len(s), 2):  # Iterate over even indices\n        if s[i] in uppercase_vowels:\n            count += 1\n            \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n    \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n    \n    >>> fizz_buzz(50)\n    0\n    >>> fizz_buzz(78)\n    2\n    >>> fizz_buzz(79)\n    3\n    \"\"\"\n    count_of_sevens = 0\n    \n    for i in range(n):\n        if i % 11 == 0 or i % 13 == 0:\n            count_of_sevens += str(i).count('7')\n    \n    return count_of_sevens", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n    \"\"\"Return only positive numbers in the list.\n    >>> get_positive([-1, 2, -4, 5, 6])\n    [2, 5, 6]\n    >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n    [5, 3, 2, 3, 9, 123, 1]\n    \"\"\"\n    return [x for x in l if x > 0]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n    \"\"\"This function takes a list l and returns a list l' such that\n    l' is identical to l in the odd indices, while its values at the even indices are equal\n    to the values of the even indices of l, but sorted.\n    \n    >>> sort_even([1, 2, 3])\n    [1, 2, 3]\n    >>> sort_even([5, 6, 3, 4])\n    [3, 6, 5, 4]\n    \"\"\"\n    # Extract even indexed elements\n    even_indices_values = [l[i] for i in range(0, len(l), 2)]\n    \n    # Sort the even indexed elements\n    even_indices_values.sort()\n    \n    # Create a new list to hold the result\n    result = l[:]  # Start with a copy of the original list\n    \n    # Place the sorted even indexed values back into the result\n    for i, value in enumerate(even_indices_values):\n        result[i * 2] = value  # Place sorted value at even index\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n    \"\"\"Return True if all numbers in the list l are below threshold t.\n    \n    >>> below_threshold([1, 2, 4, 10], 100)\n    True\n    >>> below_threshold([1, 20, 4, 10], 5)\n    False\n    \"\"\"\n    return all(x < t for x in l)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n    '''\n    Create a function that takes a value (string) representing a number\n    and returns the closest integer to it. If the number is equidistant\n    from two integers, round it away from zero.\n\n    Examples\n    >>> closest_integer(\"10\")\n    10\n    >>> closest_integer(\"15.3\")\n    15\n    >>> closest_integer(\"14.5\")\n    15\n    >>> closest_integer(\"-14.5\")\n    -15\n    >>> closest_integer(\"0.5\")\n    1\n    >>> closest_integer(\"-0.5\")\n    -1\n    '''\n    # Convert the string to a float\n    num = float(value)\n    \n    # Get the floor and ceiling of the number\n    lower = int(num // 1)\n    upper = lower + 1\n    \n    # Check if the number is equidistant from lower and upper\n    if abs(num - lower) < abs(num - upper):\n        return lower\n    elif abs(num - lower) > abs(num - upper):\n        return upper\n    else:\n        # If equidistant, round away from zero\n        if num > 0:\n            return upper\n        else:\n            return lower", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000"]]}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n    \"\"\"Return n-th Fibonacci number.\n    \n    >>> fib(10)\n    55\n    >>> fib(1)\n    1\n    >>> fib(8)\n    21\n    \"\"\"\n    if n <= 0:\n        raise ValueError(\"Input must be a positive integer.\")\n    elif n == 1:\n        return 1\n    elif n == 2:\n        return 1\n    else:\n        a, b = 1, 1\n        for _ in range(2, n):\n            a, b = b, a + b\n        return b", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[0]]}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n    \"\"\"Check if a number is prime.\"\"\"\n    if num <= 1:\n        return False\n    if num <= 3:\n        return True\n    if num % 2 == 0 or num % 3 == 0:\n        return False\n    i = 5\n    while i * i <= num:\n        if num % i == 0 or num % (i + 2) == 0:\n            return False\n        i += 6\n    return True\ndef fibonacci(n: int) -> int:\n    \"\"\"Return the n-th Fibonacci number.\"\"\"\n    a, b = 0, 1\n    for _ in range(n):\n        a, b = b, a + b\n    return a\ndef prime_fib(n: int) -> int:\n    \"\"\"\n    prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n    >>> prime_fib(1)\n    2\n    >>> prime_fib(2)\n    3\n    >>> prime_fib(3)\n    5\n    >>> prime_fib(4)\n    13\n    >>> prime_fib(5)\n    89\n    \"\"\"\n    count = 0\n    fib_index = 0\n    while True:\n        fib_number = fibonacci(fib_index)\n        if is_prime(fib_number):\n            count += 1\n            if count == n:\n                return fib_number\n        fib_index += 1", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[12]]}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n    \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n    fibfib(0) == 0\n    fibfib(1) == 0\n    fibfib(2) == 1\n    fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n    \n    Args:\n        n (int): The index of the FibFib number to compute.\n    \n    Returns:\n        int: The n-th FibFib number.\n    \n    Examples:\n    >>> fibfib(1)\n    0\n    >>> fibfib(5)\n    4\n    >>> fibfib(8)\n    24\n    \"\"\"\n    if n == 0:\n        return 0\n    elif n == 1:\n        return 0\n    elif n == 2:\n        return 1\n    \n    # Initialize the first three FibFib numbers\n    fibfib_numbers = [0, 0, 1]\n    \n    # Compute FibFib numbers iteratively\n    for i in range(3, n + 1):\n        next_fibfib = fibfib_numbers[i - 1] + fibfib_numbers[i - 2] + fibfib_numbers[i - 3]\n        fibfib_numbers.append(next_fibfib)\n    \n    return fibfib_numbers[n]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n    \"\"\"Complete the function that takes two integers and returns \n    the product of their unit digits.\n    Assume the input is always valid.\n    Examples:\n    multiply(148, 412) should return 16.\n    multiply(19, 28) should return 72.\n    multiply(2020, 1851) should return 0.\n    multiply(14,-15) should return 20.\n    \"\"\"\n    # Get the unit digit of the first number\n    unit_digit_a = abs(a) % 10\n    # Get the unit digit of the second number\n    unit_digit_b = abs(b) % 10\n    # Return the product of the unit digits\n    return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n    \"\"\"Write a function vowels_count which takes a string representing\n    a word as input and returns the number of vowels in the string.\n    Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n    vowel, but only when it is at the end of the given word.\n\n    Example:\n    >>> vowels_count(\"abcde\")\n    2\n    >>> vowels_count(\"ACEDY\")\n    3\n    \"\"\"\n    vowels = 'aeiou'\n    count = 0\n    s = s.lower()  # Convert to lowercase to handle case insensitivity\n\n    for i in range(len(s)):\n        if s[i] in vowels:\n            count += 1\n        elif s[i] == 'y' and i == len(s) - 1:  # Check if 'y' is at the end\n            count += 1\n\n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n    \"\"\"\n    You are given a list of integers.\n    Write a function next_smallest() that returns the 2nd smallest element of the list.\n    Return None if there is no such element.\n    \n    next_smallest([1, 2, 3, 4, 5]) == 2\n    next_smallest([5, 1, 4, 3, 2]) == 2\n    next_smallest([]) == None\n    next_smallest([1, 1]) == None\n    \"\"\"\n    # Remove duplicates by converting the list to a set\n    unique_elements = set(lst)\n    \n    # If there are less than 2 unique elements, return None\n    if len(unique_elements) < 2:\n        return None\n    \n    # Sort the unique elements\n    sorted_elements = sorted(unique_elements)\n    \n    # Return the second smallest element\n    return sorted_elements[1]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef words_in_sentence(sentence):\n    \"\"\"\n    You are given a string representing a sentence,\n    the sentence contains some words separated by a space,\n    and you have to return a string that contains the words from the original sentence,\n    whose lengths are prime numbers,\n    the order of the words in the new string should be the same as the original one.\n\n    Example 1:\n        Input: sentence = \"This is a test\"\n        Output: \"is\"\n\n    Example 2:\n        Input: sentence = \"lets go for swimming\"\n        Output: \"go for\"\n\n    Constraints:\n        * 1 <= len(sentence) <= 100\n        * sentence contains only letters\n    \"\"\"\n    words = sentence.split()\n    prime_length_words = [word for word in words if is_prime(len(word))]\n    return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n    \"\"\"In this problem, you will implement a function that takes two lists of numbers,\n    and determines whether it is possible to perform an exchange of elements\n    between them to make lst1 a list of only even numbers.\n    There is no limit on the number of exchanged elements between lst1 and lst2.\n    If it is possible to exchange elements between the lst1 and lst2 to make\n    all the elements of lst1 to be even, return \"YES\".\n    Otherwise, return \"NO\".\n    For example:\n    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"YES\"\n    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n    It is assumed that the input lists will be non-empty.\n    \"\"\"\n    \n    # Count the number of odd numbers in lst1\n    odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n    \n    # Count the number of even numbers in lst2\n    even_count_lst2 = sum(1 for x in lst2 if x % 2 == 0)\n    \n    # If there are no odd numbers in lst1, it's already valid\n    if odd_count_lst1 == 0:\n        return \"YES\"\n    \n    # If there are enough even numbers in lst2 to replace all odd numbers in lst1\n    if even_count_lst2 >= odd_count_lst1:\n        return \"YES\"\n    \n    return \"NO\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n    \"\"\"Simplifies the expression x * n and checks if the result is a whole number.\n    \n    Args:\n        x (str): A string representation of a fraction in the format <numerator>/<denominator>.\n        n (str): A string representation of a fraction in the format <numerator>/<denominator>.\n    \n    Returns:\n        bool: True if x * n evaluates to a whole number, False otherwise.\n    \"\"\"\n    # Split the fractions into numerator and denominator\n    x_numerator, x_denominator = map(int, x.split('/'))\n    n_numerator, n_denominator = map(int, n.split('/'))\n    \n    # Calculate the product of the fractions\n    # (x_numerator / x_denominator) * (n_numerator / n_denominator) = (x_numerator * n_numerator) / (x_denominator * n_denominator)\n    numerator_product = x_numerator * n_numerator\n    denominator_product = x_denominator * n_denominator\n    \n    # Check if the result is a whole number\n    return numerator_product % denominator_product == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n    \"\"\"\n    You are given an array arr of integers and you need to return\n    sum of magnitudes of integers multiplied by product of all signs\n    of each number in the array, represented by 1, -1 or 0.\n    Note: return None for empty arr.\n\n    Example:\n    >>> prod_signs([1, 2, 2, -4]) == -9\n    >>> prod_signs([0, 1]) == 0\n    >>> prod_signs([]) == None\n    \"\"\"\n    if not arr:\n        return None\n\n    product_of_signs = 1\n    sum_of_magnitudes = 0\n\n    for num in arr:\n        if num > 0:\n            sum_of_magnitudes += num\n        elif num < 0:\n            sum_of_magnitudes += -num\n            product_of_signs *= -1\n        else:  # num == 0\n            return 0  # If there's a zero, the product of signs is zero\n\n    return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n    \"\"\"Given a string s and a natural number n, returns a list of all words from \n    string s that contain exactly n consonants, in the order they appear in the string s.\n    \n    Args:\n    s (str): The input string containing words.\n    n (int): The number of consonants to filter words by.\n    \n    Returns:\n    list: A list of words containing exactly n consonants.\n    \"\"\"\n    if not s:\n        return []\n\n    # Define a set of consonants\n    consonants = set(\"bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ\")\n    \n    # Split the string into words\n    words = s.split()\n    \n    # Function to count consonants in a word\n    def count_consonants(word):\n        return sum(1 for char in word if char in consonants)\n    \n    # Filter words based on the number of consonants\n    result = [word for word in words if count_consonants(word) == n]\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n    \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n    \n    Examples\n    solution([5, 8, 7, 1]) ==> 12\n    solution([3, 3, 3, 3, 3]) ==> 9\n    solution([30, 13, 24, 321]) ==> 0\n    \"\"\"\n    return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n    '''\n    You are given a list of two strings, both strings consist of open\n    parentheses '(' or close parentheses ')' only.\n    Your job is to check if it is possible to concatenate the two strings in\n    some order, that the resulting string will be good.\n    A string S is considered to be good if and only if all parentheses in S\n    are balanced. For example: the string '(())()' is good, while the string\n    '())' is not.\n    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n    Examples:\n    match_parens(['()(', ')']) == 'Yes'\n    match_parens([')', ')']) == 'No'\n    '''\n\n    def is_good(s):\n        balance = 0\n        for char in s:\n            if char == '(':\n                balance += 1\n            else:  # char == ')'\n                balance -= 1\n            if balance < 0:  # More closing than opening\n                return False\n        return balance == 0  # Must be balanced at the end\n\n    # Check both concatenation orders\n    return 'Yes' if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]) else 'No'", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n    \"\"\"\n    Write a function which sorts the given list of integers\n    in ascending order according to the sum of their digits.\n    Note: if there are several items with similar sum of their digits,\n    order them based on their index in original list.\n\n    For example:\n    >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n    >>> order_by_points([]) == []\n    \"\"\"\n    \n    def digit_sum(n):\n        \"\"\"Calculate the sum of the digits of n.\"\"\"\n        return sum(int(digit) for digit in str(abs(n)))\n\n    # Sort the list based on the sum of digits and original index\n    return sorted(nums, key=lambda x: (digit_sum(x), nums.index(x)))", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": [[[-5, -12, 9, 15]]]}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n    '''\n    Given a list of numbers, return whether or not they are sorted\n    in ascending order. If list has more than 1 duplicate of the same\n    number, return False. Assume no negative numbers and only integers.\n\n    Examples\n    is_sorted([5]) \u279e True\n    is_sorted([1, 2, 3, 4, 5]) \u279e True\n    is_sorted([1, 3, 2, 4, 5]) \u279e False\n    is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n    is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n    is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n    is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n    is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n    '''\n    if not lst:  # An empty list is considered sorted\n        return True\n\n    seen = set()\n    last = None\n\n    for num in lst:\n        if num in seen:\n            # If we see a number again, check if it's the same as the last\n            if num == last:\n                return False\n            else:\n                return False  # More than one duplicate found\n        seen.add(num)\n        last = num\n\n    return all(lst[i] <= lst[i + 1] for i in range(len(lst) - 1))", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": [[[1, 1, 2, 2, 3, 3, 4]]]}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n    \"\"\"\n    This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n    multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n    change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n    \n    Examples:\n    For lst = [1,2,3] the output should be 6\n    For lst = []  the output should be 0\n    For lst = [-1,-5,2,-1,-5]  the output should be -126\n    \"\"\"\n    total_sum = 0\n    for index, value in enumerate(lst):\n        if index % 3 == 0:\n            total_sum += value ** 2\n        elif index % 4 == 0:\n            total_sum += value ** 3\n        else:\n            total_sum += value\n    return total_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef intersection(interval1, interval2):\n    \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n    start1, end1 = interval1\n    start2, end2 = interval2\n    \n    # Find the intersection\n    start_intersection = max(start1, start2)\n    end_intersection = min(end1, end2)\n    \n    # Check if there is an intersection\n    if start_intersection > end_intersection:\n        return \"NO\"\n    \n    # Calculate the length of the intersection\n    length_of_intersection = end_intersection - start_intersection\n    \n    # Check if the length is a prime number\n    if is_prime(length_of_intersection):\n        return \"YES\"\n    else:\n        return \"NO\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n    \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n    two consonants from the right side of the word (case sensitive).\n    \n    Vowels in the beginning and ending don't count. Return empty string if you didn't\n    find any vowel that meets the above condition. \n\n    You may assume that the given string contains English letters only.\n\n    Example:\n    get_closest_vowel(\"yogurt\") ==> \"u\"\n    get_closest_vowel(\"FULL\") ==> \"U\"\n    get_closest_vowel(\"quick\") ==> \"\"\n    get_closest_vowel(\"ab\") ==> \"\"\n    \"\"\"\n    vowels = \"aeiouAEIOU\"\n    n = len(word)\n\n    # Start from the end of the word\n    for i in range(n - 2, 0, -1):  # Start from the second last character\n        if word[i] in vowels:  # Check if the character is a vowel\n            # Check if the characters before and after are consonants\n            if word[i - 1].isalpha() and word[i + 1].isalpha() and \\\n               word[i - 1] not in vowels and word[i + 1] not in vowels:\n                return word[i]  # Return the vowel if conditions are met\n\n    return \"\"  # Return empty string if no vowel is found", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n    \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n    \n    >>> string_sequence(0)\n    '0'\n    >>> string_sequence(5)\n    '0 1 2 3 4 5'\n    \"\"\"\n    return ' '.join(str(i) for i in range(n + 1))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n    \"\"\"\n    Given an array arr of integers and a positive integer k, return a sorted list \n    of length k with the maximum k numbers in arr.\n\n    Example 1:\n        Input: arr = [-3, -4, 5], k = 3\n        Output: [-4, -3, 5]\n\n    Example 2:\n        Input: arr = [4, -4, 4], k = 2\n        Output: [4, 4]\n\n    Example 3:\n        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n        Output: [2]\n\n    Note:\n        1. The length of the array will be in the range of [1, 1000].\n        2. The elements in the array will be in the range of [-1000, 1000].\n        3. 0 <= k <= len(arr)\n    \"\"\"\n    # Sort the array in descending order\n    sorted_arr = sorted(arr, reverse=True)\n    # Get the top k elements\n    top_k = sorted_arr[:k]\n    # Sort the result in ascending order before returning\n    return sorted(top_k)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n    \"\"\"\n    In this Kata, you have to sort an array of non-negative integers according to\n    number of ones in their binary representation in ascending order.\n    For similar number of ones, sort based on decimal value.\n\n    It must be implemented like this:\n    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n    >>> sort_array([1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]\n    \"\"\"\n    # Sort the array using a custom key\n    return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n    \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n    of the letter with the most repetition and containing the corresponding count.\n    If several letters have the same occurrence, return all of them.\n    \n    Example:\n    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n    histogram('a b b a') == {'a': 2, 'b': 2}\n    histogram('a b c a b') == {'a': 2, 'b': 2}\n    histogram('b b b b a') == {'b': 4}\n    histogram('') == {}\n    \"\"\"\n    if not test:\n        return {}\n\n    # Split the input string into a list of letters\n    letters = test.split()\n    \n    # Create a dictionary to count occurrences of each letter\n    count_dict = {}\n    for letter in letters:\n        if letter in count_dict:\n            count_dict[letter] += 1\n        else:\n            count_dict[letter] = 1\n\n    # Find the maximum count\n    max_count = max(count_dict.values())\n    \n    # Create a result dictionary for letters with the maximum count\n    result = {letter: count for letter, count in count_dict.items() if count == max_count}\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n    from collections import deque\n\n    N = len(grid)\n    directions = [(0, 1), (1, 0), (0, -1), (-1, 0)]  # right, down, left, up\n    min_path = None\n\n    def dfs(x, y, path):\n        nonlocal min_path\n        if len(path) == k:\n            if min_path is None or path < min_path:\n                min_path = path[:]\n            return\n        \n        for dx, dy in directions:\n            nx, ny = x + dx, y + dy\n            if 0 <= nx < N and 0 <= ny < N:\n                path.append(grid[nx][ny])\n                dfs(nx, ny, path)\n                path.pop()\n\n    for i in range(N):\n        for j in range(N):\n            dfs(i, j, [grid[i][j]])\n\n    return min_path", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": [[[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 15]]}]}}
\ No newline at end of file
diff --git a/EVALPLUS-4omini/5.json b/EVALPLUS-4omini/5.json
deleted file mode 100644
index 4c474d250..000000000
--- a/EVALPLUS-4omini/5.json
+++ /dev/null
@@ -1 +0,0 @@
-{"date": "2024-07-20 13:01", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n    \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n    Example:\n        even_odd_count(-12) ==> (1, 1)\n        even_odd_count(123) ==> (1, 2)\n    \"\"\"\n    # Convert the number to a string and remove the negative sign if present\n    num_str = str(abs(num))\n    \n    even_count = 0\n    odd_count = 0\n    \n    # Iterate through each character in the string representation of the number\n    for digit in num_str:\n        if digit.isdigit():  # Check if the character is a digit\n            if int(digit) % 2 == 0:\n                even_count += 1\n            else:\n                odd_count += 1\n    \n    return (even_count, odd_count)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n    \"\"\"Compares the actual game scores with the guessed scores and returns the absolute differences.\n    \n    Args:\n        game (list of int): The actual scores of the matches.\n        guess (list of int): The guessed scores of the matches.\n        \n    Returns:\n        list of int: A list containing the absolute differences between the actual scores and the guessed scores.\n                      If the guess is correct, the difference is 0.\n    \"\"\"\n    return [abs(g - a) for a, g in zip(game, guess)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n    \"\"\"\n    Given two positive integers a and b, return the even digits between a\n    and b, in ascending order.\n\n    For example:\n    generate_integers(2, 8) => [2, 4, 6, 8]\n    generate_integers(8, 2) => [2, 4, 6, 8]\n    generate_integers(10, 14) => []\n    \"\"\"\n    # Determine the range of numbers to consider\n    start = min(a, b)\n    end = max(a, b)\n\n    # Generate a list of even integers in the specified range\n    even_integers = [i for i in range(start, end + 1) if i % 2 == 0]\n\n    return even_integers", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[2, 10]], "plus_fail_tests": [[6, 12]]}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def compare_one(a, b):\n    \"\"\"\n    Create a function that takes integers, floats, or strings representing\n    real numbers, and returns the larger variable in its given variable type.\n    Return None if the values are equal.\n    Note: If a real number is represented as a string, the floating point might be . or ,\n\n    compare_one(1, 2.5) \u279e 2.5\n    compare_one(1, \"2,3\") \u279e \"2,3\"\n    compare_one(\"5,1\", \"6\") \u279e \"6\"\n    compare_one(\"1\", 1) \u279e None\n    \"\"\"\n    \n    def parse_value(value):\n        \"\"\"Convert the input value to a float or return it as is if it's a string.\"\"\"\n        if isinstance(value, str):\n            # Replace comma with dot for float conversion\n            value = value.replace(',', '.')\n            try:\n                return float(value)\n            except ValueError:\n                return value  # Return the string if it cannot be converted\n        return value\n\n    # Parse both values\n    parsed_a = parse_value(a)\n    parsed_b = parse_value(b)\n\n    # Check for equality\n    if parsed_a == parsed_b:\n        return None\n\n    # Return the larger value in its original type\n    return a if parsed_a > parsed_b else b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n    \"\"\"\n    Write a function count_nums which takes an array of integers and returns\n    the number of elements which has a sum of digits > 0.\n    If a number is negative, then its first signed digit will be negative:\n    e.g. -123 has signed digits -1, 2, and 3.\n    \n    >>> count_nums([]) == 0\n    >>> count_nums([-1, 11, -11]) == 1\n    >>> count_nums([1, 1, 2]) == 3\n    \"\"\"\n    def sum_of_digits(n):\n        # Convert the number to string and calculate the sum of its digits\n        return sum(int(digit) if i > 0 else -int(digit) for i, digit in enumerate(str(n)) if digit.isdigit() or (i == 0 and n < 0))\n\n    count = 0\n    for number in arr:\n        if sum_of_digits(number) > 0:\n            count += 1\n            \n    return count", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[-1, -2, 0]]], "plus_fail_tests": [[[-1, 0, 1]]]}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def factorial(i):\n    \"\"\"Helper function to calculate the factorial of i.\"\"\"\n    if i == 0 or i == 1:\n        return 1\n    result = 1\n    for j in range(2, i + 1):\n        result *= j\n    return result\ndef sum_of_numbers(i):\n    \"\"\"Helper function to calculate the sum of numbers from 1 to i.\"\"\"\n    return (i * (i + 1)) // 2\ndef f(n):\n    \"\"\"Implement the function f that takes n as a parameter,\n    and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even\n    or the sum of numbers from 1 to i otherwise.\n    i starts from 1.\n    \"\"\"\n    result = []\n    for i in range(1, n + 1):\n        if i % 2 == 0:  # i is even\n            result.append(factorial(i))\n        else:  # i is odd\n            result.append(sum_of_numbers(i))\n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n    \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n    around the mean of this dataset.\n    Mean Absolute Deviation is the average absolute difference between each\n    element and a centerpoint (mean in this case):\n    MAD = average | x - x_mean |\n    \n    >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n    1.0\n    \"\"\"\n    if not numbers:\n        return 0.0  # Return 0 for empty list to avoid division by zero\n\n    mean_value = sum(numbers) / len(numbers)\n    mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n    return mad", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n    \"\"\"\n    You will be given a string of words separated by commas or spaces. Your task is\n    to split the string into words and return an array of the words.\n    \n    For example:\n    words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n    words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n    \"\"\"\n    # Split the string by commas and spaces, then filter out any empty strings\n    words = [word.strip() for word in s.replace(',', ' ').split() if word]\n    return words", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n    \"\"\" \n    You're given a list of deposit and withdrawal operations on a bank account that starts with\n    zero balance. Your task is to detect if at any point the balance of account falls below zero, and\n    at that point function should return True. Otherwise it should return False.\n    \n    >>> below_zero([1, 2, 3])\n    False\n    >>> below_zero([1, 2, -4, 5])\n    True\n    \"\"\"\n    balance = 0\n    for operation in operations:\n        balance += operation\n        if balance < 0:\n            return True\n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n    \"\"\"\n    Given a string 'text', return its md5 hash equivalent string.\n    If 'text' is an empty string, return None.\n\n    >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n    >>> string_to_md5('') is None\n    >>> string_to_md5('Python') == '5d41402abc4b2a76b9719d911017c592'\n    \"\"\"\n    if text == \"\":\n        return None\n    md5_hash = hashlib.md5(text.encode()).hexdigest()\n    return md5_hash", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n    \"\"\"Find the strongest extension based on the defined strength criteria.\"\"\"\n    strongest_extension = None\n    max_strength = float('-inf')  # Start with the lowest possible strength\n\n    for extension in extensions:\n        # Calculate the strength of the current extension\n        CAP = sum(1 for char in extension if char.isupper())\n        SM = sum(1 for char in extension if char.islower())\n        strength = CAP - SM\n\n        # Check if this extension is stronger than the current strongest\n        if strength > max_strength:\n            max_strength = strength\n            strongest_extension = extension\n\n    # Return the result in the specified format\n    return f\"{class_name}.{strongest_extension}\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n    \"\"\"You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word.\n    \n    Args:\n    a (str): The first word.\n    b (str): The second word.\n    \n    Returns:\n    bool: True if b or any of its rotations is a substring of a, False otherwise.\n    \n    Examples:\n    >>> cycpattern_check(\"abcd\", \"abd\")\n    False\n    >>> cycpattern_check(\"hello\", \"ell\")\n    True\n    >>> cycpattern_check(\"whassup\", \"psus\")\n    False\n    >>> cycpattern_check(\"abab\", \"baa\")\n    True\n    >>> cycpattern_check(\"efef\", \"eeff\")\n    False\n    >>> cycpattern_check(\"himenss\", \"simen\")\n    True\n    \"\"\"\n    # Create a string that contains all rotations of b\n    rotations = b + b  # Concatenate b with itself to get all rotations\n    \n    # Check if any rotation of b is a substring of a\n    return any(rotation in a for rotation in (rotations[i:i+len(b)] for i in range(len(b))))", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["", ""]]}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n    \"\"\" Given a positive floating point number, it can be decomposed into\n    an integer part (largest integer smaller than given number) and decimals\n    (leftover part always smaller than 1).\n\n    Return the decimal part of the number.\n    \n    >>> truncate_number(3.5)\n    0.5\n    >>> truncate_number(7.25)\n    0.25\n    >>> truncate_number(10.0)\n    0.0\n    >>> truncate_number(5.99)\n    0.99\n    \"\"\"\n    if number < 0:\n        raise ValueError(\"The number must be positive.\")\n    \n    integer_part = int(number)  # Get the integer part\n    decimal_part = number - integer_part  # Calculate the decimal part\n    return decimal_part", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n    \"\"\"Calculate the first n + 1 numbers of the Tribonacci sequence.\"\"\"\n    if n < 0:\n        return []\n\n    # Initialize the list to store the Tribonacci numbers\n    tribonacci_sequence = []\n\n    # Define the base cases\n    for i in range(n + 1):\n        if i == 0:\n            tribonacci_sequence.append(1)  # tri(0) = 1\n        elif i == 1:\n            tribonacci_sequence.append(3)  # tri(1) = 3\n        elif i % 2 == 0:  # Even case\n            tribonacci_sequence.append(1 + i / 2)\n        else:  # Odd case\n            tri_n_minus_1 = tribonacci_sequence[i - 1]\n            tri_n_minus_2 = tribonacci_sequence[i - 2]\n            tri_n_plus_1 = tribonacci_sequence[i + 1] if i + 1 <= n else 0\n            tribonacci_sequence.append(tri_n_minus_1 + tri_n_minus_2 + tri_n_plus_1)\n\n    return tribonacci_sequence", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[3]], "plus_fail_tests": [[10]]}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n    \"\"\"\n    Given a positive integer n, you have to make a pile of n levels of stones.\n    The first level has n stones.\n    The number of stones in the next level is:\n        - the next odd number if n is odd.\n        - the next even number if n is even.\n    Return the number of stones in each level in a list, where element at index\n    i represents the number of stones in the level (i+1).\n\n    Examples:\n    >>> make_a_pile(3)\n    [3, 5, 7]\n    >>> make_a_pile(4)\n    [4, 6, 8, 10]\n    >>> make_a_pile(1)\n    [1]\n    \"\"\"\n    stones = []\n    current_stones = n\n    \n    for i in range(n):\n        stones.append(current_stones)\n        if current_stones % 2 == 0:\n            current_stones += 2  # next even number\n        else:\n            current_stones += 2  # next odd number\n    \n    return stones", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n    \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers.\n    \n    Args:\n        n (int): The number to evaluate.\n        \n    Returns:\n        bool: True if n can be expressed as the sum of 4 positive even numbers, False otherwise.\n    \n    Example:\n    is_equal_to_sum_even(4) == False\n    is_equal_to_sum_even(6) == False\n    is_equal_to_sum_even(8) == True\n    \"\"\"\n    # The smallest sum of 4 positive even numbers (2 + 2 + 2 + 2) is 8\n    if n < 8:\n        return False\n    \n    # Check if n is even\n    if n % 2 != 0:\n        return False\n    \n    # If n is even and >= 8, it can be expressed as the sum of 4 positive even numbers\n    return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n    \"\"\"\n    Given a positive integer n, return a tuple that has the number of even and odd\n    integer palindromes that fall within the range(1, n), inclusive.\n\n    Example 1:\n        Input: 3\n        Output: (1, 2)\n        Explanation:\n        Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n    Example 2:\n        Input: 12\n        Output: (4, 6)\n        Explanation:\n        Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n    Note:\n        1. 1 <= n <= 10^3\n        2. returned tuple has the number of even and odd integer palindromes respectively.\n    \"\"\"\n    even_count = 0\n    odd_count = 0\n\n    for i in range(1, n + 1):\n        if str(i) == str(i)[::-1]:  # Check if the number is a palindrome\n            if i % 2 == 0:\n                even_count += 1\n            else:\n                odd_count += 1\n\n    return (even_count, odd_count)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimiter: int) -> List[int]:\n    \"\"\" Insert a number 'delimiter' between every two consecutive elements of input list `numbers`\n    \n    >>> intersperse([], 4)\n    []\n    >>> intersperse([1, 2, 3], 4)\n    [1, 4, 2, 4, 3]\n    \"\"\"\n    if not numbers:\n        return []\n    \n    result = []\n    for i in range(len(numbers) - 1):\n        result.append(numbers[i])\n        result.append(delimiter)\n    result.append(numbers[-1])  # Append the last element\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n    \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N]. The\n    numbers in the array will be randomly ordered. Your task is to determine if\n    it is possible to get an array sorted in non-decreasing order by performing \n    the following operation on the given array:\n        You are allowed to perform right shift operation any number of times.\n    \n    One right shift operation means shifting all elements of the array by one\n    position in the right direction. The last element of the array will be moved to\n    the starting position in the array i.e. 0th index. \n\n    If it is possible to obtain the sorted array by performing the above operation\n    then return True else return False.\n    If the given array is empty then return True.\n\n    Note: The given list is guaranteed to have unique elements.\n\n    For Example:\n    \n    move_one_ball([3, 4, 5, 1, 2])==>True\n    Explanation: By performing 2 right shift operations, non-decreasing order can\n                 be achieved for the given array.\n    move_one_ball([3, 5, 4, 1, 2])==>False\n    Explanation: It is not possible to get non-decreasing order for the given\n                array by performing any number of right shift operations.\n    \"\"\"\n    if not arr:\n        return True\n\n    n = len(arr)\n    sorted_arr = sorted(arr)\n    \n    # Check for the number of \"breaks\" in the sorted array\n    break_count = 0\n    for i in range(n):\n        if arr[i] > arr[(i + 1) % n]:\n            break_count += 1\n\n    # If there are more than one break, we cannot sort the array with shifts\n    return break_count <= 1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n    '''\n    Create a function that returns a tuple (a, b), where 'a' is\n    the largest of negative integers, and 'b' is the smallest\n    of positive integers in a list.\n    If there is no negative or positive integers, return them as None.\n\n    Examples:\n    largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n    largest_smallest_integers([]) == (None, None)\n    largest_smallest_integers([0]) == (None, None)\n    '''\n    largest_negative = None\n    smallest_positive = None\n\n    for num in lst:\n        if num < 0:\n            if largest_negative is None or num > largest_negative:\n                largest_negative = num\n        elif num > 0:\n            if smallest_positive is None or num < smallest_positive:\n                smallest_positive = num\n\n    return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n    \"\"\"Given a positive integer n, return the product of the odd digits.\n    Return 0 if all digits are even.\n    For example:\n    digits(1)  == 1\n    digits(4)  == 0\n    digits(235) == 15\n    \"\"\"\n    product = 1\n    has_odd = False\n    \n    for digit in str(n):\n        digit = int(digit)\n        if digit % 2 != 0:  # Check if the digit is odd\n            product *= digit\n            has_odd = True\n            \n    return product if has_odd else 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n    \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n    \n    >>> flip_case('Hello')\n    'hELLO'\n    >>> flip_case('Python')\n    'pYTHON'\n    >>> flip_case('1234')\n    '1234'\n    >>> flip_case('!@#$')\n    '!@#$'\n    >>> flip_case('Mixed CASE')\n    'mIXED case'\n    \"\"\"\n    return string.swapcase()", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n    \"\"\" Find how many times a given substring can be found in the original string. Count overlapping cases.\n    \n    >>> how_many_times('', 'a')\n    0\n    >>> how_many_times('aaa', 'a')\n    3\n    >>> how_many_times('aaaa', 'aa')\n    3\n    \"\"\"\n    count = 0\n    start = 0\n    \n    while True:\n        start = string.find(substring, start)\n        if start == -1:\n            break\n        count += 1\n        start += 1  # Move to the next character to allow for overlapping\n\n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n    \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n    other and return them in order (smaller number, larger number).\n    \n    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n    (2.0, 2.2)\n    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n    (2.0, 2.0)\n    \"\"\"\n    # Sort the numbers to find the closest pairs easily\n    sorted_numbers = sorted(numbers)\n    \n    # Initialize the minimum difference and the closest pair\n    min_diff = float('inf')\n    closest_pair = (0.0, 0.0)\n    \n    # Iterate through the sorted list to find the closest elements\n    for i in range(len(sorted_numbers) - 1):\n        diff = sorted_numbers[i + 1] - sorted_numbers[i]\n        if diff < min_diff:\n            min_diff = diff\n            closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n    \n    return closest_pair", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n    \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n    \n    Args:\n        strings (List[str]): A list of strings to filter.\n        prefix (str): The prefix to filter the strings by.\n        \n    Returns:\n        List[str]: A list of strings that start with the given prefix.\n    \n    Examples:\n        >>> filter_by_prefix([], 'a')\n        []\n        >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n        ['abc', 'array']\n    \"\"\"\n    return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n    \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n    >>> count_distinct_characters('xyzXYZ')\n    3\n    >>> count_distinct_characters('Jerry')\n    4\n    \"\"\"\n    # Convert the string to lowercase to ensure case insensitivity\n    lower_string = string.lower()\n    # Use a set to find distinct characters\n    distinct_characters = set(lower_string)\n    # Return the number of distinct characters\n    return len(distinct_characters)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n    \"\"\" Input are two strings a and b consisting only of 1s and 0s.\n    Perform binary XOR on these inputs and return result also as a string.\n    \n    >>> string_xor('010', '110')\n    '100'\n    >>> string_xor('111', '000')\n    '111'\n    >>> string_xor('101', '101')\n    '000'\n    >>> string_xor('000', '000')\n    '000'\n    \"\"\"\n    # Ensure both strings are of the same length\n    if len(a) != len(b):\n        raise ValueError(\"Input strings must be of the same length.\")\n    \n    # Perform XOR operation\n    result = []\n    for bit_a, bit_b in zip(a, b):\n        result.append('1' if bit_a != bit_b else '0')\n    \n    return ''.join(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n    \"\"\"Given length of a side and height, return the area of a triangle.\n    \n    The area of a triangle can be calculated using the formula:\n    area = (base * height) / 2\n    \n    Parameters:\n    a (float): The length of the base of the triangle.\n    h (float): The height of the triangle.\n    \n    Returns:\n    float: The area of the triangle.\n    \n    >>> triangle_area(5, 3)\n    7.5\n    >>> triangle_area(10, 2)\n    10.0\n    >>> triangle_area(0, 5)\n    0.0\n    >>> triangle_area(5, 0)\n    0.0\n    \"\"\"\n    return (a * h) / 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n    \"\"\"Return list with elements incremented by 1.\n    \n    >>> incr_list([1, 2, 3])\n    [2, 3, 4]\n    >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n    [6, 4, 6, 3, 4, 4, 10, 1, 124]\n    \"\"\"\n    return [x + 1 for x in l]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n    \"\"\"Create a function encrypt that takes a string as an argument and\n    returns a string encrypted with the alphabet being rotated. \n    The alphabet should be rotated in a manner such that the letters \n    shift down by two multiplied to two places.\n    For example:\n    encrypt('hi') returns 'lm'\n    encrypt('asdfghjkl') returns 'ewhjklnop'\n    encrypt('gf') returns 'kj'\n    encrypt('et') returns 'ix'\n    \"\"\"\n    encrypted = []\n    for char in s:\n        if char.isalpha():  # Check if the character is a letter\n            # Calculate the new character with a shift of 4 (2 * 2)\n            new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a')) if char.islower() else \\\n                        chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n            encrypted.append(new_char)\n        else:\n            encrypted.append(char)  # Non-alphabetic characters remain unchanged\n    return ''.join(encrypted)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n    '''\n    Write a function that accepts two lists of strings and returns the list that has \n    total number of chars in the all strings of the list less than the other list.\n\n    if the two lists have the same number of chars, return the first list.\n\n    Examples\n    total_match([], []) \u279e []\n    total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n    total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n    total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n    total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n    '''\n    # Calculate the total number of characters in each list\n    total_chars_lst1 = sum(len(s) for s in lst1)\n    total_chars_lst2 = sum(len(s) for s in lst2)\n\n    # Compare the total characters and return the appropriate list\n    if total_chars_lst1 < total_chars_lst2:\n        return lst1\n    else:\n        return lst2", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": [[["happy", "birthday", "sarah"], ["happy", "birthday", "sally"]]]}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n    \"\"\"\n    You are given a 2 dimensional data, as a nested lists,\n    which is similar to matrix, however, unlike matrices,\n    each row may contain a different number of columns.\n    Given lst, and integer x, find integers x in the list,\n    and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n    each tuple is a coordinate - (row, columns), starting with 0.\n    Sort coordinates initially by rows in ascending order.\n    Also, sort coordinates of the row by columns in descending order.\n    \n    Examples:\n    get_row([\n      [1,2,3,4,5,6],\n      [1,2,3,4,1,6],\n      [1,2,3,4,5,1]\n    ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n    get_row([], 1) == []\n    get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n    \"\"\"\n    coordinates = []\n    \n    for row_index, row in enumerate(lst):\n        for col_index, value in enumerate(row):\n            if value == x:\n                coordinates.append((row_index, col_index))\n    \n    # Sort by row index (ascending) and then by column index (descending)\n    coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n    \n    return coordinates", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n    \"\"\"\n    Given an array arr of integers, find the minimum number of elements that\n    need to be changed to make the array palindromic. A palindromic array is an array that\n    is read the same backwards and forwards. In one change, you can change one element to any other element.\n\n    For example:\n    smallest_change([1,2,3,5,4,7,9,6]) == 4\n    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n    smallest_change([1, 2, 3, 2, 1]) == 0\n    \"\"\"\n    n = len(arr)\n    changes = 0\n    \n    # Compare elements from the start and end towards the center\n    for i in range(n // 2):\n        if arr[i] != arr[n - 1 - i]:\n            changes += 1\n            \n    return changes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n    \"\"\" Input to this function is a string representing musical notes in a special ASCII format.\n    Your task is to parse this string and return list of integers corresponding to how many beats does each\n    note last.\n\n    Here is a legend:\n    'o' - whole note, lasts four beats\n    'o|' - half note, lasts two beats\n    '.|' - quarter note, lasts one beat\n\n    >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n    [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n    \"\"\"\n    # Define a mapping from note representation to beats\n    note_to_beats = {\n        'o': 4,   # whole note\n        'o|': 2,  # half note\n        '.|': 1   # quarter note\n    }\n    \n    # Split the input string into individual notes\n    notes = music_string.split()\n    \n    # Parse each note and convert to beats\n    beats = [note_to_beats[note] for note in notes if note in note_to_beats]\n    \n    return beats", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n    \"\"\"You are given a string s.\n    Your task is to check if the string is happy or not.\n    A string is happy if its length is at least 3 and every 3 consecutive letters are distinct.\n    \n    For example:\n    is_happy(a) => False\n    is_happy(aa) => False\n    is_happy(abcd) => True\n    is_happy(aabb) => False\n    is_happy(adb) => True\n    is_happy(xyy) => False\n    \"\"\"\n    # Check if the length of the string is at least 3\n    if len(s) < 3:\n        return False\n    \n    # Iterate through the string and check every 3 consecutive characters\n    for i in range(len(s) - 2):\n        # Get the current substring of 3 characters\n        substring = s[i:i+3]\n        # Check if all characters in the substring are distinct\n        if len(set(substring)) != 3:\n            return False\n    \n    return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n    \"\"\" Concatenate list of strings into a single string.\n    \n    Args:\n        strings (List[str]): A list of strings to concatenate.\n        \n    Returns:\n        str: A single concatenated string.\n    \n    Examples:\n        >>> concatenate([])\n        ''\n        >>> concatenate(['a', 'b', 'c'])\n        'abc'\n    \"\"\"\n    return ''.join(strings)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n    \"\"\" \n    Input is a space-delimited string of numerals from 'zero' to 'nine'.\n    Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n    Return the string with numbers sorted from smallest to largest.\n    \n    >>> sort_numbers('three one five')\n    'one three five'\n    \"\"\"\n    # Mapping of words to their corresponding numeric values\n    num_map = {\n        'zero': 0,\n        'one': 1,\n        'two': 2,\n        'three': 3,\n        'four': 4,\n        'five': 5,\n        'six': 6,\n        'seven': 7,\n        'eight': 8,\n        'nine': 9\n    }\n    \n    # Split the input string into a list of words\n    words = numbers.split()\n    \n    # Sort the words based on their numeric values using the mapping\n    sorted_words = sorted(words, key=lambda word: num_map[word])\n    \n    # Join the sorted words back into a single string\n    return ' '.join(sorted_words)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n    \"\"\" Test if given string is a palindrome \"\"\"\n    return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n    \"\"\" Find the shortest palindrome that begins with a supplied string.\n    Algorithm idea is simple:\n    - Find the longest postfix of supplied string that is a palindrome.\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n    \n    >>> make_palindrome('')\n    ''\n    >>> make_palindrome('cat')\n    'catac'\n    >>> make_palindrome('cata')\n    'catac'\n    \"\"\"\n    # Find the longest palindromic suffix\n    for i in range(len(string)):\n        if is_palindrome(string[i:]):\n            # If the suffix is a palindrome, we need to append the reverse of the prefix\n            prefix = string[:i]\n            return string + prefix[::-1]\n    return string  # In case the string is empty or already a palindrome", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n    \"\"\" From a list of integers, remove all elements that occur more than once.\n    Keep order of elements left the same as in the input.\n    \n    >>> remove_duplicates([1, 2, 3, 2, 4])\n    [1, 3, 4]\n    \"\"\"\n    # Count occurrences of each number\n    count = {}\n    for number in numbers:\n        count[number] = count.get(number, 0) + 1\n    \n    # Create a new list with elements that occur only once\n    result = [number for number in numbers if count[number] == 1]\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n    \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n    such that the smallest number will become 0 and the largest will become 1.\n    \n    >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n    [0.0, 0.25, 0.5, 0.75, 1.0]\n    \"\"\"\n    if len(numbers) < 2:\n        raise ValueError(\"The list must contain at least two elements.\")\n    \n    min_val = min(numbers)\n    max_val = max(numbers)\n    \n    # Avoid division by zero if all numbers are the same\n    if min_val == max_val:\n        return [0.0] * len(numbers)\n    \n    return [(num - min_val) / (max_val - min_val) for num in numbers]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n    \"\"\"Convert a list of GPAs to letter grades based on a specific grading scale.\"\"\"\n    letter_grades = []\n    \n    for gpa in grades:\n        if gpa == 4.0:\n            letter_grades.append('A+')\n        elif gpa > 3.7:\n            letter_grades.append('A')\n        elif gpa > 3.3:\n            letter_grades.append('A-')\n        elif gpa > 3.0:\n            letter_grades.append('B+')\n        elif gpa > 2.7:\n            letter_grades.append('B')\n        elif gpa > 2.3:\n            letter_grades.append('B-')\n        elif gpa > 2.0:\n            letter_grades.append('C+')\n        elif gpa > 1.7:\n            letter_grades.append('C')\n        elif gpa > 1.3:\n            letter_grades.append('C-')\n        elif gpa > 1.0:\n            letter_grades.append('D+')\n        elif gpa > 0.7:\n            letter_grades.append('D')\n        elif gpa > 0.0:\n            letter_grades.append('D-')\n        else:\n            letter_grades.append('E')\n    \n    return letter_grades", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef generate_primes(limit):\n    \"\"\"Generate a list of prime numbers up to a given limit.\"\"\"\n    return [num for num in range(2, limit) if is_prime(num)]\ndef is_multiply_prime(a):\n    \"\"\"Return true if the given number is the multiplication of 3 prime numbers.\"\"\"\n    if a >= 100:\n        return False\n    \n    primes = generate_primes(a)\n    prime_count = len(primes)\n    \n    # Check all combinations of three primes\n    for i in range(prime_count):\n        for j in range(i, prime_count):\n            for k in range(j, prime_count):\n                product = primes[i] * primes[j] * primes[k]\n                if product == a:\n                    return True\n                if product > a:\n                    break  # No need to check further if product exceeds a\n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n    '''\n    Write a function that returns True if the object q will fly, and False otherwise.\n    The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n\n    Example:\n    will_it_fly([1, 2], 5) \u279e False \n    # 1+2 is less than the maximum possible weight, but it's unbalanced.\n\n    will_it_fly([3, 2, 3], 1) \u279e False\n    # it's balanced, but 3+2+3 is more than the maximum possible weight.\n\n    will_it_fly([3, 2, 3], 9) \u279e True\n    # 3+2+3 is less than the maximum possible weight, and it's balanced.\n\n    will_it_fly([3], 5) \u279e True\n    # 3 is less than the maximum possible weight, and it's balanced.\n    '''\n    # Check if the list is a palindrome\n    is_balanced = q == q[::-1]\n    \n    # Calculate the sum of the elements in the list\n    total_weight = sum(q)\n    \n    # Check if the object will fly\n    return is_balanced and total_weight <= w", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n    \"\"\"\n    Write a function that takes a string and returns an ordered version of it.\n    Ordered version of string, is a string where all words (separated by space)\n    are replaced by a new word where all the characters arranged in\n    ascending order based on ascii value.\n    Note: You should keep the order of words and blank spaces in the sentence.\n\n    For example:\n    anti_shuffle('Hi') returns 'Hi'\n    anti_shuffle('hello') returns 'ehllo'\n    anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n    \"\"\"\n    # Split the input string into words and keep track of spaces\n    words = s.split(' ')\n    \n    # Sort each word and keep the spaces intact\n    sorted_words = [''.join(sorted(word)) for word in words]\n    \n    # Join the sorted words back with spaces\n    result = ' '.join(sorted_words)\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int) -> str:\n    \"\"\"Change numerical base of input number x to base.\n    return string representation after the conversion.\n    base numbers are less than 10.\n    \n    >>> change_base(8, 3)\n    '22'\n    >>> change_base(8, 2)\n    '1000'\n    >>> change_base(7, 2)\n    '111'\n    \"\"\"\n    if base < 2 or base >= 10:\n        raise ValueError(\"Base must be between 2 and 9 inclusive.\")\n    \n    if x == 0:\n        return '0'\n    \n    result = []\n    while x > 0:\n        result.append(str(x % base))\n        x //= base\n    \n    return ''.join(reversed(result))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(input_dict):\n    \"\"\"\n    Given a dictionary, return True if all keys are strings in lower \n    case or all keys are strings in upper case, else return False.\n    The function should return False if the given dictionary is empty.\n    \n    Examples:\n    check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n    check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n    check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n    check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n    check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n    \"\"\"\n    if not input_dict:\n        return False\n\n    all_lower = all(isinstance(key, str) and key.islower() for key in input_dict.keys())\n    all_upper = all(isinstance(key, str) and key.isupper() for key in input_dict.keys())\n\n    return all_lower or all_upper", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n    \"\"\"\n    Given an array of non-negative integers, return a copy of the given array after sorting,\n    you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n    or sort it in descending order if the sum( first index value, last index value) is even.\n\n    Note:\n    * don't change the given array.\n\n    Examples:\n    * sort_array([]) => []\n    * sort_array([5]) => [5]\n    * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n    * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n    \"\"\"\n    if not array:  # Check for empty array\n        return []\n    \n    first_value = array[0]\n    last_value = array[-1]\n    sum_values = first_value + last_value\n\n    # Create a copy of the array to sort\n    sorted_array = array.copy()\n\n    if sum_values % 2 == 0:\n        # Sort in descending order if the sum is even\n        sorted_array.sort(reverse=True)\n    else:\n        # Sort in ascending order if the sum is odd\n        sorted_array.sort()\n\n    return sorted_array", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n    \"\"\"\n    pairs_sum_to_zero takes a list of integers as an input.\n    it returns True if there are two distinct elements in the list that\n    sum to zero, and False otherwise.\n    \n    >>> pairs_sum_to_zero([1, 3, 5, 0])\n    False\n    >>> pairs_sum_to_zero([1, 3, -2, 1])\n    False\n    >>> pairs_sum_to_zero([1, 2, 3, 7])\n    False\n    >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n    True\n    >>> pairs_sum_to_zero([1])\n    False\n    \"\"\"\n    seen = set()\n    for number in l:\n        if -number in seen:\n            return True\n        seen.add(number)\n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n    '''\n    Create a function that takes 3 numbers.\n    Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n    Returns false in any other cases.\n    \n    Examples\n    any_int(5, 2, 7) \u279e True\n    \n    any_int(3, 2, 2) \u279e False\n\n    any_int(3, -2, 1) \u279e True\n    \n    any_int(3.6, -2.2, 2) \u279e False\n    '''\n    # Check if all inputs are integers\n    if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n        # Check if one number is equal to the sum of the other two\n        return x == y + z or y == x + z or z == x + y\n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n    \"\"\"Task\n    Write a function that takes a string as input and returns the sum of the upper characters only'\n    ASCII codes.\n\n    Examples:\n        digitSum(\"\") => 0\n        digitSum(\"abAB\") => 131\n        digitSum(\"abcCd\") => 67\n        digitSum(\"helloE\") => 69\n        digitSum(\"woArBld\") => 131\n        digitSum(\"aAaaaXa\") => 153\n    \"\"\"\n    return sum(ord(char) for char in s if char.isupper())", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str) -> bool:\n    \"\"\" \n    brackets is a string of \"(\" and \")\".\n    return True if every opening bracket has a corresponding closing bracket.\n\n    >>> correct_bracketing(\"(\")\n    False\n    >>> correct_bracketing(\"()\")\n    True\n    >>> correct_bracketing(\"(()())\")\n    True\n    >>> correct_bracketing(\")(()\")\n    False\n    \"\"\"\n    balance = 0\n    for char in brackets:\n        if char == '(':\n            balance += 1\n        elif char == ')':\n            balance -= 1\n        # If balance goes negative, there are unmatched closing brackets\n        if balance < 0:\n            return False\n    # At the end, balance should be zero for all opening brackets to be matched\n    return balance == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str) -> str:\n    \"\"\"\n    Takes as input string encoded with encode_shift function. Returns decoded string.\n    \"\"\"\n    return \"\".join([chr(((ord(ch) - ord(\"a\") - 5) % 26) + ord(\"a\")) for ch in s])", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list) -> bool:\n    \"\"\"Return True if list elements are monotonically increasing or decreasing.\n    \n    >>> monotonic([1, 2, 4, 20])\n    True\n    >>> monotonic([1, 20, 4, 10])\n    False\n    >>> monotonic([4, 1, 0, -10])\n    True\n    \"\"\"\n    if not l:  # An empty list is considered monotonic\n        return True\n    \n    increasing = decreasing = True\n    \n    for i in range(1, len(l)):\n        if l[i] > l[i - 1]:\n            decreasing = False\n        elif l[i] < l[i - 1]:\n            increasing = False\n            \n    return increasing or decreasing", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int):\n    \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n    \n    >>> largest_prime_factor(13195)\n    29\n    >>> largest_prime_factor(2048)\n    2\n    \"\"\"\n    # Start with the smallest prime factor\n    factor = 2\n    # Keep dividing n by factor until it is no longer divisible\n    while n > 1:\n        if n % factor == 0:\n            n //= factor  # Divide n by the factor\n        else:\n            factor += 1  # Move to the next potential factor\n    return factor  # The last factor is the largest prime factor", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n    \"\"\"\n    Given an array representing a branch of a tree that has non-negative integer nodes,\n    your task is to pluck one of the nodes and return it.\n    The plucked node should be the node with the smallest even value.\n    If multiple nodes with the same smallest even value are found, return the node that has the smallest index.\n\n    The plucked node should be returned in a list, [ smallest_value, its index ],\n    If there are no even values or the given array is empty, return [].\n\n    Example 1:\n        Input: [4,2,3]\n        Output: [2, 1]\n        Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n    Example 2:\n        Input: [1,2,3]\n        Output: [2, 1]\n        Explanation: 2 has the smallest even value, and 2 has the smallest index. \n\n    Example 3:\n        Input: []\n        Output: []\n    \n    Example 4:\n        Input: [5, 0, 3, 0, 4, 2]\n        Output: [0, 1]\n        Explanation: 0 is the smallest value, but there are two zeros,\n                     so we will choose the first zero, which has the smallest index.\n\n    Constraints:\n        * 1 <= nodes.length <= 10000\n        * 0 <= node.value\n    \"\"\"\n    smallest_even = float('inf')\n    smallest_index = -1\n\n    for index, value in enumerate(arr):\n        if value % 2 == 0:  # Check if the value is even\n            if value < smallest_even:  # Check if it's the smallest even found\n                smallest_even = value\n                smallest_index = index\n\n    if smallest_index == -1:  # No even value found\n        return []\n    \n    return [smallest_even, smallest_index]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float) -> float:\n    \"\"\"\n    Evaluates polynomial with coefficients xs at point x.\n    return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n    \"\"\"\n    return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\ndef derivative(xs: list) -> list:\n    \"\"\"\n    Computes the derivative of the polynomial with coefficients xs.\n    \"\"\"\n    return [i * coeff for i, coeff in enumerate(xs) if i > 0]\ndef find_zero(xs: list, initial_guess: float = 0.0, tolerance: float = 1e-7, max_iterations: int = 1000) -> float:\n    \"\"\" \n    xs are coefficients of a polynomial.\n    find_zero finds x such that poly(x) = 0.\n    find_zero returns only one zero point, even if there are many.\n    Moreover, find_zero only takes list xs having an even number of coefficients\n    and the largest non-zero coefficient as it guarantees a solution.\n    \n    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n    -0.5\n    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n    1.0\n    \"\"\"\n    if len(xs) % 2 != 0:\n        raise ValueError(\"The number of coefficients must be even.\")\n    \n    current_guess = initial_guess\n    for _ in range(max_iterations):\n        f_value = poly(xs, current_guess)\n        f_derivative = poly(derivative(xs), current_guess)\n        \n        if f_derivative == 0:\n            raise ValueError(\"Derivative is zero. No solution found.\")\n        \n        next_guess = current_guess - f_value / f_derivative\n        \n        if abs(next_guess - current_guess) < tolerance:\n            return next_guess\n        \n        current_guess = next_guess\n    \n    raise ValueError(\"Maximum iterations reached. No solution found.\")", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[[5, 10, -3, 1]]]}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n    \"\"\"Return maximum element in the list.\n    \n    >>> max_element([1, 2, 3])\n    3\n    >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n    123\n    \"\"\"\n    if not l:  # Check if the list is empty\n        raise ValueError(\"The list is empty.\")\n    \n    max_value = l[0]  # Initialize max_value with the first element\n    for item in l:\n        if item > max_value:\n            max_value = item  # Update max_value if a larger item is found\n    return max_value", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str) -> bool:\n    \"\"\" brackets is a string of \"<\" and \">\".\n    return True if every opening bracket has a corresponding closing bracket.\n\n    >>> correct_bracketing(\"<\")\n    False\n    >>> correct_bracketing(\"<>\")\n    True\n    >>> correct_bracketing(\"<<><>>\")\n    True\n    >>> correct_bracketing(\"><<>\")\n    False\n    \"\"\"\n    balance = 0\n    for char in brackets:\n        if char == '<':\n            balance += 1\n        elif char == '>':\n            balance -= 1\n        # If balance goes negative, it means there's a closing bracket without a matching opening bracket\n        if balance < 0:\n            return False\n    # At the end, balance should be zero for all opening brackets to be matched\n    return balance == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n    \"\"\"\n    remove_vowels is a function that takes a string and returns a string without vowels.\n    \n    >>> remove_vowels('')\n    ''\n    >>> remove_vowels(\"abcdef\\nghijklm\")\n    'bcdf\\nghjklm'\n    >>> remove_vowels('abcdef')\n    'bcdf'\n    >>> remove_vowels('aaaaa')\n    ''\n    >>> remove_vowels('aaBAA')\n    'B'\n    >>> remove_vowels('zbcd')\n    'zbcd'\n    \"\"\"\n    vowels = 'aeiouAEIOU'\n    return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n    '''\n    You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n    zero, and has a frequency greater than or equal to the value of the integer itself. \n    The frequency of an integer is the number of times it appears in the list.\n    If no such a value exist, return -1.\n    \n    Examples:\n        search([4, 1, 2, 2, 3, 1]) == 2\n        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n        search([5, 5, 4, 4, 4]) == -1\n    '''\n    from collections import Counter\n    \n    # Count the frequency of each number in the list\n    frequency = Counter(lst)\n    \n    # Initialize the result variable\n    result = -1\n    \n    # Iterate through the frequency dictionary\n    for num, freq in frequency.items():\n        # Check if the frequency is greater than or equal to the number itself\n        if freq >= num:\n            # Update the result if this number is greater than the current result\n            result = max(result, num)\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n    \"\"\"\n    Write a function that takes a message, and encodes in such a \n    way that it swaps case of all letters, replaces all vowels in \n    the message with the letter that appears 2 places ahead of that \n    vowel in the english alphabet. \n    Assume only letters. \n    \n    Examples:\n    >>> encode('test')\n    'TGST'\n    >>> encode('This is a message')\n    'tHKS KS C MGSSCGG'\n    \"\"\"\n    vowels = 'aeiouAEIOU'\n    encoded_message = []\n\n    for char in message:\n        if char.isalpha():  # Check if the character is a letter\n            # Swap case\n            if char in vowels:\n                # Replace vowel with the letter 2 places ahead\n                if char.islower():\n                    new_char = chr((ord(char) - ord('a') + 2) % 26 + ord('a'))\n                else:\n                    new_char = chr((ord(char) - ord('A') + 2) % 26 + ord('A'))\n            else:\n                new_char = char.swapcase()  # Swap case for consonants\n            encoded_message.append(new_char)\n        else:\n            encoded_message.append(char)  # Keep non-letter characters unchanged\n\n    return ''.join(encoded_message)", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["TEST"]], "plus_fail_tests": [["abcdefghijklmnopqrstuvwxyz"]]}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n    \"\"\"\n    In this task, you will be given a string that represents a number of apples and oranges \n    that are distributed in a basket of fruit. This basket contains \n    apples, oranges, and mango fruits. Given the string that represents the total number of \n    the oranges and apples and an integer that represents the total number of the fruits \n    in the basket, return the number of the mango fruits in the basket.\n    \n    Parameters:\n    s (str): A string representing the number of apples and oranges.\n    n (int): An integer representing the total number of fruits in the basket.\n    \n    Returns:\n    int: The number of mango fruits in the basket.\n    \n    Examples:\n    fruit_distribution(\"5 apples and 6 oranges\", 19) -> 8\n    fruit_distribution(\"0 apples and 1 oranges\", 3) -> 2\n    fruit_distribution(\"2 apples and 3 oranges\", 100) -> 95\n    fruit_distribution(\"100 apples and 1 oranges\", 120) -> 19\n    \"\"\"\n    \n    # Extract the number of apples and oranges from the string\n    parts = s.split()\n    apples = int(parts[0])  # First part is the number of apples\n    oranges = int(parts[3])  # Fourth part is the number of oranges\n    \n    # Calculate the number of mangoes\n    mangoes = n - apples - oranges\n    return mangoes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n    \"\"\"Return sorted unique common elements for two lists.\n    \n    >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n    [1, 5, 653]\n    >>> common([5, 3, 2, 8], [3, 2])\n    [2, 3]\n    \n    \"\"\"\n    # Convert both lists to sets to find unique elements\n    set1 = set(l1)\n    set2 = set(l2)\n    \n    # Find the intersection of both sets\n    common_elements = set1.intersection(set2)\n    \n    # Return the sorted list of common elements\n    return sorted(common_elements)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int) -> int:\n    \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n    \n    >>> sum_to_n(30)\n    465\n    >>> sum_to_n(100)\n    5050\n    >>> sum_to_n(5)\n    15\n    >>> sum_to_n(10)\n    55\n    >>> sum_to_n(1)\n    1\n    \"\"\"\n    return n * (n + 1) // 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n    \"\"\"Return sorted unique elements in a list.\n    \n    >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n    [0, 2, 3, 5, 9, 123]\n    \"\"\"\n    return sorted(set(l))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n    \"\"\"This function takes a list l and returns a list l' such that\n    l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n    to the values of the corresponding indices of l, but sorted.\n    \n    >>> sort_third([1, 2, 3])\n    [1, 2, 3]\n    >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n    [2, 6, 3, 4, 8, 9, 5]\n    \"\"\"\n    # Extract values at indices divisible by 3\n    divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n    \n    # Sort the extracted values\n    sorted_values = sorted(divisible_by_three)\n    \n    # Create a new list to hold the result\n    result = l.copy()\n    \n    # Replace values at indices divisible by 3 with sorted values\n    for index, value in zip((i for i in range(len(l)) if i % 3 == 0), sorted_values):\n        result[index] = value\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n    \"\"\"\n    Given an array of integers nums, find the minimum sum of any non-empty sub-array\n    of nums.\n    \n    Example\n    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n    minSubArraySum([-1, -2, -3]) == -6\n    \"\"\"\n    # Initialize variables to track the minimum sum and the current sum\n    min_sum = float('inf')\n    current_sum = 0\n    \n    for num in nums:\n        current_sum += num\n        min_sum = min(min_sum, current_sum)\n        \n        # If current_sum is positive, reset it to 0\n        if current_sum > 0:\n            current_sum = 0\n            \n    return min_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n    \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n    Each element i of the output should be \"the number of odd elements in the\n    string i of the input.\" where all the i's should be replaced by the number\n    of odd digits in the i'th string of the input.\n\n    >>> odd_count(['1234567'])\n    [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n    >>> odd_count(['3',\"11111111\"])\n    [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n     \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n    \"\"\"\n    result = []\n    for s in lst:\n        odd_count = sum(1 for char in s if int(char) % 2 != 0)\n        result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n    '''\n    Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n    should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n    alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n    Examples\n    split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n    split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n    split_words(\"abcdef\") == 3 \n    '''\n    # Check for whitespace in the text\n    if ' ' in txt:\n        return txt.split()\n    \n    # Check for commas in the text\n    elif ',' in txt:\n        return txt.split(',')\n    \n    # If no whitespace or commas, count lower-case letters with odd order\n    else:\n        odd_count = sum(1 for char in txt if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n        return odd_count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n    \"\"\"\n    Given a non-empty array of integers arr and an integer k, return\n    the sum of the elements with at most two digits from the first k elements of arr.\n\n    Example:\n\n        Input: arr = [111, 21, 3, 4000, 5, 6, 7, 8, 9], k = 4\n        Output: 24 # sum of 21 + 3\n\n    Constraints:\n        1. 1 <= len(arr) <= 100\n        2. 1 <= k <= len(arr)\n    \"\"\"\n    # Initialize the sum\n    total_sum = 0\n    \n    # Iterate through the first k elements of the array\n    for i in range(k):\n        # Check if the current element has at most two digits\n        if -100 < arr[i] < 100:\n            total_sum += arr[i]\n    \n    return total_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n    \"\"\"Accepts a list of strings, removes strings with odd lengths,\n    and returns the remaining strings sorted by length and alphabetically.\n    \n    Args:\n        lst (list of str): A list of strings.\n    \n    Returns:\n        list of str: A sorted list of strings with even lengths.\n    \"\"\"\n    # Filter out strings with odd lengths\n    filtered_lst = [s for s in lst if len(s) % 2 == 0]\n    \n    # Sort the list first by length, then alphabetically\n    sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n    \n    return sorted_lst", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n    \"\"\"\n    Given a string text, replace all spaces in it with underscores, \n    and if a string has more than 2 consecutive spaces, \n    then replace all consecutive spaces with - \n    \n    fix_spaces(\"Example\") == \"Example\"\n    fix_spaces(\"Example 1\") == \"Example_1\"\n    fix_spaces(\" Example 2\") == \"_Example_2\"\n    fix_spaces(\" Example   3\") == \"_Example-3\"\n    \"\"\"\n    import re\n    \n    # Replace more than 2 consecutive spaces with a single '-'\n    text = re.sub(r' {3,}', '-', text)\n    \n    # Replace single spaces with underscores\n    text = text.replace(' ', '_')\n    \n    return text", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n    \"\"\"\n    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n    as follows: start with any positive integer n. Then each term is obtained from the \n    previous term as follows: if the previous term is even, the next term is one half of \n    the previous term. If the previous term is odd, the next term is 3 times the previous\n    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n    Note: \n        1. Collatz(1) is [1].\n        2. returned list sorted in increasing order.\n\n    For example:\n    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n    \"\"\"\n    if n <= 0:\n        raise ValueError(\"Input must be a positive integer.\")\n    \n    collatz_sequence = []\n    current = n\n    \n    while current != 1:\n        collatz_sequence.append(current)\n        if current % 2 == 0:\n            current //= 2\n        else:\n            current = 3 * current + 1\n    \n    collatz_sequence.append(1)  # Add the last term which is 1\n    \n    # Filter odd numbers and sort them\n    odd_numbers = sorted(num for num in collatz_sequence if num % 2 != 0)\n    \n    return odd_numbers", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n    \"\"\"Validates a given date string and returns True if the date is valid, otherwise False.\n    \n    The date is valid if all of the following rules are satisfied:\n    1. The date string is not empty.\n    2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12.\n       The number of days is not less than 1 or higher than 30 days for months 4,6,9,11.\n       The number of days is not less than 1 or higher than 29 for the month 2.\n    3. The months should not be less than 1 or higher than 12.\n    4. The date should be in the format: mm-dd-yyyy\n    \n    Args:\n        date (str): The date string to validate.\n    \n    Returns:\n        bool: True if the date is valid, False otherwise.\n    \"\"\"\n    if not date:\n        return False\n    \n    # Check the format\n    if len(date) != 10 or date[2] != '-' or date[5] != '-':\n        return False\n    \n    try:\n        month = int(date[:2])\n        day = int(date[3:5])\n        year = int(date[6:])\n    except ValueError:\n        return False\n    \n    # Validate month\n    if month < 1 or month > 12:\n        return False\n    \n    # Validate day based on month\n    if month in [1, 3, 5, 7, 8, 10, 12]:  # 31 days\n        if day < 1 or day > 31:\n            return False\n    elif month in [4, 6, 9, 11]:  # 30 days\n        if day < 1 or day > 30:\n            return False\n    elif month == 2:  # February\n        if day < 1 or day > 29:\n            return False\n    \n    return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n    \"\"\"Task\n    We are given two strings s and c, you have to delete all the characters in s that are equal to any character in c\n    then check if the result string is palindrome.\n    A string is called palindrome if it reads the same backward as forward.\n    You should return a tuple containing the result string and True/False for the check.\n    Example\n    For s = \"abcde\", c = \"ae\", the result should be ('bcd',False)\n    For s = \"abcdef\", c = \"b\"  the result should be ('acdef',False)\n    For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc',True)\n    \"\"\"\n    # Create a set of characters to delete for faster lookup\n    delete_set = set(c)\n    \n    # Create the result string by filtering out characters in delete_set\n    result = ''.join(char for char in s if char not in delete_set)\n    \n    # Check if the result string is a palindrome\n    is_palindrome = result == result[::-1]\n    \n    return (result, is_palindrome)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "import math\ndef max_fill(grid, capacity):\n    \"\"\"\n    Calculate the number of times buckets need to be lowered to empty the wells.\n\n    Parameters:\n    grid (list of list of int): A rectangular grid representing wells.\n    capacity (int): The capacity of each bucket.\n\n    Returns:\n    int: The total number of times buckets need to be lowered.\n    \"\"\"\n    total_water = 0\n    \n    # Count the total amount of water in the grid\n    for row in grid:\n        total_water += sum(row)\n    \n    # Calculate the number of times buckets need to be lowered\n    # Each bucket can carry 'capacity' units of water\n    if total_water == 0:\n        return 0\n    else:\n        return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[[1, 1, 1, 1], [1, 1, 1, 1]], 9]], "plus_fail_tests": [[[[1, 0, 0, 1], [0, 1, 1, 1], [0, 0, 0, 0], [1, 0, 1, 1]], 2]]}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n    \"\"\"Create a function which takes a string representing a file's name, and returns\n    'Yes' if the the file's name is valid, and returns 'No' otherwise.\n    A file's name is considered to be valid if and only if all the following conditions \n    are met:\n    - There should not be more than three digits ('0'-'9') in the file's name.\n    - The file's name contains exactly one dot '.'\n    - The substring before the dot should not be empty, and it starts with a letter from \n    the latin alphapet ('a'-'z' and 'A'-'Z').\n    - The substring after the dot should be one of these: ['txt', 'exe', 'dll']\n    Examples:\n    file_name_check(\"example.txt\") # => 'Yes'\n    file_name_check(\"1example.dll\") # => 'No' (the name should start with a latin alphapet letter)\n    \"\"\"\n    \n    # Split the file name into name and extension\n    if file_name.count('.') != 1:\n        return 'No'\n    \n    name, extension = file_name.split('.')\n    \n    # Check if the name is empty or starts with a non-letter\n    if not name or not name[0].isalpha():\n        return 'No'\n    \n    # Check the extension\n    valid_extensions = ['txt', 'exe', 'dll']\n    if extension not in valid_extensions:\n        return 'No'\n    \n    # Count the digits in the file name\n    digit_count = sum(c.isdigit() for c in file_name)\n    if digit_count > 3:\n        return 'No'\n    \n    return 'Yes'", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n    \"\"\"Write a function that takes an array of numbers as input and returns \n    the number of elements in the array that are greater than 10 and both \n    first and last digits of a number are odd (1, 3, 5, 7, 9).\n    \n    For example:\n    specialFilter([15, -73, 14, -15]) => 1 \n    specialFilter([33, -2, -3, 45, 21, 109]) => 2\n    \"\"\"\n    \n    def is_odd_digit(digit):\n        return digit in {'1', '3', '5', '7', '9'}\n    \n    def first_and_last_odd(num):\n        str_num = str(abs(num))  # Convert to string and take absolute value\n        return is_odd_digit(str_num[0]) and is_odd_digit(str_num[-1])\n    \n    count = 0\n    for num in nums:\n        if num > 10 and first_and_last_odd(num):\n            count += 1\n            \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n    '''\n    There are eight planets in our solar system: the closest to the Sun \n    is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n    Uranus, Neptune.\n    Write a function that takes two planet names as strings planet1 and planet2. \n    The function should return a tuple containing all planets whose orbits are \n    located between the orbit of planet1 and the orbit of planet2, sorted by \n    the proximity to the sun. \n    The function should return an empty tuple if planet1 or planet2\n    are not correct planet names. \n    Examples\n    bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n    bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n    bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n    '''\n    \n    planets = [\n        \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \n        \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"\n    ]\n    \n    if planet1 not in planets or planet2 not in planets:\n        return ()\n    \n    index1 = planets.index(planet1)\n    index2 = planets.index(planet2)\n    \n    # Ensure index1 is less than index2 for slicing\n    start_index = min(index1, index2) + 1\n    end_index = max(index1, index2)\n    \n    return tuple(planets[start_index:end_index])", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "import math\ndef sum_squares(lst):\n    \"\"\"You are given a list of numbers.\n    You need to return the sum of squared numbers in the given list,\n    round each element in the list to the upper int (Ceiling) first.\n    \n    Examples:\n    For lst = [1,2,3] the output should be 14\n    For lst = [1,4,9] the output should be 98\n    For lst = [1,3,5,7] the output should be 84\n    For lst = [1.4,4.2,0] the output should be 29\n    For lst = [-2.4,1,1] the output should be 6\n    \"\"\"\n    return sum(math.ceil(x) ** 2 for x in lst)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n    '''\n    Create a function that returns True if the last character\n    of a given string is an alphabetical character and is not\n    a part of a word, and False otherwise.\n    Note: \"word\" is a group of characters separated by space.\n\n    Examples:\n    check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n    check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n    check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n    check_if_last_char_is_a_letter(\"\") \u279e False \n    '''\n    # Strip any trailing whitespace from the string\n    txt = txt.rstrip()\n    \n    # Check if the string is empty after stripping\n    if not txt:\n        return False\n    \n    # Get the last character\n    last_char = txt[-1]\n    \n    # Check if the last character is a letter\n    if last_char.isalpha():\n        # Check if the last character is part of a word\n        # A character is part of a word if it is preceded by a non-space character\n        if len(txt) > 1 and txt[-2] != ' ':\n            return False\n        return True\n    \n    return False", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["eeeee e "]], "plus_fail_tests": [["k "]]}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n    \"\"\"\n    You are given a positive integer n. You have to create an integer array a of length n.\n    For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n    Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n    and a[i] + a[j] + a[k] is a multiple of 3.\n\n    Example :\n        Input: n = 5\n        Output: 1\n        Explanation: \n        a = [1, 3, 7, 13, 21]\n        The only valid triple is (1, 7, 13).\n    \"\"\"\n    # Create the array a\n    a = [i * i - i + 1 for i in range(1, n + 1)]\n    \n    # Count the number of valid triples\n    count = 0\n    \n    # Check all combinations of triples (i, j, k) with i < j < k\n    for i in range(n):\n        for j in range(i + 1, n):\n            for k in range(j + 1, n):\n                if (a[i] + a[j] + a[k]) % 3 == 0:\n                    count += 1\n                    \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n    \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n    in the sequence.\n    \n    >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n    [1, 2, 3, 3, 3, 4, 4]\n    \"\"\"\n    if not numbers:\n        return []\n    \n    max_so_far = numbers[0]\n    result = [max_so_far]\n    \n    for num in numbers[1:]:\n        max_so_far = max(max_so_far, num)\n        result.append(max_so_far)\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n    \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n    given threshold.\n    \n    >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n    False\n    >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n    True\n    \"\"\"\n    # Sort the numbers to make it easier to find close elements\n    numbers.sort()\n    \n    # Check the difference between consecutive elements\n    for i in range(len(numbers) - 1):\n        if abs(numbers[i] - numbers[i + 1]) < threshold:\n            return True\n            \n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef sum_of_digits(n):\n    \"\"\"Return the sum of the digits of a number.\"\"\"\n    return sum(int(digit) for digit in str(n))\ndef skjkasdkd(lst):\n    \"\"\"Find the largest prime value in the list and return the sum of its digits.\"\"\"\n    largest_prime = -1\n    \n    for number in lst:\n        if is_prime(number) and number > largest_prime:\n            largest_prime = number\n            \n    if largest_prime == -1:\n        return 0  # Return 0 if no prime is found\n    \n    return sum_of_digits(largest_prime)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n    \"\"\"This function takes two positive numbers x and y and returns the\n    biggest even integer number that is in the range [x, y] inclusive. If \n    there's no such number, then the function should return -1.\n\n    For example:\n    choose_num(12, 15) = 14\n    choose_num(13, 12) = -1\n    \"\"\"\n    # Ensure x is less than or equal to y\n    if x > y:\n        return -1\n    \n    # Start from the largest number in the range and check for evenness\n    for num in range(y, x - 1, -1):\n        if num % 2 == 0:\n            return num\n    \n    return -1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n    \"\"\" Filter an input list of strings only for ones that contain given substring\n    >>> filter_by_substring([], 'a')\n    []\n    >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n    ['abc', 'bacd', 'array']\n    \"\"\"\n    return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n    '''\n    Given a list of numbers, return the sum of squares of the numbers\n    in the list that are odd. Ignore numbers that are negative or not integers.\n    \n    double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n    double_the_difference([-1, -2, 0]) == 0\n    double_the_difference([9, -2]) == 81\n    double_the_difference([0]) == 0  \n   \n    If the input list is empty, return 0.\n    '''\n    if not lst:  # Check if the list is empty\n        return 0\n    \n    return sum(x**2 for x in lst if isinstance(x, int) and x >= 0 and x % 2 != 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n    \"\"\"\n    Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n    reverse the resulting array, and then replace each digit by its corresponding name from\n    \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n    For example:\n      arr = [2, 1, 1, 4, 5, 8, 2, 3]   \n            -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n            -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n      return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n    \n      If the array is empty, return an empty array:\n      arr = []\n      return []\n    \n      If the array has any strange number ignore it:\n      arr = [1, -1 , 55] \n            -> sort arr -> [-1, 1, 55]\n            -> reverse arr -> [55, 1, -1]\n      return = ['One']\n    \"\"\"\n    \n    # Mapping of digits to their corresponding names\n    digit_to_name = {\n        1: \"One\",\n        2: \"Two\",\n        3: \"Three\",\n        4: \"Four\",\n        5: \"Five\",\n        6: \"Six\",\n        7: \"Seven\",\n        8: \"Eight\",\n        9: \"Nine\"\n    }\n    \n    # Filter the array to include only numbers between 1 and 9\n    filtered_arr = [num for num in arr if 1 <= num <= 9]\n    \n    # Sort the filtered array\n    sorted_arr = sorted(filtered_arr)\n    \n    # Reverse the sorted array\n    reversed_arr = sorted_arr[::-1]\n    \n    # Convert the digits to their corresponding names\n    result = [digit_to_name[num] for num in reversed_arr]\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n    \"\"\"\n    Given a positive integer, obtain its roman numeral equivalent as a string,\n    and return it in lowercase.\n    Restrictions: 1 <= num <= 1000\n\n    Examples:\n    >>> int_to_mini_roman(19) == 'xix'\n    >>> int_to_mini_roman(152) == 'clii'\n    >>> int_to_mini_roman(426) == 'cdxxvi'\n    \"\"\"\n    if not (1 <= number <= 1000):\n        raise ValueError(\"Number must be between 1 and 1000\")\n\n    roman_numerals = [\n        (1000, 'm'),\n        (900, 'cm'),\n        (500, 'd'),\n        (400, 'cd'),\n        (100, 'c'),\n        (90, 'xc'),\n        (50, 'l'),\n        (40, 'xl'),\n        (10, 'x'),\n        (9, 'ix'),\n        (5, 'v'),\n        (4, 'iv'),\n        (1, 'i')\n    ]\n\n    result = []\n    for value, numeral in roman_numerals:\n        while number >= value:\n            result.append(numeral)\n            number -= value\n\n    return ''.join(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n    \"\"\"\n    Given two lists operator, and operand. The first list has basic algebra operations, and \n    the second list is a list of integers. Use the two given lists to build the algebraic \n    expression and return the evaluation of this expression.\n\n    The basic algebra operations:\n    Addition ( + ) \n    Subtraction ( - ) \n    Multiplication ( * ) \n    Floor division ( // ) \n    Exponentiation ( ** ) \n\n    Example:\n    operator = ['+', '*', '-']\n    operand = [2, 3, 4, 5]\n    result = 2 + 3 * 4 - 5\n    => result = 9\n\n    Note:\n        The length of operator list is equal to the length of operand list minus one.\n        Operand is a list of non-negative integers.\n        Operator list has at least one operator, and operand list has at least two operands.\n    \"\"\"\n    # Start with the first operand\n    result = operand[0]\n    \n    # Iterate through the operators and operands\n    for i in range(len(operator)):\n        op = operator[i]\n        next_operand = operand[i + 1]\n        \n        if op == '+':\n            result += next_operand\n        elif op == '-':\n            result -= next_operand\n        elif op == '*':\n            result *= next_operand\n        elif op == '//':\n            result //= next_operand\n        elif op == '**':\n            result **= next_operand\n        else:\n            raise ValueError(f\"Unsupported operator: {op}\")\n    \n    return result", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[["+", "*", "-"], [2, 3, 4, 5]]], "plus_fail_tests": [[["+", "-", "*", "//"], [5, 2, 3, 4, 7]]]}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n    \"\"\"Write a function that accepts a list of strings.\n    The list contains different words. Return the word with maximum number\n    of unique characters. If multiple strings have maximum number of unique\n    characters, return the one which comes first in lexicographical order.\n\n    find_max([\"name\", \"of\", \"string\"]) == \"string\"\n    find_max([\"name\", \"enam\", \"game\"]) == \"enam\"\n    find_max([\"aaaaaaa\", \"bb\" ,\"cc\"]) == \"aaaaaaa\"\n    \"\"\"\n    max_word = \"\"\n    max_unique_count = 0\n\n    for word in words:\n        unique_chars = set(word)\n        unique_count = len(unique_chars)\n\n        if (unique_count > max_unique_count) or (unique_count == max_unique_count and word < max_word):\n            max_word = word\n            max_unique_count = unique_count\n\n    return max_word", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n    \"\"\"Given a list of positive integers x, return a sorted list of all \n    elements that haven't any even digit.\n\n    Note: Returned list should be sorted in increasing order.\n    \n    For example:\n    >>> unique_digits([15, 33, 1422, 1])\n    [1, 15, 33]\n    >>> unique_digits([152, 323, 1422, 10])\n    []\n    \"\"\"\n    def has_even_digit(n):\n        \"\"\"Check if the number has any even digit.\"\"\"\n        return any(int(digit) % 2 == 0 for digit in str(n))\n\n    # Filter the list to include only numbers without even digits\n    result = [num for num in x if not has_even_digit(num)]\n    \n    # Return the sorted result\n    return sorted(result)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n    \"\"\" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n    For each of the group, output the deepest level of nesting of parentheses.\n    E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n    >>> parse_nested_parens('(()()) ((())) () ((())()())')\n    [2, 3, 1, 3]\n    \"\"\"\n    def max_nesting_depth(s: str) -> int:\n        max_depth = 0\n        current_depth = 0\n        for char in s:\n            if char == '(':\n                current_depth += 1\n                max_depth = max(max_depth, current_depth)\n            elif char == ')':\n                current_depth -= 1\n        return max_depth\n\n    groups = paren_string.split()\n    return [max_nesting_depth(group) for group in groups]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n    \"\"\" \n    Input to this function is a string containing multiple groups of nested parentheses. \n    Your goal is to separate those groups into separate strings and return the list of those.\n    Separate groups are balanced (each open brace is properly closed) and not nested within each other.\n    Ignore any spaces in the input string.\n    \n    >>> separate_paren_groups('( ) (( )) (( )( ))')\n    ['()', '(())', '(()())']\n    \"\"\"\n    # Remove spaces from the input string\n    paren_string = paren_string.replace(\" \", \"\")\n    \n    result = []\n    balance = 0\n    current_group = []\n    \n    for char in paren_string:\n        if char == '(':\n            if balance == 0 and current_group:\n                # If we are starting a new group, save the previous one\n                result.append(''.join(current_group))\n                current_group = []\n            balance += 1\n            current_group.append(char)\n        elif char == ')':\n            balance -= 1\n            current_group.append(char)\n            if balance == 0:\n                # If we have closed all opened parentheses, save the current group\n                result.append(''.join(current_group))\n                current_group = []\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n    \"\"\"Create a function which returns the largest index of an element which\n    is not greater than or equal to the element immediately preceding it. If\n    no such element exists then return -1. The given array will not contain\n    duplicate values.\n\n    Examples:\n    can_arrange([1,2,4,3,5]) = 3\n    can_arrange([1,2,3]) = -1\n    \"\"\"\n    # Initialize the index to -1, which will be returned if no such element is found\n    largest_index = -1\n    \n    # Iterate through the array starting from the second element\n    for i in range(1, len(arr)):\n        # Check if the current element is less than the previous element\n        if arr[i] < arr[i - 1]:\n            largest_index = i  # Update the largest index found\n    \n    return largest_index", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n    \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n    Empty sum should be equal to 0 and empty product should be equal to 1.\n    \n    >>> sum_product([])\n    (0, 1)\n    >>> sum_product([1, 2, 3, 4])\n    (10, 24)\n    \"\"\"\n    if not numbers:\n        return (0, 1)\n    \n    total_sum = sum(numbers)\n    total_product = 1\n    for number in numbers:\n        total_product *= number\n    \n    return (total_sum, total_product)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n    '''\n    Create a function that takes a string as input which contains only square brackets.\n    The function should return True if and only if there is a valid subsequence of brackets \n    where at least one bracket in the subsequence is nested.\n\n    is_nested('[[]]') \u279e True\n    is_nested('[]]]]]]][[[[[]') \u279e False\n    is_nested('[][]') \u279e False\n    is_nested('[]') \u279e False\n    is_nested('[[][]]') \u279e True\n    is_nested('[[]][[') \u279e True\n    '''\n    # Initialize a counter for open brackets\n    open_count = 0\n    # Initialize a flag to check for nesting\n    nested = False\n    \n    for char in string:\n        if char == '[':\n            open_count += 1\n            # If we have seen at least one open bracket before and we see another one,\n            # it indicates nesting\n            if open_count > 1:\n                nested = True\n        elif char == ']':\n            open_count -= 1\n            # If we close a bracket and we had opened brackets before\n            if open_count < 0:\n                return False  # More closing brackets than opening\n        # If we have closed all opened brackets, we can stop checking\n        if open_count < 0:\n            break\n    \n    # We need at least one nested bracket and all brackets must be closed\n    return nested and open_count == 0", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["[[]][["]], "plus_fail_tests": [["[[]]]"]]}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n    \"\"\"\n    You're a hungry rabbit, and you already have eaten a certain number of carrots,\n    but now you need to eat more carrots to complete the day's meals.\n    you should return an array of [ total number of eaten carrots after your meals,\n                                    the number of carrots left after your meals ]\n    if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n    \n    Example:\n    * eat(5, 6, 10) -> [11, 4]\n    * eat(4, 8, 9) -> [12, 1]\n    * eat(1, 10, 10) -> [11, 0]\n    * eat(2, 11, 5) -> [7, 0]\n    \n    Variables:\n    @number : integer\n        the number of carrots that you have eaten.\n    @need : integer\n        the number of carrots that you need to eat.\n    @remaining : integer\n        the number of remaining carrots that exist in stock\n    \n    Constrain:\n    * 0 <= number <= 1000\n    * 0 <= need <= 1000\n    * 0 <= remaining <= 1000\n\n    Have fun :)\n    \"\"\"\n    # Calculate how many more carrots are needed\n    additional_needed = need - number\n    \n    # If no additional carrots are needed, return the current state\n    if additional_needed <= 0:\n        return [number, remaining]\n    \n    # Determine how many carrots can be eaten from the remaining stock\n    eaten = min(additional_needed, remaining)\n    \n    # Calculate the total eaten and remaining carrots\n    total_eaten = number + eaten\n    remaining_after_meal = remaining - eaten\n    \n    return [total_eaten, remaining_after_meal]", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[5, 6, 10]], "plus_fail_tests": [[2, 2, 2]]}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def factorial(n):\n    \"\"\"Calculate the factorial of a non-negative integer n.\"\"\"\n    if n == 0 or n == 1:\n        return 1\n    result = 1\n    for i in range(2, n + 1):\n        result *= i\n    return result\ndef special_factorial(n):\n    \"\"\"Calculate the Brazilian factorial of n.\"\"\"\n    if n <= 0:\n        raise ValueError(\"Input must be a positive integer.\")\n    \n    result = 1\n    for i in range(1, n + 1):\n        result *= factorial(i)\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n    \"\"\"You are given a string s.\n    if s[i] is a letter, reverse its case from lower to upper or vise versa, \n    otherwise keep it as it is.\n    If the string contains no letters, reverse the string.\n    The function should return the resulted string.\n    \n    Examples:\n    solve(\"1234\") = \"4321\"\n    solve(\"ab\") = \"AB\"\n    solve(\"#a@C\") = \"#A@c\"\n    \"\"\"\n    # Check if there are any letters in the string\n    has_letters = any(c.isalpha() for c in s)\n    \n    if has_letters:\n        # Reverse case for letters and keep others the same\n        return ''.join(c.swapcase() if c.isalpha() else c for c in s)\n    else:\n        # Reverse the string if there are no letters\n        return s[::-1]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def is_prime(num):\n    \"\"\"Check if a number is prime.\"\"\"\n    if num <= 1:\n        return False\n    for i in range(2, int(num**0.5) + 1):\n        if num % i == 0:\n            return False\n    return True\ndef x_or_y(n, x, y):\n    \"\"\"Return the value of x if n is a prime number, otherwise return y.\"\"\"\n    if is_prime(n):\n        return x\n    else:\n        return y", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n    '''\n    Given the lengths of the three sides of a triangle. Return True if the three\n    sides form a right-angled triangle, False otherwise.\n    A right-angled triangle is a triangle in which one angle is right angle or \n    90 degree.\n    \n    Example:\n    right_angle_triangle(3, 4, 5) == True\n    right_angle_triangle(1, 2, 3) == False\n    '''\n    # Sort the sides to identify the longest side\n    sides = sorted([a, b, c])\n    \n    # Check the Pythagorean theorem\n    return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n    \"\"\"Convert a decimal number to binary format with specific formatting.\n\n    Args:\n    decimal (int): A non-negative integer to convert to binary.\n\n    Returns:\n    str: A string representing the binary format of the decimal number,\n         prefixed and suffixed with 'db'.\n    \n    Examples:\n    >>> decimal_to_binary(15)\n    'db1111db'\n    >>> decimal_to_binary(32)\n    'db100000db'\n    \"\"\"\n    if decimal < 0:\n        raise ValueError(\"Input must be a non-negative integer.\")\n    \n    # Convert decimal to binary and remove the '0b' prefix\n    binary_representation = bin(decimal)[2:]\n    \n    # Format the output with 'db' at the beginning and end\n    formatted_output = f\"db{binary_representation}db\"\n    \n    return formatted_output", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int) -> int:\n    \"\"\"\n    Imagine a road that's a perfectly straight infinitely long line.\n    n cars are driving left to right; simultaneously, a different set of n cars\n    are driving right to left. The two sets of cars start out being very far from\n    each other. All cars move at the same speed. Two cars are said to collide\n    when a car that's moving left to right hits a car that's moving right to left.\n    However, the cars are infinitely sturdy and strong; as a result, they continue moving\n    in their trajectory as if they did not collide.\n\n    This function outputs the number of such collisions.\n\n    Parameters:\n    n (int): The number of cars in each direction.\n\n    Returns:\n    int: The total number of collisions.\n    \"\"\"\n    # Each car moving left to right will collide with each car moving right to left\n    # Therefore, the total number of collisions is n * n\n    return n * n", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int) -> int:\n    \"\"\"The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n    fib4(0) -> 0\n    fib4(1) -> 0\n    fib4(2) -> 2\n    fib4(3) -> 0\n    fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n    Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.\n    \n    >>> fib4(5)\n    4\n    >>> fib4(6)\n    8\n    >>> fib4(7)\n    14\n    \"\"\"\n    if n == 0:\n        return 0\n    elif n == 1:\n        return 0\n    elif n == 2:\n        return 2\n    elif n == 3:\n        return 0\n\n    # Initialize the first four values of the sequence\n    fib_values = [0, 0, 2, 0]\n\n    # Compute the values iteratively\n    for i in range(4, n + 1):\n        next_value = fib_values[i - 1] + fib_values[i - 2] + fib_values[i - 3] + fib_values[i - 4]\n        fib_values.append(next_value)\n\n    return fib_values[n]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n    \"\"\"You are given two positive integers n and m, and your task is to compute the\n    average of the integers from n through m (including n and m). \n    Round the answer to the nearest integer and convert that to binary.\n    If n is greater than m, return -1.\n    \n    Example:\n    rounded_avg(1, 5) => \"0b11\"\n    rounded_avg(7, 5) => -1\n    rounded_avg(10, 20) => \"0b1111\"\n    rounded_avg(20, 33) => \"0b11010\"\n    \"\"\"\n    if n > m:\n        return -1\n    \n    # Calculate the sum of integers from n to m\n    total_sum = sum(range(n, m + 1))\n    count = m - n + 1  # Total numbers from n to m\n    \n    # Calculate the average and round it\n    average = total_sum / count\n    rounded_average = round(average)\n    \n    # Convert the rounded average to binary\n    return bin(rounded_average)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str) -> bool:\n    \"\"\"\n    Checks if given string is a palindrome.\n    \n    A palindrome is a string that reads the same forward and backward.\n    \n    >>> is_palindrome('')\n    True\n    >>> is_palindrome('aba')\n    True\n    >>> is_palindrome('aaaaa')\n    True\n    >>> is_palindrome('zbcd')\n    False\n    \"\"\"\n    # Normalize the string by removing spaces and converting to lowercase\n    normalized_text = text.replace(\" \", \"\").lower()\n    # Check if the string is equal to its reverse\n    return normalized_text == normalized_text[::-1]", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [["never odd or even"]]}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n    '''\n    Write a function that takes an integer a and returns True \n    if this integer is a cube of some integer number.\n    Note: you may assume the input is always valid.\n    \n    Examples:\n    iscube(1) ==> True\n    iscube(2) ==> False\n    iscube(-1) ==> True\n    iscube(64) ==> True\n    iscube(0) ==> True\n    iscube(180) ==> False\n    '''\n    # Calculate the cube root of the absolute value of a\n    cube_root = round(abs(a) ** (1/3))\n    \n    # Check if the cube of the rounded cube root equals the absolute value of a\n    return cube_root ** 3 == abs(a)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n    \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n    \n    Example\n        For N = 1000, the sum of digits will be 1 the output should be \"1\".\n        For N = 150, the sum of digits will be 6 the output should be \"110\".\n        For N = 147, the sum of digits will be 12 the output should be \"1100\".\n    \n    Variables:\n        @N integer\n             Constraints: 0 \u2264 N \u2264 10000.\n    Output:\n         a string of binary number\n    \"\"\"\n    # Calculate the sum of the digits of N\n    digit_sum = sum(int(digit) for digit in str(N))\n    \n    # Convert the sum to binary and remove the '0b' prefix\n    binary_sum = bin(digit_sum)[2:]\n    \n    return binary_sum", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n    '''\n    Given list of integers, return list in strange order.\n    Strange sorting, is when you start with the minimum value,\n    then maximum of the remaining integers, then minimum and so on.\n\n    Examples:\n    strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n    strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n    strange_sort_list([]) == []\n    '''\n    if not lst:\n        return []\n\n    sorted_lst = sorted(lst)\n    result = []\n    left, right = 0, len(sorted_lst) - 1\n\n    while left <= right:\n        if left == right:\n            result.append(sorted_lst[left])\n        else:\n            result.append(sorted_lst[left])\n            result.append(sorted_lst[right])\n        left += 1\n        right -= 1\n\n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n    \"\"\" Return length of given string\n    >>> strlen('')\n    0\n    >>> strlen('abc')\n    3\n    \"\"\"\n    return len(string)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n    \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n    >>> largest_divisor(15)\n    5\n    >>> largest_divisor(28)\n    14\n    >>> largest_divisor(1)\n    0\n    >>> largest_divisor(10)\n    5\n    \"\"\"\n    if n <= 1:\n        return 0  # No divisors for 1 or less\n    for i in range(n // 2, 0, -1):\n        if n % i == 0:\n            return i", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "import math\ndef triangle_area(a, b, c):\n    '''\n    Given the lengths of the three sides of a triangle. Return the area of\n    the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n    Otherwise return -1.\n    Three sides make a valid triangle when the sum of any two sides is greater \n    than the third side.\n    \n    Example:\n    triangle_area(3, 4, 5) == 6.00\n    triangle_area(1, 2, 10) == -1\n    '''\n    # Check for valid triangle\n    if a + b > c and a + c > b and b + c > a:\n        # Calculate the semi-perimeter\n        s = (a + b + c) / 2\n        # Calculate the area using Heron's formula\n        area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n        return round(area, 2)\n    else:\n        return -1", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n    \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n    strings of the same length. Return None in case the input list is empty.\n    \n    >>> longest([])\n    >>> None\n    >>> longest(['a', 'b', 'c'])\n    'a'\n    >>> longest(['a', 'bb', 'ccc'])\n    'ccc'\n    \"\"\"\n    if not strings:\n        return None\n    \n    longest_string = strings[0]\n    \n    for string in strings:\n        if len(string) > len(longest_string):\n            longest_string = string\n            \n    return longest_string", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n    \"\"\"\n    Given a positive integer n, return the count of the numbers of n-digit\n    positive integers that start or end with 1.\n    \"\"\"\n    if n < 1:\n        return 0\n\n    # Total n-digit numbers\n    total_n_digit_numbers = 9 * (10 ** (n - 1))\n\n    # Count of n-digit numbers that start with 1\n    start_with_1 = 10 ** (n - 1)\n\n    # Count of n-digit numbers that end with 1\n    end_with_1 = total_n_digit_numbers // 10\n\n    # Count of n-digit numbers that start and end with 1\n    start_and_end_with_1 = 10 ** (n - 2) if n > 1 else 0\n\n    # Total count of numbers that start or end with 1\n    count = start_with_1 + end_with_1 - start_and_end_with_1\n\n    return count", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[1000000]]}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n    \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n    Args:\n        lst (list): A non-empty list of integers.\n\n    Returns:\n        int: The sum of even elements at odd indices.\n\n    Examples:\n        add([4, 2, 6, 7]) ==> 2 \n    \"\"\"\n    return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int) -> int:\n    \"\"\"Return 2^n modulo p (be aware of numerics).\n    \n    >>> modp(3, 5)\n    3\n    >>> modp(1101, 101)\n    2\n    >>> modp(0, 101)\n    1\n    >>> modp(3, 11)\n    8\n    >>> modp(100, 101)\n    1\n    \"\"\"\n    result = 1\n    base = 2 % p  # Start with 2 mod p\n    while n > 0:\n        if n % 2 == 1:  # If n is odd, multiply the base with the result\n            result = (result * base) % p\n        base = (base * base) % p  # Square the base\n        n //= 2  # Divide n by 2\n    return result", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[0, 1]]}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def is_prime(n):\n    \"\"\"Helper function to check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef prime_length(string):\n    \"\"\"Check if the length of the string is a prime number.\"\"\"\n    length = len(string)\n    return is_prime(length)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n    \"\"\"Returns True if x is a simple power of n, otherwise False.\n    \n    A number x is a simple power of n if there exists an integer k such that n**k = x.\n    \n    Args:\n        x (int): The number to check.\n        n (int): The base number.\n    \n    Returns:\n        bool: True if x is a simple power of n, False otherwise.\n    \"\"\"\n    if n <= 1:\n        return x == 1  # 1 is a power of any number, and no other number can be a power of 1 or 0.\n    \n    power = 1\n    while True:\n        result = n ** power\n        if result == x:\n            return True\n        elif result > x:\n            return False\n        power += 1", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[1, 12]], "plus_fail_tests": [[1, 4]]}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n    \"\"\"\n    triples_sum_to_zero takes a list of integers as an input.\n    it returns True if there are three distinct elements in the list that\n    sum to zero, and False otherwise.\n\n    >>> triples_sum_to_zero([1, 3, 5, 0])\n    False\n    >>> triples_sum_to_zero([1, 3, -2, 1])\n    True\n    >>> triples_sum_to_zero([1, 2, 3, 7])\n    False\n    >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n    True\n    >>> triples_sum_to_zero([1])\n    False\n    \"\"\"\n    n = len(l)\n    # Sort the list to use the two-pointer technique\n    l.sort()\n    \n    for i in range(n - 2):\n        # Avoid duplicates for the first element\n        if i > 0 and l[i] == l[i - 1]:\n            continue\n        \n        left, right = i + 1, n - 1\n        while left < right:\n            current_sum = l[i] + l[left] + l[right]\n            if current_sum == 0:\n                return True\n            elif current_sum < 0:\n                left += 1\n            else:\n                right -= 1\n    \n    return False", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n    \"\"\"Counts the number of prime hexadecimal digits in the given hexadecimal string.\"\"\"\n    # Define the set of prime hexadecimal digits\n    prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n    \n    # Count the number of prime hexadecimal digits in the input string\n    count = sum(1 for digit in num if digit in prime_hex_digits)\n    \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n    \"\"\"Return median of elements in the list l.\n    \n    >>> median([3, 1, 2, 4, 5])\n    3\n    >>> median([-10, 4, 6, 1000, 10, 20])\n    15.0\n    \"\"\"\n    # Sort the list\n    sorted_list = sorted(l)\n    n = len(sorted_list)\n    \n    # Calculate median\n    if n % 2 == 1:  # Odd number of elements\n        return sorted_list[n // 2]\n    else:  # Even number of elements\n        mid1 = sorted_list[n // 2 - 1]\n        mid2 = sorted_list[n // 2]\n        return (mid1 + mid2) / 2", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n    \"\"\" Return a greatest common divisor of two integers a and b\n    >>> greatest_common_divisor(3, 5)\n    1\n    >>> greatest_common_divisor(25, 15)\n    5\n    \"\"\"\n    while b:\n        a, b = b, a % b\n    return abs(a)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n    \"\"\" Return list of all prefixes from shortest to longest of the input string\n    >>> all_prefixes('abc')\n    ['a', 'ab', 'abc']\n    \"\"\"\n    return [string[:i] for i in range(1, len(string) + 1)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n    \"\"\" Filter given list of any python values only for integers\n    >>> filter_integers(['a', 3.14, 5])\n    [5]\n    >>> filter_integers([1, 2, 3, 'abc', {}, []])\n    [1, 2, 3]\n    \"\"\"\n    return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[[true, false, null, 0, -10, "test", [], {}, 3.14]]]}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n    \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n    Each of the factors should be listed number of times corresponding to how many times it appears in factorization.\n    Input number should be equal to the product of all factors\n    >>> factorize(8)\n    [2, 2, 2]\n    >>> factorize(25)\n    [5, 5]\n    >>> factorize(70)\n    [2, 5, 7]\n    \"\"\"\n    factors = []\n    # Check for number of 2s that divide n\n    while n % 2 == 0:\n        factors.append(2)\n        n //= 2\n    \n    # n must be odd at this point, so we can skip even numbers\n    for i in range(3, int(n**0.5) + 1, 2):\n        # While i divides n, append i and divide n\n        while n % i == 0:\n            factors.append(i)\n            n //= i\n    \n    # This condition is to check if n is a prime number greater than 2\n    if n > 2:\n        factors.append(n)\n    \n    return factors", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str) -> str:\n    \"\"\"\n    Takes as input a string encoded with the encode_cyclic function.\n    Returns the decoded string.\n    \"\"\"\n    # Split string into groups of length 3\n    groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n    # Reverse the cycling of elements in each group unless the group has fewer than 3 elements\n    groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n    return \"\".join(groups)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n    \"\"\"Return true if a given number is prime, and false otherwise.\n    >>> is_prime(6)\n    False\n    >>> is_prime(101)\n    True\n    >>> is_prime(11)\n    True\n    >>> is_prime(13441)\n    True\n    >>> is_prime(61)\n    True\n    >>> is_prime(4)\n    False\n    >>> is_prime(1)\n    False\n    \"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n    \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n    and return the result as a string.\n    If shift > number of digits, return digits reversed.\n    \n    >>> circular_shift(12, 1)\n    '21'\n    >>> circular_shift(12, 2)\n    '12'\n    >>> circular_shift(12345, 1)\n    '51234'\n    >>> circular_shift(12345, 5)\n    '54321'\n    >>> circular_shift(12345, 6)\n    '54321'\n    \"\"\"\n    # Convert the integer to a string to manipulate its digits\n    str_x = str(x)\n    num_digits = len(str_x)\n    \n    # If shift is greater than the number of digits, reverse the string\n    if shift >= num_digits:\n        return str_x[::-1]\n    \n    # Calculate the effective shift\n    effective_shift = shift % num_digits\n    \n    # Perform the circular shift\n    shifted_str = str_x[-effective_shift:] + str_x[:-effective_shift]\n    \n    return shifted_str", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[12, 2]], "plus_fail_tests": [[987654321, 9]]}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n    \"\"\"\n    You'll be given a string of words, and your task is to count the number\n    of boredoms. A boredom is a sentence that starts with the word \"I\".\n    Sentences are delimited by '.', '?' or '!'.\n   \n    For example:\n    >>> is_bored(\"Hello world\")\n    0\n    >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n    1\n    >>> is_bored(\"I am happy! Are you? I will go now.\")\n    2\n    >>> is_bored(\"What a day. I can't believe it! I am so excited.\")\n    2\n    \"\"\"\n    # Split the string into sentences using the delimiters\n    sentences = []\n    current_sentence = []\n    for char in S:\n        if char in '.!?':\n            if current_sentence:\n                sentences.append(''.join(current_sentence).strip())\n                current_sentence = []\n        else:\n            current_sentence.append(char)\n    if current_sentence:  # Add the last sentence if it exists\n        sentences.append(''.join(current_sentence).strip())\n    \n    # Count the sentences that start with \"I\"\n    boredom_count = sum(1 for sentence in sentences if sentence.startswith('I'))\n    \n    return boredom_count", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["Is the sky blue?"]], "plus_fail_tests": [["In the morning, I like to have a cup of coffee to start my day off right. How about you?"]]}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n    \"\"\" \n    xs represent coefficients of a polynomial.\n    xs[0] + xs[1] * x + xs[2] * x^2 + ....\n    Return derivative of this polynomial in the same form.\n    \n    >>> derivative([3, 1, 2, 4, 5])\n    [1, 4, 12, 20]\n    >>> derivative([1, 2, 3])\n    [2, 6]\n    \"\"\"\n    # The derivative of a polynomial is calculated by multiplying each coefficient\n    # by its corresponding power and reducing the power by one.\n    return [i * coeff for i, coeff in enumerate(xs[1:], start=1)]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str) -> bool:\n    \"\"\"\n    Check if two words have the same characters.\n    \n    Two words have the same characters if they contain the same unique characters,\n    regardless of the number of times each character appears.\n\n    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n    True\n    >>> same_chars('abcd', 'dddddddabc')\n    True\n    >>> same_chars('dddddddabc', 'abcd')\n    True\n    >>> same_chars('eabcd', 'dddddddabc')\n    False\n    >>> same_chars('abcd', 'dddddddabce')\n    False\n    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n    False\n    \"\"\"\n    return set(s0) == set(s1)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def is_prime(num):\n    \"\"\"Check if a number is prime.\"\"\"\n    if num <= 1:\n        return False\n    for i in range(2, int(num**0.5) + 1):\n        if num % i == 0:\n            return False\n    return True\ndef count_up_to(n):\n    \"\"\"Return an array of the first n integers that are prime numbers and less than n.\"\"\"\n    primes = []\n    for i in range(2, n):\n        if is_prime(i):\n            primes.append(i)\n    return primes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n    \"\"\"\n    Given a string s, count the number of uppercase vowels in even indices.\n    \n    For example:\n    count_upper('aBCdEf') returns 1\n    count_upper('abcdefg') returns 0\n    count_upper('dBBE') returns 0\n    \"\"\"\n    uppercase_vowels = {'A', 'E', 'I', 'O', 'U'}\n    count = 0\n    \n    for i in range(0, len(s), 2):  # Iterate over even indices\n        if s[i] in uppercase_vowels:\n            count += 1\n            \n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int) -> int:\n    \"\"\"Add two numbers x and y.\n    \n    >>> add(2, 3)\n    5\n    >>> add(5, 7)\n    12\n    \"\"\"\n    return x + y", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int) -> int:\n    \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n    \n    >>> fizz_buzz(50)\n    0\n    >>> fizz_buzz(78)\n    2\n    >>> fizz_buzz(79)\n    3\n    \"\"\"\n    count_of_sevens = 0\n    \n    for i in range(n):\n        if i % 11 == 0 or i % 13 == 0:\n            count_of_sevens += str(i).count('7')\n    \n    return count_of_sevens", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n    \"\"\"Return only positive numbers in the list.\n    \n    >>> get_positive([-1, 2, -4, 5, 6])\n    [2, 5, 6]\n    >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n    [5, 3, 2, 3, 9, 123, 1]\n    \"\"\"\n    return [x for x in l if x > 0]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n    \"\"\"This function takes a list l and returns a list l' such that\n    l' is identical to l in the odd indices, while its values at the even indices are equal\n    to the values of the even indices of l, but sorted.\n    \n    >>> sort_even([1, 2, 3])\n    [1, 2, 3]\n    >>> sort_even([5, 6, 3, 4])\n    [3, 6, 5, 4]\n    \"\"\"\n    # Extract even indexed elements\n    even_indices = [l[i] for i in range(0, len(l), 2)]\n    \n    # Sort the even indexed elements\n    even_indices.sort()\n    \n    # Create a new list to hold the result\n    result = l[:]  # Start with a copy of the original list\n    \n    # Place the sorted even indexed elements back into their positions\n    for i, value in enumerate(even_indices):\n        result[i * 2] = value\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n    '''\n    Create a function that takes a value (string) representing a number\n    and returns the closest integer to it. If the number is equidistant\n    from two integers, round it away from zero.\n\n    Examples\n    >>> closest_integer(\"10\")\n    10\n    >>> closest_integer(\"15.3\")\n    15\n    >>> closest_integer(\"14.5\")\n    15\n    >>> closest_integer(\"-14.5\")\n    -15\n    >>> closest_integer(\"0.5\")\n    1\n    >>> closest_integer(\"-0.5\")\n    -1\n    '''\n    # Convert the string to a float\n    num = float(value)\n    \n    # Get the floor and ceiling of the number\n    lower = int(num // 1)\n    upper = lower + 1\n    \n    # Check if the number is equidistant from lower and upper\n    if num - lower == 0.5:\n        return upper  # Round away from zero\n    elif lower - num == 0.5:\n        return lower  # Round away from zero\n    else:\n        return round(num)  # Regular rounding", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [["-15.5"]], "plus_fail_tests": [["-6.5"]]}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int) -> bool:\n    \"\"\"Return True if all numbers in the list l are below threshold t.\n    \n    >>> below_threshold([1, 2, 4, 10], 100)\n    True\n    >>> below_threshold([1, 20, 4, 10], 5)\n    False\n    \"\"\"\n    return all(x < t for x in l)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int) -> int:\n    \"\"\"Return n-th Fibonacci number.\n    \n    The Fibonacci sequence is defined as follows:\n    fib(0) = 0, fib(1) = 1, and fib(n) = fib(n-1) + fib(n-2) for n > 1.\n    \n    >>> fib(10)\n    55\n    >>> fib(1)\n    1\n    >>> fib(8)\n    21\n    \"\"\"\n    if n < 0:\n        raise ValueError(\"Input should be a non-negative integer.\")\n    elif n == 0:\n        return 0\n    elif n == 1:\n        return 1\n    else:\n        a, b = 0, 1\n        for _ in range(2, n + 1):\n            a, b = b, a + b\n        return b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int) -> int:\n    \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n    fibfib(0) == 0\n    fibfib(1) == 0\n    fibfib(2) == 1\n    fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n    \n    Args:\n        n (int): The index of the FibFib number to compute.\n    \n    Returns:\n        int: The n-th FibFib number.\n    \n    Examples:\n    >>> fibfib(1)\n    0\n    >>> fibfib(5)\n    4\n    >>> fibfib(8)\n    24\n    \"\"\"\n    if n == 0:\n        return 0\n    elif n == 1:\n        return 0\n    elif n == 2:\n        return 1\n    \n    # Initialize the first three FibFib numbers\n    fibfib_numbers = [0, 0, 1]\n    \n    # Compute FibFib numbers iteratively\n    for i in range(3, n + 1):\n        next_fibfib = fibfib_numbers[i - 1] + fibfib_numbers[i - 2] + fibfib_numbers[i - 3]\n        fibfib_numbers.append(next_fibfib)\n    \n    return fibfib_numbers[n]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num: int) -> bool:\n    \"\"\"Check if a number is prime.\"\"\"\n    if num <= 1:\n        return False\n    if num <= 3:\n        return True\n    if num % 2 == 0 or num % 3 == 0:\n        return False\n    i = 5\n    while i * i <= num:\n        if num % i == 0 or num % (i + 2) == 0:\n            return False\n        i += 6\n    return True\ndef fibonacci(n: int) -> int:\n    \"\"\"Return the n-th Fibonacci number.\"\"\"\n    a, b = 0, 1\n    for _ in range(n):\n        a, b = b, a + b\n    return a\ndef prime_fib(n: int) -> int:\n    \"\"\"\n    prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n    >>> prime_fib(1)\n    2\n    >>> prime_fib(2)\n    3\n    >>> prime_fib(3)\n    5\n    >>> prime_fib(4)\n    13\n    >>> prime_fib(5)\n    89\n    \"\"\"\n    count = 0\n    i = 0\n    while True:\n        fib_num = fibonacci(i)\n        if is_prime(fib_num):\n            count += 1\n            if count == n:\n                return fib_num\n        i += 1", "base_status": "pass", "plus_status": "fail", "base_fail_tests": [], "plus_fail_tests": [[12]]}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n    \"\"\"Complete the function that takes two integers and returns \n    the product of their unit digits.\n    Assume the input is always valid.\n    Examples:\n    multiply(148, 412) should return 16.\n    multiply(19, 28) should return 72.\n    multiply(2020, 1851) should return 0.\n    multiply(14,-15) should return 20.\n    \"\"\"\n    # Get the unit digit of the first number\n    unit_digit_a = abs(a) % 10\n    # Get the unit digit of the second number\n    unit_digit_b = abs(b) % 10\n    # Return the product of the unit digits\n    return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n    \"\"\"\n    You are given a list of integers.\n    Write a function next_smallest() that returns the 2nd smallest element of the list.\n    Return None if there is no such element.\n    \n    next_smallest([1, 2, 3, 4, 5]) == 2\n    next_smallest([5, 1, 4, 3, 2]) == 2\n    next_smallest([]) == None\n    next_smallest([1, 1]) == None\n    \"\"\"\n    # Remove duplicates by converting the list to a set\n    unique_elements = set(lst)\n    \n    # If there are less than 2 unique elements, return None\n    if len(unique_elements) < 2:\n        return None\n    \n    # Sort the unique elements\n    sorted_elements = sorted(unique_elements)\n    \n    # Return the second smallest element\n    return sorted_elements[1]", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n    \"\"\"Write a function vowels_count which takes a string representing\n    a word as input and returns the number of vowels in the string.\n    Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n    vowel, but only when it is at the end of the given word.\n\n    Example:\n    >>> vowels_count(\"abcde\")\n    2\n    >>> vowels_count(\"ACEDY\")\n    3\n    \"\"\"\n    vowels = 'aeiou'\n    count = 0\n    s = s.lower()  # Convert to lowercase to handle case insensitivity\n\n    for i in range(len(s)):\n        if s[i] in vowels:\n            count += 1\n        elif s[i] == 'y' and i == len(s) - 1:  # Check if 'y' is at the end\n            count += 1\n\n    return count", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef words_in_sentence(sentence):\n    \"\"\"\n    You are given a string representing a sentence,\n    the sentence contains some words separated by a space,\n    and you have to return a string that contains the words from the original sentence,\n    whose lengths are prime numbers,\n    the order of the words in the new string should be the same as the original one.\n\n    Example 1:\n        Input: sentence = \"This is a test\"\n        Output: \"is\"\n\n    Example 2:\n        Input: sentence = \"lets go for swimming\"\n        Output: \"go for\"\n\n    Constraints:\n        * 1 <= len(sentence) <= 100\n        * sentence contains only letters\n    \"\"\"\n    words = sentence.split()\n    prime_length_words = [word for word in words if is_prime(len(word))]\n    return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n    \"\"\"Simplifies the expression x * n and checks if the result is a whole number.\n    \n    Args:\n        x (str): A string representation of a fraction in the format 'numerator/denominator'.\n        n (str): A string representation of a fraction in the format 'numerator/denominator'.\n    \n    Returns:\n        bool: True if x * n evaluates to a whole number, False otherwise.\n    \"\"\"\n    # Split the fractions into numerator and denominator\n    x_numerator, x_denominator = map(int, x.split('/'))\n    n_numerator, n_denominator = map(int, n.split('/'))\n    \n    # Calculate the product of the fractions\n    # x * n = (x_numerator / x_denominator) * (n_numerator / n_denominator)\n    # This simplifies to (x_numerator * n_numerator) / (x_denominator * n_denominator)\n    numerator_product = x_numerator * n_numerator\n    denominator_product = x_denominator * n_denominator\n    \n    # Check if the result is a whole number\n    return numerator_product % denominator_product == 0", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n    \"\"\"In this problem, you will implement a function that takes two lists of numbers,\n    and determines whether it is possible to perform an exchange of elements\n    between them to make lst1 a list of only even numbers.\n    There is no limit on the number of exchanged elements between lst1 and lst2.\n    If it is possible to exchange elements between the lst1 and lst2 to make\n    all the elements of lst1 to be even, return \"YES\".\n    Otherwise, return \"NO\".\n    For example:\n    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"YES\"\n    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n    It is assumed that the input lists will be non-empty.\n    \"\"\"\n    \n    # Check if all elements in lst1 are even\n    if all(x % 2 == 0 for x in lst1):\n        return \"YES\"\n    \n    # Count the number of odd elements in lst1\n    odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n    \n    # Count the number of even elements in lst2\n    even_count_lst2 = sum(1 for x in lst2 if x % 2 == 0)\n    \n    # If there are enough even numbers in lst2 to replace all odd numbers in lst1\n    if odd_count_lst1 <= even_count_lst2:\n        return \"YES\"\n    \n    return \"NO\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n    \"\"\"\n    You are given an array arr of integers and you need to return\n    sum of magnitudes of integers multiplied by product of all signs\n    of each number in the array, represented by 1, -1 or 0.\n    Note: return None for empty arr.\n\n    Example:\n    >>> prod_signs([1, 2, 2, -4]) == -9\n    >>> prod_signs([0, 1]) == 0\n    >>> prod_signs([]) == None\n    \"\"\"\n    if not arr:\n        return None\n\n    product_of_signs = 1\n    sum_of_magnitudes = 0\n\n    for num in arr:\n        if num > 0:\n            sum_of_magnitudes += num\n        elif num < 0:\n            sum_of_magnitudes += -num\n            product_of_signs *= -1\n        else:  # num == 0\n            return 0  # If there's a zero, the product of signs is zero\n\n    return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n    \"\"\" Return a string containing space-delimited numbers starting from 0 up to n inclusive.\n    \n    >>> string_sequence(0)\n    '0'\n    >>> string_sequence(5)\n    '0 1 2 3 4 5'\n    \"\"\"\n    return ' '.join(str(i) for i in range(n + 1))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n    \"\"\"Given a string s and a natural number n, returns a list of all words from \n    string s that contain exactly n consonants, in the order they appear in the string s.\n    \n    Args:\n    s (str): The input string containing words.\n    n (int): The number of consonants to filter words by.\n    \n    Returns:\n    list: A list of words containing exactly n consonants.\n    \"\"\"\n    if not s:\n        return []\n\n    # Define a set of consonants\n    consonants = set(\"bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ\")\n    \n    # Split the string into words\n    words = s.split()\n    \n    # Function to count consonants in a word\n    def count_consonants(word):\n        return sum(1 for char in word if char in consonants)\n    \n    # Filter words that have exactly n consonants\n    result = [word for word in words if count_consonants(word) == n]\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n    \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n    \n    Examples\n    solution([5, 8, 7, 1]) ==> 12\n    solution([3, 3, 3, 3, 3]) ==> 9\n    solution([30, 13, 24, 321]) ==> 0\n    \"\"\"\n    return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n    '''\n    You are given a list of two strings, both strings consist of open\n    parentheses '(' or close parentheses ')' only.\n    Your job is to check if it is possible to concatenate the two strings in\n    some order, that the resulting string will be good.\n    A string S is considered to be good if and only if all parentheses in S\n    are balanced. For example: the string '(())()' is good, while the string\n    '())' is not.\n    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n    Examples:\n    match_parens(['()(', ')']) == 'Yes'\n    match_parens([')', ')']) == 'No'\n    '''\n\n    def is_good(s):\n        balance = 0\n        for char in s:\n            if char == '(':\n                balance += 1\n            else:  # char == ')'\n                balance -= 1\n            if balance < 0:  # More closing than opening\n                return False\n        return balance == 0  # Must be balanced at the end\n\n    # Check both concatenation orders\n    return 'Yes' if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]) else 'No'", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n    '''\n    Given a list of numbers, return whether or not they are sorted\n    in ascending order. If list has more than 1 duplicate of the same\n    number, return False. Assume no negative numbers and only integers.\n\n    Examples\n    is_sorted([5]) \u279e True\n    is_sorted([1, 2, 3, 4, 5]) \u279e True\n    is_sorted([1, 3, 2, 4, 5]) \u279e False\n    is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n    is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n    is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n    is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n    is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n    '''\n    if not lst:  # An empty list is considered sorted\n        return True\n    \n    seen = set()\n    last = None\n    \n    for num in lst:\n        if num in seen:\n            return False  # Found a duplicate\n        seen.add(num)\n        \n        if last is not None and num < last:\n            return False  # Not sorted\n        last = num\n    \n    return True", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[1, 2, 2, 3, 3, 4]]], "plus_fail_tests": [[[1, 1, 2, 2, 3, 3, 4]]]}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n    \"\"\"\n    Write a function which sorts the given list of integers\n    in ascending order according to the sum of their digits.\n    Note: if there are several items with similar sum of their digits,\n    order them based on their index in original list.\n\n    For example:\n    >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n    >>> order_by_points([]) == []\n    \"\"\"\n    \n    def digit_sum(n):\n        \"\"\"Calculate the sum of the digits of a number.\"\"\"\n        return sum(int(digit) for digit in str(abs(n)))\n\n    # Sort the list based on the sum of digits and original index\n    return sorted(nums, key=lambda x: (digit_sum(x), nums.index(x)))", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": [[[-5, -12, 9, 15]]]}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n    \"\"\"\n    This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n    multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n    change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n    \n    Examples:\n    For lst = [1,2,3] the output should be 6\n    For lst = []  the output should be 0\n    For lst = [-1,-5,2,-1,-5]  the output should be -126\n    \"\"\"\n    total = 0\n    for index, value in enumerate(lst):\n        if index % 3 == 0:\n            total += value ** 2  # Square if index is a multiple of 3\n        elif index % 4 == 0:\n            total += value ** 3  # Cube if index is a multiple of 4 and not a multiple of 3\n        else:\n            total += value  # Leave unchanged if not a multiple of 3 or 4\n    return total", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n    \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n    two consonants from the right side of the word (case sensitive).\n    \n    Vowels in the beginning and ending don't count. Return empty string if you didn't\n    find any vowel that meets the above condition. \n\n    You may assume that the given string contains English letters only.\n\n    Example:\n    get_closest_vowel(\"yogurt\") ==> \"u\"\n    get_closest_vowel(\"FULL\") ==> \"U\"\n    get_closest_vowel(\"quick\") ==> \"\"\n    get_closest_vowel(\"ab\") ==> \"\"\n    \"\"\"\n    vowels = \"aeiouAEIOU\"\n    n = len(word)\n\n    # Start from the end of the word\n    for i in range(n - 2, 0, -1):  # Start from the second last character\n        if word[i] in vowels:  # Check if the character is a vowel\n            # Check if the characters before and after are consonants\n            if word[i - 1].isalpha() and word[i + 1].isalpha() and \\\n               word[i - 1] not in vowels and word[i + 1] not in vowels:\n                return word[i]  # Return the vowel if conditions are met\n\n    return \"\"  # Return empty string if no vowel is found", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef intersection(interval1, interval2):\n    \"\"\"Determine if the length of the intersection of two intervals is a prime number.\"\"\"\n    start1, end1 = interval1\n    start2, end2 = interval2\n    \n    # Find the intersection\n    start_intersection = max(start1, start2)\n    end_intersection = min(end1, end2)\n    \n    # Check if there is an intersection\n    if start_intersection > end_intersection:\n        return \"NO\"\n    \n    # Calculate the length of the intersection\n    length_of_intersection = end_intersection - start_intersection\n    \n    # Check if the length is a prime number\n    if is_prime(length_of_intersection):\n        return \"YES\"\n    else:\n        return \"NO\"", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n    \"\"\"\n    Given an array arr of integers and a positive integer k, return a sorted list \n    of length k with the maximum k numbers in arr.\n\n    Example 1:\n\n        Input: arr = [-3, -4, 5], k = 3\n        Output: [-4, -3, 5]\n\n    Example 2:\n\n        Input: arr = [4, -4, 4], k = 2\n        Output: [4, 4]\n\n    Example 3:\n\n        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n        Output: [2]\n\n    Note:\n        1. The length of the array will be in the range of [1, 1000].\n        2. The elements in the array will be in the range of [-1000, 1000].\n        3. 0 <= k <= len(arr)\n    \"\"\"\n    # Sort the array in descending order\n    sorted_arr = sorted(arr, reverse=True)\n    # Get the top k elements\n    top_k = sorted_arr[:k]\n    # Sort the result in ascending order before returning\n    return sorted(top_k)", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n    \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n    of the letter with the most repetition and containing the corresponding count.\n    If several letters have the same occurrence, return all of them.\n    \n    Example:\n    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n    histogram('a b b a') == {'a': 2, 'b': 2}\n    histogram('a b c a b') == {'a': 2, 'b': 2}\n    histogram('b b b b a') == {'b': 4}\n    histogram('') == {}\n    \"\"\"\n    if not test:\n        return {}\n\n    # Split the input string into a list of letters\n    letters = test.split()\n    \n    # Create a dictionary to count occurrences of each letter\n    count_dict = {}\n    for letter in letters:\n        if letter in count_dict:\n            count_dict[letter] += 1\n        else:\n            count_dict[letter] = 1\n\n    # Find the maximum count\n    max_count = max(count_dict.values())\n    \n    # Create a result dictionary for letters with the maximum count\n    result = {letter: count for letter, count in count_dict.items() if count == max_count}\n    \n    return result", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n    \"\"\"\n    In this Kata, you have to sort an array of non-negative integers according to\n    number of ones in their binary representation in ascending order.\n    For similar number of ones, sort based on decimal value.\n\n    It must be implemented like this:\n    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n    >>> sort_array([1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]\n    \"\"\"\n    # Sort the array using a custom key\n    return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "pass", "plus_status": "pass", "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n    from collections import deque\n\n    N = len(grid)\n    directions = [(0, 1), (1, 0), (0, -1), (-1, 0)]  # Right, Down, Left, Up\n    min_path = None\n\n    def dfs(x, y, path):\n        nonlocal min_path\n        if len(path) == k:\n            if min_path is None or path < min_path:\n                min_path = path[:]\n            return\n        \n        for dx, dy in directions:\n            nx, ny = x + dx, y + dy\n            if 0 <= nx < N and 0 <= ny < N:\n                path.append(grid[nx][ny])\n                dfs(nx, ny, path)\n                path.pop()\n\n    for i in range(N):\n        for j in range(N):\n            dfs(i, j, [grid[i][j]])\n\n    return min_path", "base_status": "fail", "plus_status": "fail", "base_fail_tests": [[[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12]], "plus_fail_tests": [[[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 15]]}]}}
\ No newline at end of file
diff --git a/cot_humaneval.py b/cot_humaneval.py
deleted file mode 100644
index 89608645f..000000000
--- a/cot_humaneval.py
+++ /dev/null
@@ -1,53 +0,0 @@
-from examples.ags.scripts.operator import Operator
-from examples.ags.scripts.graph import SolveGraph
-from examples.ags.benchmark.humaneval import humaneval_evaluation
-from examples.ags.scripts.operator_an import GenerateOp
-from metagpt.actions.action_node import ActionNode 
-from metagpt.configs.models_config import ModelsConfig
-from metagpt.llm import LLM
-from pydantic import BaseModel, Field
-
-HUMANEVAL_PROMPT_GPT = """
-{question}\nPlease provide a step-by-step explanation in text, followed by your Python function without any additional text or test cases. 
-"""
-
-class GenerateOp(BaseModel):
-    solution: str = Field(default="", description="Python Solution For This Question.")
-
-class CoTGenerate(Operator):
-    def __init__(self, llm: LLM, name: str = "Generate"):
-        super().__init__(name, llm)
-
-    async def __call__(self, problem, function_name, mode: str = None):
-        prompt = HUMANEVAL_PROMPT_GPT.format(question=problem)
-        fill_kwargs = {"context": prompt, "llm": self.llm, "function_name": function_name}
-        if mode:
-            fill_kwargs["mode"] = mode
-        node = await ActionNode.from_pydantic(GenerateOp).fill(**fill_kwargs)
-        response = node.instruct_content.model_dump()
-        return response
-
-class CoTSolveGraph(SolveGraph):
-    def __init__(self, name: str, llm_config, dataset: str):
-        super().__init__(name, llm_config, dataset)
-        self.cot_generate = CoTGenerate(self.llm)
-
-    async def __call__(self, problem, function_name):
-        solution = await self.cot_generate(problem, function_name, mode="code_fill")
-        return solution["solution"], self.llm.cost_manager.total_cost
-
-if __name__ == "__main__":
-    async def main():
-        # llm_config = ModelsConfig.default().get("gpt-4o-mini")
-        # llm_config = ModelsConfig.default().get("gpt-35-turbo-1106")
-        llm_config = ModelsConfig.default().get("deepseek-chat")
-        # llm_config = ModelsConfig.default().get("gpt-4o")
-        graph = CoTSolveGraph(name="CoT", llm_config=llm_config, dataset="HumanEval")
-        file_path = "examples/ags/data/baseline_data/human-eval.jsonl"
-        samples = 33 # 33/131  
-        path = "examples/ags/data/baselines/general/humaneval"
-        score = await humaneval_evaluation(graph, file_path, samples, path,test=True)
-        return score
-
-    import asyncio
-    asyncio.run(main())
diff --git a/examples/ags/scripts/optimized/Gsm8K/graphs/results.json b/examples/ags/scripts/optimized/Gsm8K/graphs/results.json
deleted file mode 100644
index 0637a088a..000000000
--- a/examples/ags/scripts/optimized/Gsm8K/graphs/results.json
+++ /dev/null
@@ -1 +0,0 @@
-[]
\ No newline at end of file
diff --git a/he_test.py b/he_test.py
deleted file mode 100644
index 93fa72c66..000000000
--- a/he_test.py
+++ /dev/null
@@ -1,52 +0,0 @@
-import asyncio
-
-from examples.ags.benchmark.humaneval import sample_generate, samples_generate
-
-asyncio.run(sample_generate("HumanEval/0", result_path="llm_based_1000.jsonl", mode="llm"))
-asyncio.run(samples_generate(mode="alpha_codium", result_path="alpha_based_1000.jsonl"))
-
-# asyncio.run(sample_generate('HumanEval/140',result_path="llm_based_1000.jsonl",mode="llm"))
-# asyncio.run(sample_generate('HumanEval/140',result_path="llm_based_1000.jsonl",mode="llm"))
-# asyncio.run(sample_generate('HumanEval/67',result_path="llm_based_1000.jsonl",mode="llm"))
-# asyncio.run(sample_generate('HumanEval/108',result_path="llm_based_1000.jsonl",mode="llm"))
-# asyncio.run(sample_generate('HumanEval/110',result_path="llm_based_1000.jsonl",mode="llm"))
-# asyncio.run(samples_generate(mode='alpha',result_path="alpha_based_108.jsonl"))
-# sort_json_by_key("alpha_based_108.jsonl", "alpha_based_108.jsonl")
-
-# 64 84 160 148 109
-# result_path = "ags_based_6.jsonl"
-# if automatic_evalplus(result_path):
-#     unpassed_exapmle = extract_failure_tests(result_path[:-6]+"_eval_results.json")
-#     print(unpassed_exapmle)
-
-# unpassed_exapmle = extract_failure_tests(file_path="2_eval_results.json")
-# print(unpassed_exapmle)
-
-# for example in failure_list:
-#     asyncio.run(sample_generate(example))
-
-# id_list = [87, 95, 107, 112, 127, 136, 148, 155]
-# id_list = [155]
-# cases_id = [f"HumanEval/{case_id}" for case_id in id_list]
-# cases = {case_id: get_human_eval_plus()[case_id]['prompt'] for case_id in cases_id}
-# async def main(cases):
-#     try:
-#         tasks = [llm_extract_test_case(case_id, case) for case_id, case in cases.items()]
-#         results = await asyncio.gather(*tasks)
-#     except:
-#         failed_tasks = [task_id for task_id in results if task_id is not None]
-#         print(failed_tasks)
-#     return results
-
-# asyncio.run(main(cases))
-
-# [72, 80, 82, 87, 90, 95, 107, 109, 112, 124, 126, 127, 128, 132, 134, 136, 137, 138, 148, 154, 155]
-
-# TODO 代码问题，改动了一个地方导致Solution 没有了
-# case_prompt= get_human_eval_plus()["HumanEval/140"]['prompt']
-# solver = HumanEvalGraph(name="solver", llm=LLM(), criteria='correctness, efficiency, readability', vote_count=1)
-# result = asyncio.run(solver.alpha_codium(problem_id="HumanEval/140", problem=case_prompt, ensemble_count=1))
-
-# 1. Public Test 数据集不对
-# 2. 修改两个Prompt的具体内容
-# 3. 尝试增加Test错误之后的修改能力
diff --git a/humaneval_analysis.ipynb b/humaneval_analysis.ipynb
deleted file mode 100644
index d2b1eec83..000000000
--- a/humaneval_analysis.ipynb
+++ /dev/null
@@ -1,3463 +0,0 @@
-{
- "cells": [
-  {
-   "cell_type": "code",
-   "execution_count": 23,
-   "metadata": {},
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "def check(candidate):\n",
-      "    assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.3) == True\n",
-      "    assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.05) == False\n",
-      "    assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.95) == True\n",
-      "    assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.8) == False\n",
-      "    assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.0], 0.1) == True\n",
-      "    assert candidate([1.1, 2.2, 3.1, 4.1, 5.1], 1.0) == True\n",
-      "    assert candidate([1.1, 2.2, 3.1, 4.1, 5.1], 0.5) == False\n",
-      "\n",
-      "def test_check():\n",
-      "    check(has_close_elements)\n",
-      "\n",
-      "test_check()\n",
-      "\n"
-     ]
-    }
-   ],
-   "source": [
-    "file_path = \"public_test_reflexion.jsonl\"\n",
-    "\n",
-    "import json\n",
-    "\n",
-    "with open(file_path, 'r') as file:\n",
-    "    for line in file:\n",
-    "        data = json.loads(line)\n",
-    "        break\n",
-    "\n",
-    "print(data['test'])\n",
-    "\n",
-    "# assert_code = tests_case[0]\n",
-    "# f\"\"\"\n",
-    "# def check(candidate):\n",
-    "#     {assert_code}\n",
-    "# \"\"\"\n",
-    "\n",
-    "\n",
-    "# f\"\"\"\n",
-    "# def test_check():\n",
-    "#     check({entry_point})\n",
-    "# test_check()\n",
-    "# \"\"\""
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 21,
-   "metadata": {},
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "find_zero\n",
-      "from typing import List\n",
-      "\n",
-      "\n",
-      "def has_close_elements(numbers: List[float], threshold: float) -> bool:\n",
-      "    \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n",
-      "    given threshold.\n",
-      "    >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n",
-      "    False\n",
-      "    >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n",
-      "    True\n",
-      "    \"\"\"\n",
-      "\n",
-      "from typing import List\n",
-      "\n",
-      "\n",
-      "def has_close_elements(numbers: List[float], threshold: float) -> bool:\n",
-      "    \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n",
-      "    given threshold.\n",
-      "    >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n",
-      "    False\n",
-      "    >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n",
-      "    True\n",
-      "    \"\"\"\n",
-      "\n",
-      "from typing import List\n",
-      "\n",
-      "\n",
-      "def separate_paren_groups(paren_string: str) -> List[str]:\n",
-      "    \"\"\" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to\n",
-      "    separate those group into separate strings and return the list of those.\n",
-      "    Separate groups are balanced (each open brace is properly closed) and not nested within each other\n",
-      "    Ignore any spaces in the input string.\n",
-      "    >>> separate_paren_groups('( ) (( )) (( )( ))')\n",
-      "    ['()', '(())', '(()())']\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def truncate_number(number: float) -> float:\n",
-      "    \"\"\" Given a positive floating point number, it can be decomposed into\n",
-      "    and integer part (largest integer smaller than given number) and decimals\n",
-      "    (leftover part always smaller than 1).\n",
-      "\n",
-      "    Return the decimal part of the number.\n",
-      "    >>> truncate_number(3.5)\n",
-      "    0.5\n",
-      "    \"\"\"\n",
-      "\n",
-      "from typing import List\n",
-      "\n",
-      "\n",
-      "def below_zero(operations: List[int]) -> bool:\n",
-      "    \"\"\" You're given a list of deposit and withdrawal operations on a bank account that starts with\n",
-      "    zero balance. Your task is to detect if at any point the balance of account fallls below zero, and\n",
-      "    at that point function should return True. Otherwise it should return False.\n",
-      "    >>> below_zero([1, 2, 3])\n",
-      "    False\n",
-      "    >>> below_zero([1, 2, -4, 5])\n",
-      "    True\n",
-      "    \"\"\"\n",
-      "\n",
-      "from typing import List\n",
-      "\n",
-      "\n",
-      "def mean_absolute_deviation(numbers: List[float]) -> float:\n",
-      "    \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n",
-      "    around the mean of this dataset.\n",
-      "    Mean Absolute Deviation is the average absolute difference between each\n",
-      "    element and a centerpoint (mean in this case):\n",
-      "    MAD = average | x - x_mean |\n",
-      "    >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n",
-      "    1.0\n",
-      "    \"\"\"\n",
-      "\n",
-      "from typing import List\n",
-      "\n",
-      "\n",
-      "def intersperse(numbers: List[int], delimeter: int) -> List[int]:\n",
-      "    \"\"\" Insert a number 'delimeter' between every two consecutive elements of input list `numbers'\n",
-      "    >>> intersperse([], 4)\n",
-      "    []\n",
-      "    >>> intersperse([1, 2, 3], 4)\n",
-      "    [1, 4, 2, 4, 3]\n",
-      "    \"\"\"\n",
-      "\n",
-      "from typing import List\n",
-      "\n",
-      "\n",
-      "def parse_nested_parens(paren_string: str) -> List[int]:\n",
-      "    \"\"\" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n",
-      "    For each of the group, output the deepest level of nesting of parentheses.\n",
-      "    E.g. (()()) has maximum two levels of nesting while ((())) has three.\n",
-      "\n",
-      "    >>> parse_nested_parens('(()()) ((())) () ((())()())')\n",
-      "    [2, 3, 1, 3]\n",
-      "    \"\"\"\n",
-      "\n",
-      "from typing import List\n",
-      "\n",
-      "\n",
-      "def filter_by_substring(strings: List[str], substring: str) -> List[str]:\n",
-      "    \"\"\" Filter an input list of strings only for ones that contain given substring\n",
-      "    >>> filter_by_substring([], 'a')\n",
-      "    []\n",
-      "    >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n",
-      "    ['abc', 'bacd', 'array']\n",
-      "    \"\"\"\n",
-      "\n",
-      "from typing import List, Tuple\n",
-      "\n",
-      "\n",
-      "def sum_product(numbers: List[int]) -> Tuple[int, int]:\n",
-      "    \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n",
-      "    Empty sum should be equal to 0 and empty product should be equal to 1.\n",
-      "    >>> sum_product([])\n",
-      "    (0, 1)\n",
-      "    >>> sum_product([1, 2, 3, 4])\n",
-      "    (10, 24)\n",
-      "    \"\"\"\n",
-      "\n",
-      "from typing import List, Tuple\n",
-      "\n",
-      "\n",
-      "def rolling_max(numbers: List[int]) -> List[int]:\n",
-      "    \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n",
-      "    in the sequence.\n",
-      "    >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n",
-      "    [1, 2, 3, 3, 3, 4, 4]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def is_palindrome(string: str) -> bool:\n",
-      "    \"\"\" Test if given string is a palindrome \"\"\"\n",
-      "    return string == string[::-1]\n",
-      "\n",
-      "\n",
-      "def make_palindrome(string: str) -> str:\n",
-      "    \"\"\" Find the shortest palindrome that begins with a supplied string.\n",
-      "    Algorithm idea is simple:\n",
-      "    - Find the longest postfix of supplied string that is a palindrome.\n",
-      "    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n",
-      "    >>> make_palindrome('')\n",
-      "    ''\n",
-      "    >>> make_palindrome('cat')\n",
-      "    'catac'\n",
-      "    >>> make_palindrome('cata')\n",
-      "    'catac'\n",
-      "    \"\"\"\n",
-      "\n",
-      "from typing import List\n",
-      "\n",
-      "\n",
-      "def string_xor(a: str, b: str) -> str:\n",
-      "    \"\"\" Input are two strings a and b consisting only of 1s and 0s.\n",
-      "    Perform binary XOR on these inputs and return result also as a string.\n",
-      "    >>> string_xor('010', '110')\n",
-      "    '100'\n",
-      "    \"\"\"\n",
-      "\n",
-      "from typing import List, Optional\n",
-      "\n",
-      "\n",
-      "def longest(strings: List[str]) -> Optional[str]:\n",
-      "    \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n",
-      "    strings of the same length. Return None in case the input list is empty.\n",
-      "    >>> longest([])\n",
-      "\n",
-      "    >>> longest(['a', 'b', 'c'])\n",
-      "    'a'\n",
-      "    >>> longest(['a', 'bb', 'ccc'])\n",
-      "    'ccc'\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def greatest_common_divisor(a: int, b: int) -> int:\n",
-      "    \"\"\" Return a greatest common divisor of two integers a and b\n",
-      "    >>> greatest_common_divisor(3, 5)\n",
-      "    1\n",
-      "    >>> greatest_common_divisor(25, 15)\n",
-      "    5\n",
-      "    \"\"\"\n",
-      "\n",
-      "from typing import List\n",
-      "\n",
-      "\n",
-      "def all_prefixes(string: str) -> List[str]:\n",
-      "    \"\"\" Return list of all prefixes from shortest to longest of the input string\n",
-      "    >>> all_prefixes('abc')\n",
-      "    ['a', 'ab', 'abc']\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def string_sequence(n: int) -> str:\n",
-      "    \"\"\" Return a string containing space-delimited numbers starting from 0 upto n inclusive.\n",
-      "    >>> string_sequence(0)\n",
-      "    '0'\n",
-      "    >>> string_sequence(5)\n",
-      "    '0 1 2 3 4 5'\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def count_distinct_characters(string: str) -> int:\n",
-      "    \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n",
-      "    >>> count_distinct_characters('xyzXYZ')\n",
-      "    3\n",
-      "    >>> count_distinct_characters('Jerry')\n",
-      "    4\n",
-      "    \"\"\"\n",
-      "\n",
-      "from typing import List\n",
-      "\n",
-      "\n",
-      "def parse_music(music_string: str) -> List[int]:\n",
-      "    \"\"\" Input to this function is a string representing musical notes in a special ASCII format.\n",
-      "    Your task is to parse this string and return list of integers corresponding to how many beats does each\n",
-      "    not last.\n",
-      "\n",
-      "    Here is a legend:\n",
-      "    'o' - whole note, lasts four beats\n",
-      "    'o|' - half note, lasts two beats\n",
-      "    '.|' - quater note, lasts one beat\n",
-      "\n",
-      "    >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n",
-      "    [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def how_many_times(string: str, substring: str) -> int:\n",
-      "    \"\"\" Find how many times a given substring can be found in the original string. Count overlaping cases.\n",
-      "    >>> how_many_times('', 'a')\n",
-      "    0\n",
-      "    >>> how_many_times('aaa', 'a')\n",
-      "    3\n",
-      "    >>> how_many_times('aaaa', 'aa')\n",
-      "    3\n",
-      "    \"\"\"\n",
-      "\n",
-      "from typing import List\n",
-      "\n",
-      "\n",
-      "def sort_numbers(numbers: str) -> str:\n",
-      "    \"\"\" Input is a space-delimited string of numberals from 'zero' to 'nine'.\n",
-      "    Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n",
-      "    Return the string with numbers sorted from smallest to largest\n",
-      "    >>> sort_numbers('three one five')\n",
-      "    'one three five'\n",
-      "    \"\"\"\n",
-      "\n",
-      "from typing import List, Tuple\n",
-      "\n",
-      "\n",
-      "def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n",
-      "    \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n",
-      "    other and return them in order (smaller number, larger number).\n",
-      "    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n",
-      "    (2.0, 2.2)\n",
-      "    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n",
-      "    (2.0, 2.0)\n",
-      "    \"\"\"\n",
-      "\n",
-      "from typing import List\n",
-      "\n",
-      "\n",
-      "def rescale_to_unit(numbers: List[float]) -> List[float]:\n",
-      "    \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n",
-      "    such that the smallest number will become 0 and the largest will become 1\n",
-      "    >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n",
-      "    [0.0, 0.25, 0.5, 0.75, 1.0]\n",
-      "    \"\"\"\n",
-      "\n",
-      "from typing import List, Any\n",
-      "\n",
-      "\n",
-      "def filter_integers(values: List[Any]) -> List[int]:\n",
-      "    \"\"\" Filter given list of any python values only for integers\n",
-      "    >>> filter_integers(['a', 3.14, 5])\n",
-      "    [5]\n",
-      "    >>> filter_integers([1, 2, 3, 'abc', {}, []])\n",
-      "    [1, 2, 3]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def strlen(string: str) -> int:\n",
-      "    \"\"\" Return length of given string\n",
-      "    >>> strlen('')\n",
-      "    0\n",
-      "    >>> strlen('abc')\n",
-      "    3\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def largest_divisor(n: int) -> int:\n",
-      "    \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n",
-      "    >>> largest_divisor(15)\n",
-      "    5\n",
-      "    \"\"\"\n",
-      "\n",
-      "from typing import List\n",
-      "\n",
-      "\n",
-      "def factorize(n: int) -> List[int]:\n",
-      "    \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n",
-      "    Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.\n",
-      "    Input number should be equal to the product of all factors\n",
-      "    >>> factorize(8)\n",
-      "    [2, 2, 2]\n",
-      "    >>> factorize(25)\n",
-      "    [5, 5]\n",
-      "    >>> factorize(70)\n",
-      "    [2, 5, 7]\n",
-      "    \"\"\"\n",
-      "\n",
-      "from typing import List\n",
-      "\n",
-      "\n",
-      "def remove_duplicates(numbers: List[int]) -> List[int]:\n",
-      "    \"\"\" From a list of integers, remove all elements that occur more than once.\n",
-      "    Keep order of elements left the same as in the input.\n",
-      "    >>> remove_duplicates([1, 2, 3, 2, 4])\n",
-      "    [1, 3, 4]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def flip_case(string: str) -> str:\n",
-      "    \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n",
-      "    >>> flip_case('Hello')\n",
-      "    'hELLO'\n",
-      "    \"\"\"\n",
-      "\n",
-      "from typing import List\n",
-      "\n",
-      "\n",
-      "def concatenate(strings: List[str]) -> str:\n",
-      "    \"\"\" Concatenate list of strings into a single string\n",
-      "    >>> concatenate([])\n",
-      "    ''\n",
-      "    >>> concatenate(['a', 'b', 'c'])\n",
-      "    'abc'\n",
-      "    \"\"\"\n",
-      "\n",
-      "from typing import List\n",
-      "\n",
-      "\n",
-      "def filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n",
-      "    \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n",
-      "    >>> filter_by_prefix([], 'a')\n",
-      "    []\n",
-      "    >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n",
-      "    ['abc', 'array']\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def get_positive(l: list):\n",
-      "    \"\"\"Return only positive numbers in the list.\n",
-      "    >>> get_positive([-1, 2, -4, 5, 6])\n",
-      "    [2, 5, 6]\n",
-      "    >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n",
-      "    [5, 3, 2, 3, 9, 123, 1]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def is_prime(n):\n",
-      "    \"\"\"Return true if a given number is prime, and false otherwise.\n",
-      "    >>> is_prime(6)\n",
-      "    False\n",
-      "    >>> is_prime(101)\n",
-      "    True\n",
-      "    >>> is_prime(11)\n",
-      "    True\n",
-      "    >>> is_prime(13441)\n",
-      "    True\n",
-      "    >>> is_prime(61)\n",
-      "    True\n",
-      "    >>> is_prime(4)\n",
-      "    False\n",
-      "    >>> is_prime(1)\n",
-      "    False\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def sort_third(l: list):\n",
-      "    \"\"\"This function takes a list l and returns a list l' such that\n",
-      "    l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n",
-      "    to the values of the corresponding indicies of l, but sorted.\n",
-      "    >>> sort_third([1, 2, 3])\n",
-      "    [1, 2, 3]\n",
-      "    >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n",
-      "    [2, 6, 3, 4, 8, 9, 5]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def unique(l: list):\n",
-      "    \"\"\"Return sorted unique elements in a list\n",
-      "    >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n",
-      "    [0, 2, 3, 5, 9, 123]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def max_element(l: list):\n",
-      "    \"\"\"Return maximum element in the list.\n",
-      "    >>> max_element([1, 2, 3])\n",
-      "    3\n",
-      "    >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n",
-      "    123\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def fizz_buzz(n: int):\n",
-      "    \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n",
-      "    >>> fizz_buzz(50)\n",
-      "    0\n",
-      "    >>> fizz_buzz(78)\n",
-      "    2\n",
-      "    >>> fizz_buzz(79)\n",
-      "    3\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def sort_even(l: list):\n",
-      "    \"\"\"This function takes a list l and returns a list l' such that\n",
-      "    l' is identical to l in the odd indicies, while its values at the even indicies are equal\n",
-      "    to the values of the even indicies of l, but sorted.\n",
-      "    >>> sort_even([1, 2, 3])\n",
-      "    [1, 2, 3]\n",
-      "    >>> sort_even([5, 6, 3, 4])\n",
-      "    [3, 6, 5, 4]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def prime_fib(n: int):\n",
-      "    \"\"\"\n",
-      "    prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n",
-      "    >>> prime_fib(1)\n",
-      "    2\n",
-      "    >>> prime_fib(2)\n",
-      "    3\n",
-      "    >>> prime_fib(3)\n",
-      "    5\n",
-      "    >>> prime_fib(4)\n",
-      "    13\n",
-      "    >>> prime_fib(5)\n",
-      "    89\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def triples_sum_to_zero(l: list):\n",
-      "    \"\"\"\n",
-      "    triples_sum_to_zero takes a list of integers as an input.\n",
-      "    it returns True if there are three distinct elements in the list that\n",
-      "    sum to zero, and False otherwise.\n",
-      "\n",
-      "    >>> triples_sum_to_zero([1, 3, 5, 0])\n",
-      "    False\n",
-      "    >>> triples_sum_to_zero([1, 3, -2, 1])\n",
-      "    True\n",
-      "    >>> triples_sum_to_zero([1, 2, 3, 7])\n",
-      "    False\n",
-      "    >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n",
-      "    True\n",
-      "    >>> triples_sum_to_zero([1])\n",
-      "    False\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def car_race_collision(n: int):\n",
-      "    \"\"\"\n",
-      "    Imagine a road that's a perfectly straight infinitely long line.\n",
-      "    n cars are driving left to right;  simultaneously, a different set of n cars\n",
-      "    are driving right to left.   The two sets of cars start out being very far from\n",
-      "    each other.  All cars move in the same speed.  Two cars are said to collide\n",
-      "    when a car that's moving left to right hits a car that's moving right to left.\n",
-      "    However, the cars are infinitely sturdy and strong; as a result, they continue moving\n",
-      "    in their trajectory as if they did not collide.\n",
-      "\n",
-      "    This function outputs the number of such collisions.\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def incr_list(l: list):\n",
-      "    \"\"\"Return list with elements incremented by 1.\n",
-      "    >>> incr_list([1, 2, 3])\n",
-      "    [2, 3, 4]\n",
-      "    >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n",
-      "    [6, 4, 6, 3, 4, 4, 10, 1, 124]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def pairs_sum_to_zero(l):\n",
-      "    \"\"\"\n",
-      "    pairs_sum_to_zero takes a list of integers as an input.\n",
-      "    it returns True if there are two distinct elements in the list that\n",
-      "    sum to zero, and False otherwise.\n",
-      "    >>> pairs_sum_to_zero([1, 3, 5, 0])\n",
-      "    False\n",
-      "    >>> pairs_sum_to_zero([1, 3, -2, 1])\n",
-      "    False\n",
-      "    >>> pairs_sum_to_zero([1, 2, 3, 7])\n",
-      "    False\n",
-      "    >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n",
-      "    True\n",
-      "    >>> pairs_sum_to_zero([1])\n",
-      "    False\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def change_base(x: int, base: int):\n",
-      "    \"\"\"Change numerical base of input number x to base.\n",
-      "    return string representation after the conversion.\n",
-      "    base numbers are less than 10.\n",
-      "    >>> change_base(8, 3)\n",
-      "    '22'\n",
-      "    >>> change_base(8, 2)\n",
-      "    '1000'\n",
-      "    >>> change_base(7, 2)\n",
-      "    '111'\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def triangle_area(a, h):\n",
-      "    \"\"\"Given length of a side and high return area for a triangle.\n",
-      "    >>> triangle_area(5, 3)\n",
-      "    7.5\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def fib4(n: int):\n",
-      "    \"\"\"The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:\n",
-      "    fib4(0) -> 0\n",
-      "    fib4(1) -> 0\n",
-      "    fib4(2) -> 2\n",
-      "    fib4(3) -> 0\n",
-      "    fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n",
-      "    Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.\n",
-      "    >>> fib4(5)\n",
-      "    4\n",
-      "    >>> fib4(6)\n",
-      "    8\n",
-      "    >>> fib4(7)\n",
-      "    14\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def median(l: list):\n",
-      "    \"\"\"Return median of elements in the list l.\n",
-      "    >>> median([3, 1, 2, 4, 5])\n",
-      "    3\n",
-      "    >>> median([-10, 4, 6, 1000, 10, 20])\n",
-      "    15.0\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def is_palindrome(text: str):\n",
-      "    \"\"\"\n",
-      "    Checks if given string is a palindrome\n",
-      "    >>> is_palindrome('')\n",
-      "    True\n",
-      "    >>> is_palindrome('aba')\n",
-      "    True\n",
-      "    >>> is_palindrome('aaaaa')\n",
-      "    True\n",
-      "    >>> is_palindrome('zbcd')\n",
-      "    False\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def modp(n: int, p: int):\n",
-      "    \"\"\"Return 2^n modulo p (be aware of numerics).\n",
-      "    >>> modp(3, 5)\n",
-      "    3\n",
-      "    >>> modp(1101, 101)\n",
-      "    2\n",
-      "    >>> modp(0, 101)\n",
-      "    1\n",
-      "    >>> modp(3, 11)\n",
-      "    8\n",
-      "    >>> modp(100, 101)\n",
-      "    1\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def remove_vowels(text):\n",
-      "    \"\"\"\n",
-      "    remove_vowels is a function that takes string and returns string without vowels.\n",
-      "    >>> remove_vowels('')\n",
-      "    ''\n",
-      "    >>> remove_vowels(\"abcdef\\nghijklm\")\n",
-      "    'bcdf\\nghjklm'\n",
-      "    >>> remove_vowels('abcdef')\n",
-      "    'bcdf'\n",
-      "    >>> remove_vowels('aaaaa')\n",
-      "    ''\n",
-      "    >>> remove_vowels('aaBAA')\n",
-      "    'B'\n",
-      "    >>> remove_vowels('zbcd')\n",
-      "    'zbcd'\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def below_threshold(l: list, t: int):\n",
-      "    \"\"\"Return True if all numbers in the list l are below threshold t.\n",
-      "    >>> below_threshold([1, 2, 4, 10], 100)\n",
-      "    True\n",
-      "    >>> below_threshold([1, 20, 4, 10], 5)\n",
-      "    False\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def add(x: int, y: int):\n",
-      "    \"\"\"Add two numbers x and y\n",
-      "    >>> add(2, 3)\n",
-      "    5\n",
-      "    >>> add(5, 7)\n",
-      "    12\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def same_chars(s0: str, s1: str):\n",
-      "    \"\"\"\n",
-      "    Check if two words have the same characters.\n",
-      "    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n",
-      "    True\n",
-      "    >>> same_chars('abcd', 'dddddddabc')\n",
-      "    True\n",
-      "    >>> same_chars('dddddddabc', 'abcd')\n",
-      "    True\n",
-      "    >>> same_chars('eabcd', 'dddddddabc')\n",
-      "    False\n",
-      "    >>> same_chars('abcd', 'dddddddabce')\n",
-      "    False\n",
-      "    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n",
-      "    False\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def fib(n: int):\n",
-      "    \"\"\"Return n-th Fibonacci number.\n",
-      "    >>> fib(10)\n",
-      "    55\n",
-      "    >>> fib(1)\n",
-      "    1\n",
-      "    >>> fib(8)\n",
-      "    21\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def correct_bracketing(brackets: str):\n",
-      "    \"\"\" brackets is a string of \"<\" and \">\".\n",
-      "    return True if every opening bracket has a corresponding closing bracket.\n",
-      "\n",
-      "    >>> correct_bracketing(\"<\")\n",
-      "    False\n",
-      "    >>> correct_bracketing(\"<>\")\n",
-      "    True\n",
-      "    >>> correct_bracketing(\"<<><>>\")\n",
-      "    True\n",
-      "    >>> correct_bracketing(\"><<>\")\n",
-      "    False\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def monotonic(l: list):\n",
-      "    \"\"\"Return True is list elements are monotonically increasing or decreasing.\n",
-      "    >>> monotonic([1, 2, 4, 20])\n",
-      "    True\n",
-      "    >>> monotonic([1, 20, 4, 10])\n",
-      "    False\n",
-      "    >>> monotonic([4, 1, 0, -10])\n",
-      "    True\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def common(l1: list, l2: list):\n",
-      "    \"\"\"Return sorted unique common elements for two lists.\n",
-      "    >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n",
-      "    [1, 5, 653]\n",
-      "    >>> common([5, 3, 2, 8], [3, 2])\n",
-      "    [2, 3]\n",
-      "\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def largest_prime_factor(n: int):\n",
-      "    \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n",
-      "    >>> largest_prime_factor(13195)\n",
-      "    29\n",
-      "    >>> largest_prime_factor(2048)\n",
-      "    2\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def sum_to_n(n: int):\n",
-      "    \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n",
-      "    >>> sum_to_n(30)\n",
-      "    465\n",
-      "    >>> sum_to_n(100)\n",
-      "    5050\n",
-      "    >>> sum_to_n(5)\n",
-      "    15\n",
-      "    >>> sum_to_n(10)\n",
-      "    55\n",
-      "    >>> sum_to_n(1)\n",
-      "    1\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def correct_bracketing(brackets: str):\n",
-      "    \"\"\" brackets is a string of \"(\" and \")\".\n",
-      "    return True if every opening bracket has a corresponding closing bracket.\n",
-      "\n",
-      "    >>> correct_bracketing(\"(\")\n",
-      "    False\n",
-      "    >>> correct_bracketing(\"()\")\n",
-      "    True\n",
-      "    >>> correct_bracketing(\"(()())\")\n",
-      "    True\n",
-      "    >>> correct_bracketing(\")(()\")\n",
-      "    False\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def derivative(xs: list):\n",
-      "    \"\"\" xs represent coefficients of a polynomial.\n",
-      "    xs[0] + xs[1] * x + xs[2] * x^2 + ....\n",
-      "     Return derivative of this polynomial in the same form.\n",
-      "    >>> derivative([3, 1, 2, 4, 5])\n",
-      "    [1, 4, 12, 20]\n",
-      "    >>> derivative([1, 2, 3])\n",
-      "    [2, 6]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def fibfib(n: int):\n",
-      "    \"\"\"The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:\n",
-      "    fibfib(0) == 0\n",
-      "    fibfib(1) == 0\n",
-      "    fibfib(2) == 1\n",
-      "    fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n",
-      "    Please write a function to efficiently compute the n-th element of the fibfib number sequence.\n",
-      "    >>> fibfib(1)\n",
-      "    0\n",
-      "    >>> fibfib(5)\n",
-      "    4\n",
-      "    >>> fibfib(8)\n",
-      "    24\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "FIX = \"\"\"\n",
-      "Add more test cases.\n",
-      "\"\"\"\n",
-      "\n",
-      "def vowels_count(s):\n",
-      "    \"\"\"Write a function vowels_count which takes a string representing\n",
-      "    a word as input and returns the number of vowels in the string.\n",
-      "    Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n",
-      "    vowel, but only when it is at the end of the given word.\n",
-      "\n",
-      "    Example:\n",
-      "    >>> vowels_count(\"abcde\")\n",
-      "    2\n",
-      "    >>> vowels_count(\"ACEDY\")\n",
-      "    3\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def circular_shift(x, shift):\n",
-      "    \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n",
-      "    and return the result as a string.\n",
-      "    If shift > number of digits, return digits reversed.\n",
-      "    >>> circular_shift(12, 1)\n",
-      "    \"21\"\n",
-      "    >>> circular_shift(12, 2)\n",
-      "    \"12\"\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def digitSum(s):\n",
-      "    \"\"\"Task\n",
-      "    Write a function that takes a string as input and returns the sum of the upper characters only'\n",
-      "    ASCII codes.\n",
-      "\n",
-      "    Examples:\n",
-      "        digitSum(\"\") => 0\n",
-      "        digitSum(\"abAB\") => 131\n",
-      "        digitSum(\"abcCd\") => 67\n",
-      "        digitSum(\"helloE\") => 69\n",
-      "        digitSum(\"woArBld\") => 131\n",
-      "        digitSum(\"aAaaaXa\") => 153\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def fruit_distribution(s,n):\n",
-      "    \"\"\"\n",
-      "    In this task, you will be given a string that represents a number of apples and oranges \n",
-      "    that are distributed in a basket of fruit this basket contains \n",
-      "    apples, oranges, and mango fruits. Given the string that represents the total number of \n",
-      "    the oranges and apples and an integer that represent the total number of the fruits \n",
-      "    in the basket return the number of the mango fruits in the basket.\n",
-      "    for examble:\n",
-      "    fruit_distribution(\"5 apples and 6 oranges\", 19) ->19 - 5 - 6 = 8\n",
-      "    fruit_distribution(\"0 apples and 1 oranges\",3) -> 3 - 0 - 1 = 2\n",
-      "    fruit_distribution(\"2 apples and 3 oranges\", 100) -> 100 - 2 - 3 = 95\n",
-      "    fruit_distribution(\"100 apples and 1 oranges\",120) -> 120 - 100 - 1 = 19\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def pluck(arr):\n",
-      "    \"\"\"\n",
-      "    \"Given an array representing a branch of a tree that has non-negative integer nodes\n",
-      "    your task is to pluck one of the nodes and return it.\n",
-      "    The plucked node should be the node with the smallest even value.\n",
-      "    If multiple nodes with the same smallest even value are found return the node that has smallest index.\n",
-      "\n",
-      "    The plucked node should be returned in a list, [ smalest_value, its index ],\n",
-      "    If there are no even values or the given array is empty, return [].\n",
-      "\n",
-      "    Example 1:\n",
-      "        Input: [4,2,3]\n",
-      "        Output: [2, 1]\n",
-      "        Explanation: 2 has the smallest even value, and 2 has the smallest index.\n",
-      "\n",
-      "    Example 2:\n",
-      "        Input: [1,2,3]\n",
-      "        Output: [2, 1]\n",
-      "        Explanation: 2 has the smallest even value, and 2 has the smallest index. \n",
-      "\n",
-      "    Example 3:\n",
-      "        Input: []\n",
-      "        Output: []\n",
-      "    \n",
-      "    Example 4:\n",
-      "        Input: [5, 0, 3, 0, 4, 2]\n",
-      "        Output: [0, 1]\n",
-      "        Explanation: 0 is the smallest value, but  there are two zeros,\n",
-      "                     so we will choose the first zero, which has the smallest index.\n",
-      "\n",
-      "    Constraints:\n",
-      "        * 1 <= nodes.length <= 10000\n",
-      "        * 0 <= node.value\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def search(lst):\n",
-      "    '''\n",
-      "    You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n",
-      "    zero, and has a frequency greater than or equal to the value of the integer itself. \n",
-      "    The frequency of an integer is the number of times it appears in the list.\n",
-      "    If no such a value exist, return -1.\n",
-      "    Examples:\n",
-      "        search([4, 1, 2, 2, 3, 1]) == 2\n",
-      "        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n",
-      "        search([5, 5, 4, 4, 4]) == -1\n",
-      "    '''\n",
-      "\n",
-      "\n",
-      "def strange_sort_list(lst):\n",
-      "    '''\n",
-      "    Given list of integers, return list in strange order.\n",
-      "    Strange sorting, is when you start with the minimum value,\n",
-      "    then maximum of the remaining integers, then minimum and so on.\n",
-      "\n",
-      "    Examples:\n",
-      "    strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n",
-      "    strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n",
-      "    strange_sort_list([]) == []\n",
-      "    '''\n",
-      "\n",
-      "\n",
-      "def triangle_area(a, b, c):\n",
-      "    '''\n",
-      "    Given the lengths of the three sides of a triangle. Return the area of\n",
-      "    the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n",
-      "    Otherwise return -1\n",
-      "    Three sides make a valid triangle when the sum of any two sides is greater \n",
-      "    than the third side.\n",
-      "    Example:\n",
-      "    triangle_area(3, 4, 5) == 6.00\n",
-      "    triangle_area(1, 2, 10) == -1\n",
-      "    '''\n",
-      "\n",
-      "\n",
-      "def will_it_fly(q,w):\n",
-      "    '''\n",
-      "    Write a function that returns True if the object q will fly, and False otherwise.\n",
-      "    The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n",
-      "\n",
-      "    Example:\n",
-      "    will_it_fly([1, 2], 5) ➞ False \n",
-      "    # 1+2 is less than the maximum possible weight, but it's unbalanced.\n",
-      "\n",
-      "    will_it_fly([3, 2, 3], 1) ➞ False\n",
-      "    # it's balanced, but 3+2+3 is more than the maximum possible weight.\n",
-      "\n",
-      "    will_it_fly([3, 2, 3], 9) ➞ True\n",
-      "    # 3+2+3 is less than the maximum possible weight, and it's balanced.\n",
-      "\n",
-      "    will_it_fly([3], 5) ➞ True\n",
-      "    # 3 is less than the maximum possible weight, and it's balanced.\n",
-      "    '''\n",
-      "\n",
-      "\n",
-      "def smallest_change(arr):\n",
-      "    \"\"\"\n",
-      "    Given an array arr of integers, find the minimum number of elements that\n",
-      "    need to be changed to make the array palindromic. A palindromic array is an array that\n",
-      "    is read the same backwards and forwards. In one change, you can change one element to any other element.\n",
-      "\n",
-      "    For example:\n",
-      "    smallest_change([1,2,3,5,4,7,9,6]) == 4\n",
-      "    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n",
-      "    smallest_change([1, 2, 3, 2, 1]) == 0\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def total_match(lst1, lst2):\n",
-      "    '''\n",
-      "    Write a function that accepts two lists of strings and returns the list that has \n",
-      "    total number of chars in the all strings of the list less than the other list.\n",
-      "\n",
-      "    if the two lists have the same number of chars, return the first list.\n",
-      "\n",
-      "    Examples\n",
-      "    total_match([], []) ➞ []\n",
-      "    total_match(['hi', 'admin'], ['hI', 'Hi']) ➞ ['hI', 'Hi']\n",
-      "    total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) ➞ ['hi', 'admin']\n",
-      "    total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) ➞ ['hI', 'hi', 'hi']\n",
-      "    total_match(['4'], ['1', '2', '3', '4', '5']) ➞ ['4']\n",
-      "    '''\n",
-      "\n",
-      "\n",
-      "def is_multiply_prime(a):\n",
-      "    \"\"\"Write a function that returns true if the given number is the multiplication of 3 prime numbers\n",
-      "    and false otherwise.\n",
-      "    Knowing that (a) is less then 100. \n",
-      "    Example:\n",
-      "    is_multiply_prime(30) == True\n",
-      "    30 = 2 * 3 * 5\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def is_simple_power(x, n):\n",
-      "    \"\"\"Your task is to write a function that returns true if a number x is a simple\n",
-      "    power of n and false in other cases.\n",
-      "    x is a simple power of n if n**int=x\n",
-      "    For example:\n",
-      "    is_simple_power(1, 4) => true\n",
-      "    is_simple_power(2, 2) => true\n",
-      "    is_simple_power(8, 2) => true\n",
-      "    is_simple_power(3, 2) => false\n",
-      "    is_simple_power(3, 1) => false\n",
-      "    is_simple_power(5, 3) => false\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def iscube(a):\n",
-      "    '''\n",
-      "    Write a function that takes an integer a and returns True \n",
-      "    if this ingeger is a cube of some integer number.\n",
-      "    Note: you may assume the input is always valid.\n",
-      "    Examples:\n",
-      "    iscube(1) ==> True\n",
-      "    iscube(2) ==> False\n",
-      "    iscube(-1) ==> True\n",
-      "    iscube(64) ==> True\n",
-      "    iscube(0) ==> True\n",
-      "    iscube(180) ==> False\n",
-      "    '''\n",
-      "\n",
-      "\n",
-      "def hex_key(num):\n",
-      "    \"\"\"You have been tasked to write a function that receives \n",
-      "    a hexadecimal number as a string and counts the number of hexadecimal \n",
-      "    digits that are primes (prime number, or a prime, is a natural number \n",
-      "    greater than 1 that is not a product of two smaller natural numbers).\n",
-      "    Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.\n",
-      "    Prime numbers are 2, 3, 5, 7, 11, 13, 17,...\n",
-      "    So you have to determine a number of the following digits: 2, 3, 5, 7, \n",
-      "    B (=decimal 11), D (=decimal 13).\n",
-      "    Note: you may assume the input is always correct or empty string, \n",
-      "    and symbols A,B,C,D,E,F are always uppercase.\n",
-      "    Examples:\n",
-      "    For num = \"AB\" the output should be 1.\n",
-      "    For num = \"1077E\" the output should be 2.\n",
-      "    For num = \"ABED1A33\" the output should be 4.\n",
-      "    For num = \"123456789ABCDEF0\" the output should be 6.\n",
-      "    For num = \"2020\" the output should be 2.\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def decimal_to_binary(decimal):\n",
-      "    \"\"\"You will be given a number in decimal form and your task is to convert it to\n",
-      "    binary format. The function should return a string, with each character representing a binary\n",
-      "    number. Each character in the string will be '0' or '1'.\n",
-      "\n",
-      "    There will be an extra couple of characters 'db' at the beginning and at the end of the string.\n",
-      "    The extra characters are there to help with the format.\n",
-      "\n",
-      "    Examples:\n",
-      "    decimal_to_binary(15)   # returns \"db1111db\"\n",
-      "    decimal_to_binary(32)   # returns \"db100000db\"\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def is_happy(s):\n",
-      "    \"\"\"You are given a string s.\n",
-      "    Your task is to check if the string is happy or not.\n",
-      "    A string is happy if its length is at least 3 and every 3 consecutive letters are distinct\n",
-      "    For example:\n",
-      "    is_happy(a) => False\n",
-      "    is_happy(aa) => False\n",
-      "    is_happy(abcd) => True\n",
-      "    is_happy(aabb) => False\n",
-      "    is_happy(adb) => True\n",
-      "    is_happy(xyy) => False\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def numerical_letter_grade(grades):\n",
-      "    \"\"\"It is the last week of the semester and the teacher has to give the grades\n",
-      "    to students. The teacher has been making her own algorithm for grading.\n",
-      "    The only problem is, she has lost the code she used for grading.\n",
-      "    She has given you a list of GPAs for some students and you have to write \n",
-      "    a function that can output a list of letter grades using the following table:\n",
-      "             GPA       |    Letter grade\n",
-      "              4.0                A+\n",
-      "            > 3.7                A \n",
-      "            > 3.3                A- \n",
-      "            > 3.0                B+\n",
-      "            > 2.7                B \n",
-      "            > 2.3                B-\n",
-      "            > 2.0                C+\n",
-      "            > 1.7                C\n",
-      "            > 1.3                C-\n",
-      "            > 1.0                D+ \n",
-      "            > 0.7                D \n",
-      "            > 0.0                D-\n",
-      "              0.0                E\n",
-      "    \n",
-      "\n",
-      "    Example:\n",
-      "    grade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-']\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def prime_length(string):\n",
-      "    \"\"\"Write a function that takes a string and returns True if the string\n",
-      "    length is a prime number or False otherwise\n",
-      "    Examples\n",
-      "    prime_length('Hello') == True\n",
-      "    prime_length('abcdcba') == True\n",
-      "    prime_length('kittens') == True\n",
-      "    prime_length('orange') == False\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def starts_one_ends(n):\n",
-      "    \"\"\"\n",
-      "    Given a positive integer n, return the count of the numbers of n-digit\n",
-      "    positive integers that start or end with 1.\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def solve(N):\n",
-      "    \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n",
-      "    \n",
-      "    Example\n",
-      "        For N = 1000, the sum of digits will be 1 the output should be \"1\".\n",
-      "        For N = 150, the sum of digits will be 6 the output should be \"110\".\n",
-      "        For N = 147, the sum of digits will be 12 the output should be \"1100\".\n",
-      "    \n",
-      "    Variables:\n",
-      "        @N integer\n",
-      "             Constraints: 0 ≤ N ≤ 10000.\n",
-      "    Output:\n",
-      "         a string of binary number\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def add(lst):\n",
-      "    \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n",
-      "\n",
-      "\n",
-      "    Examples:\n",
-      "        add([4, 2, 6, 7]) ==> 2 \n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def anti_shuffle(s):\n",
-      "    \"\"\"\n",
-      "    Write a function that takes a string and returns an ordered version of it.\n",
-      "    Ordered version of string, is a string where all words (separated by space)\n",
-      "    are replaced by a new word where all the characters arranged in\n",
-      "    ascending order based on ascii value.\n",
-      "    Note: You should keep the order of words and blank spaces in the sentence.\n",
-      "\n",
-      "    For example:\n",
-      "    anti_shuffle('Hi') returns 'Hi'\n",
-      "    anti_shuffle('hello') returns 'ehllo'\n",
-      "    anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def get_row(lst, x):\n",
-      "    \"\"\"\n",
-      "    You are given a 2 dimensional data, as a nested lists,\n",
-      "    which is similar to matrix, however, unlike matrices,\n",
-      "    each row may contain a different number of columns.\n",
-      "    Given lst, and integer x, find integers x in the list,\n",
-      "    and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n",
-      "    each tuple is a coordinate - (row, columns), starting with 0.\n",
-      "    Sort coordinates initially by rows in ascending order.\n",
-      "    Also, sort coordinates of the row by columns in descending order.\n",
-      "    \n",
-      "    Examples:\n",
-      "    get_row([\n",
-      "      [1,2,3,4,5,6],\n",
-      "      [1,2,3,4,1,6],\n",
-      "      [1,2,3,4,5,1]\n",
-      "    ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n",
-      "    get_row([], 1) == []\n",
-      "    get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def sort_array(array):\n",
-      "    \"\"\"\n",
-      "    Given an array of non-negative integers, return a copy of the given array after sorting,\n",
-      "    you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n",
-      "    or sort it in descending order if the sum( first index value, last index value) is even.\n",
-      "\n",
-      "    Note:\n",
-      "    * don't change the given array.\n",
-      "\n",
-      "    Examples:\n",
-      "    * sort_array([]) => []\n",
-      "    * sort_array([5]) => [5]\n",
-      "    * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n",
-      "    * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def encrypt(s):\n",
-      "    \"\"\"Create a function encrypt that takes a string as an argument and\n",
-      "    returns a string encrypted with the alphabet being rotated. \n",
-      "    The alphabet should be rotated in a manner such that the letters \n",
-      "    shift down by two multiplied to two places.\n",
-      "    For example:\n",
-      "    encrypt('hi') returns 'lm'\n",
-      "    encrypt('asdfghjkl') returns 'ewhjklnop'\n",
-      "    encrypt('gf') returns 'kj'\n",
-      "    encrypt('et') returns 'ix'\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def next_smallest(lst):\n",
-      "    \"\"\"\n",
-      "    You are given a list of integers.\n",
-      "    Write a function next_smallest() that returns the 2nd smallest element of the list.\n",
-      "    Return None if there is no such element.\n",
-      "    \n",
-      "    next_smallest([1, 2, 3, 4, 5]) == 2\n",
-      "    next_smallest([5, 1, 4, 3, 2]) == 2\n",
-      "    next_smallest([]) == None\n",
-      "    next_smallest([1, 1]) == None\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def is_bored(S):\n",
-      "    \"\"\"\n",
-      "    You'll be given a string of words, and your task is to count the number\n",
-      "    of boredoms. A boredom is a sentence that starts with the word \"I\".\n",
-      "    Sentences are delimited by '.', '?' or '!'.\n",
-      "   \n",
-      "    For example:\n",
-      "    >>> is_bored(\"Hello world\")\n",
-      "    0\n",
-      "    >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n",
-      "    1\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def any_int(x, y, z):\n",
-      "    '''\n",
-      "    Create a function that takes 3 numbers.\n",
-      "    Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n",
-      "    Returns false in any other cases.\n",
-      "    \n",
-      "    Examples\n",
-      "    any_int(5, 2, 7) ➞ True\n",
-      "    \n",
-      "    any_int(3, 2, 2) ➞ False\n",
-      "\n",
-      "    any_int(3, -2, 1) ➞ True\n",
-      "    \n",
-      "    any_int(3.6, -2.2, 2) ➞ False\n",
-      "  \n",
-      "\n",
-      "    \n",
-      "    '''\n",
-      "\n",
-      "\n",
-      "def encode(message):\n",
-      "    \"\"\"\n",
-      "    Write a function that takes a message, and encodes in such a \n",
-      "    way that it swaps case of all letters, replaces all vowels in \n",
-      "    the message with the letter that appears 2 places ahead of that \n",
-      "    vowel in the english alphabet. \n",
-      "    Assume only letters. \n",
-      "    \n",
-      "    Examples:\n",
-      "    >>> encode('test')\n",
-      "    'TGST'\n",
-      "    >>> encode('This is a message')\n",
-      "    'tHKS KS C MGSSCGG'\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "def skjkasdkd(lst):\n",
-      "    \"\"\"You are given a list of integers.\n",
-      "    You need to find the largest prime value and return the sum of its digits.\n",
-      "\n",
-      "    Examples:\n",
-      "    For lst = [0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3] the output should be 10\n",
-      "    For lst = [1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1] the output should be 25\n",
-      "    For lst = [1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3] the output should be 13\n",
-      "    For lst = [0,724,32,71,99,32,6,0,5,91,83,0,5,6] the output should be 11\n",
-      "    For lst = [0,81,12,3,1,21] the output should be 3\n",
-      "    For lst = [0,8,1,2,1,7] the output should be 7\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def check_dict_case(dict):\n",
-      "    \"\"\"\n",
-      "    Given a dictionary, return True if all keys are strings in lower \n",
-      "    case or all keys are strings in upper case, else return False.\n",
-      "    The function should return False is the given dictionary is empty.\n",
-      "    Examples:\n",
-      "    check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n",
-      "    check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n",
-      "    check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n",
-      "    check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n",
-      "    check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def count_up_to(n):\n",
-      "    \"\"\"Implement a function that takes an non-negative integer and returns an array of the first n\n",
-      "    integers that are prime numbers and less than n.\n",
-      "    for example:\n",
-      "    count_up_to(5) => [2,3]\n",
-      "    count_up_to(11) => [2,3,5,7]\n",
-      "    count_up_to(0) => []\n",
-      "    count_up_to(20) => [2,3,5,7,11,13,17,19]\n",
-      "    count_up_to(1) => []\n",
-      "    count_up_to(18) => [2,3,5,7,11,13,17]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def multiply(a, b):\n",
-      "    \"\"\"Complete the function that takes two integers and returns \n",
-      "    the product of their unit digits.\n",
-      "    Assume the input is always valid.\n",
-      "    Examples:\n",
-      "    multiply(148, 412) should return 16.\n",
-      "    multiply(19, 28) should return 72.\n",
-      "    multiply(2020, 1851) should return 0.\n",
-      "    multiply(14,-15) should return 20.\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def count_upper(s):\n",
-      "    \"\"\"\n",
-      "    Given a string s, count the number of uppercase vowels in even indices.\n",
-      "    \n",
-      "    For example:\n",
-      "    count_upper('aBCdEf') returns 1\n",
-      "    count_upper('abcdefg') returns 0\n",
-      "    count_upper('dBBE') returns 0\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def closest_integer(value):\n",
-      "    '''\n",
-      "    Create a function that takes a value (string) representing a number\n",
-      "    and returns the closest integer to it. If the number is equidistant\n",
-      "    from two integers, round it away from zero.\n",
-      "\n",
-      "    Examples\n",
-      "    >>> closest_integer(\"10\")\n",
-      "    10\n",
-      "    >>> closest_integer(\"15.3\")\n",
-      "    15\n",
-      "\n",
-      "    Note:\n",
-      "    Rounding away from zero means that if the given number is equidistant\n",
-      "    from two integers, the one you should return is the one that is the\n",
-      "    farthest from zero. For example closest_integer(\"14.5\") should\n",
-      "    return 15 and closest_integer(\"-14.5\") should return -15.\n",
-      "    '''\n",
-      "\n",
-      "\n",
-      "def make_a_pile(n):\n",
-      "    \"\"\"\n",
-      "    Given a positive integer n, you have to make a pile of n levels of stones.\n",
-      "    The first level has n stones.\n",
-      "    The number of stones in the next level is:\n",
-      "        - the next odd number if n is odd.\n",
-      "        - the next even number if n is even.\n",
-      "    Return the number of stones in each level in a list, where element at index\n",
-      "    i represents the number of stones in the level (i+1).\n",
-      "\n",
-      "    Examples:\n",
-      "    >>> make_a_pile(3)\n",
-      "    [3, 5, 7]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def words_string(s):\n",
-      "    \"\"\"\n",
-      "    You will be given a string of words separated by commas or spaces. Your task is\n",
-      "    to split the string into words and return an array of the words.\n",
-      "    \n",
-      "    For example:\n",
-      "    words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n",
-      "    words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def choose_num(x, y):\n",
-      "    \"\"\"This function takes two positive numbers x and y and returns the\n",
-      "    biggest even integer number that is in the range [x, y] inclusive. If \n",
-      "    there's no such number, then the function should return -1.\n",
-      "\n",
-      "    For example:\n",
-      "    choose_num(12, 15) = 14\n",
-      "    choose_num(13, 12) = -1\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def rounded_avg(n, m):\n",
-      "    \"\"\"You are given two positive integers n and m, and your task is to compute the\n",
-      "    average of the integers from n through m (including n and m). \n",
-      "    Round the answer to the nearest integer and convert that to binary.\n",
-      "    If n is greater than m, return -1.\n",
-      "    Example:\n",
-      "    rounded_avg(1, 5) => \"0b11\"\n",
-      "    rounded_avg(7, 5) => -1\n",
-      "    rounded_avg(10, 20) => \"0b1111\"\n",
-      "    rounded_avg(20, 33) => \"0b11010\"\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def unique_digits(x):\n",
-      "    \"\"\"Given a list of positive integers x. return a sorted list of all \n",
-      "    elements that hasn't any even digit.\n",
-      "\n",
-      "    Note: Returned list should be sorted in increasing order.\n",
-      "    \n",
-      "    For example:\n",
-      "    >>> unique_digits([15, 33, 1422, 1])\n",
-      "    [1, 15, 33]\n",
-      "    >>> unique_digits([152, 323, 1422, 10])\n",
-      "    []\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def by_length(arr):\n",
-      "    \"\"\"\n",
-      "    Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n",
-      "    reverse the resulting array, and then replace each digit by its corresponding name from\n",
-      "    \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n",
-      "\n",
-      "    For example:\n",
-      "      arr = [2, 1, 1, 4, 5, 8, 2, 3]   \n",
-      "            -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n",
-      "            -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n",
-      "      return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n",
-      "    \n",
-      "      If the array is empty, return an empty array:\n",
-      "      arr = []\n",
-      "      return []\n",
-      "    \n",
-      "      If the array has any strange number ignore it:\n",
-      "      arr = [1, -1 , 55] \n",
-      "            -> sort arr -> [-1, 1, 55]\n",
-      "            -> reverse arr -> [55, 1, -1]\n",
-      "      return = ['One']\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def f(n):\n",
-      "    \"\"\" Implement the function f that takes n as a parameter,\n",
-      "    and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even\n",
-      "    or the sum of numbers from 1 to i otherwise.\n",
-      "    i starts from 1.\n",
-      "    the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).\n",
-      "    Example:\n",
-      "    f(5) == [1, 2, 6, 24, 15]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def even_odd_palindrome(n):\n",
-      "    \"\"\"\n",
-      "    Given a positive integer n, return a tuple that has the number of even and odd\n",
-      "    integer palindromes that fall within the range(1, n), inclusive.\n",
-      "\n",
-      "    Example 1:\n",
-      "\n",
-      "        Input: 3\n",
-      "        Output: (1, 2)\n",
-      "        Explanation:\n",
-      "        Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n",
-      "\n",
-      "    Example 2:\n",
-      "\n",
-      "        Input: 12\n",
-      "        Output: (4, 6)\n",
-      "        Explanation:\n",
-      "        Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n",
-      "\n",
-      "    Note:\n",
-      "        1. 1 <= n <= 10^3\n",
-      "        2. returned tuple has the number of even and odd integer palindromes respectively.\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def count_nums(arr):\n",
-      "    \"\"\"\n",
-      "    Write a function count_nums which takes an array of integers and returns\n",
-      "    the number of elements which has a sum of digits > 0.\n",
-      "    If a number is negative, then its first signed digit will be negative:\n",
-      "    e.g. -123 has signed digits -1, 2, and 3.\n",
-      "    >>> count_nums([]) == 0\n",
-      "    >>> count_nums([-1, 11, -11]) == 1\n",
-      "    >>> count_nums([1, 1, 2]) == 3\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def move_one_ball(arr):\n",
-      "    \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The\n",
-      "    numbers in the array will be randomly ordered. Your task is to determine if\n",
-      "    it is possible to get an array sorted in non-decreasing order by performing \n",
-      "    the following operation on the given array:\n",
-      "        You are allowed to perform right shift operation any number of times.\n",
-      "    \n",
-      "    One right shift operation means shifting all elements of the array by one\n",
-      "    position in the right direction. The last element of the array will be moved to\n",
-      "    the starting position in the array i.e. 0th index. \n",
-      "\n",
-      "    If it is possible to obtain the sorted array by performing the above operation\n",
-      "    then return True else return False.\n",
-      "    If the given array is empty then return True.\n",
-      "\n",
-      "    Note: The given list is guaranteed to have unique elements.\n",
-      "\n",
-      "    For Example:\n",
-      "    \n",
-      "    move_one_ball([3, 4, 5, 1, 2])==>True\n",
-      "    Explanation: By performin 2 right shift operations, non-decreasing order can\n",
-      "                 be achieved for the given array.\n",
-      "    move_one_ball([3, 5, 4, 1, 2])==>False\n",
-      "    Explanation:It is not possible to get non-decreasing order for the given\n",
-      "                array by performing any number of right shift operations.\n",
-      "                \n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def exchange(lst1, lst2):\n",
-      "    \"\"\"In this problem, you will implement a function that takes two lists of numbers,\n",
-      "    and determines whether it is possible to perform an exchange of elements\n",
-      "    between them to make lst1 a list of only even numbers.\n",
-      "    There is no limit on the number of exchanged elements between lst1 and lst2.\n",
-      "    If it is possible to exchange elements between the lst1 and lst2 to make\n",
-      "    all the elements of lst1 to be even, return \"YES\".\n",
-      "    Otherwise, return \"NO\".\n",
-      "    For example:\n",
-      "    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"YES\"\n",
-      "    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n",
-      "    It is assumed that the input lists will be non-empty.\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def histogram(test):\n",
-      "    \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n",
-      "    of the letter with the most repetition and containing the corresponding count.\n",
-      "    If several letters have the same occurrence, return all of them.\n",
-      "    \n",
-      "    Example:\n",
-      "    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n",
-      "    histogram('a b b a') == {'a': 2, 'b': 2}\n",
-      "    histogram('a b c a b') == {'a': 2, 'b': 2}\n",
-      "    histogram('b b b b a') == {'b': 4}\n",
-      "    histogram('') == {}\n",
-      "\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def reverse_delete(s,c):\n",
-      "    \"\"\"Task\n",
-      "    We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c\n",
-      "    then check if the result string is palindrome.\n",
-      "    A string is called palindrome if it reads the same backward as forward.\n",
-      "    You should return a tuple containing the result string and True/False for the check.\n",
-      "    Example\n",
-      "    For s = \"abcde\", c = \"ae\", the result should be ('bcd',False)\n",
-      "    For s = \"abcdef\", c = \"b\"  the result should be ('acdef',False)\n",
-      "    For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc',True)\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def odd_count(lst):\n",
-      "    \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n",
-      "    Each element i of the output should be \"the number of odd elements in the\n",
-      "    string i of the input.\" where all the i's should be replaced by the number\n",
-      "    of odd digits in the i'th string of the input.\n",
-      "\n",
-      "    >>> odd_count(['1234567'])\n",
-      "    [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n",
-      "    >>> odd_count(['3',\"11111111\"])\n",
-      "    [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n",
-      "     \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def minSubArraySum(nums):\n",
-      "    \"\"\"\n",
-      "    Given an array of integers nums, find the minimum sum of any non-empty sub-array\n",
-      "    of nums.\n",
-      "    Example\n",
-      "    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n",
-      "    minSubArraySum([-1, -2, -3]) == -6\n",
-      "    \"\"\"\n",
-      "\n",
-      "import math\n",
-      "\n",
-      "def max_fill(grid, capacity):\n",
-      "    \"\"\"\n",
-      "    You are given a rectangular grid of wells. Each row represents a single well,\n",
-      "    and each 1 in a row represents a single unit of water.\n",
-      "    Each well has a corresponding bucket that can be used to extract water from it, \n",
-      "    and all buckets have the same capacity.\n",
-      "    Your task is to use the buckets to empty the wells.\n",
-      "    Output the number of times you need to lower the buckets.\n",
-      "\n",
-      "    Example 1:\n",
-      "        Input: \n",
-      "            grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]\n",
-      "            bucket_capacity : 1\n",
-      "        Output: 6\n",
-      "\n",
-      "    Example 2:\n",
-      "        Input: \n",
-      "            grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]\n",
-      "            bucket_capacity : 2\n",
-      "        Output: 5\n",
-      "    \n",
-      "    Example 3:\n",
-      "        Input: \n",
-      "            grid : [[0,0,0], [0,0,0]]\n",
-      "            bucket_capacity : 5\n",
-      "        Output: 0\n",
-      "\n",
-      "    Constraints:\n",
-      "        * all wells have the same length\n",
-      "        * 1 <= grid.length <= 10^2\n",
-      "        * 1 <= grid[:,1].length <= 10^2\n",
-      "        * grid[i][j] -> 0 | 1\n",
-      "        * 1 <= capacity <= 10\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def sort_array(arr):\n",
-      "    \"\"\"\n",
-      "    In this Kata, you have to sort an array of non-negative integers according to\n",
-      "    number of ones in their binary representation in ascending order.\n",
-      "    For similar number of ones, sort based on decimal value.\n",
-      "\n",
-      "    It must be implemented like this:\n",
-      "    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n",
-      "    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n",
-      "    >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def select_words(s, n):\n",
-      "    \"\"\"Given a string s and a natural number n, you have been tasked to implement \n",
-      "    a function that returns a list of all words from string s that contain exactly \n",
-      "    n consonants, in order these words appear in the string s.\n",
-      "    If the string s is empty then the function should return an empty list.\n",
-      "    Note: you may assume the input string contains only letters and spaces.\n",
-      "    Examples:\n",
-      "    select_words(\"Mary had a little lamb\", 4) ==> [\"little\"]\n",
-      "    select_words(\"Mary had a little lamb\", 3) ==> [\"Mary\", \"lamb\"]\n",
-      "    select_words(\"simple white space\", 2) ==> []\n",
-      "    select_words(\"Hello world\", 4) ==> [\"world\"]\n",
-      "    select_words(\"Uncle sam\", 3) ==> [\"Uncle\"]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def get_closest_vowel(word):\n",
-      "    \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n",
-      "    two consonants from the right side of the word (case sensitive).\n",
-      "    \n",
-      "    Vowels in the beginning and ending doesn't count. Return empty string if you didn't\n",
-      "    find any vowel met the above condition. \n",
-      "\n",
-      "    You may assume that the given string contains English letter only.\n",
-      "\n",
-      "    Example:\n",
-      "    get_closest_vowel(\"yogurt\") ==> \"u\"\n",
-      "    get_closest_vowel(\"FULL\") ==> \"U\"\n",
-      "    get_closest_vowel(\"quick\") ==> \"\"\n",
-      "    get_closest_vowel(\"ab\") ==> \"\"\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def match_parens(lst):\n",
-      "    '''\n",
-      "    You are given a list of two strings, both strings consist of open\n",
-      "    parentheses '(' or close parentheses ')' only.\n",
-      "    Your job is to check if it is possible to concatenate the two strings in\n",
-      "    some order, that the resulting string will be good.\n",
-      "    A string S is considered to be good if and only if all parentheses in S\n",
-      "    are balanced. For example: the string '(())()' is good, while the string\n",
-      "    '())' is not.\n",
-      "    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n",
-      "\n",
-      "    Examples:\n",
-      "    match_parens(['()(', ')']) == 'Yes'\n",
-      "    match_parens([')', ')']) == 'No'\n",
-      "    '''\n",
-      "\n",
-      "\n",
-      "def maximum(arr, k):\n",
-      "    \"\"\"\n",
-      "    Given an array arr of integers and a positive integer k, return a sorted list \n",
-      "    of length k with the maximum k numbers in arr.\n",
-      "\n",
-      "    Example 1:\n",
-      "\n",
-      "        Input: arr = [-3, -4, 5], k = 3\n",
-      "        Output: [-4, -3, 5]\n",
-      "\n",
-      "    Example 2:\n",
-      "\n",
-      "        Input: arr = [4, -4, 4], k = 2\n",
-      "        Output: [4, 4]\n",
-      "\n",
-      "    Example 3:\n",
-      "\n",
-      "        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n",
-      "        Output: [2]\n",
-      "\n",
-      "    Note:\n",
-      "        1. The length of the array will be in the range of [1, 1000].\n",
-      "        2. The elements in the array will be in the range of [-1000, 1000].\n",
-      "        3. 0 <= k <= len(arr)\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def solution(lst):\n",
-      "    \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n",
-      "    \n",
-      "\n",
-      "    Examples\n",
-      "    solution([5, 8, 7, 1]) ==> 12\n",
-      "    solution([3, 3, 3, 3, 3]) ==> 9\n",
-      "    solution([30, 13, 24, 321]) ==>0\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def add_elements(arr, k):\n",
-      "    \"\"\"\n",
-      "    Given a non-empty array of integers arr and an integer k, return\n",
-      "    the sum of the elements with at most two digits from the first k elements of arr.\n",
-      "\n",
-      "    Example:\n",
-      "\n",
-      "        Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4\n",
-      "        Output: 24 # sum of 21 + 3\n",
-      "\n",
-      "    Constraints:\n",
-      "        1. 1 <= len(arr) <= 100\n",
-      "        2. 1 <= k <= len(arr)\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def get_odd_collatz(n):\n",
-      "    \"\"\"\n",
-      "    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n",
-      "\n",
-      "    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n",
-      "    as follows: start with any positive integer n. Then each term is obtained from the \n",
-      "    previous term as follows: if the previous term is even, the next term is one half of \n",
-      "    the previous term. If the previous term is odd, the next term is 3 times the previous\n",
-      "    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n",
-      "\n",
-      "    Note: \n",
-      "        1. Collatz(1) is [1].\n",
-      "        2. returned list sorted in increasing order.\n",
-      "\n",
-      "    For example:\n",
-      "    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def valid_date(date):\n",
-      "    \"\"\"You have to write a function which validates a given date string and\n",
-      "    returns True if the date is valid otherwise False.\n",
-      "    The date is valid if all of the following rules are satisfied:\n",
-      "    1. The date string is not empty.\n",
-      "    2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.\n",
-      "    3. The months should not be less than 1 or higher than 12.\n",
-      "    4. The date should be in the format: mm-dd-yyyy\n",
-      "\n",
-      "    for example: \n",
-      "    valid_date('03-11-2000') => True\n",
-      "\n",
-      "    valid_date('15-01-2012') => False\n",
-      "\n",
-      "    valid_date('04-0-2040') => False\n",
-      "\n",
-      "    valid_date('06-04-2020') => True\n",
-      "\n",
-      "    valid_date('06/04/2020') => False\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def split_words(txt):\n",
-      "    '''\n",
-      "    Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n",
-      "    should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n",
-      "    alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n",
-      "    Examples\n",
-      "    split_words(\"Hello world!\") ➞ [\"Hello\", \"world!\"]\n",
-      "    split_words(\"Hello,world!\") ➞ [\"Hello\", \"world!\"]\n",
-      "    split_words(\"abcdef\") == 3 \n",
-      "    '''\n",
-      "\n",
-      "\n",
-      "def is_sorted(lst):\n",
-      "    '''\n",
-      "    Given a list of numbers, return whether or not they are sorted\n",
-      "    in ascending order. If list has more than 1 duplicate of the same\n",
-      "    number, return False. Assume no negative numbers and only integers.\n",
-      "\n",
-      "    Examples\n",
-      "    is_sorted([5]) ➞ True\n",
-      "    is_sorted([1, 2, 3, 4, 5]) ➞ True\n",
-      "    is_sorted([1, 3, 2, 4, 5]) ➞ False\n",
-      "    is_sorted([1, 2, 3, 4, 5, 6]) ➞ True\n",
-      "    is_sorted([1, 2, 3, 4, 5, 6, 7]) ➞ True\n",
-      "    is_sorted([1, 3, 2, 4, 5, 6, 7]) ➞ False\n",
-      "    is_sorted([1, 2, 2, 3, 3, 4]) ➞ True\n",
-      "    is_sorted([1, 2, 2, 2, 3, 4]) ➞ False\n",
-      "    '''\n",
-      "\n",
-      "\n",
-      "def intersection(interval1, interval2):\n",
-      "    \"\"\"You are given two intervals,\n",
-      "    where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).\n",
-      "    The given intervals are closed which means that the interval (start, end)\n",
-      "    includes both start and end.\n",
-      "    For each given interval, it is assumed that its start is less or equal its end.\n",
-      "    Your task is to determine whether the length of intersection of these two \n",
-      "    intervals is a prime number.\n",
-      "    Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)\n",
-      "    which its length is 1, which not a prime number.\n",
-      "    If the length of the intersection is a prime number, return \"YES\",\n",
-      "    otherwise, return \"NO\".\n",
-      "    If the two intervals don't intersect, return \"NO\".\n",
-      "\n",
-      "\n",
-      "    [input/output] samples:\n",
-      "    intersection((1, 2), (2, 3)) ==> \"NO\"\n",
-      "    intersection((-1, 1), (0, 4)) ==> \"NO\"\n",
-      "    intersection((-3, -1), (-5, 5)) ==> \"YES\"\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def prod_signs(arr):\n",
-      "    \"\"\"\n",
-      "    You are given an array arr of integers and you need to return\n",
-      "    sum of magnitudes of integers multiplied by product of all signs\n",
-      "    of each number in the array, represented by 1, -1 or 0.\n",
-      "    Note: return None for empty arr.\n",
-      "\n",
-      "    Example:\n",
-      "    >>> prod_signs([1, 2, 2, -4]) == -9\n",
-      "    >>> prod_signs([0, 1]) == 0\n",
-      "    >>> prod_signs([]) == None\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def minPath(grid, k):\n",
-      "    \"\"\"\n",
-      "    Given a grid with N rows and N columns (N >= 2) and a positive integer k, \n",
-      "    each cell of the grid contains a value. Every integer in the range [1, N * N]\n",
-      "    inclusive appears exactly once on the cells of the grid.\n",
-      "\n",
-      "    You have to find the minimum path of length k in the grid. You can start\n",
-      "    from any cell, and in each step you can move to any of the neighbor cells,\n",
-      "    in other words, you can go to cells which share an edge with you current\n",
-      "    cell.\n",
-      "    Please note that a path of length k means visiting exactly k cells (not\n",
-      "    necessarily distinct).\n",
-      "    You CANNOT go off the grid.\n",
-      "    A path A (of length k) is considered less than a path B (of length k) if\n",
-      "    after making the ordered lists of the values on the cells that A and B go\n",
-      "    through (let's call them lst_A and lst_B), lst_A is lexicographically less\n",
-      "    than lst_B, in other words, there exist an integer index i (1 <= i <= k)\n",
-      "    such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have\n",
-      "    lst_A[j] = lst_B[j].\n",
-      "    It is guaranteed that the answer is unique.\n",
-      "    Return an ordered list of the values on the cells that the minimum path go through.\n",
-      "\n",
-      "    Examples:\n",
-      "\n",
-      "        Input: grid = [ [1,2,3], [4,5,6], [7,8,9]], k = 3\n",
-      "        Output: [1, 2, 1]\n",
-      "\n",
-      "        Input: grid = [ [5,9,3], [4,1,6], [7,8,2]], k = 1\n",
-      "        Output: [1]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def tri(n):\n",
-      "    \"\"\"Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in \n",
-      "    the last couple centuries. However, what people don't know is Tribonacci sequence.\n",
-      "    Tribonacci sequence is defined by the recurrence:\n",
-      "    tri(1) = 3\n",
-      "    tri(n) = 1 + n / 2, if n is even.\n",
-      "    tri(n) =  tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.\n",
-      "    For example:\n",
-      "    tri(2) = 1 + (2 / 2) = 2\n",
-      "    tri(4) = 3\n",
-      "    tri(3) = tri(2) + tri(1) + tri(4)\n",
-      "           = 2 + 3 + 3 = 8 \n",
-      "    You are given a non-negative integer number n, you have to a return a list of the \n",
-      "    first n + 1 numbers of the Tribonacci sequence.\n",
-      "    Examples:\n",
-      "    tri(3) = [1, 3, 2, 8]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def digits(n):\n",
-      "    \"\"\"Given a positive integer n, return the product of the odd digits.\n",
-      "    Return 0 if all digits are even.\n",
-      "    For example:\n",
-      "    digits(1)  == 1\n",
-      "    digits(4)  == 0\n",
-      "    digits(235) == 15\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def is_nested(string):\n",
-      "    '''\n",
-      "    Create a function that takes a string as input which contains only square brackets.\n",
-      "    The function should return True if and only if there is a valid subsequence of brackets \n",
-      "    where at least one bracket in the subsequence is nested.\n",
-      "\n",
-      "    is_nested('[[]]') ➞ True\n",
-      "    is_nested('[]]]]]]][[[[[]') ➞ False\n",
-      "    is_nested('[][]') ➞ False\n",
-      "    is_nested('[]') ➞ False\n",
-      "    is_nested('[[][]]') ➞ True\n",
-      "    is_nested('[[]][[') ➞ True\n",
-      "    '''\n",
-      "\n",
-      "\n",
-      "\n",
-      "def sum_squares(lst):\n",
-      "    \"\"\"You are given a list of numbers.\n",
-      "    You need to return the sum of squared numbers in the given list,\n",
-      "    round each element in the list to the upper int(Ceiling) first.\n",
-      "    Examples:\n",
-      "    For lst = [1,2,3] the output should be 14\n",
-      "    For lst = [1,4,9] the output should be 98\n",
-      "    For lst = [1,3,5,7] the output should be 84\n",
-      "    For lst = [1.4,4.2,0] the output should be 29\n",
-      "    For lst = [-2.4,1,1] the output should be 6\n",
-      "    \n",
-      "\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def check_if_last_char_is_a_letter(txt):\n",
-      "    '''\n",
-      "    Create a function that returns True if the last character\n",
-      "    of a given string is an alphabetical character and is not\n",
-      "    a part of a word, and False otherwise.\n",
-      "    Note: \"word\" is a group of characters separated by space.\n",
-      "\n",
-      "    Examples:\n",
-      "    check_if_last_char_is_a_letter(\"apple pie\") ➞ False\n",
-      "    check_if_last_char_is_a_letter(\"apple pi e\") ➞ True\n",
-      "    check_if_last_char_is_a_letter(\"apple pi e \") ➞ False\n",
-      "    check_if_last_char_is_a_letter(\"\") ➞ False \n",
-      "    '''\n",
-      "\n",
-      "\n",
-      "def can_arrange(arr):\n",
-      "    \"\"\"Create a function which returns the largest index of an element which\n",
-      "    is not greater than or equal to the element immediately preceding it. If\n",
-      "    no such element exists then return -1. The given array will not contain\n",
-      "    duplicate values.\n",
-      "\n",
-      "    Examples:\n",
-      "    can_arrange([1,2,4,3,5]) = 3\n",
-      "    can_arrange([1,2,3]) = -1\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def largest_smallest_integers(lst):\n",
-      "    '''\n",
-      "    Create a function that returns a tuple (a, b), where 'a' is\n",
-      "    the largest of negative integers, and 'b' is the smallest\n",
-      "    of positive integers in a list.\n",
-      "    If there is no negative or positive integers, return them as None.\n",
-      "\n",
-      "    Examples:\n",
-      "    largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n",
-      "    largest_smallest_integers([]) == (None, None)\n",
-      "    largest_smallest_integers([0]) == (None, None)\n",
-      "    '''\n",
-      "\n",
-      "\n",
-      "def compare_one(a, b):\n",
-      "    \"\"\"\n",
-      "    Create a function that takes integers, floats, or strings representing\n",
-      "    real numbers, and returns the larger variable in its given variable type.\n",
-      "    Return None if the values are equal.\n",
-      "    Note: If a real number is represented as a string, the floating point might be . or ,\n",
-      "\n",
-      "    compare_one(1, 2.5) ➞ 2.5\n",
-      "    compare_one(1, \"2,3\") ➞ \"2,3\"\n",
-      "    compare_one(\"5,1\", \"6\") ➞ \"6\"\n",
-      "    compare_one(\"1\", 1) ➞ None\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def is_equal_to_sum_even(n):\n",
-      "    \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers\n",
-      "    Example\n",
-      "    is_equal_to_sum_even(4) == False\n",
-      "    is_equal_to_sum_even(6) == False\n",
-      "    is_equal_to_sum_even(8) == True\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def special_factorial(n):\n",
-      "    \"\"\"The Brazilian factorial is defined as:\n",
-      "    brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!\n",
-      "    where n > 0\n",
-      "\n",
-      "    For example:\n",
-      "    >>> special_factorial(4)\n",
-      "    288\n",
-      "\n",
-      "    The function will receive an integer as input and should return the special\n",
-      "    factorial of this integer.\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def fix_spaces(text):\n",
-      "    \"\"\"\n",
-      "    Given a string text, replace all spaces in it with underscores, \n",
-      "    and if a string has more than 2 consecutive spaces, \n",
-      "    then replace all consecutive spaces with - \n",
-      "    \n",
-      "    fix_spaces(\"Example\") == \"Example\"\n",
-      "    fix_spaces(\"Example 1\") == \"Example_1\"\n",
-      "    fix_spaces(\" Example 2\") == \"_Example_2\"\n",
-      "    fix_spaces(\" Example   3\") == \"_Example-3\"\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def file_name_check(file_name):\n",
-      "    \"\"\"Create a function which takes a string representing a file's name, and returns\n",
-      "    'Yes' if the the file's name is valid, and returns 'No' otherwise.\n",
-      "    A file's name is considered to be valid if and only if all the following conditions \n",
-      "    are met:\n",
-      "    - There should not be more than three digits ('0'-'9') in the file's name.\n",
-      "    - The file's name contains exactly one dot '.'\n",
-      "    - The substring before the dot should not be empty, and it starts with a letter from \n",
-      "    the latin alphapet ('a'-'z' and 'A'-'Z').\n",
-      "    - The substring after the dot should be one of these: ['txt', 'exe', 'dll']\n",
-      "    Examples:\n",
-      "    file_name_check(\"example.txt\") # => 'Yes'\n",
-      "    file_name_check(\"1example.dll\") # => 'No' (the name should start with a latin alphapet letter)\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "\n",
-      "\n",
-      "def sum_squares(lst):\n",
-      "    \"\"\"\"\n",
-      "    This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n",
-      "    multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n",
-      "    change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n",
-      "    \n",
-      "    Examples:\n",
-      "    For lst = [1,2,3] the output should be 6\n",
-      "    For lst = []  the output should be 0\n",
-      "    For lst = [-1,-5,2,-1,-5]  the output should be -126\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def words_in_sentence(sentence):\n",
-      "    \"\"\"\n",
-      "    You are given a string representing a sentence,\n",
-      "    the sentence contains some words separated by a space,\n",
-      "    and you have to return a string that contains the words from the original sentence,\n",
-      "    whose lengths are prime numbers,\n",
-      "    the order of the words in the new string should be the same as the original one.\n",
-      "\n",
-      "    Example 1:\n",
-      "        Input: sentence = \"This is a test\"\n",
-      "        Output: \"is\"\n",
-      "\n",
-      "    Example 2:\n",
-      "        Input: sentence = \"lets go for swimming\"\n",
-      "        Output: \"go for\"\n",
-      "\n",
-      "    Constraints:\n",
-      "        * 1 <= len(sentence) <= 100\n",
-      "        * sentence contains only letters\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def simplify(x, n):\n",
-      "    \"\"\"Your task is to implement a function that will simplify the expression\n",
-      "    x * n. The function returns True if x * n evaluates to a whole number and False\n",
-      "    otherwise. Both x and n, are string representation of a fraction, and have the following format,\n",
-      "    <numerator>/<denominator> where both numerator and denominator are positive whole numbers.\n",
-      "\n",
-      "    You can assume that x, and n are valid fractions, and do not have zero as denominator.\n",
-      "\n",
-      "    simplify(\"1/5\", \"5/1\") = True\n",
-      "    simplify(\"1/6\", \"2/1\") = False\n",
-      "    simplify(\"7/10\", \"10/2\") = False\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def order_by_points(nums):\n",
-      "    \"\"\"\n",
-      "    Write a function which sorts the given list of integers\n",
-      "    in ascending order according to the sum of their digits.\n",
-      "    Note: if there are several items with similar sum of their digits,\n",
-      "    order them based on their index in original list.\n",
-      "\n",
-      "    For example:\n",
-      "    >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n",
-      "    >>> order_by_points([]) == []\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def specialFilter(nums):\n",
-      "    \"\"\"Write a function that takes an array of numbers as input and returns \n",
-      "    the number of elements in the array that are greater than 10 and both \n",
-      "    first and last digits of a number are odd (1, 3, 5, 7, 9).\n",
-      "    For example:\n",
-      "    specialFilter([15, -73, 14, -15]) => 1 \n",
-      "    specialFilter([33, -2, -3, 45, 21, 109]) => 2\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def get_max_triples(n):\n",
-      "    \"\"\"\n",
-      "    You are given a positive integer n. You have to create an integer array a of length n.\n",
-      "        For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.\n",
-      "        Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n",
-      "    and a[i] + a[j] + a[k] is a multiple of 3.\n",
-      "\n",
-      "    Example :\n",
-      "        Input: n = 5\n",
-      "        Output: 1\n",
-      "        Explanation: \n",
-      "        a = [1, 3, 7, 13, 21]\n",
-      "        The only valid triple is (1, 7, 13).\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def bf(planet1, planet2):\n",
-      "    '''\n",
-      "    There are eight planets in our solar system: the closerst to the Sun \n",
-      "    is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n",
-      "    Uranus, Neptune.\n",
-      "    Write a function that takes two planet names as strings planet1 and planet2. \n",
-      "    The function should return a tuple containing all planets whose orbits are \n",
-      "    located between the orbit of planet1 and the orbit of planet2, sorted by \n",
-      "    the proximity to the sun. \n",
-      "    The function should return an empty tuple if planet1 or planet2\n",
-      "    are not correct planet names. \n",
-      "    Examples\n",
-      "    bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n",
-      "    bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n",
-      "    bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n",
-      "    '''\n",
-      "\n",
-      "\n",
-      "def sorted_list_sum(lst):\n",
-      "    \"\"\"Write a function that accepts a list of strings as a parameter,\n",
-      "    deletes the strings that have odd lengths from it,\n",
-      "    and returns the resulted list with a sorted order,\n",
-      "    The list is always a list of strings and never an array of numbers,\n",
-      "    and it may contain duplicates.\n",
-      "    The order of the list should be ascending by length of each word, and you\n",
-      "    should return the list sorted by that rule.\n",
-      "    If two words have the same length, sort the list alphabetically.\n",
-      "    The function should return a list of strings in sorted order.\n",
-      "    You may assume that all words will have the same length.\n",
-      "    For example:\n",
-      "    assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n",
-      "    assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def x_or_y(n, x, y):\n",
-      "    \"\"\"A simple program which should return the value of x if n is \n",
-      "    a prime number and should return the value of y otherwise.\n",
-      "\n",
-      "    Examples:\n",
-      "    for x_or_y(7, 34, 12) == 34\n",
-      "    for x_or_y(15, 8, 5) == 5\n",
-      "    \n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def double_the_difference(lst):\n",
-      "    '''\n",
-      "    Given a list of numbers, return the sum of squares of the numbers\n",
-      "    in the list that are odd. Ignore numbers that are negative or not integers.\n",
-      "    \n",
-      "    double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n",
-      "    double_the_difference([-1, -2, 0]) == 0\n",
-      "    double_the_difference([9, -2]) == 81\n",
-      "    double_the_difference([0]) == 0  \n",
-      "   \n",
-      "    If the input list is empty, return 0.\n",
-      "    '''\n",
-      "\n",
-      "\n",
-      "def compare(game,guess):\n",
-      "    \"\"\"I think we all remember that feeling when the result of some long-awaited\n",
-      "    event is finally known. The feelings and thoughts you have at that moment are\n",
-      "    definitely worth noting down and comparing.\n",
-      "    Your task is to determine if a person correctly guessed the results of a number of matches.\n",
-      "    You are given two arrays of scores and guesses of equal length, where each index shows a match. \n",
-      "    Return an array of the same length denoting how far off each guess was. If they have guessed correctly,\n",
-      "    the value is 0, and if not, the value is the absolute difference between the guess and the score.\n",
-      "    \n",
-      "    \n",
-      "    example:\n",
-      "\n",
-      "    compare([1,2,3,4,5,1],[1,2,3,4,2,-2]) -> [0,0,0,0,3,3]\n",
-      "    compare([0,5,0,0,0,4],[4,1,1,0,0,-2]) -> [4,4,1,0,0,6]\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def Strongest_Extension(class_name, extensions):\n",
-      "    \"\"\"You will be given the name of a class (a string) and a list of extensions.\n",
-      "    The extensions are to be used to load additional classes to the class. The\n",
-      "    strength of the extension is as follows: Let CAP be the number of the uppercase\n",
-      "    letters in the extension's name, and let SM be the number of lowercase letters \n",
-      "    in the extension's name, the strength is given by the fraction CAP - SM. \n",
-      "    You should find the strongest extension and return a string in this \n",
-      "    format: ClassName.StrongestExtensionName.\n",
-      "    If there are two or more extensions with the same strength, you should\n",
-      "    choose the one that comes first in the list.\n",
-      "    For example, if you are given \"Slices\" as the class and a list of the\n",
-      "    extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should\n",
-      "    return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension \n",
-      "    (its strength is -1).\n",
-      "    Example:\n",
-      "    for Strongest_Extension('my_class', ['AA', 'Be', 'CC']) == 'my_class.AA'\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def cycpattern_check(a , b):\n",
-      "    \"\"\"You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word\n",
-      "    cycpattern_check(\"abcd\",\"abd\") => False\n",
-      "    cycpattern_check(\"hello\",\"ell\") => True\n",
-      "    cycpattern_check(\"whassup\",\"psus\") => False\n",
-      "    cycpattern_check(\"abab\",\"baa\") => True\n",
-      "    cycpattern_check(\"efef\",\"eeff\") => False\n",
-      "    cycpattern_check(\"himenss\",\"simen\") => True\n",
-      "\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def even_odd_count(num):\n",
-      "    \"\"\"Given an integer. return a tuple that has the number of even and odd digits respectively.\n",
-      "\n",
-      "     Example:\n",
-      "        even_odd_count(-12) ==> (1, 1)\n",
-      "        even_odd_count(123) ==> (1, 2)\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def int_to_mini_roman(number):\n",
-      "    \"\"\"\n",
-      "    Given a positive integer, obtain its roman numeral equivalent as a string,\n",
-      "    and return it in lowercase.\n",
-      "    Restrictions: 1 <= num <= 1000\n",
-      "\n",
-      "    Examples:\n",
-      "    >>> int_to_mini_roman(19) == 'xix'\n",
-      "    >>> int_to_mini_roman(152) == 'clii'\n",
-      "    >>> int_to_mini_roman(426) == 'cdxxvi'\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def right_angle_triangle(a, b, c):\n",
-      "    '''\n",
-      "    Given the lengths of the three sides of a triangle. Return True if the three\n",
-      "    sides form a right-angled triangle, False otherwise.\n",
-      "    A right-angled triangle is a triangle in which one angle is right angle or \n",
-      "    90 degree.\n",
-      "    Example:\n",
-      "    right_angle_triangle(3, 4, 5) == True\n",
-      "    right_angle_triangle(1, 2, 3) == False\n",
-      "    '''\n",
-      "\n",
-      "\n",
-      "def find_max(words):\n",
-      "    \"\"\"Write a function that accepts a list of strings.\n",
-      "    The list contains different words. Return the word with maximum number\n",
-      "    of unique characters. If multiple strings have maximum number of unique\n",
-      "    characters, return the one which comes first in lexicographical order.\n",
-      "\n",
-      "    find_max([\"name\", \"of\", \"string\"]) == \"string\"\n",
-      "    find_max([\"name\", \"enam\", \"game\"]) == \"enam\"\n",
-      "    find_max([\"aaaaaaa\", \"bb\" ,\"cc\"]) == \"\"aaaaaaa\"\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def eat(number, need, remaining):\n",
-      "    \"\"\"\n",
-      "    You're a hungry rabbit, and you already have eaten a certain number of carrots,\n",
-      "    but now you need to eat more carrots to complete the day's meals.\n",
-      "    you should return an array of [ total number of eaten carrots after your meals,\n",
-      "                                    the number of carrots left after your meals ]\n",
-      "    if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n",
-      "    \n",
-      "    Example:\n",
-      "    * eat(5, 6, 10) -> [11, 4]\n",
-      "    * eat(4, 8, 9) -> [12, 1]\n",
-      "    * eat(1, 10, 10) -> [11, 0]\n",
-      "    * eat(2, 11, 5) -> [7, 0]\n",
-      "    \n",
-      "    Variables:\n",
-      "    @number : integer\n",
-      "        the number of carrots that you have eaten.\n",
-      "    @need : integer\n",
-      "        the number of carrots that you need to eat.\n",
-      "    @remaining : integer\n",
-      "        the number of remaining carrots thet exist in stock\n",
-      "    \n",
-      "    Constrain:\n",
-      "    * 0 <= number <= 1000\n",
-      "    * 0 <= need <= 1000\n",
-      "    * 0 <= remaining <= 1000\n",
-      "\n",
-      "    Have fun :)\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def do_algebra(operator, operand):\n",
-      "    \"\"\"\n",
-      "    Given two lists operator, and operand. The first list has basic algebra operations, and \n",
-      "    the second list is a list of integers. Use the two given lists to build the algebric \n",
-      "    expression and return the evaluation of this expression.\n",
-      "\n",
-      "    The basic algebra operations:\n",
-      "    Addition ( + ) \n",
-      "    Subtraction ( - ) \n",
-      "    Multiplication ( * ) \n",
-      "    Floor division ( // ) \n",
-      "    Exponentiation ( ** ) \n",
-      "\n",
-      "    Example:\n",
-      "    operator['+', '*', '-']\n",
-      "    array = [2, 3, 4, 5]\n",
-      "    result = 2 + 3 * 4 - 5\n",
-      "    => result = 9\n",
-      "\n",
-      "    Note:\n",
-      "        The length of operator list is equal to the length of operand list minus one.\n",
-      "        Operand is a list of of non-negative integers.\n",
-      "        Operator list has at least one operator, and operand list has at least two operands.\n",
-      "\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def solve(s):\n",
-      "    \"\"\"You are given a string s.\n",
-      "    if s[i] is a letter, reverse its case from lower to upper or vise versa, \n",
-      "    otherwise keep it as it is.\n",
-      "    If the string contains no letters, reverse the string.\n",
-      "    The function should return the resulted string.\n",
-      "    Examples\n",
-      "    solve(\"1234\") = \"4321\"\n",
-      "    solve(\"ab\") = \"AB\"\n",
-      "    solve(\"#a@C\") = \"#A@c\"\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def string_to_md5(text):\n",
-      "    \"\"\"\n",
-      "    Given a string 'text', return its md5 hash equivalent string.\n",
-      "    If 'text' is an empty string, return None.\n",
-      "\n",
-      "    >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n",
-      "    \"\"\"\n",
-      "\n",
-      "\n",
-      "def generate_integers(a, b):\n",
-      "    \"\"\"\n",
-      "    Given two positive integers a and b, return the even digits between a\n",
-      "    and b, in ascending order.\n",
-      "\n",
-      "    For example:\n",
-      "    generate_integers(2, 8) => [2, 4, 6, 8]\n",
-      "    generate_integers(8, 2) => [2, 4, 6, 8]\n",
-      "    generate_integers(10, 14) => []\n",
-      "    \"\"\"\n",
-      "\n"
-     ]
-    }
-   ],
-   "source": [
-    "from evalplus.data import get_human_eval_plus\n",
-    "\n",
-    "humaneval = get_human_eval_plus()\n",
-    "print(humaneval['HumanEval/32'][\"entry_point\"])\n",
-    "print(humaneval['HumanEval/0'][\"prompt\"])\n",
-    "\n",
-    "for key, value in humaneval.items():\n",
-    "    if key == \"HumanEval/32\" or key == \"HumanEval/38\" or key == \"HumanEval/50\":\n",
-    "        pass\n",
-    "    else:\n",
-    "        entry_point = value[\"entry_point\"]\n",
-    "        prompt = value[\"prompt\"]\n",
-    "        print(prompt)"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 4,
-   "metadata": {},
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "find_zero\n",
-      "import math\n",
-      "\n",
-      "\n",
-      "def poly(xs: list, x: float):\n",
-      "    \"\"\"\n",
-      "    Evaluates polynomial with coefficients xs at point x.\n",
-      "    return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n\n",
-      "    \"\"\"\n",
-      "    return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])\n",
-      "\n",
-      "\n",
-      "def find_zero(xs: list):\n",
-      "    \"\"\" xs are coefficients of a polynomial.\n",
-      "    find_zero find x such that poly(x) = 0.\n",
-      "    find_zero returns only only zero point, even if there are many.\n",
-      "    Moreover, find_zero only takes list xs having even number of coefficients\n",
-      "    and largest non zero coefficient as it guarantees\n",
-      "    a solution.\n",
-      "    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n",
-      "    -0.5\n",
-      "    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n",
-      "    1.0\n",
-      "    \"\"\"\n",
-      "\n",
-      "import math\n",
-      "def poly(xs: list, x: float):\n",
-      "    \"\"\"\n",
-      "    Evaluates polynomial with coefficients xs at point x.\n",
-      "    return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\n",
-      "    \"\"\"\n",
-      "    return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\n",
-      "def find_zero(xs: list):\n",
-      "    \"\"\" \n",
-      "    xs are coefficients of a polynomial.\n",
-      "    find_zero finds x such that poly(x) = 0.\n",
-      "    find_zero returns only one zero point, even if there are many.\n",
-      "    Moreover, find_zero only takes list xs having an even number of coefficients\n",
-      "    and the largest non-zero coefficient as it guarantees a solution.\n",
-      "    \n",
-      "    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n",
-      "    -0.5\n",
-      "    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n",
-      "    1.0\n",
-      "    \"\"\"\n",
-      "    if len(xs) % 2 != 0:\n",
-      "        raise ValueError(\"The number of coefficients must be even.\")\n",
-      "    \n",
-      "    # Initial guess for the root\n",
-      "    x0 = 0.0\n",
-      "    tolerance = 1e-7\n",
-      "    max_iterations = 1000\n",
-      "    \n",
-      "    for _ in range(max_iterations):\n",
-      "        f_x0 = poly(xs, x0)\n",
-      "        f_prime_x0 = sum(i * coeff * math.pow(x0, i - 1) for i, coeff in enumerate(xs) if i > 0)\n",
-      "        \n",
-      "        if f_prime_x0 == 0:  # Avoid division by zero\n",
-      "            raise ValueError(\"Derivative is zero. No solution found.\")\n",
-      "        \n",
-      "        x1 = x0 - f_x0 / f_prime_x0\n",
-      "        \n",
-      "        if abs(x1 - x0) < tolerance:\n",
-      "            return x1\n",
-      "        \n",
-      "        x0 = x1\n",
-      "    \n",
-      "    raise ValueError(\"Maximum iterations reached. No solution found.\")\n"
-     ]
-    }
-   ],
-   "source": [
-    "\n",
-    "from evalplus.data import get_human_eval_plus\n",
-    "\n",
-    "humaneval = get_human_eval_plus()\n",
-    "print(humaneval['HumanEval/32'][\"entry_point\"])\n",
-    "print(humaneval['HumanEval/32'][\"prompt\"])\n",
-    "result = {\"task_id\": \"HumanEval/32\", \"solution\": \"import math\\ndef poly(xs: list, x: float):\\n    \\\"\\\"\\\"\\n    Evaluates polynomial with coefficients xs at point x.\\n    return xs[0] + xs[1] * x + xs[2] * x^2 + .... xs[n] * x^n\\n    \\\"\\\"\\\"\\n    return sum(coeff * math.pow(x, i) for i, coeff in enumerate(xs))\\ndef find_zero(xs: list):\\n    \\\"\\\"\\\" \\n    xs are coefficients of a polynomial.\\n    find_zero finds x such that poly(x) = 0.\\n    find_zero returns only one zero point, even if there are many.\\n    Moreover, find_zero only takes list xs having an even number of coefficients\\n    and the largest non-zero coefficient as it guarantees a solution.\\n    \\n    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\\n    -0.5\\n    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\\n    1.0\\n    \\\"\\\"\\\"\\n    if len(xs) % 2 != 0:\\n        raise ValueError(\\\"The number of coefficients must be even.\\\")\\n    \\n    # Initial guess for the root\\n    x0 = 0.0\\n    tolerance = 1e-7\\n    max_iterations = 1000\\n    \\n    for _ in range(max_iterations):\\n        f_x0 = poly(xs, x0)\\n        f_prime_x0 = sum(i * coeff * math.pow(x0, i - 1) for i, coeff in enumerate(xs) if i > 0)\\n        \\n        if f_prime_x0 == 0:  # Avoid division by zero\\n            raise ValueError(\\\"Derivative is zero. No solution found.\\\")\\n        \\n        x1 = x0 - f_x0 / f_prime_x0\\n        \\n        if abs(x1 - x0) < tolerance:\\n            return x1\\n        \\n        x0 = x1\\n    \\n    raise ValueError(\\\"Maximum iterations reached. No solution found.\\\")\"}\n",
-    "print(result[\"solution\"])\n",
-    "# print(\"--------------------\")\n",
-    "# print(humaneval['HumanEval/38'][\"entry_point\"])\n",
-    "# print(humaneval['HumanEval/38'][\"prompt\"])\n",
-    "# print(\"--------------------\")\n",
-    "# print(humaneval['HumanEval/50'][\"entry_point\"])\n",
-    "# print(humaneval['HumanEval/50'][\"prompt\"])\n"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 5,
-   "metadata": {},
-   "outputs": [
-    {
-     "name": "stderr",
-     "output_type": "stream",
-     "text": [
-      "2024-07-28 12:17:06.501 | INFO     | metagpt.const:get_metagpt_package_root:29 - Package root set to /Users/trl/Github_project/MetaGPT-MathAI\n"
-     ]
-    },
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "18\n",
-      "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/83'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/99'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/127'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n",
-      "22\n",
-      "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/40'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/67'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/83'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/99'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/127'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n"
-     ]
-    }
-   ],
-   "source": [
-    "from examples.ags.benchmark.humaneval import extract_failure_tests\n",
-    "\n",
-    "file_path_list = [\"alpha_based_101_eval_results.json\",\"alpha_based_102_eval_results.json\"]\n",
-    "\n",
-    "for file_path in file_path_list:\n",
-    "    unpassed_exapmle = extract_failure_tests(file_path)\n",
-    "    print(unpassed_exapmle)"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 1,
-   "metadata": {},
-   "outputs": [
-    {
-     "name": "stderr",
-     "output_type": "stream",
-     "text": [
-      "2024-07-25 16:45:31.369 | INFO     | metagpt.const:get_metagpt_package_root:29 - Package root set to /Users/trl/Github_project/MetaGPT-MathAI\n"
-     ]
-    },
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "22\n",
-      "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/40'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/67'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n",
-      "20\n",
-      "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/40'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/67'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/163'}]\n",
-      "24\n",
-      "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/40'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/67'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/89'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/163'}]\n",
-      "23\n",
-      "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/40'}, {'task_id': 'HumanEval/64'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/67'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/109'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n",
-      "22\n",
-      "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/40'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/67'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/135'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/163'}]\n"
-     ]
-    }
-   ],
-   "source": [
-    "from examples.ags.benchmark.humaneval import extract_failure_tests\n",
-    "\n",
-    "file_path_list = [\"llm_based_120_eval_results.json\", \"llm_based_121_eval_results.json\", \"llm_based_122_eval_results.json\", \"llm_based_123_eval_results.json\", \"llm_based_124_eval_results.json\"]\n",
-    "\n",
-    "for file_path in file_path_list:\n",
-    "    unpassed_exapmle = extract_failure_tests(file_path)\n",
-    "    print(unpassed_exapmle)"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 2,
-   "metadata": {},
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "17\n",
-      "[{'task_id': 'HumanEval/163'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/129'}]\n",
-      "20\n",
-      "[{'task_id': 'HumanEval/163'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/67'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/135'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/129'}]\n",
-      "17\n",
-      "[{'task_id': 'HumanEval/163'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/83'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/129'}]\n",
-      "18\n",
-      "[{'task_id': 'HumanEval/163'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/83'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/129'}]\n",
-      "18\n",
-      "[{'task_id': 'HumanEval/163'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/99'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/129'}]\n"
-     ]
-    }
-   ],
-   "source": [
-    "\n",
-    "\n",
-    "from examples.ags.benchmark.humaneval import extract_failure_tests\n",
-    "\n",
-    "file_path_list = [\"EVALPLUS-4omini/1.json\", \"EVALPLUS-4omini/2.json\", \"EVALPLUS-4omini/3.json\", \"EVALPLUS-4omini/4.json\", \"EVALPLUS-4omini/5.json\"]\n",
-    "\n",
-    "for file_path in file_path_list:\n",
-    "    unpassed_exapmle = extract_failure_tests(file_path)\n",
-    "    print(unpassed_exapmle)"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 13,
-   "metadata": {},
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "20\n",
-      "[{'task_id': 'HumanEval/16'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n",
-      "23\n",
-      "[{'task_id': 'HumanEval/16'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/33'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/67'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/116'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n",
-      "20\n",
-      "[{'task_id': 'HumanEval/16'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/67'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/116'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n",
-      "22\n",
-      "[{'task_id': 'HumanEval/16'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/67'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/116'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n",
-      "23\n",
-      "[{'task_id': 'HumanEval/16'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/33'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/67'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/116'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n"
-     ]
-    }
-   ],
-   "source": [
-    "from examples.ags.benchmark.humaneval import extract_failure_tests\n",
-    "\n",
-    "file_path_list = [\"llm_based_125_eval_results.json\", \"llm_based_126_eval_results.json\", \"llm_based_127_eval_results.json\", \"llm_based_128_eval_results.json\", \"llm_based_129_eval_results.json\"]\n",
-    "\n",
-    "for file_path in file_path_list:\n",
-    "    unpassed_exapmle = extract_failure_tests(file_path)\n",
-    "    print(unpassed_exapmle)"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 15,
-   "metadata": {},
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "21\n",
-      "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/83'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/116'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n",
-      "22\n",
-      "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/33'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n",
-      "21\n",
-      "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/33'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n",
-      "20\n",
-      "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/33'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/163'}]\n",
-      "22\n",
-      "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/83'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n"
-     ]
-    }
-   ],
-   "source": [
-    "from examples.ags.benchmark.humaneval import extract_failure_tests\n",
-    "\n",
-    "file_path_list = [\"llm_based_135_eval_results.json\", \"llm_based_136_eval_results.json\", \"llm_based_137_eval_results.json\", \"llm_based_138_eval_results.json\", \"llm_based_139_eval_results.json\"]\n",
-    "\n",
-    "for file_path in file_path_list:\n",
-    "    unpassed_exapmle = extract_failure_tests(file_path)\n",
-    "    print(unpassed_exapmle)\n"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 14,
-   "metadata": {},
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "15\n",
-      "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/40'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/67'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}]\n",
-      "14\n",
-      "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/83'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/99'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}]\n",
-      "18\n",
-      "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/40'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/99'}, {'task_id': 'HumanEval/102'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/160'}]\n",
-      "16\n",
-      "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/83'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/99'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/127'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/145'}]\n",
-      "17\n",
-      "[{'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/40'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/75'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/99'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/127'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/160'}]\n"
-     ]
-    }
-   ],
-   "source": [
-    "from examples.ags.benchmark.humaneval import extract_failure_tests\n",
-    "\n",
-    "file_path_list = [\"alpha_based_104_eval_results.json\", \"alpha_based_105_eval_results.json\", \"alpha_based_106_eval_results.json\", \"alpha_based_107_eval_results.json\", \"alpha_based_108_eval_results.json\"]\n",
-    "\n",
-    "for file_path in file_path_list:\n",
-    "    unpassed_exapmle = extract_failure_tests(file_path)\n",
-    "    print(unpassed_exapmle)"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 11,
-   "metadata": {},
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "\n",
-      "def fruit_distribution(s,n):\n",
-      "    \"\"\"\n",
-      "    In this task, you will be given a string that represents a number of apples and oranges \n",
-      "    that are distributed in a basket of fruit this basket contains \n",
-      "    apples, oranges, and mango fruits. Given the string that represents the total number of \n",
-      "    the oranges and apples and an integer that represent the total number of the fruits \n",
-      "    in the basket return the number of the mango fruits in the basket.\n",
-      "    for examble:\n",
-      "    fruit_distribution(\"5 apples and 6 oranges\", 19) ->19 - 5 - 6 = 8\n",
-      "    fruit_distribution(\"0 apples and 1 oranges\",3) -> 3 - 0 - 1 = 2\n",
-      "    fruit_distribution(\"2 apples and 3 oranges\", 100) -> 100 - 2 - 3 = 95\n",
-      "    fruit_distribution(\"100 apples and 1 oranges\",120) -> 120 - 100 - 1 = 19\n",
-      "    \"\"\"\n",
-      "\n",
-      "def fruit_distribution(s, n):\n",
-      "    \"\"\"\n",
-      "    In this task, you will be given a string that represents a number of apples and oranges \n",
-      "    that are distributed in a basket of fruit. This basket contains \n",
-      "    apples, oranges, and mango fruits. Given the string that represents the total number of \n",
-      "    the oranges and apples and an integer that represents the total number of the fruits \n",
-      "    in the basket, return the number of the mango fruits in the basket.\n",
-      "    \n",
-      "    Parameters:\n",
-      "    s (str): A string representing the number of apples and oranges.\n",
-      "    n (int): An integer representing the total number of fruits in the basket.\n",
-      "    \n",
-      "    Returns:\n",
-      "    int: The number of mango fruits in the basket.\n",
-      "    \n",
-      "    Examples:\n",
-      "    fruit_distribution(\"5 apples and 6 oranges\", 19) -> 8\n",
-      "    fruit_distribution(\"0 apples and 1 oranges\", 3) -> 2\n",
-      "    fruit_distribution(\"2 apples and 3 oranges\", 100) -> 95\n",
-      "    fruit_distribution(\"100 apples and 1 oranges\", 120) -> 19\n",
-      "    \"\"\"\n",
-      "    \n",
-      "    # Extract the number of apples and oranges from the string\n",
-      "    parts = s.split()\n",
-      "    apples = int(parts[0])  # First part is the number of apples\n",
-      "    oranges = int(parts[2])  # Third part is the number of oranges\n",
-      "    \n",
-      "    # Calculate the number of mangoes\n",
-      "    mangoes = n - apples - oranges\n",
-      "    \n",
-      "    return mangoes\n",
-      "--------------------------\n",
-      "def fruit_distribution(s, n):\n",
-      "    \"\"\"\n",
-      "    In this task, you will be given a string that represents a number of apples and oranges \n",
-      "    that are distributed in a basket of fruit. This basket contains \n",
-      "    apples, oranges, and mango fruits. Given the string that represents the total number of \n",
-      "    the oranges and apples and an integer that represents the total number of the fruits \n",
-      "    in the basket, return the number of the mango fruits in the basket.\n",
-      "    \n",
-      "    Parameters:\n",
-      "    s (str): A string representing the number of apples and oranges.\n",
-      "    n (int): An integer representing the total number of fruits in the basket.\n",
-      "    \n",
-      "    Returns:\n",
-      "    int: The number of mango fruits in the basket.\n",
-      "    \n",
-      "    Examples:\n",
-      "    fruit_distribution(\"5 apples and 6 oranges\", 19) -> 8\n",
-      "    fruit_distribution(\"0 apples and 1 oranges\", 3) -> 2\n",
-      "    fruit_distribution(\"2 apples and 3 oranges\", 100) -> 95\n",
-      "    fruit_distribution(\"100 apples and 1 oranges\", 120) -> 19\n",
-      "    \"\"\"\n",
-      "    \n",
-      "    # Extract the number of apples and oranges from the string\n",
-      "    parts = s.split()\n",
-      "    apples = int(parts[0])  # First part is the number of apples\n",
-      "    oranges = int(parts[3])  # Fourth part is the number of oranges\n",
-      "    \n",
-      "    # Calculate the number of mangoes\n",
-      "    mangoes = n - apples - oranges\n",
-      "    \n",
-      "    return mangoes\n",
-      "--------------------------\n",
-      "def fruit_distribution(s, n):\n",
-      "    \"\"\"\n",
-      "    Calculate the number of mango fruits in a basket given the number of apples and oranges.\n",
-      "\n",
-      "    Parameters:\n",
-      "    s (str): A string representing the number of apples and oranges in the format \"X apples and Y oranges\".\n",
-      "    n (int): An integer representing the total number of fruits in the basket.\n",
-      "\n",
-      "    Returns:\n",
-      "    int: The number of mango fruits in the basket.\n",
-      "    \"\"\"\n",
-      "    # Split the input string to extract the number of apples and oranges\n",
-      "    parts = s.split(\" and \")\n",
-      "    apples = int(parts[0].split()[0])  # Get the number of apples\n",
-      "    oranges = int(parts[1].split()[0])  # Get the number of oranges\n",
-      "\n",
-      "    # Calculate the number of mangoes\n",
-      "    mangoes = n - apples - oranges\n",
-      "\n",
-      "    return mangoes\n"
-     ]
-    }
-   ],
-   "source": [
-    "from evalplus.data import get_human_eval_plus\n",
-    "\n",
-    "humaneval = get_human_eval_plus()\n",
-    "print(humaneval['HumanEval/67'][\"prompt\"])\n",
-    "\n",
-    "result = {\"solution\": \"def fruit_distribution(s, n):\\n    \\\"\\\"\\\"\\n    In this task, you will be given a string that represents a number of apples and oranges \\n    that are distributed in a basket of fruit. This basket contains \\n    apples, oranges, and mango fruits. Given the string that represents the total number of \\n    the oranges and apples and an integer that represents the total number of the fruits \\n    in the basket, return the number of the mango fruits in the basket.\\n    \\n    Parameters:\\n    s (str): A string representing the number of apples and oranges.\\n    n (int): An integer representing the total number of fruits in the basket.\\n    \\n    Returns:\\n    int: The number of mango fruits in the basket.\\n    \\n    Examples:\\n    fruit_distribution(\\\"5 apples and 6 oranges\\\", 19) -> 8\\n    fruit_distribution(\\\"0 apples and 1 oranges\\\", 3) -> 2\\n    fruit_distribution(\\\"2 apples and 3 oranges\\\", 100) -> 95\\n    fruit_distribution(\\\"100 apples and 1 oranges\\\", 120) -> 19\\n    \\\"\\\"\\\"\\n    \\n    # Extract the number of apples and oranges from the string\\n    parts = s.split()\\n    apples = int(parts[0])  # First part is the number of apples\\n    oranges = int(parts[2])  # Third part is the number of oranges\\n    \\n    # Calculate the number of mangoes\\n    mangoes = n - apples - oranges\\n    \\n    return mangoes\"}\n",
-    "print(result[\"solution\"])\n",
-    "\n",
-    "print(\"--------------------------\")\n",
-    "\n",
-    "correct_result = {\"solution\":\"def fruit_distribution(s, n):\\n    \\\"\\\"\\\"\\n    In this task, you will be given a string that represents a number of apples and oranges \\n    that are distributed in a basket of fruit. This basket contains \\n    apples, oranges, and mango fruits. Given the string that represents the total number of \\n    the oranges and apples and an integer that represents the total number of the fruits \\n    in the basket, return the number of the mango fruits in the basket.\\n    \\n    Parameters:\\n    s (str): A string representing the number of apples and oranges.\\n    n (int): An integer representing the total number of fruits in the basket.\\n    \\n    Returns:\\n    int: The number of mango fruits in the basket.\\n    \\n    Examples:\\n    fruit_distribution(\\\"5 apples and 6 oranges\\\", 19) -> 8\\n    fruit_distribution(\\\"0 apples and 1 oranges\\\", 3) -> 2\\n    fruit_distribution(\\\"2 apples and 3 oranges\\\", 100) -> 95\\n    fruit_distribution(\\\"100 apples and 1 oranges\\\", 120) -> 19\\n    \\\"\\\"\\\"\\n    \\n    # Extract the number of apples and oranges from the string\\n    parts = s.split()\\n    apples = int(parts[0])  # First part is the number of apples\\n    oranges = int(parts[3])  # Fourth part is the number of oranges\\n    \\n    # Calculate the number of mangoes\\n    mangoes = n - apples - oranges\\n    \\n    return mangoes\"}\n",
-    "\n",
-    "print(correct_result[\"solution\"])\n",
-    "\n",
-    "print(\"--------------------------\")\n",
-    "\n",
-    "modify_result = {'task_id': 'HumanEval/67', 'solution': 'def fruit_distribution(s, n):\\n    \"\"\"\\n    Calculate the number of mango fruits in a basket given the number of apples and oranges.\\n\\n    Parameters:\\n    s (str): A string representing the number of apples and oranges in the format \"X apples and Y oranges\".\\n    n (int): An integer representing the total number of fruits in the basket.\\n\\n    Returns:\\n    int: The number of mango fruits in the basket.\\n    \"\"\"\\n    # Split the input string to extract the number of apples and oranges\\n    parts = s.split(\" and \")\\n    apples = int(parts[0].split()[0])  # Get the number of apples\\n    oranges = int(parts[1].split()[0])  # Get the number of oranges\\n\\n    # Calculate the number of mangoes\\n    mangoes = n - apples - oranges\\n\\n    return mangoes'}\n",
-    "\n",
-    "print(modify_result[\"solution\"])"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 12,
-   "metadata": {},
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "\n",
-      "def count_nums(arr):\n",
-      "    \"\"\"\n",
-      "    Write a function count_nums which takes an array of integers and returns\n",
-      "    the number of elements which has a sum of digits > 0.\n",
-      "    If a number is negative, then its first signed digit will be negative:\n",
-      "    e.g. -123 has signed digits -1, 2, and 3.\n",
-      "    >>> count_nums([]) == 0\n",
-      "    >>> count_nums([-1, 11, -11]) == 1\n",
-      "    >>> count_nums([1, 1, 2]) == 3\n",
-      "    \"\"\"\n",
-      "\n",
-      "def count_nums(arr):\n",
-      "    \"\"\"\n",
-      "    Write a function count_nums which takes an array of integers and returns\n",
-      "    the number of elements which has a sum of digits > 0.\n",
-      "    If a number is negative, then its first signed digit will be negative:\n",
-      "    e.g. -123 has signed digits -1, 2, and 3.\n",
-      "    \n",
-      "    >>> count_nums([]) == 0\n",
-      "    >>> count_nums([-1, 11, -11]) == 1\n",
-      "    >>> count_nums([1, 1, 2]) == 3\n",
-      "    \"\"\"\n",
-      "    def sum_of_digits(n):\n",
-      "        # Convert the number to string and calculate the sum of its digits\n",
-      "        return sum(int(digit) if digit != '-' else -int(digit[1]) for digit in str(n) if digit.isdigit() or digit == '-')\n",
-      "\n",
-      "    count = 0\n",
-      "    for number in arr:\n",
-      "        if sum_of_digits(number) > 0:\n",
-      "            count += 1\n",
-      "            \n",
-      "    return count\n",
-      "--------------------------\n",
-      "def count_nums(arr):\n",
-      "    \"\"\"\n",
-      "    Write a function count_nums which takes an array of integers and returns\n",
-      "    the number of elements which has a sum of digits > 0.\n",
-      "    If a number is negative, then its first signed digit will be negative:\n",
-      "    e.g. -123 has signed digits -1, 2, and 3.\n",
-      "    \n",
-      "    >>> count_nums([]) == 0\n",
-      "    >>> count_nums([-1, 11, -11]) == 1\n",
-      "    >>> count_nums([1, 1, 2]) == 3\n",
-      "    \"\"\"\n",
-      "    def sum_of_digits(n):\n",
-      "        # Convert the number to string and calculate the sum of its digits\n",
-      "        # For negative numbers, we need to consider the first digit as negative\n",
-      "        str_n = str(n)\n",
-      "        if n < 0:\n",
-      "            return -int(str_n[1]) + sum(int(digit) for digit in str_n[2:])\n",
-      "        else:\n",
-      "            return sum(int(digit) for digit in str_n)\n",
-      "\n",
-      "    count = 0\n",
-      "    for num in arr:\n",
-      "        if sum_of_digits(num) > 0:\n",
-      "            count += 1\n",
-      "            \n",
-      "    return count\n",
-      "--------------------------\n",
-      "def count_nums(arr):\n",
-      "    \"\"\"\n",
-      "    Write a function count_nums which takes an array of integers and returns\n",
-      "    the number of elements which has a sum of digits > 0.\n",
-      "    If a number is negative, then its first signed digit will be negative:\n",
-      "    e.g. -123 has signed digits -1, 2, and 3.\n",
-      "    \n",
-      "    >>> count_nums([]) == 0\n",
-      "    >>> count_nums([-1, 11, -11]) == 1\n",
-      "    >>> count_nums([1, 1, 2]) == 3\n",
-      "    \"\"\"\n",
-      "    \n",
-      "    def sum_of_digits(n):\n",
-      "        \"\"\"Helper function to calculate the sum of digits of a number.\"\"\"\n",
-      "        # Convert the number to string and iterate over each character\n",
-      "        # If the number is negative, we need to consider the first digit as negative\n",
-      "        str_n = str(n)\n",
-      "        digit_sum = 0\n",
-      "        \n",
-      "        for i, char in enumerate(str_n):\n",
-      "            if char.isdigit():\n",
-      "                digit_sum += int(char)\n",
-      "            elif i == 0 and char == '-':\n",
-      "                digit_sum -= 1  # First signed digit is negative\n",
-      "        \n",
-      "        return digit_sum\n",
-      "\n",
-      "    count = 0\n",
-      "    for number in arr:\n",
-      "        if sum_of_digits(number) > 0:\n",
-      "            count += 1\n",
-      "            \n",
-      "    return count\n"
-     ]
-    }
-   ],
-   "source": [
-    "from evalplus.data import get_human_eval_plus\n",
-    "\n",
-    "humaneval = get_human_eval_plus()\n",
-    "print(humaneval['HumanEval/108'][\"prompt\"])\n",
-    "\n",
-    "result = {\"solution\": \"def count_nums(arr):\\n    \\\"\\\"\\\"\\n    Write a function count_nums which takes an array of integers and returns\\n    the number of elements which has a sum of digits > 0.\\n    If a number is negative, then its first signed digit will be negative:\\n    e.g. -123 has signed digits -1, 2, and 3.\\n    \\n    >>> count_nums([]) == 0\\n    >>> count_nums([-1, 11, -11]) == 1\\n    >>> count_nums([1, 1, 2]) == 3\\n    \\\"\\\"\\\"\\n    def sum_of_digits(n):\\n        # Convert the number to string and calculate the sum of its digits\\n        return sum(int(digit) if digit != '-' else -int(digit[1]) for digit in str(n) if digit.isdigit() or digit == '-')\\n\\n    count = 0\\n    for number in arr:\\n        if sum_of_digits(number) > 0:\\n            count += 1\\n            \\n    return count\"}\n",
-    "print(result[\"solution\"])\n",
-    "\n",
-    "print(\"--------------------------\")\n",
-    "\n",
-    "correct_result = {\"solution\": \"def count_nums(arr):\\n    \\\"\\\"\\\"\\n    Write a function count_nums which takes an array of integers and returns\\n    the number of elements which has a sum of digits > 0.\\n    If a number is negative, then its first signed digit will be negative:\\n    e.g. -123 has signed digits -1, 2, and 3.\\n    \\n    >>> count_nums([]) == 0\\n    >>> count_nums([-1, 11, -11]) == 1\\n    >>> count_nums([1, 1, 2]) == 3\\n    \\\"\\\"\\\"\\n    def sum_of_digits(n):\\n        # Convert the number to string and calculate the sum of its digits\\n        # For negative numbers, we need to consider the first digit as negative\\n        str_n = str(n)\\n        if n < 0:\\n            return -int(str_n[1]) + sum(int(digit) for digit in str_n[2:])\\n        else:\\n            return sum(int(digit) for digit in str_n)\\n\\n    count = 0\\n    for num in arr:\\n        if sum_of_digits(num) > 0:\\n            count += 1\\n            \\n    return count\"}\n",
-    "print(correct_result[\"solution\"])\n",
-    "\n",
-    "print(\"--------------------------\")\n",
-    "\n",
-    "modify_result = {'task_id': 'HumanEval/108', 'solution': 'def count_nums(arr):\\n    \"\"\"\\n    Write a function count_nums which takes an array of integers and returns\\n    the number of elements which has a sum of digits > 0.\\n    If a number is negative, then its first signed digit will be negative:\\n    e.g. -123 has signed digits -1, 2, and 3.\\n    \\n    >>> count_nums([]) == 0\\n    >>> count_nums([-1, 11, -11]) == 1\\n    >>> count_nums([1, 1, 2]) == 3\\n    \"\"\"\\n    \\n    def sum_of_digits(n):\\n        \"\"\"Helper function to calculate the sum of digits of a number.\"\"\"\\n        # Convert the number to string and iterate over each character\\n        # If the number is negative, we need to consider the first digit as negative\\n        str_n = str(n)\\n        digit_sum = 0\\n        \\n        for i, char in enumerate(str_n):\\n            if char.isdigit():\\n                digit_sum += int(char)\\n            elif i == 0 and char == \\'-\\':\\n                digit_sum -= 1  # First signed digit is negative\\n        \\n        return digit_sum\\n\\n    count = 0\\n    for number in arr:\\n        if sum_of_digits(number) > 0:\\n            count += 1\\n            \\n    return count'}\n",
-    "\n",
-    "print(modify_result[\"solution\"])"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 10,
-   "metadata": {},
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "\n",
-      "def exchange(lst1, lst2):\n",
-      "    \"\"\"In this problem, you will implement a function that takes two lists of numbers,\n",
-      "    and determines whether it is possible to perform an exchange of elements\n",
-      "    between them to make lst1 a list of only even numbers.\n",
-      "    There is no limit on the number of exchanged elements between lst1 and lst2.\n",
-      "    If it is possible to exchange elements between the lst1 and lst2 to make\n",
-      "    all the elements of lst1 to be even, return \"YES\".\n",
-      "    Otherwise, return \"NO\".\n",
-      "    For example:\n",
-      "    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"YES\"\n",
-      "    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n",
-      "    It is assumed that the input lists will be non-empty.\n",
-      "    \"\"\"\n",
-      "\n",
-      "def exchange(lst1, lst2):\n",
-      "    \"\"\"Determines whether it is possible to perform an exchange of elements\n",
-      "    between two lists to make lst1 a list of only even numbers.\n",
-      "    \n",
-      "    Args:\n",
-      "    lst1 (list): The first list of numbers.\n",
-      "    lst2 (list): The second list of numbers.\n",
-      "    \n",
-      "    Returns:\n",
-      "    str: \"YES\" if lst1 can be made all even, \"NO\" otherwise.\n",
-      "    \"\"\"\n",
-      "    # Check if lst1 already contains only even numbers\n",
-      "    if all(x % 2 == 0 for x in lst1):\n",
-      "        return \"YES\"\n",
-      "    \n",
-      "    # Count the number of odd numbers in lst1\n",
-      "    odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n",
-      "    \n",
-      "    # Check if lst2 has at least one even number to exchange\n",
-      "    has_even_in_lst2 = any(x % 2 == 0 for x in lst2)\n",
-      "    \n",
-      "    # If lst1 has odd numbers and lst2 has at least one even number, we can exchange\n",
-      "    if odd_count_lst1 > 0 and has_even_in_lst2:\n",
-      "        return \"YES\"\n",
-      "    \n",
-      "    return \"NO\"\n",
-      "--------------------------\n",
-      "def exchange(lst1, lst2):\n",
-      "    \"\"\"In this problem, you will implement a function that takes two lists of numbers,\n",
-      "    and determines whether it is possible to perform an exchange of elements\n",
-      "    between them to make lst1 a list of only even numbers.\n",
-      "    There is no limit on the number of exchanged elements between lst1 and lst2.\n",
-      "    If it is possible to exchange elements between the lst1 and lst2 to make\n",
-      "    all the elements of lst1 to be even, return \"YES\".\n",
-      "    Otherwise, return \"NO\".\n",
-      "    For example:\n",
-      "    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"YES\"\n",
-      "    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n",
-      "    It is assumed that the input lists will be non-empty.\n",
-      "    \"\"\"\n",
-      "    \n",
-      "    # Count the number of odd numbers in lst1\n",
-      "    odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\n",
-      "    \n",
-      "    # Count the number of even numbers in lst2\n",
-      "    even_count_lst2 = sum(1 for x in lst2 if x % 2 == 0)\n",
-      "    \n",
-      "    # If there are no odd numbers in lst1, it's already valid\n",
-      "    if odd_count_lst1 == 0:\n",
-      "        return \"YES\"\n",
-      "    \n",
-      "    # If there are enough even numbers in lst2 to replace all odd numbers in lst1\n",
-      "    if even_count_lst2 >= odd_count_lst1:\n",
-      "        return \"YES\"\n",
-      "    \n",
-      "    return \"NO\"\n"
-     ]
-    }
-   ],
-   "source": [
-    "from evalplus.data import get_human_eval_plus\n",
-    "\n",
-    "humaneval = get_human_eval_plus()\n",
-    "print(humaneval['HumanEval/110'][\"prompt\"])\n",
-    "\n",
-    "result = {\"solution\": \"def exchange(lst1, lst2):\\n    \\\"\\\"\\\"Determines whether it is possible to perform an exchange of elements\\n    between two lists to make lst1 a list of only even numbers.\\n    \\n    Args:\\n    lst1 (list): The first list of numbers.\\n    lst2 (list): The second list of numbers.\\n    \\n    Returns:\\n    str: \\\"YES\\\" if lst1 can be made all even, \\\"NO\\\" otherwise.\\n    \\\"\\\"\\\"\\n    # Check if lst1 already contains only even numbers\\n    if all(x % 2 == 0 for x in lst1):\\n        return \\\"YES\\\"\\n    \\n    # Count the number of odd numbers in lst1\\n    odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\\n    \\n    # Check if lst2 has at least one even number to exchange\\n    has_even_in_lst2 = any(x % 2 == 0 for x in lst2)\\n    \\n    # If lst1 has odd numbers and lst2 has at least one even number, we can exchange\\n    if odd_count_lst1 > 0 and has_even_in_lst2:\\n        return \\\"YES\\\"\\n    \\n    return \\\"NO\\\"\"}\n",
-    "print(result[\"solution\"])\n",
-    "\n",
-    "print(\"--------------------------\")\n",
-    "\n",
-    "correct_result = {\"solution\": \"def exchange(lst1, lst2):\\n    \\\"\\\"\\\"In this problem, you will implement a function that takes two lists of numbers,\\n    and determines whether it is possible to perform an exchange of elements\\n    between them to make lst1 a list of only even numbers.\\n    There is no limit on the number of exchanged elements between lst1 and lst2.\\n    If it is possible to exchange elements between the lst1 and lst2 to make\\n    all the elements of lst1 to be even, return \\\"YES\\\".\\n    Otherwise, return \\\"NO\\\".\\n    For example:\\n    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \\\"YES\\\"\\n    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \\\"NO\\\"\\n    It is assumed that the input lists will be non-empty.\\n    \\\"\\\"\\\"\\n    \\n    # Count the number of odd numbers in lst1\\n    odd_count_lst1 = sum(1 for x in lst1 if x % 2 != 0)\\n    \\n    # Count the number of even numbers in lst2\\n    even_count_lst2 = sum(1 for x in lst2 if x % 2 == 0)\\n    \\n    # If there are no odd numbers in lst1, it's already valid\\n    if odd_count_lst1 == 0:\\n        return \\\"YES\\\"\\n    \\n    # If there are enough even numbers in lst2 to replace all odd numbers in lst1\\n    if even_count_lst2 >= odd_count_lst1:\\n        return \\\"YES\\\"\\n    \\n    return \\\"NO\\\"\"}\n",
-    "print(correct_result[\"solution\"])"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 14,
-   "metadata": {},
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "\n",
-      "\n",
-      "def count_distinct_characters(string: str) -> int:\n",
-      "    \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n",
-      "    >>> count_distinct_characters('xyzXYZ')\n",
-      "    3\n",
-      "    >>> count_distinct_characters('Jerry')\n",
-      "    4\n",
-      "    \"\"\"\n",
-      "\n",
-      "def count_distinct_characters(string: str) -> int:\n",
-      "    \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n",
-      "    >>> count_distinct_characters('xyzXYZ')\n",
-      "    3\n",
-      "    >>> count_distinct_characters('Jerry')\n",
-      "    4\n",
-      "    \"\"\"\n",
-      "    # Convert the string to lowercase to ensure case insensitivity\n",
-      "    lower_string = string.lower()\n",
-      "    # Use a set to find distinct characters\n",
-      "    distinct_characters = set(lower_string)\n",
-      "    # Return the number of distinct characters\n",
-      "    return len(distinct_characters)\n",
-      "--------------------------\n",
-      "def count_distinct_characters(string: str) -> int:\n",
-      "    \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n",
-      "    >>> count_distinct_characters('xyzXYZ')\n",
-      "    3\n",
-      "    >>> count_distinct_characters('Jerry')\n",
-      "    4\n",
-      "    \"\"\"\n",
-      "    # Convert the string to lowercase to ensure case insensitivity\n",
-      "    lower_string = string.lower()\n",
-      "    # Use a set to find distinct characters\n",
-      "    distinct_characters = set(lower_string)\n",
-      "    # Return the number of distinct characters\n",
-      "    return len(distinct_characters)\n",
-      "--------------------------\n",
-      "def count_distinct_characters(string: str) -> int:\n",
-      "    \"\"\" \n",
-      "    Given a string, find out how many distinct characters (regardless of case) does it consist of.\n",
-      "    \n",
-      "    >>> count_distinct_characters('xyzXYZ')\n",
-      "    3\n",
-      "    >>> count_distinct_characters('Jerry')\n",
-      "    4\n",
-      "    >>> count_distinct_characters('')\n",
-      "    0\n",
-      "    >>> count_distinct_characters('aA')\n",
-      "    1\n",
-      "    >>> count_distinct_characters('123abcABC!@#')\n",
-      "    9\n",
-      "    >>> count_distinct_characters('   ')\n",
-      "    0\n",
-      "    >>> count_distinct_characters('!@#$%^&*()')\n",
-      "    10\n",
-      "    \"\"\"\n",
-      "    # Convert the string to lowercase to ensure case insensitivity\n",
-      "    lower_string = string.lower()\n",
-      "    \n",
-      "    # Use a set to store distinct characters\n",
-      "    distinct_characters = set()\n",
-      "    \n",
-      "    # Iterate through each character in the string\n",
-      "    for char in lower_string:\n",
-      "        # Add only non-space characters to the set\n",
-      "        if char != ' ':\n",
-      "            distinct_characters.add(char)\n",
-      "    \n",
-      "    # Return the number of distinct characters\n",
-      "    return len(distinct_characters)\n"
-     ]
-    }
-   ],
-   "source": [
-    "from evalplus.data import get_human_eval_plus\n",
-    "\n",
-    "humaneval = get_human_eval_plus()\n",
-    "print(humaneval['HumanEval/16'][\"prompt\"])\n",
-    "\n",
-    "result = {\"task_id\": \"HumanEval/16\", \"solution\": \"def count_distinct_characters(string: str) -> int:\\n    \\\"\\\"\\\" Given a string, find out how many distinct characters (regardless of case) does it consist of\\n    >>> count_distinct_characters('xyzXYZ')\\n    3\\n    >>> count_distinct_characters('Jerry')\\n    4\\n    \\\"\\\"\\\"\\n    # Convert the string to lowercase to ensure case insensitivity\\n    lower_string = string.lower()\\n    # Use a set to find distinct characters\\n    distinct_characters = set(lower_string)\\n    # Return the number of distinct characters\\n    return len(distinct_characters)\"}\n",
-    "print(result[\"solution\"])\n",
-    "\n",
-    "print(\"--------------------------\")\n",
-    "\n",
-    "correct_result = {\"task_id\": \"HumanEval/16\", \"solution\": \"def count_distinct_characters(string: str) -> int:\\n    \\\"\\\"\\\" Given a string, find out how many distinct characters (regardless of case) does it consist of\\n    >>> count_distinct_characters('xyzXYZ')\\n    3\\n    >>> count_distinct_characters('Jerry')\\n    4\\n    \\\"\\\"\\\"\\n    # Convert the string to lowercase to ensure case insensitivity\\n    lower_string = string.lower()\\n    # Use a set to find distinct characters\\n    distinct_characters = set(lower_string)\\n    # Return the number of distinct characters\\n    return len(distinct_characters)\"}\n",
-    "\n",
-    "print(correct_result[\"solution\"])\n",
-    "\n",
-    "print(\"--------------------------\")\n",
-    "\n",
-    "modify_result = {\"task_id\": \"HumanEval/16\", \"solution\": \"def count_distinct_characters(string: str) -> int:\\n    \\\"\\\"\\\" \\n    Given a string, find out how many distinct characters (regardless of case) does it consist of.\\n    \\n    >>> count_distinct_characters('xyzXYZ')\\n    3\\n    >>> count_distinct_characters('Jerry')\\n    4\\n    >>> count_distinct_characters('')\\n    0\\n    >>> count_distinct_characters('aA')\\n    1\\n    >>> count_distinct_characters('123abcABC!@#')\\n    9\\n    >>> count_distinct_characters('   ')\\n    0\\n    >>> count_distinct_characters('!@#$%^&*()')\\n    10\\n    \\\"\\\"\\\"\\n    # Convert the string to lowercase to ensure case insensitivity\\n    lower_string = string.lower()\\n    \\n    # Use a set to store distinct characters\\n    distinct_characters = set()\\n    \\n    # Iterate through each character in the string\\n    for char in lower_string:\\n        # Add only non-space characters to the set\\n        if char != ' ':\\n            distinct_characters.add(char)\\n    \\n    # Return the number of distinct characters\\n    return len(distinct_characters)\"}\n",
-    "\n",
-    "print(modify_result[\"solution\"])"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 16,
-   "metadata": {},
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "\n",
-      "def fix_spaces(text):\n",
-      "    \"\"\"\n",
-      "    Given a string text, replace all spaces in it with underscores, \n",
-      "    and if a string has more than 2 consecutive spaces, \n",
-      "    then replace all consecutive spaces with - \n",
-      "    \n",
-      "    fix_spaces(\"Example\") == \"Example\"\n",
-      "    fix_spaces(\"Example 1\") == \"Example_1\"\n",
-      "    fix_spaces(\" Example 2\") == \"_Example_2\"\n",
-      "    fix_spaces(\" Example   3\") == \"_Example-3\"\n",
-      "    \"\"\"\n",
-      "\n",
-      "def fix_spaces(text):\n",
-      "    \"\"\"\n",
-      "    Given a string text, replace all spaces in it with underscores, \n",
-      "    and if a string has more than 2 consecutive spaces, \n",
-      "    then replace all consecutive spaces with - \n",
-      "    \n",
-      "    fix_spaces(\"Example\") == \"Example\"\n",
-      "    fix_spaces(\"Example 1\") == \"Example_1\"\n",
-      "    fix_spaces(\" Example 2\") == \"_Example_2\"\n",
-      "    fix_spaces(\" Example   3\") == \"_Example-3\"\n",
-      "    \"\"\"\n",
-      "    # Replace multiple spaces with a placeholder\n",
-      "    # This will help us identify sequences of spaces\n",
-      "    placeholder = '##'\n",
-      "    text = text.replace(' ' * 3, placeholder)  # Replace 3 spaces with a placeholder\n",
-      "    \n",
-      "    # Replace remaining spaces with underscores\n",
-      "    text = text.replace(' ', '_')\n",
-      "    \n",
-      "    # Replace the placeholder back to '-'\n",
-      "    text = text.replace(placeholder, '-')\n",
-      "    \n",
-      "    return text\n",
-      "--------------------------\n",
-      "def fix_spaces(text):\n",
-      "    \"\"\"\n",
-      "    Given a string text, replace all spaces in it with underscores, \n",
-      "    and if a string has more than 2 consecutive spaces, \n",
-      "    then replace all consecutive spaces with - \n",
-      "    \n",
-      "    fix_spaces(\"Example\") == \"Example\"\n",
-      "    fix_spaces(\"Example 1\") == \"Example_1\"\n",
-      "    fix_spaces(\" Example 2\") == \"_Example_2\"\n",
-      "    fix_spaces(\" Example   3\") == \"_Example-3\"\n",
-      "    \"\"\"\n",
-      "    # Replace multiple spaces with a placeholder\n",
-      "    # This will help us identify sequences of spaces\n",
-      "    placeholder = ' ' * 3  # Three spaces\n",
-      "    text = text.replace(placeholder, ' - ')\n",
-      "    \n",
-      "    # Replace all remaining spaces with underscores\n",
-      "    text = text.replace(' ', '_')\n",
-      "    \n",
-      "    # Replace the placeholder with a single dash\n",
-      "    text = text.replace(' - ', '-')\n",
-      "    \n",
-      "    return text\n"
-     ]
-    }
-   ],
-   "source": [
-    "\n",
-    "from evalplus.data import get_human_eval_plus\n",
-    "\n",
-    "humaneval = get_human_eval_plus()\n",
-    "print(humaneval['HumanEval/140'][\"prompt\"])\n",
-    "\n",
-    "correct_result = {\"task_id\": \"HumanEval/140\", \"solution\": \"def fix_spaces(text):\\n    \\\"\\\"\\\"\\n    Given a string text, replace all spaces in it with underscores, \\n    and if a string has more than 2 consecutive spaces, \\n    then replace all consecutive spaces with - \\n    \\n    fix_spaces(\\\"Example\\\") == \\\"Example\\\"\\n    fix_spaces(\\\"Example 1\\\") == \\\"Example_1\\\"\\n    fix_spaces(\\\" Example 2\\\") == \\\"_Example_2\\\"\\n    fix_spaces(\\\" Example   3\\\") == \\\"_Example-3\\\"\\n    \\\"\\\"\\\"\\n    # Replace multiple spaces with a placeholder\\n    # This will help us identify sequences of spaces\\n    placeholder = '##'\\n    text = text.replace(' ' * 3, placeholder)  # Replace 3 spaces with a placeholder\\n    \\n    # Replace remaining spaces with underscores\\n    text = text.replace(' ', '_')\\n    \\n    # Replace the placeholder back to '-'\\n    text = text.replace(placeholder, '-')\\n    \\n    return text\"}\n",
-    "\n",
-    "print(correct_result[\"solution\"])\n",
-    "\n",
-    "print(\"--------------------------\")\n",
-    "\n",
-    "modify_result = {\"task_id\": \"HumanEval/140\", \"solution\": \"def fix_spaces(text):\\n    \\\"\\\"\\\"\\n    Given a string text, replace all spaces in it with underscores, \\n    and if a string has more than 2 consecutive spaces, \\n    then replace all consecutive spaces with - \\n    \\n    fix_spaces(\\\"Example\\\") == \\\"Example\\\"\\n    fix_spaces(\\\"Example 1\\\") == \\\"Example_1\\\"\\n    fix_spaces(\\\" Example 2\\\") == \\\"_Example_2\\\"\\n    fix_spaces(\\\" Example   3\\\") == \\\"_Example-3\\\"\\n    \\\"\\\"\\\"\\n    # Replace multiple spaces with a placeholder\\n    # This will help us identify sequences of spaces\\n    placeholder = ' ' * 3  # Three spaces\\n    text = text.replace(placeholder, ' - ')\\n    \\n    # Replace all remaining spaces with underscores\\n    text = text.replace(' ', '_')\\n    \\n    # Replace the placeholder with a single dash\\n    text = text.replace(' - ', '-')\\n    \\n    return text\"}\n",
-    "\n",
-    "print(modify_result[\"solution\"])"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 8,
-   "metadata": {},
-   "outputs": [],
-   "source": [
-    "def fix_spaces(text):\n",
-    "    \"\"\"\n",
-    "    Given a string text, replace all spaces in it with underscores, \n",
-    "    and if a string has more than 2 consecutive spaces, \n",
-    "    then replace all consecutive spaces with - \n",
-    "    \n",
-    "    fix_spaces(\"Example\") == \"Example\"\n",
-    "    fix_spaces(\"Example 1\") == \"Example_1\"\n",
-    "    fix_spaces(\" Example 2\") == \"_Example_2\"\n",
-    "    fix_spaces(\" Example   3\") == \"_Example-3\"\n",
-    "    \"\"\"\n",
-    "    # Replace multiple spaces with a hyphen\n",
-    "    while '   ' in text:  # While there are more than 2 consecutive spaces\n",
-    "        text = text.replace('   ', '-')\n",
-    "    \n",
-    "    # Replace single spaces with underscores\n",
-    "    text = text.replace(' ', '_')\n",
-    "    \n",
-    "    return text\n",
-    "\n",
-    "def check(candidate):\n",
-    "    assert candidate('Example') == 'Example'\n",
-    "    assert candidate('Mudasir Hanif ') == 'Mudasir_Hanif_'\n",
-    "    assert candidate('Yellow Yellow  Dirty  Fellow') == 'Yellow_Yellow__Dirty__Fellow'\n",
-    "    assert candidate('Exa   mple') == 'Exa-mple'\n",
-    "    assert candidate('   Exa 1 2 2 mple') == '-Exa_1_2_2_mple'\n",
-    "\n",
-    "\n",
-    "check(fix_spaces)"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 13,
-   "metadata": {},
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "Example\n",
-      "Mudasir_Hanif\n"
-     ]
-    },
-    {
-     "ename": "AssertionError",
-     "evalue": "",
-     "output_type": "error",
-     "traceback": [
-      "\u001b[0;31m---------------------------------------------------------------------------\u001b[0m",
-      "\u001b[0;31mAssertionError\u001b[0m                            Traceback (most recent call last)",
-      "Cell \u001b[0;32mIn[13], line 32\u001b[0m\n\u001b[1;32m     29\u001b[0m \u001b[38;5;28;01mdef\u001b[39;00m \u001b[38;5;21mtest_check\u001b[39m():\n\u001b[1;32m     30\u001b[0m     check(fix_spaces)\n\u001b[0;32m---> 32\u001b[0m \u001b[43mtest_check\u001b[49m\u001b[43m(\u001b[49m\u001b[43m)\u001b[49m\n",
-      "Cell \u001b[0;32mIn[13], line 30\u001b[0m, in \u001b[0;36mtest_check\u001b[0;34m()\u001b[0m\n\u001b[1;32m     29\u001b[0m \u001b[38;5;28;01mdef\u001b[39;00m \u001b[38;5;21mtest_check\u001b[39m():\n\u001b[0;32m---> 30\u001b[0m     \u001b[43mcheck\u001b[49m\u001b[43m(\u001b[49m\u001b[43mfix_spaces\u001b[49m\u001b[43m)\u001b[49m\n",
-      "Cell \u001b[0;32mIn[13], line 24\u001b[0m, in \u001b[0;36mcheck\u001b[0;34m(candidate)\u001b[0m\n\u001b[1;32m     22\u001b[0m \u001b[38;5;28;01mdef\u001b[39;00m \u001b[38;5;21mcheck\u001b[39m(candidate):\n\u001b[1;32m     23\u001b[0m     \u001b[38;5;28;01massert\u001b[39;00m candidate(\u001b[38;5;124m'\u001b[39m\u001b[38;5;124mExample\u001b[39m\u001b[38;5;124m'\u001b[39m) \u001b[38;5;241m==\u001b[39m \u001b[38;5;124m'\u001b[39m\u001b[38;5;124mExample\u001b[39m\u001b[38;5;124m'\u001b[39m\n\u001b[0;32m---> 24\u001b[0m     \u001b[38;5;28;01massert\u001b[39;00m candidate(\u001b[38;5;124m'\u001b[39m\u001b[38;5;124mMudasir Hanif \u001b[39m\u001b[38;5;124m'\u001b[39m) \u001b[38;5;241m==\u001b[39m \u001b[38;5;124m'\u001b[39m\u001b[38;5;124mMudasir_Hanif_\u001b[39m\u001b[38;5;124m'\u001b[39m\n\u001b[1;32m     25\u001b[0m     \u001b[38;5;28;01massert\u001b[39;00m candidate(\u001b[38;5;124m'\u001b[39m\u001b[38;5;124mYellow Yellow  Dirty  Fellow\u001b[39m\u001b[38;5;124m'\u001b[39m) \u001b[38;5;241m==\u001b[39m \u001b[38;5;124m'\u001b[39m\u001b[38;5;124mYellow_Yellow__Dirty__Fellow\u001b[39m\u001b[38;5;124m'\u001b[39m\n\u001b[1;32m     26\u001b[0m     \u001b[38;5;28;01massert\u001b[39;00m candidate(\u001b[38;5;124m'\u001b[39m\u001b[38;5;124mExa   mple\u001b[39m\u001b[38;5;124m'\u001b[39m) \u001b[38;5;241m==\u001b[39m \u001b[38;5;124m'\u001b[39m\u001b[38;5;124mExa-mple\u001b[39m\u001b[38;5;124m'\u001b[39m\n",
-      "\u001b[0;31mAssertionError\u001b[0m: "
-     ]
-    }
-   ],
-   "source": [
-    "import re\n",
-    "\n",
-    "def fix_spaces(text):\n",
-    "    \"\"\"\n",
-    "    Given a string text, replace all spaces in it with underscores, \n",
-    "    and if a string has more than 2 consecutive spaces, \n",
-    "    then replace all consecutive spaces with - \n",
-    "    \n",
-    "    fix_spaces(\"Example\") == \"Example\"\n",
-    "    fix_spaces(\"Example 1\") == \"Example_1\"\n",
-    "    fix_spaces(\" Example 2\") == \"_Example_2\"\n",
-    "    fix_spaces(\" Example   3\") == \"_Example-3\"\n",
-    "    \"\"\"\n",
-    "    # Replace multiple spaces with a hyphen\n",
-    "    text = re.sub(r' {3,}', '-', text)\n",
-    "    # Replace single spaces with underscores\n",
-    "    text = text.replace(' ', '_')\n",
-    "    # Handle leading and trailing underscores\n",
-    "    print(text.strip('_'))\n",
-    "\n",
-    "def check(candidate):\n",
-    "    assert candidate('Example') == 'Example'\n",
-    "    assert candidate('Mudasir Hanif ') == 'Mudasir_Hanif_'\n",
-    "    assert candidate('Yellow Yellow  Dirty  Fellow') == 'Yellow_Yellow__Dirty__Fellow'\n",
-    "    assert candidate('Exa   mple') == 'Exa-mple'\n",
-    "    assert candidate('   Exa 1 2 2 mple') == '-Exa_1_2_2_mple'\n",
-    "\n",
-    "def test_check():\n",
-    "    check(fix_spaces)\n",
-    "\n",
-    "test_check()"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 10,
-   "metadata": {},
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "import re\n",
-      "\n",
-      "def fix_spaces(text):\n",
-      "    \"\"\"\n",
-      "    Given a string text, replace all spaces in it with underscores, \n",
-      "    and if a string has more than 2 consecutive spaces, \n",
-      "    then replace all consecutive spaces with - \n",
-      "    \n",
-      "    fix_spaces(\"Example\") == \"Example\"\n",
-      "    fix_spaces(\"Example 1\") == \"Example_1\"\n",
-      "    fix_spaces(\" Example 2\") == \"_Example_2\"\n",
-      "    fix_spaces(\" Example   3\") == \"_Example-3\"\n",
-      "    \"\"\"\n",
-      "    # Replace multiple spaces with a hyphen\n",
-      "    text = re.sub(r' {3,}', '-', text)\n",
-      "    # Replace single spaces with underscores\n",
-      "    text = text.replace(' ', '_')\n",
-      "    # Handle leading and trailing underscores\n",
-      "    return text.strip('_')\n"
-     ]
-    }
-   ],
-   "source": [
-    "result = {\n",
-    "    \"reflection\": \"The original code attempts to replace multiple spaces with a hyphen and single spaces with underscores, but it only checks for three consecutive spaces. This approach fails for cases with more than three consecutive spaces and does not handle leading and trailing spaces correctly. Additionally, the order of replacements can lead to incorrect results. A better approach is to use regular expressions to handle all cases in a single pass, ensuring that we replace multiple spaces with a hyphen and single spaces with underscores while also managing leading and trailing spaces appropriately.\",\n",
-    "    \"refined_solution\": \"import re\\n\\ndef fix_spaces(text):\\n    \\\"\\\"\\\"\\n    Given a string text, replace all spaces in it with underscores, \\n    and if a string has more than 2 consecutive spaces, \\n    then replace all consecutive spaces with - \\n    \\n    fix_spaces(\\\"Example\\\") == \\\"Example\\\"\\n    fix_spaces(\\\"Example 1\\\") == \\\"Example_1\\\"\\n    fix_spaces(\\\" Example 2\\\") == \\\"_Example_2\\\"\\n    fix_spaces(\\\" Example   3\\\") == \\\"_Example-3\\\"\\n    \\\"\\\"\\\"\\n    # Replace multiple spaces with a hyphen\\n    text = re.sub(r' {3,}', '-', text)\\n    # Replace single spaces with underscores\\n    text = text.replace(' ', '_')\\n    # Handle leading and trailing underscores\\n    return text.strip('_')\"\n",
-    "}\n",
-    "print(result['refined_solution'])"
-   ]
-  }
- ],
- "metadata": {
-  "kernelspec": {
-   "display_name": "ags_env",
-   "language": "python",
-   "name": "python3"
-  },
-  "language_info": {
-   "codemirror_mode": {
-    "name": "ipython",
-    "version": 3
-   },
-   "file_extension": ".py",
-   "mimetype": "text/x-python",
-   "name": "python",
-   "nbconvert_exporter": "python",
-   "pygments_lexer": "ipython3",
-   "version": "3.9.19"
-  }
- },
- "nbformat": 4,
- "nbformat_minor": 2
-}
diff --git a/io_humaneval.py b/io_humaneval.py
deleted file mode 100644
index 7507c5910..000000000
--- a/io_humaneval.py
+++ /dev/null
@@ -1,53 +0,0 @@
-from examples.ags.scripts.operator import Operator
-from examples.ags.scripts.graph import SolveGraph
-from examples.ags.benchmark.humaneval import humaneval_evaluation
-from examples.ags.scripts.operator_an import GenerateOp
-from metagpt.actions.action_node import ActionNode 
-from metagpt.configs.models_config import ModelsConfig
-from metagpt.llm import LLM
-from pydantic import BaseModel, Field
-
-HUMANEVAL_PROMPT_IO = """
-{question}\nGenerate an answer to this question, without any additional test cases. 
-"""
-
-class GenerateOp(BaseModel):
-    solution: str = Field(default="", description="Python Solution For This Question.")
-
-class Generate(Operator):
-    def __init__(self, llm: LLM, name: str = "Generate"):
-        super().__init__(name, llm)
-
-    async def __call__(self, problem, function_name, mode: str = None):
-        prompt = HUMANEVAL_PROMPT_IO.format(question=problem)
-        fill_kwargs = {"context": prompt, "llm": self.llm, "function_name": function_name}
-        if mode:
-            fill_kwargs["mode"] = mode
-        node = await ActionNode.from_pydantic(GenerateOp).fill(**fill_kwargs)
-        response = node.instruct_content.model_dump()
-        return response
-
-class IOSolveGraph(SolveGraph):
-    def __init__(self, name: str, llm_config, dataset: str):
-        super().__init__(name, llm_config, dataset)
-        self.cot_generate = Generate(self.llm)
-
-    async def __call__(self, problem, function_name):
-        solution = await self.cot_generate(problem, function_name, mode="code_fill")
-        return solution["solution"], self.llm.cost_manager.total_cost
-
-if __name__ == "__main__":
-    async def main():
-        # llm_config = ModelsConfig.default().get("gpt-4o-mini")
-        # llm_config = ModelsConfig.default().get("gpt-4o")
-        # llm_config = ModelsConfig.default().get("deepseek-chat")
-        llm_config = ModelsConfig.default().get("claude-3-5-sonnet-20240620")
-        graph = IOSolveGraph(name="Io", llm_config=llm_config, dataset="HumanEval")
-        file_path = "examples/ags/data/baseline_data/human-eval.jsonl"
-        samples = 33 # 33/131  
-        path = "examples/ags/data/baselines/general/humaneval"
-        score = await humaneval_evaluation(graph, file_path, samples, path,test=True)
-        return score
-
-    import asyncio
-    asyncio.run(main())
diff --git a/medprompt_humaneval.py b/medprompt_humaneval.py
deleted file mode 100644
index 5e492946d..000000000
--- a/medprompt_humaneval.py
+++ /dev/null
@@ -1,127 +0,0 @@
-from examples.ags.scripts.operator import Operator
-from examples.ags.scripts.graph import SolveGraph
-from examples.ags.benchmark.humaneval import humaneval_evaluation
-from examples.ags.scripts.operator_an import GenerateOp
-from metagpt.actions.action_node import ActionNode 
-from metagpt.configs.models_config import ModelsConfig
-from metagpt.llm import LLM
-from pydantic import BaseModel, Field
-from typing import Dict, Any, List, Tuple
-from collections import Counter
-
-import random
-
-HUMANEVAL_PROMPT_GPT = """
-{question}\nPlease provide a step-by-step explanation in text, followed by your Python function without any additional text or test cases. 
-"""
-
-MD_ENSEMBLE_PROMPT = """
-Given the question described as follows: {question}
-Several solutions have been generated to address the given question. They are as follows:
-{solutions}
-
-Carefully evaluate these solutions and identify the solution that is more capable of solving the problem compared to other solutions, as this is crucial for problem-solving.
-
-In the "thought" field, provide a detailed explanation of your thought process. In the "solution_letter" field, output only the single letter ID (A, B, C, etc.) corresponding to the solution. Do not include any additional text or explanation in the "solution_letter" field.
-"""
-
-class GenerateOp(BaseModel):
-    solution: str = Field(default="", description="Python Solution For This Question.")
-
-class CoTGenerate(Operator):
-    def __init__(self, llm: LLM, name: str = "Generate"):
-        super().__init__(name, llm)
-
-    async def __call__(self, problem, function_name, mode: str = None):
-        prompt = HUMANEVAL_PROMPT_GPT.format(question=problem)
-        fill_kwargs = {"context": prompt, "llm": self.llm, "function_name": function_name}
-        if mode:
-            fill_kwargs["mode"] = mode
-        node = await ActionNode.from_pydantic(GenerateOp).fill(**fill_kwargs)
-        response = node.instruct_content.model_dump()
-        return response
-
-
-class MdEnsembleOp(BaseModel):
-    thought: str = Field(
-        default="",
-        description="Step-by-step analysis of the solutions to determine the best one.",
-    )
-    solution_letter: str = Field(default="", description="The letter of the chosen best solution (only one letter).")
-
-
-class MdEnsemble(Operator):
-    """
-    Paper: Can Generalist Foundation Models Outcompete Special-Purpose Tuning? Case Study in Medicine
-    Link: https://arxiv.org/abs/2311.16452
-    """
-
-    def __init__(self, llm: LLM, name: str = "MdEnsemble", vote_count: int = 5):
-        super().__init__(name, llm)
-        self.vote_count = vote_count
-
-    @staticmethod
-    def shuffle_answers(solutions: List[str]) -> Tuple[List[str], Dict[str, str]]:
-        shuffled_solutions = solutions.copy()
-        random.shuffle(shuffled_solutions)
-        answer_mapping = {chr(65 + i): solutions.index(solution) for i, solution in enumerate(shuffled_solutions)}
-        return shuffled_solutions, answer_mapping
-
-    async def __call__(self, solutions: List[str], problem: str, mode: str = None):
-        print(f"solution count: {len(solutions)}")
-        all_responses = []
-
-        for _ in range(self.vote_count):
-            shuffled_solutions, answer_mapping = self.shuffle_answers(solutions)
-
-            solution_text = ""
-            for index, solution in enumerate(shuffled_solutions):
-                solution_text += f"{chr(65 + index)}: \n{str(solution)}\n\n\n"
-
-            prompt = MD_ENSEMBLE_PROMPT.format(solutions=solution_text, question=problem)
-            fill_kwargs = {"context": prompt, "llm": self.llm}
-            if mode:
-                fill_kwargs["mode"] = mode
-            node = await ActionNode.from_pydantic(MdEnsembleOp).fill(**fill_kwargs)
-            response = node.instruct_content.model_dump()
-
-            answer = response.get("solution_letter", "A")
-            answer = answer.strip().upper()
-
-            if answer in answer_mapping:
-                original_index = answer_mapping[answer]
-                all_responses.append(original_index)
-
-        most_frequent_index = Counter(all_responses).most_common(1)[0][0]
-        final_answer = solutions[most_frequent_index]
-        return {"solution": final_answer}  
-
-class MedPromptGraph(SolveGraph):
-    def __init__(self, name: str, llm_config, dataset: str, vote_count: int = 5):
-        super().__init__(name, llm_config, dataset)
-        self.cot_generate = CoTGenerate(self.llm)
-        self.md_ensemble = MdEnsemble(self.llm, vote_count=vote_count)
-
-    async def __call__(self, problem, function_name):
-        solutions = []
-        for i in range(3):
-            solution = await self.cot_generate(problem, function_name, mode="code_fill")
-            solutions.append(solution["solution"])
-        solution = await self.md_ensemble(solutions, problem, mode="context_fill")
-        return solution["solution"], self.llm.cost_manager.total_cost
-
-if __name__ == "__main__":
-    async def main():
-        # llm_config = ModelsConfig.default().get("gpt-4o-mini")
-        # llm_config = ModelsConfig.default().get("gpt-4o")
-        # llm_config = ModelsConfig.default().get("deepseek-chat")
-        llm_config = ModelsConfig.default().get("claude-3-5-sonnet-20240620")
-        graph = MedPromptGraph(name="MedPrompt", llm_config=llm_config, dataset="HumanEval", vote_count=5)
-        file_path = "examples/ags/data/baseline_data/human-eval.jsonl"
-        samples = 33
-        path = "examples/ags/data/baselines/general/humaneval"
-        score, cost = await humaneval_evaluation(graph, file_path, samples, path, test=True)
-        return score, cost
-
-    import asyncio
-    asyncio.run(main())
\ No newline at end of file
diff --git a/multi_persona_humaneval.py b/multi_persona_humaneval.py
deleted file mode 100644
index 3437da59c..000000000
--- a/multi_persona_humaneval.py
+++ /dev/null
@@ -1,120 +0,0 @@
-from examples.ags.scripts.operator import Operator
-from examples.ags.scripts.graph import SolveGraph
-from examples.ags.benchmark.humaneval import humaneval_evaluation
-from metagpt.actions.action_node import ActionNode 
-from metagpt.configs.models_config import ModelsConfig
-from metagpt.llm import LLM
-from pydantic import BaseModel, Field
-from typing import List
-
-DEBATE_INITIAL_PROMPT = """
-{question}\nPlease provide a step-by-step explanation in text, followed by your Python function without any additional text or test cases. 
-"""
-
-DEBATE_PROMPT = """
-{question}
-Considering the solutions provided by other agents as additional suggestions. Please think carefully and provide an updated python function without any additional text or test cases. 
-"""
-
-FINAL_DECISION_PROMPT = """
-{question}
-Considering all the thinking processes and answers:
-{all_thinking}
-{all_answers}
-Please reason carefully and provide the final answer. Make sure the code output is wrapped with ```python``` without any additional text or test cases.
-"""
-
-class DebateOp(BaseModel):
-    thinking: str = Field(default="", description="think")
-    answer: str = Field(default="", description="answer")
-
-class FinalDecisionOp(BaseModel):
-    solution: str = Field(default="", description="final answer")
-
-class DebateAgent(Operator):
-    def __init__(self, llm: LLM, name: str, role: str):
-        super().__init__(name, llm)
-        self.role = role
-
-    async def __call__(self, problem: str, function_name: str, context: List[str] = None, mode: str = None):
-        role_prompt = f"You are a {self.role}. Based on your professional knowledge and thinking style,"
-        if context is None:
-            prompt = role_prompt + DEBATE_INITIAL_PROMPT.format(question=problem)
-        else:
-            prompt = role_prompt + DEBATE_PROMPT.format(question=problem) + "\n".join(context)
-        
-        fill_kwargs = {"context": prompt, "llm": self.llm, "function_name":function_name}
-        if mode:
-            fill_kwargs["mode"] = mode
-        node = await ActionNode.from_pydantic(DebateOp).fill(**fill_kwargs)
-        return node.instruct_content.model_dump()
-
-class FinalDecisionAgent(Operator):
-    def __init__(self, llm: LLM, name: str = "FinalDecision"):
-        super().__init__(name, llm)
-
-    async def __call__(self, problem: str, function_name, all_thinking: List[str], all_answers: List[str], mode: str = None):
-        prompt = FINAL_DECISION_PROMPT.format(
-            question=problem,
-            all_thinking="\n".join(all_thinking),
-            all_answers="\n".join(all_answers)
-        )
-        fill_kwargs = {"context": prompt, "llm": self.llm, "function_name":function_name}
-        if mode:
-            fill_kwargs["mode"] = mode
-        node = await ActionNode.from_pydantic(FinalDecisionOp).fill(**fill_kwargs)
-        return node.instruct_content.model_dump()
-
-class MultiPersonaGraph(SolveGraph):
-    def __init__(self, name: str, llm_config, dataset: str):
-        super().__init__(name, llm_config, dataset)
-        self.debate_agents = [
-            DebateAgent(self.llm, f"Debate Agent {i}", role)
-            for i, role in enumerate([
-                'Innovative CS Thinker - ICPC Competitor',
-                'Critical Reasoning Expert - Math Professor',
-                'Computational Thinking Specialist - Computer Science Researcher'
-            ])
-        ]
-        self.final_decision_agent = FinalDecisionAgent(self.llm)
-
-    async def __call__(self, problem, function_name):
-        max_round = 2
-        all_thinking = [[] for _ in range(max_round)]
-        all_answers = [[] for _ in range(max_round)]
-
-        for r in range(max_round):
-            for i, agent in enumerate(self.debate_agents):
-                if r == 0:
-                    result = await agent(problem, function_name, mode="context_fill")
-                else:
-                    context = [f"{agent.role}'s previous round thinking: {all_thinking[r-1][i]}"] + \
-                              [f"{self.debate_agents[j].role}'s thinking: {all_thinking[r-1][j]}" for j in range(len(self.debate_agents)) if j != i]
-                    result = await agent(problem, context, mode="context_fill")
-                all_thinking[r].append(result["thinking"])
-                all_answers[r].append(result["answer"])
-
-        final_result = await self.final_decision_agent(
-            problem,
-            function_name ,
-            [f"{agent.role}'s final thinking: {thinking}" for agent, thinking in zip(self.debate_agents, all_thinking[-1])],
-            [f"{agent.role}'s final answer: {answer}" for agent, answer in zip(self.debate_agents, all_answers[-1])],
-            mode="code_fill"
-        )
-        return final_result['solution'], self.llm.cost_manager.total_cost
-
-if __name__ == "__main__":
-    async def main():
-        # llm_config = ModelsConfig.default().get("gpt-4o-mini")
-        # llm_config = ModelsConfig.default().get("gpt-4o")
-        # llm_config = ModelsConfig.default().get("deepseek-chat")
-        llm_config = ModelsConfig.default().get("claude-3-5-sonnet-20240620")
-        graph = MultiPersonaGraph(name="multi-persona", llm_config=llm_config, dataset="HumanEval")
-        file_path = "examples/ags/data/baseline_data/human-eval.jsonl"
-        samples = 33
-        path = "examples/ags/data/baselines/general/humaneval"
-        score, cost = await humaneval_evaluation(graph, file_path, samples, path, test=True)
-        return score, cost
-    
-    import asyncio
-    asyncio.run(main())
\ No newline at end of file
diff --git a/samples_eval_results.json b/samples_eval_results.json
deleted file mode 100644
index cbca304c0..000000000
--- a/samples_eval_results.json
+++ /dev/null
@@ -1 +0,0 @@
-{"date": "2024-07-15 15:06", "hash": "fe585eb4df8c88d844eeb463ea4d0302", "eval": {"HumanEval/0": [{"task_id": "HumanEval/0", "solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n    \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n    given threshold.\n    >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n    False\n    >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n    True\n    \"\"\"\n    for i in range(len(numbers)):\n        for j in range(i + 1, len(numbers)):\n            if abs(numbers[i] - numbers[j]) < threshold:\n                return True\n    return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/1": [{"task_id": "HumanEval/1", "solution": "from typing import List\ndef separate_paren_groups(paren_string: str) -> List[str]:\n    \"\"\" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to\n    separate those group into separate strings and return the list of those.\n    Separate groups are balanced (each open brace is properly closed) and not nested within each other\n    Ignore any spaces in the input string.\n    >>> separate_paren_groups('( ) (( )) (( )( ))')\n    ['()', '(())', '(()())']\n    \"\"\"\n    paren_string = paren_string.replace(' ', '')\n    result = []\n    stack = []\n    current_group = []\n\n    for char in paren_string:\n        if char == '(':\n            if stack:\n                current_group.append(char)\n            stack.append(char)\n        elif char == ')':\n            stack.pop()\n            current_group.append(char)\n            if not stack:\n                result.append(''.join(current_group))\n                current_group = []\n\n    return result", "base_status": "fail", "plus_status": null, "base_fail_tests": [["(()()) ((())) () ((())()())"]], "plus_fail_tests": []}], "HumanEval/3": [{"task_id": "HumanEval/3", "solution": "from typing import List\ndef below_zero(operations: List[int]) -> bool:\n    \"\"\" You're given a list of deposit and withdrawal operations on a bank account that starts with\n    zero balance. Your task is to detect if at any point the balance of account falls below zero, and\n    at that point function should return True. Otherwise it should return False.\n    >>> below_zero([1, 2, 3])\n    False\n    >>> below_zero([1, 2, -4, 5])\n    True\n    \"\"\"\n    balance = 0\n    for operation in operations:\n        balance += operation\n        if balance < 0:\n            return True\n    return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/2": [{"task_id": "HumanEval/2", "solution": "def truncate_number(number: float) -> float:\n    \"\"\" Given a positive floating point number, it can be decomposed into\n    and integer part (largest integer smaller than given number) and decimals\n    (leftover part always smaller than 1).\n\n    Return the decimal part of the number.\n    >>> truncate_number(3.5)\n    0.5\n    \"\"\"\n    return number - int(number)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/5": [{"task_id": "HumanEval/5", "solution": "from typing import List\ndef intersperse(numbers: List[int], delimeter: int) -> List[int]:\n    \"\"\" Insert a number 'delimeter' between every two consecutive elements of input list `numbers'\n    >>> intersperse([], 4)\n    []\n    >>> intersperse([1, 2, 3], 4)\n    [1, 4, 2, 4, 3]\n    \"\"\"\n    if not numbers:\n        return []\n    \n    result = []\n    for i in range(len(numbers) - 1):\n        result.append(numbers[i])\n        result.append(delimeter)\n    result.append(numbers[-1])\n    return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/4": [{"task_id": "HumanEval/4", "solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n    \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n    around the mean of this dataset.\n    Mean Absolute Deviation is the average absolute difference between each\n    element and a centerpoint (mean in this case):\n    MAD = average | x - x_mean |\n    >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n    1.0\n    \"\"\"\n    if not numbers:\n        return 0.0\n    mean_value = sum(numbers) / len(numbers)\n    absolute_deviations = [abs(x - mean_value) for x in numbers]\n    return sum(absolute_deviations) / len(absolute_deviations)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/7": [{"task_id": "HumanEval/7", "solution": "from typing import List\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n    \"\"\" Filter an input list of strings only for ones that contain given substring\n    >>> filter_by_substring([], 'a')\n    []\n    >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n    ['abc', 'bacd', 'array']\n    \"\"\"\n    return [s for s in strings if substring in s]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/6": [{"task_id": "HumanEval/6", "solution": "from typing import List\ndef parse_nested_parens(paren_string: str) -> List[int]:\n    \"\"\" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n    For each of the group, output the deepest level of nesting of parentheses.\n    E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n    >>> parse_nested_parens('(()()) ((())) () ((())()())')\n    [2, 3, 1, 3]\n    \"\"\"\n    groups = paren_string.split()\n    max_depths = []\n    for group in groups:\n        max_depth = 0\n        current_depth = 0\n        for char in group:\n            if char == '(':\n                current_depth += 1\n                if current_depth > max_depth:\n                    max_depth = current_depth\n            elif char == ')':\n                current_depth -= 1\n        max_depths.append(max_depth)\n    return max_depths", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/8": [{"task_id": "HumanEval/8", "solution": "from typing import List, Tuple\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n    \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n    Empty sum should be equal to 0 and empty product should be equal to 1.\n    >>> sum_product([])\n    (0, 1)\n    >>> sum_product([1, 2, 3, 4])\n    (10, 24)\n    \"\"\"\n    if not numbers:\n        return (0, 1)\n    total_sum = sum(numbers)\n    total_product = 1\n    for num in numbers:\n        total_product *= num\n    return (total_sum, total_product)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/9": [{"task_id": "HumanEval/9", "solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n    \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n    in the sequence.\n    >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n    [1, 2, 3, 3, 3, 4, 4]\n    \"\"\"\n    max_so_far = float('-inf')\n    result = []\n    for num in numbers:\n        if num > max_so_far:\n            max_so_far = num\n        result.append(max_so_far)\n    return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/11": [{"task_id": "HumanEval/11", "solution": "from typing import List\ndef string_xor(a: str, b: str) -> str:\n    \"\"\" Input are two strings a and b consisting only of 1s and 0s.\n    Perform binary XOR on these inputs and return result also as a string.\n    >>> string_xor('010', '110')\n    '100'\n    \"\"\"\n    result = []\n    for char_a, char_b in zip(a, b):\n        xor_result = '1' if char_a != char_b else '0'\n        result.append(xor_result)\n    return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/10": [{"task_id": "HumanEval/10", "solution": "def is_palindrome(string: str) -> bool:\n    \"\"\" Test if given string is a palindrome \"\"\"\n    return string == string[::-1]\ndef make_palindrome(string: str) -> str:\n    \"\"\" Find the shortest palindrome that begins with a supplied string.\n    Algorithm idea is simple:\n    - Find the longest postfix of supplied string that is a palindrome.\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n    \"\"\"\n    for i in range(len(string)):\n        if is_palindrome(string[i:]) and i != 0:\n            return string + string[:i][::-1]\n    return string + string[::-1]", "base_status": "fail", "plus_status": null, "base_fail_tests": [["x"]], "plus_fail_tests": []}], "HumanEval/13": [{"task_id": "HumanEval/13", "solution": "def greatest_common_divisor(a: int, b: int) -> int:\n    \"\"\" Return a greatest common divisor of two integers a and b\n    >>> greatest_common_divisor(3, 5)\n    1\n    >>> greatest_common_divisor(25, 15)\n    5\n    \"\"\"\n    while b:\n        a, b = b, a % b\n    return a", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/12": [{"task_id": "HumanEval/12", "solution": "from typing import List, Optional\ndef longest(strings: List[str]) -> Optional[str]:\n    \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n    strings of the same length. Return None in case the input list is empty.\n    >>> longest([])\n    None\n    >>> longest(['a', 'b', 'c'])\n    'a'\n    >>> longest(['a', 'bb', 'ccc'])\n    'ccc'\n    \"\"\"\n    if not strings:\n        return None\n    \n    longest_string = strings[0]\n    for string in strings:\n        if len(string) > len(longest_string):\n            longest_string = string\n    \n    return longest_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/14": [{"task_id": "HumanEval/14", "solution": "from typing import List\ndef all_prefixes(string: str) -> List[str]:\n    \"\"\" Return list of all prefixes from shortest to longest of the input string\n    >>> all_prefixes('abc')\n    ['a', 'ab', 'abc']\n    \"\"\"\n    return [string[:i] for i in range(1, len(string) + 1)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/16": [{"task_id": "HumanEval/16", "solution": "def count_distinct_characters(string: str) -> int:\n    \"\"\" Given a string, find out how many distinct characters (regardless of case)\n    >>> count_distinct_characters('xyzXYZ')\n    3\n    >>> count_distinct_characters('Jerry')\n    4\n    \"\"\"\n    return len(set(string.lower()))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/15": [{"task_id": "HumanEval/15", "solution": "def string_sequence(n: int) -> str:\n    \"\"\" Return a string containing space-delimited numbers starting from 0 upto n inclusive.\n    >>> string_sequence(0)\n    '0'\n    >>> string_sequence(5)\n    '0 1 2 3 4 5'\n    \"\"\"\n    return ' '.join(str(i) for i in range(n + 1))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/18": [{"task_id": "HumanEval/18", "solution": "def how_many_times(string: str, substring: str) -> int:\n    count = start = 0\n    while True:\n        start = string.find(substring, start) + 1\n        if start > 0:\n            count += 1\n        else:\n            return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/17": [{"task_id": "HumanEval/17", "solution": "from typing import List\ndef parse_music(music_string: str) -> List[int]:\n    \"\"\" Input to this function is a string representing musical notes in a special ASCII format.\n    Your task is to parse this string and return list of integers corresponding to how many beats does each\n    not last.\n\n    Here is a legend:\n    'o' - whole note, lasts four beats\n    'o|' - half note, lasts two beats\n    '.|' - quater note, lasts one beat\n\n    >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n    [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n    \"\"\"\n    notes = music_string.split()\n    beats = []\n    for note in notes:\n        if note == 'o':\n            beats.append(4)\n        elif note == 'o|':\n            beats.append(2)\n        elif note == '.|':\n            beats.append(1)\n    return beats", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/19": [{"task_id": "HumanEval/19", "solution": "from typing import List\ndef sort_numbers(numbers: str) -> str:\n    \"\"\" Input is a space-delimited string of numberals from 'zero' to 'nine'.\n    Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n    Return the string with numbers sorted from smallest to largest\n    >>> sort_numbers('three one five')\n    'one three five'\n    \"\"\"\n    num_dict = {'zero': 0, 'one': 1, 'two': 2, 'three': 3, 'four': 4, 'five': 5, 'six': 6, 'seven': 7, 'eight': 8, 'nine': 9}\n    num_list = numbers.split()\n    sorted_list = sorted(num_list, key=lambda x: num_dict[x])\n    return ' '.join(sorted_list)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/20": [{"task_id": "HumanEval/20", "solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n    \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n    other and return them in order (smaller number, larger number).\n    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n    (2.0, 2.2)\n    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n    (2.0, 2.0)\n    \"\"\"\n    numbers.sort()  # Sort the list to ensure the smallest difference is between consecutive elements\n    min_diff = float('inf')\n    closest_pair = (0.0, 0.0)\n    for i in range(len(numbers) - 1):\n        diff = numbers[i + 1] - numbers[i]\n        if diff < min_diff:\n            min_diff = diff\n            closest_pair = (numbers[i], numbers[i + 1])\n    return closest_pair", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/21": [{"task_id": "HumanEval/21", "solution": "from typing import List\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n    \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n    such that the smallest number will become 0 and the largest will become 1\n    >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n    [0.0, 0.25, 0.5, 0.75, 1.0]\n    \"\"\"\n    if len(numbers) < 2:\n        raise ValueError(\"List must contain at least two elements\")\n    \n    min_num = min(numbers)\n    max_num = max(numbers)\n    \n    if min_num == max_num:\n        raise ValueError(\"All numbers in the list must be distinct\")\n    \n    rescaled_numbers = [(x - min_num) / (max_num - min_num) for x in numbers]\n    return rescaled_numbers", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/22": [{"task_id": "HumanEval/22", "solution": "from typing import List, Any\ndef filter_integers(values: List[Any]) -> List[int]:\n    \"\"\" Filter given list of any python values only for integers\n    >>> filter_integers(['a', 3.14, 5])\n    [5]\n    >>> filter_integers([1, 2, 3, 'abc', {}, []])\n    [1, 2, 3]\n    \"\"\"\n    return [value for value in values if isinstance(value, int)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/24": [{"task_id": "HumanEval/24", "solution": "def largest_divisor(n: int) -> int:\n    \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n    >>> largest_divisor(15)\n    5\n    \"\"\"\n    for i in range(n-1, 0, -1):\n        if n % i == 0:\n            return i", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/23": [{"task_id": "HumanEval/23", "solution": "def strlen(string: str) -> int:\n    \"\"\" Return length of given string\n    >>> strlen('')\n    0\n    >>> strlen('abc')\n    3\n    \"\"\"\n    return len(string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/25": [{"task_id": "HumanEval/25", "solution": "from typing import List\ndef factorize(n: int) -> List[int]:\n    \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n    Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.\n    Input number should be equal to the product of all factors\n    >>> factorize(8)\n    [2, 2, 2]\n    >>> factorize(25)\n    [5, 5]\n    >>> factorize(70)\n    [2, 5, 7]\n    \"\"\"\n    factors = []\n    divisor = 2\n    while n > 1:\n        while n % divisor == 0:\n            factors.append(divisor)\n            n //= divisor\n        divisor += 1\n    return factors", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/26": [{"task_id": "HumanEval/26", "solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n    \"\"\" From a list of integers, remove all elements that occur more than once.\n    Keep order of elements left the same as in the input.\n    >>> remove_duplicates([1, 2, 3, 2, 4])\n    [1, 3, 4]\n    \"\"\"\n    from collections import Counter\n    count = Counter(numbers)\n    return [num for num in numbers if count[num] == 1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/28": [{"task_id": "HumanEval/28", "solution": "from typing import List\ndef concatenate(strings: List[str]) -> str:\n    \"\"\" Concatenate list of strings into a single string\n    >>> concatenate([])\n    ''\n    >>> concatenate(['a', 'b', 'c'])\n    'abc'\n    \"\"\"\n    return ''.join(strings)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/27": [{"task_id": "HumanEval/27", "solution": "def flip_case(string: str) -> str:\n    \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n    >>> flip_case('Hello')\n    'hELLO'\n    \"\"\"\n    return ''.join(char.lower() if char.isupper() else char.upper() for char in string)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/29": [{"task_id": "HumanEval/29", "solution": "from typing import List\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n    \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n    >>> filter_by_prefix([], 'a')\n    []\n    >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n    ['abc', 'array']\n    \"\"\"\n    return [s for s in strings if s.startswith(prefix)]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/30": [{"task_id": "HumanEval/30", "solution": "def get_positive(l: list):\n    \"\"\"Return only positive numbers in the list.\n    >>> get_positive([-1, 2, -4, 5, 6])\n    [2, 5, 6]\n    >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n    [5, 3, 2, 3, 9, 123, 1]\n    \"\"\"\n    return [x for x in l if x > 0]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/32": [{"task_id": "HumanEval/32", "solution": "import math\ndef poly(xs: list, x: float):\n    \"\"\"\n    Evaluates polynomial with coefficients xs at point x.\n    return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n\n    \"\"\"\n    return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])\ndef find_zero(xs: list):\n    \"\"\" xs are coefficients of a polynomial.\n    find_zero find x such that poly(x) = 0.\n    find_zero returns only only zero point, even if there are many.\n    Moreover, find_zero only takes list xs having even number of coefficients\n    and largest non zero coefficient as it guarantees\n    a solution.\n    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n    -0.5\n    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n    1.0\n    \"\"\"\n    def f(x):\n        return poly(xs, x)\n\n    # Initial guess for the root\n    x0 = 0.0\n    tolerance = 1e-5\n    max_iterations = 1000\n\n    for _ in range(max_iterations):\n        fx0 = f(x0)\n        if abs(fx0) < tolerance:\n            return x0\n        # Using the derivative of the polynomial for the Newton-Raphson method\n        df = sum([coeff * i * math.pow(x0, i - 1) for i, coeff in enumerate(xs) if i > 0])\n        if df == 0:\n            break\n        x0 = x0 - fx0 / df\n\n    return x0", "base_status": "fail", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/31": [{"task_id": "HumanEval/31", "solution": "def is_prime(n):\n    \"\"\"Return true if a given number is prime, and false otherwise.\n    >>> is_prime(6)\n    False\n    >>> is_prime(101)\n    True\n    >>> is_prime(11)\n    True\n    >>> is_prime(13441)\n    True\n    >>> is_prime(61)\n    True\n    >>> is_prime(4)\n    False\n    >>> is_prime(1)\n    False\n    \"\"\"\n    if n <= 1:\n        return False\n    if n == 2:\n        return True\n    if n % 2 == 0:\n        return False\n    for i in range(3, int(n**0.5) + 1, 2):\n        if n % i == 0:\n            return False\n    return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/34": [{"task_id": "HumanEval/34", "solution": "def unique(l: list):\n    \"\"\"Return sorted unique elements in a list\n    >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n    [0, 2, 3, 5, 9, 123]\n    \"\"\"\n    return sorted(set(l))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/33": [{"task_id": "HumanEval/33", "solution": "def sort_third(l: list):\n    \"\"\"This function takes a list l and returns a list l' such that\n    l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n    to the values of the corresponding indicies of l, but sorted.\n    >>> sort_third([1, 2, 3])\n    [1, 2, 3]\n    >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n    [2, 6, 3, 4, 8, 9, 5]\n    \"\"\"\n    indices = [i for i in range(len(l)) if i % 3 == 0]\n    sorted_values = sorted([l[i] for i in indices])\n    for i, value in zip(indices, sorted_values):\n        l[i] = value\n    return l", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/35": [{"task_id": "HumanEval/35", "solution": "def max_element(l: list):\n    \"\"\"Return maximum element in the list.\n    >>> max_element([1, 2, 3])\n    3\n    >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n    123\n    \"\"\"\n    return max(l)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/36": [{"task_id": "HumanEval/36", "solution": "def fizz_buzz(n: int):\n    count = 0\n    for i in range(n):\n        if (i % 11 == 0 or i % 13 == 0) and '7' in str(i):\n            count += 1\n    return count", "base_status": "fail", "plus_status": null, "base_fail_tests": [[78]], "plus_fail_tests": []}], "HumanEval/37": [{"task_id": "HumanEval/37", "solution": "def sort_even(l: list):\n    \"\"\"This function takes a list l and returns a list l' such that\n    l' is identical to l in the odd indicies, while its values at the even indicies are equal\n    to the values of the even indicies of l, but sorted.\n    >>> sort_even([1, 2, 3])\n    [1, 2, 3]\n    >>> sort_even([5, 6, 3, 4])\n    [3, 6, 5, 4]\n    \"\"\"\n    even_indices_values = [l[i] for i in range(0, len(l), 2)]\n    even_indices_values.sort()\n    result = l[:]\n    for i, val in zip(range(0, len(l), 2), even_indices_values):\n        result[i] = val\n    return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/38": [{"task_id": "HumanEval/38", "solution": "def decode_cyclic(s: str):\n    \"\"\"\n    takes as input string encoded with encode_cyclic function. Returns decoded string.\n    \"\"\"\n    # split string to groups. Each of length 3.\n    groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n    # cycle elements in each group back to original position. Unless group has fewer elements than 3.\n    groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n    return \"\".join(groups)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/40": [{"task_id": "HumanEval/40", "solution": "def triples_sum_to_zero(l: list):\n    \"\"\"\n    triples_sum_to_zero takes a list of integers as an input.\n    it returns True if there are three distinct elements in the list that\n    sum to zero, and False otherwise.\n\n    >>> triples_sum_to_zero([1, 3, 5, 0])\n    False\n    >>> triples_sum_to_zero([1, 3, -2, 1])\n    True\n    >>> triples_sum_to_zero([1, 2, 3, 7])\n    False\n    >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n    True\n    >>> triples_sum_to_zero([1])\n    False\n    \"\"\"\n    l.sort()\n    for i in range(len(l) - 2):\n        left, right = i + 1, len(l) - 1\n        while left < right:\n            current_sum = l[i] + l[left] + l[right]\n            if current_sum == 0:\n                return True\n            elif current_sum < 0:\n                left += 1\n            else:\n                right -= 1\n    return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/39": [{"task_id": "HumanEval/39", "solution": "def is_prime(num):\n    if num < 2:\n        return False\n    for i in range(2, int(num**0.5) + 1):\n        if num % i == 0:\n            return False\n    return True\ndef prime_fib(n: int):\n    \"\"\"\n    prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n    >>> prime_fib(1)\n    2\n    >>> prime_fib(2)\n    3\n    >>> prime_fib(3)\n    5\n    >>> prime_fib(4)\n    13\n    >>> prime_fib(5)\n    89\n    \"\"\"\n    a, b = 0, 1\n    count = 0\n    while True:\n        a, b = b, a + b\n        if is_prime(b):\n            count += 1\n            if count == n:\n                return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/42": [{"task_id": "HumanEval/42", "solution": "def incr_list(l: list):\n    \"\"\"Return list with elements incremented by 1.\n    >>> incr_list([1, 2, 3])\n    [2, 3, 4]\n    >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n    [6, 4, 6, 3, 4, 4, 10, 1, 124]\n    \"\"\"\n    return [x + 1 for x in l]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/41": [{"task_id": "HumanEval/41", "solution": "def car_race_collision(n: int):\n    \"\"\"\n    Imagine a road that's a perfectly straight infinitely long line.\n    n cars are driving left to right;  simultaneously, a different set of n cars\n    are driving right to left.   The two sets of cars start out being very far from\n    each other.  All cars move in the same speed.  Two cars are said to collide\n    when a car that's moving left to right hits a car that's moving right to left.\n    However, the cars are infinitely sturdy and strong; as a result, they continue moving\n    in their trajectory as if they did not collide.\n\n    This function outputs the number of such collisions.\n    \"\"\"\n    return n * n", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/43": [{"task_id": "HumanEval/43", "solution": "def pairs_sum_to_zero(l):\n    \"\"\"\n    pairs_sum_to_zero takes a list of integers as an input.\n    it returns True if there are two distinct elements in the list that\n    sum to zero, and False otherwise.\n    >>> pairs_sum_to_zero([1, 3, 5, 0])\n    False\n    >>> pairs_sum_to_zero([1, 3, -2, 1])\n    False\n    >>> pairs_sum_to_zero([1, 2, 3, 7])\n    False\n    >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n    True\n    >>> pairs_sum_to_zero([1])\n    False\n    \"\"\"\n    seen = set()\n    for num in l:\n        if -num in seen:\n            return True\n        seen.add(num)\n    return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/44": [{"task_id": "HumanEval/44", "solution": "def change_base(x: int, base: int):\n    \"\"\"Change numerical base of input number x to base.\n    return string representation after the conversion.\n    base numbers are less than 10.\n    >>> change_base(8, 3)\n    '22'\n    >>> change_base(8, 2)\n    '1000'\n    >>> change_base(7, 2)\n    '111'\n    \"\"\"\n    if x == 0:\n        return '0'\n    digits = []\n    while x:\n        digits.append(str(x % base))\n        x //= base\n    return ''.join(digits[::-1])", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/45": [{"task_id": "HumanEval/45", "solution": "def triangle_area(a, h):\n    \"\"\"Given length of a side and high return area for a triangle.\n    >>> triangle_area(5, 3)\n    7.5\n    \"\"\"\n    return 0.5 * a * h", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/46": [{"task_id": "HumanEval/46", "solution": "def fib4(n: int):\n    if n == 0:\n        return 0\n    elif n == 1:\n        return 0\n    elif n == 2:\n        return 2\n    elif n == 3:\n        return 0\n    else:\n        a, b, c, d = 0, 0, 2, 0\n        for i in range(4, n + 1):\n            next_value = a + b + c + d\n            a, b, c, d = b, c, d, next_value\n        return d", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/47": [{"task_id": "HumanEval/47", "solution": "def median(l: list):\n    \"\"\"Return median of elements in the list l.\n    >>> median([3, 1, 2, 4, 5])\n    3\n    >>> median([-10, 4, 6, 1000, 10, 20])\n    15.0\n    \"\"\"\n    sorted_l = sorted(l)\n    n = len(sorted_l)\n    if n % 2 == 1:\n        return sorted_l[n // 2]\n    else:\n        return (sorted_l[n // 2 - 1] + sorted_l[n // 2]) / 2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/48": [{"task_id": "HumanEval/48", "solution": "def is_palindrome(text: str):\n    \"\"\"\n    Checks if given string is a palindrome\n    >>> is_palindrome('')\n    True\n    >>> is_palindrome('aba')\n    True\n    >>> is_palindrome('aaaaa')\n    True\n    >>> is_palindrome('zbcd')\n    False\n    \"\"\"\n    return text == text[::-1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/49": [{"task_id": "HumanEval/49", "solution": "def modp(n: int, p: int):\n    \"\"\"Return 2^n modulo p (be aware of numerics).\n    >>> modp(3, 5)\n    3\n    >>> modp(1101, 101)\n    2\n    >>> modp(0, 101)\n    1\n    >>> modp(3, 11)\n    8\n    >>> modp(100, 101)\n    1\n    \"\"\"\n    result = 1\n    base = 2\n    while n > 0:\n        if n % 2 == 1:\n            result = (result * base) % p\n        base = (base * base) % p\n        n //= 2\n    return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/50": [{"task_id": "HumanEval/50", "solution": "def decode_shift(s: str):\n    \"\"\"\n    takes as input string encoded with encode_shift function. Returns decoded string.\n    \"\"\"\n    return \"\".join([chr(((ord(ch) - 5 - ord(\"a\")) % 26) + ord(\"a\")) for ch in s])", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/52": [{"task_id": "HumanEval/52", "solution": "def below_threshold(l: list, t: int):\n    \"\"\"Return True if all numbers in the list l are below threshold t.\n    >>> below_threshold([1, 2, 4, 10], 100)\n    True\n    >>> below_threshold([1, 20, 4, 10], 5)\n    False\n    \"\"\"\n    return all(x < t for x in l)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/51": [{"task_id": "HumanEval/51", "solution": "def remove_vowels(text):\n    \"\"\"\n    remove_vowels is a function that takes string and returns string without vowels.\n    >>> remove_vowels('')\n    ''\n    >>> remove_vowels(\"abcdef\\nghijklm\")\n    'bcdf\\nghjklm'\n    >>> remove_vowels('abcdef')\n    'bcdf'\n    >>> remove_vowels('aaaaa')\n    ''\n    >>> remove_vowels('aaBAA')\n    'B'\n    >>> remove_vowels('zbcd')\n    'zbcd'\n    \"\"\"\n    vowels = 'aeiouAEIOU'\n    return ''.join(char for char in text if char not in vowels)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/54": [{"task_id": "HumanEval/54", "solution": "def same_chars(s0: str, s1: str):\n    \"\"\"\n    Check if two words have the same characters.\n    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n    True\n    >>> same_chars('abcd', 'dddddddabc')\n    True\n    >>> same_chars('dddddddabc', 'abcd')\n    True\n    >>> same_chars('eabcd', 'dddddddabc')\n    False\n    >>> same_chars('abcd', 'dddddddabce')\n    False\n    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n    False\n    \"\"\"\n    return sorted(s0) == sorted(s1)", "base_status": "fail", "plus_status": null, "base_fail_tests": [["eabcdzzzz", "dddzzzzzzzddeddabc"]], "plus_fail_tests": []}], "HumanEval/53": [{"task_id": "HumanEval/53", "solution": "def add(x: int, y: int):\n    \"\"\"Add two numbers x and y\n    >>> add(2, 3)\n    5\n    >>> add(5, 7)\n    12\n    \"\"\"\n    return x + y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/55": [{"task_id": "HumanEval/55", "solution": "def fib(n: int):\n    \"\"\"Return n-th Fibonacci number.\n    >>> fib(10)\n    55\n    >>> fib(1)\n    1\n    >>> fib(8)\n    21\n    \"\"\"\n    if n <= 0:\n        return 0\n    elif n == 1:\n        return 1\n    else:\n        a, b = 0, 1\n        for _ in range(2, n + 1):\n            a, b = b, a + b\n        return b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/56": [{"task_id": "HumanEval/56", "solution": "def correct_bracketing(brackets: str):\n    \"\"\" brackets is a string of \"<\" and \">\".\n    return True if every opening bracket has a corresponding closing bracket.\n\n    >>> correct_bracketing(\"<\")\n    False\n    >>> correct_bracketing(\"<>\")\n    True\n    >>> correct_bracketing(\"<<><>>\")\n    True\n    >>> correct_bracketing(\"><<><\")\n    False\n    \"\"\"\n    balance = 0\n    for bracket in brackets:\n        if bracket == '<':\n            balance += 1\n        elif bracket == '>':\n            balance -= 1\n        if balance < 0:\n            return False\n    return balance == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/57": [{"task_id": "HumanEval/57", "solution": "def monotonic(l: list):\n    \"\"\"Return True if list elements are monotonically increasing or decreasing.\n    >>> monotonic([1, 2, 4, 20])\n    True\n    >>> monotonic([1, 20, 4, 10])\n    False\n    >>> monotonic([4, 1, 0, -10])\n    True\n    \"\"\"\n    return all(x <= y for x, y in zip(l, l[1:])) or all(x >= y for x, y in zip(l, l[1:]))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/58": [{"task_id": "HumanEval/58", "solution": "def common(l1: list, l2: list):\n    \"\"\"Return sorted unique common elements for two lists.\n    >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n    [1, 5, 653]\n    >>> common([5, 3, 2, 8], [3, 2])\n    [2, 3]\n\n    \"\"\"\n    return sorted(set(l1) & set(l2))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/59": [{"task_id": "HumanEval/59", "solution": "def largest_prime_factor(n: int):\n    \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n    >>> largest_prime_factor(13195)\n    29\n    >>> largest_prime_factor(2048)\n    2\n    \"\"\"\n    def is_prime(num):\n        if num <= 1:\n            return False\n        if num <= 3:\n            return True\n        if num % 2 == 0 or num % 3 == 0:\n            return False\n        i = 5\n        while i * i <= num:\n            if num % i == 0 or num % (i + 2) == 0:\n                return False\n            i += 6\n        return True\n\n    max_prime = -1\n    while n % 2 == 0:\n        max_prime = 2\n        n //= 2\n    for i in range(3, int(n**0.5) + 1, 2):\n        while n % i == 0:\n            max_prime = i\n            n //= i\n    if n > 2:\n        max_prime = n\n    return max_prime", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/60": [{"task_id": "HumanEval/60", "solution": "def sum_to_n(n: int):\n    \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n    >>> sum_to_n(30)\n    465\n    >>> sum_to_n(100)\n    5050\n    >>> sum_to_n(5)\n    15\n    >>> sum_to_n(10)\n    55\n    >>> sum_to_n(1)\n    1\n    \"\"\"\n    return sum(range(1, n + 1))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/61": [{"task_id": "HumanEval/61", "solution": "def correct_bracketing(brackets: str):\n    \"\"\" brackets is a string of \"(\" and \")\".\n    return True if every opening bracket has a corresponding closing bracket.\n\n    >>> correct_bracketing(\"(\")\n    False\n    >>> correct_bracketing(\"()\")\n    True\n    >>> correct_bracketing(\"(()())\")\n    True\n    >>> correct_bracketing(\")(()\")\n    False\n    \"\"\"\n    stack = []\n    for bracket in brackets:\n        if bracket == '(':\n            stack.append(bracket)\n        elif bracket == ')':\n            if not stack:\n                return False\n            stack.pop()\n    return not stack", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/62": [{"task_id": "HumanEval/62", "solution": "def derivative(xs: list):\n    \"\"\" xs represent coefficients of a polynomial.\n    xs[0] + xs[1] * x + xs[2] * x^2 + ....\n     Return derivative of this polynomial in the same form.\n    >>> derivative([3, 1, 2, 4, 5])\n    [1, 4, 12, 20]\n    >>> derivative([1, 2, 3])\n    [2, 6]\n    \"\"\"\n    return [xs[i] * i for i in range(1, len(xs))]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}, {"task_id": "HumanEval/62", "solution": "def derivative(xs):\n    # Check if the list is empty\n    if len(xs) == 0:\n        return []\n    # Initialize the resulting list\n    result = []\n    # Iterate through the coefficients\n    for i in range(1, len(xs)):\n        # Calculate the derivative of each term and append it to the result\n        result.append(xs[i] * i)\n    return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/63": [{"task_id": "HumanEval/63", "solution": "def fibfib(n: int):\n    if n == 0:\n        return 0\n    elif n == 1:\n        return 0\n    elif n == 2:\n        return 1\n    else:\n        a, b, c = 0, 0, 1\n        for i in range(3, n + 1):\n            a, b, c = b, c, a + b + c\n        return c", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/64": [{"task_id": "HumanEval/64", "solution": "def vowels_count(s):\n    vowels = 'aeiouAEIOU'\n    count = 0\n    s = s.lower()\n    for i, char in enumerate(s):\n        if char in vowels:\n            count += 1\n        elif char == 'y' and i == len(s) - 1:\n            count += 1\n    return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/65": [{"task_id": "HumanEval/65", "solution": "def circular_shift(x, shift):\n    x_str = str(x)\n    num_digits = len(x_str)\n    if shift > num_digits:\n        return x_str[::-1]\n    else:\n        shifted_str = x_str[-shift:] + x_str[:-shift]\n        return shifted_str", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/66": [{"task_id": "HumanEval/66", "solution": "def digitSum(s):\n    \"\"\"Task\n    Write a function that takes a string as input and returns the sum of the upper characters only'\n    ASCII codes.\n\n    Examples:\n        digitSum(\"\") => 0\n        digitSum(\"abAB\") => 131\n        digitSum(\"abcCd\") => 67\n        digitSum(\"helloE\") => 69\n        digitSum(\"woArBld\") => 131\n        digitSum(\"aAaaaXa\") => 153\n    \"\"\"\n    return sum(ord(char) for char in s if char.isupper())", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/67": [{"task_id": "HumanEval/67", "solution": "def fruit_distribution(s, n):\n    # Split the string to extract the number of apples and oranges\n    parts = s.split()\n    apples = int(parts[0])\n    oranges = int(parts[3])\n    \n    # Calculate the number of mangoes\n    mangoes = n - apples - oranges\n    \n    return mangoes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/68": [{"task_id": "HumanEval/68", "solution": "def pluck(arr):\n    \"\"\"\n    Given an array representing a branch of a tree that has non-negative integer nodes\n    your task is to pluck one of the nodes and return it.\n    The plucked node should be the node with the smallest even value.\n    If multiple nodes with the same smallest even value are found return the node that has smallest index.\n\n    The plucked node should be returned in a list, [ smalest_value, its index ],\n    If there are no even values or the given array is empty, return []\n    \"\"\"\n    if not arr:\n        return []\n\n    smallest_even_value = float('inf')\n    smallest_index = -1\n\n    for index, value in enumerate(arr):\n        if value % 2 == 0 and value < smallest_even_value:\n            smallest_even_value = value\n            smallest_index = index\n\n    if smallest_index == -1:\n        return []\n    else:\n        return [smallest_even_value, smallest_index]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/69": [{"task_id": "HumanEval/69", "solution": "def search(lst):\n    from collections import Counter\n    freq = Counter(lst)\n    result = -1\n    for num, count in freq.items():\n        if count >= num:\n            result = max(result, num)\n    return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/70": [{"task_id": "HumanEval/70", "solution": "def strange_sort_list(lst):\n    '''\n    Given list of integers, return list in strange order.\n    Strange sorting, is when you start with the minimum value,\n    then maximum of the remaining integers, then minimum and so on.\n\n    Examples:\n    strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n    strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n    strange_sort_list([]) == []\n    '''\n    if not lst:\n        return []\n    \n    sorted_lst = sorted(lst)\n    result = []\n    left = 0\n    right = len(sorted_lst) - 1\n    toggle = True\n    \n    while left <= right:\n        if toggle:\n            result.append(sorted_lst[left])\n            left += 1\n        else:\n            result.append(sorted_lst[right])\n            right -= 1\n        toggle = not toggle\n    \n    return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/71": [{"task_id": "HumanEval/71", "solution": "def triangle_area(a, b, c):\n    '''\n    Given the lengths of the three sides of a triangle. Return the area of\n    the triangle rounded to 2 decimal points if the three sides form a valid triangle.\n    Otherwise return -1\n    Three sides make a valid triangle when the sum of any two sides is greater\n    than the third side.\n    Example:\n    triangle_area(3, 4, 5) == 6.00\n    triangle_area(1, 2, 10) == -1\n    '''\n    \n    # Check if the sides form a valid triangle\n    if a + b > c and a + c > b and b + c > a:\n        # Calculate the semi-perimeter\n        s = (a + b + c) / 2\n        # Calculate the area using Heron's formula\n        area = (s * (s - a) * (s - b) * (s - c)) ** 0.5\n        # Return the area rounded to 2 decimal points\n        return round(area, 2)\n    else:\n        return -1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/72": [{"task_id": "HumanEval/72", "solution": "def will_it_fly(q, w):\n    '''\n    Write a function that returns True if the object q will fly, and False otherwise.\n    The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n\n    Example:\n    will_it_fly([1, 2], 5) \u279e False \n    # 1+2 is less than the maximum possible weight, but it's unbalanced.\n\n    will_it_fly([3, 2, 3], 1) \u279e False\n    # it's balanced, but 3+2+3 is more than the maximum possible weight.\n\n    will_it_fly([3, 2, 3], 9) \u279e True\n    # 3+2+3 is less than the maximum possible weight, and it's balanced.\n\n    will_it_fly([3], 5) \u279e True\n    # 3 is less than the maximum possible weight, and it's balanced.\n    '''\n    \n    # Check if the list is palindromic\n    is_palindromic = q == q[::-1]\n    \n    # Calculate the sum of the elements\n    total_weight = sum(q)\n    \n    # Check if the total weight is less than or equal to the maximum possible weight\n    is_within_weight_limit = total_weight <= w\n    \n    # The object will fly if it's balanced and within the weight limit\n    return is_palindromic and is_within_weight_limit", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/73": [{"task_id": "HumanEval/73", "solution": "def smallest_change(arr):\n    n = len(arr)\n    changes = 0\n    for i in range(n // 2):\n        if arr[i] != arr[n - i - 1]:\n            changes += 1\n    return changes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/74": [{"task_id": "HumanEval/74", "solution": "def total_match(lst1, lst2):\n    '''\n    Write a function that accepts two lists of strings and returns the list that has \n    total number of chars in the all strings of the list less than the other list.\n\n    if the two lists have the same number of chars, return the first list.\n\n    Examples\n    total_match([], []) \u279e []\n    total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n    total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n    total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n    total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n    '''\n    \n    def total_chars(lst):\n        return sum(len(s) for s in lst)\n\n    total_chars_lst1 = total_chars(lst1)\n    total_chars_lst2 = total_chars(lst2)\n\n    if total_chars_lst1 < total_chars_lst2:\n        return lst1\n    else:\n        return lst2", "base_status": "fail", "plus_status": null, "base_fail_tests": [[["hi", "admin"], ["hI", "hi", "hii"]]], "plus_fail_tests": []}], "HumanEval/75": [{"task_id": "HumanEval/75", "solution": "def is_prime(n):\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef is_multiply_prime(a):\n    primes = [i for i in range(2, 100) if is_prime(i)]\n    for i in range(len(primes)):\n        for j in range(i, len(primes)):\n            for k in range(j, len(primes)):\n                if primes[i] * primes[j] * primes[k] == a:\n                    return True\n    return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/76": [{"task_id": "HumanEval/76", "solution": "def is_simple_power(x, n):\n    if n == 1:\n        return x == 1\n    power = 1\n    while power < x:\n        power *= n\n    return power == x", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/77": [{"task_id": "HumanEval/77", "solution": "def iscube(a):\n    \"\"\"\n    Write a function that takes an integer a and returns True \n    if this integer is a cube of some integer number.\n    Note: you may assume the input is always valid.\n    Examples:\n    iscube(1) ==> True\n    iscube(2) ==> False\n    iscube(-1) ==> True\n    iscube(64) ==> True\n    iscube(0) ==> True\n    iscube(180) ==> False\n    \"\"\"\n    cube_root = abs(a) ** (1.0 / 3.0)\n    return round(cube_root) ** 3 == abs(a)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/78": [{"task_id": "HumanEval/78", "solution": "def hex_key(num):\n    \"\"\"You have been tasked to write a function that receives \n    a hexadecimal number as a string and counts the number of hexadecimal \n    digits that are primes (prime number, or a prime, is a natural number \n    greater than 1 that is not a product of two smaller natural numbers).\n    Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.\n    Prime numbers are 2, 3, 5, 7, 11, 13, 17,...\n    So you have to determine a number of the following digits: 2, 3, 5, 7, \n    B (=decimal 11), D (=decimal 13).\n    Note: you may assume the input is always correct or empty string, \n    and symbols A,B,C,D,E,F are always uppercase.\n    Examples:\n    For num = \"AB\" the output should be 1.\n    For num = \"1077E\" the output should be 2.\n    For num = \"ABED1A33\" the output should be 4.\n    For num = \"123456789ABCDEF0\" the output should be 6.\n    For num = \"2020\" the output should be 2.\n    \"\"\"\n    prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n    count = 0\n    for digit in num:\n        if digit in prime_hex_digits:\n            count += 1\n    return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/79": [{"task_id": "HumanEval/79", "solution": "def decimal_to_binary(decimal):\n    \"\"\"You will be given a number in decimal form and your task is to convert it to\n    binary format. The function should return a string, with each character representing a binary\n    number. Each character in the string will be '0' or '1'.\n\n    There will be an extra couple of characters 'db' at the beginning and at the end of the string.\n    The extra characters are there to help with the format.\n\n    Examples:\n    decimal_to_binary(15)   # returns \"db1111db\"\n    decimal_to_binary(32)   # returns \"db100000db\"\n    \"\"\"\n    binary_str = bin(decimal)[2:]\n    return 'db' + binary_str + 'db'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/80": [{"task_id": "HumanEval/80", "solution": "def is_happy(s):\n    if len(s) < 3:\n        return False\n    \n    for i in range(len(s) - 2):\n        if len(set(s[i:i+3])) != 3:\n            return False\n    \n    return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/81": [{"task_id": "HumanEval/81", "solution": "def numerical_letter_grade(grades):\n    letter_grades = []\n    for gpa in grades:\n        if gpa == 4.0:\n            letter_grades.append('A+')\n        elif gpa > 3.7:\n            letter_grades.append('A')\n        elif gpa > 3.3:\n            letter_grades.append('A-')\n        elif gpa > 3.0:\n            letter_grades.append('B+')\n        elif gpa > 2.7:\n            letter_grades.append('B')\n        elif gpa > 2.3:\n            letter_grades.append('B-')\n        elif gpa > 2.0:\n            letter_grades.append('C+')\n        elif gpa > 1.7:\n            letter_grades.append('C')\n        elif gpa > 1.3:\n            letter_grades.append('C-')\n        elif gpa > 1.0:\n            letter_grades.append('D+')\n        elif gpa > 0.7:\n            letter_grades.append('D')\n        elif gpa > 0.0:\n            letter_grades.append('D-')\n        elif gpa == 0.0:\n            letter_grades.append('E')\n    return letter_grades", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/82": [{"task_id": "HumanEval/82", "solution": "def prime_length(string):\n    def is_prime(n):\n        if n <= 1:\n            return False\n        for i in range(2, int(n**0.5) + 1):\n            if n % i == 0:\n                return False\n        return True\n\n    return is_prime(len(string))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/83": [{"task_id": "HumanEval/83", "solution": "def starts_one_ends(n):\n    \"\"\"\n    Given a positive integer n, return the count of the numbers of n-digit\n    positive integers that start or end with 1.\n    \"\"\"\n    if n == 1:\n        return 2  # The numbers 1 and 10\n    else:\n        return 2 * (10 ** (n - 1)) - (10 ** (n - 2))", "base_status": "fail", "plus_status": null, "base_fail_tests": [[1]], "plus_fail_tests": []}], "HumanEval/85": [{"task_id": "HumanEval/85", "solution": "def add(lst):\n    \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n    Examples:\n        add([4, 2, 6, 7]) ==> 2 \n    \"\"\"\n    return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/84": [{"task_id": "HumanEval/84", "solution": "def solve(N):\n    \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n    \n    Example\n        For N = 1000, the sum of digits will be 1 the output should be \"1\".\n        For N = 150, the sum of digits will be 6 the output should be \"110\".\n        For N = 147, the sum of digits will be 12 the output should be \"1100\".\n    \n    Variables:\n        @N integer\n             Constraints: 0 \u2264 N \u2264 10000.\n    Output:\n         a string of binary number\n    \"\"\"\n    \n    # Convert the number to a string to iterate over each digit\n    digits = str(N)\n    \n    # Calculate the sum of the digits\n    sum_of_digits = sum(int(digit) for digit in digits)\n    \n    # Convert the sum to binary and return it as a string\n    return bin(sum_of_digits)[2:]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/87": [{"task_id": "HumanEval/87", "solution": "def get_row(lst, x):\n    coordinates = []\n    for i, row in enumerate(lst):\n        for j, value in enumerate(row):\n            if value == x:\n                coordinates.append((i, j))\n    coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n    return coordinates", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/86": [{"task_id": "HumanEval/86", "solution": "def anti_shuffle(s):\n    \"\"\"\n    Write a function that takes a string and returns an ordered version of it.\n    Ordered version of string, is a string where all words (separated by space)\n    are replaced by a new word where all the characters arranged in\n    ascending order based on ascii value.\n    Note: You should keep the order of words and blank spaces in the sentence.\n\n    For example:\n    anti_shuffle('Hi') returns 'Hi'\n    anti_shuffle('hello') returns 'ehllo'\n    anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n    \"\"\"\n    words = s.split(' ')\n    ordered_words = [''.join(sorted(word)) for word in words]\n    return ' '.join(ordered_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/89": [{"task_id": "HumanEval/89", "solution": "def encrypt(s):\n    encrypted_string = ''\n    for char in s:\n        if char.isalpha():\n            shift = 4  # 2 multiplied by 2\n            if char.islower():\n                encrypted_char = chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n            else:\n                encrypted_char = chr((ord(char) - ord('A') + shift) % 26 + ord('A'))\n            encrypted_string += encrypted_char\n        else:\n            encrypted_string += char\n    return encrypted_string", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/88": [{"task_id": "HumanEval/88", "solution": "def sort_array(array):\n    \"\"\"\n    Given an array of non-negative integers, return a copy of the given array after sorting,\n    you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n    or sort it in descending order if the sum( first index value, last index value) is even.\n\n    Note:\n    * don't change the given array.\n\n    Examples:\n    * sort_array([]) => []\n    * sort_array([5]) => [5]\n    * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n    * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n    \"\"\"\n    if not array:\n        return []\n\n    first_value = array[0]\n    last_value = array[-1]\n    sum_values = first_value + last_value\n\n    if sum_values % 2 == 0:\n        return sorted(array, reverse=True)\n    else:\n        return sorted(array)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/90": [{"task_id": "HumanEval/90", "solution": "def next_smallest(lst):\n    if len(lst) < 2:\n        return None\n    \n    unique_sorted = sorted(set(lst))\n    if len(unique_sorted) < 2:\n        return None\n    \n    return unique_sorted[1]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/91": [{"task_id": "HumanEval/91", "solution": "def is_bored(S):\n    \"\"\"\n    You'll be given a string of words, and your task is to count the number\n    of boredoms. A boredom is a sentence that starts with the word \"I\".\n    Sentences are delimited by '.', '?' or '!'.\n    \n    For example:\n    >>> is_bored(\"Hello world\")\n    0\n    >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n    1\n    \"\"\"\n    sentences = re.split(r'[.!?]', S)\n    count = 0\n    for sentence in sentences:\n        words = sentence.strip().split()\n        if words and words[0].lower() == 'i':\n            count += 1\n    return count", "base_status": "fail", "plus_status": null, "base_fail_tests": [["Hello world"]], "plus_fail_tests": []}], "HumanEval/93": [{"task_id": "HumanEval/93", "solution": "def encode(message):\n    def swap_case(char):\n        if char.isupper():\n            return char.lower()\n        else:\n            return char.upper()\n\n    def replace_vowel(char):\n        vowels = 'aeiouAEIOU'\n        if char in vowels:\n            if char.islower():\n                return chr(((ord(char) - ord('a') + 2) % 26) + ord('a'))\n            else:\n                return chr(((ord(char) - ord('A') + 2) % 26) + ord('A'))\n        else:\n            return char\n\n    encoded_message = ''\n    for char in message:\n        swapped_char = swap_case(char)\n        replaced_char = replace_vowel(swapped_char)\n        encoded_message += replaced_char\n\n    return encoded_message", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/92": [{"task_id": "HumanEval/92", "solution": "def any_int(x, y, z):\n    '''\n    Create a function that takes 3 numbers.\n    Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n    Returns false in any other cases.\n    \n    Examples\n    any_int(5, 2, 7) \u279e True\n    \n    any_int(3, 2, 2) \u279e False\n\n    any_int(3, -2, 1) \u279e True\n    \n    any_int(3.6, -2.2, 2) \u279e False\n    \n    '''\n    if isinstance(x, int) and isinstance(y, int) and isinstance(z, int):\n        return x == y + z or y == x + z or z == x + y\n    else:\n        return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/94": [{"task_id": "HumanEval/94", "solution": "def skjkasdkd(lst):\n    def is_prime(n):\n        if n <= 1:\n            return False\n        if n <= 3:\n            return True\n        if n % 2 == 0 or n % 3 == 0:\n            return False\n        i = 5\n        while i * i <= n:\n            if n % i == 0 or n % (i + 2) == 0:\n                return False\n            i += 6\n        return True\n\n    def sum_of_digits(n):\n        return sum(int(digit) for digit in str(n))\n\n    largest_prime = None\n    for num in lst:\n        if is_prime(num):\n            if largest_prime is None or num > largest_prime:\n                largest_prime = num\n\n    if largest_prime is not None:\n        return sum_of_digits(largest_prime)\n    else:\n        return 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}, {"task_id": "HumanEval/94", "solution": "import math", "base_status": "fail", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/95": [{"task_id": "HumanEval/95", "solution": "def check_dict_case(dict):\n    \"\"\"\n    Given a dictionary, return True if all keys are strings in lower \n    case or all keys are strings in upper case, else return False.\n    The function should return False if the given dictionary is empty.\n    Examples:\n    check_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n    check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n    check_dict_case({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n    check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n    check_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n    \"\"\"\n    if not dict:\n        return False\n    \n    lower_case = all(isinstance(key, str) and key.islower() for key in dict)\n    upper_case = all(isinstance(key, str) and key.isupper() for key in dict)\n    \n    return lower_case or upper_case", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/96": [{"task_id": "HumanEval/96", "solution": "def count_up_to(n):\n    def is_prime(num):\n        if num <= 1:\n            return False\n        for i in range(2, int(num**0.5) + 1):\n            if num % i == 0:\n                return False\n        return True\n\n    primes = []\n    for i in range(2, n):\n        if is_prime(i):\n            primes.append(i)\n    return primes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/97": [{"task_id": "HumanEval/97", "solution": "def multiply(a, b):\n    \"\"\"Complete the function that takes two integers and returns \n    the product of their unit digits.\n    Assume the input is always valid.\n    Examples:\n    multiply(148, 412) should return 16.\n    multiply(19, 28) should return 72.\n    multiply(2020, 1851) should return 0.\n    multiply(14,-15) should return 20.\n    \"\"\"\n    unit_digit_a = abs(a) % 10\n    unit_digit_b = abs(b) % 10\n    return unit_digit_a * unit_digit_b", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/98": [{"task_id": "HumanEval/98", "solution": "def count_upper(s):\n    \"\"\"\n    Given a string s, count the number of uppercase vowels in even indices.\n    \n    For example:\n    count_upper('aBCdEf') returns 1\n    count_upper('abcdefg') returns 0\n    count_upper('dBBE') returns 0\n    \"\"\"\n    vowels = 'AEIOU'\n    count = 0\n    for i in range(0, len(s), 2):\n        if s[i] in vowels:\n            count += 1\n    return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/100": [{"task_id": "HumanEval/100", "solution": "def make_a_pile(n):\n    \"\"\"\n    Given a positive integer n, you have to make a pile of n levels of stones.\n    The first level has n stones.\n    The number of stones in the next level is:\n        - the next odd number if n is odd.\n        - the next even number if n is even.\n    Return the number of stones in each level in a list, where element at index\n    i represents the number of stones in the level (i+1).\n\n    Examples:\n    >>> make_a_pile(3)\n    [3, 5, 7]\n    \"\"\"\n    pile = []\n    current_stones = n\n    for i in range(n):\n        pile.append(current_stones)\n        if n % 2 == 0:\n            current_stones += 2\n        else:\n            current_stones += 2\n    return pile", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/99": [{"task_id": "HumanEval/99", "solution": "def closest_integer(value):\n    '''\n    Create a function that takes a value (string) representing a number\n    and returns the closest integer to it. If the number is equidistant\n    from two integers, round it away from zero.\n\n    Examples\n    >>> closest_integer(\"10\")\n    10\n    >>> closest_integer(\"15.3\")\n    15\n\n    Note:\n    Rounding away from zero means that if the given number is equidistant\n    from two integers, the one you should return is the one that is the\n    farthest from zero. For example closest_integer(\"14.5\") should\n    return 15 and closest_integer(\"-14.5\") should return -15.\n    '''\n    number = float(value)\n    if number % 1 == 0.5:\n        if number > 0:\n            return int(number + 0.5)\n        else:\n            return int(number - 0.5)\n    else:\n        return round(number)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/101": [{"task_id": "HumanEval/101", "solution": "def words_string(s):\n    \"\"\"\n    You will be given a string of words separated by commas or spaces. Your task is\n    to split the string into words and return an array of the words.\n    \n    For example:\n    words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n    words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n    \"\"\"\n    import re\n    words = re.split(r'[,\\s]+', s)\n    return words", "base_status": "fail", "plus_status": null, "base_fail_tests": [["One,, two, three, four, five, six,"]], "plus_fail_tests": []}], "HumanEval/102": [{"task_id": "HumanEval/102", "solution": "def choose_num(x, y):\n    \"\"\"This function takes two positive numbers x and y and returns the\n    biggest even integer number that is in the range [x, y] inclusive. If \n    there's no such number, then the function should return -1.\n\n    For example:\n    choose_num(12, 15) = 14\n    choose_num(13, 12) = -1\n    \"\"\"\n    if x > y:\n        return -1\n    \n    for num in range(y, x-1, -1):\n        if num % 2 == 0:\n            return num\n    \n    return -1", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/104": [{"task_id": "HumanEval/104", "solution": "def unique_digits(x):\n    \"\"\"Given a list of positive integers x. return a sorted list of all \n    elements that hasn't any even digit.\n\n    Note: Returned list should be sorted in increasing order.\n    \n    For example:\n    >>> unique_digits([15, 33, 1422, 1])\n    [1, 15, 33]\n    >>> unique_digits([152, 323, 1422, 10])\n    []\n    \"\"\"\n    def has_even_digit(num):\n        for digit in str(num):\n            if int(digit) % 2 == 0:\n                return True\n        return False\n\n    result = [num for num in x if not has_even_digit(num)]\n    return sorted(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/103": [{"task_id": "HumanEval/103", "solution": "def rounded_avg(n, m):\n    if n > m:\n        return -1\n    avg = round((n + m) / 2)\n    return bin(avg)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/106": [{"task_id": "HumanEval/106", "solution": "def f(n):\n    \"\"\" Implement the function f that takes n as a parameter,\n    and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even\n    or the sum of numbers from 1 to i otherwise.\n    i starts from 1.\n    the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).\n    Example:\n    f(5) == [1, 2, 6, 24, 15]\n    \"\"\"\n    def factorial(num):\n        result = 1\n        for i in range(1, num + 1):\n            result *= i\n        return result\n\n    def sum_of_numbers(num):\n        return sum(range(1, num + 1))\n\n    result_list = []\n    for i in range(1, n + 1):\n        if i % 2 == 0:\n            result_list.append(factorial(i))\n        else:\n            result_list.append(sum_of_numbers(i))\n    return result_list", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/105": [{"task_id": "HumanEval/105", "solution": "def by_length(arr):\n    # Define a dictionary to map numbers to their corresponding names\n    num_to_name = {1: 'One', 2: 'Two', 3: 'Three', 4: 'Four', 5: 'Five', 6: 'Six', 7: 'Seven', 8: 'Eight', 9: 'Nine'}\n    \n    # Filter the array to include only numbers between 1 and 9 inclusive\n    filtered_arr = [num for num in arr if 1 <= num <= 9]\n    \n    # Sort the filtered array\n    sorted_arr = sorted(filtered_arr)\n    \n    # Reverse the sorted array\n    reversed_arr = sorted_arr[::-1]\n    \n    # Replace each digit by its corresponding name\n    result = [num_to_name[num] for num in reversed_arr]\n    \n    return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/107": [{"task_id": "HumanEval/107", "solution": "def even_odd_palindrome(n):\n    \"\"\"\n    Given a positive integer n, return a tuple that has the number of even and odd\n    integer palindromes that fall within the range(1, n), inclusive.\n\n    Example 1:\n\n        Input: 3\n        Output: (1, 2)\n        Explanation:\n        Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n\n    Example 2:\n\n        Input: 12\n        Output: (4, 6)\n        Explanation:\n        Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n    Note:\n        1. 1 <= n <= 10^3\n        2. returned tuple has the number of even and odd integer palindromes respectively.\n    \"\"\"\n    def is_palindrome(num):\n        return str(num) == str(num)[::-1]\n\n    even_count = 0\n    odd_count = 0\n\n    for i in range(1, n + 1):\n        if is_palindrome(i):\n            if i % 2 == 0:\n                even_count += 1\n            else:\n                odd_count += 1\n\n    return (even_count, odd_count)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/108": [{"task_id": "HumanEval/108", "solution": "def count_nums(arr):\n    \"\"\"\n    Write a function count_nums which takes an array of integers and returns\n    the number of elements which has a sum of digits > 0.\n    If a number is negative, then its first signed digit will be negative:\n    e.g. -123 has signed digits -1, 2, and 3.\n    >>> count_nums([]) == 0\n    >>> count_nums([-1, 11, -11]) == 1\n    >>> count_nums([1, 1, 2]) == 3\n    \"\"\"\n    def sum_of_digits(num):\n        if num == 0:\n            return 0\n        sum_digits = 0\n        num = abs(num)\n        while num > 0:\n            sum_digits += num % 10\n            num //= 10\n        if num < 0:\n            sum_digits = -sum_digits\n        return sum_digits\n\n    count = 0\n    for num in arr:\n        if sum_of_digits(num) > 0:\n            count += 1\n    return count", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[-1, -2, 0]]], "plus_fail_tests": []}], "HumanEval/109": [{"task_id": "HumanEval/109", "solution": "def move_one_ball(arr):\n    if not arr:\n        return True\n\n    n = len(arr)\n    sorted_arr = sorted(arr)\n\n    for i in range(n):\n        if arr[i:] + arr[:i] == sorted_arr:\n            return True\n\n    return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/110": [{"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n    \"\"\"In this problem, you will implement a function that takes two lists of numbers,\n    and determines whether it is possible to perform an exchange of elements\n    between them to make lst1 a list of only even numbers.\n    There is no limit on the number of exchanged elements between lst1 and lst2.\n    If it is possible to exchange elements between the lst1 and lst2 to make\n    all the elements of lst1 to be even, return \"YES\".\n    Otherwise, return \"NO\".\n    For example:\n    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"YES\"\n    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n    It is assumed that the input lists will be non-empty.\n    \"\"\"\n    \n    # Check if there are enough even numbers in lst2 to replace all odd numbers in lst1\n    odd_count_lst1 = sum(1 for num in lst1 if num % 2 != 0)\n    even_count_lst2 = sum(1 for num in lst2 if num % 2 == 0)\n    \n    if even_count_lst2 >= odd_count_lst1:\n        return \"YES\"\n    else:\n        return \"NO\"", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}, {"task_id": "HumanEval/110", "solution": "def exchange(lst1, lst2):\n    # Check if all elements in lst1 are already even\n    if all(num % 2 == 0 for num in lst1):\n        return 'YES'\n    \n    # Count the number of odd numbers in lst1\n    count_odd = sum(1 for num in lst1 if num % 2 != 0)\n\n    # Count the number of even numbers in lst2\n    count_even = sum(1 for num in lst2 if num % 2 == 0)\n\n    # If the count of odd numbers in lst1 is 0 or the count of even numbers in lst2 is greater than or equal to the count of odd numbers in lst1,\n    # it is possible to exchange elements to make lst1 a list of only even numbers\n    if count_odd == 0 or count_even >= count_odd:\n        return 'YES'\n\n    # Iterate through lst2 and check if any odd number can be swapped\n    for num in lst2:\n        if num % 2 == 1:\n            return 'YES'\n\n    return 'NO'", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 2, 3, 4], [1, 5, 3, 4]]], "plus_fail_tests": []}], "HumanEval/111": [{"task_id": "HumanEval/111", "solution": "def histogram(test):\n    \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n    of the letter with the most repetition and containing the corresponding count.\n    If several letters have the same occurrence, return all of them.\n    \n    Example:\n    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n    histogram('a b b a') == {'a': 2, 'b': 2}\n    histogram('a b c a b') == {'a': 2, 'b': 2}\n    histogram('b b b b a') == {'b': 4}\n    histogram('') == {}\n\n    \"\"\"\n    if not test:\n        return {}\n\n    words = test.split()\n    freq = {}\n    for word in words:\n        if word in freq:\n            freq[word] += 1\n        else:\n            freq[word] = 1\n\n    max_freq = max(freq.values())\n    result = {k: v for k, v in freq.items() if v == max_freq}\n    return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/112": [{"task_id": "HumanEval/112", "solution": "def reverse_delete(s, c):\n    result = ''.join([char for char in s if char not in c])\n    is_palindrome = result == result[::-1]\n    return (result, is_palindrome)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/113": [{"task_id": "HumanEval/113", "solution": "def odd_count(lst):\n    result = []\n    for s in lst:\n        odd_count = sum(1 for char in s if int(char) % 2 != 0)\n        result.append(\"the number of odd elements {0}n the str{0}ng {0} of the {0}nput.\".format(odd_count))\n    return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/115": [{"task_id": "HumanEval/115", "solution": "def max_fill(grid, capacity):\n    total_water = 0\n    for row in grid:\n        total_water += sum(row)\n    return math.ceil(total_water / capacity)", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], 1]], "plus_fail_tests": []}], "HumanEval/114": [{"task_id": "HumanEval/114", "solution": "def minSubArraySum(nums):\n    min_sum = float('inf')\n    current_sum = 0\n    for num in nums:\n        current_sum = min(num, current_sum + num)\n        min_sum = min(min_sum, current_sum)\n    return min_sum", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/116": [{"task_id": "HumanEval/116", "solution": "def sort_array(arr):\n    \"\"\"\n    In this Kata, you have to sort an array of non-negative integers according to\n    number of ones in their binary representation in ascending order.\n    For similar number of ones, sort based on decimal value.\n\n    It must be implemented like this:\n    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n    >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]\n    \"\"\"\n    return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/117": [{"task_id": "HumanEval/117", "solution": "def select_words(s, n):\n    def count_consonants(word):\n        vowels = 'aeiouAEIOU'\n        return sum(1 for char in word if char.isalpha() and char not in vowels)\n\n    if not s:\n        return []\n\n    words = s.split()\n    result = [word for word in words if count_consonants(word) == n]\n    return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/118": [{"task_id": "HumanEval/118", "solution": "def get_closest_vowel(word):\n    vowels = 'aeiouAEIOU'\n    length = len(word)\n    for i in range(length - 2, 0, -1):\n        if word[i] in vowels and word[i - 1] not in vowels and word[i + 1] not in vowels:\n            return word[i]\n    return ''", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/119": [{"task_id": "HumanEval/119", "solution": "def match_parens(lst):\n    '''\n    You are given a list of two strings, both strings consist of open\n    parentheses '(' or close parentheses ')' only.\n    Your job is to check if it is possible to concatenate the two strings in\n    some order, that the resulting string will be good.\n    A string S is considered to be good if and only if all parentheses in S\n    are balanced. For example: the string '(())()' is good, while the string\n    '())' is not.\n    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n    Examples:\n    match_parens(['()(', ')']) == 'Yes'\n    match_parens([')', ')']) == 'No'\n    '''\n\n    def is_balanced(s):\n        balance = 0\n        for char in s:\n            if char == '(':\n                balance += 1\n            else:\n                balance -= 1\n            if balance < 0:\n                return False\n        return balance == 0\n\n    s1, s2 = lst\n    if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n        return 'Yes'\n    else:\n        return 'No'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/121": [{"task_id": "HumanEval/121", "solution": "def solution(lst):\n    \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n    \n    Examples\n    solution([5, 8, 7, 1]) ==> 12\n    solution([3, 3, 3, 3, 3]) ==> 9\n    solution([30, 13, 24, 321]) ==>0\n    \"\"\"\n    return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 != 0)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/120": [{"task_id": "HumanEval/120", "solution": "def maximum(arr, k):\n    \"\"\"\n    Given an array arr of integers and a positive integer k, return a sorted list \n    of length k with the maximum k numbers in arr.\n\n    Example 1:\n\n        Input: arr = [-3, -4, 5], k = 3\n        Output: [-4, -3, 5]\n\n    Example 2:\n\n        Input: arr = [4, -4, 4], k = 2\n        Output: [4, 4]\n\n    Example 3:\n\n        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n        Output: [2]\n\n    Note:\n        1. The length of the array will be in the range of [1, 1000].\n        2. The elements in the array will be in the range of [-1000, 1000].\n        3. 0 <= k <= len(arr)\n    \"\"\"\n    return sorted(sorted(arr, reverse=True)[:k])", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/122": [{"task_id": "HumanEval/122", "solution": "def add_elements(arr, k):\n    \"\"\"\n    Given a non-empty array of integers arr and an integer k, return\n    the sum of the elements with at most two digits from the first k elements of arr.\n\n    Example:\n\n        Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4\n        Output: 24 # sum of 21 + 3\n\n    Constraints:\n        1. 1 <= len(arr) <= 100\n        2. 1 <= k <= len(arr)\n    \"\"\"\n    sum_of_elements = 0\n    for i in range(k):\n        if 1 <= arr[i] <= 99:\n            sum_of_elements += arr[i]\n    return sum_of_elements", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, -2, -3, 41, 57, 76, 87, 88, 99], 3]], "plus_fail_tests": []}], "HumanEval/123": [{"task_id": "HumanEval/123", "solution": "def get_odd_collatz(n):\n    \"\"\"\n    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n    as follows: start with any positive integer n. Then each term is obtained from the \n    previous term as follows: if the previous term is even, the next term is one half of \n    the previous term. If the previous term is odd, the next term is 3 times the previous\n    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n    Note:\n        1. Collatz(1) is [1].\n        2. returned list sorted in increasing order.\n\n    For example:\n    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n    \"\"\"\n    odd_numbers = []\n    while n != 1:\n        if n % 2 != 0:\n            odd_numbers.append(n)\n        if n % 2 == 0:\n            n = n // 2\n        else:\n            n = 3 * n + 1\n    odd_numbers.append(1)\n    return sorted(odd_numbers)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/124": [{"task_id": "HumanEval/124", "solution": "def valid_date(date):\n    \"\"\"You have to write a function which validates a given date string and\n    returns True if the date is valid otherwise False.\n    The date is valid if all of the following rules are satisfied:\n    1. The date string is not empty.\n    2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.\n    3. The months should not be less than 1 or higher than 12.\n    4. The date should be in the format: mm-dd-yyyy\n\n    for example:\n    valid_date('03-11-2000') => True\n\n    valid_date('15-01-2012') => False\n\n    valid_date('04-0-2040') => False\n\n    valid_date('06-04-2020') => True\n\n    valid_date('06/04/2020') => False\n    \"\"\"\n    if not date or len(date) != 10 or date[2] != '-' or date[5] != '-':\n        return False\n\n    try:\n        month, day, year = map(int, date.split('-'))\n    except ValueError:\n        return False\n\n    if month < 1 or month > 12:\n        return False\n\n    if day < 1:\n        return False\n\n    if month in [1, 3, 5, 7, 8, 10, 12]:\n        if day > 31:\n            return False\n    elif month in [4, 6, 9, 11]:\n        if day > 30:\n            return False\n    elif month == 2:\n        if day > 29:\n            return False\n\n    return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/125": [{"task_id": "HumanEval/125", "solution": "def split_words(txt):\n    if ' ' in txt:\n        return txt.split()\n    elif ',' in txt:\n        return txt.replace(',', ' ').split()\n    else:\n        return sum(1 for c in txt if c.islower() and (ord(c) - ord('a')) % 2 == 1)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/126": [{"task_id": "HumanEval/126", "solution": "def is_sorted(lst):\n    '''\n    Given a list of numbers, return whether or not they are sorted\n    in ascending order. If list has more than 1 duplicate of the same\n    number, return False. Assume no negative numbers and only integers.\n\n    Examples\n    is_sorted([5]) \u279e True\n    is_sorted([1, 2, 3, 4, 5]) \u279e True\n    is_sorted([1, 3, 2, 4, 5]) \u279e False\n    is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n    is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n    is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n    is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n    is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n    '''\n    \n    for i in range(len(lst) - 1):\n        if lst[i] > lst[i + 1]:\n            return False\n        if lst[i] == lst[i + 1]:\n            if lst.count(lst[i]) > 2:\n                return False\n    return True", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/127": [{"task_id": "HumanEval/127", "solution": "def intersection(interval1, interval2):\n    def is_prime(n):\n        if n <= 1:\n            return False\n        for i in range(2, int(n**0.5) + 1):\n            if n % i == 0:\n                return False\n        return True\n\n    start1, end1 = interval1\n    start2, end2 = interval2\n\n    intersection_start = max(start1, start2)\n    intersection_end = min(end1, end2)\n\n    if intersection_start > intersection_end:\n        return \"NO\"\n\n    intersection_length = intersection_end - intersection_start + 1\n\n    if is_prime(intersection_length):\n        return \"YES\"\n    else:\n        return \"NO\"", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[-1, 1], [0, 4]]], "plus_fail_tests": []}], "HumanEval/129": [{"task_id": "HumanEval/129", "solution": "def minPath(grid, k):\n    import heapq\n    N = len(grid)\n    directions = [(0, 1), (1, 0), (0, -1), (-1, 0)]\n    \n    def is_valid(x, y):\n        return 0 <= x < N and 0 <= y < N\n    \n    min_heap = []\n    for i in range(N):\n        for j in range(N):\n            heapq.heappush(min_heap, ([grid[i][j]], i, j))\n    \n    while min_heap:\n        path, x, y = heapq.heappop(min_heap)\n        if len(path) == k:\n            return path\n        for dx, dy in directions:\n            nx, ny = x + dx, y + dy\n            if is_valid(nx, ny):\n                new_path = path + [grid[nx][ny]]\n                heapq.heappush(min_heap, (new_path, nx, ny))\n    \n    return []", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/128": [{"task_id": "HumanEval/128", "solution": "def prod_signs(arr):\n    if not arr:\n        return None\n    \n    product_of_signs = 1\n    sum_of_magnitudes = 0\n    \n    for num in arr:\n        if num > 0:\n            product_of_signs *= 1\n        elif num < 0:\n            product_of_signs *= -1\n        else:\n            product_of_signs *= 0\n        sum_of_magnitudes += abs(num)\n    \n    return product_of_signs * sum_of_magnitudes", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/131": [{"task_id": "HumanEval/131", "solution": "def digits(n):\n    \"\"\"Given a positive integer n, return the product of the odd digits.\n    Return 0 if all digits are even.\n    For example:\n    digits(1)  == 1\n    digits(4)  == 0\n    digits(235) == 15\n    \"\"\"\n    product = 1\n    has_odd_digit = False\n    while n > 0:\n        digit = n % 10\n        if digit % 2 != 0:\n            product *= digit\n            has_odd_digit = True\n        n //= 10\n    return product if has_odd_digit else 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/130": [{"task_id": "HumanEval/130", "solution": "def tri(n):\n    if n == 0:\n        return [1]\n    elif n == 1:\n        return [1, 3]\n    else:\n        sequence = [1, 3]\n        for i in range(2, n + 1):\n            if i % 2 == 0:\n                sequence.append(1 + i // 2)\n            else:\n                sequence.append(sequence[i - 1] + sequence[i - 2] + sequence[i + 1])\n        return sequence", "base_status": "fail", "plus_status": null, "base_fail_tests": [[3]], "plus_fail_tests": []}], "HumanEval/132": [{"task_id": "HumanEval/132", "solution": "def is_nested(string):\n    stack = []\n    for char in string:\n        if char == '[':\n            stack.append(char)\n        elif char == ']':\n            if stack:\n                stack.pop()\n            else:\n                return False\n    if len(stack) == 0:\n        for i in range(len(string) - 1):\n            if string[i] == '[' and string[i + 1] == ']':\n                return False\n        return True\n    return False", "base_status": "fail", "plus_status": null, "base_fail_tests": [["[[]]"]], "plus_fail_tests": []}, {"task_id": "HumanEval/132", "solution": "def is_nested(string):\n    stack = []\n    has_opening_bracket = False\n    for char in string:\n        if char == '[':\n            stack.append(char)\n            has_opening_bracket = True\n        elif char == ']':\n            if len(stack) > 0 and stack[-1] == '[':\n                stack.pop()\n            elif has_opening_bracket:\n                return True\n    return False", "base_status": "fail", "plus_status": null, "base_fail_tests": [["[[]]"]], "plus_fail_tests": []}], "HumanEval/133": [{"task_id": "HumanEval/133", "solution": "def sum_squares(lst):\n    \"\"\"You are given a list of numbers.\n    You need to return the sum of squared numbers in the given list,\n    round each element in the list to the upper int(Ceiling) first.\n    Examples:\n    For lst = [1,2,3] the output should be 14\n    For lst = [1,4,9] the output should be 98\n    For lst = [1,3,5,7] the output should be 84\n    For lst = [1.4,4.2,0] the output should be 29\n    For lst = [-2.4,1,1] the output should be 6\n    \"\"\"\n    import math\n    \n    # Round each element to the upper integer (ceiling)\n    rounded_lst = [math.ceil(num) for num in lst]\n    \n    # Calculate the sum of squared numbers\n    sum_of_squares = sum(num ** 2 for num in rounded_lst)\n    \n    return sum_of_squares", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/134": [{"task_id": "HumanEval/134", "solution": "def check_if_last_char_is_a_letter(txt):\n    if not txt or txt[-1] == ' ':\n        return False\n    words = txt.split()\n    if words:\n        last_word = words[-1]\n        if last_word.isalpha() and len(last_word) == 1:\n            return True\n    return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/135": [{"task_id": "HumanEval/135", "solution": "def can_arrange(arr):\n    for i in range(1, len(arr)):\n        if arr[i] < arr[i-1]:\n            return i\n    return -1", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[4, 8, 5, 7, 3]]], "plus_fail_tests": []}], "HumanEval/136": [{"task_id": "HumanEval/136", "solution": "def largest_smallest_integers(lst):\n    '''\n    Create a function that returns a tuple (a, b), where 'a' is\n    the largest of negative integers, and 'b' is the smallest\n    of positive integers in a list.\n    If there is no negative or positive integers, return them as None.\n\n    Examples:\n    largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n    largest_smallest_integers([]) == (None, None)\n    largest_smallest_integers([0]) == (None, None)\n    '''\n    largest_negative = None\n    smallest_positive = None\n\n    for num in lst:\n        if num < 0:\n            if largest_negative is None or num > largest_negative:\n                largest_negative = num\n        elif num > 0:\n            if smallest_positive is None or num < smallest_positive:\n                smallest_positive = num\n\n    return (largest_negative, smallest_positive)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/137": [{"task_id": "HumanEval/137", "solution": "def compare_one(a, b):\n    \"\"\"\n    Create a function that takes integers, floats, or strings representing\n    real numbers, and returns the larger variable in its given variable type.\n    Return None if the values are equal.\n    Note: If a real number is represented as a string, the floating point might be . or ,\n\n    compare_one(1, 2.5) \u279e 2.5\n    compare_one(1, \"2,3\") \u279e \"2,3\"\n    compare_one(\"5,1\", \"6\") \u279e \"6\"\n    compare_one(\"1\", 1) \u279e None\n    \"\"\"\n    \n    def to_float_if_possible(value):\n        try:\n            if isinstance(value, str):\n                value = value.replace(',', '.')\n            return float(value)\n        except ValueError:\n            return value\n\n    a_float = to_float_if_possible(a)\n    b_float = to_float_if_possible(b)\n\n    if a_float > b_float:\n        return a\n    elif a_float < b_float:\n        return b\n    else:\n        return None", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/138": [{"task_id": "HumanEval/138", "solution": "def is_equal_to_sum_even(n):\n    \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers\"\"\"\n    if n < 8:\n        return False\n    return n % 2 == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/139": [{"task_id": "HumanEval/139", "solution": "def special_factorial(n):\n    \"\"\"The Brazilian factorial is defined as:\n    brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!\n    where n > 0\n\n    For example:\n    >>> special_factorial(4)\n    288\n\n    The function will receive an integer as input and should return the special\n    factorial of this integer.\n    \"\"\"\n    def factorial(num):\n        if num == 0 or num == 1:\n            return 1\n        else:\n            return num * factorial(num - 1)\n\n    result = 1\n    for i in range(1, n + 1):\n        result *= factorial(i)\n\n    return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/140": [{"task_id": "HumanEval/140", "solution": "def fix_spaces(text):\n    \"\"\"\n    Given a string text, replace all spaces in it with underscores,\n    and if a string has more than 2 consecutive spaces,\n    then replace all consecutive spaces with -\n    \"\"\"\n    import re\n    \n    # Replace all spaces with underscores\n    text = text.replace(' ', '_')\n    \n    # Replace sequences of more than 2 underscores with a single hyphen\n    text = re.sub(r'_+', lambda m: '-' if len(m.group(0)) > 2 else m.group(0), text)\n    \n    return text", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/141": [{"task_id": "HumanEval/141", "solution": "def file_name_check(file_name):\n    \"\"\"Create a function which takes a string representing a file's name, and returns\n    'Yes' if the the file's name is valid, and returns 'No' otherwise.\n    A file's name is considered to be valid if and only if all the following conditions \n    are met:\n    - There should not be more than three digits ('0'-'9') in the file's name.\n    - The file's name contains exactly one dot '.'\n    - The substring before the dot should not be empty, and it starts with a letter from \n    the latin alphapet ('a'-'z' and 'A'-'Z').\n    - The substring after the dot should be one of these: ['txt', 'exe', 'dll']\n    Examples:\n    file_name_check(\"example.txt\") # => 'Yes'\n    file_name_check(\"1example.dll\") # => 'No' (the name should start with a latin alphapet letter)\n    \"\"\"\n    import re\n\n    # Check if there are more than three digits\n    if len(re.findall(r'\\d', file_name)) > 3:\n        return 'No'\n\n    # Split the file name into parts\n    parts = file_name.split('.', 1)\n    if len(parts) != 2:\n        return 'No'\n\n    name_part, extension_part = parts\n\n    # Check if the name part is empty or does not start with a latin alphabet letter\n    if not name_part or not re.match(r'^[a-zA-Z]', name_part):\n        return 'No'\n\n    # Check if the extension part is valid\n    if extension_part not in ['txt', 'exe', 'dll']:\n        return 'No'\n\n    return 'Yes'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/142": [{"task_id": "HumanEval/142", "solution": "def sum_squares(lst):\n    \"\"\"\n    This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n    multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n    change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n    \n    Examples:\n    For lst = [1,2,3] the output should be 6\n    For lst = []  the output should be 0\n    For lst = [-1,-5,2,-1,-5]  the output should be -126\n    \"\"\"\n    for i in range(len(lst)):\n        if i % 3 == 0:\n            lst[i] = lst[i] ** 2\n        elif i % 4 == 0:\n            lst[i] = lst[i] ** 3\n    return sum(lst)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/143": [{"task_id": "HumanEval/143", "solution": "def is_prime(n):\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\ndef words_in_sentence(sentence):\n    words = sentence.split()\n    prime_length_words = [word for word in words if is_prime(len(word))]\n    return ' '.join(prime_length_words)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/144": [{"task_id": "HumanEval/144", "solution": "def simplify(x, n):\n    \"\"\"Your task is to implement a function that will simplify the expression\n    x * n. The function returns True if x * n evaluates to a whole number and False\n    otherwise. Both x and n, are string representation of a fraction, and have the following format,\n    <numerator>/<denominator> where both numerator and denominator are positive whole numbers.\n\n    You can assume that x, and n are valid fractions, and do not have zero as denominator.\n\n    simplify(\"1/5\", \"5/1\") = True\n    simplify(\"1/6\", \"2/1\") = False\n    simplify(\"7/10\", \"10/2\") = False\n    \"\"\"\n    \n    def parse_fraction(fraction):\n        numerator, denominator = map(int, fraction.split('/'))\n        return numerator, denominator\n\n    x_numerator, x_denominator = parse_fraction(x)\n    n_numerator, n_denominator = parse_fraction(n)\n\n    # Multiply the fractions\n    result_numerator = x_numerator * n_numerator\n    result_denominator = x_denominator * n_denominator\n\n    # Check if the result is a whole number\n    return result_numerator % result_denominator == 0", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/145": [{"task_id": "HumanEval/145", "solution": "def order_by_points(nums):\n    \"\"\"\n    Write a function which sorts the given list of integers\n    in ascending order according to the sum of their digits.\n    Note: if there are several items with similar sum of their digits,\n    order them based on their index in original list.\n\n    For example:\n    >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n    >>> order_by_points([]) == []\n    \"\"\"\n    def digit_sum(n):\n        return sum(int(digit) for digit in str(abs(n)))\n\n    return sorted(nums, key=lambda x: (digit_sum(x), nums.index(x)))", "base_status": "fail", "plus_status": null, "base_fail_tests": [[[1, 11, -1, -11, -12]]], "plus_fail_tests": []}], "HumanEval/146": [{"task_id": "HumanEval/146", "solution": "def specialFilter(nums):\n    def is_odd_digit(digit):\n        return digit in [1, 3, 5, 7, 9]\n\n    count = 0\n    for num in nums:\n        if num > 10:\n            str_num = str(abs(num))\n            if is_odd_digit(int(str_num[0])) and is_odd_digit(int(str_num[-1])):\n                count += 1\n    return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/148": [{"task_id": "HumanEval/148", "solution": "def bf(planet1, planet2):\n    planets = ['Mercury', 'Venus', 'Earth', 'Mars', 'Jupiter', 'Saturn', 'Uranus', 'Neptune']\n    if planet1 not in planets or planet2 not in planets:\n        return ()\n    \n    index1 = planets.index(planet1)\n    index2 = planets.index(planet2)\n    \n    if index1 < index2:\n        return tuple(planets[index1 + 1:index2])\n    elif index1 > index2:\n        return tuple(planets[index2 + 1:index1])\n    else:\n        return ()", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/147": [{"task_id": "HumanEval/147", "solution": "def get_max_triples(n):\n    \"\"\"\n    You are given a positive integer n. You have to create an integer array a of length n.\n    For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n    Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,\n    and a[i] + a[j] + a[k] is a multiple of 3.\n\n    Example :\n        Input: n = 5\n        Output: 1\n        Explanation:\n        a = [1, 3, 7, 13, 21]\n        The only valid triple is (1, 7, 13).\n    \"\"\"\n    a = [i * i - i + 1 for i in range(1, n + 1)]\n    count = 0\n    for i in range(n):\n        for j in range(i + 1, n):\n            for k in range(j + 1, n):\n                if (a[i] + a[j] + a[k]) % 3 == 0:\n                    count += 1\n    return count", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/150": [{"task_id": "HumanEval/150", "solution": "def x_or_y(n, x, y):\n    def is_prime(num):\n        if num <= 1:\n            return False\n        for i in range(2, int(num**0.5) + 1):\n            if num % i == 0:\n                return False\n        return True\n\n    if is_prime(n):\n        return x\n    else:\n        return y", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/149": [{"task_id": "HumanEval/149", "solution": "def sorted_list_sum(lst):\n    \"\"\"Write a function that accepts a list of strings as a parameter,\n    deletes the strings that have odd lengths from it,\n    and returns the resulted list with a sorted order,\n    The list is always a list of strings and never an array of numbers,\n    and it may contain duplicates.\n    The order of the list should be ascending by length of each word, and you\n    should return the list sorted by that rule.\n    If two words have the same length, sort the list alphabetically.\n    The function should return a list of strings in sorted order.\n    You may assume that all words will have the same length.\n    For example:\n    assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n    assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n    \"\"\"\n    # Filter out strings with odd lengths\n    filtered_lst = [s for s in lst if len(s) % 2 == 0]\n    \n    # Sort the list by length and then alphabetically\n    sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n    \n    return sorted_lst", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/152": [{"task_id": "HumanEval/152", "solution": "def compare(game, guess):\n    result = []\n    for score, g in zip(game, guess):\n        if score == g:\n            result.append(0)\n        else:\n            result.append(abs(score - g))\n    return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/151": [{"task_id": "HumanEval/151", "solution": "def double_the_difference(lst):\n    '''\n    Given a list of numbers, return the sum of squares of the numbers\n    in the list that are odd. Ignore numbers that are negative or not integers.\n    \n    double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n    double_the_difference([-1, -2, 0]) == 0\n    double_the_difference([9, -2]) == 81\n    double_the_difference([0]) == 0  \n   \n    If the input list is empty, return 0.\n    '''\n    return sum(x**2 for x in lst if isinstance(x, int) and x > 0 and x % 2 != 0)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/154": [{"task_id": "HumanEval/154", "solution": "def cycpattern_check(a, b):\n    \"\"\"You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word\n    cycpattern_check(\"abcd\",\"abd\") => False\n    cycpattern_check(\"hello\",\"ell\") => True\n    cycpattern_check(\"whassup\",\"psus\") => False\n    cycpattern_check(\"abab\",\"baa\") => True\n    cycpattern_check(\"efef\",\"eeff\") => False\n    cycpattern_check(\"himenss\",\"simen\") => True\n    \"\"\"\n    len_b = len(b)\n    for i in range(len_b):\n        rotated_b = b[i:] + b[:i]\n        if rotated_b in a:\n            return True\n    return False", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/153": [{"task_id": "HumanEval/153", "solution": "def Strongest_Extension(class_name, extensions):\n    def calculate_strength(extension):\n        CAP = sum(1 for char in extension if char.isupper())\n        SM = sum(1 for char in extension if char.islower())\n        return CAP - SM\n\n    strongest_extension = max(extensions, key=calculate_strength)\n    return f'{class_name}.{strongest_extension}'", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/155": [{"task_id": "HumanEval/155", "solution": "def even_odd_count(num):\n    \"\"\"Given an integer, return a tuple that has the number of even and odd digits respectively.\n\n    Example:\n        even_odd_count(-12) ==> (1, 1)\n        even_odd_count(123) ==> (1, 2)\n    \"\"\"\n    num = abs(num)  # Convert to positive to handle negative numbers\n    even_count = 0\n    odd_count = 0\n    while num > 0:\n        digit = num % 10\n        if digit % 2 == 0:\n            even_count += 1\n        else:\n            odd_count += 1\n        num //= 10\n    return (even_count, odd_count)", "base_status": "fail", "plus_status": null, "base_fail_tests": [[0]], "plus_fail_tests": []}], "HumanEval/156": [{"task_id": "HumanEval/156", "solution": "def int_to_mini_roman(number):\n    roman_numerals = [\n        (1000, 'm'), (900, 'cm'), (500, 'd'), (400, 'cd'),\n        (100, 'c'), (90, 'xc'), (50, 'l'), (40, 'xl'),\n        (10, 'x'), (9, 'ix'), (5, 'v'), (4, 'iv'), (1, 'i')\n    ]\n    result = ''\n    for value, numeral in roman_numerals:\n        while number >= value:\n            result += numeral\n            number -= value\n    return result", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/158": [{"task_id": "HumanEval/158", "solution": "def find_max(words):\n    def unique_char_count(word):\n        return len(set(word))\n\n    max_unique_count = 0\n    max_unique_words = []\n\n    for word in words:\n        unique_count = unique_char_count(word)\n        if unique_count > max_unique_count:\n            max_unique_count = unique_count\n            max_unique_words = [word]\n        elif unique_count == max_unique_count:\n            max_unique_words.append(word)\n\n    if max_unique_words:\n        return min(max_unique_words)\n    else:\n        return None", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/157": [{"task_id": "HumanEval/157", "solution": "def right_angle_triangle(a, b, c):\n    '''\n    Given the lengths of the three sides of a triangle. Return True if the three\n    sides form a right-angled triangle, False otherwise.\n    A right-angled triangle is a triangle in which one angle is right angle or \n    90 degree.\n    Example:\n    right_angle_triangle(3, 4, 5) == True\n    right_angle_triangle(1, 2, 3) == False\n    '''\n    # Sort the sides to ensure the largest side is considered as the hypotenuse\n    sides = sorted([a, b, c])\n    return sides[0]**2 + sides[1]**2 == sides[2]**2", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/159": [{"task_id": "HumanEval/159", "solution": "def eat(number, need, remaining):\n    \"\"\"\n    You're a hungry rabbit, and you already have eaten a certain number of carrots,\n    but now you need to eat more carrots to complete the day's meals.\n    you should return an array of [ total number of eaten carrots after your meals,\n                                    the number of carrots left after your meals ]\n    if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n    \n    Example:\n    * eat(5, 6, 10) -> [11, 4]\n    * eat(4, 8, 9) -> [12, 1]\n    * eat(1, 10, 10) -> [11, 0]\n    * eat(2, 11, 5) -> [7, 0]\n    \n    Variables:\n    @number : integer\n        the number of carrots that you have eaten.\n    @need : integer\n        the number of carrots that you need to eat.\n    @remaining : integer\n        the number of remaining carrots thet exist in stock\n    \n    Constrain:\n    * 0 <= number <= 1000\n    * 0 <= need <= 1000\n    * 0 <= remaining <= 1000\n\n    Have fun :)\n    \"\"\"\n    total_eaten = number + min(need, remaining)\n    carrots_left = max(0, remaining - need)\n    return [total_eaten, carrots_left]", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/160": [{"task_id": "HumanEval/160", "solution": "def do_algebra(operator, operand):\n    \"\"\"\n    Given two lists operator, and operand. The first list has basic algebra operations, and \n    the second list is a list of integers. Use the two given lists to build the algebric \n    expression and return the evaluation of this expression.\n\n    The basic algebra operations:\n    Addition ( + ) \n    Subtraction ( - ) \n    Multiplication ( * ) \n    Floor division ( // ) \n    Exponentiation ( ** ) \n\n    Example:\n    operator['+', '*', '-']\n    array = [2, 3, 4, 5]\n    result = 2 + 3 * 4 - 5\n    => result = 9\n\n    Note:\n        The length of operator list is equal to the length of operand list minus one.\n        Operand is a list of of non-negative integers.\n        Operator list has at least one operator, and operand list has at least two operands.\n\n    \"\"\"\n    expression = str(operand[0])\n    for i in range(len(operator)):\n        expression += ' ' + operator[i] + ' ' + str(operand[i + 1])\n    return eval(expression)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/162": [{"task_id": "HumanEval/162", "solution": "import hashlib\ndef string_to_md5(text):\n    \"\"\"\n    Given a string 'text', return its md5 hash equivalent string.\n    If 'text' is an empty string, return None.\n\n    >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n    \"\"\"\n    if not text:\n        return None\n    return hashlib.md5(text.encode()).hexdigest()", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/161": [{"task_id": "HumanEval/161", "solution": "def solve(s):\n    if not any(c.isalpha() for c in s):\n        return s[::-1]\n    else:\n        result = []\n        for char in s:\n            if char.isalpha():\n                if char.islower():\n                    result.append(char.upper())\n                else:\n                    result.append(char.lower())\n            else:\n                result.append(char)\n        return ''.join(result)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}], "HumanEval/163": [{"task_id": "HumanEval/163", "solution": "def generate_integers(a, b):\n    \"\"\"\n    Given two positive integers a and b, return the even digits between a\n    and b, in ascending order.\n\n    For example:\n    generate_integers(2, 8) => [2, 4, 6, 8]\n    generate_integers(8, 2) => [2, 4, 6, 8]\n    generate_integers(10, 14) => []\n    \"\"\"\n    start = min(a, b)\n    end = max(a, b)\n    even_digits = [num for num in range(start, end + 1) if num % 2 == 0 and 10 > num >= 0]\n    return sorted(even_digits)", "base_status": "pass", "plus_status": null, "base_fail_tests": [], "plus_fail_tests": []}]}}
\ No newline at end of file
diff --git a/self_consistency_humaneval.py b/self_consistency_humaneval.py
deleted file mode 100644
index 0e8d9ec72..000000000
--- a/self_consistency_humaneval.py
+++ /dev/null
@@ -1,105 +0,0 @@
-from examples.ags.scripts.operator import Operator
-from examples.ags.scripts.graph import SolveGraph
-from examples.ags.benchmark.humaneval import humaneval_evaluation
-from examples.ags.scripts.operator_an import GenerateOp
-from metagpt.actions.action_node import ActionNode 
-from metagpt.configs.models_config import ModelsConfig
-from metagpt.llm import LLM
-from pydantic import BaseModel, Field
-from typing import List
-
-HUMANEVAL_PROMPT_GPT = """
-{question}\nPlease provide a step-by-step explanation in text, followed by your Python function without any additional text or test cases. 
-"""
-
-SC_ENSEMBLE_PROMPT = """
-Given the question described as follows: {question}
-Several solutions have been generated to address the given question. They are as follows:
-{solutions}
-
-Carefully evaluate these solutions and identify the answer that appears most frequently across them. This consistency in answers is crucial for determining the most reliable solution.
-
-In the "thought" field, provide a detailed explanation of your thought process. In the "solution_letter" field, output only the single letter ID (A, B, C, etc.) corresponding to the most consistent solution. Do not include any additional text or explanation in the "solution_letter" field.
-"""
-
-class GenerateOp(BaseModel):
-    solution: str = Field(default="", description="Python Solution For This Question.")
-
-class CoTGenerate(Operator):
-    def __init__(self, llm: LLM, name: str = "Generate"):
-        super().__init__(name, llm)
-
-    async def __call__(self, problem, function_name, mode: str = None):
-        prompt = HUMANEVAL_PROMPT_GPT.format(question=problem)
-        fill_kwargs = {"context": prompt, "llm": self.llm, "function_name": function_name}
-        if mode:
-            fill_kwargs["mode"] = mode
-        node = await ActionNode.from_pydantic(GenerateOp).fill(**fill_kwargs)
-        response = node.instruct_content.model_dump()
-        return response
-
-class ScEnsembleOp(BaseModel):
-    thought: str = Field(default="", description="The thought of the most consistent solution.")
-    solution_letter: str = Field(default="", description="The letter of most consistent solution.")
-
-class ScEnsemble(Operator):
-    """
-    Paper: Self-Consistency Improves Chain of Thought Reasoning in Language Models
-    Link: https://arxiv.org/abs/2203.11171
-    Paper: Universal Self-Consistency for Large Language Model Generation
-    Link: https://arxiv.org/abs/2311.17311
-    """
-
-    def __init__(self, llm, name: str = "ScEnsemble"):
-        super().__init__(name, llm)
-
-    async def __call__(self, solutions: List[str], problem: str, mode: str = None):
-        answer_mapping = {}
-        solution_text = ""
-        for index, solution in enumerate(solutions):
-            answer_mapping[chr(65 + index)] = index
-            solution_text += f"{chr(65 + index)}: \n{str(solution)}\n\n\n"
-
-        prompt = SC_ENSEMBLE_PROMPT.format(solutions=solution_text, question=problem)
-        fill_kwargs = {"context": prompt, "llm": self.llm}
-        if mode:
-            fill_kwargs["mode"] = mode
-        node = await ActionNode.from_pydantic(ScEnsembleOp).fill(**fill_kwargs)
-        response = node.instruct_content.model_dump()
-
-        answer = response.get("solution_letter", "A")
-        answer = answer.strip().upper()
-
-        return {"solution": solutions[answer_mapping[answer]]}
-    
-    
-class SelfConsistencyGraph(SolveGraph):
-    def __init__(self, name: str, llm_config, dataset: str):
-        super().__init__(name, llm_config, dataset)
-        self.cot_generate = CoTGenerate(llm=self.llm)
-        self.sc_ensemble = ScEnsemble(llm=self.llm)
-
-    async def __call__(self, problem, function_name):
-        solutions = []
-        for i in range(5):
-            solution = await self.cot_generate(problem, function_name, mode="code_fill")
-            solutions.append(solution["solution"])
-        solution = await self.sc_ensemble(solutions, problem, mode="context_fill")
-        return solution["solution"], self.llm.cost_manager.total_cost
-
-if __name__ == "__main__":
-    async def main():
-        # llm_config = ModelsConfig.default().get("gpt-4o-mini")
-        # llm_config = ModelsConfig.default().get("gpt-35-turbo-1106")
-        llm_config = ModelsConfig.default().get("deepseek-chat")
-        # llm_config = ModelsConfig.default().get("claude-3-5-sonnet-20240620")
-
-        graph = SelfConsistencyGraph(name="SelfConsistency", llm_config=llm_config, dataset="HumanEval")
-        file_path = "examples/ags/data/baseline_data/human-eval.jsonl"
-        samples = 33 # 33/131  
-        path = "examples/ags/data/baselines/general/humaneval"
-        score = await humaneval_evaluation(graph, file_path, samples, path,test=True)
-        return score
-
-    import asyncio
-    asyncio.run(main())
diff --git a/self_refine_humaneval.py b/self_refine_humaneval.py
deleted file mode 100644
index 2c7c6d0d4..000000000
--- a/self_refine_humaneval.py
+++ /dev/null
@@ -1,122 +0,0 @@
-from examples.ags.scripts.operator import Operator
-from examples.ags.scripts.graph import SolveGraph
-from examples.ags.benchmark.humaneval import humaneval_evaluation
-from metagpt.actions.action_node import ActionNode 
-from metagpt.configs.models_config import ModelsConfig
-from metagpt.llm import LLM
-from pydantic import BaseModel, Field
-from typing import Dict, Any
-
-HUMANEVAL_PROMPT_GPT = """
-{question}\nPlease provide a step-by-step explanation in text, followed by your Python function without any additional text or test cases. 
-"""
-
-
-REVIEW_PROMPT = """
-Given a problem and a thoughtful solution, your task is to using critical thinking (questioning) to review the solution's correctness and provide a review result in boolean format.
-
-problem: {problem}
-solution: {solution}
-
-If you are more than 95 percent confident that the final answer is incorrect, please return False and give a feedback for the error. Otherwise, please return True and give a explanation for the correctness.
-"""
-
-REVISE_PROMPT = """
-Given a problem and a thoughtful solution which is just reviewed as incorrect, your task is to revise the solution to solve the question and ensure the final code solution is wrapped with ```python```.
-
-problem: {problem}
-solution: {solution}
-feedback: {feedback}
-
-Ensure the output code is self-contained, and without any additional text or test cases.
-"""
-
-class GenerateOp(BaseModel):
-    solution: str = Field(default="", description="solution for the problem")
-
-class ReviewOp(BaseModel):
-    review_result: bool = Field(
-        default=False,
-        description="The Review Result (Bool). If you think this solution looks good for you, return 'true'; If not, return 'false'",
-    )
-    feedback: str = Field(
-        default="",
-        description="Your FeedBack for this problem based on the criteria. If the review result is true, you can put it 'nothing here'.",
-    )
-
-
-class ReviseOp(BaseModel):
-    solution: str = Field(default="", description="Based on the feedback, revised solution for this problem")
-
-
-class CoTGenerate(Operator):
-    def __init__(self, llm: LLM, name: str = "Generate"):
-        super().__init__(name, llm)
-
-    async def __call__(self, problem, function_name, mode: str = None):
-        prompt = HUMANEVAL_PROMPT_GPT.format(question=problem)
-        fill_kwargs = {"context": prompt, "llm": self.llm, "function_name": function_name}
-        if mode:
-            fill_kwargs["mode"] = mode
-        node = await ActionNode.from_pydantic(GenerateOp).fill(**fill_kwargs)
-        response = node.instruct_content.model_dump()
-        return response
-    
-class Review(Operator):
-    def __init__(self, llm: LLM, name: str = "Review"):
-        super().__init__(name, llm)
-
-    async def __call__(self, problem, solution, mode: str = None):
-        prompt = REVIEW_PROMPT.format(problem=problem, solution=solution)
-        fill_kwargs = {"context": prompt, "llm": self.llm}
-        if mode:
-            fill_kwargs["mode"] = mode
-        node = await ActionNode.from_pydantic(ReviewOp).fill(**fill_kwargs)
-        response = node.instruct_content.model_dump()
-        return response
-
-class Revise(Operator):
-    def __init__(self, llm: LLM, name: str = "Revise"):
-        super().__init__(name, llm)
-
-    async def __call__(self, problem, solution, feedback, mode: str = None):
-        prompt = REVISE_PROMPT.format(problem=problem, solution=solution, feedback=feedback)
-        fill_kwargs = {"context": prompt, "llm": self.llm}
-        if mode:
-            fill_kwargs["mode"] = mode
-        node = await ActionNode.from_pydantic(ReviseOp).fill(**fill_kwargs)
-        response = node.instruct_content.model_dump()
-        return response  
-
-class SelfRefineGraph(SolveGraph):
-    def __init__(self, name: str, llm_config, dataset: str):
-        llm_config.temperature = 0.0
-        super().__init__(name, llm_config, dataset)
-        self.cot_generate = CoTGenerate(self.llm)
-        self.review = Review(self.llm)
-        self.revise = Revise(self.llm)
-
-    async def __call__(self, problem, function_name):
-        solution = await self.cot_generate(problem, function_name, mode="code_fill")
-        for i in range(3):
-            review = await self.review(problem, solution, mode="context_fill")
-            if review["review_result"]:
-                break
-            solution = await self.revise(problem, solution, review["feedback"], mode="code_fill")
-        return solution["solution"], self.llm.cost_manager.total_cost
-
-if __name__ == "__main__":
-    async def main():
-        # llm_config = ModelsConfig.default().get("gpt-4o-mini")
-        # llm_config = ModelsConfig.default().get("gpt-4o")
-        # llm_config = ModelsConfig.default().get("deepseek-chat")
-        llm_config = ModelsConfig.default().get("claude-3-5-sonnet-20240620")
-        graph = SelfRefineGraph(name="self-refine", llm_config=llm_config, dataset="HumanEval")
-        file_path = "examples/ags/data/baseline_data/human-eval.jsonl"
-        samples = 33
-        path = "examples/ags/data/baselines/general/humaneval"
-        score, cost = await humaneval_evaluation(graph, file_path, samples, path, test=True)
-        return score, cost
-
-    import asyncio
-    asyncio.run(main())
diff --git a/test.ipynb b/test.ipynb
deleted file mode 100644
index c137a9a2e..000000000
--- a/test.ipynb
+++ /dev/null
@@ -1,243 +0,0 @@
-{
- "cells": [
-  {
-   "cell_type": "code",
-   "execution_count": 1,
-   "metadata": {},
-   "outputs": [],
-   "source": [
-    "# TODO 帮助我写一个代码，找出这种结构中，都出现的id与并不是都出现的id，以及第一，二，三批单独出现的id，\n",
-    "test_1 = [{'task_id': 'HumanEval/6'}, {'task_id': 'HumanEval/10'}, {'task_id': 'HumanEval/11'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/41'}, {'task_id': 'HumanEval/46'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/54'}, {'task_id': 'HumanEval/63'}, {'task_id': 'HumanEval/75'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/81'}, {'task_id': 'HumanEval/84'}, {'task_id': 'HumanEval/90'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/94'}, {'task_id': 'HumanEval/95'}, {'task_id': 'HumanEval/100'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/111'}, {'task_id': 'HumanEval/113'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/118'}, {'task_id': 'HumanEval/120'}, {'task_id': 'HumanEval/119'}, {'task_id': 'HumanEval/122'}, {'task_id': 'HumanEval/121'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/125'}, {'task_id': 'HumanEval/127'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/131'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/133'}, {'task_id': 'HumanEval/135'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/137'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/142'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/155'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/163'}]\n",
-    "test_2 = [{'task_id': 'HumanEval/1'}, {'task_id': 'HumanEval/6'}, {'task_id': 'HumanEval/10'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/41'}, {'task_id': 'HumanEval/54'}, {'task_id': 'HumanEval/64'}, {'task_id': 'HumanEval/75'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/77'}, {'task_id': 'HumanEval/81'}, {'task_id': 'HumanEval/84'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/100'}, {'task_id': 'HumanEval/102'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/111'}, {'task_id': 'HumanEval/113'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/118'}, {'task_id': 'HumanEval/119'}, {'task_id': 'HumanEval/120'}, {'task_id': 'HumanEval/122'}, {'task_id': 'HumanEval/125'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/127'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/133'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/135'}, {'task_id': 'HumanEval/137'}, {'task_id': 'HumanEval/138'}, {'task_id': 'HumanEval/139'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/142'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/153'}, {'task_id': 'HumanEval/155'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n",
-    "test_3 = [{'task_id': 'HumanEval/1'}, {'task_id': 'HumanEval/26'}, {'task_id': 'HumanEval/29'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/41'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/75'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/77'}, {'task_id': 'HumanEval/81'}, {'task_id': 'HumanEval/83'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/97'}, {'task_id': 'HumanEval/100'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/111'}, {'task_id': 'HumanEval/113'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/118'}, {'task_id': 'HumanEval/119'}, {'task_id': 'HumanEval/120'}, {'task_id': 'HumanEval/121'}, {'task_id': 'HumanEval/122'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/125'}, {'task_id': 'HumanEval/127'}, {'task_id': 'HumanEval/128'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/131'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/133'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/135'}, {'task_id': 'HumanEval/137'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/142'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/149'}, {'task_id': 'HumanEval/155'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/163'}]\n",
-    "test_4 = [{'task_id': 'HumanEval/1'}, {'task_id': 'HumanEval/14'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/36'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/41'}, {'task_id': 'HumanEval/43'}, {'task_id': 'HumanEval/46'}, {'task_id': 'HumanEval/54'}, {'task_id': 'HumanEval/64'}, {'task_id': 'HumanEval/73'}, {'task_id': 'HumanEval/75'}, {'task_id': 'HumanEval/77'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/84'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/97'}, {'task_id': 'HumanEval/100'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/111'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/119'}, {'task_id': 'HumanEval/120'}, {'task_id': 'HumanEval/121'}, {'task_id': 'HumanEval/125'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/127'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/128'}, {'task_id': 'HumanEval/131'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/133'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/137'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/142'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/148'}, {'task_id': 'HumanEval/155'}, {'task_id': 'HumanEval/161'}, {'task_id': 'HumanEval/163'}]"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 2,
-   "metadata": {},
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "Common IDs: length:25 {'HumanEval/32', 'HumanEval/130', 'HumanEval/127', 'HumanEval/100', 'HumanEval/132', 'HumanEval/115', 'HumanEval/129', 'HumanEval/75', 'HumanEval/76', 'HumanEval/108', 'HumanEval/140', 'HumanEval/119', 'HumanEval/41', 'HumanEval/155', 'HumanEval/145', 'HumanEval/93', 'HumanEval/120', 'HumanEval/111', 'HumanEval/126', 'HumanEval/163', 'HumanEval/134', 'HumanEval/142', 'HumanEval/125', 'HumanEval/137', 'HumanEval/133'}\n",
-      "Not Common IDs: {'HumanEval/122', 'HumanEval/6', 'HumanEval/74', 'HumanEval/81', 'HumanEval/83', 'HumanEval/90', 'HumanEval/160', 'HumanEval/36', 'HumanEval/73', 'HumanEval/94', 'HumanEval/95', 'HumanEval/14', 'HumanEval/148', 'HumanEval/29', 'HumanEval/39', 'HumanEval/64', 'HumanEval/46', 'HumanEval/102', 'HumanEval/26', 'HumanEval/153', 'HumanEval/10', 'HumanEval/161', 'HumanEval/139', 'HumanEval/11', 'HumanEval/159', 'HumanEval/54', 'HumanEval/110', 'HumanEval/131', 'HumanEval/149', 'HumanEval/1', 'HumanEval/43', 'HumanEval/128', 'HumanEval/97', 'HumanEval/118', 'HumanEval/135', 'HumanEval/77', 'HumanEval/121', 'HumanEval/154', 'HumanEval/113', 'HumanEval/63', 'HumanEval/138', 'HumanEval/91', 'HumanEval/84'}\n",
-      "Unique to test_1: {'HumanEval/11', 'HumanEval/154', 'HumanEval/63', 'HumanEval/90', 'HumanEval/94', 'HumanEval/95'}\n",
-      "Unique to test_2: {'HumanEval/139', 'HumanEval/102', 'HumanEval/160', 'HumanEval/153', 'HumanEval/138'}\n",
-      "Unique to test_3: {'HumanEval/149', 'HumanEval/29', 'HumanEval/83', 'HumanEval/26'}\n",
-      "Unique to test_4: {'HumanEval/14', 'HumanEval/148', 'HumanEval/73', 'HumanEval/36', 'HumanEval/161', 'HumanEval/43'}\n"
-     ]
-    }
-   ],
-   "source": [
-    "def extract_ids(test_list):\n",
-    "    return set(item['task_id'] for item in test_list)\n",
-    "\n",
-    "def compare_ids(test_1, test_2, test_3, test_4):\n",
-    "    ids_1 = extract_ids(test_1)\n",
-    "    ids_2 = extract_ids(test_2)\n",
-    "    ids_3 = extract_ids(test_3)\n",
-    "    ids_4 = extract_ids(test_4)\n",
-    "\n",
-    "    common_ids = ids_1 & ids_2 & ids_3 & ids_4\n",
-    "    all_ids = ids_1 | ids_2 | ids_3 | ids_4\n",
-    "    not_common_ids = all_ids - common_ids\n",
-    "\n",
-    "    unique_1 = ids_1 - (ids_2 | ids_3 | ids_4)\n",
-    "    unique_2 = ids_2 - (ids_1 | ids_3 | ids_4)\n",
-    "    unique_3 = ids_3 - (ids_1 | ids_2 | ids_4)\n",
-    "    unique_4 = ids_4 - (ids_1 | ids_2 | ids_3)\n",
-    "\n",
-    "    return {\n",
-    "        'common_ids': common_ids,\n",
-    "        'not_common_ids': not_common_ids,\n",
-    "        'unique_1': unique_1,\n",
-    "        'unique_2': unique_2,\n",
-    "        'unique_3': unique_3,\n",
-    "        'unique_4': unique_4\n",
-    "    }\n",
-    "\n",
-    "# Assuming test_1, test_2, and test_3 are defined as in your example\n",
-    "result = compare_ids(test_1, test_2, test_3, test_4)\n",
-    "\n",
-    "print(\"Common IDs:\",f\"length:{len(result['common_ids'])}\", result['common_ids'])\n",
-    "print(\"Not Common IDs:\",result['not_common_ids'])\n",
-    "print(\"Unique to test_1:\", result['unique_1'])\n",
-    "print(\"Unique to test_2:\", result['unique_2'])\n",
-    "print(\"Unique to test_3:\", result['unique_3'])\n",
-    "print(\"Unique to test_4:\", result['unique_4'])"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 3,
-   "metadata": {},
-   "outputs": [],
-   "source": [
-    "test_1 = [{'task_id': 'HumanEval/1'}, {'task_id': 'HumanEval/0'}, {'task_id': 'HumanEval/3'}, {'task_id': 'HumanEval/5'}, {'task_id': 'HumanEval/6'}, {'task_id': 'HumanEval/7'}, {'task_id': 'HumanEval/8'}, {'task_id': 'HumanEval/9'}, {'task_id': 'HumanEval/10'}, {'task_id': 'HumanEval/14'}, {'task_id': 'HumanEval/17'}, {'task_id': 'HumanEval/21'}, {'task_id': 'HumanEval/20'}, {'task_id': 'HumanEval/22'}, {'task_id': 'HumanEval/26'}, {'task_id': 'HumanEval/29'}, {'task_id': 'HumanEval/28'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/36'}, {'task_id': 'HumanEval/37'}, {'task_id': 'HumanEval/41'}, {'task_id': 'HumanEval/62'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/64'}, {'task_id': 'HumanEval/77'}, {'task_id': 'HumanEval/81'}, {'task_id': 'HumanEval/80'}, {'task_id': 'HumanEval/84'}, {'task_id': 'HumanEval/87'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/94'}, {'task_id': 'HumanEval/98'}, {'task_id': 'HumanEval/99'}, {'task_id': 'HumanEval/100'}, {'task_id': 'HumanEval/106'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/109'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/111'}, {'task_id': 'HumanEval/113'}, {'task_id': 'HumanEval/114'}, {'task_id': 'HumanEval/118'}, {'task_id': 'HumanEval/119'}, {'task_id': 'HumanEval/120'}, {'task_id': 'HumanEval/124'}, {'task_id': 'HumanEval/125'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/127'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/133'}, {'task_id': 'HumanEval/137'}, {'task_id': 'HumanEval/138'}, {'task_id': 'HumanEval/139'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/142'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/148'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n",
-    "test_2 = [{'task_id': 'HumanEval/0'}, {'task_id': 'HumanEval/1'}, {'task_id': 'HumanEval/3'}, {'task_id': 'HumanEval/5'}, {'task_id': 'HumanEval/6'}, {'task_id': 'HumanEval/7'}, {'task_id': 'HumanEval/9'}, {'task_id': 'HumanEval/12'}, {'task_id': 'HumanEval/14'}, {'task_id': 'HumanEval/21'}, {'task_id': 'HumanEval/22'}, {'task_id': 'HumanEval/26'}, {'task_id': 'HumanEval/29'}, {'task_id': 'HumanEval/28'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/54'}, {'task_id': 'HumanEval/64'}, {'task_id': 'HumanEval/70'}, {'task_id': 'HumanEval/73'}, {'task_id': 'HumanEval/74'}, {'task_id': 'HumanEval/75'}, {'task_id': 'HumanEval/82'}, {'task_id': 'HumanEval/81'}, {'task_id': 'HumanEval/84'}, {'task_id': 'HumanEval/83'}, {'task_id': 'HumanEval/88'}, {'task_id': 'HumanEval/89'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/100'}, {'task_id': 'HumanEval/101'}, {'task_id': 'HumanEval/102'}, {'task_id': 'HumanEval/106'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/109'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/111'}, {'task_id': 'HumanEval/113'}, {'task_id': 'HumanEval/114'}, {'task_id': 'HumanEval/115'}, {'task_id': 'HumanEval/119'}, {'task_id': 'HumanEval/118'}, {'task_id': 'HumanEval/120'}, {'task_id': 'HumanEval/122'}, {'task_id': 'HumanEval/124'}, {'task_id': 'HumanEval/125'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/127'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/131'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/133'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/135'}, {'task_id': 'HumanEval/137'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/142'}, {'task_id': 'HumanEval/144'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/155'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n",
-    "test_3 = [{'task_id': 'HumanEval/0'}, {'task_id': 'HumanEval/1'}, {'task_id': 'HumanEval/3'}, {'task_id': 'HumanEval/5'}, {'task_id': 'HumanEval/6'}, {'task_id': 'HumanEval/7'}, {'task_id': 'HumanEval/9'}, {'task_id': 'HumanEval/12'}, {'task_id': 'HumanEval/14'}, {'task_id': 'HumanEval/20'}, {'task_id': 'HumanEval/19'}, {'task_id': 'HumanEval/26'}, {'task_id': 'HumanEval/29'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/36'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/41'}, {'task_id': 'HumanEval/43'}, {'task_id': 'HumanEval/64'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/69'}, {'task_id': 'HumanEval/80'}, {'task_id': 'HumanEval/83'}, {'task_id': 'HumanEval/84'}, {'task_id': 'HumanEval/87'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/94'}, {'task_id': 'HumanEval/99'}, {'task_id': 'HumanEval/100'}, {'task_id': 'HumanEval/101'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/109'}, {'task_id': 'HumanEval/111'}, {'task_id': 'HumanEval/113'}, {'task_id': 'HumanEval/118'}, {'task_id': 'HumanEval/119'}, {'task_id': 'HumanEval/120'}, {'task_id': 'HumanEval/121'}, {'task_id': 'HumanEval/122'}, {'task_id': 'HumanEval/124'}, {'task_id': 'HumanEval/116'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/125'}, {'task_id': 'HumanEval/127'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/135'}, {'task_id': 'HumanEval/137'}, {'task_id': 'HumanEval/138'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/142'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 4,
-   "metadata": {},
-   "outputs": [],
-   "source": [
-    "test_1 = [{'task_id': 'HumanEval/1'}, {'task_id': 'HumanEval/0'}, {'task_id': 'HumanEval/3'}, {'task_id': 'HumanEval/5'}, {'task_id': 'HumanEval/6'}, {'task_id': 'HumanEval/7'}, {'task_id': 'HumanEval/9'}, {'task_id': 'HumanEval/12'}, {'task_id': 'HumanEval/14'}, {'task_id': 'HumanEval/17'}, {'task_id': 'HumanEval/20'}, {'task_id': 'HumanEval/21'}, {'task_id': 'HumanEval/26'}, {'task_id': 'HumanEval/28'}, {'task_id': 'HumanEval/29'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/46'}, {'task_id': 'HumanEval/54'}, {'task_id': 'HumanEval/64'}, {'task_id': 'HumanEval/68'}, {'task_id': 'HumanEval/71'}, {'task_id': 'HumanEval/75'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/77'}, {'task_id': 'HumanEval/80'}, {'task_id': 'HumanEval/84'}, {'task_id': 'HumanEval/87'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/100'}, {'task_id': 'HumanEval/102'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/109'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/111'}, {'task_id': 'HumanEval/113'}, {'task_id': 'HumanEval/116'}, {'task_id': 'HumanEval/118'}, {'task_id': 'HumanEval/119'}, {'task_id': 'HumanEval/120'}, {'task_id': 'HumanEval/122'}, {'task_id': 'HumanEval/123'}, {'task_id': 'HumanEval/124'}, {'task_id': 'HumanEval/125'}, {'task_id': 'HumanEval/127'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/131'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/135'}, {'task_id': 'HumanEval/137'}, {'task_id': 'HumanEval/138'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/142'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/156'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n",
-    "test_2 = [{'task_id': 'HumanEval/0'}, {'task_id': 'HumanEval/1'}, {'task_id': 'HumanEval/5'}, {'task_id': 'HumanEval/6'}, {'task_id': 'HumanEval/7'}, {'task_id': 'HumanEval/8'}, {'task_id': 'HumanEval/9'}, {'task_id': 'HumanEval/10'}, {'task_id': 'HumanEval/12'}, {'task_id': 'HumanEval/14'}, {'task_id': 'HumanEval/16'}, {'task_id': 'HumanEval/17'}, {'task_id': 'HumanEval/20'}, {'task_id': 'HumanEval/22'}, {'task_id': 'HumanEval/21'}, {'task_id': 'HumanEval/26'}, {'task_id': 'HumanEval/28'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/41'}, {'task_id': 'HumanEval/65'}, {'task_id': 'HumanEval/69'}, {'task_id': 'HumanEval/73'}, {'task_id': 'HumanEval/75'}, {'task_id': 'HumanEval/77'}, {'task_id': 'HumanEval/84'}, {'task_id': 'HumanEval/88'}, {'task_id': 'HumanEval/90'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/94'}, {'task_id': 'HumanEval/99'}, {'task_id': 'HumanEval/100'}, {'task_id': 'HumanEval/102'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/111'}, {'task_id': 'HumanEval/113'}, {'task_id': 'HumanEval/114'}, {'task_id': 'HumanEval/116'}, {'task_id': 'HumanEval/118'}, {'task_id': 'HumanEval/119'}, {'task_id': 'HumanEval/120'}, {'task_id': 'HumanEval/121'}, {'task_id': 'HumanEval/122'}, {'task_id': 'HumanEval/124'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/125'}, {'task_id': 'HumanEval/127'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/133'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/135'}, {'task_id': 'HumanEval/137'}, {'task_id': 'HumanEval/138'}, {'task_id': 'HumanEval/139'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/142'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/144'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]\n",
-    "test_3 = [{'task_id': 'HumanEval/0'}, {'task_id': 'HumanEval/1'}, {'task_id': 'HumanEval/5'}, {'task_id': 'HumanEval/6'}, {'task_id': 'HumanEval/7'}, {'task_id': 'HumanEval/10'}, {'task_id': 'HumanEval/12'}, {'task_id': 'HumanEval/14'}, {'task_id': 'HumanEval/20'}, {'task_id': 'HumanEval/19'}, {'task_id': 'HumanEval/22'}, {'task_id': 'HumanEval/21'}, {'task_id': 'HumanEval/25'}, {'task_id': 'HumanEval/26'}, {'task_id': 'HumanEval/28'}, {'task_id': 'HumanEval/29'}, {'task_id': 'HumanEval/32'}, {'task_id': 'HumanEval/33'}, {'task_id': 'HumanEval/37'}, {'task_id': 'HumanEval/39'}, {'task_id': 'HumanEval/41'}, {'task_id': 'HumanEval/49'}, {'task_id': 'HumanEval/63'}, {'task_id': 'HumanEval/64'}, {'task_id': 'HumanEval/68'}, {'task_id': 'HumanEval/75'}, {'task_id': 'HumanEval/76'}, {'task_id': 'HumanEval/77'}, {'task_id': 'HumanEval/80'}, {'task_id': 'HumanEval/84'}, {'task_id': 'HumanEval/87'}, {'task_id': 'HumanEval/89'}, {'task_id': 'HumanEval/91'}, {'task_id': 'HumanEval/93'}, {'task_id': 'HumanEval/94'}, {'task_id': 'HumanEval/98'}, {'task_id': 'HumanEval/100'}, {'task_id': 'HumanEval/99'}, {'task_id': 'HumanEval/102'}, {'task_id': 'HumanEval/108'}, {'task_id': 'HumanEval/110'}, {'task_id': 'HumanEval/111'}, {'task_id': 'HumanEval/113'}, {'task_id': 'HumanEval/116'}, {'task_id': 'HumanEval/120'}, {'task_id': 'HumanEval/119'}, {'task_id': 'HumanEval/124'}, {'task_id': 'HumanEval/126'}, {'task_id': 'HumanEval/125'}, {'task_id': 'HumanEval/127'}, {'task_id': 'HumanEval/129'}, {'task_id': 'HumanEval/131'}, {'task_id': 'HumanEval/132'}, {'task_id': 'HumanEval/130'}, {'task_id': 'HumanEval/134'}, {'task_id': 'HumanEval/135'}, {'task_id': 'HumanEval/137'}, {'task_id': 'HumanEval/136'}, {'task_id': 'HumanEval/140'}, {'task_id': 'HumanEval/142'}, {'task_id': 'HumanEval/145'}, {'task_id': 'HumanEval/148'}, {'task_id': 'HumanEval/153'}, {'task_id': 'HumanEval/154'}, {'task_id': 'HumanEval/155'}, {'task_id': 'HumanEval/156'}, {'task_id': 'HumanEval/159'}, {'task_id': 'HumanEval/160'}, {'task_id': 'HumanEval/163'}]"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 10,
-   "metadata": {},
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "from typing import List\n",
-      "\n",
-      "\n",
-      "def has_close_elements(numbers: List[float], threshold: float) -> bool:\n",
-      "    \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n",
-      "    given threshold.\n",
-      "    >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n",
-      "    False\n",
-      "    >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n",
-      "    True\n",
-      "    \"\"\"\n",
-      "    for i in range(len(numbers)):\n",
-      "        for j in range(i + 1, len(numbers)):\n",
-      "            if abs(numbers[i] - numbers[j]) < threshold:\n",
-      "                return True\n",
-      "    return False\n",
-      "def has_close_elements(numbers: List[float], threshold: float) -> bool:\n",
-      "    \n",
-      "    # Sort the numbers in ascending order\n",
-      "    numbers.sort()\n",
-      "    \n",
-      "    # Iterate through the numbers and check the difference between adjacent numbers\n",
-      "    for i in range(len(numbers) - 1):\n",
-      "        if abs(numbers[i] - numbers[i+1]) < threshold:\n",
-      "            return True\n",
-      "    \n",
-      "    # If no adjacent numbers are closer than the threshold, return False\n",
-      "    return False\n",
-      "\n",
-      "\n",
-      "    sorted_numbers = sorted(numbers)\n",
-      "    for i in range(len(sorted_numbers) - 1):\n",
-      "        if sorted_numbers[i + 1] - sorted_numbers[i] < threshold:\n",
-      "            return True\n",
-      "    return False\n",
-      "\n",
-      "\n",
-      "\n",
-      "\n",
-      "METADATA = {\n",
-      "    'author': 'jt',\n",
-      "    'dataset': 'test'\n",
-      "}\n",
-      "\n",
-      "\n",
-      "def check(candidate):\n",
-      "    assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.3) == True\n",
-      "    assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.05) == False\n",
-      "    assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.95) == True\n",
-      "    assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.8) == False\n",
-      "    assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.0], 0.1) == True\n",
-      "    assert candidate([1.1, 2.2, 3.1, 4.1, 5.1], 1.0) == True\n",
-      "    assert candidate([1.1, 2.2, 3.1, 4.1, 5.1], 0.5) == False\n",
-      "\n",
-      "\n"
-     ]
-    },
-    {
-     "data": {
-      "text/plain": [
-       "'\\n    assert isinstance(threshold, float) and threshold > 0, \"invalid inputs\" # $_CONTRACT_$\\n    assert isinstance(numbers, list), \"invalid inputs\" # $_CONTRACT_$\\n    assert all([isinstance(v, (int, float)) for v in numbers]), \"invalid inputs\" # $_CONTRACT_$\\n'"
-      ]
-     },
-     "execution_count": 10,
-     "metadata": {},
-     "output_type": "execute_result"
-    }
-   ],
-   "source": [
-    "from evalplus.data import get_human_eval_plus, write_jsonl\n",
-    "\n",
-    "humaneval = get_human_eval_plus()\n",
-    "d_result = {\"task_id\": \"HumanEval/0\", \"solution\": \"from typing import List\\n\\n\\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\\n    \\\"\\\"\\\" Check if in given list of numbers, are any two numbers closer to each other than\\n    given threshold.\\n    >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\\n    False\\n    >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\\n    True\\n    \\\"\\\"\\\"\\n    for i in range(len(numbers)):\\n        for j in range(i + 1, len(numbers)):\\n            if abs(numbers[i] - numbers[j]) < threshold:\\n                return True\\n    return False\"}\n",
-    "result = {\"task_id\": \"HumanEval/0\", \"solution\": \"def has_close_elements(numbers: List[float], threshold: float) -> bool:\\n    \\n    # Sort the numbers in ascending order\\n    numbers.sort()\\n    \\n    # Iterate through the numbers and check the difference between adjacent numbers\\n    for i in range(len(numbers) - 1):\\n        if abs(numbers[i] - numbers[i+1]) < threshold:\\n            return True\\n    \\n    # If no adjacent numbers are closer than the threshold, return False\\n    return False\"}\n",
-    "print(d_result[\"solution\"])\n",
-    "print(result[\"solution\"])\n",
-    "d_result = \n",
-    "result = \n",
-    "print(d_result[\"solution\"])\n",
-    "print(result[\"solution\"])\n",
-    "print(humaneval['HumanEval/0']['canonical_solution'])\n",
-    "print(humaneval['HumanEval/0']['test'])\n",
-    "humaneval['HumanEval/0']['contract']\n"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 9,
-   "metadata": {},
-   "outputs": [],
-   "source": [
-    "from typing import List\n",
-    "def has_close_elements(numbers: List[float], threshold: float) -> bool:\n",
-    "    \n",
-    "    # Sort the numbers in ascending order\n",
-    "    numbers.sort()\n",
-    "    \n",
-    "    # Iterate through the numbers and check the difference between adjacent numbers\n",
-    "    for i in range(len(numbers) - 1):\n",
-    "        if abs(numbers[i] - numbers[i+1]) < threshold:\n",
-    "            return True\n",
-    "    \n",
-    "    # If no adjacent numbers are closer than the threshold, return False\n",
-    "    return False\n",
-    "\n",
-    "def check(candidate):\n",
-    "    assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.3) == True\n",
-    "    assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.05) == False\n",
-    "    assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.95) == True\n",
-    "    assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.8) == False\n",
-    "    assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.0], 0.1) == True\n",
-    "    assert candidate([1.1, 2.2, 3.1, 4.1, 5.1], 1.0) == True\n",
-    "    assert candidate([1.1, 2.2, 3.1, 4.1, 5.1], 0.5) == False\n",
-    "\n",
-    "check(has_close_elements)"
-   ]
-  }
- ],
- "metadata": {
-  "kernelspec": {
-   "display_name": "Python 3",
-   "language": "python",
-   "name": "python3"
-  },
-  "language_info": {
-   "codemirror_mode": {
-    "name": "ipython",
-    "version": 3
-   },
-   "file_extension": ".py",
-   "mimetype": "text/x-python",
-   "name": "python",
-   "nbconvert_exporter": "python",
-   "pygments_lexer": "ipython3",
-   "version": "3.9.19"
-  }
- },
- "nbformat": 4,
- "nbformat_minor": 2
-}
diff --git a/test.py b/test.py
deleted file mode 100644
index a32c2094f..000000000
--- a/test.py
+++ /dev/null
@@ -1,51 +0,0 @@
-import asyncio
-
-from pydantic import BaseModel, Field
-
-from metagpt.actions.action_node import ActionNode
-from metagpt.configs.models_config import ModelsConfig
-from metagpt.provider.llm_provider_registry import create_llm_instance
-from metagpt.utils.cost_manager import CostManager
-
-deepseek_llm_config = ModelsConfig.default().get("deepseek-coder")
-deepseek_llm = create_llm_instance(deepseek_llm_config)
-deepseek_llm.cost_manager = CostManager()
-claude_llm_config = ModelsConfig.default().get("claude-3.5-sonnet")
-claude_llm = create_llm_instance(claude_llm_config)
-
-# TODO 思考一下，如何每次都去创建新实例，从而保证每次计数的一致。
-# llm.cost_manager = data.llm.cost_manager
-
-
-class GenerateCodeSolution(BaseModel):
-    solution: str = Field(default="", description="A description of the solution")
-    thought: str = Field(
-        default="",
-        description="Shortly explain why this solution correctly solves the problem. Be specific and detailed regarding the problem rules and goals.",
-    )
-
-
-GENERATE_ON_CONTEXT_PROMPT = """
-Please generate a solution for the following problem based on the provided context:
-
-### Problem Description
-{problem_description}
-"""
-
-
-async def main():
-    prompt = GENERATE_ON_CONTEXT_PROMPT.format(
-        problem_description="Janet\u2019s ducks lay 16 eggs per day. She eats three for breakfast every morning and bakes muffins for her friends every day with four. She sells the remainder at the farmers' market daily for $2 per fresh duck egg. How much in dollars does she make every day at the farmers' market?"
-    )
-    node = await ActionNode.from_pydantic(GenerateCodeSolution).fill(
-        context=prompt, llm=deepseek_llm, mode="context_fill"
-    )
-    response = node.instruct_content.model_dump()
-
-    print(deepseek_llm.cost_manager.total_cost)
-
-    return response
-
-
-if __name__ == "__main__":
-    print(asyncio.run(main()))
diff --git a/tester.txt b/tester.txt
deleted file mode 100644
index efe76a5c6..000000000
--- a/tester.txt
+++ /dev/null
@@ -1,168 +0,0 @@
-filter_integers
-incr_list
-string_sequence
-greatest_common_divisor
-generate_integers
-anti_shuffle
-derivative
-monotonic
-eat
-solution
-sort_numbers
-make_palindrome
-fib
-order_by_points
-numerical_letter_grade
-is_simple_power
-rounded_avg
-is_nested
-multiply
-x_or_y
-count_distinct_characters
-prime_length
-solve
-below_zero
-minSubArraySum
-count_upper
-find_closest_elements
-count_up_to
-below_threshold
-triangle_area
-choose_num
-sum_to_n
-common
-unique_digits
-intersection
-search
-factorize
-add_elements
-mean_absolute_deviation
-get_closest_vowel
-get_max_triples
-tri
-longest
-even_odd_palindrome
-get_row
-maximum
-move_one_ball
-cycpattern_check
-solve
-check_if_last_char_is_a_letter
-get_odd_collatz
-circular_shift
-exchange
-flip_case
-get_positive
-parse_music
-is_prime
-add
-unique
-is_equal_to_sum_even
-fibfib
-is_multiply_prime
-truncate_number
-fix_spaces
-vowels_count
-add
-words_string
-correct_bracketing
-any_int
-filter_by_substring
-change_base
-f
-special_factorial
-string_xor
-hex_key
-Strongest_Extension
-strange_sort_list
-prime_fib
-encrypt
-simplify
-encode_shift
-has_close_elements
-decimal_to_binary
-count_nums
-rescale_to_unit
-median
-triangle_area
-fizz_buzz
-how_many_times
-remove_vowels
-find_max
-right_angle_triangle
-int_to_mini_roman
-sum_squares
-match_parens
-smallest_change
-largest_divisor
-sort_array
-triples_sum_to_zero
-is_bored
-sorted_list_sum
-can_arrange
-encode_cyclic
-by_length
-largest_smallest_integers
-bf
-modp
-car_race_collision
-sort_third
-histogram
-compare_one
-words_in_sentence
-pluck
-is_sorted
-filter_by_prefix
-same_chars
-parse_nested_parens
-remove_duplicates
-sum_squares
-encode
-sort_even
-make_a_pile
-digitSum
-prod_signs
-largest_prime_factor
-sum_product
-double_the_difference
-split_words
-odd_count
-minPath
-total_match
-skjkasdkd
-is_palindrome
-find_zero
-check_dict_case
-string_to_md5
-next_smallest
-is_happy
-all_prefixes
-separate_paren_groups
-iscube
-select_words
-closest_integer
-fruit_distribution
-do_algebra
-max_fill
-sort_array
-digits
-even_odd_count
-correct_bracketing
-largest_smallest_integers
-reverse_delete
-strlen
-pairs_sum_to_zero
-intersperse
-rolling_max
-concatenate
-valid_date
-compare
-starts_one_ends
-will_it_fly
-max_element
-specialFilter
-file_name_check
-fib4
-largest_smallest_integers
-largest_smallest_integers
-largest_smallest_integers